Unnamed: 0 int64 0 999 | name stringlengths 9 60 | description stringlengths 168 5.26k | solution stringlengths 38 20.8k |
|---|---|---|---|
300 | 625_A. Guest From the Past | Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much more complicated.
Kolya is hungry, so he went to the nearest milk shop. In 2084 you may buy kefir in a plas... | n=(int)(input());
a=(int)(input());
b=(int)(input());
c=(int)(input());
cnt=a;
cnt=0;
cnt1=a;
cnt1=(int)(n//a);
if (n<b):
while (n//b>0):
cnt+=n//b;
n-=(n//b)*b-n//b*c;
#print (n," ",cnt);
#print(n//a," ",cnt," ",cnt+n//a);
cnt+=n//a;
print((int)(max(cnt,cnt1)));
else:
n-=b;
... |
301 | 673_C. Bear and Colors | Bear Limak has n colored balls, arranged in one long row. Balls are numbered 1 through n, from left to right. There are n possible colors, also numbered 1 through n. The i-th ball has color ti.
For a fixed interval (set of consecutive elements) of balls we can define a dominant color. It's a color occurring the bigges... | def main():
n = int(input())
a = [int(i) for i in input().strip().split()]
res = [0] * n
for st in range(n):
cnt = [0] * n
x = 0
y = 0
for ed in range(st, n):
cnt[a[ed] - 1] += 1
if (cnt[a[ed] - 1] > x) or (cnt[a[ed] - 1] == x and a[ed] - 1 < y):... |
302 | 740_B. Alyona and flowers | Little Alyona is celebrating Happy Birthday! Her mother has an array of n flowers. Each flower has some mood, the mood of i-th flower is ai. The mood can be positive, zero or negative.
Let's define a subarray as a segment of consecutive flowers. The mother suggested some set of subarrays. Alyona wants to choose severa... | I=lambda:map(int,input().split())
R=range
ans=0
n,m=I()
a=list(I())
for _ in R(m):l,r=I();ans+=max(0,sum(a[i]for i in R(l-1,r)))
print(ans) |
303 | 764_A. Taymyr is calling you | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every n minutes, i.e. in minutes n, 2n, 3n and so on. Artists come to the comrade every m minutes, i.e. in minutes m, 2m, 3m and so on. The day is z minutes long, i.e. the day cons... | from math import *
def lcm(a, b): return a*b//gcd(a, b)
n, m, z = map(int, input().split())
print(z//lcm(n, m))
|
304 | 787_C. Berzerk | Rick and Morty are playing their own version of Berzerk (which has nothing in common with the famous Berzerk game). This game needs a huge space, so they play it with a computer.
In this game there are n objects numbered from 1 to n arranged in a circle (in clockwise order). Object number 1 is a black hole and the oth... | import queue
n = int(input())
sR = list(map(int, input().split()[1:]))
sM = list(map(int, input().split()[1:]))
s = [sR, sM]
UNK = -1
WIN = 2
LOSE = 3
A = [[UNK] * n for i in range(2)]
CNT = [[0] * n for i in range(2)]
V = [[False] * n for i in range(2)]
# ricky turn 0
# morty turn 1
A[0][0] = LOSE
A[1][0] = LOSE
... |
305 | 808_G. Anthem of Berland | Berland has a long and glorious history. To increase awareness about it among younger citizens, King of Berland decided to compose an anthem.
Though there are lots and lots of victories in history of Berland, there is the one that stand out the most. King wants to mention it in the anthem as many times as possible.
H... | def prefix(st):
t = 0
p = [0] * (len(st) + 1)
o = [0] * (len(st) + 1)
for i in range(2, len(st)):
while t > 0 and st[i] != st[t + 1]:
t = p[t]
if st[i] == st[t + 1]:
t += 1
p[i] = t
while t > 0:
o[t] = 1
t = p[t]
return o
s = ' ' ... |
306 | 854_A. Fraction | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction <image> is called proper iff its numerator is smaller than its denominator (a < b) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive comm... | import math
n=int(input())
d=n//2
c=n-d
while math.gcd(c,d)!=1:
c+=1
d-=1
print(d,c)
|
307 | 902_A. Visiting a Friend | Pig is visiting a friend.
Pig's house is located at point 0, and his friend's house is located at point m on an axis.
Pig can use teleports to move along the axis.
To use a teleport, Pig should come to a certain point (where the teleport is located) and choose where to move: for each teleport there is the rightmost ... | n, m = list( map( int, input().split() ) )
A = []
B = []
CanReach = []
start_idx = 0
end_idx = 0
for i in range( n ):
a, b = list( map( int, input().split() ) )
A.append( a )
B.append( b )
memo = {}
def best( i ):
if A[i] <= m <= B[i]:
return ( True )
if i in memo:
return memo... |
308 | 924_C. Riverside Curio | Arkady decides to observe a river for n consecutive days. The river's water level on each day is equal to some real value.
Arkady goes to the riverside each day and makes a mark on the side of the channel at the height of the water level, but if it coincides with a mark made before, no new mark is created. The water d... | N = int(input())
above = list(map(int, input().split()))
if N == 1:
print(0)
quit()
required_mark = [0] * N
required_mark[N-2] = above[N-1]
for i in reversed(range(N-2)):
required_mark[i] = max(above[i+1], required_mark[i+1] - 1)
d = 0
mark = 1
for i in range(1, N):
if mark == above[i]:
mark ... |
309 | 952_E. Cheese Board | Not to be confused with [chessboard](https://en.wikipedia.org/wiki/Chessboard).
<image>
Input
The first line of input contains a single integer N (1 β€ N β€ 100) β the number of cheeses you have.
The next N lines describe the cheeses you have. Each line contains two space-separated strings: the name of the cheese and... | a, b = 0, 0
n = int(input())
for i in range(n):
x, y = input().split()
if y == 'soft':
a += 1
else:
b += 1
for i in range(1, 1000):
n = i*i
y = n // 2
x = n - y
if (a <= x and b <= y) or (a <= y and b <= x):
print(i)
break |
310 | 99_B. Help Chef Gerasim | In a far away kingdom young pages help to set the table for the King. As they are terribly mischievous, one needs to keep an eye on the control whether they have set everything correctly. This time the royal chef Gerasim had the impression that the pages have played a prank again: they had poured the juice from one cup... | n = int(input())
arr = [int(input()) for _ in range(n)]
if len(set(arr)) == 1:
print('Exemplary pages.')
elif len(set(arr)) > 3:
print('Unrecoverable configuration.')
else:
kek = set(arr)
kek = list(kek)
kek.sort()
val = kek[-1] - kek[0]
if val % 2 == 1:
print('Unrecoverable configur... |
311 | 1000_A. Codehorses T-shirts | Codehorses has just hosted the second Codehorses Cup. This year, the same as the previous one, organizers are giving T-shirts for the winners.
The valid sizes of T-shirts are either "M" or from 0 to 3 "X" followed by "S" or "L". For example, sizes "M", "XXS", "L", "XXXL" are valid and "XM", "Z", "XXXXL" are not.
Ther... | t=int(input())
pre=[]
curr=[]
for i in range(t):
s1=input()
pre.append(s1)
for i in range(t):
s2=input()
curr.append(s2)
z=0
for i in range(t):
if pre[i] in curr:
curr.remove(pre[i])
pass
else:
z+=1
print(z) |
312 | 1025_B. Weakened Common Divisor | During the research on properties of the greatest common divisor (GCD) of a set of numbers, Ildar, a famous mathematician, introduced a brand new concept of the weakened common divisor (WCD) of a list of pairs of integers.
For a given list of pairs of integers (a_1, b_1), (a_2, b_2), ..., (a_n, b_n) their WCD is arbit... | def gcd(a,b):
if a%b==0:
return b
else:
return gcd(b,a%b)
import math
def pr(n):
a=[]
while n % 2 == 0:
a.append(2)
n = n / 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
a.append(i)
n = n /... |
313 | 1068_D. Array Without Local Maximums | Ivan unexpectedly saw a present from one of his previous birthdays. It is array of n numbers from 1 to 200. Array is old and some numbers are hard to read. Ivan remembers that for all elements at least one of its neighbours ls not less than it, more formally:
a_{1} β€ a_{2},
a_{n} β€ a_{n-1} and
a_{i} β€ max(a_{i-1}, ... | import os
from io import BytesIO
from math import trunc
if os.name == 'nt':
input = BytesIO(os.read(0, os.fstat(0).st_size)).readline
MX = 201
MOD = 998244353
MODF = float(MOD)
MODF_inv = 1.0 / MODF
quickmod1 = lambda x: x - MODF * trunc(x / MODF)
def quickmod(a):
return a - MODF * trunc(a * MODF_inv)
de... |
314 | 1139_C. Edgy Trees | You are given a tree (a connected undirected graph without cycles) of n vertices. Each of the n - 1 edges of the tree is colored in either black or red.
You are also given an integer k. Consider sequences of k vertices. Let's call a sequence [a_1, a_2, β¦, a_k] good if it satisfies the following criterion:
* We will... | kk=lambda:map(int,input().split())
ll=lambda:list(kk())
n, k = kk()
dsud = {i:{i} for i in range(n)}
dsup = {i:i for i in range(n)}
for _ in range(n-1):
u, v, xi = kk()
u,v = u-1,v-1
if xi == 0:
s1, s2 = dsud[dsup[u]], dsud[dsup[v]]
if len(s1) > len(s2):
s1 |= s2
del dsud[dsup[v]]
for el in s2:
dsup... |
315 | 1157_C2. Increasing Subsequence (hard version) | The only difference between problems C1 and C2 is that all values in input of problem C1 are distinct (this condition may be false for problem C2).
You are given a sequence a consisting of n integers.
You are making a sequence of moves. During each move you must take either the leftmost element of the sequence or the... |
import sys
sys.setrecursionlimit(10**7)
N = int(input())
number = list(map(int, input().split()))
seq = []
ans = []
l = 0
r = N-1
def correct(ans, l, r, action):
for i in range(len(ans)-1, -1, -1):
if not ans[i] == 'X':
break
ans[i] = action
if action == 'L':
r ... |
316 | 1198_A. MP3 | One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
If there are exactly K distinct values in the array, then we need k = β log_{2} ... | import math
n, m = map(int, input().strip().split())
a = list(map(int, input().strip().split()))
a.sort()
lastval = -1
b = list()
for x in a:
if x != lastval:
b.append(1)
lastval = x
else:
b[-1] += 1
k = len(b)
while k > (1 << ((8*m)//n)):
k -= 1
ans = 0
for x in range(k):
ans += b[x]
res = ans
for x... |
317 | 1238_B. Kill 'Em All | Ivan plays an old action game called Heretic. He's stuck on one of the final levels of this game, so he needs some help with killing the monsters.
The main part of the level is a large corridor (so large and narrow that it can be represented as an infinite coordinate line). The corridor is divided into two parts; let'... | import sys
def input():
str = sys.stdin.readline()
return str[:-1]
def unique(x, first, last):
if first == last:
return last
result = first
while first + 1 != last:
first += 1
if(x[result] != x[first]):
result += 1
x[result] = x[first]
return resul... |
318 | 1256_C. Platforms Jumping | There is a river of width n. The left bank of the river is cell 0 and the right bank is cell n + 1 (more formally, the river can be represented as a sequence of n + 2 cells numbered from 0 to n + 1). There are also m wooden platforms on a river, the i-th platform has length c_i (so the i-th platform takes c_i consecuti... | from collections import defaultdict
import sys
input=sys.stdin.readline
n,m,d=map(int,input().split())
c=[int(i) for i in input().split()]
ind=defaultdict(int)
suff=n
for i in range(m-1,-1,-1):
suff-=c[i]
ind[i+1]=suff+1
indl=[]
for i in ind:
indl.append(i)
indl.reverse()
cur=0
for i in indl:
if ind[i]-... |
319 | 127_C. Hot Bath | Bob is about to take a hot bath.
There are two taps to fill the bath: a hot water tap and a cold water tap. The cold water's temperature is t1, and the hot water's temperature is t2. The cold water tap can transmit any integer number of water units per second from 0 to x1, inclusive. Similarly, the hot water tap can ... | import math
def gcd(a,b):
if(b==0):
return a
return gcd(b,a%b)
l=input().split()
t1=int(l[0])
t2=int(l[1])
x1=int(l[2])
x2=int(l[3])
t0=int(l[4])
num1=t2-t0
num2=t0-t1
if(t1==t2):
print(x1,x2)
quit()
if(num1==0):
print(0,x2)
quit()
if(num2==0):
print(x1,0)
quit()
z=num2/num1
maxa... |
320 | 12_B. Correct Solution? | One cold winter evening Alice and her older brother Bob was sitting at home near the fireplace and giving each other interesting problems to solve. When it was Alice's turn, she told the number n to Bob and said:
βShuffle the digits in this number in order to obtain the smallest possible number without leading zeroes.... | def sort(s):
return sorted(sorted(s), key=str.upper)
s=input()
s1=input()
l=sort(s)
c=l.count('0')
res=""
if(len(l)>c):
res=res+l[c]
for i in range(c):
res=res+l[i]
for i in range(c+1,len(s)):
res=res+l[i]
if(s1==res):
print("OK")
else:
print("WRONG_ANSWER") |
321 | 1323_D. Present | Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for each one she came up with. But when she came up with another one β xor of all pairwise sums of elements in the array, she realiz... | from bisect import bisect_left, bisect_right
def go():
n = int(input())
a = list(map(int, input().split()))
b = max(a).bit_length()
res = 0
vals = a
for i in range(b + 1):
# print("")
b2 = 2 << i
b1 = 1 << i
a0 = [aa for aa in a if aa & b1==0]
a1 = [aa f... |
322 | 1364_C. Ehab and Prefix MEXs | Given an array a of length n, find another array, b, of length n such that:
* for each i (1 β€ i β€ n) MEX(\\{b_1, b_2, β¦, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
If such array doesn't exist, determine this.
Input
The first line contains an ... | n=int(input())
arr=list(map(int,input().split()))
flag=0
vis=[0]*(10**6+1)
for i in range(n):
if arr[i]>i+1:
flag=1
vis[arr[i]]=1
if flag==1:
print(-1)
quit()
b=[-1]*(n)
for i in range(1,n):
if arr[i-1]!=arr[i]:
b[i]=arr[i-1]
not_vis=[]
for i in range(10**6+1):
if vis[i]==0:
... |
323 | 1406_A. Subset Mex | Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the smallest non-negative integer that doesn't exist in the set. For example:
* m... | t=int(input())
while t!=0:
t-=1
n=int(input())
li=list(map(int,input().split()))
dic={}
dic2={}
a=0
b=0
flag=0
ans=[0]*101
for i in li:
if i not in dic and i not in dic2:
dic[i]=1
else:
ans[i]=1
dic2[i]=1
if i in dic... |
324 | 149_B. Martian Clock | Having stayed home alone, Petya decided to watch forbidden films on the Net in secret. "What ungentlemanly behavior!" β you can say that, of course, but don't be too harsh on the kid. In his country films about the Martians and other extraterrestrial civilizations are forbidden. It was very unfair to Petya as he adored... | s = input()
a = s[:s.index(":")]
b = s[s.index(":")+1:]
a2 = ''
b2 = ''
found = False
for i in a:
if i!='0':
found = True
if found:
a2+=i
found = False
for i in b:
if i!='0':
found = True
if found:
b2+=i
a = a2
b = b2
apos = []
bpos = []
values = ['0', '1', '2'... |
325 | 155_A. I_love_%username% | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | n=int(input())
a=list(map(int,input().split()))
c=[]
d=0
c.append(a[0])
for i in range(1,n):
y=a[i]-a[i-1]
if y>0 and a[i]>max(c):
c.append(a[i])
d+=1
elif y<0 and a[i]<min(c):
c.append(a[i])
d+=1
print(d)
#print(c) |
326 | 177_C1. Party | To celebrate the second ABBYY Cup tournament, the Smart Beaver decided to throw a party. The Beaver has a lot of acquaintances, some of them are friends with each other, and some of them dislike each other. To make party successful, the Smart Beaver wants to invite only those of his friends who are connected by friends... | # maa chudaaye duniya
n = int(input())
parents = [i for i in range(n+1)]
ranks = [1 for i in range(n+1)]
def find(x):
if parents[x] != x:
parents[x] = find(parents[x])
return parents[x]
def union(x, y):
xs = find(x)
ys = find(y)
if xs == ys:
return
if ranks[xs] > ranks[ys]:
parents[ys] = xs
elif ranks[ys... |
327 | 198_B. Jumping on Walls | Vasya plays a computer game with ninjas. At this stage Vasya's ninja should get out of a deep canyon.
The canyon consists of two vertical parallel walls, their height is n meters. Let's imagine that we split these walls into 1 meter-long areas and number them with positive integers from 1 to n from bottom to top. Some... | from sys import stdin, stdout
from collections import deque
n, k = map(int, stdin.readline().split())
maps = []
maps.append(list(stdin.readline() + '-'))
maps.append(list(stdin.readline() + '-'))
visit = [[0, 0] for i in range(n + 1)]
visit[0][0] = 1
queue = deque()
label = 0
queue.append((0, -1, 0))#ΡΠ²ΠΎΠΉ ΡΡΠΎΠ²Π΅Π½Ρ, ... |
328 | 221_C. Little Elephant and Problem | The Little Elephant has got a problem β somebody has been touching his sorted by non-decreasing array a of length n and possibly swapped some elements of the array.
The Little Elephant doesn't want to call the police until he understands if he could have accidentally changed the array himself. He thinks that he could ... | n = int(input())
a = list(map(int, input().split()))
b = sorted(a)
res = 0
for i in range(n):
if a[i] != b[i]:
res += 1
print('YES' if res <= 2 else 'NO') |
329 | 245_D. Restoring Table | Recently Polycarpus has learned the "bitwise AND" operation (which is also called "AND") of non-negative integers. Now he wants to demonstrate the school IT teacher his superb manipulation with the learned operation.
For that Polycarpus came to school a little earlier and wrote on the board a sequence of non-negative ... | n=int(input())
A=[0]*n
ans=[0]*n
for i in range(n):
A[i]=list(map(int,input().split()))
for j in range(n):
if(j==i):continue
ans[i]|=A[i][j]
for i in range(n):
print(ans[i],' ',end='')
|
330 | 270_B. Multithreading | Emuskald is addicted to Codeforces, and keeps refreshing the main page not to miss any changes in the "recent actions" list. He likes to read thread conversations where each thread consists of multiple messages.
Recent actions shows a list of n different threads ordered by the time of the latest message in the thread.... | n = int(input())
arr = list(map(int,input().split()))
ans = n-1
for i in range(-1,-n,-1):
if arr[i]>arr[i-1]:
ans-=1
else:
break
print(ans) |
331 | 317_B. Ants | It has been noted that if some ants are put in the junctions of the graphene integer lattice then they will act in the following fashion: every minute at each junction (x, y) containing at least four ants a group of four ants will be formed, and these four ants will scatter to the neighbouring junctions (x + 1, y), (x ... | from sys import *
f = lambda: map(int, stdin.readline().split())
n, t = f()
m = 65
r = range(m)
p = [[0] * m for i in r]
p[1][0] = n // 4
p[0][0] = n % 4
q = k = 1
while q:
k += 1
q = 0
for x in r[1:k]:
for y in r[:x + 1]:
if p[x][y] < 4: continue
q = 1
d = ... |
332 | 341_B. Bubble Sort Graph | Iahub recently has learned Bubble Sort, an algorithm that is used to sort a permutation with n elements a1, a2, ..., an in ascending order. He is bored of this so simple algorithm, so he invents his own graph. The graph (let's call it G) initially has n vertices and 0 edges. During Bubble Sort execution, edges appear a... | from bisect import bisect_left, bisect_right, insort
R = lambda: map(int, input().split())
n, arr = int(input()), list(R())
dp = []
for i in range(n):
idx = bisect_left(dp, arr[i])
if idx >= len(dp):
dp.append(arr[i])
else:
dp[idx] = arr[i]
print(len(dp)) |
333 | 388_C. Fox and Card Game | Fox Ciel is playing a card game with her friend Fox Jiro. There are n piles of cards on the table. And there is a positive integer on each card.
The players take turns and Ciel takes the first turn. In Ciel's turn she takes a card from the top of any non-empty pile, and in Jiro's turn he takes a card from the bottom o... | import re
def main():
n=eval(input())
a=[]
s=[]
s.append(0)
s.append(0)
while n:
n-=1
temp=re.split(' ',input())
k=eval(temp[0])
for i in range(k>>1):
s[0]+=eval(temp[i+1])
if k&1:
a.append(eval(temp[(k+1)>>1]))
for i in range((k+1)>>1,k):
s[1]+=eval(temp[i+1])
a... |
334 | 436_B. Om Nom and Spiders | Om Nom really likes candies and doesn't like spiders as they frequently steal candies. One day Om Nom fancied a walk in a park. Unfortunately, the park has some spiders and Om Nom doesn't want to see them at all.
<image>
The park can be represented as a rectangular n Γ m field. The park has k spiders, each spider at ... | #!/usr/bin/python
import re
import inspect
from sys import argv, exit
def rstr():
return input()
def rint():
return int(input())
def rints(splitchar=' '):
return [int(i) for i in input().split(splitchar)]
def varnames(obj, namespace=globals()):
return [name for name in namespace if namespace[name] i... |
335 | 480_B. Long Jumps | Valery is a PE teacher at a school in Berland. Soon the students are going to take a test in long jumps, and Valery has lost his favorite ruler!
However, there is no reason for disappointment, as Valery has found another ruler, its length is l centimeters. The ruler already has n marks, with which he can make measure... | def main():
from bisect import bisect_left
n, l, x, y = map(int, input().split())
aa, d = list(map(int, input().split())), {}
for z in (x, y, y + x):
for a in aa:
a += z
if a > l:
break
b = aa[bisect_left(aa, a)]
if b <= a:
... |
336 | 505_B. Mr. Kitayuta's Colorful Graph | Mr. Kitayuta has just bought an undirected graph consisting of n vertices and m edges. The vertices of the graph are numbered from 1 to n. Each edge, namely edge i, has a color ci, connecting vertex ai and bi.
Mr. Kitayuta wants you to process the following q queries.
In the i-th query, he gives you two integers β ui... | def build_graph():
line1 = input().strip().split()
n = int(line1[0])
m = int(line1[1])
graph = {}
for _ in range(m):
line = input().strip().split()
u = int(line[0])
v = int(line[1])
c = int(line[2])
if c not in graph:
graph[c] = {j: [] for j in ran... |
337 | 554_C. Kyoya and Colored Balls | Kyoya Ootori has a bag with n colored balls that are colored with k different colors. The colors are labeled from 1 to k. Balls of the same color are indistinguishable. He draws balls from the bag one by one until the bag is empty. He noticed that he drew the last ball of color i before drawing the last ball of color i... | from sys import stdin
c = [[0]*1002 for _ in range(0,1002)]
MOD = int(1e9+7)
for i in range(0,1002):
c[i][0] = c[i][i] = 1
for j in range(0,i):
c[i][j] = (c[i-1][j-1] + c[i-1][j])%MOD
r = map(int,stdin.read().split())
n = next(r)
ans = 1
sum = 0
for _ in range(0,n):
x = next(r)
ans = (ans * ... |
338 | 580_B. Kefa and Company | Kefa wants to celebrate his first big salary by going to restaurant. However, he needs company.
Kefa has n friends, each friend will agree to go to the restaurant if Kefa asks. Each friend is characterized by the amount of money he has and the friendship factor in respect to Kefa. The parrot doesn't want any friend t... | n, d = map(int, input().split())
v = []
for i in range(0, n):
a, b = map(int, input().split())
v.append((a, b))
v = sorted(v)
lo = 0
totalFriendship = v[0][1]
bestFriendship = totalFriendship
for i in range(1, n):
while v[i][0] - v[lo][0] >= d:
totalFriendship -= v[lo][1]
lo += 1
to... |
339 | 602_A. Two Bases | After seeing the "ALL YOUR BASE ARE BELONG TO US" meme for the first time, numbers X and Y realised that they have different bases, which complicated their relations.
You're given a number X represented in base bx and a number Y represented in base by. Compare those two numbers.
Input
The first line of the input con... | # print ("Input digits and base for number one")
n1, b1 = (int(x) for x in input().split())
# print ("Input all the digits")
d1 = list(int(x) for x in input().split())
d1.reverse()
# print ("Input digits and base for number two")
n2, b2 = (int(x) for x in input().split())
# print ("Input all the digits")
d2 = list(int... |
340 | 673_A. Bear and Game | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be n interesting minutes t1, t2, ..., tn. Yo... | n=int(input())
tl = list(map(int, input().split()))
time=cnt=0
while cnt <15 and time<90:
time+=1
if tl.count(time)>0:
cnt=0
else:
cnt+=1
print(time) |
341 | 698_B. Fix a Tree | A tree is an undirected connected graph without cycles.
Let's consider a rooted undirected tree with n vertices, numbered 1 through n. There are many ways to represent such a tree. One way is to create an array with n integers p1, p2, ..., pn, where pi denotes a parent of vertex i (here, for convenience a root is cons... | from collections import defaultdict
from sys import stdin,setrecursionlimit
setrecursionlimit(10**6)
import threading
def f(a):
n=len(a)
a=list(map(lambda s:s-1,a))
root=None
for i in range(len(a)):
if a[i]==i:
root=i
vis=[0]*(n)
traitors=[]
for i in range(0,n):
cycle=-1
cur=i
move=set()
while vis... |
342 | 719_B. Anatoly and Cockroaches | Anatoly lives in the university dorm as many other students do. As you know, cockroaches are also living there together with students. Cockroaches might be of two colors: black and red. There are n cockroaches living in Anatoly's room.
Anatoly just made all his cockroaches to form a single line. As he is a perfectioni... | #http://codeforces.com/problemset/problem/719/B
#solved
n = int(input())
s = input()
red_black = True
swap_red = {"b": 0, "r": 0}
swap_black = {"b": 0, "r": 0}
for c in s:
if red_black is True and c != "b":
swap_black["r"] += 1
elif red_black is False and c != "r":
swap_black["b"] += 1
... |
343 | 787_A. The Monster | A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times b, b + a, b + 2a, b + 3a, ... and Morty screams at times d, d + c, d + 2c, d + 3c, ....
<image>
The Monster will catch them if at any point they scream at the same tim... | import math
R=lambda:list(map(int,input().split()))
a,b=R()
c,d=R()
if abs(b-d)%math.gcd(a,c)!=0:
print(-1)
exit(0)
while b != d:
if b<d: b+=a
else: d+=c
print(b)
|
344 | 808_E. Selling Souvenirs | After several latest reforms many tourists are planning to visit Berland, and Berland people understood that it's an opportunity to earn money and changed their jobs to attract tourists. Petya, for example, left the IT corporation he had been working for and started to sell souvenirs at the market.
This morning, as us... | def f():
n, m = map(int, input().split())
l = list(tuple(map(int, input().split())) for _ in range(n))
l.sort(key=lambda e: (0, 6, 3, 2)[e[0]] * e[1], reverse=True)
last, r = [0] * 4, 0
for i, (w, c) in enumerate(l):
if m < w:
break
m -= w
r += c
last[w] =... |
345 | 833_A. The Meaningless Game | <image>
Slastyona and her loyal dog Pushok are playing a meaningless game that is indeed very interesting.
The game consists of multiple rounds. Its rules are very simple: in each round, a natural number k is chosen. Then, the one who says (or barks) it faster than the other wins the round. After that, the winner's s... | import sys,os,io
from sys import stdin
from math import log, gcd, ceil
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop, heapify
from bisect import bisect_left , bisect_right
import math
def ii():
return int(input())
def li():
return list(map(int,input().split()))
if(os.p... |
346 | 878_B. Teams Formation | This time the Berland Team Olympiad in Informatics is held in a remote city that can only be reached by one small bus. Bus has n passenger seats, seat i can be occupied only by a participant from the city ai.
Today the bus has completed m trips, each time bringing n participants. The participants were then aligned in ... | import sys
from collections import deque
input=sys.stdin.readline
n,k,m=map(int,input().split())
a=list(map(int,input().split()))
r=a[0]
flag=0
for i in range(n):
if r!=a[i]:
flag=1
break
if flag==0:
print((m*n)%k)
sys.exit()
if k>n:
print(m*n)
sys.exit()
curr=a[0]
tmp=1
que=deque([(a[0],1)])
for i in... |
347 | 901_D. Weighting a Tree | You are given a connected undirected graph with n vertices and m edges. The vertices are enumerated from 1 to n.
You are given n integers c1, c2, ..., cn, each of them is between - n and n, inclusive. It is also guaranteed that the parity of cv equals the parity of degree of vertex v. The degree of a vertex is the n... |
def divisors(M):
d=[]
i=1
while M>=i**2:
if M%i==0:
d.append(i)
if i**2!=M:
d.append(M//i)
i=i+1
return d
def popcount(x):
x = x - ((x >> 1) & 0x55555555)
x = (x & 0x33333333) + ((x >> 2) & 0x33333333)
x = (x + (x >> 4)) & 0x0f0f0f0f
... |
348 | 924_A. Mystical Mosaic | There is a rectangular grid of n rows of m initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the i-th operation, a non-empty subset of rows Ri and a non-empty subset of columns Ci are chosen. For each row r in Ri and each column c in Ci, the intersection of row r and... | def read_data():
n, m = map(int, input().strip().split())
a = []
for i in range(n):
line = list(input().strip())
for j in range(len(line)):
if line[j] == ".":
line[j] = 0
else:
line[j] = 1
a.append(line)
return n, m, a
def ... |
349 | 952_C. Ravioli Sort | Everybody knows of [spaghetti sort](https://en.wikipedia.org/wiki/Spaghetti_sort). You decided to implement an analog sorting algorithm yourself, but as you survey your pantry you realize you're out of spaghetti! The only type of pasta you have is ravioli, but you are not going to let this stop you...
You come up with... | n = int(input())
l = [int(x) for x in input().split()]
while len(l) > 1:
if len([i for i in range(len(l)-1) if abs(l[i] - l[i+1]) > 1 ])>0:
print ('NO')
exit(0)
l.remove(max(l))
print('YES')
|
350 | 979_E. Kuro and Topological Parity | Kuro has recently won the "Most intelligent cat ever" contest. The three friends then decided to go to Katie's home to celebrate Kuro's winning. After a big meal, they took a small break then started playing games.
Kuro challenged Katie to create a game with only a white paper, a pencil, a pair of scissors and a lot o... | n,p=map(int,input().split())
nums=[0]+list(map(int,input().split()))
mod=10**9+7
f=[[[[0]*2 for _ in range(2)] for _ in range(2)] for _ in range(n+1)]
_2=[0]*(n+1)
_2[0]=1
for i in range(1,n+1):
_2[i]=(_2[i-1]<<1)%mod
f[0][0][0][0]=1
if nums[1]!=0:
f[1][1][0][1]+=1
if nums[1]!=1:
f[1][1][1][0]+=1
fo... |
351 | 999_F. Cards and Joy | There are n players sitting at the card table. Each player has a favorite number. The favorite number of the j-th player is f_j.
There are k β
n cards on the table. Each card contains a single integer: the i-th card contains number c_i. Also, you are given a sequence h_1, h_2, ..., h_k. Its meaning will be explained b... | def solve():
n, k = map(int, input().split())
c = list(map(int, input().split()))
f = list(map(int, input().split()))
h = list(map(int, input().split()))
cnt = {}
for i in c:
cnt[i] = cnt.get(i, 0) + 1
likecolor = {}
for i in range(n):
likecolor.setdefault(f[i], []).appen... |
352 | 1070_D. Garbage Disposal | Enough is enough. Too many times it happened that Vasya forgot to dispose of garbage and his apartment stank afterwards. Now he wants to create a garbage disposal plan and stick to it.
For each of next n days Vasya knows a_i β number of units of garbage he will produce on the i-th day. Each unit of garbage must be dis... | import sys
n, k = tuple(int(i) for i in sys.stdin.readline().split())
a = tuple(int(i) for i in sys.stdin.readline().split())
assert len(a) == n
bags = 0
r = 0
for ai in a:
leftovers = (r > 0)
q, r = divmod(ai + r, k)
if q == 0:
if leftovers:
bags += 1
r = 0
else:
... |
353 | 1140_C. Playlist | You have a playlist consisting of n songs. The i-th song is characterized by two numbers t_i and b_i β its length and beauty respectively. The pleasure of listening to set of songs is equal to the total length of the songs in the set multiplied by the minimum beauty among them. For example, the pleasure of listening to... | import heapq
n,k=map(int,input().split())
b_l=[]
for _ in range(n):
t,b=map(int,input().split())
b_l.append([b,t])
b_l.sort(reverse=True)
ans=0
sum_fg=0
h=[]
heapq.heapify(h)
for i in range(n):
sum_fg+=b_l[i][1]
heapq.heappush(h,b_l[i][1])
while(len(h)>k):
g=heapq.heappop(h)
sum_fg-=... |
354 | 1159_A. A pile of stones | Vasya has a pile, that consists of some number of stones. n times he either took one stone from the pile or added one stone to the pile. The pile was non-empty before each operation of taking one stone from the pile.
You are given n operations which Vasya has made. Find the minimal possible number of stones that can b... | '''
t= input()
lng= len(t)
li1=[]; li2=[]
for i in range(lng):
if t[i]!='a':
li1.append(t[i])
elif t[i]=='a':
li2.append(i)
aa= ''.join(li1)
if len(aa)==0:
print(t); exit(0)
if len(aa)%2==1:
print(':('); exit(0)
if len(aa)%2==0:
#print(123)
l= int(len(aa)/2); lp= l#; pri... |
355 | 1181_A. Chunga-Changa | Soon after the Chunga-Changa island was discovered, it started to acquire some forms of civilization and even market economy. A new currency arose, colloquially called "chizhik". One has to pay in chizhiks to buy a coconut now.
Sasha and Masha are about to buy some coconuts which are sold at price z chizhiks per cocon... | x,y,z=map(int,input().split())
sum=(x+y)//z
i1=x//z
i2=y//z
x=x%z
y=y%z
current=i1+i2
nu=0
if current==sum:
print(sum,end=' ')
print(nu)
else:
if x>y:
h=x
else:
h=y
current=sum-current
current=current*z
nu=current-h
print(sum, end=' ')
print(nu) |
356 | 1216_E1. Numerical Sequence (easy version) | The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one β from 1 to 2... | def isqrt(x):
if x < 0:
raise ValueError('square root not defined for negative numbers')
n = int(x)
if n == 0:
return 0
a, b = divmod(n.bit_length(), 2)
x = 2**(a+b)
while True:
y = (x + n//x)//2
if y >= x:
return x
x = y
p = [0, 45, 9045, 1395... |
357 | 125_A. Measuring Lengths in Baden | Lengths are measures in Baden in inches and feet. To a length from centimeters it is enough to know that an inch equals three centimeters in Baden and one foot contains 12 inches.
You are given a length equal to n centimeters. Your task is to convert it to feet and inches so that the number of feet was maximum. The re... | n=int(input())
e=(n+1)//36
n-=36*e
print(e,(n+1)//3) |
358 | 1281_C. Cut and Paste | We start with a string s consisting only of the digits 1, 2, or 3. The length of s is denoted by |s|. For each i from 1 to |s|, the i-th character of s is denoted by s_i.
There is one cursor. The cursor's location β is denoted by an integer in \{0, β¦, |s|\}, with the following meaning:
* If β = 0, then the cursor... | import sys
reader = (s.rstrip() for s in sys.stdin)
input = reader.__next__
MAX=10**9+7
def solve():
x = int(input())
s = [int(i) for i in input()]
ans=len(s)
c = ""
l = 0
while l < x:
l += 1
k=len(s)
if k < x:
#s += s[l:]*(s[l - 1]-1)
for i in ran... |
359 | 1344_B. Monopole Magnets | A monopole magnet is a magnet that only has one pole, either north or south. They don't actually exist since real magnets have two poles, but this is a programming contest problem, so we don't care.
There is an nΓ m grid. Initially, you may place some north magnets and some south magnets into the cells. You are allowe... | # -*- coding:utf-8 -*-
"""
created by shuangquan.huang at 2020/6/16
"""
import collections
import time
import os
import sys
import bisect
import heapq
from typing import List
def check(row):
start, end = 0, len(row) - 1
while start < len(row) and row[start] == 0:
start += 1
if start >... |
360 | 1366_B. Shuffle | You are given an array consisting of n integers a_1, a_2, ..., a_n. Initially a_x = 1, all other elements are equal to 0.
You have to perform m operations. During the i-th operation, you choose two indices c and d such that l_i β€ c, d β€ r_i, and swap a_c and a_d.
Calculate the number of indices k such that it is poss... | from __future__ import division, print_function
# import threading
# threading.stack_size(2**27)
# import sys
# sys.setrecursionlimit(10**7)
# sys.stdin = open('inpy.txt', 'r')
# sys.stdout = open('outpy.txt', 'w')
from sys import stdin, stdout
import bisect #c++ upperbound
import math
import heapq
i_m=92233... |
361 | 1408_B. Arrays Sum | You are given a non-decreasing array of non-negative integers a_1, a_2, β¦, a_n. Also you are given a positive integer k.
You want to find m non-decreasing arrays of non-negative integers b_1, b_2, β¦, b_m, such that:
* The size of b_i is equal to n for all 1 β€ i β€ m.
* For all 1 β€ j β€ n, a_j = b_{1, j} + b_{2, j}... | import sys as _sys
def main():
t = int(input())
for i_t in range(t):
n, k = _read_ints()
a = tuple(_read_ints())
try:
result = find_min_m(a, k)
except ValueError:
result = -1
print(result)
def _read_line():
result = _sys.stdin.readline()
... |
362 | 1428_E. Carrots for Rabbits | There are some rabbits in Singapore Zoo. To feed them, Zookeeper bought n carrots with lengths a_1, a_2, a_3, β¦, a_n. However, rabbits are very fertile and multiply very quickly. Zookeeper now has k rabbits and does not have enough carrots to feed all of them. To solve this problem, Zookeeper decided to cut the carrots... | import sys
from heapq import heapify, heappush, heappop
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c for j in range(b)] for i in range(a)]
def list3d(a, b, c, d): return [[[d for k in range(c)] for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e for l in ra... |
363 | 1451_F. Nullify The Matrix | Jeel and Ashish play a game on an n Γ m matrix. The rows are numbered 1 to n from top to bottom and the columns are numbered 1 to m from left to right. They play turn by turn. Ashish goes first.
Initially, each cell of the matrix contains a non-negative integer. Each turn, a player must perform all of the following ac... | def solve_case():
n, m = [int(x) for x in input().split()]
a = [[int(x) for x in input().split()] for x in range(n)]
xr = [0] * (n + m)
for i in range(n):
for j in range(m):
xr[i + j] ^= a[i][j]
return sum(xr) > 0
def main():
for _ in range(int(input())):
print(['J... |
364 | 1525_E. Assimilation IV | Monocarp is playing a game "Assimilation IV". In this game he manages a great empire: builds cities and conquers new lands.
Monocarp's empire has n cities. In order to conquer new lands he plans to build one Monument in each city. The game is turn-based and, since Monocarp is still amateur, he builds exactly one Monum... | ans = 0
n,m = map(int,input().split())
mod = 998244353
a = [list(map(int,input().split())) for i in range(n)]
fac = 1
for i in range(1,n+1): fac *= i
inv = pow(fac,mod-2,mod)
for j in range(m):
na = sorted([a[i][j] for i in range(n)])
now = 1
able = 0
for i in range(n):
while len(na) > 0... |
365 | 178_A2. Educational Game | The Smart Beaver from ABBYY began to develop a new educational game for children. The rules of the game are fairly simple and are described below.
The playing field is a sequence of n non-negative integers ai numbered from 1 to n. The goal of the game is to make numbers a1, a2, ..., ak (i.e. some prefix of the sequenc... | from math import log
n=int(input())
s=list(map(int,input().split( )))
p=[]
for i in range(0,n-1):
m=(log(n-1-i,2))//1
p.append(i+2**m)
for k in range(1,n):
g=0
f=s[:]
for i in range(0,k):
g+=f[i]
f[int(p[i])]+=f[i]
print(g)
|
366 | 19_C. Deletion of Repeats | Once Bob saw a string. It contained so many different letters, that the letters were marked by numbers, but at the same time each letter could be met in the string at most 10 times. Bob didn't like that string, because it contained repeats: a repeat of length x is such a substring of length 2x, that its first half coin... | def pow(x, exp, mod):
res = 1
while exp:
if exp & 1:
res = (res * x) % mod
x = (x * x) % mod
exp >>= 1
return res
MOD = 2 ** 121 - 1
M = int(1e9) + 1
n = int(input())
vals = list(map(int, input().split()))
groups = dict()
for i in range(n):
groups.setdefault(vals... |
367 | 272_C. Dima and Staircase | Dima's got a staircase that consists of n stairs. The first stair is at height a1, the second one is at a2, the last one is at an (1 β€ a1 β€ a2 β€ ... β€ an).
Dima decided to play with the staircase, so he is throwing rectangular boxes at the staircase from above. The i-th box has width wi and height hi. Dima throws eac... | # https://codeforces.com/problemset/problem/272/C
# we just check if the box dropped falls above the previous box or on stair number(1...w)
# the box is dropped from the top and hence we need to check the heights from the top -
# which height is suitable and higher
m = int(input())
arr = list(map(int, input().split(... |
368 | 343_C. Read Time | Mad scientist Mike does not use slow hard disks. His modification of a hard drive has not one, but n different heads that can read data in parallel.
When viewed from the side, Mike's hard drive is an endless array of tracks. The tracks of the array are numbered from left to right with integers, starting with 1. In the... | import sys
from itertools import *
from math import *
def solve():
n, m = map(int, input().split())
h = list(map(int, input().split()))
p = list(map(int, input().split()))
ss, ll = 0, int(2.2e10)
while ss < ll:
avg = (ss + ll) // 2
works = True
hidx = 0
pidx = 0
... |
369 | 366_E. Dima and Magic Guitar | Dima loves Inna very much. He decided to write a song for her. Dima has a magic guitar with n strings and m frets. Dima makes the guitar produce sounds like that: to play a note, he needs to hold one of the strings on one of the frets and then pull the string. When Dima pulls the i-th string holding it on the j-th fret... | def solution() : # ζ倧ηθ·η¦»ζ₯θͺδΊθ§θ½ιθΏηηΉ
n,m,k,s = map(int, input().split())
dis = lambda a,b : abs(a[0] - b[0]) + abs(a[1] - b[1])
corner = [(0,0), (0,m-1), (n-1,0), (n-1,m-1)]
vertex = [[(n,m), (n,-1), (-1,m), (-1,-1)] for _ in range(k+1)]
for i in range(n) :
for j,note in enumerate(map(int, input().split())) :
ve... |
370 | 38_D. Vasya the Architect | Once Vasya played bricks. All the bricks in the set had regular cubical shape. Vasya vas a talented architect, however the tower he built kept falling apart.
Let us consider the building process. Vasya takes a brick and puts it on top of the already built tower so that the sides of the brick are parallel to the sides ... | a=[list(map(int,input().split())) for i in range(int(input()))]
n=len(a)
z=n
for i in range(n):
if i!=0:
c=[(a[i][0]+a[i][2])/2,(a[i][1]+a[i][3])/2]
m=abs(a[i][0]-a[i][2])**3
for j in range(i-1,-1,-1):
x1,y1,x2,y2=min(a[j][0],a[j][2]),min(a[j][1],a[j][3]),max(a[j][0],a[j][2]),max... |
371 | 40_C. Berland Square | Last year the world's largest square was built in Berland. It is known that the square can be represented as an infinite plane with an introduced Cartesian system of coordinates. On that square two sets of concentric circles were painted. Let's call the set of concentric circles with radii 1, 2, ..., K and the center i... | def readGen(trans):
while 1:
for x in input().split():
yield(trans(x))
readint=readGen(int)
[N,x,M,y]=(next(readint) for i in range(4))
d=abs(y-x)
def interval(a,b): return range(a,b+1)
def case1(N,M,d): # d>=N
ans=0
for r in interval(1, min(M,d-N)):
ans+=1
if (M<=d-N):
return ans
for r in interval(... |
372 | 45_I. TCMCF+++ | Vasya has gotten interested in programming contests in TCMCF+++ rules. On the contest n problems were suggested and every problem had a cost β a certain integral number of points (perhaps, negative or even equal to zero). According to TCMCF+++ rules, only accepted problems can earn points and the overall number of poin... | import sys
input=sys.stdin.readline
n=int(input())
s=list(map(int,input().split()))
s.sort()
s.reverse()
num_manfi=0
num_sefr=0
flag=0
for i in s:
if i>0:
print(i,end=' ')
flag=1
elif i==0:
num_sefr+=1
else:
num_manfi+=1
num_manfi-=(num_manfi%2)
s.reverse()
for i in ... |
373 | 483_C. Diverse Permutation | Permutation p is an ordered set of integers p1, p2, ..., pn, consisting of n distinct positive integers not larger than n. We'll denote as n the length of permutation p1, p2, ..., pn.
Your task is to find such permutation p of length n, that the group of numbers |p1 - p2|, |p2 - p3|, ..., |pn - 1 - pn| has exactly k d... | from collections import Counter
import string
import math
import sys
# sys.setrecursionlimit(10**6)
from fractions import Fraction
def array_int():
return [int(i) for i in sys.stdin.readline().split()]
def vary(arrber_of_variables):
if arrber_of_variables==1:
return int(sys.stdin.readline())
if arr... |
374 | 507_C. Guess Your Way Out! | Amr bought a new video game "Guess Your Way Out!". The goal of the game is to find an exit from the maze that looks like a perfect binary tree of height h. The player is initially standing at the root of the tree and the exit from the tree is located at some leaf node.
Let's index all the leaf nodes from the left to ... | import sys
def main():
rdl = list(map(int,input().split()))
obx(rdl[0],rdl[1],0,1)
def obx(lvl, ind, kl, current):
if lvl ==0:
print(int(kl))
sys.exit()
all = 0
for i in range(lvl+1):
all += 2**i
all -= 1
if ind > (2**(lvl))/2:
if current == 1:
kl... |
375 | 556_D. Case of Fugitive | Andrewid the Android is a galaxy-famous detective. He is now chasing a criminal hiding on the planet Oxa-5, the planet almost fully covered with water.
The only dry land there is an archipelago of n narrow islands located in a row. For more comfort let's represent them as non-intersecting segments on a straight line: ... | #!/usr/bin/env python
# 556D_fug.py - Codeforces.com 556D Fug quiz
#
# Copyright (C) 2015 Sergey
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
# http://www.apache.org/licenses/LICENSE-2... |
376 | 582_B. Once Again... | You are given an array of positive integers a1, a2, ..., an Γ T of length n Γ T. We know that for any i > n it is true that ai = ai - n. Find the length of the longest non-decreasing sequence of the given array.
Input
The first line contains two space-separated integers: n, T (1 β€ n β€ 100, 1 β€ T β€ 107). The second li... | f = lambda: map(int, input().split())
n, m = f()
t = list(f())
s = [0] * 301
d = s[:]
for i in t: d[i] += 1
for i in t * min(m, 2 * n): s[i] = max(s[:i + 1]) + 1
print(max(s) + max((m - n * 2) * max(d), 0)) |
377 | 604_B. More Cowbell | Kevin Sun wants to move his precious collection of n cowbells from Naperthrill to Exeter, where there is actually grass instead of corn. Before moving, he must pack his cowbells into k boxes of a fixed size. In order to keep his collection safe during transportation, he won't place more than two cowbells into a single ... | n, k = map(int, input().split())
a = [int(s) for s in input().split()]
p = n - k
q = 2*k - n
if n < k:
q = n
p = 0
ma = 0
for i in range ((n - q) // 2):
ma = max((a[i] + a[n - q - i - 1]), ma)
ma2 = 0
for i in range(n - q, n):
ma2 = max(a[i], ma2)
print(max(ma,ma2))
|
378 | 626_E. Simple Skewness | Define the simple skewness of a collection of numbers to be the collection's mean minus its median. You are given a list of n (not necessarily distinct) integers. Find the non-empty subset (with repetition) with the maximum simple skewness.
The mean of a collection is the average of its elements. The median of a colle... | from itertools import accumulate
from fractions import Fraction
n = int(input())
A = [int(x) for x in input().split()]
A.sort()
B = list(accumulate([0] + A))
def condition(i, z):
return (2*z - 1)*(A[i-z] + A[-z]) > 2*(B[i+1] - B[i-z+1] + B[-1] - B[-z])
def average(i, z):
return Fraction((B[i+1] - B[i-z] + B[-1... |
379 | 676_A. Nicholas and Permutation | Nicholas has an array a that contains n distinct integers from 1 to n. In other words, Nicholas has a permutation of size n.
Nicholas want the minimum element (integer 1) and the maximum element (integer n) to be as far as possible from each other. He wants to perform exactly one swap in order to maximize the distance... | n = int(input())
a = list(map(int, input().split()))
maxLocate = a.index(n)
minLocate = a.index(1)
distanceMax = len(a) - 1 - a.index(n)
distanceMin = len(a) - 1 - a.index(1)
print(max(maxLocate, minLocate, distanceMax, distanceMin))
|
380 | 69_A. Young Physicist | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | sum1,sum2,sum3 = 0,0,0
n = int(input())
while n:
n-=1
l = list(map(int, input().split()))
sum1 += l[0]
sum2 += l[1]
sum3 += l[2]
if sum1==0 and sum2 ==0 and sum3 ==0:
print("YES")
else:
print("NO") |
381 | 742_A. Arpaβs hard exam and Mehrdadβs naive cheat | There exists an island called Arpaβs land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpaβs land. Arpa has prepared an exam. Exam has only one question, given n, print the last digit of 1378n.
<image>
Mehrdad has become quite confused and wants you to help him. Please hel... | n = int(input())
if n == 0:
print(1)
if n % 4 == 0 and n!= 0 :
print(6)
if n % 4 == 1:
print(8)
if n % 4 == 2:
print(4)
if n % 4 == 3:
print(2)
|
382 | 765_E. Tree Folding | Vanya wants to minimize a tree. He can perform the following operation multiple times: choose a vertex v, and two disjoint (except for v) paths of equal length a0 = v, a1, ..., ak, and b0 = v, b1, ..., bk. Additionally, vertices a1, ..., ak, b1, ..., bk must not have any neighbours in the tree other than adjacent verti... | import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time
sys.setrecursionlimit(10**7)
inf = 10**20
mod = 10**9 + 7
def LI(): return list(map(int, input().split()))
def II(): return int(input())
def LS(): return input().split()
def S(): return input()
def main():
n = II()
d = ... |
383 | 789_B. Masha and geometric depression | Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression b defined by two integers b1 and q. Remind that a geometric progression is a sequence of integers b1, b2, b3, ..., where for each i > 1 the respective term satisfies the condition bi = ... | b1,q,l,m = map(int,input().split())
a = set(map(int,input().split()))
if q==0:
if 0 in a:
if b1 in a:
print(0)
elif abs(b1)<=l:
print(1)
else:
print(0)
elif abs(b1)<=l:
print("inf")
else:
print(0)
elif q==1:
if abs(b1)<=l and b1... |
384 | 835_B. The number on the board | Some natural number was written on the board. Its sum of digits was not less than k. But you were distracted a bit, and someone changed this number to n, replacing some digits with others. It's known that the length of the number didn't change.
You have to find the minimum number of digits in which these two numbers c... | """
Author : Arif Ahmad
Date :
Algo :
Difficulty :
"""
from sys import stdin, stdout
def main():
k = int(stdin.readline().strip())
n = stdin.readline().strip()
n = sorted(n)
total = 0
for c in n:
d = ord(c) - 48
total += d
ans = 0
for c in n:
if total >= k: break
d = ord(c) - 48
total ... |
385 | 87_C. Interesting Game | Two best friends Serozha and Gena play a game.
Initially there is one pile consisting of n stones on the table. During one move one pile should be taken and divided into an arbitrary number of piles consisting of a1 > a2 > ... > ak > 0 stones. The piles should meet the condition a1 - a2 = a2 - a3 = ... = ak - 1 - ak =... | import math
from collections import Counter
n = int(input())
g = [0 for i in range(n + 1)]
prefix_xor = g.copy()
def in_range(d, k):
if (2 * k - d * d + d) % (2 * d) != 0:
return -1
x = (2 * k - d * d + d) / (2 * d)
return int(x) if x > 0 else -1
def mex(arr):
counter = Counter()
for i ... |
386 | 903_E. Swapping Characters | We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped exactly two characters (the characters we swapped could be identical, but they had different indices in the string).
You are gi... | import collections
def swapCharacters(strings, k, n):
"""
Time: O(n^2 * k)
Space: O(1)
"""
if k == 1:
s0 = list(strings[0])
s0[0], s0[1] = s0[1], s0[0]
return ''.join(s0)
# Initial check for validity
freq = collections.Counter(strings[0])
canSame = (max(freq.values()) >= 2) # could swap two of the same... |
387 | 954_G. Castle Defense | Today you are going to lead a group of elven archers to defend the castle that is attacked by an army of angry orcs. Three sides of the castle are protected by impassable mountains and the remaining side is occupied by a long wall that is split into n sections. At this moment there are exactly ai archers located at the... | import sys
border = 1 << 30
def build(x=0):
res = [0, 0]
i = 0
while x and i < 30:
if x & 1:
res[1] += (1 << i)
x >>= 1
i += 1
i = 0
while x:
if x & 1:
res[0] += (1 << i)
x >>= 1
i += 1
return res
n, r, k = map(int, ... |
388 | 1016_A. Death Note | You received a notebook which is called Death Note. This notebook has infinite number of pages. A rule is written on the last page (huh) of this notebook. It says: "You have to write names in this notebook during n consecutive days. During the i-th day you have to write exactly a_i names.". You got scared (of course yo... | (n,m) = tuple(map(int, input().split(" ")))
x = list(map(int, input().split(" ")))
nib = 0
ans = []
cou = 0;
for i in x:
nib+=i
if (nib<m):
ans.append(nib//m)
else:
ans.append(nib//m)
nib-=(nib//m)*m
print (*ans) |
389 | 103_A. Testing Pants for Sadness | The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of n questions; the questions are to be answered strictly in the order in which they are given, from question 1 to ... | import sys,math
s = int(input())
arr = list(map(int,input().split(' ')))
m = 0
for i in range(0,s):
m+=(arr[i]-1)*(i+1)+1
print(m)
'''
2 2 2
1+1 2
1+1+1 3
(1+1+1,1) 4
3 3
1+1+1 3
1+1+1+1+1 5
1+1+1,1+1+1,1 7
3
2 4 1
1+1
1+1+1+1+1+1+1
1
1+1+1+1
'''
|
390 | 1062_B. Math | JATC's math teacher always gives the class some interesting math problems so that they don't get bored. Today the problem is as follows. Given an integer n, you can perform the following operations zero or more times:
* mul x: multiplies n by x (where x is an arbitrary positive integer).
* sqrt: replaces n with β... | import math
def sieve(n):
mark = [0]*(n+1)
prime = []
for i in range(3, n+1, 2):
if not mark[i]:
for j in range(3*i, n+1, i+i):
mark[j] = 1
prime.append(2)
for i in range(3, n+1, 2):
if not mark[i]:
prime.append(i)
return prime
def isp... |
391 | 1084_A. The Fair Nut and Elevator | The Fair Nut lives in n story house. a_i people live on the i-th floor of the house. Every person uses elevator twice a day: to get from the floor where he/she lives to the ground (first) floor and to get from the first floor to the floor where he/she lives, when he/she comes back home in the evening.
It was decided ... | n = int(input())
arr = list(map(int, input().split()))
cur = 0
ans = 100000000
for x in range(n):
cur = 0
for i in range(n):
summ = 0
summ += abs(x - i)
summ += i
summ += x
summ += x
summ += i
summ += abs(x - i)
summ *= arr[i]
cur += summ
... |
392 | 1151_E. Number of Components | The Kingdom of Kremland is a tree (a connected undirected graph without cycles) consisting of n vertices. Each vertex i has its own value a_i. All vertices are connected in series by edges. Formally, for every 1 β€ i < n there is an edge between the vertices of i and i+1.
Denote the function f(l, r), which takes two in... | n = int(input()) + 1
res = 0
a = tuple(map(int, input().split()))
for ai in a:
res += ai * (n - ai)
for ai, aj in map(sorted, zip(a, a[1:])):
res -= ai * (n - aj)
print(res)
# |
393 | 1173_D. Nauuo and Circle | Nauuo is a girl who loves drawing circles.
One day she has drawn a circle and wanted to draw a tree on it.
The tree is a connected undirected graph consisting of n nodes and n-1 edges. The nodes are numbered from 1 to n.
Nauuo wants to draw a tree on the circle, the nodes of the tree should be in n distinct points o... | import sys
n = int(sys.stdin.readline().strip())
D = [0] * n
p = 998244353
for i in range (0, n - 1):
u, v = list(map(int, sys.stdin.readline().strip().split()))
D[u-1] = D[u-1] + 1
D[v-1] = D[v-1] + 1
ans = n
for i in range (0, n):
for j in range (0, D[i]):
ans = (ans * (j + 1)) % p
print(an... |
394 | 1191_A. Tokitsukaze and Enhancement | Tokitsukaze is one of the characters in the game "Kantai Collection". In this game, every character has a common attribute β health points, shortened to HP.
In general, different values of HP are grouped into 4 categories:
* Category A if HP is in the form of (4 n + 1), that is, when divided by 4, the remainder is ... | n=int(input())
d={}
d[0]='1 A'
d[1]='0 A'
d[2]='1 B'
d[3]='2 A'
x=n%4
print(d[x]) |
395 | 122_D. Lucky Transformation | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has a number consisting of n digits without leading zeroes. He represented it as an array of d... | n, k = map(int, input().split())
s = list(input())
cnt = 0
for i in range(n - 1):
if cnt == k:
break
if s[i] == '4' and s[i + 1] == '7':
if i & 1:
if s[i - 1] == '4':
if (cnt - k) & 1:
s[i] = '7'
print(''.join(s))
ex... |
396 | 1251_C. Minimize The Integer | You are given a huge integer a consisting of n digits (n is between 1 and 3 β
10^5, inclusive). It may contain leading zeros.
You can swap two digits on adjacent (neighboring) positions if the swapping digits are of different parity (that is, they have different remainders when divided by 2).
For example, if a = 032... | # -*- coding: utf-8 -*-
"""
Created on Fri Nov 1 14:39:37 2019
@author: uditg
"""
ans={}
test=int(input())
for each in range(test):
num=input()
n=len(num)
num={i:int(num[i]) for i in range(n)}
output={}
even={}
odd={}
even_count=0
odd_count=0
for i in range(n):
if num[i]%2=... |
397 | 1271_A. Suits | A new delivery of clothing has arrived today to the clothing store. This delivery consists of a ties, b scarves, c vests and d jackets.
The store does not sell single clothing items β instead, it sells suits of two types:
* a suit of the first type consists of one tie and one jacket;
* a suit of the second type ... | a = int(input())
b = int(input())
c = int(input())
d = int(input())
c1 = int(input())
c2 = int(input())
p = 0
if c2 > c1:
m = min(b,c,d)
b -= m
c -= m
d -= m
p += m * c2
if d > 0:
p += (min(a,d) * c1)
else:
m = min(a,d)
a -= m
d -= m
p += m * c1
if d > 0:
p += (min(b,c,... |
398 | 1294_B. Collecting Packages | There is a robot in a warehouse and n packages he wants to collect. The warehouse can be represented as a coordinate grid. Initially, the robot stays at the point (0, 0). The i-th package is at the point (x_i, y_i). It is guaranteed that there are no two packages at the same point. It is also guaranteed that the point ... | t=int(input())
for q in range(t):
n=int(input())
a=[list(map(int,input().split())) for i in range(n)]
a.sort()
ans=""
x,y=0,0
f=0
for i in range(n):
if a[i][0]>=x and a[i][1]>=y:
ans+='R'*(a[i][0]-x)
x=a[i][0]
ans+='U'*(a[i][1]-y)
y=a[i][1]
else:
f=1
print('NO')
break
if f==0:
print('... |
399 | 1336_E1. Chiori and Doll Picking (easy version) | This is the easy version of the problem. The only difference between easy and hard versions is the constraint of m. You can make hacks only if both versions are solved.
Chiori loves dolls and now she is going to decorate her bedroom!
<image>
As a doll collector, Chiori has got n dolls. The i-th doll has a non-negati... | import sys
MOD = 998244353
BOUND = 21
n, m = map(int, input().split())
l = list(map(int,input().split()))
basis = []
for p in range(m-1,-1,-1):
p2 = pow(2,p)
nex = -1
for i in range(n):
if l[i] >= p2:
nex = l[i]
break
if nex != -1:
basis.append(nex)
for... |
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