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values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
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student | but on the notes he was confusing us saying that for example(watch what I'm doing on the board) is increasing | 13,654 | 46 | [] |
student | how to know that a function is increasing? | 13,654 | 47 | [] |
volunteer | He is not talking about the function increasing. | 13,654 | 48 | [] |
volunteer | we will get to that. | 13,654 | 49 | [] |
volunteer | at the blue point, is the curve concave up or concave down? | 13,654 | 50 | [] |
student | Right now I'm not talking about the concavity yet, I'm just talking about that portion, but ok | 13,654 | 51 | [] |
student | down | 13,654 | 52 | [] |
volunteer | When a curve is concave down, is f" >0 or <0 ? | 13,654 | 53 | [] |
student | that Idk sorry | 13,654 | 54 | [] |
volunteer | OK, you haven't learned that yet. | 13,654 | 55 | [] |
student | as I said, he did talk about it, but I'm js so confused with his explanations | 13,654 | 56 | [] |
volunteer | I drew three tangent lines, A B and C | 13,654 | 57 | [] |
student | ok | 13,654 | 58 | [] |
volunteer | what might be an estimate for the slope of A, just roughly? | 13,654 | 59 | [] |
student | -2, maybe? | 13,654 | 60 | [] |
volunteer | OK | 13,654 | 61 | [] |
student | 0 | 13,654 | 62 | [] |
volunteer | How about at B? | 13,654 | 63 | [] |
student | 1.7 | 13,654 | 64 | [] |
volunteer | OK, so is the f', the first derivative, increasing of decreasing over that interval (we would call the curve there concave up, because it is facing up | 13,654 | 65 | [] |
volunteer | Again, as we go from A to B to C, is f' increasing or decreasing | 13,654 | 66 | [] |
student | it's increasing | 13,654 | 67 | [] |
volunteer | right. | 13,654 | 68 | [] |
volunteer | Now, f", the second derivative, is the derivative of f', right? | 13,654 | 69 | [] |
student | yes | 13,654 | 70 | [] |
volunteer | so if f' is increasiing as you go from A to C, would you expect f" to be >0 or <0? | 13,654 | 71 | [] |
student | to find that out should I draw a second graph based on the estimated slopes we found or is there an easier way? | 13,654 | 72 | [] |
volunteer | the point is that the derivative tells us if a function is increasing or decreasing. f' is itself a function. If you tell me that f' is increasing over an interval, then that means that the derivative of f' should be>0, and the derivative of f' is f". | 13,654 | 73 | [] |
volunteer | so if f' is increasing over an interval, then f" on that interval would be >0 | 13,654 | 74 | [] |
student | so that make sense, if f' isincreasing on that interval then f'' is also increasing on that interval? | 13,654 | 75 | [] |
volunteer | Exactly. | 13,654 | 76 | [] |
volunteer | no, sorry | 13,654 | 77 | [] |
volunteer | f" is positive over that interval. | 13,654 | 78 | [] |
student | wym no sorry? | 13,654 | 79 | [] |
student | so f'' is not increasing? | 13,654 | 80 | [] |
volunteer | f">0, being >0 is not the same thing as increasing. | 13,654 | 81 | [] |
volunteer | Using a similar argument, we can see that f" <0 where the blue point is, where the curve is facing down. | 13,654 | 82 | [] |
student | okay how to know smth is positive vs increasing | 13,654 | 83 | [] |
volunteer | In this case, they just want to know if f" is <0 or >0 at the blue point. | 13,654 | 84 | [] |
student | I'm asking just in case in the future I'm asked that | 13,654 | 85 | [] |
volunteer | Something happened to the site. Are you still there? | 13,654 | 86 | [] |
volunteer | but since you can see that on the left f" >0 and on the right f"<0, then that that means that as you move from from A to the blue point, f" must be decreasing | 13,654 | 87 | [] |
volunteer | Hello? | 13,654 | 88 | [] |
student | sorry | 13,654 | 89 | [] |
student | I got disconnected for a long time and js got back :( | 13,654 | 90 | [] |
volunteer | Do you understand this question now? | 13,654 | 91 | [] |
student | okay so let me recap and tell me if I'm correct | 13,654 | 92 | [] |
student | so where the blue point is f' is decreasing because the slopes around that curve are going from estimate 1.7, 0 to -2, and this then means that f'' is <0 | 13,654 | 93 | [] |
volunteer | yes, that's right. It's the fact that f' is decreasing (which means f" <0) that gives the curve that concave/facing downward look. | 13,654 | 94 | [] |
volunteer | concave down/facing downwards | 13,654 | 95 | [] |
student | does being concave up or down say anything at all? | 13,654 | 96 | [] |
volunteer | They describe the shape of the graph. That's something you couldn't do as well with just algebra | 13,654 | 97 | [] |
student | what I'm asking is does the graph being concave up or down tell us that it's increasing, decreasing, positive or negative? | 13,654 | 98 | [] |
student | at all? | 13,654 | 99 | [] |
volunteer | It tells the shape, as I drew on the board. Do you see that? | 13,654 | 100 | [] |
student | yes i see | 13,654 | 101 | [] |
volunteer | It wouldn't tell if the function is positive or negative. the curve could be above or below the x axis. it could be anywhere | 13,654 | 102 | [] |
student | ok | 13,654 | 103 | [] |
student | another question i have is f' or f'' being <0 or >0, does that say if it's positive or negative? | 13,654 | 104 | [] |
volunteer | Numbers that are <0 are negative and numbers that are >0 are positive | 13,654 | 105 | [] |
volunteer | Are you all set now? | 13,654 | 106 | [] |
student | okay that makes so much sense thx | 13,654 | 107 | [] |
student | Do you have to go or you got a little bit of time? | 13,654 | 108 | [] |
volunteer | I can do another question. | 13,654 | 109 | [] |
student | okay thx one min | 13,654 | 110 | [] |
volunteer | what do you think? | 13,654 | 111 | [] |
volunteer | hello, are you there? | 13,654 | 112 | [] |
student | sorry | 13,654 | 113 | [] |
student | Do we have to create our own graph? | 13,654 | 114 | [] |
volunteer | You can, but it's not necessary | 13,654 | 115 | [] |
student | okay, so what do we do then? | 13,654 | 116 | [] |
volunteer | First of all, is f'(2)) most likely postive or negative? | 13,654 | 117 | [] |
student | maybe positive?? | 13,654 | 118 | [] |
volunteer | what does a derivative >0 mean for a graph? | 13,654 | 119 | [] |
student | increasing | 13,654 | 120 | [] |
volunteer | Yes. It is important to remember that. Does it look like the function is increasing? | 13,654 | 121 | [] |
student | no it's decreasing | 13,654 | 122 | [] |
volunteer | Yes. For a fn to be increasing, that means that as x increases (as you move left), f(x) would go up, But here, it looks like f(x) is going down, so f(x) is most likely decreasing. | 13,654 | 123 | [] |
student | yes | 13,654 | 124 | [] |
volunteer | We can estimate the slopes of the tangent lines at x =2, 2.1, 2.2 | 13,654 | 125 | [] |
volunteer | we can do that by figuring out the rate of change between the points that they give us. | 13,654 | 126 | [] |
volunteer | What is the rate of change (the slope of the line) between (2,3) and (2.1,2.7) ? | 13,654 | 127 | [] |
volunteer | That average rate of change gives us a rough estimate of the slope of the tangent line at x =2 | 13,654 | 128 | [] |
volunteer | Now let's move to the right. | 13,654 | 129 | [] |
volunteer | let's get the rate of change between the next two points | 13,654 | 130 | [] |
volunteer | One more | 13,654 | 131 | [] |
volunteer | Good work. So, does it look like f' is increasing or decreasing over the interval from x =2 to x =2.3? | 13,654 | 132 | [] |
student | it's increasing | 13,654 | 133 | [] |
volunteer | Yes | 13,654 | 134 | [] |
volunteer | so will this curve be concave up (f">0) or concave down (f"<0)? | 13,654 | 135 | [] |
student | this will be concave up | 13,654 | 136 | [] |
volunteer | that's right. | 13,654 | 137 | [] |
volunteer | I also plotted them on Desmos, so you can see. | 13,654 | 138 | [] |
volunteer | I think you can see that the curve looks concave up. | 13,654 | 139 | [] |
student | yope | 13,654 | 140 | [] |
student | to recap, first we found out that f(x) was decreasing, then we looked for the slopes and found out that f'(x) is increase which led us to the knowledge that f" is concave up or >0, correct? | 13,654 | 141 | [] |
volunteer | yes, that's right | 13,654 | 142 | [] |
volunteer | We used the average rate of change over small intervals to estimate the slope of the tangents lines | 13,654 | 143 | [] |
student | okay now questions time, first question why did we need to find out if f(x) was increasing or decreasing? | 13,654 | 144 | [] |
volunteer | because the question asked if f'(2)) most likely >0 or <0. If f(x) is increasing that means f'(2)) >0 and if f(x) is decreasing that means that f'(2) <0 | 13,654 | 145 | [] |
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