contestId int64 0 1.01k | index stringclasses 40
values | name stringlengths 2 54 | type stringclasses 2
values | rating int64 0 3.4k | tags listlengths 0 7 | title stringclasses 393
values | time-limit stringclasses 7
values | memory-limit stringclasses 6
values | problem-description stringlengths 0 2.97k | input-specification stringlengths 4 1.87k | output-specification stringlengths 4 1.12k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 3.5k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 1
value | testset stringclasses 9
values | passedTestCount int64 1 402 | timeConsumedMillis int64 15 8.06k | memoryConsumedBytes int64 0 514M | code stringlengths 11 61.4k | prompt stringlengths 297 7.35k | response stringlengths 25 61.4k | score float64 2.82 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,673,721,814 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | x,y = map(int,input().split())
z = list(map(int,input().split()))
n = 5-y
c = 0
for i in z:
if i <= n:
c+=1
print(c//3) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
x,y = map(int,input().split())
z = list(map(int,input().split()))
n = 5-y
c = 0
for i in z:
if i <= n:
c+=1
print(c//3)
``` | 3 | |
237 | A | Free Cash | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is... | Print a single integer — the minimum number of cashes, needed to serve all clients next day. | [
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] | [
"2\n",
"1\n"
] | In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so ... | 500 | [
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "... | 1,697,522,828 | 2,147,483,647 | Python 3 | OK | TESTS | 67 | 404 | 8,601,600 | l = []
T = int(input())
for i in range(0, T):
a, b = map(int, input().split())
l.append((a, b))
d = {}
for item in l:
if item not in d:
d[item] = 1
else:
d[item] += 1
# print(d)
mx = 1
for key, value in d.items():
# print(key, value)
mx =... | Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends l... | ```python
l = []
T = int(input())
for i in range(0, T):
a, b = map(int, input().split())
l.append((a, b))
d = {}
for item in l:
if item not in d:
d[item] = 1
else:
d[item] += 1
# print(d)
mx = 1
for key, value in d.items():
# print(key, value)... | 3 | |
200 | B | Drinks | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent.
One day Vasya decided to make himself an orange cocktail. He took equal proportio... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space. | Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4. | [
"3\n50 50 100\n",
"4\n0 25 50 75\n"
] | [
"66.666666666667\n",
"37.500000000000\n"
] | Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: ... | 500 | [
{
"input": "3\n50 50 100",
"output": "66.666666666667"
},
{
"input": "4\n0 25 50 75",
"output": "37.500000000000"
},
{
"input": "3\n0 1 8",
"output": "3.000000000000"
},
{
"input": "5\n96 89 93 95 70",
"output": "88.600000000000"
},
{
"input": "7\n62 41 78 4 38 39... | 1,686,982,773 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n = int(input())
s = input().split()
c = 0
for j in range(n):
c+=(int(s[j])/100)
print ((c/n)*100) | Title: Drinks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i*... | ```python
n = int(input())
s = input().split()
c = 0
for j in range(n):
c+=(int(s[j])/100)
print ((c/n)*100)
``` | 3 | |
959 | A | Mahmoud and Ehab and the even-odd game | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab'... | The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game. | Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise. | [
"1\n",
"2\n"
] | [
"Ehab",
"Mahmoud"
] | In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mah... | 500 | [
{
"input": "1",
"output": "Ehab"
},
{
"input": "2",
"output": "Mahmoud"
},
{
"input": "10000",
"output": "Mahmoud"
},
{
"input": "33333",
"output": "Ehab"
},
{
"input": "5",
"output": "Ehab"
},
{
"input": "1000000000",
"output": "Mahmoud"
},
{
... | 1,677,521,382 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 20 | 46 | 0 |
# k=int(input())
# for i in range(k):
e=int(input())
if e%2!=0 or e==0 :
print ("Ehab")
else:
print("Mahmoud")
| Title: Mahmoud and Ehab and the even-odd game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a*... | ```python
# k=int(input())
# for i in range(k):
e=int(input())
if e%2!=0 or e==0 :
print ("Ehab")
else:
print("Mahmoud")
``` | 3 | |
990 | B | Micro-World | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | You have a Petri dish with bacteria and you are preparing to dive into the harsh micro-world. But, unfortunately, you don't have any microscope nearby, so you can't watch them.
You know that you have $n$ bacteria in the Petri dish and size of the $i$-th bacteria is $a_i$. Also you know intergalactic positive integer c... | The first line contains two space separated positive integers $n$ and $K$ ($1 \le n \le 2 \cdot 10^5$, $1 \le K \le 10^6$) — number of bacteria and intergalactic constant $K$.
The second line contains $n$ space separated integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 10^6$) — sizes of bacteria you have. | Print the only integer — minimal possible number of bacteria can remain. | [
"7 1\n101 53 42 102 101 55 54\n",
"6 5\n20 15 10 15 20 25\n",
"7 1000000\n1 1 1 1 1 1 1\n"
] | [
"3\n",
"1\n",
"7\n"
] | The first example is clarified in the problem statement.
In the second example an optimal possible sequence of swallows is: $[20, 15, 10, 15, \underline{20}, 25]$ $\to$ $[20, 15, 10, \underline{15}, 25]$ $\to$ $[20, 15, \underline{10}, 25]$ $\to$ $[20, \underline{15}, 25]$ $\to$ $[\underline{20}, 25]$ $\to$ $[25]$.
I... | 0 | [
{
"input": "7 1\n101 53 42 102 101 55 54",
"output": "3"
},
{
"input": "6 5\n20 15 10 15 20 25",
"output": "1"
},
{
"input": "7 1000000\n1 1 1 1 1 1 1",
"output": "7"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 4\n8",
"output": "1"
},
{
"inp... | 1,528,818,226 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 373 | 14,233,600 | n, k = [int(a) for a in input().split()]
s = sorted([int(a) for a in input().split()], reverse=1)
ans = 1
q = s[0]
for i in range(1, n):
if not(abs(s[i] - s[i - 1]) <= k and s[i] < q):
ans += 1
q = s[i]
print(ans) | Title: Micro-World
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a Petri dish with bacteria and you are preparing to dive into the harsh micro-world. But, unfortunately, you don't have any microscope nearby, so you can't watch them.
You know that you have $n$ bacteria in the Pe... | ```python
n, k = [int(a) for a in input().split()]
s = sorted([int(a) for a in input().split()], reverse=1)
ans = 1
q = s[0]
for i in range(1, n):
if not(abs(s[i] - s[i - 1]) <= k and s[i] < q):
ans += 1
q = s[i]
print(ans)
``` | 3 | |
18 | C | Stripe | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | C. Stripe | 2 | 64 | Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=105) — amount of squares in the stripe. The second line contains *n* space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. | Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. | [
"9\n1 5 -6 7 9 -16 0 -2 2\n",
"3\n1 1 1\n",
"2\n0 0\n"
] | [
"3\n",
"0\n",
"1\n"
] | none | 0 | [
{
"input": "9\n1 5 -6 7 9 -16 0 -2 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "0"
},
{
"input": "2\n0 0",
"output": "1"
},
{
"input": "4\n100 1 10 111",
"output": "1"
},
{
"input": "10\n0 4 -3 0 -2 2 -3 -3 2 5",
"output": "3"
},
{
"input": "... | 1,528,064,580 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 310 | 14,438,400 | def main():
n = int(input())
arr = list(map(int, input().split()))
right = sum(arr)
left = 0
result = 0
for i in range(0, n - 1):
left += arr[i]
right -= arr[i]
if left == right:
result += 1
print(result)
if __name__ == "__main__":
... | Title: Stripe
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that ... | ```python
def main():
n = int(input())
arr = list(map(int, input().split()))
right = sum(arr)
left = 0
result = 0
for i in range(0, n - 1):
left += arr[i]
right -= arr[i]
if left == right:
result += 1
print(result)
if __name__ == "__m... | 3.814926 |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,677,529,194 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | for i in range(0, int(input())):
string = input()
if len(string) > 10:
answer = string[0] + str(len(string) - 2) + string[-1]
print(answer)
else: print(string) | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
for i in range(0, int(input())):
string = input()
if len(string) > 10:
answer = string[0] + str(len(string) - 2) + string[-1]
print(answer)
else: print(string)
``` | 3.977 |
248 | B | Chilly Willy | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | Chilly Willy loves playing with numbers. He only knows prime numbers that are digits yet. These numbers are 2, 3, 5 and 7. But Willy grew rather bored of such numbers, so he came up with a few games that were connected with them.
Chilly Willy wants to find the minimum number of length *n*, such that it is simultaneous... | A single input line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | Print a single integer — the answer to the problem without leading zeroes, or "-1" (without the quotes), if the number that meet the problem condition does not exist. | [
"1\n",
"5\n"
] | [
"-1\n",
"10080"
] | none | 1,000 | [
{
"input": "1",
"output": "-1"
},
{
"input": "5",
"output": "10080"
},
{
"input": "6",
"output": "100170"
},
{
"input": "4",
"output": "1050"
},
{
"input": "15",
"output": "100000000000110"
},
{
"input": "16",
"output": "1000000000000050"
},
{
... | 1,578,129,578 | 2,147,483,647 | PyPy 3 | OK | TESTS | 66 | 280 | 512,000 | n = int(input())
if n < 3:
print(-1)
elif n == 3:
print(210)
else:
suff = ""
if n % 6 == 4:
suff = "50"
elif n % 6 == 5:
suff = "80"
elif n % 6 == 0:
suff = "170"
elif n % 6 == 1:
suff = "20"
elif n % 6 == 2:
suff = "200"
elif ... | Title: Chilly Willy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chilly Willy loves playing with numbers. He only knows prime numbers that are digits yet. These numbers are 2, 3, 5 and 7. But Willy grew rather bored of such numbers, so he came up with a few games that were connected wit... | ```python
n = int(input())
if n < 3:
print(-1)
elif n == 3:
print(210)
else:
suff = ""
if n % 6 == 4:
suff = "50"
elif n % 6 == 5:
suff = "80"
elif n % 6 == 0:
suff = "170"
elif n % 6 == 1:
suff = "20"
elif n % 6 == 2:
suff = "200"
... | 3 | |
55 | B | Smallest number | PROGRAMMING | 1,600 | [
"brute force"
] | B. Smallest number | 2 | 256 | Recently, Vladimir got bad mark in algebra again. To avoid such unpleasant events in future he decided to train his arithmetic skills. He wrote four integer numbers *a*, *b*, *c*, *d* on the blackboard. During each of the next three minutes he took two numbers from the blackboard (not necessarily adjacent) and replaced... | First line contains four integers separated by space: 0<=≤<=*a*,<=*b*,<=*c*,<=*d*<=≤<=1000 — the original numbers. Second line contains three signs ('+' or '*' each) separated by space — the sequence of the operations in the order of performing. ('+' stands for addition, '*' — multiplication) | Output one integer number — the minimal result which can be obtained.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cin (also you may use %I64d). | [
"1 1 1 1\n+ + *\n",
"2 2 2 2\n* * +\n",
"1 2 3 4\n* + +\n"
] | [
"3\n",
"8\n",
"9\n"
] | none | 1,000 | [
{
"input": "1 1 1 1\n+ + *",
"output": "3"
},
{
"input": "2 2 2 2\n* * +",
"output": "8"
},
{
"input": "1 2 3 4\n* + +",
"output": "9"
},
{
"input": "15 1 3 1\n* * +",
"output": "18"
},
{
"input": "8 1 7 14\n+ + +",
"output": "30"
},
{
"input": "7 17 3... | 1,638,214,266 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 124 | 0 | class Solution:
def find_Smallest(self,a,s):
global smallest
if len(a)==1:
if smallest > a[0]: smallest = a[0]
return
for i in range(len(a)):
for j in range(i+1,len(a)):
tmp = [0]
for k in range(len(a)):
... | Title: Smallest number
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Recently, Vladimir got bad mark in algebra again. To avoid such unpleasant events in future he decided to train his arithmetic skills. He wrote four integer numbers *a*, *b*, *c*, *d* on the blackboard. During each of the n... | ```python
class Solution:
def find_Smallest(self,a,s):
global smallest
if len(a)==1:
if smallest > a[0]: smallest = a[0]
return
for i in range(len(a)):
for j in range(i+1,len(a)):
tmp = [0]
for k in range(len(a)):
... | 3.969 |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,513,659,505 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 5,734,400 | n=int(input())
line=[int(i) for i in input().split()]
d=0
s=0
for i in range(n):
if line[i]%2==0:
s+=1
else:
d+=1
if s>d:
a=1
if d>s:
a=0
for i in range(n):
if line[i]%2==a:
x=i
print(x+1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
line=[int(i) for i in input().split()]
d=0
s=0
for i in range(n):
if line[i]%2==0:
s+=1
else:
d+=1
if s>d:
a=1
if d>s:
a=0
for i in range(n):
if line[i]%2==a:
x=i
print(x+1)
``` | 3.958319 |
697 | A | Pineapple Incident | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morn... | The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively. | Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output. | [
"3 10 4\n",
"3 10 3\n",
"3 8 51\n",
"3 8 52\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and ... | 500 | [
{
"input": "3 10 4",
"output": "NO"
},
{
"input": "3 10 3",
"output": "YES"
},
{
"input": "3 8 51",
"output": "YES"
},
{
"input": "3 8 52",
"output": "YES"
},
{
"input": "456947336 740144 45",
"output": "NO"
},
{
"input": "33 232603 599417964",
"ou... | 1,581,848,955 | 2,147,483,647 | PyPy 3 | OK | TESTS | 95 | 156 | 0 | t, s, x = map(int, input().split())
c1 = x - t - 1 - s
c2 = x - t
if (c1%s==0 and c1 >= 0) or (c2%s==0 and c2 >= 0):
print('YES')
else:
print('NO')
| Title: Pineapple Incident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times... | ```python
t, s, x = map(int, input().split())
c1 = x - t - 1 - s
c2 = x - t
if (c1%s==0 and c1 >= 0) or (c2%s==0 and c2 >= 0):
print('YES')
else:
print('NO')
``` | 3 | |
743 | B | Chloe and the sequence | PROGRAMMING | 1,200 | [
"binary search",
"bitmasks",
"constructive algorithms",
"implementation"
] | null | null | Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following algorithm of generating a sequence of integers. Initially we have a sequence consisting of a single element eq... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=2*n*<=-<=1). | Print single integer — the integer at the *k*-th position in the obtained sequence. | [
"3 2\n",
"4 8\n"
] | [
"2",
"4"
] | In the first sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1]. The number on the second position is 2.
In the second sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1]. The number on the eighth position is 4. | 1,000 | [
{
"input": "3 2",
"output": "2"
},
{
"input": "4 8",
"output": "4"
},
{
"input": "5 27",
"output": "1"
},
{
"input": "7 44",
"output": "3"
},
{
"input": "15 18432",
"output": "12"
},
{
"input": "20 259676",
"output": "3"
},
{
"input": "30 6... | 1,670,259,542 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 39 | 62 | 0 | def main():
n, k = get_list_int()
if k % 2 == 1:
print(1)
return
first_occurance_idx = [0]
for i in range(n):
step_size = 2**i
prev = first_occurance_idx[-1]
first_occurance_idx.append(prev + step_size)
for i in range(len(first_occurance_idx)):... | Title: Chloe and the sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following a... | ```python
def main():
n, k = get_list_int()
if k % 2 == 1:
print(1)
return
first_occurance_idx = [0]
for i in range(n):
step_size = 2**i
prev = first_occurance_idx[-1]
first_occurance_idx.append(prev + step_size)
for i in range(len(first_occura... | 3 | |
501 | B | Misha and Changing Handles | PROGRAMMING | 1,100 | [
"data structures",
"dsu",
"strings"
] | null | null | Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is already used or that was used at some point.
Misha has a list of handle change requests. After completing the re... | The first line contains integer *q* (1<=≤<=*q*<=≤<=1000), the number of handle change requests.
Next *q* lines contain the descriptions of the requests, one per line.
Each query consists of two non-empty strings *old* and *new*, separated by a space. The strings consist of lowercase and uppercase Latin letters and di... | In the first line output the integer *n* — the number of users that changed their handles at least once.
In the next *n* lines print the mapping between the old and the new handles of the users. Each of them must contain two strings, *old* and *new*, separated by a space, meaning that before the user had handle *old*,... | [
"5\nMisha ILoveCodeforces\nVasya Petrov\nPetrov VasyaPetrov123\nILoveCodeforces MikeMirzayanov\nPetya Ivanov\n"
] | [
"3\nPetya Ivanov\nMisha MikeMirzayanov\nVasya VasyaPetrov123\n"
] | none | 500 | [
{
"input": "5\nMisha ILoveCodeforces\nVasya Petrov\nPetrov VasyaPetrov123\nILoveCodeforces MikeMirzayanov\nPetya Ivanov",
"output": "3\nPetya Ivanov\nMisha MikeMirzayanov\nVasya VasyaPetrov123"
},
{
"input": "1\nMisha Vasya",
"output": "1\nMisha Vasya"
},
{
"input": "10\na b\nb c\nc d\nd... | 1,658,992,524 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 140 | 3,686,400 | import sys
import math
n = int(input())
lst = dict()
for _ in range(n):
s = input().split(' ')
if s[0] in lst.values():
k = list(lst.keys())[list(lst.values()).index(s[0])]
lst[k] = s[1]
else:
lst.update({s[0]: s[1]})
print(len(lst))
for x, y in lst.items():
... | Title: Misha and Changing Handles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is a... | ```python
import sys
import math
n = int(input())
lst = dict()
for _ in range(n):
s = input().split(' ')
if s[0] in lst.values():
k = list(lst.keys())[list(lst.values()).index(s[0])]
lst[k] = s[1]
else:
lst.update({s[0]: s[1]})
print(len(lst))
for x, y in lst.item... | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,593,851,715 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 218 | 0 | from sys import stdin
input = stdin.readline
n = int(input())
force = [list(map(int,input().split())) for _ in range(n)]
nx, ny, nz = 0, 0, 0
for f in force:
x, y, z = f
nx += x
ny += y
nz += z
if not nx and not ny and not nz: print("YES")
else: print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
from sys import stdin
input = stdin.readline
n = int(input())
force = [list(map(int,input().split())) for _ in range(n)]
nx, ny, nz = 0, 0, 0
for f in force:
x, y, z = f
nx += x
ny += y
nz += z
if not nx and not ny and not nz: print("YES")
else: print("NO")
``` | 3.9455 |
793 | A | Oleg and shares | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Oleg the bank client checks share prices every day. There are *n* share prices he is interested in. Today he observed that each second exactly one of these prices decreases by *k* rubles (note that each second exactly one price changes, but at different seconds different prices can change). Prices can become negative. ... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=109) — the number of share prices, and the amount of rubles some price decreases each second.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the initial prices. | Print the only line containing the minimum number of seconds needed for prices to become equal, of «-1» if it is impossible. | [
"3 3\n12 9 15\n",
"2 2\n10 9\n",
"4 1\n1 1000000000 1000000000 1000000000\n"
] | [
"3",
"-1",
"2999999997"
] | Consider the first example.
Suppose the third price decreases in the first second and become equal 12 rubles, then the first price decreases and becomes equal 9 rubles, and in the third second the third price decreases again and becomes equal 9 rubles. In this case all prices become equal 9 rubles in 3 seconds.
Ther... | 500 | [
{
"input": "3 3\n12 9 15",
"output": "3"
},
{
"input": "2 2\n10 9",
"output": "-1"
},
{
"input": "4 1\n1 1000000000 1000000000 1000000000",
"output": "2999999997"
},
{
"input": "1 11\n123",
"output": "0"
},
{
"input": "20 6\n38 86 86 50 98 62 32 2 14 62 98 50 2 50... | 1,607,511,184 | 2,147,483,647 | Python 3 | OK | TESTS | 88 | 218 | 9,216,000 | n, k = map(int, input().split())
a = sorted(list(map(int, input().split())))
result = 0
for i in a:
if (i-a[0])%k!=0:
print(-1)
exit()
else:
result+=(i-a[0])//k
print(result) | Title: Oleg and shares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Oleg the bank client checks share prices every day. There are *n* share prices he is interested in. Today he observed that each second exactly one of these prices decreases by *k* rubles (note that each second exactly o... | ```python
n, k = map(int, input().split())
a = sorted(list(map(int, input().split())))
result = 0
for i in a:
if (i-a[0])%k!=0:
print(-1)
exit()
else:
result+=(i-a[0])//k
print(result)
``` | 3 | |
513 | B1 | Permutations | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | You are given a permutation *p* of numbers 1,<=2,<=...,<=*n*. Let's define *f*(*p*) as the following sum:
Find the lexicographically *m*-th permutation of length *n* in the set of permutations having the maximum possible value of *f*(*p*). | The single line of input contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*cnt**n*), where *cnt**n* is the number of permutations of length *n* with maximum possible value of *f*(*p*).
The problem consists of two subproblems. The subproblems have different constraints on the input. You will get some score for the corr... | Output *n* number forming the required permutation. | [
"2 2\n",
"3 2\n"
] | [
"2 1 \n",
"1 3 2 \n"
] | In the first example, both permutations of numbers {1, 2} yield maximum possible *f*(*p*) which is equal to 4. Among them, (2, 1) comes second in lexicographical order. | 3 | [
{
"input": "2 2",
"output": "2 1 "
},
{
"input": "3 2",
"output": "1 3 2 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "3 1",
"output": "1 2 3 "
},
{
"input": "3 3",
"output": "2 3 1 "
},
{
"input": "3 4",
"output": "3 2 1 "
},
{
"inp... | 1,423,331,254 | 2,854 | Python 3 | OK | TESTS1 | 19 | 1,045 | 0 | __author__ = 'yushchenko'
def countf(f):
sum = 0
for i in range(len(f)):
for j in range(len(f))[i:]:
# print(i, j)
# print(f[i:j + 1])
sum += min(f[i:j + 1])
return sum
import itertools
n,m = input().split()
n = int(n)
m = int(m)
maxf = 0;
count ... | Title: Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a permutation *p* of numbers 1,<=2,<=...,<=*n*. Let's define *f*(*p*) as the following sum:
Find the lexicographically *m*-th permutation of length *n* in the set of permutations having the maximum possible ... | ```python
__author__ = 'yushchenko'
def countf(f):
sum = 0
for i in range(len(f)):
for j in range(len(f))[i:]:
# print(i, j)
# print(f[i:j + 1])
sum += min(f[i:j + 1])
return sum
import itertools
n,m = input().split()
n = int(n)
m = int(m)
maxf = ... | 3 | |
18 | C | Stripe | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | C. Stripe | 2 | 64 | Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=105) — amount of squares in the stripe. The second line contains *n* space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. | Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. | [
"9\n1 5 -6 7 9 -16 0 -2 2\n",
"3\n1 1 1\n",
"2\n0 0\n"
] | [
"3\n",
"0\n",
"1\n"
] | none | 0 | [
{
"input": "9\n1 5 -6 7 9 -16 0 -2 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "0"
},
{
"input": "2\n0 0",
"output": "1"
},
{
"input": "4\n100 1 10 111",
"output": "1"
},
{
"input": "10\n0 4 -3 0 -2 2 -3 -3 2 5",
"output": "3"
},
{
"input": "... | 1,608,399,223 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 436 | 7,782,400 | if __name__ == "__main__":
stripe_length = int(input())
square_Values = list(map(int, input().split()))
# create a prefix sum array
for i in range(1, stripe_length):
square_Values[i] += square_Values[i-1]
flag = 0
for i in range(stripe_length):
if i != stripe_le... | Title: Stripe
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that ... | ```python
if __name__ == "__main__":
stripe_length = int(input())
square_Values = list(map(int, input().split()))
# create a prefix sum array
for i in range(1, stripe_length):
square_Values[i] += square_Values[i-1]
flag = 0
for i in range(stripe_length):
if i !=... | 3.833017 |
576 | A | Vasya and Petya's Game | PROGRAMMING | 1,500 | [
"math",
"number theory"
] | null | null | Vasya and Petya are playing a simple game. Vasya thought of number *x* between 1 and *n*, and Petya tries to guess the number.
Petya can ask questions like: "Is the unknown number divisible by number *y*?".
The game is played by the following rules: first Petya asks all the questions that interest him (also, he can a... | A single line contains number *n* (1<=≤<=*n*<=≤<=103). | Print the length of the sequence of questions *k* (0<=≤<=*k*<=≤<=*n*), followed by *k* numbers — the questions *y**i* (1<=≤<=*y**i*<=≤<=*n*).
If there are several correct sequences of questions of the minimum length, you are allowed to print any of them. | [
"4\n",
"6\n"
] | [
"3\n2 4 3 \n",
"4\n2 4 3 5 \n"
] | The sequence from the answer to the first sample test is actually correct.
If the unknown number is not divisible by one of the sequence numbers, it is equal to 1.
If the unknown number is divisible by 4, it is 4.
If the unknown number is divisible by 3, then the unknown number is 3.
Otherwise, it is equal to 2. Th... | 500 | [
{
"input": "4",
"output": "3\n2 4 3 "
},
{
"input": "6",
"output": "4\n2 4 3 5 "
},
{
"input": "1",
"output": "0"
},
{
"input": "15",
"output": "9\n2 4 8 3 9 5 7 11 13 "
},
{
"input": "19",
"output": "12\n2 4 8 16 3 9 5 7 11 13 17 19 "
},
{
"input": "2... | 1,662,257,529 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 93 | 0 | n = int(input())
a = " ".join([" ".join([str(i ** k) for k in range(1, 30) if i ** k <= n]) for i in range(2, n + 1) if all([i % j != 0 for j in range(2, i)])])
print((len(a.split())), "\n" + a)
num_inp=lambda: int(input())
arr_inp=lambda: list(map(int,input().split()))
sp_inp=lambda: map(int,input().split())
s... | Title: Vasya and Petya's Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya and Petya are playing a simple game. Vasya thought of number *x* between 1 and *n*, and Petya tries to guess the number.
Petya can ask questions like: "Is the unknown number divisible by number *y*?".
The... | ```python
n = int(input())
a = " ".join([" ".join([str(i ** k) for k in range(1, 30) if i ** k <= n]) for i in range(2, n + 1) if all([i % j != 0 for j in range(2, i)])])
print((len(a.split())), "\n" + a)
num_inp=lambda: int(input())
arr_inp=lambda: list(map(int,input().split()))
sp_inp=lambda: map(int,input().s... | 3 | |
165 | B | Burning Midnight Oil | PROGRAMMING | 1,500 | [
"binary search",
"implementation"
] | null | null | One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of code, drinks a cup of tea, then he writes as much as lines, drinks another cup of tea, then he writes lin... | The input consists of two integers *n* and *k*, separated by spaces — the size of the program in lines and the productivity reduction coefficient, 1<=≤<=*n*<=≤<=109, 2<=≤<=*k*<=≤<=10. | Print the only integer — the minimum value of *v* that lets Vasya write the program in one night. | [
"7 2\n",
"59 9\n"
] | [
"4\n",
"54\n"
] | In the first sample the answer is *v* = 4. Vasya writes the code in the following portions: first 4 lines, then 2, then 1, and then Vasya falls asleep. Thus, he manages to write 4 + 2 + 1 = 7 lines in a night and complete the task.
In the second sample the answer is *v* = 54. Vasya writes the code in the following por... | 1,000 | [
{
"input": "7 2",
"output": "4"
},
{
"input": "59 9",
"output": "54"
},
{
"input": "1 9",
"output": "1"
},
{
"input": "11 2",
"output": "7"
},
{
"input": "747 2",
"output": "376"
},
{
"input": "6578 2",
"output": "3293"
},
{
"input": "37212... | 1,657,861,995 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 56 | 124 | 0 |
def check(x):
val=0
div=0
while val<n and x//(k**div)>0:
val=val+x//(k**(div))
div=div+1
# print(val,div)
# print(x,val)
if val<n:
return False
return True
n,k=list(map(int,input().split()))
# print(check(4))
i=-1
j=10**10
while i+1<j:
mid=(i+j)//2
# print(check(... | Title: Burning Midnight Oil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of c... | ```python
def check(x):
val=0
div=0
while val<n and x//(k**div)>0:
val=val+x//(k**(div))
div=div+1
# print(val,div)
# print(x,val)
if val<n:
return False
return True
n,k=list(map(int,input().split()))
# print(check(4))
i=-1
j=10**10
while i+1<j:
mid=(i+j)//2
# pr... | 3 | |
805 | B | 3-palindrome | PROGRAMMING | 1,000 | [
"constructive algorithms"
] | null | null | In the beginning of the new year Keivan decided to reverse his name. He doesn't like palindromes, so he changed Naviek to Navick.
He is too selfish, so for a given *n* he wants to obtain a string of *n* characters, each of which is either 'a', 'b' or 'c', with no palindromes of length 3 appearing in the string as a su... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=2·105) — the length of the string. | Print the string that satisfies all the constraints.
If there are multiple answers, print any of them. | [
"2\n",
"3\n"
] | [
"aa\n",
"bba\n"
] | A palindrome is a sequence of characters which reads the same backward and forward. | 1,000 | [
{
"input": "2",
"output": "aa"
},
{
"input": "3",
"output": "aab"
},
{
"input": "38",
"output": "aabbaabbaabbaabbaabbaabbaabbaabbaabbaa"
},
{
"input": "47",
"output": "aabbaabbaabbaabbaabbaabbaabbaabbaabbaabbaabbaab"
},
{
"input": "59",
"output": "aabbaabbaabb... | 1,591,127,448 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 124 | 819,200 | n=int(input())
s=''
c='a'
for i in range(n//2+1):
if c=='a':
s=s+'aa'
c='b'
else:
s=s+'bb'
c='a'
print(s[0:n]) | Title: 3-palindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the beginning of the new year Keivan decided to reverse his name. He doesn't like palindromes, so he changed Naviek to Navick.
He is too selfish, so for a given *n* he wants to obtain a string of *n* characters, each o... | ```python
n=int(input())
s=''
c='a'
for i in range(n//2+1):
if c=='a':
s=s+'aa'
c='b'
else:
s=s+'bb'
c='a'
print(s[0:n])
``` | 3 | |
430 | B | Balls Game | PROGRAMMING | 1,400 | [
"brute force",
"two pointers"
] | null | null | Iahub is training for the IOI. What is a better way to train than playing a Zuma-like game?
There are *n* balls put in a row. Each ball is colored in one of *k* colors. Initially the row doesn't contain three or more contiguous balls with the same color. Iahub has a single ball of color *x*. He can insert his ball at... | The first line of input contains three integers: *n* (1<=≤<=*n*<=≤<=100), *k* (1<=≤<=*k*<=≤<=100) and *x* (1<=≤<=*x*<=≤<=*k*). The next line contains *n* space-separated integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=*k*). Number *c**i* means that the *i*-th ball in the row has color *c**i*.
It is guaranteed th... | Print a single integer — the maximum number of balls Iahub can destroy. | [
"6 2 2\n1 1 2 2 1 1\n",
"1 1 1\n1\n"
] | [
"6\n",
"0\n"
] | none | 1,000 | [
{
"input": "6 2 2\n1 1 2 2 1 1",
"output": "6"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 2 1\n2 1 2 2 1 2 2 1 1 2",
"output": "5"
},
{
"input": "50 2 1\n1 1 2 2 1 2 1 1 2 2 1 2 1 2 1 1 2 2 1 2 1 2 2 1 2 1 2 1 2 2 1 1 2 2 1 1 2 2 1 2 1 1 2 1 1 2 2 1 1 2",
"... | 1,427,117,765 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 62 | 204,800 | R = lambda: list(map(int, input().split()))
def dfs(a):
cnt = 0
n = len(a)
a.append(10000000)
for i in range(1, n):
if a[i] != a[i - 1]:
cnt = 0
else:
cnt += 1
if cnt >= 2:
j = i
while a[j] == a[i]:
... | Title: Balls Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub is training for the IOI. What is a better way to train than playing a Zuma-like game?
There are *n* balls put in a row. Each ball is colored in one of *k* colors. Initially the row doesn't contain three or more conti... | ```python
R = lambda: list(map(int, input().split()))
def dfs(a):
cnt = 0
n = len(a)
a.append(10000000)
for i in range(1, n):
if a[i] != a[i - 1]:
cnt = 0
else:
cnt += 1
if cnt >= 2:
j = i
while a[j] == a[i]:
... | 3 | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,416,594,741 | 4,341 | Python 3 | OK | TESTS | 35 | 93 | 0 | n = input()
for i in range(1,20):
if "8" in str(int(n)+i):
print(i)
break | Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
n = input()
for i in range(1,20):
if "8" in str(int(n)+i):
print(i)
break
``` | 3 | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,601,864,071 | 2,147,483,647 | Python 3 | OK | TESTS | 114 | 124 | 0 | n,k = map(int,input().split())
l = input()
if k >= n:
print("YES")
else:
for x in l:
t = l.count(x)
if t > k:
print("NO")
break
else:
print("YES") | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
n,k = map(int,input().split())
l = input()
if k >= n:
print("YES")
else:
for x in l:
t = l.count(x)
if t > k:
print("NO")
break
else:
print("YES")
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Santa Claus has Robot which lives on the infinite grid and can move along its lines. He can also, having a sequence of *m* points *p*1,<=*p*2,<=...,<=*p**m* with integer coordinates, do the following: denote its initial location by *p*0. First, the robot will move from *p*0 to *p*1 along one of the shortest paths betwe... | The first line of input contains the only positive integer *n* (1<=≤<=*n*<=≤<=2·105) which equals the number of unit segments the robot traveled. The second line contains the movements protocol, which consists of *n* letters, each being equal either L, or R, or U, or D. *k*-th letter stands for the direction which Robo... | The only line of input should contain the minimum possible length of the sequence. | [
"4\nRURD\n",
"6\nRRULDD\n",
"26\nRRRULURURUULULLLDLDDRDRDLD\n",
"3\nRLL\n",
"4\nLRLR\n"
] | [
"2\n",
"2\n",
"7\n",
"2\n",
"4\n"
] | The illustrations to the first three tests are given below.
<img class="tex-graphics" src="https://espresso.codeforces.com/832fb8f97a482be815e0f87edde26c9791a0d330.png" style="max-width: 100.0%;max-height: 100.0%;"/> <img class="tex-graphics" src="https://espresso.codeforces.com/119a8ba68772b2c2bf76f2acdc58027f6c5cde1... | 0 | [
{
"input": "4\nRURD",
"output": "2"
},
{
"input": "6\nRRULDD",
"output": "2"
},
{
"input": "26\nRRRULURURUULULLLDLDDRDRDLD",
"output": "7"
},
{
"input": "3\nRLL",
"output": "2"
},
{
"input": "4\nLRLR",
"output": "4"
},
{
"input": "5\nLRDLR",
"outpu... | 1,482,659,151 | 2,451 | PyPy 3 | OK | TESTS | 32 | 187 | 27,955,200 | from sys import stdin
n = int(stdin.readline())
s = stdin.readline().strip()
x = 0
y = 0
xs = 0
ys = 0
ans = 0
l = 0
for ch in s:
xp = x
yp = y
if ch == 'L':
x -= 1
if ch == 'R':
x += 1
if ch == 'U':
y += 1
if ch == 'D':
y -= 1
l += 1
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has Robot which lives on the infinite grid and can move along its lines. He can also, having a sequence of *m* points *p*1,<=*p*2,<=...,<=*p**m* with integer coordinates, do the following: denote its initial location b... | ```python
from sys import stdin
n = int(stdin.readline())
s = stdin.readline().strip()
x = 0
y = 0
xs = 0
ys = 0
ans = 0
l = 0
for ch in s:
xp = x
yp = y
if ch == 'L':
x -= 1
if ch == 'R':
x += 1
if ch == 'U':
y += 1
if ch == 'D':
y -= 1
... | 3 | |
981 | A | Antipalindrome | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not.
A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2}... | The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only. | If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$.
Note that there can be multiple longest substrings that are not palindromes, but their length is unique. | [
"mew\n",
"wuffuw\n",
"qqqqqqqq\n"
] | [
"3\n",
"5\n",
"0\n"
] | "mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$.
The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$.
All sub... | 500 | [
{
"input": "mew",
"output": "3"
},
{
"input": "wuffuw",
"output": "5"
},
{
"input": "qqqqqqqq",
"output": "0"
},
{
"input": "ijvji",
"output": "4"
},
{
"input": "iiiiiii",
"output": "0"
},
{
"input": "wobervhvvkihcuyjtmqhaaigvvgiaahqmtjyuchikvvhvrebow"... | 1,567,688,810 | 2,147,483,647 | Python 3 | OK | TESTS | 133 | 187 | 0 | n = input()
s = {x for x in n}
r = n[::-1]
print(0) if len(s) == 1 else print(len(n)-1) if r == n else print(len(n))
| Title: Antipalindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" ar... | ```python
n = input()
s = {x for x in n}
r = n[::-1]
print(0) if len(s) == 1 else print(len(n)-1) if r == n else print(len(n))
``` | 3 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,670,427,662 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 124 | 0 | input()
a = list(map(int, input().split()))
j = list()
t = list()
for i in a:
if i % 2 == 0:
j.append(i)
else:
t.append(i)
if len(j) == 1:
print(a.index(j[0]) + 1)
elif len(t) == 1:
print(a.index(t[0]) + 1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
input()
a = list(map(int, input().split()))
j = list()
t = list()
for i in a:
if i % 2 == 0:
j.append(i)
else:
t.append(i)
if len(j) == 1:
print(a.index(j[0]) + 1)
elif len(t) == 1:
print(a.index(t[0]) + 1)
``` | 3.969 |
820 | A | Mister B and Book Reading | PROGRAMMING | 900 | [
"implementation"
] | null | null | Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, starting from the second, he read *a* pages more than on the previous day (at first day he read *v*0 pages, at ... | First and only line contains five space-separated integers: *c*, *v*0, *v*1, *a* and *l* (1<=≤<=*c*<=≤<=1000, 0<=≤<=*l*<=<<=*v*0<=≤<=*v*1<=≤<=1000, 0<=≤<=*a*<=≤<=1000) — the length of the book in pages, the initial reading speed, the maximum reading speed, the acceleration in reading speed and the number of pages fo... | Print one integer — the number of days Mister B needed to finish the book. | [
"5 5 10 5 4\n",
"12 4 12 4 1\n",
"15 1 100 0 0\n"
] | [
"1\n",
"3\n",
"15\n"
] | In the first sample test the book contains 5 pages, so Mister B read it right at the first day.
In the second sample test at first day Mister B read pages number 1 - 4, at second day — 4 - 11, at third day — 11 - 12 and finished the book.
In third sample test every day Mister B read 1 page of the book, so he finished... | 500 | [
{
"input": "5 5 10 5 4",
"output": "1"
},
{
"input": "12 4 12 4 1",
"output": "3"
},
{
"input": "15 1 100 0 0",
"output": "15"
},
{
"input": "1 1 1 0 0",
"output": "1"
},
{
"input": "1000 999 1000 1000 998",
"output": "2"
},
{
"input": "1000 2 2 5 1",
... | 1,499,530,406 | 1,106 | Python 3 | OK | TESTS | 110 | 62 | 5,529,600 | a = input()
b = a.split(" ")
c, v0, v1, a, l = int(b[0]), int(b[1]), int(b[2]), int(b[3]), int(b[4])
day = 1
while c > 0:
if day > 1:
c = c + l
c = c - min(v0 + a * (day - 1), v1)
if c <= 0:
break
day += 1
print(day)
| Title: Mister B and Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, ... | ```python
a = input()
b = a.split(" ")
c, v0, v1, a, l = int(b[0]), int(b[1]), int(b[2]), int(b[3]), int(b[4])
day = 1
while c > 0:
if day > 1:
c = c + l
c = c - min(v0 + a * (day - 1), v1)
if c <= 0:
break
day += 1
print(day)
``` | 3 | |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,568,563,150 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 155 | 0 | n = int(input())
answer = []
s, i = 0, 1
while s < n:
answer.append(i)
s += i
i += 1
d = s - n
answer = list(filter(lambda x: x != d, answer))
print(len(answer))
print(' '.join(map(str, answer)))
| Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
n = int(input())
answer = []
s, i = 0, 1
while s < n:
answer.append(i)
s += i
i += 1
d = s - n
answer = list(filter(lambda x: x != d, answer))
print(len(answer))
print(' '.join(map(str, answer)))
``` | 3 | |
352 | A | Jeff and Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make from the cards he's got?
Jeff must make the number without leading zero. At that, we assume that numbe... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103). The next line contains *n* integers *a*1, *a*2, ..., *a**n* (*a**i*<==<=0 or *a**i*<==<=5). Number *a**i* represents the digit that is written on the *i*-th card. | In a single line print the answer to the problem — the maximum number, divisible by 90. If you can't make any divisible by 90 number from the cards, print -1. | [
"4\n5 0 5 0\n",
"11\n5 5 5 5 5 5 5 5 0 5 5\n"
] | [
"0\n",
"5555555550\n"
] | In the first test you can make only one number that is a multiple of 90 — 0.
In the second test you can make number 5555555550, it is a multiple of 90. | 500 | [
{
"input": "4\n5 0 5 0",
"output": "0"
},
{
"input": "11\n5 5 5 5 5 5 5 5 0 5 5",
"output": "5555555550"
},
{
"input": "7\n5 5 5 5 5 5 5",
"output": "-1"
},
{
"input": "1\n5",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "11\n5 0 5 ... | 1,650,095,461 | 2,147,483,647 | PyPy 3 | OK | TESTS | 42 | 184 | 0 | input();a=input().split()
print('5'*(a.count('5')//9*9)+'0'*a.count('0') if a.count('5')>8 and a.count('0') else -(a.count('0')==0)) | Title: Jeff and Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make fr... | ```python
input();a=input().split()
print('5'*(a.count('5')//9*9)+'0'*a.count('0') if a.count('5')>8 and a.count('0') else -(a.count('0')==0))
``` | 3 | |
659 | C | Tanya and Toys | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the *i*-th type costs *i* bourles.
Tania has managed to collect *n* different types of toys *a*1,<=*a*2,<=...,<=*a**n* from the new collection... | The first line contains two integers *n* (1<=≤<=*n*<=≤<=100<=000) and *m* (1<=≤<=*m*<=≤<=109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109... | In the first line print a single integer *k* — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed *m*.
In the second line print *k* distinct space-separated ... | [
"3 7\n1 3 4\n",
"4 14\n4 6 12 8\n"
] | [
"2\n2 5 \n",
"4\n7 2 3 1\n"
] | In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | 1,000 | [
{
"input": "3 7\n1 3 4",
"output": "2\n2 5 "
},
{
"input": "4 14\n4 6 12 8",
"output": "4\n1 2 3 5 "
},
{
"input": "5 6\n97746 64770 31551 96547 65684",
"output": "3\n1 2 3 "
},
{
"input": "10 10\n94125 56116 29758 94024 29289 31663 99794 35076 25328 58656",
"output": "4\... | 1,645,810,400 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 139 | 10,240,000 | def main():
n, k = map(int, input().split())
arr = set(map(int, input().split()))
i = 1
s = 0
answer_arr = []
while True:
if i not in arr:
if s + i > k:
break
else:
s += i
answer_arr.append(i)
... | Title: Tanya and Toys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the *i*-th type costs *i* bourles.
Tania h... | ```python
def main():
n, k = map(int, input().split())
arr = set(map(int, input().split()))
i = 1
s = 0
answer_arr = []
while True:
if i not in arr:
if s + i > k:
break
else:
s += i
answer_arr.append(i)... | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,601,626,233 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 218 | 307,200 | x=int(input())
a,b,c=0,0,0
l=[]
for i in range(x):
l.append(input().split(' '))
for i in range(x):
a+=int(l[i][0])
b+=int(l[i][1])
c+=int(l[i][2])
print(['YES','NO'][a!=0 or b!=0 or c!=0])
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
x=int(input())
a,b,c=0,0,0
l=[]
for i in range(x):
l.append(input().split(' '))
for i in range(x):
a+=int(l[i][0])
b+=int(l[i][1])
c+=int(l[i][2])
print(['YES','NO'][a!=0 or b!=0 or c!=0])
``` | 3.944928 |
66 | A | Petya and Java | PROGRAMMING | 1,300 | [
"implementation",
"strings"
] | A. Petya and Java | 2 | 256 | Little Petya has recently started attending a programming club. Naturally he is facing the problem of choosing a programming language. After long considerations he realized that Java is the best choice. The main argument in favor of choosing Java was that it has a very large integer data type, called BigInteger.
But h... | The first line contains a positive number *n*. It consists of no more than 100 digits and doesn't contain any leading zeros. The number *n* can't be represented as an empty string.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d). | Print the first type from the list "byte, short, int, long, BigInteger", that can store the natural number *n*, in accordance with the data given above. | [
"127\n",
"130\n",
"123456789101112131415161718192021222324\n"
] | [
"byte\n",
"short\n",
"BigInteger\n"
] | none | 500 | [
{
"input": "127",
"output": "byte"
},
{
"input": "130",
"output": "short"
},
{
"input": "123456789101112131415161718192021222324",
"output": "BigInteger"
},
{
"input": "6",
"output": "byte"
},
{
"input": "16",
"output": "byte"
},
{
"input": "126",
... | 1,643,272,038 | 2,147,483,647 | Python 3 | OK | TESTS | 90 | 154 | 0 | n=int(input())
if n<=127: print("byte")
elif n<=32767: print("short")
elif n<=2147483647: print("int")
elif n<=9223372036854775807: print("long")
else: print("BigInteger") | Title: Petya and Java
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya has recently started attending a programming club. Naturally he is facing the problem of choosing a programming language. After long considerations he realized that Java is the best choice. The main argument in ... | ```python
n=int(input())
if n<=127: print("byte")
elif n<=32767: print("short")
elif n<=2147483647: print("int")
elif n<=9223372036854775807: print("long")
else: print("BigInteger")
``` | 3.9615 |
768 | A | Oath of the Night's Watch | PROGRAMMING | 900 | [
"constructive algorithms",
"sortings"
] | null | null | "Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am the sword in the darkness. I am the watcher on the walls. I am the shield that guards the realms of men. I ple... | First line consists of a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of stewards with Jon Snow.
Second line consists of *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) representing the values assigned to the stewards. | Output a single integer representing the number of stewards which Jon will feed. | [
"2\n1 5\n",
"3\n1 2 5\n"
] | [
"0",
"1"
] | In the first sample, Jon Snow cannot support steward with strength 1 because there is no steward with strength less than 1 and he cannot support steward with strength 5 because there is no steward with strength greater than 5.
In the second sample, Jon Snow can support steward with strength 2 because there are steward... | 500 | [
{
"input": "2\n1 5",
"output": "0"
},
{
"input": "3\n1 2 5",
"output": "1"
},
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "8\n7 8 9 4 5 6 1 2",
"output": "6"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n100",
"output": "0"
},
... | 1,684,008,681 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 88 | 92 | 13,619,200 | n = int(input())
lst = list(map(int, input().split()))
a = min(lst)
b = max(lst)
a1 = lst.count(a)
b1 = lst.count(b)
if n - a1-b1>0:
print(n - a1 - b1)
else:
print(0)
| Title: Oath of the Night's Watch
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am... | ```python
n = int(input())
lst = list(map(int, input().split()))
a = min(lst)
b = max(lst)
a1 = lst.count(a)
b1 = lst.count(b)
if n - a1-b1>0:
print(n - a1 - b1)
else:
print(0)
``` | 3 | |
216 | A | Tiling with Hexagons | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Several ages ago Berland was a kingdom. The King of Berland adored math. That's why, when he first visited one of his many palaces, he first of all paid attention to the floor in one hall. The floor was tiled with hexagonal tiles.
The hall also turned out hexagonal in its shape. The King walked along the perimeter of ... | The first line contains three integers: *a*, *b* and *c* (2<=≤<=*a*,<=*b*,<=*c*<=≤<=1000). | Print a single number — the total number of tiles on the hall floor. | [
"2 3 4\n"
] | [
"18"
] | none | 500 | [
{
"input": "2 3 4",
"output": "18"
},
{
"input": "2 2 2",
"output": "7"
},
{
"input": "7 8 13",
"output": "224"
},
{
"input": "14 7 75",
"output": "1578"
},
{
"input": "201 108 304",
"output": "115032"
},
{
"input": "999 998 996",
"output": "298302... | 1,518,303,624 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 5,632,000 | def readInts(): return map(int, input().split())
a, b, c = readInts()
ans = 0
while min(a,b,c) > 1:
ans += 2*(a+b+c) - 6
a -= 1
b -= 1
c -= 1
ans += a*b*c
print(ans)
| Title: Tiling with Hexagons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Several ages ago Berland was a kingdom. The King of Berland adored math. That's why, when he first visited one of his many palaces, he first of all paid attention to the floor in one hall. The floor was tiled with ... | ```python
def readInts(): return map(int, input().split())
a, b, c = readInts()
ans = 0
while min(a,b,c) > 1:
ans += 2*(a+b+c) - 6
a -= 1
b -= 1
c -= 1
ans += a*b*c
print(ans)
``` | 3 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,683,954,261 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 31 | 0 | a = int(input())
i = 0
s = 5
while s < a:
i += 1
s += 5 * 2 ** i
n = ['Sheldon'] + ['Leonard'] + ['Penny'] + ['Rajesh'] + ['Howard']
print(n[(a - (s - 5 * 2 ** i) - 1) // 2 ** i]) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
a = int(input())
i = 0
s = 5
while s < a:
i += 1
s += 5 * 2 ** i
n = ['Sheldon'] + ['Leonard'] + ['Penny'] + ['Rajesh'] + ['Howard']
print(n[(a - (s - 5 * 2 ** i) - 1) // 2 ** i])
``` | 3.9845 |
282 | A | Bit++ | PROGRAMMING | 800 | [
"implementation"
] | null | null | The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.
The language is that peculiar as it has exactly one variable, called *x*. Also, there are two operations:
- Operation ++ increases the value of variable *x* by 1. - Operation -- decreases the value of variable *x* by... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=150) — the number of statements in the programme.
Next *n* lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable *x* (denoted as letter «X»). Thus, there are no empty statements. The operation and th... | Print a single integer — the final value of *x*. | [
"1\n++X\n",
"2\nX++\n--X\n"
] | [
"1\n",
"0\n"
] | none | 500 | [
{
"input": "1\n++X",
"output": "1"
},
{
"input": "2\nX++\n--X",
"output": "0"
},
{
"input": "3\n++X\n++X\n++X",
"output": "3"
},
{
"input": "2\n--X\n--X",
"output": "-2"
},
{
"input": "5\n++X\n--X\n++X\n--X\n--X",
"output": "-1"
},
{
"input": "28\nX--\... | 1,696,758,283 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 46 | 0 | n = int(input())
cou = 0
for i in range(n):
a = str(input())
if a[0] == '+' or a[len(a) - 1] == '+':
cou += 1
elif a[0] == '-' or a[len(a) - 1] == '-':
cou -= 1
print(cou) | Title: Bit++
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.
The language is that peculiar as it has exactly one variable, called *x*. Also, there are two operations:
- Operation ++ incre... | ```python
n = int(input())
cou = 0
for i in range(n):
a = str(input())
if a[0] == '+' or a[len(a) - 1] == '+':
cou += 1
elif a[0] == '-' or a[len(a) - 1] == '-':
cou -= 1
print(cou)
``` | 3 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,687,269,890 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | n1 = input()
n2 = input()
t = len(n2) - 1
count = 0
for i in range(len(n1)):
if (n1[i] == n2[t]):
count += 1
t -= 1
if count == len(n1):
print("YES")
else:
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
n1 = input()
n2 = input()
t = len(n2) - 1
count = 0
for i in range(len(n1)):
if (n1[i] == n2[t]):
count += 1
t -= 1
if count == len(n1):
print("YES")
else:
print("NO")
``` | 3.977 |
703 | A | Mishka and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they started playing the game.
Rules of the game are very simple: at first number of rounds *n* is defined.... | The first line of the input contains single integer *n* *n* (1<=≤<=*n*<=≤<=100) — the number of game rounds.
The next *n* lines contains rounds description. *i*-th of them contains pair of integers *m**i* and *c**i* (1<=≤<=*m**i*,<=<=*c**i*<=≤<=6) — values on dice upper face after Mishka's and Chris' throws in *i*-th ... | If Mishka is the winner of the game, print "Mishka" (without quotes) in the only line.
If Chris is the winner of the game, print "Chris" (without quotes) in the only line.
If the result of the game is draw, print "Friendship is magic!^^" (without quotes) in the only line. | [
"3\n3 5\n2 1\n4 2\n",
"2\n6 1\n1 6\n",
"3\n1 5\n3 3\n2 2\n"
] | [
"Mishka",
"Friendship is magic!^^",
"Chris"
] | In the first sample case Mishka loses the first round, but wins second and third rounds and thus she is the winner of the game.
In the second sample case Mishka wins the first round, Chris wins the second round, and the game ends with draw with score 1:1.
In the third sample case Chris wins the first round, but there... | 500 | [
{
"input": "3\n3 5\n2 1\n4 2",
"output": "Mishka"
},
{
"input": "2\n6 1\n1 6",
"output": "Friendship is magic!^^"
},
{
"input": "3\n1 5\n3 3\n2 2",
"output": "Chris"
},
{
"input": "6\n4 1\n4 2\n5 3\n5 1\n5 3\n4 1",
"output": "Mishka"
},
{
"input": "8\n2 4\n1 4\n1 ... | 1,688,762,715 | 2,147,483,647 | Python 3 | OK | TESTS | 69 | 46 | 0 |
# это задача 703A
n = int(input())
m = 0
c = 0
for i in range(n):
a, b = map(int, input().split())
if a > b:
m = m + 1
elif b > a:
c = c + 1
if m > c:
print("Mishka")
if m < c:
print("Chris")
if m == c:
print("Friendship is magic!^^") | Title: Mishka and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they st... | ```python
# это задача 703A
n = int(input())
m = 0
c = 0
for i in range(n):
a, b = map(int, input().split())
if a > b:
m = m + 1
elif b > a:
c = c + 1
if m > c:
print("Mishka")
if m < c:
print("Chris")
if m == c:
print("Friendship is magic!^^")
``` | 3 | |
10 | A | Power Consumption Calculation | PROGRAMMING | 900 | [
"implementation"
] | A. Power Consumption Calculation | 1 | 256 | Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T... | The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<... | Output the answer to the problem. | [
"1 3 2 1 5 10\n0 10\n",
"2 8 4 2 5 10\n20 30\n50 100\n"
] | [
"30",
"570"
] | none | 0 | [
{
"input": "1 3 2 1 5 10\n0 10",
"output": "30"
},
{
"input": "2 8 4 2 5 10\n20 30\n50 100",
"output": "570"
},
{
"input": "3 15 9 95 39 19\n873 989\n1003 1137\n1172 1436",
"output": "8445"
},
{
"input": "4 73 2 53 58 16\n51 52\n209 242\n281 407\n904 945",
"output": "5287... | 1,588,366,710 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 280 | 0 | #10A - Power Consumption
from sys import stdin
#Get information about the working periods
#P - how much power the computer uses in the current state
#P1 = working mode power consumption
#P2 = screensaving mode power consumption
#P3 = sleep mode power consumption
#T - the time that passed from the last time Tom t... | Title: Power Consumption Calculation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard f... | ```python
#10A - Power Consumption
from sys import stdin
#Get information about the working periods
#P - how much power the computer uses in the current state
#P1 = working mode power consumption
#P2 = screensaving mode power consumption
#P3 = sleep mode power consumption
#T - the time that passed from the last ... | 3.86 |
893 | C | Rumor | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"greedy"
] | null | null | Vova promised himself that he would never play computer games... But recently Firestorm — a well-known game developing company — published their newest game, World of Farcraft, and it became really popular. Of course, Vova started playing it.
Now he tries to solve a quest. The task is to come to a settlement named Ove... | The first line contains two integer numbers *n* and *m* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105) — the number of characters in Overcity and the number of pairs of friends.
The second line contains *n* integer numbers *c**i* (0<=≤<=*c**i*<=≤<=109) — the amount of gold *i*-th character asks to start spreading the rumor.
... | Print one number — the minimum amount of gold Vova has to spend in order to finish the quest. | [
"5 2\n2 5 3 4 8\n1 4\n4 5\n",
"10 0\n1 2 3 4 5 6 7 8 9 10\n",
"10 5\n1 6 2 7 3 8 4 9 5 10\n1 2\n3 4\n5 6\n7 8\n9 10\n"
] | [
"10\n",
"55\n",
"15\n"
] | In the first example the best decision is to bribe the first character (he will spread the rumor to fourth character, and the fourth one will spread it to fifth). Also Vova has to bribe the second and the third characters, so they know the rumor.
In the second example Vova has to bribe everyone.
In the third example ... | 0 | [
{
"input": "5 2\n2 5 3 4 8\n1 4\n4 5",
"output": "10"
},
{
"input": "10 0\n1 2 3 4 5 6 7 8 9 10",
"output": "55"
},
{
"input": "10 5\n1 6 2 7 3 8 4 9 5 10\n1 2\n3 4\n5 6\n7 8\n9 10",
"output": "15"
},
{
"input": "1 0\n0",
"output": "0"
},
{
"input": "1 0\n10000000... | 1,666,893,790 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 982 | 19,456,000 | # funtion of bfs
def dfs(index, visited, neighbours, cost):
stack = [index]
min = cost[index]
while len(stack) > 0:
u = stack.pop()
if visited[u] == 0:
if cost[u] < min:
min = cost[u]
visited[u] = 1
for i in neighbours[u]:
if v... | Title: Rumor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vova promised himself that he would never play computer games... But recently Firestorm — a well-known game developing company — published their newest game, World of Farcraft, and it became really popular. Of course, Vova starte... | ```python
# funtion of bfs
def dfs(index, visited, neighbours, cost):
stack = [index]
min = cost[index]
while len(stack) > 0:
u = stack.pop()
if visited[u] == 0:
if cost[u] < min:
min = cost[u]
visited[u] = 1
for i in neighbours[u]:
... | 3 | |
807 | A | Is it rated? | PROGRAMMING | 900 | [
"implementation",
"sortings"
] | null | null | Is it rated?
Here it is. The Ultimate Question of Competitive Programming, Codeforces, and Everything. And you are here to answer it.
Another Codeforces round has been conducted. No two participants have the same number of points. For each participant, from the top to the bottom of the standings, their rating before ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=1000) — the number of round participants.
Each of the next *n* lines contains two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=4126) — the rating of the *i*-th participant before and after the round, respectively. The participants are listed in order... | If the round is rated for sure, print "rated". If the round is unrated for sure, print "unrated". If it's impossible to determine whether the round is rated or not, print "maybe". | [
"6\n3060 3060\n2194 2194\n2876 2903\n2624 2624\n3007 2991\n2884 2884\n",
"4\n1500 1500\n1300 1300\n1200 1200\n1400 1400\n",
"5\n3123 3123\n2777 2777\n2246 2246\n2246 2246\n1699 1699\n"
] | [
"rated\n",
"unrated\n",
"maybe\n"
] | In the first example, the ratings of the participants in the third and fifth places have changed, therefore, the round was rated.
In the second example, no one's rating has changed, but the participant in the second place has lower rating than the participant in the fourth place. Therefore, if the round was rated, som... | 500 | [
{
"input": "6\n3060 3060\n2194 2194\n2876 2903\n2624 2624\n3007 2991\n2884 2884",
"output": "rated"
},
{
"input": "4\n1500 1500\n1300 1300\n1200 1200\n1400 1400",
"output": "unrated"
},
{
"input": "5\n3123 3123\n2777 2777\n2246 2246\n2246 2246\n1699 1699",
"output": "maybe"
},
{
... | 1,659,183,925 | 2,147,483,647 | Python 3 | OK | TESTS | 150 | 46 | 0 | def isSorted(arr:list,ascending:bool):
old = arr[0]
for i in arr:
if ascending and old>i:
return False
if not ascending and old < i:
return False
old = i
return True
n = int(input())
arr = []
while n:
n-=1
inn = input().split()
if(i... | Title: Is it rated?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Is it rated?
Here it is. The Ultimate Question of Competitive Programming, Codeforces, and Everything. And you are here to answer it.
Another Codeforces round has been conducted. No two participants have the same number ... | ```python
def isSorted(arr:list,ascending:bool):
old = arr[0]
for i in arr:
if ascending and old>i:
return False
if not ascending and old < i:
return False
old = i
return True
n = int(input())
arr = []
while n:
n-=1
inn = input().split()... | 3 | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,671,487,223 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 122 | 0 | y,w = map(int,input().split())
r = (7-max(y,w))/6
if r == 1/6 :
print("1/6")
elif r == 2/6 :
print("1/3")
elif r == 3/6 :
print("1/2")
elif r == 4/6 :
print("2/3")
elif r == 5/6 :
print("5/6")
else:
print("1/1") | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
y,w = map(int,input().split())
r = (7-max(y,w))/6
if r == 1/6 :
print("1/6")
elif r == 2/6 :
print("1/3")
elif r == 3/6 :
print("1/2")
elif r == 4/6 :
print("2/3")
elif r == 5/6 :
print("5/6")
else:
print("1/1")
``` | 3.939 |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,631,842,899 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 218 | 20,172,800 | x,y,z = tuple(map(int,input().split()))
a = int(((x*z)//y)**(1/2))
b = int(x//a)
c = int(z//a)
print(4*(a+b+c))
| Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
x,y,z = tuple(map(int,input().split()))
a = int(((x*z)//y)**(1/2))
b = int(x//a)
c = int(z//a)
print(4*(a+b+c))
``` | 3 | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,461,515,868 | 168 | Python 3 | OK | TESTS | 26 | 62 | 4,915,200 | a = int(input())
print(a//3*2+[0,1][a%3!=0]) | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
a = int(input())
print(a//3*2+[0,1][a%3!=0])
``` | 3 | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,651,674,717 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 77 | 2,355,200 | n,x = (map(int,input().split()))
d = 0
for _ in range(n) :
a = input().split()
if a[0]=="+" :
x+=int(a[1])
else :
if x<int(a[1]) :
d+=1
else :
x-=int(a[1])
print(str(x)+" "+str(d)) | Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
n,x = (map(int,input().split()))
d = 0
for _ in range(n) :
a = input().split()
if a[0]=="+" :
x+=int(a[1])
else :
if x<int(a[1]) :
d+=1
else :
x-=int(a[1])
print(str(x)+" "+str(d))
``` | 3 | |
672 | B | Different is Good | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are different, he wants all substrings of his string *s* to be distinct. Substring is a string formed by some... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the length of the string *s*.
The second line contains the string *s* of length *n* consisting of only lowercase English letters. | If it's impossible to change the string *s* such that all its substring are distinct print -1. Otherwise print the minimum required number of changes. | [
"2\naa\n",
"4\nkoko\n",
"5\nmurat\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample one of the possible solutions is to change the first character to 'b'.
In the second sample, one may change the first character to 'a' and second character to 'b', so the string becomes "abko". | 1,000 | [
{
"input": "2\naa",
"output": "1"
},
{
"input": "4\nkoko",
"output": "2"
},
{
"input": "5\nmurat",
"output": "0"
},
{
"input": "6\nacbead",
"output": "1"
},
{
"input": "7\ncdaadad",
"output": "4"
},
{
"input": "25\npeoaicnbisdocqofsqdpgobpn",
"outp... | 1,546,662,367 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 124 | 204,800 | def main():
n = int(input())
s = input()
arr = [0] * 26
for char in s:
arr[ord(char) - ord('a')] += 1
ans = 0
count = 0
for c in range(26):
if arr[c] > 0:
count += 1
ans += arr[c] - 1
if 26 - count < ans:
print(-1)
else:
print(ans)
main() | Title: Different is Good
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are di... | ```python
def main():
n = int(input())
s = input()
arr = [0] * 26
for char in s:
arr[ord(char) - ord('a')] += 1
ans = 0
count = 0
for c in range(26):
if arr[c] > 0:
count += 1
ans += arr[c] - 1
if 26 - count < ans:
print(-1)
else:
print(ans)
main()
``` | 3 | |
265 | B | Roadside Trees (Simplified Edition) | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | Squirrel Liss loves nuts. There are *n* trees (numbered 1 to *n* from west to east) along a street and there is a delicious nut on the top of each tree. The height of the tree *i* is *h**i*. Liss wants to eat all nuts.
Now Liss is on the root of the tree with the number 1. In one second Liss can perform one of the fol... | The first line contains an integer *n* (1<=<=≤<=<=*n*<=≤<=105) — the number of trees.
Next *n* lines contains the height of trees: *i*-th line contains an integer *h**i* (1<=≤<=*h**i*<=≤<=104) — the height of the tree with the number *i*. | Print a single integer — the minimal time required to eat all nuts in seconds. | [
"2\n1\n2\n",
"5\n2\n1\n2\n1\n1\n"
] | [
"5\n",
"14\n"
] | none | 1,000 | [
{
"input": "2\n1\n2",
"output": "5"
},
{
"input": "5\n2\n1\n2\n1\n1",
"output": "14"
},
{
"input": "1\n1",
"output": "2"
}
] | 1,611,901,019 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 404 | 0 | i=0
ans=0
past=0
for x in range(int(input())):
n=int(input())
if i==0:
ans=n+1
past=n
##print(ans)
else:
ans+=abs(past-n)+2
##print(ans)
i+=1
past=n
print(ans) | Title: Roadside Trees (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Squirrel Liss loves nuts. There are *n* trees (numbered 1 to *n* from west to east) along a street and there is a delicious nut on the top of each tree. The height of the tree *i* is *h**i*. Liss wan... | ```python
i=0
ans=0
past=0
for x in range(int(input())):
n=int(input())
if i==0:
ans=n+1
past=n
##print(ans)
else:
ans+=abs(past-n)+2
##print(ans)
i+=1
past=n
print(ans)
``` | 3 | |
18 | C | Stripe | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | C. Stripe | 2 | 64 | Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=105) — amount of squares in the stripe. The second line contains *n* space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. | Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. | [
"9\n1 5 -6 7 9 -16 0 -2 2\n",
"3\n1 1 1\n",
"2\n0 0\n"
] | [
"3\n",
"0\n",
"1\n"
] | none | 0 | [
{
"input": "9\n1 5 -6 7 9 -16 0 -2 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "0"
},
{
"input": "2\n0 0",
"output": "1"
},
{
"input": "4\n100 1 10 111",
"output": "1"
},
{
"input": "10\n0 4 -3 0 -2 2 -3 -3 2 5",
"output": "3"
},
{
"input": "... | 1,584,862,260 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 404 | 11,878,400 | def main():
n = int(input())
a = list(map(int,input().split()))
b = [a[0]]
for i in range(1,n):
b.append(b[i-1]+a[i])
poss_count = 0
for i in range(n-1):
if b[i] == (b[n-1] - b[i]):
poss_count += 1
#print(i)
print(poss_count)
if __name__ == '__main__':... | Title: Stripe
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that ... | ```python
def main():
n = int(input())
a = list(map(int,input().split()))
b = [a[0]]
for i in range(1,n):
b.append(b[i-1]+a[i])
poss_count = 0
for i in range(n-1):
if b[i] == (b[n-1] - b[i]):
poss_count += 1
#print(i)
print(poss_count)
if __name__ == '... | 3.810499 |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,587,635,518 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 342 | 2,560,000 | n, m = map(int, input().split())
str_arr = list()
for i in range(n):
string = input()
str_arr.append(string)
i_arr = []
for i in range(n):
if "*" in str_arr[i]:
i_arr.append(i)
i_min = min(i_arr)
i_max = max(i_arr)
min_j = str_arr[i_min].find("*")
tmp_index = 0
for i in range(n)... | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
n, m = map(int, input().split())
str_arr = list()
for i in range(n):
string = input()
str_arr.append(string)
i_arr = []
for i in range(n):
if "*" in str_arr[i]:
i_arr.append(i)
i_min = min(i_arr)
i_max = max(i_arr)
min_j = str_arr[i_min].find("*")
tmp_index = 0
for i i... | 3.809927 |
386 | A | Second-Price Auction | PROGRAMMING | 800 | [
"implementation"
] | null | null | In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is, each bidder secretly informs the organizer of the auction price he is willing to pay. After that, the au... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=1000) — number of bidders. The second line contains *n* distinct integer numbers *p*1,<=*p*2,<=... *p**n*, separated by single spaces (1<=≤<=*p**i*<=≤<=10000), where *p**i* stands for the price offered by the *i*-th bidder. | The single output line should contain two integers: index of the winner and the price he will pay. Indices are 1-based. | [
"2\n5 7\n",
"3\n10 2 8\n",
"6\n3 8 2 9 4 14\n"
] | [
"2 5\n",
"1 8\n",
"6 9\n"
] | none | 500 | [
{
"input": "2\n5 7",
"output": "2 5"
},
{
"input": "3\n10 2 8",
"output": "1 8"
},
{
"input": "6\n3 8 2 9 4 14",
"output": "6 9"
},
{
"input": "4\n4707 7586 4221 5842",
"output": "2 5842"
},
{
"input": "5\n3304 4227 4869 6937 6002",
"output": "4 6002"
},
{... | 1,630,998,838 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 77 | 6,963,200 | n=int(input())
sbid=input().split()
bid=[0]*n
for i in range(n):
sbid[i]=int(sbid[i])
bid[i]=sbid[i]
sbid.sort()
winner=sbid[len(sbid)-1]
price=sbid[len(sbid)-2]
print(bid.index(winner)+1,price)
| Title: Second-Price Auction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is... | ```python
n=int(input())
sbid=input().split()
bid=[0]*n
for i in range(n):
sbid[i]=int(sbid[i])
bid[i]=sbid[i]
sbid.sort()
winner=sbid[len(sbid)-1]
price=sbid[len(sbid)-2]
print(bid.index(winner)+1,price)
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as *q*<==<=*q*1*q*2... *q**k*. The algorithm consists of two steps:
1. Find any continuous subsequence (substring) of three characters of string *q... | The first line contains non-empty string *s*, its length (*n*) doesn't exceed 105. It is guaranteed that string *s* only contains characters: 'x', 'y', 'z'.
The second line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of tests. Next *m* lines contain the tests. The *i*-th line contains a pair of integers *l**... | For each test, print "YES" (without the quotes) if the algorithm works correctly on the corresponding test and "NO" (without the quotes) otherwise. | [
"zyxxxxxxyyz\n5\n5 5\n1 3\n1 11\n1 4\n3 6\n"
] | [
"YES\nYES\nNO\nYES\nNO\n"
] | In the first example, in test one and two the algorithm will always be terminated in one step. In the fourth test you can get string "xzyx" on which the algorithm will terminate. In all other tests the algorithm doesn't work correctly. | 0 | [
{
"input": "zyxxxxxxyyz\n5\n5 5\n1 3\n1 11\n1 4\n3 6",
"output": "YES\nYES\nNO\nYES\nNO"
},
{
"input": "yxzyzxzzxyyzzxxxzyyzzyzxxzxyzyyzxyzxyxxyzxyxzyzxyzxyyxzzzyzxyyxyzxxy\n10\n17 67\n6 35\n12 45\n56 56\n14 30\n25 54\n1 1\n46 54\n3 33\n19 40",
"output": "NO\nNO\nNO\nYES\nYES\nNO\nYES\nNO\nNO\nY... | 1,684,755,733 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 38 | 296 | 14,028,800 | # https://codeforces.com/contest/368
import sys
input = lambda: sys.stdin.readline().rstrip() # faster!
s = input()
m = int(input())
n = len(s)
cx, cy, cz = [0] * (n + 1), [0] * (n + 1), [0] * (n + 1)
for i in range(n):
cx[i + 1] = cx[i] + int(s[i] == "x")
cy[i + 1] = cy[i] + int(s[i] == "y")
cz[i + 1]... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja loves all sorts of algorithms. He has recently come up with a new algorithm, which receives a string as an input. Let's represent the input string of the algorithm as *q*<==<=*q*1*q*2... *q**k*. The algorithm consists of tw... | ```python
# https://codeforces.com/contest/368
import sys
input = lambda: sys.stdin.readline().rstrip() # faster!
s = input()
m = int(input())
n = len(s)
cx, cy, cz = [0] * (n + 1), [0] * (n + 1), [0] * (n + 1)
for i in range(n):
cx[i + 1] = cx[i] + int(s[i] == "x")
cy[i + 1] = cy[i] + int(s[i] == "y")
... | 3 | |
522 | B | Photo to Remember | PROGRAMMING | 1,100 | [
"*special",
"data structures",
"dp",
"implementation"
] | null | null | One day *n* friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together.
Simply speaking, the process of taking photos can be described as follows. On the photo, each photographed friend occupies a rectangle of pixels: the *i*-th of them occupies the rectangl... | The first line contains integer *n* (2<=≤<=*n*<=≤<=200<=000) — the number of friends.
Then *n* lines follow: the *i*-th line contains information about the *i*-th friend. The line contains a pair of integers *w**i*,<=*h**i* (1<=≤<=*w**i*<=≤<=10,<=1<=≤<=*h**i*<=≤<=1000) — the width and height in pixels of the correspo... | Print *n* space-separated numbers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* — the total number of pixels on the minimum photo containing all friends expect for the *i*-th one. | [
"3\n1 10\n5 5\n10 1\n",
"3\n2 1\n1 2\n2 1\n"
] | [
"75 110 60 ",
"6 4 6 "
] | none | 1,000 | [
{
"input": "3\n1 10\n5 5\n10 1",
"output": "75 110 60 "
},
{
"input": "3\n2 1\n1 2\n2 1",
"output": "6 4 6 "
},
{
"input": "2\n1 5\n2 3",
"output": "6 5 "
},
{
"input": "2\n2 3\n1 1",
"output": "1 6 "
},
{
"input": "3\n1 10\n2 10\n3 10",
"output": "50 40 30 "
... | 1,626,110,889 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 795 | 19,763,200 | n=int(input());
a=[];b=[];
for i in range(n):
k=list(map(int,input().split()));
a.append(k[0]);
b.append(k[1]);
M=max(b);
m=b.index(M);
MM=0;
for i in range(n):
if(i!=m and b[i]>MM):MM=b[i];
k=sum(a);
c=[];
for i in range(n):
if(i==m):c.append((k-a[i])*MM);
else:c.append((k-a[i])*M);
print(*c);
... | Title: Photo to Remember
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together.
Simply speaking, the process of taking photos can be described as follows. On the p... | ```python
n=int(input());
a=[];b=[];
for i in range(n):
k=list(map(int,input().split()));
a.append(k[0]);
b.append(k[1]);
M=max(b);
m=b.index(M);
MM=0;
for i in range(n):
if(i!=m and b[i]>MM):MM=b[i];
k=sum(a);
c=[];
for i in range(n):
if(i==m):c.append((k-a[i])*MM);
else:c.append((k-a[i])*M);
pri... | 3 | |
928 | C | Dependency management | PROGRAMMING | 1,900 | [
"*special",
"graphs",
"implementation"
] | null | null | Polycarp is currently developing a project in Vaja language and using a popular dependency management system called Vamen. From Vamen's point of view both Vaja project and libraries are treated projects for simplicity.
A project in Vaja has its own uniqie non-empty name consisting of lowercase latin letters with lengt... | The first line contains an only integer *n* (1<=≤<=*n*<=≤<=1<=000) — the number of projects in Vaja.
The following lines contain the project descriptions. Each project is described by a line consisting of its name and version separated by space. The next line gives the number of direct dependencies (from 0 to *n*<=-<=... | Output all Polycarp's project's dependencies in lexicographical order. | [
"4\na 3\n2\nb 1\nc 1\n \nb 2\n0\n \nb 1\n1\nb 2\n \nc 1\n1\nb 2\n",
"9\ncodehorses 5\n3\nwebfrmk 6\nmashadb 1\nmashadb 2\n \ncommons 2\n0\n \nmashadb 3\n0\n \nwebfrmk 6\n2\nmashadb 3\ncommons 2\n \nextra 4\n1\nextra 3\n \nextra 3\n0\n \nextra 1\n0\n \nmashadb 1\n1\nextra 3\n \nmashadb 2\n1\nextra 1\n",
"3\nabc ... | [
"2\nb 1\nc 1\n",
"4\ncommons 2\nextra 1\nmashadb 2\nwebfrmk 6\n",
"1\ncba 2\n"
] | The first sample is given in the pic below. Arrow from *A* to *B* means that *B* directly depends on *A*. Projects that Polycarp's project «a» (version 3) depends on are painted black.
The second sample is again given in the pic below. Arrow from *A* to *B* means that *B* directly depends on *A*. Projects that Polycar... | 2,000 | [
{
"input": "4\na 3\n2\nb 1\nc 1\n\nb 2\n0\n\nb 1\n1\nb 2\n\nc 1\n1\nb 2",
"output": "2\nb 1\nc 1"
},
{
"input": "9\ncodehorses 5\n3\nwebfrmk 6\nmashadb 1\nmashadb 2\n\ncommons 2\n0\n\nmashadb 3\n0\n\nwebfrmk 6\n2\nmashadb 3\ncommons 2\n\nextra 4\n1\nextra 3\n\nextra 3\n0\n\nextra 1\n0\n\nmashadb 1\n... | 1,519,588,713 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 1,247 | 56,934,400 | def bfs(polycarp, all_projects, existed_projects):
# print(polycarp)
# print(all_projects)
# print(existed_projects)
queue0 = {polycarp[0]: polycarp[1]}
queue1 = {}
while queue0:
for p in queue0.items():
existed_projects[p[0]] = p[1]
for pp in queue0.it... | Title: Dependency management
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is currently developing a project in Vaja language and using a popular dependency management system called Vamen. From Vamen's point of view both Vaja project and libraries are treated projects for simpli... | ```python
def bfs(polycarp, all_projects, existed_projects):
# print(polycarp)
# print(all_projects)
# print(existed_projects)
queue0 = {polycarp[0]: polycarp[1]}
queue1 = {}
while queue0:
for p in queue0.items():
existed_projects[p[0]] = p[1]
for pp in... | 3 | |
543 | B | Destroying Roads | PROGRAMMING | 2,100 | [
"constructive algorithms",
"graphs",
"shortest paths"
] | null | null | In some country there are exactly *n* cities and *m* bidirectional roads connecting the cities. Cities are numbered with integers from 1 to *n*. If cities *a* and *b* are connected by a road, then in an hour you can go along this road either from city *a* to city *b*, or from city *b* to city *a*. The road network is s... | The first line contains two integers *n*, *m* (1<=≤<=*n*<=≤<=3000, ) — the number of cities and roads in the country, respectively.
Next *m* lines contain the descriptions of the roads as pairs of integers *a**i*, *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*). It is guaranteed that the roads that are give... | Print a single number — the answer to the problem. If the it is impossible to meet the conditions, print -1. | [
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 2\n",
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n2 4 2\n",
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 1\n"
] | [
"0\n",
"1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 2",
"output": "0"
},
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n2 4 2",
"output": "1"
},
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 1",
"output": "-1"
},
{
"input": "9 9\n1 2\n2 3\n2 4\n4 5\n5 7\n5 6\n3 8\n8 9\n9 6\n1 7 4\... | 1,665,074,435 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 63 | 1,731 | 91,955,200 | from collections import deque
n,m=map(int,input().split())
graph=[[] for _ in range(n)]
for i in range(m):
a,b=map(int,input().split())
a-=1
b-=1
graph[a].append(b)
graph[b].append(a)
d=[[-1]*n for _ in range(n)]
for i in range(n):
q=deque()
q.append(i)
d[i][i]=0
wh... | Title: Destroying Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some country there are exactly *n* cities and *m* bidirectional roads connecting the cities. Cities are numbered with integers from 1 to *n*. If cities *a* and *b* are connected by a road, then in an hour you can go... | ```python
from collections import deque
n,m=map(int,input().split())
graph=[[] for _ in range(n)]
for i in range(m):
a,b=map(int,input().split())
a-=1
b-=1
graph[a].append(b)
graph[b].append(a)
d=[[-1]*n for _ in range(n)]
for i in range(n):
q=deque()
q.append(i)
d[i][i]... | 3 | |
148 | A | Insomnia cure | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | «One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and ... | Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105). | Output the number of damaged dragons. | [
"1\n2\n3\n4\n12\n",
"2\n3\n4\n5\n24\n"
] | [
"12\n",
"17\n"
] | In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | 1,000 | [
{
"input": "1\n2\n3\n4\n12",
"output": "12"
},
{
"input": "2\n3\n4\n5\n24",
"output": "17"
},
{
"input": "1\n1\n1\n1\n100000",
"output": "100000"
},
{
"input": "10\n9\n8\n7\n6",
"output": "0"
},
{
"input": "8\n4\n4\n3\n65437",
"output": "32718"
},
{
"i... | 1,691,280,748 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 186 | 2,969,600 | import sys
*A,d = map(int,sys.stdin.read().split())
print(sum(any((i%p==0) for p in A) for i in range(1,d+1)))
| Title: Insomnia cure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entert... | ```python
import sys
*A,d = map(int,sys.stdin.read().split())
print(sum(any((i%p==0) for p in A) for i in range(1,d+1)))
``` | 3 | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,622,114,598 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 124 | 0 | import math
a,b,n=input().split()
a=int(a)
b=int(b)
n=int(n)
i=1
while(n>0):
m=0
if i%2!=0:
m=math.gcd(a,n)
n=n-m
elif i%2==0:
m=math.gcd(b,n)
n=n-m
i+=1
if i%2==0:
print(0)
else:
print(1)
| Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
import math
a,b,n=input().split()
a=int(a)
b=int(b)
n=int(n)
i=1
while(n>0):
m=0
if i%2!=0:
m=math.gcd(a,n)
n=n-m
elif i%2==0:
m=math.gcd(b,n)
n=n-m
i+=1
if i%2==0:
print(0)
else:
print(1)
``` | 3 | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,659,523,890 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 45 | 122 | 0 | import math
x = (input().split())
a = int(x[0])
b = int(x[1])
c = int(x[2])
for i in range(100000000):
if i%2==0:
c-=math.gcd(c,a)
else:
c-=math.gcd(c,b)
if c==0:
print(i%2)
break | Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
import math
x = (input().split())
a = int(x[0])
b = int(x[1])
c = int(x[2])
for i in range(100000000):
if i%2==0:
c-=math.gcd(c,a)
else:
c-=math.gcd(c,b)
if c==0:
print(i%2)
break
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,676,770,823 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | cadena=input()
contador=0
n=len(cadena)
for i in cadena:
if ord(i)<97:
contador+=1
j=n/2
if (contador>j):
print(cadena.upper())
elif (contador<j):
print(cadena.lower())
else:
print(cadena.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
cadena=input()
contador=0
n=len(cadena)
for i in cadena:
if ord(i)<97:
contador+=1
j=n/2
if (contador>j):
print(cadena.upper())
elif (contador<j):
print(cadena.lower())
else:
print(cadena.lower())
``` | 3.977 |
801 | A | Vicious Keyboard | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter in the string (or do no changes) to maximize the number of occurrences of that string. Compute the maxi... | The first line will contain a string *s* consisting only of uppercase English letters "V" and "K" with length not less than 1 and not greater than 100. | Output a single integer, the maximum number of times "VK" can appear as a substring of the given string after changing at most one character. | [
"VK\n",
"VV\n",
"V\n",
"VKKKKKKKKKVVVVVVVVVK\n",
"KVKV\n"
] | [
"1\n",
"1\n",
"0\n",
"3\n",
"1\n"
] | For the first case, we do not change any letters. "VK" appears once, which is the maximum number of times it could appear.
For the second case, we can change the second character from a "V" to a "K". This will give us the string "VK". This has one occurrence of the string "VK" as a substring.
For the fourth case, we ... | 500 | [
{
"input": "VK",
"output": "1"
},
{
"input": "VV",
"output": "1"
},
{
"input": "V",
"output": "0"
},
{
"input": "VKKKKKKKKKVVVVVVVVVK",
"output": "3"
},
{
"input": "KVKV",
"output": "1"
},
{
"input": "VKKVVVKVKVK",
"output": "5"
},
{
"input... | 1,492,357,542 | 642 | Python 3 | OK | TESTS | 63 | 62 | 5,529,600 | #l=[int(i)for i in input().split()]
s=input()
i=0
a=s.find("VK")
ans=0
while a!=-1:
ans+=1
s=s[:a]+"."+s[a+2:]
a=s.find("VK")
if s.count("VV")>0 or s.count("KK")>0:ans+=1
print(ans) | Title: Vicious Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter i... | ```python
#l=[int(i)for i in input().split()]
s=input()
i=0
a=s.find("VK")
ans=0
while a!=-1:
ans+=1
s=s[:a]+"."+s[a+2:]
a=s.find("VK")
if s.count("VV")>0 or s.count("KK")>0:ans+=1
print(ans)
``` | 3 | |
791 | A | Bear and Big Brother | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's we... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively. | Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob. | [
"4 7\n",
"4 9\n",
"1 1\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Li... | 500 | [
{
"input": "4 7",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output... | 1,693,757,144 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 46 | 0 | x,y=map(int,input().split())
c=0
while x<=y:
c=c+1
x*=3
y*=2
print(c)
| Title: Bear and Big Brother
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or e... | ```python
x,y=map(int,input().split())
c=0
while x<=y:
c=c+1
x*=3
y*=2
print(c)
``` | 3 | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,694,426,516 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | n = int(input())
ct = 0
while(n>0):
if n >= 100:
ct += n//100
n = n%100
elif n >= 20:
ct += n//20
n = n%20
elif n >= 10:
ct += n//10
n = n%10
elif n >= 5:
ct += n//5
n = n%5
else:
ct += n
n = 0
print(ct... | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
n = int(input())
ct = 0
while(n>0):
if n >= 100:
ct += n//100
n = n%100
elif n >= 20:
ct += n//20
n = n%20
elif n >= 10:
ct += n//10
n = n%10
elif n >= 5:
ct += n//5
n = n%5
else:
ct += n
n = 0... | 3 | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,694,275,547 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 62 | 4,915,200 | num = input()
results = input()
winners = list(results)
if winners.count("A") > winners.count("D"):
print("Anton")
elif winners.count("A") < winners.count("D"):
print("Danik")
else:
print("Friendship") | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
num = input()
results = input()
winners = list(results)
if winners.count("A") > winners.count("D"):
print("Anton")
elif winners.count("A") < winners.count("D"):
print("Danik")
else:
print("Friendship")
``` | 3 | |
469 | A | I Wanna Be the Guy | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There is a game called "I Wanna Be the Guy", consisting of *n* levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only *p* levels of the game. And Little Y can pass only *q* levels of the game. You are given the indices of levels Little X can... | The first line contains a single integer *n* (1<=≤<=<=*n*<=≤<=100).
The next line contains an integer *p* (0<=≤<=*p*<=≤<=*n*) at first, then follows *p* distinct integers *a*1,<=*a*2,<=...,<=*a**p* (1<=≤<=*a**i*<=≤<=*n*). These integers denote the indices of levels Little X can pass. The next line contains the levels... | If they can pass all the levels, print "I become the guy.". If it's impossible, print "Oh, my keyboard!" (without the quotes). | [
"4\n3 1 2 3\n2 2 4\n",
"4\n3 1 2 3\n2 2 3\n"
] | [
"I become the guy.\n",
"Oh, my keyboard!\n"
] | In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.
In the second sample, no one can pass level 4. | 500 | [
{
"input": "4\n3 1 2 3\n2 2 4",
"output": "I become the guy."
},
{
"input": "4\n3 1 2 3\n2 2 3",
"output": "Oh, my keyboard!"
},
{
"input": "10\n5 8 6 1 5 4\n6 1 3 2 9 4 6",
"output": "Oh, my keyboard!"
},
{
"input": "10\n8 8 10 7 3 1 4 2 6\n8 9 5 10 3 7 2 4 8",
"output":... | 1,695,950,118 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 62 | 0 | uniq = []
num = int(input())
litx = list(input().split(" "))
lity = list(input().split(" "))
del litx[0]
del lity[0]
for x in litx:
if x not in uniq:
uniq.append(x)
for y in lity:
if y not in uniq:
uniq.append(y)
if len(uniq) == num:
print("I become the guy.")
else:
print("Oh, my keyboard... | Title: I Wanna Be the Guy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a game called "I Wanna Be the Guy", consisting of *n* levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only *p* levels of the g... | ```python
uniq = []
num = int(input())
litx = list(input().split(" "))
lity = list(input().split(" "))
del litx[0]
del lity[0]
for x in litx:
if x not in uniq:
uniq.append(x)
for y in lity:
if y not in uniq:
uniq.append(y)
if len(uniq) == num:
print("I become the guy.")
else:
print("Oh, m... | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,561,377,275 | 2,147,483,647 | PyPy 3 | OK | TESTS | 81 | 248 | 0 | a=0
b=0
c=0
n=int(input())
for x in range (n):
x,y,z=map(int,input().split())
a=a+x
b=b+y
c=c+z
if a==b==c==0:
print("YES")
else:
print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
a=0
b=0
c=0
n=int(input())
for x in range (n):
x,y,z=map(int,input().split())
a=a+x
b=b+y
c=c+z
if a==b==c==0:
print("YES")
else:
print("NO")
``` | 3.938 |
965 | C | Greedy Arkady | PROGRAMMING | 2,000 | [
"math"
] | null | null | $k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.
The people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arkady will choose an integer $x$ and then give the first $x$ candies to himself, the next $x$ candies ... | The only line contains four integers $n$, $k$, $M$ and $D$ ($2 \le n \le 10^{18}$, $2 \le k \le n$, $1 \le M \le n$, $1 \le D \le \min{(n, 1000)}$, $M \cdot D \cdot k \ge n$) — the number of candies, the number of people, the maximum number of candies given to a person at once, the maximum number of times a person can ... | Print a single integer — the maximum possible number of candies Arkady can give to himself.
Note that it is always possible to choose some valid $x$. | [
"20 4 5 2\n",
"30 9 4 1\n"
] | [
"8\n",
"4\n"
] | In the first example Arkady should choose $x = 4$. He will give $4$ candies to himself, $4$ candies to the second person, $4$ candies to the third person, then $4$ candies to the fourth person and then again $4$ candies to himself. No person is given candies more than $2$ times, and Arkady receives $8$ candies in total... | 1,500 | [
{
"input": "20 4 5 2",
"output": "8"
},
{
"input": "30 9 4 1",
"output": "4"
},
{
"input": "2 2 1 1",
"output": "1"
},
{
"input": "42 20 5 29",
"output": "5"
},
{
"input": "1000000000000000000 135 1000000000000000 1000",
"output": "8325624421831635"
},
{
... | 1,530,231,318 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 124 | 0 | n,k,m,d=map(int,input().split())
ans=0
for i in range(1,d+1):
s=1
e=m
while s<e:
mid=(s+e+1)//2
if mid*(k*(i-1)+1)<=n:
s=mid
else:
e=mid-1
if s*(k*(i-1)+1)<=n:
ans=max(ans,i*s)
"""print("%d %d %d ",ans,i,s)"""
print(ans)
| Title: Greedy Arkady
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
$k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.
The people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arka... | ```python
n,k,m,d=map(int,input().split())
ans=0
for i in range(1,d+1):
s=1
e=m
while s<e:
mid=(s+e+1)//2
if mid*(k*(i-1)+1)<=n:
s=mid
else:
e=mid-1
if s*(k*(i-1)+1)<=n:
ans=max(ans,i*s)
"""print("%d %d %d ",ans,i,s)"""
print(ans)
``` | 3 | |
527 | A | Playing with Paper | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | One day Vasya was sitting on a not so interesting Maths lesson and making an origami from a rectangular *a* mm <=×<= *b* mm sheet of paper (*a*<=><=*b*). Usually the first step in making an origami is making a square piece of paper from the rectangular sheet by folding the sheet along the bisector of the right angle... | The first line of the input contains two integers *a*, *b* (1<=≤<=*b*<=<<=*a*<=≤<=1012) — the sizes of the original sheet of paper. | Print a single integer — the number of ships that Vasya will make. | [
"2 1\n",
"10 7\n",
"1000000000000 1\n"
] | [
"2\n",
"6\n",
"1000000000000\n"
] | Pictures to the first and second sample test. | 500 | [
{
"input": "2 1",
"output": "2"
},
{
"input": "10 7",
"output": "6"
},
{
"input": "1000000000000 1",
"output": "1000000000000"
},
{
"input": "3 1",
"output": "3"
},
{
"input": "4 1",
"output": "4"
},
{
"input": "3 2",
"output": "3"
},
{
"in... | 1,511,514,508 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 93 | 6,041,600 | # -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
import itertools
import sys
"""
created by shhuan at 2017/11/24 17:02
"""
# a, b
# a-b, b
# ... => b, a-kb
#
def cal(a, b):
if a < b:
return cal(b, a)
if a == b:
... | Title: Playing with Paper
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya was sitting on a not so interesting Maths lesson and making an origami from a rectangular *a* mm <=×<= *b* mm sheet of paper (*a*<=><=*b*). Usually the first step in making an origami is making a squ... | ```python
# -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
import itertools
import sys
"""
created by shhuan at 2017/11/24 17:02
"""
# a, b
# a-b, b
# ... => b, a-kb
#
def cal(a, b):
if a < b:
return cal(b, a)
if a... | 3 | |
918 | A | Eleven | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the ... | The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000). | Print Eleven's new name on the first and only line of output. | [
"8\n",
"15\n"
] | [
"OOOoOooO\n",
"OOOoOooOooooOoo\n"
] | none | 500 | [
{
"input": "8",
"output": "OOOoOooO"
},
{
"input": "15",
"output": "OOOoOooOooooOoo"
},
{
"input": "85",
"output": "OOOoOooOooooOoooooooOooooooooooooOooooooooooooooooooooOoooooooooooooooooooooooooooooo"
},
{
"input": "381",
"output": "OOOoOooOooooOoooooooOooooooooooooOooo... | 1,617,009,995 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 77 | 307,200 | n=int(input())
f1=0
f2=1
count=0
l=[]
if n==1:
l.append(n)
else:
l.append(f1)
while count<n:
f=f1+f2
l.append(f)
f1=f2
f2=f
count+=1
# print(l)
for i in range(1,n+1):
if i in l:
print('O',end="")
else:
print('o',end=""... | Title: Eleven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should o... | ```python
n=int(input())
f1=0
f2=1
count=0
l=[]
if n==1:
l.append(n)
else:
l.append(f1)
while count<n:
f=f1+f2
l.append(f)
f1=f2
f2=f
count+=1
# print(l)
for i in range(1,n+1):
if i in l:
print('O',end="")
else:
print(... | 3 | |
991 | B | Getting an A | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Translator's note: in Russia's most widespread grading system, there are four grades: 5, 4, 3, 2, the higher the better, roughly corresponding to A, B, C and F respectively in American grading system.
The term is coming to an end and students start thinking about their grades. Today, a professor told his students that... | The first line contains a single integer $n$ — the number of Vasya's grades ($1 \leq n \leq 100$).
The second line contains $n$ integers from $2$ to $5$ — Vasya's grades for his lab works. | Output a single integer — the minimum amount of lab works that Vasya has to redo. It can be shown that Vasya can always redo enough lab works to get a $5$. | [
"3\n4 4 4\n",
"4\n5 4 5 5\n",
"4\n5 3 3 5\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first sample, it is enough to redo two lab works to make two $4$s into $5$s.
In the second sample, Vasya's average is already $4.75$ so he doesn't have to redo anything to get a $5$.
In the second sample Vasya has to redo one lab work to get rid of one of the $3$s, that will make the average exactly $4.5$ so t... | 1,000 | [
{
"input": "3\n4 4 4",
"output": "2"
},
{
"input": "4\n5 4 5 5",
"output": "0"
},
{
"input": "4\n5 3 3 5",
"output": "1"
},
{
"input": "1\n5",
"output": "0"
},
{
"input": "4\n3 2 5 4",
"output": "2"
},
{
"input": "5\n5 4 3 2 5",
"output": "2"
},
... | 1,611,608,277 | 777 | PyPy 3 | OK | TESTS | 61 | 109 | 1,331,200 | def crb(a):
return sum(a)/len(a)
n=int(input())
a=list(map(int,input().split()))
a.sort()
i=0
ans=0
if crb(a)>=4.5:
print(0)
else:
while crb(a)<4.5:
a[i]=5
i +=1
ans +=1
print(ans) | Title: Getting an A
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Translator's note: in Russia's most widespread grading system, there are four grades: 5, 4, 3, 2, the higher the better, roughly corresponding to A, B, C and F respectively in American grading system.
The term is coming t... | ```python
def crb(a):
return sum(a)/len(a)
n=int(input())
a=list(map(int,input().split()))
a.sort()
i=0
ans=0
if crb(a)>=4.5:
print(0)
else:
while crb(a)<4.5:
a[i]=5
i +=1
ans +=1
print(ans)
``` | 3 | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,688,604,953 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | n, girls_pack = input().split()
n = int(n)
girls_pack = int(girls_pack)
nbr_depressed = 0
counter = girls_pack
my_list = []
for i in range(n):
packs = input()
my_list.append(packs)
for j in range(len(my_list)):
sign, packs = my_list[j].split()
packs = int(packs)
if sign == "+":
... | Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
n, girls_pack = input().split()
n = int(n)
girls_pack = int(girls_pack)
nbr_depressed = 0
counter = girls_pack
my_list = []
for i in range(n):
packs = input()
my_list.append(packs)
for j in range(len(my_list)):
sign, packs = my_list[j].split()
packs = int(packs)
if sign =... | 3 | |
63 | A | Sinking Ship | PROGRAMMING | 900 | [
"implementation",
"sortings",
"strings"
] | A. Sinking Ship | 2 | 256 | The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to *n*) and await further instructions. However, one should evacuate the crew properly, in a stri... | The first line contains an integer *n*, which is the number of people in the crew (1<=≤<=*n*<=≤<=100). Then follow *n* lines. The *i*-th of those lines contains two words — the name of the crew member who is *i*-th in line, and his status on the ship. The words are separated by exactly one space. There are no other spa... | Print *n* lines. The *i*-th of them should contain the name of the crew member who must be the *i*-th one to leave the ship. | [
"6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman\n"
] | [
"Teddy\nAlice\nBob\nJulia\nCharlie\nJack\n"
] | none | 500 | [
{
"input": "6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman",
"output": "Teddy\nAlice\nBob\nJulia\nCharlie\nJack"
},
{
"input": "1\nA captain",
"output": "A"
},
{
"input": "1\nAbcdefjhij captain",
"output": "Abcdefjhij"
},
{
"input": "5\nA captain... | 1,619,062,242 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 124 | 0 | n=int(input())
l=[]
for i in range(n):
l.append(input().split())
for i,j in l:
if j=='rat':
print(i)
for i,j in l:
if j=='woman':
print(i)
if j=='child':
print(i)
for i,j in l:
if j=='man':
print(i)
for i,j in l:
if j=='captain':
print(i) | Title: Sinking Ship
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to ... | ```python
n=int(input())
l=[]
for i in range(n):
l.append(input().split())
for i,j in l:
if j=='rat':
print(i)
for i,j in l:
if j=='woman':
print(i)
if j=='child':
print(i)
for i,j in l:
if j=='man':
print(i)
for i,j in l:
if j=='captain':
print(i)
``` | 3.969 |
712 | B | Memory and Trident | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he should move one unit right. - A 'U' indicates he should move one unit up. - A 'D' indicates he should move... | The first and only line contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) — the instructions Memory is given. | If there is a string satisfying the conditions, output a single integer — the minimum number of edits required. In case it's not possible to change the sequence in such a way that it will bring Memory to to the origin, output -1. | [
"RRU\n",
"UDUR\n",
"RUUR\n"
] | [
"-1\n",
"1\n",
"2\n"
] | In the first sample test, Memory is told to walk right, then right, then up. It is easy to see that it is impossible to edit these instructions to form a valid walk.
In the second sample test, Memory is told to walk up, then down, then up, then right. One possible solution is to change *s* to "LDUR". This string uses ... | 1,000 | [
{
"input": "RRU",
"output": "-1"
},
{
"input": "UDUR",
"output": "1"
},
{
"input": "RUUR",
"output": "2"
},
{
"input": "DDDD",
"output": "2"
},
{
"input": "RRRR",
"output": "2"
},
{
"input": "RRRUUD",
"output": "2"
},
{
"input": "UDURLRDURL... | 1,518,955,951 | 2,147,483,647 | Python 3 | OK | TESTS | 75 | 62 | 5,836,800 | s = input()
u,d,l,r = [s.count(x) for x in 'UDLR']
ud = abs(u-d)
lr = abs(l-r)
if len(s)%2:
print (-1)
else:
print (ud//2 + lr//2 + ud%2) | Title: Memory and Trident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he shou... | ```python
s = input()
u,d,l,r = [s.count(x) for x in 'UDLR']
ud = abs(u-d)
lr = abs(l-r)
if len(s)%2:
print (-1)
else:
print (ud//2 + lr//2 + ud%2)
``` | 3 | |
991 | D | Bishwock | PROGRAMMING | 1,500 | [
"dp",
"greedy"
] | null | null | Bishwock is a chess figure that consists of three squares resembling an "L-bar". This figure can be rotated by 90, 180 and 270 degrees so it can have four possible states:
Bishwocks don't attack any squares and can even occupy on the adjacent squares as long as they don't occupy the same square.
Vasya has a board wi... | The input contains two nonempty strings that describe Vasya's board. Those strings contain only symbols "0" (zero) that denote the empty squares and symbols "X" (uppercase English letter) that denote the squares occupied by pawns. Strings are nonempty and are of the same length that does not exceed $100$. | Output a single integer — the maximum amount of bishwocks that can be placed onto the given board. | [
"00\n00\n",
"00X00X0XXX0\n0XXX0X00X00\n",
"0X0X0\n0X0X0\n",
"0XXX0\n00000\n"
] | [
"1",
"4",
"0",
"2"
] | none | 1,500 | [
{
"input": "00\n00",
"output": "1"
},
{
"input": "00X00X0XXX0\n0XXX0X00X00",
"output": "4"
},
{
"input": "0X0X0\n0X0X0",
"output": "0"
},
{
"input": "0XXX0\n00000",
"output": "2"
},
{
"input": "0\n0",
"output": "0"
},
{
"input": "0\nX",
"output": "... | 1,689,043,217 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 72 | 62 | 0 | A = input()
B = input()
res = 0
p0,p1=1,1
for a,b in zip(A,B):
a, b = a=='X',b=='X'
w = a+b+p0+p1
if w<=1:
res += 1
p0,p1 = 1,w
else:
p0,p1 = a,b
print(res) | Title: Bishwock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bishwock is a chess figure that consists of three squares resembling an "L-bar". This figure can be rotated by 90, 180 and 270 degrees so it can have four possible states:
Bishwocks don't attack any squares and can even occup... | ```python
A = input()
B = input()
res = 0
p0,p1=1,1
for a,b in zip(A,B):
a, b = a=='X',b=='X'
w = a+b+p0+p1
if w<=1:
res += 1
p0,p1 = 1,w
else:
p0,p1 = a,b
print(res)
``` | 3 | |
468 | C | Hack it! | PROGRAMMING | 2,500 | [
"binary search",
"constructive algorithms",
"math"
] | null | null | Little X has met the following problem recently.
Let's define *f*(*x*) as the sum of digits in decimal representation of number *x* (for example, *f*(1234)<==<=1<=+<=2<=+<=3<=+<=4). You are to calculate
Of course Little X has solved this problem quickly, has locked it, and then has tried to hack others. He has seen... | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1018). | Print two integers: *l*,<=*r* (1<=≤<=*l*<=≤<=*r*<=<<=10200) — the required test data. Leading zeros aren't allowed. It's guaranteed that the solution exists. | [
"46\n",
"126444381000032\n"
] | [
"1 10\n",
"2333333 2333333333333\n"
] | none | 1,500 | [
{
"input": "46",
"output": "1 10"
},
{
"input": "126444381000032",
"output": "2333333 2333333333333"
},
{
"input": "69645082595",
"output": "613752823618441225798858488535 713259406474207764329704856394"
},
{
"input": "70602205995",
"output": "11 2492213340204320744986569... | 1,606,406,545 | 1,945 | PyPy 3 | OK | TESTS | 51 | 140 | 0 | A = int(input())
l = 1
r = 10**100
cnt = 10**99*100*45 + 1
cnt = -cnt % A
l += cnt
r += cnt
print(l, r) | Title: Hack it!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little X has met the following problem recently.
Let's define *f*(*x*) as the sum of digits in decimal representation of number *x* (for example, *f*(1234)<==<=1<=+<=2<=+<=3<=+<=4). You are to calculate
Of course Little X ... | ```python
A = int(input())
l = 1
r = 10**100
cnt = 10**99*100*45 + 1
cnt = -cnt % A
l += cnt
r += cnt
print(l, r)
``` | 3 | |
651 | A | Joysticks | PROGRAMMING | 1,100 | [
"dp",
"greedy",
"implementation",
"math"
] | null | null | Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if n... | The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively. | Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged. | [
"3 5\n",
"4 4\n"
] | [
"6\n",
"5\n"
] | In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joyst... | 500 | [
{
"input": "3 5",
"output": "6"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 100",
"output": "197"
},
{
"input": "1 100",
"output": "98"
},
{
"input": "100 1",
"output": "98"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "1 1",
... | 1,658,801,454 | 2,147,483,647 | PyPy 3 | OK | TESTS | 39 | 93 | 0 | def solve(p,q):
ans=0
while p>0 and q>0:
ans+=1
if p>q:
p,q=q,p
p+=1
q-=2
if p<0 or q<0:
ans-=1
break
return ans
p,q=map(int,input().split())
print(solve(p,q))
| Title: Joysticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick on... | ```python
def solve(p,q):
ans=0
while p>0 and q>0:
ans+=1
if p>q:
p,q=q,p
p+=1
q-=2
if p<0 or q<0:
ans-=1
break
return ans
p,q=map(int,input().split())
print(solve(p,q))
``` | 3 | |
40 | A | Find Color | PROGRAMMING | 1,300 | [
"constructive algorithms",
"geometry",
"implementation",
"math"
] | A. Find Color | 2 | 256 | Not so long ago as a result of combat operations the main Berland place of interest — the magic clock — was damaged. The cannon's balls made several holes in the clock, that's why the residents are concerned about the repair. The magic clock can be represented as an infinite Cartesian plane, where the origin correspond... | The first and single line contains two integers *x* and *y* — the coordinates of the hole made in the clock by the ball. Each of the numbers *x* and *y* has an absolute value that does not exceed 1000. | Find the required color.
All the points between which and the origin of coordinates the distance is integral-value are painted black. | [
"-2 1\n",
"2 1\n",
"4 3\n"
] | [
"white\n",
"black\n",
"black\n"
] | none | 500 | [
{
"input": "-2 1",
"output": "white"
},
{
"input": "2 1",
"output": "black"
},
{
"input": "4 3",
"output": "black"
},
{
"input": "3 3",
"output": "black"
},
{
"input": "4 4",
"output": "white"
},
{
"input": "-4 4",
"output": "black"
},
{
"i... | 1,597,499,367 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 218 | 0 | # from decimal import *
# getcontext().prec=16
# from math import sqrt
# from scipy.special import binom
# from collections import defaultdict
from math import sin,pi,sqrt
x,y=list(map(int,input().split(" ")))
if sqrt(x**2+y**2)%1==0:
color=1
else:
if x*y>=0:
color=1
else:
c... | Title: Find Color
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Not so long ago as a result of combat operations the main Berland place of interest — the magic clock — was damaged. The cannon's balls made several holes in the clock, that's why the residents are concerned about the repair. Th... | ```python
# from decimal import *
# getcontext().prec=16
# from math import sqrt
# from scipy.special import binom
# from collections import defaultdict
from math import sin,pi,sqrt
x,y=list(map(int,input().split(" ")))
if sqrt(x**2+y**2)%1==0:
color=1
else:
if x*y>=0:
color=1
else:
... | 3.9455 |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,692,986,760 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | def main():
s=input()
i=0;ans=''
while i<=len(s)-1:
if s[i]=='-' and s[i+1]=='-': ans+='2';i+=2;
elif s[i]=='-' and s[i+1]=='.': ans+='1';i+=2;
else: ans+='0'; i+=1
return ans
print(main()) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
def main():
s=input()
i=0;ans=''
while i<=len(s)-1:
if s[i]=='-' and s[i+1]=='-': ans+='2';i+=2;
elif s[i]=='-' and s[i+1]=='.': ans+='1';i+=2;
else: ans+='0'; i+=1
return ans
print(main())
``` | 3.977 |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,696,421,419 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 20 | 62 | 0 | loops = int(input())
for i in range(loops):
str = input()
ln = len(str)
if ln > 10:
print('{}{}{}'.format(str[0], len(str[1:ln-1]), str[ln-1]))
else:
print(str) | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
loops = int(input())
for i in range(loops):
str = input()
ln = len(str)
if ln > 10:
print('{}{}{}'.format(str[0], len(str[1:ln-1]), str[ln-1]))
else:
print(str)
``` | 3.969 |
378 | A | Playing with Dice | PROGRAMMING | 800 | [
"brute force"
] | null | null | Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many w... | The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly. | Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly. | [
"2 5\n",
"2 4\n"
] | [
"3 0 3\n",
"2 1 3\n"
] | The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | 500 | [
{
"input": "2 5",
"output": "3 0 3"
},
{
"input": "2 4",
"output": "2 1 3"
},
{
"input": "5 3",
"output": "2 1 3"
},
{
"input": "1 6",
"output": "3 0 3"
},
{
"input": "5 1",
"output": "3 1 2"
},
{
"input": "6 3",
"output": "2 0 4"
},
{
"inp... | 1,622,820,401 | 2,147,483,647 | PyPy 3 | OK | TESTS | 38 | 202 | 0 | a,b=map(int,input().split())
c1=c2=c3=0
for i in range(1,7):
if abs(a-i)<abs(i-b):
c1+=1
elif abs(a-i)==abs(b-i):
c2+=1
else:
c3+=1
print(c1,c2,c3) | Title: Playing with Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same diff... | ```python
a,b=map(int,input().split())
c1=c2=c3=0
for i in range(1,7):
if abs(a-i)<abs(i-b):
c1+=1
elif abs(a-i)==abs(b-i):
c2+=1
else:
c3+=1
print(c1,c2,c3)
``` | 3 | |
303 | A | Lucky Permutation Triple | PROGRAMMING | 1,300 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=2,<=2] and [1,<=2,<=3] is not.
A permutation triple of permutations of length *n* (*a*,<=... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | If no Lucky Permutation Triple of length *n* exists print -1.
Otherwise, you need to print three lines. Each line contains *n* space-seperated integers. The first line must contain permutation *a*, the second line — permutation *b*, the third — permutation *c*.
If there are multiple solutions, print any of them. | [
"5\n",
"2\n"
] | [
"1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3\n",
"-1\n"
] | In Sample 1, the permutation triple ([1, 4, 3, 2, 0], [1, 0, 2, 4, 3], [2, 4, 0, 1, 3]) is Lucky Permutation Triple, as following holds:
- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a6bf1b9b57809dbec5021f65f89616f259587c07.png" style="max-width: 100.0%;max-height: 100.0%;"/>; - <img... | 500 | [
{
"input": "5",
"output": "1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3"
},
{
"input": "2",
"output": "-1"
},
{
"input": "8",
"output": "-1"
},
{
"input": "9",
"output": "0 1 2 3 4 5 6 7 8 \n0 1 2 3 4 5 6 7 8 \n0 2 4 6 8 1 3 5 7 "
},
{
"input": "2",
"output": "-1"
},
{... | 1,619,279,320 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 934 | 0 | n = int(input())
if n%2:
j = 2
while j:
for i in range(n):
print(i,end=' ')
j -= 1
print('')
for i in range(n):
print((2*i)%n,end=' ')
else:
print(-1)
| Title: Lucky Permutation Triple
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of lengt... | ```python
n = int(input())
if n%2:
j = 2
while j:
for i in range(n):
print(i,end=' ')
j -= 1
print('')
for i in range(n):
print((2*i)%n,end=' ')
else:
print(-1)
``` | 3 | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,668,520,672 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 998 | 16,896,000 | n, m = map(int, input().split())
array = list(map(int, input().split()))
test = set()
dp = []
out = 0
for a_j in reversed(array):
if a_j not in test:
test.add(a_j)
out += 1
dp.append(out)
for i in range(m):
rev_index = len(array) - int(input())
print(dp[rev_index]) | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
n, m = map(int, input().split())
array = list(map(int, input().split()))
test = set()
dp = []
out = 0
for a_j in reversed(array):
if a_j not in test:
test.add(a_j)
out += 1
dp.append(out)
for i in range(m):
rev_index = len(array) - int(input())
print(dp[rev_index])
... | 3 | |
264 | B | Good Sequences | PROGRAMMING | 1,500 | [
"dp",
"number theory"
] | null | null | Squirrel Liss is interested in sequences. She also has preferences of integers. She thinks *n* integers *a*1,<=*a*2,<=...,<=*a**n* are good.
Now she is interested in good sequences. A sequence *x*1,<=*x*2,<=...,<=*x**k* is called good if it satisfies the following three conditions:
- The sequence is strictly increas... | The input consists of two lines. The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of good integers. The second line contains a single-space separated list of good integers *a*1,<=*a*2,<=...,<=*a**n* in strictly increasing order (1<=≤<=*a**i*<=≤<=105; *a**i*<=<<=*a**i*<=+<=1). | Print a single integer — the length of the longest good sequence. | [
"5\n2 3 4 6 9\n",
"9\n1 2 3 5 6 7 8 9 10\n"
] | [
"4\n",
"4\n"
] | In the first example, the following sequences are examples of good sequences: [2; 4; 6; 9], [2; 4; 6], [3; 9], [6]. The length of the longest good sequence is 4. | 1,000 | [
{
"input": "5\n2 3 4 6 9",
"output": "4"
},
{
"input": "9\n1 2 3 5 6 7 8 9 10",
"output": "4"
},
{
"input": "4\n1 2 4 6",
"output": "3"
},
{
"input": "7\n1 2 3 4 7 9 10",
"output": "3"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "8\n3 4 5 6 7 8 9... | 1,601,999,870 | 2,147,483,647 | PyPy 3 | OK | TESTS | 86 | 498 | 16,076,800 | n=10**5+1
p=[0]*n
t=[[] for _ in range(n)]
t[1]=[1]
for i in range(2,n):
if not t[i]:
t[i]=[i]
for j in range(2*i,n,i):
t[j].append(i)
m=input()
arr=list(map(int,input().split()))
x=0
#print(t[:10])
for i in arr:
x=0
for j in t[i]:
x=max(p[j],x)
x+=1
for j in t[i]:
p[j]=x
... | Title: Good Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Squirrel Liss is interested in sequences. She also has preferences of integers. She thinks *n* integers *a*1,<=*a*2,<=...,<=*a**n* are good.
Now she is interested in good sequences. A sequence *x*1,<=*x*2,<=...,<=*x**k*... | ```python
n=10**5+1
p=[0]*n
t=[[] for _ in range(n)]
t[1]=[1]
for i in range(2,n):
if not t[i]:
t[i]=[i]
for j in range(2*i,n,i):
t[j].append(i)
m=input()
arr=list(map(int,input().split()))
x=0
#print(t[:10])
for i in arr:
x=0
for j in t[i]:
x=max(p[j],x)
x+=1
for j in t[i]:
... | 3 | |
987 | A | Infinity Gauntlet | PROGRAMMING | 800 | [
"implementation"
] | null | null | You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color.
Using colors... | In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet.
In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase ... | In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems.
Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase. | [
"4\nred\npurple\nyellow\norange\n",
"0\n"
] | [
"2\nSpace\nTime\n",
"6\nTime\nMind\nSoul\nPower\nReality\nSpace\n"
] | In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space.
In the second sample Thanos doesn't have any Gems, so he needs all six. | 500 | [
{
"input": "4\nred\npurple\nyellow\norange",
"output": "2\nSpace\nTime"
},
{
"input": "0",
"output": "6\nMind\nSpace\nPower\nTime\nReality\nSoul"
},
{
"input": "6\npurple\nblue\nyellow\nred\ngreen\norange",
"output": "0"
},
{
"input": "1\npurple",
"output": "5\nTime\nReal... | 1,626,954,335 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 77 | 6,963,200 | stones=int(input())
if stones==6:
print(0)
else:
d={'purple':'Power','green':'Time','blue':'Space','orange':'Soul','red':'Reality','yellow':'Mind'}
z=[]
for i in range(stones):
s=input()
z+=s,
print(6-stones)
for i in d:
if i not in z:
print(d[... | Title: Infinity Gauntlet
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the So... | ```python
stones=int(input())
if stones==6:
print(0)
else:
d={'purple':'Power','green':'Time','blue':'Space','orange':'Soul','red':'Reality','yellow':'Mind'}
z=[]
for i in range(stones):
s=input()
z+=s,
print(6-stones)
for i in d:
if i not in z:
... | 3 | |
870 | C | Maximum splitting | PROGRAMMING | 1,300 | [
"dp",
"greedy",
"math",
"number theory"
] | null | null | You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prim... | The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query. | For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings. | [
"1\n12\n",
"2\n6\n8\n",
"3\n1\n2\n3\n"
] | [
"3\n",
"1\n2\n",
"-1\n-1\n-1\n"
] | 12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | 1,500 | [
{
"input": "1\n12",
"output": "3"
},
{
"input": "2\n6\n8",
"output": "1\n2"
},
{
"input": "3\n1\n2\n3",
"output": "-1\n-1\n-1"
},
{
"input": "6\n1\n2\n3\n5\n7\n11",
"output": "-1\n-1\n-1\n-1\n-1\n-1"
},
{
"input": "3\n4\n6\n9",
"output": "1\n1\n1"
},
{
... | 1,683,726,912 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 20 | 982 | 9,523,200 | nums=[4,9,6,15]
t=int(input())
for _ in range(t):
n=int(input())
if n < nums[n%4]:
print(-1)
else:
ans = (n-nums[n%4])//4+1
if(n%4==3):
ans+=1
print(ans) | Title: Maximum splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, o... | ```python
nums=[4,9,6,15]
t=int(input())
for _ in range(t):
n=int(input())
if n < nums[n%4]:
print(-1)
else:
ans = (n-nums[n%4])//4+1
if(n%4==3):
ans+=1
print(ans)
``` | 3 | |
520 | A | Pangram | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
You are given a string consisting of lowercase and uppercase Latin letters. Check whether thi... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of characters in the string.
The second line contains the string. The string consists only of uppercase and lowercase Latin letters. | Output "YES", if the string is a pangram and "NO" otherwise. | [
"12\ntoosmallword\n",
"35\nTheQuickBrownFoxJumpsOverTheLazyDog\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "12\ntoosmallword",
"output": "NO"
},
{
"input": "35\nTheQuickBrownFoxJumpsOverTheLazyDog",
"output": "YES"
},
{
"input": "1\na",
"output": "NO"
},
{
"input": "26\nqwertyuiopasdfghjklzxcvbnm",
"output": "YES"
},
{
"input": "26\nABCDEFGHIJKLMNOPQRSTUVWXY... | 1,699,113,088 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | n = int(input())
d = {}
s = input()
count = 0
for i in s:
x = i.lower()
if x not in d:
d[x] = 1
count = count + 1
else:
d[x] = d[x] + 1
if count==26:
print('YES')
else:
print('NO') | Title: Pangram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
... | ```python
n = int(input())
d = {}
s = input()
count = 0
for i in s:
x = i.lower()
if x not in d:
d[x] = 1
count = count + 1
else:
d[x] = d[x] + 1
if count==26:
print('YES')
else:
print('NO')
``` | 3 | |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,694,640,089 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 409,600 | n = int(input())
text_input = input()
a = text_input.count("0")
b = text_input.count("1")
c = min(a, b)
print(len(text_input) - (2 * c))
| Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
n = int(input())
text_input = input()
a = text_input.count("0")
b = text_input.count("1")
c = min(a, b)
print(len(text_input) - (2 * c))
``` | 3 | |
264 | B | Good Sequences | PROGRAMMING | 1,500 | [
"dp",
"number theory"
] | null | null | Squirrel Liss is interested in sequences. She also has preferences of integers. She thinks *n* integers *a*1,<=*a*2,<=...,<=*a**n* are good.
Now she is interested in good sequences. A sequence *x*1,<=*x*2,<=...,<=*x**k* is called good if it satisfies the following three conditions:
- The sequence is strictly increas... | The input consists of two lines. The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of good integers. The second line contains a single-space separated list of good integers *a*1,<=*a*2,<=...,<=*a**n* in strictly increasing order (1<=≤<=*a**i*<=≤<=105; *a**i*<=<<=*a**i*<=+<=1). | Print a single integer — the length of the longest good sequence. | [
"5\n2 3 4 6 9\n",
"9\n1 2 3 5 6 7 8 9 10\n"
] | [
"4\n",
"4\n"
] | In the first example, the following sequences are examples of good sequences: [2; 4; 6; 9], [2; 4; 6], [3; 9], [6]. The length of the longest good sequence is 4. | 1,000 | [
{
"input": "5\n2 3 4 6 9",
"output": "4"
},
{
"input": "9\n1 2 3 5 6 7 8 9 10",
"output": "4"
},
{
"input": "4\n1 2 4 6",
"output": "3"
},
{
"input": "7\n1 2 3 4 7 9 10",
"output": "3"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "8\n3 4 5 6 7 8 9... | 1,644,234,615 | 2,147,483,647 | PyPy 3 | OK | TESTS | 86 | 1,870 | 75,264,000 | import math
def solve():
n = int(input())
# l, r = list(map(int, input().split(" ")))
a = list(map(int, input().split(" ")))
# b = list(map(int, input().split(" ")))
# s = input()
N = int(10e5 + 5)
dp = [0]*N
fac = [[] for _ in range(N)]
seive = [1] * N
for i in range(2, N):
... | Title: Good Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Squirrel Liss is interested in sequences. She also has preferences of integers. She thinks *n* integers *a*1,<=*a*2,<=...,<=*a**n* are good.
Now she is interested in good sequences. A sequence *x*1,<=*x*2,<=...,<=*x**k*... | ```python
import math
def solve():
n = int(input())
# l, r = list(map(int, input().split(" ")))
a = list(map(int, input().split(" ")))
# b = list(map(int, input().split(" ")))
# s = input()
N = int(10e5 + 5)
dp = [0]*N
fac = [[] for _ in range(N)]
seive = [1] * N
for i in range(2... | 3 | |
665 | B | Shopping | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Ayush is a cashier at the shopping center. Recently his department has started a ''click and collect" service which allows users to shop online.
The store contains *k* items. *n* customers have already used the above service. Each user paid for *m* items. Let *a**ij* denote the *j*-th item in the *i*-th person's orde... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*k*<=≤<=100,<=1<=≤<=*m*<=≤<=*k*) — the number of users, the number of items each user wants to buy and the total number of items at the market.
The next line contains *k* distinct integers *p**l* (1<=≤<=*p**l*<=≤<=*k*) denoting the initial positions ... | Print the only integer *t* — the total time needed for Ayush to process all the orders. | [
"2 2 5\n3 4 1 2 5\n1 5\n3 1\n"
] | [
"14\n"
] | Customer 1 wants the items 1 and 5.
*pos*(1) = 3, so the new positions are: [1, 3, 4, 2, 5].
*pos*(5) = 5, so the new positions are: [5, 1, 3, 4, 2].
Time taken for the first customer is 3 + 5 = 8.
Customer 2 wants the items 3 and 1.
*pos*(3) = 3, so the new positions are: [3, 5, 1, 4, 2].
*pos*(1) = 3, so the ne... | 0 | [
{
"input": "2 2 5\n3 4 1 2 5\n1 5\n3 1",
"output": "14"
},
{
"input": "4 4 4\n1 2 3 4\n3 4 2 1\n4 3 2 1\n4 1 2 3\n4 1 2 3",
"output": "59"
},
{
"input": "1 1 1\n1\n1",
"output": "1"
},
{
"input": "10 1 100\n1 55 67 75 40 86 24 84 82 26 81 23 70 79 51 54 21 78 31 98 68 93 66 8... | 1,547,023,657 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 109 | 0 | n,m,k=map(int,input().split())
q=list(map(int,input().split()))
ans=0
for i in range(n):
lst=list(map(int,input().split()))
for j in lst:
#for x in input().split():
ind=q.index(j)
ans+=(ind+1)
q.pop(ind)
q.insert(0,j)
print(ans)
| Title: Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ayush is a cashier at the shopping center. Recently his department has started a ''click and collect" service which allows users to shop online.
The store contains *k* items. *n* customers have already used the above service... | ```python
n,m,k=map(int,input().split())
q=list(map(int,input().split()))
ans=0
for i in range(n):
lst=list(map(int,input().split()))
for j in lst:
#for x in input().split():
ind=q.index(j)
ans+=(ind+1)
q.pop(ind)
q.insert(0,j)
print(ans)
``` | 3 | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,559,034,017 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 109 | 0 | x = int(input())
if x%2 == 1:
print(0)
else:
k = x//2
if k%2 == 1:
print((k-1)//2)
else:
print((k)//2-1) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
x = int(input())
if x%2 == 1:
print(0)
else:
k = x//2
if k%2 == 1:
print((k-1)//2)
else:
print((k)//2-1)
``` | 3 | |
743 | B | Chloe and the sequence | PROGRAMMING | 1,200 | [
"binary search",
"bitmasks",
"constructive algorithms",
"implementation"
] | null | null | Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following algorithm of generating a sequence of integers. Initially we have a sequence consisting of a single element eq... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=2*n*<=-<=1). | Print single integer — the integer at the *k*-th position in the obtained sequence. | [
"3 2\n",
"4 8\n"
] | [
"2",
"4"
] | In the first sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1]. The number on the second position is 2.
In the second sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1]. The number on the eighth position is 4. | 1,000 | [
{
"input": "3 2",
"output": "2"
},
{
"input": "4 8",
"output": "4"
},
{
"input": "5 27",
"output": "1"
},
{
"input": "7 44",
"output": "3"
},
{
"input": "15 18432",
"output": "12"
},
{
"input": "20 259676",
"output": "3"
},
{
"input": "30 6... | 1,600,361,671 | 2,147,483,647 | PyPy 3 | OK | TESTS | 39 | 156 | 0 | import sys
def input(): return sys.stdin.readline().rstrip("\r\n")
def List(): return list(map(int, input().split()))
def Num(): return int(input())
def solve():
n, k = List()
return (2 * k - bin(k).count('1')) - (2 * (k - 1) - bin(k - 1).count('1'))
print(solve())
| Title: Chloe and the sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following a... | ```python
import sys
def input(): return sys.stdin.readline().rstrip("\r\n")
def List(): return list(map(int, input().split()))
def Num(): return int(input())
def solve():
n, k = List()
return (2 * k - bin(k).count('1')) - (2 * (k - 1) - bin(k - 1).count('1'))
print(solve())
``` | 3 | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,687,290,791 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 62 | 2,048,000 | a,b,c,d=map(int, input().split())
s=input()
cnt=0
for i in range(len(s)):
if s[i]=='1':
cnt+=a
elif s[i]=='2':
cnt+=b
elif s[i]=='3':
cnt+=c
elif s[i]=='4':
cnt+=d
print(cnt)
| Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
a,b,c,d=map(int, input().split())
s=input()
cnt=0
for i in range(len(s)):
if s[i]=='1':
cnt+=a
elif s[i]=='2':
cnt+=b
elif s[i]=='3':
cnt+=c
elif s[i]=='4':
cnt+=d
print(cnt)
``` | 3 | |
40 | A | Find Color | PROGRAMMING | 1,300 | [
"constructive algorithms",
"geometry",
"implementation",
"math"
] | A. Find Color | 2 | 256 | Not so long ago as a result of combat operations the main Berland place of interest — the magic clock — was damaged. The cannon's balls made several holes in the clock, that's why the residents are concerned about the repair. The magic clock can be represented as an infinite Cartesian plane, where the origin correspond... | The first and single line contains two integers *x* and *y* — the coordinates of the hole made in the clock by the ball. Each of the numbers *x* and *y* has an absolute value that does not exceed 1000. | Find the required color.
All the points between which and the origin of coordinates the distance is integral-value are painted black. | [
"-2 1\n",
"2 1\n",
"4 3\n"
] | [
"white\n",
"black\n",
"black\n"
] | none | 500 | [
{
"input": "-2 1",
"output": "white"
},
{
"input": "2 1",
"output": "black"
},
{
"input": "4 3",
"output": "black"
},
{
"input": "3 3",
"output": "black"
},
{
"input": "4 4",
"output": "white"
},
{
"input": "-4 4",
"output": "black"
},
{
"i... | 1,653,695,714 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 92 | 0 | from sys import stdin
from math import sqrt, floor
x, y = stdin.readline().split()
x = int(x)
y = int(y)
r2 = (x * x) + (y * y)
r = floor(sqrt(r2))
if (r * r) < r2 and ((r + 1) * (r + 1)) > r2 and (r % 2 == 1 and x * y > 0 or r % 2 == 0 and x * y < 0):
print("white")
else:
print("black");
| Title: Find Color
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Not so long ago as a result of combat operations the main Berland place of interest — the magic clock — was damaged. The cannon's balls made several holes in the clock, that's why the residents are concerned about the repair. Th... | ```python
from sys import stdin
from math import sqrt, floor
x, y = stdin.readline().split()
x = int(x)
y = int(y)
r2 = (x * x) + (y * y)
r = floor(sqrt(r2))
if (r * r) < r2 and ((r + 1) * (r + 1)) > r2 and (r % 2 == 1 and x * y > 0 or r % 2 == 0 and x * y < 0):
print("white")
else:
print("black");
... | 3.977 |
714 | B | Filya and Homework | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*. First, he pick an integer *x* and then he adds *x* to some elements of the array (no more than onc... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of integers in the Filya's array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — elements of the array. | If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES" (without quotes). | [
"5\n1 3 3 2 1\n",
"5\n1 2 3 4 5\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Filya should select *x* = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements. | 1,000 | [
{
"input": "5\n1 3 3 2 1",
"output": "YES"
},
{
"input": "5\n1 2 3 4 5",
"output": "NO"
},
{
"input": "2\n1 2",
"output": "YES"
},
{
"input": "3\n1 2 3",
"output": "YES"
},
{
"input": "3\n1 1 1",
"output": "YES"
},
{
"input": "2\n1 1000000000",
"ou... | 1,484,331,565 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 93 | 13,824,000 | a=int(input())
b=list(map(int,input().split()))
c=set(b)
d=sorted(list(c))
if len(c)>3:
print('NO')
elif len(c)==3:
if (d[2]+d[0])==2*d[1]:
print('YES')
else:
print('NO')
else:
print('YES')
| Title: Filya and Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a... | ```python
a=int(input())
b=list(map(int,input().split()))
c=set(b)
d=sorted(list(c))
if len(c)>3:
print('NO')
elif len(c)==3:
if (d[2]+d[0])==2*d[1]:
print('YES')
else:
print('NO')
else:
print('YES')
``` | 3 | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,693,844,697 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 62 | 0 | n, m = map(int, input().split(" "))
f = list(map(int, input().split(" ")))
f.sort() # Sort the list in ascending order
min_diff = float('inf') # Initialize with a large value
for right in range(n, m + 1):
min_diff = min(min_diff, f[right - 1] - f[right - n])
print(min_diff)
| Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
n, m = map(int, input().split(" "))
f = list(map(int, input().split(" ")))
f.sort() # Sort the list in ascending order
min_diff = float('inf') # Initialize with a large value
for right in range(n, m + 1):
min_diff = min(min_diff, f[right - 1] - f[right - n])
print(min_diff)
``` | 3 | |
900 | A | Find Extra One | PROGRAMMING | 800 | [
"geometry",
"implementation"
] | null | null | You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis. | The first line contains a single positive integer *n* (2<=≤<=*n*<=≤<=105).
The following *n* lines contain coordinates of the points. The *i*-th of these lines contains two single integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109, *x**i*<=≠<=0). No two points coincide. | Print "Yes" if there is such a point, "No" — otherwise.
You can print every letter in any case (upper or lower). | [
"3\n1 1\n-1 -1\n2 -1\n",
"4\n1 1\n2 2\n-1 1\n-2 2\n",
"3\n1 2\n2 1\n4 60\n"
] | [
"Yes",
"No",
"Yes"
] | In the first example the second point can be removed.
In the second example there is no suitable for the condition point.
In the third example any point can be removed. | 500 | [
{
"input": "3\n1 1\n-1 -1\n2 -1",
"output": "Yes"
},
{
"input": "4\n1 1\n2 2\n-1 1\n-2 2",
"output": "No"
},
{
"input": "3\n1 2\n2 1\n4 60",
"output": "Yes"
},
{
"input": "10\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n-1 -1",
"output": "Yes"
},
{
"input": "2\n1... | 1,570,742,357 | 2,147,483,647 | PyPy 3 | OK | TESTS | 71 | 967 | 9,830,400 | n = int(input())
d = 0
e = 0
for i in range(n):
x, y = map(int, input().split())
if x > 0:
d += 1
elif x < 0:
e += 1
YES = 'YES'
NO = 'NO'
if d == 0 or d == 1 or e == 0 or e == 1:
print(YES)
else:
print(NO)
| Title: Find Extra One
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis.
Input Specification:
The first li... | ```python
n = int(input())
d = 0
e = 0
for i in range(n):
x, y = map(int, input().split())
if x > 0:
d += 1
elif x < 0:
e += 1
YES = 'YES'
NO = 'NO'
if d == 0 or d == 1 or e == 0 or e == 1:
print(YES)
else:
print(NO)
``` | 3 | |
361 | A | Levko and Table | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortunately, he doesn't know any such table. Your task is to help him to find at least one of them. | The single line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). | Print any beautiful table. Levko doesn't like too big numbers, so all elements of the table mustn't exceed 1000 in their absolute value.
If there are multiple suitable tables, you are allowed to print any of them. | [
"2 4\n",
"4 7\n"
] | [
"1 3\n3 1\n",
"2 1 0 4\n4 0 2 1\n1 3 3 0\n0 3 2 2\n"
] | In the first sample the sum in the first row is 1 + 3 = 4, in the second row — 3 + 1 = 4, in the first column — 1 + 3 = 4 and in the second column — 3 + 1 = 4. There are other beautiful tables for this sample.
In the second sample the sum of elements in each row and each column equals 7. Besides, there are other table... | 500 | [
{
"input": "2 4",
"output": "4 0 \n0 4 "
},
{
"input": "4 7",
"output": "7 0 0 0 \n0 7 0 0 \n0 0 7 0 \n0 0 0 7 "
},
{
"input": "1 8",
"output": "8 "
},
{
"input": "9 3",
"output": "3 0 0 0 0 0 0 0 0 \n0 3 0 0 0 0 0 0 0 \n0 0 3 0 0 0 0 0 0 \n0 0 0 3 0 0 0 0 0 \n0 0 0 0 3 0... | 1,622,198,053 | 553 | PyPy 3 | OK | TESTS | 22 | 233 | 3,276,800 | n,k=map(int,input().split())
numberofones=n-1
req=k-(n-1)
cnt=n-1
for i in range(n):
for j in range(n):
if j==cnt:
print(req,end=" ")
else:
print(1,end=" ")
cnt-=1
print()
| Title: Levko and Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortun... | ```python
n,k=map(int,input().split())
numberofones=n-1
req=k-(n-1)
cnt=n-1
for i in range(n):
for j in range(n):
if j==cnt:
print(req,end=" ")
else:
print(1,end=" ")
cnt-=1
print()
``` | 3 | |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
Bu... | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,696,543,878 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | username = list(input())
username = list(set(username))
if len(username)%2 == 1:
print("IGNORE HIM!")
else:
print("CHAT WITH HER!") | Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he though... | ```python
username = list(input())
username = list(set(username))
if len(username)%2 == 1:
print("IGNORE HIM!")
else:
print("CHAT WITH HER!")
``` | 3 | |
580 | A | Kefa and First Steps | PROGRAMMING | 900 | [
"brute force",
"dp",
"implementation"
] | null | null | Kefa decided to make some money doing business on the Internet for exactly *n* days. He knows that on the *i*-th day (1<=≤<=*i*<=≤<=*n*) he makes *a**i* money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence *a**i*. Let us remind you that the subsegment o... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the length of the maximum non-decreasing subsegment of sequence *a*. | [
"6\n2 2 1 3 4 1\n",
"3\n2 2 9\n"
] | [
"3",
"3"
] | In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.
In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one. | 750 | [
{
"input": "6\n2 2 1 3 4 1",
"output": "3"
},
{
"input": "3\n2 2 9",
"output": "3"
},
{
"input": "5\n10 100 111 1 2",
"output": "3"
},
{
"input": "10\n1 2 3 4 1 2 3 4 5 6",
"output": "6"
},
{
"input": "50\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ... | 1,699,968,819 | 2,147,483,647 | PyPy 3 | OK | TESTS | 28 | 155 | 10,956,800 | n = int(input())
niz = [int(x) for x in input().split()]
def najduzi(niz):
najveci = 0
ukupno = 0
prvi = niz[0]
for i in range(1, len(niz)):
if prvi<=niz[i]:
najveci+=1
else:
najveci=0
ukupno=max(ukupno,najveci)
prvi= niz[i]... | Title: Kefa and First Steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kefa decided to make some money doing business on the Internet for exactly *n* days. He knows that on the *i*-th day (1<=≤<=*i*<=≤<=*n*) he makes *a**i* money. Kefa loves progress, that's why he wants to know the l... | ```python
n = int(input())
niz = [int(x) for x in input().split()]
def najduzi(niz):
najveci = 0
ukupno = 0
prvi = niz[0]
for i in range(1, len(niz)):
if prvi<=niz[i]:
najveci+=1
else:
najveci=0
ukupno=max(ukupno,najveci)
pr... | 3 | |
1,003 | A | Polycarp's Pockets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarp has $n$ coins, the value of the $i$-th coin is $a_i$. Polycarp wants to distribute all the coins between his pockets, but he cannot put two coins with the same value into the same pocket.
For example, if Polycarp has got six coins represented as an array $a = [1, 2, 4, 3, 3, 2]$, he can distribute the coins i... | The first line of the input contains one integer $n$ ($1 \le n \le 100$) — the number of coins.
The second line of the input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$) — values of coins. | Print only one integer — the minimum number of pockets Polycarp needs to distribute all the coins so no two coins with the same value are put into the same pocket. | [
"6\n1 2 4 3 3 2\n",
"1\n100\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "6\n1 2 4 3 3 2",
"output": "2"
},
{
"input": "1\n100",
"output": "1"
},
{
"input": "100\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100... | 1,694,004,011 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 | freq = [0 for _ in range(101)]
n = int(input())
for x in [int(x) for x in input().split()]:
freq[x] += 1
print(max(freq)) | Title: Polycarp's Pockets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has $n$ coins, the value of the $i$-th coin is $a_i$. Polycarp wants to distribute all the coins between his pockets, but he cannot put two coins with the same value into the same pocket.
For example, if Po... | ```python
freq = [0 for _ in range(101)]
n = int(input())
for x in [int(x) for x in input().split()]:
freq[x] += 1
print(max(freq))
``` | 3 | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,582,465,394 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 310 | 0 | a = input()
b = input()
c = int(a)
d = int(b)
ans1 = c+d
e = a.replace('0', '')
f = b.replace('0', '')
g = int(e)
f = int(f)
ans2 = g+f
temp = str(ans1)
s1 = temp.replace('0', '')
s2 = str(ans2)
if s1 == s2:
print('YES')
else:
print('NO') | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
a = input()
b = input()
c = int(a)
d = int(b)
ans1 = c+d
e = a.replace('0', '')
f = b.replace('0', '')
g = int(e)
f = int(f)
ans2 = g+f
temp = str(ans1)
s1 = temp.replace('0', '')
s2 = str(ans2)
if s1 == s2:
print('YES')
else:
print('NO')
``` | 3.9225 |
199 | A | Hexadecimal's theorem | PROGRAMMING | 900 | [
"brute force",
"constructive algorithms",
"implementation",
"number theory"
] | null | null | Recently, a chaotic virus Hexadecimal advanced a new theorem which will shake the Universe. She thinks that each Fibonacci number can be represented as sum of three not necessary different Fibonacci numbers.
Let's remember how Fibonacci numbers can be calculated. *F*0<==<=0, *F*1<==<=1, and all the next numbers are *F... | The input contains of a single integer *n* (0<=≤<=*n*<=<<=109) — the number that should be represented by the rules described above. It is guaranteed that *n* is a Fibonacci number. | Output three required numbers: *a*, *b* and *c*. If there is no answer for the test you have to print "I'm too stupid to solve this problem" without the quotes.
If there are multiple answers, print any of them. | [
"3\n",
"13\n"
] | [
"1 1 1\n",
"2 3 8\n"
] | none | 500 | [
{
"input": "3",
"output": "1 1 1"
},
{
"input": "13",
"output": "2 3 8"
},
{
"input": "0",
"output": "0 0 0"
},
{
"input": "1",
"output": "1 0 0"
},
{
"input": "2",
"output": "1 1 0"
},
{
"input": "1597",
"output": "233 377 987"
},
{
"input... | 1,595,983,492 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 310 | 20,172,800 | m = {}
fibo = [0]*47
fibo[1] = 1
m[0] = 0
for i in range(2,47):
fibo[i] = fibo[i-2] + fibo[i-1]
m[fibo[i]] = i
n = int(input())
if n == 0:
print(0,0,0)
exit(0)
print(fibo[m[n]-1],fibo[m[n]-2],0)
| Title: Hexadecimal's theorem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, a chaotic virus Hexadecimal advanced a new theorem which will shake the Universe. She thinks that each Fibonacci number can be represented as sum of three not necessary different Fibonacci numbers.
Let'... | ```python
m = {}
fibo = [0]*47
fibo[1] = 1
m[0] = 0
for i in range(2,47):
fibo[i] = fibo[i-2] + fibo[i-1]
m[fibo[i]] = i
n = int(input())
if n == 0:
print(0,0,0)
exit(0)
print(fibo[m[n]-1],fibo[m[n]-2],0)
``` | 3 |
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