id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__YErOOhWQfgOKfF6r | The average of marks obtained by 120 boys was 36. If the average of marks of passed boys was 39 and that of failed boys was 15, the number of boys who passed the examination is? Choose the correct answer:
A) 105
B) 110
C) 120
D) 130
E) 140 | <gadget id="calculator">36 * 120</gadget>
<output>4_320</output>
<gadget id="calculator">120 * 15</gadget>
<output>1_800</output>
<gadget id="calculator">4_320 - 1_800</gadget>
<output>2_520</output>
<gadget id="calculator">39 - 15</gadget>
<output>24</output>
<gadget id="calculator">2_520 / 24</gadget>
<output>105</output>
<result>A</result> | A | 105 | The average of marks obtained by 120 boys was 36. If the average of marks of passed boys was 39 and that of failed boys was 15, the number of boys who passed the examination is? | {
"A": "105",
"B": "110",
"C": "120",
"D": "130",
"E": "140"
} | divide(subtract(multiply(36, 120), multiply(120, 15)), subtract(39, 15)) | multiply(n0,n1)|multiply(n0,n3)|subtract(n2,n3)|subtract(#0,#1)|divide(#3,#2)| | "let the number of boys who passed = x . then , 39 x x + 15 x ( 120 - x ) = 120 x 36 24 x = 4320 - 1800 = > x = 2520 / 24 x = 105 . hence , the number of boys passed = 105 . answer : a" | general |
math_qa__0m5ZTnQ9VQB0qNOU | Shekar scored 76, 65, 82, 62 and 85 marks in Mathematics, Science, Social studies, English and Biology respectively. What are his average marks? Choices:
A) 74
B) 69
C) 75
D) 85
E) 90 | <gadget id="calculator">76 + 65</gadget>
<output>141</output>
<gadget id="calculator">141 + 82</gadget>
<output>223</output>
<gadget id="calculator">223 + 62</gadget>
<output>285</output>
<gadget id="calculator">285 + 85</gadget>
<output>370</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">370 / 5</gadget>
<output>74</output>
<result>A</result> | A | 74 | Shekar scored 76, 65, 82, 62 and 85 marks in Mathematics, Science, Social studies, English and Biology respectively. What are his average marks? | {
"A": "74",
"B": "69",
"C": "75",
"D": "85",
"E": "90"
} | divide(add(add(add(add(76, 65), 82), 62), 85), add(const_1, const_4)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "explanation : average = ( 76 + 65 + 82 + 62 + 85 ) / 5 = 370 / 5 = 74 hence average = 74 answer : a" | general |
math_qa__G9yO98CohemoxWbu | A rectangular plot measuring 10 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed? Choose the most appropriate option
A) 46 m
B) 66 m
C) 26 m
D) 24 m
E) 25 m | <gadget id="calculator">10 + 50</gadget>
<output>60</output>
<gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">120 / 5</gadget>
<output>24</output>
<result>D</result> | D | 24 | A rectangular plot measuring 10 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed? | {
"A": "46 m",
"B": "66 m",
"C": "26 m",
"D": "24 m",
"E": "25 m"
} | divide(multiply(add(10, 50), const_2), 5) | add(n0,n1)|multiply(#0,const_2)|divide(#1,n2)| | "perimeter of the plot = 2 ( 10 + 50 ) = 120 m no of poles = 120 / 5 = 24 m answer : d" | physics |
math_qa__28LmlmtHtzr73W9q | X can finish a work in 21 days. Y can finish the same work in 15 days. Y worked for 5 days and left the job. how many days does X alone need to finish the remaining work? Choose the correct choice from the following choices: A) 12 B) 13 C) 16 D) 14 E) 18 | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">5 * (1/15)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 21</gadget>
<output>1/21 = around 0.047619</output>
<gadget id="calculator">(2/3) / (1/21)</gadget>
<output>14</output>
<result>D</result> | D | 14 | X can finish a work in 21 days. Y can finish the same work in 15 days. Y worked for 5 days and left the job. how many days does X alone need to finish the remaining work? | {
"A": "12",
"B": "13",
"C": "16",
"D": "14",
"E": "18"
} | divide(subtract(const_1, multiply(5, divide(const_1, 15))), divide(const_1, 21)) | divide(const_1,n1)|divide(const_1,n0)|multiply(n2,#0)|subtract(const_1,#2)|divide(#3,#1)| | "work done by x in 1 day = 1 / 21 work done by y in 1 day = 1 / 15 work done by y in 5 days = 5 / 15 = 1 / 3 remaining work = 1 – 1 / 3 = 2 / 3 number of days in which x can finish the remaining work = ( 2 / 3 ) / ( 1 / 21 ) = 14 d" | physics |
math_qa__YWJs8Y89JTrfoKRV | P is able to do a piece of work in 20 days and Q can do the same work in 10 days. If they can work together for 2 days, what is the fraction of work left? Choose the correct choice from the following options:
A) 5 / 10 B) 9 / 10 C) 7 / 10 D) 6 / 10 E) 4 / 10 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/10) + (1/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 2</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<result>C</result> | C | 0.7 | P is able to do a piece of work in 20 days and Q can do the same work in 10 days. If they can work together for 2 days, what is the fraction of work left? | {
"A": "5 / 10",
"B": "9 / 10",
"C": "7 / 10",
"D": "6 / 10",
"E": "4 / 10"
} | subtract(const_1, multiply(add(divide(const_1, 10), divide(const_1, 20)), 2)) | divide(const_1,n1)|divide(const_1,n0)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)| | "explanation : amount of work p can do in 1 day = 1 / 20 amount of work q can do in 1 day = 1 / 10 amount of work p and q can do in 1 day = 1 / 20 + 1 / 10 = 3 / 20 amount of work p and q can together do in 2 days = 2 × ( 3 / 20 ) = 3 / 10 fraction of work left = 1 – 3 / 10 = 7 / 10 answer : option c" | physics |
math_qa__LW7cJsOCkFtzuivK | Carina has 70 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have? Pick:
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">70 - 10</gadget>
<output>60</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">60 / 15</gadget>
<output>4</output>
<result>C</result> | C | 4 | Carina has 70 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(subtract(70, multiply(5, 2)), add(10, 5)) | add(n1,n2)|multiply(n1,n3)|subtract(n0,#1)|divide(#2,#0)| | "lets say 5 and 10 ounce packages be x and y respectively . given that , 5 x + 10 y = 70 and x = y + 2 . what is the value of y . substituting the x in first equation , 5 y + 10 + 10 y = 70 - > y = 60 / 15 . = 4 c" | general |
math_qa__aEnW5ukNVsuNxEzw | The average weight of A, B and C is 45 kg. If the average weight of A and B be 42 kg and that of B and C be 43 kg, then the weight of B is: Select the correct option
A) 33 kg B) 31 kg C) 32 kg D) 36 kg E) 35 kg | <gadget id="calculator">42 * 2</gadget>
<output>84</output>
<gadget id="calculator">43 * 2</gadget>
<output>86</output>
<gadget id="calculator">84 + 86</gadget>
<output>170</output>
<gadget id="calculator">45 * 3</gadget>
<output>135</output>
<gadget id="calculator">170 - 135</gadget>
<output>35</output>
<result>E</result> | E | 35 | The average weight of A, B and C is 45 kg. If the average weight of A and B be 42 kg and that of B and C be 43 kg, then the weight of B is: | {
"A": "33 kg",
"B": "31 kg",
"C": "32 kg",
"D": "36 kg",
"E": "35 kg"
} | subtract(add(multiply(42, const_2), multiply(43, const_2)), multiply(45, const_3)) | multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,const_3)|add(#0,#1)|subtract(#3,#2)| | "let a , b , c represent their respective weights . then , we have : a + b + c = ( 45 x 3 ) = 135 . . . . ( i ) a + b = ( 42 x 2 ) = 84 . . . . ( ii ) b + c = ( 43 x 2 ) = 86 . . . . ( iii ) adding ( ii ) and ( iii ) , we get : a + 2 b + c = 170 . . . . ( iv ) subtracting ( i ) from ( iv ) , we get : b = 35 b ' s weight = 35 kg . e" | general |
math_qa__5IqVjfzyOKzko9RA | John found that the average of 15 numbers is 40. If 11 is added to each number then the mean of number is? Select the correct option
A) 51 B) 45 C) 65 D) 78 E) 64 | <gadget id="calculator">40 + 11</gadget>
<output>51</output>
<result>A</result> | A | 51 | John found that the average of 15 numbers is 40. If 11 is added to each number then the mean of number is? | {
"A": "51",
"B": "45",
"C": "65",
"D": "78",
"E": "64"
} | add(40, 11) | add(n1,n2)| | "( x + x 1 + . . . x 14 ) / 15 = 40 51 option a" | general |
math_qa__fQtT9CcOWy2SJnSm | A boat goes 100 km downstream in 8 hours, and 75 Km upstream in 15 hours. The speed of the stream is? Choose one
A) 3
B) 6.5
C) 5.5
D) 4
E) 3.75 | <gadget id="calculator">100 / 8</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">75 / 15</gadget>
<output>5</output>
<gadget id="calculator">(25/2) - 5</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) / 2</gadget>
<output>15/4 = around 3.75</output>
<result>E</result> | E | 3.75 | A boat goes 100 km downstream in 8 hours, and 75 Km upstream in 15 hours. The speed of the stream is? | {
"A": "3",
"B": "6.5",
"C": "5.5",
"D": "4",
"E": "3.75"
} | divide(subtract(divide(100, 8), divide(75, 15)), const_2) | divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,const_2)| | "100 - - - 10 ds = 12.5 ? - - - - 1 75 - - - - 15 us = 5 ? - - - - - 1 s = ( 12.5 - 5 ) / 2 = 3.75 kmph . answer : e" | physics |
math_qa__WKd6UAH0ci3XYuUv | What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 11 nor by 30?
Answers.
A) 884 B) 890 C) 892 D) 910 E) 945 | <gadget id="calculator">1_000 / 11</gadget>
<output>1_000/11 = around 90.909091</output>
<gadget id="calculator">1_000 / 30</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(1_000/11) + (100/3)</gadget>
<output>4_100/33 = around 124.242424</output>
<gadget id="calculator">11 * 30</gadget>
<output>330</output>
<gadget id="calculator">1_000 / 330</gadget>
<output>100/33 = around 3.030303</output>
<gadget id="calculator">(4_100/33) - (100/33)</gadget>
<output>4_000/33 = around 121.212121</output>
<gadget id="calculator">1_000 - (4_000/33)</gadget>
<output>29_000/33 = around 878.787879</output>
<result>A</result> | A | 884 | What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 11 nor by 30? | {
"A": "884",
"B": "890",
"C": "892",
"D": "910",
"E": "945"
} | subtract(1000, subtract(add(divide(1000, 11), divide(1000, 30)), divide(1000, multiply(11, 30)))) | divide(n1,n2)|divide(n1,n3)|multiply(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,#4)|subtract(n1,#5)| | "normally , i would use the method used by bunuel . it ' s the most accurate . but if you are looking for a speedy solution , you can use another method which will sometimes give you an estimate . looking at the options ( most of them are spread out ) , i wont mind trying it . ( mind you , the method is accurate here since the numbers start from 1 . ) in 1000 consecutive numbers , number of multiples of 11 = 1000 / 11 = 90 ( ignore decimals ) in 1000 consecutive numbers , number of multiples of 35 = 1000 / 35 = 28 number of multiples of 11 * 35 i . e . 385 = 1000 / 385 = 2 number of integers from 1 to 1000 that are divisible by neither 11 nor by 35 = 1000 - ( 90 + 28 - 2 ) { using the concept of sets here ) = 884 think : why did i say the method is approximate in some cases ? think what happens if the given range is 11 to 1010 both inclusive ( again 1000 numbers ) what is the number of multiples in this case ? a" | other |
math_qa__hwhLLO9dJpIaneaV | the present age of a father is 3 years more than 3 times the age of his son . 5 years hence , father ' s age will be 10 years more than twice the age of the son . find the present age of the father .
Choose the correct choice
A) 33 B) 38 C) 27 D) 40 E) 48 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">15 - 3</gadget>
<output>12</output>
<gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">3 + 36</gadget>
<output>39</output>
<gadget id="calculator">39 - 10</gadget>
<output>29</output>
<gadget id="calculator">29 - 1</gadget>
<output>28</output>
<result>C</result> | C | 27 | the present age of a father is 3 years more than 3 times the age of his son . 5 years hence , father ' s age will be 10 years more than twice the age of the son . find the present age of the father . | {
"A": "33",
"B": "38",
"C": "27",
"D": "40",
"E": "48"
} | subtract(subtract(add(3, multiply(3, subtract(subtract(add(multiply(const_2, 5), 10), 5), 3))), const_10), const_1) | multiply(n2,const_2)|add(n3,#0)|subtract(#1,n2)|subtract(#2,n0)|multiply(n0,#3)|add(n0,#4)|subtract(#5,const_10)|subtract(#6,const_1) | if the present age be x years . father ' s will be ( 3 x + 3 ) years . . so , ( 3 x + 3 + 5 ) = 2 ( x + 3 ) + 10 or , x = 8 so the fathers present age = ( 3 x + 3 ) = ( 3 * 8 + 3 ) years = 27 years . . answer : option c | general |
math_qa__avbOwRR8GZeLpUfa | x and y are positive integers. When x is divided by 9, the remainder is 2, and when x is divided by 7, the remainder is 4. When y is divided by 11, the remainder is 3, and when y is divided by 13, the remainder is 12. What is the least possible value of y - x? Select.
A) 12 B) 13 C) 14 D) 15 E) 16 | <gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">22 + 3</gadget>
<output>25</output>
<gadget id="calculator">2 + 9</gadget>
<output>11</output>
<gadget id="calculator">25 - 11</gadget>
<output>14</output>
<result>C</result> | C | 14 | x and y are positive integers. When x is divided by 9, the remainder is 2, and when x is divided by 7, the remainder is 4. When y is divided by 11, the remainder is 3, and when y is divided by 13, the remainder is 12. What is the least possible value of y - x? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | subtract(add(multiply(11, const_2), 3), add(2, 9)) | add(n0,n1)|multiply(n4,const_2)|add(n5,#1)|subtract(#2,#0)| | "when x is divided by 9 , the remainder is 2 : so , the possible values of x are : 2 , 11 , 21 , 29 , etc . when x is divided by 7 , the remainder is 4 : so , the possible values of x are : 4 , 11,18 , . . . stop . since both lists include 11 , the smallest possible value of x is 11 . when y is divided by 11 , the remainder is 3 : so , the possible values of y are : 3 , 14 , 25 , etc . when y is divided by 13 , the remainder is 12 : so , the possible values of y are : 12 , 25 , . . . stop . since both lists include 25 , the smallest possible value of y is 25 since the smallest possible values of x and y are 11 and 25 respectively , the smallest possible value of y - x is 14 . so , c is the correct answer to the original question ." | general |
math_qa__qslmSZ2WV6g23hYW | At Joes Steakhouse the hourly wage for a chef is 22% greater than that of a dishwasher, and the hourly wage of a dishwasher is half as much as the hourly wage of a manager. If a managers wage is $8.50 per hour, how much less than a manager does a chef earn each hour? Choose the correct choice from the following answers.
A) $ 1.40 B) $ 2.40 C) $ 3.315 D) $ 4.40 E) $ 5.40 | <gadget id="calculator">100 + 22</gadget>
<output>122</output>
<gadget id="calculator">122 / 100</gadget>
<output>61/50 = around 1.22</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(61/50) * (1/2)</gadget>
<output>61/100 = around 0.61</output>
<gadget id="calculator">1 - (61/100)</gadget>
<output>39/100 = around 0.39</output>
<gadget id="calculator">(39/100) * 8.5</gadget>
<output>3.315</output>
<result>C</result> | C | 3.315 | At Joes Steakhouse the hourly wage for a chef is 22% greater than that of a dishwasher, and the hourly wage of a dishwasher is half as much as the hourly wage of a manager. If a managers wage is $8.50 per hour, how much less than a manager does a chef earn each hour? | {
"A": "$ 1.40",
"B": "$ 2.40",
"C": "$ 3.315",
"D": "$ 4.40",
"E": "$ 5.40"
} | multiply(subtract(const_1, multiply(divide(add(const_100, 22), const_100), divide(const_1, const_2))), 8.50) | add(n0,const_100)|divide(const_1,const_2)|divide(#0,const_100)|multiply(#2,#1)|subtract(const_1,#3)|multiply(n1,#4)| | "manager wages per hour = $ 8.50 dishwasher wages per hour = half of manager ' s wages . = 1 / 2 ( $ 8.50 ) = = > $ 4.25 chef wages per hour = 22 % greater than dishwasher wages - - > 22 % of $ 4.25 = ( 22 * ( $ 4.25 ) ) / 100 - - > ( $ 93.5 ) / 100 - - > $ 0.935 therefore , chef wages per hour = $ 4.25 + $ 0.935 = = > $ 5.185 difference of wages between manager and chef = $ 8.50 - $ 5.185 = = > $ 3.315 answer : c" | general |
math_qa__WA3IL9zX8wtq0VrP | If xerox paper costs 5 cents a sheet and a buyer gets 10% discount on all xerox paper one buys after the first 2000 papers and 20% discount after first 10000 papers, how much will it cost to buy 15000 sheets of xerox paper? Choose the correct choice from the following options:
A) $ 1250
B) $ 700
C) $ 1350
D) $ 900
E) $ 1000 | <gadget id="calculator">10_000 - 2_000</gadget>
<output>8_000</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * (1/10)</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">8_000 * (9/100)</gadget>
<output>720</output>
<result>B</result> | B | 700 | If xerox paper costs 5 cents a sheet and a buyer gets 10% discount on all xerox paper one buys after the first 2000 papers and 20% discount after first 10000 papers, how much will it cost to buy 15000 sheets of xerox paper? | {
"A": "$ 1250",
"B": "$ 700",
"C": "$ 1350",
"D": "$ 900",
"E": "$ 1000"
} | multiply(subtract(10000, 2000), multiply(subtract(const_1, divide(const_1, 10)), divide(const_1, 10))) | divide(const_1,n1)|subtract(n4,n2)|subtract(const_1,#0)|multiply(#0,#2)|multiply(#3,#1) | 30 sec approach - solve it using approximation 15000 sheet at full price , 5 cent = 750 15000 sheet at max discount price , 4 cent = 600 your ans got to be between these two . ans b it is . | gain |
math_qa__UfrRfUBVnFken4cH | If the sum of two positive integers is 18 and the difference of their squares is 36, what is the product of the two integers? Options
A) 108
B) 80
C) 128
D) 135
E) 143 | <gadget id="calculator">36 / 18</gadget>
<output>2</output>
<gadget id="calculator">18 - 2</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">8 * 10</gadget>
<output>80</output>
<result>B</result> | B | 80 | If the sum of two positive integers is 18 and the difference of their squares is 36, what is the product of the two integers? | {
"A": "108",
"B": "80",
"C": "128",
"D": "135",
"E": "143"
} | multiply(divide(subtract(18, divide(36, 18)), divide(36, 18)), add(divide(subtract(18, divide(36, 18)), divide(36, 18)), divide(36, 18))) | divide(n1,n0)|subtract(n0,#0)|divide(#1,#0)|add(#2,#0)|multiply(#3,#2)| | "let the 2 positive numbers x and y x + y = 18 - - 1 x ^ 2 - y ^ 2 = 36 = > ( x + y ) ( x - y ) = 36 - - 2 using equation 1 in 2 , we get = > x - y = 2 - - 3 solving equation 1 and 3 , we get x = 10 y = 8 product = 10 * 8 = 80 answer b" | general |
math_qa__Z7NvmGtkhINJ83sH | A candidate appearing for an examination has to secure 35% marks to pass paper I. But he secured only 42 marks and failed by 23 marks. What is the maximum mark for paper I? Choose the most appropriate option:
A) 110
B) 120
C) 186
D) 140
E) 150 | <gadget id="calculator">42 + 23</gadget>
<output>65</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">65 / (7/20)</gadget>
<output>1_300/7 = around 185.714286</output>
<result>C</result> | C | 186 | A candidate appearing for an examination has to secure 35% marks to pass paper I. But he secured only 42 marks and failed by 23 marks. What is the maximum mark for paper I? | {
"A": "110",
"B": "120",
"C": "186",
"D": "140",
"E": "150"
} | divide(add(42, 23), divide(35, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "he secured 42 marks nd fail by 23 marks so total marks for pass the examinatn = 65 let toal marks x x * 35 / 100 = 65 x = 186 answer : c" | gain |
math_qa__bIvmuDVe5RJgU74c | A rectangular plot measuring 90 metres by 40 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed ?
Pick.
A) 55
B) 56
C) 57
D) 52
E) none of these | <gadget id="calculator">2 * (90 + 40)</gadget>
<output>260</output>
<gadget id="calculator">260 / 5</gadget>
<output>52</output>
<result>D</result> | D | 52 | A rectangular plot measuring 90 metres by 40 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed ? | {
"A": "55",
"B": "56",
"C": "57",
"D": "52",
"E": "none of these"
} | divide(rectangle_perimeter(90, 40), 5) | rectangle_perimeter(n0,n1)|divide(#0,n2)| | "solution perimeter of the plot = 2 ( 90 + 40 ) = 260 m . ∴ number of poles = [ 260 / 5 ] = 52 m answer d" | physics |
math_qa__cxyZJSbz5HabVnP2 | Find the value for x from below equation: x/3=-2? Answers.
A) - 6 B) 1 C) - 2 D) - 3 E) 4 | <gadget id="calculator">2 - 4</gadget>
<output>-2</output>
<gadget id="calculator">(-2) * 3</gadget>
<output>-6</output>
<result>A</result> | A | -6 | Find the value for x from below equation: x/3=-2? | {
"A": "- 6",
"B": "1",
"C": "- 2",
"D": "- 3",
"E": "4"
} | multiply(subtract(2, const_4), const_3) | subtract(n1,const_4)|multiply(#0,const_3) | 1 . multiply both sides by 3 : x * 3 / 3 = - 2 / 3 2 . simplify both sides : x = - 6 a | general |
math_qa__w6LtvZRRfJCuZI2F | Dan can do a job alone in 12 hours. Annie, working alone, can do the same job in just 9 hours. If Dan works alone for 4 hours and then stops, how many hours will it take Annie, working alone, to complete the job? Select.
A) 2 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 9</gadget>
<output>6</output>
<result>C</result> | C | 6 | Dan can do a job alone in 12 hours. Annie, working alone, can do the same job in just 9 hours. If Dan works alone for 4 hours and then stops, how many hours will it take Annie, working alone, to complete the job? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | multiply(subtract(const_1, divide(4, 12)), 9) | divide(n2,n0)|subtract(const_1,#0)|multiply(n1,#1)| | "dan can complete 1 / 12 of the job per hour . in 4 hours , dan completes 4 ( 1 / 12 ) = 1 / 3 of the job . annie can complete 1 / 9 of the job per hour . to complete the job , annie will take 2 / 3 / 1 / 9 = 6 hours . the answer is c ." | physics |
math_qa__DmGqqxvuA5USJPPl | Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 3x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes? Choose the correct choice from the following options.
A) 3 minutes B) 4 minutes C) 4.2 minutes D) 6 minutes E) 12 minutes | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">1 + 6</gadget>
<output>7</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<result>C</result> | C | 4.2 | Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 3x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes? | {
"A": "3 minutes",
"B": "4 minutes",
"C": "4.2 minutes",
"D": "6 minutes",
"E": "12 minutes"
} | divide(multiply(3, 10), add(speed(10, 10), speed(multiply(3, 10), 5))) | multiply(n0,n3)|multiply(n0,n1)|speed(n0,n0)|speed(#1,n2)|add(#2,#3)|divide(#0,#4)| | "rate = work / time given rate of machine a = x / 10 min machine b produces 3 x boxes in 5 min hence , machine b produces 4 x boxes in 10 min . rate of machine b = 6 x / 10 we need tofind the combined time that machines a and b , working simultaneouslytakeat their respective constant rates let ' s first find the combined rate of machine a and b rate of machine a = x / 10 min + rate of machine b = 6 x / 10 = 7 x / 10 now combine time = combine work needs to be done / combine rate = 3 x / 7 x * 10 = 4.2 min ans : c" | physics |
math_qa__QtwInybx6xcL6z7X | A student chose a number, multiplied it by 4, then subtracted 138 from the result and got 102. What was the number he chose? Choose the correct choice from the following options:
A) 60 B) 120 C) 130 D) 140 E) 150 | <gadget id="calculator">102 + 138</gadget>
<output>240</output>
<gadget id="calculator">240 / 4</gadget>
<output>60</output>
<result>A</result> | A | 60 | A student chose a number, multiplied it by 4, then subtracted 138 from the result and got 102. What was the number he chose? | {
"A": "60",
"B": "120",
"C": "130",
"D": "140",
"E": "150"
} | divide(add(102, 138), 4) | add(n1,n2)|divide(#0,n0) | solution : let xx be the number he chose , then 4 ⋅ x − 138 = 102 4 x = 240 x = 60 answer a | general |
math_qa__ttZDvKvawB4ajMg2 | What is the speed of the stream if a canoe rows upstream at 4km/hr and downstream at 12km/hr Choose the correct choice from the following answers.
A) 1 kmph B) 4 kmph C) 3 kmph D) 2 kmph E) 1.9 kmph | <gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>B</result> | B | 4 | What is the speed of the stream if a canoe rows upstream at 4km/hr and downstream at 12km/hr | {
"A": "1 kmph",
"B": "4 kmph",
"C": "3 kmph",
"D": "2 kmph",
"E": "1.9 kmph"
} | divide(subtract(12, 4), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "sol . speed of stream = 1 / 2 ( 12 - 4 ) kmph = 4 kmph . answer b" | physics |
math_qa__sQXlyuzlBVfZgiLK | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 4 litres from vessel P is mixed with 8 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? Choose one:
A) 19 : 1 B) 19 : 4 C) 19 : 8 D) 38 : 10 E) 38 : 2 | <gadget id="calculator">62.5 * 4</gadget>
<output>250</output>
<gadget id="calculator">250 / 100</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">87.5 * 8</gadget>
<output>700</output>
<gadget id="calculator">700 / 100</gadget>
<output>7</output>
<gadget id="calculator">(5/2) + 7</gadget>
<output>19/2 = around 9.5</output>
<gadget id="calculator">4 - (5/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">8 - 7</gadget>
<output>1</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(19/2) / (5/2)</gadget>
<output>19/5 = around 3.8</output>
<result>D</result> | D | 3.8 | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 4 litres from vessel P is mixed with 8 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? | {
"A": "19 : 1",
"B": "19 : 4",
"C": "19 : 8",
"D": "38 : 10",
"E": "38 : 2"
} | divide(add(divide(multiply(62.5, 4), const_100), divide(multiply(87.5, 8), const_100)), add(subtract(4, divide(multiply(62.5, 4), const_100)), subtract(8, divide(multiply(87.5, 8), const_100)))) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|subtract(n2,#2)|subtract(n3,#3)|add(#5,#6)|divide(#4,#7)| | "quantity of alcohol in vessel p = 62.5 / 100 * 4 = 5 / 2 litres quantity of alcohol in vessel q = 87.5 / 100 * 8 = 7 / 1 litres quantity of alcohol in the mixture formed = 5 / 2 + 7 / 1 = 19 / 2 = 9.50 litres as 12 litres of mixture is formed , ratio of alcohol and water in the mixture formed = 9.50 : 2.50 = 38 : 10 . answer : d" | other |
math_qa__FuWerCXTKfAA1Ici | (228% of 1265) ÷ 6 = ?
Answers: A) 125 B) 175 C) 481 D) 375 E) 524 | <gadget id="calculator">228 / 100</gadget>
<output>57/25 = around 2.28</output>
<gadget id="calculator">(57/25) * 1_265</gadget>
<output>14_421/5 = around 2_884.2</output>
<gadget id="calculator">(14_421/5) / 6</gadget>
<output>4_807/10 = around 480.7</output>
<result>C</result> | C | 481 | (228% of 1265) ÷ 6 = ? | {
"A": "125",
"B": "175",
"C": "481",
"D": "375",
"E": "524"
} | divide(multiply(divide(228, const_100), 1265), 6) | divide(n0,const_100)|multiply(n1,#0)|divide(#1,n2)| | "explanation : ? = ( 228 x 1265 / 100 ) ÷ 6 = 288420 / 600 = 481 answer : option c" | general |
math_qa__HOBohDS2QJm8vl1D | The first year, two cows produced 8100 litres of milk. The second year their production increased by 15% and 10% respectively, and the total amount of milk increased to 9100 litres a year. How many litres were milked from one cow? Select.
A) 2178 lt B) 3697 lt C) 6583 lt D) 4370 lt E) 5548 lt | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) * 8_100</gadget>
<output>8_910</output>
<gadget id="calculator">9_100 - 8_910</gadget>
<output>190</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(23/20) - (11/10)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">190 / (1/20)</gadget>
<output>3_800</output>
<gadget id="calculator">8_100 - 3_800</gadget>
<output>4_300</output>
<result>D</result> | D | 4,370 | The first year, two cows produced 8100 litres of milk. The second year their production increased by 15% and 10% respectively, and the total amount of milk increased to 9100 litres a year. How many litres were milked from one cow? | {
"A": "2178 lt",
"B": "3697 lt",
"C": "6583 lt",
"D": "4370 lt",
"E": "5548 lt"
} | subtract(8100, divide(subtract(9100, multiply(add(const_1, divide(10, const_100)), 8100)), subtract(add(const_1, divide(15, const_100)), add(const_1, divide(10, const_100))))) | divide(n2,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(n0,#2)|subtract(#3,#2)|subtract(n3,#4)|divide(#6,#5)|subtract(n0,#7)| | "let x be the amount of milk the first cow produced during the first year . then the second cow produced ( 8100 − x ) litres of milk that year . the second year , each cow produced the same amount of milk as they did the first year plus the increase of 15 % 15 % or 10 % so 8100 + 15100 ⋅ x + 10100 ⋅ ( 8100 − x ) = 9100 therefore 8100 + 320 x + 110 ( 8100 − x ) = 9100 120 x = 190 x = 3800 therefore , the cows produced 3800 and 4300 litres of milk the first year , and 4370 and 4730 litres of milk the second year , = > one cow produced 4370 litres correct answer is d ) 4370 lt" | general |
math_qa__cWivOZnu3h4Ayeuy | The average height of 40 girls out of a class of 50 is 169 cm. and that of the remaining girls is 167 cm. The average height of the whole class is : Choose the correct choice from the following answers
A) 138.9 cms
B) 149.2 cms
C) 168.6 cms
D) 159.2 cms
E) 142.5 cms | <gadget id="calculator">169 * 40</gadget>
<output>6_760</output>
<gadget id="calculator">167 * 10</gadget>
<output>1_670</output>
<gadget id="calculator">6_760 + 1_670</gadget>
<output>8_430</output>
<gadget id="calculator">8_430 / 50</gadget>
<output>843/5 = around 168.6</output>
<result>C</result> | C | 168.6 | The average height of 40 girls out of a class of 50 is 169 cm. and that of the remaining girls is 167 cm. The average height of the whole class is : | {
"A": "138.9 cms",
"B": "149.2 cms",
"C": "168.6 cms",
"D": "159.2 cms",
"E": "142.5 cms"
} | divide(add(multiply(169, 40), multiply(167, const_10)), 50) | multiply(n0,n2)|multiply(n3,const_10)|add(#0,#1)|divide(#2,n1)| | "explanation : average height of the whole class = ( 40 × 169 + 10 × 167 / 50 ) = 168.6 cms answer c" | general |
math_qa__btQI4euzUDLCVd8q | Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/7 full and other jar 1/6 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water? Answers:
A) 1 / 7 B) 7 / 12 C) 1 / 2 D) 2 / 7 E) 2 / 3 | <gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<result>D</result> | D | 0.285714 | Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/7 full and other jar 1/6 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water? | {
"A": "1 / 7",
"B": "7 / 12",
"C": "1 / 2",
"D": "2 / 7",
"E": "2 / 3"
} | divide(const_2, 7) | divide(const_2,n1)| | "same amount of water made bigger jar 1 / 7 full , then the same amount of water ( stored for a while in smaller jar ) were added to bigger jar , so bigger jar is 1 / 7 + 1 / 7 = 2 / 7 full . answer : d ." | general |
math_qa__ABQcnKI1trRXl6Fx | Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 10 = f(x – 2) ?
Select the correct option: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">20 - 11</gadget>
<output>9</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">3 * 1</gadget>
<output>3</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">9 / 3</gadget>
<output>3</output>
<result>C</result> | C | 3 | Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 10 = f(x – 2) ? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(subtract(add(multiply(2, 5), 10), add(multiply(3, 2), 5)), subtract(multiply(2, 3), multiply(3, const_1))) | multiply(n1,n2)|multiply(n4,n0)|multiply(n0,n2)|multiply(n0,const_1)|add(n3,#0)|add(n1,#1)|subtract(#2,#3)|subtract(#4,#5)|divide(#7,#6)| | "2 ( 3 x - 5 ) - 10 = 3 ( x - 2 ) - 5 3 x = 9 x = 3 the answer is c ." | general |
math_qa__ddfEO7vF2v5nVNUA | The diameter of a cylindrical tin is 8cm and height is 5 cm. Find the volume of the cylinder? Select the correct option:
A) 33 B) 45 C) 66 D) 80 E) 21 | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">pi * (4 ** 2) * 5</gadget>
<output>80*pi = around 251.327412</output>
<gadget id="calculator">(80*pi) / pi</gadget>
<output>80</output>
<result>D</result> | D | 80 | The diameter of a cylindrical tin is 8cm and height is 5 cm. Find the volume of the cylinder? | {
"A": "33",
"B": "45",
"C": "66",
"D": "80",
"E": "21"
} | divide(volume_cylinder(divide(8, const_2), 5), const_pi) | divide(n0,const_2)|volume_cylinder(#0,n1)|divide(#1,const_pi)| | "r = 4 h = 5 π * 4 * 4 * 5 = 80 π cc answer : d" | geometry |
math_qa__Il339Pj0MrOQZjID | Each of the dogs in a certain kennel is a single color. Each of the dogs in the kennel either has long fur or does not. Of the 45 dogs in the kennel, 26 have long fur, 30 are brown, and 8 are neither long-furred nor brown. How many long-furred dogs are brown? Choose the correct choice
A) 26 B) 19 C) 11 D) 8 E) 6 | <gadget id="calculator">26 + 30</gadget>
<output>56</output>
<gadget id="calculator">45 - 8</gadget>
<output>37</output>
<gadget id="calculator">56 - 37</gadget>
<output>19</output>
<result>B</result> | B | 19 | Each of the dogs in a certain kennel is a single color. Each of the dogs in the kennel either has long fur or does not. Of the 45 dogs in the kennel, 26 have long fur, 30 are brown, and 8 are neither long-furred nor brown. How many long-furred dogs are brown? | {
"A": "26",
"B": "19",
"C": "11",
"D": "8",
"E": "6"
} | subtract(add(26, 30), subtract(45, 8)) | add(n1,n2)|subtract(n0,n3)|subtract(#0,#1)| | "no of dogs = 45 long fur = 26 brown = 30 neither long fur nor brown = 8 therefore , either long fur or brown = 45 - 8 = 37 37 = 26 + 30 - both both = 19 answer b" | other |
math_qa__RjKwy8R4HZQeq3ZV | A person bought 114 glass bowls at a rate of Rs. 13 per bowl. He sold 108 of them at Rs. 17 and the remaining broke. What is the percentage gain for A? Select
A) 40
B) 3000 / 11
C) 5900 / 247
D) 2790 / 11
E) 2709 / 8 | <gadget id="calculator">108 * 17</gadget>
<output>1_836</output>
<gadget id="calculator">114 * 13</gadget>
<output>1_482</output>
<gadget id="calculator">1_836 - 1_482</gadget>
<output>354</output>
<gadget id="calculator">354 / 1_482</gadget>
<output>59/247 = around 0.238866</output>
<gadget id="calculator">(59/247) * 100</gadget>
<output>5_900/247 = around 23.88664</output>
<result>C</result> | C | 23.88664 | A person bought 114 glass bowls at a rate of Rs. 13 per bowl. He sold 108 of them at Rs. 17 and the remaining broke. What is the percentage gain for A? | {
"A": "40",
"B": "3000 / 11",
"C": "5900 / 247",
"D": "2790 / 11",
"E": "2709 / 8"
} | multiply(divide(subtract(multiply(108, 17), multiply(114, 13)), multiply(114, 13)), const_100) | multiply(n2,n3)|multiply(n0,n1)|subtract(#0,#1)|divide(#2,#1)|multiply(#3,const_100)| | "cp = 114 * 13 = 1482 and sp = 108 * 17 = 1836 gain % = 100 * ( 1836 - 1482 ) / 1482 = 5900 / 247 answer : c" | gain |
math_qa__dCQQ2FLOEz6Stgh3 | A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 147 km downstream. Choose the correct choice:
A) 4 hours B) 5 hours C) 6 hours D) 7 hours E) 8 hours | <gadget id="calculator">16 + 5</gadget>
<output>21</output>
<gadget id="calculator">147 / 21</gadget>
<output>7</output>
<result>D</result> | D | 7 | A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 147 km downstream. | {
"A": "4 hours",
"B": "5 hours",
"C": "6 hours",
"D": "7 hours",
"E": "8 hours"
} | divide(147, add(16, 5)) | add(n0,n1)|divide(n2,#0)| | "explanation : it is very important to check , if the boat speed given is in still water or with water or against water . because if we neglect it we will not reach on right answer . i just mentioned here because mostly mistakes in this chapter are of this kind only . lets see the question now . speed downstream = ( 16 + 5 ) = 21 kmph time = distance / speed = 147 / 21 = 7 hours option d" | physics |
math_qa__7P8bJhWsWvvoDlsb | The area of a square is 4761 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square. Select:
A) 5 : 28 B) 5 : 19 C) 15 : 12 D) 5 : 13 E) 15 : 46 | <gadget id="calculator">4_761 ** (1/2)</gadget>
<output>69</output>
<gadget id="calculator">69 - 24</gadget>
<output>45</output>
<gadget id="calculator">69 * 2</gadget>
<output>138</output>
<gadget id="calculator">45 / 138</gadget>
<output>15/46 = around 0.326087</output>
<result>E</result> | E | 0.326087 | The area of a square is 4761 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square. | {
"A": "5 : 28",
"B": "5 : 19",
"C": "15 : 12",
"D": "5 : 13",
"E": "15 : 46"
} | divide(subtract(sqrt(4761), 24), multiply(sqrt(4761), const_2)) | sqrt(n0)|multiply(#0,const_2)|subtract(#0,n1)|divide(#2,#1)| | "let the length and the breadth of the rectangle be l cm and b cm respectively . let the side of the square be a cm . a 2 = 4761 a = 69 l = 2 a and b = a - 24 b : l = a - 24 : 2 a = 45 : 138 = 15 : 46 answer : e" | geometry |
math_qa__6Ulepu5nCwoWtM0J | A positive integer n is a perfect number provided that the sum of all the positive factors of n, including 1 and n, is equal to 2n. What is the sum of the reciprocals of all the positive factors of the perfect number 28? Choose one:
A) 1 / 4
B) 56 / 27
C) 2
D) 3
E) 4 | <gadget id="calculator">1 / 28</gadget>
<output>1/28 = around 0.035714</output>
<gadget id="calculator">2 * (1/28)</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/14) * 28</gadget>
<output>2</output>
<result>C</result> | C | 2 | A positive integer n is a perfect number provided that the sum of all the positive factors of n, including 1 and n, is equal to 2n. What is the sum of the reciprocals of all the positive factors of the perfect number 28? | {
"A": "1 / 4",
"B": "56 / 27",
"C": "2",
"D": "3",
"E": "4"
} | multiply(multiply(const_2, divide(const_1, 28)), 28) | divide(const_1,n2)|multiply(#0,const_2)|multiply(n2,#1) | soln : 28 = 1 * 28 2 * 14 4 * 7 sum of reciprocals = 1 + 1 / 28 + 1 / 2 + 1 / 14 + 1 / 4 + 1 / 7 = 56 / 28 = 2 answer : c | general |
math_qa__eF1fdhE0W5yanN6D | Two trains 200 m and 150 m long are running on parallel rails at the rate of 40 kmph and 46 kmph respectively. In how much time will they cross each other, if they are running in the same direction? Choose the correct choice from the following options: A) 72 sec B) 210 sec C) 192 sec D) 252 sec E) none | <gadget id="calculator">200 + 150</gadget>
<output>350</output>
<gadget id="calculator">350 / 1_000</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">46 - 40</gadget>
<output>6</output>
<gadget id="calculator">(7/20) / 6</gadget>
<output>7/120 = around 0.058333</output>
<gadget id="calculator">3_600 * (7/120)</gadget>
<output>210</output>
<result>B</result> | B | 210 | Two trains 200 m and 150 m long are running on parallel rails at the rate of 40 kmph and 46 kmph respectively. In how much time will they cross each other, if they are running in the same direction? | {
"A": "72 sec",
"B": "210 sec",
"C": "192 sec",
"D": "252 sec",
"E": "none"
} | multiply(const_3600, divide(divide(add(200, 150), const_1000), subtract(46, 40))) | add(n0,n1)|subtract(n3,n2)|divide(#0,const_1000)|divide(#2,#1)|multiply(#3,const_3600)| | "solution relative speed = ( 46 - 40 ) kmph = 6 kmph = ( 6 x 5 / 18 ) m / sec = ( 30 / 18 ) m / sec time taken = ( 350 x 18 / 30 ) sec = 210 sec . answer b" | physics |
math_qa__1wcQqqPA2gjxwlDF | A can do a job in 15days and B in 20days. If they work on it together for 8 days, then the fraction of the work that is left is? Pick
A) 2 / 15 B) 8 / 15 C) 3 / 11 D) 1 / 12 E) 1 / 15 | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/15) + (1/20)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">8 * (7/60)</gadget>
<output>14/15 = around 0.933333</output>
<gadget id="calculator">1 - (14/15)</gadget>
<output>1/15 = around 0.066667</output>
<result>E</result> | E | 0.066667 | A can do a job in 15days and B in 20days. If they work on it together for 8 days, then the fraction of the work that is left is? | {
"A": "2 / 15",
"B": "8 / 15",
"C": "3 / 11",
"D": "1 / 12",
"E": "1 / 15"
} | subtract(const_1, multiply(8, add(divide(const_1, 15), divide(const_1, 20)))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)| | "a ' s 1 day work = 1 / 15 b ' s 1 day work = 1 / 20 a + b 1 day work = 1 / 15 + 1 / 20 = 7 / 60 a + b 8 days work = 7 / 60 * 8 = 14 / 15 remaining work = 1 - 14 / 15 = 1 / 15 answer is e" | physics |
math_qa__3pO4s9ZJW0Qf5kYT | A dishonest milkman wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing Rs.33 per litre so as to make a profit of 20% on cost when he sells the resulting milk and water mixture for Rs.36 In what ratio should he mix the water and milk?
Choose the correct choice from the following choices: A) 1 : 20 B) 1 : 10 C) 1 : 8 D) 1 : 4 E) 6 : 11 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<result>B</result> | B | 0.1 | A dishonest milkman wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing Rs.33 per litre so as to make a profit of 20% on cost when he sells the resulting milk and water mixture for Rs.36 In what ratio should he mix the water and milk? | {
"A": "1 : 20",
"B": "1 : 10",
"C": "1 : 8",
"D": "1 : 4",
"E": "6 : 11"
} | divide(const_1, divide(20, const_2)) | divide(n1,const_2)|divide(const_1,#0) | cost needed to net a 20 % profit : ( 36 - x ) / x = . 2 x = 30 actual cost : 33 solution ( x = liters of water needed to be added to the 1 liter of milk ) : 33 / ( 1 + x ) = 30 x = 1 / 10 so to get the cost down to 30 milk : water 1 : 1 / 10 or ( 10 / 10 ) : ( 1 / 10 ) answer : b | gain |
math_qa__eyi5aTAuUHm9KgVp | A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 980gm. for a kg.His gain is …%. Choose the correct option:
A) 2.04 % B) 5.36 % C) 4.26 % D) 6.26 % E) 7.26 % | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">980 / 1_000</gadget>
<output>49/50 = around 0.98</output>
<gadget id="calculator">1 / (49/50)</gadget>
<output>50/49 = around 1.020408</output>
<gadget id="calculator">(50/49) - 1</gadget>
<output>1/49 = around 0.020408</output>
<gadget id="calculator">(1/49) * 100</gadget>
<output>100/49 = around 2.040816</output>
<result>A</result> | A | 2.04 | A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 980gm. for a kg.His gain is …%. | {
"A": "2.04 %",
"B": "5.36 %",
"C": "4.26 %",
"D": "6.26 %",
"E": "7.26 %"
} | multiply(subtract(inverse(divide(980, multiply(multiply(add(const_4, const_1), const_2), const_100))), const_1), const_100) | add(const_1,const_4)|multiply(#0,const_2)|multiply(#1,const_100)|divide(n0,#2)|inverse(#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "his percentage gain is 100 * 20 / 980 as he is gaining 20 units for his purchase of 980 units . so 2.04 % . . answer : a" | gain |
math_qa__4Bb6zesPiQDHKdrl | If 20% of a number = 400, then 120% of that number will be?
Choose the correct choice
A) 20 B) 120 C) 360 D) 2400 E) 2820 | <gadget id="calculator">120 * 400</gadget>
<output>48_000</output>
<gadget id="calculator">48_000 / 20</gadget>
<output>2_400</output>
<result>D</result> | D | 2,400 | If 20% of a number = 400, then 120% of that number will be? | {
"A": "20",
"B": "120",
"C": "360",
"D": "2400",
"E": "2820"
} | divide(multiply(120, 400), 20) | multiply(n1,n2)|divide(#0,n0)| | "let the number x . then , 20 % of x = 400 x = ( 400 * 100 ) / 20 = 2000 120 % of x = ( 120 / 100 * 2000 ) = 2400 . answer : d" | gain |
math_qa__vMacdjpVAUqjlPZV | At a certain resort, each of the 39 food service employees is trained to work in a minimum of 1 restaurant and a maximum of 3 restaurants. The 3 restaurants are the family buffet, the dining room, and the snack bar. Exactly 17 employees are trained to work in the family buffet, 18 are trained to work in the dining room, and 12 are trained to work in the snack bar. If 4 employees are trained to work in exactly 2 restaurants, how many employees are trained to work in all 3 restaurants? Choices: A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">17 + 18</gadget>
<output>35</output>
<gadget id="calculator">35 + 12</gadget>
<output>47</output>
<gadget id="calculator">47 - 4</gadget>
<output>43</output>
<gadget id="calculator">43 - 39</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>A</result> | A | 2 | At a certain resort, each of the 39 food service employees is trained to work in a minimum of 1 restaurant and a maximum of 3 restaurants. The 3 restaurants are the family buffet, the dining room, and the snack bar. Exactly 17 employees are trained to work in the family buffet, 18 are trained to work in the dining room, and 12 are trained to work in the snack bar. If 4 employees are trained to work in exactly 2 restaurants, how many employees are trained to work in all 3 restaurants? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(subtract(subtract(add(add(17, 18), 12), 4), 39), 2) | add(n4,n5)|add(n6,#0)|subtract(#1,n7)|subtract(#2,n0)|divide(#3,n8)| | "39 = 17 + 18 + 12 - 4 - 2 x 2 x = 17 + 18 + 12 - 4 - 39 = 43 - 39 = 4 x = 2 a" | physics |
math_qa__xMpl2tAV9AGvxlJl | A cistern is filled by pipe A in 20 hours and the full cistern can be leaked out by an exhaust pipe B in 25 hours. If both the pipes are opened, in what time the cistern is full?
Choose the correct choice from the following choices: A) 50 hrs B) 60 hrs C) 70 hrs D) 80 hrs E) 100 hrs | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/20) - (1/25)</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">1 / (1/100)</gadget>
<output>100</output>
<result>E</result> | E | 100 | A cistern is filled by pipe A in 20 hours and the full cistern can be leaked out by an exhaust pipe B in 25 hours. If both the pipes are opened, in what time the cistern is full? | {
"A": "50 hrs",
"B": "60 hrs",
"C": "70 hrs",
"D": "80 hrs",
"E": "100 hrs"
} | divide(const_1, subtract(divide(const_1, 20), divide(const_1, 25))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)| | "time taken to full the cistern = ( 1 / 20 - 1 / 25 ) hrs = 1 / 100 = 100 hrs answer : e" | physics |
math_qa__bCQ4P5J7ecONIEwT | -54x29+100=? Choices:
A) - 1466
B) 2801
C) - 2801
D) - 2071
E) none of them | <gadget id="calculator">1 - 2</gadget>
<output>-1</output>
<gadget id="calculator">54 * 29</gadget>
<output>1_566</output>
<gadget id="calculator">1_566 - 100</gadget>
<output>1_466</output>
<gadget id="calculator">(-1) * 1_466</gadget>
<output>-1_466</output>
<result>A</result> | A | -1,466 | -54x29+100=? | {
"A": "- 1466",
"B": "2801",
"C": "- 2801",
"D": "- 2071",
"E": "none of them"
} | multiply(subtract(const_1, const_2), subtract(multiply(54, 29), 100)) | multiply(n0,n1)|subtract(const_1,const_2)|subtract(#0,n2)|multiply(#1,#2) | given exp . = - 54 x ( 30 - 1 ) + 100 = - ( 54 x 30 ) + 54 + 100 = - 1620 + 154 = - 1466 answer is a | general |
math_qa__AiF6UmDcvfTCOQXZ | If 50% of 100 is greater than 20% of a number by 47, what is the number? Choose the correct choice from the following options
A) 60 B) 30 C) 15 D) 75 E) 100 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<gadget id="calculator">50 - 47</gadget>
<output>3</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">3 / (1/5)</gadget>
<output>15</output>
<result>C</result> | C | 15 | If 50% of 100 is greater than 20% of a number by 47, what is the number? | {
"A": "60",
"B": "30",
"C": "15",
"D": "75",
"E": "100"
} | divide(subtract(multiply(divide(50, const_100), 100), 47), divide(20, const_100)) | divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|subtract(#2,n3)|divide(#3,#1)| | "explanation : 50 / 100 * 100 - 20 / 100 * x = 47 50 - 20 / 100 * x = 47 3 = 20 / 100 * x 3 * 100 / 20 = x 15 = x answer : option c" | gain |
math_qa__vn6fr1ddgKGKQTpN | Running at the same constant rate,6 identical machines can produce a total of 270 bottles per minute.At this rate,how many bottles could 14 such machines produce in 4 minutes ? Choose the correct option
A) 2520 B) 1800 C) 2700 D) 10800 E) none of these | <gadget id="calculator">270 / 6</gadget>
<output>45</output>
<gadget id="calculator">45 * 4</gadget>
<output>180</output>
<gadget id="calculator">180 * 14</gadget>
<output>2_520</output>
<result>A</result> | A | 2,520 | Running at the same constant rate,6 identical machines can produce a total of 270 bottles per minute.At this rate,how many bottles could 14 such machines produce in 4 minutes ? | {
"A": "2520",
"B": "1800",
"C": "2700",
"D": "10800",
"E": "none of these"
} | multiply(multiply(divide(270, 6), 4), 14) | divide(n1,n0)|multiply(n3,#0)|multiply(n2,#1)| | "solution let the required number of bottles be x . more machines , more bottles ( direct proportion ) more minutes , more bottles ( direct proportion ) â ˆ ´ 6 ã — 1 ã — x = 14 ã — 4 ã — 270 â ‡ ” x = 14 x 4 x 270 / 6 = 2520 . answer a" | gain |
math_qa__iE2cyZCUmqTtlJRw | A tank holds x gallons of a saltwater solution that is 20% salt by volume. One Fourth of the water is evaporated, leaving all of the salt. When 6 Gallons of water and 12 gallons of salt are added, the resulting mixture is 33 1/3 % salt by volume. What is the value of x? Choose the correct choice from the following choices
A) 37.5 B) 75 C) 100 D) 150 E) 90 | <gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 - 6</gadget>
<output>18</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(4/5) * (1/4)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(4/5) - (1/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">2 * (1/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/5) - (2/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">18 / (1/5)</gadget>
<output>90</output>
<result>E</result> | E | 90 | A tank holds x gallons of a saltwater solution that is 20% salt by volume. One Fourth of the water is evaporated, leaving all of the salt. When 6 Gallons of water and 12 gallons of salt are added, the resulting mixture is 33 1/3 % salt by volume. What is the value of x? | {
"A": "37.5",
"B": "75",
"C": "100",
"D": "150",
"E": "90"
} | divide(subtract(multiply(12, const_2), 6), subtract(subtract(subtract(const_1, divide(20, const_100)), multiply(subtract(const_1, divide(20, const_100)), divide(const_1, const_4))), multiply(const_2, divide(20, const_100)))) | divide(n0,const_100)|divide(const_1,const_4)|multiply(n2,const_2)|multiply(#0,const_2)|subtract(#2,n1)|subtract(const_1,#0)|multiply(#1,#5)|subtract(#5,#6)|subtract(#7,#3)|divide(#4,#8) | nope , 150 . i can only get it by following pr ' s backsolving explanation . i hate that . original mixture has 20 % salt and 80 % water . total = x out of which salt = 0.2 x and water = 0.8 x now , 1 / 4 water evaporates and all salt remains . so what remains is 0.2 x salt and 0.6 x water . now 12 gallons salt is added and 6 gallons of water is added . so salt now becomes - > ( 0.2 x + 12 ) and water - - > ( 0.6 x + 6 ) amount of salt is 33.33 % of total . so amount of water is 66.66 % . so salt is half of the volume of water . so ( 0.2 x + 12 ) = ( 0.6 x + 6 ) / 2 = > 0.4 x + 24 = 0.6 x + 6 - > 0.2 x = 18 solving , x = 90 answer : e | general |
math_qa__cosyE5TbDUZuVC5N | There are 250 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers. Choose the correct choice from the following options:
A) 325
B) 425
C) 625
D) 700
E) none of these | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">250 / (2/5)</gadget>
<output>625</output>
<result>C</result> | C | 625 | There are 250 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers. | {
"A": "325",
"B": "425",
"C": "625",
"D": "700",
"E": "none of these"
} | divide(250, divide(2, 5)) | divide(n1,n2)|divide(n0,#0)| | as per question stem 2 / 5 m ( portion of men employees who are managers ) + 250 ( portion of female employees who are managers ) = 2 / 5 t ( portion of total number of employees who are managers ) , thus we get that 2 / 5 m + 250 = 2 / 5 t , or 2 / 5 ( t - m ) = 250 , from here we get that t - m = 625 , that would be total number of female employees and the answer ( c ) | general |
math_qa__P22dD7MXP7x6bYv6 | Income and expenditure of a person are in the ratio 15 : 8. If the income of the person is Rs. 15000, then find his savings?
Choose the correct option: A) 6999 B) 7000 C) 7001 D) 7002 E) 7003 | <gadget id="calculator">8 / 15</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">(8/15) * 15_000</gadget>
<output>8_000</output>
<gadget id="calculator">15_000 - 8_000</gadget>
<output>7_000</output>
<result>B</result> | B | 7,000 | Income and expenditure of a person are in the ratio 15 : 8. If the income of the person is Rs. 15000, then find his savings? | {
"A": "6999",
"B": "7000",
"C": "7001",
"D": "7002",
"E": "7003"
} | subtract(15000, multiply(divide(8, 15), 15000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 15 x and rs . 8 x respectively . income , 15 x = 15000 = > x = 1000 savings = income - expenditure = 15 x - 8 x = 7 x = 7 ( 1000 ) so , savings = rs . 7000 . answer : b" | other |
math_qa__I48avsJfbHGFgGk2 | Ashok secured average of 78 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject?
Pick one
A) 66 B) 74 C) 78 D) 98 E) none of these | <gadget id="calculator">78 * 6</gadget>
<output>468</output>
<gadget id="calculator">74 * 5</gadget>
<output>370</output>
<gadget id="calculator">468 - 370</gadget>
<output>98</output>
<result>D</result> | D | 98 | Ashok secured average of 78 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject? | {
"A": "66",
"B": "74",
"C": "78",
"D": "98",
"E": "none of these"
} | subtract(multiply(78, 6), multiply(74, 5)) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)| | "explanation : number of subjects = 6 average of marks in 6 subjects = 78 therefore total marks in 6 subjects = 78 * 6 = 468 now , no . of subjects = 5 total marks in 5 subjects = 74 * 5 = 370 therefore marks in 6 th subject = 468 – 370 = 98 answer d" | general |
math_qa__DkeBpP5m3xeoowzS | If p/q = 3/5 , then 2p+q= ?
Answers.
A) 12 B) 11 C) 13 D) 15 E) 16 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<result>B</result> | B | 11 | If p/q = 3/5 , then 2p+q= ? | {
"A": "12",
"B": "11",
"C": "13",
"D": "15",
"E": "16"
} | add(multiply(3, 2), 5) | multiply(n0,n2)|add(n1,#0)| | "let p = 3 , q = 5 then 2 * 3 + 5 = 11 so 2 p + q = 11 . answer : b" | general |
math_qa__mG7ve3UeGo3HdegC | The difference between a two digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2? Choose the most appropriate option: A) 4 B) 8 C) 12 D) 16 E) 18 | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">21 - 12</gadget>
<output>9</output>
<gadget id="calculator">36 / 9</gadget>
<output>4</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<result>B</result> | B | 8 | The difference between a two digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1 : 2? | {
"A": "4",
"B": "8",
"C": "12",
"D": "16",
"E": "18"
} | multiply(subtract(const_3, 1), divide(36, subtract(add(multiply(const_10, 2), 1), add(const_10, 2)))) | add(n2,const_10)|multiply(n2,const_10)|subtract(const_3,n1)|add(n1,#1)|subtract(#3,#0)|divide(n0,#4)|multiply(#5,#2) | sol . since the number is greater than the number obtained on reversing the digits , so the ten ' s is greater than the unit ' s digit . let the ten ' s and units digit be 2 x and x respectively . then , ( 10 × 2 x + x ) - ( 10 x + 2 x ) = 36 ⇔ 9 x = 36 ⇔ x = 4 . ∴ required difference = ( 2 x + x ) - ( 2 x - x ) = 2 x = 8 . answer b | general |
math_qa__igZSHBhkXohydcjT | 40 + 5 * 12 / (180/3) = ? Choose the correct choice from the following answers: A) 23 B) 78 C) 27 D) 61 E) 41 | <gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">180 / 3</gadget>
<output>60</output>
<gadget id="calculator">60 / 60</gadget>
<output>1</output>
<gadget id="calculator">40 + 1</gadget>
<output>41</output>
<result>E</result> | E | 41 | 40 + 5 * 12 / (180/3) = ? | {
"A": "23",
"B": "78",
"C": "27",
"D": "61",
"E": "41"
} | add(40, divide(multiply(5, 12), divide(180, 3))) | divide(n3,n4)|multiply(n1,n2)|divide(#1,#0)|add(n0,#2)| | "explanation : 40 + 5 * 12 / ( 180 / 3 ) = 40 + 5 * 12 / ( 60 ) = 40 + ( 5 * 12 ) / 60 = 40 + 1 = 41 . answer : e" | general |
math_qa__uedsm3napFy49Ni7 | On dividing 13787 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor? Pick:
A) 743
B) 155
C) 852
D) 741
E) 785 | <gadget id="calculator">13_787 - 14</gadget>
<output>13_773</output>
<gadget id="calculator">13_773 / 89</gadget>
<output>13_773/89 = around 154.752809</output>
<result>B</result> | B | 155 | On dividing 13787 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor? | {
"A": "743",
"B": "155",
"C": "852",
"D": "741",
"E": "785"
} | divide(subtract(13787, 14), 89) | subtract(n0,n2)|divide(#0,n1)| | "divisor * quotient + remainder = dividend divisor = ( dividend ) - ( remainder ) / quotient ( 13787 - 14 ) / 89 = 155 answer ( b )" | general |
math_qa__oNeQFCf47TDQCiNn | In a mixture 60 litres, the raƟo of milk and water 2 : 1. If the this raƟo is to be 1 : 2, then the quanity
of water to be further added is Choose the correct choice from the following answers.
A) 20 liters B) 30 liters C) 50 liters D) 60 liters E) none of these | <gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">120 / 3</gadget>
<output>40</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">80 - 20</gadget>
<output>60</output>
<result>D</result> | D | 60 | In a mixture 60 litres, the raƟo of milk and water 2 : 1. If the this raƟo is to be 1 : 2, then the quanity
of water to be further added is | {
"A": "20 liters",
"B": "30 liters",
"C": "50 liters",
"D": "60 liters",
"E": "none of these"
} | subtract(multiply(divide(multiply(60, 2), add(2, 1)), 2), subtract(60, divide(multiply(60, 2), add(2, 1)))) | add(n1,n2)|multiply(n0,n1)|divide(#1,#0)|multiply(n1,#2)|subtract(n0,#2)|subtract(#3,#4) | explanation : quantity of milk = 60 * ( 2 / 3 ) = 40 liters quantity of water = 60 - 40 = 20 liters answer : d | general |
math_qa__MLswYJ3JFfCJGqpg | A scale 6 ft. 8 inches long is divided into 4 equal parts. Find the length of each part Select the correct option.
A) 17 inches B) 20 inches C) 15 inches D) 18 inches E) 19 inches | <gadget id="calculator">6 * 12</gadget>
<output>72</output>
<gadget id="calculator">72 + 8</gadget>
<output>80</output>
<gadget id="calculator">80 / 4</gadget>
<output>20</output>
<result>B</result> | B | 20 | A scale 6 ft. 8 inches long is divided into 4 equal parts. Find the length of each part | {
"A": "17 inches",
"B": "20 inches",
"C": "15 inches",
"D": "18 inches",
"E": "19 inches"
} | divide(add(multiply(6, const_12), 8), 4) | multiply(n0,const_12)|add(n1,#0)|divide(#1,n2)| | "explanation : total length of scale in inches = ( 6 * 12 ) + 8 = 80 inches length of each of the 4 parts = 80 / 4 = 20 inches answer : b" | general |
math_qa__xepGie5o2AMXp0P3 | Ramu bought an old car for Rs. 42000. He spent Rs. 12000 on repairs and sold it for Rs. 64900. What is his profit percent? Pick one.
A) 12 % B) 16 % C) 20.18 % D) 82 % E) 23 % | <gadget id="calculator">42_000 + 12_000</gadget>
<output>54_000</output>
<gadget id="calculator">64_900 - 54_000</gadget>
<output>10_900</output>
<gadget id="calculator">10_900 / 54_000</gadget>
<output>109/540 = around 0.201852</output>
<gadget id="calculator">(109/540) * 100</gadget>
<output>545/27 = around 20.185185</output>
<result>C</result> | C | 20.18 | Ramu bought an old car for Rs. 42000. He spent Rs. 12000 on repairs and sold it for Rs. 64900. What is his profit percent? | {
"A": "12 %",
"B": "16 %",
"C": "20.18 %",
"D": "82 %",
"E": "23 %"
} | multiply(divide(subtract(64900, add(42000, 12000)), add(42000, 12000)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "total cp = rs . 42000 + rs . 12000 = rs . 54000 and sp = rs . 64900 profit ( % ) = ( 64900 - 54000 ) / 54000 * 100 = 20.18 % answer : c" | gain |
math_qa__cFDuLZyNHOlA7C2L | There are 79 people that own pets. 15 people own only dogs, 10 people own only cats, 5 people own only cats and dogs, 3 people own cats, dogs and snakes. How many total snakes are there? Choose the most appropriate option
A) 2 B) 4 C) 8 D) 49 E) 32 | <gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 5</gadget>
<output>30</output>
<gadget id="calculator">30 + 3</gadget>
<output>33</output>
<gadget id="calculator">79 - 33</gadget>
<output>46</output>
<gadget id="calculator">46 + 3</gadget>
<output>49</output>
<result>D</result> | D | 49 | There are 79 people that own pets. 15 people own only dogs, 10 people own only cats, 5 people own only cats and dogs, 3 people own cats, dogs and snakes. How many total snakes are there? | {
"A": "2",
"B": "4",
"C": "8",
"D": "49",
"E": "32"
} | add(subtract(79, add(add(add(15, 10), 5), 3)), 3) | add(n1,n2)|add(n3,#0)|add(n4,#1)|subtract(n0,#2)|add(n4,#3) | lets assign variables to all the areas in venn diagram of three . three different units are dog , cat , snake = total = 79 only dog = d = 15 only cat = c = 10 only snake = s exactly dog and cat = 5 exactly dog and snake = x exactly cat and snake = y all three = 3 so 79 = 15 + 10 + 5 + 3 + x + y + s we need to know total snakes = x + y + s + 3 = 49 answer : d | general |
math_qa__qjpORAmaUX8opcsr | A man traveled a total distance of 900 km. He traveled one-third of the whole trip by plane and the distance traveled by train is two-thirds of the distance traveled by bus. If he traveled by train, plane and bus, how many kilometers did he travel by bus? Choices:
A) 240
B) 280
C) 320
D) 360
E) 400 | <gadget id="calculator">900 * 2</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 3</gadget>
<output>600</output>
<gadget id="calculator">600 * 3</gadget>
<output>1_800</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">1_800 / 5</gadget>
<output>360</output>
<result>D</result> | D | 360 | A man traveled a total distance of 900 km. He traveled one-third of the whole trip by plane and the distance traveled by train is two-thirds of the distance traveled by bus. If he traveled by train, plane and bus, how many kilometers did he travel by bus? | {
"A": "240",
"B": "280",
"C": "320",
"D": "360",
"E": "400"
} | divide(multiply(divide(multiply(900, const_2), const_3), const_3), add(const_2, const_3)) | add(const_2,const_3)|multiply(n0,const_2)|divide(#1,const_3)|multiply(#2,const_3)|divide(#3,#0)| | "total distance traveled = 900 km . distance traveled by plane = 300 km . distance traveled by bus = x distance traveled by train = 2 x / 3 x + 2 x / 3 + 300 = 900 5 x / 3 = 600 x = 360 km the answer is d ." | physics |
math_qa__IJRsXhfx5KhrKb66 | The cash difference between the selling prices of an article at a profit of 2% and 6% is Rs. 3. The ratio of the two selling prices is?
Choose one
A) 52 : 56
B) 52 : 53
C) 52 : 50
D) 22 : 56
E) 51 : 53 | <gadget id="calculator">100 + 2</gadget>
<output>102</output>
<gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">102 / 106</gadget>
<output>51/53 = around 0.962264</output>
<result>E</result> | E | 0.962264 | The cash difference between the selling prices of an article at a profit of 2% and 6% is Rs. 3. The ratio of the two selling prices is? | {
"A": "52 : 56",
"B": "52 : 53",
"C": "52 : 50",
"D": "22 : 56",
"E": "51 : 53"
} | divide(add(const_100, 2), add(const_100, 6)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)| | "let c . p . of the article be rs . x . then , required ratio = 102 % of x / 106 % of x = 102 / 106 = 51 / 53 = 51 : 53 answer : e" | gain |
math_qa__v0o7G2wDx9rGZj9x | Two pipes can fill the cistern in 10hr and 12 hr respectively, while the third empty it in 15hr. If all pipes are opened simultaneously, then the cistern will be filled in Choose the correct answer:
A) 7.5 hr B) 8 hr C) 8.57 hr D) 10 hr E) none of these | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/10) + (1/12)</gadget>
<output>11/60 = around 0.183333</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(11/60) - (1/15)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">1 / (7/60)</gadget>
<output>60/7 = around 8.571429</output>
<result>C</result> | C | 8.57 | Two pipes can fill the cistern in 10hr and 12 hr respectively, while the third empty it in 15hr. If all pipes are opened simultaneously, then the cistern will be filled in | {
"A": "7.5 hr",
"B": "8 hr",
"C": "8.57 hr",
"D": "10 hr",
"E": "none of these"
} | inverse(subtract(add(divide(const_1, 10), divide(const_1, 12)), divide(const_1, 15))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|subtract(#3,#2)|inverse(#4)| | "solution : work done by all the tanks working together in 1 hour . 1 / 10 + 1 / 12 − 1 / 15 = 7 / 60 hence , tank will be filled in 60 / 7 = 8.57 hour option ( c )" | physics |
math_qa__5kPEFA0PRSf2BjHD | In what time will a railway train 65 m long moving at the rate of 32 kmph pass a telegraph post on its way? Choose the correct choice from the following.
A) 3 sec B) 4 sec C) 5 sec D) 6 sec E) 7 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">32 * (5/18)</gadget>
<output>80/9 = around 8.888889</output>
<gadget id="calculator">65 / (80/9)</gadget>
<output>117/16 = around 7.3125</output>
<result>E</result> | E | 7 | In what time will a railway train 65 m long moving at the rate of 32 kmph pass a telegraph post on its way? | {
"A": "3 sec",
"B": "4 sec",
"C": "5 sec",
"D": "6 sec",
"E": "7 sec"
} | divide(65, multiply(32, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 65 / 32 * 18 / 5 = 7 sec answer : e" | physics |
math_qa__raFVUeu7jNwmUucz | A rectangular grass field is 75 m * 55 m, it has a path of 2.8 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m? Choose the correct choice from the following choices.
A) s . 1518.8
B) s . 1327
C) s . 1328
D) s . 1397
E) s . 1927 | <gadget id="calculator">2.8 * 2</gadget>
<output>5.6</output>
<gadget id="calculator">75 + 5.6</gadget>
<output>80.6</output>
<gadget id="calculator">55 + 5.6</gadget>
<output>60.6</output>
<gadget id="calculator">80.6 * 60.6</gadget>
<output>4_884.36</output>
<gadget id="calculator">75 * 55</gadget>
<output>4_125</output>
<gadget id="calculator">4_884.36 - 4_125</gadget>
<output>759.36</output>
<gadget id="calculator">759.36 * 2</gadget>
<output>1_518.72</output>
<result>A</result> | A | 1,518.8 | A rectangular grass field is 75 m * 55 m, it has a path of 2.8 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m? | {
"A": "s . 1518.8",
"B": "s . 1327",
"C": "s . 1328",
"D": "s . 1397",
"E": "s . 1927"
} | multiply(subtract(rectangle_area(add(75, multiply(2.8, 2)), add(55, multiply(2.8, 2))), rectangle_area(75, 55)), 2) | multiply(n2,n3)|rectangle_area(n0,n1)|add(n0,#0)|add(n1,#0)|rectangle_area(#2,#3)|subtract(#4,#1)|multiply(n3,#5)| | "area = ( l + b + 2 d ) 2 d = ( 75 + 55 + 2.8 * 2 ) 2 * 2.8 = > 759.4 759.4 * 2 = rs . 1518.8 answer : a" | geometry |
math_qa__QPHPbt85dYPngzym | The rational number for recurring decimal 0.125125.... is: Choose the correct choice:
A) 125 / 990
B) 125 / 999
C) 125 / 900
D) 12 / 999
E) 12 / 990 | <gadget id="calculator">0.125125 * 1_000</gadget>
<output>125.125</output>
<gadget id="calculator">floor(125.125)</gadget>
<output>125</output>
<gadget id="calculator">1 + 10</gadget>
<output>11</output>
<gadget id="calculator">11 * 10</gadget>
<output>110</output>
<gadget id="calculator">110 + 1</gadget>
<output>111</output>
<gadget id="calculator">111 * 3</gadget>
<output>333</output>
<gadget id="calculator">333 * 3</gadget>
<output>999</output>
<gadget id="calculator">125 / 999</gadget>
<output>125/999 = around 0.125125</output>
<result>B</result> | B | 0.125125 | The rational number for recurring decimal 0.125125.... is: | {
"A": "125 / 990",
"B": "125 / 999",
"C": "125 / 900",
"D": "12 / 999",
"E": "12 / 990"
} | divide(floor(multiply(0.125125, const_1000)), multiply(multiply(add(multiply(add(const_1, const_10), const_10), const_1), const_3), const_3)) | add(const_1,const_10)|multiply(n0,const_1000)|floor(#1)|multiply(#0,const_10)|add(#3,const_1)|multiply(#4,const_3)|multiply(#5,const_3)|divide(#2,#6) | 0.125125 . . . = 0.125 = 125 / 999 answer is b . | other |
math_qa__eJ8DzIqWPqWhSGgX | 3 candidates in an election and received 1136, 8236 and 11628 votes respectively. What % of the total votes did the winning candidate gotin that election? Select
A) 40 %
B) 55.4 %
C) 57 %
D) 60 %
E) 62 % | <gadget id="calculator">1_136 + 8_236</gadget>
<output>9_372</output>
<gadget id="calculator">9_372 + 11_628</gadget>
<output>21_000</output>
<gadget id="calculator">11_628 / 21_000</gadget>
<output>969/1_750 = around 0.553714</output>
<gadget id="calculator">(969/1_750) * 100</gadget>
<output>1_938/35 = around 55.371429</output>
<result>B</result> | B | 55.4 | 3 candidates in an election and received 1136, 8236 and 11628 votes respectively. What % of the total votes did the winning candidate gotin that election? | {
"A": "40 %",
"B": "55.4 %",
"C": "57 %",
"D": "60 %",
"E": "62 %"
} | multiply(divide(11628, add(add(1136, 8236), 11628)), const_100) | add(n1,n2)|add(n3,#0)|divide(n3,#1)|multiply(#2,const_100)| | "total number of votes polled = ( 1136 + 8236 + 11628 ) = 21000 so , required percentage = 11628 / 21000 * 100 = 55.4 % b" | gain |
math_qa__FCDO4p5UTPhIkG4K | If 12 men or 20 women can do a piece of work in 81 days, then in how many days can 9 men and 12 women together do the work? Choose the correct choice from the following:
A) 10 days B) 30 days C) 20 days D) 60 days E) 40 days | <gadget id="calculator">12 * 81</gadget>
<output>972</output>
<gadget id="calculator">9 / 972</gadget>
<output>1/108 = around 0.009259</output>
<gadget id="calculator">20 * 81</gadget>
<output>1_620</output>
<gadget id="calculator">12 / 1_620</gadget>
<output>1/135 = around 0.007407</output>
<gadget id="calculator">(1/108) + (1/135)</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">1 / (1/60)</gadget>
<output>60</output>
<result>D</result> | D | 60 | If 12 men or 20 women can do a piece of work in 81 days, then in how many days can 9 men and 12 women together do the work? | {
"A": "10 days",
"B": "30 days",
"C": "20 days",
"D": "60 days",
"E": "40 days"
} | inverse(add(divide(9, multiply(12, 81)), divide(12, multiply(20, 81)))) | multiply(n0,n2)|multiply(n1,n2)|divide(n3,#0)|divide(n4,#1)|add(#2,#3)|inverse(#4)| | "d 60 days given that 12 m = 20 w = > 3 m = 5 w 9 men + 12 women = 15 women + 12 women = 27 women 20 women can do the work in 81 days . so , 27 women can do it in ( 20 * 81 ) / 27 = 60 days ." | physics |
math_qa__qCcvlbVoqZWiSVFi | Increasing the original price of an article by 15 percent and then increasing the new price by 15 percent is equivalent to increasing the original price by Choose the correct option.
A) 32.25 %
B) 31.00 %
C) 30.25 %
D) 30.00 %
E) 22.50 % | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(23/20) * (23/20)</gadget>
<output>529/400 = around 1.3225</output>
<gadget id="calculator">(529/400) - 1</gadget>
<output>129/400 = around 0.3225</output>
<gadget id="calculator">100 * (129/400)</gadget>
<output>129/4 = around 32.25</output>
<result>A</result> | A | 32.25 | Increasing the original price of an article by 15 percent and then increasing the new price by 15 percent is equivalent to increasing the original price by | {
"A": "32.25 %",
"B": "31.00 %",
"C": "30.25 %",
"D": "30.00 %",
"E": "22.50 %"
} | multiply(const_100, subtract(multiply(add(const_1, divide(15, const_100)), add(const_1, divide(15, const_100))), const_1)) | divide(n0,const_100)|add(#0,const_1)|multiply(#1,#1)|subtract(#2,const_1)|multiply(#3,const_100)| | "you can do this by approximation , or with straight math by calculating 100 * 1.15 ^ 2 . or step by step : if you increase 100 by 15 % you ' ll get 115 , then if you increase 115 = 100 + 15 by 15 % again , 100 will gain 15 again and 15 will gain its 15 % which is 2.25 , so total gain is 15 + 2.25 = 17.25 - - > 115 + 17.25 = 132.25 . answer : a ." | gain |
math_qa__zecQVYLjfByeGi2k | A merchant purchased a jacket for $48 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 40 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale? Pick one.
A) $ 0 B) $ 3 C) $ 4 D) $ 12 E) $ 16 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">48 / (3/5)</gadget>
<output>80</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">80 * (4/5)</gadget>
<output>64</output>
<gadget id="calculator">64 - 48</gadget>
<output>16</output>
<result>E</result> | E | 16 | A merchant purchased a jacket for $48 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 40 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale? | {
"A": "$ 0",
"B": "$ 3",
"C": "$ 4",
"D": "$ 12",
"E": "$ 16"
} | subtract(multiply(divide(48, subtract(const_1, divide(40, const_100))), subtract(const_1, divide(20, const_100))), 48) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|divide(n0,#2)|multiply(#4,#3)|subtract(#5,n0)| | "actual cost = $ 48 sp = actual cost + mark up = actual cost + 40 % sp = 48 * 100 / 60 on sale sp = 80 / 100 ( 48 * 100 / 60 ) = 64 gross profit = $ 16 answer is e" | gain |
math_qa__zQtzXB9KFxPL7GQO | Pascal has 96 miles remaining to complete his cycling trip. If he reduced his current speed by 4 miles per hour, the remainder of the trip would take him 16 hours longer than it would if he increased his speed by 50%. What is his current speed O?
Select the correct option.
A) 6 B) 8 C) 10 D) 12 E) 16 | <gadget id="calculator">96 / 16</gadget>
<output>6</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 / (3/2)</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 4</gadget>
<output>64</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">64 + 36</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | Pascal has 96 miles remaining to complete his cycling trip. If he reduced his current speed by 4 miles per hour, the remainder of the trip would take him 16 hours longer than it would if he increased his speed by 50%. What is his current speed O? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "16"
} | divide(add(divide(96, 16), sqrt(add(multiply(multiply(divide(divide(96, 16), add(const_1, divide(50, const_100))), 4), const_4), power(divide(96, 16), const_2)))), const_2) | divide(n0,n2)|divide(n3,const_100)|add(#1,const_1)|power(#0,const_2)|divide(#0,#2)|multiply(n1,#4)|multiply(#5,const_4)|add(#6,#3)|sqrt(#7)|add(#0,#8)|divide(#9,const_2) | let the current speed be x miles per hour . time taken if speed is 50 % faster ( i . e . 3 x / 2 = 1.5 x ) = 96 / 1.5 x time taken if speed is reduced by 4 miles / hr ( i . e . ( x - 4 ) ) = 96 / ( x - 4 ) as per question , 96 / ( x - 4 ) - 96 / 1.5 x = 16 solving this o we get x = 8 . b . | physics |
math_qa__DsH329tW8XsomFfE | In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of the sport formulation contains 6 ounces of corn syrup, how many ounces of water does it contain?
Pick: A) 45 B) 50 C) 55 D) 60 E) 90 | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 3</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) / 2</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/4) / (1/60)</gadget>
<output>15</output>
<gadget id="calculator">15 * 6</gadget>
<output>90</output>
<result>E</result> | E | 90 | In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of the sport formulation contains 6 ounces of corn syrup, how many ounces of water does it contain? | {
"A": "45",
"B": "50",
"C": "55",
"D": "60",
"E": "90"
} | multiply(divide(multiply(divide(1, 12), const_3), divide(divide(1, 30), const_2)), 6) | divide(n0,n1)|divide(n0,n2)|divide(#1,const_2)|multiply(#0,const_3)|divide(#3,#2)|multiply(n3,#4)| | "f : c : w 1 : 12 : 30 sport version : f : c 3 : 12 f : w 1 : 60 or 3 : 180 so c : f : w = 12 : 3 : 180 c / w = 12 / 180 = 3 ounces / x ounces x = 6 * 180 / 12 = 90 ounces of water e" | other |
math_qa__nepViNsNYoj3vXfb | A circular logo is enlarged to fit the lid of a jar. The new diameter is 60 per cent larger than the original. By what percentage has the area of the logo increased? Choose the correct answer
A) 50 B) 80 C) 100 D) 143.36 E) 250 | <gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">120 / 1_000</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 3</gadget>
<output>78/25 = around 3.12</output>
<gadget id="calculator">(78/25) ** 2</gadget>
<output>6_084/625 = around 9.7344</output>
<gadget id="calculator">(6_084/625) - 4</gadget>
<output>3_584/625 = around 5.7344</output>
<gadget id="calculator">(3_584/625) / 4</gadget>
<output>896/625 = around 1.4336</output>
<gadget id="calculator">(896/625) * 100</gadget>
<output>3_584/25 = around 143.36</output>
<result>D</result> | D | 143.36 | A circular logo is enlarged to fit the lid of a jar. The new diameter is 60 per cent larger than the original. By what percentage has the area of the logo increased? | {
"A": "50",
"B": "80",
"C": "100",
"D": "143.36",
"E": "250"
} | multiply(divide(subtract(power(add(divide(multiply(60, const_2), const_1000), const_3), const_2), const_4), const_4), const_100) | multiply(n0,const_2)|divide(#0,const_1000)|add(#1,const_3)|power(#2,const_2)|subtract(#3,const_4)|divide(#4,const_4)|multiply(#5,const_100) | let old diameter be 4 , so radius is 2 old area = 4 π new diameter is 6.24 , so radius is 3.12 new area = 9.7344 π increase in area is 5.7344 π % increase in area = 5.7344 / 4 * 100 so , % increase is 143.36 % answer will be ( d ) | geometry |
math_qa__1OpYK9p1IZD7BI5l | If 4 men working 10 hours a day earn Rs. 1000 per week, then 9 men working 6 hours a day will earn how much per week? Choose the correct choice
A) rs 840 B) rs 1350 C) rs 1620 D) rs 1680 E) none of these | <gadget id="calculator">9 * 6</gadget>
<output>54</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">54 / 40</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">(27/20) * 1_000</gadget>
<output>1_350</output>
<result>B</result> | B | 1,350 | If 4 men working 10 hours a day earn Rs. 1000 per week, then 9 men working 6 hours a day will earn how much per week? | {
"A": "rs 840",
"B": "rs 1350",
"C": "rs 1620",
"D": "rs 1680",
"E": "none of these"
} | multiply(divide(multiply(9, 6), multiply(4, 10)), 1000) | multiply(n3,n4)|multiply(n0,n1)|divide(#0,#1)|multiply(n2,#2) | explanation : ( men 4 : 9 ) : ( hrs / day 10 : 6 ) : : 1000 : x hence 4 * 10 * x = 9 * 6 * 1000 or x = 9 * 6 * 1000 / 4 * 10 = 1350 answer : b | physics |
math_qa__86Wpy9ER7KkGYOz2 | The ages of two person differ by 20 years. If 10 years ago, the elder one be 5 times as old as the younger one, their present ages(in years) are respectively Choose the correct choice from the following answers:
A) 30 , 10 B) 25 , 5 C) 29 , 9 D) 35 , 15 E) 20,10 | <gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">50 + 10</gadget>
<output>60</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<gadget id="calculator">15 + 20</gadget>
<output>35</output>
<result>D</result> | D | 35 | The ages of two person differ by 20 years. If 10 years ago, the elder one be 5 times as old as the younger one, their present ages(in years) are respectively | {
"A": "30 , 10",
"B": "25 , 5",
"C": "29 , 9",
"D": "35 , 15",
"E": "20,10"
} | add(divide(add(multiply(5, 10), subtract(20, 10)), subtract(5, const_1)), 20) | multiply(n1,n2)|subtract(n0,n1)|subtract(n2,const_1)|add(#0,#1)|divide(#3,#2)|add(n0,#4)| | "let their ages be x and ( x + 20 ) years . then , 5 ( x - 10 ) = ( x + 20 - 10 ) = > 4 x = 60 = > x = 15 their present ages are 35 years and 15 year . answer : d" | general |
math_qa__Oa2Mz2swXkOpHj4v | In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate?
Choose the correct choice from the following
A) 358000
B) 368000
C) 357000
D) 358000
E) 367000 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">560_000 * (17/20)</gadget>
<output>476_000</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">476_000 * (3/4)</gadget>
<output>357_000</output>
<result>C</result> | C | 357,000 | In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate? | {
"A": "358000",
"B": "368000",
"C": "357000",
"D": "358000",
"E": "367000"
} | multiply(multiply(560000, subtract(const_1, divide(15, const_100))), divide(75, const_100)) | divide(n0,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(n2,#2)|multiply(#0,#3)| | "total number of invalid votes = 15 % of 560000 = 15 / 100 × 560000 = 8400000 / 100 = 84000 total number of valid votes 560000 – 84000 = 476000 percentage of votes polled in favour of candidate a = 75 % therefore , the number of valid votes polled in favour of candidate a = 75 % of 476000 = 75 / 100 × 476000 = 35700000 / 100 = 357000 answer : c" | gain |
math_qa__6IZX97QXyIm1R0km | If both 112 and 33 are factors of the number a * 43 * 62 * 1311, then what is the smallest possible value of a? Choices.
A) 121 B) 3267 C) 363 D) 33 E) none of the above | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 ** 2</gadget>
<output>121</output>
<gadget id="calculator">33 - 3</gadget>
<output>30</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<gadget id="calculator">lcm(121, 3)</gadget>
<output>363</output>
<result>C</result> | C | 363 | If both 112 and 33 are factors of the number a * 43 * 62 * 1311, then what is the smallest possible value of a? | {
"A": "121",
"B": "3267",
"C": "363",
"D": "33",
"E": "none of the above"
} | lcm(power(add(const_10, const_1), const_2), divide(subtract(33, const_3), const_10)) | add(const_1,const_10)|subtract(n1,const_3)|divide(#1,const_10)|power(#0,const_2)|lcm(#2,#3) | explanatory answer step 1 : prime factorize the given expression a * 43 * 62 * 1311 can be expressed in terms of its prime factors as a * 28 * 32 * 1311 step 2 : find factors missing after excluding ' a ' to make the number divisible by both 112 and 33 112 is a factor of the given number . if we do not include ' a ' , 11 is not a prime factor of the given number . if 112 is a factor of the number , 112 should have been in ' a ' 33 is a factor of the given number . if we do not include ' a ' , the number has only 32 in it . therefore , if 33 has to be a factor of the given number ' a ' has to contain 31 in it . therefore , ' a ' should be at least 112 * 3 = 363 if the given number has 112 and 33 as its factors . the smallest value that ` ` a ' ' can take is 363 . choice c is the correct answer . | other |
math_qa__W92nRAF4ti2w48pg | Two isosceles Triangles have equal vertical angles and their areas are in the ratio 9:25. Find the ratio of their corresponding heights . Choose the correct option.
A) 4 / 5
B) 5 / 4
C) 3 / 2
D) 5 / 7
E) 3 / 5 | <gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<result>E</result> | E | 0.6 | Two isosceles Triangles have equal vertical angles and their areas are in the ratio 9:25. Find the ratio of their corresponding heights . | {
"A": "4 / 5",
"B": "5 / 4",
"C": "3 / 2",
"D": "5 / 7",
"E": "3 / 5"
} | divide(sqrt(9), sqrt(25)) | sqrt(n0)|sqrt(n1)|divide(#0,#1)| | "we are basically given that the triangles are similar . in two similar triangles , the ratio of their areas is the square of the ratio of their sides and also , the square of the ratio of their corresponding heights . therefore , area / area = height ^ 2 / height ^ 2 = 9 / 25 - - > height / height = 3 / 5 . answer : e ." | geometry |
math_qa__cHQOpeuS67oH8LSt | A straight line in the xy- plane has y-intercept of 20 . On this line the x-coordinate of the point is 150 and y-coordinate is 600 then what is the slope of the line? Options
A) 3.9 B) 4.6 C) 5.2 D) 6 E) 8.1 | <gadget id="calculator">600 - 20</gadget>
<output>580</output>
<gadget id="calculator">580 / 150</gadget>
<output>58/15 = around 3.866667</output>
<result>A</result> | A | 3.9 | A straight line in the xy- plane has y-intercept of 20 . On this line the x-coordinate of the point is 150 and y-coordinate is 600 then what is the slope of the line? | {
"A": "3.9",
"B": "4.6",
"C": "5.2",
"D": "6",
"E": "8.1"
} | divide(subtract(600, 20), 150) | subtract(n2,n0)|divide(#0,n1)| | "eq of line = y = mx + c c = 20 x = 150 y = 150 m + 20 , substitute y by 600 as given in question . 600 = 150 m + 20 , m = 3.9 correct option is a" | general |
math_qa__FTnv76WcmAzPJZjW | A case contains c cartons. Each carton contains b boxes, and each box contains 400 paper clips. How many paper clips are contained in 2 cases? Select
A) 400 bc B) 400 b / c C) 800 bc D) 800 b / c E) 800 / bc | <gadget id="calculator">2 * 400</gadget>
<output>800</output>
<result>C</result> | C | 800 | A case contains c cartons. Each carton contains b boxes, and each box contains 400 paper clips. How many paper clips are contained in 2 cases? | {
"A": "400 bc",
"B": "400 b / c",
"C": "800 bc",
"D": "800 b / c",
"E": "800 / bc"
} | multiply(2, 400) | multiply(n0,n1)| | "2 cases * c cartons / case * b boxes / carton * 400 clips / box = 800 bc paper clips the answer is c ." | general |
math_qa__dXRHQXTyQMt5TSw2 | Mohit sold an article for $15000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? Choices:
A) 12500 B) 25000 C) 15000 D) 18000 E) 17000 | <gadget id="calculator">15_000 * 10</gadget>
<output>150_000</output>
<gadget id="calculator">150_000 / 100</gadget>
<output>1_500</output>
<gadget id="calculator">15_000 - 1_500</gadget>
<output>13_500</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">13_500 / 108</gadget>
<output>125</output>
<gadget id="calculator">125 * 100</gadget>
<output>12_500</output>
<result>A</result> | A | 12,500 | Mohit sold an article for $15000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? | {
"A": "12500",
"B": "25000",
"C": "15000",
"D": "18000",
"E": "17000"
} | multiply(divide(subtract(15000, divide(multiply(15000, 10), const_100)), add(const_100, 8)), const_100) | add(n2,const_100)|multiply(n0,n1)|divide(#1,const_100)|subtract(n0,#2)|divide(#3,#0)|multiply(#4,const_100)| | "let the cp be $ x . had he offered 10 % discount , profit = 8 % profit = 8 / 100 x and hence his sp = x + 8 / 100 x = $ 1.08 x = 15000 - 10 / 100 ( 15000 ) = 15000 - 1500 = $ 13500 = > 1.08 x = 13500 = > x = 12500 a" | gain |
math_qa__tVVFLJjsnZoEuW0S | A number increased by 20% gives 480. The number is? Choose the correct choice from the following
A) 200
B) 300
C) 400
D) 500
E) 600 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">480 / (6/5)</gadget>
<output>400</output>
<result>C</result> | C | 400 | A number increased by 20% gives 480. The number is? | {
"A": "200",
"B": "300",
"C": "400",
"D": "500",
"E": "600"
} | divide(480, add(const_1, divide(20, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1) | formula = total = 100 % , increase = ` ` + ' ' decrease = ` ` - ' ' a number means = 100 % that same number increased by 20 % = 120 % 120 % - - - - - - - > 480 ( 120 × 4 = 480 ) 100 % - - - - - - - > 400 ( 100 × 4 = 400 ) option ' c ' | gain |
math_qa__snX8bEdgLwqU7zIV | What least number should be added to 1052, so that the sum is completely divisible by 23 Choose the correct choice from the following answers.
A) 4 B) 1 C) 6 D) 3 E) 5 | <gadget id="calculator">1_052 % 23</gadget>
<output>17</output>
<gadget id="calculator">23 - 17</gadget>
<output>6</output>
<result>C</result> | C | 6 | What least number should be added to 1052, so that the sum is completely divisible by 23 | {
"A": "4",
"B": "1",
"C": "6",
"D": "3",
"E": "5"
} | subtract(23, reminder(1052, 23)) | reminder(n0,n1)|subtract(n1,#0)| | "explanation : ( 1052 / 23 ) gives remainder 17 17 + 6 = 23 , so we need to add 6 answer : option c" | general |
math_qa__PBUxVHzEKg4uX0Dx | Ramesh purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 16% if no discount was offered? Pick one:
A) 17608 B) 17606 C) 17604 D) 17600 E) 18560 | <gadget id="calculator">100 + 16</gadget>
<output>116</output>
<gadget id="calculator">12_500 * 100</gadget>
<output>1_250_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">1_250_000 / 80</gadget>
<output>15_625</output>
<gadget id="calculator">125 + 250</gadget>
<output>375</output>
<gadget id="calculator">15_625 + 375</gadget>
<output>16_000</output>
<gadget id="calculator">116 * 16_000</gadget>
<output>1_856_000</output>
<gadget id="calculator">1_856_000 / 100</gadget>
<output>18_560</output>
<result>E</result> | E | 18,560 | Ramesh purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 16% if no discount was offered? | {
"A": "17608",
"B": "17606",
"C": "17604",
"D": "17600",
"E": "18560"
} | divide(multiply(add(const_100, 16), add(divide(multiply(12500, const_100), subtract(const_100, 20)), add(125, 250))), const_100) | add(n4,const_100)|add(n2,n3)|multiply(n0,const_100)|subtract(const_100,n1)|divide(#2,#3)|add(#1,#4)|multiply(#0,#5)|divide(#6,const_100) | price at which the tv set is bought = rs . 12,500 discount offered = 20 % marked price = 12500 * 100 / 80 = rs . 15625 the total amount spent on transport and installation = 125 + 250 = rs . 375 \ total price of tv set = 15625 + 375 = rs . 16000 the price at which the tv should be sold to get a profit of 16 % if no discount was offered = 16000 * 116 / 100 = rs . 18560 . answer : e | gain |
math_qa__EpgDczK9zI0Mv1KV | A certain taxi company charges $3.00 for the first 1/5 of a mile plus $0.40 for each additional 1/5 of a mile. What would this company charge for a taxi ride that was 8 miles long? Choose the correct choice
A) 15.6 B) 16.0 C) 17.5 D) 18.6 E) 19.1 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">8 / (1/5)</gadget>
<output>40</output>
<gadget id="calculator">40 - 1</gadget>
<output>39</output>
<gadget id="calculator">39 * 0.4</gadget>
<output>15.6</output>
<gadget id="calculator">3 + 15.6</gadget>
<output>18.6</output>
<result>D</result> | D | 18.6 | A certain taxi company charges $3.00 for the first 1/5 of a mile plus $0.40 for each additional 1/5 of a mile. What would this company charge for a taxi ride that was 8 miles long? | {
"A": "15.6",
"B": "16.0",
"C": "17.5",
"D": "18.6",
"E": "19.1"
} | add(3.00, multiply(subtract(divide(8, divide(1, 5)), 1), 0.40)) | divide(n1,n2)|divide(n6,#0)|subtract(#1,n1)|multiply(n3,#2)|add(n0,#3)| | "a certain taxi company charges $ 3.00 for the first 1 / 5 of a mile plus $ 0.40 for each additional 1 / 5 of a mile . what would this company charge for a taxi ride that was 8 miles long ? a . 15.60 b . 16.00 c . 17.50 d . 18.70 e . 19.10 1 / 5 miles = 0.2 miles . the cost of 8 miles long ride would be $ 3.00 for the first 0.2 miles plus ( 8 - 0.2 ) / 0.2 * 0.4 = $ 3.0 + $ 15.6 = $ 18.6 . answer : d ." | general |
math_qa__LOFvshIRLgUgASlG | the sum of 3 consecutive even numbers is 246 . what are the numbers ? Choices:
A) 80 , 8284
B) 65 , 6871
C) 45 , 4742
D) 100 , 10249
E) 87 , 8889 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">246 - 6</gadget>
<output>240</output>
<gadget id="calculator">240 / 3</gadget>
<output>80</output>
<result>A</result> | A | 80 | the sum of 3 consecutive even numbers is 246 . what are the numbers ? | {
"A": "80 , 8284",
"B": "65 , 6871",
"C": "45 , 4742",
"D": "100 , 10249",
"E": "87 , 8889"
} | divide(subtract(246, add(const_2, const_4)), 3) | add(const_2,const_4)|subtract(n1,#0)|divide(#1,n0) | first x make the first x second x + 2 even numbers , sowe add 2 to get the next third x + 4 add 2 more ( 4 total ) to get the third f + s + t = 246 summeansaddfirst ( f ) plussecond ( s ) plusthird ( t ) ( x ) + ( x + 2 ) + ( x + 4 ) = 246 replace each f , s , and t withwhatwe labeled them x + x + 2 + x + 4 = 246 here the parenthesis are not needed 3 x + 6 = 246 combine like terms x + x + x and 2 + 4 − 6 − 6 subtract 6 fromboth sides 3 x = 240 the variable ismultiplied by 3 3 3 divide both sides by 3 x = 80 our solution for x first 80 replace x in the origional listwith 80 . second ( 80 ) + 2 = 82 the numbers are 80 , 82 , and 84 . third ( 80 ) + 4 = 84 correct answer a | physics |
math_qa__taMNLqZjlz9p6c8d | If 4 men can colour 48 m long cloth in 2 days, then 6 men can colour 36 m long cloth in Pick:
A) 1 day B) 2 days C) 3 days D) 4 days E) 5 days | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">36 / 36</gadget>
<output>1</output>
<result>A</result> | A | 1 | If 4 men can colour 48 m long cloth in 2 days, then 6 men can colour 36 m long cloth in | {
"A": "1 day",
"B": "2 days",
"C": "3 days",
"D": "4 days",
"E": "5 days"
} | divide(36, multiply(divide(48, multiply(4, 2)), 6)) | multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2)| | "the length of cloth painted by one man in one day = 48 / 4 × 2 = 6 m no . of days required to paint 36 m cloth by 6 men = 36 / 6 × 6 = 1 day . a" | physics |
math_qa__e3FkmD9pCU3bbT1D | The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 40 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?
Choose the correct choice
A) 75.00 % B) 56.80 % C) 110 % D) 150 % E) 180 % | <gadget id="calculator">100 / 100</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 40</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">2 + (4/5)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(14/5) ** 2</gadget>
<output>196/25 = around 7.84</output>
<gadget id="calculator">(196/25) - 1</gadget>
<output>171/25 = around 6.84</output>
<gadget id="calculator">(171/25) - 4</gadget>
<output>71/25 = around 2.84</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">(71/25) / 5</gadget>
<output>71/125 = around 0.568</output>
<gadget id="calculator">(71/125) * 100</gadget>
<output>284/5 = around 56.8</output>
<result>B</result> | B | 56.8 | The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 40 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B? | {
"A": "75.00 %",
"B": "56.80 %",
"C": "110 %",
"D": "150 %",
"E": "180 %"
} | multiply(divide(subtract(subtract(square_area(add(add(const_1, divide(100, 100)), divide(multiply(add(const_1, divide(100, 100)), 40), 100))), const_1), const_4), add(const_1, square_area(add(const_1, divide(100, 100))))), 100) | divide(n0,n0)|add(#0,const_1)|multiply(n1,#1)|square_area(#1)|add(#3,const_1)|divide(#2,n0)|add(#1,#5)|square_area(#6)|subtract(#7,const_1)|subtract(#8,const_4)|divide(#9,#4)|multiply(n0,#10) | let length of each side of square a be 10 area of a = 10 ^ 2 = 100 since , length of each side of square a is increased by 100 percent to make square b length of each side of square b = 2 * 10 = 20 area of b = 20 ^ 2 = 400 since , length of the side of square b is increased by 40 percent to make square c length of each side of square c = 1.4 * 20 = 28 area of c = 28 ^ 2 = 784 difference in areas of c and cummulative areas of a and b = 784 - ( 400 + 100 ) = 284 percent is the area of square c greater than the sum of the areas of squares a and b = ( 284 / 500 ) * 100 % = 56.80 % answer b | geometry |
math_qa__IkTOkgOU71jBzi8g | A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $228 for it, the cost price of the Cricket Bat for A is: Choose the correct choice from the following answers:
A) 152 B) 120 C) 130 D) 160 E) 210 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(6/5) * (5/4)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">228 / (3/2)</gadget>
<output>152</output>
<result>A</result> | A | 152 | A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $228 for it, the cost price of the Cricket Bat for A is: | {
"A": "152",
"B": "120",
"C": "130",
"D": "160",
"E": "210"
} | divide(228, multiply(add(const_1, divide(20, const_100)), add(const_1, divide(25, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|divide(n2,#4)| | "a 152 125 % of 120 % of a = 228 125 / 100 * 120 / 100 * a = 228 a = 228 * 2 / 3 = 152 ." | gain |
math_qa__M5tlte1bZlBgtD5L | By weight, liquid X makes up 0.8 percent of solution A and 1.8 percent of solution B. If 300 grams of solution A are mixed with 700 grams of solution B, then liquid X accounts for what percent of the weight of the resulting solution? Choose the correct choice from the following answers.
A) 1.5 % B) 1.9 % C) 10 % D) 15 % E) 19 % | <gadget id="calculator">300 * 0.8</gadget>
<output>240</output>
<gadget id="calculator">700 * 1.8</gadget>
<output>1_260</output>
<gadget id="calculator">240 + 1_260</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 1_000</gadget>
<output>3/2 = around 1.5</output>
<result>A</result> | A | 1.5 | By weight, liquid X makes up 0.8 percent of solution A and 1.8 percent of solution B. If 300 grams of solution A are mixed with 700 grams of solution B, then liquid X accounts for what percent of the weight of the resulting solution? | {
"A": "1.5 %",
"B": "1.9 %",
"C": "10 %",
"D": "15 %",
"E": "19 %"
} | divide(add(multiply(300, 0.8), multiply(700, 1.8)), const_1000) | multiply(n0,n2)|multiply(n1,n3)|add(#0,#1)|divide(#2,const_1000)| | "i think there is a typo in question . it should have been ` ` by weight liquid ' x ' makes up . . . . . ` ` weight of liquid x = 0.8 % of weight of a + 1.8 % of weight of b when 300 gms of a and 700 gms of b is mixed : weight of liquid x = ( 0.8 * 300 ) / 100 + ( 1.8 * 700 ) / 100 = 15 gms % of liquid x in resultant mixture = ( 15 / 1000 ) * 100 = 1.5 % answer : 1.5 % answer : a" | gain |
math_qa__omAJauSneUukcLG5 | Two pipes A and B can fill a tank in 10hour and 15 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank? Select:
A) 2 hrs B) 6 hrs C) 5 hrs D) 4 hrs E) 1 hr | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>B</result> | B | 6 | Two pipes A and B can fill a tank in 10hour and 15 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank? | {
"A": "2 hrs",
"B": "6 hrs",
"C": "5 hrs",
"D": "4 hrs",
"E": "1 hr"
} | divide(const_1, add(divide(const_1, 10), divide(const_1, 15))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)| | "part filled by a in 1 hour = 1 / 10 part filled by b in 1 hour = 1 / 15 part filled by a + b in 1 hour = 1 / 10 + 1 / 15 = 1 / 6 both the pipes will together will fill the tank in 6 hours . answer is b" | physics |
math_qa__sx2DQIehKR7un0oj | A certain country had a total annual expenditure of $4.8 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure?
Choose the correct choice from the following
A) $ 500 B) $ 1,000 C) $ 2,000 D) $ 3,000 E) $ 5,000 | <gadget id="calculator">10 ** 11</gadget>
<output>100_000_000_000</output>
<gadget id="calculator">4.8 * 100_000_000_000</gadget>
<output>480_000_000_000</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">10 ** 6</gadget>
<output>1_000_000</output>
<gadget id="calculator">240 * 1_000_000</gadget>
<output>240_000_000</output>
<gadget id="calculator">480_000_000_000 / 240_000_000</gadget>
<output>2_000</output>
<result>C</result> | C | 2,000 | A certain country had a total annual expenditure of $4.8 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure? | {
"A": "$ 500",
"B": "$ 1,000",
"C": "$ 2,000",
"D": "$ 3,000",
"E": "$ 5,000"
} | divide(multiply(4.8, power(10, 11)), multiply(240, power(10, add(const_4, const_2)))) | add(const_2,const_4)|power(n1,n2)|multiply(n0,#1)|power(n1,#0)|multiply(n3,#3)|divide(#2,#4)| | "total expenditure / population = per capita expenditure hence , ( 4,8 x 10 ^ 11 ) / 240 000 000 = ( 4,8 x 10 ^ 11 ) / ( 2,4 x 10 ^ 8 ) = 2 x 10 ^ ( 11 - 8 ) = 2 x 10 ^ 3 = 2000 . answer is c ." | general |
math_qa__zmPCRmvldDR1IzeN | A waitress's income consists of her salary and tips.During one week ,her tips were 2/4 of her salary.What fraction of her income for the week came from tips? Select.
A) 1 / 9
B) 1 / 6
C) 1 / 3
D) 4 / 9
E) 5 / 9 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<result>C</result> | C | 0.333333 | A waitress's income consists of her salary and tips.During one week ,her tips were 2/4 of her salary.What fraction of her income for the week came from tips? | {
"A": "1 / 9",
"B": "1 / 6",
"C": "1 / 3",
"D": "4 / 9",
"E": "5 / 9"
} | divide(2, add(2, 4)) | add(n0,n1)|divide(n0,#0)| | "her tips were 2 / 4 of her salary . let ' s say her salary = $ 4 this mean her tips = ( 2 / 4 ) ( $ 4 ) = $ 2 so , her total income = $ 4 + $ 2 = $ 6 what fraction of her income for the week came from tips $ 2 / $ 6 = 1 / 3 = c" | general |
math_qa__SkSW1gg2xagIOH6w | In a certain pond, 70 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond? Pick: A) 400 B) 625 C) 1,750 D) 2,500 E) 10,000 | <gadget id="calculator">2 / 50</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">70 / (1/25)</gadget>
<output>1_750</output>
<result>C</result> | C | 1,750 | In a certain pond, 70 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond? | {
"A": "400",
"B": "625",
"C": "1,750",
"D": "2,500",
"E": "10,000"
} | divide(70, divide(2, 50)) | divide(n2,n1)|divide(n0,#0)| | "this is a rather straight forward ratio problem . 1 . 70 fish tagged 2 . 2 out of the 50 fish caught were tagged thus 2 / 50 2 / 50 = 70 / x thus , x = 1750 think of the analogy : 2 fish is to 50 fish as 50 fish is to . . . ? you ' ve tagged 50 fish and you need to find what that comprises as a percentage of the total fish population - we have that information with the ratio of the second catch . c" | gain |
math_qa__DqySXRBkT1wcHk4W | There are 990 male and female participants in a meeting. Half the female participants and one-quarter of the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female? Choose the correct choice from the following
A) 75
B) 100
C) 125
D) 175
E) 165 | <gadget id="calculator">990 / 3</gadget>
<output>330</output>
<gadget id="calculator">330 * 4</gadget>
<output>1_320</output>
<gadget id="calculator">1_320 - 990</gadget>
<output>330</output>
<gadget id="calculator">330 / 2</gadget>
<output>165</output>
<result>E</result> | E | 165 | There are 990 male and female participants in a meeting. Half the female participants and one-quarter of the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female? | {
"A": "75",
"B": "100",
"C": "125",
"D": "175",
"E": "165"
} | divide(subtract(multiply(divide(990, const_3), const_4), 990), const_2) | divide(n0,const_3)|multiply(#0,const_4)|subtract(#1,n0)|divide(#2,const_2)| | "female = x male = 990 - x x / 2 + 990 - x / 4 = 1 / 3 * ( 990 ) = 330 x = 330 x / 2 = 165 is supposed to be the answer m is missing something correct option e" | general |
math_qa__06fgVrUZbo19BCTB | 5 years ago amith was 3 times as old as his daughter and 10 years hence , he will be two times as old as his daughter . then amith ’ s current age is ,
Choose the correct choice from the following:
A) 10 B) 50 C) 40 D) 20 E) 60 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 + 5</gadget>
<output>20</output>
<result>D</result> | D | 20 | 5 years ago amith was 3 times as old as his daughter and 10 years hence , he will be two times as old as his daughter . then amith ’ s current age is , | {
"A": "10",
"B": "50",
"C": "40",
"D": "20",
"E": "60"
} | add(multiply(5, 3), 5) | multiply(n0,n1)|add(n0,#0) | d 20 amith ’ s age = a and daughter ’ s age = b then , a – 5 = 3 ( b – 5 ) = > a – 3 b + 10 = 0 … … ( 1 ) and , a + 10 = 2 ( a + 10 ) = > a – 2 b – 10 = 0 … … ( 2 ) solving the 2 eqns , we will get a = 50 , b = 20 . therefore , amith ’ s age is 50 and his daughter ’ s age is 20 | general |
math_qa__PZvGcDjllAJKquen | A retailer buys a radio for Rs 232. His overhead expenses are Rs 15. He sellis the radio for Rs 300. The profit percent of the retailer is
Choices.
A) 10 %
B) 50 %
C) 21.4 %
D) 52 %
E) none of these | <gadget id="calculator">232 + 15</gadget>
<output>247</output>
<gadget id="calculator">300 / 247</gadget>
<output>300/247 = around 1.214575</output>
<gadget id="calculator">(300/247) * 100</gadget>
<output>30_000/247 = around 121.45749</output>
<gadget id="calculator">(30_000/247) - 100</gadget>
<output>5_300/247 = around 21.45749</output>
<result>C</result> | C | 21.4 | A retailer buys a radio for Rs 232. His overhead expenses are Rs 15. He sellis the radio for Rs 300. The profit percent of the retailer is | {
"A": "10 %",
"B": "50 %",
"C": "21.4 %",
"D": "52 %",
"E": "none of these"
} | subtract(multiply(divide(300, add(232, 15)), const_100), const_100) | add(n0,n1)|divide(n2,#0)|multiply(#1,const_100)|subtract(#2,const_100) | explanation : cost price = ( 232 + 15 ) = 247 sell price = 300 gain = ( 53 / 247 ) * 100 = 21.4 % . answer : c | gain |
math_qa__O5HMLJSMPJTDWCVi | a batch of cookies was divided among 3 tins : 2 / 3 of all the cookies were placed in either the blue tin or the green tin , and the rest were placed in the red tin . if 1 / 4 of all the cookies were placed in the blue tin , what fraction q of the cookies that were placed in the other tins were placed in the green tin ? Choose the correct choice from the following: A) 15 / 2 B) 9 / 4 C) 5 / 9 D) 7 / 5 E) 9 / 7 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/3) - (1/4)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) * 12</gadget>
<output>5</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">5 / 9</gadget>
<output>5/9 = around 0.555556</output>
<result>C</result> | C | 0.555556 | a batch of cookies was divided among 3 tins : 2 / 3 of all the cookies were placed in either the blue tin or the green tin , and the rest were placed in the red tin . if 1 / 4 of all the cookies were placed in the blue tin , what fraction q of the cookies that were placed in the other tins were placed in the green tin ? | {
"A": "15 / 2",
"B": "9 / 4",
"C": "5 / 9",
"D": "7 / 5",
"E": "9 / 7"
} | divide(multiply(subtract(divide(2, 3), divide(1, 4)), const_12), add(divide(const_12, 3), multiply(subtract(divide(2, 3), divide(1, 4)), const_12))) | divide(n1,n0)|divide(n3,n4)|divide(const_12,n0)|subtract(#0,#1)|multiply(#3,const_12)|add(#2,#4)|divide(#4,#5) | blue tin or red tin : 2 / 3 ( n ) red tin : ( 1 / 3 ) n blue tin : ( 1 / 4 ) n what the last statment meant , is it wants this fraction : ( # of cookies in green tin ) / ( # of cookies in red and green tin ) # of cookies in green tin = 2 n / 3 - n / 4 = 8 n - 3 n / 12 = 5 n / 12 # of cookies in red and green tin = n / 3 + 5 n / 12 = 9 n / 12 fraction q = 5 n / 12 * 12 / 9 n = 5 / 9 ( c ) | general |
math_qa__kH6DtIITJcMjkbW9 | The cricket team of 11members is 26yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ? Choices: A) 19 B) 21 C) 23 D) 25 E) 27 | <gadget id="calculator">26 + 3</gadget>
<output>29</output>
<gadget id="calculator">29 + 26</gadget>
<output>55</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">55 - 9</gadget>
<output>46</output>
<gadget id="calculator">11 - 9</gadget>
<output>2</output>
<gadget id="calculator">46 / 2</gadget>
<output>23</output>
<result>C</result> | C | 23 | The cricket team of 11members is 26yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ? | {
"A": "19",
"B": "21",
"C": "23",
"D": "25",
"E": "27"
} | divide(subtract(add(add(26, 3), 26), subtract(11, 2)), subtract(11, subtract(11, 2))) | add(n1,n2)|subtract(n0,n3)|add(n1,#0)|subtract(n0,#1)|subtract(#2,#1)|divide(#4,#3)| | "let the average age of the whole team be x years . 11 x - ( 26 + 29 ) = 9 ( x - 1 ) = > 11 x - 9 x = 46 = > 2 x = 46 = > x = 23 . so , average age of the team is 23 years . c" | general |
math_qa__aRipndNlZ5khcvzm | A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 73 marks. The maximum marks are? Select the correct option.
A) 450
B) 300
C) 500
D) 600
E) 175 | <gadget id="calculator">125 + 73</gadget>
<output>198</output>
<gadget id="calculator">33 / 100</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">198 / (33/100)</gadget>
<output>600</output>
<result>D</result> | D | 600 | A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 73 marks. The maximum marks are? | {
"A": "450",
"B": "300",
"C": "500",
"D": "600",
"E": "175"
} | divide(add(125, 73), divide(33, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "let the maximum marks be x then , 33 % of x = 125 + 73 33 x / 100 = 198 x = 600 answer is d" | general |
math_qa__Llm4elbRiTZC5spd | A ratio between two numbers is 3 : 4 and their L.C.M. is 180. The first number is Choose one:
A) 60 B) 45 C) 20 D) 15 E) none | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">180 / 12</gadget>
<output>15</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<result>B</result> | B | 45 | A ratio between two numbers is 3 : 4 and their L.C.M. is 180. The first number is | {
"A": "60",
"B": "45",
"C": "20",
"D": "15",
"E": "none"
} | multiply(divide(180, multiply(3, 4)), 3) | multiply(n0,n1)|divide(n2,#0)|multiply(n0,#1)| | "sol . let the required numbers be 3 x and 4 x . then , their l . c . m . is 12 x . ∴ 12 x = 180 ⇔ x = 15 . hence , the first number is 45 . answer b" | other |
math_qa__VmhuD30Yi45JKF3I | mike , jim and bob are all professional fisherman . mike can catch 30 fish in one hour , jim can catch twice as much and bob can catch 50 % more than jim . if the 3 started to fish together and after 40 minutes mike and bob left , how many fish did the 3 fishermen catch in one hour ? Choose the correct choice from the following answers.
A) 110
B) 120
C) 140
D) 130
E) 112 | <gadget id="calculator">3 * 40</gadget>
<output>120</output>
<gadget id="calculator">120 + 50</gadget>
<output>170</output>
<gadget id="calculator">170 - 30</gadget>
<output>140</output>
<result>C</result> | C | 140 | mike , jim and bob are all professional fisherman . mike can catch 30 fish in one hour , jim can catch twice as much and bob can catch 50 % more than jim . if the 3 started to fish together and after 40 minutes mike and bob left , how many fish did the 3 fishermen catch in one hour ? | {
"A": "110",
"B": "120",
"C": "140",
"D": "130",
"E": "112"
} | subtract(add(multiply(3, 40), 50), 30) | multiply(n2,n3)|add(n1,#0)|subtract(#1,n0) | all of them catch fishes in relation to number 30 . . . . 2 / 3 * 30 + 2 * 30 + 2 * 1.5 * 30 * 2 / 3 = 140 answer is c | physics |
math_qa__rILZWWuT1ur1yiYt | Two equally sized jugs full of water are each emptied into two separate unequally sized empty jugs, X and Y. Now, jug X is 1/7 full, while jug Y is 2/3 full. If water is poured from jug X into jug Y until jug Y is filled, what fraction of jug X then contains water? Choose the correct choice from the following choices.
A) 0 B) 1 / 14 C) 2 / 15 D) 1 / 10 E) 2 / 10 | <gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) / (2/3)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/7) * (1/2)</gadget>
<output>1/14 = around 0.071429</output>
<result>B</result> | B | 0.071429 | Two equally sized jugs full of water are each emptied into two separate unequally sized empty jugs, X and Y. Now, jug X is 1/7 full, while jug Y is 2/3 full. If water is poured from jug X into jug Y until jug Y is filled, what fraction of jug X then contains water? | {
"A": "0",
"B": "1 / 14",
"C": "2 / 15",
"D": "1 / 10",
"E": "2 / 10"
} | multiply(divide(1, 7), divide(subtract(const_1, divide(2, 3)), divide(2, 3))) | divide(n0,n1)|divide(n2,n3)|subtract(const_1,#1)|divide(#2,#1)|multiply(#0,#3) | suppose the water in each jug is l liters cx x ( 1 / 7 ) = l cx = 7 l liters cx is capacity of x cy x ( 2 / 3 ) = l cy = 3 l / 2 liters cy is capacity of y now , y is 3 l / 2 - l empty = l / 2 empty so , we can put only l / 2 water in jug y from jug x jug x ' s remaining water = l - l / 2 = l / 2 fraction of x which contains water = water / cx = ( l / 2 ) / 7 l = 1 / 14 answer will be b | general |
math_qa__3mnEP4pTfo2LEzo4 | If the weight of 13 meters long rod is 13.4 kg. What is the weight of 6 meters long rod ? Choose the correct choice
A) 7.2 kg . B) 10.8 kg . C) 12.4 kg . D) 6.18 kg E) none | <gadget id="calculator">6 * 13.4</gadget>
<output>80.4</output>
<gadget id="calculator">80.4 / 13</gadget>
<output>6.184615</output>
<result>D</result> | D | 6.18 | If the weight of 13 meters long rod is 13.4 kg. What is the weight of 6 meters long rod ? | {
"A": "7.2 kg .",
"B": "10.8 kg .",
"C": "12.4 kg .",
"D": "6.18 kg",
"E": "none"
} | divide(multiply(6, 13.4), 13) | multiply(n1,n2)|divide(#0,n0) | answer ∵ weight of 13 m long rod = 13.4 kg ∴ weight of 1 m long rod = 13.4 / 13 kg ∴ weight of 6 m long rod = 13.4 x 6 / 13 = 6.18 kg option : d | physics |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.