role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | by solving. | 16,685 | 32 | [] |
volunteer | So the 9 + 5 would give you the 14. | 16,685 | 33 | [] |
volunteer | Did you get that last part | 16,685 | 34 | [] |
volunteer | So it will be -2AB when you're squaring XA minus B. | 16,685 | 35 | [] |
volunteer | For A + B, it'll be +2AB. | 16,685 | 36 | [] |
volunteer | Any other questions? | 16,685 | 37 | [] |
student | the x-3^2 would be 3x3=9? | 16,685 | 38 | [] |
volunteer | Yes | 16,685 | 39 | [] |
student | so then it will be 9 and then the 5 | 16,685 | 40 | [] |
student | but do we add the 5 or subtract the 5 | 16,685 | 41 | [] |
volunteer | correct. | 16,685 | 42 | [] |
volunteer | So the answer is option C. | 16,685 | 43 | [] |
student | wait no i was asking a question | 16,685 | 44 | [] |
volunteer | The answer to your question is, uh, 9 and then the 5 gives you 14. | 16,685 | 45 | [] |
volunteer | We add the 5 only because that's one of the options and that will give you the 14. | 16,685 | 46 | [] |
volunteer | He. | 16,685 | 47 | [] |
volunteer | Are we clear | 16,685 | 48 | [] |
volunteer | Did I answer your question | 16,685 | 49 | [] |
student | but how do we know if we subtract or add the 5 | 16,685 | 50 | [] |
volunteer | If you subtract 5 | 16,685 | 51 | [] |
volunteer | then 9 minus 5. | 16,685 | 52 | [] |
volunteer | would give you 4 | 16,685 | 53 | [] |
volunteer | But if you look at the question | 16,685 | 54 | [] |
volunteer | it is x squared minus 6 x + 14. | 16,685 | 55 | [] |
volunteer | So the plus 5 is coming from option C. | 16,685 | 56 | [] |
volunteer | (x-3) ^2 = (x^2 - 6x + 9) | 16,685 | 57 | [] |
volunteer | (x-3) ^2 + 5 = (x^2 - 6x + 9) + 5 | 16,685 | 58 | [] |
student | ohh ok | 16,685 | 59 | [] |
student | because we alread subtract the x and the number | 16,685 | 60 | [] |
student | and then we just add the 5 | 16,685 | 61 | [] |
volunteer | yes | 16,685 | 62 | [] |
volunteer | good work. | 16,685 | 63 | [] |
student | ok so how do we know if its C or D | 16,685 | 64 | [] |
volunteer | because the Q has -6X | 16,685 | 65 | [] |
student | ohh we subtract the x and 3 | 16,685 | 66 | [] |
volunteer | and not +6X | 16,685 | 67 | [] |
student | ohh so it would be | 16,685 | 68 | [] |
student | ohh ok | 16,685 | 69 | [] |
volunteer | Yup. | 16,685 | 70 | [] |
volunteer | Excellent job | 16,685 | 71 | [] |
volunteer | I'm glad to see that you're trying to understand the concepts. | 16,685 | 72 | [] |
volunteer | and you have it all | 16,685 | 73 | [] |
student | ok can we do another one cause you explained it in a way for me to understand | 16,685 | 74 | [] |
volunteer | OK, let me delete the previous. | 16,685 | 75 | [] |
volunteer | answer | 16,685 | 76 | [] |
volunteer | Oh, you did it. Thank you. | 16,685 | 77 | [] |
volunteer | So you see that | 16,685 | 78 | [] |
volunteer | the, in all the options, | 16,685 | 79 | [] |
volunteer | the R is in the denominator. | 16,685 | 80 | [] |
volunteer | So our goal is to solve the above equation in such a way that our goes into the | 16,685 | 81 | [] |
volunteer | denominator | 16,685 | 82 | [] |
volunteer | So let me show you how. | 16,685 | 83 | [] |
volunteer | So when I solve the equation. | 16,685 | 84 | [] |
volunteer | on the left-hand side | 16,685 | 85 | [] |
volunteer | you get QX + 5 X. | 16,685 | 86 | [] |
volunteer | On the right-hand side | 16,685 | 87 | [] |
volunteer | You have 3Q | 16,685 | 88 | [] |
volunteer | Any questions so far | 16,685 | 89 | [] |
student | why we do 5x and we didnt do 5q? | 16,685 | 90 | [] |
volunteer | OK, good. So you caught the error | 16,685 | 91 | [] |
volunteer | I just wanted to make sure that you understand it. So it is 5Q. | 16,685 | 92 | [] |
volunteer | So now let's solve it further. | 16,685 | 93 | [] |
student | oh so it is qx + 5q and not 5x | 16,685 | 94 | [] |
volunteer | We have to isolate the eggs. | 16,685 | 95 | [] |
volunteer | Isolate the X | 16,685 | 96 | [] |
volunteer | Do you see the screen right now | 16,685 | 97 | [] |
volunteer | We, we took X out. | 16,685 | 98 | [] |
volunteer | and put Q+R in the brackets. | 16,685 | 99 | [] |
student | why we take x out? | 16,685 | 100 | [] |
volunteer | because that's the question. The question is saying, | 16,685 | 101 | [] |
volunteer | which equation represents the given equation when solved for X, so we are trying to find out. | 16,685 | 102 | [] |
volunteer | what is X equal to | 16,685 | 103 | [] |
volunteer | Do you understand that? | 16,685 | 104 | [] |
student | ok its asking when solved for x | 16,685 | 105 | [] |
volunteer | correct. | 16,685 | 106 | [] |
volunteer | If you wanna use the mic and speaker, it may be easier to kind of. | 16,685 | 107 | [] |
volunteer | walk you through that | 16,685 | 108 | [] |
student | so we have to figure out how to solve for x | 16,685 | 109 | [] |
volunteer | Yeah. | 16,685 | 110 | [] |
student | idk how we solve for x because why are we breaking apart the equation? | 16,685 | 111 | [] |
volunteer | You're not breaking apart the equation. I was just trying to explain it to you so we solve each side. | 16,685 | 112 | [] |
volunteer | of the equation, uh, but you can | 16,685 | 113 | [] |
volunteer | just um | 16,685 | 114 | [] |
volunteer | keep it as left-hand side and right hand side. | 16,685 | 115 | [] |
volunteer | because those two are the parts of the equation. | 16,685 | 116 | [] |
student | ok so we have q+r in paranthesis | 16,685 | 117 | [] |
volunteer | yes as x is common to both | 16,685 | 118 | [] |
student | why we do x(q+r) two times | 16,685 | 119 | [] |
volunteer | what do you mean? | 16,685 | 120 | [] |
student | like we did these two both times | 16,685 | 121 | [] |
volunteer | There two different lines | 16,685 | 122 | [] |
volunteer | the 2nd line has 3q-5q = -2q | 16,685 | 123 | [] |
volunteer | nothing is changes on the LHS | 16,685 | 124 | [] |
student | yea how we get -2q? | 16,685 | 125 | [] |
volunteer | i explained it above | 16,685 | 126 | [] |
student | yea so you did 5-3 | 16,685 | 127 | [] |
student | and then it got -2 | 16,685 | 128 | [] |
volunteer | dont forget the q | 16,685 | 129 | [] |
student | ok so it will be x= -2q/ ( q + r) | 16,685 | 130 | [] |
student | i think i will just be confused like doing the LHS and RHS | 16,685 | 131 | [] |
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