id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__8vFyxfpb33011tjF | Sides of a rectangular park are in the ratio 3: 2 and its area is 2400 sq m, the cost of fencing it at 50 ps per meter is? Choose the correct option.
A) 287
B) 100
C) 125
D) 988
E) 271 | <gadget id="calculator">2_400 * 2</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 3</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 ** (1/2)</gadget>
<output>40</output>
<gadget id="calculator">2_400 / 40</gadget>
<output>60</output>
<gadget id="calculator">2 * (40 + 60)</gadget>
<output>200</output>
<gadget id="calculator">50 * 200</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 100</gadget>
<output>100</output>
<result>B</result> | B | 100 | Sides of a rectangular park are in the ratio 3: 2 and its area is 2400 sq m, the cost of fencing it at 50 ps per meter is? | {
"A": "287",
"B": "100",
"C": "125",
"D": "988",
"E": "271"
} | divide(multiply(50, rectangle_perimeter(sqrt(divide(multiply(2400, 2), 3)), divide(2400, sqrt(divide(multiply(2400, 2), 3))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100)| | "3 x * 2 x = 2400 = > x = 20 2 ( 60 + 40 ) = 200 m 200 * 1 / 2 = rs . 100 answer : b" | physics |
math_qa__Ix0RXTQQ7eeDzYKY | If 3x+4y=60 and 6x-4y=12, what is the product of x and y?
Pick.
A) 80
B) 54
C) 54
D) 72
E) 12 | <gadget id="calculator">60 + 12</gadget>
<output>72</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">72 / 9</gadget>
<output>8</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">48 - 12</gadget>
<output>36</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<gadget id="calculator">8 * 9</gadget>
<output>72</output>
<result>D</result> | D | 72 | If 3x+4y=60 and 6x-4y=12, what is the product of x and y? | {
"A": "80",
"B": "54",
"C": "54",
"D": "72",
"E": "12"
} | multiply(divide(add(60, 12), add(6, 3)), divide(subtract(multiply(6, divide(add(60, 12), add(6, 3))), 12), 4)) | add(n2,n5)|add(n0,n3)|divide(#0,#1)|multiply(n3,#2)|subtract(#3,n5)|divide(#4,n1)|multiply(#2,#5) | given 3 x + 4 y = 60 - - - eq 1 6 x - 4 y = 12 - - eq 2 sum both eqns we get 9 x = 72 = > x = 8 sum 6 x in eq 2 = > 48 - 4 y = 12 . = > y = 9 now xy = 8 * 9 = 72 option d is correct answer . | general |
math_qa__GfnosGpcRhv0aoIq | A rope can make 70 rounds of the circumference of a cylinder whose radius of the base is 14cm. how many times can it go round a cylinder having radius 20 cm?
Options: A) 49 rounds B) 42 rounds C) 54 rounds D) 52 rounds E) none of these | <gadget id="calculator">2 * pi * 14</gadget>
<output>28*pi = around 87.964594</output>
<gadget id="calculator">(28*pi) * 70</gadget>
<output>1960*pi = around 6_157.521601</output>
<gadget id="calculator">2 * pi * 20</gadget>
<output>40*pi = around 125.663706</output>
<gadget id="calculator">(1960*pi) / (40*pi)</gadget>
<output>49</output>
<result>A</result> | A | 49 | A rope can make 70 rounds of the circumference of a cylinder whose radius of the base is 14cm. how many times can it go round a cylinder having radius 20 cm? | {
"A": "49 rounds",
"B": "42 rounds",
"C": "54 rounds",
"D": "52 rounds",
"E": "none of these"
} | divide(multiply(circumface(14), 70), circumface(20)) | circumface(n1)|circumface(n2)|multiply(n0,#0)|divide(#2,#1) | explanation : let the required number of rounds be x more radius , less rounds ( indirect proportion ) hence we can write as radius 14 : 20 } : : x : 70 ⇒ 14 × 70 = 20 x ⇒ 14 × 7 = 2 x ⇒ x = 7 × 7 = 49 . answer : option a | geometry |
math_qa__aKgXJHA5emT0HKhB | A seller of used cars has 18 cars to sell and each of his clients selected 3 cars that he liked most. If each car was selected exactly thrice, how many clients visited the garage?
Answers
A) 8 B) 10 C) 12 D) 18 E) 16 | <gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<result>D</result> | D | 18 | A seller of used cars has 18 cars to sell and each of his clients selected 3 cars that he liked most. If each car was selected exactly thrice, how many clients visited the garage? | {
"A": "8",
"B": "10",
"C": "12",
"D": "18",
"E": "16"
} | multiply(divide(18, 3), const_3) | divide(n0,n1)|multiply(#0,const_3)| | "ifno caris selected more than once then the number of clients = 18 / 3 = 6 but since every car is being selected three times so no . of clients must be thrice as well = 6 * 3 = 18 answer : option d" | general |
math_qa__REafC2WnUygvzQS2 | Vijay sells a cupboard at 12% below cost price. Had he got Rs.1650 more, he would have made a profit of 12%. What is the cost price of the cupboard?
Select the correct option
A) 7450 B) 14900 C) 7400 D) 6875 E) none of these | <gadget id="calculator">100 + 12</gadget>
<output>112</output>
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">112 - 88</gadget>
<output>24</output>
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">1_650 / (6/25)</gadget>
<output>6_875</output>
<result>D</result> | D | 6,875 | Vijay sells a cupboard at 12% below cost price. Had he got Rs.1650 more, he would have made a profit of 12%. What is the cost price of the cupboard? | {
"A": "7450",
"B": "14900",
"C": "7400",
"D": "6875",
"E": "none of these"
} | divide(1650, divide(subtract(add(const_100, 12), subtract(const_100, 12)), const_100)) | add(n0,const_100)|subtract(const_100,n0)|subtract(#0,#1)|divide(#2,const_100)|divide(n1,#3)| | "explanation : cost price = 1650 / ( 0.12 + 0.12 ) = 2086 / 0.24 = rs . 6875 answer d" | gain |
math_qa__096xLTAcPCDyooj7 | A hostel had provisions for 250 men for 48 days. If 50 men left the hostel, how long will the food last at the same rate? Choose the correct choice from the following options
A) 30 B) 40 C) 50 D) 60 E) 65 | <gadget id="calculator">250 * 48</gadget>
<output>12_000</output>
<gadget id="calculator">250 - 50</gadget>
<output>200</output>
<gadget id="calculator">12_000 / 200</gadget>
<output>60</output>
<result>D</result> | D | 60 | A hostel had provisions for 250 men for 48 days. If 50 men left the hostel, how long will the food last at the same rate? | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "65"
} | divide(multiply(250, 48), subtract(250, 50)) | multiply(n0,n1)|subtract(n0,n2)|divide(#0,#1)| | "a hostel had provisions for 250 men for 48 days if 50 men leaves the hostel , remaining men = 250 - 50 = 200 we need to find out how long the food will last for these 200 men . let the required number of days = x days more men , less days ( indirect proportion ) ( men ) 250 : 200 : : x : 48 250 × 48 = 200 x 5 × 48 = 4 x x = 5 × 12 = 60 answer d" | gain |
math_qa__nIssI1qT1waFP4Pu | 8 identical machines, working alone and at their constant rates, take 6 hours to complete a job lot. How long would it take for 12 such machines to perform the same job?
Choose the correct choice
A) 6 hours B) 8.75 hours C) 12 hours D) 4 hours E) 16 hours | <gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">48 / 12</gadget>
<output>4</output>
<result>D</result> | D | 4 | 8 identical machines, working alone and at their constant rates, take 6 hours to complete a job lot. How long would it take for 12 such machines to perform the same job? | {
"A": "6 hours",
"B": "8.75 hours",
"C": "12 hours",
"D": "4 hours",
"E": "16 hours"
} | divide(multiply(6, 8), 12) | multiply(n0,n1)|divide(#0,n2)| | "let each machine do 1 unit of work for 1 hour 8 machines - - > 8 units of work in 1 hour for 6 hours = 8 * 6 = 48 units of total work is done . now this 48 units of total work must be done by 3 machines 12 units of work ( 12 machines ) - - - > 1 hour for 48 units of work 12 * 4 - - - > 1 * 4 hours d 4 hours" | physics |
math_qa__yV9rQWARvWZpheUs | If a 5 percent deposit that has been paid toward the purchase of a certain product is $50, how much more remains to be paid? Options:
A) $ 550 B) $ 650 C) $ 750 D) $ 850 E) $ 950 | <gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">50 * 20</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 50</gadget>
<output>950</output>
<result>E</result> | E | 950 | If a 5 percent deposit that has been paid toward the purchase of a certain product is $50, how much more remains to be paid? | {
"A": "$ 550",
"B": "$ 650",
"C": "$ 750",
"D": "$ 850",
"E": "$ 950"
} | subtract(multiply(50, divide(const_100, 5)), 50) | divide(const_100,n0)|multiply(n1,#0)|subtract(#1,n1)| | "95 % remains to be paid so the remaining amount is 19 * 50 = $ 950 . the answer is e ." | general |
math_qa__Q36J6CeNaDQzWsHm | John buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods. Select.
A) rs . 6876.10 B) rs . 4500 C) rs . 4600 D) rs . 3400 E) rs . 7500 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 6_650</gadget>
<output>399</output>
<gadget id="calculator">6_650 - 399</gadget>
<output>6_251</output>
<gadget id="calculator">(1/10) * 6_251</gadget>
<output>6_251/10 = around 625.1</output>
<gadget id="calculator">(6_251/10) + 6_251</gadget>
<output>68_761/10 = around 6_876.1</output>
<result>A</result> | A | 6,876.1 | John buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods. | {
"A": "rs . 6876.10",
"B": "rs . 4500",
"C": "rs . 4600",
"D": "rs . 3400",
"E": "rs . 7500"
} | add(multiply(divide(10, const_100), subtract(6650, multiply(divide(6, const_100), 6650))), subtract(6650, multiply(divide(6, const_100), 6650))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#1)|subtract(n0,#2)|multiply(#0,#3)|add(#4,#3) | rebate = 6 % of rs . 6650 = rs . 6 x 6650 = rs . 399 . 100 sales tax = 10 % of rs . ( 6650 - 399 ) = rs . 10 x 6251 = rs . 625.10 100 final amount = rs . ( 6251 + 625.10 ) = rs . 6876.10 correct answer - a | gain |
math_qa__ze4EvgbebZd39Miw | The ratio of the adjacent angles of a parallelogram is 4 : 11. Also, the ratio of the angles of quadrilateral is 5 : 6 : 7 : 12. What is the sum of the smaller angle of the parallelogram and the second largest angle of the quadrilateral?
Choose the correct choice from the following choices: A) 132 ° B) 228 ° C) 156 ° D) 224 ° E) none of these | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 10</gadget>
<output>80</output>
<gadget id="calculator">80 + 100</gadget>
<output>180</output>
<gadget id="calculator">180 * 2</gadget>
<output>360</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">11 + 7</gadget>
<output>18</output>
<gadget id="calculator">18 + 12</gadget>
<output>30</output>
<gadget id="calculator">360 / 30</gadget>
<output>12</output>
<gadget id="calculator">12 * 11</gadget>
<output>132</output>
<result>A</result> | A | 132 | The ratio of the adjacent angles of a parallelogram is 4 : 11. Also, the ratio of the angles of quadrilateral is 5 : 6 : 7 : 12. What is the sum of the smaller angle of the parallelogram and the second largest angle of the quadrilateral? | {
"A": "132 °",
"B": "228 °",
"C": "156 °",
"D": "224 °",
"E": "none of these"
} | multiply(divide(multiply(add(multiply(multiply(const_4, const_2), const_10), const_100), const_2), add(add(add(5, 6), 7), 12)), 11) | add(n2,n3)|multiply(const_2,const_4)|add(n4,#0)|multiply(#1,const_10)|add(#3,const_100)|add(n5,#2)|multiply(#4,const_2)|divide(#6,#5)|multiply(n1,#7) | the measures of the adjacent angles of a parallelogram add up to be 180 ° given so , 4 x + 11 x = 180 ° or , 15 x = 180 ° or , x = 12 ° hence the angles of the parallelogram are 48 ° and 132 ° further it is given we know sum of all the four angles of a quadrilateral is 360 ° so , 5 y + 6 y + 7 y + 12 y = 360 ° or , 5 y + 6 y + 7 y + 12 y = 360 ° or , 30 y = 360 ° or , y = 12 ° hence the angles of the quadrilateral are 60 ° , 72 , 84 ° and 144 ° will be 48 ° + 84 ° = 132 ° answer : a | other |
math_qa__6XpCOueHJp1sy5Ky | A circular dartboard of radius 1 foot is at a distance of 20 feet from you. You throw a dart at it and it hits the dartboard at some point Q in the circle. What is the probability that Q is closer to the center of the circle than the periphery? Select
A) 0.75
B) 1
C) 0.25
D) 0.5
E) 0.58 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * (1/2)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">(1/4) / 1</gadget>
<output>1/4 = around 0.25</output>
<result>C</result> | C | 0.25 | A circular dartboard of radius 1 foot is at a distance of 20 feet from you. You throw a dart at it and it hits the dartboard at some point Q in the circle. What is the probability that Q is closer to the center of the circle than the periphery? | {
"A": "0.75",
"B": "1",
"C": "0.25",
"D": "0.5",
"E": "0.58"
} | divide(multiply(divide(1, const_2), divide(1, const_2)), multiply(const_1, const_1)) | divide(n0,const_2)|multiply(const_1,const_1)|multiply(#0,#0)|divide(#2,#1) | radius of inner dartboard / overall radius of dartboard ( ( r / 2 ) ^ 2 ) / ( r ^ 2 ) = 1 / 4 = 0.25 answer : c | probability |
math_qa__0FQw2TsCGgsXhLW3 | A, B and C have Rs.700 between them, A and C together have Rs.300 and B and C Rs.600. How much does C have? Choose the correct option.
A) 200 B) 250 C) 300 D) 350 E) 400 | <gadget id="calculator">300 + 600</gadget>
<output>900</output>
<gadget id="calculator">900 - 700</gadget>
<output>200</output>
<result>A</result> | A | 200 | A, B and C have Rs.700 between them, A and C together have Rs.300 and B and C Rs.600. How much does C have? | {
"A": "200",
"B": "250",
"C": "300",
"D": "350",
"E": "400"
} | subtract(add(300, 600), 700) | add(n1,n2)|subtract(#0,n0)| | "a + b + c = 700 a + c = 300 b + c = 600 - - - - - - - - - - - - - - a + b + 2 c = 900 a + b + c = 700 - - - - - - - - - - - - - - - - c = 200 answer : a" | general |
math_qa__QS20iFLpvtmDZsRJ | A and B together can do a work in7 days. If A alone can do it in 14 days. In how many days can B alone do it?
Choose the most appropriate option:
A) 14 B) 10 C) 21 D) 20 E) 25 | <gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">1 / 14</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/7) - (1/14)</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">1 / (1/14)</gadget>
<output>14</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">14 + (2/5)</gadget>
<output>72/5 = around 14.4</output>
<result>A</result> | A | 14 | A and B together can do a work in7 days. If A alone can do it in 14 days. In how many days can B alone do it? | {
"A": "14",
"B": "10",
"C": "21",
"D": "20",
"E": "25"
} | add(inverse(subtract(divide(const_1, 7), divide(const_1, 14))), divide(const_2, add(const_2, const_3))) | add(const_2,const_3)|divide(const_1,n0)|divide(const_1,n1)|divide(const_2,#0)|subtract(#1,#2)|inverse(#4)|add(#3,#5)| | "a 14 1 / 7 â € “ 1 / 14 = 1 / 14 = > 14" | physics |
math_qa__4oG5Hdj9izAXTSK8 | A and B start walking towards each other at 7am at speed of 12kmph and 13kmph. They were initially 25km apart. At what time do they meet?
Choose the correct choice from the following choices:
A) 8 pm
B) 6 am
C) 7 am
D) 10 am
E) 8 am | <gadget id="calculator">12 + 13</gadget>
<output>25</output>
<gadget id="calculator">25 / 25</gadget>
<output>1</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<result>E</result> | E | 8 | A and B start walking towards each other at 7am at speed of 12kmph and 13kmph. They were initially 25km apart. At what time do they meet? | {
"A": "8 pm",
"B": "6 am",
"C": "7 am",
"D": "10 am",
"E": "8 am"
} | add(7, divide(25, add(12, 13))) | add(n1,n2)|divide(n3,#0)|add(n0,#1)| | "time of meeting = distance / relative speed = 25 / 13 + 12 = 25 / 25 = 1 hr after 7 pm = 8 am answer is e" | physics |
math_qa__ofhKOJE5TlXvgTfQ | Find the lowest common multiple of 24, 36 and 42.
Choose the correct choice from the following:
A) 360
B) 504
C) 510
D) 320
E) 280 | <gadget id="calculator">lcm(24, 36)</gadget>
<output>72</output>
<gadget id="calculator">lcm(72, 42)</gadget>
<output>504</output>
<result>B</result> | B | 504 | Find the lowest common multiple of 24, 36 and 42. | {
"A": "360",
"B": "504",
"C": "510",
"D": "320",
"E": "280"
} | lcm(lcm(24, 36), 42) | lcm(n0,n1)|lcm(n2,#0)| | "lcm = 2 * 2 * 2 * 3 * 3 * 7 = 504 . answer is b" | general |
math_qa__hE4DmUGrGEyu6RQX | If shares of two persons in profits are Rs.800 and Rs.600 then ratio of their capitals is
Select: A) 3 : 4 B) 2 : 3 C) 4 : 3 D) 1 : 3 E) 1 : 5 | <gadget id="calculator">800 / 600</gadget>
<output>4/3 = around 1.333333</output>
<result>C</result> | C | 1.333333 | If shares of two persons in profits are Rs.800 and Rs.600 then ratio of their capitals is | {
"A": "3 : 4",
"B": "2 : 3",
"C": "4 : 3",
"D": "1 : 3",
"E": "1 : 5"
} | divide(800, 600) | divide(n0,n1)| | "total profit = 1000 ratio = 800 / 600 = 4 : 3 answer : c" | other |
math_qa__FANpX7EeJ606uZZW | If 7/10 of a pencil is green, 4/5 of the remaining is gold and the remaining 1/2 is white, what is the total length of the pencil?
Choose the correct choice from the following answers.
A) 5 B) 3 C) 1 D) 4 E) 2 | <gadget id="calculator">7 / 10</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(7/10) + (4/5)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/2) + (1/2)</gadget>
<output>2</output>
<result>E</result> | E | 2 | If 7/10 of a pencil is green, 4/5 of the remaining is gold and the remaining 1/2 is white, what is the total length of the pencil? | {
"A": "5",
"B": "3",
"C": "1",
"D": "4",
"E": "2"
} | add(add(divide(7, 10), divide(4, 5)), divide(1, 2)) | divide(n0,n1)|divide(n2,n3)|divide(n4,n5)|add(#0,#1)|add(#3,#2) | green is 7 / 10 gold is 4 / 5 which can also be written as 8 / 10 white is 1 / 2 which can also be written as 5 / 10 7 / 10 + 8 / 10 + 5 / 10 = 2 answer is e ) 2 | general |
math_qa__zEiYpfvgRovcZrL4 | A takes twice as much time as B & C takes thrice as much time as B to finish a piece of work. Working together they can finish the work in 18 days. The no. of days need for B to do the work alone is?
Choose the correct choice from the following options:
A) 30 days B) 31 days C) 33 days D) 41 days E) 52 days | <gadget id="calculator">lcm(2, 3)</gadget>
<output>6</output>
<gadget id="calculator">6 / 1</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">9 + 2</gadget>
<output>11</output>
<gadget id="calculator">11 * 18</gadget>
<output>198</output>
<gadget id="calculator">198 / 6</gadget>
<output>33</output>
<result>C</result> | C | 33 | A takes twice as much time as B & C takes thrice as much time as B to finish a piece of work. Working together they can finish the work in 18 days. The no. of days need for B to do the work alone is? | {
"A": "30 days",
"B": "31 days",
"C": "33 days",
"D": "41 days",
"E": "52 days"
} | divide(multiply(add(add(divide(lcm(const_2, const_3), const_1), divide(lcm(const_2, const_3), const_2)), divide(lcm(const_2, const_3), const_3)), 18), lcm(const_2, const_3)) | lcm(const_2,const_3)|divide(#0,const_1)|divide(#0,const_2)|divide(#0,const_3)|add(#1,#2)|add(#4,#3)|multiply(n0,#5)|divide(#6,#0) | let a takes x days to complete the work , then b takes x / 2 days and c takes 3 x / 2 days to complete the work . a , b and c together complete the work in 18 days in 1 day , all they together can do = > 1 / x + 2 / x + 2 / 3 x = 1 / 18 3 + 6 + 2 / 3 x = 1 / 18 3 x 23 x 2 = 18 x = 66 days the number of days b alone takes to finish the work = x / 2 = 33 days c | physics |
math_qa__9IlKw4Ubia1qrj0j | A man can row his boat with the stream at 20 km/h and against the stream in 8 km/h. The man's rate is? Answers:
A) 1 kmph
B) 7 kmph
C) 6 kmph
D) 5 kmph
E) 4 kmph | <gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>C</result> | C | 6 | A man can row his boat with the stream at 20 km/h and against the stream in 8 km/h. The man's rate is? | {
"A": "1 kmph",
"B": "7 kmph",
"C": "6 kmph",
"D": "5 kmph",
"E": "4 kmph"
} | divide(subtract(20, 8), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 20 us = 8 s = ? s = ( 20 - 8 ) / 2 = 6 kmph answer : c" | gain |
math_qa__oCxGYWJ7cJEPT3Ar | The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles?
Select the correct option.
A) 2898 sq m B) 1788 sq m C) 4312 sq m D) 7656 sq m E) 1786 sq m | <gadget id="calculator">2 * pi</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">352 / (2*pi)</gadget>
<output>176/pi = around 56.02254</output>
<gadget id="calculator">pi * ((176/pi) ** 2)</gadget>
<output>30976/pi = around 9_859.967034</output>
<gadget id="calculator">264 / (2*pi)</gadget>
<output>132/pi = around 42.016905</output>
<gadget id="calculator">pi * ((132/pi) ** 2)</gadget>
<output>17424/pi = around 5_546.231457</output>
<gadget id="calculator">(30976/pi) - (17424/pi)</gadget>
<output>13552/pi = around 4_313.735578</output>
<result>C</result> | C | 4,312 | The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles? | {
"A": "2898 sq m",
"B": "1788 sq m",
"C": "4312 sq m",
"D": "7656 sq m",
"E": "1786 sq m"
} | subtract(circle_area(divide(352, multiply(const_2, const_pi))), circle_area(divide(264, multiply(const_2, const_pi)))) | multiply(const_2,const_pi)|divide(n1,#0)|divide(n0,#0)|circle_area(#1)|circle_area(#2)|subtract(#3,#4) | let the radii of the smaller and the larger circles be s m and l m respectively . 2 ∏ s = 264 and 2 ∏ l = 352 s = 264 / 2 ∏ and l = 352 / 2 ∏ difference between the areas = ∏ l 2 - ∏ s 2 = ∏ { 1762 / ∏ 2 - 1322 / ∏ 2 } = 1762 / ∏ - 1322 / ∏ = ( 176 - 132 ) ( 176 + 132 ) / ∏ = ( 44 ) ( 308 ) / ( 22 / 7 ) = ( 2 ) ( 308 ) ( 7 ) = 4312 sq m answer : c | geometry |
math_qa__dxoy7KIQC512vL2u | A man buys Rs. 60 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
Select:
A) s . 12 B) s . 15 C) s . 18 D) s . 21 E) s . 45 | <gadget id="calculator">100 / 12</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">(9/100) * 60</gadget>
<output>27/5 = around 5.4</output>
<gadget id="calculator">(25/3) * (27/5)</gadget>
<output>45</output>
<result>E</result> | E | 45 | A man buys Rs. 60 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is: | {
"A": "s . 12",
"B": "s . 15",
"C": "s . 18",
"D": "s . 21",
"E": "s . 45"
} | multiply(divide(const_100, 12), multiply(divide(9, const_100), 60)) | divide(const_100,n2)|divide(n1,const_100)|multiply(n0,#1)|multiply(#0,#2)| | "dividend on rs . 60 = rs . 9 / 100 x 60 = rs . 5.4 . rs . 12 is an income on rs . 100 . rs . 5.4 is an income on rs . 100 / 12 x 5.4 = rs . 45 . answer : option e" | gain |
math_qa__UMHnOVmZiIXnFG1l | A number of 53 marbles is to be divided and contain with boxes. If each box is to contain 3, 4, or 5 marbles, what is the largest possible number of boxes? Choose the correct choice from the following answers.
A) 10 B) 12 C) 15 D) 16 E) 17 | <gadget id="calculator">53 / 3</gadget>
<output>53/3 = around 17.666667</output>
<result>E</result> | E | 17 | A number of 53 marbles is to be divided and contain with boxes. If each box is to contain 3, 4, or 5 marbles, what is the largest possible number of boxes? | {
"A": "10",
"B": "12",
"C": "15",
"D": "16",
"E": "17"
} | divide(53, 3) | divide(n0,n1)| | "to maximize # of boxes we should minimize marbles per box : 16 * 3 + 1 * 5 = 53 - - > 16 + 1 = 17 . answer : e ." | general |
math_qa__3PbTw3LEZQfZSO5W | The rhombus (AFCE) is inscribed in rectangle (ABCD). The length of BF = DE.
If the rectangle has a width of 20 yards and a length of 25 yards, what would be the total length (the perimeter) of a fence along the sides defined by AFCE? Choose the correct answer: A) 80 yards B) 82 yards C) 84 yards D) 85 yards E) 90 yards | <gadget id="calculator">25 ** 2</gadget>
<output>625</output>
<gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">625 - 400</gadget>
<output>225</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">225 / 50</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">25 - (9/2)</gadget>
<output>41/2 = around 20.5</output>
<gadget id="calculator">(41/2) * 4</gadget>
<output>82</output>
<result>B</result> | B | 82 | The rhombus (AFCE) is inscribed in rectangle (ABCD). The length of BF = DE.
If the rectangle has a width of 20 yards and a length of 25 yards, what would be the total length (the perimeter) of a fence along the sides defined by AFCE? | {
"A": "80 yards",
"B": "82 yards",
"C": "84 yards",
"D": "85 yards",
"E": "90 yards"
} | multiply(subtract(25, divide(subtract(power(25, const_2), power(20, const_2)), multiply(25, const_2))), const_4) | multiply(n1,const_2)|power(n1,const_2)|power(n0,const_2)|subtract(#1,#2)|divide(#3,#0)|subtract(n1,#4)|multiply(#5,const_4) | the definition of a rhombus states that every side is of equal length . this definition is the key to solving this question . 1 ) we state that the hypotenuse of either side triangle is x . for this solution , i will be working with the left triangle . 2 ) we state that the bottom and top sides of the rhombus are also x , due to the definition of a rhombus . 3 ) we will define the bottom of the left triangle as y . that is , for the rectangle bottom itself , we can define it as 25 = y + x , where x is a side for the rhombus and y is the bottom part of the left triangle . 4 ) from ( 1 ) , we know that x = 202 + y 2 − − − − − − − √ 202 + y 2 . 5 ) from ( 3 ) , we know x = 25 - y . 6 ) from ( 4 ) and ( 5 ) , we have the equation 202 + y 2 − − − − − − − √ = 25 − y 202 + y 2 = 25 − y 7 ) solving for y , we get 4.5 . 8 ) 25 - 4.5 = 20.5 = x 9 ) since all sides of the rhombus are the same , 20.5 * 4 = 41 * 2 = 82 . the answer is b , 82 | geometry |
math_qa__R9kesFlZZBmqfXhr | On the first of the year, James invested x dollars at Proudstar bank in an account that yields 2.4% in interest every quarter year. At the end of the year, during which he made no additional deposits or withdrawals, he had y dollars in the account. If James had invested the same amount in an account which pays interest on a yearly basis, what must the interest rate be for James to have y dollars at the end of the year?
Select
A) 2.04 %
B) 6.12 %
C) 8 %
D) 8.25 %
E) 10 % | <gadget id="calculator">2.4 * 4</gadget>
<output>9.6</output>
<result>E</result> | E | 10 | On the first of the year, James invested x dollars at Proudstar bank in an account that yields 2.4% in interest every quarter year. At the end of the year, during which he made no additional deposits or withdrawals, he had y dollars in the account. If James had invested the same amount in an account which pays interest on a yearly basis, what must the interest rate be for James to have y dollars at the end of the year? | {
"A": "2.04 %",
"B": "6.12 %",
"C": "8 %",
"D": "8.25 %",
"E": "10 %"
} | multiply(2.4, const_4) | multiply(n0,const_4)| | "if the interest were compounded annually instead of quarterly then in one year the interest would be 2.4 * 4 = 9.6 % . now , since the interest is compounded quarterly then there would be interest earned on interest ( very small amount ) thus the actual interest would be a little bit more than 9.6 % , answer : e" | gain |
math_qa__UrSV58QH37isMWUn | A can do a piece of work 60 days. B can do work in 20 days. In how many days they will complete the work together? Select
A) 12 days B) 16 days C) 15 days D) 17 days E) 18 days | <gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/60) + (1/20)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / (1/15)</gadget>
<output>15</output>
<result>C</result> | C | 15 | A can do a piece of work 60 days. B can do work in 20 days. In how many days they will complete the work together? | {
"A": "12 days",
"B": "16 days",
"C": "15 days",
"D": "17 days",
"E": "18 days"
} | divide(const_1, add(divide(const_1, 60), divide(const_1, 20))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)| | "lcm = 60 , ratio = 60 : 20 = 3 : 1 no of days = 60 / ( 3 + 1 ) = 90 / 4 = 15 days answer : c" | physics |
math_qa__lo1DmqqcNEqT6XvQ | If there are 10 apples and 20 oranges, what is the ratio of apples to oranges? Choose the most appropriate option: A) 10 : 20 B) 2 : 4 C) 1 : 2 D) 4 : 8 E) it can not be determined from the information given | <gadget id="calculator">10 / 20</gadget>
<output>1/2 = around 0.5</output>
<result>C</result> | C | 0.5 | If there are 10 apples and 20 oranges, what is the ratio of apples to oranges? | {
"A": "10 : 20",
"B": "2 : 4",
"C": "1 : 2",
"D": "4 : 8",
"E": "it can not be determined from the information given"
} | divide(10, 20) | divide(n0,n1) | a ratio should be reduced to the lowest common denominator . 10 : 20 means 10 x : 20 x which can be written as 1 ( 10 ) : 2 ( 10 ) . . . answer : c | other |
math_qa__m4ZCgnSZuQr9RYne | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.9500. If his salary for the month of May is Rs.6500, find his salary for the month of January?
Answers:
A) rs . 500 B) rs . 600 C) rs . 700 D) rs . 1500 E) rs . 2500 | <gadget id="calculator">8_000 * 4</gadget>
<output>32_000</output>
<gadget id="calculator">9_500 * 4</gadget>
<output>38_000</output>
<gadget id="calculator">38_000 - 6_500</gadget>
<output>31_500</output>
<gadget id="calculator">32_000 - 31_500</gadget>
<output>500</output>
<result>A</result> | A | 500 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.9500. If his salary for the month of May is Rs.6500, find his salary for the month of January? | {
"A": "rs . 500",
"B": "rs . 600",
"C": "rs . 700",
"D": "rs . 1500",
"E": "rs . 2500"
} | subtract(multiply(8000, const_4), subtract(multiply(9500, const_4), 6500)) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#1,n2)|subtract(#0,#2)| | "sum of the salaries of the person for the months of january , february , march and april = 4 * 8000 = 32000 - - - - ( 1 ) sum of the salaries of the person for the months of february , march , april and may = 4 * 9500 = 38000 - - - - ( 2 ) ( 2 ) - ( 1 ) i . e . may - jan = 6000 salary of may is rs . 6500 salary of january = rs . 500 answer : a" | general |
math_qa__0y1BrnLGdZXncWdT | Last week David spent 20 percent of his wages on recreation. This week, his wages are 30 percent less than last weekʼs wages and he spent 20 percent of his wages on recreation. The amount he spends on recreation this week is what percent of the amount he spent on recreation last week Choose the correct choice from the following answers.
A) 75 %
B) 72 %
C) 70 %
D) 73 %
E) 74 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(1/5) * (7/10)</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/50) / (1/5)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 100</gadget>
<output>70</output>
<result>C</result> | C | 70 | Last week David spent 20 percent of his wages on recreation. This week, his wages are 30 percent less than last weekʼs wages and he spent 20 percent of his wages on recreation. The amount he spends on recreation this week is what percent of the amount he spent on recreation last week | {
"A": "75 %",
"B": "72 %",
"C": "70 %",
"D": "73 %",
"E": "74 %"
} | multiply(divide(multiply(divide(20, const_100), subtract(const_1, divide(30, const_100))), divide(20, const_100)), const_100) | divide(n2,const_100)|divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#1)|multiply(#0,#3)|divide(#4,#2)|multiply(#5,const_100)| | "say david ' s wages last week were $ 100 , so he spent 0.20 * 100 = $ 20 on recreation ; this week ' s wages is 0.70 * 100 = $ 70 , so he spends 0.2 * 70 = $ 14 on recreation ; 14 / 20 = 0.70 , hence the amount he spends on recreation this week is 70 % of the amount he spent on recreation last week : 20 * 0.7 = 14 answer : c" | general |
math_qa__jX5nOXjbG62gb06k | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 180 votes. Find the total number of valid votes?
Choose one.
A) 450 B) 570 C) 480 D) 520 E) 550 | <gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">180 / (2/5)</gadget>
<output>450</output>
<result>A</result> | A | 450 | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 180 votes. Find the total number of valid votes? | {
"A": "450",
"B": "570",
"C": "480",
"D": "520",
"E": "550"
} | divide(180, divide(subtract(70, subtract(const_100, 70)), const_100)) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)| | "let the total number of valid votes be x . 70 % of x = 70 / 100 * x = 7 x / 10 number of votes secured by the other candidate = x - 7 x / 100 = 3 x / 10 given , 7 x / 10 - 3 x / 10 = 180 = > 4 x / 10 = 180 = > 4 x = 1800 = > x = 450 . answer : a" | gain |
math_qa__GGBOFC9TgbyYMImJ | In a can, there is a mixture of milk and water in the ratio 4:3. If the can is filled with an additional 10 liters of milk, the can would be full and the ratio of milk and water would become 5:2. Find the capacity of the can? Choose the correct option
A) 24
B) 26
C) 28
D) 30
E) 32 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">15 - 8</gadget>
<output>7</output>
<gadget id="calculator">20 / 7</gadget>
<output>20/7 = around 2.857143</output>
<gadget id="calculator">(20/7) * 4</gadget>
<output>80/7 = around 11.428571</output>
<gadget id="calculator">(80/7) + 10</gadget>
<output>150/7 = around 21.428571</output>
<gadget id="calculator">(20/7) * 3</gadget>
<output>60/7 = around 8.571429</output>
<gadget id="calculator">(150/7) + (60/7)</gadget>
<output>30</output>
<result>D</result> | D | 30 | In a can, there is a mixture of milk and water in the ratio 4:3. If the can is filled with an additional 10 liters of milk, the can would be full and the ratio of milk and water would become 5:2. Find the capacity of the can? | {
"A": "24",
"B": "26",
"C": "28",
"D": "30",
"E": "32"
} | add(add(multiply(divide(multiply(2, 10), subtract(multiply(3, 5), multiply(2, 4))), 4), 10), multiply(divide(multiply(2, 10), subtract(multiply(3, 5), multiply(2, 4))), 3)) | multiply(n2,n4)|multiply(n1,n3)|multiply(n0,n4)|subtract(#1,#2)|divide(#0,#3)|multiply(n0,#4)|multiply(n1,#4)|add(n2,#5)|add(#7,#6) | let c be the capacity of the can . ( 4 / 7 ) * ( c - 10 ) + 10 = ( 5 / 7 ) * c 4 c - 40 + 70 = 5 c c = 30 the answer is d . | general |
math_qa__5mgGC2p133CklBwV | A car runs at the speed of 55 km per hour when not serviced and runs at 90 kmph when serviced. After servicing the car covers a certain distance in 3 hours. How much time will the car take to cover the same distance when not serviced?
Choose the correct choice from the following answers:
A) 8 hours
B) 6 hours
C) 9 hours
D) 7 hours 12 minutes
E) none | <gadget id="calculator">90 / 2</gadget>
<output>45</output>
<gadget id="calculator">3 / 45</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">90 * (1/15)</gadget>
<output>6</output>
<result>B</result> | B | 6 | A car runs at the speed of 55 km per hour when not serviced and runs at 90 kmph when serviced. After servicing the car covers a certain distance in 3 hours. How much time will the car take to cover the same distance when not serviced? | {
"A": "8 hours",
"B": "6 hours",
"C": "9 hours",
"D": "7 hours 12 minutes",
"E": "none"
} | multiply(90, divide(const_3, divide(90, const_2))) | divide(n1,const_2)|divide(const_3,#0)|multiply(n1,#1) | explanation : time = 90 * 3 / 45 = 6 hours answer â € “ b | physics |
math_qa__17DI6SqQHf45R8nx | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 24 kmph, find the speed of the stream? Choose one
A) 18 kmph B) 6 kmph C) 8 kmph D) 10 kmph E) 12 kmph | <gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">48 / 3</gadget>
<output>16</output>
<gadget id="calculator">24 - 16</gadget>
<output>8</output>
<result>C</result> | C | 8 | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 24 kmph, find the speed of the stream? | {
"A": "18 kmph",
"B": "6 kmph",
"C": "8 kmph",
"D": "10 kmph",
"E": "12 kmph"
} | subtract(24, divide(multiply(24, const_2), const_3)) | multiply(n0,const_2)|divide(#0,const_3)|subtract(n0,#1)| | "the ratio of the times taken is 2 : 1 . the ratio of the speed of the boat in still water to the speed of the stream = ( 2 + 1 ) / ( 2 - 1 ) = 3 / 1 = 3 : 1 speed of the stream = 24 / 3 = 8 kmph . answer : c" | physics |
math_qa__DzUV8WqiqZWLTDZh | A began business with Rs.27000 and was joined afterwards by B with Rs.36000. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
Answers:
A) 1.5
B) 6.5
C) 7.5
D) 8
E) 2 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">27_000 * 12</gadget>
<output>324_000</output>
<gadget id="calculator">324_000 / 36_000</gadget>
<output>9</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">12 - (9/2)</gadget>
<output>15/2 = around 7.5</output>
<result>C</result> | C | 7.5 | A began business with Rs.27000 and was joined afterwards by B with Rs.36000. When did B join if the profits at the end of the year were divided in the ratio of 2:1? | {
"A": "1.5",
"B": "6.5",
"C": "7.5",
"D": "8",
"E": "2"
} | subtract(multiply(const_4, const_3), divide(divide(multiply(27000, multiply(const_4, const_3)), 36000), 2)) | multiply(const_3,const_4)|multiply(n0,#0)|divide(#1,n1)|divide(#2,n2)|subtract(#0,#3)| | "27 * 12 : 36 * x = 2 : 1 x = 4.5 12 - 4.5 = 7.5 answer : c" | other |
math_qa__xl1zuqgD7CBVh3fq | a certain kind of fuel is 1515 high octane and 4545 regular octane . if high octane costs 3 times as much as regular octane , what fraction of the cost of the fuel is due to the high octane ? Choose the correct choice from the following options:
A) 1 / 5 B) 2 / 3 C) 3 / 7 D) 3 / 5 E) 4 / 5 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<result>C</result> | C | 0.428571 | a certain kind of fuel is 1515 high octane and 4545 regular octane . if high octane costs 3 times as much as regular octane , what fraction of the cost of the fuel is due to the high octane ? | {
"A": "1 / 5",
"B": "2 / 3",
"C": "3 / 7",
"D": "3 / 5",
"E": "4 / 5"
} | divide(3, add(const_3, const_4)) | add(const_3,const_4)|divide(n2,#0) | let x be the amount of fuel high octane = x / 5 regular = 4 x / 5 price of regular = y price of high octante = 3 y cost of high octane in the fuel = 3 y * x / 5 total cost = 3 y * x / 5 + 4 x / 5 * y % = cost of high octante / total cost = 3 / 7 answer is c | general |
math_qa__JWOakLZrWWD4WUdC | 8 coins are tossed. Whats is the probability that one and only one turns up head ? Choose the correct choice from the following options.
A) 1 / 256
B) 1 / 32
C) 1 / 64
D) 1 / 128
E) 1 / 189 | <gadget id="calculator">2 ** 8</gadget>
<output>256</output>
<gadget id="calculator">8 / 256</gadget>
<output>1/32 = around 0.03125</output>
<result>B</result> | B | 0.03125 | 8 coins are tossed. Whats is the probability that one and only one turns up head ? | {
"A": "1 / 256",
"B": "1 / 32",
"C": "1 / 64",
"D": "1 / 128",
"E": "1 / 189"
} | divide(8, power(const_2, 8)) | power(const_2,n0)|divide(n0,#0) | explanation : possible outcomes ( sample space ) when 8 coins are tossed are : ( h , h , h , h , h , h , h , h ) , ( h , h , h , h , h , h , h , t ) , ( h , h , h , h , h , h , t , h ) , ( h , h , h , h , h , h , t , t ) , . . . . . . . ( t , t , t , t , t , t , t , t ) = 28 required outcomes : ( h , t , t , t , t , t , t , t ) , ( t , h , t , t , t , t , t , t ) , ( t , t , h , t , t , t , t , t ) , ( t , t , t , h , t , t , t , t ) , ( t , t , t , t , h , t , t , t ) , ( t , t , t , t , t , h , t , t ) , ( t , t , t , t , t , t , h , t ) , ( t , t , t , t , t , t , t , h ) = 8 so the required probability = 8 / 28 = 1 / 32 answer : b | probability |
math_qa__GeNdwj7gJ3fBylHR | A rectangular lawn of dimensions 110 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
Choices: A) s . 3988 B) s . 4800 C) s . 3228 D) s . 3922 E) s . 3928 | <gadget id="calculator">110 + 60</gadget>
<output>170</output>
<gadget id="calculator">170 - 10</gadget>
<output>160</output>
<gadget id="calculator">160 * 10</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 * 3</gadget>
<output>4_800</output>
<result>B</result> | B | 4,800 | A rectangular lawn of dimensions 110 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m? | {
"A": "s . 3988",
"B": "s . 4800",
"C": "s . 3228",
"D": "s . 3922",
"E": "s . 3928"
} | multiply(multiply(subtract(add(110, 60), 10), 10), 3) | add(n0,n1)|subtract(#0,n2)|multiply(n2,#1)|multiply(n3,#2)| | "area = ( l + b – d ) d ( 110 + 60 – 10 ) 10 = > 1600 m 2 1600 * 3 = rs . 4800 answer : b" | geometry |
math_qa__gxQH92HtXwdv6GR3 | If you multiply all the numbers on your mobile phone , what is the answer? Choose the correct choice from the following:
A) 2
B) 6
C) 1
D) 0
E) 7 | <gadget id="calculator">1 - 1</gadget>
<output>0</output>
<gadget id="calculator">1 * 0</gadget>
<output>0</output>
<result>D</result> | D | 0 | If you multiply all the numbers on your mobile phone , what is the answer? | {
"A": "2",
"B": "6",
"C": "1",
"D": "0",
"E": "7"
} | multiply(const_1, subtract(const_1, const_1)) | subtract(const_1,const_1)|multiply(#0,const_1) | d 0 their is a zero in your phone . | general |
math_qa__DOSo3B0XgmXUGyKq | If x is 20 percent greater than 12, then x = Choose the correct choice from the following options.
A) 10.2 B) 12.1 C) 8.1 D) 15.6 E) 14.4 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 12</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">12 + (12/5)</gadget>
<output>72/5 = around 14.4</output>
<result>E</result> | E | 14.4 | If x is 20 percent greater than 12, then x = | {
"A": "10.2",
"B": "12.1",
"C": "8.1",
"D": "15.6",
"E": "14.4"
} | add(12, multiply(divide(20, const_100), 12)) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)| | "x is 20 % greater than 12 means x is 1.2 times 12 ( in other words 12 + 20 / 100 * 12 = 1.2 * 12 ) therefore , x = 1.2 * 12 = 14.4 answer : e" | general |
math_qa__A6we5jzUZUGdk9EO | Find the probability in a group of 10 students sitting in a row , two of them
always sit next to each other Choose the correct choice from the following choices: A) 0.5 B) 0.4 C) 0.3 D) 0.2 E) 0.1 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">362_880 * 2</gadget>
<output>725_760</output>
<gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">725_760 / 3_628_800</gadget>
<output>1/5 = around 0.2</output>
<result>D</result> | D | 0.2 | Find the probability in a group of 10 students sitting in a row , two of them
always sit next to each other | {
"A": "0.5",
"B": "0.4",
"C": "0.3",
"D": "0.2",
"E": "0.1"
} | divide(multiply(factorial(subtract(10, const_1)), factorial(const_2)), factorial(10)) | factorial(const_2)|factorial(n0)|subtract(n0,const_1)|factorial(#2)|multiply(#3,#0)|divide(#4,#1) | assume that these 2 students are 1 and then u can sit is 9 ! and these 2 students can sit by 2 ways then total ways are 9 ! * 2 and the probability is 9 ! * 2 / 10 ! = 1 / 5 = 0.2 answer : d | other |
math_qa__Ovvi6kuqh1xwrb1p | A student got 74% in math and 81% in history. To get an overall average of 75%, how much should the student get in the third subject? Select the correct option
A) 66 %
B) 67 %
C) 68 %
D) 69 %
E) 70 % | <gadget id="calculator">3 * 75</gadget>
<output>225</output>
<gadget id="calculator">74 + 81</gadget>
<output>155</output>
<gadget id="calculator">225 - 155</gadget>
<output>70</output>
<result>E</result> | E | 70 | A student got 74% in math and 81% in history. To get an overall average of 75%, how much should the student get in the third subject? | {
"A": "66 %",
"B": "67 %",
"C": "68 %",
"D": "69 %",
"E": "70 %"
} | subtract(multiply(const_3, 75), add(74, 81)) | add(n0,n1)|multiply(n2,const_3)|subtract(#1,#0)| | "74 + 81 + x = 3 * 75 x = 70 the answer is e ." | general |
math_qa__gYRiGat4Xjjo89eq | A leak in the bottom of a tank can empty the full tank in 3 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold? Pick.
A) 7580
B) 7960
C) 8290
D) 1440
E) none | <gadget id="calculator">12 * 60</gadget>
<output>720</output>
<gadget id="calculator">6 * 720</gadget>
<output>4_320</output>
<gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">720 / 180</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">4_320 / 3</gadget>
<output>1_440</output>
<result>D</result> | D | 1,440 | A leak in the bottom of a tank can empty the full tank in 3 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold? | {
"A": "7580",
"B": "7960",
"C": "8290",
"D": "1440",
"E": "none"
} | divide(multiply(6, multiply(12, const_60)), subtract(divide(multiply(12, const_60), multiply(3, const_60)), const_1)) | multiply(n2,const_60)|multiply(n0,const_60)|divide(#0,#1)|multiply(n1,#0)|subtract(#2,const_1)|divide(#3,#4)| | "solution work done by the inlet in 1 hour = ( 1 / 3 - 1 / 12 ) = 1 / 4 work done by the inlet in 1 min . = ( 1 / 4 × 1 / 60 ) = 0.004167 volume of 0.004167 part = 6 litres . therefore , volume of whole = 0.004167 x 6 ‹ = › 1440 litres . answer d" | physics |
math_qa__YOhkikBQpdOr1iWT | Sam invested Rs. 12000 @ 10% per annum for one year. If the interest is compounded half-yearly, then the amount received by Sam at the end of the year will be? Pick one
A) 13230.0 B) 12300.02 C) 16537.5 D) 15000.0 E) 16537.11 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">(441/400) * 12_000</gadget>
<output>13_230</output>
<result>A</result> | A | 13,230 | Sam invested Rs. 12000 @ 10% per annum for one year. If the interest is compounded half-yearly, then the amount received by Sam at the end of the year will be? | {
"A": "13230.0",
"B": "12300.02",
"C": "16537.5",
"D": "15000.0",
"E": "16537.11"
} | multiply(power(add(divide(divide(10, const_2), const_100), const_1), const_2), 12000) | divide(n1,const_2)|divide(#0,const_100)|add(#1,const_1)|power(#2,const_2)|multiply(n0,#3)| | "p = rs . 12000 ; r = 10 % p . a . = 5 % per half - year ; t = 1 year = 2 half - year amount = [ 12000 * ( 1 + 5 / 100 ) 2 ] = ( 12000 * 21 / 20 * 21 / 20 ) = rs . 13230.00 answer : a" | gain |
math_qa__qmVcKvPh31vdjmsg | John bought a shirt on sale for 25% off the original price and another 25 % off the discounted price. If the final price was $18, what was the price before the first discount? Choose the correct choice from the following: A) $ 32 B) $ 34.31 C) $ 28.44 D) $ 67.54 E) $ 65.23 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 * 18</gadget>
<output>180_000</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 * 100</gadget>
<output>7_500</output>
<gadget id="calculator">75 * 25</gadget>
<output>1_875</output>
<gadget id="calculator">7_500 - 1_875</gadget>
<output>5_625</output>
<gadget id="calculator">180_000 / 5_625</gadget>
<output>32</output>
<result>A</result> | A | 32 | John bought a shirt on sale for 25% off the original price and another 25 % off the discounted price. If the final price was $18, what was the price before the first discount? | {
"A": "$ 32",
"B": "$ 34.31",
"C": "$ 28.44",
"D": "$ 67.54",
"E": "$ 65.23"
} | divide(multiply(multiply(const_100, const_100), 18), subtract(multiply(subtract(const_100, 25), const_100), multiply(subtract(const_100, 25), 25))) | multiply(const_100,const_100)|subtract(const_100,n0)|multiply(n2,#0)|multiply(#1,const_100)|multiply(n0,#1)|subtract(#3,#4)|divide(#2,#5) | let x be the price before the first discount . the price after the first discount is x - 25 % x ( price after first discount ) a second discount of 25 % of the discounted price after which the final price is 18 ( x - 25 % x ) - 25 % ( x - 25 % x ) = 18 solve for x x = $ 32 correct answer a | gain |
math_qa__X9k19bxBFSyw9fxn | The jogging track in a sports complex is 1000 meters in circumference. Deepak and his wife start from the same point and walk in opposite directions at 20 km/hr and 16 km/hr respectively. They will meet for the first time in? Answers:
A) 50 min
B) 40 min
C) 35 min
D) 25 min
E) 36 min | <gadget id="calculator">20 + 16</gadget>
<output>36</output>
<result>E</result> | E | 36 | The jogging track in a sports complex is 1000 meters in circumference. Deepak and his wife start from the same point and walk in opposite directions at 20 km/hr and 16 km/hr respectively. They will meet for the first time in? | {
"A": "50 min",
"B": "40 min",
"C": "35 min",
"D": "25 min",
"E": "36 min"
} | add(20, 16) | add(n1,n2)| | "clearly , the two will meet when they are 1000 m apart to be 20 + 16 = 36 km apart , they take 1 hour to be 1000 m apart , they take 36 * 1000 / 1000 = 36 min . answer is e" | general |
math_qa__i2VTtwGvTfaKmcbb | A cube of edge 5cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 10cm * 5cm , find the rise in water level? Choose the correct option:
A) 2.5 cm B) 3.6 cm C) 5 cm D) 6.43 cm E) 7.56 cm | <gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">125 / 50</gadget>
<output>5/2 = around 2.5</output>
<result>A</result> | A | 2.5 | A cube of edge 5cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 10cm * 5cm , find the rise in water level? | {
"A": "2.5 cm",
"B": "3.6 cm",
"C": "5 cm",
"D": "6.43 cm",
"E": "7.56 cm"
} | divide(volume_cube(5), multiply(10, 5)) | multiply(n1,n2)|volume_cube(n0)|divide(#1,#0)| | "increase in volume = volume of the cube = 5 * 5 * 5 cm ^ 3 rise in water level = volume / area = 5 * 5 * 5 / 10 * 5 = 2.5 cm answer is a" | geometry |
math_qa__hrXyLXRptz6sXd4H | Two brother X and Y appeared for an exam. The probability of selection of X is 1/3 and that of B is 2/5. Find the probability that both of them are selected. Choose the correct choice from the following options.
A) 2 / 69 B) 2 / 15 C) 2 / 63 D) 2 / 29 E) 2 / 10 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/3) * (2/5)</gadget>
<output>2/15 = around 0.133333</output>
<result>B</result> | B | 0.133333 | Two brother X and Y appeared for an exam. The probability of selection of X is 1/3 and that of B is 2/5. Find the probability that both of them are selected. | {
"A": "2 / 69",
"B": "2 / 15",
"C": "2 / 63",
"D": "2 / 29",
"E": "2 / 10"
} | multiply(divide(1, 3), divide(2, 5)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)| | "explanation : let a be the event that x is selected and b is the event that y is selected . p ( a ) = 1 / 3 , p ( b ) = 2 / 5 . let c be the event that both are selected . p ( c ) = p ( a ) ã — p ( b ) as a and b are independent events : = ( 1 / 3 ) ã — ( 2 / 5 ) = 2 / 15 answer : b ) 2 / 15" | general |
math_qa__5usELKakVY8pqtec | 4 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is? Options.
A) 18 : 19 B) 17 : 19 C) 15 : 19 D) 18 : 14 E) 18 : 11 | <gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">48 - 30</gadget>
<output>18</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">35 - 16</gadget>
<output>19</output>
<gadget id="calculator">18 / 19</gadget>
<output>18/19 = around 0.947368</output>
<result>A</result> | A | 0.947368 | 4 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is? | {
"A": "18 : 19",
"B": "17 : 19",
"C": "15 : 19",
"D": "18 : 14",
"E": "18 : 11"
} | divide(subtract(multiply(12, 4), multiply(6, 5)), subtract(multiply(7, 5), multiply(4, 4))) | multiply(n1,n2)|multiply(n5,n4)|multiply(n5,n3)|multiply(n0,n2)|subtract(#0,#1)|subtract(#2,#3)|divide(#4,#5)| | "4 m + 12 b - - - - - 4 days 7 m + 6 b - - - - - - - 5 days 16 m + 48 b = 35 m + 30 b 18 b = 19 m = > 5 m = 6 b m : b = 18 : 19 answer : a" | physics |
math_qa__j9ACMQowc6BoH4Sh | A boatman trying to cross the river.the width of the river is 400m.he is selling boat with 10m/sec.he takes 50sec to cross the river due to flow of water.calculate the drift. Choose the correct choice from the following answers: A) 500 B) 400 C) 300 D) 200 E) 100 | <gadget id="calculator">50 * 10</gadget>
<output>500</output>
<gadget id="calculator">500 ** 2</gadget>
<output>250_000</output>
<gadget id="calculator">400 ** 2</gadget>
<output>160_000</output>
<gadget id="calculator">250_000 - 160_000</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 ** (1/2)</gadget>
<output>300</output>
<result>C</result> | C | 300 | A boatman trying to cross the river.the width of the river is 400m.he is selling boat with 10m/sec.he takes 50sec to cross the river due to flow of water.calculate the drift. | {
"A": "500",
"B": "400",
"C": "300",
"D": "200",
"E": "100"
} | sqrt(subtract(power(multiply(50, 10), const_2), power(400, const_2))) | multiply(n1,n2)|power(n0,const_2)|power(#0,const_2)|subtract(#2,#1)|sqrt(#3) | the distance boatman travel to cross the river = 50 * 10 = 500 m he sell the boat diagonally . so height = 400 m , base be x and hypotenuse = 500 m so by pythagoras theorem , square of 400 + square of x = square of 500 so , square of x = 250000 - 160000 x = â ˆ š 250000 - 160000 , x = â ˆ š 90000 = 300 drift = 300 m answer c | physics |
math_qa__Ek1oqF1GXEMvDdtR | The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 60 ounces of this substance? Choices
A) 27 B) 36 C) 25 D) 64 E) 147 | <gadget id="calculator">48 / 112</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 60</gadget>
<output>180/7 = around 25.714286</output>
<result>C</result> | C | 25 | The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 60 ounces of this substance? | {
"A": "27",
"B": "36",
"C": "25",
"D": "64",
"E": "147"
} | multiply(divide(48, 112), 60) | divide(n0,n1)|multiply(n2,#0)| | "112 ounces of a substance has a volume of 48 cubic inches 60 ounces of a substance has a volume of ( 48 / 112 ) * 60 = 25 cubic inches answer a alternatively , we can use estimation 112 ounces of a substance has a volume of 48 cubic inches 56 ounces of a substance has a volume of 24 cubic inches therefore , 60 will have a volume a little more than 24 , that is 25 c" | geometry |
math_qa__GvDAsAbGwLHUIDTB | The average speed of a train is 87kmph. The train was scheduled to start at 9am in Bangalore, and as per schedule it has to reach a destination of 348km away from Bangalore at 1:45pm same day and a halt was scheduled onthe way. For how long was the halt scheduled? Choose the correct choice from the following options
A) 45 minutes B) 50 minutes C) 55 minutes D) 60 minutes E) none of these | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">1 + 12</gadget>
<output>13</output>
<gadget id="calculator">13 - 9</gadget>
<output>4</output>
<gadget id="calculator">4 * 60</gadget>
<output>240</output>
<gadget id="calculator">240 + 45</gadget>
<output>285</output>
<gadget id="calculator">348 / 87</gadget>
<output>4</output>
<gadget id="calculator">285 - 240</gadget>
<output>45</output>
<result>A</result> | A | 45 | The average speed of a train is 87kmph. The train was scheduled to start at 9am in Bangalore, and as per schedule it has to reach a destination of 348km away from Bangalore at 1:45pm same day and a halt was scheduled onthe way. For how long was the halt scheduled? | {
"A": "45 minutes",
"B": "50 minutes",
"C": "55 minutes",
"D": "60 minutes",
"E": "none of these"
} | subtract(add(multiply(subtract(add(1, multiply(add(const_4, const_2), const_2)), 9), const_60), 45), multiply(divide(348, 87), const_60)) | add(const_2,const_4)|divide(n2,n0)|multiply(#0,const_2)|multiply(#1,const_60)|add(n3,#2)|subtract(#4,n1)|multiply(#5,const_60)|add(n4,#6)|subtract(#7,#3) | speed of train = 87 kmph and distance it covers is 348 km . time taken to cover the distance = distance / speed = 348 / 87 = 4 hours . but total time taken by train to reach destination is = 1 : 45 pm – 9 a . m = 4 hours 45 minutes . time of halt = total time – take taken without halt = 4 hours 45 minutes – 4 hours = 45 minutes a ) | physics |
math_qa__5JeKqY4Y5ic1iNWf | The height of the wall is 4 times its width and length of the wall is 3 times its height .if the volume of the wall be 10368 cu.m.its width is Choose the correct choice from the following answers
A) 4 m
B) 5 m
C) 6 m
D) 7 m
E) 8 m | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">10_368 / 48</gadget>
<output>216</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">216 ** (1/3)</gadget>
<output>6</output>
<result>C</result> | C | 6 | The height of the wall is 4 times its width and length of the wall is 3 times its height .if the volume of the wall be 10368 cu.m.its width is | {
"A": "4 m",
"B": "5 m",
"C": "6 m",
"D": "7 m",
"E": "8 m"
} | power(divide(10368, multiply(multiply(4, 3), 4)), divide(const_1, const_3)) | divide(const_1,const_3)|multiply(n0,n1)|multiply(n0,#1)|divide(n2,#2)|power(#3,#0)| | "explanation : let width = x then , height = 4 x and length = 12 x 12 x ã — 4 x ã — x = 10368 x = 6 answer : c" | physics |
math_qa__yAbitGrRgkA5zVsS | A courtyard is 24 meter long and 14 meter board is to be paved with bricks of dimensions 25 cm by 15 cm. The total number of bricks required is : Choose the correct choice from the following answers:
A) 6000
B) 8000
C) 8960
D) 2000
E) none of these | <gadget id="calculator">24 * 100</gadget>
<output>2_400</output>
<gadget id="calculator">14 * 100</gadget>
<output>1_400</output>
<gadget id="calculator">2_400 * 1_400</gadget>
<output>3_360_000</output>
<gadget id="calculator">25 * 15</gadget>
<output>375</output>
<gadget id="calculator">3_360_000 / 375</gadget>
<output>8_960</output>
<result>C</result> | C | 8,960 | A courtyard is 24 meter long and 14 meter board is to be paved with bricks of dimensions 25 cm by 15 cm. The total number of bricks required is : | {
"A": "6000",
"B": "8000",
"C": "8960",
"D": "2000",
"E": "none of these"
} | divide(multiply(multiply(24, const_100), multiply(14, const_100)), multiply(25, 15)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,n3)|multiply(#0,#1)|divide(#3,#2)| | "explanation : number of bricks = courtyard area / 1 brick area = ( 2400 ã — 1400 / 25 ã — 15 ) = 8960 option c" | physics |
math_qa__XI7vFgC0eEIKIo7R | Rajan and Rakesh started a business and invested Rs. 20,000 and Rs. 25,000 respectively. After 4 months Rakesh left and Mukesh joined by investing Rs. 15,000. At the end of the year there was a profit of Rs. 4,600. What is the share of Rajan?
Choose the correct choice:
A) 2000 B) 2100 C) 2200 D) 2300 E) 2400 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">100 * 200</gadget>
<output>20_000</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">20_000 * 12</gadget>
<output>240_000</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">500 * 10</gadget>
<output>5_000</output>
<gadget id="calculator">20_000 + 5_000</gadget>
<output>25_000</output>
<gadget id="calculator">25_000 * 4</gadget>
<output>100_000</output>
<gadget id="calculator">240_000 + 100_000</gadget>
<output>340_000</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">5_000 + 10_000</gadget>
<output>15_000</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">15_000 * 8</gadget>
<output>120_000</output>
<gadget id="calculator">340_000 + 120_000</gadget>
<output>460_000</output>
<gadget id="calculator">240_000 / 460_000</gadget>
<output>12/23 = around 0.521739</output>
<gadget id="calculator">2 * 200</gadget>
<output>400</output>
<gadget id="calculator">5_000 - 400</gadget>
<output>4_600</output>
<gadget id="calculator">(12/23) * 4_600</gadget>
<output>2_400</output>
<result>E</result> | E | 2,400 | Rajan and Rakesh started a business and invested Rs. 20,000 and Rs. 25,000 respectively. After 4 months Rakesh left and Mukesh joined by investing Rs. 15,000. At the end of the year there was a profit of Rs. 4,600. What is the share of Rajan? | {
"A": "2000",
"B": "2100",
"C": "2200",
"D": "2300",
"E": "2400"
} | multiply(divide(multiply(multiply(const_100, multiply(multiply(add(const_2, const_3), const_4), multiply(add(const_2, const_3), const_2))), multiply(4, const_3)), add(add(multiply(multiply(const_100, multiply(multiply(add(const_2, const_3), const_4), multiply(add(const_2, const_3), const_2))), multiply(4, const_3)), multiply(add(multiply(const_100, multiply(multiply(add(const_2, const_3), const_4), multiply(add(const_2, const_3), const_2))), multiply(multiply(add(const_2, const_3), const_100), multiply(add(const_2, const_3), const_2))), 4)), multiply(add(multiply(multiply(add(const_2, const_3), const_100), multiply(add(const_2, const_3), const_2)), multiply(const_100, const_100)), add(4, 4)))), subtract(multiply(multiply(add(const_2, const_3), const_100), multiply(add(const_2, const_3), const_2)), multiply(const_2, multiply(multiply(add(const_2, const_3), const_4), multiply(add(const_2, const_3), const_2))))) | add(const_2,const_3)|add(n2,n2)|multiply(n2,const_3)|multiply(const_100,const_100)|multiply(#0,const_4)|multiply(#0,const_2)|multiply(#0,const_100)|multiply(#4,#5)|multiply(#6,#5)|add(#8,#3)|multiply(#7,const_100)|multiply(#7,const_2)|add(#10,#8)|multiply(#10,#2)|multiply(#9,#1)|subtract(#8,#11)|multiply(n2,#12)|add(#13,#16)|add(#17,#14)|divide(#13,#18)|multiply(#19,#15) | ratio of share of rajan , rakesh nd mukesh = > 20000 : 25000 : 15000 = > 4 : 5 : 3 = > 4 * 12 : 5 * 4 : 3 * 8 [ since rakesh left after 4 months nd mukesh joined after 4 months . . . ] = > 12 : 5 : 6 share of rajan = > 4600 * 12 / 23 = 2400 answer : e | gain |
math_qa__Xvcp0tsdPRsOEYyq | 20% of major airline companies equip their planes with wireless internet access. 70% of major airlines offer passengers free on-board snacks. What is the greatest possible percentage of major airline companies that offer both wireless internet and free on-board snacks?
Pick.
A) 20 %
B) 30 %
C) 40 %
D) 70 %
E) 90 % | <gadget id="calculator">20 * 1</gadget>
<output>20</output>
<result>A</result> | A | 20 | 20% of major airline companies equip their planes with wireless internet access. 70% of major airlines offer passengers free on-board snacks. What is the greatest possible percentage of major airline companies that offer both wireless internet and free on-board snacks? | {
"A": "20 %",
"B": "30 %",
"C": "40 %",
"D": "70 %",
"E": "90 %"
} | multiply(20, const_1) | multiply(n0,const_1) | to maximize the percentage of companies offering both , let ' s assume that all 20 % of companies which offer wireless internet also offer snacks . the answer is a . | general |
math_qa__mlPYFaUZ9Lyl8OHv | In how many seconds will a train 180 meters long pass an oak tree, if the speed of the train is 54 km/hr? Choose the most appropriate option:
A) 10 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 54</gadget>
<output>15</output>
<gadget id="calculator">180 / 15</gadget>
<output>12</output>
<result>B</result> | B | 12 | In how many seconds will a train 180 meters long pass an oak tree, if the speed of the train is 54 km/hr? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(180, multiply(const_0_2778, 54)) | multiply(n1,const_0_2778)|divide(n0,#0) | speed = 54 * 5 / 18 = 15 m / s time = 180 / 15 = 12 seconds the answer is b . | physics |
math_qa__tB1NsRaafRhEk9WO | If 20 typists can type 40 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour? Pick one: A) 63 B) 72 C) 144 D) 180 E) 400 | <gadget id="calculator">40 * 3</gadget>
<output>120</output>
<gadget id="calculator">120 / 20</gadget>
<output>6</output>
<gadget id="calculator">6 * 30</gadget>
<output>180</output>
<result>D</result> | D | 180 | If 20 typists can type 40 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour? | {
"A": "63",
"B": "72",
"C": "144",
"D": "180",
"E": "400"
} | multiply(divide(multiply(40, const_3), 20), 30) | multiply(n1,const_3)|divide(#0,n0)|multiply(n3,#1)| | "20 typists can type 40 letters , so 30 typists can type = 40 * 30 / 20 40 * 30 / 20 letters can be typed in 20 mins . in 60 mins typist can type = 40 * 30 * 60 / 20 * 20 = 180 d is the answer" | physics |
math_qa__NEOKQgILCPoyUyF0 | There are 4 people who has to cross a stretch of 300 km. They normally run at a speed of 10 kmph. One
of them has a bike that travels at 50 kmph. The bike first takes one person alone and crosses the
stretch while the other two keep running. Then he comes back without wasting time and picks up
another person from the way, drives him across the stretch, and does the same for the last person. How
long does this whole process take?
Pick:
A) 24 hrs B) 16 hrs C) 56 / 3 hrs D) 58 / 3 hrs E) 18 hrs | <gadget id="calculator">300 / 50</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">300 - 60</gadget>
<output>240</output>
<gadget id="calculator">50 + 10</gadget>
<output>60</output>
<gadget id="calculator">240 / 60</gadget>
<output>4</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 + 4</gadget>
<output>14</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">240 - 100</gadget>
<output>140</output>
<gadget id="calculator">300 - 140</gadget>
<output>160</output>
<gadget id="calculator">160 / 60</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">(8/3) + (8/3)</gadget>
<output>16/3 = around 5.333333</output>
<gadget id="calculator">14 + (16/3)</gadget>
<output>58/3 = around 19.333333</output>
<result>D</result> | D | 19.333333 | There are 4 people who has to cross a stretch of 300 km. They normally run at a speed of 10 kmph. One
of them has a bike that travels at 50 kmph. The bike first takes one person alone and crosses the
stretch while the other two keep running. Then he comes back without wasting time and picks up
another person from the way, drives him across the stretch, and does the same for the last person. How
long does this whole process take? | {
"A": "24 hrs",
"B": "16 hrs",
"C": "56 / 3 hrs",
"D": "58 / 3 hrs",
"E": "18 hrs"
} | add(add(add(divide(300, 50), divide(subtract(300, multiply(divide(300, 50), 10)), add(50, 10))), divide(subtract(300, multiply(divide(300, 50), 10)), add(50, 10))), add(divide(subtract(300, subtract(subtract(300, multiply(divide(300, 50), 10)), multiply(10, 10))), add(50, 10)), divide(subtract(300, subtract(subtract(300, multiply(divide(300, 50), 10)), multiply(10, 10))), add(50, 10)))) | add(n2,n3)|divide(n1,n3)|multiply(n2,n2)|multiply(n2,#1)|subtract(n1,#3)|divide(#4,#0)|subtract(#4,#2)|add(#1,#5)|subtract(n1,#6)|add(#7,#5)|divide(#8,#0)|add(#10,#10)|add(#9,#11) | expl : time taken to carry 2 nd person = 300 / 50 = 6 hrs . time taken to meet 3 rd person = ( 300 - 6 * 10 ) / ( 50 + 10 ) = 4 hrs time taken to carry 3 rd person = 4 hours time taken to meet 4 th person = ( 300 – 140 ) / 60 = 8 / 3 total time = 6 + 4 + 4 + 8 / 3 + 8 / 3 = 58 / 3 hours answer : d | physics |
math_qa__HbClZuYYtt0YFowT | A courtyard is 18 meter long and 12 meter board is to be paved with bricks of dimensions 15 cm by 13 cm. The total number of bricks required is : Answers: A) 16000 B) 18078 C) 11076 D) 11456 E) none of these | <gadget id="calculator">18 * 100</gadget>
<output>1_800</output>
<gadget id="calculator">12 * 100</gadget>
<output>1_200</output>
<gadget id="calculator">1_800 * 1_200</gadget>
<output>2_160_000</output>
<gadget id="calculator">15 * 13</gadget>
<output>195</output>
<gadget id="calculator">2_160_000 / 195</gadget>
<output>144_000/13 = around 11_076.923077</output>
<result>C</result> | C | 11,076 | A courtyard is 18 meter long and 12 meter board is to be paved with bricks of dimensions 15 cm by 13 cm. The total number of bricks required is : | {
"A": "16000",
"B": "18078",
"C": "11076",
"D": "11456",
"E": "none of these"
} | divide(multiply(multiply(18, const_100), multiply(12, const_100)), multiply(15, 13)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,n3)|multiply(#0,#1)|divide(#3,#2)| | "explanation : number of bricks = courtyard area / 1 brick area = ( 1800 ã — 1200 / 15 ã — 13 ) = 11076 option c" | physics |
math_qa__YFq4G9I9GoNMYskG | An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the ? Answers.
A) 8 : 6 B) 8 : 7 C) 8 : 1 D) 8 : 2 E) 8 : 4 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">24 / 21</gadget>
<output>8/7 = around 1.142857</output>
<result>B</result> | B | 1.142857 | An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the ? | {
"A": "8 : 6",
"B": "8 : 7",
"C": "8 : 1",
"D": "8 : 2",
"E": "8 : 4"
} | divide(multiply(multiply(3, 2), const_4), multiply(7, 3)) | multiply(n0,n1)|multiply(n0,n2)|multiply(#0,const_4)|divide(#2,#1)| | "let the length and breadth of the carpet in the first case be 3 x units and 2 x units respectively . let the dimensions of the carpet in the second case be 7 y , 3 y units respectively . from the data , . 2 ( 3 x + 2 x ) = 2 ( 7 y + 3 y ) = > 5 x = 10 y = > x = 2 y required ratio of the areas of the carpet in both the cases = 3 x * 2 x : 7 y : 3 y = 6 x 2 : 21 y 2 = 6 * ( 2 y ) 2 : 21 y 2 = 6 * 4 y 2 : 21 y 2 = 8 : 7 answer : b" | other |
math_qa__F9nJKSKTSzzzTDac | 80% of a number is added to 20, the result is the same number. Find the number? Choose the correct choice:
A) 300
B) 288
C) 270
D) 100
E) 281 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">20 / (1/5)</gadget>
<output>100</output>
<result>D</result> | D | 100 | 80% of a number is added to 20, the result is the same number. Find the number? | {
"A": "300",
"B": "288",
"C": "270",
"D": "100",
"E": "281"
} | divide(20, divide(20, const_100)) | divide(n1,const_100)|divide(n1,#0) | ( 80 / 100 ) * x + 20 = x 4 x + 100 = 5 x x = 100 answer : : d | gain |
math_qa__Muz43lpPwholjjeq | A dishonest dealer professes to sell goods at the cost price but uses a weight of 780 grams per kg, what is his percent? Choose the correct answer
A) 28 % B) 25 % C) 55 % D) 28 % E) 28.2 % | <gadget id="calculator">100 / 780</gadget>
<output>5/39 = around 0.128205</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">(5/39) * 1_000</gadget>
<output>5_000/39 = around 128.205128</output>
<gadget id="calculator">(5_000/39) - 100</gadget>
<output>1_100/39 = around 28.205128</output>
<result>E</result> | E | 28.2 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 780 grams per kg, what is his percent? | {
"A": "28 %",
"B": "25 %",
"C": "55 %",
"D": "28 %",
"E": "28.2 %"
} | subtract(multiply(divide(const_100, 780), multiply(const_100, multiply(add(const_3, const_2), const_2))), const_100) | add(const_2,const_3)|divide(const_100,n0)|multiply(#0,const_2)|multiply(#2,const_100)|multiply(#1,#3)|subtract(#4,const_100)| | "780 - - - 220 100 - - - ? = > 28.2 % answer : e" | gain |
math_qa__9BP1jXZGMXVAXny0 | Angelina walked 840 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym? Select the correct option:
A) 2 B) 3 C) 4 D) 16 E) 30 | <gadget id="calculator">480 / 2</gadget>
<output>240</output>
<gadget id="calculator">840 - 240</gadget>
<output>600</output>
<gadget id="calculator">600 / 40</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<result>E</result> | E | 30 | Angelina walked 840 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym? | {
"A": "2",
"B": "3",
"C": "4",
"D": "16",
"E": "30"
} | multiply(divide(subtract(840, divide(480, const_2)), 40), const_2) | divide(n1,const_2)|subtract(n0,#0)|divide(#1,n2)|multiply(#2,const_2)| | "let the speed be x . . . so time taken from home to grocery = 840 / x . . the speed to gym = 2 x . . so time taken = 480 / 2 x = 240 / x . . its given 840 / x - 240 / x = 40 . . 600 / x = 40 . . x = 15 m / secs . . so grocery to gym = 2 * 15 = 30 m / s . . . e" | physics |
math_qa__OY1hzsWFST2fm07z | David obtained 74, 65, 82, 67 and 90 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? Choose the correct choice from the following options
A) 87 B) 99 C) 68 D) 82 E) 76 | <gadget id="calculator">74 + 65</gadget>
<output>139</output>
<gadget id="calculator">139 + 82</gadget>
<output>221</output>
<gadget id="calculator">221 + 67</gadget>
<output>288</output>
<gadget id="calculator">288 + 90</gadget>
<output>378</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">378 / 5</gadget>
<output>378/5 = around 75.6</output>
<result>E</result> | E | 76 | David obtained 74, 65, 82, 67 and 90 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "87",
"B": "99",
"C": "68",
"D": "82",
"E": "76"
} | divide(add(add(add(add(74, 65), 82), 67), 90), add(const_2, const_3)) | add(n0,n1)|add(const_2,const_3)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "average = ( 74 + 65 + 82 + 67 + 90 ) / 5 = 380 / 5 = 76 . answer : e" | general |
math_qa__wIBw7VWPsNQPooI1 | John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase? Choose the correct choice from the following:
A) 16 % B) 16.66 % C) 17.8 % D) 18 % E) 19.5 % | <gadget id="calculator">70 - 60</gadget>
<output>10</output>
<gadget id="calculator">10 / 60</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 100</gadget>
<output>50/3 = around 16.666667</output>
<result>B</result> | B | 16.66 | John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase? | {
"A": "16 %",
"B": "16.66 %",
"C": "17.8 %",
"D": "18 %",
"E": "19.5 %"
} | multiply(divide(subtract(70, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 10 / 60 ) * 100 = ( 1 / 6 ) * 100 = 16.66 % . b" | gain |
math_qa__SZDsGdiWbE9c202Y | A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many E acres were used for corn? Choose the correct answer:
A) 188
B) 258
C) 376
D) 470
E) 517 | <gadget id="calculator">1_000 * 1</gadget>
<output>1_000</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">30 + 4</gadget>
<output>34</output>
<gadget id="calculator">1_000 + 34</gadget>
<output>1_034</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">1_034 / 11</gadget>
<output>94</output>
<gadget id="calculator">94 * 4</gadget>
<output>376</output>
<result>C</result> | C | 376 | A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many E acres were used for corn? | {
"A": "188",
"B": "258",
"C": "376",
"D": "470",
"E": "517"
} | multiply(divide(add(multiply(const_1000, const_1), add(multiply(const_10, const_3), 4)), add(add(5, 2), 4)), 4) | add(n1,n2)|multiply(const_10,const_3)|multiply(const_1,const_1000)|add(n3,#1)|add(n3,#0)|add(#3,#2)|divide(#5,#4)|multiply(n3,#6)| | "consider 5 x acres of land used for bean consider 2 x acres of land used for wheat consider 4 x acres of land used for corn total given is 1034 acres 11 x = 1034 x = 94 land used for corn e = 4 * 94 = 376 correct option - c" | other |
math_qa__fvL6QGORicFxsvU7 | Question: A sporting good store sells one type of baseball bat and one type of baseball. The cost for 2 bats and 4 balls is $180. The cost for 1 bat and 6 balls is $190, as well. If someone were to buy an equal number of bats and balls, at most how many bats can he purchase if he has a budget of $195 for the purchase?
Options: Choose the correct choice from the following choices
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">-2</gadget>
<output>-2</output>
<gadget id="calculator">(-2) * 190</gadget>
<output>-380</output>
<gadget id="calculator">180 + (-380)</gadget>
<output>-200</output>
<gadget id="calculator">(-2) * 6</gadget>
<output>-12</output>
<gadget id="calculator">4 + (-12)</gadget>
<output>-8</output>
<gadget id="calculator">(-200) / (-8)</gadget>
<output>25</output>
<gadget id="calculator">6 * 25</gadget>
<output>150</output>
<gadget id="calculator">190 - 150</gadget>
<output>40</output>
<gadget id="calculator">40 + 25</gadget>
<output>65</output>
<gadget id="calculator">195 / 65</gadget>
<output>3</output>
<result>C</result> | C | 3 | Question: A sporting good store sells one type of baseball bat and one type of baseball. The cost for 2 bats and 4 balls is $180. The cost for 1 bat and 6 balls is $190, as well. If someone were to buy an equal number of bats and balls, at most how many bats can he purchase if he has a budget of $195 for the purchase?
Options: | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(195, add(subtract(190, multiply(6, divide(add(180, multiply(negate(2), 190)), add(4, multiply(negate(2), 6))))), divide(add(180, multiply(negate(2), 190)), add(4, multiply(negate(2), 6))))) | negate(n0)|multiply(n5,#0)|multiply(n4,#0)|add(n2,#1)|add(n1,#2)|divide(#3,#4)|multiply(n4,#5)|subtract(n5,#6)|add(#5,#7)|divide(n6,#8) | imo it should be c that is c reason : formed an equation . . . bat = b ball = c 2 b + 4 c = 180 1 b + 6 c = 190 solving both we get b that is bat = 40 and c that is ball = 25 new equation 195 to be divided in equal 3 b + 3 c = 195 3 * 40 + 3 * 25 = 195 120 + 75 = 195 | geometry |
math_qa__Yn69POOFzuiQiCbe | Ramu bought an old car for Rs. 42000. He spent Rs. 8000 on repairs and sold it for Rs. 64900. What is his profit percent? Pick one:
A) 29.8 % B) 16 % C) 18 % D) 82 % E) 23 % | <gadget id="calculator">42_000 + 8_000</gadget>
<output>50_000</output>
<gadget id="calculator">64_900 - 50_000</gadget>
<output>14_900</output>
<gadget id="calculator">14_900 / 50_000</gadget>
<output>149/500 = around 0.298</output>
<gadget id="calculator">(149/500) * 100</gadget>
<output>149/5 = around 29.8</output>
<result>A</result> | A | 29.8 | Ramu bought an old car for Rs. 42000. He spent Rs. 8000 on repairs and sold it for Rs. 64900. What is his profit percent? | {
"A": "29.8 %",
"B": "16 %",
"C": "18 %",
"D": "82 %",
"E": "23 %"
} | multiply(divide(subtract(64900, add(42000, 8000)), add(42000, 8000)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "total cp = rs . 42000 + rs . 8000 = rs . 50000 and sp = rs . 64900 profit ( % ) = ( 64900 - 50000 ) / 50000 * 100 = 29.8 % answer : a" | gain |
math_qa__Q7s7RrZWLNUWSf08 | Machine P and Machine Q are each used to manufacture 990 sprockets. It takes Machine P 10 hours longer to produce 990 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce? Choose the most appropriate option
A) 5 B) 6 C) 7 D) 8 E) 9 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">990 / (11/10)</gadget>
<output>900</output>
<gadget id="calculator">990 - 900</gadget>
<output>90</output>
<gadget id="calculator">90 / 10</gadget>
<output>9</output>
<result>E</result> | E | 9 | Machine P and Machine Q are each used to manufacture 990 sprockets. It takes Machine P 10 hours longer to produce 990 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
} | divide(subtract(990, divide(990, add(divide(10, const_100), const_1))), 10) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|divide(#3,n1)| | "p makes x sprockets per hour . then q makes 1.1 x sprockets per hour . 990 / x = 990 / 1.1 x + 10 1.1 ( 990 ) = 990 + 11 x 11 x = 99 x = 9 the answer is e ." | gain |
math_qa__PQj0yOB7BAdCZReA | If the product of 2 integers is negative, at most how many of the integers can be negative? Answers:
A) 1
B) 3
C) 4
D) 5
E) 6 | <gadget id="calculator">2 - 1</gadget>
<output>1</output>
<result>A</result> | A | 1 | If the product of 2 integers is negative, at most how many of the integers can be negative? | {
"A": "1",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | subtract(2, const_1) | subtract(n0,const_1)| | "the product of 2 integers is negative thus an odd number of integers need to be negative to have a negative product we are asked at most how many are required . so , the highest odd integer before 6 , i . e . 1 correct option : a" | general |
math_qa__SvcIUV3nAiYoEqIJ | What will be the difference between simple and compound interest @ 10% per annum on the sum of Rs 1000 after 4 years Choices:
A) rs 62.10 B) rs 63.10 C) rs 64.10 D) rs 65.10 E) none of these | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 4</gadget>
<output>14_641/10_000 = around 1.4641</output>
<gadget id="calculator">1_000 * (14_641/10_000)</gadget>
<output>14_641/10 = around 1_464.1</output>
<gadget id="calculator">(14_641/10) - 1_000</gadget>
<output>4_641/10 = around 464.1</output>
<gadget id="calculator">1_000 * (1/10)</gadget>
<output>100</output>
<gadget id="calculator">100 * 4</gadget>
<output>400</output>
<gadget id="calculator">(4_641/10) - 400</gadget>
<output>641/10 = around 64.1</output>
<result>C</result> | C | 64.1 | What will be the difference between simple and compound interest @ 10% per annum on the sum of Rs 1000 after 4 years | {
"A": "rs 62.10",
"B": "rs 63.10",
"C": "rs 64.10",
"D": "rs 65.10",
"E": "none of these"
} | subtract(subtract(multiply(1000, power(add(divide(10, const_100), const_1), 4)), 1000), multiply(multiply(1000, divide(10, const_100)), 4)) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|multiply(n2,#2)|power(#1,n2)|multiply(n1,#4)|subtract(#5,n1)|subtract(#6,#3) | explanation : s . i . = 1000 ∗ 10 ∗ 4 / 100 = 400 c . i . = [ 1000 ( 1 + 10 / 100 ) 4 − 1000 ] = 464.10 so difference between simple interest and compound interest will be 464.10 - 400 = 64.10 option c | gain |
math_qa__6zXkpfVbsYlI0FWy | Find k if 16 / k = 4.
Select: A) 6 B) 7 C) 8 D) 4 E) 3 | <gadget id="calculator">16 / 4</gadget>
<output>4</output>
<result>D</result> | D | 4 | Find k if 16 / k = 4. | {
"A": "6",
"B": "7",
"C": "8",
"D": "4",
"E": "3"
} | divide(16, 4) | divide(n0,n1)| | "since 16 / k = 4 and 16 / 4 = 4 , then k = 4 correct answer d" | general |
math_qa__Utaoo9oW1qZNd5vh | The cost of the paint is rs.36.50 per kg. if 1kg of paint covers 16sq.ft, how much will it cost to paint outside of a cube having 8 feet each side Select:
A) rs . 962 B) rs . 672 C) rs . 546 D) rs . 876 E) none of these | <gadget id="calculator">6 * (8 ** 2)</gadget>
<output>384</output>
<gadget id="calculator">384 / 16</gadget>
<output>24</output>
<gadget id="calculator">24 * 36.5</gadget>
<output>876</output>
<result>D</result> | D | 876 | The cost of the paint is rs.36.50 per kg. if 1kg of paint covers 16sq.ft, how much will it cost to paint outside of a cube having 8 feet each side | {
"A": "rs . 962",
"B": "rs . 672",
"C": "rs . 546",
"D": "rs . 876",
"E": "none of these"
} | multiply(divide(surface_cube(8), 16), 36.50) | surface_cube(n3)|divide(#0,n2)|multiply(n0,#1)| | "explanation : surface area of a cube = 6 x 82 = 384 sq . ft quantity of paint required = ( 384 / 16 ) = 24 kg cost of painting = 36.5 x 24 = rs . 876 answer : d" | geometry |
math_qa__etf2bcq9UgcekeZz | In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.3 times as old as Robert? Choose the correct choice from the following answers.
A) 1960 B) 1965 C) 1970 D) 1975 E) 2040 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">1.3 + 7</gadget>
<output>8.3</output>
<gadget id="calculator">1_950 + 8.3</gadget>
<output>1_958.3</output>
<result>E</result> | E | 2,040 | In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.3 times as old as Robert? | {
"A": "1960",
"B": "1965",
"C": "1970",
"D": "1975",
"E": "2040"
} | add(1950, add(1.3, add(4, 3))) | add(n3,n1)|add(n4,#0)|add(n0,#1)| | "in 1950 : ri = 4 ro - - - - - - - - - - - - - - eq 1 in 1955 : ri + 5 = 3 ( ro + 5 ) - - - - - - - - - eq 2 thus in 1950 , solving eq 1 and eq 2 ro = 10 , ri = 40 now for each year we can calculate : 1960 : ri = 50 , ro = 20 1965 : ri = 55 , ro = 25 2040 : ri = 100 , ro = 130 thus ans : e" | general |
math_qa__f7XABr6QzoBX1w1v | The simple interest on a sum of money will be Rs.800 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? Choose the correct choice:
A) 8981 B) 3799 C) 1200 D) 1600 E) 1732 | <gadget id="calculator">800 / 10</gadget>
<output>80</output>
<gadget id="calculator">80 * 5</gadget>
<output>400</output>
<gadget id="calculator">400 * 3</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 + 400</gadget>
<output>1_600</output>
<result>D</result> | D | 1,600 | The simple interest on a sum of money will be Rs.800 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? | {
"A": "8981",
"B": "3799",
"C": "1200",
"D": "1600",
"E": "1732"
} | add(multiply(multiply(divide(800, 10), 5), const_3), multiply(divide(800, 10), 5)) | divide(n0,n1)|multiply(n2,#0)|multiply(#1,const_3)|add(#2,#1)| | "p - - - 10 - - - - 800 p - - - 5 - - - - - 400 3 p - - - 5 - - - - - 1200 - - - - - - = > 1600 answer : d" | general |
math_qa__dFjxT246NWHpMczs | A certain clock marks every hour by striking a number of times equal to the hour,and the time required for a stroke is exactly equal to the time interval between strokes. At 6:00 the time lapse between the beginning of the first stroke and the end of the last stroke is 66 seconds. at 12:00 ,how many seconds elapse between the beginning of the first stroke and the end of the last stroke?
Choose the correct option.
A) a . 138 B) b . 50 C) c . 48 D) d . 46 E) e . 44 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">66 / 11</gadget>
<output>6</output>
<gadget id="calculator">12 + 11</gadget>
<output>23</output>
<gadget id="calculator">6 * 23</gadget>
<output>138</output>
<result>A</result> | A | 138 | A certain clock marks every hour by striking a number of times equal to the hour,and the time required for a stroke is exactly equal to the time interval between strokes. At 6:00 the time lapse between the beginning of the first stroke and the end of the last stroke is 66 seconds. at 12:00 ,how many seconds elapse between the beginning of the first stroke and the end of the last stroke? | {
"A": "a . 138",
"B": "b . 50",
"C": "c . 48",
"D": "d . 46",
"E": "e . 44"
} | multiply(divide(66, add(6, add(const_1, const_4))), add(12, add(6, add(const_1, const_4)))) | add(const_1,const_4)|add(n0,#0)|add(n3,#1)|divide(n2,#1)|multiply(#2,#3)| | "at 6 : 00 it ' ll chime 6 times . if we assume that the time taken to chime is x , then time between chimes is also x . so you have 6 chimes , which is 6 x and 5 time intervals between chimes . this means that 11 x = 66 seconds . thus x = 6 seconds . by a similar logic , at 12 : 00 , there are 12 chimes and 11 intervals so the total time is ( 12 + 11 ) x = 23 x = 138 seconds . answer a" | general |
math_qa__SELTCmUUs5PtEW0i | In Lottery,there are 10 prizes and 25 blanks.A lottery is drawn at random.What is the Probability of getting a prize? Choose the correct answer:
A) 1 / 7
B) 2 / 7
C) 3 / 7
D) 4 / 7
E) 1 | <gadget id="calculator">10 + 25</gadget>
<output>35</output>
<gadget id="calculator">10 / 35</gadget>
<output>2/7 = around 0.285714</output>
<result>B</result> | B | 0.285714 | In Lottery,there are 10 prizes and 25 blanks.A lottery is drawn at random.What is the Probability of getting a prize? | {
"A": "1 / 7",
"B": "2 / 7",
"C": "3 / 7",
"D": "4 / 7",
"E": "1"
} | divide(10, add(10, 25)) | add(n0,n1)|divide(n0,#0) | total number of outcomes possible , n ( s ) = 10 + 25 = 35 . total number of prize , n ( e ) = 10 p ( e ) = n ( e ) / n ( s ) = 10 / 35 = 2 / 7 answer is option b | probability |
math_qa__a6pGuMsNRDoIppqe | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 30 percent. The enrollment on January 1, 1993, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ?
Choose the correct choice from the following:
A) 35 B) 39 C) 40 D) 41 E) 42 | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">100 / 130</gadget>
<output>10/13 = around 0.769231</output>
<gadget id="calculator">(10/13) * 45</gadget>
<output>450/13 = around 34.615385</output>
<result>A</result> | A | 35 | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 30 percent. The enrollment on January 1, 1993, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ? | {
"A": "35",
"B": "39",
"C": "40",
"D": "41",
"E": "42"
} | multiply(divide(const_100, add(const_100, 30)), 45) | add(n4,const_100)|divide(const_100,#0)|multiply(n7,#1)| | "1.30 x = 45 - - > 13 / 10 * x = 45 - - > x = 45 * 10 / 13 = 450 / 13 = ~ 35 . answer : a ." | gain |
math_qa__GRaGOzDN12A7d0iW | If $ 5,000 is invested in an account that earns 10% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest?
Choose the most appropriate option: A) $ 4 B) $ 8 C) $ 12 D) $ 16 E) $ 10 | <gadget id="calculator">10 * 1</gadget>
<output>10</output>
<result>E</result> | E | 10 | If $ 5,000 is invested in an account that earns 10% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest? | {
"A": "$ 4",
"B": "$ 8",
"C": "$ 12",
"D": "$ 16",
"E": "$ 10"
} | multiply(10, const_1) | multiply(n1,const_1) | solution amount ( ci ) = p + ( 1 + r / n ) ^ nt = 5000 + ( 1 + 0.10 / 2 ) ^ 2 = 5410 amount ( si ) = p + ptr / 100 = 5000 + ( 5000 * 1 * 10 / 100 ) = 5400 difference = 5410 - 5400 = 10 $ e | gain |
math_qa__CXq5QgeytLO70kgt | Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 35 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? Options:
A) 10 % B) 12 % C) 15 % D) 17 % E) 23 % | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(1/2) - (7/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (7/20)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(3/20) / (13/20)</gadget>
<output>3/13 = around 0.230769</output>
<gadget id="calculator">(3/13) * 100</gadget>
<output>300/13 = around 23.076923</output>
<result>E</result> | E | 23 | Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 35 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? | {
"A": "10 %",
"B": "12 %",
"C": "15 %",
"D": "17 %",
"E": "23 %"
} | multiply(divide(subtract(divide(50, const_100), divide(35, const_100)), subtract(const_1, divide(35, const_100))), const_100) | divide(n2,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(const_1,#1)|divide(#2,#3)|multiply(#4,const_100)| | "lets assume that candidate got 35 % votes and total votes is 100 . candidate won = 35 remaining = 65 to get 50 % , candidate requires 15 votes from 100 which is 15 % and 15 votes from 65 . 15 / 65 = 23.07 which is approx 23 % . hence the answer is e" | general |
math_qa__AcW3avu3LbrBAOYL | At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 28.9 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm? Choose the correct choice:
A) 16.2 B) 16.4 C) 16.6 D) 16.8 E) 17.0 | <gadget id="calculator">28.9 / 10</gadget>
<output>2.89</output>
<gadget id="calculator">2.89 ** (1/2)</gadget>
<output>1.7</output>
<gadget id="calculator">1.7 * 10</gadget>
<output>17</output>
<result>E</result> | E | 17 | At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 28.9 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm? | {
"A": "16.2",
"B": "16.4",
"C": "16.6",
"D": "16.8",
"E": "17.0"
} | multiply(sqrt(divide(28.9, 10.0)), 10.0) | divide(n5,n2)|sqrt(#0)|multiply(#1,n2)| | "let x be the factor by which the bacteria increases every three hours . at 4 : 00 pm , the amount of bacteria was 10 x and at 7 : 00 pm it was 10 x ^ 2 . 10 x ^ 2 = 28.9 x ^ 2 = 2.89 x = 1.7 at 4 : 00 pm , the amount of bacteria was 10 ( 1.7 ) = 17 grams . the answer is e ." | general |
math_qa__Cb6s66Ds3oheOEXj | rahul played weel in this season.his current batting averagge is 53.if he score 78 runs in today match.his batting average will become 58.how many matches had he played in this season. Choose the correct choice from the following choices
A) 4
B) 10
C) 9
D) 6
E) 5 | <gadget id="calculator">78 - 58</gadget>
<output>20</output>
<gadget id="calculator">58 - 53</gadget>
<output>5</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<result>A</result> | A | 4 | rahul played weel in this season.his current batting averagge is 53.if he score 78 runs in today match.his batting average will become 58.how many matches had he played in this season. | {
"A": "4",
"B": "10",
"C": "9",
"D": "6",
"E": "5"
} | divide(subtract(78, 58), subtract(58, 53)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "53 x + 78 = 58 ( x + 1 ) = > 5 x = 20 = > x = 4 answer : a" | general |
math_qa__xObAyuJO9G1gyx0M | The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
Choose the correct answer
A) 140 sq . units B) 158 sq . units C) 187 sq . units D) 607 sq . units E) 815 sq . units | <gadget id="calculator">1_225 ** (1/2)</gadget>
<output>35</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">35 / 5</gadget>
<output>7</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">10 * 14</gadget>
<output>140</output>
<result>A</result> | A | 140 | The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units? | {
"A": "140 sq . units",
"B": "158 sq . units",
"C": "187 sq . units",
"D": "607 sq . units",
"E": "815 sq . units"
} | multiply(10, multiply(const_2, divide(sqrt(1225), divide(const_10, const_2)))) | divide(const_10,const_2)|sqrt(n0)|divide(#1,#0)|multiply(#2,const_2)|multiply(n1,#3) | given that the area of the square = 1225 sq . units = > side of square = √ 1225 = 35 units the radius of the circle = side of the square = 35 units length of the rectangle = 2 / 5 * 35 = 14 units given that breadth = 10 units area of the rectangle = lb = 14 * 10 = 140 sq . units answer : a | geometry |
math_qa__P9IRfIcfFJ05ggl7 | 33 1/3% OF 390? Choose one
A) 80
B) 90
C) 110
D) 120
E) 130 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">33 + (1/3)</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) * 390</gadget>
<output>13_000</output>
<gadget id="calculator">13_000 / 100</gadget>
<output>130</output>
<result>E</result> | E | 130 | 33 1/3% OF 390? | {
"A": "80",
"B": "90",
"C": "110",
"D": "120",
"E": "130"
} | divide(multiply(add(33, divide(1, 3)), 390), const_100) | divide(n1,n2)|add(n0,#0)|multiply(n3,#1)|divide(#2,const_100)| | "33 1 / 3 % = 1 / 3 1 / 3 × 390 = 130 e )" | gain |
math_qa__PXt6mUfn8MnJm7mF | A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $186, how many hours overtime did he work? Choices:
A) 8 B) 5 C) 9 D) 6 E) 11 | <gadget id="calculator">3 * 40</gadget>
<output>120</output>
<gadget id="calculator">186 - 120</gadget>
<output>66</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">66 / 6</gadget>
<output>11</output>
<result>E</result> | E | 11 | A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $186, how many hours overtime did he work? | {
"A": "8",
"B": "5",
"C": "9",
"D": "6",
"E": "11"
} | divide(subtract(186, multiply(3, 40)), multiply(3, const_2)) | multiply(n0,n1)|multiply(n0,const_2)|subtract(n2,#0)|divide(#2,#1) | at $ 3 per hour up to 40 hours , regular pay = $ 3 x 40 = $ 120 if total pay = $ 168 , overtime pay = $ 186 - $ 120 = $ 66 overtime rate ( twice regular ) = 2 x $ 3 = $ 6 per hour = > number of overtime hours = $ 66 / $ 6 = 11 ans is e | physics |
math_qa__Je6RWw7kuwV2i4Oz | 6 workers should finish a job in 8 days. After 3 days came 4 workers join them. How many days C do they need to finish the same job? Choose the correct choice from the following answers: A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">48 - 18</gadget>
<output>30</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>A</result> | A | 3 | 6 workers should finish a job in 8 days. After 3 days came 4 workers join them. How many days C do they need to finish the same job? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(subtract(multiply(6, 8), multiply(3, 6)), add(6, 4)) | add(n0,n3)|multiply(n0,n1)|multiply(n0,n2)|subtract(#1,#2)|divide(#3,#0) | let rate of one worker be r = > ( 6 * r ) * 8 = 1 ( rate * time = work ) = > r = 1 / 48 = > work remaining after 3 days 1 - ( 3 * 6 ) / 48 = 30 / 48 after 4 ppl joined in ( ( 6 + 4 ) * time ) / 48 = 30 / 48 time c = 3 days to finish the task imo a | physics |
math_qa__fPrlGb4lB6SSQb5a | A man can row 9 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man? Choose the correct choice from the following answers:
A) 5.98 B) 9.98 C) 9.06 D) 9.87 E) 9.82 | <gadget id="calculator">9 + 1.2</gadget>
<output>10.2</output>
<gadget id="calculator">9 - 1.2</gadget>
<output>7.8</output>
<gadget id="calculator">10.2 * 7.8</gadget>
<output>79.56</output>
<gadget id="calculator">10.2 + 7.8</gadget>
<output>18</output>
<gadget id="calculator">79.56 / 18</gadget>
<output>4.42</output>
<gadget id="calculator">4.42 * 2</gadget>
<output>8.84</output>
<result>C</result> | C | 9.06 | A man can row 9 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man? | {
"A": "5.98",
"B": "9.98",
"C": "9.06",
"D": "9.87",
"E": "9.82"
} | multiply(divide(multiply(add(9, 1.2), subtract(9, 1.2)), add(add(9, 1.2), subtract(9, 1.2))), const_2) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|multiply(#0,#1)|divide(#3,#2)|multiply(#4,const_2)| | "m = 9 s = 1.2 ds = 7.2 us = 10.8 x / 10.8 + x / 7.8 = 1 x = 4.53 d = 4.53 * 2 = 9.06 answer : c" | physics |
math_qa__aolP0fH810vDNH8f | A type Q machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type Q machines and 3 type B machines working together and independently to complete the job? Select the correct option.
A) 1 / 5
B) 29 / 35
C) 5 / 6
D) 35 / 29
E) 35 / 12 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2 * (1/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3 * (2/5)</gadget>
<output>6/5 = around 1.2</output>
<result>D</result> | D | 1.206897 | A type Q machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type Q machines and 3 type B machines working together and independently to complete the job? | {
"A": "1 / 5",
"B": "29 / 35",
"C": "5 / 6",
"D": "35 / 29",
"E": "35 / 12"
} | multiply(3, multiply(const_2, divide(const_1, 5))) | divide(const_1,n0)|multiply(#0,const_2)|multiply(n3,#1) | now d should be the answer . q need 5 hours to complete and b needs 7 hours to compete so 2 q + 3 b will complete 2 / 5 + 3 / 7 or 29 / 35 portion of the job in 1 hour so the whole job will take 35 / 29 hours . . . . = d | physics |
math_qa__1SMNObgfzw75lEdG | A fellow borrowed a certain sum of money at 3% per annum at simple interest and in 3 years the interest amounted to Rs.1820 less than the sum lent. What was the sum lent? Choose one
A) 1050 B) 1220 C) 1250 D) 2000 E) 1110 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">1 - (9/100)</gadget>
<output>91/100 = around 0.91</output>
<gadget id="calculator">1_820 / (91/100)</gadget>
<output>2_000</output>
<result>D</result> | D | 2,000 | A fellow borrowed a certain sum of money at 3% per annum at simple interest and in 3 years the interest amounted to Rs.1820 less than the sum lent. What was the sum lent? | {
"A": "1050",
"B": "1220",
"C": "1250",
"D": "2000",
"E": "1110"
} | divide(1820, subtract(const_1, divide(multiply(3, 3), const_100))) | multiply(n0,n0)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)| | "p - 1820 = ( p * 3 * 3 ) / 100 p = 2000 answer : d" | gain |
math_qa__mLmhdwyxeoYpBzDX | A sum amounts to Rs.3969 in 2 years at the rate of 5% p.a. If interest was compounded yearly then what was the principal? Choose the correct choice from the following answers:
A) s . 3600 B) s . 5000 C) s . 4500 D) s . 4800 E) s . 5800 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">3_969 / (441/400)</gadget>
<output>3_600</output>
<result>A</result> | A | 3,600 | A sum amounts to Rs.3969 in 2 years at the rate of 5% p.a. If interest was compounded yearly then what was the principal? | {
"A": "s . 3600",
"B": "s . 5000",
"C": "s . 4500",
"D": "s . 4800",
"E": "s . 5800"
} | divide(3969, power(add(divide(5, const_100), const_1), 2)) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|divide(n0,#2)| | "ci = 3969 , r = 5 , n = 2 ci = p [ 1 + r / 100 ] ^ 2 = p [ 1 + 5 / 100 ] ^ 2 3969 = p [ 21 / 20 ] ^ 2 3969 [ 20 / 21 ] ^ 2 3600 answer : a" | gain |
math_qa__hqjEeM1Q41tgOU7A | A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party R. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)? Choices.
A) 15 B) 20 C) 30 D) 35 E) 45 | <gadget id="calculator">35 + 20</gadget>
<output>55</output>
<gadget id="calculator">100 - 55</gadget>
<output>45</output>
<gadget id="calculator">45 / 3</gadget>
<output>15</output>
<result>A</result> | A | 15 | A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party R. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)? | {
"A": "15",
"B": "20",
"C": "30",
"D": "35",
"E": "45"
} | divide(subtract(const_100, add(35, 20)), const_3) | add(n0,n1)|subtract(const_100,#0)|divide(#1,const_3)| | "s = 100 not ( r and b ) = 35 only r = 20 ( r and b ) / b = 1 / 2 let ( r and b ) = x only b = 2 x so now , 20 + 35 + x + 2 x = 100 x = 15 a ans" | gain |
math_qa__5exMivXkuUrKiK1i | How many pieces of 85 cm length can be cut from a rod of 38.25 meters long? Pick one:
A) 25 B) 35 C) 45 D) 55 E) 65 | <gadget id="calculator">38.25 * 100</gadget>
<output>3_825</output>
<gadget id="calculator">3_825 / 85</gadget>
<output>45</output>
<result>C</result> | C | 45 | How many pieces of 85 cm length can be cut from a rod of 38.25 meters long? | {
"A": "25",
"B": "35",
"C": "45",
"D": "55",
"E": "65"
} | divide(multiply(38.25, const_100), 85) | multiply(n1,const_100)|divide(#0,n0)| | "number of pieces = 3825 / 85 = 45 the answer is c ." | physics |
math_qa__JBeFePUEBCwGsmhG | Gretzky Street begins at Orr Street and runs directly east for 5.6 kilometers until it ends when it meets Howe Street. Gretzky Street is intersected every 350 meters by a perpendicular street, and each of those streets other than Orr Street and Howe Street is given a number beginning at 1st Street (one block east of Orr Street) and continuing consecutively (2nd Street, 3rd Street, etc...) until the highest-numbered street one block west of Howe Street. What is the highest-numbered street that intersects Gretzky Street? Choose the correct choice from the following answers.
A) 12 th B) 13 th C) 14 th D) 15 th E) 16 th | <gadget id="calculator">5.6 * 1_000</gadget>
<output>5_600</output>
<gadget id="calculator">5_600 / 350</gadget>
<output>16</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<result>D</result> | D | 15 | Gretzky Street begins at Orr Street and runs directly east for 5.6 kilometers until it ends when it meets Howe Street. Gretzky Street is intersected every 350 meters by a perpendicular street, and each of those streets other than Orr Street and Howe Street is given a number beginning at 1st Street (one block east of Orr Street) and continuing consecutively (2nd Street, 3rd Street, etc...) until the highest-numbered street one block west of Howe Street. What is the highest-numbered street that intersects Gretzky Street? | {
"A": "12 th",
"B": "13 th",
"C": "14 th",
"D": "15 th",
"E": "16 th"
} | subtract(divide(multiply(5.6, const_1000), 350), const_1) | multiply(n0,const_1000)|divide(#0,n1)|subtract(#1,const_1) | 5.6 km / 350 m = 16 . however , the street at the 5.6 - km mark is not 16 th street ; it is howe street . therefore , the highest numbered street is 15 th street . the answer is d . | physics |
math_qa__xjMT8x1Tj7y05W3U | The average weight of 19 students is 15kg. by the admission of a new student the average weight is reduced to 14.9 kg. the weight of the new student is ?
Choose the most appropriate option
A) 10.6 kg
B) 10.8 kg
C) 11 kg
D) 13 kg
E) none | <gadget id="calculator">19 + 1</gadget>
<output>20</output>
<gadget id="calculator">20 * 14.9</gadget>
<output>298</output>
<gadget id="calculator">19 * 15</gadget>
<output>285</output>
<gadget id="calculator">298 - 285</gadget>
<output>13</output>
<result>D</result> | D | 13 | The average weight of 19 students is 15kg. by the admission of a new student the average weight is reduced to 14.9 kg. the weight of the new student is ? | {
"A": "10.6 kg",
"B": "10.8 kg",
"C": "11 kg",
"D": "13 kg",
"E": "none"
} | subtract(multiply(add(19, const_1), 14.9), multiply(19, 15)) | add(n0,const_1)|multiply(n0,n1)|multiply(n2,#0)|subtract(#2,#1)| | "answer weight of new student = total weight of all 20 students - total weight of initial 19 students = ( 20 x 14.9 - 19 x 15 ) kg = 13 kg . correct option : d" | general |
math_qa__fLnrQ20EZjhIoiFj | The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ? Select:
A) 4
B) 8
C) 16
D) 12
E) 14 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">21 - 10</gadget>
<output>11</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">36 / 9</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 + 8</gadget>
<output>12</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<result>B</result> | B | 8 | The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2 ? | {
"A": "4",
"B": "8",
"C": "16",
"D": "12",
"E": "14"
} | subtract(add(divide(36, subtract(subtract(add(multiply(2, const_10), 1), const_10), 2)), multiply(divide(36, subtract(subtract(add(multiply(2, const_10), 1), const_10), 2)), 2)), subtract(multiply(divide(36, subtract(subtract(add(multiply(2, const_10), 1), const_10), 2)), 2), divide(36, subtract(subtract(add(multiply(2, const_10), 1), const_10), 2)))) | multiply(n2,const_10)|add(n1,#0)|subtract(#1,const_10)|subtract(#2,n2)|divide(n0,#3)|multiply(n2,#4)|add(#4,#5)|subtract(#5,#4)|subtract(#6,#7)| | "since the number is greater than the number obtained on reversing the digits , so the ten ' s digit is greater than the unit ' s digit . let ten ' s and unit ' s digits be 2 x and x respectively . then , ( 10 x 2 x + x ) - ( 10 x + 2 x ) = 36 9 x = 36 x = 4 . required difference = ( 2 x + x ) - ( 2 x - x ) = 2 x = 8 . answer : b" | general |
math_qa__hECBUGElUu9ck5sn | Excluding stoppages, the average speed of a bus is 80 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour? Select: A) 15 min B) 18 min C) 16 min D) 20 min E) 30 min | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">40 / 80</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 60</gadget>
<output>30</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<result>E</result> | E | 30 | Excluding stoppages, the average speed of a bus is 80 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour? | {
"A": "15 min",
"B": "18 min",
"C": "16 min",
"D": "20 min",
"E": "30 min"
} | subtract(multiply(const_1, const_60), multiply(divide(40, 80), const_60)) | divide(n1,n0)|multiply(const_1,const_60)|multiply(#0,const_60)|subtract(#1,#2)| | "in 1 hr , the bus covers 80 km without stoppages and 40 km with stoppages . stoppage time = time take to travel ( 80 - 40 ) km i . e 40 km at 80 km / hr . stoppage time = 40 / 80 hrs = 30 min answer : e" | general |
math_qa__j9T4E6nqmaEDKjR3 | By selling an article for $110, a person gains $10. What is the gain %?
Choose the correct choice from the following answers.
A) 25 %
B) 30 %
C) 50 %
D) 20 %
E) 10 % | <gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">110 - 10</gadget>
<output>100</output>
<gadget id="calculator">1_000 / 100</gadget>
<output>10</output>
<result>E</result> | E | 10 | By selling an article for $110, a person gains $10. What is the gain %? | {
"A": "25 %",
"B": "30 %",
"C": "50 %",
"D": "20 %",
"E": "10 %"
} | divide(multiply(10, const_100), subtract(110, 10)) | multiply(n1,const_100)|subtract(n0,n1)|divide(#0,#1)| | "s . p . = $ 110 gain = $ 10 c . p . = 110 - 10 = 100 gain % = 10 / 100 * 100 % = 10 % answer is e" | gain |
math_qa__OpamA29xHPAnGGNz | Tough and Tricky questions: Functions. Let a be a positive integer. Let n#a equal n^(2a) if a is odd and n^(3a) if a is even. Then (4#3) + (3#4) – (3#3) is equal to Choices
A) 64 B) 82 C) 128 D) 512 E) 4096 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">4 ** 6</gadget>
<output>4_096</output>
<result>E</result> | E | 4,096 | Tough and Tricky questions: Functions. Let a be a positive integer. Let n#a equal n^(2a) if a is odd and n^(3a) if a is even. Then (4#3) + (3#4) – (3#3) is equal to | {
"A": "64",
"B": "82",
"C": "128",
"D": "512",
"E": "4096"
} | power(4, multiply(2, 3)) | multiply(n0,n1)|power(n2,#0) | answer : 4 ^ 6 + 3 ^ 6 - 3 ^ 6 = 4 ^ 6 = 4096 ans e | general |
math_qa__u9iwOkIriAL1OcTR | Find the smallest number of 6 digits which is exactly divisible by 111.
Choose the correct choice
A) 100011 B) 111111 C) 101111 D) 201111 E) 211111 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">10 * 10_000</gadget>
<output>100_000</output>
<gadget id="calculator">100_000 - 100</gadget>
<output>99_900</output>
<gadget id="calculator">99_900 + 111</gadget>
<output>100_011</output>
<result>A</result> | A | 100,011 | Find the smallest number of 6 digits which is exactly divisible by 111. | {
"A": "100011",
"B": "111111",
"C": "101111",
"D": "201111",
"E": "211111"
} | add(subtract(multiply(const_10, multiply(const_100, const_100)), const_100), 111) | multiply(const_100,const_100)|multiply(#0,const_10)|subtract(#1,const_100)|add(n1,#2) | smallest number of 6 digits is 100000 . on dividing 100000 by 111 , we get 100 as remainder . number to be added = ( 111 - 100 ) - 11 . hence , required number = 100011 option a | general |
math_qa__3Fz6Tm8C9NijfD2W | Two stations A and B are 20 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Choose the correct answer
A) 9 B) 10 C) 11 D) 12 E) 8 | <gadget id="calculator">20 - 20</gadget>
<output>0</output>
<gadget id="calculator">25 + 20</gadget>
<output>45</output>
<gadget id="calculator">0 / 45</gadget>
<output>0</output>
<gadget id="calculator">8 + 0</gadget>
<output>8</output>
<result>E</result> | E | 8 | Two stations A and B are 20 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "8"
} | add(8, divide(subtract(20, 20), add(25, 20))) | add(n2,n4)|subtract(n0,n2)|divide(#1,#0)|add(n3,#2)| | "suppose they meet x hours after 7 a . m . distance covered by a in x hours = 20 x km . distance covered by b in ( x - 1 ) hours = 25 ( x - 1 ) km . therefore 20 x + 25 ( x - 1 ) = 20 45 x = 45 x = 1 . so , they meet at 8 a . m . answer : option e" | physics |
math_qa__RBhFfKDz5iZ9i8ZG | A crate measures 2 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate? Choose one
A) 2
B) 4
C) 6
D) 8
E) 12 | <gadget id="calculator">8 * 12</gadget>
<output>96</output>
<gadget id="calculator">96 * 2</gadget>
<output>192</output>
<gadget id="calculator">192 / 12</gadget>
<output>16</output>
<gadget id="calculator">16 / 8</gadget>
<output>2</output>
<result>A</result> | A | 2 | A crate measures 2 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "12"
} | divide(divide(multiply(multiply(8, 12), 2), 12), 8) | multiply(n1,n2)|multiply(n0,#0)|divide(#1,n2)|divide(#2,n1)| | "we can find the radius of all the three cases of cylinders . the only crux to find the answer faster is that : voulme is pi * r ^ 2 * h . the volume is a function of r ^ 2 . so r has to be the highest to find the largest volume . so r = 2 for the surface 8 * 12 face . volume = 8 pi answer a" | geometry |
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