role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | suppose if we add 2 and 3. | 13,553 | 295 | [] |
volunteer | what do we get here? | 13,553 | 296 | [] |
student | you would get 5, but like. | 13,553 | 297 | [] |
volunteer | Right, but we don't want the 5, right? | 13,553 | 298 | [] |
volunteer | What you want is plus one | 13,553 | 299 | [] |
student | Oh, wait, wait. | 13,553 | 300 | [] |
volunteer | You want the one here, right | 13,553 | 301 | [] |
student | 01, like you want a one in front of, like, do you, like, you want a 1 for B, right? | 13,553 | 302 | [] |
volunteer | Correct. You want to be equal to 1, exactly. | 13,553 | 303 | [] |
student | Because that matches the equation. | 13,553 | 304 | [] |
volunteer | Exactly | 13,553 | 305 | [] |
student | OK. | 13,553 | 306 | [] |
volunteer | So you have to think in such a way that how do I take this, now I found a factor that multiplies to 6, that is 2 and 3. We know that. So now the next step is, after we have checked for this, you have to check for this one. OK, now I want something that adds to one. So what can I add to one? If, if it is both positive, ... | 13,553 | 307 | [] |
volunteer | If it is | 13,553 | 308 | [] |
student | Should we do mm | 13,553 | 309 | [] |
volunteer | yeah, but | 13,553 | 310 | [] |
student | I mean, you would do a 3 minus 2. | 13,553 | 311 | [] |
volunteer | These are your three options, right? | 13,553 | 312 | [] |
student | Yeah, OK, so you just figure out which one matches to get what I want. | 13,553 | 313 | [] |
volunteer | Which one works for you. Correct, correct. So this one works for you basically at this point here. + 3 minus 2. | 13,553 | 314 | [] |
student | OK, some something similar than in the past where I just find the factors | 13,553 | 315 | [] |
student | like if you scroll down | 13,553 | 316 | [] |
student | um, oh wait, I don't actually have it on this one, but like I would add the different values together and at least on like later assignments I would do like 1 minus 36, 1 + 36, and then 36 minus 1. | 13,553 | 317 | [] |
student | to get the 3 versions | 13,553 | 318 | [] |
volunteer | Yeah, yeah, that works. Yeah, those are the simpler versions. I think now it's getting complicated. | 13,553 | 319 | [] |
student | OK. | 13,553 | 320 | [] |
volunteer | So coming back to this one, let me just delete what I've written here. | 13,553 | 321 | [] |
volunteer | OK, let me just uh get fixed this. All right, there you go. So what now, now that we understand the the things on the right. Let me just, uh, maybe add one more color on the thing on the right. | 13,553 | 322 | [] |
volunteer | So what you're essentially doing is you're also solving for the one which is here. So you see this? | 13,553 | 323 | [] |
volunteer | You understand there is a one ahead of X, right? | 13,553 | 324 | [] |
volunteer | Like there's a one ahead of you | 13,553 | 325 | [] |
student | Uh, yeah, that's A, no? | 13,553 | 326 | [] |
volunteer | Correct? Yeah, that's A. So A is equal to 1 and then C is equal to 6, and you always turn to the factors of a multiplied by C. | 13,553 | 327 | [] |
student | Wait, wait, uh, C would be, why is it 6 or 6. It's just like | 13,553 | 328 | [] |
student | is this the standard like equation just minus 6 or | 13,553 | 329 | [] |
volunteer | It could, yeah, it is -6. Let's see equal to -6. You're right. | 13,553 | 330 | [] |
student | like minus, I mean | 13,553 | 331 | [] |
volunteer | C is -6, C is equal. | 13,553 | 332 | [] |
student | uh or like does it just not matter that much? | 13,553 | 333 | [] |
volunteer | No, no, let's, let's stick to that. That's fine. | 13,553 | 334 | [] |
student | OK. | 13,553 | 335 | [] |
volunteer | All right. Uh, my, so similarly, you need to find out what's here. A is equal to | 13,553 | 336 | [] |
volunteer | 3, correct | 13,553 | 337 | [] |
student | All right. Also, is it like, is it like A times C equals B or? | 13,553 | 338 | [] |
volunteer | Yeah, so you need to do the, what you did the factor for 6 years is A times C. | 13,553 | 339 | [] |
volunteer | So you need to do A times C is 12 times 3. | 13,553 | 340 | [] |
volunteer | So we need factors of 36. | 13,553 | 341 | [] |
student | No, wait. So A times C is B, right? | 13,553 | 342 | [] |
volunteer | No, no, not 8 times is | 13,553 | 343 | [] |
volunteer | not going to be | 13,553 | 344 | [] |
student | OK, so | 13,553 | 345 | [] |
student | that it's just saying that earlier. OK. Well, um | 13,553 | 346 | [] |
student | yeah, | 13,553 | 347 | [] |
student | OK | 13,553 | 348 | [] |
volunteer | Hidden is not going to be, so did I say that, uh, yeah, no, no, I, I didn't mean to say that. 8 times he is not equal to B. What, what, what is happening is the factors have to add up to give you the bean. | 13,553 | 349 | [] |
volunteer | like you did here, right | 13,553 | 350 | [] |
volunteer | Sure. | 13,553 | 351 | [] |
student | factors to add up to you be. OK, so then, yeah, like 3 minus 2. | 13,553 | 352 | [] |
volunteer | Got it, got | 13,553 | 353 | [] |
student | And then | 13,553 | 354 | [] |
student | OK, yeah. | 13,553 | 355 | [] |
volunteer | So if you take 36 and apply the same method we did, so the smallest prime number is 2, correct? | 13,553 | 356 | [] |
student | And we're doing 36 because | 13,553 | 357 | [] |
student | oh yeah, so we're just multiplying A times c to get 36. | 13,553 | 358 | [] |
volunteer | Correct. | 13,553 | 359 | [] |
student | Uh | 13,553 | 360 | [] |
volunteer | Here also multiplied it by uh A C, but the CA is 1, so it didn't matter. | 13,553 | 361 | [] |
student | OK | 13,553 | 362 | [] |
volunteer | So you do the smallest factor 2 and if you do 2, you get 18, correct? | 13,553 | 363 | [] |
student | Uh, OK, so like, | 13,553 | 364 | [] |
student | so the verb, no, no, no, because they have that on the work too. | 13,553 | 365 | [] |
student | Ben, I have it on like the right side. It's | 13,553 | 366 | [
{
"pii_type": "PERSON",
"surrogate": "Ben",
"start": 0,
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student | it's like Ax C equals 3 times 12. He was 36. | 13,553 | 367 | [] |
student | And then it's 2 times 18 and the sum of that is 20. So the sum, the sum of the factory. | 13,553 | 368 | [] |
student | where | 13,553 | 369 | [] |
volunteer | Yes, so you don't need to break it down any for correct, correct. You don't need to break it down any further now because, you know, it to and 18 using the 20. | 13,553 | 370 | [] |
student | I could have a second, uh | 13,553 | 371 | [] |
volunteer | Sure. | 13,553 | 372 | [] |
student | I see that do my. Sorry. | 13,553 | 373 | [] |
student | I'm doing tutoring. | 13,553 | 374 | [] |
volunteer | Let me know when you're back | 13,553 | 375 | [] |
student | Hello | 13,553 | 376 | [] |
student | He | 13,553 | 377 | [] |
volunteer | Yeah, I'll be back | 13,553 | 378 | [] |
student | Yeah | 13,553 | 379 | [] |
volunteer | OK. So I've written down the equation based on the two factors that he shared, the 18 and the 2. | 13,553 | 380 | [] |
student | Mm | 13,553 | 381 | [] |
volunteer | You see this | 13,553 | 382 | [] |
student | OK, so | 13,553 | 383 | [] |
student | you | 13,553 | 384 | [] |
volunteer | The 18 + 2 is 20, correct? | 13,553 | 385 | [] |
student | Wait, wait, so we did a 3 X squad. | 13,553 | 386 | [] |
student | or 3 times y + 18 x + 2 X. | 13,553 | 387 | [] |
student | + 12 | 13,553 | 388 | [] |
volunteer | Yeah | 13,553 | 389 | [] |
student | OK | 13,553 | 390 | [] |
volunteer | So what we did is we took the 2 and the 18 that uses 36, right? So 18 + 2 is 20. | 13,553 | 391 | [] |
student | Mhm | 13,553 | 392 | [] |
student | Wait, so what's | 13,553 | 393 | [] |
volunteer | And we know that uh mhm. | 13,553 | 394 | [] |
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