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volunteer
Okay for how to move the terms to one side, think about the first problem we did where 10 = x - 5. How did you solve for x there? What did you do to move the 5 term to the other side?
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student
add 5
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student
so it cancelled out on one side and added 5 to the 10
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volunteer
yep exactly so if you wanted to move the x^2 to the other side what would you do
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volunteer
And then what about the 5x and the 6?
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student
minus the x^2, minus the 5x and minue the 6
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student
minus
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volunteer
Correct!
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student
woah sorry my internet cut for a moment
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student
Let me do that on my paper real quick
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student
wait
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student
oh never mind I was looking at something wrong
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student
ok so I moved that over so would I use those equations to find x?
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volunteer
Yep you'd use the quadratic formula to find x now unless you want to factor your solution and find x that way
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volunteer
Whichever way is easiest for you
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student
uh how do I do that-
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student
The formula
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volunteer
Did you talk about that formula in class?
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student
nope
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volunteer
Okay then your teacher probably wants you to factor the solution and solve that way instead
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volunteer
Do you know how to do that?
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student
not very well
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volunteer
okay give it your best shot and I'll help you fix it if its not right!
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student
uhhh
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volunteer
what would your first step be or any ideas about how to solve it?
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student
oh wait I do have the quadratic formula
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student
I didn't realize
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volunteer
Okay you can use that then if you want since its just plugging numbers in
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student
uh here's where Im confused though
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student
This is my equation: x^2-12x-3=x^2-4x+3
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volunteer
wait what
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volunteer
I thought you simplified by bringing all of the terms to one side?
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student
I only moved the one
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student
do I need to move the others too?
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volunteer
Yep
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student
oh shoot
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student
Sorry, that's my mistake
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volunteer
It's all good
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student
wait how do I do that...x^2-x^2 would be 0 wouldn't it
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volunteer
correct you'd have x^2 on one side since 2x^2 - x^2 = 1x^2 and 0 on the other side
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student
?
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volunteer
I underlined it on the screenshot of your paper
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student
oh but here's where I'm lost. I already did one which gave the equation I told you about so wouldn't it be zero or just not exist if I moved the other x^2 over
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volunteer
What do you mean you did one?
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volunteer
Like you already moved the x^2?
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volunteer
Because then yes it would be zero correct
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student
Did you see the 1,2,3 on the one paper? I can explain what I mean if you saw them
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volunteer
Yeah I see that
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student
ok so what I did is I took e.3 and put it into e.1 so I got the x^2-12x-3
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student
wait that's wrong
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volunteer
where did equation 3 come from?
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volunteer
Oh wait nevermind I see
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volunteer
So I think you never added equation 2 and 3?
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student
not together no
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volunteer
Okay start with that
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volunteer
I think that was the step you were missing that was throwing you off
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student
makes sense
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student
2x^2+x+9
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volunteer
great that's right
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volunteer
now move those terms to the other side where equation 1 is
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volunteer
and solve for x
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student
0-8x-6
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student
wait what-
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student
I don't think that's right..
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volunteer
No that's right
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student
oh
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volunteer
You have -8x - 6 = 0
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volunteer
which you can solve for x
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volunteer
So what would x be then?
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student
-0.75?
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volunteer
Yes, let's go!!!
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volunteer
Great job persevering through that one!
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student
Almost cried twice haha but would've been worth it
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volunteer
Proud of you!
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student
any way we could go through at least #3?
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volunteer
Yep, I have a little time left - about 15 more minutes. Why don't you try to work through this one using the skills we worked on in the last one and I can help you when you get stuck?
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student
oh uh-
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volunteer
So what was our very first step for the last problem?
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student
common denominator
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volunteer
Great so any ideas for the common denominator here?
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student
um
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volunteer
just give it your best guess
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student
all of them are letters, I don't know-
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volunteer
pretend they are numbers, say 3, 7, 4
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volunteer
what would you do then to find a common denominator?
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student
uh I don't remember how to find thst
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student
that
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volunteer
okay that's find you'd just multiply the denominators together
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volunteer
so in the case with the numbers it would 3 x 7 x 4
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volunteer
or in your case with the letters it would be....?
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student
rmj?
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volunteer
yes!!
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volunteer
Now go one by one and fill in the numerator for each fraction with the two letters that are missing
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volunteer
so for 1/r for example you are missing m and j right?
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student
yes
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volunteer
great, now do the other two yourself!
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student
would it be rj/rmj and rm/rmj
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volunteer
yes, exactly!
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volunteer
and all the terms again have the same denominator so what should we do next?
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student
factor the numerators
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