Datasets:
NationalTutoringObservatory
/
MathEd-PII

Dataset card Data Studio Files
xet
 Community
1
role
stringclasses
2 values
content
stringlengths
0
2.1k
session_id
int64
10
21.7k
sequence_id
int64
0
2.38k
annotations
listlengths
0
8
volunteer
Looking at the red numbers, what would the ratio be?
19,537
133
[]
student
1:root3
19,537
134
[]
volunteer
Exactly!
19,537
135
[]
volunteer
Now, do you remember how to set up the equation?
19,537
136
[]
volunteer
Let's say x is the unknown side
19,537
137
[]
student
ok
19,537
138
[]
volunteer
Can you set up the equation?
19,537
139
[]
student
no help me
19,537
140
[]
student
is it 1/root3
19,537
141
[]
volunteer
That's one side, yes!
19,537
142
[]
student
is the other 1/2
19,537
143
[]
volunteer
Not quite, remember that you now want to use the numbers and variables that you know
19,537
144
[]
volunteer
Here, you know one of the sides is 6 and the other side is x
19,537
145
[]
volunteer
Does that ring a bell?
19,537
146
[]
student
so 1/2=1/root3
19,537
147
[]
student
so x/6=1/root3?
19,537
148
[]
volunteer
The second equation is correct, yep!
19,537
149
[]
volunteer
How did you get the first equation?
19,537
150
[]
student
so in this case it would be like=ke this I'ma write on the board
19,537
151
[]
volunteer
Gotcha, sure!
19,537
152
[]
volunteer
You're totally correct so far!
19,537
153
[]
student
I need help on what to do after
19,537
154
[]
volunteer
What can you multiply both the numerator and the denominator by to get rid of the sqrt3 in the denominator?
19,537
155
[]
student
is that right?
19,537
156
[]
volunteer
Yes!
19,537
157
[]
student
can you help me after
19,537
158
[]
volunteer
Sure, I'll try to nudge you in the right direction
19,537
159
[]
volunteer
You can simplify the denominators, what's sqrt3 * sqrt3?
19,537
160
[]
student
wait so would that leave 3 by its self
19,537
161
[]
volunteer
That would leave 3 in the denominator
19,537
162
[]
student
and after
19,537
163
[]
volunteer
Now, you don't have to do anything with the sqrt3 except let it hang there
19,537
164
[]
volunteer
However, you can simplify 6/3
19,537
165
[]
student
as 2 right
19,537
166
[]
volunteer
Yes!
19,537
167
[]
student
right
19,537
168
[]
volunteer
Since that's what x is, that'll be what your last side is
19,537
169
[]
student
2xroot3?
19,537
170
[]
volunteer
x is equal to 2sqrt3, so it'll just be 2sqrt3
19,537
171
[]
volunteer
Do you mean multiplication when you write x?
19,537
172
[]
student
yes
19,537
173
[]
volunteer
Ah, gotcha
19,537
174
[]
volunteer
In that case, you're totally right!
19,537
175
[]
student
I wrote it at the top where the rest of the lengths are is that correct
19,537
176
[]
volunteer
Yep!
19,537
177
[]
volunteer
Do you understand the process a bit more now?
19,537
178
[]
student
yess I do I do
19,537
179
[]
volunteer
Great!
19,537
180
[]
volunteer
Is that all?
19,537
181
[]
student
is that all I do?
19,537
182
[]
student
yes that's all for me on my part
19,537
183
[]
volunteer
determine the length of the missing leg and hypotenuse of each the special right triangles
19,537
184
[]
volunteer
If this is the problem, I don't see what else there is to do
19,537
185
[]
volunteer
You found the missing leg and hypotenuse
19,537
186
[]
student
yess that's all thank you so much
19,537
187
[]
volunteer
Of course, I'm glad I could help!
19,537
188
[]
student
for your help and patience have a good rest of your day
19,537
189
[]
volunteer
You too, it was a joy working with you
19,537
190
[]
volunteer
Cya!
19,537
191
[]
student
bye
19,537
192
[]
volunteer
Hi Alex!
19,842
0
[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 3, "end": 7 } ]
student
Hello my name is Alex
19,842
1
[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 17, "end": 21 } ]
volunteer
Oh sorry, hey Alex
19,842
2
[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 14, "end": 18 } ]
student
Sarah is my mom
19,842
3
[ { "pii_type": "PERSON", "surrogate": "Sarah", "start": 0, "end": 5 } ]
volunteer
Okay, how can I help you today?
19,842
4
[]
student
Before do the work i have a pet to watch us
19,842
5
[]
volunteer
Okay cool
19,842
6
[]
volunteer
Is there any question you need help with? Or a general topic?
19,842
7
[]
student
The pet is coming
19,842
8
[]
volunteer
Okay
19,842
9
[]
student
I’m going to send the work pic after
19,842
10
[]
volunteer
Okay, whenever you're ready
19,842
11
[]
volunteer
Okay should we start with question 1?
19,842
12
[]
student
Yes
19,842
13
[]
student
Oh is 1 8
19,842
14
[]
volunteer
When they tell us what x is, all we need to do is swap out x for the number
19,842
15
[]
volunteer
5 is negative so we need to keep that in mind!
19,842
16
[]
volunteer
So what would 3-5 be?
19,842
17
[]
student
Then it is -2
19,842
18
[]
volunteer
Yes!
19,842
19
[]
volunteer
Okay let's move on to 2
19,842
20
[]
volunteer
Can you finish the equation?
19,842
21
[]
student
11 1/2
19,842
22
[]
volunteer
Great!
19,842
23
[]
volunteer
How would you write out the a= equation for question 3
19,842
24
[]
volunteer
Can you finish the equation?
19,842
25
[]
student
-5
19,842
26
[]
student
Wait
19,842
27
[]
volunteer
Not quite, let's take it step by step
19,842
28
[]
volunteer
First let's do (-2-3)/5
19,842
29
[]
volunteer
What would -2-3 be?
19,842
30
[]
student
-5
19,842
31
[]
volunteer
Yup!
19,842
32
[]
volunteer
And then we have -5/5 which is
19,842
33
[]
student
-5
19,842
34
[]
student
Or-1
19,842
35
[]
volunteer
Yes -1
19,842
36
[]
student
Then it should be-15
19,842
37
[]
volunteer
When we divide the same number the answer is always 1
19,842
38
[]
volunteer
And when the top number is negative, while the bottom number is positive the number is negative too
19,842
39
[]