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volunteer
-86 is right
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volunteer
but calculate for this problem?
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student
wait it was for another assingment
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student
59
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volunteer
correct
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volunteer
alright I will have to go now
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student
bye!
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volunteer
great work and bye!
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volunteer
Hi, hi
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student
Hii! How are you?
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volunteer
You are very puctual
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volunteer
Im doing good
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student
you are very punctual too
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volunteer
thank you, I try, *bowing to audience*
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student
I tried to get the topics but they were not clearly mentioned
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student
so, I got few tings
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student
like inverse trigonometry domain and range with graphs
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volunteer
ok
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student
how to solve inverse trigonmetry question, complex ones
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student
i know how to solve questions like this
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student
lemme get a hard question
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volunteer
ok
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volunteer
2cot^-1(3) is a constant
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student
such type of question, when there are multiple things inside a bracket.
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volunteer
ok
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volunteer
This is for monday right?
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student
yes
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volunteer
ok, I will prep for then. This is precalc or algebra 2?
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volunteer
is that (pi/2 - 2cot^-1(3)) inside the parenthesis?
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student
yes
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student
please give me 10 min
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student
I am having connection issue
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volunteer
Its ok. We can wait until Monday.
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student
Hi, thank you for waiting
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student
Yes, we can do on monday.
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volunteer
ok. sounds good to me
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volunteer
enjoy to your weekend
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student
I have little doubt in a quadratic question.
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student
can I ask right now?
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volunteer
sure
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student
do I show you how i try to solve it?
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volunteer
If you want
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student
squaring both sides
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volunteer
ok
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student
I put the x values into g(x) = 0, to check if these roots statisfy the equation
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volunteer
OK.
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volunteer
to be minus.
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student
wait a min
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volunteer
OK.
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volunteer
Good
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student
so, according this , it means g(x)=0 doesn't have real roots righht?
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volunteer
Wait, what?
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volunteer
Why'd you get 17?
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volunteer
Or you check two different values for
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volunteer
Uh, the one.
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student
yeah
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volunteer
Why did you, why did you check two different values?
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volunteer
Because the
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student
plus/minus sqqr root 1 = + / - 1
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volunteer
You're, um,
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volunteer
Your one route.
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volunteer
Wasn't out of a square.
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volunteer
He didn't take the square root of it.
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volunteer
So it should just be positive one. I don't know why you tested um negative one as well.
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volunteer
-1 wasn't a route.
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volunteer
Right? Cause out of the um out of your algebra, you got two roots.
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volunteer
Um, your first route, uh, the 1/81, that uh
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volunteer
can be rewritten as a complex number to get you
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volunteer
To get you a, um,
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volunteer
The actual route.
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volunteer
But I think, I think it's just 11 real route.
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student
how 1/81 can be written as complex numbeer?
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volunteer
I don't know. I was just trying stuff, and I think I found a solution.
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volunteer
So if you take
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volunteer
What did I do? Right.
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volunteer
If you go back to your 81, well, I solved it differently than you. I mean, we got the same result, but I solved this slightly different.
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volunteer
I said,
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volunteer
Let
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student
okay
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volunteer
Why be equal to square root of x.
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volunteer
Therefore, my G of X G Y.
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volunteer
becomes
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volunteer
9
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volunteer
Y^2 minus 8Y.
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volunteer
-1.
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volunteer
Which just becomes
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volunteer
9 Y + 1.
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volunteer
Time
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volunteer
Why minus 1.
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volunteer
Which is what you got.
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volunteer
Except, um, you had it just basically squared, right? You got that.
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volunteer
X minus
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volunteer
Yeah, close enough.
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volunteer
Can I get, yeah, 9, yeah, and then if you
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volunteer
Factor back in what X is.
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volunteer
Or what why is you get 9 root X.
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volunteer
Plus one
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volunteer
Times
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volunteer
Root X minus 1.
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volunteer
You said equal to 0.
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