Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	It's one real route.	21,191	392	[]
volunteer	Because math	21,191	393	[]
volunteer	And leave it at that.	21,191	394	[]
volunteer	Just throw my hands in the air.	21,191	395	[]
student	what?	21,191	396	[]
volunteer	Well, the second answer we found.	21,191	397	[]
volunteer	1/81.	21,191	398	[]
volunteer	Isn't a root, because it doesn't.	21,191	399	[]
volunteer	Cause our function to go to zero.	21,191	400	[]
student	yeah	21,191	401	[]
volunteer	By definition,	21,191	402	[]
volunteer	A root causes of function to go to 0.	21,191	403	[]
volunteer	Let's see the polynomial root theorem.	21,191	404	[]
volunteer	They said a constraint, rational rational solutions or polynomial equation.	21,191	405	[]
student	not always, right?	21,191	406	[]
volunteer	The rational zero theorem is used to determine the rational routes.	21,191	407	[]
volunteer	Huh? Not always.	21,191	408	[]
student	a root doesn't necessarily always make equation 0	21,191	409	[]
volunteer	A root doesn't necessarily always make.	21,191	410	[]
volunteer	Equation 0	21,191	411	[]
student	is that right?	21,191	412	[]
volunteer	I feel like that goes against the very definition.	21,191	413	[]
volunteer	Um, is you said determine the rational routes that you can't use a route to, you can't use a definition that	21,191	414	[]
volunteer	Define it.	21,191	415	[]
volunteer	All right. Or you can't use a term to define a term.	21,191	416	[]
volunteer	like circular reasoning.	21,191	417	[]
volunteer	OK, here we go. So here the values of x that satisfy the equation F X equals 0 are known as the roots.	21,191	418	[]
volunteer	Or zeros of the polynomial.	21,191	419	[]
volunteer	I, like, by definition, a root has to zero the function.	21,191	420	[]
student	yeah,	21,191	421	[]
volunteer	So if	21,191	422	[]
volunteer	A solution we found.	21,191	423	[]
volunteer	Does not cause it to zero, then	21,191	424	[]
volunteer	It's not a root.	21,191	425	[]
student	when c, we still have roots	21,191	426	[]
student	but they don't satisfy the equation	21,191	427	[]
volunteer	And see greater than 0, we still have roots, but they don't satisfy the equation.	21,191	428	[]
volunteer	I see what you're saying.	21,191	429	[]
volunteer	But remember, we said,	21,191	430	[]
volunteer	I see, I see what you're saying. So, when you're basically going back to a definition that when A is greater than 0, or when A and C are the same sign.	21,191	431	[]
volunteer	There are no, um,	21,191	432	[]
volunteer	There are no roots.	21,191	433	[]
student	yeah no real roots	21,191	434	[]
volunteer	On the graph.	21,191	435	[]
volunteer	Hmm.	21,191	436	[]
volunteer	I can't help but think, um.	21,191	437	[]
volunteer	I can't help but feel that's wrong.	21,191	438	[]
volunteer	Cause you're right, graphing it, that comes true.	21,191	439	[]
volunteer	But then,	21,191	440	[]
volunteer	If we say X^2 plus.	21,191	441	[]
volunteer	2 X	21,191	442	[]
volunteer	Plus one	21,191	443	[]
volunteer	Right, which is	21,191	444	[]
volunteer	X + 1 squad.	21,191	445	[]
volunteer	The route would be x equals -1 twice with a multiplicity of 2.	21,191	446	[]
volunteer	This has a	21,191	447	[]
volunteer	Um, it has a C value. Remember we said that C is not, um, strictly	21,191	448	[]
volunteer	A vertical.	21,191	449	[]
volunteer	What term shift.	21,191	450	[]
volunteer	Um	21,191	451	[]
volunteer	If we can	21,191	452	[]
student	yes	21,191	453	[]
volunteer	denigrate this back to	21,191	454	[]
volunteer	Our, um,	21,191	455	[]
volunteer	I feel like P and Q are in the same place. So this might have	21,191	456	[]
volunteer	My example might have a intercept.	21,191	457	[]
volunteer	Or, or the, I'm sorry, the	21,191	458	[]
volunteer	What's the term	21,191	459	[]
volunteer	My God, she's, it's only been a day and my mind has just completely gone off the rails.	21,191	460	[]
volunteer	Um	21,191	461	[]
student	vertex?	21,191	462	[]
volunteer	Vertex, yes.	21,191	463	[]
volunteer	Where is, uh, so I'm trying to look through my notes where we did all these derivations.	21,191	464	[]
volunteer	We said that	21,191	465	[]
volunteer	So B is equal to -2AH.	21,191	466	[]
volunteer	So be would be	21,191	467	[]
volunteer	Well, let's apply it to our original expression.	21,191	468	[]
volunteer	9	21,191	469	[]
volunteer	Um, I guess I'll keep it Y. 9 z minus 8 Y minus 1.	21,191	470	[]
volunteer	So if we solve for age,	21,191	471	[]
volunteer	For the horizontal.	21,191	472	[]
volunteer	My goodness, my brain is horizontal ****, the horizontal shift of the vertex.	21,191	473	[]
volunteer	We get	21,191	474	[]
volunteer	Wow, I'm getting, I'm getting flagged for words like shift.	21,191	475	[]
volunteer	And	21,191	476	[]
volunteer	Asympto	21,191	477	[]
volunteer	Apparently, I'm pronouncing them too close to bad language. I'd be very mindful of that.	21,191	478	[]
volunteer	K + AH squared is equal to.	21,191	479	[]
volunteer	C minus A H 2.	21,191	480	[]
volunteer	Rather than me calculating, I'm just gonna throw it up on Desmos. This is.	21,191	481	[]
volunteer	My mind is not.	21,191	482	[]
student	can we consider 1/81 as complex root?	21,191	483	[]
volunteer	Sharp is it was yesterday.	21,191	484	[]
volunteer	All right, so I'll do both forms. So 9 X squared.	21,191	485	[]
volunteer	Minus 8 X minus 1.	21,191	486	[]
volunteer	OK. So we see,	21,191	487	[]
volunteer	We have	21,191	488	[]
volunteer	Two intercepts.	21,191	489	[]
volunteer	We got one at one.	21,191	490	[]
volunteer	And	21,191	491	[]

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