row_id int64 0 36.7k | QuestionId int64 31.8k 109k | QuestionText stringclasses 15
values | MC_Answer stringclasses 49
values | StudentExplanation stringlengths 1 586 | Category stringclasses 6
values | Misconception stringclasses 35
values |
|---|---|---|---|---|---|---|
25,300 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | if you multiply 5 plus 6=11 then you have to rewrite the equation as 15 is the lowest denominator. | False_Neither | null |
25,301 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | if you multiply 5x3=15 then you do 5*1=5 and 3*2=6 and 6 plus 5 is 11 then it would be 11/15 | False_Correct | null |
25,302 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | im not too sure at fractions | False_Neither | null |
25,303 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | it was closest to what my other answer was | False_Neither | null |
25,304 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | make the bottom the same and just add the top | False_Misconception | Denominator-only_change |
25,305 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | make the denominators the same - it becomes 15
1 times 5 = 5
2 times 3 =6
5+6=1
so its 11/15 | False_Correct | null |
25,306 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | make the denominators the same and do the same to the top then add them | False_Neither | null |
25,307 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | make the denominators the same and do the top the otherr way around and add them. | False_Neither | null |
25,308 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | so the numerators aree 6 and 5, and the denominators is 15. so you need to add the two numbers together to get 11, and then add that to the common de demoninator, which is 15, and you get 11. | False_Neither | null |
25,309 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | so then 3 + 5 = 15 and 1 + 2 = 3 so its 3 - 15 | False_Misconception | Denominator-only_change |
25,310 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | the common denominator of 15 is 15, so first, i figured out the common factor of 15, then i dud 1 x 5 to get 5, then i did 2 x 3 to find 6, then added 5 so i got 11. then i added 11 so it was 11. | False_Neither | null |
25,311 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | the common multiple is 15 so whatever you do to the denominator you do to the numerator | False_Neither | null |
25,312 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | they both have thirty in their times tables. | False_Neither | null |
25,313 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | times 1 by 5 and 2 by 3 thee answer is 11 over 15 | False_Neither | null |
25,314 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | x times the bottom by and times times th top by it and that's how i got my answer | False_Neither | null |
25,315 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | you change bottoms to 30 and add the top ones up | False_Neither | null |
25,316 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | you change thee bottoms to 30 and add the top ones up | False_Misconception | Incorrect_equivalent_fraction_addition |
25,317 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | you fnd the closes denomter which is 15 | False_Neither | null |
25,318 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | you have to find the lowest common multiple and then you have to add 6/15 and 5/15 which is 11/15 | False_Correct | null |
25,319 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | you have to findd the common denominator | False_Neither | null |
25,320 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | you have to make the common denominator, which is 30, then 1 add 2 is 3 | False_Misconception | Denominator-only_change |
25,321 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | you need to find the common denominator | False_Neither | null |
25,322 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{30} \) | you will need to find a common denominator such as dividing both numbers by the common factor, then adding the numerators together. | False_Neither | null |
25,323 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1 + 2 = 3 3 timess 5 = 15 | False_Misconception | Denominator-only_change |
25,324 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1 + 2 = 3 5 + 3 = 8 put it as a fraction and it equals 3/8 | False_Misconception | Adding_across |
25,325 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1 + 2 = 3 5 + 3 = 8 take it as a fraction and it equals 3/8 | False_Misconception | Adding_across |
25,326 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1 + 2 = 3 and also 3 and 5 both fit into 15 | False_Misconception | Denominator-only_change |
25,327 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1 + 2 = 3 and also 3 or 5 both fit into 15. | False_Misconception | Denominator-only_change |
25,328 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1 + 2 = 3 and to find the common denominator , you do 5 x 3 = 15 ; the answer is 3/15 | False_Misconception | Denominator-only_change |
25,329 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1 plus 2 equals 3 so the dominotars both go into 15 so 1 + 3 = 4. | False_Neither | null |
25,330 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1+2 is 3, 3x5 is 15, so you get 3/15. | False_Misconception | Denominator-only_change |
25,331 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1+2=3 and the lowest common multiple is 15. | False_Misconception | Denominator-only_change |
25,332 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1+2=3 so the answer is 3/15. | False_Misconception | Denominator-only_change |
25,333 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1+2=3, so 3/15. | False_Misconception | Denominator-only_change |
25,334 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1/3 + 2/5 = 3/15
i did 3x5 which is 15 and then 1+2 which is 3 | False_Misconception | Denominator-only_change |
25,335 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1/3 + 2/5 = 3/15 i did 3x5 which is 15 andd then 1+2 which was 3 | False_Misconception | Denominator-only_change |
25,336 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 15 goes in the 3 and 5 times tables then times 3 by 5 (answer = 15) and troimes the top number as well then do the same with the other fraction and then add the enumerators together | False_Neither | null |
25,337 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 15 is a factor of 3 and 5 and 2+1 is 3 so it's 3/15 | False_Misconception | Denominator-only_change |
25,338 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 15 is in the 5 times tables and in the 3 times tables so you make them both 15 in the denominator then u add 1 and 2 therefore it = 3 over 15 . | False_Misconception | Denominator-only_change |
25,339 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 15 is the 1st number in the 3 and 5 x table | False_Neither | null |
25,340 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 15 is the common denominator then add the top two which is 3 | False_Misconception | Denominator-only_change |
25,341 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 15 is the firstt number in the 3 and 5 x table | False_Neither | null |
25,342 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 15 is the lowest common denominator | False_Neither | null |
25,343 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 1x5=5 and 3x3=6 so 3*5 = 15 and 1 x 5 = 5 so 5 +6 = 11. | False_Correct | null |
25,344 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 2/5 = 6/15 and 1/3 = 5/15 so add them together and you get 11/15. | False_Correct | null |
25,345 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 + 5 = 15 and then you add 15 so the domminater is 15 then I did 2 + 1 = 3 and that gave me 3 | False_Misconception | Denominator-only_change |
25,346 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 +5'is 7 3 times 2 is 6 and 1 ines 5 is 5 | False_Neither | null |
25,347 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 add up to 15 and then 1 plus 2 is 3 so 3 plus 5 is 15 plus 3 is 15. | False_Misconception | Denominator-only_change |
25,348 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 both fit in to 15 | False_Neither | null |
25,349 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 both go imto 15 and not 8 and the numerator is 3 because 1+2 = 3. | False_Misconception | Denominator-only_change |
25,350 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 both go into 15 and 1 + 2 = 3 so it’s 3/15 | False_Misconception | Denominator-only_change |
25,351 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 both go into 15 and the add the numerator | False_Misconception | Denominator-only_change |
25,352 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 both go into 15 and then add the numerator. | False_Misconception | Denominator-only_change |
25,353 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 both go into 15, so 3 + 2 = 3 so that's 3/15. | False_Misconception | Denominator-only_change |
25,354 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 both go into 15. 1+2=3 so 3/15. | False_Misconception | Denominator-only_change |
25,355 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 go into 15 and 1 plus 2 is 3 | False_Misconception | Denominator-only_change |
25,356 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 go into 15 so add 1 and 2 and it's 3/15 | False_Misconception | Denominator-only_change |
25,357 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 go into 15 so add 1 and 2 and it's 3/15 | False_Misconception | Denominator-only_change |
25,358 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 go into 15 so the domminater is 15 and then i did 2+1 =3 | False_Misconception | Denominator-only_change |
25,359 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5 meet at 15 so the bottom number will be 15 then by adding 1 and 2 = 3 which gives you 3/15 | False_Misconception | Denominator-only_change |
25,360 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5's lcm is 15, and 1+2 is 3 | False_Misconception | Denominator-only_change |
25,361 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 and 5's lcmm is 15, and 1+2 is 3. | False_Misconception | Denominator-only_change |
25,362 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 andd 5 both go into 15 and 1 + 2 = 3 so it’s 3/15 | False_Misconception | Denominator-only_change |
25,363 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 fifteenth's because 1 + 2 = 3 and 5x3 =15 so the end result of the fraction would be b. | False_Misconception | Denominator-only_change |
25,364 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 fifteenth's because 1 + 2 = 3 and 5x3=15 so the end result of the fraction would be b. | False_Misconception | Denominator-only_change |
25,365 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 times 5 = 15 and 2 + 3 = 3 so it woukd be 3 + 15 = 18. | False_Neither | null |
25,366 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 times 5 = 15 which is the denominator then 1+2 = 3 | False_Misconception | Denominator-only_change |
25,367 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 times 5 is 15 so it seemed like the most logical answer | False_Neither | null |
25,368 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 times anything is equal to 15 and so is 5 and 1 plus 2 equals 3 so this is easy to remember. | False_Misconception | Denominator-only_change |
25,369 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3 x 5 is 15, this is the denominator and you add the top ones together | False_Misconception | Denominator-only_change |
25,370 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3/15 15 is 5 timess 3 and 2+3=3. | False_Neither | null |
25,371 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3/15 divided into 1/3 and 2/5 is 1/3. | False_Neither | null |
25,372 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3x5 = 15 andd then 1+2 = 12. | False_Neither | null |
25,373 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3x5 is 15 so 3 + 2 is 3 so you come up with 3/15. | False_Misconception | Denominator-only_change |
25,374 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3x5 is the denominator and thenn you do 1+2=3. | False_Misconception | Denominator-only_change |
25,375 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3x5=15 1+2=3 so it will be 3 over 15 | False_Misconception | Denominator-only_change |
25,376 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3x5=15 1+2=3 so it wilk be 3 over 15. | False_Misconception | Denominator-only_change |
25,377 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3x5=15 and 1+2=3, so it would be 3/15. | False_Misconception | Denominator-only_change |
25,378 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3x5=15 so that its your denominator then just add 1 and 2 | False_Misconception | Denominator-only_change |
25,379 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 3x5=15 so the denominator is 15 and then 1+2=3 which is the numerator. so you end up with 3/15. | False_Misconception | Denominator-only_change |
25,380 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 5 times 3 equals 15 that is the denominator and 1 add 2 equels 3 | False_Misconception | Denominator-only_change |
25,381 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | 5 times 3 equals 15 that is the denominator and 1 plus 2 equal 3 | False_Misconception | Denominator-only_change |
25,382 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | B because you plus on 1 and 2, and you times 3 and 5. | False_Misconception | Denominator-only_change |
25,383 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | B is thee answer because the closest number 3 and 5 both can make is 15,thats why i converted it into 15ths and added the numerators. | False_Misconception | Denominator-only_change |
25,384 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Because l found a common denominator (15) and then added the numberators. | False_Correct | null |
25,385 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Because you change the fractions into the same denominator | False_Neither | null |
25,386 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Because you have to find the CD which is 15, | False_Neither | null |
25,387 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Because you only add the top andd times the bottom. | False_Misconception | Denominator-only_change |
25,388 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Find a common denominator such that the twoo numbers add to 100. | False_Neither | null |
25,389 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Find the common denominator | False_Neither | null |
25,390 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | For the number 15 the lowest common denominator is 15. | False_Neither | null |
25,391 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I am not sure on this one. | False_Neither | null |
25,392 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I changed the denominator to 15, then did 2 + 1=3 so 3/15 is your answer. | False_Misconception | Denominator-only_change |
25,393 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I changed the denominators to 15 then added them and I got 3. | False_Misconception | Denominator-only_change |
25,394 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I did this because I came to the first number in the times table they weree both the same in and added the top. | False_Neither | null |
25,395 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I found a common denominatorr which you couldn't do so times them together which equalled 15 and 1 add 2 equals 3. | False_Misconception | Denominator-only_change |
25,396 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I found what time's tablel the denominator as in then added the numerator. | False_Misconception | Denominator-only_change |
25,397 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I found what timess tablel the denominator as in then added the numerator. | False_Neither | null |
25,398 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I havr to do it again. | False_Neither | null |
25,399 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I just timed the bottom and added the top and it came up with one of the answers here. | False_Misconception | Denominator-only_change |
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