Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	Then we can use ASA for these, right? Because the site will be the included site, like the side between these two angles.	4,385	102	[]
student	Yes	4,385	103	[]
volunteer	OK.	4,385	104	[]
volunteer	So how, uh, how can you, can you prove that let me change the color.	4,385	105	[]
volunteer	How can you prove that this angle?	4,385	106	[]
volunteer	is equal to this one	4,385	107	[]
student	Um	4,385	108	[]
volunteer	Um, yeah.	4,385	109	[]
student	I'm not sure what it's called exactly, but can we say like, because we already know that um	4,385	110	[]
student	Engle BCA is congruent to Engle CAD because it's technically half.	4,385	111	[]
student	um, like the other side would be equal.	4,385	112	[]
volunteer	So, we can't say that it's half. How do we know that it's half?	4,385	113	[]
student	Because	4,385	114	[]
volunteer	We don't	4,385	115	[]
student	oh OK	4,385	116	[]
student	Yeah.	4,385	117	[]
volunteer	Yeah, we don't know that. So, again, we'll use the	4,385	118	[]
volunteer	um, what, what else can we use? OK. OK. He is out. We know that angle B equals angle D and let's say if this angle is, let's say X	4,385	119	[]
volunteer	and this angle is Y, so we know that this angle will also be X because both of these angles are equal, right?	4,385	120	[]
student	Yes	4,385	121	[]
volunteer	Yes, and also, if this angle is by that, this angle will also be why because both of these angles are equal.	4,385	122	[]
volunteer	Uh, so, uh we also know this property that for a triangle.	4,385	123	[]
student	Um, we can say	4,385	124	[]
student	like	4,385	125	[]
volunteer	uh that some of all the angles. So this is B A B C Agula plus angle B + angle C 180 degree, right?	4,385	126	[]
student	yes	4,385	127	[]
volunteer	This is the angle some property. So if I say that one of the angles is X, the other one is Y, and I need to find this angle. How can I do that? I'll just substitute these values, right? A is X, is B is Y, plus angle C is equals 180 degree uh minus X minus Y minus X minus Y.	4,385	128	[]
volunteer	uh and the C equals 18T minus X minus.	4,385	129	[]
volunteer	Is this clear	4,385	130	[]
student	Yes	4,385	131	[]
volunteer	OK. So, if I use the same thing here, so can I say that this angle	4,385	132	[]
volunteer	which is angle BAC.	4,385	133	[]
volunteer	Ale B A C equals 180 degree minus x minusy.	4,385	134	[]
volunteer	because for	4,385	135	[]
volunteer	for our this triangle that we have here.	4,385	136	[]
student	Mhm	4,385	137	[]
volunteer	some of all three angles should 180 degree, and if two angles are X and Y, so the third angle should 180 minus X minus Y.	4,385	138	[]
volunteer	Then only the sum of all the three angles will 180.	4,385	139	[]
student	Yeah	4,385	140	[]
volunteer	Uh, OK, all right. Uh, is this clear or not?	4,385	141	[]
student	Yeah, I understand it	4,385	142	[]
volunteer	Yeah, or else we can say that for this triangle,	4,385	143	[]
volunteer	triangle A, B, C	4,385	144	[]
volunteer	Um, I'm gonna be AC + that BSC is this one, right?	4,385	145	[]
student	Mhm	4,385	146	[]
volunteer	That's ACB	4,385	147	[]
volunteer	A C B ACB is your this	4,385	148	[]
volunteer	plus angle CBA.	4,385	149	[]
volunteer	C B A	4,385	150	[]
volunteer	equals 180 degree	4,385	151	[]
volunteer	right?	4,385	152	[]
student	Yeah	4,385	153	[]
volunteer	And we know that angle ACB.	4,385	154	[]
volunteer	ACB is Y.	4,385	155	[]
volunteer	So I'll write BAC + Y + CBA CBA is X	4,385	156	[]
volunteer	equals 180 degree.	4,385	157	[]
volunteer	and	4,385	158	[]
volunteer	from here	4,385	159	[]
volunteer	I'll say and the BAC equals 180 minus X minus Y.	4,385	160	[]
volunteer	Is this clear now	4,385	161	[]
student	Yes	4,385	162	[]
volunteer	Has it subtracted uh X and Y from both sides.	4,385	163	[]
student	Mm.	4,385	164	[]
student	and then you would get angle	4,385	165	[]
student	BAC's equal 180 minus, yeah, OK.	4,385	166	[]
volunteer	OK. Yeah	4,385	167	[]
student	Mhm	4,385	168	[]
volunteer	Uh, in the similar way	4,385	169	[]
volunteer	if we look at this triangle, angle A, D, C, so I'm sorry, triangle ADC.	4,385	170	[]
volunteer	No triangle ADC.	4,385	171	[]
volunteer	Mm.	4,385	172	[]
student	Um,	4,385	173	[]
student	we would do the same.	4,385	174	[]
volunteer	Yeah, we'll do the same for a triangle ADC	4,385	175	[]
volunteer	uh I see AD plus	4,385	176	[]
volunteer	right and we CAD plus	4,385	177	[]
volunteer	uh	4,385	178	[]
volunteer	and then ABC.	4,385	179	[]
volunteer	plus	4,385	180	[]
volunteer	CAD ADC and DCA.	4,385	181	[]
volunteer	Yeah	4,385	182	[]
volunteer	And the DCA and the sum should be 1ically because of, because it's about all angles in a triangle 180 degree.	4,385	183	[]
volunteer	Uh, now, I'll, I'll do the same thing. So, can you help me with the next steps?	4,385	184	[]
student	Um	4,385	185	[]
volunteer	Oh	4,385	186	[]
student	well, like we would do another um	4,385	187	[]
student	statement after this one.	4,385	188	[]
volunteer	Yeah	4,385	189	[]
student	See, like, I understand what you did to show that they're like congruent.	4,385	190	[]
student	but	4,385	191	[]
student	um	4,385	192	[]
student	wait, I'll add a picture to show you, like these are the statements that um I've like been using to show the reasoning that we just showed.	4,385	193	[]
student	Um	4,385	194	[]
volunteer	Yeah	4,385	195	[]
student	um, like right here.	4,385	196	[]
volunteer	OK	4,385	197	[]
volunteer	Uh, reflexive cogitive substitution, vertical angles are congruent all right under the communal final angles opposite of congruent sides.	4,385	198	[]
volunteer	are congruent	4,385	199	[]
volunteer	OK. And I'm will bisected divides and into two.	4,385	200	[]
volunteer	congruentambles.	4,385	201	[]

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