id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__UlhOeKl0T2HT8Yvj | A meal cost $ 33.50 and there was no tax. If the tip was more than 10 pc but less than 15pc of the price, then the total amount paid should be: Choose the correct choice from the following choices
A) 40 - 42 B) 39 - 41 C) 38 - 40 D) 37 - 39 E) 36 - 37 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">33.5 * (3/20)</gadget>
<output>5.025</output>
<gadget id="calculator">5.025 + 33.5</gadget>
<output>38.525</output>
<result>D</result> | D | 37 | A meal cost $ 33.50 and there was no tax. If the tip was more than 10 pc but less than 15pc of the price, then the total amount paid should be: | {
"A": "40 - 42",
"B": "39 - 41",
"C": "38 - 40",
"D": "37 - 39",
"E": "36 - 37"
} | add(multiply(33.50, divide(15, const_100)), 33.50) | divide(n2,const_100)|multiply(n0,#0)|add(n0,#1)| | "10 % ( 33.5 ) = 3.35 15 % ( 33.5 ) = 5.025 total amount could have been 33.5 + 3.35 and 33.5 + 5.025 = > could have been between 36.85 and 38.525 = > approximately between 37 and 39 answer is d ." | general |
math_qa__adNgn6D0x07gfmGY | What least number should be added to 1054, so that the sum is completely divisible by 23
Choose the correct option.
A) 4 B) 1 C) 2 D) 3 E) 5 | <gadget id="calculator">1_054 % 23</gadget>
<output>19</output>
<gadget id="calculator">23 - 19</gadget>
<output>4</output>
<result>A</result> | A | 4 | What least number should be added to 1054, so that the sum is completely divisible by 23 | {
"A": "4",
"B": "1",
"C": "2",
"D": "3",
"E": "5"
} | subtract(23, reminder(1054, 23)) | reminder(n0,n1)|subtract(n1,#0)| | "explanation : ( 1054 / 23 ) gives remainder 19 19 + 4 = 23 , so we need to add 4 answer : option a" | general |
math_qa__MNwWUk0c3uMrd8uy | The operation is defined for all integers a and b by the equation ab = (a - 1)(b - 1). If y10 = 90, what is the value of y ? Choose the correct choice from the following options
A) 10
B) 12
C) 15
D) 11
E) 20 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">90 / 9</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<result>D</result> | D | 11 | The operation is defined for all integers a and b by the equation ab = (a - 1)(b - 1). If y10 = 90, what is the value of y ? | {
"A": "10",
"B": "12",
"C": "15",
"D": "11",
"E": "20"
} | add(divide(90, subtract(10, 1)), 1) | subtract(n2,n0)|divide(n3,#0)|add(n0,#1)| | "ab = ( a - 1 ) ( b - 1 ) y 10 = ( y - 1 ) ( 10 - 1 ) = 90 - - > y - 1 = 10 - - > y = 11 answer : d" | general |
math_qa__LbFGyZfBRjkWfH1m | The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 Km/hr. At what time will they meet? Choose the correct answer: A) 10.30 a . m B) 11 a . m C) 10 a . m D) 12 noon E) none of these | <gadget id="calculator">330 + 75</gadget>
<output>405</output>
<gadget id="calculator">60 + 75</gadget>
<output>135</output>
<gadget id="calculator">405 / 135</gadget>
<output>3</output>
<gadget id="calculator">3 + 8</gadget>
<output>11</output>
<result>B</result> | B | 11 | The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 Km/hr. At what time will they meet? | {
"A": "10.30 a . m",
"B": "11 a . m",
"C": "10 a . m",
"D": "12 noon",
"E": "none of these"
} | add(divide(add(330, 75), add(60, 75)), 8) | add(n0,n4)|add(n2,n4)|divide(#0,#1)|add(n1,#2)| | "explanation : assume that they meet x hours after 8 a . m . then , train 1 , starting from a , travelling towards b , travels x hours till the trains meet ⇒ distance travelled by train 1 in x hours = speed × time = 60 x then , train 2 , starting from b , travelling towards a , travels ( x - 1 ) hours till the trains meet ⇒ distance travelled by train 2 in ( x - 1 ) hours = speed × time = 75 ( x - 1 ) total distance travelled = distance travelled by train 1 + distance travelled by train 2 = > 330 = 60 x + 75 ( x - 1 ) = > 12 x + 15 ( x - 1 ) = 66 = > 12 x + 15 x - 15 = 66 = > 27 x = 66 + 15 = 81 = > 3 x = 9 = > x = 3 hence the trains meet 3 hours after 8 a . m . , i . e . at 11 a . m . answer : option b" | physics |
math_qa__tH9BDrXLbRMVzvwi | One pump drains one-half of a pond in 2.5 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone? Choose one:
A) 1 hour B) 1.2 hour C) 3 hours D) 1.25 hours E) 6 hours | <gadget id="calculator">2.5 * 2</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 / (4/5)</gadget>
<output>5/4 = around 1.25</output>
<result>D</result> | D | 1.25 | One pump drains one-half of a pond in 2.5 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone? | {
"A": "1 hour",
"B": "1.2 hour",
"C": "3 hours",
"D": "1.25 hours",
"E": "6 hours"
} | divide(const_1, subtract(const_1, divide(const_1, multiply(2.5, const_2)))) | multiply(n0,const_2)|divide(const_1,#0)|subtract(const_1,#1)|divide(const_1,#2)| | "the tricky part here , i believed is one half hour = 1 / 2 . then everything would be easy . we have the 1 st pump working rate / hour = 1 / 2 : 5 / 2 = 1 / 5 working rate of 2 pumps : 1 / 2 : 1 / 2 = 1 . working rate of 2 nd pump : 1 - 1 / 5 = 4 / 5 - - > time taken for the 2 nd pump to finish : 1 : 4 / 5 = 5 / 4 = 1.25 hours . d" | physics |
math_qa__oJOmJrSfDodtspfO | A high school has 400 students 1/2 attend the arithmetic club, 5/8 attend the biology club and 3/4 attend the chemistry club. 3/8 attend all 3 clubs. If every student attends at least one club how many students attend exactly 2 clubs.
Select: A) 35 B) 45 C) 55 D) 60 E) 50 | <gadget id="calculator">400 * 1</gadget>
<output>400</output>
<gadget id="calculator">400 / 2</gadget>
<output>200</output>
<gadget id="calculator">400 * 5</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 8</gadget>
<output>250</output>
<gadget id="calculator">200 + 250</gadget>
<output>450</output>
<gadget id="calculator">400 * 3</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 4</gadget>
<output>300</output>
<gadget id="calculator">450 + 300</gadget>
<output>750</output>
<gadget id="calculator">1_200 / 8</gadget>
<output>150</output>
<gadget id="calculator">150 * 2</gadget>
<output>300</output>
<gadget id="calculator">750 - 300</gadget>
<output>450</output>
<gadget id="calculator">450 - 400</gadget>
<output>50</output>
<result>E</result> | E | 50 | A high school has 400 students 1/2 attend the arithmetic club, 5/8 attend the biology club and 3/4 attend the chemistry club. 3/8 attend all 3 clubs. If every student attends at least one club how many students attend exactly 2 clubs. | {
"A": "35",
"B": "45",
"C": "55",
"D": "60",
"E": "50"
} | subtract(subtract(add(add(divide(multiply(400, 1), 2), divide(multiply(400, 5), 8)), divide(multiply(400, 3), 4)), multiply(divide(multiply(400, 3), 8), 2)), 400) | multiply(n0,n1)|multiply(n0,n3)|multiply(n0,n5)|divide(#0,n2)|divide(#1,n4)|divide(#2,n6)|divide(#2,n4)|add(#3,#4)|multiply(n2,#6)|add(#7,#5)|subtract(#9,#8)|subtract(#10,n0) | a - club has 200 members ( 1 / 2 of 400 ) b - club has 250 members ( 5 / 8 of 400 ) c - club has 300 members ( 3 / 4 of 400 ) we can create an equation to solve this : 200 + 250 + 150 = n + x + 2 y where n is the number of students , x is the number of students in two clubs , and y is the number of students in three clubs . the question provides y for us ( 150 ) . 750 = 400 + x + 300 x = 50 e | general |
math_qa__ZZvZBjFzo8NfdcpM | A train, 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel ? Choose the correct choice from the following choices:
A) 650 meter
B) 555 meter
C) 500 meter
D) 458 meter
E) none of these | <gadget id="calculator">78 * 1_000</gadget>
<output>78_000</output>
<gadget id="calculator">78_000 / 3_600</gadget>
<output>65/3 = around 21.666667</output>
<gadget id="calculator">(65/3) * 60</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 - 800</gadget>
<output>500</output>
<result>C</result> | C | 500 | A train, 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel ? | {
"A": "650 meter",
"B": "555 meter",
"C": "500 meter",
"D": "458 meter",
"E": "none of these"
} | subtract(multiply(divide(multiply(78, const_1000), const_3600), const_60), 800) | multiply(n1,const_1000)|divide(#0,const_3600)|multiply(#1,const_60)|subtract(#2,n0) | explanation : let length of tunnel is x meter distance = 800 + x meter time = 1 minute = 60 seconds speed = 78 km / hr = 78 * 5 / 18 m / s = 65 / 3 m / s distance = speed * time = > 800 + x = 65 / 3 ∗ 60 = > 800 + x = 20 ∗ 65 = 1300 = > x = 1300 − 800 = 500 so the length of the tunnel is 500 meters . option c | physics |
math_qa__VgtkiRK6P9bnZxpu | Richard walks along Sunrise Boulevard daily. He starts walking at 07:00 from block 10 and walks to block 90 where he turns around and walks back to block 70, where he stops at 07:30. The blocks along the boulevard are numbered sequentially (1,2,3), and each block measures 40 meters. What is Richard's speed in meters per minute? Choose the most appropriate option
A) 75 B) 180 C) 198 D) 216 E) 252 | <gadget id="calculator">90 - 10</gadget>
<output>80</output>
<gadget id="calculator">90 - 70</gadget>
<output>20</output>
<gadget id="calculator">80 + 20</gadget>
<output>100</output>
<gadget id="calculator">100 * 30</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 40</gadget>
<output>75</output>
<result>A</result> | A | 75 | Richard walks along Sunrise Boulevard daily. He starts walking at 07:00 from block 10 and walks to block 90 where he turns around and walks back to block 70, where he stops at 07:30. The blocks along the boulevard are numbered sequentially (1,2,3), and each block measures 40 meters. What is Richard's speed in meters per minute? | {
"A": "75",
"B": "180",
"C": "198",
"D": "216",
"E": "252"
} | divide(multiply(add(subtract(90, 10), subtract(90, 70)), 30), 40) | subtract(n3,n2)|subtract(n3,n4)|add(#0,#1)|multiply(n6,#2)|divide(#3,n9) | total distance from 10 to 90 = 80 + from 90 to 70 = 20 so the dist is 100 × 30 ( per block dist ) speed = 3000 mts / 40 min = 75 m / min a is the answer | physics |
math_qa__nCb1KkICuqXl97J3 | A person's present age is two-fifth of the age of his mother. After 10years, he will be one - half of the age of his mother. How old is the mother at present ? Choose one
A) 25 B) 40 C) 32 D) 50 E) 28 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/2) - (2/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">5 / (1/10)</gadget>
<output>50</output>
<result>D</result> | D | 50 | A person's present age is two-fifth of the age of his mother. After 10years, he will be one - half of the age of his mother. How old is the mother at present ? | {
"A": "25",
"B": "40",
"C": "32",
"D": "50",
"E": "28"
} | divide(subtract(10, add(const_2, const_3)), subtract(divide(const_1, const_2), divide(const_2, add(const_2, const_3)))) | add(const_2,const_3)|divide(const_1,const_2)|divide(const_2,#0)|subtract(n0,#0)|subtract(#1,#2)|divide(#3,#4) | let the mother ' s present age be x years then the person ' s present age = 2 x / 5 ( 2 x / 5 ) + 10 = 1 / 2 ( x + 10 ) 2 ( 2 x + 50 ) = 5 ( x + 10 ) x = 50 answer is d | general |
math_qa__wXqMt1St9CxFIaPJ | When positive integer t is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180?
Choose the correct choice from the following choices.
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">13 * 7</gadget>
<output>91</output>
<gadget id="calculator">91 + 2</gadget>
<output>93</output>
<gadget id="calculator">93 / 93</gadget>
<output>1</output>
<result>B</result> | B | 1 | When positive integer t is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | divide(add(multiply(13, add(5, 2)), 2), add(multiply(13, add(5, 2)), 2)) | add(n1,n3)|multiply(n0,#0)|add(n1,#1)|divide(#2,#2) | the equation that can be formed t is 13 x + 2 = 8 y + 5 . . 13 x - 3 = 8 y . . . as we can see x can take only odd values as the rhs will always be even . . also x can take values till 13 as 13 * 14 > 180 . . now we have to substitue x as 1 , 35 , 79 , 1113 . . . once we find 7 fitting in , any other value need not be checked as every 4 th value will give us answer so next value will be 15 . . ans 1 . . b | general |
math_qa__x3qRoCZobtv0WNqR | A room 11 m 47 cm long and 7m 77 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor. Answers:
A) 636 B) 640 C) 647 D) 651 E) 675 | <gadget id="calculator">11 * 100</gadget>
<output>1_100</output>
<gadget id="calculator">1_100 + 47</gadget>
<output>1_147</output>
<gadget id="calculator">7 * 100</gadget>
<output>700</output>
<gadget id="calculator">700 + 77</gadget>
<output>777</output>
<gadget id="calculator">1_147 * 777</gadget>
<output>891_219</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">47 - 10</gadget>
<output>37</output>
<gadget id="calculator">37 * 37</gadget>
<output>1_369</output>
<gadget id="calculator">891_219 / 1_369</gadget>
<output>651</output>
<result>D</result> | D | 651 | A room 11 m 47 cm long and 7m 77 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor. | {
"A": "636",
"B": "640",
"C": "647",
"D": "651",
"E": "675"
} | divide(multiply(add(multiply(11, const_100), 47), add(multiply(7, const_100), 77)), multiply(subtract(47, add(multiply(const_2, const_4), const_2)), subtract(47, add(multiply(const_2, const_4), const_2)))) | multiply(n0,const_100)|multiply(n2,const_100)|multiply(const_2,const_4)|add(n1,#0)|add(n3,#1)|add(#2,const_2)|multiply(#3,#4)|subtract(n1,#5)|multiply(#7,#7)|divide(#6,#8) | explanation : area of the room = ( 1147 x 777 ) cm 2 . size of largest square tile = h . c . f . of 1147 cm and 777 cm = 37 cm . area of 1 tile = ( 37 x 37 ) cm 2 . number of tiles required = ( 1147 × 777 ) / ( 37 × 37 ) = 651 answer : option d | physics |
math_qa__8dsE6oa6CzYxTyhb | The distance from City A to City B is 180 miles. While driving from City A to City B, Cara drives at a constant speed of 30 miles per hour. Dan leaves City A 60 minutes after Cara. What is the minimum constant speed in miles per hour that Dan must exceed in order to arrive in City B before Cara? Choose the correct choice from the following options
A) 42 B) 44 C) 46 D) 36 E) 50 | <gadget id="calculator">180 / 30</gadget>
<output>6</output>
<gadget id="calculator">60 / 60</gadget>
<output>1</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">180 / 5</gadget>
<output>36</output>
<result>D</result> | D | 36 | The distance from City A to City B is 180 miles. While driving from City A to City B, Cara drives at a constant speed of 30 miles per hour. Dan leaves City A 60 minutes after Cara. What is the minimum constant speed in miles per hour that Dan must exceed in order to arrive in City B before Cara? | {
"A": "42",
"B": "44",
"C": "46",
"D": "36",
"E": "50"
} | divide(180, subtract(divide(180, 30), divide(60, 60))) | divide(n0,n1)|divide(n2,n2)|subtract(#0,#1)|divide(n0,#2)| | "the time it takes cara to drive to city b is 180 / 30 = 6 hours . dan needs to take less than 5 hours for the trip . dan needs to exceed a constant speed of 180 / 5 = 36 miles per hour . the answer is d ." | physics |
math_qa__VvrwCV6NMIGsmITA | A cube has a volume of 64 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is?
Choose the most appropriate option: A) 24 B) 48 C) 64 D) 80 E) 512 | <gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 ** 3</gadget>
<output>512</output>
<result>E</result> | E | 512 | A cube has a volume of 64 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is? | {
"A": "24",
"B": "48",
"C": "64",
"D": "80",
"E": "512"
} | volume_cube(multiply(const_2, cube_edge_by_volume(64))) | cube_edge_by_volume(n0)|multiply(#0,const_2)|volume_cube(#1) | volume = 64 = side ^ 3 i . e . side of cube = 4 new cube has dimensions 8 , 8 , and 8 as all sides are twice of teh side of first cube volume = 8 * 8 * 8 = 512 square feet answer : option e | geometry |
math_qa__SBVtuqSdCvrZJLoc | The length of the longest tape in cm which can be used to measure exactly, the length 100cm; 2m25cm; and 7m80cm is: Pick
A) 30 B) 5 C) 10 D) 36 E) 25 | <gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<result>B</result> | B | 5 | The length of the longest tape in cm which can be used to measure exactly, the length 100cm; 2m25cm; and 7m80cm is: | {
"A": "30",
"B": "5",
"C": "10",
"D": "36",
"E": "25"
} | sqrt(25) | sqrt(n2) | the three lengths in cm are 100 , 225 & 780 . hcf of 100 , 225 & 780 is 5 . hence , the answer is 5 cm . answer : b | physics |
math_qa__Iz8eYzzSPL3zjJzN | The population of a town is 10000. It increases annually at the rate of 27% p.a. What will be its population after 2 years? Choose the most appropriate option:
A) 14000
B) 14400
C) 16129
D) 14600
E) 14700 | <gadget id="calculator">10_000 * 27</gadget>
<output>270_000</output>
<gadget id="calculator">270_000 / 100</gadget>
<output>2_700</output>
<gadget id="calculator">2_700 * 2</gadget>
<output>5_400</output>
<gadget id="calculator">10_000 + 5_400</gadget>
<output>15_400</output>
<result>C</result> | C | 16,129 | The population of a town is 10000. It increases annually at the rate of 27% p.a. What will be its population after 2 years? | {
"A": "14000",
"B": "14400",
"C": "16129",
"D": "14600",
"E": "14700"
} | add(10000, multiply(divide(multiply(10000, 27), const_100), 2)) | multiply(n0,n1)|divide(#0,const_100)|multiply(#1,n2)|add(n0,#2)| | "formula : 10000 × 127 / 100 × 127 / 100 = 16129 answer : c" | gain |
math_qa__6uU5r0keC2IJi1C9 | A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.300 more. What was the Sum? Choose the most appropriate option: A) s . 1200 B) s . 1300 C) s . 600 D) s . 800 E) s . 1200 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">300 / (1/2)</gadget>
<output>600</output>
<result>C</result> | C | 600 | A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.300 more. What was the Sum? | {
"A": "s . 1200",
"B": "s . 1300",
"C": "s . 600",
"D": "s . 800",
"E": "s . 1200"
} | divide(300, multiply(divide(5, const_100), 10)) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)| | "at 5 % more rate , the increase in s . i for 10 years = rs . 300 ( given ) so , at 5 % more rate , the increase in si for 1 year = 300 / 10 = rs . 30 / - i . e . rs . 30 is 5 % of the invested sum so , 1 % of the invested sum = 30 / 5 therefore , the invested sum = 30 × 100 / 5 = rs . 600 answer : c" | gain |
math_qa__wMzirDBdpawSsB8v | In an exam 49% candidates failed in English and 36% failed in Hindi and 15% failed in both subjects. If the total number of candidates who passed in English alone is 630. What is the total number of candidates appeared in exam? Choose the correct option: A) 2000 B) 3000 C) 3500 D) 3800 E) 4000 | <gadget id="calculator">36 - 15</gadget>
<output>21</output>
<gadget id="calculator">100 / 21</gadget>
<output>100/21 = around 4.761905</output>
<gadget id="calculator">630 * (100/21)</gadget>
<output>3_000</output>
<result>B</result> | B | 3,000 | In an exam 49% candidates failed in English and 36% failed in Hindi and 15% failed in both subjects. If the total number of candidates who passed in English alone is 630. What is the total number of candidates appeared in exam? | {
"A": "2000",
"B": "3000",
"C": "3500",
"D": "3800",
"E": "4000"
} | multiply(630, divide(const_100, subtract(36, 15))) | subtract(n1,n2)|divide(const_100,#0)|multiply(n3,#1) | not fail in english = 51 % not fail in hindi = 64 % not fail in both = 30 % ( 49 + 36 - 15 ) pass in english only = 51 - 30 = 21 21 / 100 * x = 630 x = 3000 answer : b | general |
math_qa__9NeOfM5ylC1x1SUq | Each of the three people individually can complete a certain job in 4, 5, and 6 hours, respectively. What is the lowest fraction of the job that can be done in 1 hour by 2 of the people working together at their respective rates? Select:
A) 4 / 15 B) 7 / 30 C) 11 / 30 D) 5 / 18 E) 7 / 18 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/5) + (1/6)</gadget>
<output>11/30 = around 0.366667</output>
<result>C</result> | C | 0.366667 | Each of the three people individually can complete a certain job in 4, 5, and 6 hours, respectively. What is the lowest fraction of the job that can be done in 1 hour by 2 of the people working together at their respective rates? | {
"A": "4 / 15",
"B": "7 / 30",
"C": "11 / 30",
"D": "5 / 18",
"E": "7 / 18"
} | add(divide(1, 5), divide(1, 6)) | divide(n3,n1)|divide(n3,n2)|add(#0,#1)| | "the two slowest people work at rates of 1 / 5 and 1 / 6 of the job per hour . the sum of these rates is 1 / 5 + 1 / 6 = 11 / 30 of the job per hour . the answer is c ." | physics |
math_qa__atw85dUGoTvZ4sRB | Find the smallest number which when divided by 11 and 13 leaves respective remainders of 4 and 6.
Choices: A) 187 B) 197 C) 207 D) 136 E) 227 | <gadget id="calculator">11 * 13</gadget>
<output>143</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">143 - 11</gadget>
<output>132</output>
<result>D</result> | D | 136 | Find the smallest number which when divided by 11 and 13 leaves respective remainders of 4 and 6. | {
"A": "187",
"B": "197",
"C": "207",
"D": "136",
"E": "227"
} | subtract(multiply(11, 13), add(const_10, const_1)) | add(const_1,const_10)|multiply(n0,n1)|subtract(#1,#0)| | "let ' n ' is the smallest number which divided by 11 and 13 leaves respective remainders of 4 and 6 . required number = ( lcm of 11 and 13 ) - ( common difference of divisors and remainders ) = ( 143 ) - ( 7 ) = 136 . answer : d" | general |
math_qa__nlSKOzam8QlCxU3z | In what time will a train 100 meters long cross an electric pole, if its speed is 180 km/hr Choose the correct choice from the following answers.
A) 5 seconds B) 4.5 seconds C) 3 seconds D) 2 seconds E) none of these | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">180 * (5/18)</gadget>
<output>50</output>
<gadget id="calculator">100 / 50</gadget>
<output>2</output>
<result>D</result> | D | 2 | In what time will a train 100 meters long cross an electric pole, if its speed is 180 km/hr | {
"A": "5 seconds",
"B": "4.5 seconds",
"C": "3 seconds",
"D": "2 seconds",
"E": "none of these"
} | divide(100, multiply(180, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "explanation : first convert speed into m / sec speed = 180 * ( 5 / 18 ) = 50 m / sec time = distance / speed = 100 / 50 = 2 seconds answer : d" | physics |
math_qa__JhEYjcHJoXRA3FGD | In a box of 8 pens, a total of 2 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective? Select
A) 6 / 11 B) 8 / 15 C) 9 / 20 D) 11 / 25 E) 15 / 28 | <gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 8</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">(3/4) * (5/7)</gadget>
<output>15/28 = around 0.535714</output>
<result>E</result> | E | 0.535714 | In a box of 8 pens, a total of 2 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective? | {
"A": "6 / 11",
"B": "8 / 15",
"C": "9 / 20",
"D": "11 / 25",
"E": "15 / 28"
} | multiply(divide(subtract(8, 2), 8), divide(subtract(subtract(8, 2), const_1), subtract(8, const_1))) | subtract(n0,n1)|subtract(n0,const_1)|divide(#0,n0)|subtract(#0,const_1)|divide(#3,#1)|multiply(#2,#4)| | "p ( neither pen is defective ) = 6 / 8 * 5 / 7 = 15 / 28 the answer is e ." | general |
math_qa__mpVBdt6y6g3Xgy33 | If X is invested in a bank at a rate of simple interest of y% p.a. for two years, then the interest earned is 500. if X is invested at y% p.a., for two years when the interest is compounded annually, the interest is 512.50. What is the value of X? Choose the correct answer:
A) 8000 B) 6000 C) 5000 D) 4000 E) 3000 | <gadget id="calculator">500 / 2</gadget>
<output>250</output>
<gadget id="calculator">250 ** 2</gadget>
<output>62_500</output>
<gadget id="calculator">512.5 - 500</gadget>
<output>12.5</output>
<gadget id="calculator">62_500 / 12.5</gadget>
<output>5_000</output>
<result>C</result> | C | 5,000 | If X is invested in a bank at a rate of simple interest of y% p.a. for two years, then the interest earned is 500. if X is invested at y% p.a., for two years when the interest is compounded annually, the interest is 512.50. What is the value of X? | {
"A": "8000",
"B": "6000",
"C": "5000",
"D": "4000",
"E": "3000"
} | divide(power(divide(500, const_2), const_2), subtract(512.50, 500)) | divide(n0,const_2)|subtract(n1,n0)|power(#0,const_2)|divide(#2,#1)| | "simple way to solve this question is to use options . from si , we know that x * y = 25,000 . now , put the value of x = 5000 , we will have y = 5 % to calculate ci , now , we know 1 st year amount = 5000 + 5 % of 5000 = 5250 . 2 nd year , amount = 5250 + 5 % of 5250 = 5512.50 . we can see after 2 years interest = 5512.50 - 5000 = 512.50 hence , it satisfies the question . hence c is the correct answer" | gain |
math_qa__Cxko6FBLt4L6rdCa | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.2880? Choose the correct choice from the following answers:
A) 8100
B) 3388
C) 7767
D) 2009
E) 3645 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 2_880</gadget>
<output>360</output>
<gadget id="calculator">2_880 + 360</gadget>
<output>3_240</output>
<gadget id="calculator">(1/8) * 3_240</gadget>
<output>405</output>
<gadget id="calculator">3_240 + 405</gadget>
<output>3_645</output>
<result>E</result> | E | 3,645 | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.2880? | {
"A": "8100",
"B": "3388",
"C": "7767",
"D": "2009",
"E": "3645"
} | add(add(2880, multiply(divide(1, 8), 2880)), multiply(divide(1, 8), add(2880, multiply(divide(1, 8), 2880)))) | divide(n0,n1)|multiply(n2,#0)|add(n2,#1)|multiply(#2,#0)|add(#2,#3)| | "2880 * 9 / 8 * 9 / 8 = 3645 answer : e" | general |
math_qa__pbIWz3DFF8yiAdoZ | A man is walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge is Choose one:
A) 1000 meters B) 1050 meters C) 1200 meters D) 1250 meters E) none of these | <gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">5 * (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 1_000</gadget>
<output>1_250</output>
<result>D</result> | D | 1,250 | A man is walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge is | {
"A": "1000 meters",
"B": "1050 meters",
"C": "1200 meters",
"D": "1250 meters",
"E": "none of these"
} | multiply(multiply(5, divide(15, const_60)), const_1000) | divide(n1,const_60)|multiply(n0,#0)|multiply(#1,const_1000)| | "explanation : we need to get the answer in meters . so we will first of change distance from km / hour to meter / sec by multiplying it with 5 / 18 and also change 15 minutes to seconds by multiplying it with 60 . answer : d" | gain |
math_qa__mEFcLx8myPXc1U00 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 840 grams per kg, what is his percent? Choices:
A) 19
B) 25
C) 77
D) 88
E) 11 | <gadget id="calculator">100 / 840</gadget>
<output>5/42 = around 0.119048</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">(5/42) * 1_000</gadget>
<output>2_500/21 = around 119.047619</output>
<gadget id="calculator">(2_500/21) - 100</gadget>
<output>400/21 = around 19.047619</output>
<result>A</result> | A | 19 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 840 grams per kg, what is his percent? | {
"A": "19",
"B": "25",
"C": "77",
"D": "88",
"E": "11"
} | subtract(multiply(divide(const_100, 840), multiply(const_100, multiply(add(const_3, const_2), const_2))), const_100) | add(const_2,const_3)|divide(const_100,n0)|multiply(#0,const_2)|multiply(#2,const_100)|multiply(#1,#3)|subtract(#4,const_100)| | "840 - - - 160 100 - - - ? = > 19 % answer : a" | gain |
math_qa__qW1g61udOq6sBmNP | The cost price of a radio is Rs.4800 and it was sold for Rs.4400, find the loss %? Choices
A) 8
B) 9
C) 7
D) 6
E) 4 | <gadget id="calculator">4_800 - 4_400</gadget>
<output>400</output>
<gadget id="calculator">400 / 4_800</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 100</gadget>
<output>25/3 = around 8.333333</output>
<result>A</result> | A | 8 | The cost price of a radio is Rs.4800 and it was sold for Rs.4400, find the loss %? | {
"A": "8",
"B": "9",
"C": "7",
"D": "6",
"E": "4"
} | multiply(divide(subtract(4800, 4400), 4800), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "4800 - - - - 400 100 - - - - ? = > 8 % answer : a" | gain |
math_qa__0okssyaFqr447pua | Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $150, what were her original savings? Choose the correct choice from the following: A) $ 500 B) $ 600 C) $ 700 D) $ 800 E) $ 900 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">150 / (1/4)</gadget>
<output>600</output>
<result>B</result> | B | 600 | Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $150, what were her original savings? | {
"A": "$ 500",
"B": "$ 600",
"C": "$ 700",
"D": "$ 800",
"E": "$ 900"
} | divide(150, subtract(const_1, divide(3, 4))) | divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1)| | "if linda spent 3 / 4 of her savings on furniture , the rest 4 / 4 - 3 / 4 = 1 / 4 on a tv but the tv cost her $ 150 . so 1 / 4 of her savings is $ 150 . so her original savings are 4 times $ 150 = $ 600 correct answer b" | general |
math_qa__9fGkHoTWMP7XATpl | If 8 people can eat a gallon of ice cream in 10 days, how long would it take 5 people to eat a gallon of ice cream?
Choose the correct choice from the following choices:
A) 12 days B) 14 days C) 16 days D) 18 days E) 20 days | <gadget id="calculator">8 * 10</gadget>
<output>80</output>
<gadget id="calculator">80 / 5</gadget>
<output>16</output>
<result>C</result> | C | 16 | If 8 people can eat a gallon of ice cream in 10 days, how long would it take 5 people to eat a gallon of ice cream? | {
"A": "12 days",
"B": "14 days",
"C": "16 days",
"D": "18 days",
"E": "20 days"
} | divide(multiply(8, 10), 5) | multiply(n0,n1)|divide(#0,n2) | 8 * 10 = 5 * x x = 16 answer : c | physics |
math_qa__v4QGlWMceyuCUchh | In what time will a train 20 m long cross an electric pole, it its speed be 144 km/hr? Answers
A) 2.5 sec
B) 2.8 sec
C) 0.5 sec
D) 2.3 sec
E) 1.5 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">20 / 40</gadget>
<output>1/2 = around 0.5</output>
<result>C</result> | C | 0.5 | In what time will a train 20 m long cross an electric pole, it its speed be 144 km/hr? | {
"A": "2.5 sec",
"B": "2.8 sec",
"C": "0.5 sec",
"D": "2.3 sec",
"E": "1.5 sec"
} | divide(20, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 144 * 5 / 18 = 40 m / sec time taken = 20 / 40 = 0.5 sec . answer : c" | physics |
math_qa__dHrOXolCg1Dp7B8n | The sum of number of boys and girls in a school is 150. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is? Choose the most appropriate option:
A) 50 B) 40 C) 60 D) 100 E) 70 | <gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">150 / (5/2)</gadget>
<output>60</output>
<result>C</result> | C | 60 | The sum of number of boys and girls in a school is 150. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is? | {
"A": "50",
"B": "40",
"C": "60",
"D": "100",
"E": "70"
} | divide(150, add(divide(150, const_100), const_1)) | divide(n0,const_100)|add(#0,const_1)|divide(n0,#1)| | "we have x + x % of 150 = 150 x + x / 100 * 150 = 150 5 / 2 * x = 150 x = 150 * 2 / 5 = 60 answer is c" | general |
math_qa__EW7mU6FsAGKsGR3n | Two trains A and B are 175 m and 150 m long and are moving at one another at 54 Km/hr and 36 Km/hr respectively. Arun is sitting on coach B1 of train A. Calculate the time taken by Arun to completely cross Train B. Choose the correct choice: A) 10 s B) 6 s C) 4 s D) 8 s E) 13 s | <gadget id="calculator">175 + 150</gadget>
<output>325</output>
<gadget id="calculator">54 * 1_000</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 / 3_600</gadget>
<output>15</output>
<gadget id="calculator">36 * 1_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 3_600</gadget>
<output>10</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">325 / 25</gadget>
<output>13</output>
<result>E</result> | E | 13 | Two trains A and B are 175 m and 150 m long and are moving at one another at 54 Km/hr and 36 Km/hr respectively. Arun is sitting on coach B1 of train A. Calculate the time taken by Arun to completely cross Train B. | {
"A": "10 s",
"B": "6 s",
"C": "4 s",
"D": "8 s",
"E": "13 s"
} | divide(add(175, 150), add(divide(multiply(54, const_1000), const_3600), divide(multiply(36, const_1000), const_3600))) | add(n0,n1)|multiply(n2,const_1000)|multiply(n3,const_1000)|divide(#1,const_3600)|divide(#2,const_3600)|add(#3,#4)|divide(#0,#5) | detailed solution speed of a = 54 ∗ 1000 / 60 ∗ 60 = 15 m / s speed of b = 36 ∗ 1000 / 60 ∗ 60 = 10 m / s relative speed = s 1 + s 2 = 15 + 10 m / s = 25 m / s the length that needs to be crossed = length of train b = 150 m . therefore time taken = 150 / 25 = 6 s . what is the time taken for trains to completely cross each other ? the length that needs to be crossed = 175 + 150 = 325 m . time taken = 325 / 25 = 13 s . correct answer e . | physics |
math_qa__t49b9aFSwTSWL4yj | A train traveling with constant speed crosses a 90m long platform in 12 seconds and a 120m long platform in 15 seconds.Find the length of the train and its speed. Options:
A) 30 B) 40 C) 60 D) 50 E) none | <gadget id="calculator">12 * 120</gadget>
<output>1_440</output>
<gadget id="calculator">90 * 15</gadget>
<output>1_350</output>
<gadget id="calculator">1_440 - 1_350</gadget>
<output>90</output>
<gadget id="calculator">15 - 12</gadget>
<output>3</output>
<gadget id="calculator">90 / 3</gadget>
<output>30</output>
<result>A</result> | A | 30 | A train traveling with constant speed crosses a 90m long platform in 12 seconds and a 120m long platform in 15 seconds.Find the length of the train and its speed. | {
"A": "30",
"B": "40",
"C": "60",
"D": "50",
"E": "none"
} | divide(subtract(multiply(12, 120), multiply(90, 15)), subtract(15, 12)) | multiply(n1,n2)|multiply(n0,n3)|subtract(n3,n1)|subtract(#0,#1)|divide(#3,#2) | let the length of the train be x m and its speed be y m / sec . then , x / y = 12 = > y = x / 12 ( x + 90 ) / 12 = x + 120 / 15 = > x = 30 m . answer : a | physics |
math_qa__K3TyuwBvP7a4z0nu | How many seconds will a train 130 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph? Choose the correct option: A) 28 sec B) 23 sec C) 24 sec D) 25 sec E) 26 sec | <gadget id="calculator">150 + 130</gadget>
<output>280</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">280 / 10</gadget>
<output>28</output>
<result>A</result> | A | 28 | How many seconds will a train 130 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph? | {
"A": "28 sec",
"B": "23 sec",
"C": "24 sec",
"D": "25 sec",
"E": "26 sec"
} | divide(add(150, 130), multiply(36, const_0_2778)) | add(n0,n1)|multiply(n2,const_0_2778)|divide(#0,#1)| | "d = 130 + 150 = 280 s = 36 * 5 / 18 = 10 mps t = 280 / 10 = 28 sec a" | physics |
math_qa__gVNBEiMm7rBDD1ZP | If m is an integer such that (-2)^2m=2^(18-m) then m=?
Choices.
A) 4
B) 5
C) 6
D) 7
E) 8 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<result>C</result> | C | 6 | If m is an integer such that (-2)^2m=2^(18-m) then m=? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | divide(18, add(2, const_1)) | add(n0,const_1)|divide(n3,#0)| | "2 m = 18 - m 3 m = 18 m = 6 the answer is c ." | general |
math_qa__JUtW8l1iCCdQQFIt | In a school of 850 boys, 44% of Muslims, 32% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Choices
A) 125 B) 119 C) 153 D) 721 E) 159 | <gadget id="calculator">44 + 32</gadget>
<output>76</output>
<gadget id="calculator">76 + 10</gadget>
<output>86</output>
<gadget id="calculator">100 - 86</gadget>
<output>14</output>
<gadget id="calculator">850 * 14</gadget>
<output>11_900</output>
<gadget id="calculator">11_900 / 100</gadget>
<output>119</output>
<result>B</result> | B | 119 | In a school of 850 boys, 44% of Muslims, 32% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities? | {
"A": "125",
"B": "119",
"C": "153",
"D": "721",
"E": "159"
} | divide(multiply(850, subtract(const_100, add(add(44, 32), 10))), const_100) | add(n1,n2)|add(n3,#0)|subtract(const_100,#1)|multiply(n0,#2)|divide(#3,const_100)| | "44 + 32 + 10 = 86 % 100 – 84 = 14 % 850 * 14 / 100 = 119 answer : b" | gain |
math_qa__34XeeBpzMhUP9OQJ | In 10 years, A will be twice as old5as B was 10 years ago. If A is now 12 years older than B, the present age of B is Choose the correct answer:
A) 35 B) 37 C) 39 D) 41 E) 42 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">12 + 10</gadget>
<output>22</output>
<gadget id="calculator">20 + 22</gadget>
<output>42</output>
<result>E</result> | E | 42 | In 10 years, A will be twice as old5as B was 10 years ago. If A is now 12 years older than B, the present age of B is | {
"A": "35",
"B": "37",
"C": "39",
"D": "41",
"E": "42"
} | add(multiply(const_2, 10), add(12, 10)) | add(n0,n3)|multiply(n0,const_2)|add(#0,#1)| | "explanation : let b ' s age = x years . then , as age = ( x + 12 ) years . ( x + 12 + 10 ) = 2 ( x — 10 ) hence x = 42 . present age of b = 42 years answer : option e" | general |
math_qa__whAMXGVzHkAzmM08 | Drum X is 1/2 full of oil and drum Y, which has twice the capacity of drum X, is 1/5 full of oil. If all of the oil in drum X is poured into drum Y, then drum Y will be filled to what capacity? Select the correct option
A) 3 / 10 B) 7 / 10 C) 9 / 10 D) 9 / 20 E) 13 / 20 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 12</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 * (1/2)</gadget>
<output>3</output>
<gadget id="calculator">(12/5) + 3</gadget>
<output>27/5 = around 5.4</output>
<gadget id="calculator">(27/5) / 12</gadget>
<output>9/20 = around 0.45</output>
<result>D</result> | D | 0.45 | Drum X is 1/2 full of oil and drum Y, which has twice the capacity of drum X, is 1/5 full of oil. If all of the oil in drum X is poured into drum Y, then drum Y will be filled to what capacity? | {
"A": "3 / 10",
"B": "7 / 10",
"C": "9 / 10",
"D": "9 / 20",
"E": "13 / 20"
} | divide(add(multiply(divide(1, 5), const_12), multiply(divide(const_12, 2), divide(1, 2))), const_12) | divide(n0,n3)|divide(const_12,n1)|divide(n0,n1)|multiply(#0,const_12)|multiply(#1,#2)|add(#3,#4)|divide(#5,const_12)| | "( 1 / 2 ) x = ( 1 / 4 ) y ( 1 / 4 ) y + ( 1 / 5 ) y = ( 9 / 20 ) y the answer is d ." | general |
math_qa__ynEaHIgTqxLkcOaz | the average age of 3 boys is 120 years and their ages are in proportion 2 : 6 : 8 . what is the age in years of the youngest boy ? Select.
A) 10 B) 9 C) 15 D) 6 E) 12 | <gadget id="calculator">2 + 6</gadget>
<output>8</output>
<gadget id="calculator">8 + 8</gadget>
<output>16</output>
<gadget id="calculator">120 / 16</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 2</gadget>
<output>15</output>
<result>C</result> | C | 15 | the average age of 3 boys is 120 years and their ages are in proportion 2 : 6 : 8 . what is the age in years of the youngest boy ? | {
"A": "10",
"B": "9",
"C": "15",
"D": "6",
"E": "12"
} | multiply(divide(120, add(add(2, 6), 8)), 2) | add(n2,n3)|add(n4,#0)|divide(n1,#1)|multiply(n2,#2) | 2 x + 6 x + 8 x = 120 x = 7.5 2 x = 15 answer : c | general |
math_qa__N2mcVt7wLiqVVM9X | rahul played weel in this season.his current batting averagge is 50.if he score 78 runs in today match.his batting average will become 54.how many matches had he played in this season.
Choose the correct choice from the following answers:
A) 8
B) 10
C) 9
D) 6
E) 5 | <gadget id="calculator">78 - 54</gadget>
<output>24</output>
<gadget id="calculator">54 - 50</gadget>
<output>4</output>
<gadget id="calculator">24 / 4</gadget>
<output>6</output>
<result>D</result> | D | 6 | rahul played weel in this season.his current batting averagge is 50.if he score 78 runs in today match.his batting average will become 54.how many matches had he played in this season. | {
"A": "8",
"B": "10",
"C": "9",
"D": "6",
"E": "5"
} | divide(subtract(78, 54), subtract(54, 50)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "50 x + 78 = 54 ( x + 1 ) = > 4 x = 24 = > x = 6 answer : d" | general |
math_qa__C86j2hEpJqvb9wCM | A circular well with a diameter of 6 metres , is dug to a depth of 24 metres. What is the volume of the earth dug out? Choose the correct choice from the following answers.
A) 678.6 m 3 B) 36 m 3 C) 40 m 3 D) 44 m 3 E) none | <gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">pi * (3 ** 2) * 24</gadget>
<output>216*pi = around 678.584013</output>
<result>A</result> | A | 678.6 | A circular well with a diameter of 6 metres , is dug to a depth of 24 metres. What is the volume of the earth dug out? | {
"A": "678.6 m 3",
"B": "36 m 3",
"C": "40 m 3",
"D": "44 m 3",
"E": "none"
} | volume_cylinder(divide(6, const_2), 24) | divide(n0,const_2)|volume_cylinder(#0,n1)| | "solution volume = π r 2 h ‹ = › ( 22 / 7 × 3 × 3 × 24 ) m 3 ‹ = › 678.6 m 3 . answer a" | geometry |
math_qa__d4Xu28GWxl2gxwKJ | A man cycling along the road noticed that every 12 minutes a bus overtakes him and every 4 minutes he meets an oncoming bus. If all buses and the cyclist move at a constant speed, what is the time interval between consecutive buses? Choose the correct choice from the following answers
A) 5 minutes
B) 6 minutes
C) 8 minutes
D) 9 minutes
E) 10 minutes | <gadget id="calculator">4 + 12</gadget>
<output>16</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">16 / 8</gadget>
<output>2</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">6 / 1</gadget>
<output>6</output>
<result>B</result> | B | 6 | A man cycling along the road noticed that every 12 minutes a bus overtakes him and every 4 minutes he meets an oncoming bus. If all buses and the cyclist move at a constant speed, what is the time interval between consecutive buses? | {
"A": "5 minutes",
"B": "6 minutes",
"C": "8 minutes",
"D": "9 minutes",
"E": "10 minutes"
} | divide(subtract(12, divide(12, divide(add(4, 12), subtract(12, 4)))), const_1) | add(n0,n1)|subtract(n0,n1)|divide(#0,#1)|divide(n0,#2)|subtract(n0,#3)|divide(#4,const_1)| | "let ' s say the distance between the buses is d . we want to determine interval = \ frac { d } { b } , where b is the speed of bus . let the speed of cyclist be c . every 12 minutes a bus overtakes cyclist : \ frac { d } { b - c } = 12 , d = 12 b - 12 c ; every 4 minutes cyclist meets an oncoming bus : \ frac { d } { b + c } = 4 , d = 4 b + 4 c ; d = 12 b - 12 c = 4 b + 4 c , - - > b = 2 c , - - > d = 12 b - 6 b = 6 b . interval = \ frac { d } { b } = \ frac { 6 b } { b } = 6 answer : b ( 6 minutes ) ." | physics |
math_qa__rHtd2kPS4Ibd89vh | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8900. If his salary for the month of May is Rs.6500, find his salary for the month of January? Options:
A) s . 2900
B) s . 3570
C) s . 4500
D) s . 4550
E) s . 2500 | <gadget id="calculator">8_000 * 4</gadget>
<output>32_000</output>
<gadget id="calculator">8_900 * 4</gadget>
<output>35_600</output>
<gadget id="calculator">35_600 - 6_500</gadget>
<output>29_100</output>
<gadget id="calculator">32_000 - 29_100</gadget>
<output>2_900</output>
<result>A</result> | A | 2,900 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8900. If his salary for the month of May is Rs.6500, find his salary for the month of January? | {
"A": "s . 2900",
"B": "s . 3570",
"C": "s . 4500",
"D": "s . 4550",
"E": "s . 2500"
} | subtract(multiply(8000, const_4), subtract(multiply(8900, const_4), 6500)) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#1,n2)|subtract(#0,#2)| | "sum of the salaries of the person for the months of january , february , march and april = 4 * 8000 = 32000 - - - - ( 1 ) sum of the salaries of the person for the months of february , march , april and may = 4 * 8900 = 35600 - - - - ( 2 ) ( 2 ) - ( 1 ) i . e . may - jan = 3600 salary of may is rs . 6500 salary of january = rs . 2900 answer : a" | general |
math_qa__gzYf9pH9mNfo5svF | 70% of the employees of a company are men. 50% of the men in the company speak French and 40% of the employees of the company speak French. What is % of the women in the company who do not speak French? Choose the correct choice:
A) 4 % B) 10 % C) 83.33 % D) 90.33 % E) 20 % | <gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(7/10) * (1/2)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(2/5) - (7/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(3/10) - (1/20)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / (3/10)</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(5/6) * 100</gadget>
<output>250/3 = around 83.333333</output>
<result>C</result> | C | 83.33 | 70% of the employees of a company are men. 50% of the men in the company speak French and 40% of the employees of the company speak French. What is % of the women in the company who do not speak French? | {
"A": "4 %",
"B": "10 %",
"C": "83.33 %",
"D": "90.33 %",
"E": "20 %"
} | multiply(divide(subtract(divide(subtract(const_100, 70), const_100), subtract(divide(40, const_100), multiply(divide(70, const_100), divide(50, const_100)))), divide(subtract(const_100, 70), const_100)), const_100) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(const_100,n0)|divide(#3,const_100)|multiply(#1,#2)|subtract(#0,#5)|subtract(#4,#6)|divide(#7,#4)|multiply(#8,const_100)| | "no of employees = 100 ( say ) men = 70 women = 30 men speaking french = 0.5 * 70 = 35 employees speaking french = 0.4 * 100 = 40 therefore women speaking french = 40 - 35 = 5 and women not speaking french = 30 - 5 = 25 % of women not speaking french = 25 / 30 * 100 = 83.33 % answer c" | gain |
math_qa__Er2xXoMAdYUEf0Qv | A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B's money was used ? Choose the correct answer: A) 10 B) 37 C) 27 D) 18 E) 19 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 - 1</gadget>
<output>10</output>
<result>A</result> | A | 10 | A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B's money was used ? | {
"A": "10",
"B": "37",
"C": "27",
"D": "18",
"E": "19"
} | subtract(add(const_10, 1), 1) | add(n0,const_10)|subtract(#0,n0) | let the total profit be rs . z . then , b ' s share = rs . 2 z / 3 , a ' s share = rs . ( z - 2 z / 3 ) = rs . z / 3 . a : b = z / 3 : 2 z / 3 = 1 : 2 let the total capital be rs , x and suppose b ' s money was used for x months . then . ( 1 ( x ) / 4 * 15 ) / ( 3 x ) / 4 * y ) = 1 / 2 < = > y = ( 15 * 2 / 3 ) = 10 . thus , b ' s money was used for 10 months . answer : a ) 10 months | gain |
math_qa__PHwqLapaBKUFCzvI | 3*15 + 3*16 + 3*19 + 11 = ?
Choose the correct option
A) 125 B) 126 C) 130 D) 148 E) 161 | <gadget id="calculator">3 * 15</gadget>
<output>45</output>
<gadget id="calculator">3 * 16</gadget>
<output>48</output>
<gadget id="calculator">45 + 48</gadget>
<output>93</output>
<gadget id="calculator">3 * 19</gadget>
<output>57</output>
<gadget id="calculator">93 + 57</gadget>
<output>150</output>
<gadget id="calculator">150 + 11</gadget>
<output>161</output>
<result>E</result> | E | 161 | 3*15 + 3*16 + 3*19 + 11 = ? | {
"A": "125",
"B": "126",
"C": "130",
"D": "148",
"E": "161"
} | add(add(add(multiply(3, 15), multiply(3, 16)), multiply(3, 19)), 11) | multiply(n0,n1)|multiply(n0,n3)|multiply(n0,n5)|add(#0,#1)|add(#3,#2)|add(n6,#4)| | "3 * 15 + 3 * 16 + 3 * 19 + 11 = 45 + 48 + 57 + 11 = 161 the answer is e ." | general |
math_qa__GPJil0vFsrFgTKq1 | A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in? Choose the correct choice from the following
A) 17 hr B) 19 hr C) 10 hr D) 14 hr E) 16 hr | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 / 3</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">1 / (7/3)</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(1/2) - (3/7)</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">1 / (1/14)</gadget>
<output>14</output>
<result>D</result> | D | 14 | A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in? | {
"A": "17 hr",
"B": "19 hr",
"C": "10 hr",
"D": "14 hr",
"E": "16 hr"
} | inverse(subtract(divide(1, 2), inverse(divide(add(multiply(2, 3), 1), 3)))) | divide(n2,n0)|multiply(n0,n3)|add(n2,#1)|divide(#2,n3)|inverse(#3)|subtract(#0,#4)|inverse(#5)| | "work done by the tank in 1 hour = ( 1 / 2 - 1 / 3 ) = 1 / 14 leak will empty the tank in 14 hrs . answer : d" | physics |
math_qa__lc8su4x0YvRoY9e7 | Right triangle PQR is to be constructed in the xy-plane so that the right angle is at P and PR is parallel to the x-axis. The x- and y-coordinates of P, Q and R are to be integers that satisfy the inequalities -4<=x<=5 and 6<=y<=16. How many different triangles with these properties could be constructed? Answers
A) 110 B) 1100 C) 9900 D) 10000 E) 12100 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">16 - 5</gadget>
<output>11</output>
<gadget id="calculator">10 * 11</gadget>
<output>110</output>
<gadget id="calculator">9 * 110</gadget>
<output>990</output>
<gadget id="calculator">990 * 10</gadget>
<output>9_900</output>
<result>C</result> | C | 9,900 | Right triangle PQR is to be constructed in the xy-plane so that the right angle is at P and PR is parallel to the x-axis. The x- and y-coordinates of P, Q and R are to be integers that satisfy the inequalities -4<=x<=5 and 6<=y<=16. How many different triangles with these properties could be constructed? | {
"A": "110",
"B": "1100",
"C": "9900",
"D": "10000",
"E": "12100"
} | multiply(multiply(subtract(const_10, const_1), multiply(add(6, 4), subtract(16, 5))), const_10) | add(n0,n2)|subtract(n3,n1)|subtract(const_10,const_1)|multiply(#0,#1)|multiply(#3,#2)|multiply(#4,const_10)| | "we know that p , q , r can only lie on a grid 10 x 11 let ' s start by fixing p ' x - coordinate : we have 10 possible places for it then we choose x - coordinate for r : since pr | | x - axis , r ' s x - coordinate can not coincide with p ' s x - coord , so we have only 9 possible choices left . then , we fix p ' s ( and r ' s too ) y - coordinate : 11 possible choices . finally , after we fixed p and r , q ' s x - coordinate must be the same as p ' s ( because p is the right angle and pr | | x - axis ) , so the only choice is for y - coordinate , and we have 10 possible choices left . so , total number of different triangles : 10 * 9 * 11 * 10 = 9,900 answer : c" | general |
math_qa__L1grwwwtnx2oAdX6 | Sand is poured into a box so that the box is being filled at the rate of 3 cubic feet per hour. If the empty rectangular box is 5 feet long, 4 feet wide, and 3 feet deep, approximately how many hours does it take to fill the box? Choose the correct option:
A) 14 B) 16 C) 18 D) 20 E) 22 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<result>D</result> | D | 20 | Sand is poured into a box so that the box is being filled at the rate of 3 cubic feet per hour. If the empty rectangular box is 5 feet long, 4 feet wide, and 3 feet deep, approximately how many hours does it take to fill the box? | {
"A": "14",
"B": "16",
"C": "18",
"D": "20",
"E": "22"
} | divide(multiply(multiply(5, 4), 3), 3) | multiply(n1,n2)|multiply(n3,#0)|divide(#1,n0)| | "the volume the box is : length * width * depth = 5 * 4 * 3 = 60 cubic feet . 60 cubic feet / 3 cubic feet per hour = 20 hours . it will take 20 hours to fill the box . the answer is d ." | geometry |
math_qa__79COsza9otI1aB3X | Jack and Christina are standing 270 feet apart on a level surface. Their dog, Lindy, is standing next to Christina. At the same time, they all begin moving toward each other. Jack walks in a straight line toward Christina at a constant speed of 4 feet per second and Christina walks in a straight line toward Jack at a constant speed of 5 feet per second. Lindy runs at a constant speed of 8 feet per second from Christina to Jack, back to Christina, back to Jack, and so forth. What is the total distance, in feet, that Lindy has traveled when the three meet at one place? Select the correct option.
A) 150 B) 180 C) 210 D) 240 E) 270 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">270 / 9</gadget>
<output>30</output>
<gadget id="calculator">30 * 8</gadget>
<output>240</output>
<result>D</result> | D | 240 | Jack and Christina are standing 270 feet apart on a level surface. Their dog, Lindy, is standing next to Christina. At the same time, they all begin moving toward each other. Jack walks in a straight line toward Christina at a constant speed of 4 feet per second and Christina walks in a straight line toward Jack at a constant speed of 5 feet per second. Lindy runs at a constant speed of 8 feet per second from Christina to Jack, back to Christina, back to Jack, and so forth. What is the total distance, in feet, that Lindy has traveled when the three meet at one place? | {
"A": "150",
"B": "180",
"C": "210",
"D": "240",
"E": "270"
} | multiply(divide(270, add(4, 5)), 8) | add(n1,n2)|divide(n0,#0)|multiply(n3,#1)| | "the relative speed of jack and christina is 4 + 5 = 9 feet per second . the distance between them is 210 feet , hence they will meet in ( time ) = ( distance ) / ( relative speed ) = 270 / 7 = 30 seconds . for all this time lindy was running back and forth , so it covered ( distance ) = ( speed ) * ( time ) = 8 * 30 = 240 feet . answer : d ." | physics |
math_qa__ZCMqqMycIInl9BSp | Man1 alone can do a piece of work in 6 days and Man2 alone in 8 days. Man1 and Man2 undertook to do it for Rs. 3200. With the help of Man3, they completed the work in 3 days. How much is to be paid to Man3? Pick: A) 400 B) 200 C) 100 D) 150 E) 500 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/6) + (1/8)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">(1/3) - (7/24)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<gadget id="calculator">3 / 24</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">3_200 * (1/8)</gadget>
<output>400</output>
<result>A</result> | A | 400 | Man1 alone can do a piece of work in 6 days and Man2 alone in 8 days. Man1 and Man2 undertook to do it for Rs. 3200. With the help of Man3, they completed the work in 3 days. How much is to be paid to Man3? | {
"A": "400",
"B": "200",
"C": "100",
"D": "150",
"E": "500"
} | multiply(3200, divide(3, inverse(subtract(divide(const_1, 3), add(divide(const_1, 6), divide(const_1, 8)))))) | divide(const_1,n7)|divide(const_1,n1)|divide(const_1,n3)|add(#1,#2)|subtract(#0,#3)|inverse(#4)|divide(n7,#5)|multiply(n6,#6) | man 3 1 day work = 1 / 3 - ( 1 / 6 + 1 / 8 ) = 1 / 3 - 7 / 24 = 1 / 24 man 1 : man 2 : man 3 = 1 / 6 : 1 / 8 : 1 / 24 = = > 4 : 3 : 1 man 3 share = 3 * 1 / 24 * 3200 = rs 400 answer a | physics |
math_qa__X0b12JLF4JfRD6Zg | In Arun's opinion, his weight is greater than 65 kg but leas than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of diferent probable weights of Arun ? Choose the correct choice:
A) 16.5 kg B) 66.5 kg C) 26.5 kg D) 56.5 kg E) 86.5 kg | <gadget id="calculator">65 + 1</gadget>
<output>66</output>
<gadget id="calculator">68 + 66</gadget>
<output>134</output>
<gadget id="calculator">134 / 2</gadget>
<output>67</output>
<result>B</result> | B | 66.5 | In Arun's opinion, his weight is greater than 65 kg but leas than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of diferent probable weights of Arun ? | {
"A": "16.5 kg",
"B": "66.5 kg",
"C": "26.5 kg",
"D": "56.5 kg",
"E": "86.5 kg"
} | divide(add(68, add(65, const_1)), const_2) | add(n0,const_1)|add(n4,#0)|divide(#1,const_2)| | "let arun ' s weight be x kg . according to arun , 65 < x < 72 . according to arun ' s brother , 60 < x < 70 . according to arun ' s mother , x < 68 . the values satisfying all the above conditions are 66 and 67 . required average = ( 66 + 67 ) / 2 = 66.5 kg answer : b" | general |
math_qa__sDlbGszr4TwXYzH4 | Ramesh purchased a refrigerator for Rs. 15500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered? Choose the correct option:
A) 34778
B) 26888
C) 2899
D) 17600
E) 21725 | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">15_500 * 100</gadget>
<output>1_550_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">1_550_000 / 80</gadget>
<output>19_375</output>
<gadget id="calculator">125 + 250</gadget>
<output>375</output>
<gadget id="calculator">19_375 + 375</gadget>
<output>19_750</output>
<gadget id="calculator">110 * 19_750</gadget>
<output>2_172_500</output>
<gadget id="calculator">2_172_500 / 100</gadget>
<output>21_725</output>
<result>E</result> | E | 21,725 | Ramesh purchased a refrigerator for Rs. 15500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered? | {
"A": "34778",
"B": "26888",
"C": "2899",
"D": "17600",
"E": "21725"
} | divide(multiply(add(const_100, 10), add(divide(multiply(15500, const_100), subtract(const_100, 20)), add(125, 250))), const_100) | add(n4,const_100)|add(n2,n3)|multiply(n0,const_100)|subtract(const_100,n1)|divide(#2,#3)|add(#1,#4)|multiply(#0,#5)|divide(#6,const_100)| | "price at which the tv set is bought = rs . 15,500 discount offered = 20 % marked price = 15500 * 100 / 80 = rs . 19375 the total amount spent on transport and installation = 125 + 250 = rs . 375 \ total price of tv set = 19375 + 375 = rs . 19750 the price at which the tv should be sold to get a profit of 10 % if no discount was offered = 19750 * 110 / 100 = rs . 21725 answer : e" | gain |
math_qa__UWjZDjHWbjhzcUps | How many numbers from 10 to 1000000 are exactly divisible by 9? Pick one.
A) 900 B) 8000 C) 1100 D) 111110 E) 14 | <gadget id="calculator">1_000_000 / 9</gadget>
<output>1_000_000/9 = around 111_111.111111</output>
<gadget id="calculator">floor(1_000_000/9)</gadget>
<output>111_111</output>
<gadget id="calculator">111_111 * 9</gadget>
<output>999_999</output>
<gadget id="calculator">10 / 9</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">floor(10/9)</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 9</gadget>
<output>18</output>
<gadget id="calculator">999_999 - 18</gadget>
<output>999_981</output>
<gadget id="calculator">999_981 / 9</gadget>
<output>111_109</output>
<gadget id="calculator">111_109 + 1</gadget>
<output>111_110</output>
<result>D</result> | D | 111,110 | How many numbers from 10 to 1000000 are exactly divisible by 9? | {
"A": "900",
"B": "8000",
"C": "1100",
"D": "111110",
"E": "14"
} | add(divide(subtract(multiply(floor(divide(1000000, 9)), 9), multiply(add(floor(divide(10, 9)), const_1), 9)), 9), const_1) | divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|add(#3,const_1)|multiply(n2,#2)|multiply(n2,#4)|subtract(#5,#6)|divide(#7,n2)|add(#8,const_1)| | "10 / 9 = 1 and 1000000 / 9 = 111111 = = > 111111 - 1 = 111110 . answer : d" | general |
math_qa__aLzGMuvg4d4yOlyW | A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train?
Choose the correct choice from the following
A) 150 B) 872 C) 287 D) 288 E) 212 | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 9</gadget>
<output>150</output>
<result>A</result> | A | 150 | A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train? | {
"A": "150",
"B": "872",
"C": "287",
"D": "288",
"E": "212"
} | multiply(divide(multiply(60, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * ( 5 / 18 ) m / sec = 50 / 3 m / sec length of train ( distance ) = speed * time ( 50 / 3 ) * 9 = 150 meter answer : a" | physics |
math_qa__7qDcho9IUoGWiDCu | A rectangular plot measuring 30 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed? Choose the correct choice
A) 46 m B) 66 m C) 26 m D) 56 m E) 32 m | <gadget id="calculator">30 + 50</gadget>
<output>80</output>
<gadget id="calculator">80 * 2</gadget>
<output>160</output>
<gadget id="calculator">160 / 5</gadget>
<output>32</output>
<result>E</result> | E | 32 | A rectangular plot measuring 30 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed? | {
"A": "46 m",
"B": "66 m",
"C": "26 m",
"D": "56 m",
"E": "32 m"
} | divide(multiply(add(30, 50), const_2), 5) | add(n0,n1)|multiply(#0,const_2)|divide(#1,n2)| | "perimeter of the plot = 2 ( 30 + 50 ) = 160 m no of poles = 160 / 5 = 32 m answer : e" | physics |
math_qa__KWZm1efaGHTwjjK1 | A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list? Choose the correct option: A) 1 / 20 B) 1 / 6 C) 1 / 5 D) 4 / 21 E) 5 / 21 | <gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">5 + 21</gadget>
<output>26</output>
<gadget id="calculator">26 / 4</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">(13/2) * 2</gadget>
<output>13</output>
<gadget id="calculator">13 - 4</gadget>
<output>9</output>
<gadget id="calculator">9 - 3</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<result>B</result> | B | 0.166667 | A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list? | {
"A": "1 / 20",
"B": "1 / 6",
"C": "1 / 5",
"D": "4 / 21",
"E": "5 / 21"
} | divide(multiply(const_1, const_1), subtract(subtract(multiply(divide(add(divide(20, 4), 21), 4), const_2), 4), const_3)) | divide(n2,n1)|multiply(const_1,const_1)|add(n0,#0)|divide(#2,n1)|multiply(#3,const_2)|subtract(#4,n1)|subtract(#5,const_3)|divide(#1,#6)| | "series : a 1 , a 2 . . . . a 20 , n sum of a 1 + a 2 + . . . + a 20 = 20 * x ( x = average ) so , n = 4 * x hence , a 1 + a 2 + . . + a 20 + n = 24 x so , the fraction asked = 4 x / 24 x = 1 / 6 ; answer : b ." | general |
math_qa__Fi7RZlBJqjVfsOrw | A batsman in his 12th innings makes a score of 80 and thereby increases his average by 2 runs. What is his average after the 12th innings if he had never been ‘not out’? Choose the correct choice from the following options
A) 42 B) 43 C) 44 D) 45 E) 58 | <gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">80 - 24</gadget>
<output>56</output>
<gadget id="calculator">56 + 2</gadget>
<output>58</output>
<result>E</result> | E | 58 | A batsman in his 12th innings makes a score of 80 and thereby increases his average by 2 runs. What is his average after the 12th innings if he had never been ‘not out’? | {
"A": "42",
"B": "43",
"C": "44",
"D": "45",
"E": "58"
} | add(subtract(80, multiply(12, 2)), 2) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1)| | "let ‘ x ’ be the average score after 12 th innings ⇒ 12 x = 11 × ( x – 2 ) + 80 ∴ x = 58 answer e" | general |
math_qa__o2RcGmRBI0QVBypY | Danny can divide his herd into 5 equal parts and also to 6 equal parts, but not to 9 equal parts. What could be the number of cows Danny has in his herd? Choose the correct choice from the following choices
A) 120
B) 155
C) 180
D) 336
E) 456 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<result>A</result> | A | 120 | Danny can divide his herd into 5 equal parts and also to 6 equal parts, but not to 9 equal parts. What could be the number of cows Danny has in his herd? | {
"A": "120",
"B": "155",
"C": "180",
"D": "336",
"E": "456"
} | add(const_100, multiply(5, const_4)) | multiply(n0,const_4)|add(#0,const_100) | danny can divide his herd into 5 equal parts and also to 6 equal parts = > no of cows = multiple of 5 and 6 = multiple of 30 . only option a and c qualify . now 2 nd condition : but not to 9 equal parts : so it should not be a multiple of 9 . answer : a | general |
math_qa__osK5GN0vIyfKdEtB | How much is 90% of 40 is greater than 4/5 of 25?
Select the correct option.
A) 29 B) 776 C) 66 D) 16 E) 99 | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">40 * (9/10)</gadget>
<output>36</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 25</gadget>
<output>20</output>
<gadget id="calculator">36 - 20</gadget>
<output>16</output>
<result>D</result> | D | 16 | How much is 90% of 40 is greater than 4/5 of 25? | {
"A": "29",
"B": "776",
"C": "66",
"D": "16",
"E": "99"
} | subtract(multiply(40, divide(90, const_100)), multiply(divide(4, 5), 25)) | divide(n0,const_100)|divide(n2,n3)|multiply(n1,#0)|multiply(n4,#1)|subtract(#2,#3)| | "( 90 / 100 ) * 40 – ( 4 / 5 ) * 25 36 - 20 = 16 answer : d" | general |
math_qa__db4AlO8796urJgnx | A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 6 inches, then what is the maximum number of soap boxes that can be placed in each carton? Choose the correct answer
A) 210 B) 252 C) 250 D) 300 E) 420 | <gadget id="calculator">25 * 42</gadget>
<output>1_050</output>
<gadget id="calculator">1_050 * 60</gadget>
<output>63_000</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">42 * 6</gadget>
<output>252</output>
<gadget id="calculator">63_000 / 252</gadget>
<output>250</output>
<result>C</result> | C | 250 | A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 6 inches, then what is the maximum number of soap boxes that can be placed in each carton? | {
"A": "210",
"B": "252",
"C": "250",
"D": "300",
"E": "420"
} | divide(multiply(multiply(25, 42), 60), multiply(multiply(7, 6), 6)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|multiply(n5,#1)|divide(#2,#3)| | "however the process of dividing the volume of box by the volume of a soap seems flawed but it does work in this case due to the numbers dimensions of the box = 25 * 42 * 60 dimensions of the soap = 6 * 6 * 7 placing the 7 inch side along 42 inch side we get 6 soaps in a line and in a similar way 5 along 25 and 6 along 60 we get = 5 x 5 x 10 = 250 so the question is why this particular arrangement , in order to maximize number of soaps we need to minimize the space wasted and this is the only config where we dont waste any space so we can expect the maximum number the answer is ( c )" | general |
math_qa__IkGXd8YidkSY2DPS | Suresh and Ramesh started a business investing Rs. 24,000 and Rs. 40,000 respectively. Out of total profit of Rs. 19,000, what is Ramesh's share? Choose the most appropriate option: A) s . 7375 B) s . 8379 C) s . 9875 D) s . 10875 E) s . 11875 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">40 * 1_000</gadget>
<output>40_000</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 - 5</gadget>
<output>19</output>
<gadget id="calculator">19 * 1_000</gadget>
<output>19_000</output>
<gadget id="calculator">24 * 1_000</gadget>
<output>24_000</output>
<gadget id="calculator">24_000 + 40_000</gadget>
<output>64_000</output>
<gadget id="calculator">19_000 / 64_000</gadget>
<output>19/64 = around 0.296875</output>
<gadget id="calculator">40_000 * (19/64)</gadget>
<output>11_875</output>
<result>E</result> | E | 11,875 | Suresh and Ramesh started a business investing Rs. 24,000 and Rs. 40,000 respectively. Out of total profit of Rs. 19,000, what is Ramesh's share? | {
"A": "s . 7375",
"B": "s . 8379",
"C": "s . 9875",
"D": "s . 10875",
"E": "s . 11875"
} | multiply(multiply(multiply(const_4, multiply(const_2, add(const_2, const_3))), multiply(const_100, multiply(const_2, add(const_2, const_3)))), divide(multiply(subtract(multiply(multiply(const_3, const_4), const_2), add(const_2, const_3)), multiply(const_100, multiply(const_2, add(const_2, const_3)))), add(multiply(multiply(multiply(const_3, const_4), const_2), multiply(const_100, multiply(const_2, add(const_2, const_3)))), multiply(multiply(const_4, multiply(const_2, add(const_2, const_3))), multiply(const_100, multiply(const_2, add(const_2, const_3))))))) | add(const_2,const_3)|multiply(const_3,const_4)|multiply(#0,const_2)|multiply(#1,const_2)|multiply(#2,const_100)|multiply(#2,const_4)|subtract(#3,#0)|multiply(#4,#6)|multiply(#3,#4)|multiply(#5,#4)|add(#8,#9)|divide(#7,#10)|multiply(#11,#9) | explanation : ratio of suresh and ramesh ' s share = 24,000 : 40,000 = 3 : 5 ramesh ' s share = rs . ( 19000 x 5 / 8 ) = rs . 11875 answer : e | gain |
math_qa__CSLoi1yfb8UykunG | If difference between compound interest and simple interest on a sum at 5% P.a. for 2 years is Rs.60, then what is the sum? Options:
A) rs . 8000 B) rs . 4000 C) rs . 5000 D) rs . 6000 E) rs . 24000 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * (1/20)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">60 / (1/400)</gadget>
<output>24_000</output>
<result>E</result> | E | 24,000 | If difference between compound interest and simple interest on a sum at 5% P.a. for 2 years is Rs.60, then what is the sum? | {
"A": "rs . 8000",
"B": "rs . 4000",
"C": "rs . 5000",
"D": "rs . 6000",
"E": "rs . 24000"
} | divide(60, multiply(divide(5, const_100), divide(5, const_100))) | divide(n0,const_100)|multiply(#0,#0)|divide(n2,#1)| | "c . i - s . i = 60 si = ( x * 2 * 5 ) / 100 = x / 10 ci = { x * ( 1 + 5 / 100 ) ^ 2 - x } = 41 x / 400 ci - si = 41 x / 400 - x / 10 = 60 x = 24000 answer : e" | gain |
math_qa__WzNdFXkD6aVW93FK | A larger cube has 343 cubic inch as a volume and in the cube there are 343 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 343 smaller cubes and the surface area of the larger cube, in square inch? Choose the correct choice
A) 54 B) 64 C) 81 D) 108 E) 1764 | <gadget id="calculator">1 ** (1/3)</gadget>
<output>1</output>
<gadget id="calculator">6 * (1 ** 2)</gadget>
<output>6</output>
<gadget id="calculator">6 * 343</gadget>
<output>2_058</output>
<gadget id="calculator">343 ** (1/3)</gadget>
<output>7</output>
<gadget id="calculator">6 * (7 ** 2)</gadget>
<output>294</output>
<gadget id="calculator">2_058 - 294</gadget>
<output>1_764</output>
<result>E</result> | E | 1,764 | A larger cube has 343 cubic inch as a volume and in the cube there are 343 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 343 smaller cubes and the surface area of the larger cube, in square inch? | {
"A": "54",
"B": "64",
"C": "81",
"D": "108",
"E": "1764"
} | subtract(multiply(surface_cube(cube_edge_by_volume(1)), 343), surface_cube(cube_edge_by_volume(343))) | cube_edge_by_volume(n2)|cube_edge_by_volume(n0)|surface_cube(#0)|surface_cube(#1)|multiply(n0,#2)|subtract(#4,#3)| | "volume of larger cube = 343 = 7 ^ 3 side of larger cube = 7 volume of smaller cube = 1 - - > side of smaller cube = 1 surface area of larger cube = 6 * 7 ^ 2 = 294 surface area of 27 smaller cubes = 343 * 6 * 1 = 2058 difference = 2058 - 294 = 1764 answer : e" | geometry |
math_qa__R6XLO3tRlbbFozf9 | If it is assumed that 60 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed?
Choose the correct choice from the following choices: A) 400 B) 420 C) 480 D) 500 E) 600 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">300 / (3/5)</gadget>
<output>500</output>
<result>D</result> | D | 500 | If it is assumed that 60 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed? | {
"A": "400",
"B": "420",
"C": "480",
"D": "500",
"E": "600"
} | divide(300, divide(60, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "minimum no of mail to be sent for getting 300 responses at 60 % = 300 / 0.6 = 500 option d" | gain |
math_qa__IM1A0nreEIwIeQpm | A person crosses a 1000 m long street in 10 minutes. What is his speed in km per hour? Choose the correct choice from the following answers:
A) 7.1 B) 8.2 C) 4.6 D) 6.0 E) 12.8 | <gadget id="calculator">1_000 / 1_000</gadget>
<output>1</output>
<gadget id="calculator">10 * 60</gadget>
<output>600</output>
<gadget id="calculator">600 / 3_600</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>D</result> | D | 6 | A person crosses a 1000 m long street in 10 minutes. What is his speed in km per hour? | {
"A": "7.1",
"B": "8.2",
"C": "4.6",
"D": "6.0",
"E": "12.8"
} | divide(divide(1000, const_1000), divide(multiply(10, const_60), const_3600)) | divide(n0,const_1000)|multiply(n1,const_60)|divide(#1,const_3600)|divide(#0,#2)| | "distance = 1000 meter time = 10 minutes = 10 x 60 seconds = 600 seconds speed = distance / time = 1000 / 600 = 1.67 m / s = 1.67 ã — 18 / 5 km / hr = 6.0 km / hr answer : d" | physics |
math_qa__xdwPyvKODgnrf9IY | How long does a train 110 m long travelling at 60 kmph takes to cross a bridge of 170 m in length? Choose one:
A) 15.8 sec B) 14.9 sec C) 12.4 sec D) 16.8 sec E) 11.8 sec | <gadget id="calculator">110 + 170</gadget>
<output>280</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">280 / (50/3)</gadget>
<output>84/5 = around 16.8</output>
<result>D</result> | D | 16.8 | How long does a train 110 m long travelling at 60 kmph takes to cross a bridge of 170 m in length? | {
"A": "15.8 sec",
"B": "14.9 sec",
"C": "12.4 sec",
"D": "16.8 sec",
"E": "11.8 sec"
} | divide(add(110, 170), multiply(60, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "d 16.8 sec d = 110 + 170 = 280 m s = 60 * 5 / 18 = 50 / 3 t = 280 * 3 / 50 = 16.8 sec" | physics |
math_qa__Q1pZClJxpo99S6p5 | Two trains from opposite directions are to cross each other. The length of two trains are 100 meter and 200 meter respectively. The speed of first train is 100 km/hour and second train 200 km/hour. In how much time will they cross each other? Choose the correct option:
A) 2 second
B) 3.6 second
C) 5 second
D) 5.5 second
E) 6 second | <gadget id="calculator">100 + 200</gadget>
<output>300</output>
<gadget id="calculator">300 * 1_000</gadget>
<output>300_000</output>
<gadget id="calculator">300_000 / 3_600</gadget>
<output>250/3 = around 83.333333</output>
<gadget id="calculator">300 / (250/3)</gadget>
<output>18/5 = around 3.6</output>
<result>B</result> | B | 3.6 | Two trains from opposite directions are to cross each other. The length of two trains are 100 meter and 200 meter respectively. The speed of first train is 100 km/hour and second train 200 km/hour. In how much time will they cross each other? | {
"A": "2 second",
"B": "3.6 second",
"C": "5 second",
"D": "5.5 second",
"E": "6 second"
} | divide(add(100, 200), divide(multiply(add(100, 200), const_1000), const_3600)) | add(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|divide(#0,#2) | the crossing moment starts when the head of first compartment of two trains meet or touch . the process of crossing each other continues till 100 + 200 meter = 300 meter is covered . the speed will be 100 km / hour + 200 km / hour = 300 km / hour . 300 x 1000 meter covered in 3600 seconds . so , 300 meter covered in 3.6 seconds . answer : b . | physics |
math_qa__9QcR7Xb7mkhRqsoz | Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: Choose the correct choice from the following answers
A) 4 B) 5 C) 6 D) 8 E) 10 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<result>A</result> | A | 4 | Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: | {
"A": "4",
"B": "5",
"C": "6",
"D": "8",
"E": "10"
} | add(add(const_1, const_1), const_2) | add(const_1,const_1)|add(#0,const_2)| | "explanation : n = h . c . f . of ( 4665 - 1305 ) , ( 6905 - 4665 ) and ( 6905 - 1305 ) = h . c . f . of 3360 , 2240 and 5600 = 1120 . sum of digits in n = ( 1 + 1 + 2 + 0 ) = 4 answer is a" | general |
math_qa__arEPPYQ7Yz13rbfQ | In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of five metre is left from all sides of the boundary of the garden. What is the length of the garden?
Choices.
A) 32 B) 24 C) 26 D) 28 E) 30 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">22 + 5</gadget>
<output>27</output>
<gadget id="calculator">27 + 5</gadget>
<output>32</output>
<result>A</result> | A | 32 | In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of five metre is left from all sides of the boundary of the garden. What is the length of the garden? | {
"A": "32",
"B": "24",
"C": "26",
"D": "28",
"E": "30"
} | add(add(multiply(subtract(12, const_1), 2), divide(10, 2)), divide(10, 2)) | divide(n0,n2)|subtract(n1,const_1)|multiply(n2,#1)|add(#0,#2)|add(#3,#0) | between the 12 mango trees , there are 11 gaps and each gap has 2 meter length also , 5 meter is left from all sides of the boundary of the garden . hence , length of the garden = ( 11 ã — 2 ) + 5 + 5 = 32 meter answer is a . | physics |
math_qa__soCe33H3Ju5eMf7K | Darcy lives 1.5 miles from work. She can walk to work at a constant rate of 3 miles per hour, or she can ride the train to work at a constant rate of 20 miles per hour. If she rides the train, there is an additional x minutes spent walking to the nearest train station, waiting for the train, and walking from the final train station to her work. If it takes Darcy a total of 2 more minutes to commute to work by walking than it takes her to commute to work by riding the train, what is the value of x? Choose the correct choice from the following answers:
A) 10.5
B) 15
C) 25.5
D) 30
E) 23.5 | <gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 - 2</gadget>
<output>28</output>
<gadget id="calculator">20 / 1.5</gadget>
<output>13.333333</output>
<gadget id="calculator">60 / 13.333333</gadget>
<output>4.5</output>
<gadget id="calculator">28 - 4.5</gadget>
<output>23.5</output>
<result>E</result> | E | 23.5 | Darcy lives 1.5 miles from work. She can walk to work at a constant rate of 3 miles per hour, or she can ride the train to work at a constant rate of 20 miles per hour. If she rides the train, there is an additional x minutes spent walking to the nearest train station, waiting for the train, and walking from the final train station to her work. If it takes Darcy a total of 2 more minutes to commute to work by walking than it takes her to commute to work by riding the train, what is the value of x? | {
"A": "10.5",
"B": "15",
"C": "25.5",
"D": "30",
"E": "23.5"
} | subtract(subtract(divide(const_60, const_2), 2), divide(const_60, divide(20, 1.5))) | divide(const_60,const_2)|divide(n2,n0)|divide(const_60,#1)|subtract(#0,n3)|subtract(#3,#2)| | "the time it takes darcy to walk to work is ( 1.5 / 3 ) * 60 = 30 minutes the time it takes darcy to take the train is ( 1.5 / 20 ) * 60 + x = 4.5 + x minutes it takes 15 minutes longer to walk , so 30 = 4.5 + x + 2 x = 23.5 minutes answer : e" | physics |
math_qa__JJsjRDrD3Bne57qs | A driver would have reduced the time it took to drive from home to the store by 1/4 if the average speed had been increased by 12 miles per hour. What was the actual average speed, in miles per hour, when the driver drove from home to the store?
Choose the correct choice from the following
A) 24 B) 28 C) 32 D) 36 E) 40 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 12</gadget>
<output>9</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">9 / (1/4)</gadget>
<output>36</output>
<result>D</result> | D | 36 | A driver would have reduced the time it took to drive from home to the store by 1/4 if the average speed had been increased by 12 miles per hour. What was the actual average speed, in miles per hour, when the driver drove from home to the store? | {
"A": "24",
"B": "28",
"C": "32",
"D": "36",
"E": "40"
} | divide(multiply(subtract(1, divide(1, 4)), 12), subtract(1, subtract(1, divide(1, 4)))) | divide(n0,n1)|subtract(n0,#0)|multiply(#1,n2)|subtract(n0,#1)|divide(#2,#3)| | "since the distance remains the same ( we ' re just changing the rate and time ) , any increase in rate or time is met with a decrease in the other term . decreasing the time by 1 / 4 would give us : d = ( r ) ( t ) = ( 3 t / 4 ) ( x * r ) x = 4 / 3 since ( 3 t / 4 ) ( 4 r / 3 ) = ( r ) ( t ) = d 4 r / 3 = r + 12 r / 3 = 12 r = 36 the answer is d ." | general |
math_qa__tKw9k3AOT2HJTFDu | A certain company expects quarterly earnings of $0.80 per share of stock, half of which will be distributed as dividends to shareholders while the rest will be used for research and development. If earnings are greater than expected , shareholders will receive an additional $0.04 per share for each additional $0.10 of per share earnings. If quarterly earnings are $1.10 per share, what will be the dividend paid to a person who owns 300 shares of the company's stock? Answers.
A) $ 92 B) $ 96 C) $ 156 D) $ 120 E) $ 240 | <gadget id="calculator">0.8 / 2</gadget>
<output>0.4</output>
<gadget id="calculator">1.1 - 0.8</gadget>
<output>0.3</output>
<gadget id="calculator">0.3 * 10</gadget>
<output>3</output>
<gadget id="calculator">3 * 0.04</gadget>
<output>0.12</output>
<gadget id="calculator">0.4 + 0.12</gadget>
<output>0.52</output>
<gadget id="calculator">0.52 * 300</gadget>
<output>156</output>
<result>C</result> | C | 156 | A certain company expects quarterly earnings of $0.80 per share of stock, half of which will be distributed as dividends to shareholders while the rest will be used for research and development. If earnings are greater than expected , shareholders will receive an additional $0.04 per share for each additional $0.10 of per share earnings. If quarterly earnings are $1.10 per share, what will be the dividend paid to a person who owns 300 shares of the company's stock? | {
"A": "$ 92",
"B": "$ 96",
"C": "$ 156",
"D": "$ 120",
"E": "$ 240"
} | multiply(add(divide(0.80, const_2), multiply(multiply(subtract(1.10, 0.80), const_10), 0.04)), 300) | divide(n0,const_2)|subtract(n3,n0)|multiply(#1,const_10)|multiply(n1,#2)|add(#0,#3)|multiply(n4,#4)| | "eps actual > eps expected . each gets and additional . 12 per share . thus . 52 * 300 - - > $ 156 answer is c" | general |
math_qa__PfUdxd76uogOvmAb | The difference of two numbers is 1360. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
Pick.
A) 240
B) 270
C) 295
D) 360
E) 269 | <gadget id="calculator">1_360 + 15</gadget>
<output>1_375</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_375 / 5</gadget>
<output>275</output>
<result>E</result> | E | 269 | The difference of two numbers is 1360. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? | {
"A": "240",
"B": "270",
"C": "295",
"D": "360",
"E": "269"
} | divide(add(1360, 15), subtract(6, const_1)) | add(n0,n2)|subtract(n1,const_1)|divide(#0,#1)| | "let the smaller number be x . then larger number = ( x + 1360 ) . x + 1360 = 6 x + 15 5 x = 1345 x = 269 smaller number = 270 . answer e" | general |
math_qa__44ilLSjPfS2JGaix | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.50 per glass on the first day, what was the price per glass on the second day? Choose the correct choice from the following answers
A) $ 0.15 B) $ 0.20 C) $ 0.33 D) $ 0.40 E) $ 0.45 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 0.5</gadget>
<output>1</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<result>C</result> | C | 0.33 | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.50 per glass on the first day, what was the price per glass on the second day? | {
"A": "$ 0.15",
"B": "$ 0.20",
"C": "$ 0.33",
"D": "$ 0.40",
"E": "$ 0.45"
} | divide(multiply(add(const_1, const_1), 0.50), add(const_1, const_2)) | add(const_1,const_1)|add(const_1,const_2)|multiply(n0,#0)|divide(#2,#1)| | "on the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade ; on the second day 1 unit of orange juice and 2 units of water was used to make 3 units of orangeade ; so , the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 3 . naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 3 . we are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 3 glasses on the second day . say the price of the glass of the orangeade on the second day was $ x then 2 * 0.5 = 3 * x - - > x = $ 0.33 . answer : c ." | general |
math_qa__4aTfonuFkDsKLgz4 | A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party T. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)? Choices:
A) 15 B) 20 C) 30 D) 35 E) 45 | <gadget id="calculator">35 + 20</gadget>
<output>55</output>
<gadget id="calculator">100 - 55</gadget>
<output>45</output>
<gadget id="calculator">45 / 3</gadget>
<output>15</output>
<result>A</result> | A | 15 | A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party T. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)? | {
"A": "15",
"B": "20",
"C": "30",
"D": "35",
"E": "45"
} | divide(subtract(const_100, add(35, 20)), const_3) | add(n0,n1)|subtract(const_100,#0)|divide(#1,const_3)| | "s = 100 not ( t and b ) = 35 only t = 20 ( t and b ) / b = 1 / 2 let ( t and b ) = x only b = 2 x so now , 20 + 35 + x + 2 x = 100 x = 15 a ans" | gain |
math_qa__Sd2B7yObfIJoCVU0 | Excluding stoppages, the speed of a train is 30 kmph and including stoppages it is 21 kmph. Of how many minutes does the train stop per hour?
Choose the correct choice from the following answers
A) 16
B) 17
C) 12
D) 15
E) 18 | <gadget id="calculator">21 / 30</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">60 * (7/10)</gadget>
<output>42</output>
<gadget id="calculator">60 - 42</gadget>
<output>18</output>
<result>E</result> | E | 18 | Excluding stoppages, the speed of a train is 30 kmph and including stoppages it is 21 kmph. Of how many minutes does the train stop per hour? | {
"A": "16",
"B": "17",
"C": "12",
"D": "15",
"E": "18"
} | subtract(const_60, multiply(const_60, divide(21, 30))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "t = 9 / 30 * 60 = 18 answer : e" | physics |
math_qa__ZvYPeV3nkCEEXp3l | A man took loan from a bank at the rate of 5% p.a. S.I. After 13 years he had to pay Rs. 1300 interest only for the period. The principal amount borrowed by him was? Pick
A) 1750 B) 4000 C) 3500 D) 2000 E) 1000 | <gadget id="calculator">1_300 * 100</gadget>
<output>130_000</output>
<gadget id="calculator">130_000 / 13</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 5</gadget>
<output>2_000</output>
<result>D</result> | D | 2,000 | A man took loan from a bank at the rate of 5% p.a. S.I. After 13 years he had to pay Rs. 1300 interest only for the period. The principal amount borrowed by him was? | {
"A": "1750",
"B": "4000",
"C": "3500",
"D": "2000",
"E": "1000"
} | divide(divide(multiply(1300, const_100), 13), 5) | multiply(n2,const_100)|divide(#0,n1)|divide(#1,n0)| | "principal = ( 100 * 1300 ) / ( 5 * 13 ) = rs . 2000 answer : d" | gain |
math_qa__1a6z0wwggQTDof5j | In a games hour 4 different types of players came to the ground? cricket 15, hokey 12, football 13, softball 15. How many players are present in the ground? Pick one
A) 70 B) 52 C) 55 D) 49 E) 50 | <gadget id="calculator">15 + 12</gadget>
<output>27</output>
<gadget id="calculator">13 + 15</gadget>
<output>28</output>
<gadget id="calculator">27 + 28</gadget>
<output>55</output>
<result>C</result> | C | 55 | In a games hour 4 different types of players came to the ground? cricket 15, hokey 12, football 13, softball 15. How many players are present in the ground? | {
"A": "70",
"B": "52",
"C": "55",
"D": "49",
"E": "50"
} | add(add(15, 12), add(13, 15)) | add(n1,n2)|add(n3,n4)|add(#0,#1)| | "total number of players = 15 + 12 + 13 + 15 = 55 answer is c" | physics |
math_qa__8YQKuoeMH0wb6JvO | If 2/z = 2/(z + 1) + 2/(z + 25) which of these integers could be the value of z? Choose the correct choice from the following options
A) 0
B) 1
C) 2
D) 3
E) 5 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">25 / 5</gadget>
<output>5</output>
<result>E</result> | E | 5 | If 2/z = 2/(z + 1) + 2/(z + 25) which of these integers could be the value of z? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "5"
} | divide(25, add(add(2, 2), 1)) | add(n0,n0)|add(n2,#0)|divide(n4,#1) | solving for z algebraically in this problem would not be easy . instead , we can follow the hint in the question ( “ which of these integers … ” ) and test each answer choice : a . 2 / 0 = 2 / 1 + 2 / 25 incorrect ( division by zero ) b . 2 / 1 = 2 / 2 + 2 / 26 incorrect c . 2 / 2 = 2 / 3 + 2 / 27 incorrect d . 2 / 3 = 2 / 4 + 2 / 28 incorrect e . 2 / 4 = 2 / 5 + 2 / 30 correct the correct answer is e , because it contains the only value that makes the equation work . notice how quickly this strategy worked in this case | general |
math_qa__EAjy2MCmAMHvRNN6 | The average student age of a certain class which has 45 students is 14. If one student aged 15 go to another class and the age of the class teacher is included the average changes to 14.66. What is the age of class teacher? Choose the correct choice from the following choices: A) 30 B) 35 C) 38 D) 40 E) 45 | <gadget id="calculator">45 * 14.66</gadget>
<output>659.7</output>
<gadget id="calculator">45 * 14</gadget>
<output>630</output>
<gadget id="calculator">630 - 15</gadget>
<output>615</output>
<gadget id="calculator">659.7 - 615</gadget>
<output>44.7</output>
<result>E</result> | E | 45 | The average student age of a certain class which has 45 students is 14. If one student aged 15 go to another class and the age of the class teacher is included the average changes to 14.66. What is the age of class teacher? | {
"A": "30",
"B": "35",
"C": "38",
"D": "40",
"E": "45"
} | subtract(multiply(45, 14.66), subtract(multiply(45, 14), 15)) | multiply(n0,n3)|multiply(n0,n1)|subtract(#1,n2)|subtract(#0,#2) | sum of ages of class before replacement = 45 x 14 = 630 sum of ages of class without teacher = 630 - 15 = 615 sum of ages of class after replacement = 45 x 14.66 = 660 age of teacher = 660 - 615 = 45 answer : e | general |
math_qa__NabRSbSiUUGGkjOH | The mean of 50 observations was 41. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is Choose the correct choice from the following options:
A) 35.2 B) 36.1 C) 36.5 D) 41.5 E) none | <gadget id="calculator">41 * 50</gadget>
<output>2_050</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">48 - 23</gadget>
<output>25</output>
<gadget id="calculator">2_050 + 25</gadget>
<output>2_075</output>
<gadget id="calculator">2_075 / 50</gadget>
<output>83/2 = around 41.5</output>
<result>D</result> | D | 41.5 | The mean of 50 observations was 41. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is | {
"A": "35.2",
"B": "36.1",
"C": "36.5",
"D": "41.5",
"E": "none"
} | divide(add(multiply(41, 50), subtract(subtract(50, const_2), 23)), 50) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,n3)|add(#0,#2)|divide(#3,n0)| | "sol . therefore correct sum = ( 41 × 50 + 48 – 23 ) = 2075 . therefore correct mean = 2075 / 50 = 41.5 . answer d" | general |
math_qa__w7rL3T0YKJJc8byj | In what time will a train 300 meters long cross an electric pole, if its speed is 90 km/hr Pick one:
A) 5 seconds
B) 12 seconds
C) 3 seconds
D) 2.5 seconds
E) none of these | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">90 * (5/18)</gadget>
<output>25</output>
<gadget id="calculator">300 / 25</gadget>
<output>12</output>
<result>B</result> | B | 12 | In what time will a train 300 meters long cross an electric pole, if its speed is 90 km/hr | {
"A": "5 seconds",
"B": "12 seconds",
"C": "3 seconds",
"D": "2.5 seconds",
"E": "none of these"
} | divide(300, multiply(90, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "explanation : first convert speed into m / sec speed = 90 * ( 5 / 18 ) = 25 m / sec time = distance / speed = 300 / 25 = 12 seconds answer : b" | physics |
math_qa__1LQA2hUI9A6fGKxx | A present value of a machine is $1100. Its value depletion rate is 10% per annum then find the machine value after 2 years? Choose the correct choice from the following answers
A) $ 900 B) $ 891 C) $ 915 D) $ 715 E) $ 795 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) ** 2</gadget>
<output>81/100 = around 0.81</output>
<gadget id="calculator">1_100 * (81/100)</gadget>
<output>891</output>
<result>B</result> | B | 891 | A present value of a machine is $1100. Its value depletion rate is 10% per annum then find the machine value after 2 years? | {
"A": "$ 900",
"B": "$ 891",
"C": "$ 915",
"D": "$ 715",
"E": "$ 795"
} | multiply(1100, power(subtract(const_1, divide(10, const_100)), 2)) | divide(n1,const_100)|subtract(const_1,#0)|power(#1,n2)|multiply(n0,#2) | p = $ 1100 r = 10 % t = 2 years machine value after 2 years = p [ ( 1 - r / 100 ) ^ t ] = 1100 * 9 / 10 * 9 / 10 = $ 891 answer is b | gain |
math_qa__aegnkJKoOmcQ8RJC | Vanessa, Mike and Sarah have missed a total of 17 days of school this year. Vanessa and Mike have missed 14 days total, and Mike and Sarah have missed 12 days total. How many days of school did Vanessa miss alone? Select the correct option:
A) 9 B) 4 C) 5 D) 2 E) 3 | <gadget id="calculator">17 - 12</gadget>
<output>5</output>
<result>C</result> | C | 5 | Vanessa, Mike and Sarah have missed a total of 17 days of school this year. Vanessa and Mike have missed 14 days total, and Mike and Sarah have missed 12 days total. How many days of school did Vanessa miss alone? | {
"A": "9",
"B": "4",
"C": "5",
"D": "2",
"E": "3"
} | subtract(17, 12) | subtract(n0,n2) | vanessa + mike + sarah = 17 v + m = 14 m + s = 12 < < use this formula & plug into the original formula , to get vanessa ' s total v + ( m + s ) = 17 v + 12 = 17 subtract 12 from both sides v = 5 answer : c | physics |
math_qa__2sXeFklmZbmE65m9 | Sandy is younger than Molly by 16 years. If the ratio of their ages is 7:9, how old is Sandy? Select: A) 42 B) 49 C) 56 D) 63 E) 70 | <gadget id="calculator">9 - 7</gadget>
<output>2</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) * 16</gadget>
<output>56</output>
<result>C</result> | C | 56 | Sandy is younger than Molly by 16 years. If the ratio of their ages is 7:9, how old is Sandy? | {
"A": "42",
"B": "49",
"C": "56",
"D": "63",
"E": "70"
} | multiply(divide(7, subtract(9, 7)), 16) | subtract(n2,n1)|divide(n1,#0)|multiply(n0,#1)| | "let sandy ' s age be 7 x and let molly ' s age be 9 x . 9 x - 7 x = 16 x = 8 sandy is 56 years old . the answer is c ." | other |
math_qa__BqLj3elUZLbwiGE6 | In a village of 2,600 people, 800 people are over 70 years old and 850 people are female. It is known that 40 percent of the females are younger than 70 years old. If no one in the village is 70 years old, what is the probability that a person chosen at random is either a male or younger than 70 years old? Select:
A) 221 / 250 B) 199 / 250 C) 33 / 50 D) 8 / 25 E) 209 / 260 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">25 / (1/4)</gadget>
<output>100</output>
<gadget id="calculator">26 * 100</gadget>
<output>2_600</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">850 * (3/5)</gadget>
<output>510</output>
<gadget id="calculator">2_600 - 510</gadget>
<output>2_090</output>
<gadget id="calculator">2_090 / 2_600</gadget>
<output>209/260 = around 0.803846</output>
<result>E</result> | E | 0.803846 | In a village of 2,600 people, 800 people are over 70 years old and 850 people are female. It is known that 40 percent of the females are younger than 70 years old. If no one in the village is 70 years old, what is the probability that a person chosen at random is either a male or younger than 70 years old? | {
"A": "221 / 250",
"B": "199 / 250",
"C": "33 / 50",
"D": "8 / 25",
"E": "209 / 260"
} | divide(subtract(multiply(const_26, divide(multiply(const_5, const_5), const_0_25)), multiply(850, subtract(const_1, divide(40, divide(multiply(const_5, const_5), const_0_25))))), multiply(const_26, divide(multiply(const_5, const_5), const_0_25))) | multiply(const_5,const_5)|divide(#0,const_0_25)|divide(n4,#1)|multiply(#1,const_26)|subtract(const_1,#2)|multiply(n3,#4)|subtract(#3,#5)|divide(#6,#3) | the number of people younger than 70 years old is 2600 - 800 = 1800 the number of females older than 70 years old is 0.6 * 850 = 510 then the number of males older than 70 years old is 800 - 510 = 290 . the number of people who are either male or younger than 70 is 1800 + 290 = 2090 . p ( a person is younger than 70 or male ) = 2090 / 2600 = 209 / 260 the answer is e . | gain |
math_qa__P99h9SyXrSCATrms | A circle graph shows how the budget of a certain company was spent: 60 percent for salaries, 9 percent for research and development, 5 percent for utilities, 4 percent for equipment, 2 percent for supplies, and the remainder for transportation. If the area of each sector of the graph is proportional to the percent of the budget it represents, how many degrees of the circle are used to represent transportation? Choose the most appropriate option
A) 18 ° B) 36 ° C) 54 ° D) 72 ° E) 90 ° | <gadget id="calculator">60 + 9</gadget>
<output>69</output>
<gadget id="calculator">69 + 5</gadget>
<output>74</output>
<gadget id="calculator">74 + 4</gadget>
<output>78</output>
<gadget id="calculator">78 + 2</gadget>
<output>80</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">360 * 20</gadget>
<output>7_200</output>
<gadget id="calculator">7_200 / 100</gadget>
<output>72</output>
<result>D</result> | D | 72 | A circle graph shows how the budget of a certain company was spent: 60 percent for salaries, 9 percent for research and development, 5 percent for utilities, 4 percent for equipment, 2 percent for supplies, and the remainder for transportation. If the area of each sector of the graph is proportional to the percent of the budget it represents, how many degrees of the circle are used to represent transportation? | {
"A": "18 °",
"B": "36 °",
"C": "54 °",
"D": "72 °",
"E": "90 °"
} | divide(multiply(const_360, subtract(const_100, add(add(add(add(60, 9), 5), 4), 2))), const_100) | add(n0,n1)|add(n2,#0)|add(n3,#1)|add(n4,#2)|subtract(const_100,#3)|multiply(#4,const_360)|divide(#5,const_100)| | "the percent of the budget for transportation is 100 - ( 60 + 9 + 5 + 4 + 2 ) = 20 % 100 % of the circle is 360 degrees . then ( 20 % / 100 % ) * 360 = 72 degrees the answer is d ." | geometry |
math_qa__151td471HbFXGHEw | Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Choose the correct choice from the following choices.
A) 7
B) 8.2
C) 2
D) 10.8
E) 11.2 | <gadget id="calculator">140 + 160</gadget>
<output>300</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">300 / (250/9)</gadget>
<output>54/5 = around 10.8</output>
<result>D</result> | D | 10.8 | Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "7",
"B": "8.2",
"C": "2",
"D": "10.8",
"E": "11.2"
} | divide(add(140, 160), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "answer : option d relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 140 + 160 = 300 m . required time = 300 * 9 / 250 = 54 / 5 = 10.8 sec" | physics |
math_qa__VqsoDPJtegUhh8GW | Working alone, A can complete a certain kind of job in 6 hours. A and D, working together at their respective rates, can complete one of these jobs in 4 hours. In how many hours can D, working alone, complete one of these jobs?
Choose the correct answer: A) 8 B) 10 C) 12 D) 14 E) 16 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/4) - (1/6)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>C</result> | C | 12 | Working alone, A can complete a certain kind of job in 6 hours. A and D, working together at their respective rates, can complete one of these jobs in 4 hours. In how many hours can D, working alone, complete one of these jobs? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "16"
} | inverse(subtract(inverse(4), inverse(6))) | inverse(n1)|inverse(n0)|subtract(#0,#1)|inverse(#2)| | "let total time taken by d to complete the job = d total time taken by a to complete the job = 6 work done by a in an hour 1 / a = 1 / 6 working together a and d can complete the job in 4 hours 1 / a + 1 / d = 1 / 4 = > 1 / d = 1 / 4 - 1 / a = 1 / 4 - 1 / 6 = 1 / 12 = > d = 12 hours answer c" | physics |
math_qa__gvmHjNLmft7sLaRh | Ashok secured average of 70 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject? Answers:
A) 50 B) 74 C) 78 D) 80 E) none of these | <gadget id="calculator">70 * 6</gadget>
<output>420</output>
<gadget id="calculator">74 * 5</gadget>
<output>370</output>
<gadget id="calculator">420 - 370</gadget>
<output>50</output>
<result>A</result> | A | 50 | Ashok secured average of 70 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject? | {
"A": "50",
"B": "74",
"C": "78",
"D": "80",
"E": "none of these"
} | subtract(multiply(70, 6), multiply(74, 5)) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)| | "explanation : number of subjects = 6 average of marks in 6 subjects = 70 therefore total marks in 6 subjects = 70 * 6 = 420 now , no . of subjects = 5 total marks in 5 subjects = 74 * 5 = 370 therefore marks in 6 th subject = 420 – 370 = 50 answer a" | general |
math_qa__5SIDgDgQIypBUJNP | Population is 23000. Population increases by 10% every year, then the population after 3 years is? Choose the correct choice from the following answers: A) 26630 B) 26640 C) 36623 D) 30613 E) 26820 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">23_000 * (13/10)</gadget>
<output>29_900</output>
<result>D</result> | D | 30,613 | Population is 23000. Population increases by 10% every year, then the population after 3 years is? | {
"A": "26630",
"B": "26640",
"C": "36623",
"D": "30613",
"E": "26820"
} | multiply(23000, add(const_1, divide(multiply(3, 10), const_100))) | multiply(n1,n2)|divide(#0,const_100)|add(#1,const_1)|multiply(n0,#2)| | "population after 1 st year = 23000 * 10 / 100 = 2300 = = = > 23000 + 2000 = 25300 population after 2 nd year = 25300 * 10 / 100 = 2530 = = = > 25300 + 2530 = 27830 population after 3 rd year = 27830 * 10 / 100 = 2783 = = = > 27830 + 2783 = 30613 answer : d" | gain |
math_qa__zJIHNP8wkYjI3E8Q | A train running at the speed of 72 km/hr crosses a pole in 9 seconds. Find the length of the train?
Choose the correct choice from the following choices:
A) 150 meter B) 299 meter C) 666 meter D) 155 meter E) 180 meter | <gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">20 * 9</gadget>
<output>180</output>
<result>E</result> | E | 180 | A train running at the speed of 72 km/hr crosses a pole in 9 seconds. Find the length of the train? | {
"A": "150 meter",
"B": "299 meter",
"C": "666 meter",
"D": "155 meter",
"E": "180 meter"
} | multiply(divide(multiply(72, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 72 * ( 5 / 18 ) m / sec = 20 m / sec length of train ( distance ) = speed * time ( 20 ) * 9 = 180 meter answer : e" | physics |
math_qa__v8Rn2mr3kEkqHI2q | A train running at the speed of 180 km/hr crosses a pole in 7 seconds. What is the length of the train? Choose the correct choice from the following answers
A) 530 B) 305 C) 503 D) 430 E) 350 | <gadget id="calculator">180 * 1_000</gadget>
<output>180_000</output>
<gadget id="calculator">180_000 / 3_600</gadget>
<output>50</output>
<gadget id="calculator">50 * 7</gadget>
<output>350</output>
<result>E</result> | E | 350 | A train running at the speed of 180 km/hr crosses a pole in 7 seconds. What is the length of the train? | {
"A": "530",
"B": "305",
"C": "503",
"D": "430",
"E": "350"
} | multiply(divide(multiply(180, const_1000), const_3600), 7) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 180 * 5 / 18 ) m / sec = ( 50 ) m / sec length of the train = ( speed x time ) = ( 50 * 7 ) m = 350 m . answer : e" | physics |
math_qa__vVVNN8ojNYDEDPs2 | The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 432 sq m, then what is the breadth of the rectangular plot?
Choose the correct choice from the following options:
A) 12 B) 17 C) 18 D) 19 E) 14 | <gadget id="calculator">432 / 3</gadget>
<output>144</output>
<gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<result>A</result> | A | 12 | The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 432 sq m, then what is the breadth of the rectangular plot? | {
"A": "12",
"B": "17",
"C": "18",
"D": "19",
"E": "14"
} | sqrt(divide(432, const_3)) | divide(n0,const_3)|sqrt(#0)| | "let the breadth of the plot be b m . length of the plot = 3 b m ( 3 b ) ( b ) = 432 3 b 2 = 432 b 2 = 144 b = 12 m . answer : option a" | geometry |
math_qa__UYXEZ8emk8f9YWyH | The difference between simple interest and compound interest on Rs.1200 for one year at 10% per annum reckoned half-yearly is :
Choose the most appropriate option.
A) rs . 2.50 B) rs . 3 C) rs . 3.75 D) rs . 4 E) rs . 5 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">(441/400) * 1_200</gadget>
<output>1_323</output>
<gadget id="calculator">1_323 - 1_200</gadget>
<output>123</output>
<gadget id="calculator">1_200 * 10</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 / 100</gadget>
<output>120</output>
<gadget id="calculator">123 - 120</gadget>
<output>3</output>
<result>B</result> | B | 3 | The difference between simple interest and compound interest on Rs.1200 for one year at 10% per annum reckoned half-yearly is : | {
"A": "rs . 2.50",
"B": "rs . 3",
"C": "rs . 3.75",
"D": "rs . 4",
"E": "rs . 5"
} | subtract(subtract(multiply(power(add(divide(divide(10, const_2), const_100), const_1), const_2), 1200), 1200), divide(multiply(1200, 10), const_100)) | divide(n1,const_2)|multiply(n0,n1)|divide(#0,const_100)|divide(#1,const_100)|add(#2,const_1)|power(#4,const_2)|multiply(n0,#5)|subtract(#6,n0)|subtract(#7,#3) | s . i = ( 1000 * 10 * 4 ) / 100 = rs . 400 c . i = 1200 * 1 + 5 / 100 ) 2 – 1200 = 123 . difference = rs . ( 123 - 120 ) = rs . 3 answer : b | gain |
math_qa__EK7xreu7WM6AwvvU | A rectangular tank needs to be coated with insulation. The tank has dimensions of 3 feet, 6 feet, and 2 feet. Each square foot of insulation costs $20. How much will it cost to cover the surface of the tank with insulation?
Choices.
A) $ 980 B) $ 1060 C) $ 1220 D) $ 1440 E) $ 1650 | <gadget id="calculator">2 * (3 * 6 + 6 * 2 + 3 * 2)</gadget>
<output>72</output>
<gadget id="calculator">72 * 20</gadget>
<output>1_440</output>
<result>D</result> | D | 1,440 | A rectangular tank needs to be coated with insulation. The tank has dimensions of 3 feet, 6 feet, and 2 feet. Each square foot of insulation costs $20. How much will it cost to cover the surface of the tank with insulation? | {
"A": "$ 980",
"B": "$ 1060",
"C": "$ 1220",
"D": "$ 1440",
"E": "$ 1650"
} | multiply(surface_rectangular_prism(3, 6, 2), 20) | surface_rectangular_prism(n0,n1,n2)|multiply(n3,#0) | the total surface area is 2 ( 2 * 3 + 3 * 6 + 2 * 6 ) = 72 square feet the total cost is 72 * $ 20 = $ 1440 the answer is d . | geometry |
math_qa__9FgBzLOGyGy5ANdu | If a trader sold two cars each at Rs. 325475 and gains 13% on the first and loses 13% on the second, then his profit or loss percent on the whole is? Choose the correct choice.
A) 1.69 % B) 1.74 % C) 1.84 % D) 1.47 % E) 1.24 % | <gadget id="calculator">13 * 13</gadget>
<output>169</output>
<gadget id="calculator">169 / 100</gadget>
<output>169/100 = around 1.69</output>
<result>A</result> | A | 1.69 | If a trader sold two cars each at Rs. 325475 and gains 13% on the first and loses 13% on the second, then his profit or loss percent on the whole is? | {
"A": "1.69 %",
"B": "1.74 %",
"C": "1.84 %",
"D": "1.47 %",
"E": "1.24 %"
} | divide(multiply(13, 13), const_100) | multiply(n1,n1)|divide(#0,const_100)| | "sp of each car is rs . 325475 , he gains 13 % on first car and losses 13 % on second car . in this case , there will be loss and percentage of loss is given by = [ ( profit % ) ( loss % ) ] / 100 = ( 13 ) ( 13 ) / 100 % = 1.69 % answer : a" | gain |
math_qa__0s1T50YGJGzMqzYR | P, Q and R have Rs.5000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? Answers.
A) rs . 3000 B) rs . 3600 C) rs . 2000 D) rs . 4000 E) none of these | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 + (2/3)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">5_000 / (5/3)</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 * (2/3)</gadget>
<output>2_000</output>
<result>C</result> | C | 2,000 | P, Q and R have Rs.5000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? | {
"A": "rs . 3000",
"B": "rs . 3600",
"C": "rs . 2000",
"D": "rs . 4000",
"E": "none of these"
} | multiply(divide(5000, add(const_1, divide(const_2, const_3))), divide(const_2, const_3)) | divide(const_2,const_3)|add(#0,const_1)|divide(n0,#1)|multiply(#2,#0)| | "let the amount with r be rs . r r = 2 / 3 ( total amount with p and q ) r = 2 / 3 ( 5000 - r ) = > 3 r = 10000 - 2 r = > 5 r = 10000 = > r = 2000 . answer : c" | general |
math_qa__21rVdK5uNuLMxIZ6 | A cab driver 5 days income was $250, $400, $750, $400 , $500. Then his average income is? Choose the correct option
A) $ 440 B) $ 450 C) $ 460 D) $ 470 E) $ 480 | <gadget id="calculator">250 + 400</gadget>
<output>650</output>
<gadget id="calculator">650 + 750</gadget>
<output>1_400</output>
<gadget id="calculator">1_400 + 400</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 + 500</gadget>
<output>2_300</output>
<gadget id="calculator">2_300 / 5</gadget>
<output>460</output>
<result>C</result> | C | 460 | A cab driver 5 days income was $250, $400, $750, $400 , $500. Then his average income is? | {
"A": "$ 440",
"B": "$ 450",
"C": "$ 460",
"D": "$ 470",
"E": "$ 480"
} | divide(add(add(add(add(250, 400), 750), 400), 500), 5) | add(n1,n2)|add(n3,#0)|add(n4,#1)|add(n5,#2)|divide(#3,n0)| | "avg = sum of observations / number of observations avg income = ( 250 + 400 + 750 + 400 + 500 ) / 5 = 460 answer is c" | general |
math_qa__zPzpgBGQ3N6Qglsl | A man, a woman and a boy can together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 9 days, how long will a woman take to complete the work? Select: A) 12 days B) 15 days C) 16 days D) 24 days E) 18 days | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/6) + (1/9)</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(1/3) - (5/18)</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">1 / (1/18)</gadget>
<output>18</output>
<result>E</result> | E | 18 | A man, a woman and a boy can together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 9 days, how long will a woman take to complete the work? | {
"A": "12 days",
"B": "15 days",
"C": "16 days",
"D": "24 days",
"E": "18 days"
} | inverse(subtract(inverse(3), add(inverse(6), inverse(9)))) | inverse(n0)|inverse(n1)|inverse(n2)|add(#1,#2)|subtract(#0,#3)|inverse(#4) | explanation : ( 1 man + 1 woman + 1 boy ) ’ s 1 day ’ s work = 1 / 3 1 man ’ s 1 day work = 1 / 6 1 boy ’ s 1 day ’ s work = 1 / 9 ( 1 man + 1 boy ) ‘ s 1 day ’ s work = 1 / 6 + 1 / 9 = 5 / 18 therefore , 1 woman ’ s 1 day ’ s work = 1 / 3 – 5 / 18 = 1 / 18 therefore , the woman alone can finish the work in 18 days . answer : option e | physics |
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