role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
student | is this something we only do for a cube equation? | 15,785 | 118 | [] |
volunteer | Not really, there's other ways into solving cube equations, but I only demonstrated one of the few | 15,785 | 119 | [] |
student | so 3a and 4c become 9a and 16c | 15,785 | 120 | [] |
volunteer | Yes | 15,785 | 121 | [] |
student | what about 3a+4c | 15,785 | 122 | [] |
volunteer | Good job at executing each problem with effort | 15,785 | 123 | [] |
volunteer | 3a and 4c will remain the same as they only act as a factor | 15,785 | 124 | [] |
student | alright | 15,785 | 125 | [] |
volunteer | Okay I hope I helped you effectively to understand and solve questions like these | 15,785 | 126 | [] |
student | wait | 15,785 | 127 | [] |
student | I cant think of a number multiplying to 16 and adding to 12 | 15,785 | 128 | [] |
volunteer | Are you trying to further simplify the fully factored expression? | 15,785 | 129 | [] |
student | do we have to square it again? | 15,785 | 130 | [] |
volunteer | No you don't have to | 15,785 | 131 | [] |
student | oh wait | 15,785 | 132 | [] |
volunteer | The final product should be: (3a + 4c)(9a^2 -12ac + 16c^2) | 15,785 | 133 | [] |
student | now? | 15,785 | 134 | [] |
volunteer | No it wouldn't work | 15,785 | 135 | [] |
volunteer | Because the last term of c will be 12c^2 and not 16c^2, which we are looking for | 15,785 | 136 | [] |
volunteer | So your first answer that you wrote down was correct | 15,785 | 137 | [] |
student | (a-2c)^2 and (3a+4c)? | 15,785 | 138 | [] |
volunteer | No, it won't be the same | 15,785 | 139 | [] |
student | what... | 15,785 | 140 | [] |
volunteer | Because you will receive -8a^2c - 4ac^2 | 15,785 | 141 | [] |
volunteer | So it wouldn't align with 9a^2 -12ac + 16c^2 | 15,785 | 142 | [] |
student | oh | 15,785 | 143 | [] |
volunteer | Okay is there any more questions that you have before I end the session. | 15,785 | 144 | [] |
volunteer | Also it was nice meeting you Alex | 15,785 | 145 | [
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"pii_type": "PERSON",
"surrogate": "Alex",
"start": 29,
"end": 33
}
] |
student | what are the two formulas? | 15,785 | 146 | [] |
volunteer | The cube and square? | 15,785 | 147 | [] |
student | yes | 15,785 | 148 | [] |
volunteer | Square formula: (a^2 - b^2) = (a-b)(a+b) and Cube formula: a^3 + b^3 = (a+b)(a^2 - ab + b^2) | 15,785 | 149 | [] |
volunteer | Is there any other questions? | 15,785 | 150 | [] |
student | thats it | 15,785 | 151 | [] |
student | thank you for working with me | 15,785 | 152 | [] |
volunteer | My pleasure. If you ever need help again, feel free to contact me since Tutor Provider is available 24/7 | 15,785 | 153 | [] |
volunteer | It was nice working and speaking to you Alex! | 15,785 | 154 | [
{
"pii_type": "PERSON",
"surrogate": "Alex",
"start": 40,
"end": 44
}
] |
student | Alright then, see you another possible day | 15,785 | 155 | [] |
student | Bye then! | 15,785 | 156 | [] |
volunteer | Of course, I'll look forward into working with you | 15,785 | 157 | [] |
volunteer | Bye Alex!!! | 15,785 | 158 | [
{
"pii_type": "PERSON",
"surrogate": "Alex",
"start": 4,
"end": 8
}
] |
student | bye! | 15,785 | 159 | [] |
volunteer | Hi Liam! How is your day so far? | 15,792 | 0 | [
{
"pii_type": "PERSON",
"surrogate": "Liam",
"start": 3,
"end": 7
}
] |
student | It's okay. thanks for asking | 15,792 | 1 | [] |
volunteer | My pleasure, well I hope you're excited because by the end of this session, you'll be able to solve and understand the topic and questions that you need help with | 15,792 | 2 | [] |
student | Awesome. Thank you. I'm not really sure how this works. I just signed up | 15,792 | 3 | [] |
volunteer | Oh it's okay, I'm just here for guidance and help on what you're confused about | 15,792 | 4 | [] |
volunteer | Okay let's jump right into the question | 15,792 | 5 | [] |
student | Ok. I will write it on the board | 15,792 | 6 | [] |
volunteer | Okay perfect. | 15,792 | 7 | [] |
volunteer | After you write down the equations. Can you provide specific information on what the question is asking you to solve or do | 15,792 | 8 | [] |
volunteer | But based on what you're writing, it seems like system of equations if I'm not mistaken | 15,792 | 9 | [] |
student | Yes it is. The question asks: Solve the following system of equations using any method. I remember doing this my freshman year but I don't know how to do it anymore | 15,792 | 10 | [
{
"pii_type": "GRADE_LEVEL",
"surrogate": "freshman",
"start": 113,
"end": 121
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volunteer | What methods do you know to solve system of equations? | 15,792 | 11 | [] |
student | Substitution is all | 15,792 | 12 | [] |
student | That I know | 15,792 | 13 | [] |
volunteer | Oh okay, we can use that method then to solve the given equations | 15,792 | 14 | [] |
volunteer | Do you know what to do first? | 15,792 | 15 | [] |
student | No | 15,792 | 16 | [] |
volunteer | What do you remember from substitution? | 15,792 | 17 | [] |
student | That there has to be the same number to cancel each other out | 15,792 | 18 | [] |
volunteer | Oh, you mixed elimination and substitution together where substitution requires you to solve for y through putting your equation into slope-intercept form | 15,792 | 19 | [] |
volunteer | Then you substitute it into the other equation of y. For example y = 2x + 2, If I want to figure out whether it has a solution or not then I would plug in 6x - 2(2x + 2) = 10 | 15,792 | 20 | [] |
volunteer | Hi Alex! | 15,826 | 0 | [
{
"pii_type": "PERSON",
"surrogate": "Alex",
"start": 3,
"end": 7
}
] |
volunteer | How can I best help you today? | 15,826 | 1 | [] |
student | Hi. Well first I wanna make sure i'Northwood High algebra wasn't an option :( | 15,826 | 2 | [
{
"pii_type": "SCHOOL",
"surrogate": "Northwood High",
"start": 35,
"end": 49
}
] |
volunteer | I don'Northwood High algebra is an option...but depending on what it is I can probably help! | 15,826 | 3 | [
{
"pii_type": "SCHOOL",
"surrogate": "Northwood High",
"start": 6,
"end": 20
}
] |
student | Ok thank you! Let me get the photo | 15,826 | 4 | [] |
student | Honestly I have been struggling to understand ANY of this unit | 15,826 | 5 | [] |
volunteer | Okay no worries! I think I can help! | 15,826 | 6 | [] |
volunteer | Let's start with the first one... any ideas on how to start? If not that's totally fine! | 15,826 | 7 | [] |
student | I have no idea | 15,826 | 8 | [] |
volunteer | Okay that's all good! I'll do a mix of writing on the board and typing out explanations to hopefully make it clearer | 15,826 | 9 | [] |
volunteer | okay let's start by multiplying both sides by x-5 | 15,826 | 10 | [] |
volunteer | what will that give us? | 15,826 | 11 | [] |
student | well I think on the first side, it cancels out the bottom.. | 15,826 | 12 | [] |
volunteer | Yep exactly right! | 15,826 | 13 | [] |
student | I'm not sure it would affect the 10 though | 15,826 | 14 | [] |
volunteer | it would not affect the 10 | 15,826 | 15 | [] |
student | so the other would just be x-5 right? Because 1x1 is still 1 | 15,826 | 16 | [] |
volunteer | Yep! | 15,826 | 17 | [] |
volunteer | and then what would x be? | 15,826 | 18 | [] |
student | if I did my math right, I think 15? | 15,826 | 19 | [] |
volunteer | Yeah, you got it! | 15,826 | 20 | [] |
volunteer | Alright, ready for the next one? | 15,826 | 21 | [] |
student | yes | 15,826 | 22 | [] |
volunteer | Great! So for this one since there are multiple fractions we will need a common denominator | 15,826 | 23 | [] |
volunteer | Any idea how to do that? | 15,826 | 24 | [] |
student | nope | 15,826 | 25 | [] |
volunteer | Okay no worries! | 15,826 | 26 | [] |
volunteer | so let's start with the one on the right....if we pull a negative sign out front, it will look closer to the other denominators | 15,826 | 27 | [] |
volunteer | does what I just did make sense so far? | 15,826 | 28 | [] |
student | kinda? | 15,826 | 29 | [] |
student | sorry, I'm just a little confused on why it would become negative if that makes sense | 15,826 | 30 | [] |
volunteer | Okay no worries, that's a great question to ask. So what I did was basically multiplying by a -1 over a -1 which is just 1 right? So it doesn't actually change the fraction | 15,826 | 31 | [] |
volunteer | but what it does do, is when the negative gets distributed to all the terms the x becomes positive and the three becomes negative | 15,826 | 32 | [] |
volunteer | You also don't have to do this step, but it will make your other steps much easier. | 15,826 | 33 | [] |
student | oh ok | 15,826 | 34 | [] |
volunteer | I'm hoping that makes a little more sense now? | 15,826 | 35 | [] |
student | Mostly, yeah | 15,826 | 36 | [] |
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