row_id int64 0 36.7k | QuestionId int64 31.8k 109k | QuestionText stringclasses 15
values | MC_Answer stringclasses 49
values | StudentExplanation stringlengths 1 586 | Category stringclasses 6
values | Misconception stringclasses 35
values |
|---|---|---|---|---|---|---|
25,500 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | all you do is change the dint dominators the same which is 15 then add the nominators which makes 3 so it is b | False_Misconception | Denominator-only_change |
25,501 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | and the common denominator is 3 ; the answerr is 1 + 2. | False_Neither | null |
25,502 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | and then you add 1 and 2 to make 15. | False_Neither | null |
25,503 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | and then you have to make a common drnominator and 3 and 5 both go into 15 so that is how i got 3/15 | False_Misconception | Denominator-only_change |
25,504 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because 1+2=3 and then you have to make a common denominator and 3 and 5 both go into 15 that is how i got 3/15 | False_Misconception | Denominator-only_change |
25,505 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because 1/3 + 2/5 you can’t do so you would then have to convert 1/3 into 1/15 and 2/5 into 2/15 add them together you get 3/15 | False_Misconception | Denominator-only_change |
25,506 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because 1/3 + 2/5 youu cant do you would have to convert 1/3 into 1/15 and 2/15 into 2/1 putting them together you get 3/15 | False_Misconception | Denominator-only_change |
25,507 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because 3 times 5 is 15 and 2 + 3 = 5. | False_Neither | null |
25,508 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because 3x5=15 so the denometer would be 15 and add 2 and 1 together that make 3 so that would make the answer would 3/15. | False_Misconception | Denominator-only_change |
25,509 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because 3x5=15 so the denometer would be 15 and add 2 and 1 together that make 3 so the answer would be 3/15 | False_Misconception | Denominator-only_change |
25,510 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because if you have 2 plus 1 then that will equel 3 so then you will know that the answer to this question has to be 3/15 | False_Misconception | Denominator-only_change |
25,511 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because u times the denominator by the other denotinar and add two add one so your answer is a. | False_Neither | null |
25,512 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b because you plus on 1 and 2 and you times 3 and 5 | False_Misconception | Denominator-only_change |
25,513 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | b is the answer because the closest number 3 and five both can make is 15,thats why i converted it into 15ths and added the numerators. | False_Misconception | Denominator-only_change |
25,514 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 x 5 = 15 so 15 is the denominator
1 + 2 = 3 so the answer would be 3/15 | False_Misconception | Denominator-only_change |
25,515 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 1+2 =3 and 3 and 5 are in the 15 times table | False_Misconception | Denominator-only_change |
25,516 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 1+2 =3 and 3 and 5 are in the 15 times table. | False_Misconception | Denominator-only_change |
25,517 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 1+2 is 3 and 3+5 is 8 so that answer could be 3/8 but again i'm not really sure. | False_Misconception | Adding_across |
25,518 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 1+2=3
3 and 5 both go into 15 | False_Misconception | Denominator-only_change |
25,519 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 1+2=3 3 and 5 both go into 15 | False_Misconception | Denominator-only_change |
25,520 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 1+2=3 and the lowest common multiple is 15 | False_Misconception | Denominator-only_change |
25,521 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 15 goes into 3 and 5 so that becomes the denominator and 1 +2 =3 | False_Misconception | Denominator-only_change |
25,522 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 15 is in both timestables | False_Neither | null |
25,523 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 15 is in the 3 and 5 timetables | False_Neither | null |
25,524 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 15 is in the 3 and 5 timetables | False_Neither | null |
25,525 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 15 is the lowest denominator for 3 and 5 | False_Neither | null |
25,526 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 2/5=6/15 and 1/3=5/15 add them together you get 11/15 | False_Correct | null |
25,527 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 and 5 both go into 15 and 2+1=3 so its b | False_Misconception | Denominator-only_change |
25,528 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 and 5 both go into 15 and 2 + 3 = 3 so its b | False_Misconception | Denominator-only_change |
25,529 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 and 5 both go into 15 and not 8 and the numerator is 3 because 1+2 = 3 | False_Misconception | Denominator-only_change |
25,530 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 and 5 go into 15 so that would be you denominator | False_Neither | null |
25,531 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 and 5 meet at 15 making the bottom number 15 then by adding 1+2 = 3 which gives you 3/15 | False_Misconception | Denominator-only_change |
25,532 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 and 5 so that bevomes the denominator and 1 plus 2 =3 | False_Neither | null |
25,533 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 and 5 timee table have the number 15 and 1+2 is 3 | False_Misconception | Denominator-only_change |
25,534 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 snd 5 are multiples of 15 and because 15 is the lowest denominator for those three and five numbers. | False_Neither | null |
25,535 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3 times 5 is 15 and then you just add the top ones together | False_Misconception | Denominator-only_change |
25,536 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3x5 = 15 and 1x5=5 and then 2x3=6 and 5+6=11 | False_Correct | null |
25,537 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3x5 =15 so that's the denominator and 1+2=3 so that's the numerator | False_Misconception | Denominator-only_change |
25,538 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3x5 is 15 so 1+2 is 3 you come up with3/15 | False_Misconception | Denominator-only_change |
25,539 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3x5 is the denominator and then you do 1+2=3 | False_Misconception | Denominator-only_change |
25,540 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 3x5=15 and 1+2= 3 so it would be 3/15 | False_Misconception | Denominator-only_change |
25,541 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 5 and 3 both go into 15 | False_Neither | null |
25,542 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 5 and 3 both go into 15. | False_Correct | null |
25,543 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 5*3 =15 and 1+2 =3 so the answer is 3/15. | False_Misconception | Denominator-only_change |
25,544 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because 5x3is 15 spit will be the denominator and then u just add the top numbers | False_Misconception | Denominator-only_change |
25,545 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because a number that goes into 3 and 5 is 15 and then you just add the numerators | False_Neither | null |
25,546 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because all you do is change the dint dominators the same which is 15 then add the nominators which makes 3 so it is b | False_Misconception | Denominator-only_change |
25,547 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because convert both 3 5 so they both have the same denominator that is 15 so 1+2=3 | False_Misconception | Denominator-only_change |
25,548 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because i changed the denominator to 15 then did 2+1=3 so 3/15 is your answer | False_Misconception | Denominator-only_change |
25,549 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because i done 3 times 5and i got 15 and then i added the top number together too get the awnser | False_Misconception | Denominator-only_change |
25,550 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because i found the common multiple of 3 and 5 which is 15, kept the denominators the same and added the numeratorsame (1 and 2) together and got my answer! | False_Misconception | Adding_across |
25,551 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because i made them the same denominator (15) and added 1 + 2 = 3 | False_Misconception | Denominator-only_change |
25,552 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because if you do 1+2 is 3, after that you do 3x5 which is 15
so you get 3/15 | False_Misconception | Denominator-only_change |
25,553 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because if you do 3x5 = 15 and then 1+2 | False_Misconception | Denominator-only_change |
25,554 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because if you have 3 and 5 then times 5 by 3 and that equals 15 so the denominator is 15 then add 1 and 2 and b is your answer | False_Misconception | Denominator-only_change |
25,555 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because if you make the same dominator the same then add them together it is 3/15 | False_Misconception | Denominator-only_change |
25,556 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because if you times the denominators together you get 15 on the bottom then you add the numerators and get 3 | False_Misconception | Denominator-only_change |
25,557 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because it is the correct answer | False_Neither | null |
25,558 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because it is the correct answer | False_Neither | null |
25,559 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because l found a common denominator (15) and then added the numberators. | False_Neither | null |
25,560 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because since u cant make 3 into 5 or 5 into 3 i found the most closes same time table which was 15 and added the 1 and 2 =3/15. | False_Misconception | Denominator-only_change |
25,561 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the common denominator in 3 and 5 is 15 and 1+2=3 | False_Misconception | Denominator-only_change |
25,562 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the common denominator is 15 (it divides into both 3 and 5) and 1+2 is 3. if you were to simplify the answer, you'd get 1/5 | False_Misconception | Denominator-only_change |
25,563 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the common denominatorr in 3 and 5 is 15, and 1+2=3. | False_Misconception | Denominator-only_change |
25,564 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the denominators are different and they both have 15 in there multiples, then you add the numerators together which makes 3 over 15. | False_Misconception | Denominator-only_change |
25,565 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the denominators are different and they both have 15 in there multiples. then you add the numerators together which makes 3 over 15. | False_Misconception | Denominator-only_change |
25,566 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the dinominater must be the same and 2 + 1 = 3 and 15 is in both 3 times tables and 5 times table | False_Misconception | Denominator-only_change |
25,567 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the dinominater must be the same and 2+1 =3 and 15 is in both 3 times tables and 5 times table | False_Misconception | Denominator-only_change |
25,568 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the highest number you can get in the 3s and 5s is 15 so the bottom would be 15 and the top will be three because of 1+2=3 | False_Misconception | Denominator-only_change |
25,569 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the lcm of the denominator is 15 and then 1+2=3 | False_Misconception | Denominator-only_change |
25,570 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the lowest common denominator is 15 so then you do three add two and that equals 3/15. | False_Misconception | Denominator-only_change |
25,571 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the lowest common multipul of 3 and 5 is 15 sothe answer is 3/15 | False_Neither | null |
25,572 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because the lowest lcm of them both are 15 and 2+1=3 | False_Misconception | Denominator-only_change |
25,573 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because they both go into 15 | False_Neither | null |
25,574 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because to me keep it easier you need a number that is in the three and five times table and fifteen is one of them so you add one and two together which is three and then it is three fiteenths | False_Misconception | Denominator-only_change |
25,575 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because u have to do 3x5 equal 15 and 5x3 equal 15 | False_Neither | null |
25,576 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because we must first make the denominators the same so we could multiply the denominators and then add the numerators | False_Neither | null |
25,577 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you add the top and times the bottom | False_Misconception | Denominator-only_change |
25,578 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you add the top and times the bottom. | False_Neither | null |
25,579 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you add the top fraction and then find a number that is in both the lower fractions timetables | False_Misconception | Denominator-only_change |
25,580 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you add the top fraction and then find a number that is in both the lower fractions timetables | False_Misconception | Denominator-only_change |
25,581 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you add them to gaver | False_Neither | null |
25,582 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you both bottom numbers have to be in the same times tables and then add the top two | False_Neither | null |
25,583 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you cant find the lcm so you x | False_Neither | null |
25,584 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you convert the fractions into the same denominator | False_Neither | null |
25,585 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you covert the denominators to their common denominator which is 15 and then you can add the numerators | False_Misconception | Denominator-only_change |
25,586 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you find out the common denominator (which is 15) , make both the denominators 15 and then add them | False_Misconception | Denominator-only_change |
25,587 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you find the common denominater which is 15 then you add one and two which is three | False_Misconception | Denominator-only_change |
25,588 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you find the common denominator | False_Neither | null |
25,589 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you find the common denominator and add the two together | False_Neither | null |
25,590 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you have to find the common denominator than add the top | False_Neither | null |
25,591 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you have to find the lcm which is fifteen and then add one and two which is three | False_Misconception | Denominator-only_change |
25,592 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you have to find the lowest common multiple | False_Neither | null |
25,593 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you have to get the denominators the same so 15 so x the one by 5 and the 2 by three so 6 and 6+5=11 | False_Correct | null |
25,594 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you have to make the denominator so the same and the simulartys for 3 and 5 is 15 and then 1+2=3 so it's 3/15 | False_Misconception | Denominator-only_change |
25,595 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you have to make the denominators the same numbers then you have to add the top numbers. that makes 3/15 | False_Misconception | Denominator-only_change |
25,596 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you have to make the nemarater the same | False_Neither | null |
25,597 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you just add the numbers | False_Neither | null |
25,598 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you multiply the dominator and add the numerator | False_Neither | null |
25,599 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to add 1+2 and then x 3+5. | False_Misconception | Adding_across |
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