Datasets:
NationalTutoringObservatory
/
MathEd-PII

Dataset card Data Studio Files
xet
 Community
1
role
stringclasses
2 values
content
stringlengths
0
2.1k
session_id
int64
10
21.7k
sequence_id
int64
0
2.38k
annotations
listlengths
0
8
student
Of course!
15,914
14
[]
volunteer
Look at the 4th deck. What do you see?
15,914
15
[]
student
A polar bear equals three zebras
15,914
16
[]
volunteer
Correct. Now look at the third deck.
15,914
17
[]
volunteer
How many zebras are on the left?
15,914
18
[]
student
6
15,914
19
[]
volunteer
And if 1 bear = 3 zebras, how many bears should you have on the right-hand side?
15,914
20
[]
volunteer
My bad. We need to put seals (not bears) on the 3rd deck.
15,914
21
[]
student
No worries, I went through that too
15,914
22
[]
volunteer
OK. I'll keep solving...
15,914
23
[]
student
Okay!
15,914
24
[]
volunteer
It's a trial-and-error problem. We try different things until it's solved. If you're not in a rush, you can leave the session open, and I'll keep trying. It's an interesting problem.
15,914
25
[]
student
Yeah of course!
15,914
26
[]
student
It is very intresting
15,914
27
[]
volunteer
It's a long problem, but I think I solved it.
15,914
28
[]
volunteer
We'll use a bit of algebra.
15,914
29
[]
volunteer
Are you still there?
15,914
30
[]
student
SO sorry! My computer died for a second
15,914
31
[]
volunteer
OK. I can explain if you like.
15,914
32
[]
student
im so sorry, it died again
15,914
33
[]
volunteer
Your battery is running out?
15,914
34
[]
student
Before you do explain, can I ask a question? I think i may have a method as well
15,914
35
[]
student
Umm, not exactly. it's on my charger, but the charger just kept falling out of the outlet
15,914
36
[]
student
It should be good now!
15,914
37
[]
volunteer
OK. Ask your question.
15,914
38
[]
student
So, I think the seals may be a fraction instead of a whole number itself. In the second row, two kangaroos and four seals somehow equals two polarpears. I thought if I divided 6/2 I might get somehwere, but I'm not sure
15,914
39
[]
student
I guess that's not a question
15,914
40
[]
volunteer
Each animal has a different weight. Looking at the different decks, it would make sense that the elephant is the heaviest, correct?
15,914
41
[]
student
Yes
15,914
42
[]
volunteer
So let's give the elephant a "weight", say 24 units.
15,914
43
[]
volunteer
24 is convenient, because this number can be divided many different ways. OK so far?
15,914
44
[]
student
Okay!
15,914
45
[]
volunteer
Now look at deck 4. If one elements = 24, what is the weight of a bear?
15,914
46
[]
volunteer
... one *elephant
15,914
47
[]
student
is this where i divide?
15,914
48
[]
student
12?
15,914
49
[]
volunteer
Good. So far, we have elephant weighs "24" and bear "12".
15,914
50
[]
volunteer
I meant deck 5, by the way. Now look at deck 4. 1 bear = 3 zebras, correct?
15,914
51
[]
student
yes
15,914
52
[]
volunteer
So if the bear weighs "12", how much does a zebra weigh?
15,914
53
[]
student
4
15,914
54
[]
volunteer
Perfect. I'm writing this on the board.
15,914
55
[]
volunteer
Now we look at deck 1.
15,914
56
[]
volunteer
Let's label the animals: E = elephant, B = bear, S = seal, Z = zebra, K = kangaroo. OK so far?
15,914
57
[]
student
ok!
15,914
58
[]
volunteer
We'll write an equation for deck 1 that includes the weight of all animals on that deck.
15,914
59
[]
volunteer
How many elephants are on deck 1?
15,914
60
[]
student
1
15,914
61
[]
volunteer
I'll write this as 1E. How many bears?
15,914
62
[]
student
1
15,914
63
[]
volunteer
And one the left side, we also have 2S, correct?
15,914
64
[]
student
yes
15,914
65
[]
volunteer
Then on the right side, we have 6Z + 2K, right?
15,914
66
[]
student
yes
15,914
67
[]
volunteer
So we put 6Z+2K to the right of the equal sign. Now we plug in the known weights of the animals.
15,914
68
[]
volunteer
Now don't know S and K yet, so I write these in purple color.
15,914
69
[]
student
but we dont know the kangroos weight yet
15,914
70
[]
volunteer
Yes. That's why we leave their weights as variables (S and K in purple).
15,914
71
[]
student
ah ok
15,914
72
[]
volunteer
Now let's do the math. On the left, we have 1(24)+1(12) = ?
15,914
73
[]
student
36
15,914
74
[]
volunteer
Good. And on the right, 6(4) = ?
15,914
75
[]
student
24
15,914
76
[]
volunteer
To make things more tidy, we'll subtract 24 from both sides, then subtract 2S from both sides.
15,914
77
[]
student
wait how did you get 6(4)? thats 6 zebras and 2 kangaroos
15,914
78
[]
volunteer
Yes. 1 zebra weighs 4 units, correct?
15,914
79
[]
student
yes?
15,914
80
[]
volunteer
Look at deck 1. I'll write the weights above each animal.
15,914
81
[]
volunteer
On the right, we have 6 zebras. Each zebra weighs 4 units, so 6(4)=24 is the total weight of zebras on deck 1.
15,914
82
[]
student
but then we'd be multiplying the zebra with itself
15,914
83
[]
volunteer
I'll add a picture to explain.
15,914
84
[]
volunteer
Do you see the picture I uploaded showing deck 1?
15,914
85
[]
student
yes
15,914
86
[]
volunteer
Each elephant weighs 24. We have 1 elephant, so the total weight of elephants is 1(24), correct?
15,914
87
[]
student
yes
15,914
88
[]
student
ohhh i think i get it now
15,914
89
[]
volunteer
Next, we add the weight of one bear = 1(12).
15,914
90
[]
student
yes
15,914
91
[]
volunteer
We don't know the seal's weight, so we write it as 2S.
15,914
92
[]
volunteer
OK so far?
15,914
93
[]
student
yes!
15,914
94
[]
volunteer
After doing the math, we end up with 12 = 2K-2S as our last equation, right?
15,914
95
[]
student
after subtracting 24 from boh sides?
15,914
96
[]
volunteer
Yes, After subracting 24 from both sides, and also subtracting 2S from both sides.
15,914
97
[]
student
thats 36 + 2s = 24 + 2k -24 -24 12 + 2s = 2k
15,914
98
[]
student
where would 25 come in
15,914
99
[]
volunteer
It's not "25". It's 2*S or 2S.
15,914
100
[]
student
ohhh
15,914
101
[]
volunteer
I'll write the S more clearly.
15,914
102
[]
student
No it's fine! i wasn't looking at the board
15,914
103
[]
volunteer
There are just a couple of steps left to do.
15,914
104
[]
student
so that's 36 + 2s = 24 + 2k -24 -24 12 + 2s = 2k -2s -2s 12 = k? or 12 = 2k + s?
15,914
105
[]
student
Also, i have to use the restroom. i will return in a couple of minutes
15,914
106
[]
volunteer
OK.
15,914
107
[]
volunteer
12 + 2S = 2K is correct. Subtract 2S from both sides, we get: 12+2S-2S = 2K-2S => 12 = 2K-2S.
15,914
108
[]
student
Ah okay
15,914
109
[]
student
and i'm back!
15,914
110
[]
volunteer
Lastly, we can factor out "2" from the last equation. So divide both sides by 2.
15,914
111
[]
student
12 = 2k - 2s /2 /2 6 = k-s
15,914
112
[]
volunteer
Yes. Let's call that Equation (1)
15,914
113
[]