role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | -86 is right | 21,186 | 65 | [] |
volunteer | but calculate for this problem? | 21,186 | 66 | [] |
student | wait it was for another assingment | 21,186 | 67 | [] |
student | 59 | 21,186 | 68 | [] |
volunteer | correct | 21,186 | 69 | [] |
volunteer | alright I will have to go now | 21,186 | 70 | [] |
student | bye! | 21,186 | 71 | [] |
volunteer | great work and bye! | 21,186 | 72 | [] |
volunteer | Hi, hi | 21,191 | 0 | [] |
student | Hii! How are you? | 21,191 | 1 | [] |
volunteer | You are very puctual | 21,191 | 2 | [] |
volunteer | Im doing good | 21,191 | 3 | [] |
student | you are very punctual too | 21,191 | 4 | [] |
volunteer | thank you, I try, *bowing to audience* | 21,191 | 5 | [] |
student | I tried to get the topics but they were not clearly mentioned | 21,191 | 6 | [] |
student | so, I got few tings | 21,191 | 7 | [] |
student | like inverse trigonometry domain and range with graphs | 21,191 | 8 | [] |
volunteer | ok | 21,191 | 9 | [] |
student | how to solve inverse trigonmetry question, complex ones | 21,191 | 10 | [] |
student | i know how to solve questions like this | 21,191 | 11 | [] |
student | lemme get a hard question | 21,191 | 12 | [] |
volunteer | ok | 21,191 | 13 | [] |
volunteer | 2cot^-1(3) is a constant | 21,191 | 14 | [] |
student | such type of question, when there are multiple things inside a bracket. | 21,191 | 15 | [] |
volunteer | ok | 21,191 | 16 | [] |
volunteer | This is for monday right? | 21,191 | 17 | [] |
student | yes | 21,191 | 18 | [] |
volunteer | ok, I will prep for then. This is precalc or algebra 2? | 21,191 | 19 | [] |
volunteer | is that (pi/2 - 2cot^-1(3)) inside the parenthesis? | 21,191 | 20 | [] |
student | yes | 21,191 | 21 | [] |
student | please give me 10 min | 21,191 | 22 | [] |
student | I am having connection issue | 21,191 | 23 | [] |
volunteer | Its ok. We can wait until Monday. | 21,191 | 24 | [] |
student | Hi, thank you for waiting | 21,191 | 25 | [] |
student | Yes, we can do on monday. | 21,191 | 26 | [] |
volunteer | ok. sounds good to me | 21,191 | 27 | [] |
volunteer | enjoy to your weekend | 21,191 | 28 | [] |
student | I have little doubt in a quadratic question. | 21,191 | 29 | [] |
student | can I ask right now? | 21,191 | 30 | [] |
volunteer | sure | 21,191 | 31 | [] |
student | do I show you how i try to solve it? | 21,191 | 32 | [] |
volunteer | If you want | 21,191 | 33 | [] |
student | squaring both sides | 21,191 | 34 | [] |
volunteer | ok | 21,191 | 35 | [] |
student | I put the x values into g(x) = 0, to check if these roots statisfy the equation | 21,191 | 36 | [] |
volunteer | OK. | 21,191 | 37 | [] |
volunteer | to be minus. | 21,191 | 38 | [] |
student | wait a min | 21,191 | 39 | [] |
volunteer | OK. | 21,191 | 40 | [] |
volunteer | Good | 21,191 | 41 | [] |
student | so, according this , it means g(x)=0 doesn't have real roots righht? | 21,191 | 42 | [] |
volunteer | Wait, what? | 21,191 | 43 | [] |
volunteer | Why'd you get 17? | 21,191 | 44 | [] |
volunteer | Or you check two different values for | 21,191 | 45 | [] |
volunteer | Uh, the one. | 21,191 | 46 | [] |
student | yeah | 21,191 | 47 | [] |
volunteer | Why did you, why did you check two different values? | 21,191 | 48 | [] |
volunteer | Because the | 21,191 | 49 | [] |
student | plus/minus sqqr root 1 = + / - 1 | 21,191 | 50 | [] |
volunteer | You're, um, | 21,191 | 51 | [] |
volunteer | Your one route. | 21,191 | 52 | [] |
volunteer | Wasn't out of a square. | 21,191 | 53 | [] |
volunteer | He didn't take the square root of it. | 21,191 | 54 | [] |
volunteer | So it should just be positive one. I don't know why you tested um negative one as well. | 21,191 | 55 | [] |
volunteer | -1 wasn't a route. | 21,191 | 56 | [] |
volunteer | Right? Cause out of the um out of your algebra, you got two roots. | 21,191 | 57 | [] |
volunteer | Um, your first route, uh, the 1/81, that uh | 21,191 | 58 | [] |
volunteer | can be rewritten as a complex number to get you | 21,191 | 59 | [] |
volunteer | To get you a, um, | 21,191 | 60 | [] |
volunteer | The actual route. | 21,191 | 61 | [] |
volunteer | But I think, I think it's just 11 real route. | 21,191 | 62 | [] |
student | how 1/81 can be written as complex numbeer? | 21,191 | 63 | [] |
volunteer | I don't know. I was just trying stuff, and I think I found a solution. | 21,191 | 64 | [] |
volunteer | So if you take | 21,191 | 65 | [] |
volunteer | What did I do? Right. | 21,191 | 66 | [] |
volunteer | If you go back to your 81, well, I solved it differently than you. I mean, we got the same result, but I solved this slightly different. | 21,191 | 67 | [] |
volunteer | I said, | 21,191 | 68 | [] |
volunteer | Let | 21,191 | 69 | [] |
student | okay | 21,191 | 70 | [] |
volunteer | Why be equal to square root of x. | 21,191 | 71 | [] |
volunteer | Therefore, my G of X G Y. | 21,191 | 72 | [] |
volunteer | becomes | 21,191 | 73 | [] |
volunteer | 9 | 21,191 | 74 | [] |
volunteer | Y^2 minus 8Y. | 21,191 | 75 | [] |
volunteer | -1. | 21,191 | 76 | [] |
volunteer | Which just becomes | 21,191 | 77 | [] |
volunteer | 9 Y + 1. | 21,191 | 78 | [] |
volunteer | Time | 21,191 | 79 | [] |
volunteer | Why minus 1. | 21,191 | 80 | [] |
volunteer | Which is what you got. | 21,191 | 81 | [] |
volunteer | Except, um, you had it just basically squared, right? You got that. | 21,191 | 82 | [] |
volunteer | X minus | 21,191 | 83 | [] |
volunteer | Yeah, close enough. | 21,191 | 84 | [] |
volunteer | Can I get, yeah, 9, yeah, and then if you | 21,191 | 85 | [] |
volunteer | Factor back in what X is. | 21,191 | 86 | [] |
volunteer | Or what why is you get 9 root X. | 21,191 | 87 | [] |
volunteer | Plus one | 21,191 | 88 | [] |
volunteer | Times | 21,191 | 89 | [] |
volunteer | Root X minus 1. | 21,191 | 90 | [] |
volunteer | You said equal to 0. | 21,191 | 91 | [] |
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