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student
Got it
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volunteer
Then add the 1 and -6
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volunteer
Then repeat the process
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volunteer
So now we would do -6 x -5
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volunteer
Now the results are at the bottom
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volunteer
The last term is always the remainder
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student
oh okioki
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volunteer
And the other terms are applied to increasing powers of x starting from 0
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student
so whts hte fa
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volunteer
So for -5 it would be -5x^0 which is just -5
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volunteer
Then 1x^1 which is x
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volunteer
If there's any remainder, you would write that over the existent divisor
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volunteer
Since the remainder is 0 it makes no difference
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student
Hmm
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student
then the next numberr??
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volunteer
Which number?
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student
x+2 so i can do 2 --2
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volunteer
Ok
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volunteer
Do you understand this?
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student
yup
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volunteer
That's great!
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volunteer
Do you still want my help for the other questions?
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student
what why is 2 -2 when in x+2 is x+2
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student
you change signs?
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volunteer
For the denominator (i.e. divisor), you're supposed to solve for the root of x
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volunteer
So in this case you would do x+2=0, which would give x=-2
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student
ohhh I see
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student
wait
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student
plz check
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student
4-3-12-32
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student
if you have any corrections feel free to correct in the thing i did
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volunteer
Ok
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volunteer
What's this?
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student
4 as we bring the first one down(?)
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volunteer
Yeah, that's correct, it was just a bit hard to read
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student
then abt abt -3-12-32
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volunteer
The final answer is wrong
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volunteer
Wait I'll write in red
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student
Understood
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student
whast the fa
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volunteer
Perfect
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student
plz check
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volunteer
Sure
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student
The solution is below the worksheet
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volunteer
Ok
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student
can you check
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volunteer
Yeah
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volunteer
-3x-2=6
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student
okay next
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student
oki please checkk
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volunteer
You should put the values in descending order of powers of x
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volunteer
So 3 should be first not lasr
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student
oh
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student
plz check
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student
can you write it with the variables?
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volunteer
Yes that's correct
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student
can you check
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student
can you do (2x^3 - 9x^2 + 4x + 12) / (2x-3)
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student
also check for (2x^3 - 9x^2 + 4x + 12) / (2x-3) i did the fa
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volunteer
Yes it's correct
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volunteer
9+2=1
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volunteer
9+2=11
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student
also can you do (2x^3 - 9x^2 + 4x + 12) / (2x-3) plz?
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volunteer
It's the same concept, equate the denominator to 0, solve for x, then apply synthetic division
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student
i dont get it plz helpp
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volunteer
For the divisor, you need to solve for x in 2x-3=0
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volunteer
And then the rest of the steps are the same
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student
huh i dont get it tot
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student
can you solve (2x^3 - 9x^2 + 4x + 12) / (2x-3) plz
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student
huh
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volunteer
It's the same steps, you're just multiplying and adding fractions instead of whole numbers
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student
plz can you do itt??
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student
dont get it??
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volunteer
I've written it in red
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volunteer
I'll explain it to you step by step
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volunteer
First for the divisor, we solve for x in 2x-3=0, which gives x=3/2
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student
lets do it together
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volunteer
I'll solve it in the gray box
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student
Okay
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volunteer
Do you understand so far?
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student
yup
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volunteer
3/2 x 3 = 9/2
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volunteer
-9+9/2=-9/2
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volunteer
3/2 x -9/2 = -27/4
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student
oh okoki
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volunteer
-4+(-27/4)=-43/4
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student
oh okiki
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volunteer
3/2 x -43/4 = -129/8
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volunteer
12+(-129/8)=-33/8
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volunteer
That's it
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student
oh okioki
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student
is it correct??
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volunteer
The denominator should be 2x-3
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volunteer
For the last term
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student
huh
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volunteer
We always use the denominator of the original question
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student
thank youu
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volunteer
No problem!
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volunteer
Happy to help
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volunteer
hello
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