role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | sorry 3 root n | 18,576 | 62 | [] |
student | Oohh, so the range in the function is defined by the domain, if n can't be negative and has to be greater than or equal to 0, m has to be the same, right? | 18,576 | 63 | [] |
volunteer | Well, that changes on the function. The domain is not always equal to the range. Imagine a vertical shift up 1 for this same function. The domain would be the same but the range would be [1, infinite) | 18,576 | 64 | [] |
student | So it depends on the starting point basically, so if it was n≥4, it would start at four and be [4,∞) | 18,576 | 65 | [] |
volunteer | That is 4 the domain. The range would still be [0, infinite). What I am talking about with a vertical shift is a +1. See graph :) | 18,576 | 66 | [] |
volunteer | You are right about that being the domain. The range is altered by a different value though. | 18,576 | 67 | [] |
volunteer | Your problem does not have a vertical shift. So don't worry too much about it for this particular question. | 18,576 | 68 | [] |
student | So it would shift up depending on the y function, so if it m=3√n+4 it would still start at 4 | 18,576 | 69 | [] |
volunteer | The range would start at 4, yes. | 18,576 | 70 | [] |
volunteer | The domain is still [0, infite) | 18,576 | 71 | [] |
student | So the range for this function would be m≥0 because it starts at 0 and continues that or [0,∞) | 18,576 | 72 | [] |
volunteer | Yes. That is right! | 18,576 | 73 | [] |
volunteer | Do you understand it well enough? | 18,576 | 74 | [] |
student | Im getting there, if I were to see it on a test I would freeze | 18,576 | 75 | [] |
volunteer | Yes. You can always just use the graph. There are only a few you will ever see in Algebra 2. You have to use the original function and apply the transformation sto get the domain and range. | 18,576 | 76 | [] |
volunteer | This is radical. I will put a few on the bottom of the current graph. | 18,576 | 77 | [] |
volunteer | Have you seen these? | 18,576 | 78 | [] |
student | I think I have but I can't be too sure | 18,576 | 79 | [] |
volunteer | Okay. It is the start of the school year, so you will. | 18,576 | 80 | [] |
volunteer | Just remember that this question already gave you the input (n, often seen as x) | 18,576 | 81 | [] |
student | I'm in Algebra 2 algebra, so we kind of go through topics very fast, it doesn't help that I missed this topic in algebra 1 | 18,576 | 82 | [] |
volunteer | You already had the domain/ | 18,576 | 83 | [] |
volunteer | Okay. I also skipped Algebra 1. Khan Academy. It truly explains everything very well. Algebra 2 does become much easirer with a lot of Algebra 1 practice. | 18,576 | 84 | [] |
student | That's what I've heard, I'll make sure to stay on top of that! | 18,576 | 85 | [] |
volunteer | Yes. It is great. Remmember to keep inputs and outputs straight and to always look for what the problem already gives you. | 18,576 | 86 | [] |
volunteer | x and y are not the only possible function variables. | 18,576 | 87 | [] |
student | Question, if f(x)=x⁴ and domain is xeR, all real numbers would the range be all real numbers to? | 18,576 | 88 | [] |
volunteer | For this question, I believe so. | 18,576 | 89 | [] |
volunteer | The root is even so all numbers will be positive. The lowest (x=0) will be negative. | 18,576 | 90 | [] |
volunteer | Great job! | 18,576 | 91 | [] |
volunteer | sorry x=0 will be 0 | 18,576 | 92 | [] |
volunteer | NOT negative | 18,576 | 93 | [] |
student | And for this question I'm going to write it out | 18,576 | 94 | [] |
volunteer | You can write it out if that helps you. :) | 18,576 | 95 | [] |
volunteer | Okay. This is absolute value. | 18,576 | 96 | [] |
volunteer | The range is [0, infinite) and the domain is all real numbers (here, the horizontal shift does not matter) | 18,576 | 97 | [] |
student | How did you get that | 18,576 | 98 | [] |
volunteer | Do you see the graph? | 18,576 | 99 | [] |
student | Yes | 18,576 | 100 | [] |
volunteer | What are all the possible x-vales? | 18,576 | 101 | [] |
volunteer | values | 18,576 | 102 | [] |
volunteer | Over what portion of the x-axis will it cover? | 18,576 | 103 | [] |
student | Anything between -10 and 10 | 18,576 | 104 | [] |
volunteer | Why do you think that? | 18,576 | 105 | [] |
student | Wait, anything less than or equal to -10 and 10 because of the symbol | 18,576 | 106 | [] |
volunteer | No. It is all real numbers because it stretches infintely on the x-axis in both directions. | 18,576 | 107 | [] |
student | How? | 18,576 | 108 | [] |
volunteer | The graph is a V and its sides are contining forever (per the nature of the graph). The arrows represent infinite. | 18,576 | 109 | [] |
student | But wouldn't it be negative | 18,576 | 110 | [] |
volunteer | all real numbers includes possible negative values | 18,576 | 111 | [] |
student | So what does the domain indicate | 18,576 | 112 | [] |
volunteer | the x-values that can be inputed | 18,576 | 113 | [] |
volunteer | the range is separate on the y-axis | 18,576 | 114 | [] |
volunteer | Liam, I am so sorry but I must leave the session. You have been great. Contact support or requesting another session to continue your learning. | 18,576 | 115 | [
{
"pii_type": "PERSON",
"surrogate": "Liam",
"start": 0,
"end": 4
}
] |
student | Thank you again for all your help | 18,576 | 116 | [] |
volunteer | Your welcome! | 18,576 | 117 | [] |
volunteer | hello | 18,609 | 0 | [] |
student | hiii | 18,609 | 1 | [] |
student | ow r uu | 18,609 | 2 | [] |
volunteer | good | 18,609 | 3 | [] |
volunteer | how can i help you today | 18,609 | 4 | [] |
student | I need help preparing for a unit exam | 18,609 | 5 | [] |
volunteer | did you want me to walk you through solving this problem? | 18,609 | 6 | [] |
student | yes that would be great | 18,609 | 7 | [] |
volunteer | alright sounds good | 18,609 | 8 | [] |
volunteer | so do you know what complementary means | 18,609 | 9 | [] |
student | yes but I forgot | 18,609 | 10 | [] |
volunteer | alright so complementary angles are angles whos sums add up to 90 degrees | 18,609 | 11 | [] |
student | ok thats what I thought | 18,609 | 12 | [] |
volunteer | so we know that these two angles that we have to solve for add up to 90 | 18,609 | 13 | [] |
student | ok | 18,609 | 14 | [] |
volunteer | so then it says one angle is 3 degrees less than 2 times the other angle | 18,609 | 15 | [] |
volunteer | which i wrote as x=2y-3 | 18,609 | 16 | [] |
volunteer | so now that we have that we can plug 2y-3 in for x | 18,609 | 17 | [] |
student | ok that makes sense | 18,609 | 18 | [] |
volunteer | so when i plug that in i get 31 =y | 18,609 | 19 | [] |
volunteer | or 31 degrees for angle 2 | 18,609 | 20 | [] |
student | ok | 18,609 | 21 | [] |
volunteer | however the question is asking for both angles | 18,609 | 22 | [] |
volunteer | so we can plug in the value we got for y | 18,609 | 23 | [] |
volunteer | to find x | 18,609 | 24 | [] |
volunteer | and we get x=59 | 18,609 | 25 | [] |
volunteer | any questions | 18,609 | 26 | [] |
student | nope | 18,609 | 27 | [] |
volunteer | alright sounds good | 18,609 | 28 | [] |
volunteer | anything else you need help on today | 18,609 | 29 | [] |
student | no thank u so much that helped a lot | 18,609 | 30 | [] |
volunteer | k | 18,609 | 31 | [] |
volunteer | well good luck on your exam | 18,609 | 32 | [] |
volunteer | and have a great rest of your day | 18,609 | 33 | [] |
student | u too | 18,609 | 34 | [] |
student | Hello I need help with solving this I honestly don't understand it since this has no numbers | 18,801 | 0 | [] |
volunteer | ok | 18,801 | 1 | [] |
volunteer | basically it just wants you to get b on one side of the equal sign by itself | 18,801 | 2 | [] |
student | yeah ik but like how | 18,801 | 3 | [] |
volunteer | so | 18,801 | 4 | [] |
volunteer | if we want to isolate b | 18,801 | 5 | [] |
volunteer | what should we remove first from the left side | 18,801 | 6 | [] |
student | b? | 18,801 | 7 | [] |
volunteer | We want to remove all other terms from the left side so that we can solve for b(isolate b) | 18,801 | 8 | [] |
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