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student
ok
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student
makes sense
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volunteer
I hope I'm not confusing you more than helping.
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student
no this helps
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volunteer
Ok. Good.
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volunteer
Now we are ready to set up our integral.
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volunteer
Since y^2 is now the area of a representative triangle, We can integrate it with respect to x.
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volunteer
First would you solve for y^2 from the original ellipse equation, please?
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student
this?
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volunteer
I think y^2 = 25 - x^2, if you go back to the original equation for the ellipse.
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volunteer
I'm sorry. YOu are right!!!
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student
ok
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volunteer
Now let's think of the limits for our integral\
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volunteer
Recall that the x-axis runs from -2 to 2.
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student
ok why is that?
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volunteer
When we standardized the ellipse equation, we got x^2/2^2 = Y^2/25 = 1
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student
ok got it
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volunteer
That means the left most point on the ellipse is at -2 and the right most point is 2. Do you see that?
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volunteer
Great
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volunteer
Let's write down our integral with limits.
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student
ok
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volunteer
You've got most of it right there.
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student
ok got it
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student
let me paste in my answer
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student
i 200/3
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volunteer
Let me calculate for a minute
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student
ok
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volunteer
You got it!
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volunteer
That is correct.
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student
yay!
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student
i have one more and it seems easier than these
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student
if that's okay
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volunteer
OK
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volunteer
Let me read for a few
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volunteer
Ok. Have any thoughts?
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volunteer
Great start
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student
im stuck
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volunteer
Too complicated
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volunteer
Let's think about the representative squares.
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student
ok
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volunteer
Write me an equation for the line that connects the x and y axis.
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volunteer
please
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student
y=-x+5
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volunteer
Super!
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volunteer
Now. Isn't true that y represents the side of the square we want?
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volunteer
length
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student
yes
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volunteer
So, isn't it true that the area of a representative square is simply y^2 = (5 - x)^2
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student
so a(x)=(-x+5)^2?
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volunteer
Indeed!
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volunteer
What are my limits for x?
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student
0 to 5
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volunteer
Fantastic!!!!
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volunteer
Crank it out my friend!
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student
i got this :))
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volunteer
Yes you do!!! Great job. :)
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student
thanks so much for explaining all of this with me :DD
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student
This was my last question so I shall take a break now
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volunteer
YOu are quite welcome and very deserving
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student
have a nice rest of your day :))
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volunteer
Bye
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student
Hello! I need help with this.
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volunteer
Hi Alex!
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[ { "pii_type": "PERSON", "surrogate": "Alex", "start": 3, "end": 7 } ]
student
Hi!
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student
I solved this a little but idk if this is correct
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student
Or if this is the correc way to solve
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student
for the 9%
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volunteer
Because we are given the total interest, I think that we should combine the two accounts into one equation
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student
Oh it says "each"
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student
So I thought seperate
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volunteer
That is a good point, but we want to solve the combined equation first and then we will get both parts
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student
Ok how would I do that then
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volunteer
Let's start with the 9% account: We know that the 1 year interest will just be 0.09 times the amount invested
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volunteer
What should we use instead of x for the 10% account
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student
0.1
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student
oh
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student
ummm
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student
b?
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volunteer
Keep in mind that x and this must add to 15000
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student
ok
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volunteer
we can actually use 15000 - x, because 15000 - x + x = 15000
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volunteer
That way, we simplify the problem into only one variable
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volunteer
And finally, what does this equation equal?
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student
1432
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volunteer
perfect
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volunteer
How should we solve this equation?
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student
distribute
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volunteer
That is actually 1500 because we distribute the 0.1 to the 15000 as well
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student
o
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volunteer
And that should equal because 1500-1432 is 68
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volunteer
Nice job!
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volunteer
So that is the amount invested in the 9% account. How should we find the amount for the 10% account?
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student
yep
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student
would we add that number into x?
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volunteer
6800 is our x. There is something that we can do with substitution here
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student
hmmm
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student
oh
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student
put it in the parenthesis?
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student
6800-x?
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volunteer
So close! We do use the 15000 - x. However, 6800 is our x value. So, the amount invested in the 10% account is 15000 - 6800
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