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proofwiki-16300
Set Consisting of Empty Set is not Empty
Let $S$ be the set defined as: :$S = \set \O$ Then $S$ is not the empty set. That is: :$\O \ne \set \O$
We have: :$\O \in \set \O$ and so: :$\neg \paren {\forall x: x \notin \O}$ The result follows by definition of the empty set. {{qed}}
Let $S$ be the [[Definition:Set|set]] defined as: :$S = \set \O$ Then $S$ is not the [[Definition:Empty Set|empty set]]. That is: :$\O \ne \set \O$
We have: :$\O \in \set \O$ and so: :$\neg \paren {\forall x: x \notin \O}$ The result follows by definition of the [[Definition:Empty Set|empty set]]. {{qed}}
Set Consisting of Empty Set is not Empty
https://proofwiki.org/wiki/Set_Consisting_of_Empty_Set_is_not_Empty
https://proofwiki.org/wiki/Set_Consisting_of_Empty_Set_is_not_Empty
[ "Empty Set" ]
[ "Definition:Set", "Definition:Empty Set" ]
[ "Definition:Empty Set" ]
proofwiki-16301
Elements of Ordered Pair do not Commute
Let $\set {a, b}$ be a doubleton, so that $a$ and $b$ are distinct objects. Let $\tuple {a, b}$ denote the ordered pair such that the first coordinate is $a$ and the second coordinate is $b$. Then: :$\tuple {a, b} \ne \tuple {b, a}$
By the Kuratowski formalization of $\tuple {a, b}$: :$\tuple {a, b} = \set {\set a, \set {a, b} }$ and by Equality of Ordered Pairs: :$\tuple {a, b} = \tuple {b, a} \iff a = b$ But $a \ne b$ and so: :$\tuple {a, b} \ne \tuple {b, a}$ {{qed}}
Let $\set {a, b}$ be a [[Definition:Doubleton|doubleton]], so that $a$ and $b$ are [[Definition:Distinct Objects|distinct objects]]. Let $\tuple {a, b}$ denote the [[Definition:Ordered Pair|ordered pair]] such that the [[Definition:Coordinate of Ordered Pair|first coordinate]] is $a$ and the [[Definition:Coordinate of...
By the [[Definition:Kuratowski Formalization of Ordered Pair|Kuratowski formalization of $\tuple {a, b}$]]: :$\tuple {a, b} = \set {\set a, \set {a, b} }$ and by [[Equality of Ordered Pairs]]: :$\tuple {a, b} = \tuple {b, a} \iff a = b$ But $a \ne b$ and so: :$\tuple {a, b} \ne \tuple {b, a}$ {{qed}}
Elements of Ordered Pair do not Commute
https://proofwiki.org/wiki/Elements_of_Ordered_Pair_do_not_Commute
https://proofwiki.org/wiki/Elements_of_Ordered_Pair_do_not_Commute
[ "Ordered Pairs" ]
[ "Definition:Doubleton", "Definition:Distinct/Plural", "Definition:Ordered Pair", "Definition:Coordinate System/Coordinate/Element of Ordered Pair", "Definition:Coordinate System/Coordinate/Element of Ordered Pair" ]
[ "Definition:Ordered Pair/Kuratowski Formalization", "Equality of Ordered Pairs" ]
proofwiki-16302
Definite Integral to Infinity of Cosine m x over x Squared plus a Squared
:$\ds \int_0^\infty \frac {\cos m x} {x^2 + a^2} \rd x = \frac \pi {2 a} e^{-m a}$
From Definite Integral of Even Function: :$\ds \frac 1 2 \int_{-\infty}^\infty \frac {\cos m x} {x^2 + a^2} \rd x = \int_0^\infty \frac {\cos m x} {x^2 + a^2} \rd x$ Let $R$ be a positive real number with $R > a$. Let $C_1$ be the straight line segment from $-R$ to $R$. Let $C_2$ be the arc of the circle of radius $R$ ...
:$\ds \int_0^\infty \frac {\cos m x} {x^2 + a^2} \rd x = \frac \pi {2 a} e^{-m a}$
From [[Definite Integral of Even Function]]: :$\ds \frac 1 2 \int_{-\infty}^\infty \frac {\cos m x} {x^2 + a^2} \rd x = \int_0^\infty \frac {\cos m x} {x^2 + a^2} \rd x$ Let $R$ be a [[Definition:Positive Real Number|positive real number]] with $R > a$. Let $C_1$ be the [[Definition:Straight Line Segment|straight li...
Definite Integral to Infinity of Cosine m x over x Squared plus a Squared
https://proofwiki.org/wiki/Definite_Integral_to_Infinity_of_Cosine_m_x_over_x_Squared_plus_a_Squared
https://proofwiki.org/wiki/Definite_Integral_to_Infinity_of_Cosine_m_x_over_x_Squared_plus_a_Squared
[ "Definite Integrals involving Cosine Function" ]
[]
[ "Definite Integral of Even Function", "Definition:Positive/Real Number", "Definition:Line/Straight Line Segment", "Definition:Circle/Arc", "Definition:Anticlockwise", "Euler's Formula", "Linear Combination of Integrals/Definite", "Definite Integral of Odd Function", "Definition:Integration/Integrand...
proofwiki-16303
Combination Theorem for Continuous Mappings/Normed Division Ring/Sum Rule
:$f + g: \struct {S, \tau_{_S} } \to \struct{R, \tau_{_R} }$ is continuous.
From {{Corollary|Normed Division Ring Operations are Continuous}}: :$\struct {R, +, *, \tau_{_R} }$ is a topological division ring. From Sum Rule for Continuous Mappings to Topological Division Ring: :$f + g: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is a continuous mapping. {{qed}}
:$f + g: \struct {S, \tau_{_S} } \to \struct{R, \tau_{_R} }$ is [[Definition:Continuous Mapping on Set|continuous]].
From {{Corollary|Normed Division Ring Operations are Continuous}}: :$\struct {R, +, *, \tau_{_R} }$ is a [[Definition:Topological Division Ring|topological division ring]]. From [[Sum Rule for Continuous Mappings to Topological Division Ring]]: :$f + g: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is a [[Defin...
Combination Theorem for Continuous Mappings/Normed Division Ring/Sum Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Normed_Division_Ring/Sum_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Normed_Division_Ring/Sum_Rule
[ "Combination Theorem for Continuous Mappings to Normed Division Ring" ]
[ "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Topological Division Ring", "Combination Theorem for Continuous Mappings/Topological Division Ring/Sum Rule", "Definition:Continuous Mapping (Topology)/Set" ]
proofwiki-16304
Combination Theorem for Continuous Mappings/Normed Division Ring/Multiple Rule
:$\lambda * f: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is continuous :$f * \lambda: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is continuous.
From {{Corollary|Normed Division Ring Operations are Continuous}}: :$\struct {R, +, *, \tau_{_R} }$ is a topological division ring. From Multiple Rule for Continuous Mappings to Topological Division Ring: :$\lambda * f, f * \lambda: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ are continuous mappings. {{qed}}
:$\lambda * f: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is [[Definition:Continuous Mapping on Set|continuous]] :$f * \lambda: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is [[Definition:Continuous Mapping on Set|continuous]].
From {{Corollary|Normed Division Ring Operations are Continuous}}: :$\struct {R, +, *, \tau_{_R} }$ is a [[Definition:Topological Division Ring|topological division ring]]. From [[Multiple Rule for Continuous Mappings to Topological Division Ring]]: :$\lambda * f, f * \lambda: \struct {S, \tau_{_S} } \to \struct {R, \...
Combination Theorem for Continuous Mappings/Normed Division Ring/Multiple Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Normed_Division_Ring/Multiple_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Normed_Division_Ring/Multiple_Rule
[ "Combination Theorem for Continuous Mappings to Normed Division Ring" ]
[ "Definition:Continuous Mapping (Topology)/Set", "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Topological Division Ring", "Combination Theorem for Continuous Mappings/Topological Division Ring/Multiple Rule", "Definition:Continuous Mapping (Topology)/Set" ]
proofwiki-16305
Combination Theorem for Continuous Mappings/Normed Division Ring/Product Rule
:$f * g: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is continuous.
From {{Corollary|Normed Division Ring Operations are Continuous}}: :$\struct {R, +, *, \tau_{_R} }$ is a topological division ring. From Product Rule for Continuous Mappings to Topological Division Ring: :$f * g: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is a continuous mapping. {{qed}}
:$f * g: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is [[Definition:Continuous Mapping on Set|continuous]].
From {{Corollary|Normed Division Ring Operations are Continuous}}: :$\struct {R, +, *, \tau_{_R} }$ is a [[Definition:Topological Division Ring|topological division ring]]. From [[Product Rule for Continuous Mappings to Topological Division Ring]]: :$f * g: \struct {S, \tau_{_S} } \to \struct {R, \tau_{_R} }$ is a [[D...
Combination Theorem for Continuous Mappings/Normed Division Ring/Product Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Normed_Division_Ring/Product_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Normed_Division_Ring/Product_Rule
[ "Combination Theorem for Continuous Mappings to Normed Division Ring" ]
[ "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Topological Division Ring", "Combination Theorem for Continuous Mappings/Topological Division Ring/Product Rule", "Definition:Continuous Mapping (Topology)/Set" ]
proofwiki-16306
Combination Theorem for Continuous Mappings/Normed Division Ring/Inverse Rule
:$g^{-1}: \struct {U, \tau_{_U} } \to \struct {R, \tau_{_R} }$ is continuous.
From {{Corollary|Normed Division Ring Operations are Continuous}}: :$\struct {R, +, *, \tau_{_R} }$ is a topological division ring. From Inverse Rule for Continuous Mappings to Topological Division Ring: :$g^{-1}: \struct {U, \tau_{_U} } \to \struct {R, \tau_{_R} }$ is a continuous mapping. {{qed}}
:$g^{-1}: \struct {U, \tau_{_U} } \to \struct {R, \tau_{_R} }$ is [[Definition:Continuous Mapping on Set|continuous]].
From {{Corollary|Normed Division Ring Operations are Continuous}}: :$\struct {R, +, *, \tau_{_R} }$ is a [[Definition:Topological Division Ring|topological division ring]]. From [[Inverse Rule for Continuous Mappings to Topological Division Ring]]: :$g^{-1}: \struct {U, \tau_{_U} } \to \struct {R, \tau_{_R} }$ is a [[...
Combination Theorem for Continuous Mappings/Normed Division Ring/Inverse Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Normed_Division_Ring/Inverse_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Normed_Division_Ring/Inverse_Rule
[ "Combination Theorem for Continuous Mappings to Normed Division Ring" ]
[ "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Topological Division Ring", "Combination Theorem for Continuous Mappings/Topological Division Ring/Inverse Rule", "Definition:Continuous Mapping (Topology)/Set" ]
proofwiki-16307
Definite Integral to Infinity of x by Sine m x over x Squared plus a Squared
:$\ds \int_0^\infty \frac {x \sin m x} {x^2 + a^2} \rd x = \frac \pi 2 e^{-m a}$
From Definite Integral of Even Function: :$\ds \frac 1 2 \int_{-\infty}^\infty \frac {x \sin m x} {x^2 + a^2} \rd x = \int_0^\infty \frac {x \sin m x} {x^2 + a^2} \rd x$ With the aim of integrating over the domain, we split the domain up into $2$ components as follows: Let $R$ be a positive real number with $R > a$. Le...
:$\ds \int_0^\infty \frac {x \sin m x} {x^2 + a^2} \rd x = \frac \pi 2 e^{-m a}$
From [[Definite Integral of Even Function]]: :$\ds \frac 1 2 \int_{-\infty}^\infty \frac {x \sin m x} {x^2 + a^2} \rd x = \int_0^\infty \frac {x \sin m x} {x^2 + a^2} \rd x$ With the aim of integrating over the [[Definition:Domain of Mapping|domain]], we split the [[Definition:Domain of Mapping|domain]] up into $2$ ...
Definite Integral to Infinity of x by Sine m x over x Squared plus a Squared/Proof 1
https://proofwiki.org/wiki/Definite_Integral_to_Infinity_of_x_by_Sine_m_x_over_x_Squared_plus_a_Squared
https://proofwiki.org/wiki/Definite_Integral_to_Infinity_of_x_by_Sine_m_x_over_x_Squared_plus_a_Squared/Proof_1
[ "Definite Integrals involving Sine Function", "Definite Integral to Infinity of x by Sine m x over x Squared plus a Squared" ]
[]
[ "Definite Integral of Even Function", "Definition:Domain (Set Theory)/Mapping", "Definition:Domain (Set Theory)/Mapping", "Definition:Component (Topology)", "Definition:Positive/Real Number", "Definition:Line/Straight Line", "Definition:Circle/Arc", "Definition:Circle/Radius", "Definition:Coordinate...
proofwiki-16308
Definite Integral to Infinity of x by Sine m x over x Squared plus a Squared
:$\ds \int_0^\infty \frac {x \sin m x} {x^2 + a^2} \rd x = \frac \pi 2 e^{-m a}$
From Definite Integral to Infinity of $\dfrac {\cos m x} {x^2 + a^2}$: :$\ds \int_0^\infty \frac {\cos m x} {x^2 + a^2} \rd x = \frac \pi {2 a} e^{-m a}$ We have: {{begin-eqn}} {{eqn | l = \frac \d {\d m} \int_0^\infty \frac {\cos m x} {x^2 + a^2} \rd x | r = \int_0^\infty \frac \partial {\partial m} \paren {\frac {\...
:$\ds \int_0^\infty \frac {x \sin m x} {x^2 + a^2} \rd x = \frac \pi 2 e^{-m a}$
From [[Definite Integral to Infinity of Cosine m x over x Squared plus a Squared|Definite Integral to Infinity of $\dfrac {\cos m x} {x^2 + a^2}$]]: :$\ds \int_0^\infty \frac {\cos m x} {x^2 + a^2} \rd x = \frac \pi {2 a} e^{-m a}$ We have: {{begin-eqn}} {{eqn | l = \frac \d {\d m} \int_0^\infty \frac {\cos m x} {x...
Definite Integral to Infinity of x by Sine m x over x Squared plus a Squared/Proof 2
https://proofwiki.org/wiki/Definite_Integral_to_Infinity_of_x_by_Sine_m_x_over_x_Squared_plus_a_Squared
https://proofwiki.org/wiki/Definite_Integral_to_Infinity_of_x_by_Sine_m_x_over_x_Squared_plus_a_Squared/Proof_2
[ "Definite Integrals involving Sine Function", "Definite Integral to Infinity of x by Sine m x over x Squared plus a Squared" ]
[]
[ "Definite Integral to Infinity of Cosine m x over x Squared plus a Squared", "Definite Integral of Partial Derivative", "Derivative of Cosine Function/Corollary", "Derivative of Exponential Function/Corollary 1" ]
proofwiki-16309
Power Series Expansion for Cosine Integral Function
{{begin-eqn}} {{eqn | l = \map \Ci x | r = -\gamma - \ln x + \sum_{n \mathop = 1}^\infty \paren {-1}^{n + 1} \frac {x^{2 n} } {\paren {2 n} \times \paren {2 n}!} | c = }} {{eqn | r = -\gamma - \ln x + \dfrac {x^2} {2 \cdot 2!} - \dfrac {x^4} {4 \cdot 4!} + \dfrac {x^6} {6 \cdot 6!} - \dfrac {x^8} {8 \cdot ...
{{begin-eqn}} {{eqn | l = \map \Ci x | r = -\gamma - \ln x + \int_0^x \frac {1 - \cos u} u \rd u | c = Characterization of Cosine Integral Function }} {{eqn | r = -\gamma - \ln x + \int_0^x \frac 1 u \paren {1 - \sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {u^{2 n} } {\paren {2 n}!} } \rd u | c = P...
{{begin-eqn}} {{eqn | l = \map \Ci x | r = -\gamma - \ln x + \sum_{n \mathop = 1}^\infty \paren {-1}^{n + 1} \frac {x^{2 n} } {\paren {2 n} \times \paren {2 n}!} | c = }} {{eqn | r = -\gamma - \ln x + \dfrac {x^2} {2 \cdot 2!} - \dfrac {x^4} {4 \cdot 4!} + \dfrac {x^6} {6 \cdot 6!} - \dfrac {x^8} {8 \cdot ...
{{begin-eqn}} {{eqn | l = \map \Ci x | r = -\gamma - \ln x + \int_0^x \frac {1 - \cos u} u \rd u | c = [[Characterization of Cosine Integral Function]] }} {{eqn | r = -\gamma - \ln x + \int_0^x \frac 1 u \paren {1 - \sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {u^{2 n} } {\paren {2 n}!} } \rd u | c...
Power Series Expansion for Cosine Integral Function
https://proofwiki.org/wiki/Power_Series_Expansion_for_Cosine_Integral_Function
https://proofwiki.org/wiki/Power_Series_Expansion_for_Cosine_Integral_Function
[ "Cosine Integral Function", "Examples of Power Series" ]
[]
[ "Characterization of Cosine Integral Function", "Power Series Expansion for Cosine Function", "Power Series is Termwise Integrable within Radius of Convergence", "Primitive of Power" ]
proofwiki-16310
Derivative of Cosine Integral Function
:$\dfrac \d {\d x} \paren {\map \Ci x} = -\dfrac {\cos x} x$
{{begin-eqn}} {{eqn | l = \frac \d {\d x} \paren {\map \Ci x} | r = \frac \d {\d x} \paren {-\gamma - \ln x + \int_0^x \frac {1 - \cos t} t \rd t} | c = Characterization of Cosine Integral Function }} {{eqn | r = -\frac 1 x + \frac 1 x - \frac {\cos x} x | c = Derivative of Constant, Derivative of Natural Logarithm,...
:$\dfrac \d {\d x} \paren {\map \Ci x} = -\dfrac {\cos x} x$
{{begin-eqn}} {{eqn | l = \frac \d {\d x} \paren {\map \Ci x} | r = \frac \d {\d x} \paren {-\gamma - \ln x + \int_0^x \frac {1 - \cos t} t \rd t} | c = [[Characterization of Cosine Integral Function]] }} {{eqn | r = -\frac 1 x + \frac 1 x - \frac {\cos x} x | c = [[Derivative of Constant]], [[Derivative of Natural ...
Derivative of Cosine Integral Function
https://proofwiki.org/wiki/Derivative_of_Cosine_Integral_Function
https://proofwiki.org/wiki/Derivative_of_Cosine_Integral_Function
[ "Cosine Integral Function", "Derivatives" ]
[]
[ "Characterization of Cosine Integral Function", "Derivative of Constant", "Derivative of Natural Logarithm Function", "Fundamental Theorem of Calculus/First Part/Corollary" ]
proofwiki-16311
Derivative of Exponential Integral Function
Let $\Ei: \R_{>0} \to \R$ denote the exponential integral function: :$\map \Ei x = \ds \int_{t \mathop = x}^{t \mathop \to +\infty} \frac {e^{-t} } t \rd t$ Then: :$\dfrac \d {\d x} \paren {\map \Ei x} = -\dfrac {e^{-x} } x$
{{begin-eqn}} {{eqn | l = \map {\frac \d {\d x} } {\map \Ei x} | r = \map {\frac \d {\d x} } {-\gamma - \ln x + \int_0^x \frac {1 - e^{-t} } t \rd t} | c = Characterization of Exponential Integral Function }} {{eqn | r = -\frac 1 x + \frac 1 x - \frac {e^{-x} } x | c = Derivative of Constant, Derivati...
Let $\Ei: \R_{>0} \to \R$ denote the [[Definition:Exponential Integral Function/Formulation 1|exponential integral function]]: :$\map \Ei x = \ds \int_{t \mathop = x}^{t \mathop \to +\infty} \frac {e^{-t} } t \rd t$ Then: :$\dfrac \d {\d x} \paren {\map \Ei x} = -\dfrac {e^{-x} } x$
{{begin-eqn}} {{eqn | l = \map {\frac \d {\d x} } {\map \Ei x} | r = \map {\frac \d {\d x} } {-\gamma - \ln x + \int_0^x \frac {1 - e^{-t} } t \rd t} | c = [[Characterization of Exponential Integral Function/Formulation 1|Characterization of Exponential Integral Function]] }} {{eqn | r = -\frac 1 x + \frac ...
Derivative of Exponential Integral Function
https://proofwiki.org/wiki/Derivative_of_Exponential_Integral_Function
https://proofwiki.org/wiki/Derivative_of_Exponential_Integral_Function
[ "Derivatives", "Exponential Integral Function" ]
[ "Definition:Exponential Integral Function/Formulation 1" ]
[ "Characterization of Exponential Integral Function/Formulation 1", "Derivative of Constant", "Derivative of Natural Logarithm Function", "Fundamental Theorem of Calculus/First Part/Corollary", "Category:Derivatives", "Category:Exponential Integral Function" ]
proofwiki-16312
Derivative of Sine Integral Function
:$\dfrac \d {\d x} \paren {\map \Si x} = \dfrac {\sin x} x$
We have, by the definition of the sine integral function: :$\ds \map \Si x = \int_0^x \frac {\sin t} t \rd t$ By {{Corollary|Fundamental Theorem of Calculus/First Part|disp = Fundamental Theorem of Calculus (First Part)}}, we have: :$\ds \frac \d {\d x} \paren {\map \Si x} = \frac {\sin x} x$ {{qed}}
:$\dfrac \d {\d x} \paren {\map \Si x} = \dfrac {\sin x} x$
We have, by the definition of the [[Definition:Sine Integral Function|sine integral function]]: :$\ds \map \Si x = \int_0^x \frac {\sin t} t \rd t$ By {{Corollary|Fundamental Theorem of Calculus/First Part|disp = Fundamental Theorem of Calculus (First Part)}}, we have: :$\ds \frac \d {\d x} \paren {\map \Si x} = ...
Derivative of Sine Integral Function
https://proofwiki.org/wiki/Derivative_of_Sine_Integral_Function
https://proofwiki.org/wiki/Derivative_of_Sine_Integral_Function
[ "Sine Integral Function", "Derivatives" ]
[]
[ "Definition:Sine Integral Function" ]
proofwiki-16313
Primitive of Cosine Integral Function
:$\ds \int \map \Ci x \rd x = x \map \Ci x + \sin x + C$
By Derivative of Cosine Integral Function, we have: :$\ds \frac \d {\d x} \paren {\map \Ci x} = -\frac {\cos x} x$ So: {{begin-eqn}} {{eqn | l = \int \map \Ci x \rd x | r = \int 1 \times \map \Ci \rd x }} {{eqn | r = x \map \Ci x - \int \paren {-x \frac {\cos x} x} \rd x | c = Integration by Parts }} {{eqn | r = x \...
:$\ds \int \map \Ci x \rd x = x \map \Ci x + \sin x + C$
By [[Derivative of Cosine Integral Function]], we have: :$\ds \frac \d {\d x} \paren {\map \Ci x} = -\frac {\cos x} x$ So: {{begin-eqn}} {{eqn | l = \int \map \Ci x \rd x | r = \int 1 \times \map \Ci \rd x }} {{eqn | r = x \map \Ci x - \int \paren {-x \frac {\cos x} x} \rd x | c = [[Integration by Parts]] }} {{eq...
Primitive of Cosine Integral Function
https://proofwiki.org/wiki/Primitive_of_Cosine_Integral_Function
https://proofwiki.org/wiki/Primitive_of_Cosine_Integral_Function
[ "Primitives", "Cosine Integral Function" ]
[]
[ "Derivative of Cosine Integral Function", "Integration by Parts", "Primitive of Cosine Function", "Category:Primitives", "Category:Cosine Integral Function" ]
proofwiki-16314
Primitive of Exponential Integral Function
Let $\Ei: \R_{>0} \to \R$ denote the exponential integral function: :$\map \Ei x = \ds \int_{t \mathop = x}^{t \mathop \to +\infty} \frac {e^{-t} } t \rd t$ Then: :$\ds \int \map \Ei x \rd x = x \map \Ei x - e^{-x} + C$
By Derivative of Exponential Integral Function, we have: :$\ds \frac \d {\d x} \paren {\map \Ei x} = -\frac {e^{-x} } x$ So: {{begin-eqn}} {{eqn | l = \int \map \Ei x \rd x | r = \int 1 \times \map \Ei x \rd x }} {{eqn | r = x \map \Ei x - \int \paren {-x \frac {e^{-x} } x} \rd x | c = Integration by Part...
Let $\Ei: \R_{>0} \to \R$ denote the [[Definition:Exponential Integral Function/Formulation 1|exponential integral function]]: :$\map \Ei x = \ds \int_{t \mathop = x}^{t \mathop \to +\infty} \frac {e^{-t} } t \rd t$ Then: :$\ds \int \map \Ei x \rd x = x \map \Ei x - e^{-x} + C$
By [[Derivative of Exponential Integral Function]], we have: :$\ds \frac \d {\d x} \paren {\map \Ei x} = -\frac {e^{-x} } x$ So: {{begin-eqn}} {{eqn | l = \int \map \Ei x \rd x | r = \int 1 \times \map \Ei x \rd x }} {{eqn | r = x \map \Ei x - \int \paren {-x \frac {e^{-x} } x} \rd x | c = [[Integratio...
Primitive of Exponential Integral Function
https://proofwiki.org/wiki/Primitive_of_Exponential_Integral_Function
https://proofwiki.org/wiki/Primitive_of_Exponential_Integral_Function
[ "Primitives", "Exponential Integral Function" ]
[ "Definition:Exponential Integral Function/Formulation 1" ]
[ "Derivative of Exponential Integral Function", "Integration by Parts", "Primitive of Exponential of a x", "Category:Primitives", "Category:Exponential Integral Function" ]
proofwiki-16315
Direct Image Mapping of Domain is Image Set of Mapping
Let $S$ and $T$ be sets. Let $\powerset S$ and $\powerset T$ be their power sets. Let $f \subseteq S \times T$ be a mapping from $S$ to $T$. Let $f^\to: \powerset S \to \powerset T$ be the direct image mapping of $f$: :$\forall X \in \powerset S: \map {f^\to} X = \begin {cases} \set {t \in T: \exists s \in X: \map f s ...
{{begin-eqn}} {{eqn | l = y | o = \in | r = \map {f^\to} S | c = }} {{eqn | ll= \leadstoandfrom | q = \exists x \in S | l = \map f x | r = y | c = {{Defof|Direct Image Mapping of Mapping}} }} {{eqn | ll= \leadstoandfrom | l = y | o = \in | r = \Img f | ...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $\powerset S$ and $\powerset T$ be their [[Definition:Power Set|power sets]]. Let $f \subseteq S \times T$ be a [[Definition:Mapping|mapping]] from $S$ to $T$. Let $f^\to: \powerset S \to \powerset T$ be the [[Definition:Direct Image Mapping of Mapping|direct image map...
{{begin-eqn}} {{eqn | l = y | o = \in | r = \map {f^\to} S | c = }} {{eqn | ll= \leadstoandfrom | q = \exists x \in S | l = \map f x | r = y | c = {{Defof|Direct Image Mapping of Mapping}} }} {{eqn | ll= \leadstoandfrom | l = y | o = \in | r = \Img f | ...
Direct Image Mapping of Domain is Image Set of Mapping
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Domain_is_Image_Set_of_Mapping
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Domain_is_Image_Set_of_Mapping
[ "Direct Image Mappings" ]
[ "Definition:Set", "Definition:Power Set", "Definition:Mapping", "Definition:Direct Image Mapping/Mapping", "Definition:Image (Set Theory)/Mapping/Mapping" ]
[ "Category:Direct Image Mappings" ]
proofwiki-16316
Direct Image Mapping of Domain is Image Set of Relation
Let $S$ and $T$ be sets. Let $\powerset S$ and $\powerset T$ be their power sets. Let $\RR \subseteq S \times T$ be a relation on $S \times T$. Let $\RR^\to: \powerset S \to \powerset T$ be the direct image mapping of $\RR$: :$\forall X \in \powerset S: \map {\RR^\to} X = \begin {cases} \set {t \in T: \exists s \in X: ...
{{begin-eqn}} {{eqn | l = y | o = \in | r = \map {\RR^\to} {\Dom \RR} | c = }} {{eqn | ll= \leadstoandfrom | q = \exists x \in S | l = \tuple {x, y} | o = \in | r = \RR | c = {{Defof|Direct Image Mapping of Mapping}} }} {{eqn | ll= \leadstoandfrom | l = y | o...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $\powerset S$ and $\powerset T$ be their [[Definition:Power Set|power sets]]. Let $\RR \subseteq S \times T$ be a [[Definition:Relation|relation]] on $S \times T$. Let $\RR^\to: \powerset S \to \powerset T$ be the [[Definition:Direct Image Mapping of Relation|direct im...
{{begin-eqn}} {{eqn | l = y | o = \in | r = \map {\RR^\to} {\Dom \RR} | c = }} {{eqn | ll= \leadstoandfrom | q = \exists x \in S | l = \tuple {x, y} | o = \in | r = \RR | c = {{Defof|Direct Image Mapping of Mapping}} }} {{eqn | ll= \leadstoandfrom | l = y | o...
Direct Image Mapping of Domain is Image Set of Relation
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Domain_is_Image_Set_of_Relation
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Domain_is_Image_Set_of_Relation
[ "Direct Image Mappings" ]
[ "Definition:Set", "Definition:Power Set", "Definition:Relation", "Definition:Direct Image Mapping/Relation", "Definition:Domain (Set Theory)/Relation", "Definition:Image (Set Theory)/Relation/Relation" ]
[ "Category:Direct Image Mappings" ]
proofwiki-16317
Inverse Image Mapping of Codomain is Preimage Set of Mapping
Let $S$ and $T$ be sets. Let $\powerset S$ and $\powerset T$ be their power sets. Let $f \subseteq S \times T$ be a mapping from $S$ to $T$. Let $f^\gets: \powerset T \to \powerset S$ be the inverse image mapping of $f$: :$\forall Y \in \powerset T: \map {f^\gets} Y = \begin {cases} \set {s \in S: \exists t \in Y: \map...
{{begin-eqn}} {{eqn | l = x | o = \in | r = \map {f^\gets} T | c = }} {{eqn | ll= \leadstoandfrom | q = \exists y \in T | l = \map f x | r = y | c = {{Defof|Inverse Image Mapping of Mapping}} }} {{eqn | ll= \leadstoandfrom | l = x | o = \in | r = \Preimg f ...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $\powerset S$ and $\powerset T$ be their [[Definition:Power Set|power sets]]. Let $f \subseteq S \times T$ be a [[Definition:Mapping|mapping]] from $S$ to $T$. Let $f^\gets: \powerset T \to \powerset S$ be the [[Definition:Inverse Image Mapping of Mapping|inverse image...
{{begin-eqn}} {{eqn | l = x | o = \in | r = \map {f^\gets} T | c = }} {{eqn | ll= \leadstoandfrom | q = \exists y \in T | l = \map f x | r = y | c = {{Defof|Inverse Image Mapping of Mapping}} }} {{eqn | ll= \leadstoandfrom | l = x | o = \in | r = \Preimg f ...
Inverse Image Mapping of Codomain is Preimage Set of Mapping
https://proofwiki.org/wiki/Inverse_Image_Mapping_of_Codomain_is_Preimage_Set_of_Mapping
https://proofwiki.org/wiki/Inverse_Image_Mapping_of_Codomain_is_Preimage_Set_of_Mapping
[ "Inverse Image Mappings" ]
[ "Definition:Set", "Definition:Power Set", "Definition:Mapping", "Definition:Inverse Image Mapping/Mapping", "Definition:Preimage/Mapping/Mapping" ]
[ "Category:Inverse Image Mappings" ]
proofwiki-16318
Inverse Image Mapping of Codomain is Preimage Set of Relation
Let $S$ and $T$ be sets. Let $\powerset S$ and $\powerset T$ be their power sets. Let $\RR \subseteq S \times T$ be a relation on $S \times T$. Let $\RR^\gets: \powerset T \to \powerset S$ be the inverse image mapping of $\RR$: :$\forall X \in \powerset S: \map {\RR^\to} X = \begin {cases} \set {t \in T: \exists s \in ...
{{begin-eqn}} {{eqn | l = x | o = \in | r = \map {\RR^\gets} T | c = }} {{eqn | ll= \leadstoandfrom | q = \exists x \in S | l = \tuple {x, y} | o = \in | r = \RR | c = {{Defof|Inverse Image Mapping of Mapping}} }} {{eqn | ll= \leadstoandfrom | l = x | o = \in...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $\powerset S$ and $\powerset T$ be their [[Definition:Power Set|power sets]]. Let $\RR \subseteq S \times T$ be a [[Definition:Relation|relation]] on $S \times T$. Let $\RR^\gets: \powerset T \to \powerset S$ be the [[Definition:Inverse Image Mapping of Relation|invers...
{{begin-eqn}} {{eqn | l = x | o = \in | r = \map {\RR^\gets} T | c = }} {{eqn | ll= \leadstoandfrom | q = \exists x \in S | l = \tuple {x, y} | o = \in | r = \RR | c = {{Defof|Inverse Image Mapping of Mapping}} }} {{eqn | ll= \leadstoandfrom | l = x | o = \in...
Inverse Image Mapping of Codomain is Preimage Set of Relation
https://proofwiki.org/wiki/Inverse_Image_Mapping_of_Codomain_is_Preimage_Set_of_Relation
https://proofwiki.org/wiki/Inverse_Image_Mapping_of_Codomain_is_Preimage_Set_of_Relation
[ "Inverse Image Mappings" ]
[ "Definition:Set", "Definition:Power Set", "Definition:Relation", "Definition:Inverse Image Mapping/Relation", "Definition:Preimage/Relation/Relation" ]
[ "Category:Inverse Image Mappings" ]
proofwiki-16319
Direct Image Mapping of Mapping is Mapping
Let $S$ and $T$ be sets. Let $f: S \to T$ be a mapping on $S \times T$. Let $f^\to: \powerset S \to \powerset T$ be the direct image mapping of $f$: :$\forall X \in \powerset S: \map {f^\to} X = \set {t \in T: \exists s \in X: \map f s = t}$ Then $f^\to$ is indeed a mapping.
$f$, being a mapping, is also a relation. Hence Direct Image Mapping of Relation is Mapping can be applied directly. {{qed}}
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ be a [[Definition:Mapping|mapping]] on $S \times T$. Let $f^\to: \powerset S \to \powerset T$ be the [[Definition:Direct Image Mapping of Mapping|direct image mapping]] of $f$: :$\forall X \in \powerset S: \map {f^\to} X = \set {t \in T: \exists s \in X: \...
$f$, being a [[Definition:Mapping|mapping]], is also a [[Definition:Relation|relation]]. Hence [[Direct Image Mapping of Relation is Mapping]] can be applied directly. {{qed}}
Direct Image Mapping of Mapping is Mapping
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Mapping_is_Mapping
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Mapping_is_Mapping
[ "Direct Image Mappings" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Direct Image Mapping/Mapping", "Definition:Mapping" ]
[ "Definition:Mapping", "Definition:Relation", "Direct Image Mapping of Relation is Mapping" ]
proofwiki-16320
Inverse Image Mapping of Mapping is Mapping
Let $S$ and $T$ be sets. Let $f: S \to T$ be a mapping from $S$ to $T$. Let $f^\gets$ be the inverse image mapping of $f$: :$f^\gets: \powerset T \to \powerset S: \map {f^\gets} Y = f^{-1} \sqbrk Y$ Then $f^\gets$ is indeed a mapping.
$f^{-1}$ is a relation. So Inverse Image Mapping of Relation is Mapping applies directly. {{qed}}
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ be a [[Definition:Mapping|mapping]] from $S$ to $T$. Let $f^\gets$ be the [[Definition:Inverse Image Mapping of Mapping|inverse image mapping]] of $f$: :$f^\gets: \powerset T \to \powerset S: \map {f^\gets} Y = f^{-1} \sqbrk Y$ Then $f^\gets$ is indeed ...
$f^{-1}$ is a [[Definition:Relation|relation]]. So [[Inverse Image Mapping of Relation is Mapping]] applies directly. {{qed}}
Inverse Image Mapping of Mapping is Mapping
https://proofwiki.org/wiki/Inverse_Image_Mapping_of_Mapping_is_Mapping
https://proofwiki.org/wiki/Inverse_Image_Mapping_of_Mapping_is_Mapping
[ "Inverse Image Mappings" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Inverse Image Mapping/Mapping", "Definition:Mapping" ]
[ "Definition:Relation", "Inverse Image Mapping of Relation is Mapping" ]
proofwiki-16321
Direct Image Mapping of Mapping is Empty iff Argument is Empty
Let $S$ and $T$ be sets. Let $f: S \to T$ be a mapping from $S$ to $T$. Let $f^\to$ be the direct image mapping of $f$: :$f^\to: \powerset S \to \powerset T: \map {f^\to} X = \set {t \in T: \exists s \in X: \map f s = t}$ Then: :$\map {f^\to} X = \O \iff X = \O$
By definition, a mapping is a left-total relation. The result then follows from Direct Image Mapping of Left-Total Relation is Empty iff Argument is Empty. {{qed}}
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ be a [[Definition:Mapping|mapping]] from $S$ to $T$. Let $f^\to$ be the [[Definition:Direct Image Mapping of Mapping|direct image mapping]] of $f$: :$f^\to: \powerset S \to \powerset T: \map {f^\to} X = \set {t \in T: \exists s \in X: \map f s = t}$ The...
By definition, a [[Definition:Mapping|mapping]] is a [[Definition:Left-Total Relation|left-total relation]]. The result then follows from [[Direct Image Mapping of Left-Total Relation is Empty iff Argument is Empty]]. {{qed}}
Direct Image Mapping of Mapping is Empty iff Argument is Empty
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Mapping_is_Empty_iff_Argument_is_Empty
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Mapping_is_Empty_iff_Argument_is_Empty
[ "Direct Image Mappings" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Direct Image Mapping/Mapping" ]
[ "Definition:Mapping", "Definition:Left-Total Relation", "Direct Image Mapping of Left-Total Relation is Empty iff Argument is Empty" ]
proofwiki-16322
Derivative of Fresnel Sine Integral Function
:$\dfrac {\d \mathrm S} {\d x} = \sqrt {\dfrac 2 \pi} \sin x^2$
We have, by the definition of the Fresnel sine integral function: :$\ds \map {\mathrm S} x = \sqrt {\frac 2 \pi} \int_0^x \sin u^2 \rd u$ By Fundamental Theorem of Calculus (First Part): Corollary, we therefore have: :$\dfrac {\d \mathrm S} {\d x} = \sqrt {\dfrac 2 \pi} \sin x^2$ {{qed}} Category:Fresnel Sine Integral ...
:$\dfrac {\d \mathrm S} {\d x} = \sqrt {\dfrac 2 \pi} \sin x^2$
We have, by the definition of the [[Definition:Fresnel Sine Integral Function|Fresnel sine integral function]]: :$\ds \map {\mathrm S} x = \sqrt {\frac 2 \pi} \int_0^x \sin u^2 \rd u$ By [[Fundamental Theorem of Calculus/First Part/Corollary|Fundamental Theorem of Calculus (First Part): Corollary]], we therefore have...
Derivative of Fresnel Sine Integral Function
https://proofwiki.org/wiki/Derivative_of_Fresnel_Sine_Integral_Function
https://proofwiki.org/wiki/Derivative_of_Fresnel_Sine_Integral_Function
[ "Fresnel Sine Integral Function", "Derivatives" ]
[]
[ "Definition:Fresnel Integral/Sine", "Fundamental Theorem of Calculus/First Part/Corollary", "Category:Fresnel Sine Integral Function", "Category:Derivatives" ]
proofwiki-16323
Derivative of Fresnel Cosine Integral Function
:$\dfrac {\d \mathrm C} {\d x} = \sqrt {\dfrac 2 \pi} \cos x^2$
We have, by the definition of the Fresnel cosine integral function: :$\ds \map {\mathrm C} x = \sqrt {\dfrac 2 \pi} \int_0^x \cos u^2 \rd u$ By Fundamental Theorem of Calculus (First Part): Corollary, we therefore have: :$\dfrac {\d \mathrm C} {\d x} = \sqrt {\dfrac 2 \pi} \cos x^2$ {{qed}} Category:Fresnel Cosine Inte...
:$\dfrac {\d \mathrm C} {\d x} = \sqrt {\dfrac 2 \pi} \cos x^2$
We have, by the definition of the [[Definition:Fresnel Cosine Integral Function|Fresnel cosine integral function]]: :$\ds \map {\mathrm C} x = \sqrt {\dfrac 2 \pi} \int_0^x \cos u^2 \rd u$ By [[Fundamental Theorem of Calculus/First Part/Corollary|Fundamental Theorem of Calculus (First Part): Corollary]], we therefore...
Derivative of Fresnel Cosine Integral Function
https://proofwiki.org/wiki/Derivative_of_Fresnel_Cosine_Integral_Function
https://proofwiki.org/wiki/Derivative_of_Fresnel_Cosine_Integral_Function
[ "Fresnel Cosine Integral Function", "Derivatives" ]
[]
[ "Definition:Fresnel Integral/Cosine", "Fundamental Theorem of Calculus/First Part/Corollary", "Category:Fresnel Cosine Integral Function", "Category:Derivatives" ]
proofwiki-16324
Power Series Expansion for Fresnel Sine Integral Function
{{begin-eqn}} {{eqn | l = \map {\operatorname S} x | r = \sqrt {\frac 2 \pi} \sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {x^{4 n + 3} } {\paren {4 n + 3} \paren {2 n + 1}!} | c = }} {{eqn | r = \sqrt {\frac 2 \pi} \paren {\dfrac {x^3} {3 \cdot 1!} - \dfrac {x^7} {7 \cdot 3!} + \dfrac {x^{11} } {11 \cdo...
{{begin-eqn}} {{eqn | l = \map {\operatorname S} x | r = \sqrt {\frac 2 \pi} \int_0^x \sin u^2 \rd u | c = {{Defof|Fresnel Sine Integral Function}} }} {{eqn | r = \sqrt {\frac 2 \pi} \int_0^x \paren {\sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {\paren {u^2}^{2 n + 1} } {\paren {2 n + 1}!} } \rd u ...
{{begin-eqn}} {{eqn | l = \map {\operatorname S} x | r = \sqrt {\frac 2 \pi} \sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {x^{4 n + 3} } {\paren {4 n + 3} \paren {2 n + 1}!} | c = }} {{eqn | r = \sqrt {\frac 2 \pi} \paren {\dfrac {x^3} {3 \cdot 1!} - \dfrac {x^7} {7 \cdot 3!} + \dfrac {x^{11} } {11 \cdo...
{{begin-eqn}} {{eqn | l = \map {\operatorname S} x | r = \sqrt {\frac 2 \pi} \int_0^x \sin u^2 \rd u | c = {{Defof|Fresnel Sine Integral Function}} }} {{eqn | r = \sqrt {\frac 2 \pi} \int_0^x \paren {\sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {\paren {u^2}^{2 n + 1} } {\paren {2 n + 1}!} } \rd u ...
Power Series Expansion for Fresnel Sine Integral Function
https://proofwiki.org/wiki/Power_Series_Expansion_for_Fresnel_Sine_Integral_Function
https://proofwiki.org/wiki/Power_Series_Expansion_for_Fresnel_Sine_Integral_Function
[ "Fresnel Sine Integral Function", "Examples of Power Series" ]
[]
[ "Power Series Expansion for Sine Function", "Power Series is Termwise Integrable within Radius of Convergence", "Primitive of Power" ]
proofwiki-16325
Power Series Expansion for Fresnel Cosine Integral Function
{{begin-eqn}} {{eqn | l = \map {\operatorname C} x | r = \sqrt {\frac 2 \pi} \sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {x^{4 n + 1} } {\paren {4 n + 1} \paren {2 n}!} | c = }} {{eqn | r = \sqrt {\frac 2 \pi} \paren {\dfrac x {1!} - \dfrac {x^5} {5 \cdot 2!} + \dfrac {x^9} {9 \cdot 4!} - \dfrac {x^{13...
{{begin-eqn}} {{eqn | l = \map {\operatorname C} x | r = \sqrt {\frac 2 \pi} \int_0^x \cos u^2 \rd u | c = {{Defof|Fresnel Cosine Integral Function}} }} {{eqn | r = \sqrt {\frac 2 \pi} \int_0^x \paren {\sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {\paren {u^2}^{2 n} } {\paren {2 n}!} } \rd u | c =...
{{begin-eqn}} {{eqn | l = \map {\operatorname C} x | r = \sqrt {\frac 2 \pi} \sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {x^{4 n + 1} } {\paren {4 n + 1} \paren {2 n}!} | c = }} {{eqn | r = \sqrt {\frac 2 \pi} \paren {\dfrac x {1!} - \dfrac {x^5} {5 \cdot 2!} + \dfrac {x^9} {9 \cdot 4!} - \dfrac {x^{13...
{{begin-eqn}} {{eqn | l = \map {\operatorname C} x | r = \sqrt {\frac 2 \pi} \int_0^x \cos u^2 \rd u | c = {{Defof|Fresnel Cosine Integral Function}} }} {{eqn | r = \sqrt {\frac 2 \pi} \int_0^x \paren {\sum_{n \mathop = 0}^\infty \paren {-1}^n \frac {\paren {u^2}^{2 n} } {\paren {2 n}!} } \rd u | c =...
Power Series Expansion for Fresnel Cosine Integral Function
https://proofwiki.org/wiki/Power_Series_Expansion_for_Fresnel_Cosine_Integral_Function
https://proofwiki.org/wiki/Power_Series_Expansion_for_Fresnel_Cosine_Integral_Function
[ "Fresnel Cosine Integral Function", "Examples of Power Series" ]
[]
[ "Power Series Expansion for Cosine Function", "Power Series is Termwise Integrable within Radius of Convergence", "Primitive of Power" ]
proofwiki-16326
Fresnel Sine Integral Function is Odd
:$\map {\operatorname S} {-x} = -\map {\operatorname S} x$
{{begin-eqn}} {{eqn | l = \map {\operatorname S} {-x} | r = \sqrt {\frac 2 \pi} \int_0^{-x} \sin u^2 \rd u | c = {{Defof|Fresnel Sine Integral Function}} }} {{eqn | r = -\sqrt {\frac 2 \pi} \int_0^{-\paren {-x} } \map \sin {\paren {-u}^2} \rd u | c = substituting $u \mapsto -u$ }} {{eqn | r = -\sqrt {...
:$\map {\operatorname S} {-x} = -\map {\operatorname S} x$
{{begin-eqn}} {{eqn | l = \map {\operatorname S} {-x} | r = \sqrt {\frac 2 \pi} \int_0^{-x} \sin u^2 \rd u | c = {{Defof|Fresnel Sine Integral Function}} }} {{eqn | r = -\sqrt {\frac 2 \pi} \int_0^{-\paren {-x} } \map \sin {\paren {-u}^2} \rd u | c = [[Integration by Substitution|substituting]] $u \ma...
Fresnel Sine Integral Function is Odd
https://proofwiki.org/wiki/Fresnel_Sine_Integral_Function_is_Odd
https://proofwiki.org/wiki/Fresnel_Sine_Integral_Function_is_Odd
[ "Fresnel Sine Integral Function", "Examples of Odd Functions" ]
[]
[ "Integration by Substitution" ]
proofwiki-16327
Fresnel Sine Integral Function of Zero
:$\map {\operatorname S} 0 = 0$
By Fresnel Sine Integral Function is Odd, $\operatorname S$ is an odd function. Therefore, by Odd Function of Zero is Zero: :$\map {\operatorname S} 0 = 0$ {{qed}}
:$\map {\operatorname S} 0 = 0$
By [[Fresnel Sine Integral Function is Odd]], $\operatorname S$ is an [[Definition:Odd Function|odd function]]. Therefore, by [[Odd Function of Zero is Zero]]: :$\map {\operatorname S} 0 = 0$ {{qed}}
Fresnel Sine Integral Function of Zero
https://proofwiki.org/wiki/Fresnel_Sine_Integral_Function_of_Zero
https://proofwiki.org/wiki/Fresnel_Sine_Integral_Function_of_Zero
[ "Fresnel Sine Integral Function" ]
[]
[ "Fresnel Sine Integral Function is Odd", "Definition:Odd Function", "Odd Function of Zero is Zero" ]
proofwiki-16328
Limit to Infinity of Fresnel Sine Integral Function
:$\ds \lim_{x \mathop \to \infty} \map {\mathrm S} x = \frac 1 2$
{{begin-eqn}} {{eqn | l = \lim_{x \mathop \to \infty} \map {\mathrm S} x | r = \sqrt {\frac 2 \pi} \lim_{x \mathop \to \infty} \int_0^x \sin u^2 \rd u | c = Multiple Rule for Limits of Real Functions, {{Defof|Fresnel Sine Integral Function}} }} {{eqn | r = \sqrt {\frac 2 \pi} \int_0^\infty \sin u^2 \rd u }}...
:$\ds \lim_{x \mathop \to \infty} \map {\mathrm S} x = \frac 1 2$
{{begin-eqn}} {{eqn | l = \lim_{x \mathop \to \infty} \map {\mathrm S} x | r = \sqrt {\frac 2 \pi} \lim_{x \mathop \to \infty} \int_0^x \sin u^2 \rd u | c = [[Multiple Rule for Limits of Real Functions]], {{Defof|Fresnel Sine Integral Function}} }} {{eqn | r = \sqrt {\frac 2 \pi} \int_0^\infty \sin u^2 \rd ...
Limit to Infinity of Fresnel Sine Integral Function
https://proofwiki.org/wiki/Limit_to_Infinity_of_Fresnel_Sine_Integral_Function
https://proofwiki.org/wiki/Limit_to_Infinity_of_Fresnel_Sine_Integral_Function
[ "Fresnel Sine Integral Function" ]
[]
[ "Combination Theorem for Limits of Functions/Real/Multiple Rule", "Definite Integral to Infinity of Sine of a x^2" ]
proofwiki-16329
Asymptotic Expansion for Fresnel Sine Integral Function
:$\map {\operatorname S} x \sim \dfrac 1 2 - \dfrac 1 {\sqrt {2 \pi} } \paren {\map \cos {x^2} \paren {\dfrac 1 x - \dfrac {1 \times 3} {2^2 x^5} + \dfrac {1 \times 3 \times 5 \times 7} {2^4 x^9} - \ldots} + \map \sin {x^2} \paren {\dfrac 1 {2 x^3} - \dfrac {1 \times 3 \times 5} {2^3 x^7} + \ldots} }$
{{ProofWanted|also establish general term and write sums with $\sum$}}
:$\map {\operatorname S} x \sim \dfrac 1 2 - \dfrac 1 {\sqrt {2 \pi} } \paren {\map \cos {x^2} \paren {\dfrac 1 x - \dfrac {1 \times 3} {2^2 x^5} + \dfrac {1 \times 3 \times 5 \times 7} {2^4 x^9} - \ldots} + \map \sin {x^2} \paren {\dfrac 1 {2 x^3} - \dfrac {1 \times 3 \times 5} {2^3 x^7} + \ldots} }$
{{ProofWanted|also establish general term and write sums with $\sum$}}
Asymptotic Expansion for Fresnel Sine Integral Function
https://proofwiki.org/wiki/Asymptotic_Expansion_for_Fresnel_Sine_Integral_Function
https://proofwiki.org/wiki/Asymptotic_Expansion_for_Fresnel_Sine_Integral_Function
[ "Fresnel Sine Integral Function", "Asymptotic Expansions" ]
[]
[]
proofwiki-16330
Fresnel Cosine Integral Function is Odd
:$\map {\operatorname C} {-x} = -\map {\operatorname C} x$
{{begin-eqn}} {{eqn | l = \map {\operatorname C} {-x} | r = \sqrt {\frac 2 \pi} \int_0^{-x} \cos u^2 \rd u | c = {{Defof|Fresnel Cosine Integral Function}} }} {{eqn | r = -\sqrt {\frac 2 \pi} \int_0^{-\paren {-x} } \map \cos {\paren {-u}^2} \rd u | c = substituting $u \mapsto -u$ }} {{eqn | r = -\sqrt...
:$\map {\operatorname C} {-x} = -\map {\operatorname C} x$
{{begin-eqn}} {{eqn | l = \map {\operatorname C} {-x} | r = \sqrt {\frac 2 \pi} \int_0^{-x} \cos u^2 \rd u | c = {{Defof|Fresnel Cosine Integral Function}} }} {{eqn | r = -\sqrt {\frac 2 \pi} \int_0^{-\paren {-x} } \map \cos {\paren {-u}^2} \rd u | c = [[Integration by Substitution|substituting]] $u \...
Fresnel Cosine Integral Function is Odd
https://proofwiki.org/wiki/Fresnel_Cosine_Integral_Function_is_Odd
https://proofwiki.org/wiki/Fresnel_Cosine_Integral_Function_is_Odd
[ "Fresnel Cosine Integral Function", "Examples of Odd Functions" ]
[]
[ "Integration by Substitution" ]
proofwiki-16331
Fresnel Cosine Integral Function of Zero
:$\map {\operatorname C} 0 = 0$
By Fresnel Cosine Integral Function is Odd, $\operatorname C$ is an odd function. Therefore, by Odd Function of Zero is Zero: :$\map {\operatorname C} 0 = 0$ {{qed}}
:$\map {\operatorname C} 0 = 0$
By [[Fresnel Cosine Integral Function is Odd]], $\operatorname C$ is an [[Definition:Odd Function|odd function]]. Therefore, by [[Odd Function of Zero is Zero]]: :$\map {\operatorname C} 0 = 0$ {{qed}}
Fresnel Cosine Integral Function of Zero
https://proofwiki.org/wiki/Fresnel_Cosine_Integral_Function_of_Zero
https://proofwiki.org/wiki/Fresnel_Cosine_Integral_Function_of_Zero
[ "Fresnel Cosine Integral Function" ]
[]
[ "Fresnel Cosine Integral Function is Odd", "Definition:Odd Function", "Odd Function of Zero is Zero" ]
proofwiki-16332
Direct Image Mapping of Left-Total Relation is Empty iff Argument is Empty
Let $S$ and $T$ be sets. Let $\RR: S \to T$ be a left-total relation on $S \times T$. Let $\RR^\to$ be the direct image mapping of $\RR$: :$\RR^\to: \powerset S \to \powerset T: \map {\RR^\to} X = \set {t \in T: \exists s \in X: \tuple {s, t} \in \RR}$ Then: :$\map {\RR^\to} X = \O \iff X = \O$
=== Sufficient Condition === Let $\map {\RR^\to} X = \O$. By definition of direct image mapping: :$\set {t \in T: \exists s \in X: \tuple {s, t} \in \RR} = \O$ That is: :$\neg \exists s \in X: \tuple {s, t} \in \RR$ But as $\RR$ is a left-total relation: :$\forall s \in X: \exists t \in T: \tuple {s, t} \in \RR$ Thus: ...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $\RR: S \to T$ be a [[Definition:Left-Total Relation|left-total relation]] on $S \times T$. Let $\RR^\to$ be the [[Definition:Direct Image Mapping of Relation|direct image mapping]] of $\RR$: :$\RR^\to: \powerset S \to \powerset T: \map {\RR^\to} X = \set {t \in T: \e...
=== Sufficient Condition === Let $\map {\RR^\to} X = \O$. By definition of [[Definition:Direct Image Mapping of Relation|direct image mapping]]: :$\set {t \in T: \exists s \in X: \tuple {s, t} \in \RR} = \O$ That is: :$\neg \exists s \in X: \tuple {s, t} \in \RR$ But as $\RR$ is a [[Definition:Left-Total Relation|l...
Direct Image Mapping of Left-Total Relation is Empty iff Argument is Empty
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Left-Total_Relation_is_Empty_iff_Argument_is_Empty
https://proofwiki.org/wiki/Direct_Image_Mapping_of_Left-Total_Relation_is_Empty_iff_Argument_is_Empty
[ "Direct Image Mappings" ]
[ "Definition:Set", "Definition:Left-Total Relation", "Definition:Direct Image Mapping/Relation" ]
[ "Definition:Direct Image Mapping/Relation", "Definition:Left-Total Relation", "Definition:Direct Image Mapping/Relation" ]
proofwiki-16333
Limit to Infinity of Fresnel Cosine Integral Function
:$\ds \lim_{x \mathop \to \infty} \map {\mathrm C} x = \frac 1 2$
{{begin-eqn}} {{eqn | l = \lim_{x \mathop \to \infty} \map {\mathrm C} x | r = \sqrt {\frac 2 \pi} \lim_{x \mathop \to \infty} \int_0^x \cos u^2 \rd u | c = Multiple Rule for Limits of Real Functions, {{Defof|Fresnel Cosine Integral Function}} }} {{eqn | r = \sqrt {\frac 2 \pi} \int_0^\infty \cos u^2 \rd u ...
:$\ds \lim_{x \mathop \to \infty} \map {\mathrm C} x = \frac 1 2$
{{begin-eqn}} {{eqn | l = \lim_{x \mathop \to \infty} \map {\mathrm C} x | r = \sqrt {\frac 2 \pi} \lim_{x \mathop \to \infty} \int_0^x \cos u^2 \rd u | c = [[Multiple Rule for Limits of Real Functions]], {{Defof|Fresnel Cosine Integral Function}} }} {{eqn | r = \sqrt {\frac 2 \pi} \int_0^\infty \cos u^2 \r...
Limit to Infinity of Fresnel Cosine Integral Function
https://proofwiki.org/wiki/Limit_to_Infinity_of_Fresnel_Cosine_Integral_Function
https://proofwiki.org/wiki/Limit_to_Infinity_of_Fresnel_Cosine_Integral_Function
[ "Fresnel Cosine Integral Function" ]
[]
[ "Combination Theorem for Limits of Functions/Real/Multiple Rule", "Definite Integral to Infinity of Cosine of a x^2" ]
proofwiki-16334
Successor Mapping on Natural Numbers is not Surjection
Let $f: \N \to \N$ be the successor mapping on the natural numbers $\N$: :$\forall n \in \N: \map f n = n + 1$ Then $f$ is not a surjection.
There exists no $n \in \N$ such that $n + 1 = 0$. Thus $\map f 0$ has no preimage. The result follows by definition of surjection. {{qed}}
Let $f: \N \to \N$ be the [[Definition:Successor Mapping on Natural Numbers|successor mapping]] on the [[Definition:Natural Numbers|natural numbers]] $\N$: :$\forall n \in \N: \map f n = n + 1$ Then $f$ is not a [[Definition:Surjection|surjection]].
There exists no $n \in \N$ such that $n + 1 = 0$. Thus $\map f 0$ has no [[Definition:Preimage of Element under Mapping|preimage]]. The result follows by definition of [[Definition:Surjection|surjection]]. {{qed}}
Successor Mapping on Natural Numbers is not Surjection
https://proofwiki.org/wiki/Successor_Mapping_on_Natural_Numbers_is_not_Surjection
https://proofwiki.org/wiki/Successor_Mapping_on_Natural_Numbers_is_not_Surjection
[ "Surjections" ]
[ "Definition:Successor Mapping on Natural Numbers", "Definition:Natural Numbers", "Definition:Surjection" ]
[ "Definition:Preimage/Mapping/Element", "Definition:Surjection" ]
proofwiki-16335
Composition of Direct Image Mappings of Mappings
Let $A, B, C$ be non-empty sets. Let $f: A \to B$ and $g: B \to C$ be mappings. Let: :$f^\to: \powerset A \to \powerset B$ and :$g^\to: \powerset B \to \powerset C$ be the direct image mappings of $f$ and $g$. Then: :$\paren {g \circ f}^\to = g^\to \circ f^\to$
Let $S \subseteq A$ such that $S \ne \O$. Then: {{begin-eqn}} {{eqn | l = \map {\paren {g^\to \circ f^\to} } S | r = \map {g^\to} {\map {f^\to} S} | c = }} {{eqn | r = \set {\map g x: x \in \map {f^\to} S} | c = }} {{eqn | r = \set {\map g x: \exists y \in S: x = \map f y} | c = }} {{eqn | r ...
Let $A, B, C$ be [[Definition:Non-Empty Set|non-empty]] [[Definition:Set|sets]]. Let $f: A \to B$ and $g: B \to C$ be [[Definition:Mapping|mappings]]. Let: :$f^\to: \powerset A \to \powerset B$ and :$g^\to: \powerset B \to \powerset C$ be the [[Definition:Direct Image Mapping of Mapping|direct image mappings]] of $f...
Let $S \subseteq A$ such that $S \ne \O$. Then: {{begin-eqn}} {{eqn | l = \map {\paren {g^\to \circ f^\to} } S | r = \map {g^\to} {\map {f^\to} S} | c = }} {{eqn | r = \set {\map g x: x \in \map {f^\to} S} | c = }} {{eqn | r = \set {\map g x: \exists y \in S: x = \map f y} | c = }} {{eqn |...
Composition of Direct Image Mappings of Mappings/Proof 1
https://proofwiki.org/wiki/Composition_of_Direct_Image_Mappings_of_Mappings
https://proofwiki.org/wiki/Composition_of_Direct_Image_Mappings_of_Mappings/Proof_1
[ "Composite Mappings", "Direct Image Mappings", "Composition of Direct Image Mappings of Mappings" ]
[ "Definition:Non-Empty Set", "Definition:Set", "Definition:Mapping", "Definition:Direct Image Mapping/Mapping" ]
[]
proofwiki-16336
Composition of Inverse Image Mappings of Mappings
Let $A, B, C$ be non-empty sets. Let $f: A \to B, g: B \to C$ be mappings. Let: :$f^\gets: \powerset B \to \powerset A$ and :$g^\gets: \powerset C \to \powerset B$ be the inverse image mappings of $f$ and $g$. Then: :$\paren {g \circ f}^\gets = f^\gets \circ g^\gets$
Let $T \subseteq C$. We have: {{begin-eqn}} {{eqn | l = \map {\paren {f \circ g}^\gets} T | r = \begin {cases} \set {x \in A: \map g {\map f x} \in T} & : \Img {g \circ f} \cap T \ne \O \\ \O & : \Img {g \circ f} \cap T = \O \end {cases} | c = }} {{eqn-intertext|and}} {{eqn | l = \map {f^\gets \circ g^\get...
Let $A, B, C$ be [[Definition:Non-Empty Set|non-empty]] [[Definition:Set|sets]]. Let $f: A \to B, g: B \to C$ be [[Definition:Mapping|mappings]]. Let: :$f^\gets: \powerset B \to \powerset A$ and :$g^\gets: \powerset C \to \powerset B$ be the [[Definition:Inverse Image Mapping of Mapping|inverse image mappings]] of $...
Let $T \subseteq C$. We have: {{begin-eqn}} {{eqn | l = \map {\paren {f \circ g}^\gets} T | r = \begin {cases} \set {x \in A: \map g {\map f x} \in T} & : \Img {g \circ f} \cap T \ne \O \\ \O & : \Img {g \circ f} \cap T = \O \end {cases} | c = }} {{eqn-intertext|and}} {{eqn | l = \map {f^\gets \circ g^\g...
Composition of Inverse Image Mappings of Mappings
https://proofwiki.org/wiki/Composition_of_Inverse_Image_Mappings_of_Mappings
https://proofwiki.org/wiki/Composition_of_Inverse_Image_Mappings_of_Mappings
[ "Composite Relations", "Composite Mappings", "Inverse Image Mappings" ]
[ "Definition:Non-Empty Set", "Definition:Set", "Definition:Mapping", "Definition:Inverse Image Mapping/Mapping" ]
[ "Empty Intersection iff Subset of Complement", "Complement of Preimage equals Preimage of Complement", "Intersection with Complement is Empty iff Subset", "Subset of Preimage under Relation is Preimage of Subset/Corollary", "Empty Intersection iff Subset of Complement" ]
proofwiki-16337
Unit of Ring of Mappings iff Image is Subset of Ring Units
Let $\struct {R, +, \circ}$ be a ring with unity $1_R$. Let $U_R$ be the set of units in $R$. Let $S$ be a set. Let $\struct {R^S, +', \circ'}$ be the ring of mappings on the set of mappings $R^S$. Then: :$f \in R^S$ is a unit of $R^S$ {{iff}} $\Img f \subseteq U_R$ where $\Img f$ is the image of $f$. In this case, the...
From Structure Induced by Ring with Unity Operations is Ring with Unity, $\struct {R^S, +', \circ'}$ has a unity $f_{1_R}$ defined by: :$\forall x \in S: \map {f_{1_R}} x = 1_R$
Let $\struct {R, +, \circ}$ be a [[Definition:Ring with Unity|ring]] with [[Definition:Unity of Ring|unity]] $1_R$. Let $U_R$ be the [[Definition:Set|set]] of [[Definition:Unit of Ring|units]] in $R$. Let $S$ be a [[Definition:Set|set]]. Let $\struct {R^S, +', \circ'}$ be the [[Definition:Ring of Mappings|ring of ma...
From [[Structure Induced by Ring with Unity Operations is Ring with Unity]], $\struct {R^S, +', \circ'}$ has a [[Definition:Unity of Ring|unity]] $f_{1_R}$ defined by: :$\forall x \in S: \map {f_{1_R}} x = 1_R$
Unit of Ring of Mappings iff Image is Subset of Ring Units
https://proofwiki.org/wiki/Unit_of_Ring_of_Mappings_iff_Image_is_Subset_of_Ring_Units
https://proofwiki.org/wiki/Unit_of_Ring_of_Mappings_iff_Image_is_Subset_of_Ring_Units
[ "Unit of Ring of Mappings iff Image is Subset of Ring Units", "Rings of Mappings", "Rings with Unity" ]
[ "Definition:Ring with Unity", "Definition:Unity (Abstract Algebra)/Ring", "Definition:Set", "Definition:Unit of Ring", "Definition:Set", "Definition:Ring of Mappings", "Definition:Set", "Definition:Mapping", "Definition:Unit of Ring", "Definition:Image (Set Theory)/Mapping/Mapping", "Definition:...
[ "Structure Induced by Ring with Unity Operations is Ring with Unity", "Definition:Unity (Abstract Algebra)/Ring" ]
proofwiki-16338
Mapping is Bijection iff Composite with Direct Image Mapping with Complementation Commutes
Let $S$ and $T$ be sets. Let $f: S \to T$ be a mapping. Then: :$f$ is a bijection {{iff}}: :$f^\to \circ \complement_S = \complement_T \circ f^\to$ where: :$f^\to: \powerset S \to \powerset T$ denotes the direct image mapping of $f$ :$\complement_S: \powerset S \to \powerset S$ denotes the complement relative to $S$ :$...
=== Sufficient Condition === Let $f$ be a bijection. Thus a fortiori $f$ is: :a surjection :a one-to-many relation From One-to-Many Image of Set Difference: Corollary 2 we have: :$\forall X \in \powerset S: \map {\paren {f^\to \circ \complement_S} } X = \map {\paren {\complement_{\Img f} \circ f^\to} } X$ By definition...
Let $S$ and $T$ be [[Definition:Set|sets]]. Let $f: S \to T$ be a [[Definition:Mapping|mapping]]. Then: :$f$ is a [[Definition:Bijection|bijection]] {{iff}}: :$f^\to \circ \complement_S = \complement_T \circ f^\to$ where: :$f^\to: \powerset S \to \powerset T$ denotes the [[Definition:Direct Image Mapping of Mapping|...
=== Sufficient Condition === Let $f$ be a [[Definition:Bijection|bijection]]. Thus [[Definition:A Fortiori|a fortiori]] $f$ is: :a [[Definition:Surjection|surjection]] :a [[Definition:One-to-Many Relation|one-to-many relation]] From [[One-to-Many Image of Set Difference/Corollary 2|One-to-Many Image of Set Differen...
Mapping is Bijection iff Composite with Direct Image Mapping with Complementation Commutes
https://proofwiki.org/wiki/Mapping_is_Bijection_iff_Composite_with_Direct_Image_Mapping_with_Complementation_Commutes
https://proofwiki.org/wiki/Mapping_is_Bijection_iff_Composite_with_Direct_Image_Mapping_with_Complementation_Commutes
[ "Set Complement", "Bijections", "Direct Image Mappings" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Bijection", "Definition:Direct Image Mapping/Mapping", "Definition:Relative Complement", "Definition:Relative Complement", "Definition:Power Set" ]
[ "Definition:Bijection", "Definition:A Fortiori", "Definition:Surjection", "Definition:One-to-Many Relation", "One-to-Many Image of Set Difference/Corollary 2", "Definition:Surjection", "Definition:Surjection", "Definition:Surjection", "Definition:Bijection" ]
proofwiki-16339
Relative Complement Mapping on Powerset is Bijection
Let $S$ be a set. Let $\complement_S: \powerset S \to \powerset S$ denote the relative complement mapping on the power set of $S$. Then $\complement_S$ is a bijection. Thus each $T \subseteq S$ is in one-to-one correspondence with its relative complement.
Let $f: \powerset S \to \powerset S$ be a mapping defined as: :$\forall T \in \powerset S: \map f T = \relcomp S T$ It is to be demonstrated that $f$ is a bijection. By definition of relative complement: :$\relcomp S T = S \setminus T = \set {x \in S: x \notin T}$ and so it can be seen that $f$ is well-defined. Let $T_...
Let $S$ be a [[Definition:Set|set]]. Let $\complement_S: \powerset S \to \powerset S$ denote the [[Definition:Relative Complement|relative complement mapping]] on the [[Definition:Power Set|power set]] of $S$. Then $\complement_S$ is a [[Definition:Bijection|bijection]]. Thus each $T \subseteq S$ is in [[Definition...
Let $f: \powerset S \to \powerset S$ be a [[Definition:Mapping|mapping]] defined as: :$\forall T \in \powerset S: \map f T = \relcomp S T$ It is to be demonstrated that $f$ is a [[Definition:Bijection|bijection]]. By definition of [[Definition:Relative Complement|relative complement]]: :$\relcomp S T = S \setminus T...
Relative Complement Mapping on Powerset is Bijection/Proof 2
https://proofwiki.org/wiki/Relative_Complement_Mapping_on_Powerset_is_Bijection
https://proofwiki.org/wiki/Relative_Complement_Mapping_on_Powerset_is_Bijection/Proof_2
[ "Relative Complement", "Examples of Bijections", "Relative Complement Mapping on Powerset is Bijection" ]
[ "Definition:Set", "Definition:Relative Complement", "Definition:Power Set", "Definition:Bijection", "Definition:Bijection", "Definition:Relative Complement" ]
[ "Definition:Mapping", "Definition:Bijection", "Definition:Relative Complement", "Definition:Well-Defined/Mapping", "Relative Complement of Relative Complement", "Definition:Injection", "Relative Complement of Relative Complement", "Definition:Surjection", "Definition:Bijection" ]
proofwiki-16340
Power of One plus x in terms of Gaussian Hypergeometric Function
:$\map F {-p, 1; 1; -x} = \paren {1 + x}^p$
{{begin-eqn}} {{eqn | l = \map F {-p, 1; 1; -x} | r = \sum_{n \mathop = 0}^\infty \frac {\paren {-p}^{\overline n} 1^{\overline n} } {1^{\overline n} } \frac {\paren {-x}^n} {n!} | c = {{Defof|Gaussian Hypergeometric Function}} }} {{eqn | r = \sum_{n \mathop = 0}^\infty \paren {-1}^n \paren {\prod_{j \matho...
:$\map F {-p, 1; 1; -x} = \paren {1 + x}^p$
{{begin-eqn}} {{eqn | l = \map F {-p, 1; 1; -x} | r = \sum_{n \mathop = 0}^\infty \frac {\paren {-p}^{\overline n} 1^{\overline n} } {1^{\overline n} } \frac {\paren {-x}^n} {n!} | c = {{Defof|Gaussian Hypergeometric Function}} }} {{eqn | r = \sum_{n \mathop = 0}^\infty \paren {-1}^n \paren {\prod_{j \matho...
Power of One plus x in terms of Gaussian Hypergeometric Function
https://proofwiki.org/wiki/Power_of_One_plus_x_in_terms_of_Gaussian_Hypergeometric_Function
https://proofwiki.org/wiki/Power_of_One_plus_x_in_terms_of_Gaussian_Hypergeometric_Function
[ "Gaussian Hypergeometric Function", "Hypergeometric Functions" ]
[]
[ "Product of Products", "Binomial Theorem/General Binomial Theorem" ]
proofwiki-16341
Logarithm of One plus x in terms of Gaussian Hypergeometric Function
:$\map \ln {1 + x} = x \map F {1, 1; 2; -x}$
{{begin-eqn}} {{eqn | l = x \map F {1, 1; 2; -x} | r = x \sum_{n \mathop = 0}^\infty \frac {\paren {1^{\overline n} }^2} {2^{\overline n} } \frac {\paren {-x}^n} {n!} | c = {{Defof|Gaussian Hypergeometric Function}} }} {{eqn | r = \sum_{n \mathop = 0}^\infty \paren {-1}^n \paren {n!}^2 \paren {\frac {\paren...
:$\map \ln {1 + x} = x \map F {1, 1; 2; -x}$
{{begin-eqn}} {{eqn | l = x \map F {1, 1; 2; -x} | r = x \sum_{n \mathop = 0}^\infty \frac {\paren {1^{\overline n} }^2} {2^{\overline n} } \frac {\paren {-x}^n} {n!} | c = {{Defof|Gaussian Hypergeometric Function}} }} {{eqn | r = \sum_{n \mathop = 0}^\infty \paren {-1}^n \paren {n!}^2 \paren {\frac {\paren...
Logarithm of One plus x in terms of Gaussian Hypergeometric Function
https://proofwiki.org/wiki/Logarithm_of_One_plus_x_in_terms_of_Gaussian_Hypergeometric_Function
https://proofwiki.org/wiki/Logarithm_of_One_plus_x_in_terms_of_Gaussian_Hypergeometric_Function
[ "Gaussian Hypergeometric Function", "Hypergeometric Functions", "Logarithms" ]
[]
[ "Rising Factorial as Quotient of Factorials", "One to Integer Rising is Integer Factorial", "Power Series Expansion for Logarithm of 1 + x" ]
proofwiki-16342
Laplace Transform of Exponential times Sine
:$\map {\laptrans {e^{b t} \sin a t} } s = \dfrac a {\paren {s - b}^2 + a^2}$
{{begin-eqn}} {{eqn | l = \map {\laptrans {e^{b t} \sin a t} } s | r = \map {\laptrans {\sin a t} } {s - b} | c = First Translation Property of Laplace Transforms }} {{eqn | r = \frac a {\paren {s - b}^2 + a^2} | c = Laplace Transform of Sine }} {{end-eqn}} {{qed}}
:$\map {\laptrans {e^{b t} \sin a t} } s = \dfrac a {\paren {s - b}^2 + a^2}$
{{begin-eqn}} {{eqn | l = \map {\laptrans {e^{b t} \sin a t} } s | r = \map {\laptrans {\sin a t} } {s - b} | c = [[First Translation Property of Laplace Transforms]] }} {{eqn | r = \frac a {\paren {s - b}^2 + a^2} | c = [[Laplace Transform of Sine]] }} {{end-eqn}} {{qed}}
Laplace Transform of Exponential times Sine
https://proofwiki.org/wiki/Laplace_Transform_of_Exponential_times_Sine
https://proofwiki.org/wiki/Laplace_Transform_of_Exponential_times_Sine
[ "Laplace Transform of Exponential times Sine", "Laplace Transforms involving Exponential Function", "Laplace Transforms involving Sine Function", "Examples of Laplace Transforms" ]
[]
[ "First Translation Property of Laplace Transforms", "Laplace Transform of Sine" ]
proofwiki-16343
Laplace Transform of Exponential times Cosine
:$\map {\laptrans {e^{b t} \cos a t} } s = \dfrac {s - b} {\paren {s - b}^2 + a^2}$
{{begin-eqn}} {{eqn | l = \map {\laptrans {e^{b t} \cos a t} } s | r = \map {\laptrans {\cos a t} } {s - b} | c = First Translation Property of Laplace Transforms }} {{eqn | r = \frac {s - b} {\paren {s - b}^2 + a^2} | c = Laplace Transform of Cosine }} {{end-eqn}} {{qed}}
:$\map {\laptrans {e^{b t} \cos a t} } s = \dfrac {s - b} {\paren {s - b}^2 + a^2}$
{{begin-eqn}} {{eqn | l = \map {\laptrans {e^{b t} \cos a t} } s | r = \map {\laptrans {\cos a t} } {s - b} | c = [[First Translation Property of Laplace Transforms]] }} {{eqn | r = \frac {s - b} {\paren {s - b}^2 + a^2} | c = [[Laplace Transform of Cosine]] }} {{end-eqn}} {{qed}}
Laplace Transform of Exponential times Cosine
https://proofwiki.org/wiki/Laplace_Transform_of_Exponential_times_Cosine
https://proofwiki.org/wiki/Laplace_Transform_of_Exponential_times_Cosine
[ "Laplace Transforms involving Exponential Function", "Laplace Transforms involving Cosine Function", "Examples of Laplace Transforms" ]
[]
[ "First Translation Property of Laplace Transforms", "Laplace Transform of Cosine" ]
proofwiki-16344
Complement of Direct Image Mapping of Injection equals Direct Image of Complement
Let $f: S \to T$ be an injection. Let $f^\to: \powerset S \to \powerset T$ denote the direct image mapping of $f$. Then: :$\forall A \in \powerset S: \map {\paren {\complement_{\Img f} \circ f^\to} } A = \map {\paren {f^\to \circ \complement_S} } A$ where $\circ$ denotes composition of mappings.
As $f$ is an injection, it is a fortiori a one-to-many relation. From Image of Set Difference under Relation: Corollary 2: :$\forall A \in \powerset S: \map {\paren {\complement_{\Img \RR} \circ \RR^\to} } A = \map {\paren {\RR^\to \circ \complement_S} } A$ where $\RR \subseteq S \times T$ is a one-to-many relation on ...
Let $f: S \to T$ be an [[Definition:Injection|injection]]. Let $f^\to: \powerset S \to \powerset T$ denote the [[Definition:Direct Image Mapping of Mapping|direct image mapping]] of $f$. Then: :$\forall A \in \powerset S: \map {\paren {\complement_{\Img f} \circ f^\to} } A = \map {\paren {f^\to \circ \complement_S} ...
As $f$ is an [[Definition:Injection|injection]], it is [[Definition:A Fortiori|a fortiori]] a [[Definition:One-to-Many Relation|one-to-many relation]]. From [[Image of Set Difference under Relation/Corollary 2|Image of Set Difference under Relation: Corollary 2]]: :$\forall A \in \powerset S: \map {\paren {\complemen...
Complement of Direct Image Mapping of Injection equals Direct Image of Complement
https://proofwiki.org/wiki/Complement_of_Direct_Image_Mapping_of_Injection_equals_Direct_Image_of_Complement
https://proofwiki.org/wiki/Complement_of_Direct_Image_Mapping_of_Injection_equals_Direct_Image_of_Complement
[ "Direct Image Mappings", "Injections", "Relative Complement" ]
[ "Definition:Injection", "Definition:Direct Image Mapping/Mapping", "Definition:Composition of Mappings" ]
[ "Definition:Injection", "Definition:A Fortiori", "Definition:One-to-Many Relation", "Image of Set Difference under Relation/Corollary 2", "Definition:One-to-Many Relation" ]
proofwiki-16345
Direct Image of Inverse Image of Direct Image equals Direct Image Mapping
Let $f: S \to T$ be a mapping. Let: :$f^\to: \powerset S \to \powerset T$ denote the direct image mapping of $f$ :$f^\gets: \powerset T \to \powerset S$ denote the inverse image mapping of $f$ where $\powerset S$ denotes the power set of $S$. Then: :$f^\to \circ f^\gets \circ f^\to = f^\to$ where $\circ$ denotes compos...
{{begin-eqn}} {{eqn | q = \forall A \in \powerset S | l = A | o = \subseteq | r = \map {\paren {f^\gets \circ f^\to} } A | c = Subset of Domain is Subset of Preimage of Image }} {{eqn | ll= \leadsto | q = \forall A \in \powerset S | l = \map {f^\to} A | o = \subseteq | r ...
Let $f: S \to T$ be a [[Definition:Mapping|mapping]]. Let: :$f^\to: \powerset S \to \powerset T$ denote the [[Definition:Direct Image Mapping of Mapping|direct image mapping]] of $f$ :$f^\gets: \powerset T \to \powerset S$ denote the [[Definition:Inverse Image Mapping of Mapping|inverse image mapping]] of $f$ where $\...
{{begin-eqn}} {{eqn | q = \forall A \in \powerset S | l = A | o = \subseteq | r = \map {\paren {f^\gets \circ f^\to} } A | c = [[Subset of Domain is Subset of Preimage of Image]] }} {{eqn | ll= \leadsto | q = \forall A \in \powerset S | l = \map {f^\to} A | o = \subseteq ...
Direct Image of Inverse Image of Direct Image equals Direct Image Mapping
https://proofwiki.org/wiki/Direct_Image_of_Inverse_Image_of_Direct_Image_equals_Direct_Image_Mapping
https://proofwiki.org/wiki/Direct_Image_of_Inverse_Image_of_Direct_Image_equals_Direct_Image_Mapping
[ "Direct Image Mappings", "Inverse Image Mappings" ]
[ "Definition:Mapping", "Definition:Direct Image Mapping/Mapping", "Definition:Inverse Image Mapping/Mapping", "Definition:Power Set", "Definition:Composition of Mappings" ]
[ "Subset of Domain is Subset of Preimage of Image", "Image of Subset under Mapping is Subset of Image", "Subset of Codomain is Superset of Image of Preimage", "Image of Subset under Mapping is Subset of Image" ]
proofwiki-16346
Inverse Image of Direct Image of Inverse Image equals Inverse Image Mapping
Let $f: S \to T$ be a mapping. Let: :$f^\to: \powerset S \to \powerset T$ denote the direct image mapping of $f$ :$f^\gets: \powerset T \to \powerset S$ denote the inverse image mapping of $f$ where $\powerset S$ denotes the power set of $S$. Then: :$f^\gets \circ f^\to \circ f^\gets = f^\gets$ where $\circ$ denotes co...
{{begin-eqn}} {{eqn | q = \forall A \in \powerset S | l = A | o = \subseteq | r = \map {\paren {f^\gets \circ f^\to} } A | c = Subset of Domain is Subset of Preimage of Image }} {{eqn | ll= \leadsto | q = \forall B \in \powerset T | l = \map {f^\gets} B | o = \subseteq | ...
Let $f: S \to T$ be a [[Definition:Mapping|mapping]]. Let: :$f^\to: \powerset S \to \powerset T$ denote the [[Definition:Direct Image Mapping of Mapping|direct image mapping]] of $f$ :$f^\gets: \powerset T \to \powerset S$ denote the [[Definition:Inverse Image Mapping of Mapping|inverse image mapping]] of $f$ where $\...
{{begin-eqn}} {{eqn | q = \forall A \in \powerset S | l = A | o = \subseteq | r = \map {\paren {f^\gets \circ f^\to} } A | c = [[Subset of Domain is Subset of Preimage of Image]] }} {{eqn | ll= \leadsto | q = \forall B \in \powerset T | l = \map {f^\gets} B | o = \subseteq ...
Inverse Image of Direct Image of Inverse Image equals Inverse Image Mapping
https://proofwiki.org/wiki/Inverse_Image_of_Direct_Image_of_Inverse_Image_equals_Inverse_Image_Mapping
https://proofwiki.org/wiki/Inverse_Image_of_Direct_Image_of_Inverse_Image_equals_Inverse_Image_Mapping
[ "Direct Image Mappings", "Inverse Image Mappings" ]
[ "Definition:Mapping", "Definition:Direct Image Mapping/Mapping", "Definition:Inverse Image Mapping/Mapping", "Definition:Power Set", "Definition:Composition of Mappings" ]
[ "Subset of Domain is Subset of Preimage of Image", "Image of Subset under Mapping is Subset of Image", "Subset of Codomain is Superset of Image of Preimage", "Image of Subset under Mapping is Subset of Image" ]
proofwiki-16347
Direct Image of Intersection with Inverse Image
Then: :$\forall A \in \powerset S, B \in \powerset T: \map {f^\to} {A \cap \map {f^\gets} B} = \map {f^\to} A \cap B$
Let $A \in \powerset S, B \in \powerset T$ be arbitrary. Then: {{begin-eqn}} {{eqn | l = \map {f^\to} {A \cap \map {f^\gets} B} | o = \subseteq | r = \map {f^\to} A \cap \map {f^\to} {\map {f^\gets} B} | c = Image of Intersection under Mapping }} {{eqn | o = \subseteq | r = \map {f^\to} A \cap...
Then: :$\forall A \in \powerset S, B \in \powerset T: \map {f^\to} {A \cap \map {f^\gets} B} = \map {f^\to} A \cap B$
Let $A \in \powerset S, B \in \powerset T$ be arbitrary. Then: {{begin-eqn}} {{eqn | l = \map {f^\to} {A \cap \map {f^\gets} B} | o = \subseteq | r = \map {f^\to} A \cap \map {f^\to} {\map {f^\gets} B} | c = [[Image of Intersection under Mapping]] }} {{eqn | o = \subseteq | r = \map {f^\to} ...
Direct Image of Intersection with Inverse Image
https://proofwiki.org/wiki/Direct_Image_of_Intersection_with_Inverse_Image
https://proofwiki.org/wiki/Direct_Image_of_Intersection_with_Inverse_Image
[ "Direct Image Mappings", "Inverse Image Mappings", "Set Intersection" ]
[]
[ "Image of Intersection under Mapping", "Subset of Codomain is Superset of Image of Preimage", "Definition:Set Equality" ]
proofwiki-16348
Graph of Real Function in Cartesian Plane intersects Vertical at One Point
Let $f: \R \to \R$ be a real function. Let its graph be embedded in the Cartesian plane $\CC$: :520px Every vertical line through a point $a$ in the domain of $f$ intersects the graph of $f$ at exactly one point $P = \tuple {a, \map f a}$.
From Equation of Vertical Line, a vertical line in $\CC$ through the point $\tuple {a, 0}$ on the $x$-axis has an equation $x = a$. A real function is by definition a mapping. Hence: :$\forall a_1, a_2 \in \Dom f: a_1 = a_2 \implies \map f {a_1} = \map f {a_2}$ where $\Dom f$ denotes the domain of $f$. Thus for each $a...
Let $f: \R \to \R$ be a [[Definition:Real Function|real function]]. Let its [[Definition:Graph of Mapping|graph]] be embedded in the [[Definition:Cartesian Plane|Cartesian plane]] $\CC$: :[[File:Graph-of-function-intersect-vertical.png|520px]] Every [[Definition:Vertical Line|vertical line]] through a [[Definition...
From [[Equation of Vertical Line]], a [[Definition:Vertical Line|vertical line]] in $\CC$ through the [[Definition:Point|point]] $\tuple {a, 0}$ on the [[Definition:X-Axis|$x$-axis]] has an [[Definition:Equation of Geometric Figure|equation]] $x = a$. A [[Definition:Real Function|real function]] is by definition a [[...
Graph of Real Function in Cartesian Plane intersects Vertical at One Point
https://proofwiki.org/wiki/Graph_of_Real_Function_in_Cartesian_Plane_intersects_Vertical_at_One_Point
https://proofwiki.org/wiki/Graph_of_Real_Function_in_Cartesian_Plane_intersects_Vertical_at_One_Point
[ "Real Functions", "Graphs of Mappings" ]
[ "Definition:Real Function", "Definition:Graph of Mapping", "Definition:Cartesian Plane", "File:Graph-of-function-intersect-vertical.png", "Definition:Vertical Line", "Definition:Point", "Definition:Domain (Set Theory)/Mapping", "Definition:Intersection (Geometry)", "Definition:Graph of Mapping", "...
[ "Equation of Vertical Line", "Definition:Vertical Line", "Definition:Point", "Definition:Axis/X-Axis", "Definition:Equation of Geometric Figure", "Definition:Real Function", "Definition:Mapping", "Definition:Domain (Set Theory)/Mapping", "Definition:Unique", "Definition:Ordered Pair", "Definitio...
proofwiki-16349
Equation of Vertical Line
Let $\LL$ be a vertical line embedded in the Cartesian plane $\CC$. Then the equation of $\LL$ can be given by: :$x = a$ where $\tuple {a, 0}$ is the point at which $\LL$ intersects the $x$-axis. :520px
From the Normal Form of Equation of Straight Line in Plane, a general straight line can be expressed in the form: :$x \cos \alpha + y \sin \alpha = p$ where: :$p$ is the length of a perpendicular $\PP$ from $\LL$ to the origin. :$\alpha$ is the angle made between $\PP$ and the $x$-axis. As $\LL$ is vertical, then by de...
Let $\LL$ be a [[Definition:Vertical Line|vertical line]] embedded in the [[Definition:Cartesian Plane|Cartesian plane]] $\CC$. Then the [[Definition:Equation of Geometric Figure|equation]] of $\LL$ can be given by: :$x = a$ where $\tuple {a, 0}$ is the [[Definition:Point|point]] at which $\LL$ [[Definition:Intersec...
From the [[Equation of Straight Line in Plane/Normal Form|Normal Form of Equation of Straight Line in Plane]], a general [[Definition:Straight Line|straight line]] can be expressed in the form: :$x \cos \alpha + y \sin \alpha = p$ where: :$p$ is the [[Definition:Length of Line|length]] of a [[Definition:Perpendicular...
Equation of Vertical Line
https://proofwiki.org/wiki/Equation_of_Vertical_Line
https://proofwiki.org/wiki/Equation_of_Vertical_Line
[ "Equations of Straight Lines in Plane" ]
[ "Definition:Vertical Line", "Definition:Cartesian Plane", "Definition:Equation of Geometric Figure", "Definition:Point", "Definition:Intersection (Geometry)", "Definition:Axis/X-Axis", "File:Graph-of-vertical-line.png" ]
[ "Equation of Straight Line in Plane/Normal Form", "Definition:Line/Straight Line", "Definition:Linear Measure/Length", "Definition:Right Angle/Perpendicular", "Definition:Coordinate System/Origin", "Definition:Angle", "Definition:Axis/X-Axis", "Definition:Vertical Line", "Definition:Horizontal Line"...
proofwiki-16350
Equation of Horizontal Line
Let $\LL$ be a horizontal line embedded in the Cartesian plane $\CC$. Then the equation of $\LL$ can be given by: :$y = b$ where $\tuple {0, b}$ is the point at which $\LL$ intersects the $y$-axis. :520px
From the Normal Form of Equation of Straight Line in Plane, a general straight line can be expressed in the form: :$x \cos \alpha + y \sin \alpha = p$ where: :$p$ is the length of a perpendicular $\PP$ from $\LL$ to the origin :$\alpha$ is the angle made between $\PP$ and the $x$-axis. As $\LL$ is horizontal, then by d...
Let $\LL$ be a [[Definition:Horizontal Line|horizontal line]] embedded in the [[Definition:Cartesian Plane|Cartesian plane]] $\CC$. Then the [[Definition:Equation of Geometric Figure|equation]] of $\LL$ can be given by: :$y = b$ where $\tuple {0, b}$ is the [[Definition:Point|point]] at which $\LL$ [[Definition:Inte...
From the [[Equation of Straight Line in Plane/Normal Form|Normal Form of Equation of Straight Line in Plane]], a general [[Definition:Straight Line|straight line]] can be expressed in the form: :$x \cos \alpha + y \sin \alpha = p$ where: :$p$ is the [[Definition:Length of Line|length]] of a [[Definition:Perpendicular...
Equation of Horizontal Line
https://proofwiki.org/wiki/Equation_of_Horizontal_Line
https://proofwiki.org/wiki/Equation_of_Horizontal_Line
[ "Equations of Straight Lines in Plane" ]
[ "Definition:Horizontal Line", "Definition:Cartesian Plane", "Definition:Equation of Geometric Figure", "Definition:Point", "Definition:Intersection (Geometry)", "Definition:Axis/Y-Axis", "File:Graph-of-horizontal-line.png" ]
[ "Equation of Straight Line in Plane/Normal Form", "Definition:Line/Straight Line", "Definition:Linear Measure/Length", "Definition:Right Angle/Perpendicular", "Definition:Coordinate System/Origin", "Definition:Angle", "Definition:Axis/X-Axis", "Definition:Horizontal Line", "Definition:Vertical Line"...
proofwiki-16351
Unit of Ring of Mappings iff Image is Subset of Ring Units/Image is Subset of Ring Units implies Unit of Ring of Mappings
Let $\struct {R, +, \circ}$ be a ring with unity $1_R$. Let $U_R$ be the set of units in $R$. Let $S$ be a set. Let $\struct {R^S, +', \circ'}$ be the ring of mappings on the set of mappings $R^S$. Let $\Img f \subseteq U_R$ where $\Img f$ is the image of $f$. Then: :$f \in R^S$ is a unit of $R^S$ and the inverse of $f...
By assumption: :$\forall x \in S: \exists \map f x^{-1} : \map f x \circ \map f x^{-1} = \map f x^{-1} \circ \map f x = 1_R$ Let $f^{-1} : S \to U_R$ be defined by: :$\forall x \in S : \map {f^{-1}} {x} = \map f x^{-1}$ Consider the mapping $f \circ’ f^{-1}$. For all $x \in S$: {{begin-eqn}} {{eqn | l = \map {\paren...
Let $\struct {R, +, \circ}$ be a [[Definition:Ring with Unity|ring]] with [[Definition:Unity of Ring|unity]] $1_R$. Let $U_R$ be the [[Definition:Set|set]] of [[Definition:Unit of Ring|units]] in $R$. Let $S$ be a [[Definition:Set|set]]. Let $\struct {R^S, +', \circ'}$ be the [[Definition:Ring of Mappings|ring of ma...
By assumption: :$\forall x \in S: \exists \map f x^{-1} : \map f x \circ \map f x^{-1} = \map f x^{-1} \circ \map f x = 1_R$ Let $f^{-1} : S \to U_R$ be defined by: :$\forall x \in S : \map {f^{-1}} {x} = \map f x^{-1}$ Consider the [[Definition:Mapping|mapping]] $f \circ’ f^{-1}$. For all $x \in S$: {{begin-eqn...
Unit of Ring of Mappings iff Image is Subset of Ring Units/Image is Subset of Ring Units implies Unit of Ring of Mappings
https://proofwiki.org/wiki/Unit_of_Ring_of_Mappings_iff_Image_is_Subset_of_Ring_Units/Image_is_Subset_of_Ring_Units_implies_Unit_of_Ring_of_Mappings
https://proofwiki.org/wiki/Unit_of_Ring_of_Mappings_iff_Image_is_Subset_of_Ring_Units/Image_is_Subset_of_Ring_Units_implies_Unit_of_Ring_of_Mappings
[ "Unit of Ring of Mappings iff Image is Subset of Ring Units" ]
[ "Definition:Ring with Unity", "Definition:Unity (Abstract Algebra)/Ring", "Definition:Set", "Definition:Unit of Ring", "Definition:Set", "Definition:Ring of Mappings", "Definition:Set", "Definition:Mapping", "Definition:Image (Set Theory)/Mapping/Mapping", "Definition:Unit of Ring", "Definition:...
[ "Definition:Mapping", "Definition:Unit of Ring", "Definition:Inverse (Abstract Algebra)/Inverse", "Definition:Mapping" ]
proofwiki-16352
Unit of Ring of Mappings iff Image is Subset of Ring Units/Unit of Ring of Mappings implies Image is Subset of Ring Units
Let $\struct {R, +, \circ}$ be a ring with unity $1_R$. Let $U_R$ be the set of units in $R$. Let $S$ be a set. Let $\struct {R^S, +', \circ'}$ be the ring of mappings on the set of mappings $R^S$. Let $f \in R^S$ be a unit of $R^S$. Then: :$\Img f \subseteq U_R$ where $\Img f$ is the image of $f$. In which case, the i...
Let $f^{-1}$ be the product inverse of $f$. Let $x \in R$. Then: {{begin-eqn}} {{eqn | l = 1_R | r = \map {f_{1_R} } x | c = Structure Induced by Ring with Unity Operations is Ring with Unity }} {{eqn | r = \map {\paren {f \circ' f^{-1} } } x | c = {{Defof|Product Inverse|product inverse}} }} {{eqn |...
Let $\struct {R, +, \circ}$ be a [[Definition:Ring with Unity|ring]] with [[Definition:Unity of Ring|unity]] $1_R$. Let $U_R$ be the [[Definition:Set|set]] of [[Definition:Unit of Ring|units]] in $R$. Let $S$ be a [[Definition:Set|set]]. Let $\struct {R^S, +', \circ'}$ be the [[Definition:Ring of Mappings|ring of ma...
Let $f^{-1}$ be the [[Definition:Product Inverse|product inverse]] of $f$. Let $x \in R$. Then: {{begin-eqn}} {{eqn | l = 1_R | r = \map {f_{1_R} } x | c = [[Structure Induced by Ring with Unity Operations is Ring with Unity]] }} {{eqn | r = \map {\paren {f \circ' f^{-1} } } x | c = {{Defof|Produc...
Unit of Ring of Mappings iff Image is Subset of Ring Units/Unit of Ring of Mappings implies Image is Subset of Ring Units
https://proofwiki.org/wiki/Unit_of_Ring_of_Mappings_iff_Image_is_Subset_of_Ring_Units/Unit_of_Ring_of_Mappings_implies_Image_is_Subset_of_Ring_Units
https://proofwiki.org/wiki/Unit_of_Ring_of_Mappings_iff_Image_is_Subset_of_Ring_Units/Unit_of_Ring_of_Mappings_implies_Image_is_Subset_of_Ring_Units
[ "Unit of Ring of Mappings iff Image is Subset of Ring Units" ]
[ "Definition:Ring with Unity", "Definition:Unity (Abstract Algebra)/Ring", "Definition:Set", "Definition:Unit of Ring", "Definition:Set", "Definition:Ring of Mappings", "Definition:Set", "Definition:Mapping", "Definition:Unit of Ring", "Definition:Image (Set Theory)/Mapping/Mapping", "Definition:...
[ "Definition:Product Inverse", "Structure Induced by Ring with Unity Operations is Ring with Unity", "Definition:Product Inverse", "Definition:Unit of Ring" ]
proofwiki-16353
Graph of Real Surjection in Coordinate Plane intersects Every Horizontal Line
Let $f: \R \to \R$ be a real function which is surjective. Let its graph be embedded in the Cartesian plane $\CC$: :520px Every horizontal line through a point $b$ in the codomain of $f$ intersects the graph of $f$ on at least one point $P = \tuple {a, b}$ where $b = \map f a$.
From Equation of Horizontal Line, a horizontal line in $\CC$ through the point $\tuple {0, b}$ on the $y$-axis has an equation $y = b$. By hypothesis, $f$ is a surjection. Hence: :$\forall b \in \R: \exists a \in \R: b = \map f a$ Thus for each $b \in \R$ there exists at least one ordered pair $\tuple {a, b}$ such that...
Let $f: \R \to \R$ be a [[Definition:Real Function|real function]] which is [[Definition:Surjection|surjective]]. Let its [[Definition:Graph of Mapping|graph]] be embedded in the [[Definition:Cartesian Plane|Cartesian plane]] $\CC$: :[[File:Graph-of-surjection-intersect-horizontal.png|520px]] Every [[Definition:Ho...
From [[Equation of Horizontal Line]], a [[Definition:Horizontal Line|horizontal line]] in $\CC$ through the [[Definition:Point|point]] $\tuple {0, b}$ on the [[Definition:Y-Axis|$y$-axis]] has an [[Definition:Equation of Geometric Figure|equation]] $y = b$. [[Definition:By Hypothesis|By hypothesis]], $f$ is a [[Defin...
Graph of Real Surjection in Coordinate Plane intersects Every Horizontal Line
https://proofwiki.org/wiki/Graph_of_Real_Surjection_in_Coordinate_Plane_intersects_Every_Horizontal_Line
https://proofwiki.org/wiki/Graph_of_Real_Surjection_in_Coordinate_Plane_intersects_Every_Horizontal_Line
[ "Real Functions", "Surjections", "Graphs of Mappings" ]
[ "Definition:Real Function", "Definition:Surjection", "Definition:Graph of Mapping", "Definition:Cartesian Plane", "File:Graph-of-surjection-intersect-horizontal.png", "Definition:Horizontal Line", "Definition:Point", "Definition:Codomain (Set Theory)/Mapping", "Definition:Intersection (Geometry)", ...
[ "Equation of Horizontal Line", "Definition:Horizontal Line", "Definition:Point", "Definition:Axis/Y-Axis", "Definition:Equation of Geometric Figure", "Definition:By Hypothesis", "Definition:Surjection", "Definition:Ordered Pair", "Definition:Point", "Definition:Graph of Mapping" ]
proofwiki-16354
Graph of Real Injection in Coordinate Plane intersects Horizontal Line at most Once
Let $f: \R \to \R$ be a real function which is injective. Let its graph be embedded in the Cartesian plane $\CC$: :520px Let $\LL$ be a horizontal line through a point $b$ in the codomain of $f$. Then $\LL$ intersects the graph of $f$ on at most one point $P = \tuple {a, b}$ where $b = \map f a$.
From Equation of Horizontal Line, a horizontal line in $\CC$ through the point $\tuple {0, b}$ on the $y$-axis has an equation $y = b$. By hypothesis, $f$ is a injection. Hence: :$\forall a_1, a_2 \in \Dom f: \map f {a_1} = \map f {a_2} \implies a_1 = a_2$ where $\Dom f$ denotes the domain of $f$. Thus for each $b \in ...
Let $f: \R \to \R$ be a [[Definition:Real Function|real function]] which is [[Definition:Injection|injective]]. Let its [[Definition:Graph of Mapping|graph]] be embedded in the [[Definition:Cartesian Plane|Cartesian plane]] $\CC$: :[[File:Graph-of-injection-intersect-horizontal.png|520px]] Let $\LL$ be a [[Definit...
From [[Equation of Horizontal Line]], a [[Definition:Horizontal Line|horizontal line]] in $\CC$ through the [[Definition:Point|point]] $\tuple {0, b}$ on the [[Definition:Y-Axis|$y$-axis]] has an [[Definition:Equation of Geometric Figure|equation]] $y = b$. [[Definition:By Hypothesis|By hypothesis]], $f$ is a [[Defin...
Graph of Real Injection in Coordinate Plane intersects Horizontal Line at most Once
https://proofwiki.org/wiki/Graph_of_Real_Injection_in_Coordinate_Plane_intersects_Horizontal_Line_at_most_Once
https://proofwiki.org/wiki/Graph_of_Real_Injection_in_Coordinate_Plane_intersects_Horizontal_Line_at_most_Once
[ "Real Functions", "Injections", "Graphs of Mappings" ]
[ "Definition:Real Function", "Definition:Injection", "Definition:Graph of Mapping", "Definition:Cartesian Plane", "File:Graph-of-injection-intersect-horizontal.png", "Definition:Horizontal Line", "Definition:Point", "Definition:Codomain (Set Theory)/Mapping", "Definition:Intersection (Geometry)", "...
[ "Equation of Horizontal Line", "Definition:Horizontal Line", "Definition:Point", "Definition:Axis/Y-Axis", "Definition:Equation of Geometric Figure", "Definition:By Hypothesis", "Definition:Injection", "Definition:Domain (Set Theory)/Mapping", "Definition:Unique", "Definition:Ordered Pair", "Def...
proofwiki-16355
Graph of Real Bijection in Coordinate Plane intersects Horizontal Line at One Point
Let $f: \R \to \R$ be a real function which is bijective. Let its graph be embedded in the Cartesian plane $\CC$: :520px Every horizontal line through a point $b$ in the codomain of $f$ intersects the graph of $f$ on exactly one point $P = \tuple {a, b}$ where $b = \map f a$.
By definition, a bijection is a mapping which is both an injection and a surjection. Let $\LL$ be a horizontal line through a point $b$ in the codomain of $f$. From Graph of Real Surjection in Coordinate Plane intersects Every Horizontal Line: :$\LL$ intersects the graph of $f$ on at least one point $P = \tuple {a, b}$...
Let $f: \R \to \R$ be a [[Definition:Real Function|real function]] which is [[Definition:Bijection|bijective]]. Let its [[Definition:Graph of Mapping|graph]] be embedded in the [[Definition:Cartesian Plane|Cartesian plane]] $\CC$: :[[File:Graph-of-bijection-intersect-horizontal.png|520px]] Every [[Definition:Horiz...
By definition, a [[Definition:Bijection|bijection]] is a [[Definition:Mapping|mapping]] which is both an [[Definition:Injection|injection]] and a [[Definition:Surjection|surjection]]. Let $\LL$ be a [[Definition:Horizontal Line|horizontal line]] through a [[Definition:Point|point]] $b$ in the [[Definition:Codomain of...
Graph of Real Bijection in Coordinate Plane intersects Horizontal Line at One Point
https://proofwiki.org/wiki/Graph_of_Real_Bijection_in_Coordinate_Plane_intersects_Horizontal_Line_at_One_Point
https://proofwiki.org/wiki/Graph_of_Real_Bijection_in_Coordinate_Plane_intersects_Horizontal_Line_at_One_Point
[ "Real Functions", "Bijections", "Graphs of Mappings" ]
[ "Definition:Real Function", "Definition:Bijection", "Definition:Graph of Mapping", "Definition:Cartesian Plane", "File:Graph-of-bijection-intersect-horizontal.png", "Definition:Horizontal Line", "Definition:Point", "Definition:Codomain (Set Theory)/Mapping", "Definition:Intersection (Geometry)", "...
[ "Definition:Bijection", "Definition:Mapping", "Definition:Injection", "Definition:Surjection", "Definition:Horizontal Line", "Definition:Point", "Definition:Codomain (Set Theory)/Mapping", "Graph of Real Surjection in Coordinate Plane intersects Every Horizontal Line", "Definition:Intersection (Geom...
proofwiki-16356
Composite of Surjection on Injection is not necessarily Either
Let $f$ be an injection. Let $g$ be a surjection. Let $g \circ f$ denote the composition of $g$ with $f$. Then it is not necessarily the case that $g \circ f$ is either a surjection or an injection.
Let $X, Y, Z$ be sets defined as: {{begin-eqn}} {{eqn | l = X | r = \set {a, b, c} | c = }} {{eqn | l = Y | r = \set {1, 2, 3, 4} | c = }} {{eqn | l = Z | r = \set {z, y, z} | c = }} {{end-eqn}} Let $f: X \to Y$ be defined in two-row notation as: :$\dbinom {a \ b \ c } {1 \ 2 \ 3}...
Let $f$ be an [[Definition:Injection|injection]]. Let $g$ be a [[Definition:Surjection|surjection]]. Let $g \circ f$ denote the [[Definition:Composition of Mappings|composition]] of $g$ with $f$. Then it is not necessarily the case that $g \circ f$ is either a [[Definition:Surjection|surjection]] or an [[Definition...
Let $X, Y, Z$ be [[Definition:Set|sets]] defined as: {{begin-eqn}} {{eqn | l = X | r = \set {a, b, c} | c = }} {{eqn | l = Y | r = \set {1, 2, 3, 4} | c = }} {{eqn | l = Z | r = \set {z, y, z} | c = }} {{end-eqn}} Let $f: X \to Y$ be defined in [[Definition:Two-Row Notation|tw...
Composite of Surjection on Injection is not necessarily Either
https://proofwiki.org/wiki/Composite_of_Surjection_on_Injection_is_not_necessarily_Either
https://proofwiki.org/wiki/Composite_of_Surjection_on_Injection_is_not_necessarily_Either
[ "Injections", "Surjections", "Composite Mappings" ]
[ "Definition:Injection", "Definition:Surjection", "Definition:Composition of Mappings", "Definition:Surjection", "Definition:Injection" ]
[ "Definition:Set", "Definition:Permutation on n Letters/Two-Row Notation", "Definition:Injection", "Definition:Permutation on n Letters/Two-Row Notation", "Definition:Surjection", "Definition:Composition of Mappings", "Definition:Injection", "Definition:Surjection", "Category:Injections", "Category...
proofwiki-16357
Composition of 3 Mappings where Pairs of Mappings are Bijections
Let $A$, $B$, $C$ and $D$ be sets. Let: :$f: A \to B$ :$g: B \to C$ :$h: C \to D$ be mappings. Let $g \circ f$ and $h \circ g$ be bijections. Then $f$, $g$ and $h$ are all bijections.
We note that both $g \circ f$ and $h \circ g$ are both injections and surjections by definition of bijection. First it is shown that $g$ is a bijection. We are given that: :$g \circ f$ is a bijection. From Injection if Composite is Injection it follows that $f$ is an injection. From Surjection if Composite is Surjectio...
Let $A$, $B$, $C$ and $D$ be [[Definition:Set|sets]]. Let: :$f: A \to B$ :$g: B \to C$ :$h: C \to D$ be [[Definition:Mapping|mappings]]. Let $g \circ f$ and $h \circ g$ be [[Definition:Bijection|bijections]]. Then $f$, $g$ and $h$ are all [[Definition:Bijection|bijections]].
We note that both $g \circ f$ and $h \circ g$ are both [[Definition:Injection|injections]] and [[Definition:Surjection|surjections]] by definition of [[Definition:Bijection|bijection]]. First it is shown that $g$ is a [[Definition:Bijection|bijection]]. We are given that: :$g \circ f$ is a [[Definition:Bijection|bij...
Composition of 3 Mappings where Pairs of Mappings are Bijections
https://proofwiki.org/wiki/Composition_of_3_Mappings_where_Pairs_of_Mappings_are_Bijections
https://proofwiki.org/wiki/Composition_of_3_Mappings_where_Pairs_of_Mappings_are_Bijections
[ "Bijections", "Composite Mappings" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Bijection", "Definition:Bijection" ]
[ "Definition:Injection", "Definition:Surjection", "Definition:Bijection", "Definition:Bijection", "Definition:Bijection", "Injection if Composite is Injection", "Definition:Injection", "Surjection if Composite is Surjection", "Definition:Surjection", "Definition:Bijection", "Injection if Composit...
proofwiki-16358
Mapping Composed with Bijection forming Bijection is Bijection
Let $A$, $B$ and $C$ be sets. Let $f: A \to B$ and $g: B \to C$ be mappings. Let the composite mapping $g \circ f$ be a bijection. Let either $f$ or $g$ be a bijection. Then both $f$ and $g$ are bijections.
We note that $g \circ f$ is both an injection and a surjection by definition of bijection. We are given that: :$g \circ f$ is a bijection. From Injection if Composite is Injection it follows that $f$ is an injection. From Surjection if Composite is Surjection it follows that $g$ is a surjection. {{qed|lemma}} First sup...
Let $A$, $B$ and $C$ be [[Definition:Set|sets]]. Let $f: A \to B$ and $g: B \to C$ be [[Definition:Mapping|mappings]]. Let the [[Definition:Composition of Mappings|composite mapping]] $g \circ f$ be a [[Definition:Bijection|bijection]]. Let either $f$ or $g$ be a [[Definition:Bijection|bijection]]. Then both $f$ a...
We note that $g \circ f$ is both an [[Definition:Injection|injection]] and a [[Definition:Surjection|surjection]] by definition of [[Definition:Bijection|bijection]]. We are given that: :$g \circ f$ is a [[Definition:Bijection|bijection]]. From [[Injection if Composite is Injection]] it follows that $f$ is an [[Defi...
Mapping Composed with Bijection forming Bijection is Bijection
https://proofwiki.org/wiki/Mapping_Composed_with_Bijection_forming_Bijection_is_Bijection
https://proofwiki.org/wiki/Mapping_Composed_with_Bijection_forming_Bijection_is_Bijection
[ "Bijections", "Composite Mappings" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Composition of Mappings", "Definition:Bijection", "Definition:Bijection", "Definition:Bijection" ]
[ "Definition:Injection", "Definition:Surjection", "Definition:Bijection", "Definition:Bijection", "Injection if Composite is Injection", "Definition:Injection", "Surjection if Composite is Surjection", "Definition:Surjection", "Definition:Bijection", "Definition:Injection", "Definition:Surjection...
proofwiki-16359
Composite of Three Mappings in Cycle forming Injections and Surjection
Let $A$, $B$ and $C$ be non-empty sets. Let $f: A \to B$, $g: B \to C$ and $h: C \to A$ be mappings. Let the following hold: :$h \circ g \circ f$ is an injection :$f \circ h \circ g$ is an injection :$g \circ f \circ h$ is a surjection. where: :$g \circ f$ (and so on) denote composition of mappings. Then each of $f$, $...
First note that from Composition of Mappings is Associative: :$\paren {h \circ g} \circ f = h \circ \paren {g \circ f}$ and so on. However, while there is no need to use parenthesis to establish the order of composition of mappings, in the following the technique will be used in order to clarify what is being done. We ...
Let $A$, $B$ and $C$ be [[Definition:Non-Empty Set|non-empty]] [[Definition:Set|sets]]. Let $f: A \to B$, $g: B \to C$ and $h: C \to A$ be [[Definition:Mapping|mappings]]. Let the following hold: :$h \circ g \circ f$ is an [[Definition:Injection|injection]] :$f \circ h \circ g$ is an [[Definition:Injection|injectio...
First note that from [[Composition of Mappings is Associative]]: :$\paren {h \circ g} \circ f = h \circ \paren {g \circ f}$ and so on. However, while there is no need to use [[Definition:Parenthesis|parenthesis]] to establish the order of [[Definition:Composition of Mappings|composition of mappings]], in the followin...
Composite of Three Mappings in Cycle forming Injections and Surjection
https://proofwiki.org/wiki/Composite_of_Three_Mappings_in_Cycle_forming_Injections_and_Surjection
https://proofwiki.org/wiki/Composite_of_Three_Mappings_in_Cycle_forming_Injections_and_Surjection
[ "Injections", "Surjections", "Bijections", "Composite Mappings" ]
[ "Definition:Non-Empty Set", "Definition:Set", "Definition:Mapping", "Definition:Injection", "Definition:Injection", "Definition:Surjection", "Definition:Composition of Mappings", "Definition:Bijection" ]
[ "Composition of Mappings is Associative", "Definition:Parenthesis", "Definition:Composition of Mappings", "Definition:Injection", "Injection if Composite is Injection", "Definition:Injection", "Definition:Injection", "Definition:Injection", "Definition:Injection", "Definition:Injection", "Defini...
proofwiki-16360
Component Mappings of Set Coproduct are Injective
Let $S_1$ and $S_2$ be sets. Let $\struct {C, i_1, i_2}$ be a coproduct of $S_1$ and $S_2$. Then $i_1$ and $i_2$ are injections.
By definition of coproduct: :for all sets $X$ and mappings $f_1: S_1 \to X$ and $f_1: S_1 \to X$ ::there exists a unique mapping $h: C \to X$ such that: :::$h \circ i_1 = f_1$ :::$h \circ i_2 = f_2$ Let $X := S_1$ and $f_1: S_1 \to X = I_{S_1}$ where $I_{S_1}$ denotes the identity mapping. We have: :$h \circ i_1 = I_{S...
Let $S_1$ and $S_2$ be [[Definition:Set|sets]]. Let $\struct {C, i_1, i_2}$ be a [[Definition:Set Coproduct|coproduct]] of $S_1$ and $S_2$. Then $i_1$ and $i_2$ are [[Definition:Injection|injections]].
By definition of [[Definition:Set Coproduct|coproduct]]: :for all [[Definition:Set|sets]] $X$ and [[Definition:Mapping|mappings]] $f_1: S_1 \to X$ and $f_1: S_1 \to X$ ::there exists a unique [[Definition:Mapping|mapping]] $h: C \to X$ such that: :::$h \circ i_1 = f_1$ :::$h \circ i_2 = f_2$ Let $X := S_1$ and $f_1:...
Component Mappings of Set Coproduct are Injective
https://proofwiki.org/wiki/Component_Mappings_of_Set_Coproduct_are_Injective
https://proofwiki.org/wiki/Component_Mappings_of_Set_Coproduct_are_Injective
[ "Set Coproducts" ]
[ "Definition:Set", "Definition:Coproduct/Sets", "Definition:Injection" ]
[ "Definition:Coproduct/Sets", "Definition:Set", "Definition:Mapping", "Definition:Mapping", "Definition:Identity Mapping", "Identity Mapping is Injection", "Definition:Injection", "Injection if Composite is Injection", "Definition:Injection", "Definition:Injection" ]
proofwiki-16361
Coproduct on Disjoint Union
Let $S_1$ and $S_2$ be sets. Let $S_1 \sqcup S_2 := \paren {S_1 \times \set 1} \cup \paren {S_2 \times \set 2}$ be the disjoint union of $S_1$ and $S_2$. Let $i_1: S_1 \to S_1 \sqcup S_2$ and $i_2: S_2 \to S_1 \sqcup S_2$ be the mappings defined as: :$\forall s_1 \in S_1: \map {i_1} {s_1} = \tuple {s_1, 1}$ :$\forall s...
For $\struct {S_1 \sqcup S_2, i_1, i_2}$ to be a coproduct, it is necessary that: :for all sets $X$ and all mappings $f_1: S_1 \to X$ and $f_2: S_2 \to X$ ::there exists a unique mapping $h: S_1 \sqcup S_2 \to X$ such that: :::$h \circ i_1 = f_1$ :::$h \circ i_2 = f_2$ Let $h$ be the mapping defined as: :$\forall \tupl...
Let $S_1$ and $S_2$ be [[Definition:Set|sets]]. Let $S_1 \sqcup S_2 := \paren {S_1 \times \set 1} \cup \paren {S_2 \times \set 2}$ be the [[Definition:Disjoint Union (Set Theory)|disjoint union]] of $S_1$ and $S_2$. Let $i_1: S_1 \to S_1 \sqcup S_2$ and $i_2: S_2 \to S_1 \sqcup S_2$ be the [[Definition:Mapping|mappi...
For $\struct {S_1 \sqcup S_2, i_1, i_2}$ to be a [[Definition:Set Coproduct|coproduct]], it is necessary that: :for all [[Definition:Set|sets]] $X$ and all [[Definition:Mapping|mappings]] $f_1: S_1 \to X$ and $f_2: S_2 \to X$ ::there exists a [[Definition:Unique|unique]] [[Definition:Mapping|mapping]] $h: S_1 \sqcup S...
Coproduct on Disjoint Union
https://proofwiki.org/wiki/Coproduct_on_Disjoint_Union
https://proofwiki.org/wiki/Coproduct_on_Disjoint_Union
[ "Set Coproducts", "Disjoint Unions" ]
[ "Definition:Set", "Definition:Disjoint Union (Set Theory)", "Definition:Mapping", "Definition:Coproduct/Sets" ]
[ "Definition:Coproduct/Sets", "Definition:Set", "Definition:Mapping", "Definition:Unique", "Definition:Mapping", "Definition:Mapping", "Definition:Unique", "Definition:Mapping", "Definition:Unique", "Definition:Coproduct/Sets" ]
proofwiki-16362
Existence of Bijection between Coproducts of two Sets
Let $S_1$ and $S_2$ be sets. Let $\struct {C, i_1, i_2}$ and $\struct {D, j_1, j_2}$ be two coproducts on $S_1$ and $S_2$. Then there exists a unique bijection $\theta: D \to C$ such that: :$\theta \circ j_i = i_1$ :$\theta \circ j_2 = i_2$
Let $X$ be an arbitrary set. Let $f_1: S_1 \to X$ and $f_2: S_2 \to X$ be arbitrary mappings. Let $h_C: C \to X$ be the unique mapping such that: :$h_C \circ i_1 = f_1$ :$h_C \circ i_2 = f_2$ Let $h_D: D \to X$ be the unique mapping such that: :$h_D \circ j_1 = f_1$ :$h_D \circ j_2 = f_2$ The existence and uniqueness o...
Let $S_1$ and $S_2$ be [[Definition:Set|sets]]. Let $\struct {C, i_1, i_2}$ and $\struct {D, j_1, j_2}$ be two [[Definition:Set Coproduct|coproducts]] on $S_1$ and $S_2$. Then there exists a [[Definition:Unique|unique]] [[Definition:Bijection|bijection]] $\theta: D \to C$ such that: :$\theta \circ j_i = i_1$ :$\theta...
Let $X$ be an arbitrary [[Definition:Set|set]]. Let $f_1: S_1 \to X$ and $f_2: S_2 \to X$ be arbitrary [[Definition:Mapping|mappings]]. Let $h_C: C \to X$ be the [[Definition:Unique|unique]] [[Definition:Mapping|mapping]] such that: :$h_C \circ i_1 = f_1$ :$h_C \circ i_2 = f_2$ Let $h_D: D \to X$ be the [[Definiti...
Existence of Bijection between Coproducts of two Sets
https://proofwiki.org/wiki/Existence_of_Bijection_between_Coproducts_of_two_Sets
https://proofwiki.org/wiki/Existence_of_Bijection_between_Coproducts_of_two_Sets
[ "Set Coproducts" ]
[ "Definition:Set", "Definition:Coproduct/Sets", "Definition:Unique", "Definition:Bijection" ]
[ "Definition:Set", "Definition:Mapping", "Definition:Unique", "Definition:Mapping", "Definition:Unique", "Definition:Mapping", "Definition:Unique", "Definition:Coproduct/Sets" ]
proofwiki-16363
Number of Friday 13ths in a Year
In any given year, there are between $1$ and $3$ (inclusive) months in which the $13$th falls on a Friday.
The day of the week on which the $13$th falls is directly dependent upon the day of the week that the $1$st of the month falls. From Months that Start on the Same Day of the Week, the months can be grouped into equivalence classes according to which day of the week the month starts: For a non-leap year, the set of equi...
In any given year, there are between $1$ and $3$ (inclusive) [[Definition:Month|months]] in which the $13$th falls on a Friday.
The [[Definition:Day|day]] of the [[Definition:Week|week]] on which the $13$th falls is directly dependent upon the [[Definition:Day|day]] of the [[Definition:Week|week]] that the $1$st of the [[Definition:Month|month]] falls. From [[Equivalence Class/Examples/Months that Start on the Same Day of the Week|Months that ...
Number of Friday 13ths in a Year
https://proofwiki.org/wiki/Number_of_Friday_13ths_in_a_Year
https://proofwiki.org/wiki/Number_of_Friday_13ths_in_a_Year
[ "Calendars" ]
[ "Definition:Time/Unit/Month" ]
[ "Definition:Time/Unit/Day", "Definition:Time/Unit/Week", "Definition:Time/Unit/Day", "Definition:Time/Unit/Week", "Definition:Time/Unit/Month", "Equivalence Class/Examples/Months that Start on the Same Day of the Week", "Definition:Time/Unit/Month", "Definition:Equivalence Class", "Definition:Time/U...
proofwiki-16364
Equivalence Relation on Natural Numbers such that Quotient is Power of Two/Equivalence Class Contains 1 Odd Number
Let $\eqclass n \alpha$ be the $\alpha$-equivalence class of a natural number $n$. Then $\eqclass n \alpha$ contains exactly $1$ odd number.
That $\alpha$ is an equivalence relation is proved in Equivalence Relation on Natural Numbers such that Quotient is Power of Two. Let $x$ be a natural number whose $\alpha$-equivalence class is $\eqclass x \alpha$. If $x$ is odd, then $\eqclass x \alpha$ contains that odd number $x$ We have that $x$ is of the form $x =...
Let $\eqclass n \alpha$ be the [[Definition:Equivalence Class|$\alpha$-equivalence class]] of a [[Definition:Natural Number|natural number]] $n$. Then $\eqclass n \alpha$ contains [[Definition:Unique|exactly $1$]] [[Definition:Odd Number|odd number]].
That $\alpha$ is an [[Definition:Equivalence Relation|equivalence relation]] is proved in [[Equivalence Relation on Natural Numbers such that Quotient is Power of Two]]. Let $x$ be a [[Definition:Natural Number|natural number]] whose [[Definition:Equivalence Class|$\alpha$-equivalence class]] is $\eqclass x \alpha$. ...
Equivalence Relation on Natural Numbers such that Quotient is Power of Two/Equivalence Class Contains 1 Odd Number
https://proofwiki.org/wiki/Equivalence_Relation_on_Natural_Numbers_such_that_Quotient_is_Power_of_Two/Equivalence_Class_Contains_1_Odd_Number
https://proofwiki.org/wiki/Equivalence_Relation_on_Natural_Numbers_such_that_Quotient_is_Power_of_Two/Equivalence_Class_Contains_1_Odd_Number
[ "Equivalence Relation on Natural Numbers such that Quotient is Power of Two", "Examples of Equivalence Relations" ]
[ "Definition:Equivalence Class", "Definition:Natural Numbers", "Definition:Unique", "Definition:Odd Integer" ]
[ "Definition:Equivalence Relation", "Equivalence Relation on Natural Numbers such that Quotient is Power of Two", "Definition:Natural Numbers", "Definition:Equivalence Class", "Definition:Odd Integer", "Definition:Odd Integer", "Definition:Odd Integer", "Definition:Odd Integer", "Definition:Odd Integ...
proofwiki-16365
Equivalence Relation on Natural Numbers such that Quotient is Power of Two/One of Pair of Equivalent Elements is Divisor of the Other
Let $c, d \in \N$ such that $c \mathrel \alpha d$. Then either: :$c \divides d$ or: :$d \divides c$ where $\divides$ denotes divisibility.
That $\alpha$ is an equivalence relation is proved in Equivalence Relation on Natural Numbers such that Quotient is Power of Two. We are given that $c \mathrel \alpha d$. {{WLOG}}, suppose $c < d$. If $d < c$ then the same argument holds, {{mutatis}}. By definition of $\alpha$, we have that: :$c = 2^n d$ for some $n \i...
Let $c, d \in \N$ such that $c \mathrel \alpha d$. Then either: :$c \divides d$ or: :$d \divides c$ where $\divides$ denotes [[Definition:Divisor of Integer|divisibility]].
That $\alpha$ is an [[Definition:Equivalence Relation|equivalence relation]] is proved in [[Equivalence Relation on Natural Numbers such that Quotient is Power of Two]]. We are given that $c \mathrel \alpha d$. {{WLOG}}, suppose $c < d$. If $d < c$ then the same argument holds, {{mutatis}}. By definition of $\alp...
Equivalence Relation on Natural Numbers such that Quotient is Power of Two/One of Pair of Equivalent Elements is Divisor of the Other
https://proofwiki.org/wiki/Equivalence_Relation_on_Natural_Numbers_such_that_Quotient_is_Power_of_Two/One_of_Pair_of_Equivalent_Elements_is_Divisor_of_the_Other
https://proofwiki.org/wiki/Equivalence_Relation_on_Natural_Numbers_such_that_Quotient_is_Power_of_Two/One_of_Pair_of_Equivalent_Elements_is_Divisor_of_the_Other
[ "Equivalence Relation on Natural Numbers such that Quotient is Power of Two" ]
[ "Definition:Divisor (Algebra)/Integer" ]
[ "Definition:Equivalence Relation", "Equivalence Relation on Natural Numbers such that Quotient is Power of Two", "Definition:Divisor (Algebra)/Integer" ]
proofwiki-16366
Exists Divisor in Set of n+1 Natural Numbers no greater than 2n
Let $S$ be a set of $n + 1$ non-non-zero natural numbers all less than or equal to $2 n$. Then there exists $a, b \in S$ such that :$a \divides b$ where $\divides$ denotes divisibility.
Let $\alpha$ denote the relation defined on the natural numbers $\N$ by: :$\forall x, y \in \N: x \mathrel \alpha y \iff \exists n \in \Z: x = 2^n y$ From Equivalence Relation on Natural Numbers such that Quotient is Power of Two, $\alpha$ is an equivalence relation. From Equivalence Class under $\alpha$ Contains $1$ O...
Let $S$ be a [[Definition:Set|set]] of $n + 1$ non-[[Definition:Zero (Number)|non-zero]] [[Definition:Natural Number|natural numbers]] all less than or equal to $2 n$. Then there exists $a, b \in S$ such that :$a \divides b$ where $\divides$ denotes [[Definition:Divisor of Integer|divisibility]].
Let $\alpha$ denote the [[Definition:Relation|relation]] defined on the [[Definition:Natural Numbers|natural numbers]] $\N$ by: :$\forall x, y \in \N: x \mathrel \alpha y \iff \exists n \in \Z: x = 2^n y$ From [[Equivalence Relation on Natural Numbers such that Quotient is Power of Two]], $\alpha$ is an [[Definition:E...
Exists Divisor in Set of n+1 Natural Numbers no greater than 2n
https://proofwiki.org/wiki/Exists_Divisor_in_Set_of_n+1_Natural_Numbers_no_greater_than_2n
https://proofwiki.org/wiki/Exists_Divisor_in_Set_of_n+1_Natural_Numbers_no_greater_than_2n
[ "Divisibility" ]
[ "Definition:Set", "Definition:Zero (Number)", "Definition:Natural Numbers", "Definition:Divisor (Algebra)/Integer" ]
[ "Definition:Relation", "Definition:Natural Numbers", "Equivalence Relation on Natural Numbers such that Quotient is Power of Two", "Definition:Equivalence Relation", "Equivalence Relation on Natural Numbers such that Quotient is Power of Two/Equivalence Class Contains 1 Odd Number", "Definition:Odd Intege...
proofwiki-16367
Equality of Squares Modulo Integer is Equivalence Relation
Let $n \in \Z_{>0}$ be a (strictly) positive integer. Let $\RR_n$ be the relation on the set of integers $\Z$ defined as: :$\forall x, y \in \Z: x \mathrel {\RR_n} y \iff x^2 \equiv y^2 \pmod n$ Then $\RR_n$ is an equivalence relation.
Checking in turn each of the criteria for equivalence:
Let $n \in \Z_{>0}$ be a [[Definition:Strictly Positive Integer|(strictly) positive integer]]. Let $\RR_n$ be the [[Definition:Endorelation|relation]] on the [[Definition:Integer|set of integers]] $\Z$ defined as: :$\forall x, y \in \Z: x \mathrel {\RR_n} y \iff x^2 \equiv y^2 \pmod n$ Then $\RR_n$ is an [[Definition...
Checking in turn each of the criteria for [[Definition:Equivalence Relation|equivalence]]:
Equality of Squares Modulo Integer is Equivalence Relation
https://proofwiki.org/wiki/Equality_of_Squares_Modulo_Integer_is_Equivalence_Relation
https://proofwiki.org/wiki/Equality_of_Squares_Modulo_Integer_is_Equivalence_Relation
[ "Examples of Equivalence Relations", "Examples of Equivalence Relations" ]
[ "Definition:Strictly Positive/Integer", "Definition:Endorelation", "Definition:Integer", "Definition:Equivalence Relation" ]
[ "Definition:Equivalence Relation", "Definition:Equivalence Relation" ]
proofwiki-16368
Left Ideal is Left Module over Ring
Let $\struct {R, +, \times}$ be a ring. Let $J \subseteq R$ be a left ideal of $R$. Let $\circ : R \times J \to J$ be the restriction of $\times$ to $R \times J$. Then $\struct {J, +, \circ}$ is a left module over $\struct {R, +, \times}$.
By definition of a left ideal then $\circ$ is well-defined.
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $J \subseteq R$ be a [[Definition:Left Ideal of Ring|left ideal]] of $R$. Let $\circ : R \times J \to J$ be the [[Definition:Restriction of Mapping|restriction]] of $\times$ to $R \times J$. Then $\struct {J, +, \circ}$ is a [[Defini...
By definition of a [[Definition:Left Ideal of Ring|left ideal]] then $\circ$ is [[Definition:Well-Defined|well-defined]].
Left Ideal is Left Module over Ring
https://proofwiki.org/wiki/Left_Ideal_is_Left_Module_over_Ring
https://proofwiki.org/wiki/Left_Ideal_is_Left_Module_over_Ring
[ "Left Ideal is Left Module over Ring", "Left Modules over Rings", "Ideal Theory" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Ideal of Ring/Left Ideal", "Definition:Restriction/Mapping", "Definition:Left Module over Ring" ]
[ "Definition:Ideal of Ring/Left Ideal", "Definition:Well-Defined" ]
proofwiki-16369
Right Ideal is Right Module over Ring
Let $\struct {R, +, \times}$ be a ring. Let $J \subseteq R$ be a right ideal of $R$. Let $\circ : J \times R \to J$ be the restriction of $\times$ to $J \times R$. Then $\struct {J, +, \circ}$ is a right module over $\struct {R, +, \times}$.
By definition of a right ideal then $\circ$ is well-defined.
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $J \subseteq R$ be a [[Definition:Right Ideal of Ring|right ideal]] of $R$. Let $\circ : J \times R \to J$ be the [[Definition:Restriction of Mapping|restriction]] of $\times$ to $J \times R$. Then $\struct {J, +, \circ}$ is a [[Defi...
By definition of a [[Definition:Right Ideal of Ring|right ideal]] then $\circ$ is [[Definition:Well-Defined|well-defined]].
Right Ideal is Right Module over Ring
https://proofwiki.org/wiki/Right_Ideal_is_Right_Module_over_Ring
https://proofwiki.org/wiki/Right_Ideal_is_Right_Module_over_Ring
[ "Right Ideal is Right Module over Ring", "Module Theory", "Ideal Theory" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Ideal of Ring/Right Ideal", "Definition:Restriction/Mapping", "Definition:Right Module over Ring" ]
[ "Definition:Ideal of Ring/Right Ideal", "Definition:Well-Defined" ]
proofwiki-16370
Opposite Ring is Ring
Let $\struct {R, +, \times}$ be a ring. Let $\struct {R, +, *}$ be the opposite ring of $\struct {R, +, \times}$. Then $\struct {R, +, *}$ is a ring.
By definition of the opposite ring: :$\forall x, y \in R: x * y = y \times x$. By definition of the ring $R$, $\struct {R, +}$ is an abelian group. To complete the proof, it remains to be shown that $\struct {R, *}$ is a semigroup. That is, it remains to show that $\struct{R, *}$ is associative. Let $a, b, c \in R$. {{...
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct {R, +, *}$ be the [[Definition:Opposite Ring|opposite ring]] of $\struct {R, +, \times}$. Then $\struct {R, +, *}$ is a [[Definition:Ring (Abstract Algebra)|ring]].
By definition of the [[Definition:Opposite Ring|opposite ring]]: :$\forall x, y \in R: x * y = y \times x$. By definition of the [[Definition:Ring (Abstract Algebra)|ring]] $R$, $\struct {R, +}$ is an [[Definition:Abelian Group|abelian group]]. To complete the proof, it remains to be shown that $\struct {R, *}$ is a...
Opposite Ring is Ring
https://proofwiki.org/wiki/Opposite_Ring_is_Ring
https://proofwiki.org/wiki/Opposite_Ring_is_Ring
[ "Examples of Rings" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Opposite Ring", "Definition:Ring (Abstract Algebra)" ]
[ "Definition:Opposite Ring", "Definition:Ring (Abstract Algebra)", "Definition:Abelian Group", "Definition:Semigroup", "Definition:Associative Operation" ]
proofwiki-16371
Opposite Ring of Opposite Ring
Let $\struct {R, +, \times}$ be a ring. Let $\struct {R, +, *}$ be the opposite ring of $\struct {R, +, \times}$. Let $\struct {R, +, \circ}$ be the opposite ring of $\struct {R, +, *}$. Then $\struct {R, +, \circ} = \struct {R, +, \times}$.
By definition of the opposite ring: :$\forall x, y \in S: x * y = y \times x$ :$\forall x, y \in S: x \circ y = y * x$ Hence for all $x,y \in S$: :$x \circ y = y * x = x \times y$ The result follows. {{qed}} Category:Ring Theory k14myncy6bkp8xbic8ndvx15pkuigex
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct {R, +, *}$ be the [[Definition:Opposite Ring|opposite ring]] of $\struct {R, +, \times}$. Let $\struct {R, +, \circ}$ be the [[Definition:Opposite Ring|opposite ring]] of $\struct {R, +, *}$. Then $\struct {R, +, \circ} = \s...
By definition of the [[Definition:Opposite Ring|opposite ring]]: :$\forall x, y \in S: x * y = y \times x$ :$\forall x, y \in S: x \circ y = y * x$ Hence for all $x,y \in S$: :$x \circ y = y * x = x \times y$ The result follows. {{qed}} [[Category:Ring Theory]] k14myncy6bkp8xbic8ndvx15pkuigex
Opposite Ring of Opposite Ring
https://proofwiki.org/wiki/Opposite_Ring_of_Opposite_Ring
https://proofwiki.org/wiki/Opposite_Ring_of_Opposite_Ring
[ "Ring Theory" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Opposite Ring", "Definition:Opposite Ring" ]
[ "Definition:Opposite Ring", "Category:Ring Theory" ]
proofwiki-16372
Left Module over Ring Induces Right Module over Opposite Ring
Let $\struct {R, +_R, \times_R}$ be a ring. Let $\struct {R, +_R, *_R}$ be the opposite ring of $\struct {R, +_R, \times_R}$. Let $\struct{G, +_G, \circ}$ be a left module over $\struct {R, +_R, \times_R}$. Let $\circ' : G \times R \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: x \...
It is shown that $\struct{G, +_G, \circ'}$ satisfies the right module axioms. By definition of the opposite ring: :$\forall x, y \in R: x *_R y = y \times_R x$
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct {R, +_R, *_R}$ be the [[Definition:Opposite Ring|opposite ring]] of $\struct {R, +_R, \times_R}$. Let $\struct{G, +_G, \circ}$ be a [[Definition:Left Module over Ring|left module]] over $\struct {R, +_R, \times_R}$. Let $...
It is shown that $\struct{G, +_G, \circ'}$ satisfies the [[Axiom:Right Module Axioms|right module axioms]]. By definition of the [[Definition:Opposite Ring|opposite ring]]: :$\forall x, y \in R: x *_R y = y \times_R x$
Left Module over Ring Induces Right Module over Opposite Ring
https://proofwiki.org/wiki/Left_Module_over_Ring_Induces_Right_Module_over_Opposite_Ring
https://proofwiki.org/wiki/Left_Module_over_Ring_Induces_Right_Module_over_Opposite_Ring
[ "Right Modules over Rings", "Left Modules over Rings", "Modules over Rings" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Opposite Ring", "Definition:Left Module over Ring", "Definition:Operation/Binary Operation", "Definition:Right Module over Ring" ]
[ "Axiom:Right Module Axioms", "Definition:Opposite Ring" ]
proofwiki-16373
Right Module over Ring Induces Left Module over Opposite Ring
Let $\struct {R, +_R, \times_R}$ be a ring. Let $\struct {R, +_R, *_R}$ be the opposite ring of $\struct {R, +_R, \times_R}$. Let $\struct{G, +_G, \circ}$ be a right module over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: \l...
It is shown that $\struct {G, +_G, \circ'}$ satisfies the left module axioms. By definition of the opposite ring: :$\forall x, y \in S: x *_R y = y \times_R x$.
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct {R, +_R, *_R}$ be the [[Definition:Opposite Ring|opposite ring]] of $\struct {R, +_R, \times_R}$. Let $\struct{G, +_G, \circ}$ be a [[Definition:Right Module over Ring|right module]] over $\struct {R, +_R, \times_R}$. Let...
It is shown that $\struct {G, +_G, \circ'}$ satisfies the [[Axiom:Left Module Axioms|left module axioms]]. By definition of the [[Definition:Opposite Ring|opposite ring]]: :$\forall x, y \in S: x *_R y = y \times_R x$.
Right Module over Ring Induces Left Module over Opposite Ring
https://proofwiki.org/wiki/Right_Module_over_Ring_Induces_Left_Module_over_Opposite_Ring
https://proofwiki.org/wiki/Right_Module_over_Ring_Induces_Left_Module_over_Opposite_Ring
[ "Right Modules over Rings", "Left Modules over Rings", "Modules over Rings" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Opposite Ring", "Definition:Right Module over Ring", "Definition:Operation/Binary Operation", "Definition:Left Module over Ring" ]
[ "Axiom:Left Module Axioms", "Definition:Opposite Ring" ]
proofwiki-16374
Ring is Commutative iff Opposite Ring is Itself
Let $\struct {R, +, \times}$ be a ring. Let $\struct {R, +, *}$ be the opposite ring of $\struct {R, +, \times}$. Then $\struct {R, +, \times}$ is a commutative ring {{iff}}: :$\struct {R, +, \times} = \struct {R, +, *}$
By definition of the opposite ring: :$\forall x, y \in R: x * y = y \times x$
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct {R, +, *}$ be the [[Definition:Opposite Ring|opposite ring]] of $\struct {R, +, \times}$. Then $\struct {R, +, \times}$ is a [[Definition:Commutative Ring|commutative ring]] {{iff}}: :$\struct {R, +, \times} = \struct {R, +, ...
By definition of the [[Definition:Opposite Ring|opposite ring]]: :$\forall x, y \in R: x * y = y \times x$
Ring is Commutative iff Opposite Ring is Itself
https://proofwiki.org/wiki/Ring_is_Commutative_iff_Opposite_Ring_is_Itself
https://proofwiki.org/wiki/Ring_is_Commutative_iff_Opposite_Ring_is_Itself
[ "Examples of Rings" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Opposite Ring", "Definition:Commutative Ring" ]
[ "Definition:Opposite Ring" ]
proofwiki-16375
Ceva's Theorem
Let $\triangle ABC$ be a triangle. Let $L$, $M$ and $N$ be points on the sides $BC$, $AC$ and $AB$ respectively. Then the lines $AL$, $BM$ and $CN$ are concurrent {{iff}}: :$\dfrac {BL} {LC} \times \dfrac {CM} {MA} \times \dfrac {AN} {NB} = 1$
:400px === Necessary Condition === Let $AL$, $BM$ and $CN$ be concurrent. Let the point of concurrency be $P$. Consider the triangles $\triangle ALB$ and $\triangle ALC$. They have the same altitude from the common base $BC$. Hence: :$\dfrac {\map \Area {ALB} } {\map \Area {ALC} } = \dfrac {BL} {LC}$ Similarly, conside...
Let $\triangle ABC$ be a [[Definition:Triangle (Geometry)|triangle]]. Let $L$, $M$ and $N$ be [[Definition:Point|points]] on the [[Definition:Side of Polygon|sides]] $BC$, $AC$ and $AB$ respectively. Then the [[Definition:Line Segment|lines]] $AL$, $BM$ and $CN$ are [[Definition:Concurrent Lines|concurrent]] {{iff}}...
:[[File:Cevas-Theorem.png|400px]] === Necessary Condition === Let $AL$, $BM$ and $CN$ be [[Definition:Concurrent Lines|concurrent]]. Let the point of [[Definition:Concurrent Lines|concurrency]] be $P$. Consider the [[Definition:Triangle (Geometry)|triangles]] $\triangle ALB$ and $\triangle ALC$. They have the sam...
Ceva's Theorem/Proof 1
https://proofwiki.org/wiki/Ceva's_Theorem
https://proofwiki.org/wiki/Ceva's_Theorem/Proof_1
[ "Ceva's Theorem", "Triangles", "Concurrency" ]
[ "Definition:Triangle (Geometry)", "Definition:Point", "Definition:Polygon/Side", "Definition:Line/Segment", "Definition:Concurrent Lines" ]
[ "File:Cevas-Theorem.png", "Definition:Concurrent Lines", "Definition:Concurrent Lines", "Definition:Triangle (Geometry)", "Definition:Altitude of Triangle", "Definition:Triangle (Geometry)/Base", "Definition:Triangle (Geometry)", "Definition:Altitude of Triangle", "Definition:Triangle (Geometry)/Bas...
proofwiki-16376
Ceva's Theorem
Let $\triangle ABC$ be a triangle. Let $L$, $M$ and $N$ be points on the sides $BC$, $AC$ and $AB$ respectively. Then the lines $AL$, $BM$ and $CN$ are concurrent {{iff}}: :$\dfrac {BL} {LC} \times \dfrac {CM} {MA} \times \dfrac {AN} {NB} = 1$
=== Necessary Condition === We have {{hypothesis}}: :$AL$, $BM$ and $CN$ are concurrent in $\triangle ABC$ at point $P$. :400px Following the sides anticlockwise in $\triangle LAB$: {{begin-eqn}} {{eqn | n = 1 | l = \dfrac {LP} {PA} \cdot \dfrac {AN} {NB} \cdot \dfrac {BC} {CL} | r = -1 | c = Menelaus...
Let $\triangle ABC$ be a [[Definition:Triangle (Geometry)|triangle]]. Let $L$, $M$ and $N$ be [[Definition:Point|points]] on the [[Definition:Side of Polygon|sides]] $BC$, $AC$ and $AB$ respectively. Then the [[Definition:Line Segment|lines]] $AL$, $BM$ and $CN$ are [[Definition:Concurrent Lines|concurrent]] {{iff}}...
=== Necessary Condition === We have {{hypothesis}}: :$AL$, $BM$ and $CN$ are [[Definition:Concurrent|concurrent]] in $\triangle ABC$ at [[Definition:Point|point]] $P$. :[[File:Cevas-Theorem.png|400px]] Following the [[Definition:Side|sides]] [[Definition:Anticlockwise|anticlockwise]] in $\triangle LAB$: {{begin-eqn...
Ceva's Theorem/Proof 2
https://proofwiki.org/wiki/Ceva's_Theorem
https://proofwiki.org/wiki/Ceva's_Theorem/Proof_2
[ "Ceva's Theorem", "Triangles", "Concurrency" ]
[ "Definition:Triangle (Geometry)", "Definition:Point", "Definition:Polygon/Side", "Definition:Line/Segment", "Definition:Concurrent Lines" ]
[ "Definition:Concurrent", "Definition:Point", "File:Cevas-Theorem.png", "Definition:Side", "Definition:Anticlockwise", "Menelaus's Theorem", "Definition:Side", "Definition:Clockwise", "Menelaus's Theorem", "Definition:Directed Line Segment", "Definition:Concurrent", "Definition:Point", "Defin...
proofwiki-16377
Left Module induces Right Module over same Ring iff Actions are Commutative
Let $\struct {R, +_R, \times_R}$ be a ring. Let $\struct {G, +_G, \circ}$ be a left module over $\struct {R, +_R, \times_R}$. Let $\circ': G \times R \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: x \circ' \lambda = \lambda \circ x$ Then $\struct {G, +_G, \circ'}$ is a right module...
=== Necessary Condition === Let $\struct {G, +_G, \circ'}$ be a right module over $\struct {R, +_R, \times_R}$. Then: {{begin-eqn}} {{eqn | l = \paren {\lambda \times_R \mu} \circ x | r = x \circ' \paren {\lambda \times_R \mu} | c = Definition of $\circ'$ }} {{eqn | r = \paren {x \circ' \lambda} \circ' \mu ...
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct {G, +_G, \circ}$ be a [[Definition:Left Module over Ring|left module]] over $\struct {R, +_R, \times_R}$. Let $\circ': G \times R \to G$ be the [[Definition:Binary Operation|binary operation]] defined by: :$\forall \lambda...
=== Necessary Condition === Let $\struct {G, +_G, \circ'}$ be a [[Definition:Right Module over Ring|right module]] over $\struct {R, +_R, \times_R}$. Then: {{begin-eqn}} {{eqn | l = \paren {\lambda \times_R \mu} \circ x | r = x \circ' \paren {\lambda \times_R \mu} | c = Definition of $\circ'$ }} {{eqn | r...
Left Module induces Right Module over same Ring iff Actions are Commutative
https://proofwiki.org/wiki/Left_Module_induces_Right_Module_over_same_Ring_iff_Actions_are_Commutative
https://proofwiki.org/wiki/Left_Module_induces_Right_Module_over_same_Ring_iff_Actions_are_Commutative
[ "Module Theory", "Ring Theory" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Left Module over Ring", "Definition:Operation/Binary Operation", "Definition:Right Module over Ring" ]
[ "Definition:Right Module over Ring" ]
proofwiki-16378
Right Module induces Left Module over same Ring iff Actions are Commutative
Let $\struct {R, +_R, \times_R}$ be a ring. Let $\struct {G, +_G, \circ}$ be a right module over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: \lambda \circ' x = x \circ \lambda $ Then $\struct {G, +_G, \circ'}$ is a left modu...
=== Necessary Condition === Let $\struct {G, +_G, \circ'}$ be a left module over $\struct {R, +_R, \times_R}$. Then: {{begin-eqn}} {{eqn | l = x \circ \paren {\lambda \times_R \mu} | r = \paren {\lambda \times_R \mu} \circ' x | c = Definition of $\circ'$ }} {{eqn | r = \lambda \circ' \paren {\mu \circ' x} ...
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct {G, +_G, \circ}$ be a [[Definition:Right Module over Ring|right module]] over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the [[Definition:Binary Operation|binary operation]] defined by: :$\forall \lam...
=== Necessary Condition === Let $\struct {G, +_G, \circ'}$ be a [[Definition:Left Module over Ring|left module]] over $\struct {R, +_R, \times_R}$. Then: {{begin-eqn}} {{eqn | l = x \circ \paren {\lambda \times_R \mu} | r = \paren {\lambda \times_R \mu} \circ' x | c = Definition of $\circ'$ }} {{eqn | r =...
Right Module induces Left Module over same Ring iff Actions are Commutative
https://proofwiki.org/wiki/Right_Module_induces_Left_Module_over_same_Ring_iff_Actions_are_Commutative
https://proofwiki.org/wiki/Right_Module_induces_Left_Module_over_same_Ring_iff_Actions_are_Commutative
[ "Module Theory", "Ring Theory" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Right Module over Ring", "Definition:Operation/Binary Operation", "Definition:Left Module over Ring" ]
[ "Definition:Left Module over Ring" ]
proofwiki-16379
Fermat Problem
Let $\triangle ABC$ be a triangle Let the vertices of $\triangle ABC$ all have angles less than $120 \degrees$. Let $\triangle ABG$, $\triangle BCE$ and $\triangle ACF$ be equilateral triangles constructed on the sides of $ABC$. Let $AE$, $BF$ and $CG$ be constructed. Let $P$ be the point at which $AE$, $BF$ and $CG$ m...
The sum of the distances will be a minimum when the lines $PA$, $PB$ and $PC$ all meet at an angle of $120 \degrees$. This is a consequence of the '''Fermat problem''' being a special case of the Steiner tree problem. Consider the circles which circumscribe the $3$ equilateral triangles $\triangle ABG$, $\triangle BCE$...
Let $\triangle ABC$ be a [[Definition:Triangle (Geometry)|triangle]] Let the [[Definition:Vertex of Polygon|vertices]] of $\triangle ABC$ all have [[Definition:Plane Angle|angles]] less than $120 \degrees$. Let $\triangle ABG$, $\triangle BCE$ and $\triangle ACF$ be [[Definition:Equilateral Triangle|equilateral tria...
The sum of the [[Definition:Distance between Points|distances]] will be a minimum when the [[Definition:Line Segment|lines]] $PA$, $PB$ and $PC$ all meet at an [[Definition:Plane Angle|angle]] of $120 \degrees$. This is a consequence of the '''[[Fermat Problem|Fermat problem]]''' being a special case of the [[Steiner ...
Fermat Problem
https://proofwiki.org/wiki/Fermat_Problem
https://proofwiki.org/wiki/Fermat_Problem
[ "Fermat Problem", "Fermat-Torricelli Point", "Triangles", "Extremum Problems" ]
[ "Definition:Triangle (Geometry)", "Definition:Polygon/Vertex", "Definition:Angle", "Definition:Triangle (Geometry)/Equilateral", "Definition:Polygon/Side", "Definition:Point", "File:FermatPointConstruction.png", "Definition:Fermat-Torricelli Point", "Definition:Polygon/Vertex", "Definition:Polygon...
[ "Definition:Distance between Points", "Definition:Line/Segment", "Definition:Angle", "Fermat Problem", "Steiner Tree Problem", "Definition:Circle", "Definition:Circumscribe/Circle around Polygon", "Definition:Triangle (Geometry)/Equilateral", "Definition:Quadrilateral", "Definition:Point", "Defi...
proofwiki-16380
Left Module over Commutative Ring induces Right Module
Let $\struct {R, +_R, \times_R}$ be a commutative ring. Let $\struct {G, +_G, \circ}$ be a left module over $\struct {R, +_R, \times_R}$. Let $\circ' : G \times R \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: x \circ' \lambda = \lambda \circ x$ Then $\struct {G, +_G, \circ'}$ is a...
From Ring is Commutative iff Opposite Ring is Itself, $\struct {R, +_R, \times_R}$ is its own opposite ring. From Left Module over Ring Induces Right Module over Opposite Ring, $\struct {G, +_G, \circ'}$ is a right module over $\struct {R, +_R, \times_R}$. {{qed}}
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Commutative Ring|commutative ring]]. Let $\struct {G, +_G, \circ}$ be a [[Definition:Left Module over Ring|left module]] over $\struct {R, +_R, \times_R}$. Let $\circ' : G \times R \to G$ be the [[Definition:Binary Operation|binary operation]] defined by: :$\forall \...
From [[Ring is Commutative iff Opposite Ring is Itself]], $\struct {R, +_R, \times_R}$ is its own [[Definition:Opposite Ring|opposite ring]]. From [[Left Module over Ring Induces Right Module over Opposite Ring]], $\struct {G, +_G, \circ'}$ is a [[Definition:Right Module over Ring|right module]] over $\struct {R, +_R,...
Left Module over Commutative Ring induces Right Module
https://proofwiki.org/wiki/Left_Module_over_Commutative_Ring_induces_Right_Module
https://proofwiki.org/wiki/Left_Module_over_Commutative_Ring_induces_Right_Module
[ "Right Modules over Rings", "Left Modules over Rings", "Modules over Rings" ]
[ "Definition:Commutative Ring", "Definition:Left Module over Ring", "Definition:Operation/Binary Operation", "Definition:Right Module over Ring" ]
[ "Ring is Commutative iff Opposite Ring is Itself", "Definition:Opposite Ring", "Left Module over Ring Induces Right Module over Opposite Ring", "Definition:Right Module over Ring" ]
proofwiki-16381
Right Module over Commutative Ring induces Left Module
Let $\struct {R, +_R, \times_R}$ be a commutative ring. Let $\struct{G, +_G, \circ}$ be a right module over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: \lambda \circ’ x = x \circ \lambda$ Then $\struct{G, +_G, \circ'}$ is a ...
From Ring is Commutative iff Opposite Ring is Itself, $\struct {R, +_R, \times_R}$ is its own opposite ring. From Right Module over Ring Induces Left Module over Opposite Ring, $\struct{G, +_G, \circ'}$ is a left module over $\struct {R, +_R, \times_R}$. {{qed}}
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Commutative Ring|commutative ring]]. Let $\struct{G, +_G, \circ}$ be a [[Definition:Right Module over Ring|right module]] over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the [[Definition:Binary Operation|binary operation]] defined by: :$\forall ...
From [[Ring is Commutative iff Opposite Ring is Itself]], $\struct {R, +_R, \times_R}$ is its own [[Definition:Opposite Ring|opposite ring]]. From [[Right Module over Ring Induces Left Module over Opposite Ring]], $\struct{G, +_G, \circ'}$ is a [[Definition:Left Module over Ring|left module]] over $\struct {R, +_R, \t...
Right Module over Commutative Ring induces Left Module
https://proofwiki.org/wiki/Right_Module_over_Commutative_Ring_induces_Left_Module
https://proofwiki.org/wiki/Right_Module_over_Commutative_Ring_induces_Left_Module
[ "Right Modules over Rings", "Left Modules over Rings", "Modules over Rings" ]
[ "Definition:Commutative Ring", "Definition:Right Module over Ring", "Definition:Operation/Binary Operation", "Definition:Left Module over Ring" ]
[ "Ring is Commutative iff Opposite Ring is Itself", "Definition:Opposite Ring", "Right Module over Ring Induces Left Module over Opposite Ring", "Definition:Left Module over Ring" ]
proofwiki-16382
Right Ideal is Right Module over Ring/Ring is Right Module over Ring
Let $\struct {R, +, \times}$ be a ring. Then $\struct {R, +, \times}$ is a right module over $\struct {R, +, \times}$.
From Ring is Ideal of Itself, $R$ is a right ideal. From Right Ideal is Right Module over Ring, $\struct {R, +, \times}$ is a right module over $\struct {R, +, \times}$. {{qed}}
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Then $\struct {R, +, \times}$ is a [[Definition:Right Module over Ring|right module]] over $\struct {R, +, \times}$.
From [[Ring is Ideal of Itself]], $R$ is a [[Definition:Right Ideal of Ring|right ideal]]. From [[Right Ideal is Right Module over Ring]], $\struct {R, +, \times}$ is a [[Definition:Right Module over Ring|right module]] over $\struct {R, +, \times}$. {{qed}}
Right Ideal is Right Module over Ring/Ring is Right Module over Ring
https://proofwiki.org/wiki/Right_Ideal_is_Right_Module_over_Ring/Ring_is_Right_Module_over_Ring
https://proofwiki.org/wiki/Right_Ideal_is_Right_Module_over_Ring/Ring_is_Right_Module_over_Ring
[ "Right Ideal is Right Module over Ring" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Right Module over Ring" ]
[ "Ring is Ideal of Itself", "Definition:Ideal of Ring/Right Ideal", "Right Ideal is Right Module over Ring", "Definition:Right Module over Ring" ]
proofwiki-16383
Left Ideal is Left Module over Ring/Ring is Left Module over Ring
Let $\struct {R, +, \times}$ be a ring. Then $\struct {R, +, \times}$ is a left module over $\struct {R, +, \times}$.
From Ring is Ideal of Itself, $R$ is a left ideal. From Left Ideal is Left Module over Ring, $\struct {R, +, \times}$ is a left module over $\struct {R, +, \times}$. {{qed}}
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Then $\struct {R, +, \times}$ is a [[Definition:Left Module over Ring|left module]] over $\struct {R, +, \times}$.
From [[Ring is Ideal of Itself]], $R$ is a [[Definition:Left Ideal of Ring|left ideal]]. From [[Left Ideal is Left Module over Ring]], $\struct {R, +, \times}$ is a [[Definition:Left Module over Ring|left module]] over $\struct {R, +, \times}$. {{qed}}
Left Ideal is Left Module over Ring/Ring is Left Module over Ring
https://proofwiki.org/wiki/Left_Ideal_is_Left_Module_over_Ring/Ring_is_Left_Module_over_Ring
https://proofwiki.org/wiki/Left_Ideal_is_Left_Module_over_Ring/Ring_is_Left_Module_over_Ring
[ "Left Ideal is Left Module over Ring" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Left Module over Ring" ]
[ "Ring is Ideal of Itself", "Definition:Ideal of Ring/Left Ideal", "Left Ideal is Left Module over Ring", "Definition:Left Module over Ring" ]
proofwiki-16384
Integration by Inversion
:$\ds \int_0^{+\infty} \map f x \rd x = \int_0^{+\infty} \dfrac {\map f {\frac 1 x} } {x^2} \rd x$
{{begin-eqn}} {{eqn | l = \int_0^{+\infty} \map f x \rd x | r = \int_{x \mathop \to 0}^{x \mathop \to +\infty} \map f x \rd x | c = {{Defof|Improper Integral}} }} {{eqn | r = \int_{\frac 1 x \mathop \to 0}^{\frac 1 x \mathop \to +\infty} \map f {\frac 1 x} \map \rd {\frac 1 x} | c = Integration by Sub...
:$\ds \int_0^{+\infty} \map f x \rd x = \int_0^{+\infty} \dfrac {\map f {\frac 1 x} } {x^2} \rd x$
{{begin-eqn}} {{eqn | l = \int_0^{+\infty} \map f x \rd x | r = \int_{x \mathop \to 0}^{x \mathop \to +\infty} \map f x \rd x | c = {{Defof|Improper Integral}} }} {{eqn | r = \int_{\frac 1 x \mathop \to 0}^{\frac 1 x \mathop \to +\infty} \map f {\frac 1 x} \map \rd {\frac 1 x} | c = [[Integration by S...
Integration by Inversion
https://proofwiki.org/wiki/Integration_by_Inversion
https://proofwiki.org/wiki/Integration_by_Inversion
[ "Definite Integrals" ]
[]
[ "Integration by Substitution", "Power Rule for Derivatives", "Reversal of Limits of Definite Integral", "Category:Definite Integrals" ]
proofwiki-16385
Left Module Does Not Necessarily Induce Right Module over Ring
Let $\struct {R, +_R, \times_R}$ be a ring. Let $\struct{G, +_G, \circ}$ be a left module over $\struct {R, +_R, \times_R}$. Let $\circ' : G \times R \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: x \circ' \lambda = \lambda \circ x$ Then $\struct{G, +_G, \circ'}$ is not necessarily...
Proof by Counterexample: Let $\struct {S, +, \times}$ be a ring with unity Let $\struct {\map {\MM_S} 2, +, \times}$ denote the ring of square matrices of order $2$ over $S$. From Ring of Square Matrices over Ring is Ring, $\struct {\map {\MM_S} 2, +, \times}$ is a ring. Let: :$G := \set {\begin {bmatrix} x & 0 \\ y & ...
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct{G, +_G, \circ}$ be a [[Definition:Left Module over Ring|left module]] over $\struct {R, +_R, \times_R}$. Let $\circ' : G \times R \to G$ be the [[Definition:Binary Operation|binary operation]] defined by: :$\forall \lambda...
[[Proof by Counterexample]]: Let $\struct {S, +, \times}$ be a [[Definition:Ring with Unity|ring with unity]] Let $\struct {\map {\MM_S} 2, +, \times}$ denote the [[Definition:Ring of Square Matrices|ring of square matrices of order $2$ over $S$]]. From [[Ring of Square Matrices over Ring is Ring]], $\struct {\map {...
Left Module Does Not Necessarily Induce Right Module over Ring
https://proofwiki.org/wiki/Left_Module_Does_Not_Necessarily_Induce_Right_Module_over_Ring
https://proofwiki.org/wiki/Left_Module_Does_Not_Necessarily_Induce_Right_Module_over_Ring
[ "Left Module Does Not Necessarily Induce Right Module over Ring", "Right Modules over Rings", "Left Modules over Rings", "Modules over Rings" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Left Module over Ring", "Definition:Operation/Binary Operation", "Definition:Right Module over Ring" ]
[ "Proof by Counterexample", "Definition:Ring with Unity", "Definition:Ring of Square Matrices", "Ring of Square Matrices over Ring is Ring", "Definition:Ring (Abstract Algebra)" ]
proofwiki-16386
Right Module Does Not Necessarily Induce Left Module over Ring
Let $\struct {R, +_R, \times_R}$ be a ring. Let $\struct{G, +_G, \circ}$ be a right module over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: \lambda \circ' x = x \circ \lambda$ Then $\struct{G, +_G, \circ'}$ is not necessaril...
Proof by Counterexample: Let $\struct {S, +, \times}$ be a ring with unity Let $\struct {\map {\MM_S} 2, +, \times}$ denote the ring of square matrices of order $2$ over $S$. From Ring of Square Matrices over Ring is Ring, $\struct {\map {\MM_S} 2, +, \times}$ is a ring. Let: :$G := \set {\begin{bmatrix} x & y \\ 0 & 0...
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $\struct{G, +_G, \circ}$ be a [[Definition:Right Module over Ring|right module]] over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the [[Definition:Binary Operation|binary operation]] defined by: :$\forall \lamb...
[[Proof by Counterexample]]: Let $\struct {S, +, \times}$ be a [[Definition:Ring with Unity|ring with unity]] Let $\struct {\map {\MM_S} 2, +, \times}$ denote the [[Definition:Ring of Square Matrices|ring of square matrices of order $2$ over $S$]]. From [[Ring of Square Matrices over Ring is Ring]], $\struct {\map {...
Right Module Does Not Necessarily Induce Left Module over Ring
https://proofwiki.org/wiki/Right_Module_Does_Not_Necessarily_Induce_Left_Module_over_Ring
https://proofwiki.org/wiki/Right_Module_Does_Not_Necessarily_Induce_Left_Module_over_Ring
[ "Right Module Does Not Necessarily Induce Left Module over Ring", "Right Modules over Rings", "Left Modules over Rings", "Modules over Rings" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Right Module over Ring", "Definition:Operation/Binary Operation", "Definition:Left Module over Ring" ]
[ "Proof by Counterexample", "Definition:Ring with Unity", "Definition:Ring of Square Matrices", "Ring of Square Matrices over Ring is Ring", "Definition:Ring (Abstract Algebra)" ]
proofwiki-16387
Left Module Does Not Necessarily Induce Right Module over Ring/Lemma
:$G$ is a left ideal of $\struct {\map {\MM_S} 2, +, \times}$.
From Test for Left Ideal, the following need to be proved: :$(1): \quad G \ne \O$ :$(2): \quad \forall \mathop {\mathbf X}, \mathop {\mathbf Y} \in G: \mathbf X + \paren {-\mathbf Y} \in G$ :$(3): \quad \forall \mathop{\mathbf J} \in G, \mathop {\mathbf R} \in \map {\MM_S} 2: \mathbf R \times \mathbf J \in G$
:$G$ is a [[Definition:Left Ideal of Ring|left ideal]] of $\struct {\map {\MM_S} 2, +, \times}$.
From [[Test for Left Ideal]], the following need to be proved: :$(1): \quad G \ne \O$ :$(2): \quad \forall \mathop {\mathbf X}, \mathop {\mathbf Y} \in G: \mathbf X + \paren {-\mathbf Y} \in G$ :$(3): \quad \forall \mathop{\mathbf J} \in G, \mathop {\mathbf R} \in \map {\MM_S} 2: \mathbf R \times \mathbf J \in G$
Left Module Does Not Necessarily Induce Right Module over Ring/Lemma
https://proofwiki.org/wiki/Left_Module_Does_Not_Necessarily_Induce_Right_Module_over_Ring/Lemma
https://proofwiki.org/wiki/Left_Module_Does_Not_Necessarily_Induce_Right_Module_over_Ring/Lemma
[ "Left Module Does Not Necessarily Induce Right Module over Ring" ]
[ "Definition:Ideal of Ring/Left Ideal" ]
[ "Test for Left Ideal" ]
proofwiki-16388
Right Module Does Not Necessarily Induce Left Module over Ring/Lemma
:$G$ is a right ideal of $\struct {\map {\MM_S} 2, +, \times}$.
From Test for Right Ideal, the following need to be proved: :$(1): \quad G \ne \O$ :$(2): \quad \forall \mathop {\mathbf X}, \mathop{\mathbf Y} \in G: \mathbf X + \paren {-\mathbf Y} \in G$ :$(3): \quad \forall \mathop{\mathbf J} \in G, \mathop{\mathbf R} \in \map {\MM_S} 2: \mathbf J \times \mathbf R \in G$
:$G$ is a [[Definition:Right Ideal of Ring|right ideal]] of $\struct {\map {\MM_S} 2, +, \times}$.
From [[Test for Right Ideal]], the following need to be proved: :$(1): \quad G \ne \O$ :$(2): \quad \forall \mathop {\mathbf X}, \mathop{\mathbf Y} \in G: \mathbf X + \paren {-\mathbf Y} \in G$ :$(3): \quad \forall \mathop{\mathbf J} \in G, \mathop{\mathbf R} \in \map {\MM_S} 2: \mathbf J \times \mathbf R \in G$
Right Module Does Not Necessarily Induce Left Module over Ring/Lemma
https://proofwiki.org/wiki/Right_Module_Does_Not_Necessarily_Induce_Left_Module_over_Ring/Lemma
https://proofwiki.org/wiki/Right_Module_Does_Not_Necessarily_Induce_Left_Module_over_Ring/Lemma
[ "Right Module Does Not Necessarily Induce Left Module over Ring" ]
[ "Definition:Ideal of Ring/Right Ideal" ]
[ "Test for Right Ideal" ]
proofwiki-16389
Ideal is Bimodule over Ring
Let $\struct {R, +, \times}$ be a ring. Let $J \subseteq R$ be an ideal of $R$. Let $\circ_l : R \times J \to J$ be the restriction of $\times$ to $R \times J$. Let $\circ_r : J \times R \to J$ be the restriction of $\times$ to $J \times R$. Then $\struct {J, +, \circ_l, \circ_r}$ is a bimodule over $\struct {R, +, \ti...
By definition of an ideal, $J$ is both a left ideal and a right ideal. From Left Ideal is Left Module over Ring then $\struct {J, +, \circ_l}$ is a left module. From Right Ideal is Right Module over Ring then $\struct {J, +, \circ_r}$ is a right module. Then: {{begin-eqn}} {{eqn | q = \forall x, y \in R: \forall j \in ...
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Let $J \subseteq R$ be an [[Definition:Ideal of Ring|ideal]] of $R$. Let $\circ_l : R \times J \to J$ be the [[Definition:Restriction of Mapping|restriction]] of $\times$ to $R \times J$. Let $\circ_r : J \times R \to J$ be the [[Definiti...
By definition of an [[Definition:Ideal of Ring|ideal]], $J$ is both a [[Definition:Left Ideal of Ring|left ideal]] and a [[Definition:Right Ideal of Ring|right ideal]]. From [[Left Ideal is Left Module over Ring]] then $\struct {J, +, \circ_l}$ is a [[Definition:Left Module over Ring|left module]]. From [[Right Ideal...
Ideal is Bimodule over Ring
https://proofwiki.org/wiki/Ideal_is_Bimodule_over_Ring
https://proofwiki.org/wiki/Ideal_is_Bimodule_over_Ring
[ "Bimodules", "Ideal Theory" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Ideal of Ring", "Definition:Restriction/Mapping", "Definition:Restriction/Mapping", "Definition:Bimodule" ]
[ "Definition:Ideal of Ring", "Definition:Ideal of Ring/Left Ideal", "Definition:Ideal of Ring/Right Ideal", "Left Ideal is Left Module over Ring", "Definition:Left Module over Ring", "Right Ideal is Right Module over Ring", "Definition:Right Module over Ring", "Definition:Bimodule" ]
proofwiki-16390
Ideal is Bimodule over Ring/Ring is Bimodule over Ring
Let $\struct {R, +, \times}$ be a ring. Then $\struct {R, +, \times, \times}$ is a bimodule over $\struct {R, +, \times}$.
From Ring is Ideal of Itself and Ideal is Bimodule over Ring, $\struct {R, +, \times, \times}$ is a bimodule over $\struct {R, +, \times}$. {{qed}}
Let $\struct {R, +, \times}$ be a [[Definition:Ring (Abstract Algebra)|ring]]. Then $\struct {R, +, \times, \times}$ is a [[Definition:Bimodule|bimodule]] over $\struct {R, +, \times}$.
From [[Ring is Ideal of Itself]] and [[Ideal is Bimodule over Ring]], $\struct {R, +, \times, \times}$ is a [[Definition:Bimodule|bimodule]] over $\struct {R, +, \times}$. {{qed}}
Ideal is Bimodule over Ring/Ring is Bimodule over Ring
https://proofwiki.org/wiki/Ideal_is_Bimodule_over_Ring/Ring_is_Bimodule_over_Ring
https://proofwiki.org/wiki/Ideal_is_Bimodule_over_Ring/Ring_is_Bimodule_over_Ring
[ "Bimodules", "Module Theory", "Ring Theory" ]
[ "Definition:Ring (Abstract Algebra)", "Definition:Bimodule" ]
[ "Ring is Ideal of Itself", "Ideal is Bimodule over Ring", "Definition:Bimodule" ]
proofwiki-16391
Left Module over Commutative Ring induces Bimodule
Let $\struct {R, +_R, \times_R}$ be a commutative ring. Let $\struct{G, +_G, \circ}$ be a left module over $\struct {R, +_R, \times_R}$. Let $\circ' : G \times R \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: x \circ' \lambda = \lambda \circ x$ Then $\struct{G, +_G, \circ, \circ'}$...
From Left Module over Commutative Ring induces Right Module, $\struct{G, +_G, \circ'}$ is a right module. Let $\lambda, \mu \in R$ and $x \in G$. Then: {{begin-eqn}} {{eqn | l = \lambda \circ \paren{x \circ' \mu} | r = \lambda \circ \paren{\mu \circ x} | c = Definition of $\circ’$ }} {{eqn | r = \paren {\la...
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Commutative Ring|commutative ring]]. Let $\struct{G, +_G, \circ}$ be a [[Definition:Left Module over Ring|left module]] over $\struct {R, +_R, \times_R}$. Let $\circ' : G \times R \to G$ be the [[Definition:Binary Operation|binary operation]] defined by: :$\forall \l...
From [[Left Module over Commutative Ring induces Right Module]], $\struct{G, +_G, \circ'}$ is a [[Definition:Right Module over Ring|right module]]. Let $\lambda, \mu \in R$ and $x \in G$. Then: {{begin-eqn}} {{eqn | l = \lambda \circ \paren{x \circ' \mu} | r = \lambda \circ \paren{\mu \circ x} | c = Defin...
Left Module over Commutative Ring induces Bimodule
https://proofwiki.org/wiki/Left_Module_over_Commutative_Ring_induces_Bimodule
https://proofwiki.org/wiki/Left_Module_over_Commutative_Ring_induces_Bimodule
[ "Module Theory", "Ring Theory" ]
[ "Definition:Commutative Ring", "Definition:Left Module over Ring", "Definition:Operation/Binary Operation", "Definition:Bimodule" ]
[ "Left Module over Commutative Ring induces Right Module", "Definition:Right Module over Ring", "Definition:Ring (Abstract Algebra)/Product", "Definition:Commutative/Operation", "Definition:Bimodule" ]
proofwiki-16392
Right Module over Commutative Ring induces Bimodule
Let $\struct {R, +_R, \times_R}$ be a commutative ring. Let $\struct {G, +_G, \circ}$ be a right module over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the binary operation defined by: :$\forall \lambda \in R: \forall x \in G: \lambda \circ' x = x \circ \lambda $ Then $\struct {G, +_G, \circ', \ci...
From Right Module over Commutative Ring induces Left Module, $\struct {G, +_G, \circ'}$ is a left module. Let $\lambda, \mu \in R$ and $x \in G$. Then: {{begin-eqn}} {{eqn | l = \lambda \circ' \paren {x \circ \mu} | r = \paren {x \circ \mu} \circ \lambda | c = Definition of $\circ’$ }} {{eqn | r = x \circ \...
Let $\struct {R, +_R, \times_R}$ be a [[Definition:Commutative Ring|commutative ring]]. Let $\struct {G, +_G, \circ}$ be a [[Definition:Right Module over Ring|right module]] over $\struct {R, +_R, \times_R}$. Let $\circ' : R \times G \to G$ be the [[Definition:Binary Operation|binary operation]] defined by: :$\forall...
From [[Right Module over Commutative Ring induces Left Module]], $\struct {G, +_G, \circ'}$ is a [[Definition:Left Module over Ring|left module]]. Let $\lambda, \mu \in R$ and $x \in G$. Then: {{begin-eqn}} {{eqn | l = \lambda \circ' \paren {x \circ \mu} | r = \paren {x \circ \mu} \circ \lambda | c = Defi...
Right Module over Commutative Ring induces Bimodule
https://proofwiki.org/wiki/Right_Module_over_Commutative_Ring_induces_Bimodule
https://proofwiki.org/wiki/Right_Module_over_Commutative_Ring_induces_Bimodule
[ "Module Theory", "Ring Theory" ]
[ "Definition:Commutative Ring", "Definition:Right Module over Ring", "Definition:Operation/Binary Operation", "Definition:Bimodule" ]
[ "Right Module over Commutative Ring induces Left Module", "Definition:Left Module over Ring", "Axiom:Right Module Axioms", "Definition:Ring (Abstract Algebra)/Product", "Definition:Commutative/Operation", "Axiom:Right Module Axioms", "Definition:Bimodule" ]
proofwiki-16393
Diagonals of Kite are Perpendicular
Let $ABCD$ be a kite such that $AC$ and $BD$ are its diagonals. Then $AC$ and $BD$ are perpendicular.
:450px Let $AC$ and $BD$ meet at $E$. Consider the triangles $\triangle ABD$ and $\triangle CBD$. We have that: :$AB = CB$ :$AD = CD$ :$BD$ is common. Hence by Triangle Side-Side-Side Congruence, $\triangle ABD$ and $\triangle CBD$ are congruent. Consider the triangles $\triangle ABE$ and $\triangle CBE$. We have from ...
Let $ABCD$ be a [[Definition:Kite|kite]] such that $AC$ and $BD$ are its [[Definition:Diagonal of Quadrilateral|diagonals]]. Then $AC$ and $BD$ are [[Definition:Perpendicular|perpendicular]].
:[[File:Diagonals-of-Kite.png|450px]] Let $AC$ and $BD$ [[Definition:Intersection (Geometry)|meet]] at $E$. Consider the [[Definition:Triangle (Geometry)|triangles]] $\triangle ABD$ and $\triangle CBD$. We have that: :$AB = CB$ :$AD = CD$ :$BD$ is common. Hence by [[Triangle Side-Side-Side Congruence]], $\triangl...
Diagonals of Kite are Perpendicular
https://proofwiki.org/wiki/Diagonals_of_Kite_are_Perpendicular
https://proofwiki.org/wiki/Diagonals_of_Kite_are_Perpendicular
[ "Kites" ]
[ "Definition:Quadrilateral/Kite", "Definition:Diameter of Quadrilateral", "Definition:Right Angle/Perpendicular" ]
[ "File:Diagonals-of-Kite.png", "Definition:Intersection (Geometry)", "Definition:Triangle (Geometry)", "Triangle Side-Side-Side Congruence", "Definition:Congruence (Geometry)", "Definition:Triangle (Geometry)", "Definition:Congruence (Geometry)", "Triangle Side-Angle-Side Congruence", "Definition:Con...
proofwiki-16394
One Diagonal of Kite Bisects the Other
Let $ABCD$ be a kite such that: :$AC$ and $BD$ are its diagonals :$AB = BC$ :$AD = DC$ Then $BD$ is the perpendicular bisector of $AC$.
:450px Let $AC$ and $BD$ meet at $E$. From Diagonals of Kite are Perpendicular, $AC$ and $BD$ are perpendicular. That is: :$\angle AEB = \angle CEB$ both being right angles. Consider the triangles $\triangle ABE$ and $\triangle CBE$. We have that: :$\angle AEB = \angle CEB$ are both right angles. :$AB = BC$ :$BE$ is co...
Let $ABCD$ be a [[Definition:Kite|kite]] such that: :$AC$ and $BD$ are its [[Definition:Diagonal of Quadrilateral|diagonals]] :$AB = BC$ :$AD = DC$ Then $BD$ is the [[Definition:Perpendicular Bisector|perpendicular bisector]] of $AC$.
:[[File:Diagonals-of-Kite.png|450px]] Let $AC$ and $BD$ [[Definition:Intersection (Geometry)|meet]] at $E$. From [[Diagonals of Kite are Perpendicular]], $AC$ and $BD$ are [[Definition:Perpendicular|perpendicular]]. That is: :$\angle AEB = \angle CEB$ both being [[Definition:Right Angle|right angles]]. Consider t...
One Diagonal of Kite Bisects the Other
https://proofwiki.org/wiki/One_Diagonal_of_Kite_Bisects_the_Other
https://proofwiki.org/wiki/One_Diagonal_of_Kite_Bisects_the_Other
[ "Kites" ]
[ "Definition:Quadrilateral/Kite", "Definition:Diameter of Quadrilateral", "Definition:Perpendicular Bisector" ]
[ "File:Diagonals-of-Kite.png", "Definition:Intersection (Geometry)", "Diagonals of Kite are Perpendicular", "Definition:Right Angle/Perpendicular", "Definition:Right Angle", "Definition:Triangle (Geometry)", "Definition:Right Angle", "Triangle Right-Angle-Hypotenuse-Side Congruence", "Definition:Cong...
proofwiki-16395
Combination Theorem for Continuous Mappings/Topological Group/Product Rule
:$f * g : \struct {S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a continuous mapping.
By definition, a topological group is a topological semigroup. Hence $\struct {G, *, \tau_{_G} }$ is a topological semigroup. From Product Rule for Continuous Mappings to Topological Semigroup: :$f * g: \struct {S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a continuous mapping. {{qed}}
:$f * g : \struct {S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a [[Definition:Continuous Mapping on Set|continuous mapping]].
By definition, a [[Definition:Topological Group|topological group]] is a [[Definition:Topological Semigroup|topological semigroup]]. Hence $\struct {G, *, \tau_{_G} }$ is a [[Definition:Topological Semigroup|topological semigroup]]. From [[Product Rule for Continuous Mappings to Topological Semigroup]]: :$f * g: \str...
Combination Theorem for Continuous Mappings/Topological Group/Product Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Group/Product_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Group/Product_Rule
[ "Combination Theorem for Continuous Mappings to Topological Group" ]
[ "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Topological Group", "Definition:Topological Semigroup", "Definition:Topological Semigroup", "Combination Theorem for Continuous Mappings/Topological Semigroup/Product Rule", "Definition:Continuous Mapping (Topology)/Set" ]
proofwiki-16396
Combination Theorem for Continuous Mappings/Topological Group/Multiple Rule
:$\lambda * f: \struct {S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a continuous mapping :$f * \lambda: \struct {S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a continuous mapping.
By definition, a topological group is a topological semigroup. Hence $\struct {G, *, \tau_{_G}}$ is a topological semigroup. From Multiple Rule for Continuous Mappings to Topological Semigroup: :$\lambda * f, f * \lambda: \struct {S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ are continuous mappings. {{qed}}
:$\lambda * f: \struct {S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a [[Definition:Continuous Mapping on Set|continuous mapping]] :$f * \lambda: \struct {S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a [[Definition:Continuous Mapping on Set|continuous mapping]].
By definition, a [[Definition:Topological Group|topological group]] is a [[Definition:Topological Semigroup|topological semigroup]]. Hence $\struct {G, *, \tau_{_G}}$ is a [[Definition:Topological Semigroup|topological semigroup]]. From [[Multiple Rule for Continuous Mappings to Topological Semigroup]]: :$\lambda * f...
Combination Theorem for Continuous Mappings/Topological Group/Multiple Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Group/Multiple_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Group/Multiple_Rule
[ "Combination Theorem for Continuous Mappings to Topological Group" ]
[ "Definition:Continuous Mapping (Topology)/Set", "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Topological Group", "Definition:Topological Semigroup", "Definition:Topological Semigroup", "Combination Theorem for Continuous Mappings/Topological Semigroup/Multiple Rule", "Definition:Continuous Mapping (Topology)/Set" ]
proofwiki-16397
Combination Theorem for Continuous Mappings/Topological Group/Inverse Rule
:$g^{-1}: \struct {S, \tau_S} \to \struct {G, \tau_G}$ is a continuous mapping.
By definition of a topological group: :$\phi: \struct {G, \tau_G} \to \struct {G, \tau_G}$ such that $\forall x \in G: \map \phi x = x^{-1}$ is a continuous mapping From Composite of Continuous Mappings is Continuous: :the composition $\phi \circ g: \struct {S, \tau_S} \to \struct {G, \tau_G}$ is continuous. Now: {{beg...
:$g^{-1}: \struct {S, \tau_S} \to \struct {G, \tau_G}$ is a [[Definition:Continuous Mapping on Set|continuous mapping]].
By definition of a [[Definition:Topological Group|topological group]]: :$\phi: \struct {G, \tau_G} \to \struct {G, \tau_G}$ such that $\forall x \in G: \map \phi x = x^{-1}$ is a [[Definition:Everywhere Continuous Mapping (Topology)|continuous mapping]] From [[Composite of Continuous Mappings is Continuous]]: :the [[D...
Combination Theorem for Continuous Mappings/Topological Group/Inverse Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Group/Inverse_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Group/Inverse_Rule
[ "Combination Theorem for Continuous Mappings to Topological Group" ]
[ "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Topological Group", "Definition:Continuous Mapping (Topology)/Everywhere", "Composite of Continuous Mappings is Continuous", "Definition:Composition of Mappings", "Definition:Continuous Mapping (Topology)/Everywhere", "Equality of Mappings", "Category:Combination Theorem for Continuous Mappi...
proofwiki-16398
Combination Theorem for Continuous Mappings/Topological Semigroup/Product Rule
:$f * g: \struct{S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a continuous mapping.
Let $f \times g: S \to G \times G$ be the mapping defined by: :$\forall x \in S : \map {\paren {f \times g} } x = \tuple {\map f x, \map g x}$ From Pointwise Operation is Composite of Operation with Mapping to Cartesian Product: :$f * g = * \circ \paren {f \times g}$ Let $\tau$ be the product topology on $G \times G$. ...
:$f * g: \struct{S, \tau_{_S} } \to \struct {G, \tau_{_G} }$ is a [[Definition:Continuous Mapping on Set|continuous mapping]].
Let $f \times g: S \to G \times G$ be the [[Definition:Mapping|mapping]] defined by: :$\forall x \in S : \map {\paren {f \times g} } x = \tuple {\map f x, \map g x}$ From [[Pointwise Operation is Composite of Operation with Mapping to Cartesian Product]]: :$f * g = * \circ \paren {f \times g}$ Let $\tau$ be the [[De...
Combination Theorem for Continuous Mappings/Topological Semigroup/Product Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Semigroup/Product_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Semigroup/Product_Rule
[ "Combination Theorem for Continuous Mappings to Topological Semigroup" ]
[ "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Mapping", "Pointwise Operation is Composite of Operation with Mapping to Cartesian Product", "Definition:Product Topology", "Definition:Continuous Mapping (Topology)/Set", "Definition:Continuous Mapping (Topology)/Set", "Definition:Topological Semigroup", "Composite of Continuous Mappings is...
proofwiki-16399
Combination Theorem for Continuous Mappings/Topological Semigroup/Multiple Rule
:$\lambda * f: \struct {S, \tau_S} \to \struct {G, \tau_G}$ is a continuous mapping :$f * \lambda: \struct {S, \tau_S} \to \struct {G, \tau_G}$ is a continuous mapping.
Let $c_\lambda : S \to G$ be the constant mapping defined by: :$\forall x \in S: \map {c_\lambda} x = \lambda$ From Constant Mapping is Continuous, $c_\lambda$ is continuous. From Product Rule for Continuous Mappings to Topological Semigroup: :$c_\lambda * f$ and $f * c_\lambda$ are continuous. Now: {{begin-eqn}} {{eqn...
:$\lambda * f: \struct {S, \tau_S} \to \struct {G, \tau_G}$ is a [[Definition:Continuous Mapping on Set|continuous mapping]] :$f * \lambda: \struct {S, \tau_S} \to \struct {G, \tau_G}$ is a [[Definition:Continuous Mapping on Set|continuous mapping]].
Let $c_\lambda : S \to G$ be the [[Definition:Constant Mapping|constant mapping]] defined by: :$\forall x \in S: \map {c_\lambda} x = \lambda$ From [[Constant Mapping is Continuous]], $c_\lambda$ is [[Definition:Continuous Mapping on Set|continuous]]. From [[Product Rule for Continuous Mappings to Topological Semigro...
Combination Theorem for Continuous Mappings/Topological Semigroup/Multiple Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Semigroup/Multiple_Rule
https://proofwiki.org/wiki/Combination_Theorem_for_Continuous_Mappings/Topological_Semigroup/Multiple_Rule
[ "Combination Theorem for Continuous Mappings to Topological Semigroup" ]
[ "Definition:Continuous Mapping (Topology)/Set", "Definition:Continuous Mapping (Topology)/Set" ]
[ "Definition:Constant Mapping", "Constant Mapping is Continuous", "Definition:Continuous Mapping (Topology)/Set", "Combination Theorem for Continuous Mappings/Topological Semigroup/Product Rule", "Definition:Continuous Mapping (Topology)/Set", "Equality of Mappings", "Category:Combination Theorem for Con...