role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
student | Ohh I see | 17,853 | 39 | [] |
student | 8200 | 17,853 | 40 | [] |
volunteer | Yes! 6800 was invested in the first account, 8200 was invested in the second account | 17,853 | 41 | [] |
student | yep! | 17,853 | 42 | [] |
student | I have another one that looks confusing | 17,853 | 43 | [] |
student | like i dont get it | 17,853 | 44 | [] |
volunteer | I think we will be able to do it :) | 17,853 | 45 | [] |
student | it says "find the union or intersection of the given intervals. Write the answers in interval notation." | 17,853 | 46 | [] |
volunteer | Ok! I always like to use a number line for tricky interval problems | 17,853 | 47 | [] |
student | ok | 17,853 | 48 | [] |
volunteer | Could you draw the first interval on the number line for me? | 17,853 | 49 | [] |
student | -5 and 3? | 17,853 | 50 | [] |
student | oh nvm its not negative | 17,853 | 51 | [] |
student | they are already on the line | 17,853 | 52 | [] |
student | 5 and 3 | 17,853 | 53 | [] |
volunteer | I will show you what I mean | 17,853 | 54 | [] |
student | this? | 17,853 | 55 | [] |
volunteer | Just so we can see the interval | 17,853 | 56 | [] |
student | ok | 17,853 | 57 | [] |
volunteer | Now, it is a lot easier to see where these two intervals intersect! | 17,853 | 58 | [] |
student | why is one open and one closed like the circle | 17,853 | 59 | [] |
volunteer | We have an open circle at the 5 because, if you look at the interval, there is a parenthesis as a bracket. This means that the number 5 itself is not included in the interval | 17,853 | 60 | [] |
student | Ohh ok | 17,853 | 61 | [] |
volunteer | There is a closed circle at 3 because of the "hard" bracket in the interval in the question. This means that 3 is included | 17,853 | 62 | [] |
student | let me write this on my paper | 17,853 | 63 | [] |
student | so 3 is closed 5 is open | 17,853 | 64 | [] |
volunteer | Yes | 17,853 | 65 | [] |
student | ok | 17,853 | 66 | [] |
student | oh bc 3 has bracket and 5 has parenthesis ok gotcha | 17,853 | 67 | [] |
volunteer | Right | 17,853 | 68 | [] |
student | ok now what do we do next | 17,853 | 69 | [] |
volunteer | Now that we have the intervals lined up on the number line, we just need to find where they overlap | 17,853 | 70 | [] |
student | at 3 | 17,853 | 71 | [] |
volunteer | Yes. And where does the overlap end? | 17,853 | 72 | [] |
student | it ends at 5? | 17,853 | 73 | [] |
volunteer | Exactly. Is 5 included in the overlap? | 17,853 | 74 | [] |
student | Yes | 17,853 | 75 | [] |
volunteer | It actually isn't because of the open circle on the first interval | 17,853 | 76 | [] |
student | oh so 5 starts it off | 17,853 | 77 | [] |
student | gotcha | 17,853 | 78 | [] |
student | oh nvm | 17,853 | 79 | [] |
student | no | 17,853 | 80 | [] |
student | 5 is overlapping 3 | 17,853 | 81 | [] |
volunteer | The overlap goes from 3 to 5, but 5 is not included | 17,853 | 82 | [] |
student | oh | 17,853 | 83 | [] |
student | why | 17,853 | 84 | [] |
volunteer | As you drew on the line, the overlap only happens where the two intervals are on top of each other. We know that 3 is included, and that the numbers between 3 and 5 are included. | 17,853 | 85 | [] |
volunteer | However, 5 is not included because, while the second interval includes it, the first one does not (because of the open circle). To be in the overlap, both intervals have to include 5 which the first one doesn't | 17,853 | 86 | [] |
student | Ok I see | 17,853 | 87 | [] |
student | so the overlap ends at 5 because that’s where the two intervals stop overlapping? | 17,853 | 88 | [] |
student | this is why 5 is not included? | 17,853 | 89 | [] |
volunteer | For it to be overlapping, both intervals have to include a point. They don't overlap at 5 because of the open circle (the first interval doesn't include 5) | 17,853 | 90 | [] |
student | yeah so 3 starts it and it ends at 5? | 17,853 | 91 | [] |
volunteer | Yes, and 3 is included and 5 is not | 17,853 | 92 | [] |
student | yep got it | 17,853 | 93 | [] |
student | so it should be written as [3,5) | 17,853 | 94 | [] |
student | ? | 17,853 | 95 | [] |
volunteer | This is actually problem 87b* | 17,853 | 96 | [] |
volunteer | Exactlu! | 17,853 | 97 | [] |
student | i thought we were doing the first one | 17,853 | 98 | [] |
student | bc im writing this on paper in order to turn in | 17,853 | 99 | [] |
student | let me just erase it rq | 17,853 | 100 | [] |
volunteer | I missed a detail with the symbols they gave (union vs intersection | 17,853 | 101 | [] |
volunteer | The problems aren't very different, so you can keep the two interval lines on the number line | 17,853 | 102 | [] |
volunteer | Sorry about that! | 17,853 | 103 | [] |
student | its ok i fixed it | 17,853 | 104 | [] |
student | what does the upside down U mean | 17,853 | 105 | [] |
volunteer | That means the intersection between the two intervals, which is the problem that we did | 17,853 | 106 | [] |
student | Ok | 17,853 | 107 | [] |
student | now for A | 17,853 | 108 | [] |
volunteer | Problem a wants the union between the two intervals | 17,853 | 109 | [] |
student | ok | 17,853 | 110 | [] |
student | lets start | 17,853 | 111 | [] |
volunteer | What do you think we should do to find the union between the two intervals? | 17,853 | 112 | [] |
student | draw the lines again? | 17,853 | 113 | [] |
volunteer | Yep. Now the union means that we essentially combine the two intervals into one. | 17,853 | 114 | [] |
volunteer | We use the word "or" to describe unions, and "and" to describe intersection | 17,853 | 115 | [] |
volunteer | So the answer will be the interval of all points contained in either interval | 17,853 | 116 | [] |
student | ok | 17,853 | 117 | [] |
student | would it be 3,5 again or? | 17,853 | 118 | [] |
student | ? | 17,853 | 119 | [] |
volunteer | Here, we can use the number line and want to find points that are not included in either interval. | 17,853 | 120 | [] |
volunteer | Are there any points that aren't in either interval? | 17,853 | 121 | [] |
student | uhhh 12 | 17,853 | 122 | [] |
student | 67 | 17,853 | 123 | [] |
student | 1,2,6,7 | 17,853 | 124 | [] |
student | 4 is included | 17,853 | 125 | [] |
volunteer | That would be correct for intersection. For union, we want to find points that aren't in EITHER. For example, 1 and 2 are included in the first interval. So, they are fine | 17,853 | 126 | [] |
student | let me redraw my line | 17,853 | 127 | [] |
student | a lot of numbers are included | 17,853 | 128 | [] |
volunteer | Yes. Are there any numbers not included? | 17,853 | 129 | [] |
volunteer | Let's try putting the intervals together to visualize this scenario better | 17,853 | 130 | [] |
student | ok | 17,853 | 131 | [] |
student | its like 1-10 are included | 17,853 | 132 | [] |
volunteer | Actually, everything is included from -infinity to infinity. | 17,853 | 133 | [] |
volunteer | The combined line never ends. The only interesting point is 5 because of the open circle. However, we only need one interval to include 5, which the second one does | 17,853 | 134 | [] |
student | ohh yeah | 17,853 | 135 | [] |
volunteer | I am glad that makes sense! Union is a very difficult concept to understand. Nice job with it! | 17,853 | 136 | [] |
student | Wait so | 17,853 | 137 | [] |
student | I'm still confused bc idk what the answer is like | 17,853 | 138 | [] |
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