row_id int64 0 36.7k | QuestionId int64 31.8k 109k | QuestionText stringclasses 15
values | MC_Answer stringclasses 49
values | StudentExplanation stringlengths 1 586 | Category stringclasses 6
values | Misconception stringclasses 35
values |
|---|---|---|---|---|---|---|
25,400 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I know this because you have to convert the fractions in to the same denominator which would be 15 and then you add the numerators together and the answer is 3/15 which is partlyy what I was guessing at because I have never done this before. | False_Neither | null |
25,401 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I made the denominator the same and the highest common multiple was 15 then I added the numerators together. | False_Misconception | Denominator-only_change |
25,402 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think it is b because 3 doesn’t go into 5, but 15 does into 3 and 5, so it has to be 3/15. | False_Misconception | Denominator-only_change |
25,403 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think it is because you times the bottom and add the top. | False_Misconception | Denominator-only_change |
25,404 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think its this answer becausr 3 and 5 go in to 15 the bottom then 1+2=3 so its 3/15 | False_Misconception | Denominator-only_change |
25,405 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this because 3 times 5 = 15 then 1 + 2 = 3. | False_Misconception | Denominator-only_change |
25,406 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this because 3 times 5 = 15, then 1 plus 2 =3. | False_Misconception | Denominator-only_change |
25,407 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this because it is this. | False_Neither | null |
25,408 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this because the common denominator is 15, and thenn 2 + 1 is 3, so the answers is 3/15. | False_Misconception | Denominator-only_change |
25,409 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this because the least common multiple for 3 and 5 is 15. | False_Neither | null |
25,410 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this because when adding fractions that don't work immediately you should find the lowest common multiple. | False_Neither | null |
25,411 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this because you add the top which will be 3 then find the common denominator between 3 and 5. | False_Misconception | Denominator-only_change |
25,412 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this because you need to turn it into a common denominator which is 15 then 1 plus 2 equals 3 over 15 and that is how i got my answer. | False_Misconception | Denominator-only_change |
25,413 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this is because when you find the common multiplee of 5 and 3 you get 15, then add the numerators 1 and 2 you got 3 over 15. | False_Misconception | Denominator-only_change |
25,414 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this is because when you make thee denominators the same and add the numerators you get 3/15. | False_Misconception | Denominator-only_change |
25,415 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this is because you add thee numerator and multiply the denominator | False_Neither | null |
25,416 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this is because you make the bottom 15 then + the top together | False_Misconception | Denominator-only_change |
25,417 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this is because you must find the common denominator and then add the numerators together. | False_Misconception | Denominator-only_change |
25,418 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this is correct because 15 is thee closest number in both tables. | False_Neither | null |
25,419 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think this is the answer because I timed the bottom andd the top | False_Neither | null |
25,420 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I think thus is because when you find the common multiple of 5 and 3 you get 15, and then add the numerators 1 and 2, you got 3 over 15. | False_Misconception | Denominator-only_change |
25,421 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I timed 3 by five and that gave me 15 and then added 1 and 2 and so that was 16. | False_Neither | null |
25,422 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I worked it out using my maths skills with fractions. | False_Neither | null |
25,423 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I worked this iut in my revision book | False_Neither | null |
25,424 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I'm kind of guessing but I still don't know. This one seems like the most reasonable one. | False_Neither | null |
25,425 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | I'm not sure if it's 3 or 8 because 1+2 is 3 and 3+5 is 8 but I think it might be 3/8. | False_Misconception | Adding_across |
25,426 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If the common denominator is 15, then 1/15 plus 2/15 is going to be 3/15. | False_Misconception | Denominator-only_change |
25,427 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If the first cimmon denominator is 15, then 1/3 x 5 = 5/15, and 2/5 X 3 = 6/15. 3x1/15 = 3/15 and 3 / 15 = 1/15 | False_Neither | null |
25,428 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If yiu take the whole number and divide it by 2, you get 2, and then you add the two numbers together to get the third number which is 15 and you can add that to the first number to find the remainder which equals 12. | False_Neither | null |
25,429 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you add 3 andd 5 you get 15 as it is rhe nearest number. | False_Neither | null |
25,430 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you converted them to 15ths, then you would get 3/15 after adding them up. | False_Misconception | Denominator-only_change |
25,431 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you have 3 and 5, then times 5 by 3, then that equals 15 then the denominator is 15 so you add 1 and 2 and b is your answer. | False_Misconception | Denominator-only_change |
25,432 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you have two plus one then thst equals three so then you will know that the answer to this question has to be 3/15 | False_Misconception | Denominator-only_change |
25,433 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you made them equal then it would be 15 then you would add 2 and 1 to give you 3. | False_Misconception | Denominator-only_change |
25,434 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you multiply 15 times anything, it comes out to be 3 times 15 becausr you add 1 and 2. | False_Misconception | Denominator-only_change |
25,435 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you multiply 3 and 5 then you get 12, and if you add 15 then it gives you 21, and the denominator is 15. | False_Neither | null |
25,436 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you multiply 3 and 5, then that gives you 15 so that would be your denominator. | False_Neither | null |
25,437 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you need to find the lowest number you times the two bottom ones together then you add 1 and 2 together to get 3. | False_Misconception | Denominator-only_change |
25,438 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you round 3 and 5 and round to 15 thenn it is 3/15. | False_Misconception | Denominator-only_change |
25,439 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you take the first and the second number you get the common denominator which was 15 which is the same number so you add the two together to get 3/15. | False_Misconception | Denominator-only_change |
25,440 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you times 1;3 by 5, you will get 3;15. | False_Neither | null |
25,441 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | If you times the denominators together you get 15 on the bottom then you add the numerators and get 3. | False_Misconception | Denominator-only_change |
25,442 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | It is because 15 is the lowest that appears in the 5 and 3 times tables and 1 + 2 is 3. | False_Misconception | Denominator-only_change |
25,443 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Let the number be the multiplee of 15 then add 1 to 2. | False_Misconception | Denominator-only_change |
25,444 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Make the bottom number the same number that goes into both = 15 then add the top number up which is 3 then put that to the left side and it cant be simplified. | False_Misconception | Denominator-only_change |
25,445 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Since the denominator is 15, then 1+2=3. | False_Misconception | Denominator-only_change |
25,446 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Since u cant make 3 into 5 or 5 into 3 i found the vlosest timetable which was 15 and added the 1 and 2 =3/15. | False_Misconception | Denominator-only_change |
25,447 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So if you find the commonn denominator which is 15 then you add one and two which equals three. | False_Misconception | Denominator-only_change |
25,448 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So it's 3 times 3 andd 1 times 2 and 3 is 3 so it is 1 3 3 15 times 15 so that is 15 3 1 and 2 3 | False_Neither | null |
25,449 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So the answer is 3 over 15. | False_Neither | null |
25,450 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So the first thing to do is to make the denominator the same amd the second thing is do the reciprocal of the third and fifth numbers which is 15 and then 1+2=3 so it's 3/15 which will be the 3rd and 15th. | False_Misconception | Denominator-only_change |
25,451 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So they both have the same denominator that is 15 so 1+2=3. | False_Misconception | Denominator-only_change |
25,452 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So we have to make the denominators the same, thenn we can multiply the numerators. | False_Neither | null |
25,453 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So you do 5x3 which is 15 because you see which number goes into both of the denominators which are 15 so you know which one is 3 which will be 15 and so do 3x15 which would be 15. | False_Neither | null |
25,454 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So you find the common denominator which is 15 andd you add the two numbers together to get 3/15 which equals 3 times 15 which was the number of times the 2 and the 1 went together. | False_Misconception | Denominator-only_change |
25,455 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So you have to multiply the denominators which is 15 and then you add the numerators, which in this case is 3, which gives you 3/15. | False_Misconception | Denominator-only_change |
25,456 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So you need to get the same denominator and you times them together and then add 1+2 then thats the numeratour | False_Misconception | Denominator-only_change |
25,457 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | So your denominator is 15 and you just need to add 1 and 2. | False_Misconception | Denominator-only_change |
25,458 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The answer is 3 because 3 times 5 is equal to 15 and 1 plus 2 equals 3, so the answer must be 3/15. | False_Misconception | Denominator-only_change |
25,459 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The common denominator is 15 so you have to add the top two which is 3 so 15 is the common factor. | False_Misconception | Denominator-only_change |
25,460 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The common denominator was 15, so then I added 2 and 3 whichh gave me 3/15. | False_Misconception | Denominator-only_change |
25,461 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The dominaner is not in the times tables | False_Neither | null |
25,462 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The first step is to find the common denominator, thrn add the two numbers together. | False_Neither | null |
25,463 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The lcm of 3&5 is 15, so you just add the numerators together to get 3. Therefore it's 3/5. | False_Misconception | Denominator-only_change |
25,464 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The least common denomimator for 3 & 5 is 15, so 1/15 plus 2/15 = 3/15. | False_Misconception | Denominator-only_change |
25,465 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The leastt common denominator is 15, 1+2 =3. | False_Misconception | Denominator-only_change |
25,466 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The lowest common multiple of 3 and 5 is 15 so the denominator is 15. 3+2=6 so if the answer is 3 then the fraction is 1 / 3 which is equall to 3 - 1/5. | False_Neither | null |
25,467 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | The two denominators have to be the same 5 x 3 thatll make it 15 and you don the top off it | False_Neither | null |
25,468 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Thee common denominator is 15 and 2+3 is 4. So, the answer is 19. | False_Neither | null |
25,469 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Then addd the numerators together which is 3 because you need to make the denominators the same 15 and add them together. | False_Neither | null |
25,470 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Then you add the numerators whichh was 15 which is equal to 45. The common denominator is 15 so the answer is 45 which simplifies to 15 because the whole number is multiplied by the common factor. | False_Neither | null |
25,471 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | This method will work with any denominators. This will give us the same number of decimal places, and will simplify the whole number. | False_Neither | null |
25,472 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Three and fuve both go in 15 and 3 x 1=3, so it's 3/15. | False_Misconception | Denominator-only_change |
25,473 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Three times 5 is 15 so it seemed like the mist logical answer. | False_Neither | null |
25,474 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Thrre are three ways to do it: 3x5 = 15, 5x3 = 15 and 3 times 3 = 12. | False_Neither | null |
25,475 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | To do the calculation you must make the dominate the same and then and the numerater. | False_Neither | null |
25,476 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | When you multiply the denominator by 15, you get 15, then add 1 amd 2 which is 3/15. | False_Misconception | Denominator-only_change |
25,477 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You change the denominator to 15 because you times 3 amd 5 to get 15 then you add 2 and 1 which gives you 3 the answer is the 3/15 | False_Misconception | Denominator-only_change |
25,478 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You change the denominators to the samee and the whole thing comes out to be the 5 times tables, and you just add the numerator. | False_Neither | null |
25,479 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You have to change the bottom because you cant add them when they are different so you have change it to 15 | False_Misconception | Denominator-only_change |
25,480 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You have to convert the denominator of the first number into a multiple that both 3 and 5 go into (15) and then add the numerators of both numbers. | False_Misconception | Denominator-only_change |
25,481 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You have to convert the denominator to a multiple that both 3 and 5 go into (15) and then add the numerators. | False_Misconception | Denominator-only_change |
25,482 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You have to find the common denominator and then add the top. | False_Misconception | Denominator-only_change |
25,483 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You have to find the lcm which is fifteen and then add one and two which equals three. | False_Misconception | Denominator-only_change |
25,484 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You just add the numbers | False_Neither | null |
25,485 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You multiply 3 and 5 to get 15 and thenn add 1 and 2 toget three. | False_Misconception | Denominator-only_change |
25,486 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You multiply both sidess by 3, which is 15 ; then add the numerators to get the answer 3 over 15 | False_Misconception | Denominator-only_change |
25,487 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You multiply the dominator by the numerator, then add the result. | False_Neither | null |
25,488 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You need to change the denominators to something they both go into, and they go both into 15 | False_Neither | null |
25,489 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You need to find the common denominator, then add the numerators together. | False_Neither | null |
25,490 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You need to find the least common multiple. | False_Neither | null |
25,491 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You need to get the same denominator which is 15 and then you add the numerators like normal | False_Misconception | Denominator-only_change |
25,492 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | You times the bottom and add the top. | False_Misconception | Denominator-only_change |
25,493 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | Youu have to get the fractions with the same denominator | False_Neither | null |
25,494 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | add both numbers but find a common denominator | False_Neither | null |
25,495 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | add by the top ,times by the bottom | False_Neither | null |
25,496 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | add by the top,times by bythe bottom | False_Misconception | Adding_across |
25,497 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | add the first two numbers together and then multiply the second two and you have the answer. | False_Neither | null |
25,498 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | add the numerators and the denominators come out to be 15 thenn add that to the other numbers to find the final number. | False_Neither | null |
25,499 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | add the top two but mulitply the bottom 2 numbers and thats the answer | False_Neither | null |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.