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PxCxlsl_YwY
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the first component of B,
the second with the second,
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and the third with the third.
OK, say that A was
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***amp***lt;a1,
a2, a3***amp***gt;
|
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|
B was ***amp***lt;b1,
b2, b3***amp***gt;,
|
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|
then you just add this way.
OK, so it's pretty
|
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|
straightforward.
So, for example,
|
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|
I said that my vector over
there, its components are three,
|
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|
two, one.
But, I also wrote it as 3i 2j k.
|
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|
What does that mean?
OK, so I need to tell you first
|
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|
about multiplying by a scalar.
So, this is about addition.
|
PxCxlsl_YwY
|
So, multiplication by a scalar,
it's very easy.
|
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|
If you have a vector,
A, then you can form a vector
|
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|
2A just by making it go twice as
far in the same direction.
|
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|
Or, we can make half A more
modestly.
|
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|
We can even make minus A,
and so on.
|
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|
So now, you see,
if I do the calculation,
|
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|
3i 2j k, well,
what does it mean?
|
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|
3i is just going to go along
the x axis, but by distance of
|
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|
three instead of one.
And then, 2j goes two units
|
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|
along the y axis,
and k goes up by one unit.
|
PxCxlsl_YwY
|
Well, if you add these
together, you will go from the
|
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|
origin, then along the x axis,
then parallel to the y axis,
|
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|
and then up.
And, you will end up,
|
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|
indeed, at the endpoint of a
vector.
|
PxCxlsl_YwY
|
OK, any questions at this point?
Yes?
|
PxCxlsl_YwY
|
Exactly.
To add vectors geometrically,
|
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|
you just put the head of the
first vector and the tail of the
|
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|
second vector in the same place.
And then, it's head to tail
|
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|
addition.
Any other questions?
|
PxCxlsl_YwY
|
Yes?
That's correct.
|
PxCxlsl_YwY
|
If you subtract two vectors,
that just means you add the
|
PxCxlsl_YwY
|
opposite of a vector.
So, for example,
|
PxCxlsl_YwY
|
if I wanted to do A minus B,
I would first go along A and
|
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|
then along minus B,
which would take me somewhere
|
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|
over there, OK?
So, A minus B,
|
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|
if you want,
would go from here to here.
|
PxCxlsl_YwY
|
OK, so hopefully you've kind of
seen that stuff either before in
|
PxCxlsl_YwY
|
your lives, or at least
yesterday.
|
PxCxlsl_YwY
|
So, I'm going to use that as an
excuse to move quickly forward.
|
PxCxlsl_YwY
|
So, now we are going to learn a
few more operations about
|
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|
vectors.
And, these operations will be
|
PxCxlsl_YwY
|
useful to us when we start
trying to do a bit of geometry.
|
PxCxlsl_YwY
|
So, of course,
you've all done some geometry.
|
PxCxlsl_YwY
|
But, we are going to see that
geometry can be done using
|
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|
vectors.
And, in many ways,
|
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|
it's the right language for
that,
|
PxCxlsl_YwY
|
and in particular when we learn
about functions we really will
|
PxCxlsl_YwY
|
want to use vectors more than,
maybe, the other kind of
|
PxCxlsl_YwY
|
geometry that you've seen
before.
|
PxCxlsl_YwY
|
I mean, of course,
it's just a language in a way.
|
PxCxlsl_YwY
|
I mean, we are just
reformulating things that you
|
PxCxlsl_YwY
|
have seen, you already know
since childhood.
|
PxCxlsl_YwY
|
But, you will see that notation
somehow helps to make it more
|
PxCxlsl_YwY
|
straightforward.
So, what is dot product?
|
PxCxlsl_YwY
|
Well, dot product as a way of
multiplying two vectors to get a
|
PxCxlsl_YwY
|
number, a scalar.
And, well, let me start by
|
PxCxlsl_YwY
|
giving you a definition in terms
of components.
|
PxCxlsl_YwY
|
What we do, let's say that we
have a vector,
|
PxCxlsl_YwY
|
A, with components a1,
a2, a3, vector B with
|
PxCxlsl_YwY
|
components b1,
b2, b3.
|
PxCxlsl_YwY
|
Well, we multiply the first
components by the first
|
PxCxlsl_YwY
|
components, the second by the
second, the third by the third.
|
PxCxlsl_YwY
|
If you have N components,
you keep going.
|
PxCxlsl_YwY
|
And, you sum all of these
together.
|
PxCxlsl_YwY
|
OK, and important:
this is a scalar.
|
PxCxlsl_YwY
|
OK, you do not get a vector.
You get a number.
|
PxCxlsl_YwY
|
I know it sounds completely
obvious from the definition
|
PxCxlsl_YwY
|
here,
but in the middle of the action
|
PxCxlsl_YwY
|
when you're going to do
complicated problems,
|
PxCxlsl_YwY
|
it's sometimes easy to forget.
So, that's the definition.
|
PxCxlsl_YwY
|
What is it good for?
Why would we ever want to do
|
PxCxlsl_YwY
|
that?
That's kind of a strange
|
PxCxlsl_YwY
|
operation.
So, probably to see what it's
|
PxCxlsl_YwY
|
good for, I should first tell
you what it is geometrically.
|
PxCxlsl_YwY
|
OK, so what does it do
geometrically?
|
PxCxlsl_YwY
|
Well, what you do when you
multiply two vectors in this
|
PxCxlsl_YwY
|
way,
I claim the answer is equal to
|
PxCxlsl_YwY
|
the length of A times the length
of B times the cosine of the
|
PxCxlsl_YwY
|
angle between them.
So, I have my vector, A,
|
PxCxlsl_YwY
|
and if I have my vector, B,
and I have some angle between
|
PxCxlsl_YwY
|
them,
I multiply the length of A
|
PxCxlsl_YwY
|
times the length of B times the
cosine of that angle.
|
PxCxlsl_YwY
|
So, that looks like a very
artificial operation.
|
PxCxlsl_YwY
|
I mean, why would want to do
that complicated multiplication?
|
PxCxlsl_YwY
|
Well, the basic answer is it
tells us at the same time about
|
PxCxlsl_YwY
|
lengths and about angles.
And, the extra bonus thing is
|
PxCxlsl_YwY
|
that it's very easy to compute
if you have components,
|
PxCxlsl_YwY
|
see, that formula is actually
pretty easy.
|
PxCxlsl_YwY
|
So, OK, maybe I should first
tell you, how do we get this
|
PxCxlsl_YwY
|
from that?
Because, you know,
|
PxCxlsl_YwY
|
in math, one tries to justify
everything to prove theorems.
|
PxCxlsl_YwY
|
So, if you want,
that's the theorem.
|
PxCxlsl_YwY
|
That's the first theorem in
18.02.
|
PxCxlsl_YwY
|
So, how do we prove the theorem?
How do we check that this is,
|
PxCxlsl_YwY
|
indeed, correct using this
definition?
|
PxCxlsl_YwY
|
So, in more common language,
what does this geometric
|
PxCxlsl_YwY
|
definition mean?
Well, the first thing it means,
|
PxCxlsl_YwY
|
before we multiply two vectors,
let's start multiplying a
|
PxCxlsl_YwY
|
vector with itself.
That's probably easier.
|
PxCxlsl_YwY
|
So, if we multiply a vector,
A, with itself,
|
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