contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
13 | E | Holes | PROGRAMMING | 2,700 | [
"data structures",
"dsu"
] | E. Holes | 1 | 64 | Little Petya likes to play a lot. Most of all he likes to play a game «Holes». This is a game for one person with following rules:
There are *N* holes located in a single row and numbered from left to right with numbers from 1 to *N*. Each hole has it's own power (hole number *i* has the power *a**i*). If you throw a ... | The first line contains two integers *N* and *M* (1<=≤<=*N*<=≤<=105, 1<=≤<=*M*<=≤<=105) — the number of holes in a row and the number of moves. The second line contains *N* positive integers not exceeding *N* — initial values of holes power. The following *M* lines describe moves made by Petya. Each of these line can b... | For each move of the type 1 output two space-separated numbers on a separate line — the number of the last hole the ball visited before leaving the row and the number of jumps it made. | [
"8 5\n1 1 1 1 1 2 8 2\n1 1\n0 1 3\n1 1\n0 3 4\n1 2\n"
] | [
"8 7\n8 5\n7 3\n"
] | none | 0 | [
{
"input": "8 5\n1 1 1 1 1 2 8 2\n1 1\n0 1 3\n1 1\n0 3 4\n1 2",
"output": "8 7\n8 5\n7 3"
},
{
"input": "10 10\n5 1 2 4 1 7 3 8 10 8\n0 5 6\n1 8\n1 1\n0 10 3\n1 5\n1 3\n1 2\n0 6 1\n1 9\n1 1",
"output": "8 1\n6 2\n5 1\n5 2\n5 3\n9 1\n10 4"
}
] | 1,695,799,058 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 5,632,000 | print('test')
# Wed Sep 27 2023 10:17:21 GMT+0300 (Moscow Standard Time)
| Title: Holes
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Little Petya likes to play a lot. Most of all he likes to play a game «Holes». This is a game for one person with following rules:
There are *N* holes located in a single row and numbered from left to right with numbers from 1 to *N*... | ```python
print('test')
# Wed Sep 27 2023 10:17:21 GMT+0300 (Moscow Standard Time)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,657,968,242 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 77 | 1,638,400 | n,k=map(int,input().split())
a=list(map(int,input().split()))
for i in range(n):
a[i]=5-a[i]
a.sort()
count=0
for i in range(n):
if a[i]>=k:
count+=1
print(count//3)
| Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
n,k=map(int,input().split())
a=list(map(int,input().split()))
for i in range(n):
a[i]=5-a[i]
a.sort()
count=0
for i in range(n):
if a[i]>=k:
count+=1
print(count//3)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
498 | A | Crazy Town | PROGRAMMING | 1,700 | [
"geometry"
] | null | null | Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the plane into connected regions, possibly of infinite space. Let's call each such region a block. We ... | The first line contains two space-separated integers *x*1, *y*1 (<=-<=106<=≤<=*x*1,<=*y*1<=≤<=106) — the coordinates of your home.
The second line contains two integers separated by a space *x*2, *y*2 (<=-<=106<=≤<=*x*2,<=*y*2<=≤<=106) — the coordinates of the university you are studying at.
The third line contains a... | Output the answer to the problem. | [
"1 1\n-1 -1\n2\n0 1 0\n1 0 0\n",
"1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3\n"
] | [
"2\n",
"2\n"
] | Pictures to the samples are presented below (A is the point representing the house; B is the point representing the university, different blocks are filled with different colors): | 500 | [
{
"input": "1 1\n-1 -1\n2\n0 1 0\n1 0 0",
"output": "2"
},
{
"input": "1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3",
"output": "2"
},
{
"input": "841746 527518\n595261 331297\n10\n-946901 129987 670374\n-140388 -684770 309555\n-302589 415564 -387435\n-565799 -72069 -395358\n-523453 -511446 85489... | 1,452,804,645 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 62 | 0 | (x1, y1) = input().split(" ")
x1 = int(x1)
y1 = int(y1)
(x2, y2) = input().split(" ")
x2 = int(x2)
y2 = int(y2)
n = int(input())
lineslist = []
for i in range(n):
(a, b, c) = input().split(" ")
lineslist.append((int(a), int(b), int(c)))
def greaterThanLine(x, y, a, b, c):
return a*x + b*y + c ... | Title: Crazy Town
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the pl... | ```python
(x1, y1) = input().split(" ")
x1 = int(x1)
y1 = int(y1)
(x2, y2) = input().split(" ")
x2 = int(x2)
y2 = int(y2)
n = int(input())
lineslist = []
for i in range(n):
(a, b, c) = input().split(" ")
lineslist.append((int(a), int(b), int(c)))
def greaterThanLine(x, y, a, b, c):
return a*x ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
189 | A | Cut Ribbon | PROGRAMMING | 1,300 | [
"brute force",
"dp"
] | null | null | Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon piece... | The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide. | Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists. | [
"5 5 3 2\n",
"7 5 5 2\n"
] | [
"2\n",
"2\n"
] | In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | 500 | [
{
"input": "5 5 3 2",
"output": "2"
},
{
"input": "7 5 5 2",
"output": "2"
},
{
"input": "4 4 4 4",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "4000 1 2 3",
"output": "4000"
},
{
"input": "4000 3 4 5",
"output": "1333"
},
... | 1,692,805,269 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n , a, b,c = map(int,inout().split())
temp = 0
for i in range(n+1):
for j in range(n+1):
if i*a+j*b<= n:
if(n-(i*a+j*b))% c == 0:
flag = i+j+(n-(i*a+j*b))//c
if flag > temp and flag !=0:
temp = flag
print(temp) | Title: Cut Ribbon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the... | ```python
n , a, b,c = map(int,inout().split())
temp = 0
for i in range(n+1):
for j in range(n+1):
if i*a+j*b<= n:
if(n-(i*a+j*b))% c == 0:
flag = i+j+(n-(i*a+j*b))//c
if flag > temp and flag !=0:
temp = flag
print(temp)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,653,305,760 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 13,004,800 | n = int(input())
num = [int(x) for x in input().split()]
m = int(input())
que = [int(x) for x in input().split()]
c1 = 0
c2 = 0
for i in que:
c1+= num.index(i)
c1+=1
num.reverse()
for i in que:
c2+=num.index(i)
c2+=1
print(c1,c2) | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
n = int(input())
num = [int(x) for x in input().split()]
m = int(input())
que = [int(x) for x in input().split()]
c1 = 0
c2 = 0
for i in que:
c1+= num.index(i)
c1+=1
num.reverse()
for i in que:
c2+=num.index(i)
c2+=1
print(c1,c2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
701 | A | Cards | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards ... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card. | Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print... | [
"6\n1 5 7 4 4 3\n",
"4\n10 10 10 10\n"
] | [
"1 3\n6 2\n4 5\n",
"1 2\n3 4\n"
] | In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | 500 | [
{
"input": "6\n1 5 7 4 4 3",
"output": "1 3\n6 2\n4 5"
},
{
"input": "4\n10 10 10 10",
"output": "1 4\n2 3"
},
{
"input": "100\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,590,391,673 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 140 | 0 | n = int(input())
a = [int(i) for i in input().split()]
copy = a[:]
x = []
for i in range(len(a) // 2):
x.append(copy.index(max(a)))
x.append(copy.index(min(a)))
a.remove(max(a))
a.remove(min(a))
for i in range(len(x)):
x[i] += 1
for i in range(len(x)):
if x.count(x[i]) == 2:
... | Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one p... | ```python
n = int(input())
a = [int(i) for i in input().split()]
copy = a[:]
x = []
for i in range(len(a) // 2):
x.append(copy.index(max(a)))
x.append(copy.index(min(a)))
a.remove(max(a))
a.remove(min(a))
for i in range(len(x)):
x[i] += 1
for i in range(len(x)):
if x.count(x[i]) ==... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
81 | A | Plug-in | PROGRAMMING | 1,400 | [
"implementation"
] | A. Plug-in | 1 | 256 | Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once. For example, instead of the phrase "how are you" he can type "hhoow aaaare yy... | The input data consists of a single line to be processed. The length of the line is from 1 to 2·105 characters inclusive. The string contains only lowercase Latin letters. | Print the given string after it is processed. It is guaranteed that the result will contain at least one character. | [
"hhoowaaaareyyoouu\n",
"reallazy\n",
"abacabaabacabaa\n"
] | [
"wre",
"rezy",
"a"
] | none | 500 | [
{
"input": "hhoowaaaareyyoouu",
"output": "wre"
},
{
"input": "reallazy",
"output": "rezy"
},
{
"input": "abacabaabacabaa",
"output": "a"
},
{
"input": "xraccabccbry",
"output": "xy"
},
{
"input": "a",
"output": "a"
},
{
"input": "b",
"output": "b"... | 1,562,919,461 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 1,000 | 7,680,000 | def is_Sublist(l, s):
#print(l,s)
sub_set = False
if s == []:
sub_set = True
elif s == l:
sub_set = True
elif len(s) > len(l):
sub_set = False
else:
for i in range(len(l)):
if l[i] == s[0]:
n = 0
while (n ... | Title: Plug-in
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed... | ```python
def is_Sublist(l, s):
#print(l,s)
sub_set = False
if s == []:
sub_set = True
elif s == l:
sub_set = True
elif len(s) > len(l):
sub_set = False
else:
for i in range(len(l)):
if l[i] == s[0]:
n = 0
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
735 | D | Taxes | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not equal to *n*, of course). For example, if *n*<==<=6 then Funt has to pay 3 burles, while fo... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·109) — the total year income of mr. Funt. | Print one integer — minimum possible number of burles that mr. Funt has to pay as a tax. | [
"4\n",
"27\n"
] | [
"2\n",
"3\n"
] | none | 1,750 | [
{
"input": "4",
"output": "2"
},
{
"input": "27",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "5",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "2000000000",
"output": "2"
},
{
"input": "26",
"output": ... | 1,644,427,335 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 62 | 0 | from math import sqrt
n=int(input(""))
s=int(sqrt(n))
def prime(n):
c=0
for i in range(2, s + 1):
if (n % i == 0):
c = 1
break
if c==1:
return False
else:
return True
if prime(n)==True:
print("1")
else:
if n==2:
print("1")
... | Title: Taxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not ... | ```python
from math import sqrt
n=int(input(""))
s=int(sqrt(n))
def prime(n):
c=0
for i in range(2, s + 1):
if (n % i == 0):
c = 1
break
if c==1:
return False
else:
return True
if prime(n)==True:
print("1")
else:
if n==2:
p... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
259 | B | Little Elephant and Magic Square | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the magic square, the sum of integers in all its rows, columns and diagonals equals ... | The first three lines of the input contain the Little Elephant's notes. The first line contains elements of the first row of the magic square. The second line contains the elements of the second row, the third line is for the third row. The main diagonal elements that have been forgotten by the Elephant are represented... | Print three lines, in each line print three integers — the Little Elephant's magic square. If there are multiple magic squares, you are allowed to print any of them. Note that all numbers you print must be positive and not exceed 105.
It is guaranteed that there exists at least one magic square that meets the conditio... | [
"0 1 1\n1 0 1\n1 1 0\n",
"0 3 6\n5 0 5\n4 7 0\n"
] | [
"1 1 1\n1 1 1\n1 1 1\n",
"6 3 6\n5 5 5\n4 7 4\n"
] | none | 1,000 | [
{
"input": "0 1 1\n1 0 1\n1 1 0",
"output": "1 1 1\n1 1 1\n1 1 1"
},
{
"input": "0 3 6\n5 0 5\n4 7 0",
"output": "6 3 6\n5 5 5\n4 7 4"
},
{
"input": "0 4 4\n4 0 4\n4 4 0",
"output": "4 4 4\n4 4 4\n4 4 4"
},
{
"input": "0 54 48\n36 0 78\n66 60 0",
"output": "69 54 48\n36 5... | 1,620,970,722 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 6,963,200 | l=[]
for i in range(3):
l.append(list(map(int,input().split())))
for i in range(3):
for j in range(3):
if(l[i][j]==0 and i==0):
l[i][j] = l[i][-1]
elif(l[i][j]==0 and i==1):
l[i][j] = ((l[i][0]+l[i][-1])//2)
elif(l[i][j]==0 and i==2):
l[i][j]... | Title: Little Elephant and Magic Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table ... | ```python
l=[]
for i in range(3):
l.append(list(map(int,input().split())))
for i in range(3):
for j in range(3):
if(l[i][j]==0 and i==0):
l[i][j] = l[i][-1]
elif(l[i][j]==0 and i==1):
l[i][j] = ((l[i][0]+l[i][-1])//2)
elif(l[i][j]==0 and i==2):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
248 | A | Cupboards | PROGRAMMING | 800 | [
"implementation"
] | null | null | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on *n* woode... | The first input line contains a single integer *n* — the number of cupboards in the kitchen (2<=≤<=*n*<=≤<=104). Then follow *n* lines, each containing two integers *l**i* and *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=1). Number *l**i* equals one, if the left door of the *i*-th cupboard is opened, otherwise number *l**i* equal... | In the only output line print a single integer *t* — the minimum number of seconds Karlsson needs to change the doors of all cupboards to the position he needs. | [
"5\n0 1\n1 0\n0 1\n1 1\n0 1\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "5\n0 1\n1 0\n0 1\n1 1\n0 1",
"output": "3"
},
{
"input": "2\n0 0\n0 0",
"output": "0"
},
{
"input": "3\n0 1\n1 1\n1 1",
"output": "1"
},
{
"input": "8\n0 1\n1 0\n0 1\n1 1\n0 1\n1 0\n0 1\n1 0",
"output": "7"
},
{
"input": "8\n1 0\n1 0\n1 0\n0 1\n0 1\n1 ... | 1,631,790,311 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 154 | 6,758,400 | n = int(input())
leftOpen, righOpen = 0, 0
for _ in range(n):
l, r = input().split()
if l == '0':
leftOpen += 1
if r == '0':
righOpen += 1
print(min(n - leftOpen, leftOpen) + min(n - righOpen, righOpen)) | Title: Cupboards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any long... | ```python
n = int(input())
leftOpen, righOpen = 0, 0
for _ in range(n):
l, r = input().split()
if l == '0':
leftOpen += 1
if r == '0':
righOpen += 1
print(min(n - leftOpen, leftOpen) + min(n - righOpen, righOpen))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,610,320,219 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 62 | 307,200 | from sys import stdin as _stdin
from sys import stdout
stdin = lambda type_="int", sep=" ": list(
map(eval(type_), _stdin.readline().split(sep))
)
joint = lambda sep=" ", *args: sep.join(
str(i) if type(i) != list else sep.join(map(str, i)) for i in args
)
def iters():
return range(int(input()))
def so... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
from sys import stdin as _stdin
from sys import stdout
stdin = lambda type_="int", sep=" ": list(
map(eval(type_), _stdin.readline().split(sep))
)
joint = lambda sep=" ", *args: sep.join(
str(i) if type(i) != list else sep.join(map(str, i)) for i in args
)
def iters():
return range(int(input())... | 3.968428 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a spotlight on the stage in some good position. The spotlight will project light in one of t... | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the plan.
The next *n* lines contain *m* integers, 0 or 1 each — the description of the plan. Integer 1, means there will be an actor in the corresponding cell, while 0 means the cell ... | Print one integer — the number of good positions for placing the spotlight. | [
"2 4\n0 1 0 0\n1 0 1 0\n",
"4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0\n"
] | [
"9\n",
"20\n"
] | In the first example the following positions are good:
1. the (1, 1) cell and right direction; 1. the (1, 1) cell and down direction; 1. the (1, 3) cell and left direction; 1. the (1, 3) cell and down direction; 1. the (1, 4) cell and left direction; 1. the (2, 2) cell and left direction; 1. the (2, 2) cell and... | 0 | [
{
"input": "2 4\n0 1 0 0\n1 0 1 0",
"output": "9"
},
{
"input": "4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0",
"output": "20"
},
{
"input": "1 5\n1 1 0 0 0",
"output": "3"
},
{
"input": "2 10\n0 0 0 0 0 0 0 1 0 0\n1 0 0 0 0 0 0 0 0 0",
"output": "20"
},
{
"input": "3 ... | 1,479,635,500 | 2,800 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 24 | 1,000 | 6,656,000 | n,m = [int(x) for x in input().split()]
data = [[int(x) for x in input().split()] for i in range(n)]
ans = 0
for i in range(n):
a_c = 0
min_r = 100000
max_r = -1
for j in range(m):
if data[i][j] == 1:
a_c += 1
if j < min_r:
min_r = j
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a ... | ```python
n,m = [int(x) for x in input().split()]
data = [[int(x) for x in input().split()] for i in range(n)]
ans = 0
for i in range(n):
a_c = 0
min_r = 100000
max_r = -1
for j in range(m):
if data[i][j] == 1:
a_c += 1
if j < min_r:
min_r = j
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
166 | A | Rank List | PROGRAMMING | 1,100 | [
"binary search",
"implementation",
"sortings"
] | null | null | Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for no team we are shown its final place.
You know the rules of comparing the results of two give... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50). Then *n* lines contain the description of the teams: the *i*-th line contains two integers *p**i* and *t**i* (1<=≤<=*p**i*,<=*t**i*<=≤<=50) — the number of solved problems and the total penalty time of the *i*-th team, correspondingly. All num... | In the only line print the sought number of teams that got the *k*-th place in the final results' table. | [
"7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10\n",
"5 4\n3 1\n3 1\n5 3\n3 1\n3 1\n"
] | [
"3\n",
"4\n"
] | The final results' table for the first sample is:
- 1-3 places — 4 solved problems, the penalty time equals 10 - 4 place — 3 solved problems, the penalty time equals 20 - 5-6 places — 2 solved problems, the penalty time equals 1 - 7 place — 1 solved problem, the penalty time equals 10
The table shows that the se... | 500 | [
{
"input": "7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10",
"output": "3"
},
{
"input": "5 4\n3 1\n3 1\n5 3\n3 1\n3 1",
"output": "4"
},
{
"input": "5 1\n2 2\n1 1\n1 1\n1 1\n2 2",
"output": "2"
},
{
"input": "6 3\n2 2\n3 1\n2 2\n4 5\n2 2\n4 5",
"output": "1"
},
{
"i... | 1,618,928,474 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 124 | 102,400 | from collections import defaultdict
n,k=map(int,input().split())
x=[]
k-=1
for i in range(n):
x.append(list(map(int,input().split())))
d=defaultdict(list)
for i in x:
d[i[0]].append(i)
for i in d:
d[i]=sorted(d[i],key=lambda a:a[1],reverse=True)
y=[]
x=sorted(d,reverse=True)
for i in x:
... | Title: Rank List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for... | ```python
from collections import defaultdict
n,k=map(int,input().split())
x=[]
k-=1
for i in range(n):
x.append(list(map(int,input().split())))
d=defaultdict(list)
for i in x:
d[i[0]].append(i)
for i in d:
d[i]=sorted(d[i],key=lambda a:a[1],reverse=True)
y=[]
x=sorted(d,reverse=True)
for i i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
322 | B | Ciel and Flowers | PROGRAMMING | 1,600 | [
"combinatorics",
"math"
] | null | null | Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red flowers. - To make a "green bouquet", it needs 3 green flowers. - To make a "blue bouquet", it needs 3... | The first line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=109) — the number of red, green and blue flowers. | Print the maximal number of bouquets Fox Ciel can make. | [
"3 6 9\n",
"4 4 4\n",
"0 0 0\n"
] | [
"6\n",
"4\n",
"0\n"
] | In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.
In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet. | 1,000 | [
{
"input": "3 6 9",
"output": "6"
},
{
"input": "4 4 4",
"output": "4"
},
{
"input": "0 0 0",
"output": "0"
},
{
"input": "0 3 6",
"output": "3"
},
{
"input": "7 8 9",
"output": "7"
},
{
"input": "8 8 9",
"output": "8"
},
{
"input": "15 3 9... | 1,498,766,416 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 124 | 4,608,000 | r,g,b = map(int,input().split(' '))
sum=0
sum+=r//3;sum+=g//3;sum+=b//3
r,g,b = r%3,g%3,b%3
while r>0 and g>0 and b>0:
r-=1;g-=1;b-=1
sum+=1
print(sum) | Title: Ciel and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red fl... | ```python
r,g,b = map(int,input().split(' '))
sum=0
sum+=r//3;sum+=g//3;sum+=b//3
r,g,b = r%3,g%3,b%3
while r>0 and g>0 and b>0:
r-=1;g-=1;b-=1
sum+=1
print(sum)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,641,553,721 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int main()
{
int n;cin>>n;
int c=0;
for(int i=1;i<n;i++){
if(n%i == 0)c++;
}
cout<<c;
return 0;
}
| Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;cin>>n;
int c=0;
for(int i=1;i<n;i++){
if(n%i == 0)c++;
}
cout<<c;
return 0;
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,545,846,257 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 218 | 0 | t=int(input())
num=[int(x) for x in input().split()]
a=list(filter(lambda x:x%2==0,num))
b=list(filter(lambda x:x%2==1,num))
if len(a)==1:
c=a[0]
else:
c=b[0]
print(num.index(c)+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
t=int(input())
num=[int(x) for x in input().split()]
a=list(filter(lambda x:x%2==0,num))
b=list(filter(lambda x:x%2==1,num))
if len(a)==1:
c=a[0]
else:
c=b[0]
print(num.index(c)+1)
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
152 | C | Pocket Book | PROGRAMMING | 1,400 | [
"combinatorics"
] | null | null | One day little Vasya found mom's pocket book. The book had *n* names of her friends and unusually enough, each name was exactly *m* letters long. Let's number the names from 1 to *n* in the order in which they are written.
As mom wasn't home, Vasya decided to play with names: he chose three integers *i*, *j*, *k* (1<=... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of names and the length of each name, correspondingly. Then *n* lines contain names, each name consists of exactly *m* uppercase Latin letters. | Print the single number — the number of different names that could end up in position number 1 in the pocket book after the applying the procedures described above. Print the number modulo 1000000007 (109<=+<=7). | [
"2 3\nAAB\nBAA\n",
"4 5\nABABA\nBCGDG\nAAAAA\nYABSA\n"
] | [
"4\n",
"216\n"
] | In the first sample Vasya can get the following names in the position number 1: "AAB", "AAA", "BAA" and "BAB". | 1,500 | [
{
"input": "2 3\nAAB\nBAA",
"output": "4"
},
{
"input": "4 5\nABABA\nBCGDG\nAAAAA\nYABSA",
"output": "216"
},
{
"input": "1 1\nE",
"output": "1"
},
{
"input": "2 2\nNS\nPD",
"output": "4"
},
{
"input": "3 4\nPJKD\nNFJX\nFGFK",
"output": "81"
},
{
"inpu... | 1,685,973,273 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 122 | 2,560,000 | import sys
from math import ceil
input = sys.stdin.readline
for ii in range(1):
a,b=(map(int,input().split()))
s=[]
r=1
g={}
for o in range(b):
g[o]=[]
for i in range(a):
d=input()
for x in range(b):
g[x]+=d[x]
r=1
for i in g:
... | Title: Pocket Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day little Vasya found mom's pocket book. The book had *n* names of her friends and unusually enough, each name was exactly *m* letters long. Let's number the names from 1 to *n* in the order in which they are written.
... | ```python
import sys
from math import ceil
input = sys.stdin.readline
for ii in range(1):
a,b=(map(int,input().split()))
s=[]
r=1
g={}
for o in range(b):
g[o]=[]
for i in range(a):
d=input()
for x in range(b):
g[x]+=d[x]
r=1
for i in g... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
920 | C | Swap Adjacent Elements | PROGRAMMING | 1,400 | [
"dfs and similar",
"greedy",
"math",
"sortings",
"two pointers"
] | null | null | You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<=1)-th, for other indices it is not possible. You may perform any number of swapping operations any order. T... | The first line contains one integer *n* (2<=≤<=*n*<=≤<=200000) — the number of elements in the array.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=200000) — the elements of the array. Each integer from 1 to *n* appears exactly once.
The third line contains a string of *n*<=-<=1 char... | If it is possible to sort the array in ascending order using any sequence of swaps you are allowed to make, print YES. Otherwise, print NO. | [
"6\n1 2 5 3 4 6\n01110\n",
"6\n1 2 5 3 4 6\n01010\n"
] | [
"YES\n",
"NO\n"
] | In the first example you may swap *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, and then swap *a*<sub class="lower-index">4</sub> and *a*<sub class="lower-index">5</sub>. | 0 | [
{
"input": "6\n1 2 5 3 4 6\n01110",
"output": "YES"
},
{
"input": "6\n1 2 5 3 4 6\n01010",
"output": "NO"
},
{
"input": "6\n1 6 3 4 5 2\n01101",
"output": "NO"
},
{
"input": "6\n2 3 1 4 5 6\n01111",
"output": "NO"
},
{
"input": "4\n2 3 1 4\n011",
"output": "NO... | 1,517,814,758 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 124 | 1,000 | 19,353,600 | n=int(input())
a=list(map(int,input().split()))
s=input()
if '0' not in s:
print('YES')
exit()
for i in range(n):
dif=a[i]-1-i
if dif>0:
if '0' in s[i:dif+i]:
print('NO')
exit()
print('YES') | Title: Swap Adjacent Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<... | ```python
n=int(input())
a=list(map(int,input().split()))
s=input()
if '0' not in s:
print('YES')
exit()
for i in range(n):
dif=a[i]-1-i
if dif>0:
if '0' in s[i:dif+i]:
print('NO')
exit()
print('YES')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
902 | A | Visiting a Friend | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Pig is visiting a friend.
Pig's house is located at point 0, and his friend's house is located at point *m* on an axis.
Pig can use teleports to move along the axis.
To use a teleport, Pig should come to a certain point (where the teleport is located) and choose where to move: for each teleport there is the rightmos... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*m*<=≤<=100) — the number of teleports and the location of the friend's house.
The next *n* lines contain information about teleports.
The *i*-th of these lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=*b**i*<=≤<=*m*), where ... | Print "YES" if there is a path from Pig's house to his friend's house that uses only teleports, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"3 5\n0 2\n2 4\n3 5\n",
"3 7\n0 4\n2 5\n6 7\n"
] | [
"YES\n",
"NO\n"
] | The first example is shown on the picture below:
Pig can use the first teleport from his house (point 0) to reach point 2, then using the second teleport go from point 2 to point 3, then using the third teleport go from point 3 to point 5, where his friend lives.
The second example is shown on the picture below:
You... | 500 | [
{
"input": "3 5\n0 2\n2 4\n3 5",
"output": "YES"
},
{
"input": "3 7\n0 4\n2 5\n6 7",
"output": "NO"
},
{
"input": "1 1\n0 0",
"output": "NO"
},
{
"input": "30 10\n0 7\n1 2\n1 2\n1 4\n1 4\n1 3\n2 2\n2 4\n2 6\n2 9\n2 2\n3 5\n3 8\n4 8\n4 5\n4 6\n5 6\n5 7\n6 6\n6 9\n6 7\n6 9\n7 7... | 1,513,699,946 | 2,246 | Python 3 | WRONG_ANSWER | PRETESTS | 4 | 62 | 5,529,600 | n,m = map(int,input().split())
a = []
for i in range(n):
a.append(list(map(int,input().split())))
if a[0][0] != 0:
print('NO')
else:
for i in range(n-1):
if m <= a[i][1]:
print('YES')
break
if a[i][1] < a[i+1][0]:
print('NO')
... | Title: Visiting a Friend
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pig is visiting a friend.
Pig's house is located at point 0, and his friend's house is located at point *m* on an axis.
Pig can use teleports to move along the axis.
To use a teleport, Pig should come to a certain ... | ```python
n,m = map(int,input().split())
a = []
for i in range(n):
a.append(list(map(int,input().split())))
if a[0][0] != 0:
print('NO')
else:
for i in range(n-1):
if m <= a[i][1]:
print('YES')
break
if a[i][1] < a[i+1][0]:
print('NO')
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
789 | A | Anastasia and pebbles | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has only two pockets. She can put at most *k* pebbles in each pocket at the same tim... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 1<=≤<=*k*<=≤<=109) — the number of different pebble types and number of pebbles Anastasia can place in one pocket.
The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (1<=≤<=*w**i*<=≤<=104) — number of pebbles of each type. | The only line of output contains one integer — the minimum number of days Anastasia needs to collect all the pebbles. | [
"3 2\n2 3 4\n",
"5 4\n3 1 8 9 7\n"
] | [
"3\n",
"5\n"
] | In the first sample case, Anastasia can collect all pebbles of the first type on the first day, of second type — on the second day, and of third type — on the third day.
Optimal sequence of actions in the second sample case:
- In the first day Anastasia collects 8 pebbles of the third type. - In the second day she... | 500 | [
{
"input": "3 2\n2 3 4",
"output": "3"
},
{
"input": "5 4\n3 1 8 9 7",
"output": "5"
},
{
"input": "1 22\n1",
"output": "1"
},
{
"input": "3 57\n78 165 54",
"output": "3"
},
{
"input": "5 72\n74 10 146 189 184",
"output": "6"
},
{
"input": "9 13\n132 8... | 1,492,612,945 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 4,608,000 | import math
n,k = map(int, input().split())
l = list(map(int, input().split()))
nbr_days=0
for i in range(n-1):
while(l[i]>0):
l[i] = l[i]-k
l[i+1] = l[i+1]-k
nbr_days+=1
if(l[n-1]>0):
t = l[n-1]/(2*k)
t = math.ceil(t)
nbr_days += t
print(nbr_days, nd="") | Title: Anastasia and pebbles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could ... | ```python
import math
n,k = map(int, input().split())
l = list(map(int, input().split()))
nbr_days=0
for i in range(n-1):
while(l[i]>0):
l[i] = l[i]-k
l[i+1] = l[i+1]-k
nbr_days+=1
if(l[n-1]>0):
t = l[n-1]/(2*k)
t = math.ceil(t)
nbr_days += t
print(nbr_days, nd="")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
21 | B | Intersection | PROGRAMMING | 2,000 | [
"implementation",
"math"
] | B. Intersection | 1 | 256 | You are given two set of points. The first set is determined by the equation *A*1*x*<=+<=*B*1*y*<=+<=*C*1<==<=0, and the second one is determined by the equation *A*2*x*<=+<=*B*2*y*<=+<=*C*2<==<=0.
Write the program which finds the number of points in the intersection of two given sets. | The first line of the input contains three integer numbers *A*1,<=*B*1,<=*C*1 separated by space. The second line contains three integer numbers *A*2,<=*B*2,<=*C*2 separated by space. All the numbers are between -100 and 100, inclusive. | Print the number of points in the intersection or -1 if there are infinite number of points. | [
"1 1 0\n2 2 0\n",
"1 1 0\n2 -2 0\n"
] | [
"-1\n",
"1\n"
] | none | 1,000 | [
{
"input": "1 1 0\n2 2 0",
"output": "-1"
},
{
"input": "1 1 0\n2 -2 0",
"output": "1"
},
{
"input": "0 0 0\n0 0 0",
"output": "-1"
},
{
"input": "1 1 1\n1 1 1",
"output": "-1"
},
{
"input": "8 3 -4\n-5 2 7",
"output": "1"
},
{
"input": "-1 -1 0\n0 -1 ... | 1,572,031,001 | 2,147,483,647 | Python 3 | OK | TESTS | 140 | 140 | 307,200 | a1, b1, c1 = list(map(int, input().split()))
a2, b2, c2 = list(map(int, input().split()))
if(b1 != 0 and b2 != 0):
if(a1*b2 == a2*b1):
if(c1*b2 == c2*b1):
print(-1)
else:
print(0)
else:
print(1)
elif(b1 == 0 and b2 == 0):
if(a1 != 0):
if(a2 != 0):... | Title: Intersection
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given two set of points. The first set is determined by the equation *A*1*x*<=+<=*B*1*y*<=+<=*C*1<==<=0, and the second one is determined by the equation *A*2*x*<=+<=*B*2*y*<=+<=*C*2<==<=0.
Write the program which fin... | ```python
a1, b1, c1 = list(map(int, input().split()))
a2, b2, c2 = list(map(int, input().split()))
if(b1 != 0 and b2 != 0):
if(a1*b2 == a2*b1):
if(c1*b2 == c2*b1):
print(-1)
else:
print(0)
else:
print(1)
elif(b1 == 0 and b2 == 0):
if(a1 != 0):
if... | 3.929428 | MatrixStudio/Codeforces-Python-Submissions |
456 | A | Laptops | PROGRAMMING | 1,100 | [
"sortings"
] | null | null | One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the numb... | If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). | [
"2\n1 2\n2 1\n"
] | [
"Happy Alex\n"
] | none | 500 | [
{
"input": "2\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "2\n1 1\n2 2",
"output": "Poor Alex"
},
{
"input": "3\n2 2\n3 3\n1 1",
"output": "Poor Alex"
},
{
"input": "3\n3 3\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "1\n1 1",
"output": "Poor Alex"
... | 1,670,862,208 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 819,200 | import copy
def Sort_Tuple(tup):
# getting length of list of tuples
lst = len(tup)
for i in range(0, lst):
for j in range(0, lst-i-1):
if (tup[j][1] > tup[j + 1][1]):
temp = tup[j]
tup[j]= tup[j + 1]
tup[j + 1]= t... | Title: Laptops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the... | ```python
import copy
def Sort_Tuple(tup):
# getting length of list of tuples
lst = len(tup)
for i in range(0, lst):
for j in range(0, lst-i-1):
if (tup[j][1] > tup[j + 1][1]):
temp = tup[j]
tup[j]= tup[j + 1]
tup... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | E | Shortest Path | PROGRAMMING | 2,000 | [
"graphs",
"shortest paths"
] | E. Shortest Path | 3 | 256 | In Ancient Berland there were *n* cities and *m* two-way roads of equal length. The cities are numbered with integers from 1 to *n* inclusively. According to an ancient superstition, if a traveller visits three cities *a**i*, *b**i*, *c**i* in row, without visiting other cities between them, a great disaster awaits him... | The first line contains three integers *n*, *m*, *k* (2<=≤<=*n*<=≤<=3000,<=1<=≤<=*m*<=≤<=20000,<=0<=≤<=*k*<=≤<=105) which are the number of cities, the number of roads and the number of the forbidden triplets correspondingly.
Then follow *m* lines each containing two integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<... | If there are no path from 1 to *n* print -1. Otherwise on the first line print the number of roads *d* along the shortest path from the city 1 to the city *n*. On the second line print *d*<=+<=1 numbers — any of the possible shortest paths for Vasya. The path should start in the city 1 and end in the city *n*. | [
"4 4 1\n1 2\n2 3\n3 4\n1 3\n1 4 3\n",
"3 1 0\n1 2\n",
"4 4 2\n1 2\n2 3\n3 4\n1 3\n1 2 3\n1 3 4\n"
] | [
"2\n1 3 4\n",
"-1\n",
"4\n1 3 2 3 4\n"
] | none | 2,500 | [
{
"input": "4 4 1\n1 2\n2 3\n3 4\n1 3\n1 4 3",
"output": "2\n1 3 4"
},
{
"input": "3 1 0\n1 2",
"output": "-1"
},
{
"input": "4 4 2\n1 2\n2 3\n3 4\n1 3\n1 2 3\n1 3 4",
"output": "4\n1 3 2 3 4"
},
{
"input": "4 4 1\n1 2\n2 3\n3 4\n1 3\n1 2 3",
"output": "2\n1 3 4"
},
{... | 1,635,511,874 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 31 | 3,000 | 268,390,400 | from sys import stdin
input = stdin.readline
from collections import defaultdict,deque
def il(): #Input list
return list(map(int,input().split()))
def ii(): #Input int
return int(input())
def imi(): #Input multiple int
return map(int,input().split())
def ist(): #Input String
return input()
... | Title: Shortest Path
Time Limit: 3 seconds
Memory Limit: 256 megabytes
Problem Description:
In Ancient Berland there were *n* cities and *m* two-way roads of equal length. The cities are numbered with integers from 1 to *n* inclusively. According to an ancient superstition, if a traveller visits three cities *a**i*,... | ```python
from sys import stdin
input = stdin.readline
from collections import defaultdict,deque
def il(): #Input list
return list(map(int,input().split()))
def ii(): #Input int
return int(input())
def imi(): #Input multiple int
return map(int,input().split())
def ist(): #Input String
return... | 0 | MatrixStudio/Codeforces-Python-Submissions |
270 | A | Fancy Fence | PROGRAMMING | 1,100 | [
"geometry",
"implementation",
"math"
] | null | null | Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle *a*.
Will the robot be able to build the fence Emuska... | The first line of input contains an integer *t* (0<=<<=*t*<=<<=180) — the number of tests. Each of the following *t* lines contains a single integer *a* (0<=<<=*a*<=<<=180) — the angle the robot can make corners at measured in degrees. | For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible. | [
"3\n30\n60\n90\n"
] | [
"NO\nYES\nYES\n"
] | In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/df5f4b07dd5316fde165b43657b2696e2919e791.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second test case, the fence is a r... | 500 | [
{
"input": "3\n30\n60\n90",
"output": "NO\nYES\nYES"
},
{
"input": "6\n1\n2\n3\n170\n179\n25",
"output": "NO\nNO\nNO\nYES\nYES\nNO"
}
] | 1,632,871,963 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n=int(input))
for j in range(n):
k=int(input())
if k<60 :
print('NO')
elif 360%(180-k)==o:
print('YES')
else:
print('NO')
| Title: Fancy Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can... | ```python
n=int(input))
for j in range(n):
k=int(input())
if k<60 :
print('NO')
elif 360%(180-k)==o:
print('YES')
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
336 | C | Vasily the Bear and Sequence | PROGRAMMING | 1,800 | [
"brute force",
"greedy",
"implementation",
"number theory"
] | null | null | Vasily the bear has got a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Vasily the Bear wants to write out several numbers on a piece of paper so that the beauty of the numbers he wrote out was maximum.
The beauty of the written out numbers *b*1,<=*b*2,<=...,<=*b**k* is such maximum non-negative integer *... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=109). | In the first line print a single integer *k* (*k*<=><=0), showing how many numbers to write out. In the second line print *k* integers *b*1,<=*b*2,<=...,<=*b**k* — the numbers to write out. You are allowed to print numbers *b*1,<=*b*2,<=...,<=*b**k* in any order, but all of them must be distinct. If there are multip... | [
"5\n1 2 3 4 5\n",
"3\n1 2 4\n"
] | [
"2\n4 5\n",
"1\n4\n"
] | none | 1,500 | [
{
"input": "5\n1 2 3 4 5",
"output": "2\n4 5"
},
{
"input": "3\n1 2 4",
"output": "1\n4"
},
{
"input": "3\n1 20 22",
"output": "2\n20 22"
},
{
"input": "10\n109070199 215498062 361633800 406156967 452258663 530571268 670482660 704334662 841023955 967424642",
"output": "6\... | 1,630,773,839 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 358 | 52,326,400 | def process(A):
d = {}
for x in A:
i = 0
i1 = 1
while i1 <= x:
if i1&x==i1:
if i not in d:
d[i] = [None, []]
if d[i][0] is None:
d[i][0] = x
else:
d[i][0] =... | Title: Vasily the Bear and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the bear has got a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Vasily the Bear wants to write out several numbers on a piece of paper so that the beauty of the numbers he wrote out was ... | ```python
def process(A):
d = {}
for x in A:
i = 0
i1 = 1
while i1 <= x:
if i1&x==i1:
if i not in d:
d[i] = [None, []]
if d[i][0] is None:
d[i][0] = x
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,620,808,862 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 218 | 20,172,800 | from math import ceil, floor, sqrt, log, gcd
def solve ():
A, B, N = [int(X) for X in input().split()]
turn = 'A'
while True:
if turn == 'A':
if N < A:
print(1)
return
N -= gcd (N,A)
turn = 'B'
if turn == 'B' :
if N < B:
print (0)
return
N -= gcd (N,B)
turn = '... | Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
from math import ceil, floor, sqrt, log, gcd
def solve ():
A, B, N = [int(X) for X in input().split()]
turn = 'A'
while True:
if turn == 'A':
if N < A:
print(1)
return
N -= gcd (N,A)
turn = 'B'
if turn == 'B' :
if N < B:
print (0)
return
N -= gcd (N,B)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,661,268,829 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | n,m = map(int, input().split())
l = list(map(int, input().split()))
l.sort()
c = 0
for i in range(m):
if l[i] <= 0:
c -= l[i]
print(c) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n,m = map(int, input().split())
l = list(map(int, input().split()))
l.sort()
c = 0
for i in range(m):
if l[i] <= 0:
c -= l[i]
print(c)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,459,544,851 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 124 | 4,608,000 | s = input()
a = map(lambda c : c.islower(), s)
if sum(a) > len(s) / 2:
print(s.lower())
elif sum(a) > len(s) / 2:
print(s.upper())
else:
print(s.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
a = map(lambda c : c.islower(), s)
if sum(a) > len(s) / 2:
print(s.lower())
elif sum(a) > len(s) / 2:
print(s.upper())
else:
print(s.lower())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
285 | C | Building Permutation | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"sortings"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
You ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the size of the sought permutation. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Print a single number — the minimum number of moves.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"2\n3 0\n",
"3\n-1 -1 2\n"
] | [
"2\n",
"6\n"
] | In the first sample you should decrease the first number by one and then increase the second number by one. The resulting permutation is (2, 1).
In the second sample you need 6 moves to build permutation (1, 3, 2). | 1,500 | [
{
"input": "2\n3 0",
"output": "2"
},
{
"input": "3\n-1 -1 2",
"output": "6"
},
{
"input": "5\n-3 5 -3 3 3",
"output": "10"
},
{
"input": "10\n9 6 -2 4 1 1 1 9 6 2",
"output": "18"
},
{
"input": "9\n2 0 0 6 5 4 1 9 3",
"output": "15"
},
{
"input": "100... | 1,496,430,190 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 872 | 24,780,800 | n = int(input())
nums = sorted(map(int, input().split(' ')))
changes = 0
for i in range(n):
changes += abs(nums[i] - i - 1)
print(changes)
| Title: Building Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *... | ```python
n = int(input())
nums = sorted(map(int, input().split(' ')))
changes = 0
for i in range(n):
changes += abs(nums[i] - i - 1)
print(changes)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
289 | B | Polo the Penguin and Matrix | PROGRAMMING | 1,400 | [
"brute force",
"dp",
"implementation",
"sortings",
"ternary search"
] | null | null | Little penguin Polo has an *n*<=×<=*m* matrix, consisting of integers. Let's index the matrix rows from 1 to *n* from top to bottom and let's index the columns from 1 to *m* from left to right. Let's represent the matrix element on the intersection of row *i* and column *j* as *a**ij*.
In one move the penguin can add ... | The first line contains three integers *n*, *m* and *d* (1<=≤<=*n*,<=*m*<=≤<=100,<=1<=≤<=*d*<=≤<=104) — the matrix sizes and the *d* parameter. Next *n* lines contain the matrix: the *j*-th integer in the *i*-th row is the matrix element *a**ij* (1<=≤<=*a**ij*<=≤<=104). | In a single line print a single integer — the minimum number of moves the penguin needs to make all matrix elements equal. If that is impossible, print "-1" (without the quotes). | [
"2 2 2\n2 4\n6 8\n",
"1 2 7\n6 7\n"
] | [
"4\n",
"-1\n"
] | none | 1,000 | [
{
"input": "2 2 2\n2 4\n6 8",
"output": "4"
},
{
"input": "1 2 7\n6 7",
"output": "-1"
},
{
"input": "3 2 1\n5 7\n1 2\n5 100",
"output": "104"
},
{
"input": "3 3 3\n5 8 5\n11 11 17\n14 5 2",
"output": "12"
},
{
"input": "3 3 3\n5 8 5\n11 11 17\n14 5 3",
"outpu... | 1,588,412,981 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 184 | 307,200 | n,m,d=map(int,input().split(" "))
a=[]
for x in range(0,n):
l=list(map(int,input().split(" ")))
a.append(l)
c=a[0][0]
for x in range(0,n):
for y in range(0,m):
if a[x][y]>c:
c=a[x][y]
c=c-d
z=0
if c not in a:
c-=d
if d%2==0:
for x in range(0,n):
for y in r... | Title: Polo the Penguin and Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little penguin Polo has an *n*<=×<=*m* matrix, consisting of integers. Let's index the matrix rows from 1 to *n* from top to bottom and let's index the columns from 1 to *m* from left to right. Let's represe... | ```python
n,m,d=map(int,input().split(" "))
a=[]
for x in range(0,n):
l=list(map(int,input().split(" ")))
a.append(l)
c=a[0][0]
for x in range(0,n):
for y in range(0,m):
if a[x][y]>c:
c=a[x][y]
c=c-d
z=0
if c not in a:
c-=d
if d%2==0:
for x in range(0,n):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,681,161,157 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | def solve(a):
uppers = 0
lowers = 0
for i in a:
if i.isupper():
uppers += 1
else:
lowers += 1
if uppers > lowers:
print(a.upper())
else:
print(a.lower())
user = input()
solve(user)
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
def solve(a):
uppers = 0
lowers = 0
for i in a:
if i.isupper():
uppers += 1
else:
lowers += 1
if uppers > lowers:
print(a.upper())
else:
print(a.lower())
user = input()
solve(user)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,500,484,161 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 122 | 4,608,000 | y, k, n = map(int, input().split())
var = list()
for i in range(y, n):
if i % k == 0:
var.append(i - y)
if var:
print(*var)
else:
print(-1)
| Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
y, k, n = map(int, input().split())
var = list()
for i in range(y, n):
if i % k == 0:
var.append(i - y)
if var:
print(*var)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,691,591,592 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | y = int(input()) + 1
while len(set(str(y)))<=3:
y += 1
print(y)
| Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
y = int(input()) + 1
while len(set(str(y)))<=3:
y += 1
print(y)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,684,475,894 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | word=input()
capital=[]
lenght=len(word)
# print(lenght)
for x in word:
if x.isupper():
capital.append(x)
capital_letters=len(capital)
if lenght/2==capital_letters:
print(word.lower())
elif lenght/2>capital_letters:
print(word.lower())
elif lenght/2<capital_letters:
prin... | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
word=input()
capital=[]
lenght=len(word)
# print(lenght)
for x in word:
if x.isupper():
capital.append(x)
capital_letters=len(capital)
if lenght/2==capital_letters:
print(word.lower())
elif lenght/2>capital_letters:
print(word.lower())
elif lenght/2<capital_letters:... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,659,995,492 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 1,740,800 | n,t = map(int, input().split())
x = list(map(int, input().split()))
fl=0
for i in range(1,n):
z=i+x[i-1]
if (z==t):
print("YES")
fl=1
break
elif (i > t):
print("NO")
break
| Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
n,t = map(int, input().split())
x = list(map(int, input().split()))
fl=0
for i in range(1,n):
z=i+x[i-1]
if (z==t):
print("YES")
fl=1
break
elif (i > t):
print("NO")
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-th device currently has *b**i* units of power stored. All devices can store an arbitrary amount of pow... | The first line contains two integers, *n* and *p* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*p*<=≤<=109) — the number of devices and the power of the charger.
This is followed by *n* lines which contain two integers each. Line *i* contains the integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=100<=000) — the power of the dev... | If you can use the devices indefinitely, print -1. Otherwise, print the maximum amount of time before any one device hits 0 power.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=4.
Namely, let's assume that your answer is *a* and the answer of the jury is *b*. The chec... | [
"2 1\n2 2\n2 1000\n",
"1 100\n1 1\n",
"3 5\n4 3\n5 2\n6 1\n"
] | [
"2.0000000000",
"-1\n",
"0.5000000000"
] | In sample test 1, you can charge the first device for the entire time until it hits zero power. The second device has enough power to last this time without being charged.
In sample test 2, you can use the device indefinitely.
In sample test 3, we can charge the third device for 2 / 5 of a second, then switch to char... | 0 | [
{
"input": "2 1\n2 2\n2 1000",
"output": "2.0000000000"
},
{
"input": "1 100\n1 1",
"output": "-1"
},
{
"input": "3 5\n4 3\n5 2\n6 1",
"output": "0.5000000000"
},
{
"input": "1 1\n1 87",
"output": "-1"
},
{
"input": "1 1\n100 77",
"output": "0.7777777778"
},... | 1,559,142,234 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 93 | 0 | import math
n, p = map(int, input().split())
items = []
for i in range(n):
ai, bi = map(int, input().split())
items += [(ai, bi)]
items.sort(key=lambda item: item[1]/item[0])
surv_time = math.inf
cur_saved = 0
cur_power = 0
for i, item in enumerate(items):
ai, bi = item
current_death_time = bi /... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-th device cu... | ```python
import math
n, p = map(int, input().split())
items = []
for i in range(n):
ai, bi = map(int, input().split())
items += [(ai, bi)]
items.sort(key=lambda item: item[1]/item[0])
surv_time = math.inf
cur_saved = 0
cur_power = 0
for i, item in enumerate(items):
ai, bi = item
current_death_t... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
590 | D | Top Secret Task | PROGRAMMING | 2,300 | [
"dp"
] | null | null | A top-secret military base under the command of Colonel Zuev is expecting an inspection from the Ministry of Defence. According to the charter, each top-secret military base must include a top-secret troop that should... well, we cannot tell you exactly what it should do, it is a top secret troop at the end. The proble... | The first line of the input contains three positive integers *n*, *k*, *s* (1<=≤<=*k*<=≤<=*n*<=≤<=150, 1<=≤<=*s*<=≤<=109) — the number of soldiers in the line, the size of the top-secret troop to be formed and the maximum possible number of swap operations of the consecutive pair of soldiers, respectively.
The second ... | Print a single integer — the minimum possible total loquacity of the top-secret troop. | [
"3 2 2\n2 4 1\n",
"5 4 2\n10 1 6 2 5\n",
"5 2 3\n3 1 4 2 5\n"
] | [
"3\n",
"18\n",
"3\n"
] | In the first sample Colonel has to swap second and third soldiers, he doesn't really need the remaining swap. The resulting soldiers order is: (2, 1, 4). Minimum possible summary loquacity of the secret troop is 3. In the second sample Colonel will perform swaps in the following order:
1. (10, 1, 6 — 2, 5) 1. (10, 1... | 1,750 | [] | 1,448,340,932 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 204,800 | import heapq
def choose(l, n, k, d, swaps, allowed):
try:
return d[(n,k)]
except KeyError:
if n == k:
d[(n,k)] = (sum(l[:k]), swaps)
elif k == 0:
d[(n,k)] = (0, swaps)
else:
a = choose(l, n-1, k, d, swaps, allowed)
if s... | Title: Top Secret Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A top-secret military base under the command of Colonel Zuev is expecting an inspection from the Ministry of Defence. According to the charter, each top-secret military base must include a top-secret troop that should..... | ```python
import heapq
def choose(l, n, k, d, swaps, allowed):
try:
return d[(n,k)]
except KeyError:
if n == k:
d[(n,k)] = (sum(l[:k]), swaps)
elif k == 0:
d[(n,k)] = (0, swaps)
else:
a = choose(l, n-1, k, d, swaps, allowed)
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
259 | B | Little Elephant and Magic Square | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the magic square, the sum of integers in all its rows, columns and diagonals equals ... | The first three lines of the input contain the Little Elephant's notes. The first line contains elements of the first row of the magic square. The second line contains the elements of the second row, the third line is for the third row. The main diagonal elements that have been forgotten by the Elephant are represented... | Print three lines, in each line print three integers — the Little Elephant's magic square. If there are multiple magic squares, you are allowed to print any of them. Note that all numbers you print must be positive and not exceed 105.
It is guaranteed that there exists at least one magic square that meets the conditio... | [
"0 1 1\n1 0 1\n1 1 0\n",
"0 3 6\n5 0 5\n4 7 0\n"
] | [
"1 1 1\n1 1 1\n1 1 1\n",
"6 3 6\n5 5 5\n4 7 4\n"
] | none | 1,000 | [
{
"input": "0 1 1\n1 0 1\n1 1 0",
"output": "1 1 1\n1 1 1\n1 1 1"
},
{
"input": "0 3 6\n5 0 5\n4 7 0",
"output": "6 3 6\n5 5 5\n4 7 4"
},
{
"input": "0 4 4\n4 0 4\n4 4 0",
"output": "4 4 4\n4 4 4\n4 4 4"
},
{
"input": "0 54 48\n36 0 78\n66 60 0",
"output": "69 54 48\n36 5... | 1,576,237,244 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 23 | 312 | 1,843,200 | sp = [list(map(int, input().split())) for i in range(3)]
for i in range(1, 10**5):
s = sp[0][1] +sp[0][2]+i
x1, x2, x3 = s - sum(sp[0]), s - sum(sp[1]), s - sum(sp[2])
if (x1+x2+x3 == s) and (x1 > 0) and (x2>0) and (x3>0):
for j in range(3):
for h in range(j):
prin... | Title: Little Elephant and Magic Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table ... | ```python
sp = [list(map(int, input().split())) for i in range(3)]
for i in range(1, 10**5):
s = sp[0][1] +sp[0][2]+i
x1, x2, x3 = s - sum(sp[0]), s - sum(sp[1]), s - sum(sp[2])
if (x1+x2+x3 == s) and (x1 > 0) and (x2>0) and (x3>0):
for j in range(3):
for h in range(j):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
907 | B | Tic-Tac-Toe | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Two bears are playing tic-tac-toe via mail. It's boring for them to play usual tic-tac-toe game, so they are a playing modified version of this game. Here are its rules.
The game is played on the following field.
Players are making moves by turns. At first move a player can put his chip in any cell of any small field... | First 11 lines contains descriptions of table with 9 rows and 9 columns which are divided into 9 small fields by spaces and empty lines. Each small field is described by 9 characters without spaces and empty lines. character "x" (ASCII-code 120) means that the cell is occupied with chip of the first player, character "... | Output the field in same format with characters "!" (ASCII-code 33) on positions where the current player can put his chip. All other cells should not be modified. | [
"... ... ...\n... ... ...\n... ... ...\n\n... ... ...\n... ... ...\n... x.. ...\n\n... ... ...\n... ... ...\n... ... ...\n6 4\n",
"xoo x.. x..\nooo ... ...\nooo ... ...\n\nx.. x.. x..\n... ... ...\n... ... ...\n\nx.. x.. x..\n... ... ...\n... ... ...\n7 4\n",
"o.. ... ...\n... ... ...\n... ... ...\n\n... xxx ..... | [
"... ... ... \n... ... ... \n... ... ... \n\n... ... ... \n... ... ... \n... x.. ... \n\n!!! ... ... \n!!! ... ... \n!!! ... ... \n\n",
"xoo x!! x!! \nooo !!! !!! \nooo !!! !!! \n\nx!! x!! x!! \n!!! !!! !!! \n!!! !!! !!! \n\nx!! x!! x!! \n!!! !!! !!! \n!!! !!! !!! \n\n",
"o!! !!! !!! \n!!! !!! !!! \n!!! !!! !!!... | In the first test case the first player made a move to lower left cell of central field, so the second player can put a chip only to cells of lower left field.
In the second test case the last move was done to upper left cell of lower central field, however all cells in upper left field are occupied, so the second pla... | 1,000 | [
{
"input": "... ... ...\n... ... ...\n... ... ...\n\n... ... ...\n... ... ...\n... x.. ...\n\n... ... ...\n... ... ...\n... ... ...\n6 4",
"output": "... ... ... \n... ... ... \n... ... ... \n\n... ... ... \n... ... ... \n... x.. ... \n\n!!! ... ... \n!!! ... ... \n!!! ... ... "
},
{
"input": "xoo x... | 1,514,166,009 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 62 | 5,632,000 | R=input
g=[list(R()) for _ in range(11)]
r,c=map(int,R().split())
r,c=(r-1)%3*4,(c-1)%3*4
f='.'
for i in range(9):
s=g[r+i//3]
if '.'==s[c+i%3]:
s[c+i%3]=f='!'
for v in g:
print(''.join(v).replace(f,'!'))
| Title: Tic-Tac-Toe
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two bears are playing tic-tac-toe via mail. It's boring for them to play usual tic-tac-toe game, so they are a playing modified version of this game. Here are its rules.
The game is played on the following field.
Players ... | ```python
R=input
g=[list(R()) for _ in range(11)]
r,c=map(int,R().split())
r,c=(r-1)%3*4,(c-1)%3*4
f='.'
for i in range(9):
s=g[r+i//3]
if '.'==s[c+i%3]:
s[c+i%3]=f='!'
for v in g:
print(''.join(v).replace(f,'!'))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
858 | D | Polycarp's phone book | PROGRAMMING | 1,600 | [
"data structures",
"implementation",
"sortings"
] | null | null | There are *n* phone numbers in Polycarp's contacts on his phone. Each number is a 9-digit integer, starting with a digit different from 0. All the numbers are distinct.
There is the latest version of Berdroid OS installed on Polycarp's phone. If some number is entered, is shows up all the numbers in the contacts for w... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=70000) — the total number of phone contacts in Polycarp's contacts.
The phone numbers follow, one in each line. Each number is a positive 9-digit integer starting with a digit from 1 to 9. All the numbers are distinct. | Print exactly *n* lines: the *i*-th of them should contain the shortest non-empty sequence of digits, such that if Polycarp enters it, the Berdroid OS shows up only the *i*-th number from the contacts. If there are several such sequences, print any of them. | [
"3\n123456789\n100000000\n100123456\n",
"4\n123456789\n193456789\n134567819\n934567891\n"
] | [
"9\n000\n01\n",
"2\n193\n81\n91\n"
] | none | 2,000 | [
{
"input": "3\n123456789\n100000000\n100123456",
"output": "9\n000\n01"
},
{
"input": "4\n123456789\n193456789\n134567819\n934567891",
"output": "2\n193\n81\n91"
},
{
"input": "1\n167038488",
"output": "4"
},
{
"input": "5\n115830748\n403459907\n556271610\n430358099\n41396141... | 1,505,735,494 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 4,000 | 34,304,000 | from collections import Counter
B = 11
def getPrefs(s):
res = [0] * 9
for i in range(9):
if i == 0:
res[i] = ord(s[i]) - ord('0') + 1
else:
res[i] = res[i - 1] * B + ord(s[i]) - ord('0') + 1
return res
n = int(input())
s = [""] * n
ps = [None f... | Title: Polycarp's phone book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* phone numbers in Polycarp's contacts on his phone. Each number is a 9-digit integer, starting with a digit different from 0. All the numbers are distinct.
There is the latest version of Berdroid OS ... | ```python
from collections import Counter
B = 11
def getPrefs(s):
res = [0] * 9
for i in range(9):
if i == 0:
res[i] = ord(s[i]) - ord('0') + 1
else:
res[i] = res[i - 1] * B + ord(s[i]) - ord('0') + 1
return res
n = int(input())
s = [""] * n
ps... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
392 | A | Blocked Points | PROGRAMMING | 0 | [
"math"
] | null | null | Imagine you have an infinite 2D plane with Cartesian coordinate system. Some of the integral points are blocked, and others are not. Two integral points *A* and *B* on the plane are 4-connected if and only if:
- the Euclidean distance between *A* and *B* is one unit and neither *A* nor *B* is blocked; - or there is ... | The first line contains an integer *n* (0<=≤<=*n*<=≤<=4·107). | Print a single integer — the minimum number of points that should be blocked. | [
"1\n",
"2\n",
"3\n"
] | [
"4\n",
"8\n",
"16\n"
] | none | 500 | [
{
"input": "1",
"output": "4"
},
{
"input": "2",
"output": "8"
},
{
"input": "3",
"output": "16"
},
{
"input": "4",
"output": "20"
},
{
"input": "0",
"output": "1"
},
{
"input": "30426905",
"output": "172120564"
},
{
"input": "38450759",
... | 1,411,032,256 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | Inpt=int(input())
Count1=4
for I in range(Inpt-1):
Count1*=2
if Inpt>0:print(Count1)
else:print(1)
| Title: Blocked Points
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine you have an infinite 2D plane with Cartesian coordinate system. Some of the integral points are blocked, and others are not. Two integral points *A* and *B* on the plane are 4-connected if and only if:
- the Eu... | ```python
Inpt=int(input())
Count1=4
for I in range(Inpt-1):
Count1*=2
if Inpt>0:print(Count1)
else:print(1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,699,519,133 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<iostream>
using namespace std;
int main(){
int a[5];
for (int i = 1; i <= 4; i ++)
cin >> a[i];
string s;
cin >> s;
int sum = 0;
for (int i = 0 ;i < s.size(); i ++)
sum += a[s[i]-'0'];
cout << sum << endl;
return 0;
} | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
#include<iostream>
using namespace std;
int main(){
int a[5];
for (int i = 1; i <= 4; i ++)
cin >> a[i];
string s;
cin >> s;
int sum = 0;
for (int i = 0 ;i < s.size(); i ++)
sum += a[s[i]-'0'];
cout << sum << endl;
return 0;
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
755 | A | PolandBall and Hypothesis | PROGRAMMING | 800 | [
"brute force",
"graphs",
"math",
"number theory"
] | null | null | PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is a prime number".
Unfortunately, PolandBall is not experienced yet and doesn't know that his hypothesis is inc... | The only number in the input is *n* (1<=≤<=*n*<=≤<=1000) — number from the PolandBall's hypothesis. | Output such *m* that *n*·*m*<=+<=1 is not a prime number. Your answer will be considered correct if you output any suitable *m* such that 1<=≤<=*m*<=≤<=103. It is guaranteed the the answer exists. | [
"3\n",
"4\n"
] | [
"1",
"2"
] | A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself.
For the first sample testcase, 3·1 + 1 = 4. We can output 1.
In the second sample testcase, 4·1 + 1 = 5. We cannot output 1 because 5 is prime. However, *m* = 2 is okay since 4·2 + 1 = 9, which is not... | 500 | [
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "2"
},
{
"input": "153",
"output": "1"
},
{
"input": "1000",
"output": "1"
},
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "4"
... | 1,680,017,350 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 63 | 62 | 0 | n = int(input())
if n == 1: print(3)
elif n % 2 == 1: print(1)
elif n % 3 == 1: print(2)
elif n % 3 == 2: print(4)
else: print(n +2) | Title: PolandBall and Hypothesis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is... | ```python
n = int(input())
if n == 1: print(3)
elif n % 2 == 1: print(1)
elif n % 3 == 1: print(2)
elif n % 3 == 2: print(4)
else: print(n +2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
8 | B | Obsession with Robots | PROGRAMMING | 1,400 | [
"constructive algorithms",
"graphs",
"implementation"
] | B. Obsession with Robots | 2 | 64 | The whole world got obsessed with robots,and to keep pace with the progress, great Berland's programmer Draude decided to build his own robot. He was working hard at the robot. He taught it to walk the shortest path from one point to another, to record all its movements, but like in many Draude's programs, there was a ... | The first line of the input file contains the recording of the robot's movements. This recording is a non-empty string, consisting of uppercase Latin letters L, R, U and D, standing for movements left, right, up and down respectively. The length of the string does not exceed 100. | In the first line output the only word OK (if the above described map exists), or BUG (if such a map does not exist). | [
"LLUUUR\n",
"RRUULLDD\n"
] | [
"OK\n",
"BUG\n"
] | none | 0 | [
{
"input": "LLUUUR",
"output": "OK"
},
{
"input": "RRUULLDD",
"output": "BUG"
},
{
"input": "L",
"output": "OK"
},
{
"input": "R",
"output": "OK"
},
{
"input": "R",
"output": "OK"
},
{
"input": "RR",
"output": "OK"
},
{
"input": "DL",
"... | 1,624,856,829 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 216 | 0 | s = input()
x, y = 0, 0
for i in range(len(s)):
if s[i] == 'L':
x -= 1
elif s[i] == 'R':
x += 1
elif s[i] == 'D':
y -= 1
else:
y += 1
if x == 0 and y == 0:
print('BUG')
else:
print('OK') | Title: Obsession with Robots
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
The whole world got obsessed with robots,and to keep pace with the progress, great Berland's programmer Draude decided to build his own robot. He was working hard at the robot. He taught it to walk the shortest path fr... | ```python
s = input()
x, y = 0, 0
for i in range(len(s)):
if s[i] == 'L':
x -= 1
elif s[i] == 'R':
x += 1
elif s[i] == 'D':
y -= 1
else:
y += 1
if x == 0 and y == 0:
print('BUG')
else:
print('OK')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
90 | B | African Crossword | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | B. African Crossword | 2 | 256 | An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Next *n* lines contain *m* lowercase Latin letters each. That is the crossword grid. | Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter. | [
"3 3\ncba\nbcd\ncbc\n",
"5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf\n"
] | [
"abcd",
"codeforces"
] | none | 1,000 | [
{
"input": "3 3\ncba\nbcd\ncbc",
"output": "abcd"
},
{
"input": "5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf",
"output": "codeforces"
},
{
"input": "4 4\nusah\nusha\nhasu\nsuha",
"output": "ahhasusu"
},
{
"input": "7 5\naabcd\neffgh\niijkk\nlmnoo\npqqrs\nttuvw\nxxyyz",
"output... | 1,449,695,960 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 124 | 0 | n, m = map(int, input().split())
g = [input() for i in range(n)]
rc = [[0] * 26 for i in range(n)]
cc = [[0] * 26 for j in range(m)]
for i in range(n):
for j, ch in enumerate(g[i]):
k = ord(ch) - ord('a')
rc[i][k] += 1
cc[j][k] += 1
v = []
for i in range(n):
for j, ch in enume... | Title: African Crossword
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To s... | ```python
n, m = map(int, input().split())
g = [input() for i in range(n)]
rc = [[0] * 26 for i in range(n)]
cc = [[0] * 26 for j in range(m)]
for i in range(n):
for j, ch in enumerate(g[i]):
k = ord(ch) - ord('a')
rc[i][k] += 1
cc[j][k] += 1
v = []
for i in range(n):
for j, c... | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
628 | C | Bear and String Distance | PROGRAMMING | 1,300 | [
"greedy",
"strings"
] | null | null | Limak is a little polar bear. He likes nice strings — strings of length *n*, consisting of lowercase English letters only.
The distance between two letters is defined as the difference between their positions in the alphabet. For example, , and .
Also, the distance between two nice strings is defined as the sum of di... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=106).
The second line contains a string *s* of length *n*, consisting of lowercase English letters. | If there is no string satisfying the given conditions then print "-1" (without the quotes).
Otherwise, print any nice string *s*' that . | [
"4 26\nbear\n",
"2 7\naf\n",
"3 1000\nhey\n"
] | [
"roar",
"db\n",
"-1\n"
] | none | 0 | [
{
"input": "4 26\nbear",
"output": "zcar"
},
{
"input": "2 7\naf",
"output": "hf"
},
{
"input": "3 1000\nhey",
"output": "-1"
},
{
"input": "5 50\nkzsij",
"output": "zaiij"
},
{
"input": "5 500\nvsdxg",
"output": "-1"
},
{
"input": "1 0\na",
"outpu... | 1,611,017,127 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 204,800 | import sys
n, k = (map(int, input().split()))
str = input()
a = list(max(int(ord(c) - ord('a')), int(ord('z') - ord(c))) for c in str)
if sum(a) < k :
print (-1)
exit()
for i in range(len(str)):
if k >= a[i]:
print('a' if int(ord(str[i]) - ord('a')) == a[i] else 'z', end = '')
... | Title: Bear and String Distance
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He likes nice strings — strings of length *n*, consisting of lowercase English letters only.
The distance between two letters is defined as the difference between their positions ... | ```python
import sys
n, k = (map(int, input().split()))
str = input()
a = list(max(int(ord(c) - ord('a')), int(ord('z') - ord(c))) for c in str)
if sum(a) < k :
print (-1)
exit()
for i in range(len(str)):
if k >= a[i]:
print('a' if int(ord(str[i]) - ord('a')) == a[i] else 'z', end =... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
630 | A | Again Twenty Five! | PROGRAMMING | 800 | [
"number theory"
] | null | null | The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and get last two digits of the number. Yes, of course, *n* can be rather big, and one cannot find the power us... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·1018) — the power in which you need to raise number 5. | Output the last two digits of 5*n* without spaces between them. | [
"2\n"
] | [
"25"
] | none | 0 | [
{
"input": "2",
"output": "25"
},
{
"input": "7",
"output": "25"
},
{
"input": "1000000000000000000",
"output": "25"
},
{
"input": "2000000000000000000",
"output": "25"
},
{
"input": "987654321012345678",
"output": "25"
}
] | 1,692,220,380 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 500 | 19,660,800 | n=int(input())
print(5**n%100) | Title: Again Twenty Five!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and ge... | ```python
n=int(input())
print(5**n%100)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
989 | B | A Tide of Riverscape | PROGRAMMING | 1,200 | [
"constructive algorithms",
"strings"
] | null | null | "Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its own period, and I think I've figured out this one," says Mino with confidence.
Doubtfully, Kanno peeks a... | The first line contains two space-separated integers $n$ and $p$ ($1 \leq p \leq n \leq 2000$) — the length of the given string and the supposed period, respectively.
The second line contains a string $s$ of $n$ characters — Mino's records. $s$ only contains characters '0', '1' and '.', and contains at least one '.' c... | Output one line — if it's possible that $p$ is not a period of the resulting string, output any one of such strings; otherwise output "No" (without quotes, you can print letters in any case (upper or lower)). | [
"10 7\n1.0.1.0.1.\n",
"10 6\n1.0.1.1000\n",
"10 9\n1........1\n"
] | [
"1000100010\n",
"1001101000\n",
"No\n"
] | In the first example, $7$ is not a period of the resulting string because the $1$-st and $8$-th characters of it are different.
In the second example, $6$ is not a period of the resulting string because the $4$-th and $10$-th characters of it are different.
In the third example, $9$ is always a period because the onl... | 1,000 | [
{
"input": "10 7\n1.0.1.0.1.",
"output": "1000100010"
},
{
"input": "10 6\n1.0.1.1000",
"output": "1001101000"
},
{
"input": "10 9\n1........1",
"output": "No"
},
{
"input": "1 1\n.",
"output": "No"
},
{
"input": "5 1\n0...1",
"output": "00001"
},
{
"i... | 1,528,743,261 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | a , b = map(int , input().split())
x = list(str(input()))
s = ['0'] + x
bo = 0
for i in range(1,a+1):
j = i + b
if j > a : break
if s[i] == '0' and s[j] != '0':
bo = 1
if s[j] == '.':
s[j] = '1'
break
if s[i] == '1' and s[j] != '1':
bo = 2
if s[j] == '.':
s[j] = ... | Title: A Tide of Riverscape
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its... | ```python
a , b = map(int , input().split())
x = list(str(input()))
s = ['0'] + x
bo = 0
for i in range(1,a+1):
j = i + b
if j > a : break
if s[i] == '0' and s[j] != '0':
bo = 1
if s[j] == '.':
s[j] = '1'
break
if s[i] == '1' and s[j] != '1':
bo = 2
if s[j] == '.':
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
540 | A | Combination Lock | PROGRAMMING | 800 | [
"implementation"
] | null | null | Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is represented by *n* rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of disks on the combination lock.
The second line contains a string of *n* digits — the original state of the disks.
The third line contains a string of *n* digits — Scrooge McDuck's combination that opens the lock. | Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock. | [
"5\n82195\n64723\n"
] | [
"13\n"
] | In the sample he needs 13 moves:
- 1 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b8967f65a723782358b93eff9ce69f336817cf70.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 2 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/07fa58573ece0d32... | 500 | [
{
"input": "5\n82195\n64723",
"output": "13"
},
{
"input": "12\n102021090898\n010212908089",
"output": "16"
},
{
"input": "1\n8\n1",
"output": "3"
},
{
"input": "2\n83\n57",
"output": "7"
},
{
"input": "10\n0728592530\n1362615763",
"output": "27"
},
{
... | 1,617,707,344 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 109 | 0 | # A. Combination Lock
n=int(input())
s=input()
o=input()
c=0
for i in range(n):
f=abs(ord(o[i])-ord(s[i]))
b=10-f
c+=min(f,b)
# print(f,b,c)
print(c)
| Title: Combination Lock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is ... | ```python
# A. Combination Lock
n=int(input())
s=input()
o=input()
c=0
for i in range(n):
f=abs(ord(o[i])-ord(s[i]))
b=10-f
c+=min(f,b)
# print(f,b,c)
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
299 | B | Ksusha the Squirrel | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to the end of the road, that is, get to sector *n*. Unfortunately, there are some rocks on the road. We know ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=3·105,<=1<=≤<=*k*<=≤<=3·105). The next line contains *n* characters — the description of the road: the *i*-th character equals ".", if the *i*-th sector contains no rocks. Otherwise, it equals "#".
It is guaranteed that the first and the last characters e... | Print "YES" (without the quotes) if Ksusha can reach the end of the road, otherwise print "NO" (without the quotes). | [
"2 1\n..\n",
"5 2\n.#.#.\n",
"7 3\n.#.###.\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 1,000 | [
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "5 2\n.#.#.",
"output": "YES"
},
{
"input": "7 3\n.#.###.",
"output": "NO"
},
{
"input": "2 200\n..",
"output": "YES"
},
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "2 2\n..",
"output": "Y... | 1,683,454,271 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n,j=map(int,input().split())
r=input()
l=list(r)
count=0
max=0
for i in range (n):
if l[i]=="#":
count+=1
if max<count:
max=count
if l[i]!='#':
count=0
if count>=j:
print('NO')
else:
print('YES')
| Title: Ksusha the Squirrel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to t... | ```python
n,j=map(int,input().split())
r=input()
l=list(r)
count=0
max=0
for i in range (n):
if l[i]=="#":
count+=1
if max<count:
max=count
if l[i]!='#':
count=0
if count>=j:
print('NO')
else:
print('YES')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
652 | C | Foe Pairs | PROGRAMMING | 1,800 | [
"combinatorics",
"sortings",
"two pointers"
] | null | null | You are given a permutation *p* of length *n*. Also you are given *m* foe pairs (*a**i*,<=*b**i*) (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*).
Your task is to count the number of different intervals (*x*,<=*y*) (1<=≤<=*x*<=≤<=*y*<=≤<=*n*) that do not contain any foe pairs. So you shouldn't count intervals (*x... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3·105) — the length of the permutation *p* and the number of foe pairs.
The second line contains *n* distinct integers *p**i* (1<=≤<=*p**i*<=≤<=*n*) — the elements of the permutation *p*.
Each of the next *m* lines contains two integers (*a**i*,<=*... | Print the only integer *c* — the number of different intervals (*x*,<=*y*) that does not contain any foe pairs.
Note that the answer can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | [
"4 2\n1 3 2 4\n3 2\n2 4\n",
"9 5\n9 7 2 3 1 4 6 5 8\n1 6\n4 5\n2 7\n7 2\n2 7\n"
] | [
"5\n",
"20\n"
] | In the first example the intervals from the answer are (1, 1), (1, 2), (2, 2), (3, 3) and (4, 4). | 0 | [
{
"input": "4 2\n1 3 2 4\n3 2\n2 4",
"output": "5"
},
{
"input": "9 5\n9 7 2 3 1 4 6 5 8\n1 6\n4 5\n2 7\n7 2\n2 7",
"output": "20"
},
{
"input": "2 1\n1 2\n1 2",
"output": "2"
},
{
"input": "10 3\n4 10 5 1 6 8 9 2 3 7\n10 5\n2 10\n4 1",
"output": "39"
},
{
"input"... | 1,465,578,476 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
#include <vector>
#include <map>
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
typedef long long ll;
const int N = 3e5 + 10;
vector<int> G[N];
int mp[N],vis[N],a[N];
int check(int u)
{
int cnt = 0;
for(int i = 0; i < G[u].size(); ++i)
... | Title: Foe Pairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a permutation *p* of length *n*. Also you are given *m* foe pairs (*a**i*,<=*b**i*) (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*).
Your task is to count the number of different intervals (*x*,<=*y*) (1<=... | ```python
#include <iostream>
#include <vector>
#include <map>
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
typedef long long ll;
const int N = 3e5 + 10;
vector<int> G[N];
int mp[N],vis[N],a[N];
int check(int u)
{
int cnt = 0;
for(int i = 0; i < G[u].size();... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
903 | A | Hungry Student Problem | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat. | Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO. | [
"2\n6\n5\n"
] | [
"YES\nNO\n"
] | In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | 0 | [
{
"input": "2\n6\n5",
"output": "YES\nNO"
},
{
"input": "100\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n18\n19\n20\n21\n22\n23\n24\n25\n26\n27\n28\n29\n30\n31\n32\n33\n34\n35\n36\n37\n38\n39\n40\n41\n42\n43\n44\n45\n46\n47\n48\n49\n50\n51\n52\n53\n54\n55\n56\n57\n58\n59\n60\n61\n62\... | 1,606,900,760 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | def chickens (total) :
if total%3== 0 or total%7 == 0 :
return "YES"
else :
if total%3 == 1 and total//2 >= 2 :
return "YES"
elif total%3 == 2 and total//2 >= 4 :
return "YES"
return "NO"
... | Title: Hungry Student Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chun... | ```python
def chickens (total) :
if total%3== 0 or total%7 == 0 :
return "YES"
else :
if total%3 == 1 and total//2 >= 2 :
return "YES"
elif total%3 == 2 and total//2 >= 4 :
return "YES"
retur... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
892 | B | Wrath | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the *i*-th person kills the *j*-th person if and only if *j*<=<<=*i* and *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — the number of guilty people.
Second line contains *n* space-separated integers *L*1,<=*L*2,<=...,<=*L**n* (0<=≤<=*L**i*<=≤<=109), where *L**i* is the length of the *i*-th person's claw. | Print one integer — the total number of alive people after the bell rings. | [
"4\n0 1 0 10\n",
"2\n0 0\n",
"10\n1 1 3 0 0 0 2 1 0 3\n"
] | [
"1\n",
"2\n",
"3\n"
] | In first sample the last person kills everyone in front of him. | 1,000 | [
{
"input": "4\n0 1 0 10",
"output": "1"
},
{
"input": "2\n0 0",
"output": "2"
},
{
"input": "10\n1 1 3 0 0 0 2 1 0 3",
"output": "3"
},
{
"input": "10\n0 0 2 0 0 3 3 2 2 0",
"output": "2"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "5\n0 0 0 1 0"... | 1,693,237,588 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
L = list(map(int, input().split()))
s = []
for i, c in enumerate(L):
while s and s[-1] < i - c:
s.pop()
s.append(i)
print(len(s)) | Title: Wrath
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same ... | ```python
n = int(input())
L = list(map(int, input().split()))
s = []
for i, c in enumerate(L):
while s and s[-1] < i - c:
s.pop()
s.append(i)
print(len(s))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
777 | B | Game of Credit Cards | PROGRAMMING | 1,300 | [
"data structures",
"dp",
"greedy",
"sortings"
] | null | null | After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simple: each player bring his favourite *n*-digit credit card. Then both players name the digits written on the... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits in the cards Sherlock and Moriarty are going to use.
The second line contains *n* digits — Sherlock's credit card number.
The third line contains *n* digits — Moriarty's credit card number. | First print the minimum possible number of flicks Moriarty will get. Then print the maximum possible number of flicks that Sherlock can get from Moriarty. | [
"3\n123\n321\n",
"2\n88\n00\n"
] | [
"0\n2\n",
"2\n0\n"
] | First sample is elaborated in the problem statement. In the second sample, there is no way Moriarty can avoid getting two flicks. | 1,000 | [
{
"input": "3\n123\n321",
"output": "0\n2"
},
{
"input": "2\n88\n00",
"output": "2\n0"
},
{
"input": "1\n4\n5",
"output": "0\n1"
},
{
"input": "1\n8\n7",
"output": "1\n0"
},
{
"input": "2\n55\n55",
"output": "0\n0"
},
{
"input": "3\n534\n432",
"out... | 1,487,940,358 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 61 | 4,608,000 | n=int(input())
a=list(map(int,list(input())))
b=list(map(int,list(input())))
c=[0]*11
for i in b:c[i]+=1
d=list(c)
s1=0
for i in a:
for j in range(i+1,11):
if c[j]>0:c[j]-=1;s1+=1;break
s2=0
for i in a:
for j in range(i,11):
if d[j]>0:d[j]-=1;break
elif j==9:s2+=1
print(s2)
print(s1)
| Title: Game of Credit Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simpl... | ```python
n=int(input())
a=list(map(int,list(input())))
b=list(map(int,list(input())))
c=[0]*11
for i in b:c[i]+=1
d=list(c)
s1=0
for i in a:
for j in range(i+1,11):
if c[j]>0:c[j]-=1;s1+=1;break
s2=0
for i in a:
for j in range(i,11):
if d[j]>0:d[j]-=1;break
elif j==9:s2+=1
print(s2)
pri... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
631 | A | Interview | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function *f*(*x*,<=*l*,<=*r*) as a bitwise OR of integers *x... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the length of the arrays.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=109).
The third line contains *n* integers *b**i* (0<=≤<=*b**i*<=≤<=109). | Print a single integer — the maximum value of sum *f*(*a*,<=*l*,<=*r*)<=+<=*f*(*b*,<=*l*,<=*r*) among all possible 1<=≤<=*l*<=≤<=*r*<=≤<=*n*. | [
"5\n1 2 4 3 2\n2 3 3 12 1\n",
"10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6\n"
] | [
"22",
"46"
] | Bitwise OR of two non-negative integers *a* and *b* is the number *c* = *a* *OR* *b*, such that each of its digits in binary notation is 1 if and only if at least one of *a* or *b* have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is *l* = 2 and *r* = 4, because *... | 500 | [
{
"input": "5\n1 2 4 3 2\n2 3 3 12 1",
"output": "22"
},
{
"input": "10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6",
"output": "46"
},
{
"input": "25\n12 30 38 109 81 124 80 33 38 48 29 78 96 48 96 27 80 77 102 65 80 113 31 118 35\n25 64 95 13 12 6 111 80 85 16 61 119 23 65 73 65 20 9... | 1,602,936,368 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 140 | 102,400 | n = int(input())
data1 = [int(x) for x in input().split()]
data2 = [int(x) for x in input().split()]
k = 0
for i in range(len(data2)):
k = k | data2[i]
k1 = 0
for i in range(len(data1)):
k1 = k1 | data1[i]
print(k1 + k) | Title: Interview
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of... | ```python
n = int(input())
data1 = [int(x) for x in input().split()]
data2 = [int(x) for x in input().split()]
k = 0
for i in range(len(data2)):
k = k | data2[i]
k1 = 0
for i in range(len(data1)):
k1 = k1 | data1[i]
print(k1 + k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,687,376,727 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | #https://codeforces.com/problemset/problem/337/A
n, m = (map(int,input().split()))
f = list(map(int, input().split()))
f.sort()
cont = (f[m-1]) - (f[0])
ans = 0
for k in range(n, m, 1):
ans = f[k - 1] - f[k - n]
ans = abs(ans)
cont = min(cont, ans)
print(cont) | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
#https://codeforces.com/problemset/problem/337/A
n, m = (map(int,input().split()))
f = list(map(int, input().split()))
f.sort()
cont = (f[m-1]) - (f[0])
ans = 0
for k in range(n, m, 1):
ans = f[k - 1] - f[k - n]
ans = abs(ans)
cont = min(cont, ans)
print(cont)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,640,438,550 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 62 | 409,600 | import string
n,k =map(int,input().split())
d=string.ascii_letters[:k]
pw =d
d =d*(n//k +1)
pw = pw +d[:n-k]
print(pw)
| Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
import string
n,k =map(int,input().split())
d=string.ascii_letters[:k]
pw =d
d =d*(n//k +1)
pw = pw +d[:n-k]
print(pw)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
985 | A | Chess Placing | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | You are given a chessboard of size 1<=×<=*n*. It is guaranteed that *n* is even. The chessboard is painted like this: "BWBW...BW".
Some cells of the board are occupied by the chess pieces. Each cell contains no more than one chess piece. It is known that the total number of pieces equals to .
In one step you can move... | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100, *n* is even) — the size of the chessboard.
The second line of the input contains integer numbers (1<=≤<=*p**i*<=≤<=*n*) — initial positions of the pieces. It is guaranteed that all the positions are distinct. | Print one integer — the minimum number of moves you have to make to place all the pieces in the cells of the same color. | [
"6\n1 2 6\n",
"10\n1 2 3 4 5\n"
] | [
"2\n",
"10\n"
] | In the first example the only possible strategy is to move the piece at the position 6 to the position 5 and move the piece at the position 2 to the position 3. Notice that if you decide to place the pieces in the white cells the minimum number of moves will be 3.
In the second example the possible strategy is to move... | 0 | [
{
"input": "6\n1 2 6",
"output": "2"
},
{
"input": "10\n1 2 3 4 5",
"output": "10"
},
{
"input": "2\n2",
"output": "0"
},
{
"input": "100\n2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 ... | 1,647,426,811 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 31 | 0 | n=int(input())
l=list(map(int,input().strip().split()))
l.sort()
lo=[i for i in range(1,n+1,2)]
le=[i for i in range(2,n+1,2)]
odd,even=0,0
for i in range(n//2):
odd+=abs(lo[i]-l[i])
even+=abs(le[i]-l[i])
print(min(odd,even)) | Title: Chess Placing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a chessboard of size 1<=×<=*n*. It is guaranteed that *n* is even. The chessboard is painted like this: "BWBW...BW".
Some cells of the board are occupied by the chess pieces. Each cell contains no more than... | ```python
n=int(input())
l=list(map(int,input().strip().split()))
l.sort()
lo=[i for i in range(1,n+1,2)]
le=[i for i in range(2,n+1,2)]
odd,even=0,0
for i in range(n//2):
odd+=abs(lo[i]-l[i])
even+=abs(le[i]-l[i])
print(min(odd,even))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
559 | B | Equivalent Strings | PROGRAMMING | 1,700 | [
"divide and conquer",
"hashing",
"sortings",
"strings"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 1,000 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,645,566,733 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | def solve(a, b, num): if a == b: return True if int(num%2) == 1: return False a1 = '' a2 = '' b1 = '' b2 = '' a1 = a[0 :int(num/2)] a2 = a[int(num/2) : ] b1 = b[0: int(num/2)] b2 = b[int(num/2) :] if(solve(a1, b2, int(num/2))): return solve(a2, b1, int(num/... | Title: Equivalent Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split str... | ```python
def solve(a, b, num): if a == b: return True if int(num%2) == 1: return False a1 = '' a2 = '' b1 = '' b2 = '' a1 = a[0 :int(num/2)] a2 = a[int(num/2) : ] b1 = b[0: int(num/2)] b2 = b[int(num/2) :] if(solve(a1, b2, int(num/2))): return solve(a2, b1... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
103 | A | Testing Pants for Sadness | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"math"
] | A. Testing Pants for Sadness | 2 | 256 | The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of *n* questions; the questions are to be answered strictly in the order in which they are given, from question 1 t... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). It is the number of questions in the test. The second line contains space-separated *n* positive integers *a**i* (1<=≤<=*a**i*<=≤<=109), the number of answer variants to question *i*. | Print a single number — the minimal number of clicks needed to pass the test it the worst-case scenario.
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"2\n1 1\n",
"2\n2 2\n",
"1\n10\n"
] | [
"2",
"5",
"10"
] | Note to the second sample. In the worst-case scenario you will need five clicks:
- the first click selects the first variant to the first question, this answer turns out to be wrong. - the second click selects the second variant to the first question, it proves correct and we move on to the second question; - the ... | 500 | [
{
"input": "2\n1 1",
"output": "2"
},
{
"input": "2\n2 2",
"output": "5"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "3\n2 4 1",
"output": "10"
},
{
"input": "4\n5 5 3 1",
"output": "22"
},
{
"input": "2\n1000000000 1000000000",
"output": "... | 1,594,145,730 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 216 | 6,656,000 | n=int(input())
l=list(map(int,input().split()))
i=0
x=0
for j in range(n):
x=x+(l[j]-1)*(j+1)+1
print(x) | Title: Testing Pants for Sadness
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of *n* q... | ```python
n=int(input())
l=list(map(int,input().split()))
i=0
x=0
for j in range(n):
x=x+(l[j]-1)*(j+1)+1
print(x)
``` | 3.933602 | MatrixStudio/Codeforces-Python-Submissions |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,559,505,917 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s = input()
i = -1
d = ['h','e','l','l','o']
for ch in d:
i = s.find(ch, i+1)
if i == -1:
print("NO")
exit()
'print("YES") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = input()
i = -1
d = ['h','e','l','l','o']
for ch in d:
i = s.find(ch, i+1)
if i == -1:
print("NO")
exit()
'print("YES")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
1,009 | B | Minimum Ternary String | PROGRAMMING | 1,400 | [
"greedy",
"implementation"
] | null | null | You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa).
For e... | The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive). | Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero). | [
"100210\n",
"11222121\n",
"20\n"
] | [
"001120\n",
"11112222\n",
"20\n"
] | none | 0 | [
{
"input": "100210",
"output": "001120"
},
{
"input": "11222121",
"output": "11112222"
},
{
"input": "20",
"output": "20"
},
{
"input": "1002",
"output": "0012"
},
{
"input": "10",
"output": "01"
},
{
"input": "000021",
"output": "000012"
},
{
... | 1,532,060,322 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | k=list(map(int,input()))
c=0
for i in range(len(k)):
if (a[i] == 2):
pass2 = True
if (a[i] == 0 & pass2 = True):
pass2 = False
k[c:i].sort()
c = i
print(k) | Title: Minimum Ternary String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) ... | ```python
k=list(map(int,input()))
c=0
for i in range(len(k)):
if (a[i] == 2):
pass2 = True
if (a[i] == 0 & pass2 = True):
pass2 = False
k[c:i].sort()
c = i
print(k)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,628,351,193 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 124 | 6,963,200 | n = int(input())
strn = str(n)
condition = False;
count = 0
for i in strn:
if((i == '1' or i == '4') and i != "0" and count < 2):
if(i=="4"):
count += 1
else:
condition = True
count = 0
else:
condition = False
print("YES") if condition e... | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
n = int(input())
strn = str(n)
condition = False;
count = 0
for i in strn:
if((i == '1' or i == '4') and i != "0" and count < 2):
if(i=="4"):
count += 1
else:
condition = True
count = 0
else:
condition = False
print("YES") if c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
534 | B | Covered Path | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"math"
] | null | null | The on-board computer on Polycarp's car measured that the car speed at the beginning of some section of the path equals *v*1 meters per second, and in the end it is *v*2 meters per second. We know that this section of the route took exactly *t* seconds to pass.
Assuming that at each of the seconds the speed is constan... | The first line contains two integers *v*1 and *v*2 (1<=≤<=*v*1,<=*v*2<=≤<=100) — the speeds in meters per second at the beginning of the segment and at the end of the segment, respectively.
The second line contains two integers *t* (2<=≤<=*t*<=≤<=100) — the time when the car moves along the segment in seconds, *d* (0<... | Print the maximum possible length of the path segment in meters. | [
"5 6\n4 2\n",
"10 10\n10 0\n"
] | [
"26",
"100"
] | In the first sample the sequence of speeds of Polycarpus' car can look as follows: 5, 7, 8, 6. Thus, the total path is 5 + 7 + 8 + 6 = 26 meters.
In the second sample, as *d* = 0, the car covers the whole segment at constant speed *v* = 10. In *t* = 10 seconds it covers the distance of 100 meters. | 1,000 | [
{
"input": "5 6\n4 2",
"output": "26"
},
{
"input": "10 10\n10 0",
"output": "100"
},
{
"input": "87 87\n2 10",
"output": "174"
},
{
"input": "1 11\n6 2",
"output": "36"
},
{
"input": "100 10\n10 10",
"output": "550"
},
{
"input": "1 1\n100 10",
"o... | 1,659,213,644 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 11 | 62 | 0 | import sys
input = sys.stdin.readline
a, b = map(int, input().split())
t, d = map(int, input().split())
s = a+b
for i in range(1, t-1):
x = i*d+a
if x <= (b+d*(t-2-i)):
s += x
else:
c = 1
for j in range(t-1, i, -1):
s += b+d*c
c += 1
br... | Title: Covered Path
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The on-board computer on Polycarp's car measured that the car speed at the beginning of some section of the path equals *v*1 meters per second, and in the end it is *v*2 meters per second. We know that this section of the ... | ```python
import sys
input = sys.stdin.readline
a, b = map(int, input().split())
t, d = map(int, input().split())
s = a+b
for i in range(1, t-1):
x = i*d+a
if x <= (b+d*(t-2-i)):
s += x
else:
c = 1
for j in range(t-1, i, -1):
s += b+d*c
c += 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
888 | C | K-Dominant Character | PROGRAMMING | 1,400 | [
"binary search",
"implementation",
"two pointers"
] | null | null | You are given a string *s* consisting of lowercase Latin letters. Character *c* is called *k*-dominant iff each substring of *s* with length at least *k* contains this character *c*.
You have to find minimum *k* such that there exists at least one *k*-dominant character. | The first line contains string *s* consisting of lowercase Latin letters (1<=≤<=|*s*|<=≤<=100000). | Print one number — the minimum value of *k* such that there exists at least one *k*-dominant character. | [
"abacaba\n",
"zzzzz\n",
"abcde\n"
] | [
"2\n",
"1\n",
"3\n"
] | none | 0 | [
{
"input": "abacaba",
"output": "2"
},
{
"input": "zzzzz",
"output": "1"
},
{
"input": "abcde",
"output": "3"
},
{
"input": "bcaccacaaabaacaabaaabcbbcbcaacacbcbaaaacccacbbcbaabcbacaacbabacacacaccbbccbcbacbbbbccccabcabaaab",
"output": "8"
},
{
"input": "daabcdabbab... | 1,513,082,688 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 6,144,000 | from os import *
while True:
startfile("a.py")
| Title: K-Dominant Character
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting of lowercase Latin letters. Character *c* is called *k*-dominant iff each substring of *s* with length at least *k* contains this character *c*.
You have to find minimum *k* s... | ```python
from os import *
while True:
startfile("a.py")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
633 | A | Ebony and Ivory | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
For every bullet that hits the shield, Ebony deals *a* units of damage while Ivory deals *b* units of ... | The first line of the input contains three integers *a*, *b*, *c* (1<=≤<=*a*,<=*b*<=≤<=100,<=1<=≤<=*c*<=≤<=10<=000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively. | Print "Yes" (without quotes) if Dante can deal exactly *c* damage to the shield and "No" (without quotes) otherwise. | [
"4 6 15\n",
"3 2 7\n",
"6 11 6\n"
] | [
"No\n",
"Yes\n",
"Yes\n"
] | In the second sample, Dante can fire 1 bullet from Ebony and 2 from Ivory to deal exactly 1·3 + 2·2 = 7 damage. In the third sample, Dante can fire 1 bullet from ebony and no bullets from ivory to do 1·6 + 0·11 = 6 damage. | 250 | [
{
"input": "4 6 15",
"output": "No"
},
{
"input": "3 2 7",
"output": "Yes"
},
{
"input": "6 11 6",
"output": "Yes"
},
{
"input": "3 12 15",
"output": "Yes"
},
{
"input": "5 5 10",
"output": "Yes"
},
{
"input": "6 6 7",
"output": "No"
},
{
"... | 1,646,832,761 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 22 | 62 | 512,000 | def solve(m, n):
if n == 0:
return m, 1, 0
d, x0, y0 = solve(n, m % n)
x = y0
y = x - (m // n) * y0
return d, x, y
a, b, c = map(int, input().split())
d, x, y = solve(a, b)
if c % d:
print('No')
else:
x *= c / d
y *= c / d
if x >= 0 and y >= 0:
prin... | Title: Ebony and Ivory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
F... | ```python
def solve(m, n):
if n == 0:
return m, 1, 0
d, x0, y0 = solve(n, m % n)
x = y0
y = x - (m // n) * y0
return d, x, y
a, b, c = map(int, input().split())
d, x, y = solve(a, b)
if c % d:
print('No')
else:
x *= c / d
y *= c / d
if x >= 0 and y >= 0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,679,066,495 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 46 | 0 | import math
n = int(input())
print(math.comb(2 * n - 2, n - 1)) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
import math
n = int(input())
print(math.comb(2 * n - 2, n - 1))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
898 | B | Proper Nutrition | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"number theory"
] | null | null | Vasya has *n* burles. One bottle of Ber-Cola costs *a* burles and one Bars bar costs *b* burles. He can buy any non-negative integer number of bottles of Ber-Cola and any non-negative integer number of Bars bars.
Find out if it's possible to buy some amount of bottles of Ber-Cola and Bars bars and spend exactly *n* bu... | First line contains single integer *n* (1<=≤<=*n*<=≤<=10<=000<=000) — amount of money, that Vasya has.
Second line contains single integer *a* (1<=≤<=*a*<=≤<=10<=000<=000) — cost of one bottle of Ber-Cola.
Third line contains single integer *b* (1<=≤<=*b*<=≤<=10<=000<=000) — cost of one Bars bar. | If Vasya can't buy Bars and Ber-Cola in such a way to spend exactly *n* burles print «NO» (without quotes).
Otherwise in first line print «YES» (without quotes). In second line print two non-negative integers *x* and *y* — number of bottles of Ber-Cola and number of Bars bars Vasya should buy in order to spend exactly... | [
"7\n2\n3\n",
"100\n25\n10\n",
"15\n4\n8\n",
"9960594\n2551\n2557\n"
] | [
"YES\n2 1\n",
"YES\n0 10\n",
"NO\n",
"YES\n1951 1949\n"
] | In first example Vasya can buy two bottles of Ber-Cola and one Bars bar. He will spend exactly 2·2 + 1·3 = 7 burles.
In second example Vasya can spend exactly *n* burles multiple ways:
- buy two bottles of Ber-Cola and five Bars bars; - buy four bottles of Ber-Cola and don't buy Bars bars; - don't buy Ber-Cola an... | 750 | [
{
"input": "7\n2\n3",
"output": "YES\n2 1"
},
{
"input": "100\n25\n10",
"output": "YES\n0 10"
},
{
"input": "15\n4\n8",
"output": "NO"
},
{
"input": "9960594\n2551\n2557",
"output": "YES\n1951 1949"
},
{
"input": "10000000\n1\n1",
"output": "YES\n0 10000000"
... | 1,600,310,247 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | //************************************************************
/* << AUTHOR : NAVEEN KUMAR >> */
//************************************************************
//*********
#include <bits/stdc++.h>
using namespace std;
//#pragma GCC optimize ("O3")
//#pragma GCC target ("sse4")
//#pragma GCC target("avx,av... | Title: Proper Nutrition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* burles. One bottle of Ber-Cola costs *a* burles and one Bars bar costs *b* burles. He can buy any non-negative integer number of bottles of Ber-Cola and any non-negative integer number of Bars bars.
Find... | ```python
//************************************************************
/* << AUTHOR : NAVEEN KUMAR >> */
//************************************************************
//*********
#include <bits/stdc++.h>
using namespace std;
//#pragma GCC optimize ("O3")
//#pragma GCC target ("sse4")
//#pragma GCC targ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=2,<=2] and [1,<=2,<=3] is not.
A permutation triple of permutations of length *n* (*a*,<=... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | If no Lucky Permutation Triple of length *n* exists print -1.
Otherwise, you need to print three lines. Each line contains *n* space-seperated integers. The first line must contain permutation *a*, the second line — permutation *b*, the third — permutation *c*.
If there are multiple solutions, print any of them. | [
"5\n",
"2\n"
] | [
"1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3\n",
"-1\n"
] | In Sample 1, the permutation triple ([1, 4, 3, 2, 0], [1, 0, 2, 4, 3], [2, 4, 0, 1, 3]) is Lucky Permutation Triple, as following holds:
- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a6bf1b9b57809dbec5021f65f89616f259587c07.png" style="max-width: 100.0%;max-height: 100.0%;"/>; - <img... | 0 | [
{
"input": "5",
"output": "1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3"
},
{
"input": "2",
"output": "-1"
},
{
"input": "8",
"output": "-1"
},
{
"input": "9",
"output": "0 1 2 3 4 5 6 7 8 \n0 1 2 3 4 5 6 7 8 \n0 2 4 6 8 1 3 5 7 "
},
{
"input": "2",
"output": "-1"
},
{... | 1,593,193,492 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 1,308 | 34,816,000 | import random
t=1
for _ in range(t):
n=int(input())
if(n%2==1):
a=[i for i in range(n)]
b=a
c=[(a[i]+b[i])%n for i in range(n)]
print(*a)
print(*b)
print(*c)
else:
print(-1)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=... | ```python
import random
t=1
for _ in range(t):
n=int(input())
if(n%2==1):
a=[i for i in range(n)]
b=a
c=[(a[i]+b[i])%n for i in range(n)]
print(*a)
print(*b)
print(*c)
else:
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | It is a balmy spring afternoon, and Farmer John's *n* cows are ruminating about link-cut cacti in their stalls. The cows, labeled 1 through *n*, are arranged so that the *i*-th cow occupies the *i*-th stall from the left. However, Elsie, after realizing that she will forever live in the shadows beyond Bessie's limeligh... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100<=000) — the number of cows and the length of Farmer John's nap, respectively. | Output a single integer, the maximum messiness that the Mischievous Mess Makers can achieve by performing no more than *k* swaps. | [
"5 2\n",
"1 10\n"
] | [
"10\n",
"0\n"
] | In the first sample, the Mischievous Mess Makers can swap the cows in the stalls 1 and 5 during the first minute, then the cows in stalls 2 and 4 during the second minute. This reverses the arrangement of cows, giving us a total messiness of 10.
In the second sample, there is only one cow, so the maximum possible mess... | 0 | [
{
"input": "5 2",
"output": "10"
},
{
"input": "1 10",
"output": "0"
},
{
"input": "100000 2",
"output": "399990"
},
{
"input": "1 1",
"output": "0"
},
{
"input": "8 3",
"output": "27"
},
{
"input": "7 1",
"output": "11"
},
{
"input": "1000... | 1,584,189,538 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | n,k=map(int,input().split())
if k==1:
print('0')
elif k>(n/2):
print((n/2)*n)
else:
print(k*2)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is a balmy spring afternoon, and Farmer John's *n* cows are ruminating about link-cut cacti in their stalls. The cows, labeled 1 through *n*, are arranged so that the *i*-th cow occupies the *i*-th stall from the left. However,... | ```python
n,k=map(int,input().split())
if k==1:
print('0')
elif k>(n/2):
print((n/2)*n)
else:
print(k*2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,586,350,527 | 2,147,483,647 | PyPy 3 | OK | TESTS | 20 | 342 | 1,740,800 | dic = {}
lae = []
ma = ""
n = int(input())
na,po = (input().strip()).split()
ma = na
# dic.update({na : int(po)})
dic[na] = int(po)
for _ in range(n-1):
na,po = (input().strip()).split()
dic[na] = dic.get(na,0) + int(po)
lae.append([na,dic[na]])
# if (dic[na] > dic[ma]): ma = na
max_ele = max(dic.values... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
dic = {}
lae = []
ma = ""
n = int(input())
na,po = (input().strip()).split()
ma = na
# dic.update({na : int(po)})
dic[na] = int(po)
for _ in range(n-1):
na,po = (input().strip()).split()
dic[na] = dic.get(na,0) + int(po)
lae.append([na,dic[na]])
# if (dic[na] > dic[ma]): ma = na
max_ele = max(... | 3.81603 | MatrixStudio/Codeforces-Python-Submissions |
837 | D | Round Subset | PROGRAMMING | 2,100 | [
"dp",
"math"
] | null | null | Let's call the roundness of the number the number of zeros to which it ends.
You have an array of *n* numbers. You need to choose a subset of exactly *k* numbers so that the roundness of the product of the selected numbers will be maximum possible. | The first line contains two integer numbers *n* and *k* (1<=≤<=*n*<=≤<=200,<=1<=≤<=*k*<=≤<=*n*).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1018). | Print maximal roundness of product of the chosen subset of length *k*. | [
"3 2\n50 4 20\n",
"5 3\n15 16 3 25 9\n",
"3 3\n9 77 13\n"
] | [
"3\n",
"3\n",
"0\n"
] | In the first example there are 3 subsets of 2 numbers. [50, 4] has product 200 with roundness 2, [4, 20] — product 80, roundness 1, [50, 20] — product 1000, roundness 3.
In the second example subset [15, 16, 25] has product 6000, roundness 3.
In the third example all subsets has product with roundness 0. | 0 | [
{
"input": "3 2\n50 4 20",
"output": "3"
},
{
"input": "5 3\n15 16 3 25 9",
"output": "3"
},
{
"input": "3 3\n9 77 13",
"output": "0"
},
{
"input": "1 1\n200000000",
"output": "8"
},
{
"input": "1 1\n3",
"output": "0"
},
{
"input": "3 1\n10000000000000... | 1,691,562,342 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | # LUOGU_RID: 119847934
'''111111111111111111111111111111111111111111111'''
print(0) | Title: Round Subset
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call the roundness of the number the number of zeros to which it ends.
You have an array of *n* numbers. You need to choose a subset of exactly *k* numbers so that the roundness of the product of the selected number... | ```python
# LUOGU_RID: 119847934
'''111111111111111111111111111111111111111111111'''
print(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
501 | A | Contest | PROGRAMMING | 900 | [
"implementation"
] | null | null | Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the ... | The first line contains four integers *a*, *b*, *c*, *d* (250<=≤<=*a*,<=*b*<=≤<=3500, 0<=≤<=*c*,<=*d*<=≤<=180).
It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round). | Output on a single line:
"Misha" (without the quotes), if Misha got more points than Vasya.
"Vasya" (without the quotes), if Vasya got more points than Misha.
"Tie" (without the quotes), if both of them got the same number of points. | [
"500 1000 20 30\n",
"1000 1000 1 1\n",
"1500 1000 176 177\n"
] | [
"Vasya\n",
"Tie\n",
"Misha\n"
] | none | 500 | [
{
"input": "500 1000 20 30",
"output": "Vasya"
},
{
"input": "1000 1000 1 1",
"output": "Tie"
},
{
"input": "1500 1000 176 177",
"output": "Misha"
},
{
"input": "1500 1000 74 177",
"output": "Misha"
},
{
"input": "750 2500 175 178",
"output": "Vasya"
},
{
... | 1,694,254,587 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 0 | a, b, c, d = map(int, input().split())
m = max(a*3//10, a - a//250*c)
v = max(b*3//10, b - b//250*d)
if m > v:
print("Misha")
elif m < v:
print("Vasya")
else:
print("Tie")
#1 4
#4
#5 4 3 2
#2 1 3 2
#3
| Title: Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved t... | ```python
a, b, c, d = map(int, input().split())
m = max(a*3//10, a - a//250*c)
v = max(b*3//10, b - b//250*d)
if m > v:
print("Misha")
elif m < v:
print("Vasya")
else:
print("Tie")
#1 4
#4
#5 4 3 2
#2 1 3 2
#3
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
845 | C | Two TVs | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at a... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of shows.
Each of the next *n* lines contains two integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=109) — starting and ending time of *i*-th show. | If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes). | [
"3\n1 2\n2 3\n4 5\n",
"4\n1 2\n2 3\n2 3\n1 2\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "3\n1 2\n2 3\n4 5",
"output": "YES"
},
{
"input": "4\n1 2\n2 3\n2 3\n1 2",
"output": "NO"
},
{
"input": "4\n0 1\n1 2\n2 3\n3 4",
"output": "YES"
},
{
"input": "3\n1 2\n2 3\n2 4",
"output": "NO"
},
{
"input": "3\n0 100\n0 100\n0 100",
"output": "NO"
... | 1,603,432,352 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 717 | 16,179,200 | import sys
count = 0
lesson_list = []
for line in sys.stdin:
if count == 0:
num = int(line.strip())
count += 1
continue
start = int(line.strip().split(' ')[0])
end = int(line.strip().split(' ')[1])
lesson_list.append((start, end))
lesson_list.sort()
a_status = True
b_status... | Title: Two TVs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He ... | ```python
import sys
count = 0
lesson_list = []
for line in sys.stdin:
if count == 0:
num = int(line.strip())
count += 1
continue
start = int(line.strip().split(' ')[0])
end = int(line.strip().split(' ')[1])
lesson_list.append((start, end))
lesson_list.sort()
a_status = Tru... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
997 | B | Roman Digits | PROGRAMMING | 2,000 | [
"brute force",
"combinatorics",
"dp",
"greedy",
"math"
] | null | null | Let's introduce a number system which is based on a roman digits. There are digits I, V, X, L which correspond to the numbers $1$, $5$, $10$ and $50$ respectively. The use of other roman digits is not allowed.
Numbers in this system are written as a sequence of one or more digits. We define the value of the sequence s... | The only line of the input file contains a single integer $n$ ($1 \le n \le 10^9$) — the number of roman digits to use. | Output a single integer — the number of distinct integers which can be represented using $n$ roman digits exactly. | [
"1\n",
"2\n",
"10\n"
] | [
"4\n",
"10\n",
"244\n"
] | In the first sample there are exactly $4$ integers which can be represented — I, V, X and L.
In the second sample it is possible to represent integers $2$ (II), $6$ (VI), $10$ (VV), $11$ (XI), $15$ (XV), $20$ (XX), $51$ (IL), $55$ (VL), $60$ (XL) and $100$ (LL). | 1,250 | [
{
"input": "1",
"output": "4"
},
{
"input": "2",
"output": "10"
},
{
"input": "10",
"output": "244"
},
{
"input": "1000",
"output": "48753"
},
{
"input": "2000",
"output": "97753"
},
{
"input": "5000",
"output": "244753"
},
{
"input": "1000... | 1,558,834,504 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | values = {
'M': 1000,
'D': 500,
'C': 100,
'L': 50,
'X': 10,
'V': 5,
'I': 1
}
def convert_roman_to_decimal(roman):
if not roman:
return 0
pchar = roman[-1]
decimal = values[pchar]
for char in reversed(roman[:-1]):
decimal += values[char] * ... | Title: Roman Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's introduce a number system which is based on a roman digits. There are digits I, V, X, L which correspond to the numbers $1$, $5$, $10$ and $50$ respectively. The use of other roman digits is not allowed.
Numbers in ... | ```python
values = {
'M': 1000,
'D': 500,
'C': 100,
'L': 50,
'X': 10,
'V': 5,
'I': 1
}
def convert_roman_to_decimal(roman):
if not roman:
return 0
pchar = roman[-1]
decimal = values[pchar]
for char in reversed(roman[:-1]):
decimal += value... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
678 | D | Iterated Linear Function | PROGRAMMING | 1,700 | [
"math",
"number theory"
] | null | null | Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find the value of *g*(*n*)(*x*) modulo 109<=+<=7. | The only line contains four integers *A*, *B*, *n* and *x* (1<=≤<=*A*,<=*B*,<=*x*<=≤<=109,<=1<=≤<=*n*<=≤<=1018) — the parameters from the problem statement.
Note that the given value *n* can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you c... | Print the only integer *s* — the value *g*(*n*)(*x*) modulo 109<=+<=7. | [
"3 4 1 1\n",
"3 4 2 1\n",
"3 4 3 1\n"
] | [
"7\n",
"25\n",
"79\n"
] | none | 0 | [
{
"input": "3 4 1 1",
"output": "7"
},
{
"input": "3 4 2 1",
"output": "25"
},
{
"input": "3 4 3 1",
"output": "79"
},
{
"input": "1 1 1 1",
"output": "2"
},
{
"input": "3 10 723 6",
"output": "443623217"
},
{
"input": "14 81 51 82",
"output": "908... | 1,610,860,113 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | def process(A,B,n,x):
mod_N = 10**9+7
if n == 0:
return x%(10**9+7)
if A == 1:
return (x + n*B)%(10**9+7)
else:
return ((((x-B/(1-A))%mod_N)*pow(A,n,mod_N))%mod_N + B/(1-A)%mod_N)%mod_N
if __name__ == '__main__':
A,B,n,x = list(map(int,input().strip().split(' ')))
print(... | Title: Iterated Linear Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find th... | ```python
def process(A,B,n,x):
mod_N = 10**9+7
if n == 0:
return x%(10**9+7)
if A == 1:
return (x + n*B)%(10**9+7)
else:
return ((((x-B/(1-A))%mod_N)*pow(A,n,mod_N))%mod_N + B/(1-A)%mod_N)%mod_N
if __name__ == '__main__':
A,B,n,x = list(map(int,input().strip().split(' ')))
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,698,924,380 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s=raw_input()
print s[0].upper() | Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
s=raw_input()
print s[0].upper()
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
570 | C | Replacement | PROGRAMMING | 1,600 | [
"constructive algorithms",
"data structures",
"implementation"
] | null | null | Daniel has a string *s*, consisting of lowercase English letters and period signs (characters '.'). Let's define the operation of replacement as the following sequence of steps: find a substring ".." (two consecutive periods) in string *s*, of all occurrences of the substring let's choose the first one, and replace thi... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=300<=000) the length of the string and the number of queries.
The second line contains string *s*, consisting of *n* lowercase English letters and period signs.
The following *m* lines contain the descriptions of queries. The *i*-th line contains i... | Print *m* numbers, one per line, the *i*-th of these numbers must be equal to the value of *f*(*s*) after performing the *i*-th assignment. | [
"10 3\n.b..bz....\n1 h\n3 c\n9 f\n",
"4 4\n.cc.\n2 .\n3 .\n2 a\n1 a\n"
] | [
"4\n3\n1\n",
"1\n3\n1\n1\n"
] | Note to the first sample test (replaced periods are enclosed in square brackets).
The original string is ".b..bz....".
- after the first query *f*(hb..bz....) = 4 ("hb[..]bz...." → "hb.bz[..].." → "hb.bz[..]." → "hb.bz[..]" → "hb.bz.")- after the second query *f*(hbс.bz....) = 3 ("hbс.bz[..].." → "hb... | 1,500 | [
{
"input": "10 3\n.b..bz....\n1 h\n3 c\n9 f",
"output": "4\n3\n1"
},
{
"input": "4 4\n.cc.\n2 .\n3 .\n2 a\n1 a",
"output": "1\n3\n1\n1"
},
{
"input": "3 3\n...\n1 .\n2 a\n3 b",
"output": "2\n0\n0"
},
{
"input": "5 1\n.....\n5 z",
"output": "3"
},
{
"input": "1 5\n... | 1,510,073,775 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 37,273,600 | import sys
def main():
def count():
ans = 0
for seg in segs:
if seg[2] == '.':
ans += (seg[1] - seg[0])
return ans
def insert(xi, ci):
nonlocal segs, n
for i in range(len(segs)):
seg = segs[i]
# single element
... | Title: Replacement
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Daniel has a string *s*, consisting of lowercase English letters and period signs (characters '.'). Let's define the operation of replacement as the following sequence of steps: find a substring ".." (two consecutive period... | ```python
import sys
def main():
def count():
ans = 0
for seg in segs:
if seg[2] == '.':
ans += (seg[1] - seg[0])
return ans
def insert(xi, ci):
nonlocal segs, n
for i in range(len(segs)):
seg = segs[i]
# single elemen... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
888 | D | Almost Identity Permutations | PROGRAMMING | 1,600 | [
"combinatorics",
"dp",
"math"
] | null | null | A permutation *p* of size *n* is an array such that every integer from 1 to *n* occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least *n*<=-<=*k* indices *i* (1<=≤<=*i*<=≤<=*n*) such that *p**i*<==<=*i*.
Your task is to count the number of almost identity ... | The first line contains two integers *n* and *k* (4<=≤<=*n*<=≤<=1000, 1<=≤<=*k*<=≤<=4). | Print the number of almost identity permutations for given *n* and *k*. | [
"4 1\n",
"4 2\n",
"5 3\n",
"5 4\n"
] | [
"1\n",
"7\n",
"31\n",
"76\n"
] | none | 0 | [
{
"input": "4 1",
"output": "1"
},
{
"input": "4 2",
"output": "7"
},
{
"input": "5 3",
"output": "31"
},
{
"input": "5 4",
"output": "76"
},
{
"input": "200 1",
"output": "1"
},
{
"input": "200 2",
"output": "19901"
},
{
"input": "200 3",
... | 1,615,016,640 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 62 | 307,200 | mod = 1e9+7
def power(a):
re = 1
for i in range(1,a+1):
re*=i;
return re
def func(n):
if n==0:
return 1
sum = 0
for i in range(2,n+1):
sum+=pow(-1,i)/power(i)
return power(n)*sum
def C(a,b):
return power(b)/(power(b-a)*power(a));
_in = input()
n = int(_in[:-1])
k = int(_in[-1:])
sum=0;
for i in range... | Title: Almost Identity Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation *p* of size *n* is an array such that every integer from 1 to *n* occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least *n*<=-<=*... | ```python
mod = 1e9+7
def power(a):
re = 1
for i in range(1,a+1):
re*=i;
return re
def func(n):
if n==0:
return 1
sum = 0
for i in range(2,n+1):
sum+=pow(-1,i)/power(i)
return power(n)*sum
def C(a,b):
return power(b)/(power(b-a)*power(a));
_in = input()
n = int(_in[:-1])
k = int(_in[-1:])
sum=0;
for ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
26 | B | Regular Bracket Sequence | PROGRAMMING | 1,400 | [
"greedy"
] | B. Regular Bracket Sequence | 5 | 256 | A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters «+» and «1» into this sequence. For example, sequences «(())()», «()» and «(()(()))» are regular, while «)(», «(()» and «(()))(» are not.
One day Johnny got bracket sequence. He decided to remove some... | Input consists of a single line with non-empty string of «(» and «)» characters. Its length does not exceed 106. | Output the maximum possible length of a regular bracket sequence. | [
"(()))(\n",
"((()())\n"
] | [
"4\n",
"6\n"
] | none | 1,000 | [
{
"input": "(()))(",
"output": "4"
},
{
"input": "((()())",
"output": "6"
},
{
"input": "(",
"output": "0"
},
{
"input": ")",
"output": "0"
},
{
"input": ")(()(",
"output": "2"
},
{
"input": "))))))(",
"output": "0"
},
{
"input": "()()(()((... | 1,589,236,709 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 654 | 3,174,400 | s = input()
c = 0
r = 0
n = len(s)
for x in s:
if x == "(":
c += 1
else:
if c == 0:
r += 1
else:
c -= 1
print(n - (r + c)) | Title: Regular Bracket Sequence
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters «+» and «1» into this sequence. For example, sequences «(())()», «()» and «(()(()))» are regula... | ```python
s = input()
c = 0
r = 0
n = len(s)
for x in s:
if x == "(":
c += 1
else:
if c == 0:
r += 1
else:
c -= 1
print(n - (r + c))
``` | 3.928687 | MatrixStudio/Codeforces-Python-Submissions |
888 | D | Almost Identity Permutations | PROGRAMMING | 1,600 | [
"combinatorics",
"dp",
"math"
] | null | null | A permutation *p* of size *n* is an array such that every integer from 1 to *n* occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least *n*<=-<=*k* indices *i* (1<=≤<=*i*<=≤<=*n*) such that *p**i*<==<=*i*.
Your task is to count the number of almost identity ... | The first line contains two integers *n* and *k* (4<=≤<=*n*<=≤<=1000, 1<=≤<=*k*<=≤<=4). | Print the number of almost identity permutations for given *n* and *k*. | [
"4 1\n",
"4 2\n",
"5 3\n",
"5 4\n"
] | [
"1\n",
"7\n",
"31\n",
"76\n"
] | none | 0 | [
{
"input": "4 1",
"output": "1"
},
{
"input": "4 2",
"output": "7"
},
{
"input": "5 3",
"output": "31"
},
{
"input": "5 4",
"output": "76"
},
{
"input": "200 1",
"output": "1"
},
{
"input": "200 2",
"output": "19901"
},
{
"input": "200 3",
... | 1,653,231,124 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 46 | 512,000 | # (4 ≤ n ≤ 1000, 1 ≤ k ≤ 4)
D4 = 9
D3 = 2
D2 = 1
D1 = 0
x = input().split()
n = int(x[0])
k = int(x[1])
# answer in this cases is 1 + sigma Di * nCi i from 2 to k
summa = 0
if k == 1:
print(1)
else:
if k == 2:
print(((n*(n-1))//2)*D2 + 1)
elif k == 3:
print(((n*(n-1)*(n-2))/... | Title: Almost Identity Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation *p* of size *n* is an array such that every integer from 1 to *n* occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least *n*<=-<=*... | ```python
# (4 ≤ n ≤ 1000, 1 ≤ k ≤ 4)
D4 = 9
D3 = 2
D2 = 1
D1 = 0
x = input().split()
n = int(x[0])
k = int(x[1])
# answer in this cases is 1 + sigma Di * nCi i from 2 to k
summa = 0
if k == 1:
print(1)
else:
if k == 2:
print(((n*(n-1))//2)*D2 + 1)
elif k == 3:
print(((n*(n-... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
710 | E | Generate a String | PROGRAMMING | 2,000 | [
"dfs and similar",
"dp"
] | null | null | zscoder wants to generate an input file for some programming competition problem.
His input is a string consisting of *n* letters 'a'. He is too lazy to write a generator so he will manually generate the input in a text editor.
Initially, the text editor is empty. It takes him *x* seconds to insert or delete a letter... | The only line contains three integers *n*, *x* and *y* (1<=≤<=*n*<=≤<=107, 1<=≤<=*x*,<=*y*<=≤<=109) — the number of letters 'a' in the input file and the parameters from the problem statement. | Print the only integer *t* — the minimum amount of time needed to generate the input file. | [
"8 1 1\n",
"8 1 10\n"
] | [
"4\n",
"8\n"
] | none | 0 | [
{
"input": "8 1 1",
"output": "4"
},
{
"input": "8 1 10",
"output": "8"
},
{
"input": "10 62 99",
"output": "384"
},
{
"input": "88 417 591",
"output": "4623"
},
{
"input": "57 5289 8444",
"output": "60221"
},
{
"input": "382 81437847 324871127",
"... | 1,654,916,097 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 78 | 0 | n, x, y = map(int, input().split())
INF = 10**18
memo = {}
def dfs(n):
if n in memo:
return memo[n]
if n == 1:
return x
if n == 0:
return 0
if n < 0:
return INF
res = INF
res = min(n*x, (n-(n//2)*2)*x+y+dfs(n//2), (((n+1)//2)*2-n)*x+y+dfs((n+1)//2))... | Title: Generate a String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
zscoder wants to generate an input file for some programming competition problem.
His input is a string consisting of *n* letters 'a'. He is too lazy to write a generator so he will manually generate the input in a t... | ```python
n, x, y = map(int, input().split())
INF = 10**18
memo = {}
def dfs(n):
if n in memo:
return memo[n]
if n == 1:
return x
if n == 0:
return 0
if n < 0:
return INF
res = INF
res = min(n*x, (n-(n//2)*2)*x+y+dfs(n//2), (((n+1)//2)*2-n)*x+y+dfs(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
670 | D1 | Magic Powder - 1 | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation"
] | null | null | This problem is given in two versions that differ only by constraints. If you can solve this problem in large constraints, then you can just write a single solution to the both versions. If you find the problem too difficult in large constraints, you can write solution to the simplified version only.
Waking up in the ... | The first line of the input contains two positive integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1000) — the number of ingredients and the number of grams of the magic powder.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where the *i*-th number is equal to the number of grams of... | Print the maximum number of cookies, which Apollinaria will be able to bake using the ingredients that she has and the magic powder. | [
"3 1\n2 1 4\n11 3 16\n",
"4 3\n4 3 5 6\n11 12 14 20\n"
] | [
"4\n",
"3\n"
] | In the first sample it is profitably for Apollinaria to make the existing 1 gram of her magic powder to ingredient with the index 2, then Apollinaria will be able to bake 4 cookies.
In the second sample Apollinaria should turn 1 gram of magic powder to ingredient with the index 1 and 1 gram of magic powder to ingredie... | 1,000 | [
{
"input": "3 1\n2 1 4\n11 3 16",
"output": "4"
},
{
"input": "4 3\n4 3 5 6\n11 12 14 20",
"output": "3"
},
{
"input": "10 926\n5 6 8 1 2 5 1 8 4 4\n351 739 998 725 953 970 906 691 707 1000",
"output": "137"
},
{
"input": "20 925\n7 3 1 2 1 3 1 3 1 2 3 1 5 8 1 3 7 3 4 2\n837 ... | 1,680,069,678 | 2,147,483,647 | Python 3 | OK | TESTS | 119 | 77 | 0 | n, k=map(int,input().split())
a=list(map(int, input().split()))
b=list(map(int, input().split()))
ans = 0
while True:
for i in range(n):
if b[i]<a[i]:
k-=a[i]-b[i]
b[i]=a[i]
b[i]-=a[i]
if k>=0:
ans+=1
else: break
print(ans) | Title: Magic Powder - 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem is given in two versions that differ only by constraints. If you can solve this problem in large constraints, then you can just write a single solution to the both versions. If you find the problem too dif... | ```python
n, k=map(int,input().split())
a=list(map(int, input().split()))
b=list(map(int, input().split()))
ans = 0
while True:
for i in range(n):
if b[i]<a[i]:
k-=a[i]-b[i]
b[i]=a[i]
b[i]-=a[i]
if k>=0:
ans+=1
else: break
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
702 | B | Powers of Two | PROGRAMMING | 1,500 | [
"brute force",
"data structures",
"implementation",
"math"
] | null | null | You are given *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Find the number of pairs of indexes *i*,<=*j* (*i*<=<<=*j*) that *a**i*<=+<=*a**j* is a power of 2 (i. e. some integer *x* exists so that *a**i*<=+<=*a**j*<==<=2*x*). | The first line contains the single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print the number of pairs of indexes *i*,<=*j* (*i*<=<<=*j*) that *a**i*<=+<=*a**j* is a power of 2. | [
"4\n7 3 2 1\n",
"3\n1 1 1\n"
] | [
"2\n",
"3\n"
] | In the first example the following pairs of indexes include in answer: (1, 4) and (2, 4).
In the second example all pairs of indexes (*i*, *j*) (where *i* < *j*) include in answer. | 0 | [
{
"input": "4\n7 3 2 1",
"output": "2"
},
{
"input": "3\n1 1 1",
"output": "3"
},
{
"input": "1\n1000000000",
"output": "0"
},
{
"input": "10\n2827343 1373647 96204862 723505 796619138 71550121 799843967 5561265 402690754 446173607",
"output": "2"
},
{
"input": "1... | 1,676,560,024 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | from numpy import log2 as ln
count = 0
n = input()
num_list_str = input()
num_list = num_list_str.split()
ind = 0
for i in num_list:
for j in num_list[ind+1:]:
comp = ln(int(i)+int(j)) / ln(2)
if int(comp) - comp == 0:
count = count + 1
ind = ind + 1
print(count)
| Title: Powers of Two
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Find the number of pairs of indexes *i*,<=*j* (*i*<=<<=*j*) that *a**i*<=+<=*a**j* is a power of 2 (i. e. some integer *x* exists so that *a**i*<=+<=*a**j*<==<=2*x... | ```python
from numpy import log2 as ln
count = 0
n = input()
num_list_str = input()
num_list = num_list_str.split()
ind = 0
for i in num_list:
for j in num_list[ind+1:]:
comp = ln(int(i)+int(j)) / ln(2)
if int(comp) - comp == 0:
count = count + 1
ind = ind + 1
print(count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
967 | A | Mind the Gap | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing lasts $1$ minute.
He was asked to insert one takeoff in the schedule. The takeoff takes $1$ minut... | The first line of input contains two integers $n$ and $s$ ($1 \le n \le 100$, $1 \le s \le 60$) — the number of landings on the schedule and the minimum allowed time (in minutes) between a landing and a takeoff.
Each of next $n$ lines contains two integers $h$ and $m$ ($0 \le h \le 23$, $0 \le m \le 59$) — the time, i... | Print two integers $h$ and $m$ — the hour and the minute from the current moment of the earliest time Arkady can insert the takeoff. | [
"6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40\n",
"16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59\n",
"3 17\n0 30\n1 0\n12 0\n"
] | [
"6 1\n",
"24 50\n",
"0 0\n"
] | In the first example note that there is not enough time between 1:20 and 3:21, because each landing and the takeoff take one minute.
In the second example there is no gaps in the schedule, so Arkady can only add takeoff after all landings. Note that it is possible that one should wait more than $24$ hours to insert th... | 500 | [
{
"input": "6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40",
"output": "6 1"
},
{
"input": "16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59",
"output": "24 50"
},
{
"input": "3 17\n0 30\n1 0\n12 0",
"output": "0 0"
},
{
... | 1,580,778,443 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | # def _input():
# return map(int, input().strip().split())
# def _print(s):
# print(''.join(map(str, s)))
n, s = map(int, input().strip().split())
mi = list()
for _ in range(n):
h, m = map(int, input().strip().split())
mi.append(h * 60 + m)
for i in range(1, n):
d = mi[i] - mi[i - 1] - 1... | Title: Mind the Gap
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing ... | ```python
# def _input():
# return map(int, input().strip().split())
# def _print(s):
# print(''.join(map(str, s)))
n, s = map(int, input().strip().split())
mi = list()
for _ in range(n):
h, m = map(int, input().strip().split())
mi.append(h * 60 + m)
for i in range(1, n):
d = mi[i] - mi[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
672 | A | Summer Camp | PROGRAMMING | 800 | [
"implementation"
] | null | null | Every year, hundreds of people come to summer camps, they learn new algorithms and solve hard problems.
This is your first year at summer camp, and you are asked to solve the following problem. All integers starting with 1 are written in one line. The prefix of these line is "123456789101112131415...". Your task is to... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the position of the digit you need to print. | Print the *n*-th digit of the line. | [
"3\n",
"11\n"
] | [
"3\n",
"0\n"
] | In the first sample the digit at position 3 is '3', as both integers 1 and 2 consist on one digit.
In the second sample, the digit at position 11 is '0', it belongs to the integer 10. | 500 | [
{
"input": "3",
"output": "3"
},
{
"input": "11",
"output": "0"
},
{
"input": "12",
"output": "1"
},
{
"input": "13",
"output": "1"
},
{
"input": "29",
"output": "9"
},
{
"input": "30",
"output": "2"
},
{
"input": "1000",
"output": "3"
... | 1,544,049,826 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 124 | 0 | s = ""
for i in range (0 , 1000) :
s+= str(i)
print(s[int(input())])
| Title: Summer Camp
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Every year, hundreds of people come to summer camps, they learn new algorithms and solve hard problems.
This is your first year at summer camp, and you are asked to solve the following problem. All integers starting with 1... | ```python
s = ""
for i in range (0 , 1000) :
s+= str(i)
print(s[int(input())])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
937 | B | Vile Grasshoppers | PROGRAMMING | 1,400 | [
"brute force",
"math",
"number theory"
] | null | null | The weather is fine today and hence it's high time to climb the nearby pine and enjoy the landscape.
The pine's trunk includes several branches, located one above another and numbered from 2 to *y*. Some of them (more precise, from 2 to *p*) are occupied by tiny vile grasshoppers which you're at war with. These grassh... | The only line contains two integers *p* and *y* (2<=≤<=*p*<=≤<=*y*<=≤<=109). | Output the number of the highest suitable branch. If there are none, print -1 instead. | [
"3 6\n",
"3 4\n"
] | [
"5\n",
"-1\n"
] | In the first sample case grasshopper from branch 2 reaches branches 2, 4 and 6 while branch 3 is initially settled by another grasshopper. Therefore the answer is 5.
It immediately follows that there are no valid branches in second sample case. | 1,000 | [
{
"input": "3 6",
"output": "5"
},
{
"input": "3 4",
"output": "-1"
},
{
"input": "2 2",
"output": "-1"
},
{
"input": "5 50",
"output": "49"
},
{
"input": "944192806 944193066",
"output": "944192807"
},
{
"input": "1000000000 1000000000",
"output":... | 1,521,747,262 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 61 | 21,401,600 | import sys
p, y = input().split()
p, y = [int(p), int(y)]
s = set()
for i in range(y, 3, -1):
if y%i==0:
if i>p:
print(y)
sys.exit(0)
print(-1) | Title: Vile Grasshoppers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The weather is fine today and hence it's high time to climb the nearby pine and enjoy the landscape.
The pine's trunk includes several branches, located one above another and numbered from 2 to *y*. Some of them (mor... | ```python
import sys
p, y = input().split()
p, y = [int(p), int(y)]
s = set()
for i in range(y, 3, -1):
if y%i==0:
if i>p:
print(y)
sys.exit(0)
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
585 | B | Phillip and Trains | PROGRAMMING | 1,700 | [
"dfs and similar",
"graphs",
"shortest paths"
] | null | null | The mobile application store has a new game called "Subway Roller".
The protagonist of the game Philip is located in one end of the tunnel and wants to get out of the other one. The tunnel is a rectangular field consisting of three rows and *n* columns. At the beginning of the game the hero is in some cell of the left... | Each test contains from one to ten sets of the input data. The first line of the test contains a single integer *t* (1<=≤<=*t*<=≤<=10 for pretests and tests or *t*<==<=1 for hacks; see the Notes section for details) — the number of sets.
Then follows the description of *t* sets of the input data.
The first line of t... | For each set of the input data print on a single line word YES, if it is possible to win the game and word NO otherwise. | [
"2\n16 4\n...AAAAA........\ns.BBB......CCCCC\n........DDDDD...\n16 4\n...AAAAA........\ns.BBB....CCCCC..\n.......DDDDD....\n",
"2\n10 4\ns.ZZ......\n.....AAABB\n.YYYYYY...\n10 4\ns.ZZ......\n....AAAABB\n.YYYYYY...\n"
] | [
"YES\nNO\n",
"YES\nNO\n"
] | In the first set of the input of the first sample Philip must first go forward and go down to the third row of the field, then go only forward, then go forward and climb to the second row, go forward again and go up to the first row. After that way no train blocks Philip's path, so he can go straight to the end of the ... | 750 | [] | 1,697,700,307 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | # Read the initial potential victims
victim1, victim2 = input().split()
n = int(input())
# Loop through each day to update the potential victims list
for _ in range(n):
print(victim1, victim2)
killed, new_victim = input().split()
if victim1 == killed:
victim1 = new_victim
else:
... | Title: Phillip and Trains
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The mobile application store has a new game called "Subway Roller".
The protagonist of the game Philip is located in one end of the tunnel and wants to get out of the other one. The tunnel is a rectangular field con... | ```python
# Read the initial potential victims
victim1, victim2 = input().split()
n = int(input())
# Loop through each day to update the potential victims list
for _ in range(n):
print(victim1, victim2)
killed, new_victim = input().split()
if victim1 == killed:
victim1 = new_victim
el... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,677,703,405 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 92 | 0 | o = int(input())
n = input()
n+=" "
num = ""
lis = []
for i in range(len(n)):
if(n[i]!=" "):
num+=n[i]
else:
lis.append(int(num))
num=""
s = [lis[0],lis[1],lis[2]]
ft = [0,0]
for i in s:
if i%2==0:
ft[0]+=1
else:
ft[1]+=1
if int(ft[0])>in... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
o = int(input())
n = input()
n+=" "
num = ""
lis = []
for i in range(len(n)):
if(n[i]!=" "):
num+=n[i]
else:
lis.append(int(num))
num=""
s = [lis[0],lis[1],lis[2]]
ft = [0,0]
for i in s:
if i%2==0:
ft[0]+=1
else:
ft[1]+=1
if int... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
548 | A | Mike and Fax | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"strings"
] | null | null | While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly *k* messages ... | The first line of input contains string *s* containing lowercase English letters (1<=≤<=|*s*|<=≤<=1000).
The second line contains integer *k* (1<=≤<=*k*<=≤<=1000). | Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise. | [
"saba\n2\n",
"saddastavvat\n2\n"
] | [
"NO\n",
"YES\n"
] | Palindrome is a string reading the same forward and backward.
In the second sample, the faxes in his back-bag can be "saddas" and "tavvat". | 500 | [
{
"input": "saba\n2",
"output": "NO"
},
{
"input": "saddastavvat\n2",
"output": "YES"
},
{
"input": "aaaaaaaaaa\n3",
"output": "NO"
},
{
"input": "aaaaaa\n3",
"output": "YES"
},
{
"input": "abaacca\n2",
"output": "NO"
},
{
"input": "a\n1",
"output"... | 1,432,658,761 | 661 | Python 3 | OK | TESTS | 56 | 62 | 0 | s = input()
n = int(input())
#a = [int(c) for c in input().split()]
wordlength = len(s)//n
if wordlength*n != len(s):
print("NO")
else:
current = wordlength
word = 0
yes = True
for i in range(n):
if not yes:
break
for j in range(wordlength):
if s[i*wordlengt... | Title: Mike and Fax
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure ... | ```python
s = input()
n = int(input())
#a = [int(c) for c in input().split()]
wordlength = len(s)//n
if wordlength*n != len(s):
print("NO")
else:
current = wordlength
word = 0
yes = True
for i in range(n):
if not yes:
break
for j in range(wordlength):
if s[i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
409 | C | Magnum Opus | PROGRAMMING | 1,700 | [
"*special"
] | null | null | Salve, mi amice.
Et tu quidem de lapis philosophorum. Barba non facit philosophum. Labor omnia vincit. Non potest creatio ex nihilo. Necesse est partibus.
Rp:
I Aqua Fortis
I Aqua Regia
II Amalgama
VII Minium
IV Vitriol
Misce in vitro et æstus, et nil admirari. Festina lente, et nulla tenaci... | The first line of input contains several space-separated integers *a**i* (0<=≤<=*a**i*<=≤<=100). | Print a single integer. | [
"2 4 6 8 10\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "2 4 6 8 10",
"output": "1"
},
{
"input": "50 27 17 31 89",
"output": "4"
},
{
"input": "50 87 29 81 21",
"output": "5"
},
{
"input": "74 21 36 68 80",
"output": "9"
},
{
"input": "75 82 48 95 12",
"output": "3"
},
{
"input": "41 85 14 43 23... | 1,606,432,759 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 202 | 2,150,400 | cnt = [1, 1, 2, 7, 4]
arr = map(int, input().split(" "))
for i in range(5):
arr[i] /= cnt[i]
print(min(arr)) | Title: Magnum Opus
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Salve, mi amice.
Et tu quidem de lapis philosophorum. Barba non facit philosophum. Labor omnia vincit. Non potest creatio ex nihilo. Necesse est partibus.
Rp:
I Aqua Fortis
I Aqua Regia
II Amalgama
VII... | ```python
cnt = [1, 1, 2, 7, 4]
arr = map(int, input().split(" "))
for i in range(5):
arr[i] /= cnt[i]
print(min(arr))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,687,186,181 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 92 | 0 | s = input()
t = input()
position = 1
for instruction in t:
if instruction == s[position - 1]:
position += 1
print(position)
| Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
s = input()
t = input()
position = 1
for instruction in t:
if instruction == s[position - 1]:
position += 1
print(position)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,617,007,886 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 77 | 307,200 | n=int(input())
a=[[0]*n]*n
for i in range(0,n):
for j in range(0,n):
a[i][0]=1
a[0][j]=1
for i in range(1,n):
for j in range(1,n):
a[i][j]=a[i-1][j]+a[i][j-1]
print(a[n-1][n-1]) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
n=int(input())
a=[[0]*n]*n
for i in range(0,n):
for j in range(0,n):
a[i][0]=1
a[0][j]=1
for i in range(1,n):
for j in range(1,n):
a[i][j]=a[i-1][j]+a[i][j-1]
print(a[n-1][n-1])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
614 | B | Gena's Code | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from each country, find their product. If it is turns to be too large, then the servers might have not en... | The first line of the input contains the number of countries *n* (1<=≤<=*n*<=≤<=100<=000). The second line contains *n* non-negative integers *a**i* without leading zeroes — the number of tanks of the *i*-th country.
It is guaranteed that the second line contains at least *n*<=-<=1 beautiful numbers and the total leng... | Print a single number without leading zeroes — the product of the number of tanks presented by each country. | [
"3\n5 10 1\n",
"4\n1 1 10 11\n",
"5\n0 3 1 100 1\n"
] | [
"50",
"110",
"0"
] | In sample 1 numbers 10 and 1 are beautiful, number 5 is not not.
In sample 2 number 11 is not beautiful (contains two '1's), all others are beautiful.
In sample 3 number 3 is not beautiful, all others are beautiful. | 1,000 | [
{
"input": "3\n5 10 1",
"output": "50"
},
{
"input": "4\n1 1 10 11",
"output": "110"
},
{
"input": "5\n0 3 1 100 1",
"output": "0"
},
{
"input": "40\n10 100 10 1 10 10 100 10 10 100 10 100 100 10 1824868942 100 100 1 10 100 100 10 100 100 10 100 10 1 10 100 100 100 10 1 10 1 ... | 1,669,145,514 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = int(input())
rec = 1
for i in range(n):
a = int(input())
rec = rec* a
print(rec) | Title: Gena's Code
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from eac... | ```python
n = int(input())
rec = 1
for i in range(n):
a = int(input())
rec = rec* a
print(rec)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,513,941,071 | 371 | Python 3 | OK | TESTS | 63 | 124 | 307,200 | n, d = [int(i) for i in input().split()]
a = input()
dp = [1e9] * n
dp[0] = 0
for i in range(1, n):
if a[i] == '0':
continue
for j in range(1, d + 1):
if i - j < 0:
break
dp[i] = min(dp[i], dp[i - j] + 1)
print(dp[-1] if dp[-1] != 1e9 else -1) | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
n, d = [int(i) for i in input().split()]
a = input()
dp = [1e9] * n
dp[0] = 0
for i in range(1, n):
if a[i] == '0':
continue
for j in range(1, d + 1):
if i - j < 0:
break
dp[i] = min(dp[i], dp[i - j] + 1)
print(dp[-1] if dp[-1] != 1e9 else -1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,686,441,819 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 14 | 61 | 0 | word=str(input())
check_word="hello"
i=0
if len(word)<=100 and len(word)>=3 :
if len(word)>=len(check_word):
for char in word:
if i!=len(check_word):
if char==check_word[i]:
i+=1
if i==len(check_word):
print("YES")
else:
... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
word=str(input())
check_word="hello"
i=0
if len(word)<=100 and len(word)>=3 :
if len(word)>=len(check_word):
for char in word:
if i!=len(check_word):
if char==check_word[i]:
i+=1
if i==len(check_word):
print("YES")
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her *t* queries, each of one of the following type:
1. <=+<= *a**i* — add non-negative integer *a**i* to the multiset. Note, that she has a multiset, thus there may b... | The first line of the input contains an integer *t* (1<=≤<=*t*<=≤<=100<=000) — the number of operation Sonya has to perform.
Next *t* lines provide the descriptions of the queries in order they appear in the input file. The *i*-th row starts with a character *c**i* — the type of the corresponding operation. If *c**i* ... | For each query of the third type print the number of integers matching the given pattern. Each integer is counted as many times, as it appears in the multiset at this moment of time. | [
"12\n+ 1\n+ 241\n? 1\n+ 361\n- 241\n? 0101\n+ 101\n? 101\n- 101\n? 101\n+ 4000\n? 0\n",
"4\n+ 200\n+ 200\n- 200\n? 0\n"
] | [
"2\n1\n2\n1\n1\n",
"1\n"
] | Consider the integers matching the patterns from the queries of the third type. Queries are numbered in the order they appear in the input.
1. 1 and 241. 1. 361. 1. 101 and 361. 1. 361. 1. 4000. | 0 | [
{
"input": "12\n+ 1\n+ 241\n? 1\n+ 361\n- 241\n? 0101\n+ 101\n? 101\n- 101\n? 101\n+ 4000\n? 0",
"output": "2\n1\n2\n1\n1"
},
{
"input": "4\n+ 200\n+ 200\n- 200\n? 0",
"output": "1"
},
{
"input": "20\n+ 61\n+ 99\n+ 51\n+ 70\n+ 7\n+ 34\n+ 71\n+ 86\n+ 68\n+ 39\n+ 78\n+ 81\n+ 89\n? 10\n? 00... | 1,474,012,982 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 1,000 | 1,126,400 | t = int(input())
a = [0] * 262144
for j in range(t):
s, z = input().split()
num = ''
for i in z:
if(i in ['0', '2', '4', '6', '8']):
num += '0'
else:
num += '1'
num = int(num, 2)
if(s[0] == '-'):
a[num] -= 1
elif(s[0] == '+'):
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her *t* queries, each of one of the following type:
1. <=+<= *a**i* — add no... | ```python
t = int(input())
a = [0] * 262144
for j in range(t):
s, z = input().split()
num = ''
for i in z:
if(i in ['0', '2', '4', '6', '8']):
num += '0'
else:
num += '1'
num = int(num, 2)
if(s[0] == '-'):
a[num] -= 1
elif(s[0] == '+')... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
255 | A | Greg's Workout | PROGRAMMING | 800 | [
"implementation"
] | null | null | Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercise... | The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. | Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous. | [
"2\n2 8\n",
"3\n5 1 10\n",
"7\n3 3 2 7 9 6 8\n"
] | [
"biceps\n",
"back\n",
"chest\n"
] | In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the mos... | 500 | [
{
"input": "2\n2 8",
"output": "biceps"
},
{
"input": "3\n5 1 10",
"output": "back"
},
{
"input": "7\n3 3 2 7 9 6 8",
"output": "chest"
},
{
"input": "4\n5 6 6 2",
"output": "chest"
},
{
"input": "5\n8 2 2 6 3",
"output": "chest"
},
{
"input": "6\n8 7 ... | 1,673,822,131 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | chest=0
biceps=0
back=0
chest_index=0
biceps_index=1
back_index=2
exercise_repeating=[]
number_of_exercises=int(input())
if 1<=number_of_exercises<=20:
for i in range(0,number_of_exercises):
number_of_repeating=int(input())
if 1<=number_of_repeating<=25:
exercise_repeating.appen... | Title: Greg's Workout
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg ... | ```python
chest=0
biceps=0
back=0
chest_index=0
biceps_index=1
back_index=2
exercise_repeating=[]
number_of_exercises=int(input())
if 1<=number_of_exercises<=20:
for i in range(0,number_of_exercises):
number_of_repeating=int(input())
if 1<=number_of_repeating<=25:
exercise_repea... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,435,164,614 | 1,214 | Python 3 | WRONG_ANSWER | PRETESTS | 1 | 31 | 0 | s = input()
res = 26
for i in range(len(s)):
if i % 2 == 0:
res += 25
else:
res += 26
print(res)
| Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
s = input()
res = 26
for i in range(len(s)):
if i % 2 == 0:
res += 25
else:
res += 26
print(res)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null |
Nephren is playing a game with little leprechauns.
She gives them an infinite array of strings, *f*0... ∞.
*f*0 is "What are you doing at the end of the world? Are you busy? Will you save us?".
She wants to let more people know about it, so she defines *f**i*<==<= "What are you doing while sending "*f**i*<=-<=1"? ... | The first line contains one integer *q* (1<=≤<=*q*<=≤<=10) — the number of Nephren's questions.
Each of the next *q* lines describes Nephren's question and contains two integers *n* and *k* (0<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=1018). | One line containing *q* characters. The *i*-th character in it should be the answer for the *i*-th query. | [
"3\n1 1\n1 2\n1 111111111111\n",
"5\n0 69\n1 194\n1 139\n0 47\n1 66\n",
"10\n4 1825\n3 75\n3 530\n4 1829\n4 1651\n3 187\n4 584\n4 255\n4 774\n2 474\n"
] | [
"Wh.",
"abdef",
"Areyoubusy"
] | For the first two examples, refer to *f*<sub class="lower-index">0</sub> and *f*<sub class="lower-index">1</sub> given in the legend. | 0 | [
{
"input": "3\n1 1\n1 2\n1 111111111111",
"output": "Wh."
},
{
"input": "5\n0 69\n1 194\n1 139\n0 47\n1 66",
"output": "abdef"
},
{
"input": "10\n4 1825\n3 75\n3 530\n4 1829\n4 1651\n3 187\n4 584\n4 255\n4 774\n2 474",
"output": "Areyoubusy"
},
{
"input": "1\n0 1",
"outpu... | 1,512,229,944 | 6,444 | Python 3 | MEMORY_LIMIT_EXCEEDED | PRETESTS | 4 | 265 | 268,390,400 | memo = {}
memo[-1] = "What are you doing at the end of the world? Are you busy? Will you save us?"
last = -1
final = ""
for _ in range(int(input())):
n, k = map(int, input().split(" "))
if n-1 not in memo:
index = last+1
while(index<n):
memo[index] = "What are you doing while sending \""+ memo[index... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nephren is playing a game with little leprechauns.
She gives them an infinite array of strings, *f*0... ∞.
*f*0 is "What are you doing at the end of the world? Are you busy? Will you save us?".
She wants to let more people kn... | ```python
memo = {}
memo[-1] = "What are you doing at the end of the world? Are you busy? Will you save us?"
last = -1
final = ""
for _ in range(int(input())):
n, k = map(int, input().split(" "))
if n-1 not in memo:
index = last+1
while(index<n):
memo[index] = "What are you doing while sending \""+ ... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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