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student
is this something we only do for a cube equation?
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volunteer
Not really, there's other ways into solving cube equations, but I only demonstrated one of the few
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student
so 3a and 4c become 9a and 16c
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volunteer
Yes
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student
what about 3a+4c
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volunteer
Good job at executing each problem with effort
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volunteer
3a and 4c will remain the same as they only act as a factor
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student
alright
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volunteer
Okay I hope I helped you effectively to understand and solve questions like these
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student
wait
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student
I cant think of a number multiplying to 16 and adding to 12
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volunteer
Are you trying to further simplify the fully factored expression?
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student
do we have to square it again?
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volunteer
No you don't have to
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student
oh wait
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volunteer
The final product should be: (3a + 4c)(9a^2 -12ac + 16c^2)
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student
now?
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volunteer
No it wouldn't work
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volunteer
Because the last term of c will be 12c^2 and not 16c^2, which we are looking for
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volunteer
So your first answer that you wrote down was correct
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student
(a-2c)^2 and (3a+4c)?
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volunteer
No, it won't be the same
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student
what...
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volunteer
Because you will receive -8a^2c - 4ac^2
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volunteer
So it wouldn't align with 9a^2 -12ac + 16c^2
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student
oh
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volunteer
Okay is there any more questions that you have before I end the session.
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volunteer
Also it was nice meeting you Alex
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[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 29, "end": 33 } ]
student
what are the two formulas?
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volunteer
The cube and square?
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student
yes
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volunteer
Square formula: (a^2 - b^2) = (a-b)(a+b) and Cube formula: a^3 + b^3 = (a+b)(a^2 - ab + b^2)
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volunteer
Is there any other questions?
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student
thats it
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student
thank you for working with me
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volunteer
My pleasure. If you ever need help again, feel free to contact me since Tutor Provider is available 24/7
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volunteer
It was nice working and speaking to you Alex!
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[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 40, "end": 44 } ]
student
Alright then, see you another possible day
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student
Bye then!
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volunteer
Of course, I'll look forward into working with you
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volunteer
Bye Alex!!!
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[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 4, "end": 8 } ]
student
bye!
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volunteer
Hi Liam! How is your day so far?
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[ { "pii_type": "PERSON", "surrogate": "Liam", "start": 3, "end": 7 } ]
student
It's okay. thanks for asking
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volunteer
My pleasure, well I hope you're excited because by the end of this session, you'll be able to solve and understand the topic and questions that you need help with
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student
Awesome. Thank you. I'm not really sure how this works. I just signed up
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volunteer
Oh it's okay, I'm just here for guidance and help on what you're confused about
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volunteer
Okay let's jump right into the question
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student
Ok. I will write it on the board
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volunteer
Okay perfect.
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volunteer
After you write down the equations. Can you provide specific information on what the question is asking you to solve or do
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volunteer
But based on what you're writing, it seems like system of equations if I'm not mistaken
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student
Yes it is. The question asks: Solve the following system of equations using any method. I remember doing this my freshman year but I don't know how to do it anymore
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[ { "pii_type": "GRADE_LEVEL", "surrogate": "freshman", "start": 113, "end": 121 } ]
volunteer
What methods do you know to solve system of equations?
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student
Substitution is all
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student
That I know
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volunteer
Oh okay, we can use that method then to solve the given equations
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volunteer
Do you know what to do first?
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student
No
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volunteer
What do you remember from substitution?
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student
That there has to be the same number to cancel each other out
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volunteer
Oh, you mixed elimination and substitution together where substitution requires you to solve for y through putting your equation into slope-intercept form
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volunteer
Then you substitute it into the other equation of y. For example y = 2x + 2, If I want to figure out whether it has a solution or not then I would plug in 6x - 2(2x + 2) = 10
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volunteer
Hi Alex!
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[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 3, "end": 7 } ]
volunteer
How can I best help you today?
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student
Hi. Well first I wanna make sure i'Northwood High algebra wasn't an option :(
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[ { "pii_type": "SCHOOL", "surrogate": "Northwood High", "start": 35, "end": 49 } ]
volunteer
I don'Northwood High algebra is an option...but depending on what it is I can probably help!
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[ { "pii_type": "SCHOOL", "surrogate": "Northwood High", "start": 6, "end": 20 } ]
student
Ok thank you! Let me get the photo
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student
Honestly I have been struggling to understand ANY of this unit
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volunteer
Okay no worries! I think I can help!
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volunteer
Let's start with the first one... any ideas on how to start? If not that's totally fine!
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student
I have no idea
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volunteer
Okay that's all good! I'll do a mix of writing on the board and typing out explanations to hopefully make it clearer
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volunteer
okay let's start by multiplying both sides by x-5
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volunteer
what will that give us?
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student
well I think on the first side, it cancels out the bottom..
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volunteer
Yep exactly right!
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student
I'm not sure it would affect the 10 though
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volunteer
it would not affect the 10
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student
so the other would just be x-5 right? Because 1x1 is still 1
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volunteer
Yep!
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volunteer
and then what would x be?
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student
if I did my math right, I think 15?
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volunteer
Yeah, you got it!
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volunteer
Alright, ready for the next one?
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student
yes
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volunteer
Great! So for this one since there are multiple fractions we will need a common denominator
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volunteer
Any idea how to do that?
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student
nope
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volunteer
Okay no worries!
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volunteer
so let's start with the one on the right....if we pull a negative sign out front, it will look closer to the other denominators
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volunteer
does what I just did make sense so far?
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student
kinda?
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student
sorry, I'm just a little confused on why it would become negative if that makes sense
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volunteer
Okay no worries, that's a great question to ask. So what I did was basically multiplying by a -1 over a -1 which is just 1 right? So it doesn't actually change the fraction
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volunteer
but what it does do, is when the negative gets distributed to all the terms the x becomes positive and the three becomes negative
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volunteer
You also don't have to do this step, but it will make your other steps much easier.
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student
oh ok
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volunteer
I'm hoping that makes a little more sense now?
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student
Mostly, yeah
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