role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
volunteer | Okay for how to move the terms to one side, think about the first problem we did where 10 = x - 5. How did you solve for x there? What did you do to move the 5 term to the other side? | 15,826 | 137 | [] |
student | add 5 | 15,826 | 138 | [] |
student | so it cancelled out on one side and added 5 to the 10 | 15,826 | 139 | [] |
volunteer | yep exactly so if you wanted to move the x^2 to the other side what would you do | 15,826 | 140 | [] |
volunteer | And then what about the 5x and the 6? | 15,826 | 141 | [] |
student | minus the x^2, minus the 5x and minue the 6 | 15,826 | 142 | [] |
student | minus | 15,826 | 143 | [] |
volunteer | Correct! | 15,826 | 144 | [] |
student | woah sorry my internet cut for a moment | 15,826 | 145 | [] |
student | Let me do that on my paper real quick | 15,826 | 146 | [] |
student | wait | 15,826 | 147 | [] |
student | oh never mind I was looking at something wrong | 15,826 | 148 | [] |
student | ok so I moved that over so would I use those equations to find x? | 15,826 | 149 | [] |
volunteer | Yep you'd use the quadratic formula to find x now unless you want to factor your solution and find x that way | 15,826 | 150 | [] |
volunteer | Whichever way is easiest for you | 15,826 | 151 | [] |
student | uh how do I do that- | 15,826 | 152 | [] |
student | The formula | 15,826 | 153 | [] |
volunteer | Did you talk about that formula in class? | 15,826 | 154 | [] |
student | nope | 15,826 | 155 | [] |
volunteer | Okay then your teacher probably wants you to factor the solution and solve that way instead | 15,826 | 156 | [] |
volunteer | Do you know how to do that? | 15,826 | 157 | [] |
student | not very well | 15,826 | 158 | [] |
volunteer | okay give it your best shot and I'll help you fix it if its not right! | 15,826 | 159 | [] |
student | uhhh | 15,826 | 160 | [] |
volunteer | what would your first step be or any ideas about how to solve it? | 15,826 | 161 | [] |
student | oh wait I do have the quadratic formula | 15,826 | 162 | [] |
student | I didn't realize | 15,826 | 163 | [] |
volunteer | Okay you can use that then if you want since its just plugging numbers in | 15,826 | 164 | [] |
student | uh here's where Im confused though | 15,826 | 165 | [] |
student | This is my equation: x^2-12x-3=x^2-4x+3 | 15,826 | 166 | [] |
volunteer | wait what | 15,826 | 167 | [] |
volunteer | I thought you simplified by bringing all of the terms to one side? | 15,826 | 168 | [] |
student | I only moved the one | 15,826 | 169 | [] |
student | do I need to move the others too? | 15,826 | 170 | [] |
volunteer | Yep | 15,826 | 171 | [] |
student | oh shoot | 15,826 | 172 | [] |
student | Sorry, that's my mistake | 15,826 | 173 | [] |
volunteer | It's all good | 15,826 | 174 | [] |
student | wait how do I do that...x^2-x^2 would be 0 wouldn't it | 15,826 | 175 | [] |
volunteer | correct you'd have x^2 on one side since 2x^2 - x^2 = 1x^2 and 0 on the other side | 15,826 | 176 | [] |
student | ? | 15,826 | 177 | [] |
volunteer | I underlined it on the screenshot of your paper | 15,826 | 178 | [] |
student | oh but here's where I'm lost. I already did one which gave the equation I told you about so wouldn't it be zero or just not exist if I moved the other x^2 over | 15,826 | 179 | [] |
volunteer | What do you mean you did one? | 15,826 | 180 | [] |
volunteer | Like you already moved the x^2? | 15,826 | 181 | [] |
volunteer | Because then yes it would be zero correct | 15,826 | 182 | [] |
student | Did you see the 1,2,3 on the one paper? I can explain what I mean if you saw them | 15,826 | 183 | [] |
volunteer | Yeah I see that | 15,826 | 184 | [] |
student | ok so what I did is I took e.3 and put it into e.1 so I got the x^2-12x-3 | 15,826 | 185 | [] |
student | wait that's wrong | 15,826 | 186 | [] |
volunteer | where did equation 3 come from? | 15,826 | 187 | [] |
volunteer | Oh wait nevermind I see | 15,826 | 188 | [] |
volunteer | So I think you never added equation 2 and 3? | 15,826 | 189 | [] |
student | not together no | 15,826 | 190 | [] |
volunteer | Okay start with that | 15,826 | 191 | [] |
volunteer | I think that was the step you were missing that was throwing you off | 15,826 | 192 | [] |
student | makes sense | 15,826 | 193 | [] |
student | 2x^2+x+9 | 15,826 | 194 | [] |
volunteer | great that's right | 15,826 | 195 | [] |
volunteer | now move those terms to the other side where equation 1 is | 15,826 | 196 | [] |
volunteer | and solve for x | 15,826 | 197 | [] |
student | 0-8x-6 | 15,826 | 198 | [] |
student | wait what- | 15,826 | 199 | [] |
student | I don't think that's right.. | 15,826 | 200 | [] |
volunteer | No that's right | 15,826 | 201 | [] |
student | oh | 15,826 | 202 | [] |
volunteer | You have -8x - 6 = 0 | 15,826 | 203 | [] |
volunteer | which you can solve for x | 15,826 | 204 | [] |
volunteer | So what would x be then? | 15,826 | 205 | [] |
student | -0.75? | 15,826 | 206 | [] |
volunteer | Yes, let's go!!! | 15,826 | 207 | [] |
volunteer | Great job persevering through that one! | 15,826 | 208 | [] |
student | Almost cried twice haha but would've been worth it | 15,826 | 209 | [] |
volunteer | Proud of you! | 15,826 | 210 | [] |
student | any way we could go through at least #3? | 15,826 | 211 | [] |
volunteer | Yep, I have a little time left - about 15 more minutes. Why don't you try to work through this one using the skills we worked on in the last one and I can help you when you get stuck? | 15,826 | 212 | [] |
student | oh uh- | 15,826 | 213 | [] |
volunteer | So what was our very first step for the last problem? | 15,826 | 214 | [] |
student | common denominator | 15,826 | 215 | [] |
volunteer | Great so any ideas for the common denominator here? | 15,826 | 216 | [] |
student | um | 15,826 | 217 | [] |
volunteer | just give it your best guess | 15,826 | 218 | [] |
student | all of them are letters, I don't know- | 15,826 | 219 | [] |
volunteer | pretend they are numbers, say 3, 7, 4 | 15,826 | 220 | [] |
volunteer | what would you do then to find a common denominator? | 15,826 | 221 | [] |
student | uh I don't remember how to find thst | 15,826 | 222 | [] |
student | that | 15,826 | 223 | [] |
volunteer | okay that's find you'd just multiply the denominators together | 15,826 | 224 | [] |
volunteer | so in the case with the numbers it would 3 x 7 x 4 | 15,826 | 225 | [] |
volunteer | or in your case with the letters it would be....? | 15,826 | 226 | [] |
student | rmj? | 15,826 | 227 | [] |
volunteer | yes!! | 15,826 | 228 | [] |
volunteer | Now go one by one and fill in the numerator for each fraction with the two letters that are missing | 15,826 | 229 | [] |
volunteer | so for 1/r for example you are missing m and j right? | 15,826 | 230 | [] |
student | yes | 15,826 | 231 | [] |
volunteer | great, now do the other two yourself! | 15,826 | 232 | [] |
student | would it be rj/rmj and rm/rmj | 15,826 | 233 | [] |
volunteer | yes, exactly! | 15,826 | 234 | [] |
volunteer | and all the terms again have the same denominator so what should we do next? | 15,826 | 235 | [] |
student | factor the numerators | 15,826 | 236 | [] |
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