Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	cosine X	15,912	529	[]
volunteer	is equal to, I'm sorry, we know that.	15,912	530	[]
volunteer	cosine	15,912	531	[]
volunteer	um let's just use X	15,912	532	[]
volunteer	is equal to sin.	15,912	533	[]
volunteer	X	15,912	534	[]
volunteer	90 I think.	15,912	535	[]
volunteer	or minus 90.	15,912	536	[]
volunteer	I think that's true	15,912	537	[]
volunteer	because that'd be sign X.	15,912	538	[]
volunteer	times cosine of 2.	15,912	539	[]
volunteer	minus	15,912	540	[]
volunteer	cosine X.	15,912	541	[]
volunteer	maybe.	15,912	542	[]
volunteer	I guess it's pie, I guess it's plus plus 90.	15,912	543	[]
volunteer	Does that help	15,912	544	[]
volunteer	I think it does cause then that would rewrite the arc sign	15,912	545	[]
volunteer	from cosine to sign.	15,912	546	[]
volunteer	of X + 90.	15,912	547	[]
volunteer	and then that will just become X + 90 or pie or 2 whatever.	15,912	548	[]
volunteer	DX	15,912	549	[]
volunteer	huh	15,912	550	[]
volunteer	Is it really that simple	15,912	551	[]
volunteer	I almost feel scared	15,912	552	[]
volunteer	1/2 X. oh, I'm sorry, it's it.	15,912	553	[]
volunteer	1/2 x 2 plus.	15,912	554	[]
volunteer	i over 2	15,912	555	[]
volunteer	X	15,912	556	[]
volunteer	C	15,912	557	[]
volunteer	that makes sense	15,912	558	[]
volunteer	Does that make sense what I just did	15,912	559	[]
volunteer	Can you see anything wrong? I can make it bigger.	15,912	560	[]
volunteer	It just kind of scribbles.	15,912	561	[]
student	no, I can see.	15,912	562	[]
student	gimme a min	15,912	563	[]
student	i can't understand this	15,912	564	[]
volunteer	Oh yeah, I'm sorry. I was trying to do the um	15,912	565	[]
volunteer	the summoned property. So sign, it's supposed to be signed.	15,912	566	[]
volunteer	um	15,912	567	[]
volunteer	A + B.	15,912	568	[]
volunteer	where I said A is X and B is night is pirate 2, it should be pirate 299.	15,912	569	[]
volunteer	To many scribbles. Let me try that again.	15,912	570	[]
volunteer	Sign.	15,912	571	[]
volunteer	I did X minus, I'll just use Pi too instead.	15,912	572	[]
volunteer	I couldn't remember what the shift was.	15,912	573	[]
volunteer	So I tried um	15,912	574	[]
volunteer	theta plus	15,912	575	[]
volunteer	Sine, cosine, cosign, sign.	15,912	576	[]
volunteer	So we sign	15,912	577	[]
volunteer	X cosine pi over 2.	15,912	578	[]
volunteer	plus.	15,912	579	[]
volunteer	cosine X sine i over 2, I ran in a room.	15,912	580	[]
volunteer	Yeah	15,912	581	[]
volunteer	There we go	15,912	582	[]
volunteer	And then cosiney 2 is 0, so you're just left with.	15,912	583	[]
volunteer	cosine X. Sorry, I was just trying to prove, um,	15,912	584	[]
volunteer	the relationship between	15,912	585	[]
volunteer	sine and Cosina.	15,912	586	[]
volunteer	And that um cosina and sinex are just face face shifted from each other.	15,912	587	[]
volunteer	Sorry, phase	15,912	588	[]
volunteer	You can't see that. Oh, I'm sorry. I keep forgetting you can't see that.	15,912	589	[]
volunteer	do this	15,912	590	[]
volunteer	Is that better	15,912	591	[]
volunteer	Uh I really wrote small. I'm sorry.	15,912	592	[]
student	oh okay, then you re write the equation?	15,912	593	[]
volunteer	Yeah, and then at the bottom, I just, I, once I once I proved that cosine x is equal to sin of x + i over 2, I keep saying 90 should be pi over 2.	15,912	594	[]
volunteer	Um, then I just substituted that back in for, you know, arc sign of sign, just canceled out.	15,912	595	[]
student	😦 it was this easy?	15,912	596	[]
volunteer	Yeah, I'm almost	15,912	597	[]
volunteer	I almost feel doubtful. It's OK if I look at the answers now?	15,912	598	[]
volunteer	Huh, that is the answer.	15,912	599	[]
volunteer	Though I got a negative somewhere wrong.	15,912	600	[]
volunteer	Let me, um.	15,912	601	[]
volunteer	Can you see it?	15,912	602	[]
student	yeah	15,912	603	[]
volunteer	So I got	15,912	604	[]
volunteer	I got the pie over 2 X, right? But I guess I got the negative	15,912	605	[]
volunteer	x or 2. Where did they get the negative?	15,912	606	[]
volunteer	Unless they did	15,912	607	[]
volunteer	I think they did um	15,912	608	[]
volunteer	sign of pie over 2 minus X.	15,912	609	[]
volunteer	cause then that would cancel out too.	15,912	610	[]
volunteer	But then I'd have to prove that cosine x is equal to sin of x, i over 2 minus X.	15,912	611	[]
student	i think sin(x+90) should be -cosx?	15,912	612	[]
volunteer	Is that right	15,912	613	[]
volunteer	Would it	15,912	614	[]
volunteer	do anything though? I feel like the negative should be within the phase shift.	15,912	615	[]
volunteer	It would make the whole	15,912	616	[]
volunteer	it would make the entire um	15,912	617	[]
volunteer	thing be negative rather than just one of the values being negative.	15,912	618	[]
student	oh no, that's wrong. you're right	15,912	619	[]
volunteer	Anyway, looking at your 19, did you get 10 squared? I don't remember if you got 10 squared.	15,912	620	[]
volunteer	You got seekin X	15,912	621	[]
volunteer	log tangent you get express log tangent. So you get the log tangent, right, but you're missing the one half	15,912	622	[]
volunteer	tangent square, which you got for sequent.	15,912	623	[]
volunteer	We got to double back to that.	15,912	624	[]
volunteer	Your work seems correct	15,912	625	[]
volunteer	Oh, sorry, let's get back to 21.	15,912	626	[]
volunteer	And let's prove 21.	15,912	627	[]
volunteer	Um	15,912	628	[]

Subsets and Splits

No community queries yet

The top public SQL queries from the community will appear here once available.