role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | Thats why here we have -1 | 19,842 | 40 | [] |
volunteer | All good with that? | 19,842 | 41 | [] |
student | Yes | 19,842 | 42 | [] |
student | Is the answer -15 | 19,842 | 43 | [] |
volunteer | yeah the final answer is -15 | 19,842 | 44 | [] |
volunteer | You got it in the end :) | 19,842 | 45 | [] |
student | W=-8 | 19,842 | 46 | [] |
volunteer | Yes! | 19,842 | 47 | [] |
volunteer | Okay let's start with -1^2 | 19,842 | 48 | [] |
student | Are we on 6 | 19,842 | 49 | [] |
student | Yes or no | 19,842 | 50 | [] |
volunteer | Not yet, we're on 5 | 19,842 | 51 | [] |
volunteer | Do you know how to calculate -1 squared? | 19,842 | 52 | [] |
student | M=3 | 19,842 | 53 | [] |
volunteer | Not quite, let's take it step by step | 19,842 | 54 | [] |
volunteer | What is -1 squared | 19,842 | 55 | [] |
student | Do we follow pemdas | 19,842 | 56 | [] |
volunteer | Yes, so we first want to see what -1 squared is | 19,842 | 57 | [] |
student | And it is 1 | 19,842 | 58 | [] |
volunteer | Yes | 19,842 | 59 | [] |
volunteer | So we have 3 x 1 | 19,842 | 60 | [] |
student | 3 | 19,842 | 61 | [] |
volunteer | Now we have -(-1) which would be | 19,842 | 62 | [] |
student | 1 | 19,842 | 63 | [] |
volunteer | Yes | 19,842 | 64 | [] |
student | 2 | 19,842 | 65 | [] |
volunteer | And now we just have -7 | 19,842 | 66 | [] |
volunteer | So what is 4 - 7? | 19,842 | 67 | [] |
student | -3 | 19,842 | 68 | [] |
student | M=-3 | 19,842 | 69 | [] |
volunteer | Yes! | 19,842 | 70 | [] |
volunteer | Awesome | 19,842 | 71 | [] |
volunteer | Do you have an idea how you would write an algebraic equation for 6? | 19,842 | 72 | [] |
volunteer | Just the equation for now, without solving it yet | 19,842 | 73 | [] |
student | No | 19,842 | 74 | [] |
student | No | 19,842 | 75 | [] |
student | No | 19,842 | 76 | [] |
volunteer | Okay | 19,842 | 77 | [] |
student | Wait | 19,842 | 78 | [] |
volunteer | Let's make p stand for pineapples and m stand for mango | 19,842 | 79 | [] |
volunteer | Okay | 19,842 | 80 | [] |
student | No | 19,842 | 81 | [] |
student | You can continue | 19,842 | 82 | [] |
volunteer | Okay | 19,842 | 83 | [] |
volunteer | So we want to just focus on this part for now | 19,842 | 84 | [] |
volunteer | we have p and m and we know that there are 8 less p than m | 19,842 | 85 | [] |
volunteer | How could we write that out? | 19,842 | 86 | [] |
student | 8=P-8 | 19,842 | 87 | [] |
student | No m=p-8 | 19,842 | 88 | [] |
volunteer | Good thinking but not quite | 19,842 | 89 | [] |
volunteer | We do use the subtraction that's true | 19,842 | 90 | [] |
volunteer | What would we do to m to make it the same number as p | 19,842 | 91 | [] |
student | - | 19,842 | 92 | [] |
volunteer | which one would you pick a or b | 19,842 | 93 | [] |
student | What is a | 19,842 | 94 | [] |
student | And whaat is b | 19,842 | 95 | [] |
volunteer | a) p = m + 8 pr b) p = m -8 | 19,842 | 96 | [] |
student | B | 19,842 | 97 | [] |
student | B | 19,842 | 98 | [] |
student | B | 19,842 | 99 | [] |
student | B | 19,842 | 100 | [] |
student | B | 19,842 | 101 | [] |
student | B | 19,842 | 102 | [] |
student | B | 19,842 | 103 | [] |
student | B | 19,842 | 104 | [] |
student | B | 19,842 | 105 | [] |
student | B | 19,842 | 106 | [] |
volunteer | Yes | 19,842 | 107 | [] |
student | B | 19,842 | 108 | [] |
volunteer | Okay let's go through the difference between your answer and b before we move forward | 19,842 | 109 | [] |
volunteer | Let's say p is 10 | 19,842 | 110 | [] |
student | We just need the eq | 19,842 | 111 | [] |
student | But yes | 19,842 | 112 | [] |
volunteer | Yes but what we need more importantly, is for you to understand how to get there without my help so you can be ready for class and tests | 19,842 | 113 | [] |
volunteer | So with your equation we have that m is 2 and p is 10 | 19,842 | 114 | [] |
volunteer | But does this satisfy our original rule that p has 8 less than m? | 19,842 | 115 | [] |
student | Yes | 19,842 | 116 | [] |
student | Yes | 19,842 | 117 | [] |
student | Yes | 19,842 | 118 | [] |
volunteer | But is m is 2, then it's m that's 8 less than m | 19,842 | 119 | [] |
student | Nod | 19,842 | 120 | [] |
volunteer | But what we need, is p to be eight digits smaller than m | 19,842 | 121 | [] |
volunteer | So what do we change to your equation, to make sure that p is eight smaller than m instead | 19,842 | 122 | [] |
student | P+8 | 19,842 | 123 | [] |
volunteer | Yes that works! | 19,842 | 124 | [] |
volunteer | Awesome | 19,842 | 125 | [] |
student | Now i think i have an eq for 7 | 19,842 | 126 | [] |
volunteer | Okay, great type it out for me | 19,842 | 127 | [] |
student | J=(b-12)divide 2 | 19,842 | 128 | [] |
volunteer | Yeah that's right | 19,842 | 129 | [] |
volunteer | Do you want to go over how you calculated that | 19,842 | 130 | [] |
student | That becomes the - and the divide | 19,842 | 131 | [] |
volunteer | Yup | 19,842 | 132 | [] |
volunteer | Great work! | 19,842 | 133 | [] |
student | The answer key says it is b=2j+12 | 19,842 | 134 | [] |
volunteer | I feel like you're doing really well with these. My advice would be to double check as you're going along because one small blunder can impact the whole equation, and have more confidence | 19,842 | 135 | [] |
volunteer | Yes b = 2j + 12 is your equation rearranged | 19,842 | 136 | [] |
student | Which is the opposite | 19,842 | 137 | [] |
volunteer | Do you want me to show you how to rearrange it into the answer guide | 19,842 | 138 | [] |
student | You just flip the signs into + and x | 19,842 | 139 | [] |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.