prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
//Check if two words have the same characters.
// >>> same_chars("eabcdzzzz", "dddzzzzzzzddeddabc")
// true
// >>> same_chars("abcd", "dddddddabc")
// true
// >>> same_chars("dddddddabc", "abcd")
// true
// >>> same_chars("eabcd", "dddddddabc")
// false
// >>> same_chars("abcd", "dddddddabce")
// false
// >>> same_char... | let res = true; | for(let i = 0; i < s0.length; i++){
if(s1.indexOf(s0[i]) === -1){
res = false;
break;
}
}
for(let i = 0; i < s1.length; i++){
if(s0.indexOf(s1[i]) === -1){
res = false;
break;
}
}
return res;
}
|
//Create a function that returns an array (a, b), where 'a' is
// the largest of negative integers, and 'b' is the smallest
// of positive integers in an array.
// If there is no negative or positive integers, return them as undefined.
// Examples:
// >>> largest_smallest_integers([2, 4, 1, 3, 5, 7])
// [undefined, 1]
... | return[lst.filter(x=>x<0).sort((a,b)=>b-a)[0],lst.filter(x=>x>0).sort((a,b)=>a-b)[0]] | }
|
//Create a function that takes integers, floats, or strings representing
// real numbers, and returns the larger variable in its given variable type.
// Return undefined if the values are equal.
// Note: If a real number is represented as a string, the floating point might be . or ,
// >>> compare_one(1, 2.5)
// 2.5
//... | return a; | } else if (a[0] < b){
return b;
} else {
return undefined;
}
}
else if (typeof a === "number" && typeof b === "string"){
if (a > b[0]){
return a;
} else if (a < b[0]){
return b;
} else {
return undefined;
}
}
}
|
//Write a function that accepts an array of strings as a parameter,
// deletes the strings that have odd lengths from it,
// and returns the resulted array with a sorted order,
// The array is always an array of strings and never an array of numbers,
// and it may contain duplicates.
// The order of the array should be... | return -1; | }
else if(a.length > b.length){
return 1;
}
else{
if(a < b){
return -1;
}
else if(a > b){
return 1;
}
else{
return 0;
}
}
});
}
var a = ["aa", "... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
// >>> fizzBuzz((50l))
... | for (int j = 0; j < s.length(); j++) { | if (s.charAt(j) == '7') {
res++;
}
}
}
}
return res;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of strings, where each string consists of only digits, return an array array list.
// Each element i of t... | if (Integer.parseInt(lst.get(i).substring(j, j + 1)) % 2 == 1) { | count++;
}
}
res.add("the number of odd elements " + count + "n the str" + count + "ng " + count + " of the " + count + "nput.");
}
return res;
}
} |
//The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
// fibfib(0) == 0
// fibfib(1) == 0
// fibfib(2) == 1
// fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
// Please write a function to efficiently compute the n-th element of the fibfib number sequence.
// >>>... | if(n == 1){ | return 0;
}
if(n == 2){
return 1;
}
return fibfib(n-1) + fibfib(n-2) + fibfib(n-3);
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// brackets is a string of "<" and ">".
// return true if every opening bracket has a corresponding closing bracket.
// >>> correc... | if (open < 0) { | return false;
}
}
return open == 0;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of strings, where each string consists of only digits, return an array array list.
// Each element i of t... | res.add("the number of odd elements " + count + "n the str" + count + "ng " + count + " of the " + count + "nput."); | }
return res;
}
} |
from typing import List
def sort_third(l: List[int]) -> List[int]:
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding ... | j -= 3 | return l
|
from typing import Dict
def histogram(test: str) -> Dict[str, int]:
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
... | result = {} | for letter in test.split():
letters[letter] = letters.get(letter, 0) + 1
if letters[letter] >= most_count:
most_count = letters[letter]
for letter in letters:
if letters[letter] == most_count:
result[letter] = most_count
return result
|
//You are given an array of two strings, both strings consist of open
// parentheses '(' or close parentheses ')' only.
// Your job is to check if it is possible to concatenate the two strings in
// some order, that the resulting string will be good.
// A string S is considered to be good if and only if all parentheses... | return 'Yes'; | }
return 'No';
} |
from typing import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
| numbers.sort() | numbers = [i for i in numbers if numbers.count(i) == 1]
return numbers
|
//You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as it is.
// If the string contains no letters, reverse the string.
// The function should return the resulted string.
// Examples
// >>> solve("1234")
// "4321"
// >>> solve("ab")
// "AB"
// >>... | ? char.toUpperCase() | : char.toLowerCase();
}
return char;
});
return swapped.join('');
}
return s.split('').reverse().join('');
}
|
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
// numbers in the array will be randomly ordered. Your task is to determine if
// it is possible to get an array sorted in non-decreasing order by performing
// the following operation on the given array:
// You are allowed to perform right shift o... | } | if(diff_count > 1){
return false;
}
else{
return true;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupit... | ArrayList<String> planetsInBetween = new ArrayList<String>(); | for (int i = indexMin + 1; i < indexMax; i++) {
planetsInBetween.add(planets.get(i));
}
return planetsInBetween;
} else {
return new ArrayList<String>();
}
}
} |
from typing import List
def minSubArraySum(nums: List[int]) -> int:
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
>>> minSubArraySum([2, 3, 4, 1, 2, 4])
1
>>> minSubArraySum([-1, -2, -3])
-6
"""
for i in range(1, len(nums))... | return min(nums) | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupit... | int indexPlanet1 = planets.indexOf(planet1); | int indexPlanet2 = planets.indexOf(planet2);
int indexMin = 0;
int indexMax = 0;
if (indexPlanet1 >= 0 && indexPlanet2 >= 0) {
if (indexPlanet1 < indexPlanet2) {
indexMin = indexPlanet1;
indexMax = indexPlanet2;
} else {
... |
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | while(res < n){ | if(isPrime(fib(fibNum))){
res++;
}
fibNum++;
}
return fib(fibNum - 1);
} |
//You are given a positive integer n. You have to create an integer array a of length n.
// For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
// Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
// and a[i] + a[j] + a[k] is a multiple of 3.
// Example :
// >>> get_max_triples(5)
// 1
// Ex... | let result = 0; | let arr = [];
for(let i = 1; i<=n; i++){
arr.push(i*i-i+1);
}
for(let i = 0; i<arr.length; i++){
for(let j = i+1; j<arr.length; j++){
for(let k = j+1; k<arr.length; k++){
if((arr[i]+arr[j]+arr[k])%3 === 0){
result++;
}
... |
//Write a function that accepts an array of strings.
// The array contains different words. Return the word with maximum number
// of unique characters. If multiple strings have maximum number of unique
// characters, return the one which comes first in lexicographical order.
// >>> find_max(["name", "of", "string"])
/... | max_unique = unique_word; | }
else if(Object.keys(unique_word).length > Object.keys(max_unique).length){
max_unique_word = word;
max_unique = unique_word;
}
else if(Object.keys(unique_word).length === Object.keys(max_unique).length){
if(word < max_unique_word){
ma... |
//Write a function that takes a string and returns true if the string
// length is a prime number or false otherwise
// Examples
// >>> prime_length("Hello")
// true
// >>> prime_length("abcdcba")
// true
// >>> prime_length("kittens")
// true
// >>> prime_length("orange")
// false
function prime_length(string){
le... | let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199]; | if (primes.includes(length)){
return true;
} else {
return false;
}
} |
def get_closest_vowel(word: str) -> str:
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the a... | return '' | |
//There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
// Uranus, Neptune.
// Write a function that takes two planet names as strings planet1 and planet2.
// The function should return an array containing all planets whose orbit... | 'Mars':4, | 'Jupiter':5,
'Saturn':6,
'Uranus':7,
'Neptune':8
}
if(!planets[planet1] || !planets[planet2]){
return [];
}
var keys = Object.keys(planets);
var position1 = keys.indexOf(planet1);
var position2 = keys.indexOf(planet2);
if(position1 > position2){
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of numbers, return whether or not they are sorted
// in ascending order. If array list has more than 1 du... | boolean seen_2_in_a_row = false; | for (Long number : lst) {
if (first_time) {
first_time = false;
previous_number = number.intValue();
running_max = number.intValue();
}
else {
if (running_max > number.intValue()) ... |
//Your task is to implement a function that will simplify the expression
// x * n. The function returns true if x * n evaluates to a whole number and false
// otherwise. Both x and n, are string representation of a fraction, and have the following format,
// <numerator>/<denominator> where both numerator and denominato... | let xDenominator = parseInt(x.split('/')[1]); | let nNumerator = parseInt(n.split('/')[0]);
let nDenominator = parseInt(n.split('/')[1]);
let xTimesN = xNumerator * nNumerator / (xDenominator * nDenominator);
return Number.isInteger(xTimesN);
}
|
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> is_equal_to_sum_even(4)
// false
// >>> is_equal_to_sum_even(6)
// false
// >>> is_equal_to_sum_even(8)
// true
function is_equal_to_sum_even(n){
let m =0; | for(let i=2;i<n;i+=2){ | for(let j=2;j<n;j+=2){
for(let k=2;k<n;k+=2){
for(let l=2;l<n;l+=2){
if((i+j+k+l)==n){
m=1;
break;
}
}
}
}
}
if(m==1){
return true;
}
el... |
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([1... | temp, temp2 = abs(numbers[0] - numbers[1]), abs(numbers[0] - numbers[1]) | temp_index, temp2_index = 0, 1
if numbers[0] > numbers[1]:
temp, temp2 = temp2, temp
temp_index, temp2_index = temp2_index, temp_index
for i in range(len(numbers)):
for j in range(i+1, len(numbers)):
if abs(numbers[i] - numbers[j]) < temp:
temp = abs(numbe... |
def get_max_triples(n: int) -> int:
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multipl... | return count | |
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | if(lst2[num2] % 2 == 0){ | lst1[num1] = lst2[num2];
exchange = true;
}
num2++;
}
}
}
num1++;
}
if(exchange){
return "YES";
}else{
return "NO";
}
}
|
//Given an array of numbers, return whether or not they are sorted
// in ascending order. If array has more than 1 duplicate of the same
// number, return false. Assume no negative numbers and only integers.
// Examples
// >>> is_sorted([5])
// true
// >>> is_sorted([1, 2, 3, 4, 5])
// true
// >>> is_sorted([1, 3, 2, 4... | } else if (x == last){ | if (dupe_found){
return false;
} else {
dupe_found = true;
}
} else {
last = x;
dupe_found = false;
}
}
return true;
}
|
//You are given an array of integers.
// Write a function next_smallest() that returns the 2nd smallest element of the array.
// Return undefined if there is no such element.
// >>> next_smallest([1, 2, 3, 4, 5])
// 2
// >>> next_smallest([5, 1, 4, 3, 2])
// 2
// >>> next_smallest([])
// undefined
// >>> next_smallest(... | return undefined; | }
return second_smallest;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You have to write a function which validates a given date string and
// returns true if the date is valid otherwise false.
// T... | } catch (Exception e) { | valid_date = false;
}
return valid_date;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive floating point number, it can be decomposed into
// and integer part (largest integer smaller than given number) a... | } | } |
//Task
// We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
// then check if the result string is palindrome.
// A string is called palindrome if it reads the same backward as forward.
// You should return an array containing the result string and true/fa... | const filterString = filter.join(''); | const filterStringReverse = filter.reverse().join('');
const result = [];
if (filterString === filterStringReverse) {
result.push(filterString, true);
} else {
result.push(filterString, false);
}
return result;
} |
//Write a function that accepts an array of strings as a parameter,
// deletes the strings that have odd lengths from it,
// and returns the resulted array with a sorted order,
// The array is always an array of strings and never an array of numbers,
// and it may contain duplicates.
// The order of the array should be... | for(var i = 0; i < lst.length; i++){ | if(lst[i].length % 2 == 0){
result.push(lst[i]);
}
}
return result.sort(function(a, b){
if(a.length < b.length){
return -1;
}
else if(a.length > b.length){
return 1;
}
else{
if(a < b){
return ... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the odd indicies,... | if (index % 2 == 0) { | res.add(evenIndexed.get(0));
evenIndexed.remove(0);
} else {
res.add(num);
}
index++;
}
return res;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string representing musical notes in a special ASCII format.
// Your task is to parse this string and r... | i += 1; | } else {
res.add((long)4l);
}
} else if (chars[i] == '.') {
if (i + 1 < chars.length && chars[i + 1] == '|') {
res.add((long)1l);
i += 1;
}
}
}
return res;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a non-empty array list of integers, return the sum of all of the odd elements that are in even positions.
// Examples
// ... | long sum = 0; | for (int i = 0; i < lst.size(); i++) {
if (i % 2 == 0 && lst.get(i) % 2 == 1) {
sum += lst.get(i);
}
}
return sum;
}
} |
from typing import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:
""" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
Empty sum should be equal to 0 and empty product should be equal to 1.
>>> sum_product([])
(0, 1)
... | sum = 0 | product = 1
for i in numbers:
sum += i
product *= i
return (sum, product)
|
//Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <= num <= 1000
// Examples:
// >>> int_to_mini_roman(19)
// "xix"
// >>> int_to_mini_roman(152)
// "clii"
// >>> int_to_mini_roman(426)
// "cdxxvi"
function int_to_mini_roman(number){
var r... | 1000: "m", | 900: "cm",
500: "d",
400: "cd",
100: "c",
90: "xc",
50: "l",
40: "xl",
10: "x",
9: "ix",
5: "v",
4: "iv",
1: "i"
};
var output = "";
while (number > 0){
var key_list = Object.keys(roman_conversion).map(Nu... |
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | } | answer = operand[0];
operand.splice(0, 1);
while(operand.length > 0){
switch(operator[0]){
case '+':
answer += operand[0];
break;
case '-':
answer -= operand[0];
break;
}
operand.splice(0, 1);
operator.splice(0, 1);
}
return answer;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that returns true if the given number is the multiplication of 3 prime numbers
// and false otherwise.
// Know... | arr.add(a); | }
return arr.size() == 3;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the odd indicies,... | res.add(evenIndexed.get(0)); | evenIndexed.remove(0);
} else {
res.add(num);
}
index++;
}
return res;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the indicies that... | l_s.add(l_r.get(i - j)); | }
}
return l_s;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Your task is to implement a function that will simplify the expression
// x * n. The function returns true if x * n evaluates to a ... | int x_num = Integer.parseInt(nums[0]); | int n_num = Integer.parseInt(n_nums[0]);
int x_denom = Integer.parseInt(nums[1]);
int n_denom = Integer.parseInt(n_nums[1]);
int res_num = x_num * n_num;
int res_denom = x_denom * n_denom;
return (res_num % res_denom == 0);
}
} |
from typing import List
def specialFilter(nums: List[int]) -> int:
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
>>> specialFilte... | count = 0 | for num in nums:
if num < 10:
continue
else:
rev = int(str(num)[::-1])
if num % 2 != 0 and rev % 2 != 0:
count += 1
return count
|
from typing import List
def make_a_pile(n: int) -> List[int]:
"""
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
... | pile = [n] | for i in range(1, n):
pile.append(pile[i-1] + 2)
return pile
|
//Write a function that accepts an array of strings.
// The array contains different words. Return the word with maximum number
// of unique characters. If multiple strings have maximum number of unique
// characters, return the one which comes first in lexicographical order.
// >>> find_max(["name", "of", "string"])
/... | max_unique_word = word; | max_unique = unique_word;
}
else if(Object.keys(unique_word).length > Object.keys(max_unique).length){
max_unique_word = word;
max_unique = unique_word;
}
else if(Object.keys(unique_word).length === Object.keys(max_unique).length){
if(word ... |
//Given an array of positive integers x. return a sorted array of all
// elements that hasn't any even digit.
// Note: Returned array should be sorted in increasing order.
// For example:
// >>> unique_digits([15, 33, 1422, 1])
// [1, 15, 33]
// >>> unique_digits([152, 323, 1422, 10])
// []
function unique_digits(x){
... | if(num.indexOf('2') === -1 && num.indexOf('4') === -1 && num.indexOf('6') === -1 && num.indexOf('8') === -1 && num.indexOf('0') === -1){ | result.push(x[i])
}
}
return result.sort(function(a, b){return a-b})
}
|
//Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
// Return the string with numbers sorted from smallest to largest
// >>> sort_numbers("three one five")
// "one three five"
function sort_number... | "zero": 0, | "one": 1,
"two": 2,
"three": 3,
"four": 4,
"five": 5,
"six": 6,
"seven": 7,
"eight": 8,
"nine": 9
};
numString.sort(function(a, b){
return numMap[a] - numMap[b];
});
numString = numString.join(" ");
return numString;
} |
//Given an array arr of integers, find the minimum number of elements that
// need to be changed to make the array palindromic. A palindromic array is an array that
// is read the same backwards and forwards. In one change, you can change one element to any other element.
// For example:
// >>> smallest_change([1, 2, 3... | } | }
return changes;
} |
//The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
// fib4(0) -> 0
// fib4(1) -> 0
// fib4(2) -> 2
// fib4(3) -> 0
// fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
// Please write a function to efficiently compute the n-th element of the fib4 number sequen... | prev[3] = curr; | }
return prev[3];
}
|
def get_max_triples(n: int) -> int:
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multipl... | a = [i * i - i + 1 for i in range(1, n + 1)] | i = 0
j = 1
k = 2
count = 0
while (i < n - 2):
while (j < n - 1):
while (k < n):
if (a[i] + a[j] + a[k]) % 3 == 0:
count += 1
k += 1
j += 1
k = j + 1
i += 1
j = i + 1
k = j + 1
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function count_nums which takes an array array list of integers and returns
// the number of elements which has a sum of di... | } | }
if (sum > 0) {
result++;
}
}
return result;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input are two strings a and b consisting only of 1s and 0s.
// Perform binary XOR on these inputs and return result also as a strin... | c.append(a.charAt(i) ^ b.charAt(i)); | }
return c.toString();
}
} |
from typing import List
def below_threshold(l: List[int], t: int) -> bool:
"""Return True if all numbers in the list l are below threshold t.
>>> below_threshold([1, 2, 4, 10], 100)
True
>>> below_threshold([1, 20, 4, 10], 5)
False
"""
| for num in l: | if num >= t:
return False
return True
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a string representing a space separated lowercase letters, return a hash map
// of the letter with the most repetition and co... | return s; | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of non-negative integers, return a cojava of the given array array list after sorting,
// you will sort t... | if(array.size()==1) { | return array;
}
if(array.size()>1) {
if((array.get(0)+array.get(array.size()-1))%2==0) {
Collections.sort(array, Collections.reverseOrder());
}
else {
Collections.sort(array);
}
}
return array;
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | num -= 400; | }
while (num >= 100) {
res += "c";
num -= 100;
}
if (num >= 90) {
res += "xc";
num -= 90;
}
if (num >= 50) {
res += "l";
num -= 50;
}
if (num >= 40) {
res += "xl";
... |
//Given a string s and a natural number n, you have been tasked to implement
// a function that returns an array of all words from string s that contain exactly
// n consonants, in order these words appear in the string s.
// If the string s is empty then the function should return an empty array.
// Note: you may as... | let selected = words.filter(e => e.match(/[bcdfghjklmnpqrstvwxyz]/gi) != null); | if(n > 0){
return selected.filter(e => e.match(/[bcdfghjklmnpqrstvwxyz]/gi).length == n);
}else{
return [];
}
}
|
//Create a function that takes integers, floats, or strings representing
// real numbers, and returns the larger variable in its given variable type.
// Return undefined if the values are equal.
// Note: If a real number is represented as a string, the floating point might be . or ,
// >>> compare_one(1, 2.5)
// 2.5
//... | } else { | return undefined;
}
}
else if (typeof a === "number" && typeof b === "string"){
if (a > b[0]){
return a;
} else if (a < b[0]){
return b;
} else {
return undefined;
}
}
}
|
//Write a function that returns true if the given number is the multiplication of 3 prime numbers
// and false otherwise.
// Knowing that (a) is less then 100.
// Example:
// >>> is_multiply_prime(30)
// true
// 30 = 2 * 3 * 5
function is_multiply_prime(a){
a = Math.abs(a); | const prime = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]; | let i = 0;
let check = [];
while(a != 1){
if(a % prime[i] == 0){
a = a / prime[i];
check.push(prime[i]);
}else{
i++;
}
}
if(check.length == 3){
return true;
}else{
return false;
}
} |
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, 0... | _min, _max = min(numbers), max(numbers) | if _min == _max:
return [0.5] * len(numbers)
return [(val - _min) / (_max - _min) for val in numbers]
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string representing a sentence,
// the sentence contains some words separated by a space,
// and you have to re... | if (isPrime) { | ans.append(word + " ");
}
}
if (ans.length() > 0) {
ans.deleteCharAt(ans.length() - 1);
}
return ans.toString();
}
} |
//Given a grid with N rows and N columns (N >= 2) and a positive integer k,
// each cell of the grid contains a value. Every integer in the range [1, N * N]
// inclusive appears exactly once on the cells of the grid.
// You have to find the minimum path of length k in the grid. You can start
// from any cell, and in e... | for(let i = 0; i < n; i++){ | for(let j = 0; j < n; j++){
let curr = grid[i][j];
if(curr < startCell){
startCell = curr;
}
}
}
let currCell = startCell;
for(let l = 0; l < k; l++){
path.push(currCell);
let neighbours = [];
let x = null;
l... |
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | exchange = false; | if(num2 < lst2.length){
while(num2 < lst2.length && exchange == false){
if(lst2[num2] % 2 == 0){
lst1[num1] = lst2[num2];
exchange = true;
}
num2++;
}
}
... |
//Return array of prime factors of given integer in the order from smallest to largest.
// Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
// Input number should be equal to the product of all factors
// >>> factorize(8)
// [2, 2, 2]
// >>> factorize(2... | while (n > 1) { | if (n % factor == 0) {
arr.push(factor);
n = n / factor;
} else {
factor++;
}
}
return arr;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
// >>> flipCase(("Hello"))
// ("hELLO")
... | for (int i = 0; i < string.length(); i++) { | if (Character.isLowerCase(string.charAt(i))) {
answer += Character.toUpperCase(string.charAt(i));
} else {
answer += Character.toLowerCase(string.charAt(i));
}
}
return answer;
}
} |
from typing import Tuple
def even_odd_count(num: int) -> Tuple[int, int]:
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
>>> even_odd_count(-12)
(1, 1)
>>> even_odd_count(123)
(1, 2)
"""
num_str = str(abs(num))
even_count = 0 | odd_count = 0 | for ch in num_str:
digit = int(ch)
if digit % 2 == 0:
even_count += 1
else:
odd_count += 1
return even_count, odd_count
|
//Given an array of integers nums, find the minimum sum of any non-empty sub-array
// of nums.
// Example
// >>> minSubArraySum([2, 3, 4, 1, 2, 4])
// 1
// >>> minSubArraySum([-1, -2, -3])
// -6
function minSubArraySum(nums){
let sum = 0;
let minSum = nums[0];
for(let i = 0; i < nums.length; i++){
s... | } | }
return minSum;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
// fib4(0) -> 0
// fib4(1)... | } | |
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | var num1 = 0; | var num2 = 0;
var exchange = true;
while(num1 < lst1.length && exchange){
if(lst1[num1] % 2 !== 0){
exchange = false;
if(num2 < lst2.length){
while(num2 < lst2.length && exchange == false){
if(lst2[num2] % 2 == 0){
l... |
def string_xor(a: str, b: str) -> str:
""" Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
>>> string_xor('010', '110')
'100'
"""
| return ''.join(str(int(i) ^ int(j)) for i, j in zip(a, b)) | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of integers.
// You need to find the largest prime value and return the sum of its digits.
//... | largestPrime = number; | }
}
}
if (largestPrime == 0) {
return 0l;
}
else {
long output = 0l;
while (largestPrime > 0) {
output += largestPrime % 10;
largestPrime /= 10;
}
return output;
... |
//You are given a rectangular grid of wells. Each row represents a single well,
// and each 1 in a row represents a single unit of water.
// Each well has a corresponding bucket that can be used to extract water from it,
// and all buckets have the same capacity.
// Your task is to use the buckets to empty the wells.
... | return maxFill; | }
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return n-th Fibonacci number.
// >>> fib((10l))
// (55l)
// >>> fib((1l))
// (1l)
// >>> fib((8l))
// (21l)
... | return 0l; | }
else if (n == 1) {
return 1l;
}
else {
return Problem.fib((n - 1)) + Problem.fib((n - 2));
}
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive floating point number, it can be decomposed into
// and integer part (largest integer smaller than given number) a... | } | |
from typing import List
def get_odd_collatz(n: int) -> List[int]:
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. The... | collatz_list = [] | current_num = n
while (current_num > 1):
collatz_list.append(current_num)
if (current_num % 2 == 0):
current_num = current_num // 2
else:
current_num = current_num * 3 + 1
collatz_list.append(1)
return sorted(list(set([x for x in collatz_list if x % 2 != 0... |
//Return 2^n modulo p (be aware of numerics).
// >>> modp(3, 5)
// 3
// >>> modp(1101, 101)
// 2
// >>> modp(0, 101)
// 1
// >>> modp(3, 11)
// 8
// >>> modp(100, 101)
// 1
function modp(n, p){
var result = 1;
while(n>0){
result = (result*2)%p;
n--;
}
return result; | } | |
//Write a function that accepts an array of strings.
// The array contains different words. Return the word with maximum number
// of unique characters. If multiple strings have maximum number of unique
// characters, return the one which comes first in lexicographical order.
// >>> find_max(["name", "of", "string"])
/... | return max_unique_word; | } |
//Task
// Write a function that takes a string as input and returns the sum of the upper characters only'
// ASCII codes.
// Examples:
// >>> digitSum("")
// 0
// >>> digitSum("abAB")
// 131
// >>> digitSum("abcCd")
// 67
// >>> digitSum("helloE")
// 69
// >>> digitSum("woArBld")
// 131
// >>> digitSum("aAaaaXa")
// 15... | if(s[i] >= 'A' && s[i] <= 'Z'){ | sum += s.charCodeAt(i);
}
}
return sum;
} |
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> is_equal_to_sum_even(4)
// false
// >>> is_equal_to_sum_even(6)
// false
// >>> is_equal_to_sum_even(8)
// true
function is_equal_to_sum_even(n){
| let m =0; | for(let i=2;i<n;i+=2){
for(let j=2;j<n;j+=2){
for(let k=2;k<n;k+=2){
for(let l=2;l<n;l+=2){
if((i+j+k+l)==n){
m=1;
break;
}
}
}
}
}
if(m==1){
... |
from typing import List
def sum_squares(lst: List[int]) -> int:
""""
This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3.... | lst[index] = lst[index] ** 2 | elif index % 4 == 0:
lst[index] = lst[index] ** 3
return sum(lst) |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// We have an array array list 'arr' of N integers arr[1], arr[2], ..., arr[N].The
// numbers in the array array list will be randomly... | long last = copy.remove(copy.size() - 1); | copy.add(0, last);
if (copy.equals(sorted)) return true;
arr = copy;
}
return false;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as ... | if (Character.isUpperCase(s.charAt(i))) { | sb.append(Character.toLowerCase(s.charAt(i)));
} else {
sb.append(Character.toUpperCase(s.charAt(i)));
}
} else {
sb.append(s.charAt(i));
}
}
if (letterNotFound) {
return sb.revers... |
//From an array of integers, remove all elements that occur more than once.
// Keep order of elements left the same as in the input.
// >>> remove_duplicates([1, 2, 3, 2, 4])
// [1, 3, 4]
function remove_duplicates(numbers){
let result = [];
numbers.forEach(function(value){ | if(numbers.indexOf(value) === numbers.lastIndexOf(value)){ | result.push(value);
}
});
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Find the shortest palindrome that begins with a supplied string.
// Algorithm idea is simple:
// - Find the longest postfix of ... | } | |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | if (grades[i] >= 4.0){ | grades_array.push("A+");
}
else if (grades[i] > 3.7){
grades_array.push("A");
}
else if (grades[i] > 3.3){
grades_array.push("A-");
}
else if (grades[i] > 3.0){
grades_array.push("B+");
}
else if (grades[i] >... |
//Write a function count_nums which takes an array of integers and returns
// the number of elements which has a sum of digits > 0.
// If a number is negative, then its first signed digit will be negative:
// e.g. -123 has signed digits -1, 2, and 3.
// >>> count_nums([])
// 0
// >>> count_nums([-1, 11, -11])
// 1
// >... | } | if(sum > 0) {
count++;
}
}
return count;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return true is array list elements are monotonically increasing or decreasing.
// >>> monotonic((new ArrayList<Long>(Arrays.asList(... | boolean inc = true; | boolean dec = true;
for (int i = 1; i < l.size(); i++) {
if (l.get(i) < a) {
inc = false;
}
if (l.get(i) > a) {
dec = false;
}
a = l.get(i);
}
return inc || dec;
}
} |
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([1... | temp, temp2 = numbers[temp2_index], numbers[temp_index] | else:
temp, temp2 = numbers[temp_index], numbers[temp2_index]
return temp, temp2
print(find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])) |
//You are given an array arr of integers and you need to return
// sum of magnitudes of integers multiplied by product of all signs
// of each number in the array, represented by 1, -1 or 0.
// Note: return undefined for empty arr.
// Example:
// >>> prod_signs([1, 2, 2, -4])
// 9
// >>> prod_signs([0, 1])
// 0
// >>> ... | pro *= 0; | }
}
total *= pro;
return total;
}
}
|
//You are given an array of integers.
// You need to find the largest prime value and return the sum of its digits.
// Examples:
// >>> skjkasdkd([0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3])
// 10
// >>> skjkasdkd([1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1])
// 25
// >>> skj... | let sum = 0; | for (let i=0; i<digits.length; i++){
sum += Number(digits[i]);
}
return sum;
} |
from typing import List
def find_max(words: List[str]) -> str:
"""Write a function that accepts a list of strings.
The list contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first ... | max_word = word | return max_word
|
def choose_num(x: int, y: int) -> int:
"""This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
>>> choose_num(12, 15)
14
>>> choose_num... | even_numbers = list(filter(lambda num: num % 2 == 0, numbers)) | return max(even_numbers) if even_numbers else -1
|
//Create a function which takes a string representing a file's name, and returns
// 'Yes' if the the file's name is valid, and returns 'No' otherwise.
// A file's name is considered to be valid if and only if all the following conditions
// are met:
// - There should not be more than three digits ('0'-'9') in the file... | (str_2 == 'txt' || str_2 == 'exe' || str_2 == 'dll') && str_1.length != 0 && | str_3.filter(item => /[0-9]/.test(item)).length < 4) {
return 'Yes';
}
return 'No';
}
|
from typing import List
def add_elements(arr: List[int], k: int) -> int:
"""
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
>>> add_elements([111, 21, 3, 4000, 5, 6, 7, 8, 9], 4)
24
... | total = 0 | for num in arr[:k]:
if num < 100:
total += num
return total
|
def fruit_distribution(s: str, n: int) -> int:
"""
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the ora... | fruits.append(int(fruit)) | except:
pass
return n - sum(fruits)
|
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | var case_type = -1; | for (let key in dict){
if (typeof key == "string"){
if (case_type == -1){
if (key == key.toUpperCase()){
case_type = 1;
}
else if (key == key.toLowerCase()){
case_type = 0;
}
e... |
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