Datasets:
NationalTutoringObservatory
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MathEd-PII

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student
Hey!
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student
I put my first sheet on board I’m on 17 I’m doing every other odd until 71
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volunteer
You mean finding h(1) ?
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student
I just wanna make sure my process is correct
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volunteer
What do you get for h(1)?
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student
So I converted 1/2 to 0.5 and done 0.5-10=-9.5
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volunteer
yes, that's right
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student
Ok so then I’m ready to do 21
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volunteer
that involves graphing
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student
Yes
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volunteer
Did you graph it?
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student
Not yet cause I’m trying to find out where to start
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volunteer
You could start by plotting the top function. You could start by finding f(1))
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volunteer
i uploaded some graph paper
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student
Mr. Evans t do you mean like so 2x graph that?
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[ { "pii_type": "PERSON", "surrogate": "Mr. Evans", "start": 0, "end": 9 } ]
volunteer
Yes, but only for values of x that are greater than or equal to 1
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volunteer
it's a good idea to graph the endpoint, which in this case is x =1
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volunteer
That point is not in the right place
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student
What point?
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volunteer
I guess that I am not sure what you are doing.
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student
Me either😂
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student
I’m just being honest
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volunteer
what is f(1)) ?
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volunteer
not sure?
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student
2x
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volunteer
yes, that is the equation to use for x =1. So what is f(1))? do you know what I mean by writing f(1))?
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student
No I guess
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volunteer
the notation f(1)) means to plug in 1 for x. the notation f( ) means that you plug in whatever is in those parentheses ( ) in for x and that gives you the value of y
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volunteer
so in this case, where f(x) =2x, f(1)) =2*1 =2
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student
Ok
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volunteer
so then the point you would plot for that would be (1,2)
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volunteer
you plotted (2,1) not (1,2)
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volunteer
hello?
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volunteer
Hello Sarah, what do you need help with today?
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[ { "pii_type": "PERSON", "surrogate": "Sarah", "start": 6, "end": 11 } ]
student
hi
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volunteer
Do you need help with this question on the board?
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volunteer
Do you have any thought on some first step we can take here?
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student
yes
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volunteer
Is there an equation form you will like to use here? Like the slope intercept form?
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student
-4/3x+14/3
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student
y=-4/3x+14/3
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volunteer
That looks good to me!
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volunteer
Great job!
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student
ok
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volunteer
Do you need any help with this question? Feel free to try it yourself first
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student
yes
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volunteer
Is there a first step you can think of?
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student
not really
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volunteer
That's totally fine! Let's start with the problem, they gave us a graph instead of two points (like in the last problem). Is there any information we can get from the graph?
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student
the two points
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volunteer
Exactly! Can you start with writing down the two points?
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student
yes
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student
(3,4) and (-3,-5)
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student
ok
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volunteer
great job!
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volunteer
now we have two points, can you try to find an equation?
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student
yes
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volunteer
good job on calculating the slope! I do see one thing, please double check how you simplify the fraction in the last step here
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student
ok
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volunteer
How is it going so far?
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volunteer
Let me know if you have other questions! I will end the session shortly if you don't need any more help.
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student
Graphing lines on a coordinate plane
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volunteer
Hi how can I help you today?
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student
Hello
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student
Nice to meet you
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student
Hope you're doing well
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volunteer
Nice to meet you!
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student
So I wanted to understand how to graph specific lines on a coordinate plane
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student
Help me?
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volunteer
Okay sure I can help you with that
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student
Let me show a picture
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volunteer
Okay take your time
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student
See the question labelled 4?
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volunteer
yes
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student
That
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volunteer
do you have any idea about how to graph it?
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student
No
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volunteer
so does it mean if we randomly take a x value and it is corresponding a y value
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volunteer
so if we know x and y value then it means we have a point
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volunteer
so that we can draw a graph
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volunteer
is it make sense?
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student
Uh
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student
example.com/graph-image
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[ { "pii_type": "URL", "surrogate": "example.com/graph-image", "start": 0, "end": 23 } ]
student
Alex
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[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 0, "end": 4 } ]
volunteer
this equation has an x and a y right? means that for each value of x, you can calculate a corresponding y value
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student
Yeah
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volunteer
and we can plug them into the equation to find the matching y
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student
What value is for the x and y?
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volunteer
x is the independent variable that you choose, and y is the dependent variable that you calculate using the equation
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volunteer
actually x doesn’t have a single fixed value. You choose different values of x to calculate y, but usually we pick x values within the range shown on the graph
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volunteer
such as x=0 x=1 x=-2
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student
Okay
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volunteer
can you choose a x value first?
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volunteer
and we can calculate the corresponding y value
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student
Any x?
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volunteer
uhh the range of x on this graph is -6 to 6 right?
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volunteer
so we just need this range of x
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student
Yup
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volunteer
you can calculate each of them of course
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volunteer
from -6 to 6
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