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values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
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value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
349 | A | Cinema Line | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. | Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". | [
"4\n25 25 50 50\n",
"2\n25 100\n",
"4\n50 50 25 25\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "4\n25 25 50 50",
"output": "YES"
},
{
"input": "2\n25 100",
"output": "NO"
},
{
"input": "4\n50 50 25 25",
"output": "NO"
},
{
"input": "3\n25 50 100",
"output": "NO"
},
{
"input": "10\n25 25 25 25 25 25 25 25 25 25",
"output": "YES"
},
{
"... | 1,641,233,142 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 404 | 12,800,000 | n=int(input())
lst=list(map(int,input().split(' ')))
mon={}
mon[25]=0
mon[50]=0
flag=True
for i in lst:
if i==25:
mon[25]+=1
if i==50:
mon[25] -=1
if mon[25]<0:
flag=False
break
mon[50]+=1
if i==100:
if mon[50]>0:
i... | Title: Cinema Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the bookin... | ```python
n=int(input())
lst=list(map(int,input().split(' ')))
mon={}
mon[25]=0
mon[50]=0
flag=True
for i in lst:
if i==25:
mon[25]+=1
if i==50:
mon[25] -=1
if mon[25]<0:
flag=False
break
mon[50]+=1
if i==100:
if mon[50]>0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,647,419,084 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n=int(input())
s=sum(list(map(int,input().split())))
k=0
for i in range(5):
if (s+i)%(n+1)!=0:
k=k+1
print(k) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
n=int(input())
s=sum(list(map(int,input().split())))
k=0
for i in range(5):
if (s+i)%(n+1)!=0:
k=k+1
print(k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,643,446,482 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 92 | 0 | x,y,z=map(int,input().split())
import math
print(int((z*math.gcd(x,y))/(x*y))) | Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
x,y,z=map(int,input().split())
import math
print(int((z*math.gcd(x,y))/(x*y)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,672,235,141 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | length = int(input())
numbers = list(map(int,input().split(" ")))
num_even = [i%2 for i in numbers]
if sum(num_even) == 1:
print(num_even.index(1)+1)
else:
print(num_even.index(0)+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
length = int(input())
numbers = list(map(int,input().split(" ")))
num_even = [i%2 for i in numbers]
if sum(num_even) == 1:
print(num_even.index(1)+1)
else:
print(num_even.index(0)+1)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,698,770,267 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | import math
t = int(input())
for i in range(t):
n = int(input())
sum = (n * (n+1)) / 2
sum -= 2 * (math.pow(2, int(math.log2(n)) + 1) - 1)
print(int(sum))
| Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, be... | ```python
import math
t = int(input())
for i in range(t):
n = int(input())
sum = (n * (n+1)) / 2
sum -= 2 * (math.pow(2, int(math.log2(n)) + 1) - 1)
print(int(sum))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,669,754,384 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 46 | 0 | n = input()
s = input().split()
total = 0
for i in s:
t = 0
for j in i:
if j.isupper():
t += 1
if total < t:
total = t
print(total) | Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
n = input()
s = input().split()
total = 0
for i in s:
t = 0
for j in i:
if j.isupper():
t += 1
if total < t:
total = t
print(total)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
146 | A | Lucky Ticket | PROGRAMMING | 800 | [
"implementation"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya loves tickets very much. As we know, each ticket has a number that is a positive integer. It... | The first line contains an even integer *n* (2<=≤<=*n*<=≤<=50) — the length of the ticket number that needs to be checked. The second line contains an integer whose length equals exactly *n* — the ticket number. The number may contain leading zeros. | On the first line print "YES" if the given ticket number is lucky. Otherwise, print "NO" (without the quotes). | [
"2\n47\n",
"4\n4738\n",
"4\n4774\n"
] | [
"NO\n",
"NO\n",
"YES\n"
] | In the first sample the sum of digits in the first half does not equal the sum of digits in the second half (4 ≠ 7).
In the second sample the ticket number is not the lucky number. | 500 | [
{
"input": "2\n47",
"output": "NO"
},
{
"input": "4\n4738",
"output": "NO"
},
{
"input": "4\n4774",
"output": "YES"
},
{
"input": "4\n4570",
"output": "NO"
},
{
"input": "6\n477477",
"output": "YES"
},
{
"input": "6\n777777",
"output": "YES"
},
... | 1,640,400,758 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | n = int(input())
number = input()
number = list(number)
def solve(n , number) :
sum1 = 0
sum2 = 0
print(number)
for i in range(int(n / 2)):
if number[i] != '4' and number[i] != '7' :
return "NO"
sum1 += int(number[i])
for i in range(int(n/2) , n ):
... | Title: Lucky Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
number = input()
number = list(number)
def solve(n , number) :
sum1 = 0
sum2 = 0
print(number)
for i in range(int(n / 2)):
if number[i] != '4' and number[i] != '7' :
return "NO"
sum1 += int(number[i])
for i in range(int(n/2) , n... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,626,261,337 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 77 | 6,758,400 | n = input()
k = input()
a =''
for i , j in zip(n , k):
if i == j :
a+='0'
else:
a+='1'
print(a)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
n = input()
k = input()
a =''
for i , j in zip(n , k):
if i == j :
a+='0'
else:
a+='1'
print(a)
``` | 3.968161 | MatrixStudio/Codeforces-Python-Submissions |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,694,162,369 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = int(input())
s = [int(i) for i in input().split()]
s.sort(reverse=True)
half = sum(s) / 2
counter_1, counter_2 = 0, 0
for i in s:
counter_1 += i
counter_2 += 1
if counter > half:
print(counter_2)
else:
continue | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
n = int(input())
s = [int(i) for i in input().split()]
s.sort(reverse=True)
half = sum(s) / 2
counter_1, counter_2 = 0, 0
for i in s:
counter_1 += i
counter_2 += 1
if counter > half:
print(counter_2)
else:
continue
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,690,049,133 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | m,n=map(int,input().split())
count=(m*n)//2
print(count)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
m,n=map(int,input().split())
count=(m*n)//2
print(count)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,648,306,791 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 62 | 3,481,600 | n,m,z=map(int,input().split())
st1=set()
st2=set()
x,y=n,m
while x<=z:
st1.add(x);x+=n
while y<=z:
st2.add(y);y+=m
print(len(st1&st2)) | Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
n,m,z=map(int,input().split())
st1=set()
st2=set()
x,y=n,m
while x<=z:
st1.add(x);x+=n
while y<=z:
st2.add(y);y+=m
print(len(st1&st2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
690 | D1 | The Wall (easy) | PROGRAMMING | 1,200 | [] | null | null | "The zombies are lurking outside. Waiting. Moaning. And when they come..."
"When they come?"
"I hope the Wall is high enough."
Zombie attacks have hit the Wall, our line of defense in the North. Its protection is failing, and cracks are showing. In places, gaps have appeared, splitting the wall into multiple segment... | The first line of the input consists of two space-separated integers *R* and *C*, 1<=≤<=*R*,<=*C*<=≤<=100. The next *R* lines provide a description of the columns as follows:
- each of the *R* lines contains a string of length *C*, - the *c*-th character of line *r* is B if there is a brick in column *c* and row *R... | The number of wall segments in the input configuration. | [
"3 7\n.......\n.......\n.BB.B..\n",
"4 5\n..B..\n..B..\nB.B.B\nBBB.B\n",
"4 6\n..B...\nB.B.BB\nBBB.BB\nBBBBBB\n",
"1 1\nB\n",
"10 7\n.......\n.......\n.......\n.......\n.......\n.......\n.......\n.......\n...B...\nB.BB.B.\n",
"8 8\n........\n........\n........\n........\n.B......\n.B.....B\n.B.....B\n.BB.... | [
"2\n",
"2\n",
"1\n",
"1\n",
"3\n",
"2\n"
] | In the first sample case, the 2nd and 3rd columns define the first wall segment, and the 5th column defines the second. | 0 | [
{
"input": "3 7\n.......\n.......\n.BB.B..",
"output": "2"
},
{
"input": "4 5\n..B..\n..B..\nB.B.B\nBBB.B",
"output": "2"
},
{
"input": "4 6\n..B...\nB.B.BB\nBBB.BB\nBBBBBB",
"output": "1"
},
{
"input": "1 1\nB",
"output": "1"
},
{
"input": "10 7\n.......\n.......... | 1,468,160,299 | 2,147,483,647 | Python 3 | OK | TESTS | 119 | 62 | 0 | n,m=map(int,input().split())
for i in range(n):
k=input()
f=1
ans=0
for i in k:
if i=='B' and f:
ans+=1
f=0
if i=='.':
f=1
print(ans) | Title: The Wall (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"The zombies are lurking outside. Waiting. Moaning. And when they come..."
"When they come?"
"I hope the Wall is high enough."
Zombie attacks have hit the Wall, our line of defense in the North. Its protection is fai... | ```python
n,m=map(int,input().split())
for i in range(n):
k=input()
f=1
ans=0
for i in k:
if i=='B' and f:
ans+=1
f=0
if i=='.':
f=1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,699,288,674 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 39 | 92 | 0 | v = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47]
n, m = map(int, input().split())
k = v.index(n)
if v[k+1]==m:
print("YES")
else:
print("NO") | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
v = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47]
n, m = map(int, input().split())
k = v.index(n)
if v[k+1]==m:
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,658,484,285 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 102,400 | n=int(input())
m=int(input())
power=1
for i in range(1,n+1):
power=power*2
print(m%power) | Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
n=int(input())
m=int(input())
power=1
for i in range(1,n+1):
power=power*2
print(m%power)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
859 | B | Lazy Security Guard | PROGRAMMING | 1,000 | [
"brute force",
"geometry",
"math"
] | null | null | Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is, your friend must walk the perimeter of a region whose area is exactly *N* blocks. Your friend is quite ... | Input will consist of a single integer *N* (1<=≤<=*N*<=≤<=106), the number of city blocks that must be enclosed by the route. | Print the minimum perimeter that can be achieved. | [
"4\n",
"11\n",
"22\n"
] | [
"8\n",
"14\n",
"20\n"
] | Here are some possible shapes for the examples:
<img class="tex-graphics" src="https://espresso.codeforces.com/e11bef2cf82b55dd583cfc97d12b5aee5e483a65.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 750 | [
{
"input": "4",
"output": "8"
},
{
"input": "11",
"output": "14"
},
{
"input": "22",
"output": "20"
},
{
"input": "3",
"output": "8"
},
{
"input": "1024",
"output": "128"
},
{
"input": "101",
"output": "42"
},
{
"input": "30",
"output":... | 1,542,144,533 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 109 | 0 | n=int(input())
num=int(pow(n,0.5))
ans=4*num
#print(ans)
if n-num*num:
diff=n-num*num
div=diff//num
if diff%num==0:
print(ans+2*div)
else:
print(ans+2*div+2)
else:
print(ans) | Title: Lazy Security Guard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is... | ```python
n=int(input())
num=int(pow(n,0.5))
ans=4*num
#print(ans)
if n-num*num:
diff=n-num*num
div=diff//num
if diff%num==0:
print(ans+2*div)
else:
print(ans+2*div+2)
else:
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,695,056,506 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 62 | 0 | n = int(input())
b = 1
n += 1
while ("8" not in str(n)):
n += 1
b += 1
print(b) | Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
n = int(input())
b = 1
n += 1
while ("8" not in str(n)):
n += 1
b += 1
print(b)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,467,763,637 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | enteros = input()
#n es número de vendedores
#v cantidad de dinero de Valera
n, v = enteros.split()
n = int(n)
v = int(v)
#print("n", n, "v", v)
resultado = []
for i in range(n):
datos = input().split()
datos = [int(x) for x in datos]
indice = datos[0]
for j in datos[1:]:
if j < 50000:
... | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
enteros = input()
#n es número de vendedores
#v cantidad de dinero de Valera
n, v = enteros.split()
n = int(n)
v = int(v)
#print("n", n, "v", v)
resultado = []
for i in range(n):
datos = input().split()
datos = [int(x) for x in datos]
indice = datos[0]
for j in datos[1:]:
if j < 50000:... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
507 | A | Amr and Music | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"sortings"
] | null | null | Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for ... | The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument. | In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use al... | [
"4 10\n4 3 1 2\n",
"5 6\n4 3 1 1 2\n",
"1 3\n4\n"
] | [
"4\n1 2 3 4",
"3\n1 3 4",
"0\n"
] | In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | 500 | [
{
"input": "4 10\n4 3 1 2",
"output": "4\n1 2 3 4"
},
{
"input": "5 6\n4 3 1 1 2",
"output": "3\n3 4 5"
},
{
"input": "1 3\n4",
"output": "0"
},
{
"input": "2 100\n100 100",
"output": "1\n1"
},
{
"input": "3 150\n50 50 50",
"output": "3\n1 2 3"
},
{
"i... | 1,607,324,177 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 307,200 | n ,days = map(int, input().split())
arr = list(map(int, input().split()))
key = list(range(1,n+1))
dict1 = dict(zip(key, arr))
sorted_tuples = sorted(dict1.items(), key=lambda item: item[1])
sorted_dict = {k: v for k, v in sorted_tuples}
tot = 0
ans = list()
for k,v in sorted_dict.items():
if (days-v)>=0:
... | Title: Amr and Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr ... | ```python
n ,days = map(int, input().split())
arr = list(map(int, input().split()))
key = list(range(1,n+1))
dict1 = dict(zip(key, arr))
sorted_tuples = sorted(dict1.items(), key=lambda item: item[1])
sorted_dict = {k: v for k, v in sorted_tuples}
tot = 0
ans = list()
for k,v in sorted_dict.items():
if (da... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,698,571,475 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 46 | 614,400 | #https://codeforces.com/contest/734/problem/A
from collections import Counter
n = input()
str = input()
str = Counter(str)
if(str['A'] == str['D']):
print('Friendship')
elif(str['A'] > str['D']):
print('Anton')
else:
print('Danik') | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
#https://codeforces.com/contest/734/problem/A
from collections import Counter
n = input()
str = input()
str = Counter(str)
if(str['A'] == str['D']):
print('Friendship')
elif(str['A'] > str['D']):
print('Anton')
else:
print('Danik')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
616 | A | Comparing Two Long Integers | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can r... | The first line contains a non-negative integer *a*.
The second line contains a non-negative integer *b*.
The numbers *a*,<=*b* may contain leading zeroes. Each of them contains no more than 106 digits. | Print the symbol "<" if *a*<=<<=*b* and the symbol ">" if *a*<=><=*b*. If the numbers are equal print the symbol "=". | [
"9\n10\n",
"11\n10\n",
"00012345\n12345\n",
"0123\n9\n",
"0123\n111\n"
] | [
"<\n",
">\n",
"=\n",
">\n",
">\n"
] | none | 0 | [
{
"input": "9\n10",
"output": "<"
},
{
"input": "11\n10",
"output": ">"
},
{
"input": "00012345\n12345",
"output": "="
},
{
"input": "0123\n9",
"output": ">"
},
{
"input": "0123\n111",
"output": ">"
},
{
"input": "9\n9",
"output": "="
},
{
... | 1,594,520,004 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 202 | 22,220,800 | n1 = list(input())
n2 = list(input())
while len(n1) and n1[0]=="0":
n1.remove("0")
while len(n2) and n2[0]=="0":
n2.remove("0")
if len(n1)>len(n1):
print(">")
elif len(n1)<len(n2):
print("<")
else:
i=0
while int(n1[i])==int(n2[i]):
i+=1
if i==len(n1):
print("="... | Title: Comparing Two Long Integers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use th... | ```python
n1 = list(input())
n2 = list(input())
while len(n1) and n1[0]=="0":
n1.remove("0")
while len(n2) and n2[0]=="0":
n2.remove("0")
if len(n1)>len(n1):
print(">")
elif len(n1)<len(n2):
print("<")
else:
i=0
while int(n1[i])==int(n2[i]):
i+=1
if i==len(n1):
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
676 | C | Vasya and String | PROGRAMMING | 1,500 | [
"binary search",
"dp",
"strings",
"two pointers"
] | null | null | High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequence) consisting of equal letters.
Vasya can change no more than *k* characters of the original strin... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000,<=0<=≤<=*k*<=≤<=*n*) — the length of the string and the maximum number of characters to change.
The second line contains the string, consisting of letters 'a' and 'b' only. | Print the only integer — the maximum beauty of the string Vasya can achieve by changing no more than *k* characters. | [
"4 2\nabba\n",
"8 1\naabaabaa\n"
] | [
"4\n",
"5\n"
] | In the first sample, Vasya can obtain both strings "aaaa" and "bbbb".
In the second sample, the optimal answer is obtained with the string "aaaaabaa" or with the string "aabaaaaa". | 1,500 | [
{
"input": "4 2\nabba",
"output": "4"
},
{
"input": "8 1\naabaabaa",
"output": "5"
},
{
"input": "1 0\na",
"output": "1"
},
{
"input": "1 1\nb",
"output": "1"
},
{
"input": "1 0\nb",
"output": "1"
},
{
"input": "1 1\na",
"output": "1"
},
{
... | 1,689,644,247 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 2 | 62 | 2,867,200 | def II():
return(int(input()))
def LMI():
return(list(map(int,input().split())))
def I():
return(input())
def MII():
return(map(int,input().split()))
import sys
input=sys.stdin.readline
# import io,os
# input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
# from collections import Cou... | Title: Vasya and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequ... | ```python
def II():
return(int(input()))
def LMI():
return(list(map(int,input().split())))
def I():
return(input())
def MII():
return(map(int,input().split()))
import sys
input=sys.stdin.readline
# import io,os
# input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
# from collections ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
803 | C | Maximal GCD | PROGRAMMING | 1,900 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Greatest common divisor of sequence is maximum of such numbers that every element of sequence is divi... | The first line consists of two numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1010). | If the answer exists then output *k* numbers — resulting sequence. Otherwise output -1. If there are multiple answers, print any of them. | [
"6 3\n",
"8 2\n",
"5 3\n"
] | [
"1 2 3\n",
"2 6\n",
"-1\n"
] | none | 0 | [
{
"input": "6 3",
"output": "1 2 3"
},
{
"input": "8 2",
"output": "2 6"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "2 1",
"output": "2"
},
{
"input": "2 10000000... | 1,595,621,569 | 3,769 | PyPy 3 | WRONG_ANSWER | TESTS | 20 | 140 | 20,172,800 | n, k = map(int, input().split())
if (k == 1):
print(n)
else:
left = 1
right = n
ans = -1
while (left <= right):
mid = left + (right - left)//2
ss = mid * k * (k+1)//2
if (ss <= n):
left = mid+1
ans = mid
resto = n - ss
else:
... | Title: Maximal GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Grea... | ```python
n, k = map(int, input().split())
if (k == 1):
print(n)
else:
left = 1
right = n
ans = -1
while (left <= right):
mid = left + (right - left)//2
ss = mid * k * (k+1)//2
if (ss <= n):
left = mid+1
ans = mid
resto = n - ss
el... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,690,305,733 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 108 | 1,638,400 | listX = list(map(int,input().split(" ")))
n = listX[0]
k = listX[1]
listA = list(map(int,input().split(" ")))
value = 5-k
count = 0
for a in listA:
if a in range(0,value+1):
count+=1
ans = count//3
print(ans) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
listX = list(map(int,input().split(" ")))
n = listX[0]
k = listX[1]
listA = list(map(int,input().split(" ")))
value = 5-k
count = 0
for a in listA:
if a in range(0,value+1):
count+=1
ans = count//3
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
796 | B | Find The Bone | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Zane the wizard is going to perform a magic show shuffling the cups.
There are *n* cups, numbered from 1 to *n*, placed along the *x*-axis on a table that has *m* holes on it. More precisely, cup *i* is on the table at the position *x*<==<=*i*.
The problematic bone is initially at the position *x*<==<=1. Zane will co... | The first line contains three integers *n*, *m*, and *k* (2<=≤<=*n*<=≤<=106, 1<=≤<=*m*<=≤<=*n*, 1<=≤<=*k*<=≤<=3·105) — the number of cups, the number of holes on the table, and the number of swapping operations, respectively.
The second line contains *m* distinct integers *h*1,<=*h*2,<=...,<=*h**m* (1<=≤<=*h**i*<=≤<=*... | Print one integer — the final position along the *x*-axis of the bone. | [
"7 3 4\n3 4 6\n1 2\n2 5\n5 7\n7 1\n",
"5 1 2\n2\n1 2\n2 4\n"
] | [
"1",
"2"
] | In the first sample, after the operations, the bone becomes at *x* = 2, *x* = 5, *x* = 7, and *x* = 1, respectively.
In the second sample, after the first operation, the bone becomes at *x* = 2, and falls into the hole onto the ground. | 750 | [
{
"input": "7 3 4\n3 4 6\n1 2\n2 5\n5 7\n7 1",
"output": "1"
},
{
"input": "5 1 2\n2\n1 2\n2 4",
"output": "2"
},
{
"input": "10000 1 9\n55\n44 1\n2929 9292\n9999 9998\n44 55\n49 94\n55 53\n100 199\n55 50\n53 11",
"output": "55"
},
{
"input": "100000 3 7\n2 3 4\n1 5\n5 1\n1 5... | 1,613,812,257 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 1,278 | 72,192,000 | import sys
def ints_input():
return [int(i) for i in sys.stdin.readline().strip("\n").split(" ")]
def print_list(arr):
sys.stdout.writelines(str(x)+" " for x in arr)
sys.stdout.write("\n")
def fast_input(type=str):
return type(sys.stdin.readline().strip("\n"))
n, m ,k = ints_input(... | Title: Find The Bone
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Zane the wizard is going to perform a magic show shuffling the cups.
There are *n* cups, numbered from 1 to *n*, placed along the *x*-axis on a table that has *m* holes on it. More precisely, cup *i* is on the table at t... | ```python
import sys
def ints_input():
return [int(i) for i in sys.stdin.readline().strip("\n").split(" ")]
def print_list(arr):
sys.stdout.writelines(str(x)+" " for x in arr)
sys.stdout.write("\n")
def fast_input(type=str):
return type(sys.stdin.readline().strip("\n"))
n, m ,k = i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
508 | B | Anton and currency you all know | PROGRAMMING | 1,300 | [
"greedy",
"math",
"strings"
] | null | null | Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed to be an integer.
Reliable sources have informed the financier Anton of some information about the exchange rate of... | The first line contains an odd positive integer *n* — the exchange rate of currency you all know for today. The length of number *n*'s representation is within range from 2 to 105, inclusive. The representation of *n* doesn't contain any leading zeroes. | If the information about tomorrow's exchange rate is inconsistent, that is, there is no integer that meets the condition, print <=-<=1.
Otherwise, print the exchange rate of currency you all know against the burle for tomorrow. This should be the maximum possible number of those that are even and that are obtained fro... | [
"527\n",
"4573\n",
"1357997531\n"
] | [
"572\n",
"3574\n",
"-1\n"
] | none | 1,000 | [
{
"input": "527",
"output": "572"
},
{
"input": "4573",
"output": "3574"
},
{
"input": "1357997531",
"output": "-1"
},
{
"input": "444443",
"output": "444434"
},
{
"input": "22227",
"output": "72222"
},
{
"input": "24683",
"output": "34682"
},
... | 1,670,340,368 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 58 | 77 | 7,270,400 | import os
import sys
import math
from io import BytesIO, IOBase
def binaryexponent(a,n):
if n==1:
return a
if n%2==0:
return binaryexponent(a,n//2)*binaryexponent(a,n//2)
else:
return a*binaryexponent(a,(n-1)//2)*binaryexponent(a,(n-1)//2)
def binaryexpMatrix(L,n):
... | Title: Anton and currency you all know
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed... | ```python
import os
import sys
import math
from io import BytesIO, IOBase
def binaryexponent(a,n):
if n==1:
return a
if n%2==0:
return binaryexponent(a,n//2)*binaryexponent(a,n//2)
else:
return a*binaryexponent(a,(n-1)//2)*binaryexponent(a,(n-1)//2)
def binaryexpMatrix(L... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,563,399,980 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 248 | 0 | n = int(input())
teams = []
for i in range(n):
teams.append(input())
unique_teams = list(set(teams))
first = unique_teams[0]
second = '' if len(unique_teams) < 2 else unique_teams[1]
f_c, s_c = 0, 0
for i in range(n):
if teams[i] == first:
f_c += 1
else:
s_c += 1
if f_c > s_c:
... | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
n = int(input())
teams = []
for i in range(n):
teams.append(input())
unique_teams = list(set(teams))
first = unique_teams[0]
second = '' if len(unique_teams) < 2 else unique_teams[1]
f_c, s_c = 0, 0
for i in range(n):
if teams[i] == first:
f_c += 1
else:
s_c += 1
if f_... | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
616 | A | Comparing Two Long Integers | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can r... | The first line contains a non-negative integer *a*.
The second line contains a non-negative integer *b*.
The numbers *a*,<=*b* may contain leading zeroes. Each of them contains no more than 106 digits. | Print the symbol "<" if *a*<=<<=*b* and the symbol ">" if *a*<=><=*b*. If the numbers are equal print the symbol "=". | [
"9\n10\n",
"11\n10\n",
"00012345\n12345\n",
"0123\n9\n",
"0123\n111\n"
] | [
"<\n",
">\n",
"=\n",
">\n",
">\n"
] | none | 0 | [
{
"input": "9\n10",
"output": "<"
},
{
"input": "11\n10",
"output": ">"
},
{
"input": "00012345\n12345",
"output": "="
},
{
"input": "0123\n9",
"output": ">"
},
{
"input": "0123\n111",
"output": ">"
},
{
"input": "9\n9",
"output": "="
},
{
... | 1,635,448,883 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 77 | 17,715,200 | a = str(input())
b = str(input())
def strip(s):
first = 1
for i in range(len(s)):
if s[i] != '0':
first = i + 1
break
return first
if strip(a) != 1:
a = a[(strip(a) - 1):]
if strip(b) != 1:
b = b[(strip(b) - 1):]
if len(a) < len(b):
print('<')
elif len(a) > len(b):
print('>')
else:... | Title: Comparing Two Long Integers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use th... | ```python
a = str(input())
b = str(input())
def strip(s):
first = 1
for i in range(len(s)):
if s[i] != '0':
first = i + 1
break
return first
if strip(a) != 1:
a = a[(strip(a) - 1):]
if strip(b) != 1:
b = b[(strip(b) - 1):]
if len(a) < len(b):
print('<')
elif len(a) > len(b):
print('... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
63 | A | Sinking Ship | PROGRAMMING | 900 | [
"implementation",
"sortings",
"strings"
] | A. Sinking Ship | 2 | 256 | The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to *n*) and await further instructions. However, one should evacuate the crew properly, in a stri... | The first line contains an integer *n*, which is the number of people in the crew (1<=≤<=*n*<=≤<=100). Then follow *n* lines. The *i*-th of those lines contains two words — the name of the crew member who is *i*-th in line, and his status on the ship. The words are separated by exactly one space. There are no other spa... | Print *n* lines. The *i*-th of them should contain the name of the crew member who must be the *i*-th one to leave the ship. | [
"6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman\n"
] | [
"Teddy\nAlice\nBob\nJulia\nCharlie\nJack\n"
] | none | 500 | [
{
"input": "6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman",
"output": "Teddy\nAlice\nBob\nJulia\nCharlie\nJack"
},
{
"input": "1\nA captain",
"output": "A"
},
{
"input": "1\nAbcdefjhij captain",
"output": "Abcdefjhij"
},
{
"input": "5\nA captain... | 1,604,408,937 | 2,147,483,647 | PyPy 3 | OK | TESTS | 26 | 280 | 0 | n = int(input())
ls = []
title_order = {"rat": 0, "woman": 1, "child": 1, "man": 2, "captain": 3}
for i in range(n):
name, title = input().split()
ls.append((name, title_order[title]))
ls.sort(key=lambda x: x[1])
for i in range(n):
print(ls[i][0])
| Title: Sinking Ship
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to ... | ```python
n = int(input())
ls = []
title_order = {"rat": 0, "woman": 1, "child": 1, "man": 2, "captain": 3}
for i in range(n):
name, title = input().split()
ls.append((name, title_order[title]))
ls.sort(key=lambda x: x[1])
for i in range(n):
print(ls[i][0])
``` | 3.93 | MatrixStudio/Codeforces-Python-Submissions |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,698,921,425 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 17,100,800 | t=int(input(""))
L=list(map(int,input().split()))
L1=[]
for j in range(2,1000001):
c=False
for k in range(2,j):
if(k*k>j):
break
if(j%k==0):
c=True
break
if(c==False):
L1.append(j*j)
for j in range(... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
t=int(input(""))
L=list(map(int,input().split()))
L1=[]
for j in range(2,1000001):
c=False
for k in range(2,j):
if(k*k>j):
break
if(j%k==0):
c=True
break
if(c==False):
L1.append(j*j)
for j... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
520 | B | Two Buttons | PROGRAMMING | 1,400 | [
"dfs and similar",
"graphs",
"greedy",
"implementation",
"math",
"shortest paths"
] | null | null | Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by two. After clicking the blue button, device subtracts one from the number on the display. If at so... | The first and the only line of the input contains two distinct integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=104), separated by a space . | Print a single number — the minimum number of times one needs to push the button required to get the number *m* out of number *n*. | [
"4 6\n",
"10 1\n"
] | [
"2\n",
"9\n"
] | In the first example you need to push the blue button once, and then push the red button once.
In the second example, doubling the number is unnecessary, so we need to push the blue button nine times. | 1,000 | [
{
"input": "4 6",
"output": "2"
},
{
"input": "10 1",
"output": "9"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "1 3",
"output": "3"
},
{
"input": "3 1",
"output": "2"
},
{
"input": "2 10",
"outpu... | 1,693,155,489 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | import sys
input=sys.stdin.readline
d={}
def f(n,m):
if(n==m):
d[n]=True
return 0
elif n>m:
return n-m
else:
if 2*n==m or n-1==m:
d[n]=True
return 1
if n==0:
d[n]=True
return 100000
if n not in ... | Title: Two Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by t... | ```python
import sys
input=sys.stdin.readline
d={}
def f(n,m):
if(n==m):
d[n]=True
return 0
elif n>m:
return n-m
else:
if 2*n==m or n-1==m:
d[n]=True
return 1
if n==0:
d[n]=True
return 100000
if... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,573,268,994 | 2,147,483,647 | Python 3 | OK | TESTS | 72 | 109 | 0 |
n, p, q = map(int, input().split())
l = list(input())
for i in range(n // p + 1):
co = 1
for j in range(n // q + 1):
if i * p + j * q == n:
co = 0
break
if co == 0:
break
else:
print(-1)
exit()
print(i + j)
for k in range(i):
li = l[k * p : (k + 1) * p]
print(*li, sep = '')
co... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n, p, q = map(int, input().split())
l = list(input())
for i in range(n // p + 1):
co = 1
for j in range(n // q + 1):
if i * p + j * q == n:
co = 0
break
if co == 0:
break
else:
print(-1)
exit()
print(i + j)
for k in range(i):
li = l[k * p : (k + 1) * p]
print(*li, sep ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
559 | B | Equivalent Strings | PROGRAMMING | 1,700 | [
"divide and conquer",
"hashing",
"sortings",
"strings"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 1,000 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,672,500,283 | 2,147,483,647 | Python 3 | OK | TESTS | 104 | 748 | 1,331,200 | def X(A, B, size):
if A == B:
return True
if size%2 == 1:
return False
A1 = A[:size//2]
A2 = A[size//2:]
B1 = B[:size//2]
B2 = B[size//2:]
if X(A1, B2, size//2):
return X(A2, B1, size//2)
if X(A1, B1, size//2):
return X(A2, B2, size//2)
el... | Title: Equivalent Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split str... | ```python
def X(A, B, size):
if A == B:
return True
if size%2 == 1:
return False
A1 = A[:size//2]
A2 = A[size//2:]
B1 = B[:size//2]
B2 = B[size//2:]
if X(A1, B2, size//2):
return X(A2, B1, size//2)
if X(A1, B1, size//2):
return X(A2, B2, size//... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* s... | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Ch... | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,567,425,740 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 109 | 0 | n,d=map(int,input().split())
s=list(map(int,input().split()))
sumt=sum(s)+10*(len(s)-1)
if sumt>d:
sol=-1
else:
sol=(d-sum(s))//5
print(sol)
| Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invit... | ```python
n,d=map(int,input().split())
s=list(map(int,input().split()))
sumt=sum(s)+10*(len(s)-1)
if sumt>d:
sol=-1
else:
sol=(d-sum(s))//5
print(sol)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,689,365,003 | 2,303 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | // const sum = function (n) {
// const res = (n * (n + 1)) / 2;
// return res;
// };
// console.log(sum(12));
// let sum1 = 0;
// for (let i = 1; i <= 12; i++) {
// sum1 = sum1 + i;
// }
// console.log(sum1);
// function isPythagorusTriplet(a, b, c) {
// //Find the max value
// const max = Mat... | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
// const sum = function (n) {
// const res = (n * (n + 1)) / 2;
// return res;
// };
// console.log(sum(12));
// let sum1 = 0;
// for (let i = 1; i <= 12; i++) {
// sum1 = sum1 + i;
// }
// console.log(sum1);
// function isPythagorusTriplet(a, b, c) {
// //Find the max value
// const... | -1 | MatrixStudio/Codeforces-Python-Submissions |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,685,456,208 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 31 | 0 | total,l1,l2=map(int,input().split())
count=0
max,min=max(l1,l2),min(l1,l2)
string=input()
mo=total%max
if mo%min==0:
all=(total-mo)//max+mo//min
print(all)
for i in range(max,total-mo+1,max):
print(string[i-max:i])
for j in range(total-mo+min,total+1,min):
print(string[j-min:j... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
total,l1,l2=map(int,input().split())
count=0
max,min=max(l1,l2),min(l1,l2)
string=input()
mo=total%max
if mo%min==0:
all=(total-mo)//max+mo//min
print(all)
for i in range(max,total-mo+1,max):
print(string[i-max:i])
for j in range(total-mo+min,total+1,min):
print(stri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,578,271,718 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 218 | 307,200 | n = int(input())
players = {}
mx = 0
for k in range(n):
line = input().split()
if not line[0] in players:
players[line[0]] = [0, -1]
players[line[0]][0] += int(line[1])
players[line[0]][1] = k
mx = max(mx, players[line[0]][0])
winner = ['', float('inf')]
for p in players:
if players[p][0] == mx and players... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n = int(input())
players = {}
mx = 0
for k in range(n):
line = input().split()
if not line[0] in players:
players[line[0]] = [0, -1]
players[line[0]][0] += int(line[1])
players[line[0]][1] = k
mx = max(mx, players[line[0]][0])
winner = ['', float('inf')]
for p in players:
if players[p][0] == mx a... | 0 | MatrixStudio/Codeforces-Python-Submissions |
735 | A | Ostap and Grasshopper | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles. Then, he places his grasshopper to one of the empty cells and a small insect in another empty cell. The gr... | The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=*n*<=-<=1) — the number of cells in the line and the length of one grasshopper's jump.
The second line contains a string of length *n* consisting of characters '.', '#', 'G' and 'T'. Character '.' means that the correspondi... | If there exists a sequence of jumps (each jump of length *k*), such that the grasshopper can get from his initial position to the cell with the insect, print "YES" (without quotes) in the only line of the input. Otherwise, print "NO" (without quotes). | [
"5 2\n#G#T#\n",
"6 1\nT....G\n",
"7 3\nT..#..G\n",
"6 2\n..GT..\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | In the first sample, the grasshopper can make one jump to the right in order to get from cell 2 to cell 4.
In the second sample, the grasshopper is only able to jump to neighboring cells but the way to the insect is free — he can get there by jumping left 5 times.
In the third sample, the grasshopper can't make a sin... | 500 | [
{
"input": "5 2\n#G#T#",
"output": "YES"
},
{
"input": "6 1\nT....G",
"output": "YES"
},
{
"input": "7 3\nT..#..G",
"output": "NO"
},
{
"input": "6 2\n..GT..",
"output": "NO"
},
{
"input": "2 1\nGT",
"output": "YES"
},
{
"input": "100 5\nG####.####.###... | 1,593,939,859 | 2,147,483,647 | Python 3 | OK | TESTS | 83 | 109 | 6,963,200 | nk = input().split()
n = int(nk[0])
k = int(nk[1])
s = input()
g_ind = 0
t_ind = 0
for i in range(0, n):
if(s[i] == 'G'):
g_ind = i
elif(s[i] == 'T'):
t_ind = i
start = 0
end =0
if(g_ind < t_ind):
start = g_ind
end = t_ind
else:
start = t_ind
end = g_ind
... | Title: Ostap and Grasshopper
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles.... | ```python
nk = input().split()
n = int(nk[0])
k = int(nk[1])
s = input()
g_ind = 0
t_ind = 0
for i in range(0, n):
if(s[i] == 'G'):
g_ind = i
elif(s[i] == 'T'):
t_ind = i
start = 0
end =0
if(g_ind < t_ind):
start = g_ind
end = t_ind
else:
start = t_ind
end =... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,692,813,132 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 716,800 | import re
input_string = "{a, b, c}"
alphabets = re.findall(r'[a-zA-Z]', input_string)
unique_alphabets = set(alphabets)
num_unique_alphabets = len(unique_alphabets)
print("Unique number of alphabets:", num_unique_alphabets)
| Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
import re
input_string = "{a, b, c}"
alphabets = re.findall(r'[a-zA-Z]', input_string)
unique_alphabets = set(alphabets)
num_unique_alphabets = len(unique_alphabets)
print("Unique number of alphabets:", num_unique_alphabets)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,631,367,026 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 61 | 6,963,200 | n=int(input())
count=0
while True:
if n>=5:
count+=1
n-=5
elif n>=4:
count+=1
n-=4
elif n>=3:
count+=1
n-=3
elif n>=2:
count+=1
n-=2
elif n>=1:
count+=1
n-=1
elif n==0:
break
print(count) | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
n=int(input())
count=0
while True:
if n>=5:
count+=1
n-=5
elif n>=4:
count+=1
n-=4
elif n>=3:
count+=1
n-=3
elif n>=2:
count+=1
n-=2
elif n>=1:
count+=1
n-=1
elif n==0:
break
pri... | -1 | MatrixStudio/Codeforces-Python-Submissions |
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,698,046,353 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 31 | 0 | k,n,w=map(int,input().split())
m=k*((w*(w+1))//2)
if m <=n:
print(0)
else:
print(m-n) | Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
k,n,w=map(int,input().split())
m=k*((w*(w+1))//2)
if m <=n:
print(0)
else:
print(m-n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,695,642,097 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | def elephant():
steps = [5,4,3,2,1]
dis = int(input())
found = False
for step in steps:
if not found:
if dis % step == 0:
found = True
print(int(dis / step))
elephant() | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
def elephant():
steps = [5,4,3,2,1]
dis = int(input())
found = False
for step in steps:
if not found:
if dis % step == 0:
found = True
print(int(dis / step))
elephant()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
91 | A | Newspaper Headline | PROGRAMMING | 1,500 | [
"greedy",
"strings"
] | A. Newspaper Headline | 2 | 256 | A newspaper is published in Walrusland. Its heading is *s*1, it consists of lowercase Latin letters. Fangy the little walrus wants to buy several such newspapers, cut out their headings, glue them one to another in order to get one big string. After that walrus erase several letters from this string in order to get a n... | The input data contain two lines. The first line contain the heading *s*1, the second line contains the word *s*2. The lines only consist of lowercase Latin letters (1<=≤<=|*s*1|<=≤<=104,<=1<=≤<=|*s*2|<=≤<=106). | If it is impossible to get the word *s*2 in the above-described manner, print "-1" (without the quotes). Otherwise, print the least number of newspaper headings *s*1, which Fangy will need to receive the word *s*2. | [
"abc\nxyz\n",
"abcd\ndabc\n"
] | [
"-1\n",
"2\n"
] | none | 500 | [
{
"input": "abc\nxyz",
"output": "-1"
},
{
"input": "abcd\ndabc",
"output": "2"
},
{
"input": "ab\nbabaaab",
"output": "5"
},
{
"input": "ab\nbaaabba",
"output": "6"
},
{
"input": "fbaaigiihhfaahgdbddgeggjdeigfadhfddja\nhbghjgijijcdafcbgiedichdeebaddfddb",
"ou... | 1,686,029,211 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 51 | 842 | 63,385,600 | from collections import defaultdict
from bisect import bisect_left
s1 = list(input())
s2 = list(input())
m = defaultdict(list)
ans = 1
for i, v in enumerate(s1):
m[v].append(i)
pos = 0
for v in s2:
if not m[v]:
print(-1)
exit()
p = bisect_left(m[v], pos)
while p >= len(m[v]):
... | Title: Newspaper Headline
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A newspaper is published in Walrusland. Its heading is *s*1, it consists of lowercase Latin letters. Fangy the little walrus wants to buy several such newspapers, cut out their headings, glue them one to another in order... | ```python
from collections import defaultdict
from bisect import bisect_left
s1 = list(input())
s2 = list(input())
m = defaultdict(list)
ans = 1
for i, v in enumerate(s1):
m[v].append(i)
pos = 0
for v in s2:
if not m[v]:
print(-1)
exit()
p = bisect_left(m[v], pos)
while p >= le... | 3.671435 | MatrixStudio/Codeforces-Python-Submissions |
702 | C | Cellular Network | PROGRAMMING | 1,500 | [
"binary search",
"implementation",
"two pointers"
] | null | null | You are given *n* points on the straight line — the positions (*x*-coordinates) of the cities and *m* points on the same line — the positions (*x*-coordinates) of the cellular towers. All towers work in the same way — they provide cellular network for all cities, which are located at the distance which is no more than ... | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of cities and the number of cellular towers.
The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109) — the coordinates of cities. It is allowed that there are any number... | Print minimal *r* so that each city will be covered by cellular network. | [
"3 2\n-2 2 4\n-3 0\n",
"5 3\n1 5 10 14 17\n4 11 15\n"
] | [
"4\n",
"3\n"
] | none | 0 | [
{
"input": "3 2\n-2 2 4\n-3 0",
"output": "4"
},
{
"input": "5 3\n1 5 10 14 17\n4 11 15",
"output": "3"
},
{
"input": "1 1\n-1000000000\n1000000000",
"output": "2000000000"
},
{
"input": "1 1\n1000000000\n-1000000000",
"output": "2000000000"
},
{
"input": "10 10\n... | 1,682,326,205 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def find_min_range(cities, towers):
cities.sort()
towers.sort()
max_distance = max(cities[i+1] - cities[i] for i in range(len(cities)-1))
lo, hi = 0, max_distance
while lo < hi:
mid = (lo + hi) // 2
i = j = 0
while i < len(cities) and j < len(towers):
if abs(citie... | Title: Cellular Network
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on the straight line — the positions (*x*-coordinates) of the cities and *m* points on the same line — the positions (*x*-coordinates) of the cellular towers. All towers work in the same way — ... | ```python
def find_min_range(cities, towers):
cities.sort()
towers.sort()
max_distance = max(cities[i+1] - cities[i] for i in range(len(cities)-1))
lo, hi = 0, max_distance
while lo < hi:
mid = (lo + hi) // 2
i = j = 0
while i < len(cities) and j < len(towers):
if... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,661,365,180 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 58 | 78 | 13,516,800 | n,b,d=map(int,input().split())
m=list(map(int,input().split()))
c=0
k=0
for i in m:
if i > b:
continue
elif i<=b:
c+=i
if c>d:
k+=1
c=0
print(k) | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
n,b,d=map(int,input().split())
m=list(map(int,input().split()))
c=0
k=0
for i in m:
if i > b:
continue
elif i<=b:
c+=i
if c>d:
k+=1
c=0
print(k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
598 | C | Nearest vectors | PROGRAMMING | 2,300 | [
"geometry",
"sortings"
] | null | null | You are given the set of vectors on the plane, each of them starting at the origin. Your task is to find a pair of vectors with the minimal non-oriented angle between them.
Non-oriented angle is non-negative value, minimal between clockwise and counterclockwise direction angles. Non-oriented angle is always between 0 ... | First line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of vectors.
The *i*-th of the following *n* lines contains two integers *x**i* and *y**i* (|*x*|,<=|*y*|<=≤<=10<=000,<=*x*2<=+<=*y*2<=><=0) — the coordinates of the *i*-th vector. Vectors are numbered from 1 to *n* in order ... | Print two integer numbers *a* and *b* (*a*<=≠<=*b*) — a pair of indices of vectors with the minimal non-oriented angle. You can print the numbers in any order. If there are many possible answers, print any. | [
"4\n-1 0\n0 -1\n1 0\n1 1\n",
"6\n-1 0\n0 -1\n1 0\n1 1\n-4 -5\n-4 -6\n"
] | [
"3 4\n",
"6 5"
] | none | 0 | [
{
"input": "4\n-1 0\n0 -1\n1 0\n1 1",
"output": "3 4"
},
{
"input": "6\n-1 0\n0 -1\n1 0\n1 1\n-4 -5\n-4 -6",
"output": "5 6"
},
{
"input": "10\n8 6\n-7 -3\n9 8\n7 10\n-3 -8\n3 7\n6 -8\n-9 8\n9 2\n6 7",
"output": "1 3"
},
{
"input": "20\n-9 8\n-7 3\n0 10\n3 7\n6 -9\n6 8\n7 -6\... | 1,648,283,819 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
xy = []
for i in range(n):
xy.append(list(map(int, input().split()))) # 0, 1
xy[i].append(i + 1) # 2
xy[i].append(xy[i][1]*xy[i][1]/(xy[i][0]*xy[i][0]+xy[i][1]*xy[i][1])) # 3
# xy[i].append(xy[i][1]/xy[i][0]) # zero division
# print(xy)
xy.sort(key=lambda z: z[3])
min_ind = 100... | Title: Nearest vectors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the set of vectors on the plane, each of them starting at the origin. Your task is to find a pair of vectors with the minimal non-oriented angle between them.
Non-oriented angle is non-negative value, min... | ```python
n = int(input())
xy = []
for i in range(n):
xy.append(list(map(int, input().split()))) # 0, 1
xy[i].append(i + 1) # 2
xy[i].append(xy[i][1]*xy[i][1]/(xy[i][0]*xy[i][0]+xy[i][1]*xy[i][1])) # 3
# xy[i].append(xy[i][1]/xy[i][0]) # zero division
# print(xy)
xy.sort(key=lambda z: z[3])
min... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,676,832,491 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 2,150,400 | a,b = int(input()),int(input())
c = 0
for i in range(min(a,b)):
c += 1
a -=1
b -=1
o = max(a,b) // 2
print(c,o)
| Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
a,b = int(input()),int(input())
c = 0
for i in range(min(a,b)):
c += 1
a -=1
b -=1
o = max(a,b) // 2
print(c,o)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
631 | B | Print Check | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Kris works in a large company "Blake Technologies". As a best engineer of the company he was assigned a task to develop a printer that will be able to print horizontal and vertical strips. First prototype is already built and Kris wants to tests it. He wants you to implement the program that checks the result of the pr... | The first line of the input contains three integers *n*, *m* and *k* (1<=<=≤<=<=*n*,<=<=*m*<=<=≤<=5000, *n*·*m*<=≤<=100<=000, 1<=≤<=*k*<=≤<=100<=000) — the dimensions of the sheet and the number of operations, respectively.
Each of the next *k* lines contains the description of exactly one query:
- 1 *r**i* *a**i* ... | Print *n* lines containing *m* integers each — the resulting table after all operations are applied. | [
"3 3 3\n1 1 3\n2 2 1\n1 2 2\n",
"5 3 5\n1 1 1\n1 3 1\n1 5 1\n2 1 1\n2 3 1\n"
] | [
"3 1 3 \n2 2 2 \n0 1 0 \n",
"1 1 1 \n1 0 1 \n1 1 1 \n1 0 1 \n1 1 1 \n"
] | The figure below shows all three operations for the first sample step by step. The cells that were painted on the corresponding step are marked gray. | 1,000 | [
{
"input": "3 3 3\n1 1 3\n2 2 1\n1 2 2",
"output": "3 1 3 \n2 2 2 \n0 1 0 "
},
{
"input": "5 3 5\n1 1 1\n1 3 1\n1 5 1\n2 1 1\n2 3 1",
"output": "1 1 1 \n1 0 1 \n1 1 1 \n1 0 1 \n1 1 1 "
},
{
"input": "5 5 4\n1 2 1\n1 4 1\n2 2 1\n2 4 1",
"output": "0 1 0 1 0 \n1 1 1 1 1 \n0 1 0 1 0 \n1... | 1,597,734,495 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 218 | 2,048,000 | import numpy as np
def main():
n,m, k = map(int,input().split())
a = np.zeros((n,m),dtype=int)
for i in range(k):
c,h,col = map(int,input().split())
if c == 1:
a[h-1,:]=col
else:
a[:,h-1]=col
for i in range(n):
print(*a[i,:].tolist())
if __... | Title: Print Check
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kris works in a large company "Blake Technologies". As a best engineer of the company he was assigned a task to develop a printer that will be able to print horizontal and vertical strips. First prototype is already built a... | ```python
import numpy as np
def main():
n,m, k = map(int,input().split())
a = np.zeros((n,m),dtype=int)
for i in range(k):
c,h,col = map(int,input().split())
if c == 1:
a[h-1,:]=col
else:
a[:,h-1]=col
for i in range(n):
print(*a[i,:].tolis... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,661,864,403 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | n=int(input())
seq=list(map(int,input().split()))
k=min(seq)
smallest=0
for i in range(n):
if seq[i]>k:
print(seq[i])
break
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n=int(input())
seq=list(map(int,input().split()))
k=min(seq)
smallest=0
for i in range(n):
if seq[i]>k:
print(seq[i])
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
485 | A | Factory | PROGRAMMING | 1,400 | [
"implementation",
"math",
"matrices"
] | null | null | One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the factory has to produce (remainder after dividing *x* by *m*) more details. Unfortunately, no cu... | The first line contains two integers *a* and *m* (1<=≤<=*a*,<=*m*<=≤<=105). | Print "Yes" (without quotes) if the production will eventually stop, otherwise print "No". | [
"1 5\n",
"3 6\n"
] | [
"No\n",
"Yes\n"
] | none | 1,000 | [
{
"input": "1 5",
"output": "No"
},
{
"input": "3 6",
"output": "Yes"
},
{
"input": "1 8",
"output": "Yes"
},
{
"input": "2 3",
"output": "No"
},
{
"input": "3 24",
"output": "Yes"
},
{
"input": "1 1",
"output": "Yes"
},
{
"input": "100000 ... | 1,619,354,476 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | x , m = [int(x) for x in input().split()]
mod = x % m
x = x + mod
while x % m != 0 and x % m != mod:
x = x + x % m
if x % m == 0:
print("YES")
else:
print("NO")
| Title: Factory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the fac... | ```python
x , m = [int(x) for x in input().split()]
mod = x % m
x = x + mod
while x % m != 0 and x % m != mod:
x = x + x % m
if x % m == 0:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
625 | A | Guest From the Past | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much more complicated.
Kolya is hungry, so he went to the nearest milk shop. In 2084 you may buy kefir in a plas... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1018) — the number of rubles Kolya has at the beginning.
Then follow three lines containing integers *a*, *b* and *c* (1<=≤<=*a*<=≤<=1018, 1<=≤<=*c*<=<<=*b*<=≤<=1018) — the cost of one plastic liter bottle, the cost of one glass liter bottle and t... | Print the only integer — maximum number of liters of kefir, that Kolya can drink. | [
"10\n11\n9\n8\n",
"10\n5\n6\n1\n"
] | [
"2\n",
"2\n"
] | In the first sample, Kolya can buy one glass bottle, then return it and buy one more glass bottle. Thus he will drink 2 liters of kefir.
In the second sample, Kolya can buy two plastic bottle and get two liters of kefir, or he can buy one liter glass bottle, then return it and buy one plastic bottle. In both cases he ... | 750 | [
{
"input": "10\n11\n9\n8",
"output": "2"
},
{
"input": "10\n5\n6\n1",
"output": "2"
},
{
"input": "2\n2\n2\n1",
"output": "1"
},
{
"input": "10\n3\n3\n1",
"output": "4"
},
{
"input": "10\n1\n2\n1",
"output": "10"
},
{
"input": "10\n2\n3\n1",
"outpu... | 1,521,224,783 | 683 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 7,065,600 | n,a,b,c = int(input()), int(input()), int(input()), int(input())
if n>=b:
k = (n-b)//(b-c)
nk = n-k*(b-c)
print(k,nk)
print(max(n//a, k+max(1,nk//a)))
else:
print(n//a)
| Title: Guest From the Past
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much mor... | ```python
n,a,b,c = int(input()), int(input()), int(input()), int(input())
if n>=b:
k = (n-b)//(b-c)
nk = n-k*(b-c)
print(k,nk)
print(max(n//a, k+max(1,nk//a)))
else:
print(n//a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
602 | A | Two Bases | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | After seeing the "ALL YOUR BASE ARE BELONG TO US" meme for the first time, numbers *X* and *Y* realised that they have different bases, which complicated their relations.
You're given a number *X* represented in base *b**x* and a number *Y* represented in base *b**y*. Compare those two numbers. | The first line of the input contains two space-separated integers *n* and *b**x* (1<=≤<=*n*<=≤<=10, 2<=≤<=*b**x*<=≤<=40), where *n* is the number of digits in the *b**x*-based representation of *X*.
The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x**i*<=<<=*b**x*) — the dig... | Output a single character (quotes for clarity):
- '<' if *X*<=<<=*Y* - '>' if *X*<=><=*Y* - '=' if *X*<==<=*Y* | [
"6 2\n1 0 1 1 1 1\n2 10\n4 7\n",
"3 3\n1 0 2\n2 5\n2 4\n",
"7 16\n15 15 4 0 0 7 10\n7 9\n4 8 0 3 1 5 0\n"
] | [
"=\n",
"<\n",
">\n"
] | In the first sample, *X* = 101111<sub class="lower-index">2</sub> = 47<sub class="lower-index">10</sub> = *Y*.
In the second sample, *X* = 102<sub class="lower-index">3</sub> = 21<sub class="lower-index">5</sub> and *Y* = 24<sub class="lower-index">5</sub> = 112<sub class="lower-index">3</sub>, thus *X* < *Y*.
In ... | 500 | [
{
"input": "6 2\n1 0 1 1 1 1\n2 10\n4 7",
"output": "="
},
{
"input": "3 3\n1 0 2\n2 5\n2 4",
"output": "<"
},
{
"input": "7 16\n15 15 4 0 0 7 10\n7 9\n4 8 0 3 1 5 0",
"output": ">"
},
{
"input": "2 2\n1 0\n2 3\n1 0",
"output": "<"
},
{
"input": "2 2\n1 0\n1 3\n1"... | 1,448,384,280 | 1,380 | Python 3 | OK | TESTS | 118 | 62 | 0 | nx, bx = map(int, input().split(' ')[:2])
xs = list(map(int, input().split(' ')[:nx]))
ny, by = map(int, input().split(' ')[:2])
ys = list(map(int, input().split(' ')[:ny]))
p = 1
x = 0
for d in reversed(xs):
x += d * p
p *= bx
p = 1
y = 0
for d in reversed(ys):
y += d * p
p *= by
if x == y:
prin... | Title: Two Bases
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After seeing the "ALL YOUR BASE ARE BELONG TO US" meme for the first time, numbers *X* and *Y* realised that they have different bases, which complicated their relations.
You're given a number *X* represented in base *b**x* ... | ```python
nx, bx = map(int, input().split(' ')[:2])
xs = list(map(int, input().split(' ')[:nx]))
ny, by = map(int, input().split(' ')[:2])
ys = list(map(int, input().split(' ')[:ny]))
p = 1
x = 0
for d in reversed(xs):
x += d * p
p *= bx
p = 1
y = 0
for d in reversed(ys):
y += d * p
p *= by
if x == y... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
900 | A | Find Extra One | PROGRAMMING | 800 | [
"geometry",
"implementation"
] | null | null | You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis. | The first line contains a single positive integer *n* (2<=≤<=*n*<=≤<=105).
The following *n* lines contain coordinates of the points. The *i*-th of these lines contains two single integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109, *x**i*<=≠<=0). No two points coincide. | Print "Yes" if there is such a point, "No" — otherwise.
You can print every letter in any case (upper or lower). | [
"3\n1 1\n-1 -1\n2 -1\n",
"4\n1 1\n2 2\n-1 1\n-2 2\n",
"3\n1 2\n2 1\n4 60\n"
] | [
"Yes",
"No",
"Yes"
] | In the first example the second point can be removed.
In the second example there is no suitable for the condition point.
In the third example any point can be removed. | 500 | [
{
"input": "3\n1 1\n-1 -1\n2 -1",
"output": "Yes"
},
{
"input": "4\n1 1\n2 2\n-1 1\n-2 2",
"output": "No"
},
{
"input": "3\n1 2\n2 1\n4 60",
"output": "Yes"
},
{
"input": "10\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n-1 -1",
"output": "Yes"
},
{
"input": "2\n1... | 1,619,424,447 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | a = []
b = []
for i in range(int(input())):
x,y = input().split()
a.append(x)
b.append(y)
if len(a) == len(b):
print('No')
else :
print('Yes') | Title: Find Extra One
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis.
Input Specification:
The first li... | ```python
a = []
b = []
for i in range(int(input())):
x,y = input().split()
a.append(x)
b.append(y)
if len(a) == len(b):
print('No')
else :
print('Yes')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
909 | C | Python Indentation | PROGRAMMING | 1,800 | [
"dp"
] | null | null | In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An ex... | The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement. | Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7. | [
"4\ns\nf\nf\ns\n",
"4\nf\ns\nf\ns\n"
] | [
"1\n",
"2\n"
] | In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one... | 1,500 | [
{
"input": "4\ns\nf\nf\ns",
"output": "1"
},
{
"input": "4\nf\ns\nf\ns",
"output": "2"
},
{
"input": "156\nf\ns\nf\ns\nf\ns\ns\ns\ns\nf\ns\ns\nf\nf\ns\nf\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\nf\nf\nf\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\nf\nf\nf\ns\ns\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\ns... | 1,690,702,026 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 77 | 2,867,200 | mod = 10**9+7
#-functions-
def shift():
for j in range(2*n-1,0,-1): dp[j] = dp[j-1]
dp[0] = 0
def do(i):
sum = 0
for j in range(n-1,-1,-1):
sum+= dp[j]
dp[j] = sum % mod
#-main-
n = int(input())
a = []
dp = [0] * 2* n
for i in range(n): a.append(input())
# print(dp)
... | Title: Python Indentation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python... | ```python
mod = 10**9+7
#-functions-
def shift():
for j in range(2*n-1,0,-1): dp[j] = dp[j-1]
dp[0] = 0
def do(i):
sum = 0
for j in range(n-1,-1,-1):
sum+= dp[j]
dp[j] = sum % mod
#-main-
n = int(input())
a = []
dp = [0] * 2* n
for i in range(n): a.append(input())
# ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
757 | A | Gotta Catch Em' All! | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Bash wants to become a Pokemon master one day. Although he liked a lot of Pokemon, he has always been fascinated by Bulbasaur the most. Soon, things started getting serious and his fascination turned into an obsession. Since he is too young to go out and catch Bulbasaur, he came up with his own way of catching a Bulbas... | Input contains a single line containing a string *s* (1<=<=≤<=<=|*s*|<=<=≤<=<=105) — the text on the front page of the newspaper without spaces and punctuation marks. |*s*| is the length of the string *s*.
The string *s* contains lowercase and uppercase English letters, i.e. . | Output a single integer, the answer to the problem. | [
"Bulbbasaur\n",
"F\n",
"aBddulbasaurrgndgbualdBdsagaurrgndbb\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first case, you could pick: Bulbbasaur.
In the second case, there is no way to pick even a single Bulbasaur.
In the third case, you can rearrange the string to BulbasaurBulbasauraddrgndgddgargndbb to get two words "Bulbasaur". | 500 | [
{
"input": "Bulbbasaur",
"output": "1"
},
{
"input": "F",
"output": "0"
},
{
"input": "aBddulbasaurrgndgbualdBdsagaurrgndbb",
"output": "2"
},
{
"input": "BBBBBBBBBBbbbbbbbbbbuuuuuuuuuullllllllllssssssssssaaaaaaaaaarrrrrrrrrr",
"output": "5"
},
{
"input": "BBBBBBB... | 1,497,240,807 | 2,147,483,647 | Python 3 | OK | TESTS | 107 | 93 | 204,800 | # print("Input the string")
st = input()
Bcount = 0
ucount = 0
lcount = 0
bcount = 0
acount = 0
scount = 0
rcount = 0
for ch in st:
if ch == "B":
Bcount += 1
elif ch == "u":
ucount += 1
elif ch == "l":
lcount += 1
elif ch == "b":
bcount += 1
elif ch == "a":
... | Title: Gotta Catch Em' All!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bash wants to become a Pokemon master one day. Although he liked a lot of Pokemon, he has always been fascinated by Bulbasaur the most. Soon, things started getting serious and his fascination turned into an obsess... | ```python
# print("Input the string")
st = input()
Bcount = 0
ucount = 0
lcount = 0
bcount = 0
acount = 0
scount = 0
rcount = 0
for ch in st:
if ch == "B":
Bcount += 1
elif ch == "u":
ucount += 1
elif ch == "l":
lcount += 1
elif ch == "b":
bcount += 1
elif ch == "a"... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
915 | E | Physical Education Lessons | PROGRAMMING | 2,300 | [
"data structures",
"implementation",
"sortings"
] | null | null | This year Alex has finished school, and now he is a first-year student of Berland State University. For him it was a total surprise that even though he studies programming, he still has to attend physical education lessons. The end of the term is very soon, but, unfortunately, Alex still hasn't attended a single lesson... | The first line contains one integer *n*, and the second line — one integer *q* (1<=≤<=*n*<=≤<=109, 1<=≤<=*q*<=≤<=3·105) — the number of days left before the end of the term, and the number of orders, respectively.
Then *q* lines follow, *i*-th line containing three integers *l**i*, *r**i* and *k**i* representing *i*-t... | Print *q* integers. *i*-th of them must be equal to the number of working days left until the end of the term after the first *i* orders are published. | [
"4\n6\n1 2 1\n3 4 1\n2 3 2\n1 3 2\n2 4 1\n1 4 2\n"
] | [
"2\n0\n2\n3\n1\n4\n"
] | none | 0 | [
{
"input": "4\n6\n1 2 1\n3 4 1\n2 3 2\n1 3 2\n2 4 1\n1 4 2",
"output": "2\n0\n2\n3\n1\n4"
},
{
"input": "3\n8\n2 2 1\n3 3 2\n1 1 1\n1 3 2\n2 3 2\n3 3 1\n1 2 1\n2 2 2",
"output": "2\n2\n1\n3\n3\n2\n0\n1"
},
{
"input": "7\n10\n5 7 1\n5 6 2\n7 7 2\n6 7 2\n5 5 1\n3 6 2\n1 3 2\n5 6 1\n1 3 1\n... | 1,691,142,247 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1691142247.0960367")# 1691142247.0960538 | Title: Physical Education Lessons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This year Alex has finished school, and now he is a first-year student of Berland State University. For him it was a total surprise that even though he studies programming, he still has to attend physical edu... | ```python
print("_RANDOM_GUESS_1691142247.0960367")# 1691142247.0960538
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
60 | A | Where Are My Flakes? | PROGRAMMING | 1,300 | [
"implementation",
"two pointers"
] | A. Where Are My Flakes? | 2 | 256 | One morning the Cereal Guy found out that all his cereal flakes were gone. He found a note instead of them. It turned out that his smart roommate hid the flakes in one of *n* boxes. The boxes stand in one row, they are numbered from 1 to *n* from the left to the right. The roommate left hints like "Hidden to the left o... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=1000,<=0<=≤<=*m*<=≤<=1000) which represent the number of boxes and the number of hints correspondingly. Next *m* lines contain hints like "To the left of *i*" and "To the right of *i*", where *i* is integer (1<=≤<=*i*<=≤<=*n*). The hints may coincide. | The answer should contain exactly one integer — the number of boxes that should necessarily be checked or "-1" if the hints are contradictory. | [
"2 1\nTo the left of 2\n",
"3 2\nTo the right of 1\nTo the right of 2\n",
"3 1\nTo the left of 3\n",
"3 2\nTo the left of 2\nTo the right of 1\n"
] | [
"1\n",
"1\n",
"2\n",
"-1\n"
] | none | 500 | [
{
"input": "2 1\nTo the left of 2",
"output": "1"
},
{
"input": "3 2\nTo the right of 1\nTo the right of 2",
"output": "1"
},
{
"input": "3 1\nTo the left of 3",
"output": "2"
},
{
"input": "3 2\nTo the left of 2\nTo the right of 1",
"output": "-1"
},
{
"input": "... | 1,616,963,918 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 154 | 0 | n, m = map(int, input().split())
left, right = 1, n
for i in range(m):
inp = input().split()
if inp[2] == "left":
right = min(right, int(inp[4]) - 1)
else:
left = max(left, int(inp[4]) + 1)
if left <= right:
print(right - left + 1)
else:
print(-1) | Title: Where Are My Flakes?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One morning the Cereal Guy found out that all his cereal flakes were gone. He found a note instead of them. It turned out that his smart roommate hid the flakes in one of *n* boxes. The boxes stand in one row, they are... | ```python
n, m = map(int, input().split())
left, right = 1, n
for i in range(m):
inp = input().split()
if inp[2] == "left":
right = min(right, int(inp[4]) - 1)
else:
left = max(left, int(inp[4]) + 1)
if left <= right:
print(right - left + 1)
else:
... | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
287 | A | IQ Test | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and others are painted white. Your task is to repaint at most one cell the other color so that the... | Four lines contain four characters each: the *j*-th character of the *i*-th line equals "." if the cell in the *i*-th row and the *j*-th column of the square is painted white, and "#", if the cell is black. | Print "YES" (without the quotes), if the test can be passed and "NO" (without the quotes) otherwise. | [
"####\n.#..\n####\n....\n",
"####\n....\n####\n....\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample it is enough to repaint the first cell in the second row. After such repainting the required 2 × 2 square is on the intersection of the 1-st and 2-nd row with the 1-st and 2-nd column. | 500 | [
{
"input": "###.\n...#\n###.\n...#",
"output": "NO"
},
{
"input": ".##.\n#..#\n.##.\n#..#",
"output": "NO"
},
{
"input": ".#.#\n#.#.\n.#.#\n#.#.",
"output": "NO"
},
{
"input": "##..\n..##\n##..\n..##",
"output": "NO"
},
{
"input": "#.#.\n#.#.\n.#.#\n.#.#",
"ou... | 1,676,977,384 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 46 | 0 | # your code goes here
import math
l=[]
for i in range(4):
s =input()
l.append(s)
m=[]
ans=0
for i in l:
a=[]
for j in i:
if j=='#':
a.append(1)
else:
a.append(0)
m.append(a)
for i in range(len(m)-1):
for j in range(len(m[i])-1):
temp = m[i][j]+m[i][j+1]+m[i+1][j]+m[i+1][j+1]
if ... | Title: IQ Test
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and o... | ```python
# your code goes here
import math
l=[]
for i in range(4):
s =input()
l.append(s)
m=[]
ans=0
for i in l:
a=[]
for j in i:
if j=='#':
a.append(1)
else:
a.append(0)
m.append(a)
for i in range(len(m)-1):
for j in range(len(m[i])-1):
temp = m[i][j]+m[i][j+1]+m[i+1][j]+m[i+1][j... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
513 | B1 | Permutations | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | You are given a permutation *p* of numbers 1,<=2,<=...,<=*n*. Let's define *f*(*p*) as the following sum:
Find the lexicographically *m*-th permutation of length *n* in the set of permutations having the maximum possible value of *f*(*p*). | The single line of input contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*cnt**n*), where *cnt**n* is the number of permutations of length *n* with maximum possible value of *f*(*p*).
The problem consists of two subproblems. The subproblems have different constraints on the input. You will get some score for the corr... | Output *n* number forming the required permutation. | [
"2 2\n",
"3 2\n"
] | [
"2 1 \n",
"1 3 2 \n"
] | In the first example, both permutations of numbers {1, 2} yield maximum possible *f*(*p*) which is equal to 4. Among them, (2, 1) comes second in lexicographical order. | 3 | [
{
"input": "2 2",
"output": "2 1 "
},
{
"input": "3 2",
"output": "1 3 2 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "3 1",
"output": "1 2 3 "
},
{
"input": "3 3",
"output": "2 3 1 "
},
{
"input": "3 4",
"output": "3 2 1 "
},
{
"inp... | 1,477,743,360 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS1 | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int f(vector<int> v){
int ans=0;
for(int i=0;i<v.size();i++){
int mini=v[i];
ans+=mini;
for(int j=i+1;j<v.size();j++){
mini = min(mini,v[j]);
ans+=mini;
}
}
return ans;
}
int main(){
int n,m;
cin>>n>>m;
vector<int> ... | Title: Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a permutation *p* of numbers 1,<=2,<=...,<=*n*. Let's define *f*(*p*) as the following sum:
Find the lexicographically *m*-th permutation of length *n* in the set of permutations having the maximum possible ... | ```python
#include <bits/stdc++.h>
using namespace std;
int f(vector<int> v){
int ans=0;
for(int i=0;i<v.size();i++){
int mini=v[i];
ans+=mini;
for(int j=i+1;j<v.size();j++){
mini = min(mini,v[j]);
ans+=mini;
}
}
return ans;
}
int main(){
int n,m;
cin>>n>>m;
ve... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
522 | A | Reposts | PROGRAMMING | 1,200 | [
"*special",
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the n... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and ... | Print a single integer — the maximum length of a repost chain. | [
"5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n",
"6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n",
"1\nSoMeStRaNgEgUe repos... | [
"6\n",
"2\n",
"2\n"
] | none | 500 | [
{
"input": "5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya",
"output": "6"
},
{
"input": "6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforc... | 1,630,770,560 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 6,758,400 | import sys
N = int(input())
d = {}
while N:
s = [i for i in sys.stdin.readline().strip().split()]
#print(s)
d[s[0].lower()] = s[2].lower()
N -= 1
print(len(set(d.values())) + 1)
| Title: Reposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
... | ```python
import sys
N = int(input())
d = {}
while N:
s = [i for i in sys.stdin.readline().strip().split()]
#print(s)
d[s[0].lower()] = s[2].lower()
N -= 1
print(len(set(d.values())) + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,592,028,406 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 186 | 0 | n=int(input())
list=[int(i) for i in input().split()]
a,b=map(int,input().split())
result=list[a-1]
for i in range(a,b-a):
result+=list[i]
print(result) | Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
n=int(input())
list=[int(i) for i in input().split()]
a,b=map(int,input().split())
result=list[a-1]
for i in range(a,b-a):
result+=list[i]
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
884 | B | Japanese Crosswords Strike Back | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | A one-dimensional Japanese crossword can be represented as a binary string of length *x*. An encoding of this crossword is an array *a* of size *n*, where *n* is the number of segments formed completely of 1's, and *a**i* is the length of *i*-th segment. No two segments touch or intersect.
For example:
- If *x*<==<... | The first line contains two integer numbers *n* and *x* (1<=≤<=*n*<=≤<=100000, 1<=≤<=*x*<=≤<=109) — the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains *n* integer numbers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=10000) — the encoding. | Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO. | [
"2 4\n1 3\n",
"3 10\n3 3 2\n",
"2 10\n1 3\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "2 4\n1 3",
"output": "NO"
},
{
"input": "3 10\n3 3 2",
"output": "YES"
},
{
"input": "2 10\n1 3",
"output": "NO"
},
{
"input": "1 1\n1",
"output": "YES"
},
{
"input": "1 10\n10",
"output": "YES"
},
{
"input": "1 10000\n10000",
"output":... | 1,509,115,320 | 2,220 | Python 3 | OK | TESTS | 66 | 93 | 7,372,800 | n,t=map(int,input().split())
l=list(map(int,input().split()))
if (sum(l)+(n-1))==t:
print('Yes')
else :
print('NO') | Title: Japanese Crosswords Strike Back
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A one-dimensional Japanese crossword can be represented as a binary string of length *x*. An encoding of this crossword is an array *a* of size *n*, where *n* is the number of segments formed completely ... | ```python
n,t=map(int,input().split())
l=list(map(int,input().split()))
if (sum(l)+(n-1))==t:
print('Yes')
else :
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
765 | A | Neverending competitions | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.
Jinotega's best friends, team ... | In the first line of input there is a single integer *n*: the number of Jinotega's flights (1<=≤<=*n*<=≤<=100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next *n* lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX"... | If Jinotega is now at home, print "home" (without quotes), otherwise print "contest". | [
"4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO\n",
"3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP\n"
] | [
"home\n",
"contest\n"
] | In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list. | 500 | [
{
"input": "4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO",
"output": "home"
},
{
"input": "3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP",
"output": "contest"
},
{
"input": "1\nESJ\nESJ->TSJ",
"output": "contest"
},
{
"input": "2\nXMR\nFAJ->XMR\nXMR->FAJ",
"output": "home"
},
... | 1,618,500,592 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | n = int(input())
h = input()
for i in range(n-1):
z= input()
l = input().split("->")
if(l[1] == h):
print("home")
else:
print("contest") | Title: Neverending competitions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from thei... | ```python
n = int(input())
h = input()
for i in range(n-1):
z= input()
l = input().split("->")
if(l[1] == h):
print("home")
else:
print("contest")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,621,626,723 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 154 | 0 | # author : Leandro
# problem : https://codeforces.com/problemset/problem/41/A
# platform : Codeforces
# date : 2021-05-21
a = input()
b = input()
print('YES' if a == b[::-1] else 'NO')
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
# author : Leandro
# problem : https://codeforces.com/problemset/problem/41/A
# platform : Codeforces
# date : 2021-05-21
a = input()
b = input()
print('YES' if a == b[::-1] else 'NO')
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,558,572,514 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | print(int(input()+5)/10*10) | Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
print(int(input()+5)/10*10)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,483,377,724 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 62 | 4,608,000 | n = int(input())
l = []
w = 0
sm = 0
while True:
w += 1
sm += w
if sm<n+1:
l.append(w)
else:
break
sm -= w
l[-1] = n - sm + l[-1]
print(len(l))
s = ""
for i in l:
s += " "+str(i)
print(s[1:])
| Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
n = int(input())
l = []
w = 0
sm = 0
while True:
w += 1
sm += w
if sm<n+1:
l.append(w)
else:
break
sm -= w
l[-1] = n - sm + l[-1]
print(len(l))
s = ""
for i in l:
s += " "+str(i)
print(s[1:])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Let's define a forest as a non-directed acyclic graph (also without loops and parallel edges). One day Misha played with the forest consisting of *n* vertices. For each vertex *v* from 0 to *n*<=-<=1 he wrote down two integers, *degree**v* and *s**v*, were the first integer is the number of vertices adjacent to vertex ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=216), the number of vertices in the graph.
The *i*-th of the next lines contains numbers *degree**i* and *s**i* (0<=≤<=*degree**i*<=≤<=*n*<=-<=1, 0<=≤<=*s**i*<=<<=216), separated by a space. | In the first line print number *m*, the number of edges of the graph.
Next print *m* lines, each containing two distinct numbers, *a* and *b* (0<=≤<=*a*<=≤<=*n*<=-<=1, 0<=≤<=*b*<=≤<=*n*<=-<=1), corresponding to edge (*a*,<=*b*).
Edges can be printed in any order; vertices of the edge can also be printed in any order. | [
"3\n2 3\n1 0\n1 0\n",
"2\n1 1\n1 0\n"
] | [
"2\n1 0\n2 0\n",
"1\n0 1\n"
] | The XOR sum of numbers is the result of bitwise adding numbers modulo 2. This operation exists in many modern programming languages. For example, in languages C++, Java and Python it is represented as "^", and in Pascal — as "xor". | 0 | [
{
"input": "3\n2 3\n1 0\n1 0",
"output": "2\n1 0\n2 0"
},
{
"input": "2\n1 1\n1 0",
"output": "1\n0 1"
},
{
"input": "10\n3 13\n2 6\n1 5\n3 5\n1 3\n2 2\n2 6\n1 6\n1 3\n2 3",
"output": "9\n2 5\n4 3\n7 6\n8 3\n5 0\n6 1\n3 9\n1 0\n9 0"
},
{
"input": "10\n1 2\n1 7\n1 0\n1 8\n0 0\... | 1,567,414,219 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 733 | 16,896,000 | from collections import deque
class CodeforcesTask504ASolution:
def __init__(self):
self.result = ''
self.n = 0
self.vertices = []
def read_input(self):
self.n = int(input())
for x in range(self.n):
self.vertices.append([int(y) for y in input().split(" ")])... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's define a forest as a non-directed acyclic graph (also without loops and parallel edges). One day Misha played with the forest consisting of *n* vertices. For each vertex *v* from 0 to *n*<=-<=1 he wrote down two integers, *d... | ```python
from collections import deque
class CodeforcesTask504ASolution:
def __init__(self):
self.result = ''
self.n = 0
self.vertices = []
def read_input(self):
self.n = int(input())
for x in range(self.n):
self.vertices.append([int(y) for y in input().sp... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,685,877,124 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 92 | 0 | x=input()
a=x.split(" ")
b=0
c=0
for i in range(4):
b=0
for j in range(4):
if a[i]==a[j]:
b=b+1
if b>1:
c=c+1
if c>0:
c=c-1
print(c) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
x=input()
a=x.split(" ")
b=0
c=0
for i in range(4):
b=0
for j in range(4):
if a[i]==a[j]:
b=b+1
if b>1:
c=c+1
if c>0:
c=c-1
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
79 | B | Colorful Field | PROGRAMMING | 1,400 | [
"implementation",
"sortings"
] | B. Colorful Field | 2 | 256 | Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
After seeing the field carefully, Ciel found that the crop plants of each cell were planted in f... | In the first line there are four positive integers *n*,<=*m*,<=*k*,<=*t* (1<=≤<=*n*<=≤<=4·104,<=1<=≤<=*m*<=≤<=4·104,<=1<=≤<=*k*<=≤<=103,<=1<=≤<=*t*<=≤<=103), each of which represents the height of the field, the width of the field, the number of waste cells and the number of queries that ask the kind of crop plants in ... | For each query, if the cell is waste, print Waste. Otherwise, print the name of crop plants in the cell: either Carrots or Kiwis or Grapes. | [
"4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1\n"
] | [
"Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots\n"
] | The sample corresponds to the figure in the statement. | 1,000 | [
{
"input": "4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1",
"output": "Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots"
},
{
"input": "2 3 2 2\n1 1\n2 2\n2 1\n2 2",
"output": "Grapes\nWaste"
},
{
"input": "31 31 31 4\n4 9\n16 27\n11 29\n8 28\n11 2\n10 7\n22 6\n1 25\n14 8... | 1,653,204,266 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 498 | 0 | n, m, k, t = map(int, input().split())
x = [0] * k
for i in range(k):
a, b = map(int, input().split())
x[i] = (a, b)
plants = ['Carrots', 'Kiwis',' Grapes']
for _ in range(t):
i, j = map(int, input().split())
if (i, j) in x:
print('Waste')
continue
... | Title: Colorful Field
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
... | ```python
n, m, k, t = map(int, input().split())
x = [0] * k
for i in range(k):
a, b = map(int, input().split())
x[i] = (a, b)
plants = ['Carrots', 'Kiwis',' Grapes']
for _ in range(t):
i, j = map(int, input().split())
if (i, j) in x:
print('Waste')
continue... | 3.8755 | MatrixStudio/Codeforces-Python-Submissions |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,687,442,692 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | m,n = map(int,input().split())
ans = m*n
print(ans//2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
m,n = map(int,input().split())
ans = m*n
print(ans//2)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
550 | C | Divisibility by Eight | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"math"
] | null | null | You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a no... | The single line of the input contains a non-negative integer *n*. The representation of number *n* doesn't contain any leading zeroes and its length doesn't exceed 100 digits. | Print "NO" (without quotes), if there is no such way to remove some digits from number *n*.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number *n* in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any ... | [
"3454\n",
"10\n",
"111111\n"
] | [
"YES\n344\n",
"YES\n0\n",
"NO\n"
] | none | 1,000 | [
{
"input": "3454",
"output": "YES\n344"
},
{
"input": "10",
"output": "YES\n0"
},
{
"input": "111111",
"output": "NO"
},
{
"input": "8996988892",
"output": "YES\n8"
},
{
"input": "5555555555",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
... | 1,673,589,696 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 15 | 0 | from itertools import combinations
n = input()
lst = []
for i in range(1,len(n)+1):
for j in list(combinations(n,i)):
if(j[0]!='0'):
lst.append("".join(j))
flag=True
for num in lst:
if(int(num)%8==0):
print(f"YES\n{num}")
flag=False
break
if(flag... | Title: Divisibility by Eight
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of t... | ```python
from itertools import combinations
n = input()
lst = []
for i in range(1,len(n)+1):
for j in list(combinations(n,i)):
if(j[0]!='0'):
lst.append("".join(j))
flag=True
for num in lst:
if(int(num)%8==0):
print(f"YES\n{num}")
flag=False
break
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
729 | C | Road to Cinema | PROGRAMMING | 1,700 | [
"binary search",
"greedy",
"sortings"
] | null | null | Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in *t* minutes. There is a straight road of length *s* from the service to the cinema. Let's introduce a coordinate system so that the car rental service is at the point 0, and the cinema is at the point... | The first line contains four positive integers *n*, *k*, *s* and *t* (1<=≤<=*n*<=≤<=2·105, 1<=≤<=*k*<=≤<=2·105, 2<=≤<=*s*<=≤<=109, 1<=≤<=*t*<=≤<=2·109) — the number of cars at the car rental service, the number of gas stations along the road, the length of the road and the time in which the film starts.
Each of the n... | Print the minimum rent price of an appropriate car, i.e. such car that Vasya will be able to reach the cinema before the film starts (not later than in *t* minutes). If there is no appropriate car, print -1. | [
"3 1 8 10\n10 8\n5 7\n11 9\n3\n",
"2 2 10 18\n10 4\n20 6\n5 3\n"
] | [
"10\n",
"20\n"
] | In the first sample, Vasya can reach the cinema in time using the first or the third cars, but it would be cheaper to choose the first one. Its price is equal to 10, and the capacity of its fuel tank is 8. Then Vasya can drive to the first gas station in the accelerated mode in 3 minutes, spending 6 liters of fuel. Aft... | 1,750 | [
{
"input": "3 1 8 10\n10 8\n5 7\n11 9\n3",
"output": "10"
},
{
"input": "2 2 10 18\n10 4\n20 6\n5 3",
"output": "20"
},
{
"input": "2 1 1000000000 2000000000\n111 1000000000\n101 1000000000\n5",
"output": "101"
},
{
"input": "2 1 1000000000 2000000000\n111 999999998\n101 9999... | 1,479,732,307 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 1,000 | 307,200 | def timechecker(topl,way,t):
time = 0
if topl < way:
time += 1000000000000
while topl > way and way > 0:
time += 1
topl -= 2
way -= 1
time += way * 2
return time
def getMinPos(arr):
minim = arr[0]
for i in range(len(arr)):
if arr[i] < minim:
minim = arr[i]
return arr.index(minim)
ch... | Title: Road to Cinema
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in *t* minutes. There is a straight road of length *s* from the service to the cinema. Let's introduce ... | ```python
def timechecker(topl,way,t):
time = 0
if topl < way:
time += 1000000000000
while topl > way and way > 0:
time += 1
topl -= 2
way -= 1
time += way * 2
return time
def getMinPos(arr):
minim = arr[0]
for i in range(len(arr)):
if arr[i] < minim:
minim = arr[i]
return arr.index(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
784 | F | Crunching Numbers Just for You | PROGRAMMING | 1,900 | [
"*special",
"implementation"
] | null | null | You are developing a new feature for the website which sells airline tickets: being able to sort tickets by price! You have already extracted the tickets' prices, so there's just the last step to be done...
You are given an array of integers. Sort it in non-descending order. | The input consists of a single line of space-separated integers. The first number is *n* (1<=≤<=*n*<=≤<=10) — the size of the array. The following *n* numbers are the elements of the array (1<=≤<=*a**i*<=≤<=100). | Output space-separated elements of the sorted array. | [
"3 3 1 2\n"
] | [
"1 2 3 \n"
] | Remember, this is a very important feature, and you have to make sure the customers appreciate it! | 0 | [
{
"input": "3 3 1 2",
"output": "1 2 3 "
},
{
"input": "10 54 100 27 1 33 27 80 49 27 6",
"output": "1 6 27 27 27 33 49 54 80 100 "
}
] | 1,522,330,413 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 77 | 7,372,800 | print(' '.join([str(x) for x in sorted(set(map(int, input().split())))])) | Title: Crunching Numbers Just for You
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are developing a new feature for the website which sells airline tickets: being able to sort tickets by price! You have already extracted the tickets' prices, so there's just the last step to be done.... | ```python
print(' '.join([str(x) for x in sorted(set(map(int, input().split())))]))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
51 | A | Cheaterius's Problem | PROGRAMMING | 1,300 | [
"implementation"
] | A. Cheaterius's Problem | 2 | 256 | Cheaterius is a famous in all the Berland astrologist, magician and wizard, and he also is a liar and a cheater. One of his latest inventions is Cheaterius' amulets! They bring luck and wealth, but are rather expensive. Cheaterius makes them himself. The technology of their making is kept secret. But we know that throu... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000), where *n* is the number of amulets. Then the amulet's descriptions are contained. Every description occupies two lines and contains two numbers (from 1 to 6) in each line. Between every pair of amulets the line "**" is located. | Print the required number of piles. | [
"4\n31\n23\n**\n31\n23\n**\n13\n32\n**\n32\n13\n",
"4\n51\n26\n**\n54\n35\n**\n25\n61\n**\n45\n53\n"
] | [
"1\n",
"2\n"
] | none | 500 | [
{
"input": "4\n31\n23\n**\n31\n23\n**\n13\n32\n**\n32\n13",
"output": "1"
},
{
"input": "4\n51\n26\n**\n54\n35\n**\n25\n61\n**\n45\n53",
"output": "2"
},
{
"input": "4\n56\n61\n**\n31\n31\n**\n33\n11\n**\n11\n33",
"output": "2"
},
{
"input": "4\n36\n44\n**\n32\n46\n**\n66\n41... | 1,450,547,115 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 124 | 0 | n, s = int(input()), {input() + input()}
for i in range(n - 1):
d, c, u = input(), input() + input(), True
for j in range(4):
if c in s:
u = False
c = c[2] + c[0] + c[3] + c[1]
if u:
s.add(c)
print(len(s))
| Title: Cheaterius's Problem
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Cheaterius is a famous in all the Berland astrologist, magician and wizard, and he also is a liar and a cheater. One of his latest inventions is Cheaterius' amulets! They bring luck and wealth, but are rather expensive... | ```python
n, s = int(input()), {input() + input()}
for i in range(n - 1):
d, c, u = input(), input() + input(), True
for j in range(4):
if c in s:
u = False
c = c[2] + c[0] + c[3] + c[1]
if u:
s.add(c)
print(len(s))
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,682,857,650 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 51 | 124 | 1,638,400 | s = input() ; c = 0
while len(s) != 1 : s = str(sum(map(int, s))) ; c += 1
print(c) | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
s = input() ; c = 0
while len(s) != 1 : s = str(sum(map(int, s))) ; c += 1
print(c)
``` | 3.966052 | MatrixStudio/Codeforces-Python-Submissions |
376 | A | Lever | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar is a segment on the *Ox* axis between points 0 and |*s*|<=-<=1.
The decoding of the lever d... | The first line contains the lever description as a non-empty string *s* (3<=≤<=|*s*|<=≤<=106), consisting of digits (1-9) and characters "^" and "=". It is guaranteed that the line contains exactly one character "^". It is guaranteed that the pivot of the lever isn't located in any end of the lever bar.
To solve the p... | Print "left" if the given lever tilts to the left, "right" if it tilts to the right and "balance", if it is in balance. | [
"=^==\n",
"9===^==1\n",
"2==^7==\n",
"41^52==\n"
] | [
"balance\n",
"left\n",
"right\n",
"balance\n"
] | As you solve the problem, you may find the following link useful to better understand how a lever functions: http://en.wikipedia.org/wiki/Lever.
The pictures to the examples: | 500 | [
{
"input": "=^==",
"output": "balance"
},
{
"input": "9===^==1",
"output": "left"
},
{
"input": "2==^7==",
"output": "right"
},
{
"input": "41^52==",
"output": "balance"
},
{
"input": "=^2=4=1===1=",
"output": "right"
},
{
"input": "9=6===5==3=9=1=1^7=... | 1,415,534,355 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 55 | 935 | 14,131,200 | import sys
import math
instr = sys.stdin.readline().split("^")
ll = len(instr[0])
lr = len(instr[1]) - 1
vlmax = max(ll, lr)
kl = [0] * vlmax
kr = [0] * vlmax
for i in range(ll - 1, -1, -1):
if(instr[0][i] != '='):
kl[i - (vlmax - ll)] = int(instr[0][i])
for i in range(lr):
if(inst... | Title: Lever
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar i... | ```python
import sys
import math
instr = sys.stdin.readline().split("^")
ll = len(instr[0])
lr = len(instr[1]) - 1
vlmax = max(ll, lr)
kl = [0] * vlmax
kr = [0] * vlmax
for i in range(ll - 1, -1, -1):
if(instr[0][i] != '='):
kl[i - (vlmax - ll)] = int(instr[0][i])
for i in range(lr):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
205 | B | Little Elephant and Sorting | PROGRAMMING | 1,400 | [
"brute force",
"greedy"
] | null | null | The Little Elephant loves sortings.
He has an array *a* consisting of *n* integers. Let's number the array elements from 1 to *n*, then the *i*-th element will be denoted as *a**i*. The Little Elephant can make one move to choose an arbitrary pair of integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) and increase *a**i*... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of array *a*. The next line contains *n* integers, separated by single spaces — array *a* (1<=≤<=*a**i*<=≤<=109). The array elements are listed in the line in the order of their index's increasing. | In a single line print a single integer — the answer to the problem.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3\n1 2 3\n",
"3\n3 2 1\n",
"4\n7 4 1 47\n"
] | [
"0\n",
"2\n",
"6\n"
] | In the first sample the array is already sorted in the non-decreasing order, so the answer is 0.
In the second sample you need to perform two operations: first increase numbers from second to third (after that the array will be: [3, 3, 2]), and second increase only the last element (the array will be: [3, 3, 3]).
In ... | 1,000 | [
{
"input": "3\n1 2 3",
"output": "0"
},
{
"input": "3\n3 2 1",
"output": "2"
},
{
"input": "4\n7 4 1 47",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 1000000000",
"output": "0"
},
{
"input": "10\n1000000000 1 1000000000 1 1000000000 1 1000000000 1 100000000... | 1,626,994,647 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 93 | 20,172,800 | def main(arr):
max_val=-float('inf')
ans=0
for i in range(len(arr)):
if arr[i]>=max_val:
max_val=arr[i]
else:
ans=max(ans,max_val-arr[i])
return ans
n=int(input())
arr=list(map(int,input().split()))
print(main(arr)) | Title: Little Elephant and Sorting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves sortings.
He has an array *a* consisting of *n* integers. Let's number the array elements from 1 to *n*, then the *i*-th element will be denoted as *a**i*. The Little Elephant can ... | ```python
def main(arr):
max_val=-float('inf')
ans=0
for i in range(len(arr)):
if arr[i]>=max_val:
max_val=arr[i]
else:
ans=max(ans,max_val-arr[i])
return ans
n=int(input())
arr=list(map(int,input().split()))
print(main(arr))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
106 | A | Card Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Card Game | 2 | 256 | There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselves if you want.
To play durak you need a pack of 36 cards. Each card has a suit ("S", "H", ... | The first line contains the tramp suit. It is "S", "H", "D" or "C".
The second line contains the description of the two different cards. Each card is described by one word consisting of two symbols. The first symbol stands for the rank ("6", "7", "8", "9", "T", "J", "Q", "K" and "A"), and the second one stands for the... | Print "YES" (without the quotes) if the first cards beats the second one. Otherwise, print "NO" (also without the quotes). | [
"H\nQH 9S\n",
"S\n8D 6D\n",
"C\n7H AS\n"
] | [
"YES\n",
"YES",
"NO"
] | none | 500 | [
{
"input": "H\nQH 9S",
"output": "YES"
},
{
"input": "S\n8D 6D",
"output": "YES"
},
{
"input": "C\n7H AS",
"output": "NO"
},
{
"input": "C\nKC 9C",
"output": "YES"
},
{
"input": "D\n7D KD",
"output": "NO"
},
{
"input": "H\n7H KD",
"output": "YES"
... | 1,598,190,134 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 47 | 218 | 6,656,000 | rnks=["6", "7", "8", "9", "T", "J", "Q", "K", "A"]
cur=input()
v1,v2=input().split()
t1=v1[1]==cur
t2=v2[1]==cur
if(t1+t2==1):
print("YES" if t1 else "NO")
else:
print("YES" if rnks.index(v1[0])>rnks.index(v2[0]) else "NO")
| Title: Card Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselve... | ```python
rnks=["6", "7", "8", "9", "T", "J", "Q", "K", "A"]
cur=input()
v1,v2=input().split()
t1=v1[1]==cur
t2=v2[1]==cur
if(t1+t2==1):
print("YES" if t1 else "NO")
else:
print("YES" if rnks.index(v1[0])>rnks.index(v2[0]) else "NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
27 | A | Next Test | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Next Test | 2 | 256 | «Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests. | Output the required default value for the next test index. | [
"3\n1 7 2\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "1\n1",
"output": "2"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "3\n3 4 1",
"output": "2"
},
{
"input": "4\n6 4 3 5",
"output": "1"
},
{
"input": "5\n3 2 1 7 4",
"output": "5"
},
{
"input": "6\n4 1 2 5 3 7",
"output": "6"
},
... | 1,638,495,185 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | a=int(input())
b=input()
print(a)
| Title: Next Test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the... | ```python
a=int(input())
b=input()
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Santa Claus has Robot which lives on the infinite grid and can move along its lines. He can also, having a sequence of *m* points *p*1,<=*p*2,<=...,<=*p**m* with integer coordinates, do the following: denote its initial location by *p*0. First, the robot will move from *p*0 to *p*1 along one of the shortest paths betwe... | The first line of input contains the only positive integer *n* (1<=≤<=*n*<=≤<=2·105) which equals the number of unit segments the robot traveled. The second line contains the movements protocol, which consists of *n* letters, each being equal either L, or R, or U, or D. *k*-th letter stands for the direction which Robo... | The only line of input should contain the minimum possible length of the sequence. | [
"4\nRURD\n",
"6\nRRULDD\n",
"26\nRRRULURURUULULLLDLDDRDRDLD\n",
"3\nRLL\n",
"4\nLRLR\n"
] | [
"2\n",
"2\n",
"7\n",
"2\n",
"4\n"
] | The illustrations to the first three tests are given below.
<img class="tex-graphics" src="https://espresso.codeforces.com/832fb8f97a482be815e0f87edde26c9791a0d330.png" style="max-width: 100.0%;max-height: 100.0%;"/> <img class="tex-graphics" src="https://espresso.codeforces.com/119a8ba68772b2c2bf76f2acdc58027f6c5cde1... | 0 | [
{
"input": "4\nRURD",
"output": "2"
},
{
"input": "6\nRRULDD",
"output": "2"
},
{
"input": "26\nRRRULURURUULULLLDLDDRDRDLD",
"output": "7"
},
{
"input": "3\nRLL",
"output": "2"
},
{
"input": "4\nLRLR",
"output": "4"
},
{
"input": "5\nLRDLR",
"outpu... | 1,482,742,626 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 140 | 5,222,400 | n = int(input())
moves = input()
cur = {'UD': None,
'LR': None}
ans = 1
for move in moves:
if move in 'UD':
if cur['UD'] is not None and cur['UD'] != move:
ans += 1
cur['LR'] = None
cur['UD'] = move
if move in 'LR':
if cur['LR'] is not Non... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has Robot which lives on the infinite grid and can move along its lines. He can also, having a sequence of *m* points *p*1,<=*p*2,<=...,<=*p**m* with integer coordinates, do the following: denote its initial location b... | ```python
n = int(input())
moves = input()
cur = {'UD': None,
'LR': None}
ans = 1
for move in moves:
if move in 'UD':
if cur['UD'] is not None and cur['UD'] != move:
ans += 1
cur['LR'] = None
cur['UD'] = move
if move in 'LR':
if cur['LR'] ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
447 | A | DZY Loves Hash | PROGRAMMING | 800 | [
"implementation"
] | null | null | DZY has a hash table with *p* buckets, numbered from 0 to *p*<=-<=1. He wants to insert *n* numbers, in the order they are given, into the hash table. For the *i*-th number *x**i*, DZY will put it into the bucket numbered *h*(*x**i*), where *h*(*x*) is the hash function. In this problem we will assume, that *h*(*x*)<==... | The first line contains two integers, *p* and *n* (2<=≤<=*p*,<=*n*<=≤<=300). Then *n* lines follow. The *i*-th of them contains an integer *x**i* (0<=≤<=*x**i*<=≤<=109). | Output a single integer — the answer to the problem. | [
"10 5\n0\n21\n53\n41\n53\n",
"5 5\n0\n1\n2\n3\n4\n"
] | [
"4\n",
"-1\n"
] | none | 500 | [
{
"input": "10 5\n0\n21\n53\n41\n53",
"output": "4"
},
{
"input": "5 5\n0\n1\n2\n3\n4",
"output": "-1"
},
{
"input": "10 6\n811966798\n734823552\n790326404\n929189974\n414343256\n560346537",
"output": "4"
},
{
"input": "2 2\n788371161\n801743052",
"output": "-1"
},
{
... | 1,421,607,455 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 0 | a=input().split()
l=[]
for i in range(int(a[1])):
b=int(input())
l.append(b)
p=[]
s=0
for j in range(int(a[1])):
if l[j] not in p:
p.append(l[j])
s=1
else:
s=2
print(j)
break
if s==1:
print(-1) | Title: DZY Loves Hash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a hash table with *p* buckets, numbered from 0 to *p*<=-<=1. He wants to insert *n* numbers, in the order they are given, into the hash table. For the *i*-th number *x**i*, DZY will put it into the bucket numbere... | ```python
a=input().split()
l=[]
for i in range(int(a[1])):
b=int(input())
l.append(b)
p=[]
s=0
for j in range(int(a[1])):
if l[j] not in p:
p.append(l[j])
s=1
else:
s=2
print(j)
break
if s==1:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,656,845,386 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 124 | 2,252,800 | s = input()
res = 0
n = len(s)
for i in range(n):
for j in range(i,n):
for k in range(j,n):
if s[i] == 'Q' and s[j] =='A' and s[k] =='Q':
res+=1
print(res) | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
s = input()
res = 0
n = len(s)
for i in range(n):
for j in range(i,n):
for k in range(j,n):
if s[i] == 'Q' and s[j] =='A' and s[k] =='Q':
res+=1
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
721 | C | Journey | PROGRAMMING | 1,800 | [
"dp",
"graphs"
] | null | null | Recently Irina arrived to one of the most famous cities of Berland — the Berlatov city. There are *n* showplaces in the city, numbered from 1 to *n*, and some of them are connected by one-directional roads. The roads in Berlatov are designed in a way such that there are no cyclic routes between showplaces.
Initially I... | The first line of the input contains three integers *n*,<=*m* and *T* (2<=≤<=*n*<=≤<=5000,<=<=1<=≤<=*m*<=≤<=5000,<=<=1<=≤<=*T*<=≤<=109) — the number of showplaces, the number of roads between them and the time of Irina's stay in Berlatov respectively.
The next *m* lines describes roads in Berlatov. *i*-th of them cont... | Print the single integer *k* (2<=≤<=*k*<=≤<=*n*) — the maximum number of showplaces that Irina can visit during her journey from showplace 1 to showplace *n* within time not exceeding *T*, in the first line.
Print *k* distinct integers in the second line — indices of showplaces that Irina will visit on her route, in t... | [
"4 3 13\n1 2 5\n2 3 7\n2 4 8\n",
"6 6 7\n1 2 2\n1 3 3\n3 6 3\n2 4 2\n4 6 2\n6 5 1\n",
"5 5 6\n1 3 3\n3 5 3\n1 2 2\n2 4 3\n4 5 2\n"
] | [
"3\n1 2 4 \n",
"4\n1 2 4 6 \n",
"3\n1 3 5 \n"
] | none | 1,500 | [
{
"input": "4 3 13\n1 2 5\n2 3 7\n2 4 8",
"output": "3\n1 2 4 "
},
{
"input": "6 6 7\n1 2 2\n1 3 3\n3 6 3\n2 4 2\n4 6 2\n6 5 1",
"output": "4\n1 2 4 6 "
},
{
"input": "5 5 6\n1 3 3\n3 5 3\n1 2 2\n2 4 3\n4 5 2",
"output": "3\n1 3 5 "
},
{
"input": "10 10 100\n1 4 1\n6 4 1\n9 3... | 1,668,507,448 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | import heapq as hq
def dijkstra(x):
distances = [[-1, 1e13, -1] for i in range(n+1)]
# sp number, weight, prev
#prev = [[] for i in range(n+1)]
distances[x] = [1, 0, -1]
pq = [(-1, 0, x)]
while pq:
mx_sp, curdist, v = hq.heappop(pq)
#print(v, -mx_sp)
# if -m... | Title: Journey
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Irina arrived to one of the most famous cities of Berland — the Berlatov city. There are *n* showplaces in the city, numbered from 1 to *n*, and some of them are connected by one-directional roads. The roads in Berlato... | ```python
import heapq as hq
def dijkstra(x):
distances = [[-1, 1e13, -1] for i in range(n+1)]
# sp number, weight, prev
#prev = [[] for i in range(n+1)]
distances[x] = [1, 0, -1]
pq = [(-1, 0, x)]
while pq:
mx_sp, curdist, v = hq.heappop(pq)
#print(v, -mx_sp)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
552 | D | Vanya and Triangles | PROGRAMMING | 1,900 | [
"brute force",
"combinatorics",
"data structures",
"geometry",
"math",
"sortings"
] | null | null | Vanya got bored and he painted *n* distinct points on the plane. After that he connected all the points pairwise and saw that as a result many triangles were formed with vertices in the painted points. He asks you to count the number of the formed triangles with the non-zero area. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of the points painted on the plane.
Next *n* lines contain two integers each *x**i*,<=*y**i* (<=-<=100<=≤<=*x**i*,<=*y**i*<=≤<=100) — the coordinates of the *i*-th point. It is guaranteed that no two given points coincide. | In the first line print an integer — the number of triangles with the non-zero area among the painted points. | [
"4\n0 0\n1 1\n2 0\n2 2\n",
"3\n0 0\n1 1\n2 0\n",
"1\n1 1\n"
] | [
"3\n",
"1\n",
"0\n"
] | Note to the first sample test. There are 3 triangles formed: (0, 0) - (1, 1) - (2, 0); (0, 0) - (2, 2) - (2, 0); (1, 1) - (2, 2) - (2, 0).
Note to the second sample test. There is 1 triangle formed: (0, 0) - (1, 1) - (2, 0).
Note to the third sample test. A single point doesn't form a single triangle. | 2,000 | [
{
"input": "4\n0 0\n1 1\n2 0\n2 2",
"output": "3"
},
{
"input": "3\n0 0\n1 1\n2 0",
"output": "1"
},
{
"input": "1\n1 1",
"output": "0"
},
{
"input": "5\n0 0\n1 1\n2 2\n3 3\n4 4",
"output": "0"
},
{
"input": "5\n0 0\n1 1\n2 3\n3 6\n4 10",
"output": "10"
},
... | 1,538,014,584 | 2,147,483,647 | Python 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 6 | 1,247 | 536,883,200 | import itertools
n=int(input())
c=[]
for x in range(n):
c.append(input())
co=0
for z in list(itertools.combinations(c,3)):
z0x,z0y=map(int,z[0].split())
z1x,z1y=map(int,z[1].split())
z2x,z2y=map(int,z[2].split())
if(z0x*z1y-z0y*z1x+z1x*z2y-z1y*z2x+z2x*z0y-z2y*z0x!=0):
co+=1
print(co) | Title: Vanya and Triangles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got bored and he painted *n* distinct points on the plane. After that he connected all the points pairwise and saw that as a result many triangles were formed with vertices in the painted points. He asks you t... | ```python
import itertools
n=int(input())
c=[]
for x in range(n):
c.append(input())
co=0
for z in list(itertools.combinations(c,3)):
z0x,z0y=map(int,z[0].split())
z1x,z1y=map(int,z[1].split())
z2x,z2y=map(int,z[2].split())
if(z0x*z1y-z0y*z1x+z1x*z2y-z1y*z2x+z2x*z0y-z2y*z0x!=0):
co+=1
print(co)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,656,586,631 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | rijec = input()
lowerCount = 0
upperCount = 0
for i in range(len(rijec)):
if rijec[i].islower():
lowerCount += 1
elif rijec[i].isupper():
upperCount += 1
if lowerCount > upperCount:
rijec = rijec.lower()
elif lowerCount <= upperCount:
rijec = rijec.upper()
print(rijec)
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
rijec = input()
lowerCount = 0
upperCount = 0
for i in range(len(rijec)):
if rijec[i].islower():
lowerCount += 1
elif rijec[i].isupper():
upperCount += 1
if lowerCount > upperCount:
rijec = rijec.lower()
elif lowerCount <= upperCount:
rijec = rijec.upper()
print(rijec)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
862 | A | Mahmoud and Ehab and the MEX | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | Dr. Evil kidnapped Mahmoud and Ehab in the evil land because of their performance in the Evil Olympiad in Informatics (EOI). He decided to give them some problems to let them go.
Dr. Evil is interested in sets, He has a set of *n* integers. Dr. Evil calls a set of integers evil if the MEX of it is exactly *x*. the MEX... | The first line contains two integers *n* and *x* (1<=≤<=*n*<=≤<=100, 0<=≤<=*x*<=≤<=100) — the size of the set Dr. Evil owns, and the desired MEX.
The second line contains *n* distinct non-negative integers not exceeding 100 that represent the set. | The only line should contain one integer — the minimal number of operations Dr. Evil should perform. | [
"5 3\n0 4 5 6 7\n",
"1 0\n0\n",
"5 0\n1 2 3 4 5\n"
] | [
"2\n",
"1\n",
"0\n"
] | For the first test case Dr. Evil should add 1 and 2 to the set performing 2 operations.
For the second test case Dr. Evil should erase 0 from the set. After that, the set becomes empty, so the MEX of it is 0.
In the third test case the set is already evil. | 500 | [
{
"input": "5 3\n0 4 5 6 7",
"output": "2"
},
{
"input": "1 0\n0",
"output": "1"
},
{
"input": "5 0\n1 2 3 4 5",
"output": "0"
},
{
"input": "10 5\n57 1 47 9 93 37 76 70 78 15",
"output": "4"
},
{
"input": "10 5\n99 98 93 97 95 100 92 94 91 96",
"output": "5"
... | 1,688,795,715 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | def findMex(set_mex):
p0 = set_mex[0]
p1 = set_mex[1]
if(p0 > 0):
mex = p0 - 1
return mex
elif((p1-p0) != 1):
mex = p1 - 1
return mex
else:
return -1;
def count_operations(set_n, count):
mex = findMex(set_n)
if(mex == -1):
print(count)
return
else:
count += 1
set_n.appe... | Title: Mahmoud and Ehab and the MEX
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Evil kidnapped Mahmoud and Ehab in the evil land because of their performance in the Evil Olympiad in Informatics (EOI). He decided to give them some problems to let them go.
Dr. Evil is interested in ... | ```python
def findMex(set_mex):
p0 = set_mex[0]
p1 = set_mex[1]
if(p0 > 0):
mex = p0 - 1
return mex
elif((p1-p0) != 1):
mex = p1 - 1
return mex
else:
return -1;
def count_operations(set_n, count):
mex = findMex(set_n)
if(mex == -1):
print(count)
return
else:
count += 1
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,538,830,396 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 409,600 | import math
p=input().split()
m=int(p[0])
p=int(p[1])
def kthdivisor(n,k) :
list = []
for i in range(1, int(math.sqrt(n) + 1)) :
if (n % i == 0) :
if (n / i == i) :
list=list+[i]
else :
list=list+[i]
... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
import math
p=input().split()
m=int(p[0])
p=int(p[1])
def kthdivisor(n,k) :
list = []
for i in range(1, int(math.sqrt(n) + 1)) :
if (n % i == 0) :
if (n / i == i) :
list=list+[i]
else :
list=list+[i]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
916 | A | Jamie and Alarm Snooze | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every *x* minutes until *hh*:<=*mm* is reached, and only then he will wake up. He ... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=60).
The second line contains two two-digit integers, *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59). | Print the minimum number of times he needs to press the button. | [
"3\n11 23\n",
"5\n01 07\n"
] | [
"2\n",
"0\n"
] | In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.
In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky. | 500 | [
{
"input": "3\n11 23",
"output": "2"
},
{
"input": "5\n01 07",
"output": "0"
},
{
"input": "34\n09 24",
"output": "3"
},
{
"input": "2\n14 37",
"output": "0"
},
{
"input": "14\n19 54",
"output": "9"
},
{
"input": "42\n15 44",
"output": "12"
},
... | 1,516,421,308 | 2,147,483,647 | Python 3 | OK | TESTS | 254 | 62 | 5,632,000 | def haveseven(a):
return ((a % 10 == 7) or (int(a/10) == 7))
x = int(input())
hh, mm = map(int, input().split())
t = hh*60 + mm
cnt = 0
while '7' not in str(t//60) + str(t%60):
cnt+=1
t-=x
if (t < 0):
t += 24*60
print(cnt) | Title: Jamie and Alarm Snooze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will the... | ```python
def haveseven(a):
return ((a % 10 == 7) or (int(a/10) == 7))
x = int(input())
hh, mm = map(int, input().split())
t = hh*60 + mm
cnt = 0
while '7' not in str(t//60) + str(t%60):
cnt+=1
t-=x
if (t < 0):
t += 24*60
print(cnt)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
717 | E | Paint it really, really dark gray | PROGRAMMING | 1,900 | [
"dfs and similar"
] | null | null | I see a pink boar and I want it painted black. Black boars look much more awesome and mighty than the pink ones. Since Jaggy became the ruler of the forest, he has been trying his best to improve the diplomatic relations between the forest region and the nearby ones.
Some other rulers, however, have requested too muc... | The first line of input contains integer *n* (2<=≤<=*n*<=≤<=200<=000), denoting the number of vertices in the tree. The following *n* lines contains *n* integers, which represent the color of the nodes.
If the *i*-th integer is 1, if the *i*-th vertex is black and <=-<=1 if the *i*-th vertex is pink.
Each of the next... | Output path of a squirrel: output a sequence of visited nodes' indexes in order of visiting. In case of all the nodes are initially black, you should print 1. Solution is guaranteed to exist. If there are multiple solutions to the problem you can output any of them provided length of sequence is not longer than 107. | [
"5\n1\n1\n-1\n1\n-1\n2 5\n4 3\n2 4\n4 1\n"
] | [
"1 4 2 5 2 4 3 4 1 4 1\n"
] | At the beginning squirrel is at node 1 and its color is black. Next steps are as follows:
- From node 1 we walk to node 4 and change its color to pink. - From node 4 we walk to node 2 and change its color to pink. - From node 2 we walk to node 5 and change its color to black. - From node 5 we return to node 2 and... | 0 | [
{
"input": "5\n1\n1\n-1\n1\n-1\n2 5\n4 3\n2 4\n4 1",
"output": "1 4 2 5 2 4 3 4 1 4 1"
},
{
"input": "2\n-1\n1\n2 1",
"output": "1 2 1 2 1 2 1 2"
},
{
"input": "12\n-1\n-1\n1\n-1\n1\n1\n-1\n1\n1\n-1\n1\n-1\n1 3\n1 2\n2 5\n2 4\n3 7\n3 6\n4 9\n4 8\n5 11\n5 10\n12 11",
"output": "1 2 4 ... | 1,685,948,184 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 1 | 1,000 | 8,908,800 | # https://codeforces.com/contest/717/problem/E
n = int(input())
graph = [[] for _ in range(n)]
color = []
for _ in range(n):
color.append(int(input()))
pinks_here = [0] * n
def invert(c):
return 1 if c == -1 else -1
def dfs_1(curr, parent=-1):
''' Count the number of pinks that this node parents, inclu... | Title: Paint it really, really dark gray
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
I see a pink boar and I want it painted black. Black boars look much more awesome and mighty than the pink ones. Since Jaggy became the ruler of the forest, he has been trying his best to improve the d... | ```python
# https://codeforces.com/contest/717/problem/E
n = int(input())
graph = [[] for _ in range(n)]
color = []
for _ in range(n):
color.append(int(input()))
pinks_here = [0] * n
def invert(c):
return 1 if c == -1 else -1
def dfs_1(curr, parent=-1):
''' Count the number of pinks that this node pare... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
886 | A | ACM ICPC | PROGRAMMING | 1,000 | [
"brute force"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. ... | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 500 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,514,257,724 | 2,147,483,647 | Python 3 | OK | TESTS | 53 | 77 | 5,632,000 | from itertools import permutations
m=list(map(int,input().split()))
for p in permutations(m):
if(p[0]+p[1]+p[2]==p[3]+p[4]+p[5]):
print("YES")
exit()
print("NO")
| Title: ACM ICPC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build ... | ```python
from itertools import permutations
m=list(map(int,input().split()))
for p in permutations(m):
if(p[0]+p[1]+p[2]==p[3]+p[4]+p[5]):
print("YES")
exit()
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
888 | B | Buggy Robot | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — mo... | The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R. | Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell. | [
"4\nLDUR\n",
"5\nRRRUU\n",
"6\nLLRRRR\n"
] | [
"4\n",
"0\n",
"4\n"
] | none | 0 | [
{
"input": "4\nLDUR",
"output": "4"
},
{
"input": "5\nRRRUU",
"output": "0"
},
{
"input": "6\nLLRRRR",
"output": "4"
},
{
"input": "88\nLLUUULRDRRURDDLURRLRDRLLRULRUUDDLLLLRRDDURDURRLDURRLDRRRUULDDLRRRDDRRLUULLURDURUDDDDDLDR",
"output": "76"
},
{
"input": "89\nLDL... | 1,564,455,052 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | n=int(input())
s=str(input())
x=min(s.count('R'),s.count('L'))
y=min(s.count('U'),s.count('D'))
print(x+y) | Title: Buggy Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the ce... | ```python
n=int(input())
s=str(input())
x=min(s.count('R'),s.count('L'))
y=min(s.count('U'),s.count('D'))
print(x+y)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
637 | B | Chat Order | PROGRAMMING | 1,200 | [
"*special",
"binary search",
"constructive algorithms",
"data structures",
"sortings"
] | null | null | Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The relative order of the other chats doesn't change. If there was no chat with this friend before, then... | The first line contains integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Polycarpus' messages. Next *n* lines enlist the message recipients in the order in which the messages were sent. The name of each participant is a non-empty sequence of lowercase English letters of length at most 10. | Print all the recipients to who Polycarp talked to in the order of chats with them, from top to bottom. | [
"4\nalex\nivan\nroman\nivan\n",
"8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina\n"
] | [
"ivan\nroman\nalex\n",
"alina\nmaria\nekaterina\ndarya\n"
] | In the first test case Polycarpus first writes to friend by name "alex", and the list looks as follows:
1. alex
Then Polycarpus writes to friend by name "ivan" and the list looks as follows:
1. ivan 1. alex
Polycarpus writes the third message to friend by name "roman" and the list looks as follows:
1. roman 1... | 1,000 | [
{
"input": "4\nalex\nivan\nroman\nivan",
"output": "ivan\nroman\nalex"
},
{
"input": "8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina",
"output": "alina\nmaria\nekaterina\ndarya"
},
{
"input": "1\nwdi",
"output": "wdi"
},
{
"input": "2\nypg\nypg",
"outpu... | 1,597,767,418 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 7 | 187 | 2,150,400 | from collections import deque
n = int(input())
friends = []
chat = {}
final = []
for i in range(n):
friends.append(input())
for i in range(len(friends)):
if friends[i] not in chat:
chat[friends[i]] = i
final.append(friends[i])
elif friends[i] in chat:
index = chat[friends[i]]
... | Title: Chat Order
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The rela... | ```python
from collections import deque
n = int(input())
friends = []
chat = {}
final = []
for i in range(n):
friends.append(input())
for i in range(len(friends)):
if friends[i] not in chat:
chat[friends[i]] = i
final.append(friends[i])
elif friends[i] in chat:
index = chat[friends[... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
171 | A | Mysterious numbers - 1 | PROGRAMMING | 1,200 | [
"*special",
"constructive algorithms"
] | null | null | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output a single integer. | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space. | Output a single integer. | [
"3 14\n",
"27 12\n",
"100 200\n"
] | [
"44\n",
"48\n",
"102\n"
] | none | 0 | [
{
"input": "3 14",
"output": "44"
},
{
"input": "27 12",
"output": "48"
},
{
"input": "100 200",
"output": "102"
},
{
"input": "0 0",
"output": "0"
},
{
"input": "31415 92653",
"output": "67044"
},
{
"input": "1000000000 0",
"output": "1000000000"
... | 1,617,115,799 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 218 | 0 | a,b=map(int,input().split(' '))
newb = 0
while b > 0:
newb *= 10
newb+= b % 10
b //= 10
print(a+newb) | Title: Mysterious numbers - 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output a single integer.
Input Specification:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109),... | ```python
a,b=map(int,input().split(' '))
newb = 0
while b > 0:
newb *= 10
newb+= b % 10
b //= 10
print(a+newb)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
109 | A | Lucky Sum of Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | A. Lucky Sum of Digits | 2 | 256 | Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope wi... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number. | Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1. | [
"11\n",
"10\n"
] | [
"47\n",
"-1\n"
] | none | 500 | [
{
"input": "11",
"output": "47"
},
{
"input": "10",
"output": "-1"
},
{
"input": "64",
"output": "4477777777"
},
{
"input": "1",
"output": "-1"
},
{
"input": "4",
"output": "4"
},
{
"input": "7",
"output": "7"
},
{
"input": "12",
"outpu... | 1,520,082,695 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 154 | 5,836,800 | #!/usr/bin/python3
def func(n):
if n < 4:
return -1
q1, r1 = n // 7, n % 7
q2, r2 = r1 // 4, r1 % 4
# import pdb
# pdb.set_trace()
if r2 != 0:
if q1 >= r2:
q2 += ((7*r2) + r2)//4
q1 -= r2
else:
return -1
return "4"*q2 + "7"*q1
n = ... | Title: Lucky Sum of Digits
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
#!/usr/bin/python3
def func(n):
if n < 4:
return -1
q1, r1 = n // 7, n % 7
q2, r2 = r1 // 4, r1 % 4
# import pdb
# pdb.set_trace()
if r2 != 0:
if q1 >= r2:
q2 += ((7*r2) + r2)//4
q1 -= r2
else:
return -1
return "4"*q2 + "7"... | 3.950628 | MatrixStudio/Codeforces-Python-Submissions |
411 | C | Kicker | PROGRAMMING | 1,700 | [
"implementation"
] | null | null | Kicker (table football) is a board game based on football, in which players control the footballers' figures mounted on rods by using bars to get the ball into the opponent's goal. When playing two on two, one player of each team controls the goalkeeper and the full-backs (plays defence), the other player controls the ... | The input contain the players' description in four lines. The *i*-th line contains two space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=100) — the defence and the attack skill of the *i*-th player, correspondingly. | If the first team can win, print phrase "Team 1" (without the quotes), if the second team can win, print phrase "Team 2" (without the quotes). If no of the teams can definitely win, print "Draw" (without the quotes). | [
"1 100\n100 1\n99 99\n99 99\n",
"1 1\n2 2\n3 3\n2 2\n",
"3 3\n2 2\n1 1\n2 2\n"
] | [
"Team 1\n",
"Team 2\n",
"Draw\n"
] | Let consider the first test sample. The first team can definitely win if it will choose the following arrangement: the first player plays attack, the second player plays defence.
Consider the second sample. The order of the choosing roles for players makes sense in this sample. As the members of the first team choose ... | 0 | [
{
"input": "1 100\n100 1\n99 99\n99 99",
"output": "Team 1"
},
{
"input": "1 1\n2 2\n3 3\n2 2",
"output": "Team 2"
},
{
"input": "3 3\n2 2\n1 1\n2 2",
"output": "Draw"
},
{
"input": "80 79\n79 30\n80 81\n40 80",
"output": "Team 2"
},
{
"input": "10 10\n4 9\n8 9\n7... | 1,397,512,671 | 7,071 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | n1=n2=z1=z2=0
a=input()
a=a.split('\n')
k=-1
for i in range(0,4):
a[i]=a[i].split(' ')
for i in range(0,4):
for j in range(0,2):
a[i][j]=int(a[i][j])
z1=max(int(a[0][0]),int(a[1][0]))
k1=((a[2][0]>n1) and (a[3][1]>z1))
k2=((a[3][0]>n1) and (a[2][1]>z1))
if a[0][0]==str(z1):
n1=a[1][1]
else:
n1=a[0][1]
i... | Title: Kicker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kicker (table football) is a board game based on football, in which players control the footballers' figures mounted on rods by using bars to get the ball into the opponent's goal. When playing two on two, one player of each tea... | ```python
n1=n2=z1=z2=0
a=input()
a=a.split('\n')
k=-1
for i in range(0,4):
a[i]=a[i].split(' ')
for i in range(0,4):
for j in range(0,2):
a[i][j]=int(a[i][j])
z1=max(int(a[0][0]),int(a[1][0]))
k1=((a[2][0]>n1) and (a[3][1]>z1))
k2=((a[3][0]>n1) and (a[2][1]>z1))
if a[0][0]==str(z1):
n1=a[1][1]
else:
n1... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
214 | A | System of Equations | PROGRAMMING | 800 | [
"brute force"
] | null | null | Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of int... | A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space. | On a single line print the answer to the problem. | [
"9 3\n",
"14 28\n",
"4 20\n"
] | [
"1\n",
"1\n",
"0\n"
] | In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | 500 | [
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10"... | 1,650,881,149 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 248 | 0 | n,m=map(int,input().split())
cnt=0
for i in range(1,1001):
for j in range(i):
if i*i+j==n and j*j+i==m:
cnt+=1
print(cnt) | Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immedi... | ```python
n,m=map(int,input().split())
cnt=0
for i in range(1,1001):
for j in range(i):
if i*i+j==n and j*j+i==m:
cnt+=1
print(cnt)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
911 | A | Nearest Minimums | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | You are given an array of *n* integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. Find the distance between two closest (nearest) minimums in it. It is guaranteed that in the array a minimum occurs at least two times. | The first line contains positive integer *n* (2<=≤<=*n*<=≤<=105) — size of the given array. The second line contains *n* integers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=109) — elements of the array. It is guaranteed that in the array a minimum occurs at least two times. | Print the only number — distance between two nearest minimums in the array. | [
"2\n3 3\n",
"3\n5 6 5\n",
"9\n2 1 3 5 4 1 2 3 1\n"
] | [
"1\n",
"2\n",
"3\n"
] | none | 0 | [
{
"input": "2\n3 3",
"output": "1"
},
{
"input": "3\n5 6 5",
"output": "2"
},
{
"input": "9\n2 1 3 5 4 1 2 3 1",
"output": "3"
},
{
"input": "6\n4 6 7 8 6 4",
"output": "5"
},
{
"input": "2\n1000000000 1000000000",
"output": "1"
},
{
"input": "42\n1 1 ... | 1,611,055,736 | 2,147,483,647 | Python 3 | OK | TESTS | 140 | 155 | 9,523,200 | n = int(input())
a = list(map(int,input().split()))
mini = min(a)
first = None
second = None
ans = 999999999999999
for i in range(n):
if a[i]==mini:
if first==None:
first = i
else:
second = i
ans = min(ans,second-first)
first = second
... | Title: Nearest Minimums
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array of *n* integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. Find the distance between two closest (nearest) minimums in it. It is guaranteed that in the array a minimum occurs at least two times.
I... | ```python
n = int(input())
a = list(map(int,input().split()))
mini = min(a)
first = None
second = None
ans = 999999999999999
for i in range(n):
if a[i]==mini:
if first==None:
first = i
else:
second = i
ans = min(ans,second-first)
first = s... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
858 | B | Which floor? | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | In a building where Polycarp lives there are equal number of flats on each floor. Unfortunately, Polycarp don't remember how many flats are on each floor, but he remembers that the flats are numbered from 1 from lower to upper floors. That is, the first several flats are on the first floor, the next several flats are o... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100, 0<=≤<=*m*<=≤<=100), where *n* is the number of the flat you need to restore floor for, and *m* is the number of flats in Polycarp's memory.
*m* lines follow, describing the Polycarp's memory: each of these lines contains a pair of integers *k**i*,<=*... | Print the number of the floor in which the *n*-th flat is located, if it is possible to determine it in a unique way. Print -1 if it is not possible to uniquely restore this floor. | [
"10 3\n6 2\n2 1\n7 3\n",
"8 4\n3 1\n6 2\n5 2\n2 1\n"
] | [
"4\n",
"-1\n"
] | In the first example the 6-th flat is on the 2-nd floor, while the 7-th flat is on the 3-rd, so, the 6-th flat is the last on its floor and there are 3 flats on each floor. Thus, the 10-th flat is on the 4-th floor.
In the second example there can be 3 or 4 flats on each floor, so we can't restore the floor for the 8-... | 750 | [
{
"input": "10 3\n6 2\n2 1\n7 3",
"output": "4"
},
{
"input": "8 4\n3 1\n6 2\n5 2\n2 1",
"output": "-1"
},
{
"input": "8 3\n7 2\n6 2\n1 1",
"output": "2"
},
{
"input": "4 2\n8 3\n3 1",
"output": "2"
},
{
"input": "11 4\n16 4\n11 3\n10 3\n15 4",
"output": "3"
... | 1,505,765,495 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 78 | 0 | n, m = map(int, input().split())
e = []
for i in range(m):
e.append(list(map(int,input().split())))
check = False
if m == 0 and n != 1:
print(-1)
exit(0)
ans = []
for i in range(1, 101):
check = True
for j in range(0, m):
if (e[j][0] + i - 1) // i != e[j][1]:
check =... | Title: Which floor?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a building where Polycarp lives there are equal number of flats on each floor. Unfortunately, Polycarp don't remember how many flats are on each floor, but he remembers that the flats are numbered from 1 from lower to u... | ```python
n, m = map(int, input().split())
e = []
for i in range(m):
e.append(list(map(int,input().split())))
check = False
if m == 0 and n != 1:
print(-1)
exit(0)
ans = []
for i in range(1, 101):
check = True
for j in range(0, m):
if (e[j][0] + i - 1) // i != e[j][1]:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
730 | J | Bottles | PROGRAMMING | 1,900 | [
"dp"
] | null | null | Nick has *n* bottles of soda left after his birthday. Each bottle is described by two values: remaining amount of soda *a**i* and bottle volume *b**i* (*a**i*<=≤<=*b**i*).
Nick has decided to pour all remaining soda into minimal number of bottles, moreover he has to do it as soon as possible. Nick spends *x* seconds t... | The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the amount of soda remaining in the *i*-th bottle.
The third line contains *n* positive integers *b*1,<=*b*2,<=...... | The only line should contain two integers *k* and *t*, where *k* is the minimal number of bottles that can store all the soda and *t* is the minimal time to pour the soda into *k* bottles. | [
"4\n3 3 4 3\n4 7 6 5\n",
"2\n1 1\n100 100\n",
"5\n10 30 5 6 24\n10 41 7 8 24\n"
] | [
"2 6\n",
"1 1\n",
"3 11\n"
] | In the first example Nick can pour soda from the first bottle to the second bottle. It will take 3 seconds. After it the second bottle will contain 3 + 3 = 6 units of soda. Then he can pour soda from the fourth bottle to the second bottle and to the third bottle: one unit to the second and two units to the third. It wi... | 0 | [
{
"input": "4\n3 3 4 3\n4 7 6 5",
"output": "2 6"
},
{
"input": "2\n1 1\n100 100",
"output": "1 1"
},
{
"input": "5\n10 30 5 6 24\n10 41 7 8 24",
"output": "3 11"
},
{
"input": "1\n1\n100",
"output": "1 0"
},
{
"input": "1\n100\n100",
"output": "1 0"
},
{
... | 1,688,620,416 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 2,000 | 2,150,400 | n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
arr=[[a[i],b[i]] for i in range(n)]
arr.sort(key=lambda x:-x[1])
p,ans1=0,-1
s=sum(a)
for i in range(n):
p+=arr[i][1]
if p>=s:
ans1=i+1
break
ans=[[-10**9]*(p+1) for i in range(ans1+1)]
ans[0][0]=0
for... | Title: Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nick has *n* bottles of soda left after his birthday. Each bottle is described by two values: remaining amount of soda *a**i* and bottle volume *b**i* (*a**i*<=≤<=*b**i*).
Nick has decided to pour all remaining soda into minim... | ```python
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
arr=[[a[i],b[i]] for i in range(n)]
arr.sort(key=lambda x:-x[1])
p,ans1=0,-1
s=sum(a)
for i in range(n):
p+=arr[i][1]
if p>=s:
ans1=i+1
break
ans=[[-10**9]*(p+1) for i in range(ans1+1)]
ans[0]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
447 | A | DZY Loves Hash | PROGRAMMING | 800 | [
"implementation"
] | null | null | DZY has a hash table with *p* buckets, numbered from 0 to *p*<=-<=1. He wants to insert *n* numbers, in the order they are given, into the hash table. For the *i*-th number *x**i*, DZY will put it into the bucket numbered *h*(*x**i*), where *h*(*x*) is the hash function. In this problem we will assume, that *h*(*x*)<==... | The first line contains two integers, *p* and *n* (2<=≤<=*p*,<=*n*<=≤<=300). Then *n* lines follow. The *i*-th of them contains an integer *x**i* (0<=≤<=*x**i*<=≤<=109). | Output a single integer — the answer to the problem. | [
"10 5\n0\n21\n53\n41\n53\n",
"5 5\n0\n1\n2\n3\n4\n"
] | [
"4\n",
"-1\n"
] | none | 500 | [
{
"input": "10 5\n0\n21\n53\n41\n53",
"output": "4"
},
{
"input": "5 5\n0\n1\n2\n3\n4",
"output": "-1"
},
{
"input": "10 6\n811966798\n734823552\n790326404\n929189974\n414343256\n560346537",
"output": "4"
},
{
"input": "2 2\n788371161\n801743052",
"output": "-1"
},
{
... | 1,565,493,193 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 109 | 0 | p,n = map(int,input().split())
l,f = [],0
for i in range(n):
k = int(input())
if k%p in l:
print(i+1)
f=1
break
else:
l.append(k%p)
if f==0:print(-1) | Title: DZY Loves Hash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a hash table with *p* buckets, numbered from 0 to *p*<=-<=1. He wants to insert *n* numbers, in the order they are given, into the hash table. For the *i*-th number *x**i*, DZY will put it into the bucket numbere... | ```python
p,n = map(int,input().split())
l,f = [],0
for i in range(n):
k = int(input())
if k%p in l:
print(i+1)
f=1
break
else:
l.append(k%p)
if f==0:print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,627,400,899 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 184 | 20,172,800 | n, m = map(int, input().split(" "))
ls = list(map(int, input().split(" ")))
ls.sort(reverse=True)
# MIN
count = n
_min_ = 0
i = m-1
while count>0:
_min_ += (ls[i]*(ls[i]+1)//2 - max(0,ls[i]-count)*(max(0,ls[i]-count)+1)//2)
count -= ls[i]
i -= 1
if i==-1:
i = m-1
# MAX
count = ... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
n, m = map(int, input().split(" "))
ls = list(map(int, input().split(" ")))
ls.sort(reverse=True)
# MIN
count = n
_min_ = 0
i = m-1
while count>0:
_min_ += (ls[i]*(ls[i]+1)//2 - max(0,ls[i]-count)*(max(0,ls[i]-count)+1)//2)
count -= ls[i]
i -= 1
if i==-1:
i = m-1
# MAX... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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