contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
510 | C | Fox And Names | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"sortings"
] | null | null | Fox Ciel is going to publish a paper on FOCS (Foxes Operated Computer Systems, pronounce: "Fox"). She heard a rumor: the authors list on the paper is always sorted in the lexicographical order.
After checking some examples, she found out that sometimes it wasn't true. On some papers authors' names weren't sorted in l... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100): number of names.
Each of the following *n* lines contain one string *name**i* (1<=≤<=|*name**i*|<=≤<=100), the *i*-th name. Each name contains only lowercase Latin letters. All names are different. | If there exists such order of letters that the given names are sorted lexicographically, output any such order as a permutation of characters 'a'–'z' (i. e. first output the first letter of the modified alphabet, then the second, and so on).
Otherwise output a single word "Impossible" (without quotes). | [
"3\nrivest\nshamir\nadleman\n",
"10\ntourist\npetr\nwjmzbmr\nyeputons\nvepifanov\nscottwu\noooooooooooooooo\nsubscriber\nrowdark\ntankengineer\n",
"10\npetr\negor\nendagorion\nfeferivan\nilovetanyaromanova\nkostka\ndmitriyh\nmaratsnowbear\nbredorjaguarturnik\ncgyforever\n",
"7\ncar\ncare\ncareful\ncarefully\n... | [
"bcdefghijklmnopqrsatuvwxyz\n",
"Impossible\n",
"aghjlnopefikdmbcqrstuvwxyz\n",
"acbdefhijklmnogpqrstuvwxyz\n"
] | none | 1,500 | [
{
"input": "3\nrivest\nshamir\nadleman",
"output": "bcdefghijklmnopqrsatuvwxyz"
},
{
"input": "10\ntourist\npetr\nwjmzbmr\nyeputons\nvepifanov\nscottwu\noooooooooooooooo\nsubscriber\nrowdark\ntankengineer",
"output": "Impossible"
},
{
"input": "10\npetr\negor\nendagorion\nfeferivan\nilov... | 1,675,120,887 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 93 | 3,584,000 | from math import ceil
from collections import defaultdict, deque
n = int(input())
S = []
for _ in range(n):
s = input()
S.append(s)
def idx(c):
return ord(c) - ord("a")
def solve(S, n):
adj = [[] for _ in range(26)]
nodes = set()
edges = set()
indegree = [0 for _ in range(26)]
for ... | Title: Fox And Names
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel is going to publish a paper on FOCS (Foxes Operated Computer Systems, pronounce: "Fox"). She heard a rumor: the authors list on the paper is always sorted in the lexicographical order.
After checking some examp... | ```python
from math import ceil
from collections import defaultdict, deque
n = int(input())
S = []
for _ in range(n):
s = input()
S.append(s)
def idx(c):
return ord(c) - ord("a")
def solve(S, n):
adj = [[] for _ in range(26)]
nodes = set()
edges = set()
indegree = [0 for _ in range(26)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
884 | C | Bertown Subway | PROGRAMMING | 1,500 | [
"dfs and similar",
"greedy",
"math"
] | null | null | The construction of subway in Bertown is almost finished! The President of Berland will visit this city soon to look at the new subway himself.
There are *n* stations in the subway. It was built according to the Bertown Transport Law:
1. For each station *i* there exists exactly one train that goes from this station... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100000) — the number of stations.
The second line contains *n* integer numbers *p*1, *p*2, ..., *p**n* (1<=≤<=*p**i*<=≤<=*n*) — the current structure of the subway. All these numbers are distinct. | Print one number — the maximum possible value of convenience. | [
"3\n2 1 3\n",
"5\n1 5 4 3 2\n"
] | [
"9\n",
"17\n"
] | In the first example the mayor can change *p*<sub class="lower-index">2</sub> to 3 and *p*<sub class="lower-index">3</sub> to 1, so there will be 9 pairs: (1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3).
In the second example the mayor can change *p*<sub class="lower-index">2</sub> to 4 and *p*<... | 0 | [
{
"input": "3\n2 1 3",
"output": "9"
},
{
"input": "5\n1 5 4 3 2",
"output": "17"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n1 2",
"output": "4"
},
{
"input": "2\n2 1",
"output": "4"
},
{
"input": "100\n98 52 63 2 18 96 31 58 84 40 41 45 66 ... | 1,520,383,514 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 140 | 30,924,800 |
n = int(input())
P = [int(x) - 1 for x in input().split()]
visited = [-1] * n
cc = []
for i in range(n):
if visited[i] == -1:
visited[i] = 0
amount = 1
x = P[i]
while visited[x] == -1:
visited[x] = 0
amount += 1
x = P[x]
cc += [amount]
... | Title: Bertown Subway
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The construction of subway in Bertown is almost finished! The President of Berland will visit this city soon to look at the new subway himself.
There are *n* stations in the subway. It was built according to the Bertown... | ```python
n = int(input())
P = [int(x) - 1 for x in input().split()]
visited = [-1] * n
cc = []
for i in range(n):
if visited[i] == -1:
visited[i] = 0
amount = 1
x = P[i]
while visited[x] == -1:
visited[x] = 0
amount += 1
x = P[x]
cc +=... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,690,275,431 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a= int(input())
if m %2==0 and a>2
print("yes")
else:
print("no")
| Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
a= int(input())
if m %2==0 and a>2
print("yes")
else:
print("no")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
940 | A | Points on the line | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"sortings"
] | null | null | We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1,<=3,<=2,<=1} is 2.
D... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=100,<=0<=≤<=*d*<=≤<=100) — the amount of points and the maximum allowed diameter respectively.
The second line contains *n* space separated integers (1<=≤<=*x**i*<=≤<=100) — the coordinates of the points. | Output a single integer — the minimum number of points you have to remove. | [
"3 1\n2 1 4\n",
"3 0\n7 7 7\n",
"6 3\n1 3 4 6 9 10\n"
] | [
"1\n",
"0\n",
"3\n"
] | In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal stra... | 500 | [
{
"input": "3 1\n2 1 4",
"output": "1"
},
{
"input": "3 0\n7 7 7",
"output": "0"
},
{
"input": "6 3\n1 3 4 6 9 10",
"output": "3"
},
{
"input": "11 5\n10 11 12 13 14 15 16 17 18 19 20",
"output": "5"
},
{
"input": "1 100\n1",
"output": "0"
},
{
"input"... | 1,519,840,318 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 62 | 5,632,000 | n,d=[int(i) for i in input().split()]
l=[int(i) for i in input().split()]
l.sort()
mymap={}
max=0
for i in range(n):
sol=1
x=l[i]
for j in range(n):
if j!=i and abs(x-l[j])<=d and l[j]>=x:
sol+=1
if sol>max:
max=sol
print(n-max)
| Title: Points on the line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest dista... | ```python
n,d=[int(i) for i in input().split()]
l=[int(i) for i in input().split()]
l.sort()
mymap={}
max=0
for i in range(n):
sol=1
x=l[i]
for j in range(n):
if j!=i and abs(x-l[j])<=d and l[j]>=x:
sol+=1
if sol>max:
max=sol
print(n-max)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
886 | A | ACM ICPC | PROGRAMMING | 1,000 | [
"brute force"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. ... | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 500 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,510,509,085 | 6,385 | Python 3 | WRONG_ANSWER | TESTS | 9 | 61 | 0 | l = list(map(int,input().split()))
l.sort()
s = int(sum(l) / 2)
k = len(l)//2
t = l[0]+l[len(l)-1]
fl = False
if (t+l[1]==l[2]+l[3]+l[4]):
fl = True
if t + l[2] == l[1]+l[3]+l[4]:
fl = True
if t + l[3] == l[1]+l[2]+l[4]:
fl = True
if t + l[4] == l[1]+l[3]+l[2]:
fl = True
if fl:
print(... | Title: ACM ICPC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build ... | ```python
l = list(map(int,input().split()))
l.sort()
s = int(sum(l) / 2)
k = len(l)//2
t = l[0]+l[len(l)-1]
fl = False
if (t+l[1]==l[2]+l[3]+l[4]):
fl = True
if t + l[2] == l[1]+l[3]+l[4]:
fl = True
if t + l[3] == l[1]+l[2]+l[4]:
fl = True
if t + l[4] == l[1]+l[3]+l[2]:
fl = True
if fl:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,664,024,432 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | a = input().split()
N = int(a[0])
K = int(a[1])
list = []
kord = input().split()
for i in range(N):
if int(kord[i]) + K > 5:
continue
else:
list.append(kord[i])
arv = len(list)/3
print(int(arv))
| Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
a = input().split()
N = int(a[0])
K = int(a[1])
list = []
kord = input().split()
for i in range(N):
if int(kord[i]) + K > 5:
continue
else:
list.append(kord[i])
arv = len(list)/3
print(int(arv))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,650,596,084 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 0 | m, n = map(int, input().split())
if n%2==0:
print(m*(n//2))
elif m%2==0:
print(n*(m//2))
else:
print(m*((n-1)//2)+(m-1)//2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
m, n = map(int, input().split())
if n%2==0:
print(m*(n//2))
elif m%2==0:
print(n*(m//2))
else:
print(m*((n-1)//2)+(m-1)//2)
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,694,868,190 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 1 | 61 | 2,867,200 | q=int(input())
a=set(list(map(int,input().split())))
b=set(list(map(int,input().split())))
c=set(list(map(int,input().split())))
print(list(a-b)[0])
print(list(b-c)[0]) | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
q=int(input())
a=set(list(map(int,input().split())))
b=set(list(map(int,input().split())))
c=set(list(map(int,input().split())))
print(list(a-b)[0])
print(list(b-c)[0])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,518,105,666 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 5,529,600 |
def printmatrix(matrix,N):
for i in range(N):
for j in range(N):
print(matrix[i][j], end = '')
print()
N = int(input())
matrix = [['.' for _ in range(N)] for _ in range(N)]
for i in range(N):
for j in range(N):
if j % 2 == 0 and i % 2 == 0:
ma... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
def printmatrix(matrix,N):
for i in range(N):
for j in range(N):
print(matrix[i][j], end = '')
print()
N = int(input())
matrix = [['.' for _ in range(N)] for _ in range(N)]
for i in range(N):
for j in range(N):
if j % 2 == 0 and i % 2 == 0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,604,582,416 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 109 | 0 | meat_total = 0
strategic_min_price = 100000
for _ in range(int(input())):
a,p = (int(x) for x in input().split())
if p < strategic_min_price:
strategic_min_price = p
meat_total += (a*strategic_min_price)
else:
meat_total += (a*p)
print(meat_total)
| Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
meat_total = 0
strategic_min_price = 100000
for _ in range(int(input())):
a,p = (int(x) for x in input().split())
if p < strategic_min_price:
strategic_min_price = p
meat_total += (a*strategic_min_price)
else:
meat_total += (a*p)
print(meat_total)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
633 | A | Ebony and Ivory | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
For every bullet that hits the shield, Ebony deals *a* units of damage while Ivory deals *b* units of ... | The first line of the input contains three integers *a*, *b*, *c* (1<=≤<=*a*,<=*b*<=≤<=100,<=1<=≤<=*c*<=≤<=10<=000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively. | Print "Yes" (without quotes) if Dante can deal exactly *c* damage to the shield and "No" (without quotes) otherwise. | [
"4 6 15\n",
"3 2 7\n",
"6 11 6\n"
] | [
"No\n",
"Yes\n",
"Yes\n"
] | In the second sample, Dante can fire 1 bullet from Ebony and 2 from Ivory to deal exactly 1·3 + 2·2 = 7 damage. In the third sample, Dante can fire 1 bullet from ebony and no bullets from ivory to do 1·6 + 0·11 = 6 damage. | 250 | [
{
"input": "4 6 15",
"output": "No"
},
{
"input": "3 2 7",
"output": "Yes"
},
{
"input": "6 11 6",
"output": "Yes"
},
{
"input": "3 12 15",
"output": "Yes"
},
{
"input": "5 5 10",
"output": "Yes"
},
{
"input": "6 6 7",
"output": "No"
},
{
"... | 1,530,554,829 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 127 | 124 | 0 | def strelba(a, b, c):
flag = 0
for i in range(0, c):
z = c - a * i
if z < 0:
break
if z % b == 0:
flag = 1
break
if flag:
return "YES"
return "NO"
A, B, C = [int(k) for k in input().split()]
print(strelba(A, B, C))
| Title: Ebony and Ivory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
F... | ```python
def strelba(a, b, c):
flag = 0
for i in range(0, c):
z = c - a * i
if z < 0:
break
if z % b == 0:
flag = 1
break
if flag:
return "YES"
return "NO"
A, B, C = [int(k) for k in input().split()]
print(strelba(A, B... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
127 | A | Wasted Time | PROGRAMMING | 900 | [
"geometry"
] | null | null | Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count the time he has wasted signing papers.
Mr. Scrooge's signature can be represented as a polyline ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). Each of the following *n* lines contains the coordinates of the polyline's endpoints. The *i*-th one contains coordinates of the point *A**i* — integers *x**i* and *y**i*, separated by a space.
All points *A**i* are different. Th... | Print one real number — the total time Scrooges wastes on signing the papers in seconds. The absolute or relative error should not exceed 10<=-<=6. | [
"2 1\n0 0\n10 0\n",
"5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0\n",
"6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0\n"
] | [
"0.200000000",
"6.032163204",
"3.000000000"
] | none | 500 | [
{
"input": "2 1\n0 0\n10 0",
"output": "0.200000000"
},
{
"input": "5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0",
"output": "6.032163204"
},
{
"input": "6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0",
"output": "3.000000000"
},
{
"input": "10 95\n-20 -5\n2 -8\n14 13\n10 3\n17 11\n13 -12\n-6 11\n1... | 1,683,700,187 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | n, k = map(int, input().split())
points = []
for i in range(n):
x, y = map(int, input().split())
points.append((x, y))
total_distance = 0
for i in range(1, n):
distance = ((points[i][0] - points[i-1][0])**2 + (points[i][1] - points[i-1][1])**2)**0.5
total_distance += distance
time = total... | Title: Wasted Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count ... | ```python
n, k = map(int, input().split())
points = []
for i in range(n):
x, y = map(int, input().split())
points.append((x, y))
total_distance = 0
for i in range(1, n):
distance = ((points[i][0] - points[i-1][0])**2 + (points[i][1] - points[i-1][1])**2)**0.5
total_distance += distance
ti... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,683,696,251 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 62 | 0 | #ColorfulStones
colorStone = input()
instruStone = input()
numinstr = 0
numcolor= 0
count = 0
while(numinstr < len(instruStone)):
if(instruStone[numinstr] == colorStone[numcolor]):
count +=1
numinstr +=1
numcolor+=1
else:
numinstr+=1
print(count+1) | Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
#ColorfulStones
colorStone = input()
instruStone = input()
numinstr = 0
numcolor= 0
count = 0
while(numinstr < len(instruStone)):
if(instruStone[numinstr] == colorStone[numcolor]):
count +=1
numinstr +=1
numcolor+=1
else:
numinstr+=1
print(count+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,687,805,341 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 |
import math
t = 1#int(input())
for q in range(0, t):
#l = int(input())
#n, num = map(int, input().split(' '))
l = int(input())
s = input().split(' ')
sum = 0
for i in range(0, l):
s[i] = int(s[i])
sum += s[i]
# l = len(s)
tr = 0
ch = 0
my = 0... | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
import math
t = 1#int(input())
for q in range(0, t):
#l = int(input())
#n, num = map(int, input().split(' '))
l = int(input())
s = input().split(' ')
sum = 0
for i in range(0, l):
s[i] = int(s[i])
sum += s[i]
# l = len(s)
tr = 0
ch = 0
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
877 | C | Slava and tanks | PROGRAMMING | 1,600 | [
"constructive algorithms"
] | null | null | Slava plays his favorite game "Peace Lightning". Now he is flying a bomber on a very specific map.
Formally, map is a checkered field of size 1<=×<=*n*, the cells of which are numbered from 1 to *n*, in each cell there can be one or several tanks. Slava doesn't know the number of tanks and their positions, because he ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000) — the size of the map. | In the first line print *m* — the minimum number of bombs Slava needs to destroy all tanks.
In the second line print *m* integers *k*1,<=*k*2,<=...,<=*k**m*. The number *k**i* means that the *i*-th bomb should be dropped at the cell *k**i*.
If there are multiple answers, you can print any of them. | [
"2\n",
"3\n"
] | [
"3\n2 1 2 ",
"4\n2 1 3 2 "
] | none | 1,500 | [
{
"input": "2",
"output": "3\n2 1 2 "
},
{
"input": "3",
"output": "4\n2 1 3 2 "
},
{
"input": "4",
"output": "6\n2 4 1 3 2 4 "
},
{
"input": "6",
"output": "9\n2 4 6 1 3 5 2 4 6 "
},
{
"input": "10",
"output": "15\n2 4 6 8 10 1 3 5 7 9 2 4 6 8 10 "
},
{
... | 1,593,451,187 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 155 | 20,172,800 | n = int( input() )
if n == 2:
print(3)
strs = "2 1 2"
print(strs)
elif n == 3:
print(4)
strs = "2 1 3 2"
print(strs)
else:
half = n // 2
counter = 0
ans = ""
for i in range( half ):
cur = half - i
ans += str(cur)
ans += " "
coun... | Title: Slava and tanks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Slava plays his favorite game "Peace Lightning". Now he is flying a bomber on a very specific map.
Formally, map is a checkered field of size 1<=×<=*n*, the cells of which are numbered from 1 to *n*, in each cell there... | ```python
n = int( input() )
if n == 2:
print(3)
strs = "2 1 2"
print(strs)
elif n == 3:
print(4)
strs = "2 1 3 2"
print(strs)
else:
half = n // 2
counter = 0
ans = ""
for i in range( half ):
cur = half - i
ans += str(cur)
ans += " "
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
574 | B | Bear and Three Musketeers | PROGRAMMING | 1,500 | [
"brute force",
"dfs and similar",
"graphs",
"hashing"
] | null | null | Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three brave warriors to help him to fight against bad guys.
There are *n* warriors. Richelimakieu wants to choose thre... | The first line contains two space-separated integers, *n* and *m* (3<=≤<=*n*<=≤<=4000, 0<=≤<=*m*<=≤<=4000) — respectively number of warriors and number of pairs of warriors knowing each other.
*i*-th of the following *m* lines contains two space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**... | If Richelimakieu can choose three musketeers, print the minimum possible sum of their recognitions. Otherwise, print "-1" (without the quotes). | [
"5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5\n",
"7 4\n2 1\n3 6\n5 1\n1 7\n"
] | [
"2\n",
"-1\n"
] | In the first sample Richelimakieu should choose a triple 1, 2, 3. The first musketeer doesn't know anyone except other two musketeers so his recognition is 0. The second musketeer has recognition 1 because he knows warrior number 4. The third musketeer also has recognition 1 because he knows warrior 4. Sum of recogniti... | 1,000 | [
{
"input": "5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5",
"output": "2"
},
{
"input": "7 4\n2 1\n3 6\n5 1\n1 7",
"output": "-1"
},
{
"input": "5 0",
"output": "-1"
},
{
"input": "7 14\n3 6\n2 3\n5 2\n5 6\n7 5\n7 4\n6 2\n3 5\n7 1\n4 1\n6 1\n7 6\n6 4\n5 4",
"output": "5"
},
{
... | 1,620,047,653 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 77 | 716,800 | graph = {} # {node: [idx, idx]}
def find_k3(node, parent=None, iter=0):
ret = -1
costs = []
for adj in graph[node]:
if adj != parent:
if iter == 0:
cost_next_iter = find_k3(adj, node, iter=1)
if cost_next_iter != -1:
costs.append((cos... | Title: Bear and Three Musketeers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three br... | ```python
graph = {} # {node: [idx, idx]}
def find_k3(node, parent=None, iter=0):
ret = -1
costs = []
for adj in graph[node]:
if adj != parent:
if iter == 0:
cost_next_iter = find_k3(adj, node, iter=1)
if cost_next_iter != -1:
costs.a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,644,775,455 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 122 | 409,600 | from tokenize import String
word_input = input()
no_of_upp=0
no_of_low=0
for x in word_input:
if ord(x)>=65 and ord(x)<=90:
no_of_upp +=1
else:
no_of_low+=1
if no_of_upp > no_of_low:
print(word_input.upper())
else:
print(word_input.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
from tokenize import String
word_input = input()
no_of_upp=0
no_of_low=0
for x in word_input:
if ord(x)>=65 and ord(x)<=90:
no_of_upp +=1
else:
no_of_low+=1
if no_of_upp > no_of_low:
print(word_input.upper())
else:
print(word_input.lower())
``` | 3.968737 | MatrixStudio/Codeforces-Python-Submissions |
120 | I | Luck is in Numbers | PROGRAMMING | 2,200 | [
"greedy"
] | null | null | Vasya has been collecting transport tickets for quite a while now. His collection contains several thousands of tram, trolleybus and bus tickets. Vasya is already fed up with the traditional definition of what a lucky ticket is. Thus, he's looking for new perspectives on that. Besides, Vasya cannot understand why all t... | The first line contains the number of the ticket that consists of *k* characters (*k*<==<=2*n*,<=1<=≤<=*n*<=≤<=105). | Print the number of the sought ticket or "-1" (without the quotes) if no such ticket exists. | [
"13\n",
"2345\n",
"88\n"
] | [
"20\n",
"2348\n",
"-1\n"
] | none | 0 | [
{
"input": "13",
"output": "20"
},
{
"input": "2345",
"output": "2348"
},
{
"input": "88",
"output": "-1"
},
{
"input": "682444",
"output": "682445"
},
{
"input": "685116",
"output": "685120"
},
{
"input": "576079",
"output": "576086"
},
{
... | 1,691,501,011 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1691501011.1933095")# 1691501011.1933281 | Title: Luck is in Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has been collecting transport tickets for quite a while now. His collection contains several thousands of tram, trolleybus and bus tickets. Vasya is already fed up with the traditional definition of what a luck... | ```python
print("_RANDOM_GUESS_1691501011.1933095")# 1691501011.1933281
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
808 | D | Array Division | PROGRAMMING | 1,900 | [
"binary search",
"data structures",
"implementation"
] | null | null | Vasya has an array *a* consisting of positive integer numbers. Vasya wants to divide this array into two non-empty consecutive parts (the prefix and the suffix) so that the sum of all elements in the first part equals to the sum of elements in the second part. It is not always possible, so Vasya will move some element ... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100000) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2... *a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the array. | Print YES if Vasya can divide the array after moving one element. Otherwise print NO. | [
"3\n1 3 2\n",
"5\n1 2 3 4 5\n",
"5\n2 2 3 4 5\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example Vasya can move the second element to the end of the array.
In the second example no move can make the division possible.
In the third example Vasya can move the fourth element by one position to the left. | 0 | [
{
"input": "3\n1 3 2",
"output": "YES"
},
{
"input": "5\n1 2 3 4 5",
"output": "NO"
},
{
"input": "5\n2 2 3 4 5",
"output": "YES"
},
{
"input": "5\n72 32 17 46 82",
"output": "NO"
},
{
"input": "6\n26 10 70 11 69 57",
"output": "NO"
},
{
"input": "7\n4... | 1,595,494,275 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 11 | 140 | 20,172,800 | from sys import stdin
n= int(stdin.readline())
arr = [int(x) for x in stdin.readline().split()]
s = sum(arr)
if s%2 == 1:
print('NO')
else:
goal = s//2
s = 0
e = {}
for x in arr:
if x in e:
e[x] += 1
else:
e[x] = 1
if goal in e:
... | Title: Array Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has an array *a* consisting of positive integer numbers. Vasya wants to divide this array into two non-empty consecutive parts (the prefix and the suffix) so that the sum of all elements in the first part equals to... | ```python
from sys import stdin
n= int(stdin.readline())
arr = [int(x) for x in stdin.readline().split()]
s = sum(arr)
if s%2 == 1:
print('NO')
else:
goal = s//2
s = 0
e = {}
for x in arr:
if x in e:
e[x] += 1
else:
e[x] = 1
if goa... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
779 | B | Weird Rounding | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For example, if *k*<==<=3, in the number 30020 it is enough to delete a single digit (2). In this case, t... | The only line of the input contains two integer numbers *n* and *k* (0<=≤<=*n*<=≤<=2<=000<=000<=000, 1<=≤<=*k*<=≤<=9).
It is guaranteed that the answer exists. All numbers in the input are written in traditional notation of integers, that is, without any extra leading zeros. | Print *w* — the required minimal number of digits to erase. After removing the appropriate *w* digits from the number *n*, the result should have a value that is divisible by 10*k*. The result can start with digit 0 in the single case (the result is zero and written by exactly the only digit 0). | [
"30020 3\n",
"100 9\n",
"10203049 2\n"
] | [
"1\n",
"2\n",
"3\n"
] | In the example 2 you can remove two digits: 1 and any 0. The result is number 0 which is divisible by any number. | 1,000 | [
{
"input": "30020 3",
"output": "1"
},
{
"input": "100 9",
"output": "2"
},
{
"input": "10203049 2",
"output": "3"
},
{
"input": "0 1",
"output": "0"
},
{
"input": "0 9",
"output": "0"
},
{
"input": "100 2",
"output": "0"
},
{
"input": "102... | 1,604,356,039 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 170 | 2,048,000 | from sys import maxsize, stdout, stdin, stderr
# mod = int(1e9 + 7)
import re # can use multiple splits
tup = lambda: map(int, stdin.readline().split())
I = lambda: int(stdin.readline())
lint = lambda: [int(x) for x in stdin.readline().split()]
S = lambda: stdin.readline().replace('\n', '').strip()
def grid(r, ... | Title: Weird Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For e... | ```python
from sys import maxsize, stdout, stdin, stderr
# mod = int(1e9 + 7)
import re # can use multiple splits
tup = lambda: map(int, stdin.readline().split())
I = lambda: int(stdin.readline())
lint = lambda: [int(x) for x in stdin.readline().split()]
S = lambda: stdin.readline().replace('\n', '').strip()
de... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,569,902,035 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | import math
class Solution(object):
def __init__(self):
pass
def sol(self, n):
r = int(math.floor((-1 + math.sqrt(1 + 8 * n)) / 2))
return r, [i for i in range(1, r + 1)]
def main():
n = int(input())
sol = Solution()
r = sol.sol(n)
print(r[0])
print(' '.join(map(la... | Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
import math
class Solution(object):
def __init__(self):
pass
def sol(self, n):
r = int(math.floor((-1 + math.sqrt(1 + 8 * n)) / 2))
return r, [i for i in range(1, r + 1)]
def main():
n = int(input())
sol = Solution()
r = sol.sol(n)
print(r[0])
print(' '.j... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,687,707,042 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 85 | 186 | 0 | s=input()
if(s.find('H')!=-1 or s.find('Q')!=-1 or s.find('9')!=-1):
print("YES")
else:
print("NO")
| Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
s=input()
if(s.find('H')!=-1 or s.find('Q')!=-1 or s.find('9')!=-1):
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
928 | A | Login Verification | PROGRAMMING | 1,200 | [
"*special",
"strings"
] | null | null | When registering in a social network, users are allowed to create their own convenient login to make it easier to share contacts, print it on business cards, etc.
Login is an arbitrary sequence of lower and uppercase latin letters, digits and underline symbols («_»). However, in order to decrease the number of frauds ... | The first line contains a non-empty string *s* consisting of lower and uppercase latin letters, digits and underline symbols («_») with length not exceeding 50 — the login itself.
The second line contains a single integer *n* (1<=≤<=*n*<=≤<=1<=000) — the number of existing logins.
The next *n* lines describe the exi... | Print «Yes» (without quotes), if user can register via this login, i.e. none of the existing logins is similar with it.
Otherwise print «No» (without quotes). | [
"1_wat\n2\n2_wat\nwat_1\n",
"000\n3\n00\nooA\noOo\n",
"_i_\n3\n__i_\n_1_\nI\n",
"La0\n3\n2a0\nLa1\n1a0\n",
"abc\n1\naBc\n",
"0Lil\n2\nLIL0\n0Ril\n"
] | [
"Yes\n",
"No\n",
"No\n",
"No\n",
"No\n",
"Yes\n"
] | In the second sample case the user wants to create a login consisting of three zeros. It's impossible due to collision with the third among the existing.
In the third sample case the new login is similar with the second one. | 500 | [
{
"input": "1_wat\n2\n2_wat\nwat_1",
"output": "Yes"
},
{
"input": "000\n3\n00\nooA\noOo",
"output": "No"
},
{
"input": "_i_\n3\n__i_\n_1_\nI",
"output": "No"
},
{
"input": "La0\n3\n2a0\nLa1\n1a0",
"output": "No"
},
{
"input": "abc\n1\naBc",
"output": "No"
}... | 1,587,198,525 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<stdio.h>
int main()
{
int a[50],i,n,x,y,sum=0,large,small;
printf("\nEnter the number of elements : ");
scanf("%d",&n);
printf("\nInput the array elements : ");
for(i=0;i<n;++i)
scanf("%d",&a[i]);
for(i=0; i<n; i++)
{
if (i%2==0)
{sum = sum + a[i];}
}
printf("%d",sum);
return 0;
} | Title: Login Verification
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When registering in a social network, users are allowed to create their own convenient login to make it easier to share contacts, print it on business cards, etc.
Login is an arbitrary sequence of lower and uppercas... | ```python
#include<stdio.h>
int main()
{
int a[50],i,n,x,y,sum=0,large,small;
printf("\nEnter the number of elements : ");
scanf("%d",&n);
printf("\nInput the array elements : ");
for(i=0;i<n;++i)
scanf("%d",&a[i]);
for(i=0; i<n; i++)
{
if (i%2==0)
{sum = sum + a[i];}
}
printf("%d",sum);
return 0;
}
`... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
979 | A | Pizza, Pizza, Pizza!!! | PROGRAMMING | 1,000 | [
"math"
] | null | null | Katie, Kuro and Shiro are best friends. They have known each other since kindergarten. That's why they often share everything with each other and work together on some very hard problems.
Today is Shiro's birthday. She really loves pizza so she wants to invite her friends to the pizza restaurant near her house to cele... | A single line contains one non-negative integer $n$ ($0 \le n \leq 10^{18}$) — the number of Shiro's friends. The circular pizza has to be sliced into $n + 1$ pieces. | A single integer — the number of straight cuts Shiro needs. | [
"3\n",
"4\n"
] | [
"2",
"5"
] | To cut the round pizza into quarters one has to make two cuts through the center with angle $90^{\circ}$ between them.
To cut the round pizza into five equal parts one has to make five cuts. | 500 | [
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "5"
},
{
"input": "10",
"output": "11"
},
{
"input": "10000000000",
"output": "10000000001"
},
{
"input": "1234567891",
"output": "617283946"
},
{
"input": "7509213957",
"output": "37546069... | 1,582,079,138 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 109 | 0 | n = int(input(""))
if n == 0: print(0)
elif n%2 ==0: print(n+1)
else: print(int((n+1)/2))
| Title: Pizza, Pizza, Pizza!!!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Katie, Kuro and Shiro are best friends. They have known each other since kindergarten. That's why they often share everything with each other and work together on some very hard problems.
Today is Shiro's birthd... | ```python
n = int(input(""))
if n == 0: print(0)
elif n%2 ==0: print(n+1)
else: print(int((n+1)/2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
446 | A | DZY Loves Sequences | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"two pointers"
] | null | null | DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | In a single line print the answer to the problem — the maximum length of the required subsegment. | [
"6\n7 2 3 1 5 6\n"
] | [
"5\n"
] | You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | 500 | [
{
"input": "6\n7 2 3 1 5 6",
"output": "5"
},
{
"input": "10\n424238336 649760493 681692778 714636916 719885387 804289384 846930887 957747794 596516650 189641422",
"output": "9"
},
{
"input": "50\n804289384 846930887 681692778 714636916 957747794 424238336 719885387 649760493 596516650 1... | 1,601,010,654 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 77 | 307,200 | n=int(input())
arr=list(map(int,input().split()))
l=[1 for i in range(n)]
m=[1 for i in range(n)]
for i in range(n):
if i != n-1:
if arr[i+1]>arr[i]:
l[i+1]+=l[i]
for i in range(n-2,-1,-1):
if arr[i+1]>arr[i]:
m[i]+=m[i+1]
max1=max(l)
for i in range(n-2):
if arr[i+2]... | Title: DZY Loves Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the... | ```python
n=int(input())
arr=list(map(int,input().split()))
l=[1 for i in range(n)]
m=[1 for i in range(n)]
for i in range(n):
if i != n-1:
if arr[i+1]>arr[i]:
l[i+1]+=l[i]
for i in range(n-2,-1,-1):
if arr[i+1]>arr[i]:
m[i]+=m[i+1]
max1=max(l)
for i in range(n-2):
i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,694,678,574 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | friends = input('')
height = input('')
road=0
for friend in friends:
width=1
length=input('')
if length > height:
width=2
road+=width
print(road) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
friends = input('')
height = input('')
road=0
for friend in friends:
width=1
length=input('')
if length > height:
width=2
road+=width
print(road)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,607,152,576 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 5,734,400 | a,b,n = map(int, input().split())
for i in range(n):
a *= 10
di = False
for j in range(10):
if (a+j) % b == 0:
di = True; a+=j;break
if not di: print(-1);exit()
print(a)
| Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
a,b,n = map(int, input().split())
for i in range(n):
a *= 10
di = False
for j in range(10):
if (a+j) % b == 0:
di = True; a+=j;break
if not di: print(-1);exit()
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
584 | D | Dima and Lisa | PROGRAMMING | 1,800 | [
"brute force",
"math",
"number theory"
] | null | null | Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes.
More formally, you are given an odd numer *n*. Find a set of numbers *p**i* (1<=≤<=*i*<=≤<=*k*), such that
1. 1<=... | The single line contains an odd number *n* (3<=≤<=*n*<=<<=109). | In the first line print *k* (1<=≤<=*k*<=≤<=3), showing how many numbers are in the representation you found.
In the second line print numbers *p**i* in any order. If there are multiple possible solutions, you can print any of them. | [
"27\n"
] | [
"3\n5 11 11\n"
] | A prime is an integer strictly larger than one that is divisible only by one and by itself. | 2,000 | [
{
"input": "27",
"output": "3\n2 2 23"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "25",
"output": "2\n2 23"
},
{
"input": "9",
"output": "2\n2 7"
},
{
"input": "91",
"output": "2\n2 89"
},
{
"input": "57",
"output": "3\n2 2 53"
},
{
... | 1,689,343,116 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | print("_RANDOM_GUESS_1689343116.331787")# 1689343116.331794 | Title: Dima and Lisa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes.
More formally, ... | ```python
print("_RANDOM_GUESS_1689343116.331787")# 1689343116.331794
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,579,781,913 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 248 | 0 | n = int(input())
a = list(map(int,input().split()))
a.sort()
cur = a[0]
t = 1
mx = -1
curnum = 1
for i in range(1,n):
if a[i] == cur:
curnum += 1
else:
t += 1
cur = a[i]
if curnum > mx:
mx = curnum
curnum = 1
print(mx,t) | Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
n = int(input())
a = list(map(int,input().split()))
a.sort()
cur = a[0]
t = 1
mx = -1
curnum = 1
for i in range(1,n):
if a[i] == cur:
curnum += 1
else:
t += 1
cur = a[i]
if curnum > mx:
mx = curnum
curnum = 1
print(mx,t)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
855 | A | Tom Riddle's Diary | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they ... | First line of input contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of names in the list.
Next *n* lines each contain a string *s**i*, consisting of lowercase English letters. The length of each string is between 1 and 100. | Output *n* lines each containing either "YES" or "NO" (without quotes), depending on whether this string was already present in the stream or not.
You can print each letter in any case (upper or lower). | [
"6\ntom\nlucius\nginny\nharry\nginny\nharry\n",
"3\na\na\na\n"
] | [
"NO\nNO\nNO\nNO\nYES\nYES\n",
"NO\nYES\nYES\n"
] | In test case 1, for *i* = 5 there exists *j* = 3 such that *s*<sub class="lower-index">*i*</sub> = *s*<sub class="lower-index">*j*</sub> and *j* < *i*, which means that answer for *i* = 5 is "YES". | 500 | [
{
"input": "6\ntom\nlucius\nginny\nharry\nginny\nharry",
"output": "NO\nNO\nNO\nNO\nYES\nYES"
},
{
"input": "3\na\na\na",
"output": "NO\nYES\nYES"
},
{
"input": "1\nzn",
"output": "NO"
},
{
"input": "9\nliyzmbjwnzryjokufuxcqtzwworjeoxkbaqrujrhdidqdvwdfzilwszgnzglnnbogaclckfnb... | 1,672,207,454 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 46 | 0 | def tomRiddleDiary(s):
if s in a:
return "YES"
else:
return "NO"
a = set()
t = int(input())
while t > 0:
s = input()
print(tomRiddleDiary(s))
t = t - 1
a.add(s)
| Title: Tom Riddle's Diary
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber ... | ```python
def tomRiddleDiary(s):
if s in a:
return "YES"
else:
return "NO"
a = set()
t = int(input())
while t > 0:
s = input()
print(tomRiddleDiary(s))
t = t - 1
a.add(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,658,298,221 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 46 | 0 | n, p, q = map(int, input().split())
s = input()
i = 0
while n > 0:
if n % q == 0:
j = n // q
break
i += 1
n -= p
else:
print(-1)
exit()
print(i + j)
k = 0
for _ in range(i):
print(s[k : k + p])
k += p
for _ in range(j):
print(s[k : k + q])
k += q
| Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n, p, q = map(int, input().split())
s = input()
i = 0
while n > 0:
if n % q == 0:
j = n // q
break
i += 1
n -= p
else:
print(-1)
exit()
print(i + j)
k = 0
for _ in range(i):
print(s[k : k + p])
k += p
for _ in range(j):
print(s[k : k + q])
k += q
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,622,654,411 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 622 | 9,625,600 | from fractions import Fraction
y,w=[int(i) for i in input().split()]
x=max(y,w)
if (7-x)//6==1:
print('1')
else:
print(Fraction(7-x,6)) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
from fractions import Fraction
y,w=[int(i) for i in input().split()]
x=max(y,w)
if (7-x)//6==1:
print('1')
else:
print(Fraction(7-x,6))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
17 | A | Noldbach problem | PROGRAMMING | 1,000 | [
"brute force",
"math",
"number theory"
] | A. Noldbach problem | 2 | 64 | Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a problem of his own and call it Noldbach problem. Since Nick is interested only in prime numbers, Nold... | The first line of the input contains two integers *n* (2<=≤<=*n*<=≤<=1000) and *k* (0<=≤<=*k*<=≤<=1000). | Output YES if at least *k* prime numbers from 2 to *n* inclusively can be expressed as it was described above. Otherwise output NO. | [
"27 2\n",
"45 7\n"
] | [
"YES",
"NO"
] | In the first sample the answer is YES since at least two numbers can be expressed as it was described (for example, 13 and 19). In the second sample the answer is NO since it is impossible to express 7 prime numbers from 2 to 45 in the desired form. | 0 | [
{
"input": "27 2",
"output": "YES"
},
{
"input": "45 7",
"output": "NO"
},
{
"input": "2 0",
"output": "YES"
},
{
"input": "15 1",
"output": "YES"
},
{
"input": "17 1",
"output": "YES"
},
{
"input": "34 5",
"output": "NO"
},
{
"input": "37 ... | 1,646,428,846 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 2 | 186 | 10,854,400 | from math import sqrt
arr = [int(item) for item in input().split()]
parr = []
def isPrime(n):
if (n <= 0):
return
else:
for i in range(2, int(sqrt(n)) +1):
if (n % i == 0):
return False
else:
return True
for i in range(2, arr[0]... | Title: Noldbach problem
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a prob... | ```python
from math import sqrt
arr = [int(item) for item in input().split()]
parr = []
def isPrime(n):
if (n <= 0):
return
else:
for i in range(2, int(sqrt(n)) +1):
if (n % i == 0):
return False
else:
return True
for i in range... | -1 | MatrixStudio/Codeforces-Python-Submissions |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,616,928,079 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 307,200 | n=int(input())
l=list(map(int,input().split()))
for i in range(len(l)):
if l[(l[(l[i]-1)]-1)]==i+1:
print("YES")
break
else:
print("NO")
break | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
n=int(input())
l=list(map(int,input().split()))
for i in range(len(l)):
if l[(l[(l[i]-1)]-1)]==i+1:
print("YES")
break
else:
print("NO")
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
342 | A | Xenia and Divisors | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,<=*b*,<=*c* the following conditions held:
- *a*<=<<=*b*<=<<=*c*; - *a* divides *b*, *b* divide... | The first line contains integer *n* (3<=≤<=*n*<=≤<=99999) — the number of elements in the sequence. The next line contains *n* positive integers, each of them is at most 7.
It is guaranteed that *n* is divisible by 3. | If the required partition exists, print groups of three. Print each group as values of the elements it contains. You should print values in increasing order. Separate the groups and integers in groups by whitespaces. If there are multiple solutions, you can print any of them.
If there is no solution, print -1. | [
"6\n1 1 1 2 2 2\n",
"6\n2 2 1 1 4 6\n"
] | [
"-1\n",
"1 2 4\n1 2 6\n"
] | none | 500 | [
{
"input": "6\n1 1 1 2 2 2",
"output": "-1"
},
{
"input": "6\n2 2 1 1 4 6",
"output": "1 2 4\n1 2 6"
},
{
"input": "3\n1 2 3",
"output": "-1"
},
{
"input": "3\n7 5 7",
"output": "-1"
},
{
"input": "3\n1 3 4",
"output": "-1"
},
{
"input": "3\n1 1 1",
... | 1,417,265,918 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 15 | 61 | 0 | import sys
import math
from _collections import deque
n = int(sys.stdin.readline())
an = [int(x) for x in (sys.stdin.readline()).split()]
ar = [0] * 8
for i in range(n):
ar[an[i]] += 1
t = int(n / 3)
c = 0
d = []
for i in range(t):
if(ar[2] > 0 and ar[4] > 0):
ar[2] -= 1
... | Title: Xenia and Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,... | ```python
import sys
import math
from _collections import deque
n = int(sys.stdin.readline())
an = [int(x) for x in (sys.stdin.readline()).split()]
ar = [0] * 8
for i in range(n):
ar[an[i]] += 1
t = int(n / 3)
c = 0
d = []
for i in range(t):
if(ar[2] > 0 and ar[4] > 0):
ar[2] ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
845 | B | Luba And The Ticket | PROGRAMMING | 1,600 | [
"brute force",
"greedy",
"implementation"
] | null | null | Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make the ticket lucky.
The ticket is considered lucky if the sum of first three digits equals to the sum of las... | You are given a string consisting of 6 characters (all characters are digits from 0 to 9) — this string denotes Luba's ticket. The ticket can start with the digit 0. | Print one number — the minimum possible number of digits Luba needs to replace to make the ticket lucky. | [
"000000\n",
"123456\n",
"111000\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first example the ticket is already lucky, so the answer is 0.
In the second example Luba can replace 4 and 5 with zeroes, and the ticket will become lucky. It's easy to see that at least two replacements are required.
In the third example Luba can replace any zero with 3. It's easy to see that at least one re... | 0 | [
{
"input": "000000",
"output": "0"
},
{
"input": "123456",
"output": "2"
},
{
"input": "111000",
"output": "1"
},
{
"input": "120111",
"output": "0"
},
{
"input": "999999",
"output": "0"
},
{
"input": "199880",
"output": "1"
},
{
"input": "... | 1,513,762,724 | 2,147,483,647 | Python 3 | OK | TESTS | 145 | 62 | 5,529,600 | a=list(str(input()))
a=[int(i) for i in a]
one=a[:3]
two=a[3:]
o=sum(one)
t=sum(two)
one.sort()
two.sort()
s=0
c=[]
if o==t:
s=0
elif o>t:
b=o-t
c.append(one[0])
c.append(one[1])
c.append(one[2])
c.append(9-two[0])
c.append(9-two[1])
c.append(9-two[2])
c.sort()
... | Title: Luba And The Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make th... | ```python
a=list(str(input()))
a=[int(i) for i in a]
one=a[:3]
two=a[3:]
o=sum(one)
t=sum(two)
one.sort()
two.sort()
s=0
c=[]
if o==t:
s=0
elif o>t:
b=o-t
c.append(one[0])
c.append(one[1])
c.append(one[2])
c.append(9-two[0])
c.append(9-two[1])
c.append(9-two[2])
c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,658,406,747 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 6 | 1,278 | 44,851,200 | s=0
def summ(n):
global s
if n==0:
return s
s+=n%10
return summ(n//10)
a=int(input())
c=0
while True:
s=0
if a//10==0:
print(c)
break
a=summ(a)
c+=1 | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
s=0
def summ(n):
global s
if n==0:
return s
s+=n%10
return summ(n//10)
a=int(input())
c=0
while True:
s=0
if a//10==0:
print(c)
break
a=summ(a)
c+=1
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
222 | A | Shooshuns and Sequence | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current ... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. | Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. | [
"3 2\n3 1 1\n",
"3 1\n3 1 1\n"
] | [
"1\n",
"-1\n"
] | In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1.... | 500 | [
{
"input": "3 2\n3 1 1",
"output": "1"
},
{
"input": "3 1\n3 1 1",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 1\n2 1",
"output": "-1"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
}... | 1,694,094,358 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 10,547,200 | n,k=map(int,input().split())
l=list(map(int,input().split()))
v = len(l) - 1
i=0
flag=False
while i < n :
er=set(l)
if len(er) == 1:
print(i)
flag = True
break
p=l[(k-1)]
del l[0]
l.append(p)
i+=1
if flag == False :
print(-1) | Title: Shooshuns and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the cur... | ```python
n,k=map(int,input().split())
l=list(map(int,input().split()))
v = len(l) - 1
i=0
flag=False
while i < n :
er=set(l)
if len(er) == 1:
print(i)
flag = True
break
p=l[(k-1)]
del l[0]
l.append(p)
i+=1
if flag == False :
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
387 | A | George and Sleep | PROGRAMMING | 900 | [
"implementation"
] | null | null | George woke up and saw the current time *s* on the digital clock. Besides, George knows that he has slept for time *t*.
Help George! Write a program that will, given time *s* and *t*, determine the time *p* when George went to bed. Note that George could have gone to bed yesterday relatively to the current time (see ... | The first line contains current time *s* as a string in the format "hh:mm". The second line contains time *t* in the format "hh:mm" — the duration of George's sleep. It is guaranteed that the input contains the correct time in the 24-hour format, that is, 00<=≤<=*hh*<=≤<=23, 00<=≤<=*mm*<=≤<=59. | In the single line print time *p* — the time George went to bed in the format similar to the format of the time in the input. | [
"05:50\n05:44\n",
"00:00\n01:00\n",
"00:01\n00:00\n"
] | [
"00:06\n",
"23:00\n",
"00:01\n"
] | In the first sample George went to bed at "00:06". Note that you should print the time only in the format "00:06". That's why answers "0:06", "00:6" and others will be considered incorrect.
In the second sample, George went to bed yesterday.
In the third sample, George didn't do to bed at all. | 500 | [
{
"input": "05:50\n05:44",
"output": "00:06"
},
{
"input": "00:00\n01:00",
"output": "23:00"
},
{
"input": "00:01\n00:00",
"output": "00:01"
},
{
"input": "23:59\n23:59",
"output": "00:00"
},
{
"input": "23:44\n23:55",
"output": "23:49"
},
{
"input": "... | 1,581,538,934 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 108 | 307,200 | s = input().split(":")
t = input().split(":")
start = int(s[0])*60 + int(s[1])
time = int(t[0])*60 + int(t[1])
ans = start - time
if ans < 0:
ans = 24*60 + ans
hours = ans // 60
minutes = ans % 60
if hours < 10:
print("0{}:".format(hours), end="")
else:
print("{}:".format(hours), end="")
if minutes < 10:
prin... | Title: George and Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George woke up and saw the current time *s* on the digital clock. Besides, George knows that he has slept for time *t*.
Help George! Write a program that will, given time *s* and *t*, determine the time *p* when Geor... | ```python
s = input().split(":")
t = input().split(":")
start = int(s[0])*60 + int(s[1])
time = int(t[0])*60 + int(t[1])
ans = start - time
if ans < 0:
ans = 24*60 + ans
hours = ans // 60
minutes = ans % 60
if hours < 10:
print("0{}:".format(hours), end="")
else:
print("{}:".format(hours), end="")
if minutes <... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
868 | A | Bark to Unlock | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's p... | The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of words Kashtanka knows.
The next *n* lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to b... | Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"ya\n4\nah\noy\nto\nha\n",
"hp\n2\nht\ntp\n",
"ah\n1\nha\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" produ... | 250 | [
{
"input": "ya\n4\nah\noy\nto\nha",
"output": "YES"
},
{
"input": "hp\n2\nht\ntp",
"output": "NO"
},
{
"input": "ah\n1\nha",
"output": "YES"
},
{
"input": "bb\n4\nba\nab\naa\nbb",
"output": "YES"
},
{
"input": "bc\n4\nca\nba\nbb\ncc",
"output": "YES"
},
{
... | 1,593,195,935 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 14 | 139 | 20,172,800 | s = input()
n = int(input())
ans = []
l = []
for i in range(n):
x = input()
l.append(x)
for i in l :
if i[0] == s[1] :
ans.append(i[0])
if i[1] == s[0]:
ans.append(i[1])
if len(ans) == 2 :
break
if len(ans) == 0 :
print('NO')
else:
print('YES'... | Title: Bark to Unlock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a passw... | ```python
s = input()
n = int(input())
ans = []
l = []
for i in range(n):
x = input()
l.append(x)
for i in l :
if i[0] == s[1] :
ans.append(i[0])
if i[1] == s[0]:
ans.append(i[1])
if len(ans) == 2 :
break
if len(ans) == 0 :
print('NO')
else:
p... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
727 | A | Transformation: from A to B | PROGRAMMING | 1,000 | [
"brute force",
"dfs and similar",
"math"
] | null | null | Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - append the digit 1 to the right of current number (that is, replace the number *x* by 10·*x*<=+<=1).
You need to he... | The first line contains two positive integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=109) — the number which Vasily has and the number he wants to have. | If there is no way to get *b* from *a*, print "NO" (without quotes).
Otherwise print three lines. On the first line print "YES" (without quotes). The second line should contain single integer *k* — the length of the transformation sequence. On the third line print the sequence of transformations *x*1,<=*x*2,<=...,<=*x... | [
"2 162\n",
"4 42\n",
"100 40021\n"
] | [
"YES\n5\n2 4 8 81 162 \n",
"NO\n",
"YES\n5\n100 200 2001 4002 40021 \n"
] | none | 1,000 | [
{
"input": "2 162",
"output": "YES\n5\n2 4 8 81 162 "
},
{
"input": "4 42",
"output": "NO"
},
{
"input": "100 40021",
"output": "YES\n5\n100 200 2001 4002 40021 "
},
{
"input": "1 111111111",
"output": "YES\n9\n1 11 111 1111 11111 111111 1111111 11111111 111111111 "
},
... | 1,632,263,793 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 62 | 6,963,200 | a,b=map(int,input().split())
c=10
x=[b]
while a<b:
if (1>1&b):
b>>=1
elif (2>b%c):
b//=c
else:
break
x.append(b)
if (a!=b):
print('NO')
else:
print('YES')
print(len(x))
print(*reversed(x)) | Title: Transformation: from A to B
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - app... | ```python
a,b=map(int,input().split())
c=10
x=[b]
while a<b:
if (1>1&b):
b>>=1
elif (2>b%c):
b//=c
else:
break
x.append(b)
if (a!=b):
print('NO')
else:
print('YES')
print(len(x))
print(*reversed(x))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
959 | A | Mahmoud and Ehab and the even-odd game | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab'... | The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game. | Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise. | [
"1\n",
"2\n"
] | [
"Ehab",
"Mahmoud"
] | In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mah... | 500 | [
{
"input": "1",
"output": "Ehab"
},
{
"input": "2",
"output": "Mahmoud"
},
{
"input": "10000",
"output": "Mahmoud"
},
{
"input": "33333",
"output": "Ehab"
},
{
"input": "5",
"output": "Ehab"
},
{
"input": "1000000000",
"output": "Mahmoud"
},
{
... | 1,684,179,814 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | smb=int(input())
if smb&1==0:
print('Mahmoud')
else:
print('Ehab')
print(turns) | Title: Mahmoud and Ehab and the even-odd game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a*... | ```python
smb=int(input())
if smb&1==0:
print('Mahmoud')
else:
print('Ehab')
print(turns)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
569 | A | Music | PROGRAMMING | 1,500 | [
"implementation",
"math"
] | null | null | Little Lesha loves listening to music via his smartphone. But the smartphone doesn't have much memory, so Lesha listens to his favorite songs in a well-known social network InTalk.
Unfortunately, internet is not that fast in the city of Ekaterinozavodsk and the song takes a lot of time to download. But Lesha is quite ... | The single line contains three integers *T*,<=*S*,<=*q* (2<=≤<=*q*<=≤<=104, 1<=≤<=*S*<=<<=*T*<=≤<=105). | Print a single integer — the number of times the song will be restarted. | [
"5 2 2\n",
"5 4 7\n",
"6 2 3\n"
] | [
"2\n",
"1\n",
"1\n"
] | In the first test, the song is played twice faster than it is downloaded, which means that during four first seconds Lesha reaches the moment that has not been downloaded, and starts the song again. After another two seconds, the song is downloaded completely, and thus, Lesha starts the song twice.
In the second test,... | 500 | [
{
"input": "5 2 2",
"output": "2"
},
{
"input": "5 4 7",
"output": "1"
},
{
"input": "6 2 3",
"output": "1"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "2 1 3",
"output": "1"
},
{
"input": "2 1 10000",
"output": "1"
},
{
"input": "12... | 1,699,764,391 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 78 | 131,891,200 | import sys
from bisect import bisect, insort
from collections import Counter, OrderedDict, defaultdict, deque
from functools import cache, lru_cache, reduce
from heapq import heapify, heappop, heappush, nlargest
from itertools import accumulate, combinations, permutations, product, repeat
from math import ceil, f... | Title: Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Lesha loves listening to music via his smartphone. But the smartphone doesn't have much memory, so Lesha listens to his favorite songs in a well-known social network InTalk.
Unfortunately, internet is not that fast in the... | ```python
import sys
from bisect import bisect, insort
from collections import Counter, OrderedDict, defaultdict, deque
from functools import cache, lru_cache, reduce
from heapq import heapify, heappop, heappush, nlargest
from itertools import accumulate, combinations, permutations, product, repeat
from math impo... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
485 | B | Valuable Resources | PROGRAMMING | 1,300 | [
"brute force",
"greedy"
] | null | null | Many computer strategy games require building cities, recruiting army, conquering tribes, collecting resources. Sometimes it leads to interesting problems.
Let's suppose that your task is to build a square city. The world map uses the Cartesian coordinates. The sides of the city should be parallel to coordinate axes.... | The first line of the input contains number *n* — the number of mines on the map (2<=≤<=*n*<=≤<=1000). Each of the next *n* lines contains a pair of integers *x**i* and *y**i* — the coordinates of the corresponding mine (<=-<=109<=≤<=*x**i*,<=*y**i*<=≤<=109). All points are pairwise distinct. | Print the minimum area of the city that can cover all the mines with valuable resources. | [
"2\n0 0\n2 2\n",
"2\n0 0\n0 3\n"
] | [
"4\n",
"9\n"
] | none | 500 | [
{
"input": "2\n0 0\n2 2",
"output": "4"
},
{
"input": "2\n0 0\n0 3",
"output": "9"
},
{
"input": "2\n0 1\n1 0",
"output": "1"
},
{
"input": "3\n2 2\n1 1\n3 3",
"output": "4"
},
{
"input": "3\n3 1\n1 3\n2 2",
"output": "4"
},
{
"input": "3\n0 1\n1 0\n2 ... | 1,620,644,760 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 6,758,400 | n=int(input())
m=0
for i in range(n):
x,y = map(int, input().strip().split(' '))
if x>m*m:
m=x
if y>m*m:
m=y
print(m**2) | Title: Valuable Resources
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Many computer strategy games require building cities, recruiting army, conquering tribes, collecting resources. Sometimes it leads to interesting problems.
Let's suppose that your task is to build a square city. Th... | ```python
n=int(input())
m=0
for i in range(n):
x,y = map(int, input().strip().split(' '))
if x>m*m:
m=x
if y>m*m:
m=y
print(m**2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
221 | A | Little Elephant and Function | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works... | A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation. | In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists. | [
"1\n",
"2\n"
] | [
"1 ",
"2 1 "
] | none | 500 | [
{
"input": "1",
"output": "1 "
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "3 1 2 "
},
{
"input": "4",
"output": "4 1 2 3 "
},
{
"input": "5",
"output": "5 1 2 3 4 "
},
{
"input": "6",
"output": "6 1 2 3 4 5 "
},
{
"inp... | 1,529,688,800 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | n = int(input())
a = [i for i in range(n+1)]
def f(x):
if x == 1:
return
else:
f(x-1)
a[x], a[x-1] = a[x-1], a[x]
# print(f(n))
f(n)
print(a[1:]) | Title: Little Elephant and Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the perm... | ```python
n = int(input())
a = [i for i in range(n+1)]
def f(x):
if x == 1:
return
else:
f(x-1)
a[x], a[x-1] = a[x-1], a[x]
# print(f(n))
f(n)
print(a[1:])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
189 | A | Cut Ribbon | PROGRAMMING | 1,300 | [
"brute force",
"dp"
] | null | null | Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon piece... | The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide. | Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists. | [
"5 5 3 2\n",
"7 5 5 2\n"
] | [
"2\n",
"2\n"
] | In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | 500 | [
{
"input": "5 5 3 2",
"output": "2"
},
{
"input": "7 5 5 2",
"output": "2"
},
{
"input": "4 4 4 4",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "4000 1 2 3",
"output": "4000"
},
{
"input": "4000 3 4 5",
"output": "1333"
},
... | 1,695,827,273 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | SIZE = 4010
ar = [0] * 10
dp = [[-1] * SIZE for _ in range(4)]
n = 0
def Function(pos, taken, cnt):
if pos >= 3:
if taken == n:
return cnt
else:
return 0
if taken == n:
return cnt
if dp[pos][taken] != -1:
return dp[pos][taken]
... | Title: Cut Ribbon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the... | ```python
SIZE = 4010
ar = [0] * 10
dp = [[-1] * SIZE for _ in range(4)]
n = 0
def Function(pos, taken, cnt):
if pos >= 3:
if taken == n:
return cnt
else:
return 0
if taken == n:
return cnt
if dp[pos][taken] != -1:
return dp[pos][tak... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,650,386,838 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 154 | 0 | worda = input()[::-1]
wordb = input()
if worda == wordb:
print("YES")
else:
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
worda = input()[::-1]
wordb = input()
if worda == wordb:
print("YES")
else:
print("NO")
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,641,821,336 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 186 | 0 | s=str(input(""))
t=str(input(""))
result="NO"
if(t[-1::-1]==s):
result="YES"
print(result) | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
s=str(input(""))
t=str(input(""))
result="NO"
if(t[-1::-1]==s):
result="YES"
print(result)
``` | 3.9535 | MatrixStudio/Codeforces-Python-Submissions |
108 | A | Palindromic Times | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | A. Palindromic Times | 2 | 256 | Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling asleep, he was staring at the digital watch around Saher's wrist. He noticed that the digits on th... | The first and only line of the input starts with a string with the format "HH:MM" where "HH" is from "00" to "23" and "MM" is from "00" to "59". Both "HH" and "MM" have exactly two digits. | Print the palindromic time of day that comes soonest after the time given in the input. If the input time is palindromic, output the soonest palindromic time after the input time. | [
"12:21\n",
"23:59\n"
] | [
"13:31\n",
"00:00\n"
] | none | 500 | [
{
"input": "12:21",
"output": "13:31"
},
{
"input": "23:59",
"output": "00:00"
},
{
"input": "15:51",
"output": "20:02"
},
{
"input": "10:44",
"output": "11:11"
},
{
"input": "04:02",
"output": "04:40"
},
{
"input": "02:11",
"output": "02:20"
},
... | 1,433,322,945 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | s=input()
h=int(s[:2])
m=int(s[3:])
mm=int(s[4]+s[3])
if m<=mm:
print(str(h)+':'+str(mm))
else:
h=(h+1)%24;
if(h<10):
h='0'+str(h)
print(h+':'+h[1]+h[0])
| Title: Palindromic Times
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling... | ```python
s=input()
h=int(s[:2])
m=int(s[3:])
mm=int(s[4]+s[3])
if m<=mm:
print(str(h)+':'+str(mm))
else:
h=(h+1)%24;
if(h<10):
h='0'+str(h)
print(h+':'+h[1]+h[0])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
165 | B | Burning Midnight Oil | PROGRAMMING | 1,500 | [
"binary search",
"implementation"
] | null | null | One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of code, drinks a cup of tea, then he writes as much as lines, drinks another cup of tea, then he writes lin... | The input consists of two integers *n* and *k*, separated by spaces — the size of the program in lines and the productivity reduction coefficient, 1<=≤<=*n*<=≤<=109, 2<=≤<=*k*<=≤<=10. | Print the only integer — the minimum value of *v* that lets Vasya write the program in one night. | [
"7 2\n",
"59 9\n"
] | [
"4\n",
"54\n"
] | In the first sample the answer is *v* = 4. Vasya writes the code in the following portions: first 4 lines, then 2, then 1, and then Vasya falls asleep. Thus, he manages to write 4 + 2 + 1 = 7 lines in a night and complete the task.
In the second sample the answer is *v* = 54. Vasya writes the code in the following por... | 1,000 | [
{
"input": "7 2",
"output": "4"
},
{
"input": "59 9",
"output": "54"
},
{
"input": "1 9",
"output": "1"
},
{
"input": "11 2",
"output": "7"
},
{
"input": "747 2",
"output": "376"
},
{
"input": "6578 2",
"output": "3293"
},
{
"input": "37212... | 1,681,098,763 | 2,147,483,647 | PyPy 3 | OK | TESTS | 56 | 154 | 0 | n, k = [int(i) for i in input().split()]
ub = n
lb = 0
sagot = 0
while lb <= ub:
mid = ( lb + ub )// 2
sm = 0
mid_d = mid
while mid_d > 0:
sm += mid_d
mid_d//=k
if n > sm:
#print('up')
lb = mid + 1
elif n < sm:
#print('d')
ub = mid ... | Title: Burning Midnight Oil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of c... | ```python
n, k = [int(i) for i in input().split()]
ub = n
lb = 0
sagot = 0
while lb <= ub:
mid = ( lb + ub )// 2
sm = 0
mid_d = mid
while mid_d > 0:
sm += mid_d
mid_d//=k
if n > sm:
#print('up')
lb = mid + 1
elif n < sm:
#print('d')
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
768 | A | Oath of the Night's Watch | PROGRAMMING | 900 | [
"constructive algorithms",
"sortings"
] | null | null | "Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am the sword in the darkness. I am the watcher on the walls. I am the shield that guards the realms of men. I ple... | First line consists of a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of stewards with Jon Snow.
Second line consists of *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) representing the values assigned to the stewards. | Output a single integer representing the number of stewards which Jon will feed. | [
"2\n1 5\n",
"3\n1 2 5\n"
] | [
"0",
"1"
] | In the first sample, Jon Snow cannot support steward with strength 1 because there is no steward with strength less than 1 and he cannot support steward with strength 5 because there is no steward with strength greater than 5.
In the second sample, Jon Snow can support steward with strength 2 because there are steward... | 500 | [
{
"input": "2\n1 5",
"output": "0"
},
{
"input": "3\n1 2 5",
"output": "1"
},
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "8\n7 8 9 4 5 6 1 2",
"output": "6"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n100",
"output": "0"
},
... | 1,670,493,258 | 2,147,483,647 | Python 3 | OK | TESTS | 88 | 139 | 10,956,800 | import math
import string
import sys
input = sys.stdin.readline
# take a list input in a single line
def invr():
return list(map(int, input().split()))
def solve():
n = int(input())
stringInput = input()
lst = list(map(int, stringInput.split()))
lst.sort()
count = 0
for i in... | Title: Oath of the Night's Watch
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am... | ```python
import math
import string
import sys
input = sys.stdin.readline
# take a list input in a single line
def invr():
return list(map(int, input().split()))
def solve():
n = int(input())
stringInput = input()
lst = list(map(int, stringInput.split()))
lst.sort()
count = 0
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
166 | A | Rank List | PROGRAMMING | 1,100 | [
"binary search",
"implementation",
"sortings"
] | null | null | Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for no team we are shown its final place.
You know the rules of comparing the results of two give... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50). Then *n* lines contain the description of the teams: the *i*-th line contains two integers *p**i* and *t**i* (1<=≤<=*p**i*,<=*t**i*<=≤<=50) — the number of solved problems and the total penalty time of the *i*-th team, correspondingly. All num... | In the only line print the sought number of teams that got the *k*-th place in the final results' table. | [
"7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10\n",
"5 4\n3 1\n3 1\n5 3\n3 1\n3 1\n"
] | [
"3\n",
"4\n"
] | The final results' table for the first sample is:
- 1-3 places — 4 solved problems, the penalty time equals 10 - 4 place — 3 solved problems, the penalty time equals 20 - 5-6 places — 2 solved problems, the penalty time equals 1 - 7 place — 1 solved problem, the penalty time equals 10
The table shows that the se... | 500 | [
{
"input": "7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10",
"output": "3"
},
{
"input": "5 4\n3 1\n3 1\n5 3\n3 1\n3 1",
"output": "4"
},
{
"input": "5 1\n2 2\n1 1\n1 1\n1 1\n2 2",
"output": "2"
},
{
"input": "6 3\n2 2\n3 1\n2 2\n4 5\n2 2\n4 5",
"output": "1"
},
{
"i... | 1,631,380,570 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 186 | 21,401,600 | def cmp(x,y):
if x[0]>y[0]:
return True
elif x[0]==y[0] and x[1]<y[1]:
return True
else:
return False
def bubbleSort(arr):
n = len(arr)
for i in range(n-1):
for j in range(0, n-i-1):
if cmp(arr[j],arr[j + 1]):
arr[j], arr[j + 1] = arr[j + 1], arr[j]
n,k ... | Title: Rank List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for... | ```python
def cmp(x,y):
if x[0]>y[0]:
return True
elif x[0]==y[0] and x[1]<y[1]:
return True
else:
return False
def bubbleSort(arr):
n = len(arr)
for i in range(n-1):
for j in range(0, n-i-1):
if cmp(arr[j],arr[j + 1]):
arr[j], arr[j + 1] = arr[j + 1], arr[j]... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,685,518,344 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | n, k = map(int,input().split())
y = list(map(int, input().split()))
s = 0
for i in range(n):
if y[i-1]<=(5-k):
s+=1
else:
s+=0
print(s//3) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
n, k = map(int,input().split())
y = list(map(int, input().split()))
s = 0
for i in range(n):
if y[i-1]<=(5-k):
s+=1
else:
s+=0
print(s//3)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,489,587,084 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 77 | 4,608,000 | n=int(input())
if n%2==0:
print(int(n*n/2))
else :
print(int((n*n+1)/2))
s1=""
s2=""
for j in range(0,n):
if j%2==0:
s1+='C'
else :
s1+='.'
for j in range(0,n):
if j%2==0:
s2+='.'
else :
s2+='C'
for i in range(0,n):
if i%2==0:
print(... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
n=int(input())
if n%2==0:
print(int(n*n/2))
else :
print(int((n*n+1)/2))
s1=""
s2=""
for j in range(0,n):
if j%2==0:
s1+='C'
else :
s1+='.'
for j in range(0,n):
if j%2==0:
s2+='.'
else :
s2+='C'
for i in range(0,n):
if i%2==0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,633,527,147 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 6,758,400 | x=input()
n,k=int(x[0]),int(x[2])
s=input()
if len(s)%k!=0:print("NO")
for i in s:
if s.count(i)%k!=0:print("NO")
else:print("YES")
| Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
x=input()
n,k=int(x[0]),int(x[2])
s=input()
if len(s)%k!=0:print("NO")
for i in s:
if s.count(i)%k!=0:print("NO")
else:print("YES")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
106 | A | Card Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Card Game | 2 | 256 | There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselves if you want.
To play durak you need a pack of 36 cards. Each card has a suit ("S", "H", ... | The first line contains the tramp suit. It is "S", "H", "D" or "C".
The second line contains the description of the two different cards. Each card is described by one word consisting of two symbols. The first symbol stands for the rank ("6", "7", "8", "9", "T", "J", "Q", "K" and "A"), and the second one stands for the... | Print "YES" (without the quotes) if the first cards beats the second one. Otherwise, print "NO" (also without the quotes). | [
"H\nQH 9S\n",
"S\n8D 6D\n",
"C\n7H AS\n"
] | [
"YES\n",
"YES",
"NO"
] | none | 500 | [
{
"input": "H\nQH 9S",
"output": "YES"
},
{
"input": "S\n8D 6D",
"output": "YES"
},
{
"input": "C\n7H AS",
"output": "NO"
},
{
"input": "C\nKC 9C",
"output": "YES"
},
{
"input": "D\n7D KD",
"output": "NO"
},
{
"input": "H\n7H KD",
"output": "YES"
... | 1,617,701,663 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 186 | 0 | boss = input()
a , b = input().split()
if a[1]==boss and b[1]!=boss:
print("YES")
elif a[1]==boss and b[1]!=boss:
print("NO")
else:
val = {}
val['6'] = 6
val['7'] = 7
val['8'] = 8
val['9'] = 9
val['T'] = 10
val['J'] = 11
val['K'] = 12
val['Q'] =... | Title: Card Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselve... | ```python
boss = input()
a , b = input().split()
if a[1]==boss and b[1]!=boss:
print("YES")
elif a[1]==boss and b[1]!=boss:
print("NO")
else:
val = {}
val['6'] = 6
val['7'] = 7
val['8'] = 8
val['9'] = 9
val['T'] = 10
val['J'] = 11
val['K'] = 12
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,640,487,462 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | inp = list(map(int,input().split()))
high = 0
for i in inp:
high = max(max, i)
ans = 6 - high + 1
if ans == 1:
print("1/6")
elif ans == 2:
print("1/3")
elif ans == 3:
print("1/2")
elif ans == 4:
print("2/3")
elif ans == 5:
print("5/6")
else:
print("1/1") | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
inp = list(map(int,input().split()))
high = 0
for i in inp:
high = max(max, i)
ans = 6 - high + 1
if ans == 1:
print("1/6")
elif ans == 2:
print("1/3")
elif ans == 3:
print("1/2")
elif ans == 4:
print("2/3")
elif ans == 5:
print("5/6")
else:
print("1/1")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
929 | B | Места в самолёте | PROGRAMMING | 1,300 | [
"*special",
"implementation"
] | null | null | В самолёте есть *n* рядов мест. Если смотреть на ряды сверху, то в каждом ряду есть 3 места слева, затем проход между рядами, затем 4 центральных места, затем ещё один проход между рядами, а затем ещё 3 места справа.
Известно, что некоторые места уже заняты пассажирами. Всего есть два вида пассажиров — статусные (те, ... | В первой строке следуют два целых числа *n* и *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=10·*n*) — количество рядов мест в самолёте и количество пассажиров, которых нужно рассадить.
Далее следует описание рядов мест самолёта по одному ряду в строке. Если очередной символ равен '-', то это проход между рядами. Если очередно... | В первую строку выведите минимальное суммарное число соседей у статусных пассажиров.
Далее выведите план рассадки пассажиров, который минимизирует суммарное количество соседей у статусных пассажиров, в том же формате, что и во входных данных. Если в свободное место нужно посадить одного из *k* пассажиров, выведите стр... | [
"1 2\nSP.-SS.S-S.S\n",
"4 9\nPP.-PPPS-S.S\nPSP-PPSP-.S.\n.S.-S..P-SS.\nP.S-P.PP-PSP\n"
] | [
"5\nSPx-SSxS-S.S\n",
"15\nPPx-PPPS-S.S\nPSP-PPSP-xSx\nxSx-SxxP-SSx\nP.S-PxPP-PSP\n"
] | В первом примере нужно посадить ещё двух обычных пассажиров. Для минимизации соседей у статусных пассажиров, нужно посадить первого из них на третье слева место, а второго на любое из оставшихся двух мест, так как независимо от выбора места он станет соседом двух статусных пассажиров.
Изначально, у статусного пассажи... | 1,000 | [
{
"input": "1 2\nSP.-SS.S-S.S",
"output": "5\nSPx-SSxS-S.S"
},
{
"input": "4 9\nPP.-PPPS-S.S\nPSP-PPSP-.S.\n.S.-S..P-SS.\nP.S-P.PP-PSP",
"output": "15\nPPx-PPPS-S.S\nPSP-PPSP-xSx\nxSx-SxxP-SSx\nP.S-PxPP-PSP"
},
{
"input": "3 7\n.S.-SSSP-..S\nS..-.SPP-S.P\n.S.-PPPP-PSP",
"output": "13... | 1,520,091,278 | 86,378 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 46 | 5,632,000 | n, k = map(int, input().split())
w = 0
mesto = []
while w<n:
w +=1
mesto.append(input())
l = len(mesto)
w = 0
d = dict()
count =0
while w<n:
w2 = 0
while w2 < 12:
steck = ''
if mesto[w][w2] == '.':
steck = ''
if w2 == 0:
steck = ... | Title: Места в самолёте
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
В самолёте есть *n* рядов мест. Если смотреть на ряды сверху, то в каждом ряду есть 3 места слева, затем проход между рядами, затем 4 центральных места, затем ещё один проход между рядами, а затем ещё 3 места справа.
... | ```python
n, k = map(int, input().split())
w = 0
mesto = []
while w<n:
w +=1
mesto.append(input())
l = len(mesto)
w = 0
d = dict()
count =0
while w<n:
w2 = 0
while w2 < 12:
steck = ''
if mesto[w][w2] == '.':
steck = ''
if w2 == 0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
730 | I | Olympiad in Programming and Sports | PROGRAMMING | 2,000 | [
"dp",
"flows",
"graphs",
"greedy"
] | null | null | There are *n* students at Berland State University. Every student has two skills, each measured as a number: *a**i* — the programming skill and *b**i* — the sports skill.
It is announced that an Olympiad in programming and sports will be held soon. That's why Berland State University should choose two teams: one to ta... | The first line contains three positive integer numbers *n*, *p* and *s* (2<=≤<=*n*<=≤<=3000, *p*<=+<=*s*<=≤<=*n*) — the number of students, the size of the programming team and the size of the sports team.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000), where *a**i* i... | In the first line, print the the maximum strength of the university on the Olympiad. In the second line, print *p* numbers — the members of the programming team. In the third line, print *s* numbers — the members of the sports team.
The students are numbered from 1 to *n* as they are given in the input. All numbers pr... | [
"5 2 2\n1 3 4 5 2\n5 3 2 1 4\n",
"4 2 2\n10 8 8 3\n10 7 9 4\n",
"5 3 1\n5 2 5 1 7\n6 3 1 6 3\n"
] | [
"18\n3 4 \n1 5 \n",
"31\n1 2 \n3 4 \n",
"23\n1 3 5 \n4 \n"
] | none | 0 | [
{
"input": "5 2 2\n1 3 4 5 2\n5 3 2 1 4",
"output": "18\n3 4 \n1 5 "
},
{
"input": "4 2 2\n10 8 8 3\n10 7 9 4",
"output": "31\n1 2 \n3 4 "
},
{
"input": "5 3 1\n5 2 5 1 7\n6 3 1 6 3",
"output": "23\n1 3 5 \n4 "
},
{
"input": "2 1 1\n100 101\n1 100",
"output": "200\n1 \n2 ... | 1,631,206,278 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 71 | 2,000 | 49,459,200 | def process(p, s, A, B):
n = len(A)
d = {(0, 0): [0, [], []]}
for i in range(n):
ai = A[i]
bi = B[i]
new_d = {}
for pi, si in d:
if (p-pi+s-si) <= n-i:
if (pi, si) not in new_d:
new_d[(pi, si)] = [-1, None, None]
... | Title: Olympiad in Programming and Sports
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* students at Berland State University. Every student has two skills, each measured as a number: *a**i* — the programming skill and *b**i* — the sports skill.
It is announced that an Olym... | ```python
def process(p, s, A, B):
n = len(A)
d = {(0, 0): [0, [], []]}
for i in range(n):
ai = A[i]
bi = B[i]
new_d = {}
for pi, si in d:
if (p-pi+s-si) <= n-i:
if (pi, si) not in new_d:
new_d[(pi, si)] = [-1, None, N... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,694,092,276 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | a,b=map(int, input().split())
count=a
while a>a%b:
count+=a//b
a=(a//b)+(a%b)
print(count)
| Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
a,b=map(int, input().split())
count=a
while a>a%b:
count+=a//b
a=(a//b)+(a%b)
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,695,125,820 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 50 | 61 | 0 | size = [int(i) for i in input().split()]
color = [input().split() for _ in range(size[0])]
for i in color:
if 'C' in i or 'M' in i or 'Y' in i:
print('#Color')
break
else:
print('#Black&White') | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
size = [int(i) for i in input().split()]
color = [input().split() for _ in range(size[0])]
for i in color:
if 'C' in i or 'M' in i or 'Y' in i:
print('#Color')
break
else:
print('#Black&White')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
743 | B | Chloe and the sequence | PROGRAMMING | 1,200 | [
"binary search",
"bitmasks",
"constructive algorithms",
"implementation"
] | null | null | Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following algorithm of generating a sequence of integers. Initially we have a sequence consisting of a single element eq... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=2*n*<=-<=1). | Print single integer — the integer at the *k*-th position in the obtained sequence. | [
"3 2\n",
"4 8\n"
] | [
"2",
"4"
] | In the first sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1]. The number on the second position is 2.
In the second sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1]. The number on the eighth position is 4. | 1,000 | [
{
"input": "3 2",
"output": "2"
},
{
"input": "4 8",
"output": "4"
},
{
"input": "5 27",
"output": "1"
},
{
"input": "7 44",
"output": "3"
},
{
"input": "15 18432",
"output": "12"
},
{
"input": "20 259676",
"output": "3"
},
{
"input": "30 6... | 1,622,620,928 | 2,147,483,647 | PyPy 3 | OK | TESTS | 39 | 155 | 0 | n,k=map(int,input().split())
ans=1
while(True):
if k%2!=0:
print(ans)
break
else:
k=k//2
ans+=1
| Title: Chloe and the sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following a... | ```python
n,k=map(int,input().split())
ans=1
while(True):
if k%2!=0:
print(ans)
break
else:
k=k//2
ans+=1
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
365 | A | Good Number | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*). | The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the number of *k*-good numbers in *a*. | [
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] | [
"10\n",
"1\n"
] | none | 500 | [
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
... | 1,638,178,326 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | def cn(h):
d=m.count(h)
if d>1:
e=m.index(h)
else:
e=-1
return e
n,k=map(int,input().split())
l=[]
o=str(k)
sum=0
for i in range(n):
a=int(input())
l.append(a)
for j in range(n):
s=0
m=str(l[j])
for p in range(len(m)):
if m[p]<=o ... | Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number eve... | ```python
def cn(h):
d=m.count(h)
if d>1:
e=m.index(h)
else:
e=-1
return e
n,k=map(int,input().split())
l=[]
o=str(k)
sum=0
for i in range(n):
a=int(input())
l.append(a)
for j in range(n):
s=0
m=str(l[j])
for p in range(len(m)):
i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
620 | A | Professor GukiZ's Robot | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of them) by one (decrease or increase). So the robot can move in one of the 8 directions. Find the minimal numbe... | The first line contains two integers *x*1,<=*y*1 (<=-<=109<=≤<=*x*1,<=*y*1<=≤<=109) — the start position of the robot.
The second line contains two integers *x*2,<=*y*2 (<=-<=109<=≤<=*x*2,<=*y*2<=≤<=109) — the finish position of the robot. | Print the only integer *d* — the minimal number of steps to get the finish position. | [
"0 0\n4 5\n",
"3 4\n6 1\n"
] | [
"5\n",
"3\n"
] | In the first example robot should increase both of its coordinates by one four times, so it will be in position (4, 4). After that robot should simply increase its *y* coordinate and get the finish position.
In the second example robot should simultaneously increase *x* coordinate and decrease *y* coordinate by one th... | 0 | [
{
"input": "0 0\n4 5",
"output": "5"
},
{
"input": "3 4\n6 1",
"output": "3"
},
{
"input": "0 0\n4 6",
"output": "6"
},
{
"input": "1 1\n-3 -5",
"output": "6"
},
{
"input": "-1 -1\n-10 100",
"output": "101"
},
{
"input": "1 -1\n100 -100",
"output":... | 1,670,851,180 | 2,147,483,647 | Python 3 | OK | TESTS | 75 | 46 | 0 | a = input()
a = a.split()
a = [int(x) for x in a]
x1, y1 = a
a = input()
a = a.split()
a = [int(x) for x in a]
x2, y2 = a
print(max(abs(x1-x2), abs(y1-y2))) | Title: Professor GukiZ's Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of ... | ```python
a = input()
a = a.split()
a = [int(x) for x in a]
x1, y1 = a
a = input()
a = a.split()
a = [int(x) for x in a]
x2, y2 = a
print(max(abs(x1-x2), abs(y1-y2)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,693,721,141 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 124 | 13,619,200 | n = int(input())
a = list(map(int, input().split()))
# Create a frequency count of each number in the sequence
freq = [0] * (max(a) + 1)
for num in a:
freq[num] += 1
# Initialize dp array to store maximum points for each number
dp = [0] * (max(a) + 1)
# Calculate the maximum points using dynamic progr... | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
n = int(input())
a = list(map(int, input().split()))
# Create a frequency count of each number in the sequence
freq = [0] * (max(a) + 1)
for num in a:
freq[num] += 1
# Initialize dp array to store maximum points for each number
dp = [0] * (max(a) + 1)
# Calculate the maximum points using dyn... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
234 | C | Weather | PROGRAMMING | 1,300 | [
"dp",
"implementation"
] | null | null | Scientists say a lot about the problems of global warming and cooling of the Earth. Indeed, such natural phenomena strongly influence all life on our planet.
Our hero Vasya is quite concerned about the problems. He decided to try a little experiment and observe how outside daily temperature changes. He hung out a ther... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of days for which Vasya has been measuring the temperature.
The second line contains a sequence of *n* integers *t*1,<=*t*2,<=...,<=*t**n* (|*t**i*|<=≤<=109) — the sequence of temperature values. Numbers *t**i* are separated by single space... | Print a single integer — the answer to the given task. | [
"4\n-1 1 -2 1\n",
"5\n0 -1 1 2 -5\n"
] | [
"1\n",
"2\n"
] | Note to the first sample: there are two ways to change exactly one number so that the sequence met Vasya's condition. You can either replace the first number 1 by any negative number or replace the number -2 by any positive number. | 0 | [
{
"input": "4\n-1 1 -2 1",
"output": "1"
},
{
"input": "5\n0 -1 1 2 -5",
"output": "2"
},
{
"input": "6\n0 0 0 0 0 0",
"output": "6"
},
{
"input": "6\n-1 -2 -3 -4 5 6",
"output": "0"
},
{
"input": "8\n1 2 -1 0 10 2 12 13",
"output": "3"
},
{
"input": "... | 1,617,770,239 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | t=*map(int,open('input.txt','r').readlines()[1].split()),
c=sum(x<=0for x in t);n=len(t)
for i in range(n-1):c+=-(t[i]<0);n=min(n,c)
print(n,file=open('output.txt','w')) | Title: Weather
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Scientists say a lot about the problems of global warming and cooling of the Earth. Indeed, such natural phenomena strongly influence all life on our planet.
Our hero Vasya is quite concerned about the problems. He decided to ... | ```python
t=*map(int,open('input.txt','r').readlines()[1].split()),
c=sum(x<=0for x in t);n=len(t)
for i in range(n-1):c+=-(t[i]<0);n=min(n,c)
print(n,file=open('output.txt','w'))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
353 | A | Domino | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the numbers on the upper halves and the sum of the numbers on the lower halves to be even.
To do... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), denoting the number of dominoes Valera has. Next *n* lines contain two space-separated integers *x**i*,<=*y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=6). Number *x**i* is initially written on the upper half of the *i*-th domino, *y**i* is initially written on the lower half... | Print a single number — the minimum required number of seconds. If Valera can't do the task in any time, print <=-<=1. | [
"2\n4 2\n6 4\n",
"1\n2 3\n",
"3\n1 4\n2 3\n4 4\n"
] | [
"0\n",
"-1\n",
"1\n"
] | In the first test case the sum of the numbers on the upper halves equals 10 and the sum of the numbers on the lower halves equals 6. Both numbers are even, so Valera doesn't required to do anything.
In the second sample Valera has only one piece of domino. It is written 3 on the one of its halves, therefore one of the... | 500 | [
{
"input": "2\n4 2\n6 4",
"output": "0"
},
{
"input": "1\n2 3",
"output": "-1"
},
{
"input": "3\n1 4\n2 3\n4 4",
"output": "1"
},
{
"input": "5\n5 4\n5 4\n1 5\n5 5\n3 3",
"output": "1"
},
{
"input": "20\n1 3\n5 2\n5 2\n2 6\n2 4\n1 1\n1 3\n1 4\n2 6\n4 2\n5 6\n2 2\n... | 1,637,498,066 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 62 | 0 | n=int(input())
l1=[]
l2=[]
for i in range(n):
a,b=map(int, input().split())
l1.append(a)
l2.append(b)
if sum(l1)%2==0 and sum(l2)%2==0:
print(0)
elif sum(l1)%2==1 and sum(l2)%2==1:
print(1)
else:
print(-1) | Title: Domino
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the n... | ```python
n=int(input())
l1=[]
l2=[]
for i in range(n):
a,b=map(int, input().split())
l1.append(a)
l2.append(b)
if sum(l1)%2==0 and sum(l2)%2==0:
print(0)
elif sum(l1)%2==1 and sum(l2)%2==1:
print(1)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
550 | A | Two Substrings | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"greedy",
"implementation",
"strings"
] | null | null | You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order). | The only line of input contains a string *s* of length between 1 and 105 consisting of uppercase Latin letters. | Print "YES" (without the quotes), if string *s* contains two non-overlapping substrings "AB" and "BA", and "NO" otherwise. | [
"ABA\n",
"BACFAB\n",
"AXBYBXA\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | In the first sample test, despite the fact that there are substrings "AB" and "BA", their occurrences overlap, so the answer is "NO".
In the second sample test there are the following occurrences of the substrings: BACFAB.
In the third sample test there is no substring "AB" nor substring "BA". | 1,000 | [
{
"input": "ABA",
"output": "NO"
},
{
"input": "BACFAB",
"output": "YES"
},
{
"input": "AXBYBXA",
"output": "NO"
},
{
"input": "ABABAB",
"output": "YES"
},
{
"input": "BBBBBBBBBB",
"output": "NO"
},
{
"input": "ABBA",
"output": "YES"
},
{
"... | 1,686,928,823 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | s = input()
ab = False
ba = False
# Search for "AB" substring
for i in range(len(s)-1):
if s[i:i+2] == "AB":
ab = True
break
# Search for "BA" substring, starting from the position after "AB"
for j in range(i+2, len(s)-1):
if s[j:j+2] == "BA":
ba = True
break
... | Title: Two Substrings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order).
Input Specification:
The only line of input contain... | ```python
s = input()
ab = False
ba = False
# Search for "AB" substring
for i in range(len(s)-1):
if s[i:i+2] == "AB":
ab = True
break
# Search for "BA" substring, starting from the position after "AB"
for j in range(i+2, len(s)-1):
if s[j:j+2] == "BA":
ba = True
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,684,869,578 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 234 | 0 | n=int(input())
count=0
for i in range(n):
s=input()
if (s[0]=='T'):
count+=4
elif(s[0]=='C'):
count+=6
elif(s[0]=='O'):
count+=8
elif(s[0]=='D'):
count+=12
elif(s[0]=='I'):
count+=20
print(count) | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
n=int(input())
count=0
for i in range(n):
s=input()
if (s[0]=='T'):
count+=4
elif(s[0]=='C'):
count+=6
elif(s[0]=='O'):
count+=8
elif(s[0]=='D'):
count+=12
elif(s[0]=='I'):
count+=20
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
454 | B | Little Pony and Sort by Shift | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. That is, she can move the last element of the sequence to its beginning:
Help Twilight Sparkle to calculate: what ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=105). The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105). | If it's impossible to sort the sequence output -1. Otherwise output the minimum number of operations Twilight Sparkle needs to sort it. | [
"2\n2 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"1\n",
"-1\n",
"0\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 3 2",
"output": "-1"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "6\n3 4 5 6 3 2",
"output": "-1"
},
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n1 1 2 1 1",
"output": "2"
}... | 1,634,314,683 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 22 | 124 | 7,372,800 | n=int(input())
l=list(map(int,input().split()))
l2=l.copy()
l3=l.copy()
l2.sort()
x=l.index(min(l))
y=n-l[::-1].index(min(l))-1
if l!=l2:
l=l[x:]+l[:x]
l3=l3[y:]+l3[:y]
else:
x=n
f=True
# print(l)
# print(l2)
# print(l3)
for i in range(n):
if(l[i]!=l2[i]):
# print("ajh")
f=False
break
if(... | Title: Little Pony and Sort by Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. ... | ```python
n=int(input())
l=list(map(int,input().split()))
l2=l.copy()
l3=l.copy()
l2.sort()
x=l.index(min(l))
y=n-l[::-1].index(min(l))-1
if l!=l2:
l=l[x:]+l[:x]
l3=l3[y:]+l3[:y]
else:
x=n
f=True
# print(l)
# print(l2)
# print(l3)
for i in range(n):
if(l[i]!=l2[i]):
# print("ajh")
f=False
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
251 | A | Points on Line | PROGRAMMING | 1,300 | [
"binary search",
"combinatorics",
"two pointers"
] | null | null | Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen... | The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input stri... | Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n1 2 3 4\n",
"4 2\n-3 -2 -1 0\n",
"5 19\n1 10 20 30 50\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | 500 | [
{
"input": "4 3\n1 2 3 4",
"output": "4"
},
{
"input": "4 2\n-3 -2 -1 0",
"output": "2"
},
{
"input": "5 19\n1 10 20 30 50",
"output": "1"
},
{
"input": "10 5\n31 36 43 47 48 50 56 69 71 86",
"output": "2"
},
{
"input": "10 50\n1 4 20 27 65 79 82 83 99 100",
"... | 1,459,340,935 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 512,000 | def num(s):
a = [0]
sign = [1]
i = 0
for k in s:
if k == ' ':
a[i] = sign[i]*a[i]
i += 1
a.append(0)
sign.append(1)
elif k == '-':
sign[i] = -1
else:
a[i] = a[i]*10 + int(k)
a[i] = a[i]*sign... | Title: Points on Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two fart... | ```python
def num(s):
a = [0]
sign = [1]
i = 0
for k in s:
if k == ' ':
a[i] = sign[i]*a[i]
i += 1
a.append(0)
sign.append(1)
elif k == '-':
sign[i] = -1
else:
a[i] = a[i]*10 + int(k)
a[i] =... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
886 | B | Vlad and Cafes | PROGRAMMING | 1,000 | [] | null | null | Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes... | In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, ... | Print one integer — index of the cafe that Vlad hasn't visited for as long as possible. | [
"5\n1 3 2 1 2\n",
"6\n2 1 2 2 4 1\n"
] | [
"3\n",
"2\n"
] | In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with in... | 1,000 | [
{
"input": "5\n1 3 2 1 2",
"output": "3"
},
{
"input": "6\n2 1 2 2 4 1",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n200000",
"output": "200000"
},
{
"input": "2\n2018 2017",
"output": "2018"
},
{
"input": "5\n100 1000 1000 1000... | 1,555,327,174 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 249 | 15,769,600 | #آخرین بازدید از اون کافه قبل آخرین بازدید از کافه های دیگر باشه
n=int(input())
l = [*map(int,input().split())]
tmp={}
Ans=None
for i in range(n-1,-1,-1):
if tmp.get(l[i],-1)==-1:
tmp[l[i]]=1
Ans=l[i]
else:
pass
print(Ans) | Title: Vlad and Cafes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research... | ```python
#آخرین بازدید از اون کافه قبل آخرین بازدید از کافه های دیگر باشه
n=int(input())
l = [*map(int,input().split())]
tmp={}
Ans=None
for i in range(n-1,-1,-1):
if tmp.get(l[i],-1)==-1:
tmp[l[i]]=1
Ans=l[i]
else:
pass
print(Ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
990 | A | Commentary Boxes | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation should get the same number of the commentary boxes. If any box is left unoccupied then the delegations wil... | The only line contains four integer numbers $n$, $m$, $a$ and $b$ ($1 \le n, m \le 10^{12}$, $1 \le a, b \le 100$), where $n$ is the initial number of the commentary boxes, $m$ is the number of delegations to come, $a$ is the fee to build a box and $b$ is the fee to demolish a box. | Output the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$). It is allowed that the final number of the boxes is equal to $0$. | [
"9 7 3 8\n",
"2 7 3 7\n",
"30 6 17 19\n"
] | [
"15\n",
"14\n",
"0\n"
] | In the first example organizers can build $5$ boxes to make the total of $14$ paying $3$ burles for the each of them.
In the second example organizers can demolish $2$ boxes to make the total of $0$ paying $7$ burles for the each of them.
In the third example organizers are already able to distribute all the boxes eq... | 0 | [
{
"input": "9 7 3 8",
"output": "15"
},
{
"input": "2 7 3 7",
"output": "14"
},
{
"input": "30 6 17 19",
"output": "0"
},
{
"input": "500000000001 1000000000000 100 100",
"output": "49999999999900"
},
{
"input": "1000000000000 750000000001 10 100",
"output": "... | 1,653,311,595 | 2,147,483,647 | Python 3 | OK | TESTS | 109 | 46 | 0 | s = input().split(" ");
n = int(s[0])
m = int(s[1])
a = int(s[2])
b = int(s[3])
print(min((n%m) * b, (m - (n%m))*a)) | Title: Commentary Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation shou... | ```python
s = input().split(" ");
n = int(s[0])
m = int(s[1])
a = int(s[2])
b = int(s[3])
print(min((n%m) * b, (m - (n%m))*a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,611,093,375 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 186 | 0 | s = input()
up_count, down_count = 0,0
for i in range(len(s)):
if s[i].isupper():
up_count += 1
else:
down_count += 1
if up_count > down_count:
print(s.upper())
elif up_count < down_count:
print(s.lower())
else:
print(s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
up_count, down_count = 0,0
for i in range(len(s)):
if s[i].isupper():
up_count += 1
else:
down_count += 1
if up_count > down_count:
print(s.upper())
elif up_count < down_count:
print(s.lower())
else:
print(s.lower())
``` | 3.9535 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has two strings *a* and *b* of the same length *n*. The strings consist only of lucky digits... | The first and the second line contains strings *a* and *b*, correspondingly. Strings *a* and *b* have equal lengths and contain only lucky digits. The strings are not empty, their length does not exceed 105. | Print on the single line the single number — the minimum number of operations needed to convert string *a* into string *b*. | [
"47\n74\n",
"774\n744\n",
"777\n444\n"
] | [
"1\n",
"1\n",
"3\n"
] | In the first sample it is enough simply to swap the first and the second digit.
In the second sample we should replace the second digit with its opposite.
In the third number we should replace all three digits with their opposites. | 0 | [
{
"input": "47\n74",
"output": "1"
},
{
"input": "774\n744",
"output": "1"
},
{
"input": "777\n444",
"output": "3"
},
{
"input": "74747474\n77777777",
"output": "4"
},
{
"input": "444444444444\n777777777777",
"output": "12"
},
{
"input": "4744744447774... | 1,628,964,005 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 6,963,200 | a = (input())
b = (input())
a4 = 0
a7 = 0
b4 = 0
b7 = 0
eq = 0
res = 0
for i in range(len(a)):
if (a[i] == b[i]):
eq += 1
if (a[i] == '4'):
a4 += 1
if (a[i] == '7'):
a7 += 1
if (b[i] == '4'):
b4 += 1
if (b[i] == '7'):
b7 += 1
res += (abs(a7-b7))
print(re... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya ha... | ```python
a = (input())
b = (input())
a4 = 0
a7 = 0
b4 = 0
b7 = 0
eq = 0
res = 0
for i in range(len(a)):
if (a[i] == b[i]):
eq += 1
if (a[i] == '4'):
a4 += 1
if (a[i] == '7'):
a7 += 1
if (b[i] == '4'):
b4 += 1
if (b[i] == '7'):
b7 += 1
res += (abs(a7-b7))... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
580 | A | Kefa and First Steps | PROGRAMMING | 900 | [
"brute force",
"dp",
"implementation"
] | null | null | Kefa decided to make some money doing business on the Internet for exactly *n* days. He knows that on the *i*-th day (1<=≤<=*i*<=≤<=*n*) he makes *a**i* money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence *a**i*. Let us remind you that the subsegment o... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the length of the maximum non-decreasing subsegment of sequence *a*. | [
"6\n2 2 1 3 4 1\n",
"3\n2 2 9\n"
] | [
"3",
"3"
] | In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.
In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one. | 750 | [
{
"input": "6\n2 2 1 3 4 1",
"output": "3"
},
{
"input": "3\n2 2 9",
"output": "3"
},
{
"input": "5\n10 100 111 1 2",
"output": "3"
},
{
"input": "10\n1 2 3 4 1 2 3 4 5 6",
"output": "6"
},
{
"input": "50\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ... | 1,687,270,554 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 30 | 0 | n=int(input())
lst=list(map(int,input().split()))
c=0
ls=[]
k=True
for i in range(1,n):
if lst[i]-lst[i-1]>=0:
c+=1
else:
ls+=[c]
k=False
c=0
if k:
print(c+1)
else:
print(max(ls)+1) | Title: Kefa and First Steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kefa decided to make some money doing business on the Internet for exactly *n* days. He knows that on the *i*-th day (1<=≤<=*i*<=≤<=*n*) he makes *a**i* money. Kefa loves progress, that's why he wants to know the l... | ```python
n=int(input())
lst=list(map(int,input().split()))
c=0
ls=[]
k=True
for i in range(1,n):
if lst[i]-lst[i-1]>=0:
c+=1
else:
ls+=[c]
k=False
c=0
if k:
print(c+1)
else:
print(max(ls)+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
600 | B | Queries about less or equal elements | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"sortings",
"two pointers"
] | null | null | You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the sizes of arrays *a* and *b*.
The second line contains *n* integers — the elements of array *a* (<=-<=109<=≤<=*a**i*<=≤<=109).
The third line contains *m* integers — the elements of array *b* (<=-<=109<=≤<=*b**j*<=≤<=109). | Print *m* integers, separated by spaces: the *j*-th of which is equal to the number of such elements in array *a* that are less than or equal to the value *b**j*. | [
"5 4\n1 3 5 7 9\n6 4 2 8\n",
"5 5\n1 2 1 2 5\n3 1 4 1 5\n"
] | [
"3 2 1 4\n",
"4 2 4 2 5\n"
] | none | 0 | [
{
"input": "5 4\n1 3 5 7 9\n6 4 2 8",
"output": "3 2 1 4"
},
{
"input": "5 5\n1 2 1 2 5\n3 1 4 1 5",
"output": "4 2 4 2 5"
},
{
"input": "1 1\n-1\n-2",
"output": "0"
},
{
"input": "1 1\n-80890826\n686519510",
"output": "1"
},
{
"input": "11 11\n237468511 -77918754... | 1,683,292,370 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | n,m=map(int,input().split())
a1=list(map(int,input().split()))
a2=list(map(int,input().split()))
#a1.sort(reverse=True)
for i in a2:
count=0
for y in a1:
if i>y:
count+=1
print(count, end=' ')
| Title: Queries about less or equal elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*.
In... | ```python
n,m=map(int,input().split())
a1=list(map(int,input().split()))
a2=list(map(int,input().split()))
#a1.sort(reverse=True)
for i in a2:
count=0
for y in a1:
if i>y:
count+=1
print(count, end=' ')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
382 | A | Ksenia and Pan Scales | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium ... | The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially ... | If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them. | [
"AC|T\nL\n",
"|ABC\nXYZ\n",
"W|T\nF\n",
"ABC|\nD\n"
] | [
"AC|TL\n",
"XYZ|ABC\n",
"Impossible\n",
"Impossible\n"
] | none | 500 | [
{
"input": "AC|T\nL",
"output": "AC|TL"
},
{
"input": "|ABC\nXYZ",
"output": "XYZ|ABC"
},
{
"input": "W|T\nF",
"output": "Impossible"
},
{
"input": "ABC|\nD",
"output": "Impossible"
},
{
"input": "A|BC\nDEF",
"output": "ADF|BCE"
},
{
"input": "|\nABC",... | 1,561,224,453 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 109 | 0 | mezan = input()
ba2y = list(input())
leftl = ""
rightl = ""
left = True
x = len(mezan)-1+len(ba2y)
for i in range(len(mezan)):
if mezan[i] =="|":
left = False
continue
if left:
leftl += mezan[i]
else:
rightl += mezan[i]
if x % 2 != 0 or len(leftl) > x/2 or len... | Title: Ksenia and Pan Scales
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all ... | ```python
mezan = input()
ba2y = list(input())
leftl = ""
rightl = ""
left = True
x = len(mezan)-1+len(ba2y)
for i in range(len(mezan)):
if mezan[i] =="|":
left = False
continue
if left:
leftl += mezan[i]
else:
rightl += mezan[i]
if x % 2 != 0 or len(leftl) > ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,485,109,308 | 408 | Python 3 | OK | TESTS | 104 | 93 | 4,608,000 | import sys
#sys.stdin = open("in.txt" , "r")
#sys.stdout = open("out.txt" , "w")
from math import ceil
days = [0,31,28,31,30,31,30,31,31,30,31,30,31]
m,d = map(int,input().split())
days = d - 1 + days[m]
print(ceil(days/7))
| Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
import sys
#sys.stdin = open("in.txt" , "r")
#sys.stdout = open("out.txt" , "w")
from math import ceil
days = [0,31,28,31,30,31,30,31,31,30,31,30,31]
m,d = map(int,input().split())
days = d - 1 + days[m]
print(ceil(days/7))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
961 | A | Tetris | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given a following process.
There is a platform with $n$ columns. $1 \times 1$ squares are appearing one after another in some columns on this platform. If there are no squares in the column, a square will occupy the bottom row. Otherwise a square will appear at the top of the highest square of this column.
... | The first line of input contain 2 integer numbers $n$ and $m$ ($1 \le n, m \le 1000$) — the length of the platform and the number of the squares.
The next line contain $m$ integer numbers $c_1, c_2, \dots, c_m$ ($1 \le c_i \le n$) — column in which $i$-th square will appear. | Print one integer — the amount of points you will receive. | [
"3 9\n1 1 2 2 2 3 1 2 3\n"
] | [
"2\n"
] | In the sample case the answer will be equal to $2$ because after the appearing of $6$-th square will be removed one row (counts of the squares on the platform will look like $[2~ 3~ 1]$, and after removing one row will be $[1~ 2~ 0]$).
After the appearing of $9$-th square counts will be $[2~ 3~ 1]$, and after removing... | 0 | [
{
"input": "3 9\n1 1 2 2 2 3 1 2 3",
"output": "2"
},
{
"input": "1 7\n1 1 1 1 1 1 1",
"output": "7"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "3 5\n1 1 1 2 3",
"output": "1"
},
{
"input": "4 6\n4 4 4 4 4 4",
"output": "0"
},
{
"input": "4 6\... | 1,566,569,969 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 139 | 1,228,800 | x,y=map(int,input().split())
p=list(map(int,input().split()))
k=list()
for i in range(y):
if p[i] in p[0:i]:continue
else:k.append(p.count(p[i]))
ma,mi=max(k),min(k)
if ma==mi:print(ma)
else:print(ma-mi)
| Title: Tetris
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a following process.
There is a platform with $n$ columns. $1 \times 1$ squares are appearing one after another in some columns on this platform. If there are no squares in the column, a square will occupy the bo... | ```python
x,y=map(int,input().split())
p=list(map(int,input().split()))
k=list()
for i in range(y):
if p[i] in p[0:i]:continue
else:k.append(p.count(p[i]))
ma,mi=max(k),min(k)
if ma==mi:print(ma)
else:print(ma-mi)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
841 | B | Godsend | PROGRAMMING | 1,100 | [
"games",
"math"
] | null | null | Leha somehow found an array consisting of *n* integers. Looking at it, he came up with a task. Two players play the game on the array. Players move one by one. The first player can choose for his move a subsegment of non-zero length with an odd sum of numbers and remove it from the array, after that the remaining parts... | First line of input data contains single integer *n* (1<=≤<=*n*<=≤<=106) — length of the array.
Next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109). | Output answer in single line. "First", if first player wins, and "Second" otherwise (without quotes). | [
"4\n1 3 2 3\n",
"2\n2 2\n"
] | [
"First\n",
"Second\n"
] | In first sample first player remove whole array in one move and win.
In second sample first player can't make a move and lose. | 1,000 | [
{
"input": "4\n1 3 2 3",
"output": "First"
},
{
"input": "2\n2 2",
"output": "Second"
},
{
"input": "4\n2 4 6 8",
"output": "Second"
},
{
"input": "5\n1 1 1 1 1",
"output": "First"
},
{
"input": "4\n720074544 345031254 849487632 80870826",
"output": "Second"
... | 1,503,379,360 | 2,147,483,647 | Python 3 | OK | TESTS | 88 | 592 | 57,241,600 | n = int(input())
arr = map(int, input().split())
if sum(map(lambda x: x % 2, arr)) == 0:
print("Second")
else:
print("First")
| Title: Godsend
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Leha somehow found an array consisting of *n* integers. Looking at it, he came up with a task. Two players play the game on the array. Players move one by one. The first player can choose for his move a subsegment of non-zero l... | ```python
n = int(input())
arr = map(int, input().split())
if sum(map(lambda x: x % 2, arr)) == 0:
print("Second")
else:
print("First")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
359 | B | Permutation | PROGRAMMING | 1,400 | [
"constructive algorithms",
"dp",
"math"
] | null | null | A permutation *p* is an ordered group of numbers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers, each is no more than *n*. We'll define number *n* as the length of permutation *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*.
Simon has a positive integer *n* and a non-negative integer *k*, ... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50000, 0<=≤<=2*k*<=≤<=*n*). | Print 2*n* integers *a*1,<=*a*2,<=...,<=*a*2*n* — the required permutation *a*. It is guaranteed that the solution exists. If there are multiple solutions, you can print any of them. | [
"1 0\n",
"2 1\n",
"4 0\n"
] | [
"1 2",
"3 2 1 4\n",
"2 7 4 6 1 3 5 8\n"
] | Record |*x*| represents the absolute value of number *x*.
In the first sample |1 - 2| - |1 - 2| = 0.
In the second sample |3 - 2| + |1 - 4| - |3 - 2 + 1 - 4| = 1 + 3 - 2 = 2.
In the third sample |2 - 7| + |4 - 6| + |1 - 3| + |5 - 8| - |2 - 7 + 4 - 6 + 1 - 3 + 5 - 8| = 12 - 12 = 0. | 1,000 | [
{
"input": "1 0",
"output": "1 2"
},
{
"input": "2 1",
"output": "3 2 1 4"
},
{
"input": "4 0",
"output": "2 7 4 6 1 3 5 8"
},
{
"input": "50000 0",
"output": "1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 4... | 1,621,698,058 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 109 | 2,150,400 | _,k=map(int,input().split())
for _ in range(_):
d=i>=k;print(2*i+1+d,2*i+2-d) | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation *p* is an ordered group of numbers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers, each is no more than *n*. We'll define number *n* as the length of permutation *p*1,<=<=... | ```python
_,k=map(int,input().split())
for _ in range(_):
d=i>=k;print(2*i+1+d,2*i+2-d)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,697,137,831 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 46 | 0 | n,k = map(int,input().split())
s = input()
idx = 0
cnt = 0
flag = 0
while(True):
if(idx==n-1):
break
cnt += 1
new = min(idx+k,n-1)
if(s[new] == '1'):
idx = new
continue
flag = 1
for i in range(new,idx,-1):
if(s[i] == '1'):
idx = i
flag... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
n,k = map(int,input().split())
s = input()
idx = 0
cnt = 0
flag = 0
while(True):
if(idx==n-1):
break
cnt += 1
new = min(idx+k,n-1)
if(s[new] == '1'):
idx = new
continue
flag = 1
for i in range(new,idx,-1):
if(s[i] == '1'):
idx = i
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,628,349,055 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 6,758,400 | x,y,z=map(int, input().split())
k=x+y+z
ll=(x+y)*2
if k>ll:
print(ll)
else:
print(k) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
x,y,z=map(int, input().split())
k=x+y+z
ll=(x+y)*2
if k>ll:
print(ll)
else:
print(k)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
779 | B | Weird Rounding | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For example, if *k*<==<=3, in the number 30020 it is enough to delete a single digit (2). In this case, t... | The only line of the input contains two integer numbers *n* and *k* (0<=≤<=*n*<=≤<=2<=000<=000<=000, 1<=≤<=*k*<=≤<=9).
It is guaranteed that the answer exists. All numbers in the input are written in traditional notation of integers, that is, without any extra leading zeros. | Print *w* — the required minimal number of digits to erase. After removing the appropriate *w* digits from the number *n*, the result should have a value that is divisible by 10*k*. The result can start with digit 0 in the single case (the result is zero and written by exactly the only digit 0). | [
"30020 3\n",
"100 9\n",
"10203049 2\n"
] | [
"1\n",
"2\n",
"3\n"
] | In the example 2 you can remove two digits: 1 and any 0. The result is number 0 which is divisible by any number. | 1,000 | [
{
"input": "30020 3",
"output": "1"
},
{
"input": "100 9",
"output": "2"
},
{
"input": "10203049 2",
"output": "3"
},
{
"input": "0 1",
"output": "0"
},
{
"input": "0 9",
"output": "0"
},
{
"input": "100 2",
"output": "0"
},
{
"input": "102... | 1,488,937,016 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n,k=map(int,input().split())
n1=n
d=0
c=0
while(n1>0):
if(n1%10==0):
c+=1
d+=1
n1=int(n1/10)
if(c<k):
print(d-1)
else:
if(c%k==0):
print(d-c)
while(c%k!=0):
| Title: Weird Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For e... | ```python
n,k=map(int,input().split())
n1=n
d=0
c=0
while(n1>0):
if(n1%10==0):
c+=1
d+=1
n1=int(n1/10)
if(c<k):
print(d-1)
else:
if(c%k==0):
print(d-c)
while(c%k!=0):
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least... | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,683,045,394 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | n, d = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
f_ind = a[0]
count = 0
for i in range(1, n):
sec_ind = a[i]
if (sec_ind <= f_ind):
a[i] += d * ((f_ind - sec_ind) // d + 1)
count += (f_ind - sec_ind) // d + 1
f_ind = a[i]
print(count) | Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*... | ```python
n, d = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
f_ind = a[0]
count = 0
for i in range(1, n):
sec_ind = a[i]
if (sec_ind <= f_ind):
a[i] += d * ((f_ind - sec_ind) // d + 1)
count += (f_ind - sec_ind) // d + 1
f_ind = a[i]
print(count)
``` | 3.954 | MatrixStudio/Codeforces-Python-Submissions |
895 | A | Pizza Separation | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | Students Vasya and Petya are studying at the BSU (Byteland State University). At one of the breaks they decided to order a pizza. In this problem pizza is a circle of some radius. The pizza was delivered already cut into *n* pieces. The *i*-th piece is a sector of angle equal to *a**i*. Vasya and Petya want to divide a... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=360) — the number of pieces into which the delivered pizza was cut.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=360) — the angles of the sectors into which the pizza was cut. The sum of all *a**i* is 360. | Print one integer — the minimal difference between angles of sectors that will go to Vasya and Petya. | [
"4\n90 90 90 90\n",
"3\n100 100 160\n",
"1\n360\n",
"4\n170 30 150 10\n"
] | [
"0\n",
"40\n",
"360\n",
"0\n"
] | In first sample Vasya can take 1 and 2 pieces, Petya can take 3 and 4 pieces. Then the answer is |(90 + 90) - (90 + 90)| = 0.
In third sample there is only one piece of pizza that can be taken by only one from Vasya and Petya. So the answer is |360 - 0| = 360.
In fourth sample Vasya can take 1 and 4 pieces, then Pety... | 500 | [
{
"input": "4\n90 90 90 90",
"output": "0"
},
{
"input": "3\n100 100 160",
"output": "40"
},
{
"input": "1\n360",
"output": "360"
},
{
"input": "4\n170 30 150 10",
"output": "0"
},
{
"input": "5\n10 10 10 10 320",
"output": "280"
},
{
"input": "8\n45 4... | 1,511,712,562 | 262 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 5,529,600 | n = int(input())
a = list(map(int, input().split()))
ps = [0] * n
mindif = 2e9
for i in range(n):
ps[i] = ps[i - 1] if i > 0 else 0
ps[i] += a[i]
for i in range(n):
mindif = min(mindif, abs((ps[i - 1] if i > 0 else 0) - (ps[n - 1] - (ps[i - 1] if i > 0 else 0))))
print(mindif) | Title: Pizza Separation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Students Vasya and Petya are studying at the BSU (Byteland State University). At one of the breaks they decided to order a pizza. In this problem pizza is a circle of some radius. The pizza was delivered already cut in... | ```python
n = int(input())
a = list(map(int, input().split()))
ps = [0] * n
mindif = 2e9
for i in range(n):
ps[i] = ps[i - 1] if i > 0 else 0
ps[i] += a[i]
for i in range(n):
mindif = min(mindif, abs((ps[i - 1] if i > 0 else 0) - (ps[n - 1] - (ps[i - 1] if i > 0 else 0))))
print(mindif)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
202 | A | LLPS | PROGRAMMING | 800 | [
"binary search",
"bitmasks",
"brute force",
"greedy",
"implementation",
"strings"
] | null | null | This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string *s* consisting of lowercase English letters only. Find its lexicographically largest palindromic subsequence.
We'll call a non-empty string *s*[*p*1*p*2... *p**k*] = *s**p*1*... | The only input line contains a non-empty string *s* consisting of lowercase English letters only. Its length does not exceed 10. | Print the lexicographically largest palindromic subsequence of string *s*. | [
"radar\n",
"bowwowwow\n",
"codeforces\n",
"mississipp\n"
] | [
"rr\n",
"wwwww\n",
"s\n",
"ssss\n"
] | Among all distinct subsequences of string "radar" the following ones are palindromes: "a", "d", "r", "aa", "rr", "ada", "rar", "rdr", "raar" and "radar". The lexicographically largest of them is "rr". | 500 | [
{
"input": "radar",
"output": "rr"
},
{
"input": "bowwowwow",
"output": "wwwww"
},
{
"input": "codeforces",
"output": "s"
},
{
"input": "mississipp",
"output": "ssss"
},
{
"input": "tourist",
"output": "u"
},
{
"input": "romka",
"output": "r"
},
... | 1,696,688,865 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | s = input()
largest_char = 'a' # Initialize the largest character as 'a'
result = ""
for char in s:
if char >= largest_char:
result = char + result # Append the character to the beginning of the result
largest_char = char # Update the largest character
print(result)
| Title: LLPS
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string *s* consisting of lowercase English letters only. Find its lexicographically largest ... | ```python
s = input()
largest_char = 'a' # Initialize the largest character as 'a'
result = ""
for char in s:
if char >= largest_char:
result = char + result # Append the character to the beginning of the result
largest_char = char # Update the largest character
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,694,711,155 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 124 | 0 | n = int(input())
a = list(map(int,input().split()))
a.sort(reverse= True)
sum = 0
count = 0
barrier = 0
for i in a:
sum += i
half_of_sum = sum/2
for i in a:
barrier += i
count +=1
if barrier > half_of_sum:
break
print(count) | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
n = int(input())
a = list(map(int,input().split()))
a.sort(reverse= True)
sum = 0
count = 0
barrier = 0
for i in a:
sum += i
half_of_sum = sum/2
for i in a:
barrier += i
count +=1
if barrier > half_of_sum:
break
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
540 | A | Combination Lock | PROGRAMMING | 800 | [
"implementation"
] | null | null | Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is represented by *n* rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of disks on the combination lock.
The second line contains a string of *n* digits — the original state of the disks.
The third line contains a string of *n* digits — Scrooge McDuck's combination that opens the lock. | Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock. | [
"5\n82195\n64723\n"
] | [
"13\n"
] | In the sample he needs 13 moves:
- 1 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b8967f65a723782358b93eff9ce69f336817cf70.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 2 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/07fa58573ece0d32... | 500 | [
{
"input": "5\n82195\n64723",
"output": "13"
},
{
"input": "12\n102021090898\n010212908089",
"output": "16"
},
{
"input": "1\n8\n1",
"output": "3"
},
{
"input": "2\n83\n57",
"output": "7"
},
{
"input": "10\n0728592530\n1362615763",
"output": "27"
},
{
... | 1,598,898,293 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 124 | 409,600 | from collections import deque
def girar_derecha(num_ini, num_fin):
numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
num_moves = 0
while numbers[0] != num_ini:
numbers = deque(numbers)
numbers.rotate(1)
numbers = list(numbers)
while numbers[0] != num_fin:
numbers = deque(numbers)
numbers.rotate(1... | Title: Combination Lock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is ... | ```python
from collections import deque
def girar_derecha(num_ini, num_fin):
numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
num_moves = 0
while numbers[0] != num_ini:
numbers = deque(numbers)
numbers.rotate(1)
numbers = list(numbers)
while numbers[0] != num_fin:
numbers = deque(numbers)
number... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
246 | B | Increase and Decrease | PROGRAMMING | 1,300 | [
"greedy",
"math"
] | null | null | Polycarpus has an array, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Polycarpus likes it when numbers in an array match. That's why he wants the array to have as many equal numbers as possible. For that Polycarpus performs the following operation multiple times:
- he chooses two elements of the array *a**i... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the array size. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=104) — the original array. | Print a single integer — the maximum number of equal array elements he can get if he performs an arbitrary number of the given operation. | [
"2\n2 1\n",
"3\n1 4 1\n"
] | [
"1\n",
"3\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 4 1",
"output": "3"
},
{
"input": "4\n2 -7 -2 -6",
"output": "3"
},
{
"input": "4\n2 0 -2 -1",
"output": "3"
},
{
"input": "6\n-1 1 0 0 -1 -1",
"output": "5"
},
{
"input": "5\n0 0 0 0 0",
"outp... | 1,628,397,628 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 15 | 248 | 25,292,800 | def main():
n = int(input())
arr = list(map(int, input().split()))
for i in range(n - 1):
if arr[i] < 0:
arr[n - 1] -= arr[i]
arr[i] = 0
elif arr[i] > 0:
arr[n - 1] += arr[i]
arr[i] = 0
else:
pass
if arr[... | Title: Increase and Decrease
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has an array, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Polycarpus likes it when numbers in an array match. That's why he wants the array to have as many equal numbers as possible. For that... | ```python
def main():
n = int(input())
arr = list(map(int, input().split()))
for i in range(n - 1):
if arr[i] < 0:
arr[n - 1] -= arr[i]
arr[i] = 0
elif arr[i] > 0:
arr[n - 1] += arr[i]
arr[i] = 0
else:
pass
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,495,357,803 | 2,147,483,647 | Python 3 | OK | TESTS | 106 | 62 | 0 | n, k = map(int, input().split())
a = list(map(int, input().split()))
print(max(0, 2 * n * k - 2 * sum(a) - n)) | Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
n, k = map(int, input().split())
a = list(map(int, input().split()))
print(max(0, 2 * n * k - 2 * sum(a) - n))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
167 | A | Wizards and Trolleybuses | PROGRAMMING | 1,600 | [
"implementation",
"math"
] | null | null | In some country live wizards. They love to ride trolleybuses.
A city in this country has a trolleybus depot with *n* trolleybuses. Every day the trolleybuses leave the depot, one by one and go to the final station. The final station is at a distance of *d* meters from the depot. We know for the *i*-th trolleybus that ... | The first input line contains three space-separated integers *n*, *a*, *d* (1<=≤<=*n*<=≤<=105, 1<=≤<=*a*,<=*d*<=≤<=106) — the number of trolleybuses, their maximum acceleration and the distance from the depot to the final station, correspondingly.
Next *n* lines contain pairs of integers *t**i* *v**i* (0<=≤<=*t*1<=<... | For each trolleybus print a single line the time it arrives to the final station. Print the times for the trolleybuses in the order in which the trolleybuses are given in the input. The answer will be accepted if the absolute or relative error doesn't exceed 10<=-<=4. | [
"3 10 10000\n0 10\n5 11\n1000 1\n",
"1 2 26\n28 29\n"
] | [
"1000.5000000000\n1000.5000000000\n11000.0500000000\n",
"33.0990195136\n"
] | In the first sample the second trolleybus will catch up with the first one, that will happen at distance 510.5 meters from the depot. The trolleybuses will go the remaining 9489.5 meters together at speed 10 meters per second. As a result, both trolleybuses will arrive to the final station by the moment of time 1000.5 ... | 500 | [
{
"input": "3 10 10000\n0 10\n5 11\n1000 1",
"output": "1000.5000000000\n1000.5000000000\n11000.0500000000"
},
{
"input": "1 2 26\n28 29",
"output": "33.0990195136"
},
{
"input": "7 8 3\n1 3\n5 26\n7 3\n10 15\n18 7\n21 17\n23 21",
"output": "2.1875000000\n5.8660254038\n8.1875000000\n... | 1,687,967,939 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 57 | 312 | 11,673,600 | import sys
input = lambda: sys.stdin.readline().rstrip()
import math
N,A,D = map(int, input().split())
pre = 0
for _ in range(N):
t,v = map(int, input().split())
# 到达最高速度需要的时间
t1 = v/A
# 加速时间段行走距离(已知时间和加速度求距离)
d1 = t1*(t1*A/2)
# 能加到全速
if d1<=D:
# 剩下距离需要的时间
... | Title: Wizards and Trolleybuses
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some country live wizards. They love to ride trolleybuses.
A city in this country has a trolleybus depot with *n* trolleybuses. Every day the trolleybuses leave the depot, one by one and go to the final sta... | ```python
import sys
input = lambda: sys.stdin.readline().rstrip()
import math
N,A,D = map(int, input().split())
pre = 0
for _ in range(N):
t,v = map(int, input().split())
# 到达最高速度需要的时间
t1 = v/A
# 加速时间段行走距离(已知时间和加速度求距离)
d1 = t1*(t1*A/2)
# 能加到全速
if d1<=D:
# ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,697,301,636 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | s=str(input())
alphabets_upper='ABCDEFGHIJKLMNOPQRSTUVWXYZ'
alphabets_lower='abcdefghijklmnopqrstuvwxyz'
new_str=''
if s[0] in alphabets_upper:
print(s)
else:
index=alphabets_lower.index(s[0])
new_=alphabets_upper[index]
new_str = new_
for i in range (1,len(s)):
new_str+=s[i]
print(new_s... | Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
s=str(input())
alphabets_upper='ABCDEFGHIJKLMNOPQRSTUVWXYZ'
alphabets_lower='abcdefghijklmnopqrstuvwxyz'
new_str=''
if s[0] in alphabets_upper:
print(s)
else:
index=alphabets_lower.index(s[0])
new_=alphabets_upper[index]
new_str = new_
for i in range (1,len(s)):
new_str+=s[i]
p... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
707 | C | Pythagorean Triples | PROGRAMMING | 1,500 | [
"math",
"number theory"
] | null | null | Katya studies in a fifth grade. Recently her class studied right triangles and the Pythagorean theorem. It appeared, that there are triples of positive integers such that you can construct a right triangle with segments of lengths corresponding to triple. Such triples are called Pythagorean triples.
For example, tripl... | The only line of the input contains single integer *n* (1<=≤<=*n*<=≤<=109) — the length of some side of a right triangle. | Print two integers *m* and *k* (1<=≤<=*m*,<=*k*<=≤<=1018), such that *n*, *m* and *k* form a Pythagorean triple, in the only line.
In case if there is no any Pythagorean triple containing integer *n*, print <=-<=1 in the only line. If there are many answers, print any of them. | [
"3\n",
"6\n",
"1\n",
"17\n",
"67\n"
] | [
"4 5",
"8 10",
"-1",
"144 145",
"2244 2245"
] | Illustration for the first sample. | 1,500 | [
{
"input": "3",
"output": "4 5"
},
{
"input": "6",
"output": "8 10"
},
{
"input": "1",
"output": "-1"
},
{
"input": "17",
"output": "144 145"
},
{
"input": "67",
"output": "2244 2245"
},
{
"input": "10",
"output": "24 26"
},
{
"input": "14"... | 1,679,366,414 | 2,147,483,647 | Python 3 | OK | TESTS | 90 | 46 | 0 | import sys
input = lambda: sys.stdin.readline().strip()
n=int(input())
if n<3: print(-1)
elif n%2==0: print(((n//2)**2)-1,((n//2)**2)+1)
elif (n%3==0) or (n%4==0) or (n%5==0):
if n%3==0: print((n//3)*4,(n//3)*5)
elif n%4==0: print((n//4)*3,(n//4)*5)
else: print((n//5)*3,(n//5)*4)
else: print(((n**2... | Title: Pythagorean Triples
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Katya studies in a fifth grade. Recently her class studied right triangles and the Pythagorean theorem. It appeared, that there are triples of positive integers such that you can construct a right triangle with segm... | ```python
import sys
input = lambda: sys.stdin.readline().strip()
n=int(input())
if n<3: print(-1)
elif n%2==0: print(((n//2)**2)-1,((n//2)**2)+1)
elif (n%3==0) or (n%4==0) or (n%5==0):
if n%3==0: print((n//3)*4,(n//3)*5)
elif n%4==0: print((n//4)*3,(n//4)*5)
else: print((n//5)*3,(n//5)*4)
else: pr... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,607,010,897 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 0 | n=int(input())
l=[int(i) for i in input().split]
l.sort()
h=1
t=1
c=1
for i in range(1,len(l)):
if(l[i]==l[i-1]):
c=c+1
h=max(c,h)
else:
t=t+1
c=1
print(h,t) | Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
n=int(input())
l=[int(i) for i in input().split]
l.sort()
h=1
t=1
c=1
for i in range(1,len(l)):
if(l[i]==l[i-1]):
c=c+1
h=max(c,h)
else:
t=t+1
c=1
print(h,t)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
713 | A | Sonya and Queries | PROGRAMMING | 1,400 | [
"data structures",
"implementation"
] | null | null | Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her *t* queries, each of one of the following type:
1. <=+<= *a**i* — add non-negative integer *a**i* to the multiset. Note, that she has a multiset, thus there may b... | The first line of the input contains an integer *t* (1<=≤<=*t*<=≤<=100<=000) — the number of operation Sonya has to perform.
Next *t* lines provide the descriptions of the queries in order they appear in the input file. The *i*-th row starts with a character *c**i* — the type of the corresponding operation. If *c**i* ... | For each query of the third type print the number of integers matching the given pattern. Each integer is counted as many times, as it appears in the multiset at this moment of time. | [
"12\n+ 1\n+ 241\n? 1\n+ 361\n- 241\n? 0101\n+ 101\n? 101\n- 101\n? 101\n+ 4000\n? 0\n",
"4\n+ 200\n+ 200\n- 200\n? 0\n"
] | [
"2\n1\n2\n1\n1\n",
"1\n"
] | Consider the integers matching the patterns from the queries of the third type. Queries are numbered in the order they appear in the input.
1. 1 and 241. 1. 361. 1. 101 and 361. 1. 361. 1. 4000. | 500 | [
{
"input": "12\n+ 1\n+ 241\n? 1\n+ 361\n- 241\n? 0101\n+ 101\n? 101\n- 101\n? 101\n+ 4000\n? 0",
"output": "2\n1\n2\n1\n1"
},
{
"input": "4\n+ 200\n+ 200\n- 200\n? 0",
"output": "1"
},
{
"input": "20\n+ 61\n+ 99\n+ 51\n+ 70\n+ 7\n+ 34\n+ 71\n+ 86\n+ 68\n+ 39\n+ 78\n+ 81\n+ 89\n? 10\n? 00... | 1,618,120,951 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 109 | 0 | t = int(input())
zero, one = 20 * [0], 20 * [0]
for iter in range(t):
oper, num = [str(j) for j in input().split()]
while len(num) < 20:
num = '0' + num
if oper == '+':
for s_iter in range(20):
n = ord(num[s_iter])
if n % 2 == 0:
zero[s_iter]... | Title: Sonya and Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her *t* queries, each of one of the following type:
1. <=+<= *a... | ```python
t = int(input())
zero, one = 20 * [0], 20 * [0]
for iter in range(t):
oper, num = [str(j) for j in input().split()]
while len(num) < 20:
num = '0' + num
if oper == '+':
for s_iter in range(20):
n = ord(num[s_iter])
if n % 2 == 0:
ze... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,630,767,123 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 154 | 6,758,400 | l, w = list(map(int, input().split()))
area = l*w
dominos = 0
while 1:
if area <= 1:
break
area = area - 2
dominos = dominos+1
print(dominos)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
l, w = list(map(int, input().split()))
area = l*w
dominos = 0
while 1:
if area <= 1:
break
area = area - 2
dominos = dominos+1
print(dominos)
``` | 3.948911 | MatrixStudio/Codeforces-Python-Submissions |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,692,376,150 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<stdio.h>
void main()
{
int n;
scanf("%d",&n);
char s[n+1];
scanf("%s",s);
int c1=0,c2=0;
for(int i=0;i<n;i++){
if(s[i]=='A'){
c1++;
}
else{
c2++;
}
}
if(c1>c2){
printf("ANTON");
else{
... | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
#include<stdio.h>
void main()
{
int n;
scanf("%d",&n);
char s[n+1];
scanf("%s",s);
int c1=0,c2=0;
for(int i=0;i<n;i++){
if(s[i]=='A'){
c1++;
}
else{
c2++;
}
}
if(c1>c2){
printf("ANTON");
else{... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
629 | B | Far Relative’s Problem | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Famil Door wants to celebrate his birthday with his friends from Far Far Away. He has *n* friends and each of them can come to the party in a specific range of days of the year from *a**i* to *b**i*. Of course, Famil Door wants to have as many friends celebrating together with him as possible.
Far cars are as weird as... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=5000) — then number of Famil Door's friends.
Then follow *n* lines, that describe the friends. Each line starts with a capital letter 'F' for female friends and with a capital letter 'M' for male friends. Then follow two integers *a**i* and *b**i... | Print the maximum number of people that may come to Famil Door's party. | [
"4\nM 151 307\nF 343 352\nF 117 145\nM 24 128\n",
"6\nM 128 130\nF 128 131\nF 131 140\nF 131 141\nM 131 200\nM 140 200\n"
] | [
"2\n",
"4\n"
] | In the first sample, friends 3 and 4 can come on any day in range [117, 128].
In the second sample, friends with indices 3, 4, 5 and 6 can come on day 140. | 1,000 | [
{
"input": "4\nM 151 307\nF 343 352\nF 117 145\nM 24 128",
"output": "2"
},
{
"input": "6\nM 128 130\nF 128 131\nF 131 140\nF 131 141\nM 131 200\nM 140 200",
"output": "4"
},
{
"input": "1\nF 68 307",
"output": "0"
},
{
"input": "40\nM 55 363\nF 117 252\nM 157 282\nF 322 345\... | 1,455,992,593 | 6,493 | Python 3 | RUNTIME_ERROR | PRETESTS | 2 | 46 | 512,000 | import re
n = int(input())
list = [[0,0] for i in range(366)]
for i in range(n):
s = input()
lis = re.split(r'[\s]', s)
ch = lis[0]
a = int(lis[1])
b = int(lis[2])
for j in range(b - a + 1):
if ch == "M":
list[j+a][0] += 1
else:
list[j+a][... | Title: Far Relative’s Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Famil Door wants to celebrate his birthday with his friends from Far Far Away. He has *n* friends and each of them can come to the party in a specific range of days of the year from *a**i* to *b**i*. Of course, F... | ```python
import re
n = int(input())
list = [[0,0] for i in range(366)]
for i in range(n):
s = input()
lis = re.split(r'[\s]', s)
ch = lis[0]
a = int(lis[1])
b = int(lis[2])
for j in range(b - a + 1):
if ch == "M":
list[j+a][0] += 1
else:
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
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