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ZK3O402wf1c
So this was the first component.
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The second component was a minus one.
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Maybe up here.
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That's column three, that's the column zero minus one and four.
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This guy.
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So, again, what's my problem?
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What this equation is asking me to do
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is to combine these three vectors
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with a right combination to produce this one.
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Well, you can see what the right combination is, because
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in this special problem, specially chosen
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by the lecturer, that right-hand side that I'm trying to get
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is actually one of these columns.
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So I know how to get that one.
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So what's the solution?
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What combination will work?
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I just want one of these and none of these.
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So x should be zero, y should be zero and z should
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be one.
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That's the combination.
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One of those is obviously the right one.
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Column three is actually the same
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as b in this particular problem.
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I made it work that way just so we
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would get an answer, (0,0,1), so somehow that's
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the point where those three planes met
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and I couldn't see it before.
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Of course, I won't always be able to see it from the column
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picture, either.
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It's the next lecture, actually, which is about elimination,
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which is the systematic way that everybody --
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every bit of software, too --
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production, large-scale software would solve the equations.
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So the lecture that's coming up.
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If I was to add that to the syllabus,
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will be about how to find x, y, z in all cases.
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Can I just think again, though, about the big picture?
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By the big picture I mean let's keep this same matrix
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on the left but imagine that we have
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a different right-hand side.
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Oh, let me take a different right-hand side.
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So I'll change that right-hand side
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to something that actually is also pretty special.
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Let me change it to --
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if I add those first two columns,
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that would give me a one and a one and a minus three.
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There's a very special right-hand side.
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I just cooked it up by adding this one to this one.
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Now, what's the solution with this new right-hand side?
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The solution with this new right-hand side is clear.
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took one of these and none of those.
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So actually, it just changed around to this
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when I took this new right-hand side.
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Okay.
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So in the row picture, I have three different planes,
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three new planes meeting now at this point.
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In the column picture, I have the same three columns,
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but now I'm combining them to produce this guy,
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and it turned out that column one plus column two which would
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be somewhere -- there is the right column --
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one of this and one of this would give me the new b.
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Okay.
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So we squeezed in an extra example.
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But now think about all bs, all right-hand sides.
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Can I solve these equations for every right-hand side?
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Can I ask that question?
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So that's the algebra question.
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Can I solve A x=b for every b?
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Let me write that down.
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Can I solve A x =b for every right-hand side b?
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I mean, is there a solution?
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And then, if there is, elimination
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will give me a way to find it.
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I really wanted to ask, is there a solution
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for every right-hand side?
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So now, can I put that in different words --
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in this linear combination words?
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So in linear combination words, do the linear combinations
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of the columns fill three dimensional space?
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Every b means all the bs in three dimensional space.
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Do you see that I'm just asking the same question
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in different words?
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Solving A x --
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A x -- that's very important.
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A times x -- when I multiply a matrix by a vector,
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I get a combination of the columns.
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I'll write that down in a moment.
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But in my column picture, that's really what I'm doing.
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I'm taking linear combinations of these three columns
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and I'm trying to find b.
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And, actually, the answer for this matrix will be yes.
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For this matrix A -- for these columns, the answer is yes.
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This matrix -- that I chose for an example is a good matrix.
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A non-singular matrix.
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An invertible matrix.
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Those will be the matrices that we like best.
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There could be other --
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and we will see other matrices where the answer becomes, no --
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oh, actually, you can see when it would become no.
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What could go wrong? find out -- because if elimination fails,