prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
//Return the largest prime factor of n. Assume n > 1 and is not a prime.
// >>> largest_prime_factor(13195)
// 29
// >>> largest_prime_factor(2048)
// 2
function largest_prime_factor(n){
var result = 2;
while(n > result){
if(n % result == 0){
n = n / result;
} | else{ | result = result + 1;
}
}
return result;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
// >>> fizzBuzz((50l))
... | if (i % 11 == 0 || i % 13 == 0) { | String s = String.valueOf(i);
for (int j = 0; j < s.length(); j++) {
if (s.charAt(j) == '7') {
res++;
}
}
}
}
return res;
}
} |
//Out of array of strings, return the longest one. Return the first one in case of multiple
// strings of the same length. Return undefined in case the input array is empty.
// >>> longest([])
// undefined
// >>> longest(["a", "b", "c"])
// "a"
// >>> longest(["a", "bb", "ccc"])
// "ccc"
function longest(strings){
va... | if (strings.length === 0) { | return undefined;
}
for (var i = 0; i < strings.length; i++) {
if (!result || strings[i].length > result.length) {
result = strings[i];
}
}
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a non-empty array list of integers lst. add the even elements that are at odd indices..
// Examples:
// >>> add((new Arra... | } | return sum;
}
} |
//Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
// >>> fizz_buzz(50)
// 0
// >>> fizz_buzz(78)
// 2
// >>> fizz_buzz(79)
// 3
function fizz_buzz(n){
let result = 0;
for(let i = 0; i < n; i++){
if(i % 11 === 0 || i % 13 === 0){ | let arr = i.toString().split(''); | for(let j = 0; j < arr.length; j++){
if(arr[j] === '7'){
result++;
}
}
}
}
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that returns true if the given number is the multiplication of 3 prime numbers
// and false otherwise.
// Know... | a /= 2; | }
for (long i = 3; i <= Math.sqrt(a); i += 2) {
while (a % i == 0) {
arr.add(i);
a /= i;
}
}
if (a > 2) {
arr.add(a);
}
return arr.size() == 3;
}
} |
//Given a string s, count the number of uppercase vowels in even indices.
// For example:
// >>> count_upper("aBCdEf")
// 1
// >>> count_upper("abcdefg")
// 0
// >>> count_upper("dBBE")
// 0
function count_upper(s){
var index;
var result = 0;
var vowel = ['A', 'E', 'I', 'O', 'U'];
for (index = 0; index ... | return result; | } |
//Return 2^n modulo p (be aware of numerics).
// >>> modp(3, 5)
// 3
// >>> modp(1101, 101)
// 2
// >>> modp(0, 101)
// 1
// >>> modp(3, 11)
// 8
// >>> modp(100, 101)
// 1
function modp(n, p){
var result = 1;
while(n>0){
result = (result*2)%p;
n--;
} | return result; | }
|
//Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
// For each of the group, output the deepest level of nesting of parentheses.
// E.g. (()()) has maximum two levels of nesting while ((())) has three.
// >>> parse_nested_parens("(()()) ((())) () ((())()())")
//... | level -= 1; | }
else if (paren_string[i] == " "){
result.push(maxlevel);
maxlevel = 0;
level = 0;
}
}
result.push(maxlevel);
return result;
}
|
//Return array of all prefixes from shortest to longest of the input string
// >>> all_prefixes("abc")
// ["a", "ab", "abc"]
function all_prefixes(string){
var result = [];
for (var i = 1; i <= string.length; i++){ | result.push(string.slice(0, i)); | }
return result;
}
|
from typing import List, Optional
def prod_signs(arr: List[int]) -> Optional[int]:
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty a... | sign_arr = [] | for num in arr:
if num > 0:
sign_arr.append(1)
elif num < 0:
sign_arr.append(-1)
else:
sign_arr.append(0)
return sum(map(abs, arr)) * product(sign_arr) |
//Given array of numbers (of at least two elements), apply a linear transform to that array,
// such that the smallest number will become 0 and the largest will become 1
// >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
// [0.0, 0.25, 0.5, 0.75, 1.0]
function rescale_to_unit(numbers){
var min = Math.min.apply(Math, n... | for (var i = 0; i < numbers.length; i++) { | unit.push((numbers[i] - min) / sub);
}
return unit;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of integers.
// You need to find the largest prime value and return the sum of its digits.
//... | if (largestPrime == 0) { | return 0l;
}
else {
long output = 0l;
while (largestPrime > 0) {
output += largestPrime % 10;
largestPrime /= 10;
}
return output;
}
}
} |
//Write a function count_nums which takes an array of integers and returns
// the number of elements which has a sum of digits > 0.
// If a number is negative, then its first signed digit will be negative:
// e.g. -123 has signed digits -1, 2, and 3.
// >>> count_nums([])
// 0
// >>> count_nums([-1, 11, -11])
// 1
// >... | return 0; | }
var count = 0;
for(var i = 0; i < arr.length; i++) {
var sum = 0;
var str = arr[i].toString();
if(str[0] === '-') {
sum += Number(str[0] + str[1]);
for(var j = 2; j < str.length; j++) {
sum += Number(str[j]);
}
} else {
for(var k = 0; k < str.length; k++) {
sum += Number(str[k]);
}
... |
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([1... | temp2_index = j | elif abs(numbers[i] - numbers[j]) == temp:
if numbers[i] > numbers[j]:
temp = abs(numbers[i] - numbers[j])
temp_index = i
temp2_index = j
if numbers[temp_index] > numbers[temp2_index]:
temp, temp2 = numbers[temp2_index],... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes two positive numbers x and y and returns the
// biggest even integer number that is in the range [x, y] inclusi... | } | } |
//Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
// Return the string with numbers sorted from smallest to largest
// >>> sort_numbers("three one five")
// "one three five"
function sort_number... | numString.sort(function(a, b){ | return numMap[a] - numMap[b];
});
numString = numString.join(" ");
return numString;
} |
//In this Kata, you have to sort an array of non-negative integers according to
// number of ones in their binary representation in ascending order.
// For similar number of ones, sort based on decimal value.
// It must be implemented like this:
// >>> sort_array([1, 5, 2, 3, 4])
// [1, 2, 3, 4, 5]
// >>> sort_array([-... | if (aBinary === bBinary) { | return a - b;
} else {
return aBinary - bBinary;
}
});
} |
//Given array of integers, return array in strange order.
// Strange sorting, is when you start with the minimum value,
// then maximum of the remaining integers, then minimum and so on.
// Examples:
// >>> strange_sort_list([1, 2, 3, 4])
// [1, 4, 2, 3]
// >>> strange_sort_list([5, 5, 5, 5])
// [5, 5, 5, 5]
// >>> str... | var tmp = lst.slice(); | for(var i = 0; i < lst.length; i++){
if(i % 2 === 0){
output.push(Math.min.apply(null, tmp));
}
else{
output.push(Math.max.apply(null, tmp));
}
tmp.splice(tmp.indexOf(output[i]), 1);
}
return output;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// brackets is a string of "<" and ">".
// return true if every opening bracket has a corresponding closing bracket.
// >>> correc... | return open == 0; | }
} |
//Imagine a road that's a perfectly straight infinitely long line.
// n cars are driving left to right; simultaneously, a different set of n cars
// are driving right to left. The two sets of cars start out being very far from
// each other. All cars move in the same speed. Two cars are said to collide
// when a c... | } | return num_collisions;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// brackets is a string of "<" and ">".
// return true if every opening bracket has a corresponding closing bracket.
// >>> correc... | return false; | }
}
return open == 0;
}
} |
//Given an array of numbers, return whether or not they are sorted
// in ascending order. If array has more than 1 duplicate of the same
// number, return false. Assume no negative numbers and only integers.
// Examples
// >>> is_sorted([5])
// true
// >>> is_sorted([1, 2, 3, 4, 5])
// true
// >>> is_sorted([1, 3, 2, 4... | return false; | } else if (x == last){
if (dupe_found){
return false;
} else {
dupe_found = true;
}
} else {
last = x;
dupe_found = false;
}
}
return true;
}
|
from typing import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return True... | return True | return False
print(below_zero([1, 2, 3]))
print(below_zero([1, 2, -4, 5])) |
//Given an array of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array, and then replace each digit by its corresponding name from
// "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
// For example:
// >>> by_length([2, 1, 1, 4, 5, 8, 2, 3])
// ["Eight"... | } | return arr3;
} |
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | num1++; | }
if(exchange){
return "YES";
}else{
return "NO";
}
}
|
def anti_shuffle(s: str) -> str:
"""
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: ... | words = s.split(' ') | shuffled_words = [''.join(sorted(word)) for word in words]
return ' '.join(shuffled_words)
|
//Create a function that takes a value (string) representing a number
// and returns the closest integer to it. If the number is equidistant
// from two integers, round it away from zero.
// Examples
// >>> closest_integer("10")
// 10
// >>> closest_integer("15.3")
// 15
// Note:
// Rounding away from zero means that i... | }else{ | if(value - Math.floor(value) > -0.5){
return Math.floor(value);
}else{
return Math.ceil(value);
}
}
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return length of given string
// >>> stringLength((""))
// (0l)
// >>> stringLength(("abc"))
// (3l)
public static ... | return string.length(); | }
} |
//Change numerical base of input number x to base.
// return string representation after the conversion.
// base numbers are less than 10.
// >>> change_base(8, 3)
// "22"
// >>> change_base(8, 2)
// "1000"
// >>> change_base(7, 2)
// "111"
function change_base(x, base){
let r = x % base;
let q = Math.floor(x /... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return maximum element in the array list.
// >>> maxElement((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l))))
... | } | return max;
}
} |
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | } | else{
return false;
}
}
else if (case_type == 1){
if (key != key.toUpperCase()){
return false;
}
}
else if (case_type == 0){
if (key != key.toLowerCase(... |
//Return median of elements in the array l.
// >>> median([3, 1, 2, 4, 5])
// 3
// >>> median([-10, 4, 6, 1000, 10, 20])
// 15.0
function median(l){
let middle = Math.floor(l.length / 2);
let sorted = l.sort((a, b) => a - b);
if (l.length % 2 === 0) {
return (sorted[middle - 1] + sorted[middle]) / 2... | return sorted[middle]; | }
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> isEqualToSum... | minX = x + 1; | } else if (2 * x + y > n) {
maxX = x - 1;
} else {
return true;
}
}
return false;
}
} |
from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2... | return True | return False
|
def car_race_collision(n: int) -> int:
"""
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the s... | return count | |
//This function takes an array l and returns an array l' such that
// l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
// to the values of the corresponding indicies of l, but sorted.
// >>> sort_third([1, 2, 3])
// [1, 2, 3]
//... | k=k+1; | }
else{
x[i]=l[i];
}
}
y.sort();
k=0;
for(let i=0;i<l.length;i++){
if(i%3==0){
x[i]=y[k];
k=k+1;
}
}
return x;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You'll be given a string of words, and your task is to count the number
// of boredoms. A boredom is a sentence that starts with th... | String[] sentences = S.split("\\.\\s|\\?\\s|\\!\\s"); | for (String sentence : sentences) {
String[] words = sentence.split("\\s");
if (words.length > 0 && words[0].equals("I")) {
boredoms++;
}
}
return boredoms;
}
} |
//Given an array of integers nums, find the minimum sum of any non-empty sub-array
// of nums.
// Example
// >>> minSubArraySum([2, 3, 4, 1, 2, 4])
// 1
// >>> minSubArraySum([-1, -2, -3])
// -6
function minSubArraySum(nums){
let sum = 0;
let minSum = nums[0];
for(let i = 0; i < nums.length; i++){
s... | } | if(sum > 0){
sum = 0;
}
}
return minSum;
}
|
//Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
// Return the string with numbers sorted from smallest to largest
// >>> sort_numbers("three one five")
// "one three five"
function sort_number... | var numMap = { | "zero": 0,
"one": 1,
"two": 2,
"three": 3,
"four": 4,
"five": 5,
"six": 6,
"seven": 7,
"eight": 8,
"nine": 9
};
numString.sort(function(a, b){
return numMap[a] - numMap[b];
});
numString = numString.join(" ");
return numString;
} |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | else if (grades[i] > 3.3){ | grades_array.push("A-");
}
else if (grades[i] > 3.0){
grades_array.push("B+");
}
else if (grades[i] > 2.7){
grades_array.push("B");
}
else if (grades[i] > 2.3){
grades_array.push("B-");
}
else if (grades[i] >... |
from typing import List, Tuple, Optional
def largest_smallest_integers(lst: List[int]) -> Tuple[Optional[int], Optional[int]]:
"""
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no neg... | elif num < 0: | if largest_negative is None or num > largest_negative:
largest_negative = num
return (largest_negative, smallest_positive)
|
from typing import List
def match_parens(lst: List[str]) -> str:
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will b... | for c in s: | if c == '(':
open_parens += 1
elif c == ')':
if open_parens:
open_parens -= 1
else:
close_parens += 1
if open_parens == 0 and close_parens == 0:
return 'Yes'
return 'No'
|
//Check if two words have the same characters.
// >>> same_chars("eabcdzzzz", "dddzzzzzzzddeddabc")
// true
// >>> same_chars("abcd", "dddddddabc")
// true
// >>> same_chars("dddddddabc", "abcd")
// true
// >>> same_chars("eabcd", "dddddddabc")
// false
// >>> same_chars("abcd", "dddddddabce")
// false
// >>> same_char... | } | }
for(let i = 0; i < s1.length; i++){
if(s0.indexOf(s1[i]) === -1){
res = false;
break;
}
}
return res;
}
|
//Write a function that takes an array of numbers as input and returns
// the number of elements in the array that are greater than 10 and both
// first and last digits of a number are odd (1, 3, 5, 7, 9).
// For example:
// >>> specialFilter([15, -73, 14, -15])
// 1
// >>> specialFilter([33, -2, -3, 45, 21, 109])
//... | } | |
def sort_numbers(numbers: str) -> str:
""" Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
>>> sort_numbers('three one... | for word in sorted(words, key=lambda x: mapper[x]): | res += ' ' + word
return res.strip()
|
//Given a positive integer n, return the product of the odd digits.
// Return 0 if all digits are even.
// For example:
// >>> digits(1)
// 1
// >>> digits(4)
// 0
// >>> digits(235)
// 15
function digits(n){
if(!n){
return "error";
} | if(n < 0){ | return "error";
}
var temp = 0;
var prod = 1;
var odd = true;
for(n; n > 0; n = Math.floor(n/10)){
temp = n % 10;
if(temp % 2 != 0){
prod *= temp;
odd = false;
}
}
if(odd){
return 0;
}
return prod;
}
|
from typing import List
def Strongest_Extension(class_name: str, extensions: List[str]) -> str:
"""You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the nu... | n_uppercase = sum(1 for c in extension if c.isupper()) | n_lowercase = sum(1 for c in extension if c.islower())
if n_uppercase - n_lowercase > best_strength:
best_strength = n_uppercase - n_lowercase
best_extension = extension
return class_name + '.' + best_extension |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | } | }
return grades_array;
} |
def fib4(n: int) -> int:
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-... | if n == 0: | return 0
elif n == 1:
return 0
elif n == 2:
return 2
elif n == 3:
return 0
else:
return fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4)
|
//"
// This function will take an array of integers. For all entries in the array, the function shall square the integer entry if its index is a
// multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
// change the entries in the array whose inde... | sum += lst[i]; | }
}
return sum;
} |
from typing import List
def sort_even(l: List[int]) -> List[int]:
"""This function takes a list l and returns a list l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
>>> sort_even([1, 2, 3])
[... | for i in range(0, len(l), 2): | l[i] = temp[i // 2]
return l |
def is_simple_power(x: int, n: int) -> bool:
"""Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
>>> is_simple_power(1, 4)
true
>>> is_simple_power(2, 2)
true
>>> is_sim... | while x > 1: | if x % n != 0:
return False
x /= n
return True
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// From an array array list of integers, remove all elements that occur more than once.
// Keep order of elements left the same as in ... | if (hashmap.containsKey(key)) { | hashmap.put(key, hashmap.get(key) + 1);
} else {
hashmap.put(key, 1L);
}
}
ArrayList<Long> out = new ArrayList<Long>();
for (int i = 0; i < numbers.size(); i++) {
Long key = numbers.get(i);
if (hashmap.get(key) == 1)... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Input to this function is a string representing musical notes in a special ASCII format.
// Your task is to parse this string and r... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Implement a function that takes an non-negative integer and returns an array array list of the first n
// integers that are prime n... | for (long i = 2l; i < n; i++) { | boolean isPrime = true;
for (long j = 2l; j < i; j++) {
if (i % j == 0) {
isPrime = false;
break;
}
}
if (isPrime) {
arrayList.add(i);
}
}
return arrayList;... |
//In this problem, you will implement a function that takes two arrays of numbers,
// and determines whether it is possible to perform an exchange of elements
// between them to make lst1 an array of only even numbers.
// There is no limit on the number of exchanged elements between lst1 and lst2.
// If it is possible ... | var num2 = 0; | var exchange = true;
while(num1 < lst1.length && exchange){
if(lst1[num1] % 2 !== 0){
exchange = false;
if(num2 < lst2.length){
while(num2 < lst2.length && exchange == false){
if(lst2[num2] % 2 == 0){
lst1[num1] = lst2[n... |
from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
result = []
if len(numbers... | for num in numbers[1:]: | result.append(delimeter)
result.append(num)
return result
|
from typing import List
def numerical_letter_grade(grades: List[float]) -> List[str]:
"""It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
Sh... | final = [] | for x in grades:
if x == 4.0:
final.append('A+')
elif x > 3.7:
final.append('A')
elif x > 3.3:
final.append('A-')
elif x > 3.0:
final.append('B+')
elif x > 2.7:
final.append('B')
elif x > 2.3:
fin... |
from typing import List
def numerical_letter_grade(grades: List[float]) -> List[str]:
"""It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
Sh... | else: | final.append('E')
return final
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the odd indicies,... | int index = 0; | for (Long num : l) {
if (index % 2 == 0) {
evenIndexed.add(num);
}
index++;
}
Collections.sort(evenIndexed);
index = 0;
for (Long num : l) {
if (index % 2 == 0) {
res.add(evenIndexed.get(0));
... |
from typing import List
def odd_count(lst: List[str]) -> List[str]:
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
... | for i in range(len(lst)): | count = 0
for j in range(len(lst[i])):
if int(lst[i][j]) % 2 != 0:
count += 1
output.append(f"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.")
return output
|
//Checks if given string is a palindrome
// >>> is_palindrome("")
// true
// >>> is_palindrome("aba")
// true
// >>> is_palindrome("aaaaa")
// true
// >>> is_palindrome("zbcd")
// false
function is_palindrome(text){
| return text == text.split("").reverse().join(""); | }
|
//Write a function count_nums which takes an array of integers and returns
// the number of elements which has a sum of digits > 0.
// If a number is negative, then its first signed digit will be negative:
// e.g. -123 has signed digits -1, 2, and 3.
// >>> count_nums([])
// 0
// >>> count_nums([-1, 11, -11])
// 1
// >... | } | } else {
for(var k = 0; k < str.length; k++) {
sum += Number(str[k]);
}
}
if(sum > 0) {
count++;
}
}
return count;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Circular shift the digits of the integer x, shift the digits right by shift
// and return the result as a string.
// If shift >... | if (shift > digits.length()) { | return new StringBuilder(digits).reverse().toString();
}
return (digits.substring(digits.length() - (int)shift, digits.length()) + digits.substring(0, digits.length() - (int)shift));
}
} |
//Change numerical base of input number x to base.
// return string representation after the conversion.
// base numbers are less than 10.
// >>> change_base(8, 3)
// "22"
// >>> change_base(8, 2)
// "1000"
// >>> change_base(7, 2)
// "111"
function change_base(x, base){
let r = x % base; | let q = Math.floor(x / base); | if (q === 0) return r.toString();
return change_base(q, base) + r.toString();
}
|
//Return the largest prime factor of n. Assume n > 1 and is not a prime.
// >>> largest_prime_factor(13195)
// 29
// >>> largest_prime_factor(2048)
// 2
function largest_prime_factor(n){
var result = 2; | while(n > result){ | if(n % result == 0){
n = n / result;
}
else{
result = result + 1;
}
}
return result;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given two array lists operator, and operand. The first array list has basic algebra operations, and
// the second array list is an... | return list.stream().mapToLong(x -> x).sum(); | }
} |
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | temp = a; | a = a + b;
b = temp;
num--;
}
return b;
}
var res = 0;
var fibNum = 0;
while(res < n){
if(isPrime(fib(fibNum))){
res++;
}
fibNum++;
}
return fib(fibNum - 1);
} |
//Input are two strings a and b consisting only of 1s and 0s.
// Perform binary XOR on these inputs and return result also as a string.
// >>> string_xor("010", "110")
// "100"
function string_xor(a, b){
var arrayA = [];
var arrayB = [];
var arrayXOR = [];
var result = '';
for (var i = 0; i < a.length; i++) {... | for (var j = 0; j < b.length; j++) { | arrayB.push(parseInt(b[j]));
}
for (var k = 0; k < arrayA.length; k++) {
if (arrayA[k] !== arrayB[k]) {
arrayXOR.push(1);
}
else {
arrayXOR.push(0);
}
}
result = arrayXOR.join('');
return result;
} |
//Check if two words have the same characters.
// >>> same_chars("eabcdzzzz", "dddzzzzzzzddeddabc")
// true
// >>> same_chars("abcd", "dddddddabc")
// true
// >>> same_chars("dddddddabc", "abcd")
// true
// >>> same_chars("eabcd", "dddddddabc")
// false
// >>> same_chars("abcd", "dddddddabce")
// false
// >>> same_char... | res = false; | break;
}
}
for(let i = 0; i < s1.length; i++){
if(s0.indexOf(s1[i]) === -1){
res = false;
break;
}
}
return res;
}
|
//Create a function that takes a value (string) representing a number
// and returns the closest integer to it. If the number is equidistant
// from two integers, round it away from zero.
// Examples
// >>> closest_integer("10")
// 10
// >>> closest_integer("15.3")
// 15
// Note:
// Rounding away from zero means that i... | return Math.ceil(value); | }
}
}
|
//Write a function that accepts two arrays of strings and returns the array that has
// total number of chars in the all strings of the array less than the other array.
// if the two arrays have the same number of chars, return the first array.
// Examples
// >>> total_match([], [])
// []
// >>> total_match(["hi", "ad... | } | |
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | else if (key == key.toLowerCase()){ | case_type = 0;
}
else{
return false;
}
}
else if (case_type == 1){
if (key != key.toUpperCase()){
return false;
}
}
else if (case_ty... |
//Write a function count_nums which takes an array of integers and returns
// the number of elements which has a sum of digits > 0.
// If a number is negative, then its first signed digit will be negative:
// e.g. -123 has signed digits -1, 2, and 3.
// >>> count_nums([])
// 0
// >>> count_nums([-1, 11, -11])
// 1
// >... | } | }
if(sum > 0) {
count++;
}
}
return count;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// remove_vowels is a function that takes string and returns string without vowels.
// >>> removeVowels((""))
// ("")
// >>> r... | } | return newText;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return the largest prime factor of n. Assume n > 1 and is not a prime.
// >>> largestPrimeFactor((13195l))
// (29l)
// >>> ... | } | |
//Given an array of numbers, return the sum of squares of the numbers
// in the array that are odd. Ignore numbers that are negative or not integers.
// >>> double_the_difference([1, 3, 2, 0])
// 10
// >>> double_the_difference([-1, -2, 0])
// 0
// >>> double_the_difference([9, -2])
// 81
// >>> double_the_difference([... | return sum; | }
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list arr of integers, find the minimum number of elements that
// need to be changed to make the array array l... | int last = arr.size() - 1; | int count = 0;
while (first < last) {
if (arr.get(first) != arr.get(last)) {
count++;
}
first++;
last--;
}
return count;
}
} |
//Write a function that accepts an array of strings as a parameter,
// deletes the strings that have odd lengths from it,
// and returns the resulted array with a sorted order,
// The array is always an array of strings and never an array of numbers,
// and it may contain duplicates.
// The order of the array should be... | return -1; | }
else if(a > b){
return 1;
}
else{
return 0;
}
}
});
}
var a = ["aa", "a", "aaa"];
var b = ["ab", "a", "aaa", "cd"]; |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return true is array list elements are monotonically increasing or decreasing.
// >>> monotonic((new ArrayList<Long>(Arrays.asList(... | } | } |
def change_base(x: int, base: int) -> str:
"""Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
>>> change_base(8, 3)
'22'
>>> change_base(8, 2)
'1000'
>>> change_base(7, 2)
'111'
"""
if x == 0:
... | ans = [] | while x != 0:
ans.append(str(x % base))
x //= base
return ''.join(ans[::-1])
|
//Given a positive integer n, return an array that has the number of even and odd
// integer palindromes that fall within the range(1, n), inclusive.
// Example 1:
// >>> even_odd_palindrome(3)
// [1, 2]
// Explanation:
// Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
// Example 2:
// >>... | var y = x.toString().split('').reverse().join(''); | return y == x;
}
for(var i = 1; i <= n; i++){
if(isPalindrome(i)){
pal.push(i);
}
}
var odd = 0;
var even = 0;
for(var i = 0; i < pal.length; i++){
if(pal[i] % 2 == 0){
even++;
}
else{
odd++;
}
}
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> isEqualToSum... | if (y % 2 == 1) { | y--;
}
if (2 * x + y < n) {
minX = x + 1;
} else if (2 * x + y > n) {
maxX = x - 1;
} else {
return true;
}
}
return false;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given an array array list of integers nums, find the minimum sum of any non-empty sub-array array list
// of nums.
// Example
... | if (currSum < prevMinSum) { | prevMinSum = currSum;
}
if (currSum < minSum) {
minSum = currSum;
}
}
}
return minSum;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of numbers.
// You need to return the sum of squared numbers in the given array list,
// roun... | sum += (long)Math.ceil(lst.get(i)) * (long)Math.ceil(lst.get(i)); | }
return sum;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a string representing a space separated lowercase letters, return a hash map
// of the letter with the most repetition and co... | max = hm.get(key); | }
}
for (String key : hm.keySet()) {
if (hm.get(key) == max) {
s.put(key, hm.get(key));
}
}
}
return s;
}
} |
//Return array of prime factors of given integer in the order from smallest to largest.
// Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
// Input number should be equal to the product of all factors
// >>> factorize(8)
// [2, 2, 2]
// >>> factorize(2... | return arr; | }
|
//Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
// For each of the group, output the deepest level of nesting of parentheses.
// E.g. (()()) has maximum two levels of nesting while ((())) has three.
// >>> parse_nested_parens("(()()) ((())) () ((())()())")
//... | for (var i = 0; i < paren_string.length; i++){ | if (paren_string[i] == "("){
level += 1;
if (level > maxlevel){
maxlevel = level;
}
}
else if (paren_string[i] == ")"){
level -= 1;
}
else if (paren_string[i] == " "){
result.push(maxlevel);
m... |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | } | else if (grades[i] > 0.7){
grades_array.push("D");
}
else if (grades[i] > 0.0){
grades_array.push("D-");
}
else if (grades[i] == 0.0){
grades_array.push("E");
}
}
return grades_array;
} |
//Input is a space-delimited string of numberals from 'zero' to 'nine'.
// Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
// Return the string with numbers sorted from smallest to largest
// >>> sort_numbers("three one five")
// "one three five"
function sort_number... | "five": 5, | "six": 6,
"seven": 7,
"eight": 8,
"nine": 9
};
numString.sort(function(a, b){
return numMap[a] - numMap[b];
});
numString = numString.join(" ");
return numString;
} |
from typing import List
def minPath(grid: List[List[int]], k: int) -> List[int]:
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You... | min_val = float('inf') | for i in range(len(grid)):
for j in range(len(grid[0])):
if grid[i][j] < min_val:
min_val = grid[i][j]
row = i
col = j
path = [min_val]
while len(path) < k:
min_val = float('inf')
for i, j in (row - 1, col), (row + 1, col), ... |
//Input to this function is a string representing musical notes in a special ASCII format.
// Your task is to parse this string and return array of integers corresponding to how many beats does each
// not last.
// Here is a legend:
// 'o' - whole note, lasts four beats
// 'o|' - half note, lasts two beats
// '.|' - qu... | }); | return song;
}
|
//Given a non-empty array of integers arr and an integer k, return
// the sum of the elements with at most two digits from the first k elements of arr.
// Example:
// >>> add_elements([111, 21, 3, 4000, 5, 6, 7, 8, 9], 4)
// 24
// Constraints:
// 1. 1 <= len(arr) <= 100
// 2. 1 <= k <= len(arr)
function add_elements(ar... | } | }
return sum;
}
|
//Create a function which returns the largest index of an element which
// is not greater than or equal to the element immediately preceding it. If
// no such element exists then return -1. The given array will not contain
// duplicate values.
// Examples:
// >>> can_arrange([1, 2, 4, 3, 5])
// 3
// >>> can_arrange([1,... | for(var i = 1; i < arr.length; i++){ | if(arr[i] < max){
res = i;
}else{
max = arr[i];
}
}
return res;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function count_nums which takes an array array list of integers and returns
// the number of elements which has a sum of di... | } | if (sum > 0) {
result++;
}
}
return result;
}
} |
from typing import Union, List
def split_words(txt: str) -> Union[List[str], int]:
"""
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd ord... | elif ',' in txt: | return txt.split(',')
else:
return len([letter for letter in txt if letter in alphabet and alphabet.index(letter) % 2 == 1])
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string s.
// if s[i] is a letter, reverse its case from lower to upper or vise versa,
// otherwise keep it as ... | } | }
if (letterNotFound) {
return sb.reverse().toString();
}
return sb.toString();
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given array list of numbers (of at least two elements), apply a linear transform to that array list,
// such that the smallest numb... | float min = numbers.stream().min(Float::compare).get(); | float max = numbers.stream().max(Float::compare).get();
return numbers.stream().map(e -> (e - min) / (max - min)).collect(Collectors.toCollection(ArrayList::new));
}
} |
from typing import List
def pluck(arr: List[int]) -> List[int]:
"""
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the ... | evens = [e for e in arr if e % 2 == 0] | if len(evens) == 0:
return []
return [min(evens), arr.index(min(evens))]
|
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