Datasets:
NationalTutoringObservatory
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MathEd-PII

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 Community
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volunteer
Good! But it can be simplified further. cos(66) can be substituted in for cos(A)
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student
ok
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student
take two
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student
8.331
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volunteer
Correct! Great job.
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volunteer
Now we can solve for the measure of angle b! How do you think we would do this?
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student
not sure
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volunteer
No worries! Since we have side a and the measure of the angle opposite to it, we can use the law of sines.
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student
ok
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student
a / sin(A) = b/sin(B) = c/sin(C)
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volunteer
That's a good start! What can be substituted into that equation?
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student
8.331/sin(66deg) = 9mm/sin(B) = 5mm/sin(C)
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volunteer
Right! Let's ignore the 5mm/sin(C) for now since we are only solving for angle B right now.
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student
ok
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volunteer
How do you think we solve for angle B?
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student
80.73deg
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student
8.331/sin(66deg) = 9mm/sin(B)
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volunteer
That is correct! Angle B would be 80.73 degrees, which would be 80.7 since we are rounding.
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volunteer
What about angle C?
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student
8.331/sin(66deg) = 5mm/sin(C)
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volunteer
Great! And that gives us?
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student
33.24
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volunteer
Well done!
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volunteer
And since we already solved for side a, we finished this problem!
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volunteer
Do you have any more problems you'd like to go over?
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student
yes
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volunteer
Alright! Feel free to add it to the board.
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student
it says that they are all wrong
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volunteer
That is strange. Did you round them correctly?
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student
yes
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student
it only gives me one attempt on the practice quiz but it says I can try a similar question
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volunteer
Alright, we can do the similar question if you want.
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student
ok
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volunteer
This one is similar to the last one, we have to solve for side a first to find the other angle measures.
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volunteer
What would the equation look like to solve for side a?
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student
a = sqrt (7mm^2 + 6mm^2 - 2(7)(6) cos(72deg)
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student
7.684
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volunteer
Great job! That is correct.
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volunteer
How do you think we will find the measure of angle B?
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student
7.684/ cos(72deg) = 7mm/cos(B)
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student
60.0deg
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student
7.684/ cos(72deg) = 6mm/cos(C)
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volunteer
Correct! Well done, and now you can solve for angle c.
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student
48deg
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volunteer
Great job! This should be right, let me know if it says it's correct or not.
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student
its correct
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student
k next question if ur down
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volunteer
Alright! I can do one more question and then I have to leave in about 20 minutes.
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student
ok
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student
its similar to the last two
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volunteer
Okay. Which of the three do you think we should solve for first?
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student
a
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volunteer
Actually, we can't solve for side a first because the measure of the angle opposite to it is not given.
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student
oh
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volunteer
This also means we can't solve for angle A since it has the same problem, the measure of the opposite side is not given. The only thing we can solve for now is angle C.
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student
ok
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student
how will we do that
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volunteer
The measure of the side opposite to angle C is given. Another pair of an opposite side and opposite angle is also given. This means we can use the law of sines.
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student
ok
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student
18/sin(44deg) = 13/sin(C)?
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volunteer
Yes, that's right!
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student
ok
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student
30.11 deg
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student
is that right
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volunteer
Yes, that's correct! We can round this to 30.1 degrees.
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volunteer
Now, what do you think we can solve for next? Angle A or side a?
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student
a?
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volunteer
Not quite. If we have the measures of two other angles, we can find the third one (A). Do you know how we can do this?
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student
no
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volunteer
That's okay! The Angle Sum theorem states that all angles of a triangle add up 180 degrees. Using this theorem, how can we solve for angle A?
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student
A+B+c= 180deg Which means A + 44deg + 30.1deg = 180 deg
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volunteer
That's right! So what would the measure of angle A be?
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student
105.9
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student
but that sounds like too big of an angle
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volunteer
105.9 degrees is correct!
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student
ok
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volunteer
Now all that's left is to solve for side a!
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volunteer
How do you want to approach this? There are multiple different ways.
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student
any is fine
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volunteer
Alright! What do you think one of the ways we can do this is?
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student
idk
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volunteer
One way we can solve it is by using the law of sines.
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volunteer
Do you know what the equation would be to set it up?
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student
a / sin(105.9) = 18/sin(44deg)
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volunteer
Right! And what does this get us?
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student
24.918
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student
is that correct
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volunteer
Yes, that looks correct!
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student
ok
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student
awesome!!! thank u for ur help today
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volunteer
No problem! I'm going to end the session now, have a nice day!
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volunteer
Hello How are you?
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student
hi I'm good and u?
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volunteer
I am fine ynx. How can I help?
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student
may you please help me with my homework
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volunteer
OK Shall we start with what is on the board?
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student
the question
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volunteer
Yes OK
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volunteer
Can u tell me what "domain" menas for a function?
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student
x values
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