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PxCxlsl_YwY
the first component of B, the second with the second,
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and the third with the third. OK, say that A was
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***amp***lt;a1, a2, a3***amp***gt;
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B was ***amp***lt;b1, b2, b3***amp***gt;,
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then you just add this way. OK, so it's pretty
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straightforward. So, for example,
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I said that my vector over there, its components are three,
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two, one. But, I also wrote it as 3i 2j k.
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What does that mean? OK, so I need to tell you first
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about multiplying by a scalar. So, this is about addition.
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So, multiplication by a scalar, it's very easy.
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If you have a vector, A, then you can form a vector
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2A just by making it go twice as far in the same direction.
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Or, we can make half A more modestly.
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We can even make minus A, and so on.
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So now, you see, if I do the calculation,
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3i 2j k, well, what does it mean?
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3i is just going to go along the x axis, but by distance of
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three instead of one. And then, 2j goes two units
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along the y axis, and k goes up by one unit.
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Well, if you add these together, you will go from the
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origin, then along the x axis, then parallel to the y axis,
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and then up. And, you will end up,
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indeed, at the endpoint of a vector.
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OK, any questions at this point? Yes?
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Exactly. To add vectors geometrically,
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you just put the head of the first vector and the tail of the
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second vector in the same place. And then, it's head to tail
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addition. Any other questions?
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Yes? That's correct.
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If you subtract two vectors, that just means you add the
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opposite of a vector. So, for example,
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if I wanted to do A minus B, I would first go along A and
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then along minus B, which would take me somewhere
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over there, OK? So, A minus B,
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if you want, would go from here to here.
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OK, so hopefully you've kind of seen that stuff either before in
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your lives, or at least yesterday.
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So, I'm going to use that as an excuse to move quickly forward.
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So, now we are going to learn a few more operations about
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vectors. And, these operations will be
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useful to us when we start trying to do a bit of geometry.
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So, of course, you've all done some geometry.
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But, we are going to see that geometry can be done using
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vectors. And, in many ways,
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it's the right language for that,
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and in particular when we learn about functions we really will
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want to use vectors more than, maybe, the other kind of
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geometry that you've seen before.
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I mean, of course, it's just a language in a way.
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I mean, we are just reformulating things that you
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have seen, you already know since childhood.
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But, you will see that notation somehow helps to make it more
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straightforward. So, what is dot product?
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Well, dot product as a way of multiplying two vectors to get a
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number, a scalar. And, well, let me start by
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giving you a definition in terms of components.
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What we do, let's say that we have a vector,
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A, with components a1, a2, a3, vector B with
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components b1, b2, b3.
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Well, we multiply the first components by the first
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components, the second by the second, the third by the third.
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If you have N components, you keep going.
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And, you sum all of these together.
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OK, and important: this is a scalar.
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OK, you do not get a vector. You get a number.
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I know it sounds completely obvious from the definition
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here, but in the middle of the action
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when you're going to do complicated problems,
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it's sometimes easy to forget. So, that's the definition.
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What is it good for? Why would we ever want to do
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that? That's kind of a strange
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operation. So, probably to see what it's
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good for, I should first tell you what it is geometrically.
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OK, so what does it do geometrically?
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Well, what you do when you multiply two vectors in this
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way, I claim the answer is equal to
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the length of A times the length of B times the cosine of the
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angle between them. So, I have my vector, A,
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and if I have my vector, B, and I have some angle between
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them, I multiply the length of A
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times the length of B times the cosine of that angle.
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So, that looks like a very artificial operation.
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I mean, why would want to do that complicated multiplication?
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Well, the basic answer is it tells us at the same time about
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lengths and about angles. And, the extra bonus thing is
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that it's very easy to compute if you have components,
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see, that formula is actually pretty easy.
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So, OK, maybe I should first tell you, how do we get this
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from that? Because, you know,
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in math, one tries to justify everything to prove theorems.
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So, if you want, that's the theorem.
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That's the first theorem in 18.02.
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So, how do we prove the theorem? How do we check that this is,
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indeed, correct using this definition?
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So, in more common language, what does this geometric
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definition mean? Well, the first thing it means,
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before we multiply two vectors, let's start multiplying a
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vector with itself. That's probably easier.
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So, if we multiply a vector, A, with itself,