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8
student
that
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student
No, no, no, like the cross, like the, the one at the top where it's like 3 X plus W times whatever.
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volunteer
Mhm.
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student
Like, um, how would we use legends that
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volunteer
Oh, you mean the graph
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student
Yeah, the grasser
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student
Or is that just like
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volunteer
I don't know
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volunteer
what we're doing there. Oh, you're, you're talking about the area method.
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student
The what now
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volunteer
So there is something called the area method, so let me
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volunteer
show you what. So your answer is X minus 2 and 4 x + 5, right?
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student
Uh
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volunteer
This, this, uh.
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student
Oh yeah, yeah, yeah.
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student
Yeah.
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volunteer
check, check by my markers I'm gonna write something in blue. This one, right?
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student
uh Wait, where are you at the bottom?
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volunteer
Yeah, you scroll down to the bottom.
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student
OK.
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volunteer
See my cursor?
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student
It's just got more lay over time.
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volunteer
It shouldn't
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student
Oh, a computer slow.
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student
Uh, yeah, I have at the bottom.
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volunteer
Yeah, you see my cursor, yeah, good. I see yours now. OK, now, so what, so the, what they're saying is essentially this, uh, bear with me for a second.
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student
Dear.
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volunteer
So think about this as 4 rectangles. Do you see it?
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student
Yeah.
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volunteer
What they're saying is that one rectangle, you put X, X, and then you put 2 here.
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student
Like I don't have like a basic area model works, but
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volunteer
Oh, that's what they're saying, I think. No?
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student
but none like the way they're doing it is like they're converting it into this form and that format. I just don't really get why they're doing with some of that.
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volunteer
I don't know, what you think.
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student
or even like what it does.
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volunteer
Yeah, I don't understand what they're trying to do there then maybe if you're talking about this on the rough work, they did some, you know, factors. Do you see that?
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volunteer
The 36 is 36 multiplied by 1, 18 multiplied by 2, 12. Do you, are you asking that question?
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volunteer
No right
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student
No
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volunteer
I, you.
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student
I mean, I'll just, I'll just ask my teacher if it's fine if I don't use it because the way you told me isn't that complicated. It's
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student
uh
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volunteer
Yeah, I, I don't understand what he's trying to be trying to communicate there.
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student
OK.
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student
Well, I think that's it then.
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volunteer
but
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student
So I have to do the homework
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student
a look
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volunteer
All right, good luck with the homework. I think this should be easy now that you have this.
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student
Yeah
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student
OK.
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volunteer
All right, have a good evening
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student
but
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volunteer
Yeah, bye
13,553
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volunteer
Hello
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student
Hello Emily, how are you?
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[ { "pii_type": "PERSON", "surrogate": "Emily", "start": 6, "end": 11 } ]
volunteer
I am fine, how are you?
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student
I'm fine thanks
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student
so we started a topic called higher order derivatives and graphs and I'm kind of confused, so I wanted to see if you could maybe help
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volunteer
do you have a question that you are working on?
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student
Yes, but do you know what they are?
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volunteer
Yes, I know what higher order derivatives are.
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student
okay, I'll put something on the board
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student
first question
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student
how do you find the derivative of e with that big number 2470
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volunteer
what is f' ?
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student
not f' f''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
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student
basically f(2470)
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volunteer
I am asking you to first find f'
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volunteer
do you know how to do that?
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student
2e^(2x)
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volunteer
OK, what is f"
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student
4e^2x
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volunteer
Yes, but let's write it a bit differently
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volunteer
What is the third derivative?
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student
2^3e^2x
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volunteer
what is f(4)?
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volunteer
do you see the pattern?
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student
is all you are trying to say is that whenever you are trying to find such a big derivative for the power of e^smth, all you do is keep the 2 and just put the big number to the power of it?
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volunteer
I am asking if you see a pattern?
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student
yes, that's what I was explaining
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volunteer
good.
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volunteer
Any questions about that?
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student
no i guess we can move on
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student
there is the next one
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volunteer
I wrote the answer, just to make sure.
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student
ok
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volunteer
Is that the graph of y=f(x)?
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student
i guess
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student
this is a different question
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volunteer
It should say in the problem. Is it the graph of f(x) or f'(x)?
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student
it's f(x) since in the answer it's asking for f'(x) and f''(x)
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volunteer
Well, that's not actually true, but let's assume that it's f(x)
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student
ok
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volunteer
Assuming that the graph is f(x), is f'(a) >0 or <0 ?
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student
i wanna say >0
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volunteer
You don't sound very sure. Why is f' >0 at that point?
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student
i am sure, it's bc the slope of the tangent line is increasing and looks higher than 0
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volunteer
You mean that the tangent line has a positive slope. That's right. Also, even without thinking about the tangent line, you can see that the function is increasing at that point. If a function is increasing then f' >0
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volunteer
How about f" ?
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