contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third ... | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain ... | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,668,112,953 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 31 | 307,200 |
x = int(input())
y = list(map(str, input().split()))
J= []
for i in range(0,(x-1)*2,2):
if y[0][i].upper() != y[0][i+1]:
J.append(y[0][i])
for j in range(len(J)-1):
if J[j].upper() == y[0][i+1]:
J.pop(j)
print(len(J))
| Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from... | ```python
x = int(input())
y = list(map(str, input().split()))
J= []
for i in range(0,(x-1)*2,2):
if y[0][i].upper() != y[0][i+1]:
J.append(y[0][i])
for j in range(len(J)-1):
if J[j].upper() == y[0][i+1]:
J.pop(j)
print(len(J))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
985 | A | Chess Placing | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | You are given a chessboard of size 1<=×<=*n*. It is guaranteed that *n* is even. The chessboard is painted like this: "BWBW...BW".
Some cells of the board are occupied by the chess pieces. Each cell contains no more than one chess piece. It is known that the total number of pieces equals to .
In one step you can move... | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100, *n* is even) — the size of the chessboard.
The second line of the input contains integer numbers (1<=≤<=*p**i*<=≤<=*n*) — initial positions of the pieces. It is guaranteed that all the positions are distinct. | Print one integer — the minimum number of moves you have to make to place all the pieces in the cells of the same color. | [
"6\n1 2 6\n",
"10\n1 2 3 4 5\n"
] | [
"2\n",
"10\n"
] | In the first example the only possible strategy is to move the piece at the position 6 to the position 5 and move the piece at the position 2 to the position 3. Notice that if you decide to place the pieces in the white cells the minimum number of moves will be 3.
In the second example the possible strategy is to move... | 0 | [
{
"input": "6\n1 2 6",
"output": "2"
},
{
"input": "10\n1 2 3 4 5",
"output": "10"
},
{
"input": "2\n2",
"output": "0"
},
{
"input": "100\n2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 ... | 1,621,001,470 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 93 | 20,172,800 | n = int(input())
a = list(map(int, input().split(' ')))
a = sorted(a)
x = 0
y = 0
j = 1
for i in range(n//2):
x += abs(j-a[i])
j += 2
j = 2
for i in range(n//2):
y += abs(j-a[i])
j += 2
print(min(x, y)) | Title: Chess Placing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a chessboard of size 1<=×<=*n*. It is guaranteed that *n* is even. The chessboard is painted like this: "BWBW...BW".
Some cells of the board are occupied by the chess pieces. Each cell contains no more than... | ```python
n = int(input())
a = list(map(int, input().split(' ')))
a = sorted(a)
x = 0
y = 0
j = 1
for i in range(n//2):
x += abs(j-a[i])
j += 2
j = 2
for i in range(n//2):
y += abs(j-a[i])
j += 2
print(min(x, y))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,621,789,218 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 421 | 15,052,800 | n = int(input())
a = sorted(list(map(int, input().split())))
b = sorted(list(map(int, input().split()))) + [-1]
c = sorted(list(map(int, input().split()))) + [-1, -1]
for i in range(n):
if a[i] != b[i]:
print(a[i])
break
for i in range(n):
if b[i] != c[i]:
print(b[i])
... | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
n = int(input())
a = sorted(list(map(int, input().split())))
b = sorted(list(map(int, input().split()))) + [-1]
c = sorted(list(map(int, input().split()))) + [-1, -1]
for i in range(n):
if a[i] != b[i]:
print(a[i])
break
for i in range(n):
if b[i] != c[i]:
print(b[i])... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
248 | B | Chilly Willy | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | Chilly Willy loves playing with numbers. He only knows prime numbers that are digits yet. These numbers are 2, 3, 5 and 7. But Willy grew rather bored of such numbers, so he came up with a few games that were connected with them.
Chilly Willy wants to find the minimum number of length *n*, such that it is simultaneous... | A single input line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | Print a single integer — the answer to the problem without leading zeroes, or "-1" (without the quotes), if the number that meet the problem condition does not exist. | [
"1\n",
"5\n"
] | [
"-1\n",
"10080"
] | none | 1,000 | [
{
"input": "1",
"output": "-1"
},
{
"input": "5",
"output": "10080"
},
{
"input": "6",
"output": "100170"
},
{
"input": "4",
"output": "1050"
},
{
"input": "15",
"output": "100000000000110"
},
{
"input": "16",
"output": "1000000000000050"
},
{
... | 1,569,966,169 | 2,147,483,647 | Python 3 | OK | TESTS | 66 | 1,590 | 409,600 | #!/bin/python
n = int(input())
const = 2 * 3 * 5 * 7
if n < 3:
print(-1)
else:
print(((10 ** (n - 1)) // const + 1) * const) | Title: Chilly Willy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chilly Willy loves playing with numbers. He only knows prime numbers that are digits yet. These numbers are 2, 3, 5 and 7. But Willy grew rather bored of such numbers, so he came up with a few games that were connected wit... | ```python
#!/bin/python
n = int(input())
const = 2 * 3 * 5 * 7
if n < 3:
print(-1)
else:
print(((10 ** (n - 1)) // const + 1) * const)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,696,430,056 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | str=input()
def check(str):
for char in str:
if char in "HQ9":
return "YES"
return "NO"
result=check(str)
print(result) | Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
str=input()
def check(str):
for char in str:
if char in "HQ9":
return "YES"
return "NO"
result=check(str)
print(result)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,575,812,042 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 1,228,800 | n = int(input())
print(n*n//2 + (n%2))
for i in range(0,n):
for j in range(0,n):
if(i % 2 == 0 and j % 2 == 0):
print('C',end = '')
elif(i % 2 == 1 and j % 2 == 1):
print('C',end = '')
else:
print('.',end = '')
print()
| Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
n = int(input())
print(n*n//2 + (n%2))
for i in range(0,n):
for j in range(0,n):
if(i % 2 == 0 and j % 2 == 0):
print('C',end = '')
elif(i % 2 == 1 and j % 2 == 1):
print('C',end = '')
else:
print('.',end = '')
print()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
9 | C | Hexadecimal's Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation",
"math"
] | C. Hexadecimal's Numbers | 1 | 64 | One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural numbers from 1 to *n* to obtain total control over her energy.
But his plan failed. The reason for th... | Input data contains the only number *n* (1<=≤<=*n*<=≤<=109). | Output the only number — answer to the problem. | [
"10\n"
] | [
"2"
] | For *n* = 10 the answer includes numbers 1 and 10. | 0 | [
{
"input": "10",
"output": "2"
},
{
"input": "20",
"output": "3"
},
{
"input": "72",
"output": "3"
},
{
"input": "99",
"output": "3"
},
{
"input": "100",
"output": "4"
},
{
"input": "101",
"output": "5"
},
{
"input": "102",
"output": "5... | 1,676,989,716 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 92 | 0 | class solve:
def __init__(self):
n=int(input())
ans=0
for i in range(1,2**10-1):
b=int(bin(i).replace("0b",'0'))
if b<=n:
ans+=1
else:
break
print(ans)
obj=solve() | Title: Hexadecimal's Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural ... | ```python
class solve:
def __init__(self):
n=int(input())
ans=0
for i in range(1,2**10-1):
b=int(bin(i).replace("0b",'0'))
if b<=n:
ans+=1
else:
break
print(ans)
obj=solve()
``` | 3.954 | MatrixStudio/Codeforces-Python-Submissions |
317 | A | Perfect Pair | PROGRAMMING | 1,600 | [
"brute force"
] | null | null | Let us call a pair of integer numbers *m*-perfect, if at least one number in the pair is greater than or equal to *m*. Thus, the pairs (3, 3) and (0, 2) are 2-perfect while the pair (-1, 1) is not.
Two integers *x*, *y* are written on the blackboard. It is allowed to erase one of them and replace it with the sum of th... | Single line of the input contains three integers *x*, *y* and *m* (<=-<=1018<=≤<=*x*, *y*, *m*<=≤<=1018).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preffered to use the cin, cout streams or the %I64d specifier. | Print the minimum number of operations or "-1" (without quotes), if it is impossible to transform the given pair to the *m*-perfect one. | [
"1 2 5\n",
"-1 4 15\n",
"0 -1 5\n"
] | [
"2\n",
"4\n",
"-1\n"
] | In the first sample the following sequence of operations is suitable: (1, 2) <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> (3, 2) <img align="middle" class="tex-formula" src="https://espresso.cod... | 500 | [
{
"input": "1 2 5",
"output": "2"
},
{
"input": "-1 4 15",
"output": "4"
},
{
"input": "0 -1 5",
"output": "-1"
},
{
"input": "0 1 8",
"output": "5"
},
{
"input": "-134 -345 -134",
"output": "0"
},
{
"input": "-134 -345 -133",
"output": "-1"
},
... | 1,621,141,199 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 216 | 0 | x,y,m=map(int,input().split())
if x<=0 and y<=0 and x<m and y<m:
print(-1)
exit()
cnt=0
if x<0 and y>0:
m=(-x)//y
x+=m*y
cnt+=m
while x<m and y<m:
if x<y:
x+=y
else:
y+=x
cnt+=1
print(cnt) | Title: Perfect Pair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let us call a pair of integer numbers *m*-perfect, if at least one number in the pair is greater than or equal to *m*. Thus, the pairs (3, 3) and (0, 2) are 2-perfect while the pair (-1, 1) is not.
Two integers *x*, *y* a... | ```python
x,y,m=map(int,input().split())
if x<=0 and y<=0 and x<m and y<m:
print(-1)
exit()
cnt=0
if x<0 and y>0:
m=(-x)//y
x+=m*y
cnt+=m
while x<m and y<m:
if x<y:
x+=y
else:
y+=x
cnt+=1
print(cnt)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it la... | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on... | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,651,428,433 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 46 | 0 | number_of_socks, dates = map(int, input().split())
def calculate(number_of_socks, dates):
if number_of_socks == dates:
return number_of_socks + 1
count = 1
while count * dates <= number_of_socks:
count += 1
number_of_socks += 1
return number_of_socks
result = calculate... | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th... | ```python
number_of_socks, dates = map(int, input().split())
def calculate(number_of_socks, dates):
if number_of_socks == dates:
return number_of_socks + 1
count = 1
while count * dates <= number_of_socks:
count += 1
number_of_socks += 1
return number_of_socks
result =... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 0 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,570,512,724 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 108 | 0 | def main():
n = int(input())
seq = [int(c) for c in input().split()]
seq.sort()
s = sum(seq)
ans = 2 * s
for i in range(n-2):
s -= seq[i]
ans += s
print(ans)
if __name__ == "__main__":
main()
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and ... | ```python
def main():
n = int(input())
seq = [int(c) for c in input().split()]
seq.sort()
s = sum(seq)
ans = 2 * s
for i in range(n-2):
s -= seq[i]
ans += s
print(ans)
if __name__ == "__main__":
main()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
358 | B | Dima and Text Messages | PROGRAMMING | 1,500 | [
"brute force",
"strings"
] | null | null | Seryozha has a very changeable character. This time he refused to leave the room to Dima and his girlfriend (her hame is Inna, by the way). However, the two lovebirds can always find a way to communicate. Today they are writing text messages to each other.
Dima and Inna are using a secret code in their text messages. ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of words in Dima's message. Next *n* lines contain non-empty words, one word per line. The words only consist of small English letters. The total length of all words doesn't exceed 105.
The last line contains non-empty text message that Inna has got... | In a single line, print "yes" (without the quotes), if Dima decoded the text message correctly, and "no" (without the quotes) otherwise. | [
"3\ni\nlove\nyou\n<3i<3love<23you<3\n",
"7\ni\nam\nnot\nmain\nin\nthe\nfamily\n<3i<>3am<3the<3<main<3in<3the<3><3family<3\n"
] | [
"yes\n",
"no\n"
] | Please note that Dima got a good old kick in the pants for the second sample from the statement. | 1,000 | [
{
"input": "3\ni\nlove\nyou\n<3i<3love<23you<3",
"output": "yes"
},
{
"input": "7\ni\nam\nnot\nmain\nin\nthe\nfamily\n<3i<>3am<3the<3<main<3in<3the<3><3family<3",
"output": "no"
},
{
"input": "3\ni\nlove\nyou\n<3i<3lo<3ve<3y<<<<<<<ou3<3",
"output": "yes"
},
{
"input": "4\na\n... | 1,458,823,106 | 1,825 | Python 3 | WRONG_ANSWER | TESTS | 7 | 62 | 4,608,000 | #!/usr/bin/env python3
n = int(input())
ts = [input() for i in range(n)]
t = '<3' + '<3'.join(ts) + '<3'
s = input()
ans = True
i = 0
j = 0
while i < len(t) and j < len(s):
if t[i] == s[j]:
i += 1
j += 1
elif s[j] in '<>0123456789':
j += 1
else:
ans = False
break
if i... | Title: Dima and Text Messages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Seryozha has a very changeable character. This time he refused to leave the room to Dima and his girlfriend (her hame is Inna, by the way). However, the two lovebirds can always find a way to communicate. Today t... | ```python
#!/usr/bin/env python3
n = int(input())
ts = [input() for i in range(n)]
t = '<3' + '<3'.join(ts) + '<3'
s = input()
ans = True
i = 0
j = 0
while i < len(t) and j < len(s):
if t[i] == s[j]:
i += 1
j += 1
elif s[j] in '<>0123456789':
j += 1
else:
ans = False
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
227 | A | Where do I Turn? | PROGRAMMING | 1,300 | [
"geometry"
] | null | null | Trouble came from the overseas lands: a three-headed dragon Gorynych arrived. The dragon settled at point *C* and began to terrorize the residents of the surrounding villages.
A brave hero decided to put an end to the dragon. He moved from point *A* to fight with Gorynych. The hero rode from point *A* along a straight... | The first input line contains two space-separated integers *x**a*,<=*y**a* (|*x**a*|,<=|*y**a*|<=≤<=109) — the coordinates of point *A*. The second line contains the coordinates of point *B* in the same form, the third line contains the coordinates of point *C*.
It is guaranteed that all points are pairwise different.... | Print a single line. If a hero must turn left, print "LEFT" (without the quotes); If he must go straight ahead, print "TOWARDS" (without the quotes); if he should turn right, print "RIGHT" (without the quotes). | [
"0 0\n0 1\n1 1\n",
"-1 -1\n-3 -3\n-4 -4\n",
"-4 -6\n-3 -7\n-2 -6\n"
] | [
"RIGHT\n",
"TOWARDS\n",
"LEFT\n"
] | The picture to the first sample:
The red color shows points A, B and C. The blue arrow shows the hero's direction. The green color shows the hero's trajectory.
The picture to the second sample: | 500 | [
{
"input": "0 0\n0 1\n1 1",
"output": "RIGHT"
},
{
"input": "-1 -1\n-3 -3\n-4 -4",
"output": "TOWARDS"
},
{
"input": "-4 -6\n-3 -7\n-2 -6",
"output": "LEFT"
},
{
"input": "-44 57\n-118 -41\n-216 33",
"output": "RIGHT"
},
{
"input": "39 100\n90 85\n105 136",
"o... | 1,630,951,047 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 124 | 6,963,200 | xa,ya = input().split()
xa = int(xa)
ya = int(ya)
xb,yb = input().split()
xb = int(xb)
yb = int(yb)
xc,yc = input().split()
xc = int(xc)
yc = int(yc)
vab_x = xb-xa
vab_y = yb-ya
vbc_x = xc - xb
vbc_y = yc - yb
produto_vetorial = (vab_x * vbc_y) - (vab_y * vbc_x)
if(produto_vetorial == 0):
... | Title: Where do I Turn?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Trouble came from the overseas lands: a three-headed dragon Gorynych arrived. The dragon settled at point *C* and began to terrorize the residents of the surrounding villages.
A brave hero decided to put an end to the... | ```python
xa,ya = input().split()
xa = int(xa)
ya = int(ya)
xb,yb = input().split()
xb = int(xb)
yb = int(yb)
xc,yc = input().split()
xc = int(xc)
yc = int(yc)
vab_x = xb-xa
vab_y = yb-ya
vbc_x = xc - xb
vbc_y = yc - yb
produto_vetorial = (vab_x * vbc_y) - (vab_y * vbc_x)
if(produto_vetorial =... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
766 | A | Mahmoud and Longest Uncommon Subsequence | PROGRAMMING | 1,000 | [
"constructive algorithms",
"strings"
] | null | null | While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two strings *a* and *b*, find the length of their longest uncommon subsequence, which is the longest string that is a subsequence ... | The first line contains string *a*, and the second line — string *b*. Both of these strings are non-empty and consist of lowercase letters of English alphabet. The length of each string is not bigger than 105 characters. | If there's no uncommon subsequence, print "-1". Otherwise print the length of the longest uncommon subsequence of *a* and *b*. | [
"abcd\ndefgh\n",
"a\na\n"
] | [
"5\n",
"-1\n"
] | In the first example: you can choose "defgh" from string *b* as it is the longest subsequence of string *b* that doesn't appear as a subsequence of string *a*. | 500 | [
{
"input": "abcd\ndefgh",
"output": "5"
},
{
"input": "a\na",
"output": "-1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaacccccccccccccccccccccccccccccccccccccccccccccccccc\naaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaadddddddddddddddddddddddddddddddddddddddddddd... | 1,689,328,396 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | a = input()
b = input()
if b not in a:
print(len(b))
elif a not in b:
print(len(a))
else:
print(-1)
| Title: Mahmoud and Longest Uncommon Subsequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two ... | ```python
a = input()
b = input()
if b not in a:
print(len(b))
elif a not in b:
print(len(a))
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,524,992,373 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 186 | 7,065,600 | v=input()
x=input()
y=v[::-1]
if x==y:
print("YES")
else:
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
v=input()
x=input()
y=v[::-1]
if x==y:
print("YES")
else:
print("NO")
``` | 3.940339 | MatrixStudio/Codeforces-Python-Submissions |
1,009 | B | Minimum Ternary String | PROGRAMMING | 1,400 | [
"greedy",
"implementation"
] | null | null | You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa).
For e... | The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive). | Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero). | [
"100210\n",
"11222121\n",
"20\n"
] | [
"001120\n",
"11112222\n",
"20\n"
] | none | 0 | [
{
"input": "100210",
"output": "001120"
},
{
"input": "11222121",
"output": "11112222"
},
{
"input": "20",
"output": "20"
},
{
"input": "1002",
"output": "0012"
},
{
"input": "10",
"output": "01"
},
{
"input": "000021",
"output": "000012"
},
{
... | 1,535,905,488 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 204,800 | n = input()
t = n.count('1')
n = n.replace('1', '')
if '2' in n:
r = n.index('2')
print('0'*r + '1'*t+n[r:])
else:
print('0'*n.count('0')+'1'*t)
| Title: Minimum Ternary String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) ... | ```python
n = input()
t = n.count('1')
n = n.replace('1', '')
if '2' in n:
r = n.index('2')
print('0'*r + '1'*t+n[r:])
else:
print('0'*n.count('0')+'1'*t)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,658,898,160 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | s = "".join([*filter(lambda x: x in ("Q","A"),input())])
n = s.count("Q");i = 0
cnt = 0
while n:
if(s[i] != "Q"): i += 1
else:
m = s[i:].count("A")
j = i+1
while m:
if(s[j]!="A"): j+=1
else: cnt += s[j:].count("Q"); m-= 1; j+=1
n -= 1; i += 1
p... | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
s = "".join([*filter(lambda x: x in ("Q","A"),input())])
n = s.count("Q");i = 0
cnt = 0
while n:
if(s[i] != "Q"): i += 1
else:
m = s[i:].count("A")
j = i+1
while m:
if(s[j]!="A"): j+=1
else: cnt += s[j:].count("Q"); m-= 1; j+=1
n -= 1;... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | На координатной прямой сидит *n* собачек, *i*-я собачка находится в точке *x**i*. Кроме того, на прямой есть *m* мисок с едой, для каждой известна её координата на прямой *u**j* и время *t**j*, через которое еда в миске остынет и станет невкусной. Это значит, что если собачка прибежит к миске в момент времени, строго б... | В первой строке находится пара целых чисел *n* и *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — количество собачек и мисок соответственно.
Во второй строке находятся *n* целых чисел *x**i* (<=-<=109<=≤<=*x**i*<=≤<=109) — координата *i*-й собачки.
В следующих *m* строках находятся пары целых чисел *u**j* и *t**j* (<=-<=109<=≤<=... | Выведите одно целое число *a* — максимальное количество собачек, которые смогут покушать. | [
"5 4\n-2 0 4 8 13\n-1 1\n4 3\n6 3\n11 2\n",
"3 3\n-1 3 7\n1 1\n4 1\n7 1\n",
"4 4\n20 1 10 30\n1 1\n2 5\n22 2\n40 10\n"
] | [
"4\n",
"2\n",
"3\n"
] | В первом примере первая собачка побежит направо к первой миске, третья собачка сразу начнёт есть из второй миски, четвёртая собачка побежит влево к третьей миске, а пятая собачка побежит влево к четвёртой миске. | 0 | [] | 1,458,751,420 | 6,220 | PyPy 3 | WRONG_ANSWER | PRETESTS | 3 | 187 | 27,955,200 | n, m = [int(x) for x in input().split()]
x = [int(i) for i in input().split()]
t = []
for i in range(m):
f = [int(j) for j in input().split()]
t.append(f)
x.sort()
t.sort()
mini = 0
ans = 0
last = 0
for i in range(m):
for j in range(mini, n):
if abs(x[j] - t[i][0]) <= t[i][1]:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
На координатной прямой сидит *n* собачек, *i*-я собачка находится в точке *x**i*. Кроме того, на прямой есть *m* мисок с едой, для каждой известна её координата на прямой *u**j* и время *t**j*, через которое еда в миске остынет и ... | ```python
n, m = [int(x) for x in input().split()]
x = [int(i) for i in input().split()]
t = []
for i in range(m):
f = [int(j) for j in input().split()]
t.append(f)
x.sort()
t.sort()
mini = 0
ans = 0
last = 0
for i in range(m):
for j in range(mini, n):
if abs(x[j] - t[i][0]) <= t[i][1]:... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,664,114,163 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 77 | 1,536,000 | n, m = map(int, input().split())
li = []
for i in range(n):
s = [int(i) for i in input().split()]
s.remove(s[0])
li += s
if len(set(li)) == m:
print('YES')
else:
print('NO') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
n, m = map(int, input().split())
li = []
for i in range(n):
s = [int(i) for i in input().split()]
s.remove(s[0])
li += s
if len(set(li)) == m:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
454 | A | Little Pony and Crystal Mine | PROGRAMMING | 800 | [
"implementation"
] | null | null | Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You need to draw a crystal of size *n*. The diamond cells of the matrix should be represented by character "D". All ot... | The only line contains an integer *n* (3<=≤<=*n*<=≤<=101; *n* is odd). | Output a crystal of size *n*. | [
"3\n",
"5\n",
"7\n"
] | [
"*D*\nDDD\n*D*\n",
"**D**\n*DDD*\nDDDDD\n*DDD*\n**D**\n",
"***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***\n"
] | none | 500 | [
{
"input": "3",
"output": "*D*\nDDD\n*D*"
},
{
"input": "5",
"output": "**D**\n*DDD*\nDDDDD\n*DDD*\n**D**"
},
{
"input": "7",
"output": "***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***"
},
{
"input": "11",
"output": "*****D*****\n****DDD****\n***DDDDD***\n**... | 1,664,262,053 | 2,147,483,647 | Python 3 | OK | TESTS | 12 | 31 | 0 | n =int(input())
for i in range(n):
a = abs(n//2-i)
print(a*'*'+((n//2-a)*2+1)*'D'+a*'*') | Title: Little Pony and Crystal Mine
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You ... | ```python
n =int(input())
for i in range(n):
a = abs(n//2-i)
print(a*'*'+((n//2-a)*2+1)*'D'+a*'*')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
637 | B | Chat Order | PROGRAMMING | 1,200 | [
"*special",
"binary search",
"constructive algorithms",
"data structures",
"sortings"
] | null | null | Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The relative order of the other chats doesn't change. If there was no chat with this friend before, then... | The first line contains integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Polycarpus' messages. Next *n* lines enlist the message recipients in the order in which the messages were sent. The name of each participant is a non-empty sequence of lowercase English letters of length at most 10. | Print all the recipients to who Polycarp talked to in the order of chats with them, from top to bottom. | [
"4\nalex\nivan\nroman\nivan\n",
"8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina\n"
] | [
"ivan\nroman\nalex\n",
"alina\nmaria\nekaterina\ndarya\n"
] | In the first test case Polycarpus first writes to friend by name "alex", and the list looks as follows:
1. alex
Then Polycarpus writes to friend by name "ivan" and the list looks as follows:
1. ivan 1. alex
Polycarpus writes the third message to friend by name "roman" and the list looks as follows:
1. roman 1... | 1,000 | [
{
"input": "4\nalex\nivan\nroman\nivan",
"output": "ivan\nroman\nalex"
},
{
"input": "8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina",
"output": "alina\nmaria\nekaterina\ndarya"
},
{
"input": "1\nwdi",
"output": "wdi"
},
{
"input": "2\nypg\nypg",
"outpu... | 1,680,024,459 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 3,000 | 8,294,400 | import time
im = []
for x in range(int(input())):
im.append(input())
start = time.time()
imn = []
for y in reversed(im):
if y not in imn:
imn.append(y)
print(*imn,sep='\n') | Title: Chat Order
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The rela... | ```python
import time
im = []
for x in range(int(input())):
im.append(input())
start = time.time()
imn = []
for y in reversed(im):
if y not in imn:
imn.append(y)
print(*imn,sep='\n')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
817 | B | Makes And The Product | PROGRAMMING | 1,500 | [
"combinatorics",
"implementation",
"math",
"sortings"
] | null | null | After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular question: how many triples of indices (*i*,<= *j*,<= *k*) (*i*<=<<=*j*<=<<=*k*), such that *a**i*·*a**j*·*a... | The first line of input contains a positive integer number *n* (3<=≤<=*n*<=≤<=105) — the number of elements in array *a*. The second line contains *n* positive integer numbers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of a given array. | Print one number — the quantity of triples (*i*,<= *j*,<= *k*) such that *i*,<= *j* and *k* are pairwise distinct and *a**i*·*a**j*·*a**k* is minimum possible. | [
"4\n1 1 1 1\n",
"5\n1 3 2 3 4\n",
"6\n1 3 3 1 3 2\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first example Makes always chooses three ones out of four, and the number of ways to choose them is 4.
In the second example a triple of numbers (1, 2, 3) is chosen (numbers, not indices). Since there are two ways to choose an element 3, then the answer is 2.
In the third example a triple of numbers (1, 1, 2) ... | 0 | [
{
"input": "4\n1 1 1 1",
"output": "4"
},
{
"input": "5\n1 3 2 3 4",
"output": "2"
},
{
"input": "6\n1 3 3 1 3 2",
"output": "1"
},
{
"input": "3\n1000000000 1000000000 1000000000",
"output": "1"
},
{
"input": "4\n1 1 2 2",
"output": "2"
},
{
"input": ... | 1,554,962,587 | 2,147,483,647 | PyPy 3 | OK | TESTS | 80 | 202 | 15,667,200 | from math import factorial
n=int(input())
a=[int(i) for i in input().split()]
a.sort()
c1 = c2 = c3 = 0
for i in range(n):
if a[i] == a[0]:
c1 += 1
if a[i] == a[1]:
c2 += 1
if a[i] == a[2]:
c3 += 1
if a[0] == a[1]:
if a[1] == a[2]:
print((c1*(c1-1)*(c1-2))//... | Title: Makes And The Product
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular questi... | ```python
from math import factorial
n=int(input())
a=[int(i) for i in input().split()]
a.sort()
c1 = c2 = c3 = 0
for i in range(n):
if a[i] == a[0]:
c1 += 1
if a[i] == a[1]:
c2 += 1
if a[i] == a[2]:
c3 += 1
if a[0] == a[1]:
if a[1] == a[2]:
print((c1*(c1-1)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
29 | A | Spit Problem | PROGRAMMING | 1,000 | [
"brute force"
] | A. Spit Problem | 2 | 256 | In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know if in the zoo there are two camels, which spitted at each other. Help him to solve this task.
... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the amount of camels in the zoo. Each of the following *n* lines contains two integers *x**i* and *d**i* (<=-<=104<=≤<=*x**i*<=≤<=104,<=1<=≤<=|*d**i*|<=≤<=2·104) — records in Bob's notepad. *x**i* is a position of the *i*-th camel, and *d**i* is a distance at wh... | If there are two camels, which spitted at each other, output YES. Otherwise, output NO. | [
"2\n0 1\n1 -1\n",
"3\n0 1\n1 1\n2 -2\n",
"5\n2 -10\n3 10\n0 5\n5 -5\n10 1\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "2\n0 1\n1 -1",
"output": "YES"
},
{
"input": "3\n0 1\n1 1\n2 -2",
"output": "NO"
},
{
"input": "5\n2 -10\n3 10\n0 5\n5 -5\n10 1",
"output": "YES"
},
{
"input": "10\n-9897 -1144\n-4230 -6350\n2116 -3551\n-3635 4993\n3907 -9071\n-2362 4120\n-6542 984\n5807 3745\n759... | 1,649,867,873 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n = int(input())
camel = {}
for i in range(n):
a,b = map(int, input().split())
camel[a] = b
flag=False
for key in camel.keys():
p = key+camel[key]
if p in camel and camel[p]+p==key:
flag=True
if(flag):
print("YES")
else:
print("NO")
| Title: Spit Problem
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know ... | ```python
n = int(input())
camel = {}
for i in range(n):
a,b = map(int, input().split())
camel[a] = b
flag=False
for key in camel.keys():
p = key+camel[key]
if p in camel and camel[p]+p==key:
flag=True
if(flag):
print("YES")
else:
print("NO")
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
727 | A | Transformation: from A to B | PROGRAMMING | 1,000 | [
"brute force",
"dfs and similar",
"math"
] | null | null | Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - append the digit 1 to the right of current number (that is, replace the number *x* by 10·*x*<=+<=1).
You need to he... | The first line contains two positive integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=109) — the number which Vasily has and the number he wants to have. | If there is no way to get *b* from *a*, print "NO" (without quotes).
Otherwise print three lines. On the first line print "YES" (without quotes). The second line should contain single integer *k* — the length of the transformation sequence. On the third line print the sequence of transformations *x*1,<=*x*2,<=...,<=*x... | [
"2 162\n",
"4 42\n",
"100 40021\n"
] | [
"YES\n5\n2 4 8 81 162 \n",
"NO\n",
"YES\n5\n100 200 2001 4002 40021 \n"
] | none | 1,000 | [
{
"input": "2 162",
"output": "YES\n5\n2 4 8 81 162 "
},
{
"input": "4 42",
"output": "NO"
},
{
"input": "100 40021",
"output": "YES\n5\n100 200 2001 4002 40021 "
},
{
"input": "1 111111111",
"output": "YES\n9\n1 11 111 1111 11111 111111 1111111 11111111 111111111 "
},
... | 1,617,661,078 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 77 | 307,200 | n = []
def a_to_b(a, b):
if b % 2 == 0:
b = b / 2
if b >= a:
n.insert(0, int(b))
a_to_b(a, b)
elif b % 10 == 1:
b = b // 10
if b >= a:
n.insert(0, int(b))
a_to_b(a, b)
a, b = map(int, input().split())
a_to_b(a... | Title: Transformation: from A to B
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - app... | ```python
n = []
def a_to_b(a, b):
if b % 2 == 0:
b = b / 2
if b >= a:
n.insert(0, int(b))
a_to_b(a, b)
elif b % 10 == 1:
b = b // 10
if b >= a:
n.insert(0, int(b))
a_to_b(a, b)
a, b = map(int, input().split())... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
285 | B | Find Marble | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the glasses are not.
First Petya puts a marble under the glass in position *s*. Then he performs som... | The first line contains three integers: *n*,<=*s*,<=*t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*s*,<=*t*<=≤<=*n*) — the number of glasses, the ball's initial and final position. The second line contains *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the shuffling operation parameters. It is guaran... | If the marble can move from position *s* to position *t*, then print on a single line a non-negative integer — the minimum number of shuffling operations, needed to get the marble to position *t*. If it is impossible, print number -1. | [
"4 2 1\n2 3 4 1\n",
"4 3 3\n4 1 3 2\n",
"4 3 4\n1 2 3 4\n",
"3 1 3\n2 1 3\n"
] | [
"3\n",
"0\n",
"-1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "4 2 1\n2 3 4 1",
"output": "3"
},
{
"input": "4 3 3\n4 1 3 2",
"output": "0"
},
{
"input": "4 3 4\n1 2 3 4",
"output": "-1"
},
{
"input": "3 1 3\n2 1 3",
"output": "-1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 6 7\n10 7 8 1... | 1,633,803,017 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | n,s,t = map(int,input().split(' '))
p = map(int,input().split(' '))
l=list(p)
if s!=t:
if l[0]>t:
print(len(l)-abs(s-t))
else:
print('-1')
else:
print('0')
| Title: Find Marble
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the ... | ```python
n,s,t = map(int,input().split(' '))
p = map(int,input().split(' '))
l=list(p)
if s!=t:
if l[0]>t:
print(len(l)-abs(s-t))
else:
print('-1')
else:
print('0')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
518 | D | Ilya and Escalator | PROGRAMMING | 1,700 | [
"combinatorics",
"dp",
"math",
"probabilities"
] | null | null | Ilya got tired of sports programming, left university and got a job in the subway. He was given the task to determine the escalator load factor.
Let's assume that *n* people stand in the queue for the escalator. At each second one of the two following possibilities takes place: either the first person in the queue en... | The first line of the input contains three numbers *n*,<=*p*,<=*t* (1<=≤<=*n*,<=*t*<=≤<=2000, 0<=≤<=*p*<=≤<=1). Numbers *n* and *t* are integers, number *p* is real, given with exactly two digits after the decimal point. | Print a single real number — the expected number of people who will be standing on the escalator after *t* seconds. The absolute or relative error mustn't exceed 10<=-<=6. | [
"1 0.50 1\n",
"1 0.50 4\n",
"4 0.20 2\n"
] | [
"0.5\n",
"0.9375\n",
"0.4\n"
] | none | 2,000 | [
{
"input": "1 0.50 1",
"output": "0.500000000000000"
},
{
"input": "1 0.50 4",
"output": "0.937500000000000"
},
{
"input": "4 0.20 2",
"output": "0.400000000000000"
},
{
"input": "2000 0.61 2000",
"output": "1219.999999999999545"
},
{
"input": "100 1.00 200",
... | 1,622,278,841 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 187 | 44,339,200 | n,p,t=map(float,input().split())
n,t=int(n),int(t)
dp=[[0 for i in range(t+1)] for j in range(t+1)]
dp[0][0]=1
for i in range(1,t+1):
for j in range(i+1):
if j>=1:
dp[i][j]=p*dp[i-1][j-1]+(1-p)*dp[i-1][j]
else:
dp[i][j] = (1 - p) * dp[i - 1][j]
s=0
s1=sum(dp[... | Title: Ilya and Escalator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya got tired of sports programming, left university and got a job in the subway. He was given the task to determine the escalator load factor.
Let's assume that *n* people stand in the queue for the escalator. At... | ```python
n,p,t=map(float,input().split())
n,t=int(n),int(t)
dp=[[0 for i in range(t+1)] for j in range(t+1)]
dp[0][0]=1
for i in range(1,t+1):
for j in range(i+1):
if j>=1:
dp[i][j]=p*dp[i-1][j-1]+(1-p)*dp[i-1][j]
else:
dp[i][j] = (1 - p) * dp[i - 1][j]
s=0
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
960 | A | Check the string | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gi... | The first and only line consists of a string $S$ ($ 1 \le |S| \le 5\,000 $). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'. | Print "YES" or "NO", according to the condition. | [
"aaabccc\n",
"bbacc\n",
"aabc\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'. | 500 | [
{
"input": "aaabccc",
"output": "YES"
},
{
"input": "bbacc",
"output": "NO"
},
{
"input": "aabc",
"output": "YES"
},
{
"input": "aabbcc",
"output": "YES"
},
{
"input": "aaacccbb",
"output": "NO"
},
{
"input": "abc",
"output": "YES"
},
{
"in... | 1,523,189,991 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 61 | 7,065,600 | a=list(input())
b=list(set(a))
b.sort()
c=[]
p=97
for k in range(len(a)):
if ord(a[k])<p:
p=0
break
if a[k] not in c:
c.append(a[k])
p+=1
if len(set(a))==2 or p==0:
print('NO')
else:
if b==c and (a.count('a')==a.count('c') or a.count('b')==a.count('c')):
... | Title: Check the string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b... | ```python
a=list(input())
b=list(set(a))
b.sort()
c=[]
p=97
for k in range(len(a)):
if ord(a[k])<p:
p=0
break
if a[k] not in c:
c.append(a[k])
p+=1
if len(set(a))==2 or p==0:
print('NO')
else:
if b==c and (a.count('a')==a.count('c') or a.count('b')==a.count... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
252 | A | Little Xor | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Petya likes arrays that consist of non-negative integers a lot. Recently his mom has presented him one such array consisting of *n* elements. Petya immediately decided to find there a segment of consecutive elements, such that the *xor* of all numbers from this segment was maximal possible. Help him with that.
... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains the space-separated integers from the array. All numbers are non-negative integers strictly less than 230. | Print a single integer — the required maximal *xor* of a segment of consecutive elements. | [
"5\n1 2 1 1 2\n",
"3\n1 2 7\n",
"4\n4 2 4 8\n"
] | [
"3\n",
"7\n",
"14\n"
] | In the first sample one of the optimal segments is the segment that consists of the first and the second array elements, if we consider the array elements indexed starting from one.
The second sample contains only one optimal segment, which contains exactly one array element (element with index three). | 500 | [
{
"input": "5\n1 2 1 1 2",
"output": "3"
},
{
"input": "3\n1 2 7",
"output": "7"
},
{
"input": "4\n4 2 4 8",
"output": "14"
},
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "16\n0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15",
"output": "15"
},
{
"inpu... | 1,521,969,286 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 186 | 7,065,600 | count = int(input())
number = [int(i) for i in input().split()]
max = -1
for i in range(0, count):
tmp = number[i]
if tmp > max:
max = tmp
if not i + 1 == count:
for j in (i + 1, count - 1):
tmp = tmp ^ number[j]
if tmp > max:
max = tmp
print("%d" ... | Title: Little Xor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes arrays that consist of non-negative integers a lot. Recently his mom has presented him one such array consisting of *n* elements. Petya immediately decided to find there a segment of consecutive elements, ... | ```python
count = int(input())
number = [int(i) for i in input().split()]
max = -1
for i in range(0, count):
tmp = number[i]
if tmp > max:
max = tmp
if not i + 1 == count:
for j in (i + 1, count - 1):
tmp = tmp ^ number[j]
if tmp > max:
max = tmp
p... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
254 | A | Cards with Numbers | PROGRAMMING | 1,200 | [
"constructive algorithms",
"sortings"
] | null | null | Petya has got 2*n* cards, each card contains some integer. The numbers on the cards can be the same. Let's index all cards by consecutive integers from 1 to 2*n*. We'll denote the number that is written on a card with number *i*, as *a**i*. In order to play one entertaining game with his friends, Petya needs to split t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains the sequence of 2*n* positive integers *a*1,<=*a*2,<=...,<=*a*2*n* (1<=≤<=*a**i*<=≤<=5000) — the numbers that are written on the cards. The numbers on the line are separated by single spaces. | If it is impossible to divide the cards into pairs so that cards in each pair had the same numbers, print on a single line integer -1. But if the required partition exists, then print *n* pairs of integers, a pair per line — the indices of the cards that form the pairs.
Separate the numbers on the lines by spaces. You... | [
"3\n20 30 10 30 20 10\n",
"1\n1 2\n"
] | [
"4 2\n1 5\n6 3\n",
"-1"
] | none | 500 | [
{
"input": "3\n20 30 10 30 20 10",
"output": "4 2\n1 5\n6 3"
},
{
"input": "1\n1 2",
"output": "-1"
},
{
"input": "5\n2 2 2 2 2 1 2 2 1 2",
"output": "2 1\n3 4\n7 5\n6 9\n10 8"
},
{
"input": "5\n2 1 2 2 1 1 1 1 1 2",
"output": "3 1\n2 5\n7 6\n8 9\n10 4"
},
{
"inpu... | 1,453,202,167 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 409,600 | # n = int(input())
# w, h = map(int, input().split())
# to_zero_based = lambda x: int(x) - 1
from collections import defaultdict
def main():
with open('input.txt') as fin:
n = int(fin.readline())
nums = list(map(int, fin.readline().split()))
distincts = defaultdict(list)
for i, num in enum... | Title: Cards with Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has got 2*n* cards, each card contains some integer. The numbers on the cards can be the same. Let's index all cards by consecutive integers from 1 to 2*n*. We'll denote the number that is written on a card wit... | ```python
# n = int(input())
# w, h = map(int, input().split())
# to_zero_based = lambda x: int(x) - 1
from collections import defaultdict
def main():
with open('input.txt') as fin:
n = int(fin.readline())
nums = list(map(int, fin.readline().split()))
distincts = defaultdict(list)
for i, n... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,653,593,424 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 46 | 102,400 |
n, m = list(map(int, input().split()))
col = []
for i in range(n):
st = input().split()
ss = sorted(list(set(st)))
try:
if ss[0] == 'B' and ss[1] == 'W' or ss[0] == 'B' or ss[1]=='W':
col.append(True)
else:
col.append(False)
except:
pass
if F... | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
n, m = list(map(int, input().split()))
col = []
for i in range(n):
st = input().split()
ss = sorted(list(set(st)))
try:
if ss[0] == 'B' and ss[1] == 'W' or ss[0] == 'B' or ss[1]=='W':
col.append(True)
else:
col.append(False)
except:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
80 | B | Depression | PROGRAMMING | 1,200 | [
"geometry",
"math"
] | B. Depression | 1 | 256 | Do you remember a kind cartoon "Beauty and the Beast"? No, no, there was no firing from machine guns or radiation mutants time-travels!
There was a beauty named Belle. Once she had violated the Beast's order and visited the West Wing. After that she was banished from the castle...
Everybody was upset. The beautiful ... | The only line of input contains current time according to the digital clock, formatted as HH:MM (00<=≤<=HH<=≤<=23, 00<=≤<=MM<=≤<=59). The mantel clock initially shows 12:00.
Pretests contain times of the beginning of some morning TV programs of the Channel One Russia. | Print two numbers *x* and *y* — the angles of turning the hour and minute hands, respectively (0<=≤<=*x*,<=*y*<=<<=360). The absolute or relative error in the answer should not exceed 10<=-<=9. | [
"12:00\n",
"04:30\n",
"08:17\n"
] | [
"0 0",
"135 180",
"248.5 102"
] | A note to the second example: the hour hand will be positioned exactly in the middle, between 4 and 5. | 1,000 | [
{
"input": "12:00",
"output": "0 0"
},
{
"input": "04:30",
"output": "135 180"
},
{
"input": "08:17",
"output": "248.5 102"
},
{
"input": "07:20",
"output": "220 120"
},
{
"input": "09:55",
"output": "297.5 330"
},
{
"input": "11:59",
"output": "35... | 1,566,066,335 | 2,147,483,647 | PyPy 3 | OK | TESTS | 66 | 139 | 0 | a=input()
b=int(a[:2])
c=int(a[3:])
d=c/60
e=((b+d)*30)%360
f=(c*6)%360
print(e,f) | Title: Depression
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Do you remember a kind cartoon "Beauty and the Beast"? No, no, there was no firing from machine guns or radiation mutants time-travels!
There was a beauty named Belle. Once she had violated the Beast's order and visited the Wes... | ```python
a=input()
b=int(a[:2])
c=int(a[3:])
d=c/60
e=((b+d)*30)%360
f=(c*6)%360
print(e,f)
``` | 3.9305 | MatrixStudio/Codeforces-Python-Submissions |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,698,673,104 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | # -*- coding: utf-8 -*-
"""
Created on Mon Oct 30 21:29:45 2023
@author: 2300011376
"""
N=int(input())
B=[i for i in map(int,input().split())]
B=sorted(B,key=lambda x:x)
p=0
time=0 #排队时间
per=0 #满意的人数
while True:
if time<B[p]:
time+=B[p]
per+=1
p+=1
if p==N:
pr... | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time... | ```python
# -*- coding: utf-8 -*-
"""
Created on Mon Oct 30 21:29:45 2023
@author: 2300011376
"""
N=int(input())
B=[i for i in map(int,input().split())]
B=sorted(B,key=lambda x:x)
p=0
time=0 #排队时间
per=0 #满意的人数
while True:
if time<B[p]:
time+=B[p]
per+=1
p+=1
if p==N:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
628 | C | Bear and String Distance | PROGRAMMING | 1,300 | [
"greedy",
"strings"
] | null | null | Limak is a little polar bear. He likes nice strings — strings of length *n*, consisting of lowercase English letters only.
The distance between two letters is defined as the difference between their positions in the alphabet. For example, , and .
Also, the distance between two nice strings is defined as the sum of di... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=106).
The second line contains a string *s* of length *n*, consisting of lowercase English letters. | If there is no string satisfying the given conditions then print "-1" (without the quotes).
Otherwise, print any nice string *s*' that . | [
"4 26\nbear\n",
"2 7\naf\n",
"3 1000\nhey\n"
] | [
"roar",
"db\n",
"-1\n"
] | none | 0 | [
{
"input": "4 26\nbear",
"output": "zcar"
},
{
"input": "2 7\naf",
"output": "hf"
},
{
"input": "3 1000\nhey",
"output": "-1"
},
{
"input": "5 50\nkzsij",
"output": "zaiij"
},
{
"input": "5 500\nvsdxg",
"output": "-1"
},
{
"input": "1 0\na",
"outpu... | 1,549,735,212 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | import math
a = "abcdefghijklmnopqrstuvwxyz"
x, y = map(int, input().split())
s = input()
ss = str()
for j in range(0, len(s)):
z = a.find(s[j])
z += min(25, y)
z %= 26
y -= min(25, y)
ss += a[z]
if(y > 0):
print("-1\n")
else:
print(ss) | Title: Bear and String Distance
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He likes nice strings — strings of length *n*, consisting of lowercase English letters only.
The distance between two letters is defined as the difference between their positions ... | ```python
import math
a = "abcdefghijklmnopqrstuvwxyz"
x, y = map(int, input().split())
s = input()
ss = str()
for j in range(0, len(s)):
z = a.find(s[j])
z += min(25, y)
z %= 26
y -= min(25, y)
ss += a[z]
if(y > 0):
print("-1\n")
else:
print(ss)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
334 | B | Eight Point Sets | PROGRAMMING | 1,400 | [
"sortings"
] | null | null | Gerald is very particular to eight point sets. He thinks that any decent eight point set must consist of all pairwise intersections of three distinct integer vertical straight lines and three distinct integer horizontal straight lines, except for the average of these nine points. In other words, there must be three int... | The input consists of eight lines, the *i*-th line contains two space-separated integers *x**i* and *y**i* (0<=≤<=*x**i*,<=*y**i*<=≤<=106). You do not have any other conditions for these points. | In a single line print word "respectable", if the given set of points corresponds to Gerald's decency rules, and "ugly" otherwise. | [
"0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2\n",
"0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0\n",
"1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n"
] | [
"respectable\n",
"ugly\n",
"ugly\n"
] | none | 1,000 | [
{
"input": "0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2",
"output": "respectable"
},
{
"input": "0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0",
"output": "ugly"
},
{
"input": "1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2",
"output": "ugly"
},
{
"input": "0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0... | 1,374,998,249 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 0 | u=set()
v=set()
w=set()
s=set()
def work():
global u,v
if len(u)<3 or len(v)<3:
return 0
u = sorted(list(u))
v = sorted(list(v))
for i in range(3):
for j in range(3):
if i!=1 or j!=1:
w.add((u[i],v[j]))
return w == s
a = input().split(... | Title: Eight Point Sets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald is very particular to eight point sets. He thinks that any decent eight point set must consist of all pairwise intersections of three distinct integer vertical straight lines and three distinct integer horizonta... | ```python
u=set()
v=set()
w=set()
s=set()
def work():
global u,v
if len(u)<3 or len(v)<3:
return 0
u = sorted(list(u))
v = sorted(list(v))
for i in range(3):
for j in range(3):
if i!=1 or j!=1:
w.add((u[i],v[j]))
return w == s
a = inpu... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
412 | B | Network Configuration | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | The R1 company wants to hold a web search championship. There were *n* computers given for the competition, each of them is connected to the Internet. The organizers believe that the data transfer speed directly affects the result. The higher the speed of the Internet is, the faster the participant will find the necess... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100) — the number of computers and the number of participants, respectively. In the second line you have a space-separated sequence consisting of *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (16<=≤<=*a**i*<=≤<=32768); number *a**i* deno... | Print a single integer — the maximum Internet speed value. It is guaranteed that the answer to the problem is always an integer. | [
"3 2\n40 20 30\n",
"6 4\n100 20 40 20 50 50\n"
] | [
"30\n",
"40\n"
] | In the first test case the organizers can cut the first computer's speed to 30 kilobits. Then two computers (the first and the third one) will have the same speed of 30 kilobits. They should be used as the participants' computers. This answer is optimal. | 1,000 | [
{
"input": "3 2\n40 20 30",
"output": "30"
},
{
"input": "6 4\n100 20 40 20 50 50",
"output": "40"
},
{
"input": "1 1\n16",
"output": "16"
},
{
"input": "2 1\n10000 17",
"output": "10000"
},
{
"input": "2 2\n200 300",
"output": "200"
},
{
"input": "3 1... | 1,587,992,192 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 124 | 0 | n,k=list(map(int,input().split()))
t=list(map(int,input().split()))
t.sort()
s=t[::-1]
print(s[k-1])
| Title: Network Configuration
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The R1 company wants to hold a web search championship. There were *n* computers given for the competition, each of them is connected to the Internet. The organizers believe that the data transfer speed directly a... | ```python
n,k=list(map(int,input().split()))
t=list(map(int,input().split()))
t.sort()
s=t[::-1]
print(s[k-1])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
372 | A | Counting Kangaroos is Fun | PROGRAMMING | 1,600 | [
"binary search",
"greedy",
"sortings",
"two pointers"
] | null | null | There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as large as the size of kangaroo who is held.
Each kangaroo can hold at most one kangaroo, and the kangaroo who i... | The first line contains a single integer — *n* (1<=≤<=*n*<=≤<=5·105). Each of the next *n* lines contains an integer *s**i* — the size of the *i*-th kangaroo (1<=≤<=*s**i*<=≤<=105). | Output a single integer — the optimal number of visible kangaroos. | [
"8\n2\n5\n7\n6\n9\n8\n4\n2\n",
"8\n9\n1\n6\n2\n6\n5\n8\n3\n"
] | [
"5\n",
"5\n"
] | none | 500 | [
{
"input": "8\n2\n5\n7\n6\n9\n8\n4\n2",
"output": "5"
},
{
"input": "8\n9\n1\n6\n2\n6\n5\n8\n3",
"output": "5"
},
{
"input": "12\n3\n99\n24\n46\n75\n63\n57\n55\n10\n62\n34\n52",
"output": "7"
},
{
"input": "12\n55\n75\n1\n98\n63\n64\n9\n39\n82\n18\n47\n9",
"output": "6"
... | 1,617,537,666 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 40,857,600 | import sys,os,io
import math,bisect,operator
inf,mod = float('inf'),10**9+7
# sys.setrecursionlimit(10 ** 6)
from itertools import groupby,accumulate
from heapq import heapify,heappop,heappush
from collections import deque,Counter,defaultdict
input = iter(sys.stdin.buffer.read().decode().splitlines()).__next__
... | Title: Counting Kangaroos is Fun
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as ... | ```python
import sys,os,io
import math,bisect,operator
inf,mod = float('inf'),10**9+7
# sys.setrecursionlimit(10 ** 6)
from itertools import groupby,accumulate
from heapq import heapify,heappop,heappush
from collections import deque,Counter,defaultdict
input = iter(sys.stdin.buffer.read().decode().splitlines()).... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,647,532,709 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 92 | 0 | """
given ab,bc,ac
find out 4a+4b+4c?
b=sqrt(([(bc+ac)/ac]/[(bc+ac)/bc])*ab) =sqrt(b**2)
"""
import math
class Solution:
def __init__(self):
self.a,self.b,self.c=None,None,None
def sum12Edges(self,ab,bc,ac):
self.b=math.sqrt((((bc+ac)/ac)/((bc+ac)/bc))*ab)
self.a=ab/self... | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
"""
given ab,bc,ac
find out 4a+4b+4c?
b=sqrt(([(bc+ac)/ac]/[(bc+ac)/bc])*ab) =sqrt(b**2)
"""
import math
class Solution:
def __init__(self):
self.a,self.b,self.c=None,None,None
def sum12Edges(self,ab,bc,ac):
self.b=math.sqrt((((bc+ac)/ac)/((bc+ac)/bc))*ab)
self... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
476 | A | Dreamoon and Stairs | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb to the top of the stairs that satisfies his condition? | The single line contains two space separated integers *n*, *m* (0<=<<=*n*<=≤<=10000,<=1<=<<=*m*<=≤<=10). | Print a single integer — the minimal number of moves being a multiple of *m*. If there is no way he can climb satisfying condition print <=-<=1 instead. | [
"10 2\n",
"3 5\n"
] | [
"6\n",
"-1\n"
] | For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.
For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5. | 500 | [
{
"input": "10 2",
"output": "6"
},
{
"input": "3 5",
"output": "-1"
},
{
"input": "29 7",
"output": "21"
},
{
"input": "2 2",
"output": "2"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "10000 2",
"output": "5000"
},
{
"input": "10000 ... | 1,653,819,997 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 92 | 1,433,600 | a,b=map(int,input().split())
if a>=b:
x=a//b
y=1
while x<a and (int(y/b)!=y/b or y<a/2):
y+=1
x+=1
print(y)
else:
print(-1) | Title: Dreamoon and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb ... | ```python
a,b=map(int,input().split())
if a>=b:
x=a//b
y=1
while x<a and (int(y/b)!=y/b or y<a/2):
y+=1
x+=1
print(y)
else:
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
165 | B | Burning Midnight Oil | PROGRAMMING | 1,500 | [
"binary search",
"implementation"
] | null | null | One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of code, drinks a cup of tea, then he writes as much as lines, drinks another cup of tea, then he writes lin... | The input consists of two integers *n* and *k*, separated by spaces — the size of the program in lines and the productivity reduction coefficient, 1<=≤<=*n*<=≤<=109, 2<=≤<=*k*<=≤<=10. | Print the only integer — the minimum value of *v* that lets Vasya write the program in one night. | [
"7 2\n",
"59 9\n"
] | [
"4\n",
"54\n"
] | In the first sample the answer is *v* = 4. Vasya writes the code in the following portions: first 4 lines, then 2, then 1, and then Vasya falls asleep. Thus, he manages to write 4 + 2 + 1 = 7 lines in a night and complete the task.
In the second sample the answer is *v* = 54. Vasya writes the code in the following por... | 1,000 | [
{
"input": "7 2",
"output": "4"
},
{
"input": "59 9",
"output": "54"
},
{
"input": "1 9",
"output": "1"
},
{
"input": "11 2",
"output": "7"
},
{
"input": "747 2",
"output": "376"
},
{
"input": "6578 2",
"output": "3293"
},
{
"input": "37212... | 1,611,313,289 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 122 | 204,800 | n , k = map(int,input().split())
def isSolution(n,k,v):
i = 0
Sum = 0
while(int(v/pow(k,i))>0):
Sum += int(v/pow(k,i))
i += 1
return True if Sum >= n else False
start = 0
end = n
while(start < end):
v = int(start + (end - start)/2)
print(v)
print(isSoluti... | Title: Burning Midnight Oil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of c... | ```python
n , k = map(int,input().split())
def isSolution(n,k,v):
i = 0
Sum = 0
while(int(v/pow(k,i))>0):
Sum += int(v/pow(k,i))
i += 1
return True if Sum >= n else False
start = 0
end = n
while(start < end):
v = int(start + (end - start)/2)
print(v)
prin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,669,552,791 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | These are your Discord backup codes for account [email protected]. Keep them safe!
* zn6c-77wd
* x33b-y9ao
* l3l5-j4rs
* 2t57-e095
* qyu2-qvjz
* dgxo-rl4r
* 7cin-osmb
* 7hz3-3m6m
* wbfq-ly5u
* 85d4-v9lw | Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
These are your Discord backup codes for account [email protected]. Keep them safe!
* zn6c-77wd
* x33b-y9ao
* l3l5-j4rs
* 2t57-e095
* qyu2-qvjz
* dgxo-rl4r
* 7cin-osmb
* 7hz3-3m6m
* wbfq-ly5u
* 85d4-v9lw
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,607,949,021 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 140 | 0 | import math
n=int(input())
print((2*n)//3+1 if n%3!=0 else print((2*n)//3)) | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
import math
n=int(input())
print((2*n)//3+1 if n%3!=0 else print((2*n)//3))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You already know that Valery's favorite sport is biathlon. Due to your help, he learned to shoot without missing, and his skills are unmatched at the shooting range. But now a smaller task is to be performed, he should learn to complete the path fastest.
The track's map is represented by a rectangle *n*<=×<=*m* in siz... | The first input line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=50,<=*n*·*m*<=≥<=2,<=1<=≤<=*k*<=≤<=4). Then *n* lines contain the map. Each line has the length of exactly *m* characters and consists of lowercase Latin letters and characters *S* and *T*. It is guaranteed that the map contains exactly ... | If there is a path that satisfies the condition, print it as a sequence of letters — the plot types. Otherwise, print "-1" (without quotes). You shouldn't print the character *S* in the beginning and *T* in the end.
Note that this sequence may be empty. This case is present in pretests. You can just print nothing or p... | [
"5 3 2\nSba\nccc\naac\nccc\nabT\n",
"3 4 1\nSxyy\nyxxx\nyyyT\n",
"1 3 3\nTyS\n",
"1 4 1\nSxyT\n"
] | [
"bcccc\n",
"xxxx\n",
"y\n",
"-1\n"
] | none | 0 | [
{
"input": "5 3 2\nSba\nccc\naac\nccc\nabT",
"output": "bcccc"
},
{
"input": "3 4 1\nSxyy\nyxxx\nyyyT",
"output": "xxxx"
},
{
"input": "1 3 3\nTyS",
"output": "y"
},
{
"input": "1 4 1\nSxyT",
"output": "-1"
},
{
"input": "1 3 3\nSaT",
"output": "a"
},
{
... | 1,693,827,305 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | print("_RANDOM_GUESS_1693827305.1644115")# 1693827305.1644297 | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You already know that Valery's favorite sport is biathlon. Due to your help, he learned to shoot without missing, and his skills are unmatched at the shooting range. But now a smaller task is to be performed, he should learn to co... | ```python
print("_RANDOM_GUESS_1693827305.1644115")# 1693827305.1644297
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
978 | B | File Name | PROGRAMMING | 800 | [
"greedy",
"strings"
] | null | null | You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin letters "x") in a row, the system considers that the file content does not correspond to the socia... | The first line contains integer $n$ $(3 \le n \le 100)$ — the length of the file name.
The second line contains a string of length $n$ consisting of lowercase Latin letters only — the file name. | Print the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. If initially the file name dost not contain a forbidden substring "xxx", print 0. | [
"6\nxxxiii\n",
"5\nxxoxx\n",
"10\nxxxxxxxxxx\n"
] | [
"1\n",
"0\n",
"8\n"
] | In the first example Polycarp tried to send a file with name contains number $33$, written in Roman numerals. But he can not just send the file, because it name contains three letters "x" in a row. To send the file he needs to remove any one of this letters. | 0 | [
{
"input": "6\nxxxiii",
"output": "1"
},
{
"input": "5\nxxoxx",
"output": "0"
},
{
"input": "10\nxxxxxxxxxx",
"output": "8"
},
{
"input": "100\nxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx",
"output": "98"
},
{
... | 1,661,510,901 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 31 | 0 | num=int(input())
str=input()
c=0
for i in range(len(str)):
if(str[i]=='x' and i!=len(str)-1):
if(str[i+1]=='x'):
if(str[i+2]=='x'):
c+=1
print(c)
| Title: File Name
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin let... | ```python
num=int(input())
str=input()
c=0
for i in range(len(str)):
if(str[i]=='x' and i!=len(str)-1):
if(str[i+1]=='x'):
if(str[i+2]=='x'):
c+=1
print(c)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,700,111,565 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 46 | 0 | n = int(input())
even = (n//2)*(n//2+1);
odd = (n*(n+1)//2)-even;
print(even-odd); | Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
n = int(input())
even = (n//2)*(n//2+1);
odd = (n*(n+1)//2)-even;
print(even-odd);
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be sw... | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,657,572,635 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | # -*- coding: utf-8 -*-
"""
Created on Tue Jul 12 02:07:52 2022
@author: muamb
"""
grid=[]
for i in range(3):
col=[]
x,y,z=input().split()
x=int(x)
y=int(y)
z=int(z)
col.append(x)
col.append(y)
col.append(z)
grid.append(col)
out=[[1,1,1],[1,1,1],[1,1,1]]
for i in... | Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the ... | ```python
# -*- coding: utf-8 -*-
"""
Created on Tue Jul 12 02:07:52 2022
@author: muamb
"""
grid=[]
for i in range(3):
col=[]
x,y,z=input().split()
x=int(x)
y=int(y)
z=int(z)
col.append(x)
col.append(y)
col.append(z)
grid.append(col)
out=[[1,1,1],[1,1,1],[1,1,1]]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
17 | A | Noldbach problem | PROGRAMMING | 1,000 | [
"brute force",
"math",
"number theory"
] | A. Noldbach problem | 2 | 64 | Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a problem of his own and call it Noldbach problem. Since Nick is interested only in prime numbers, Nold... | The first line of the input contains two integers *n* (2<=≤<=*n*<=≤<=1000) and *k* (0<=≤<=*k*<=≤<=1000). | Output YES if at least *k* prime numbers from 2 to *n* inclusively can be expressed as it was described above. Otherwise output NO. | [
"27 2\n",
"45 7\n"
] | [
"YES",
"NO"
] | In the first sample the answer is YES since at least two numbers can be expressed as it was described (for example, 13 and 19). In the second sample the answer is NO since it is impossible to express 7 prime numbers from 2 to 45 in the desired form. | 0 | [
{
"input": "27 2",
"output": "YES"
},
{
"input": "45 7",
"output": "NO"
},
{
"input": "2 0",
"output": "YES"
},
{
"input": "15 1",
"output": "YES"
},
{
"input": "17 1",
"output": "YES"
},
{
"input": "34 5",
"output": "NO"
},
{
"input": "37 ... | 1,627,797,685 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 186 | 21,401,600 | n,k = map(int,input().split())
in_lis = []
prime_lis = []
for i in range(2,n+1):
if i not in in_lis:
prime_lis.append(i)
for j in range(i*i,n+1,i):
in_lis.append(j)
#print(prime_lis) -----denotes list of prime numbers using sieve of eratosthenes
count = 0
for ... | Title: Noldbach problem
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a prob... | ```python
n,k = map(int,input().split())
in_lis = []
prime_lis = []
for i in range(2,n+1):
if i not in in_lis:
prime_lis.append(i)
for j in range(i*i,n+1,i):
in_lis.append(j)
#print(prime_lis) -----denotes list of prime numbers using sieve of eratosthenes
count... | 3.794046 | MatrixStudio/Codeforces-Python-Submissions |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,685,135,742 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 13,107,200 | na,nb=map(int,input().split())
k,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
b.sort(reverse=True)
a1=a[:k]
b1=b[:m]
c=0
for i in a1:
for j in b1:
if j>i:
c=c+1
if c==(m*k):
print("YES")
else:
print("NO") | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
na,nb=map(int,input().split())
k,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
b.sort(reverse=True)
a1=a[:k]
b1=b[:m]
c=0
for i in a1:
for j in b1:
if j>i:
c=c+1
if c==(m*k):
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
994 | B | Knights of a Polygonal Table | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"sortings"
] | null | null | Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power is greater than the power of victim. However, even such a knight will torment his conscience, so he can kill no mo... | The first line contains two integers $n$ and $k$ $(1 \le n \le 10^5, 0 \le k \le \min(n-1,10))$ — the number of knights and the number $k$ from the statement.
The second line contains $n$ integers $p_1, p_2 ,\ldots,p_n$ $(1 \le p_i \le 10^9)$ — powers of the knights. All $p_i$ are distinct.
The third line contains $n... | Print $n$ integers — the maximum number of coins each knight can have it only he kills other knights. | [
"4 2\n4 5 9 7\n1 2 11 33\n",
"5 1\n1 2 3 4 5\n1 2 3 4 5\n",
"1 0\n2\n3\n"
] | [
"1 3 46 36 ",
"1 3 5 7 9 ",
"3 "
] | Consider the first example.
- The first knight is the weakest, so he can't kill anyone. That leaves him with the only coin he initially has. - The second knight can kill the first knight and add his coin to his own two. - The third knight is the strongest, but he can't kill more than $k = 2$ other knights. It is o... | 1,000 | [
{
"input": "4 2\n4 5 9 7\n1 2 11 33",
"output": "1 3 46 36 "
},
{
"input": "5 1\n1 2 3 4 5\n1 2 3 4 5",
"output": "1 3 5 7 9 "
},
{
"input": "1 0\n2\n3",
"output": "3 "
},
{
"input": "7 1\n2 3 4 5 7 8 9\n0 3 7 9 5 8 9",
"output": "0 3 10 16 14 17 18 "
},
{
"input"... | 1,529,188,112 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 1,000 | 19,763,200 | n,k=map(int, input().split())
power = list(map(int, input().split()))
total=[int(i) for i in input().split()]
money = [{"f":power[i],"s":total[i]} for i in range(n)]
#print(money)
def merge(arr, l, m, r):
n1 = m - l + 1
n2 = r- m
# create temp arrays
L = [0] * (n1)
R = [0] * (n2)
... | Title: Knights of a Polygonal Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power ... | ```python
n,k=map(int, input().split())
power = list(map(int, input().split()))
total=[int(i) for i in input().split()]
money = [{"f":power[i],"s":total[i]} for i in range(n)]
#print(money)
def merge(arr, l, m, r):
n1 = m - l + 1
n2 = r- m
# create temp arrays
L = [0] * (n1)
R = [0]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
383 | A | Milking cows | PROGRAMMING | 1,600 | [
"data structures",
"greedy"
] | null | null | Iahub helps his grandfather at the farm. Today he must milk the cows. There are *n* cows sitting in a row, numbered from 1 to *n* from left to right. Each cow is either facing to the left or facing to the right. When Iahub milks a cow, all the cows that see the current cow get scared and lose one unit of the quantity o... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=200000). The second line contains *n* integers *a*1, *a*2, ..., *a**n*, where *a**i* is 0 if the cow number *i* is facing left, and 1 if it is facing right. | Print a single integer, the minimum amount of lost milk.
Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4\n0 0 1 0\n",
"5\n1 0 1 0 1\n"
] | [
"1",
"3"
] | In the first sample Iahub milks the cows in the following order: cow 3, cow 4, cow 2, cow 1. When he milks cow 3, cow 4 loses 1 unit of milk. After that, no more milk is lost. | 500 | [
{
"input": "4\n0 0 1 0",
"output": "1"
},
{
"input": "5\n1 0 1 0 1",
"output": "3"
},
{
"input": "50\n1 1 0 1 1 1 1 1 1 0 0 1 1 0 1 1 0 0 1 0 1 1 0 1 1 1 1 0 1 0 1 0 1 1 1 0 0 0 0 0 0 0 1 1 0 1 0 0 1 0",
"output": "416"
},
{
"input": "100\n1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 0 0 ... | 1,559,131,155 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 187 | 3,072,000 | #! usr/bin/env python3
# coding:UTF-8
# wdnmd UKE
ans = 0
cnt = 0
N = input()
t = input().split()
for i in t:
if(int(i) == 1):
cnt += 1
else:
ans += cnt
print(ans)
| Title: Milking cows
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub helps his grandfather at the farm. Today he must milk the cows. There are *n* cows sitting in a row, numbered from 1 to *n* from left to right. Each cow is either facing to the left or facing to the right. When Iahub... | ```python
#! usr/bin/env python3
# coding:UTF-8
# wdnmd UKE
ans = 0
cnt = 0
N = input()
t = input().split()
for i in t:
if(int(i) == 1):
cnt += 1
else:
ans += cnt
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain num... | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,686,073,378 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | n, x = map(int, input().split())
if x > n * n:
print(0)
exit()
if x < 1:
print(0)
if x == 1:
print(1)
count = 0
sqx2 = int((x)**0.5)
sq_flag = False
for j in range(2, sqx2 + 1):
if x % j == 0 and x // j <= n:
count += 1
if x // j == j :
sq_flag = True
if x... | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
Y... | ```python
n, x = map(int, input().split())
if x > n * n:
print(0)
exit()
if x < 1:
print(0)
if x == 1:
print(1)
count = 0
sqx2 = int((x)**0.5)
sq_flag = False
for j in range(2, sqx2 + 1):
if x % j == 0 and x // j <= n:
count += 1
if x // j == j :
sq_flag = ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,697,147,161 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 3,379,200 | n, t = map(int, input().split())
cells = [int(x) for x in input().split()]
print("YES") if cells[t - 1] >= cells[t - 2] else print("NO")
| Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
n, t = map(int, input().split())
cells = [int(x) for x in input().split()]
print("YES") if cells[t - 1] >= cells[t - 2] else print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,694,586,030 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 154 | 2,764,800 | n = int(input())
arr = []
for i in range(n):
arr(input())
p = 1
for i in range(1, n):
if arr[i-1] != arr[i]:
p += 1
print(p)
| Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
n = int(input())
arr = []
for i in range(n):
arr(input())
p = 1
for i in range(1, n):
if arr[i-1] != arr[i]:
p += 1
print(p)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
440 | A | Forgotten Episode | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episodes not one by one but in a random order. He has already watched all the episodes except for one. Which... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100000) — the number of episodes in a season. Assume that the episodes are numbered by integers from 1 to *n*.
The second line contains *n*<=-<=1 integer *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the numbers of episodes that Polycarpus has watch... | Print the number of the episode that Polycarpus hasn't watched. | [
"10\n3 8 10 1 7 9 6 5 2\n"
] | [
"4\n"
] | none | 500 | [
{
"input": "10\n3 8 10 1 7 9 6 5 2",
"output": "4"
},
{
"input": "5\n4 3 2 1",
"output": "5"
},
{
"input": "2\n1",
"output": "2"
},
{
"input": "2\n2",
"output": "1"
},
{
"input": "3\n1 2",
"output": "3"
},
{
"input": "3\n1 3",
"output": "2"
},
... | 1,620,126,528 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 140 | 12,083,200 | n = int(input())
a = set(input().split())
b = set()
for i in range(1, n + 1):
b.add(str(i))
for i in b.difference(a):
print(i) | Title: Forgotten Episode
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episo... | ```python
n = int(input())
a = set(input().split())
b = set()
for i in range(1, n + 1):
b.add(str(i))
for i in b.difference(a):
print(i)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,692,167,827 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 62 | 0 | n = input()
x = str()
i = int()
while len(n) > 0:
if n[i] == '1':
if n[i+1] == '4':
n = n[i+2:]
elif n[i+1]+n[i+2] == '44':
n = n[i+3:]
else:
n = n[i+1:]
else:
print("NO")
break
else:
print("YES")
| Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
n = input()
x = str()
i = int()
while len(n) > 0:
if n[i] == '1':
if n[i+1] == '4':
n = n[i+2:]
elif n[i+1]+n[i+2] == '44':
n = n[i+3:]
else:
n = n[i+1:]
else:
print("NO")
break
else:
print("YES")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
712 | C | Memory and De-Evolution | PROGRAMMING | 1,600 | [
"greedy",
"math"
] | null | null | Memory is now interested in the de-evolution of objects, specifically triangles. He starts with an equilateral triangle of side length *x*, and he wishes to perform operations to obtain an equilateral triangle of side length *y*.
In a single second, he can modify the length of a single side of the current triangle suc... | The first and only line contains two integers *x* and *y* (3<=≤<=*y*<=<<=*x*<=≤<=100<=000) — the starting and ending equilateral triangle side lengths respectively. | Print a single integer — the minimum number of seconds required for Memory to obtain the equilateral triangle of side length *y* if he starts with the equilateral triangle of side length *x*. | [
"6 3\n",
"8 5\n",
"22 4\n"
] | [
"4\n",
"3\n",
"6\n"
] | In the first sample test, Memory starts with an equilateral triangle of side length 6 and wants one of side length 3. Denote a triangle with sides *a*, *b*, and *c* as (*a*, *b*, *c*). Then, Memory can do <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/18af21f738bad490df83097a90e1f2879a4b21... | 1,500 | [
{
"input": "6 3",
"output": "4"
},
{
"input": "8 5",
"output": "3"
},
{
"input": "22 4",
"output": "6"
},
{
"input": "4 3",
"output": "3"
},
{
"input": "57 27",
"output": "4"
},
{
"input": "61 3",
"output": "9"
},
{
"input": "5 4",
"out... | 1,481,353,631 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 62 | 0 | x,y=input().split()
x=int(x)
y=int(y)
a=y
b=y
c=y
z=1
ans=0
while True:
if z==1:
a=b+c-1
z+=1
ans+=1
if a>=x:
break
elif z==2:
b=c+a-1
z+=1
ans+=1
if b>=x:
break
else:
c=a+b-1
z=1
... | Title: Memory and De-Evolution
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Memory is now interested in the de-evolution of objects, specifically triangles. He starts with an equilateral triangle of side length *x*, and he wishes to perform operations to obtain an equilateral triangle o... | ```python
x,y=input().split()
x=int(x)
y=int(y)
a=y
b=y
c=y
z=1
ans=0
while True:
if z==1:
a=b+c-1
z+=1
ans+=1
if a>=x:
break
elif z==2:
b=c+a-1
z+=1
ans+=1
if b>=x:
break
else:
c=a+b-1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
404 | A | Valera and X | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the... | The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper. | Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes. | [
"5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n",
"3\nwsw\nsws\nwsw\n",
"3\nxpx\npxp\nxpe\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox",
"output": "NO"
},
{
"input": "3\nwsw\nsws\nwsw",
"output": "YES"
},
{
"input": "3\nxpx\npxp\nxpe",
"output": "NO"
},
{
"input": "5\nliiil\nilili\niilii\nilili\nliiil",
"output": "YES"
},
{
"input": "7\nbwccccb\nck... | 1,697,331,158 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 93 | 7,065,600 | from sys import stdin,stdout
#input = stdin.readline
def main():
#t = int(input())
t = 1
for z in range(t):
n = int(input())
#a,b,c = map(int,input().split())
#ai = list(map(int,input().split()))
s = [list(input()) for i in range(n)]
if s[0][0] == s[0][1]:... | Title: Valera and X
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a... | ```python
from sys import stdin,stdout
#input = stdin.readline
def main():
#t = int(input())
t = 1
for z in range(t):
n = int(input())
#a,b,c = map(int,input().split())
#ai = list(map(int,input().split()))
s = [list(input()) for i in range(n)]
if s[0][0] =... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
712 | B | Memory and Trident | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he should move one unit right. - A 'U' indicates he should move one unit up. - A 'D' indicates he should move... | The first and only line contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) — the instructions Memory is given. | If there is a string satisfying the conditions, output a single integer — the minimum number of edits required. In case it's not possible to change the sequence in such a way that it will bring Memory to to the origin, output -1. | [
"RRU\n",
"UDUR\n",
"RUUR\n"
] | [
"-1\n",
"1\n",
"2\n"
] | In the first sample test, Memory is told to walk right, then right, then up. It is easy to see that it is impossible to edit these instructions to form a valid walk.
In the second sample test, Memory is told to walk up, then down, then up, then right. One possible solution is to change *s* to "LDUR". This string uses ... | 1,000 | [
{
"input": "RRU",
"output": "-1"
},
{
"input": "UDUR",
"output": "1"
},
{
"input": "RUUR",
"output": "2"
},
{
"input": "DDDD",
"output": "2"
},
{
"input": "RRRR",
"output": "2"
},
{
"input": "RRRUUD",
"output": "2"
},
{
"input": "UDURLRDURL... | 1,473,528,405 | 2,505 | Python 3 | OK | TESTS | 75 | 62 | 307,200 | s = input()
if len(s)%2==1: print('-1')
else:
L = s.count('L')
R = s.count('R')
U = s.count('U')
D = s.count('D')
print(int(abs(L-R)/2+abs(U-D)/2)) | Title: Memory and Trident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he shou... | ```python
s = input()
if len(s)%2==1: print('-1')
else:
L = s.count('L')
R = s.count('R')
U = s.count('U')
D = s.count('D')
print(int(abs(L-R)/2+abs(U-D)/2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
761 | A | Dasha and Stairs | PROGRAMMING | 1,000 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | On her way to programming school tiger Dasha faced her first test — a huge staircase!
The steps were numbered from one to infinity. As we know, tigers are very fond of all striped things, it is possible that it has something to do with their color. So on some interval of her way she calculated two values — the number ... | In the only line you are given two integers *a*, *b* (0<=≤<=*a*,<=*b*<=≤<=100) — the number of even and odd steps, accordingly. | In the only line print "YES", if the interval of steps described above exists, and "NO" otherwise. | [
"2 3\n",
"3 1\n"
] | [
"YES\n",
"NO\n"
] | In the first example one of suitable intervals is from 1 to 5. The interval contains two even steps — 2 and 4, and three odd: 1, 3 and 5. | 500 | [
{
"input": "2 3",
"output": "YES"
},
{
"input": "3 1",
"output": "NO"
},
{
"input": "5 4",
"output": "YES"
},
{
"input": "9 9",
"output": "YES"
},
{
"input": "85 95",
"output": "NO"
},
{
"input": "0 1",
"output": "YES"
},
{
"input": "89 25"... | 1,574,969,312 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | A = list(map(int, input().split()))
if (A[0] - 1) > A[1] or (A[0] + 1) > A[1] or A[0] == A[1]:
print('YES')
else:
print('NO') | Title: Dasha and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On her way to programming school tiger Dasha faced her first test — a huge staircase!
The steps were numbered from one to infinity. As we know, tigers are very fond of all striped things, it is possible that it has so... | ```python
A = list(map(int, input().split()))
if (A[0] - 1) > A[1] or (A[0] + 1) > A[1] or A[0] == A[1]:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,682,518,863 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | def solve():
s=[int(i) for i in input().split()]
k=[int(i) for i in input().split()]
k.sort()
add=0
n,m=s[0],s[1]
for i in range(m):
add+=(-1*k[i] if k[i]<0 else k[i])
print(add)
solve() | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
def solve():
s=[int(i) for i in input().split()]
k=[int(i) for i in input().split()]
k.sort()
add=0
n,m=s[0],s[1]
for i in range(m):
add+=(-1*k[i] if k[i]<0 else k[i])
print(add)
solve()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,598,826,722 | 2,147,483,647 | PyPy 3 | OK | TESTS | 60 | 140 | 20,377,600 | n=int(input())
no=1
for i in range(n):
k=input().split()
if int(k[1])>=2400 and int(k[1])<int(k[2]):
print("YES")
no=0
break
if no==1:
print("NO")
| Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
n=int(input())
no=1
for i in range(n):
k=input().split()
if int(k[1])>=2400 and int(k[1])<int(k[2]):
print("YES")
no=0
break
if no==1:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
229 | D | Towers | PROGRAMMING | 2,100 | [
"dp",
"greedy",
"two pointers"
] | null | null | The city of D consists of *n* towers, built consecutively on a straight line. The height of the tower that goes *i*-th (from left to right) in the sequence equals *h**i*. The city mayor decided to rebuild the city to make it beautiful. In a beautiful city all towers are are arranged in non-descending order of their hei... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=5000) — the number of towers in the city. The next line contains *n* space-separated integers: the *i*-th number *h**i* (1<=≤<=*h**i*<=≤<=105) determines the height of the tower that is *i*-th (from left to right) in the initial tower sequence. | Print a single integer — the minimum number of operations needed to make the city beautiful. | [
"5\n8 2 7 3 1\n",
"3\n5 2 1\n"
] | [
"3\n",
"2\n"
] | none | 1,000 | [
{
"input": "5\n8 2 7 3 1",
"output": "3"
},
{
"input": "3\n5 2 1",
"output": "2"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 3 2",
"output": "1"
},
{
"i... | 1,676,657,834 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | import heapq
n = int(input())
towers = list(map(int, input().split()))
heapq.heapify(towers)
result = 0
while len(towers) > 1:
a = heapq.heappop(towers)
b = heapq.heappop(towers)
result += a + b
heapq.heappush(towers, a + b)
print(result)
| Title: Towers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The city of D consists of *n* towers, built consecutively on a straight line. The height of the tower that goes *i*-th (from left to right) in the sequence equals *h**i*. The city mayor decided to rebuild the city to make it bea... | ```python
import heapq
n = int(input())
towers = list(map(int, input().split()))
heapq.heapify(towers)
result = 0
while len(towers) > 1:
a = heapq.heappop(towers)
b = heapq.heappop(towers)
result += a + b
heapq.heappush(towers, a + b)
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,615,031,636 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 307,200 | b = int(input())
a = list(map(int,input().split()))
k = 0
q = 0
f = 0
h = 0
for j in range(len(a)):
if a[j] % 2 == 0:
k +=1
f = a[j]
else:
q+=1
h = a[j]
if k == 1:
print(a.index(f)+1)
elif q == 1:
print(a.index(h)+1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
b = int(input())
a = list(map(int,input().split()))
k = 0
q = 0
f = 0
h = 0
for j in range(len(a)):
if a[j] % 2 == 0:
k +=1
f = a[j]
else:
q+=1
h = a[j]
if k == 1:
print(a.index(f)+1)
elif q == 1:
print(a.index(h)+1)
... | 3.968428 | MatrixStudio/Codeforces-Python-Submissions |
10 | A | Power Consumption Calculation | PROGRAMMING | 900 | [
"implementation"
] | A. Power Consumption Calculation | 1 | 256 | Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T... | The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<... | Output the answer to the problem. | [
"1 3 2 1 5 10\n0 10\n",
"2 8 4 2 5 10\n20 30\n50 100\n"
] | [
"30",
"570"
] | none | 0 | [
{
"input": "1 3 2 1 5 10\n0 10",
"output": "30"
},
{
"input": "2 8 4 2 5 10\n20 30\n50 100",
"output": "570"
},
{
"input": "3 15 9 95 39 19\n873 989\n1003 1137\n1172 1436",
"output": "8445"
},
{
"input": "4 73 2 53 58 16\n51 52\n209 242\n281 407\n904 945",
"output": "5287... | 1,643,256,754 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n,p1,p2,p3,t1,t2=map(int,input().split())
t1=t1+1
st=0
p=0
rt=-1
while n:
n=n-1
l,r=map(int,input().split())
if rt==-1: rt=l+1
while rt<=r:
if l<rt: st=0
else: st=st+1
if st>=t1+t2: p=p+p3
elif st>=t1: p=p+p2
else: p=p+p1
rt=rt+1
print(p)
| Title: Power Consumption Calculation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard f... | ```python
n,p1,p2,p3,t1,t2=map(int,input().split())
t1=t1+1
st=0
p=0
rt=-1
while n:
n=n-1
l,r=map(int,input().split())
if rt==-1: rt=l+1
while rt<=r:
if l<rt: st=0
else: st=st+1
if st>=t1+t2: p=p+p3
elif st>=t1: p=p+p2
else: p=p+p1
rt=rt+1
... | 3.954 | MatrixStudio/Codeforces-Python-Submissions |
3 | C | Tic-tac-toe | PROGRAMMING | 1,800 | [
"brute force",
"games",
"implementation"
] | C. Tic-tac-toe | 1 | 64 | Certainly, everyone is familiar with tic-tac-toe game. The rules are very simple indeed. Two players take turns marking the cells in a 3<=×<=3 grid (one player always draws crosses, the other — noughts). The player who succeeds first in placing three of his marks in a horizontal, vertical or diagonal line wins, and the... | The input consists of three lines, each of the lines contains characters ".", "X" or "0" (a period, a capital letter X, or a digit zero). | Print one of the six verdicts: first, second, illegal, the first player won, the second player won or draw. | [
"X0X\n.0.\n.X.\n"
] | [
"second\n"
] | none | 0 | [
{
"input": "X0X\n.0.\n.X.",
"output": "second"
},
{
"input": "0.X\nXX.\n000",
"output": "illegal"
},
{
"input": "XXX\n.0.\n000",
"output": "illegal"
},
{
"input": "XXX\n...\n000",
"output": "illegal"
},
{
"input": "X.X\nX..\n00.",
"output": "second"
},
{
... | 1,629,782,833 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 124 | 6,963,200 | s = [input().strip()for i in range(3)]
o = [[s[i].count('0')for i in range(3)],[0,0,0],[0,0]]
x = [[s[i].count('X')for i in range(3)],[0,0,0],[0,0]]
for i in range(3):
for j in range(3):
if s[j][i] == '0':
o[1][i] += 1
if s[j][i] == 'X':
x[1][i] += 1
if s[i][i] =... | Title: Tic-tac-toe
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Certainly, everyone is familiar with tic-tac-toe game. The rules are very simple indeed. Two players take turns marking the cells in a 3<=×<=3 grid (one player always draws crosses, the other — noughts). The player who succeeds ... | ```python
s = [input().strip()for i in range(3)]
o = [[s[i].count('0')for i in range(3)],[0,0,0],[0,0]]
x = [[s[i].count('X')for i in range(3)],[0,0,0],[0,0]]
for i in range(3):
for j in range(3):
if s[j][i] == '0':
o[1][i] += 1
if s[j][i] == 'X':
x[1][i] += 1
if... | 0 | MatrixStudio/Codeforces-Python-Submissions |
115 | A | Party | PROGRAMMING | 900 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of another employee *B* if at least one of the following is true:
- Employee *A* is the immedi... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of employees.
The next *n* lines contain the integers *p**i* (1<=≤<=*p**i*<=≤<=*n* or *p**i*<==<=-1). Every *p**i* denotes the immediate manager for the *i*-th employee. If *p**i* is -1, that means that the *i*-th employee does not have an immediate... | Print a single integer denoting the minimum number of groups that will be formed in the party. | [
"5\n-1\n1\n2\n1\n-1\n"
] | [
"3\n"
] | For the first example, three groups are sufficient, for example:
- Employee 1 - Employees 2 and 4 - Employees 3 and 5 | 500 | [
{
"input": "5\n-1\n1\n2\n1\n-1",
"output": "3"
},
{
"input": "4\n-1\n1\n2\n3",
"output": "4"
},
{
"input": "12\n-1\n1\n2\n3\n-1\n5\n6\n7\n-1\n9\n10\n11",
"output": "4"
},
{
"input": "6\n-1\n-1\n2\n3\n1\n1",
"output": "3"
},
{
"input": "3\n-1\n1\n1",
"output": ... | 1,681,543,733 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | c=[]
y=0
x=0
final=[]
a=int (input())
for i in range (a):
b=int(input())
c.append(b)
for i in range(1,len(c)+1):
for e in c:
if e==i:
x=x+1
final.append(x)
x=0
for i in final:
if i!=0:
y=y+1
print(y+1) | Title: Party
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of an... | ```python
c=[]
y=0
x=0
final=[]
a=int (input())
for i in range (a):
b=int(input())
c.append(b)
for i in range(1,len(c)+1):
for e in c:
if e==i:
x=x+1
final.append(x)
x=0
for i in final:
if i!=0:
y=y+1
print(y+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
687 | B | Remainders Game | PROGRAMMING | 1,800 | [
"chinese remainder theorem",
"math",
"number theory"
] | null | null | Today Pari and Arya are playing a game called Remainders.
Pari chooses two positive integer *x* and *k*, and tells Arya *k* but not *x*. Arya have to find the value . There are *n* ancient numbers *c*1,<=*c*2,<=...,<=*c**n* and Pari has to tell Arya if Arya wants. Given *k* and the ancient values, tell us if Arya has... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<= *k*<=≤<=1<=000<=000) — the number of ancient integers and value *k* that is chosen by Pari.
The second line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=1<=000<=000). | Print "Yes" (without quotes) if Arya has a winning strategy independent of value of *x*, or "No" (without quotes) otherwise. | [
"4 5\n2 3 5 12\n",
"2 7\n2 3\n"
] | [
"Yes\n",
"No\n"
] | In the first sample, Arya can understand <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/d170efffcde0907ee6bcf32de21051bce0677a2c.png" style="max-width: 100.0%;max-height: 100.0%;"/> because 5 is one of the ancient numbers.
In the second sample, Arya can't be sure what <img align="middle" ... | 1,000 | [
{
"input": "4 5\n2 3 5 12",
"output": "Yes"
},
{
"input": "2 7\n2 3",
"output": "No"
},
{
"input": "1 6\n8",
"output": "No"
},
{
"input": "2 3\n9 4",
"output": "Yes"
},
{
"input": "4 16\n19 16 13 9",
"output": "Yes"
},
{
"input": "5 10\n5 16 19 9 17",
... | 1,558,445,682 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 139 | 0 | from sys import stdin
# stdin = open('input.txt')
# from sys import stdout
# stdout = open('output.txt',mode='w+')
# def print1(x, end='\n'):
# stdout.write(str(x) +end)
# a, b = map(int, input().split())
# l = list(map(int, input().split()))
# # CODE BEGINS HERE.................
# import copy
import math
... | Title: Remainders Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Pari and Arya are playing a game called Remainders.
Pari chooses two positive integer *x* and *k*, and tells Arya *k* but not *x*. Arya have to find the value . There are *n* ancient numbers *c*1,<=*c*2,<=...,<=*... | ```python
from sys import stdin
# stdin = open('input.txt')
# from sys import stdout
# stdout = open('output.txt',mode='w+')
# def print1(x, end='\n'):
# stdout.write(str(x) +end)
# a, b = map(int, input().split())
# l = list(map(int, input().split()))
# # CODE BEGINS HERE.................
# import copy
im... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
851 | A | Arpa and a research in Mexican wave | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Arpa is researching the Mexican wave.
There are *n* spectators in the stadium, labeled from 1 to *n*. They start the Mexican wave at time 0.
- At time 1, the first spectator stands. - At time 2, the second spectator stands. - ... - At time *k*, the *k*-th spectator stands. - At time *k*<=+<=1, the (*k*<=+<=1)-t... | The first line contains three integers *n*, *k*, *t* (1<=≤<=*n*<=≤<=109, 1<=≤<=*k*<=≤<=*n*, 1<=≤<=*t*<=<<=*n*<=+<=*k*). | Print single integer: how many spectators are standing at time *t*. | [
"10 5 3\n",
"10 5 7\n",
"10 5 12\n"
] | [
"3\n",
"5\n",
"3\n"
] | In the following a sitting spectator is represented as -, a standing spectator is represented as ^.
- At *t* = 0 ---------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spe... | 500 | [
{
"input": "10 5 3",
"output": "3"
},
{
"input": "10 5 7",
"output": "5"
},
{
"input": "10 5 12",
"output": "3"
},
{
"input": "840585600 770678331 788528791",
"output": "770678331"
},
{
"input": "25462281 23343504 8024619",
"output": "8024619"
},
{
"in... | 1,686,305,808 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | n,k,t = map(int, input().split())
if t <= k:
print(t)
elif (t > k) and (t < n):
print(5)
elif (t > n) and (t < n + k):
print(n + k - t)
else:
print(0)
| Title: Arpa and a research in Mexican wave
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arpa is researching the Mexican wave.
There are *n* spectators in the stadium, labeled from 1 to *n*. They start the Mexican wave at time 0.
- At time 1, the first spectator stands. - At time 2,... | ```python
n,k,t = map(int, input().split())
if t <= k:
print(t)
elif (t > k) and (t < n):
print(5)
elif (t > n) and (t < n + k):
print(n + k - t)
else:
print(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
127 | A | Wasted Time | PROGRAMMING | 900 | [
"geometry"
] | null | null | Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count the time he has wasted signing papers.
Mr. Scrooge's signature can be represented as a polyline ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). Each of the following *n* lines contains the coordinates of the polyline's endpoints. The *i*-th one contains coordinates of the point *A**i* — integers *x**i* and *y**i*, separated by a space.
All points *A**i* are different. Th... | Print one real number — the total time Scrooges wastes on signing the papers in seconds. The absolute or relative error should not exceed 10<=-<=6. | [
"2 1\n0 0\n10 0\n",
"5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0\n",
"6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0\n"
] | [
"0.200000000",
"6.032163204",
"3.000000000"
] | none | 500 | [
{
"input": "2 1\n0 0\n10 0",
"output": "0.200000000"
},
{
"input": "5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0",
"output": "6.032163204"
},
{
"input": "6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0",
"output": "3.000000000"
},
{
"input": "10 95\n-20 -5\n2 -8\n14 13\n10 3\n17 11\n13 -12\n-6 11\n1... | 1,608,188,526 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 218 | 307,200 | import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def rinput(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
n,k = rinput()
m=[]
for i in range(n):
a,b=rinput()
... | Title: Wasted Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count ... | ```python
import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def rinput(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
n,k = rinput()
m=[]
for i in range(n):
a,b=ri... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,602,658,434 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 307,200 | import random
import numpy as np
x=int(input(""))
y=int(input(""))
l=list()
z=chr(random.randint(97, 122))
for i in range(y):
z=chr(random.randint(97, 122))
if(z in l):
continue
l.append(z)
if (len(l)<x):
sub=abs(x-y)
for i in range(sub):
l.append(l[i])
print(l)
... | Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
import random
import numpy as np
x=int(input(""))
y=int(input(""))
l=list()
z=chr(random.randint(97, 122))
for i in range(y):
z=chr(random.randint(97, 122))
if(z in l):
continue
l.append(z)
if (len(l)<x):
sub=abs(x-y)
for i in range(sub):
l.append(l[i])
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,641,436,215 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | num = int(input())
coordinates = list(map(int, input().split()))
def find_min(arr, center):
min = 10000
for i in range(num):
if(i != center):
diff = abs(arr[i] - arr[center])
if(diff < min):
min = diff
return min
def find_max(arr, center):
... | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
num = int(input())
coordinates = list(map(int, input().split()))
def find_min(arr, center):
min = 10000
for i in range(num):
if(i != center):
diff = abs(arr[i] - arr[center])
if(diff < min):
min = diff
return min
def find_max(arr,... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
629 | A | Far Relative’s Birthday Cake | PROGRAMMING | 800 | [
"brute force",
"combinatorics",
"constructive algorithms",
"implementation"
] | null | null | Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with side length 1. Each square is either empty or consists of a single chocolate. They bought the cake and randomly sta... | In the first line of the input, you are given a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the side of the cake.
Then follow *n* lines, each containing *n* characters. Empty cells are denoted with '.', while cells that contain chocolates are denoted by 'C'. | Print the value of Famil Door's happiness, i.e. the number of pairs of chocolate pieces that share the same row or the same column. | [
"3\n.CC\nC..\nC.C\n",
"4\nCC..\nC..C\n.CC.\n.CC.\n"
] | [
"4\n",
"9\n"
] | If we number rows from top to bottom and columns from left to right, then, pieces that share the same row in the first sample are:
1. (1, 2) and (1, 3) 1. (3, 1) and (3, 3) 1. (2, 1) and (3, 1) 1. (1, 3) and (3, 3) | 500 | [
{
"input": "3\n.CC\nC..\nC.C",
"output": "4"
},
{
"input": "4\nCC..\nC..C\n.CC.\n.CC.",
"output": "9"
},
{
"input": "5\n.CCCC\nCCCCC\n.CCC.\nCC...\n.CC.C",
"output": "46"
},
{
"input": "7\n.CC..CC\nCC.C..C\nC.C..C.\nC...C.C\nCCC.CCC\n.CC...C\n.C.CCC.",
"output": "84"
},... | 1,594,593,535 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 187 | 7,987,200 | import math,itertools,fractions,heapq,collections,bisect,sys,queue,copy
sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7
dd=[(-1,0),(0,1),(1,0),(0,-1)]
ddn=[(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
# def LF(): return [float(x) for x in s... | Title: Far Relative’s Birthday Cake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with s... | ```python
import math,itertools,fractions,heapq,collections,bisect,sys,queue,copy
sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7
dd=[(-1,0),(0,1),(1,0),(0,-1)]
ddn=[(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
# def LF(): return [float(x) ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
288 | C | Polo the Penguin and XOR operation | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | Little penguin Polo likes permutations. But most of all he likes permutations of integers from 0 to *n*, inclusive.
For permutation *p*<==<=*p*0,<=*p*1,<=...,<=*p**n*, Polo has defined its beauty — number .
Expression means applying the operation of bitwise excluding "OR" to numbers *x* and *y*. This operation exist... | The single line contains a positive integer *n* (1<=≤<=*n*<=≤<=106). | In the first line print integer *m* the maximum possible beauty. In the second line print any permutation of integers from 0 to *n* with the beauty equal to *m*.
If there are several suitable permutations, you are allowed to print any of them. | [
"4\n"
] | [
"20\n0 2 1 4 3\n"
] | none | 1,500 | [
{
"input": "4",
"output": "20\n0 2 1 4 3"
},
{
"input": "7",
"output": "56\n7 6 5 4 3 2 1 0"
},
{
"input": "1",
"output": "2\n1 0"
},
{
"input": "2",
"output": "6\n0 2 1"
},
{
"input": "3",
"output": "12\n3 2 1 0"
},
{
"input": "8",
"output": "72\n... | 1,686,468,409 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 12 | 154 | 2,867,200 | import sys
import bisect
input = sys.stdin.readline
n = int(input())
l = []
for i in range(21):
l.append((1 << i)-1)
def up(key):
for i in range(20):
if (key <= l[i]):
return l[i]
ans = []
x = up(n)
i = n
while (i > -1):
if (x-i <= n and x-i not in ans):
a... | Title: Polo the Penguin and XOR operation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little penguin Polo likes permutations. But most of all he likes permutations of integers from 0 to *n*, inclusive.
For permutation *p*<==<=*p*0,<=*p*1,<=...,<=*p**n*, Polo has defined its beauty — n... | ```python
import sys
import bisect
input = sys.stdin.readline
n = int(input())
l = []
for i in range(21):
l.append((1 << i)-1)
def up(key):
for i in range(20):
if (key <= l[i]):
return l[i]
ans = []
x = up(n)
i = n
while (i > -1):
if (x-i <= n and x-i not in ans):
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,568,229,197 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 109 | 0 | n = int(input())
l = 0
t = list(map(int, input().split()))
c = 15
for i in t:
if i > c:
break
c = i+15
print(min(c, 90))
| Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = int(input())
l = 0
t = list(map(int, input().split()))
c = 15
for i in t:
if i > c:
break
c = i+15
print(min(c, 90))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,696,932,247 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | #刚好有三个因数
#分析：只有一个质因数
#埃氏筛
n=int(input())
def is_prime(num):
#初始默认为素数
global bool_p
bool_p=[0]*(num+1)
for i in range(2,num+1):
if bool_p[i]==0:
for j in range(i+i,num+1,i):
bool_p[j]=1
bool_t=[0]*n#默认都是NO
nums=[int(i) for i in input().split()]
max_n... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
#刚好有三个因数
#分析：只有一个质因数
#埃氏筛
n=int(input())
def is_prime(num):
#初始默认为素数
global bool_p
bool_p=[0]*(num+1)
for i in range(2,num+1):
if bool_p[i]==0:
for j in range(i+i,num+1,i):
bool_p[j]=1
bool_t=[0]*n#默认都是NO
nums=[int(i) for i in input().split... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,667,308,863 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | import math
a=list(input())
w=0
for i in a:
if i>='a' and i<='z':
w+=1
p=list([str(a).lower(),str(a).upper()][w<math.ceil(len(a)/2)])
for o in p:
print(o,end='') | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
import math
a=list(input())
w=0
for i in a:
if i>='a' and i<='z':
w+=1
p=list([str(a).lower(),str(a).upper()][w<math.ceil(len(a)/2)])
for o in p:
print(o,end='')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,653,077,038 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 92 | 409,600 | import re; print("YNEOS" [re.sub(r'[144|14|1]', "", input()) != ''::2]) | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
import re; print("YNEOS" [re.sub(r'[144|14|1]', "", input()) != ''::2])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,599,635,764 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 156 | 0 | y = int(input("enter any no. "))
w = int(input("enter any another no. "))
print(y,w)
prob1 = 6 / y
if prob1 == 1:
print("1/1")
elif prob1 == 1.5:
print("1/2")
elif prob1 == 0:
print("0/1")
else:
pass | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
y = int(input("enter any no. "))
w = int(input("enter any another no. "))
print(y,w)
prob1 = 6 / y
if prob1 == 1:
print("1/1")
elif prob1 == 1.5:
print("1/2")
elif prob1 == 0:
print("0/1")
else:
pass
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
114 | A | Cifera | PROGRAMMING | 1,000 | [
"math"
] | null | null | When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million... | The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1). | You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*. | [
"5\n25\n",
"3\n8\n"
] | [
"YES\n1\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n25",
"output": "YES\n1"
},
{
"input": "3\n8",
"output": "NO"
},
{
"input": "123\n123",
"output": "YES\n0"
},
{
"input": "99\n970300",
"output": "NO"
},
{
"input": "1000\n6666666",
"output": "NO"
},
{
"input": "59\n3571",
"output": "N... | 1,642,095,619 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | a = int(input())
c = a
b = int(input())
count = 0
while a==b:
print("YES")
print("1")
break
while a != b:
a = a * c
count += 1
if a == b:
print("YES")
print(count)
if a > b:
print("NO")
break
| Title: Cifera
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousa... | ```python
a = int(input())
c = a
b = int(input())
count = 0
while a==b:
print("YES")
print("1")
break
while a != b:
a = a * c
count += 1
if a == b:
print("YES")
print(count)
if a > b:
print("NO")
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
499 | A | Watching a movie | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the player automatically proceeds to the next minute of the movie. 1. Skip exactly *x* minutes of the movie... | The first line contains two space-separated integers *n*, *x* (1<=≤<=*n*<=≤<=50, 1<=≤<=*x*<=≤<=105) — the number of the best moments of the movie and the value of *x* for the second button.
The following *n* lines contain the descriptions of the best moments of the movie, the *i*-th line of the description contains tw... | Output a single number — the answer to the problem. | [
"2 3\n5 6\n10 12\n",
"1 1\n1 100000\n"
] | [
"6\n",
"100000\n"
] | In the first sample, the player was initially standing on the first minute. As the minutes from the 1-st to the 4-th one don't contain interesting moments, we press the second button. Now we can not press the second button and skip 3 more minutes, because some of them contain interesting moments. Therefore, we watch th... | 500 | [
{
"input": "2 3\n5 6\n10 12",
"output": "6"
},
{
"input": "1 1\n1 100000",
"output": "100000"
},
{
"input": "10 1\n2156 3497\n4784 7775\n14575 31932\n33447 35902\n36426 47202\n48772 60522\n63982 68417\n78537 79445\n90081 90629\n94325 95728",
"output": "53974"
},
{
"input": "1... | 1,606,295,848 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a = int(input())
try:
if 1<= a <= 100:
if a % 2 is 0 && s >2 :
print("YES")
else:
print("NO")
except:
pass | Title: Watching a movie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the pl... | ```python
a = int(input())
try:
if 1<= a <= 100:
if a % 2 is 0 && s >2 :
print("YES")
else:
print("NO")
except:
pass
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,695,653,473 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | s=input()
print(s.swapcase()) | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
s=input()
print(s.swapcase())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
920 | C | Swap Adjacent Elements | PROGRAMMING | 1,400 | [
"dfs and similar",
"greedy",
"math",
"sortings",
"two pointers"
] | null | null | You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<=1)-th, for other indices it is not possible. You may perform any number of swapping operations any order. T... | The first line contains one integer *n* (2<=≤<=*n*<=≤<=200000) — the number of elements in the array.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=200000) — the elements of the array. Each integer from 1 to *n* appears exactly once.
The third line contains a string of *n*<=-<=1 char... | If it is possible to sort the array in ascending order using any sequence of swaps you are allowed to make, print YES. Otherwise, print NO. | [
"6\n1 2 5 3 4 6\n01110\n",
"6\n1 2 5 3 4 6\n01010\n"
] | [
"YES\n",
"NO\n"
] | In the first example you may swap *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, and then swap *a*<sub class="lower-index">4</sub> and *a*<sub class="lower-index">5</sub>. | 0 | [
{
"input": "6\n1 2 5 3 4 6\n01110",
"output": "YES"
},
{
"input": "6\n1 2 5 3 4 6\n01010",
"output": "NO"
},
{
"input": "6\n1 6 3 4 5 2\n01101",
"output": "NO"
},
{
"input": "6\n2 3 1 4 5 6\n01111",
"output": "NO"
},
{
"input": "4\n2 3 1 4\n011",
"output": "NO... | 1,587,624,994 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 18 | 280 | 17,715,200 | a=int(input())
z=list(map(int,input().split()))
s=input()
ans=[]
k=min(z)
ans=[0 for i in range(len(z))]
flag=0
for i in range(len(z)-1,-1,-1):
if(i==len(z)-1):
ans[i]=z[-1]
else:
ans[i]=min(z[i],ans[i+1])
for i in range(len(z)-1):
if(s[i]=='0' and ans[i]<z[i]):
flag=... | Title: Swap Adjacent Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<... | ```python
a=int(input())
z=list(map(int,input().split()))
s=input()
ans=[]
k=min(z)
ans=[0 for i in range(len(z))]
flag=0
for i in range(len(z)-1,-1,-1):
if(i==len(z)-1):
ans[i]=z[-1]
else:
ans[i]=min(z[i],ans[i+1])
for i in range(len(z)-1):
if(s[i]=='0' and ans[i]<z[i]):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
33 | D | Knights | PROGRAMMING | 2,000 | [
"geometry",
"graphs",
"shortest paths",
"sortings"
] | D. Knights | 2 | 256 | Berland is facing dark times again. The army of evil lord Van de Mart is going to conquer the whole kingdom. To the council of war called by the Berland's king Valery the Severe came *n* knights. After long discussions it became clear that the kingdom has exactly *n* control points (if the enemy conquers at least one o... | The first input line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*<=≤<=1000, 0<=≤<=*k*<=≤<=100000). Then follow *n* lines, each containing two integers *Kx**i*, *Ky**i* (<=-<=109<=≤<=*Kx**i*,<=*Ky**i*<=≤<=109) — coordinates of control point with index *i*. Control points can coincide.
Each of the following *m... | Output exactly *k* lines, each containing one integer — the answer to the corresponding request. | [
"2 1 1\n0 0\n3 3\n2 0 0\n1 2\n",
"2 3 1\n0 0\n4 4\n1 0 0\n2 0 0\n3 0 0\n1 2\n"
] | [
"1\n",
"3\n"
] | none | 2,000 | [] | 1,616,693,267 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 186 | 102,400 | import sys; input = sys.stdin.readline
from collections import deque
import heapq as hq
N = 2*10**5+5
def read():
return map(int, input().split())
n, m, k = read()
points = [list(read()) for i in range(n)]
fences = [list(read()) for i in range(m)]
def dist(x1, y1, x2, y2):
return (x1-x2)**2 + (y1-y2)**2
p = [[] for i... | Title: Knights
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Berland is facing dark times again. The army of evil lord Van de Mart is going to conquer the whole kingdom. To the council of war called by the Berland's king Valery the Severe came *n* knights. After long discussions it became cl... | ```python
import sys; input = sys.stdin.readline
from collections import deque
import heapq as hq
N = 2*10**5+5
def read():
return map(int, input().split())
n, m, k = read()
points = [list(read()) for i in range(n)]
fences = [list(read()) for i in range(m)]
def dist(x1, y1, x2, y2):
return (x1-x2)**2 + (y1-y2)**2
p =... | 0 | MatrixStudio/Codeforces-Python-Submissions |
985 | A | Chess Placing | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | You are given a chessboard of size 1<=×<=*n*. It is guaranteed that *n* is even. The chessboard is painted like this: "BWBW...BW".
Some cells of the board are occupied by the chess pieces. Each cell contains no more than one chess piece. It is known that the total number of pieces equals to .
In one step you can move... | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100, *n* is even) — the size of the chessboard.
The second line of the input contains integer numbers (1<=≤<=*p**i*<=≤<=*n*) — initial positions of the pieces. It is guaranteed that all the positions are distinct. | Print one integer — the minimum number of moves you have to make to place all the pieces in the cells of the same color. | [
"6\n1 2 6\n",
"10\n1 2 3 4 5\n"
] | [
"2\n",
"10\n"
] | In the first example the only possible strategy is to move the piece at the position 6 to the position 5 and move the piece at the position 2 to the position 3. Notice that if you decide to place the pieces in the white cells the minimum number of moves will be 3.
In the second example the possible strategy is to move... | 0 | [
{
"input": "6\n1 2 6",
"output": "2"
},
{
"input": "10\n1 2 3 4 5",
"output": "10"
},
{
"input": "2\n2",
"output": "0"
},
{
"input": "100\n2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 ... | 1,586,174,676 | 276 | PyPy 3 | OK | TESTS | 27 | 140 | 0 | n = int(input())
a = list(map(int, input().split()))
for i in range(n // 2):
a[i] -= 1
a = sorted(a)
ans1 = 0
for i in range(n // 2):
ans1 += abs(a[i] - 2 * i)
ans2 = 0
for i in range(n // 2):
ans2 += abs(a[i] - (2 * i + 1))
print(min(ans1, ans2)) | Title: Chess Placing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a chessboard of size 1<=×<=*n*. It is guaranteed that *n* is even. The chessboard is painted like this: "BWBW...BW".
Some cells of the board are occupied by the chess pieces. Each cell contains no more than... | ```python
n = int(input())
a = list(map(int, input().split()))
for i in range(n // 2):
a[i] -= 1
a = sorted(a)
ans1 = 0
for i in range(n // 2):
ans1 += abs(a[i] - 2 * i)
ans2 = 0
for i in range(n // 2):
ans2 += abs(a[i] - (2 * i + 1))
print(min(ans1, ans2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,550,048,737 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 186 | 0 | s = list(input().split('.'))
news = ''
for i in range(len(s)):
if s[i] == '-':
news += '1'
elif s[i] == '':
news += '0'
else:
news += '2'*(s[i].count('-')//2)
print(news) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s = list(input().split('.'))
news = ''
for i in range(len(s)):
if s[i] == '-':
news += '1'
elif s[i] == '':
news += '0'
else:
news += '2'*(s[i].count('-')//2)
print(news)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
7 | A | Kalevitch and Chess | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms"
] | A. Kalevitch and Chess | 2 | 64 | A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch decided to put an end to this tradition and to introduce a new attitude to chessboards.
As before, th... | The input file contains 8 lines, each of the lines contains 8 characters. The given matrix describes the client's requirements, W character stands for a white square, and B character — for a square painted black.
It is guaranteed that client's requirments can be fulfilled with a sequence of allowed strokes (vertical/c... | Output the only number — the minimum amount of rows and columns that Kalevitch has to paint on the white chessboard to meet the client's requirements. | [
"WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\n",
"WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\n"
] | [
"3\n",
"1\n"
] | none | 0 | [
{
"input": "WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW",
"output": "3"
},
{
"input": "WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW",
"output": "1"
},
{
"input": "WWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWW... | 1,539,545,039 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | a = []
r = 0
for k in range(8):
a.append(input())
for i in a:
m = 0
for k in range(len(i)):
m += ord(i[k])
if m == 528:
r += 1
if r == 8:
print(r)
exit()
for i in range(len(a)):
m = 0
for k in range(8):
m += ord(a[i][1])
if m == 528:
r += 1
print(r)
| Title: Kalevitch and Chess
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch de... | ```python
a = []
r = 0
for k in range(8):
a.append(input())
for i in a:
m = 0
for k in range(len(i)):
m += ord(i[k])
if m == 528:
r += 1
if r == 8:
print(r)
exit()
for i in range(len(a)):
m = 0
for k in range(8):
m += ord(a[i][1])
if m == 528:
r += 1
p... | 0 | MatrixStudio/Codeforces-Python-Submissions |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should b... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right aft... | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,643,964,043 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | def printHave(snakes):
snakes = sorted(snakes , reverse=True)
big = snakes[0]
for snake in snakes:
print(f"{snake} ", end='')
return big
biggest_snake = int(input())
fallings = list(map(int, input().split()))
have = []
for snake in fallings:
if snake == biggest_snake:
... | Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents sh... | ```python
def printHave(snakes):
snakes = sorted(snakes , reverse=True)
big = snakes[0]
for snake in snakes:
print(f"{snake} ", end='')
return big
biggest_snake = int(input())
fallings = list(map(int, input().split()))
have = []
for snake in fallings:
if snake == bigges... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,694,046,131 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | s = input()
minus = 0
mayus = 0
for c in s:
if c.islower():
minus += 1
else:
mayus += 1
if minus >= mayus:
s = s.lower()
else:
s = s.upper()
print(s)
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
minus = 0
mayus = 0
for c in s:
if c.islower():
minus += 1
else:
mayus += 1
if minus >= mayus:
s = s.lower()
else:
s = s.upper()
print(s)
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
454 | A | Little Pony and Crystal Mine | PROGRAMMING | 800 | [
"implementation"
] | null | null | Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You need to draw a crystal of size *n*. The diamond cells of the matrix should be represented by character "D". All ot... | The only line contains an integer *n* (3<=≤<=*n*<=≤<=101; *n* is odd). | Output a crystal of size *n*. | [
"3\n",
"5\n",
"7\n"
] | [
"*D*\nDDD\n*D*\n",
"**D**\n*DDD*\nDDDDD\n*DDD*\n**D**\n",
"***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***\n"
] | none | 500 | [
{
"input": "3",
"output": "*D*\nDDD\n*D*"
},
{
"input": "5",
"output": "**D**\n*DDD*\nDDDDD\n*DDD*\n**D**"
},
{
"input": "7",
"output": "***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***"
},
{
"input": "11",
"output": "*****D*****\n****DDD****\n***DDDDD***\n**... | 1,587,326,173 | 2,147,483,647 | PyPy 3 | OK | TESTS | 12 | 187 | 5,632,000 | def printDiamond(n):
k = 0
reverse = False
mid = n // 2
for i in range(n):
for j in range(n):
if j >= mid - k and j <= mid + k:
print("D", end = "")
else:
print("*", end = "")
print()
if i == mid:
rev... | Title: Little Pony and Crystal Mine
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You ... | ```python
def printDiamond(n):
k = 0
reverse = False
mid = n // 2
for i in range(n):
for j in range(n):
if j >= mid - k and j <= mid + k:
print("D", end = "")
else:
print("*", end = "")
print()
if i == mid:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
492 | B | Vanya and Lanterns | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"math",
"sortings"
] | null | null | Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point *l*. Then the *i*-th lantern is at the point *a**i*. The lantern lights all points of the street that... | The first line contains two integers *n*, *l* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*l*<=≤<=109) — the number of lanterns and the length of the street respectively.
The next line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=*l*). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of th... | Print the minimum light radius *d*, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=9. | [
"7 15\n15 5 3 7 9 14 0\n",
"2 5\n2 5\n"
] | [
"2.5000000000\n",
"2.0000000000\n"
] | Consider the second sample. At *d* = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | 1,000 | [
{
"input": "7 15\n15 5 3 7 9 14 0",
"output": "2.5000000000"
},
{
"input": "2 5\n2 5",
"output": "2.0000000000"
},
{
"input": "46 615683844\n431749087 271781274 274974690 324606253 480870261 401650581 13285442 478090364 266585394 425024433 588791449 492057200 391293435 563090494 317950 1... | 1,695,194,516 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | n, l = map(int, input().split())
lanterns = list(map(int, input().split()))
lanterns.sort()
max_distance = 0
for i in range(n - 1):
max_distance = max(max_distance, lanterns[i + 1] - lanterns[i])
# Consider the distance from the first lantern to the beginning and from the last lantern to the end
max_... | Title: Vanya and Lanterns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the poi... | ```python
n, l = map(int, input().split())
lanterns = list(map(int, input().split()))
lanterns.sort()
max_distance = 0
for i in range(n - 1):
max_distance = max(max_distance, lanterns[i + 1] - lanterns[i])
# Consider the distance from the first lantern to the beginning and from the last lantern to the... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
675 | A | Infinite Sequence | PROGRAMMING | 1,100 | [
"math"
] | null | null | Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c* (*s**i*<=-<=*s**i*<=-<=1<==<=*c*). In particular, Vasya wonders if his favourite integer *b* appears ... | The first line of the input contain three integers *a*, *b* and *c* (<=-<=109<=≤<=*a*,<=*b*,<=*c*<=≤<=109) — the first element of the sequence, Vasya's favorite number and the difference between any two neighbouring elements of the sequence, respectively. | If *b* appears in the sequence *s* print "YES" (without quotes), otherwise print "NO" (without quotes). | [
"1 7 3\n",
"10 10 0\n",
"1 -4 5\n",
"0 60 50\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | In the first sample, the sequence starts from integers 1, 4, 7, so 7 is its element.
In the second sample, the favorite integer of Vasya is equal to the first element of the sequence.
In the third sample all elements of the sequence are greater than Vasya's favorite integer.
In the fourth sample, the sequence starts... | 500 | [
{
"input": "1 7 3",
"output": "YES"
},
{
"input": "10 10 0",
"output": "YES"
},
{
"input": "1 -4 5",
"output": "NO"
},
{
"input": "0 60 50",
"output": "NO"
},
{
"input": "1 -4 -5",
"output": "YES"
},
{
"input": "0 1 0",
"output": "NO"
},
{
... | 1,590,984,719 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | a,fav,sec=map(int,input().split())
if (fav-a)%sec :
print('YES')
else:
print('NO') | Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c... | ```python
a,fav,sec=map(int,input().split())
if (fav-a)%sec :
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
161 | A | Dress'em in Vests! | PROGRAMMING | 1,300 | [
"binary search",
"brute force",
"greedy",
"two pointers"
] | null | null | The Two-dimensional kingdom is going through hard times... This morning the Three-Dimensional kingdom declared war on the Two-dimensional one. This (possibly armed) conflict will determine the ultimate owner of the straight line.
The Two-dimensional kingdom has a regular army of *n* people. Each soldier registered him... | The first input line contains four integers *n*, *m*, *x* and *y* (1<=≤<=*n*,<=*m*<=≤<=105, 0<=≤<=*x*,<=*y*<=≤<=109) — the number of soldiers, the number of vests and two numbers that specify the soldiers' unpretentiousness, correspondingly.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i... | In the first line print a single integer *k* — the maximum number of soldiers equipped with bulletproof vests.
In the next *k* lines print *k* pairs, one pair per line, as "*u**i* *v**i*" (without the quotes). Pair (*u**i*, *v**i*) means that soldier number *u**i* must wear vest number *v**i*. Soldiers and vests are ... | [
"5 3 0 0\n1 2 3 3 4\n1 3 5\n",
"3 3 2 2\n1 5 9\n3 5 7\n"
] | [
"2\n1 1\n3 2\n",
"3\n1 1\n2 2\n3 3\n"
] | In the first sample you need the vests' sizes to match perfectly: the first soldier gets the first vest (size 1), the third soldier gets the second vest (size 3). This sample allows another answer, which gives the second vest to the fourth soldier instead of the third one.
In the second sample the vest size can differ... | 1,000 | [
{
"input": "5 3 0 0\n1 2 3 3 4\n1 3 5",
"output": "2\n1 1\n3 2"
},
{
"input": "3 3 2 2\n1 5 9\n3 5 7",
"output": "3\n1 1\n2 2\n3 3"
},
{
"input": "1 1 0 0\n1\n1",
"output": "1\n1 1"
},
{
"input": "1 1 0 0\n1\n2",
"output": "0"
},
{
"input": "2 3 1 4\n1 5\n1 2 2",
... | 1,573,501,671 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 248 | 0 | n, m, x, y = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
i = 0
j = 0
l = []
while i < n and j < m:
if b[j] < a[i]-x:
j += 1
elif b[j] > a[i]+x:
i += 1
else:
l.append([i+1, j+1])
i +... | Title: Dress'em in Vests!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Two-dimensional kingdom is going through hard times... This morning the Three-Dimensional kingdom declared war on the Two-dimensional one. This (possibly armed) conflict will determine the ultimate owner of the s... | ```python
n, m, x, y = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
i = 0
j = 0
l = []
while i < n and j < m:
if b[j] < a[i]-x:
j += 1
elif b[j] > a[i]+x:
i += 1
else:
l.append([i+1, j+1])
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,540,650,685 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 216 | 0 |
n = int(input())
k = list(map(int,input().split()))
hash = {}
k.sort()
# print(k)
c = k.copy()
hash['dif'] = 0
for i in k:
if i not in hash.keys():
hash[i] = 1
else:
hash[i] = hash[i] + 1
# print(hash)
for i in hash.keys():
if i!='dif':
for j in hash.keys():
if i!=j and j!='di... | Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
n = int(input())
k = list(map(int,input().split()))
hash = {}
k.sort()
# print(k)
c = k.copy()
hash['dif'] = 0
for i in k:
if i not in hash.keys():
hash[i] = 1
else:
hash[i] = hash[i] + 1
# print(hash)
for i in hash.keys():
if i!='dif':
for j in hash.keys():
if i!=j ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
842 | A | Kirill And The Game | PROGRAMMING | 1,200 | [
"brute force",
"two pointers"
] | null | null | Kirill plays a new computer game. He came to the potion store where he can buy any potion. Each potion is characterized by two integers — amount of experience and cost. The efficiency of a potion is the ratio of the amount of experience to the cost. Efficiency may be a non-integer number.
For each two integer numbers ... | First string contains five integer numbers *l*, *r*, *x*, *y*, *k* (1<=≤<=*l*<=≤<=*r*<=≤<=107, 1<=≤<=*x*<=≤<=*y*<=≤<=107, 1<=≤<=*k*<=≤<=107). | Print "YES" without quotes if a potion with efficiency exactly *k* can be bought in the store and "NO" without quotes otherwise.
You can output each of the letters in any register. | [
"1 10 1 10 1\n",
"1 5 6 10 1\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "1 10 1 10 1",
"output": "YES"
},
{
"input": "1 5 6 10 1",
"output": "NO"
},
{
"input": "1 1 1 1 1",
"output": "YES"
},
{
"input": "1 1 1 1 2",
"output": "NO"
},
{
"input": "1 100000 1 100000 100000",
"output": "YES"
},
{
"input": "1 100000 ... | 1,613,968,901 | 2,147,483,647 | Python 3 | OK | TESTS | 101 | 62 | 0 | import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def rinput(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
l,r,x,y,k=rinput()
if max((l + k - 1) // k, x) > min(r // k, ... | Title: Kirill And The Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kirill plays a new computer game. He came to the potion store where he can buy any potion. Each potion is characterized by two integers — amount of experience and cost. The efficiency of a potion is the ratio of the... | ```python
import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def rinput(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
l,r,x,y,k=rinput()
if max((l + k - 1) // k, x) > mi... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
522 | A | Reposts | PROGRAMMING | 1,200 | [
"*special",
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the n... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and ... | Print a single integer — the maximum length of a repost chain. | [
"5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n",
"6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n",
"1\nSoMeStRaNgEgUe repos... | [
"6\n",
"2\n",
"2\n"
] | none | 500 | [
{
"input": "5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya",
"output": "6"
},
{
"input": "6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforc... | 1,639,725,992 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 62 | 102,400 | from collections import deque
n = int(input())
q = deque()
q.append("polycarp")
val = {"polycarp":1}
tree = {"polycarp":[]}
for i in range(n):
a,b,c = input().split()
a = a.lower()
c = c.lower()
val[a] = 1
tree[a] = []
tree[c].append(a)
while q:
node = q.popleft()
fo... | Title: Reposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
... | ```python
from collections import deque
n = int(input())
q = deque()
q.append("polycarp")
val = {"polycarp":1}
tree = {"polycarp":[]}
for i in range(n):
a,b,c = input().split()
a = a.lower()
c = c.lower()
val[a] = 1
tree[a] = []
tree[c].append(a)
while q:
node = q.popleft... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
742 | A | Arpa’s hard exam and Mehrdad’s naive cheat | PROGRAMMING | 1,000 | [
"implementation",
"math",
"number theory"
] | null | null | There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, al... | The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109). | Print single integer — the last digit of 1378*n*. | [
"1\n",
"2\n"
] | [
"8",
"4"
] | In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | 500 | [
{
"input": "1",
"output": "8"
},
{
"input": "2",
"output": "4"
},
{
"input": "1000",
"output": "6"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "6"
},
{
"input": "1000000000",
"output": "6"
},
{
"input": "5",
"output": ... | 1,644,374,754 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 15 | 92 | 0 | num = int(input())
lst = [6, 8, 4, 2]
print(lst[num % 4]) | Title: Arpa’s hard exam and Mehrdad’s naive cheat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one ques... | ```python
num = int(input())
lst = [6, 8, 4, 2]
print(lst[num % 4])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
23 | E | Tree | PROGRAMMING | 2,500 | [
"dp"
] | E. Tree | 2 | 256 | Recently Bob invented a new game with a tree (we should remind you, that a tree is a connected graph without cycles): he deletes any (possibly, zero) amount of edges of the tree, and counts the product of sizes of the connected components left after the deletion. Your task is to find out the maximum number that Bob can... | The first input line contains integer number *n* (1<=≤<=*n*<=≤<=700) — amount of vertices in the tree. The following *n*<=-<=1 lines contain the description of the edges. Each line contains the pair of vertices' indexes, joined by an edge, *a**i*, *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*). It's guaranteed that the graph d... | Output the only number — the maximum product of sizes of the connected components, that Bob can get after deleting some of the tree's edges. | [
"5\n1 2\n2 3\n3 4\n4 5\n",
"8\n1 2\n1 3\n2 4\n2 5\n3 6\n3 7\n6 8\n",
"3\n1 2\n1 3\n"
] | [
"6",
"18",
"3"
] | none | 0 | [
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "6"
},
{
"input": "8\n1 2\n1 3\n2 4\n2 5\n3 6\n3 7\n6 8",
"output": "18"
},
{
"input": "3\n1 2\n1 3",
"output": "3"
},
{
"input": "5\n3 2\n1 5\n4 5\n5 3",
"output": "6"
},
{
"input": "5\n2 1\n3 4\n3 5\n5 2",
"outpu... | 1,667,912,791 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | G=[[] for i in range(1000)]
h=[0 for i in range(1000)]
f=[0 for i in range(1000)]
T=[[] for i in range(1000)]
size=[0 for i in range(1000)]
def cmp((a,b),(c,d)):
if b*c>a*d:
return 1
if b*c==a*d:
return 0
return -1
def dfs(u,fa):
T[u]=[]
size[u]=1;
f[u]=1;h[u]=1;
... | Title: Tree
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Recently Bob invented a new game with a tree (we should remind you, that a tree is a connected graph without cycles): he deletes any (possibly, zero) amount of edges of the tree, and counts the product of sizes of the connected compon... | ```python
G=[[] for i in range(1000)]
h=[0 for i in range(1000)]
f=[0 for i in range(1000)]
T=[[] for i in range(1000)]
size=[0 for i in range(1000)]
def cmp((a,b),(c,d)):
if b*c>a*d:
return 1
if b*c==a*d:
return 0
return -1
def dfs(u,fa):
T[u]=[]
size[u]=1;
f[u]=1;... | -1 | MatrixStudio/Codeforces-Python-Submissions |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,675,043,074 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 1,000 | 2,457,600 | l = int(input())
n = [*input()]
while n.count("0") > 0 and n.count("1") > 0:
for i in range(len(n)-1):
if (n[i] == "1" and n[i+1] == "0") or (n[i] == "0" and n[i+1] == "1"):
n = (n[:i] + n[i+2:]) if i+2 < len(n) else n[:i]
break
print(len(n)) | Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
l = int(input())
n = [*input()]
while n.count("0") > 0 and n.count("1") > 0:
for i in range(len(n)-1):
if (n[i] == "1" and n[i+1] == "0") or (n[i] == "0" and n[i+1] == "1"):
n = (n[:i] + n[i+2:]) if i+2 < len(n) else n[:i]
break
print(len(n))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
653 | A | Bear and Three Balls | PROGRAMMING | 900 | [
"brute force",
"implementation",
"sortings"
] | null | null | Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy:
- No two friends can get balls of the same size. - No two friends can get balls of sizes th... | The first line of the input contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of balls Limak has.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000) where *t**i* denotes the size of the *i*-th ball. | Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes). | [
"4\n18 55 16 17\n",
"6\n40 41 43 44 44 44\n",
"8\n5 972 3 4 1 4 970 971\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes 18, 16 and 17.
In the second sample, there is no way to give gifts to three friends without breaking the rules.
In the third sample, there is even more than one way to choose bal... | 500 | [
{
"input": "4\n18 55 16 17",
"output": "YES"
},
{
"input": "6\n40 41 43 44 44 44",
"output": "NO"
},
{
"input": "8\n5 972 3 4 1 4 970 971",
"output": "YES"
},
{
"input": "3\n959 747 656",
"output": "NO"
},
{
"input": "4\n1 2 2 3",
"output": "YES"
},
{
... | 1,565,885,617 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | n=int(input())
x = sorted(set(list(map(int, input().split(" ")))))
for i in range(n-2):
if x[i+2]-x[i]==0:
print("YES")
exit()
print("NO")
| Title: Bear and Three Balls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make fri... | ```python
n=int(input())
x = sorted(set(list(map(int, input().split(" ")))))
for i in range(n-2):
if x[i+2]-x[i]==0:
print("YES")
exit()
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
688 | B | Lovely Palindromes | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is trying to love them too, but only very special and gifted people can understand the beauty behind palindro... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=10100<=000). | Print the *n*-th even-length palindrome number. | [
"1\n",
"10\n"
] | [
"11\n",
"1001\n"
] | The first 10 even-length palindrome numbers are 11, 22, 33, ... , 88, 99 and 1001. | 1,000 | [
{
"input": "1",
"output": "11"
},
{
"input": "10",
"output": "1001"
},
{
"input": "11",
"output": "1111"
},
{
"input": "12",
"output": "1221"
},
{
"input": "100",
"output": "100001"
},
{
"input": "1321",
"output": "13211231"
},
{
"input": "... | 1,643,494,930 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 1,000 | 614,400 | n = input()
mirror = ''
for number in n:
mirror = f'{number}{mirror}'
print(f'{n}{mirror}') | Title: Lovely Palindromes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is tr... | ```python
n = input()
mirror = ''
for number in n:
mirror = f'{number}{mirror}'
print(f'{n}{mirror}')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
888 | B | Buggy Robot | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — mo... | The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R. | Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell. | [
"4\nLDUR\n",
"5\nRRRUU\n",
"6\nLLRRRR\n"
] | [
"4\n",
"0\n",
"4\n"
] | none | 0 | [
{
"input": "4\nLDUR",
"output": "4"
},
{
"input": "5\nRRRUU",
"output": "0"
},
{
"input": "6\nLLRRRR",
"output": "4"
},
{
"input": "88\nLLUUULRDRRURDDLURRLRDRLLRULRUUDDLLLLRRDDURDURRLDURRLDRRRUULDDLRRRDDRRLUULLURDURUDDDDDLDR",
"output": "76"
},
{
"input": "89\nLDL... | 1,579,885,951 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 140 | 0 | n=int(input())
s=input()
l,r,d,u=0,0,0,0
for i in range(n):
if s[i]=='L':
l+=1
elif s[i]=='R':
r+=1
elif s[i]=='U':
u+=1
elif s[i]=='D':
d+=1
print(2*min(l,r)+2*min(u,d)) | Title: Buggy Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the ce... | ```python
n=int(input())
s=input()
l,r,d,u=0,0,0,0
for i in range(n):
if s[i]=='L':
l+=1
elif s[i]=='R':
r+=1
elif s[i]=='U':
u+=1
elif s[i]=='D':
d+=1
print(2*min(l,r)+2*min(u,d))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
39 | D | Cubical Planet | PROGRAMMING | 1,100 | [
"math"
] | D. Cubical Planet | 2 | 64 | You can find anything whatsoever in our Galaxy! A cubical planet goes round an icosahedral star. Let us introduce a system of axes so that the edges of the cubical planet are parallel to the coordinate axes and two opposite vertices lay in the points (0,<=0,<=0) and (1,<=1,<=1). Two flies live on the planet. At the mom... | The first line contains three space-separated integers (0 or 1) — the coordinates of the first fly, the second line analogously contains the coordinates of the second fly. | Output "YES" (without quotes) if the flies see each other. Otherwise, output "NO". | [
"0 0 0\n0 1 0\n",
"1 1 0\n0 1 0\n",
"0 0 0\n1 1 1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "0 0 0\n0 1 0",
"output": "YES"
},
{
"input": "1 1 0\n0 1 0",
"output": "YES"
},
{
"input": "0 0 0\n1 1 1",
"output": "NO"
},
{
"input": "0 0 0\n1 0 0",
"output": "YES"
},
{
"input": "0 0 0\n0 1 0",
"output": "YES"
},
{
"input": "0 0 0\n1 1 ... | 1,690,362,188 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 59 | 154 | 0 | a, b, c = map(int, input().split())
a1, b1, c1 = map(int, input().split())
if a == a1 or b == b1 or c == c1:
print("YES")
else:
print("NO") | Title: Cubical Planet
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
You can find anything whatsoever in our Galaxy! A cubical planet goes round an icosahedral star. Let us introduce a system of axes so that the edges of the cubical planet are parallel to the coordinate axes and two opposite v... | ```python
a, b, c = map(int, input().split())
a1, b1, c1 = map(int, input().split())
if a == a1 or b == b1 or c == c1:
print("YES")
else:
print("NO")
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.