Split (1)

train · 116k rows

role stringclasses 2 values	content stringlengths 0 2.1k	session_id int64 10 21.7k	sequence_id int64 0 2.38k	annotations listlengths 0 8
volunteer	oops.	12,175	321	[]
student	I will do it, where is the formula, or X-rays to the plow up the minus	12,175	322	[]
student	X. 820.	12,175	323	[]
student	So then maybe help	12,175	324	[]
volunteer	Yeah. Yeah, that's right. That's correct.	12,175	325	[]
student	based from this like, since we already have the formulas at the zeros, what we can do with the, this uh formula is that we can make it into the quadratic formula.	12,175	326	[]
student	We can, we can quadratic, we can make the formula to sign.	12,175	327	[]
student	Yeah	12,175	328	[]
volunteer	Well, first thing you need to do is take a derivative of it, right? You're trying to, if you, we know the zeros of the graph, we know it	12,175	329	[]
volunteer	Now we, if you want to find	12,175	330	[]
volunteer	you know, the maxes and men's are gonna happen right between them.	12,175	331	[]
volunteer	But	12,175	332	[]
volunteer	how do you take	12,175	333	[]
volunteer	I think your paper up here said	12,175	334	[]
volunteer	yeah	12,175	335	[]
student	first therariation, the the variation. Oh my gosh.	12,175	336	[]
volunteer	Yeah, so you take a derivative.	12,175	337	[]
student	The thing was, I remembered our our teacher submitting like uh, like from a shared like classroom from another like uh from another class that had APA. They had this, they had this thing like the shared like like uh like what do you mean 3rd grading recorded, uh, for this	12,175	338	[]
student	but then I can't find, I can't find the file that had	12,175	339	[]
student	had had this, wait, uh, let me find the dress.	12,175	340	[]
volunteer	Does this notation, let me ask you this, do you know what this notation means for derivative.	12,175	341	[]
student	find the	12,175	342	[]
volunteer	So if I go, I want you to take the derivative, right?	12,175	343	[]
student	Yes	12,175	344	[]
volunteer	Do you know how to take the derivative of this function.	12,175	345	[]
student	uh, I, I, I know it cause I seen my teacher done it, but I'm not that confident doing it in school.	12,175	346	[]
volunteer	OK, I'll, I'll show you. It's called the Power rule, right?	12,175	347	[]
student	one the probably	12,175	348	[]
volunteer	So I basically	12,175	349	[]
volunteer	I take the, I take whatever so I take	12,175	350	[]
volunteer	the power roll says I take whatever power is. I multiply it out front and I reduce this. So this becomes	12,175	351	[]
volunteer	3	12,175	352	[]
volunteer	times 4	12,175	353	[]
volunteer	X	12,175	354	[]
volunteer	2	12,175	355	[]
student	OK	12,175	356	[]
volunteer	OK	12,175	357	[]
student	yeah	12,175	358	[]
volunteer	So, you know, the power role.	12,175	359	[]
volunteer	Power roll is the following. If F of X	12,175	360	[]
volunteer	this is really the only, there's a lot of diff F ofvax.	12,175	361	[]
student	Yeah	12,175	362	[]
volunteer	You do you know what F of X is? Like a functional notation. Are you comfortable? OK.	12,175	363	[]
student	Yeah.	12,175	364	[]
volunteer	If uh if E of X equals X.	12,175	365	[]
volunteer	to the N	12,175	366	[]
volunteer	right	12,175	367	[]
volunteer	F	12,175	368	[]
volunteer	X	12,175	369	[]
volunteer	E	12,175	370	[]
student	Oh, wait. Oh, this is like what I	12,175	371	[]
student	um	12,175	372	[]
volunteer	F of X equals N	12,175	373	[]
volunteer	right? The N comes down	12,175	374	[]
volunteer	times X	12,175	375	[]
student	you know	12,175	376	[]
volunteer	times N	12,175	377	[]
volunteer	minus 1.	12,175	378	[]
volunteer	So that's what I did over here, right? I took the 3	12,175	379	[]
student	Oh	12,175	380	[]
volunteer	put it out front, but I have to multiply it by the 4, then I took X^2, right? So that's gonna be.	12,175	381	[]
student	Oh	12,175	382	[]
volunteer	so this is gonna be equal to 12.	12,175	383	[]
volunteer	x	12,175	384	[]
student	Oh, well X^2.	12,175	385	[]
student	Oh.	12,175	386	[]
volunteer	2. OK. So what's the next um what's the next factor?	12,175	387	[]
student	54 x 2. So it's uh from what I've understand negative. We, my nose, we have	12,175	388	[]
student	2	12,175	389	[]
student	times 54 and 2 minus 1 is 1, so it's just two times 54 and	12,175	390	[]
student	2 times 54 X.	12,175	391	[]
student	Am I correct	12,175	392	[]
volunteer	Not, yeah, yeah, yep, so that's gonna be minus	12,175	393	[]
student	100 and	12,175	394	[]
volunteer	108	12,175	395	[]
student	And then 182.	12,175	396	[]
volunteer	OK, what's, uh, what, what happens to X?	12,175	397	[]
student	X becomes a 1 because it it was a minus.	12,175	398	[]
volunteer	No, it goes from x, it goes to X to the 1, right? Because	12,175	399	[]
student	Yeah	12,175	400	[]
student	it was suggested	12,175	401	[]
volunteer	next to the one goes to.	12,175	402	[]
student	Yeah	12,175	403	[]
volunteer	no X^2 becomes X, right? 2 becomes 2 minus 1, so this should be X, right?	12,175	404	[]
student	Oh yeah, I forgot. 108, I, I forgot, but I did follow the rule now X becomes one.	12,175	405	[]
student	one	12,175	406	[]
volunteer	OK, how about do do this next factor. What 182X become?	12,175	407	[]
student	Um	12,175	408	[]
student	wait	12,175	409	[]
student	OK about it. There's nothing really much to wait, I mean.	12,175	410	[]
student	think	12,175	411	[]
student	It just becomes one.	12,175	412	[]
student	and 182	12,175	413	[]
student	then X-ray 1 minus 1 to 0. So it's just 182	12,175	414	[]
volunteer	Yeah, what's what's X to the 0 equal to?	12,175	415	[]
student	uh	12,175	416	[]
student	X-rays the part of 0.	12,175	417	[]
volunteer	Yeah	12,175	418	[]
student	is basically, wait, let me think. It's just 0, so it's just cancel.	12,175	419	[]
volunteer	No	12,175	420	[]

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