contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
548 | B | Mike and Fun | PROGRAMMING | 1,400 | [
"brute force",
"dp",
"greedy",
"implementation"
] | null | null | Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an *n*<=×<=*m* grid, there's exactly one bear in each cell. We denote the bear standing in column number *j* of row number *i* by (*i*,<=*j*). Mike's hands are on his ears (since he's the judge) and each bear s... | The first line of input contains three integers *n*, *m* and *q* (1<=≤<=*n*,<=*m*<=≤<=500 and 1<=≤<=*q*<=≤<=5000).
The next *n* lines contain the grid description. There are *m* integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next *q* lines contain the inf... | After each round, print the current score of the bears. | [
"5 4 5\n0 1 1 0\n1 0 0 1\n0 1 1 0\n1 0 0 1\n0 0 0 0\n1 1\n1 4\n1 1\n4 2\n4 3\n"
] | [
"3\n4\n3\n3\n4\n"
] | none | 1,000 | [
{
"input": "5 4 5\n0 1 1 0\n1 0 0 1\n0 1 1 0\n1 0 0 1\n0 0 0 0\n1 1\n1 4\n1 1\n4 2\n4 3",
"output": "3\n4\n3\n3\n4"
},
{
"input": "2 2 10\n1 1\n0 1\n1 1\n2 1\n1 1\n2 2\n1 1\n2 1\n2 2\n2 2\n1 1\n1 1",
"output": "1\n2\n2\n2\n1\n1\n1\n1\n2\n1"
},
{
"input": "2 2 10\n1 1\n0 1\n2 2\n2 2\n1 1\... | 1,653,228,871 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 61 | 512,000 | def tenhoirmao(linha, coluna):
global ncol, grid
if vivo(linha, coluna+1) or vivo(linha, coluna-1):
return True
else:
return False
def vivo(linha, coluna):
global ncol, grid
if linha < 0 or linha >= nlin or coluna < 0 or coluna >= ncol:
return False
if grid[linha][co... | Title: Mike and Fun
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an *n*<=×<=*m* grid, there's exactly one bear in each cell. We denote the bear standing in column number *j* of ... | ```python
def tenhoirmao(linha, coluna):
global ncol, grid
if vivo(linha, coluna+1) or vivo(linha, coluna-1):
return True
else:
return False
def vivo(linha, coluna):
global ncol, grid
if linha < 0 or linha >= nlin or coluna < 0 or coluna >= ncol:
return False
if grid... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
931 | A | Friends Meeting | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes acco... | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*. | Print the minimum possible total tiredness if the friends meet in the same point. | [
"3\n4\n",
"101\n99\n",
"5\n10\n"
] | [
"1\n",
"2\n",
"9\n"
] | In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, an... | 500 | [
{
"input": "3\n4",
"output": "1"
},
{
"input": "101\n99",
"output": "2"
},
{
"input": "5\n10",
"output": "9"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "1\n1000",
"output": "250000"
},
{
"input": "999\n1000",
"output": "1"
},
{
"inpu... | 1,618,636,573 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 62 | 0 | a=int(input())
b=int(input())
len=abs(a-b)
if len%2==0:
moves=len//2*(len//2+1)
else:
moves=len//2*(len//2+2)+1
print(moves)
| Title: Friends Meeting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in... | ```python
a=int(input())
b=int(input())
len=abs(a-b)
if len%2==0:
moves=len//2*(len//2+1)
else:
moves=len//2*(len//2+2)+1
print(moves)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,650,713,909 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | w = input()
if "".join(reversed(input()))==w:
print("YES")
else:
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
w = input()
if "".join(reversed(input()))==w:
print("YES")
else:
print("NO")
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
900 | B | Position in Fraction | PROGRAMMING | 1,300 | [
"math",
"number theory"
] | null | null | You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point. | The first contains three single positive integers *a*, *b*, *c* (1<=≤<=*a*<=<<=*b*<=≤<=105, 0<=≤<=*c*<=≤<=9). | Print position of the first occurrence of digit *c* into the fraction. Positions are numbered from 1 after decimal point. It there is no such position, print -1. | [
"1 2 0\n",
"2 3 7\n"
] | [
"2",
"-1"
] | The fraction in the first example has the following decimal notation: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/896357459a466614a0542f34c9cfb0cef1afc9ed.png" style="max-width: 100.0%;max-height: 100.0%;"/>. The first zero stands on second position.
The fraction in the second example ... | 1,000 | [
{
"input": "1 2 0",
"output": "2"
},
{
"input": "2 3 7",
"output": "-1"
},
{
"input": "1 100000 1",
"output": "5"
},
{
"input": "1 7 7",
"output": "6"
},
{
"input": "99999 100000 8",
"output": "-1"
},
{
"input": "44102 73848 2",
"output": "132"
}... | 1,573,043,284 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 93 | 204,800 | a,b,c=list(map(int,input().split()))
n=str(a/b)+'0'
p=0
for i in range (2,len(n)):
if int(n[i])==c:
p=i
break
if p>0: print (p-1)
else: print(-1) | Title: Position in Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point.
Input Specification:
The first contains three single positive integers *a*, *b*, ... | ```python
a,b,c=list(map(int,input().split()))
n=str(a/b)+'0'
p=0
for i in range (2,len(n)):
if int(n[i])==c:
p=i
break
if p>0: print (p-1)
else: print(-1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
10 | D | LCIS | PROGRAMMING | 2,800 | [
"dp"
] | D. LCIS | 1 | 256 | This problem differs from one which was on the online contest.
The sequence *a*1,<=*a*2,<=...,<=*a**n* is called increasing, if *a**i*<=<<=*a**i*<=+<=1 for *i*<=<<=*n*.
The sequence *s*1,<=*s*2,<=...,<=*s**k* is called the subsequence of the sequence *a*1,<=*a*2,<=...,<=*a**n*, if there exist such a set of inde... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=500) — the length of the first sequence. The second line contains *n* space-separated integers from the range [0,<=109] — elements of the first sequence. The third line contains an integer *m* (1<=≤<=*m*<=≤<=500) — the length of the second sequence. The fourth line ... | In the first line output *k* — the length of the longest common increasing subsequence. In the second line output the subsequence itself. Separate the elements with a space. If there are several solutions, output any. | [
"7\n2 3 1 6 5 4 6\n4\n1 3 5 6\n",
"5\n1 2 0 2 1\n3\n1 0 1\n"
] | [
"3\n3 5 6 \n",
"2\n0 1 \n"
] | none | 0 | [
{
"input": "7\n2 3 1 6 5 4 6\n4\n1 3 5 6",
"output": "3\n3 5 6 "
},
{
"input": "5\n1 2 0 2 1\n3\n1 0 1",
"output": "2\n0 1 "
},
{
"input": "2\n6 10\n3\n6 3 3",
"output": "1\n6 "
},
{
"input": "1\n7\n2\n7 9",
"output": "1\n7 "
},
{
"input": "3\n37 49 24\n3\n33 5 70... | 1,696,710,158 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int main()
{
ll n; cin >> n;
vector<ll> v(n + 1);
for (ll i = 1; i <= n; ++i) {
cin >> v[i];
}
ll m; cin >> m;
vector<ll> u(m + 1);
for (ll i = 1; i <= m; ++i) {
cin >> u[i];
}
v... | Title: LCIS
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
This problem differs from one which was on the online contest.
The sequence *a*1,<=*a*2,<=...,<=*a**n* is called increasing, if *a**i*<=<<=*a**i*<=+<=1 for *i*<=<<=*n*.
The sequence *s*1,<=*s*2,<=...,<=*s**k* is called the sub... | ```python
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int main()
{
ll n; cin >> n;
vector<ll> v(n + 1);
for (ll i = 1; i <= n; ++i) {
cin >> v[i];
}
ll m; cin >> m;
vector<ll> u(m + 1);
for (ll i = 1; i <= m; ++i) {
cin >> u[i];
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
534 | A | Exam | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | An exam for *n* students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (*i* and *i*<=+<=1) always studied side by side and became friends and if they take an exam sitting next to each other, they will help each other... | A single line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of students at an exam. | In the first line print integer *k* — the maximum number of students who can be seated so that no two students with adjacent numbers sit next to each other.
In the second line print *k* distinct integers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=*n*), where *a**i* is the number of the student on the *i*-th position... | [
"6",
"3\n"
] | [
"6\n1 5 3 6 2 4",
"2\n1 3"
] | none | 500 | [
{
"input": "6",
"output": "6\n5 3 1 6 4 2 "
},
{
"input": "3",
"output": "2\n1 3"
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "2",
"output": "1\n1"
},
{
"input": "4",
"output": "4\n3 1 4 2 "
},
{
"input": "5",
"output": "5\n5 3 1 4 2 "
},
... | 1,589,853,832 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | n = int(input())
if n <= 2:
print('1\n1')
elif n == 3:
print('2\n1 3')
else:
w = ''
s = 0
for r in range(2,n+1,2):
w = w + str(r) + ' '
for r in range(1,n+1,2):
w = w + str(r) + ' '
print(w)
| Title: Exam
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An exam for *n* students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (*i* and *i*<=+<=1) always studied side by side and bec... | ```python
n = int(input())
if n <= 2:
print('1\n1')
elif n == 3:
print('2\n1 3')
else:
w = ''
s = 0
for r in range(2,n+1,2):
w = w + str(r) + ' '
for r in range(1,n+1,2):
w = w + str(r) + ' '
print(w)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
378 | A | Playing with Dice | PROGRAMMING | 800 | [
"brute force"
] | null | null | Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many w... | The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly. | Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly. | [
"2 5\n",
"2 4\n"
] | [
"3 0 3\n",
"2 1 3\n"
] | The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | 500 | [
{
"input": "2 5",
"output": "3 0 3"
},
{
"input": "2 4",
"output": "2 1 3"
},
{
"input": "5 3",
"output": "2 1 3"
},
{
"input": "1 6",
"output": "3 0 3"
},
{
"input": "5 1",
"output": "3 1 2"
},
{
"input": "6 3",
"output": "2 0 4"
},
{
"inp... | 1,576,669,971 | 2,147,483,647 | PyPy 3 | OK | TESTS | 38 | 140 | 0 | a,b=map(int,input().split())
l=[0]*3
for i in range(1,7):
if abs(a-i)<abs(b-i):
l[0]+=1
elif abs(a-i)==abs(b-i):
l[1]+=1
else:
l[2]+=1
print(*l)
| Title: Playing with Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same diff... | ```python
a,b=map(int,input().split())
l=[0]*3
for i in range(1,7):
if abs(a-i)<abs(b-i):
l[0]+=1
elif abs(a-i)==abs(b-i):
l[1]+=1
else:
l[2]+=1
print(*l)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,573,064,032 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 202 | 2,457,600 | s = "heidi"
k = 0
a = input()
for i in range(len(a)):
if(a[i] == s[k]):
k += 1
if(k >= len(s)):
print("YES")
else:
print("NO") | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
s = "heidi"
k = 0
a = input()
for i in range(len(a)):
if(a[i] == s[k]):
k += 1
if(k >= len(s)):
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
465 | A | inc ARG | PROGRAMMING | 900 | [
"implementation"
] | null | null | Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of *n* bits. These bits are numbered from 1 to *n*. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of bits in the cell.
The second line contains a string consisting of *n* characters — the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significan... | Print a single integer — the number of bits in the cell which change their state after we add 1 to the cell. | [
"4\n1100\n",
"4\n1111\n"
] | [
"3\n",
"4\n"
] | In the first sample the cell ends up with value 0010, in the second sample — with 0000. | 500 | [
{
"input": "4\n1100",
"output": "3"
},
{
"input": "4\n1111",
"output": "4"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "1"
},
{
"input": "2\n01",
"output": "1"
},
{
"input": "2\n1... | 1,569,567,099 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 109 | 0 |
n = int(input())
l = list(input())
li = [int(i) for i in l]
if 0 in li:
print(li.index(0) + 1)
else:
print(n) | Title: inc ARG
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of *n* bits. These bits are numbered from 1 to *n*. An integer is stored in the cell in the following way: the lea... | ```python
n = int(input())
l = list(input())
li = [int(i) for i in l]
if 0 in li:
print(li.index(0) + 1)
else:
print(n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
817 | B | Makes And The Product | PROGRAMMING | 1,500 | [
"combinatorics",
"implementation",
"math",
"sortings"
] | null | null | After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular question: how many triples of indices (*i*,<= *j*,<= *k*) (*i*<=<<=*j*<=<<=*k*), such that *a**i*·*a**j*·*a... | The first line of input contains a positive integer number *n* (3<=≤<=*n*<=≤<=105) — the number of elements in array *a*. The second line contains *n* positive integer numbers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of a given array. | Print one number — the quantity of triples (*i*,<= *j*,<= *k*) such that *i*,<= *j* and *k* are pairwise distinct and *a**i*·*a**j*·*a**k* is minimum possible. | [
"4\n1 1 1 1\n",
"5\n1 3 2 3 4\n",
"6\n1 3 3 1 3 2\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first example Makes always chooses three ones out of four, and the number of ways to choose them is 4.
In the second example a triple of numbers (1, 2, 3) is chosen (numbers, not indices). Since there are two ways to choose an element 3, then the answer is 2.
In the third example a triple of numbers (1, 1, 2) ... | 0 | [
{
"input": "4\n1 1 1 1",
"output": "4"
},
{
"input": "5\n1 3 2 3 4",
"output": "2"
},
{
"input": "6\n1 3 3 1 3 2",
"output": "1"
},
{
"input": "3\n1000000000 1000000000 1000000000",
"output": "1"
},
{
"input": "4\n1 1 2 2",
"output": "2"
},
{
"input": ... | 1,498,338,637 | 2,147,483,647 | PyPy 3 | IDLENESS_LIMIT_EXCEEDED | TESTS | 1 | 93 | 23,142,400 | n=int(input())
list=list(map(int,input().split()))
list.sort()
a,b,c=list[0],list[1],list[2]
rslt=0
for i in list[2:]:
if c==i :rslt+=1
else :break
if c!=b :print(rslt)
elif a!=b :print(rslt*(rslt+1)//2)
else : print(rslt*(rslt+1)*(rslt+2)//6)
| Title: Makes And The Product
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular questi... | ```python
n=int(input())
list=list(map(int,input().split()))
list.sort()
a,b,c=list[0],list[1],list[2]
rslt=0
for i in list[2:]:
if c==i :rslt+=1
else :break
if c!=b :print(rslt)
elif a!=b :print(rslt*(rslt+1)//2)
else : print(rslt*(rslt+1)*(rslt+2)//6)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
804 | B | Minimum number of steps | PROGRAMMING | 1,400 | [
"combinatorics",
"greedy",
"implementation",
"math"
] | null | null | We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substring, our job is done. Print the minimum number of steps we should perform to make our job done modulo 109<=+<... | The first line contains the initial string consisting of letters 'a' and 'b' only with length from 1 to 106. | Print the minimum number of steps modulo 109<=+<=7. | [
"ab\n",
"aab\n"
] | [
"1\n",
"3\n"
] | The first example: "ab" → "bba".
The second example: "aab" → "abba" → "bbaba" → "bbbbaa". | 1,000 | [
{
"input": "ab",
"output": "1"
},
{
"input": "aab",
"output": "3"
},
{
"input": "aaaaabaabababaaaaaba",
"output": "17307"
},
{
"input": "abaabaaabbabaabab",
"output": "1795"
},
{
"input": "abbaa",
"output": "2"
},
{
"input": "abbaaabaabaaaaabbbbaababaa... | 1,653,438,975 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 61 | 614,400 | from collections import deque
sequencia = list(input())
usoA = deque([0])
usoB = deque()
primeiroA = len(sequencia)
contadorA = 0
contadorB = 0
for a in range(len(sequencia)):
if sequencia[a] == "a" and primeiroA == len(sequencia):
y = 1
primeiroA = a
contadorA += 1
elif sequencia[... | Title: Minimum number of steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substr... | ```python
from collections import deque
sequencia = list(input())
usoA = deque([0])
usoB = deque()
primeiroA = len(sequencia)
contadorA = 0
contadorB = 0
for a in range(len(sequencia)):
if sequencia[a] == "a" and primeiroA == len(sequencia):
y = 1
primeiroA = a
contadorA += 1
elif ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,699,527,614 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 2 | 249 | 268,390,400 | n = int(input())
z = list(range(2, n))
inter_sum = 0
for i in range(len(z)):
if z == []:
break
if z[i] == 0:
inter_sum += z[i]
if z[i] % 2 != 0:
inter_sum -= z[i]
else:
inter_sum += z[i]
y = -1 + inter_sum + ((-1) ** n) * n
print(y) | Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
n = int(input())
z = list(range(2, n))
inter_sum = 0
for i in range(len(z)):
if z == []:
break
if z[i] == 0:
inter_sum += z[i]
if z[i] % 2 != 0:
inter_sum -= z[i]
else:
inter_sum += z[i]
y = -1 + inter_sum + ((-1) ** n) * n
print(y)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
44 | E | Anfisa the Monkey | PROGRAMMING | 1,400 | [
"dp"
] | E. Anfisa the Monkey | 2 | 256 | Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into *k* lines not shorter than *a* and not longer than *b*, for the text to resemble h... | The first line contains three integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=200, 1<=≤<=*a*<=≤<=*b*<=≤<=200). The second line contains a sequence of lowercase Latin letters — the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols. | Print *k* lines, each of which contains no less than *a* and no more than *b* symbols — Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print... | [
"3 2 5\nabrakadabra\n",
"4 1 2\nabrakadabra\n"
] | [
"ab\nrakad\nabra\n",
"No solution\n"
] | none | 0 | [
{
"input": "3 2 5\nabrakadabra",
"output": "abra\nkada\nbra"
},
{
"input": "4 1 2\nabrakadabra",
"output": "No solution"
},
{
"input": "3 1 2\nvgnfpo",
"output": "vg\nnf\npo"
},
{
"input": "5 3 4\nvrrdnhazvexzjfv",
"output": "vrr\ndnh\nazv\nexz\njfv"
},
{
"input":... | 1,602,689,266 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 17 | 2,000 | 10,035,200 | s=input()
s1=s.split()
k=int(s1[0])
a=int(s1[1])
b=int(s1[2])
s=input()
n=len(s)
final=[]
flag=0
def fun(x,tot):
global flag
global final
if tot==k and sum(x)==n:
final=x
flag=1
return
if sum(x)>n:
return
if tot>k:
retu... | Title: Anfisa the Monkey
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she ... | ```python
s=input()
s1=s.split()
k=int(s1[0])
a=int(s1[1])
b=int(s1[2])
s=input()
n=len(s)
final=[]
flag=0
def fun(x,tot):
global flag
global final
if tot==k and sum(x)==n:
final=x
flag=1
return
if sum(x)>n:
return
if tot>k:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,679,663,203 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n = int(input())
home_uniforms = []
guest_uniforms = []
for i in range(n):
h, g = map(int, input().split())
home_uniforms.append(h)
guest_uniforms.append(g)
count = 0
for i in range(n):
for j in range(n):
if i != j and home_uniforms[i] == guest_uniforms[j]:
count +... | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
n = int(input())
home_uniforms = []
guest_uniforms = []
for i in range(n):
h, g = map(int, input().split())
home_uniforms.append(h)
guest_uniforms.append(g)
count = 0
for i in range(n):
for j in range(n):
if i != j and home_uniforms[i] == guest_uniforms[j]:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
225 | C | Barcode | PROGRAMMING | 1,700 | [
"dp",
"matrices"
] | null | null | You've got an *n*<=×<=*m* pixel picture. Each pixel can be white or black. Your task is to change the colors of as few pixels as possible to obtain a barcode picture.
A picture is a barcode if the following conditions are fulfilled:
- All pixels in each column are of the same color. - The width of each monochrome ... | The first line contains four space-separated integers *n*, *m*, *x* and *y* (1<=≤<=*n*,<=*m*,<=*x*,<=*y*<=≤<=1000; *x*<=≤<=*y*).
Then follow *n* lines, describing the original image. Each of these lines contains exactly *m* characters. Character "." represents a white pixel and "#" represents a black pixel. The pictur... | In the first line print the minimum number of pixels to repaint. It is guaranteed that the answer exists. | [
"6 5 1 2\n##.#.\n.###.\n###..\n#...#\n.##.#\n###..\n",
"2 5 1 1\n#####\n.....\n"
] | [
"11\n",
"5\n"
] | In the first test sample the picture after changing some colors can looks as follows:
In the second test sample the picture after changing some colors can looks as follows: | 1,500 | [
{
"input": "6 5 1 2\n##.#.\n.###.\n###..\n#...#\n.##.#\n###..",
"output": "11"
},
{
"input": "10 5 3 7\n.####\n###..\n##.##\n#..#.\n.#...\n#.##.\n.##..\n.#.##\n#.#..\n.#..#",
"output": "24"
},
{
"input": "6 3 1 4\n##.\n#..\n#..\n..#\n.#.\n#.#",
"output": "6"
},
{
"input": "5 ... | 1,603,691,271 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 29 | 2,000 | 181,248,000 | import sys
cache = {}
def DP(curPos, color, placing, x, y, grid):
# since readGrid is represented by (white, black), color is rep.
# by 0 and 1. if color is 0 (white), we need to turn the BLACK squares
# white (grid[1], so we should lookup color^1.
if curPos == 0:
if x <= placing <= y:
... | Title: Barcode
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got an *n*<=×<=*m* pixel picture. Each pixel can be white or black. Your task is to change the colors of as few pixels as possible to obtain a barcode picture.
A picture is a barcode if the following conditions are fulf... | ```python
import sys
cache = {}
def DP(curPos, color, placing, x, y, grid):
# since readGrid is represented by (white, black), color is rep.
# by 0 and 1. if color is 0 (white), we need to turn the BLACK squares
# white (grid[1], so we should lookup color^1.
if curPos == 0:
if x <= placing <=... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
362 | B | Petya and Staircases | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump over one or two stairs at a time. But some stairs are too dirty and Petya doesn't want to step on them.
No... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=109, 0<=≤<=*m*<=≤<=3000) — the number of stairs in the staircase and the number of dirty stairs, correspondingly. The second line contains *m* different space-separated integers *d*1,<=*d*2,<=...,<=*d**m* (1<=≤<=*d**i*<=≤<=*n*) — the numbers of the dirty s... | Print "YES" if Petya can reach stair number *n*, stepping only on the clean stairs. Otherwise print "NO". | [
"10 5\n2 4 8 3 6\n",
"10 5\n2 4 5 7 9\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "10 5\n2 4 8 3 6",
"output": "NO"
},
{
"input": "10 5\n2 4 5 7 9",
"output": "YES"
},
{
"input": "10 9\n2 3 4 5 6 7 8 9 10",
"output": "NO"
},
{
"input": "5 2\n4 5",
"output": "NO"
},
{
"input": "123 13\n36 73 111 2 92 5 47 55 48 113 7 78 37",
"outp... | 1,623,393,627 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 77 | 409,600 | from sys import *
from math import *
from sys import stdin,stdout
from collections import *
int_arr = lambda : list(map(int,stdin.readline().strip().split()))
str_arr = lambda :list(map(str,stdin.readline().split()))
get_str = lambda : map(str,stdin.readline().strip().split())
get_int = lambda: map(int,stdin.r... | Title: Petya and Staircases
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump o... | ```python
from sys import *
from math import *
from sys import stdin,stdout
from collections import *
int_arr = lambda : list(map(int,stdin.readline().strip().split()))
str_arr = lambda :list(map(str,stdin.readline().split()))
get_str = lambda : map(str,stdin.readline().strip().split())
get_int = lambda: map(i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,611,946,337 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | input()
l =list( map(int, input().split()))
l1 = []
l2 = []
l3 = []
neg = 0
for e in l:
if e < 0:
neg += 1
neg_added = False
for e in l:
if e < 0 and not neg_added:
l1.append(e)
neg_added = True
elif e == 0:
l3.append(e)
elif neg%2 == 1 and e... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
input()
l =list( map(int, input().split()))
l1 = []
l2 = []
l3 = []
neg = 0
for e in l:
if e < 0:
neg += 1
neg_added = False
for e in l:
if e < 0 and not neg_added:
l1.append(e)
neg_added = True
elif e == 0:
l3.append(e)
elif neg%2 ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
146 | A | Lucky Ticket | PROGRAMMING | 800 | [
"implementation"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya loves tickets very much. As we know, each ticket has a number that is a positive integer. It... | The first line contains an even integer *n* (2<=≤<=*n*<=≤<=50) — the length of the ticket number that needs to be checked. The second line contains an integer whose length equals exactly *n* — the ticket number. The number may contain leading zeros. | On the first line print "YES" if the given ticket number is lucky. Otherwise, print "NO" (without the quotes). | [
"2\n47\n",
"4\n4738\n",
"4\n4774\n"
] | [
"NO\n",
"NO\n",
"YES\n"
] | In the first sample the sum of digits in the first half does not equal the sum of digits in the second half (4 ≠ 7).
In the second sample the ticket number is not the lucky number. | 500 | [
{
"input": "2\n47",
"output": "NO"
},
{
"input": "4\n4738",
"output": "NO"
},
{
"input": "4\n4774",
"output": "YES"
},
{
"input": "4\n4570",
"output": "NO"
},
{
"input": "6\n477477",
"output": "YES"
},
{
"input": "6\n777777",
"output": "YES"
},
... | 1,690,134,938 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 92 | 0 | n = int(input())
m = int(n/2)
A= input()
dem=0
t1=0
t2=0
for i in range(m):
t1 += int(A[i])
if A[i] != "4" and A[i]!= "7":
dem += 1
for i in range(m,n):
t2 += int(A[i])
if A[i] != "4" and A[i]!= "7":
dem+=1
if dem > 0 or t1 != t2:
print("NO")
else:
print("YES") | Title: Lucky Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
m = int(n/2)
A= input()
dem=0
t1=0
t2=0
for i in range(m):
t1 += int(A[i])
if A[i] != "4" and A[i]!= "7":
dem += 1
for i in range(m,n):
t2 += int(A[i])
if A[i] != "4" and A[i]!= "7":
dem+=1
if dem > 0 or t1 != t2:
print("NO")
else:
prin... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,687,689,686 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | s = input()
ok = "NO"
for i in s:
if i == 'H' or i == '9' or i == 'Q':
ok = "YES"
break
print(ok) | Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
s = input()
ok = "NO"
for i in s:
if i == 'H' or i == '9' or i == 'Q':
ok = "YES"
break
print(ok)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,607,400,293 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 109 | 0 | n, k = map(int, input().split())
a = list(map(int, input().split()))
i = 0
avg = round(sum(a)/n, 3)
while avg < k - 0.5 :
i += 1
avg = round((sum(a) + i*k) / (n+i), 3)
print(i)
| Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
n, k = map(int, input().split())
a = list(map(int, input().split()))
i = 0
avg = round(sum(a)/n, 3)
while avg < k - 0.5 :
i += 1
avg = round((sum(a) + i*k) / (n+i), 3)
print(i)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
121 | A | Lucky Sum | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let *next*(*x*) be the minimum lucky number which is larger than or equals *x*. Petya is interested ... | The single line contains two integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=109) — the left and right interval limits. | In the single line print the only number — the sum *next*(*l*)<=+<=*next*(*l*<=+<=1)<=+<=...<=+<=*next*(*r*<=-<=1)<=+<=*next*(*r*).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"2 7\n",
"7 7\n"
] | [
"33\n",
"7\n"
] | In the first sample: *next*(2) + *next*(3) + *next*(4) + *next*(5) + *next*(6) + *next*(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: *next*(7) = 7 | 500 | [
{
"input": "2 7",
"output": "33"
},
{
"input": "7 7",
"output": "7"
},
{
"input": "1 9",
"output": "125"
},
{
"input": "4 7",
"output": "25"
},
{
"input": "12 47",
"output": "1593"
},
{
"input": "6 77",
"output": "4012"
},
{
"input": "1 100... | 1,590,295,729 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 2,764,800 | def nex(t):
t = ['0']+list(str(t))
l = t.copy()
for i in range(1,len(l)):
if l[i]>'7':
l[i-1]='4' if t[i-1]<'4' else '7'
l[i]='4'
elif l[i]<='4':
l[i]='4'
else:
l[i]='7'
return int(''.join(l))
l,r = map(int, input().sp... | Title: Lucky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let *... | ```python
def nex(t):
t = ['0']+list(str(t))
l = t.copy()
for i in range(1,len(l)):
if l[i]>'7':
l[i-1]='4' if t[i-1]<'4' else '7'
l[i]='4'
elif l[i]<='4':
l[i]='4'
else:
l[i]='7'
return int(''.join(l))
l,r = map(int, ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift.... | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,695,179,664 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 101 | 124 | 0 | N=int(input())
Arr=[0]*(N+1)
L=list(map(int,input().split()))
for i in range(1,N+1):
Arr[i-1]=L.index(i)+1
Arr=Arr[:-1]
for i in Arr:
print(i,end=' ') | Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on t... | ```python
N=int(input())
Arr=[0]*(N+1)
L=list(map(int,input().split()))
for i in range(1,N+1):
Arr[i-1]=L.index(i)+1
Arr=Arr[:-1]
for i in Arr:
print(i,end=' ')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
152 | A | Marks | PROGRAMMING | 900 | [
"implementation"
] | null | null | Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at ... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepa... | Print the single number — the number of successful students in the given group. | [
"3 3\n223\n232\n112\n",
"3 5\n91728\n11828\n11111\n"
] | [
"2\n",
"3\n"
] | In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | 500 | [
{
"input": "3 3\n223\n232\n112",
"output": "2"
},
{
"input": "3 5\n91728\n11828\n11111",
"output": "3"
},
{
"input": "2 2\n48\n27",
"output": "1"
},
{
"input": "2 1\n4\n6",
"output": "1"
},
{
"input": "1 2\n57",
"output": "1"
},
{
"input": "1 1\n5",
... | 1,697,459,441 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 31 | 0 | x, t, = map(int, input().split())
stds = []
for _ in range(x):
stds.append(input())
count_ = 0
for i in range(x):
k = 0
for j in range(i, x):
if int(stds[i][k]) >= int(stds[j][k]) and i != j:
count_ += 1
continue
k += 1
print(count_) | Title: Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student ... | ```python
x, t, = map(int, input().split())
stds = []
for _ in range(x):
stds.append(input())
count_ = 0
for i in range(x):
k = 0
for j in range(i, x):
if int(stds[i][k]) >= int(stds[j][k]) and i != j:
count_ += 1
continue
k += 1
print(count_)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,421,352,221 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 2,000 | 102,400 | b=input()
def b2d(a):
p=0
for i in range(len(a)):
p=p+2**(len(a)-i-1)*int(a[i])
return p
mx=0
t=""
for i in range(len(b)):
s=""
for j in range(len(b)):
if i!=j:
s=s+b[j]
m=b2d(s)
if m>mx:
mx=m
t=s
print(t)
| Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
b=input()
def b2d(a):
p=0
for i in range(len(a)):
p=p+2**(len(a)-i-1)*int(a[i])
return p
mx=0
t=""
for i in range(len(b)):
s=""
for j in range(len(b)):
if i!=j:
s=s+b[j]
m=b2d(s)
if m>mx:
mx=m
t=s
print(t)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
910 | B | Door Frames | PROGRAMMING | 1,600 | [
"greedy",
"implementation"
] | null | null | Petya has equal wooden bars of length *n*. He wants to make a frame for two equal doors. Each frame has two vertical (left and right) sides of length *a* and one top side of length *b*. A solid (i.e. continuous without breaks) piece of bar is needed for each side.
Determine a minimal number of wooden bars which are ne... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1<=000) — the length of each wooden bar.
The second line contains a single integer *a* (1<=≤<=*a*<=≤<=*n*) — the length of the vertical (left and right) sides of a door frame.
The third line contains a single integer *b* (1<=≤<=*b*<=≤<=*n*) — the length of t... | Print the minimal number of wooden bars with length *n* which are needed to make the frames for two doors. | [
"8\n1\n2\n",
"5\n3\n4\n",
"6\n4\n2\n",
"20\n5\n6\n"
] | [
"1\n",
"6\n",
"4\n",
"2\n"
] | In the first example one wooden bar is enough, since the total length of all six sides of the frames for two doors is 8.
In the second example 6 wooden bars is enough, because for each side of the frames the new wooden bar is needed. | 1,000 | [
{
"input": "8\n1\n2",
"output": "1"
},
{
"input": "5\n3\n4",
"output": "6"
},
{
"input": "6\n4\n2",
"output": "4"
},
{
"input": "20\n5\n6",
"output": "2"
},
{
"input": "1\n1\n1",
"output": "6"
},
{
"input": "3\n1\n2",
"output": "3"
},
{
"in... | 1,514,988,153 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 61 | 5,529,600 | n = int(input())
a = int(input())
b = int(input())
if (2*a+b)*2 <= n:
print(1)
exit()
if a+b > n:
print(6)
exit()
res = 6
ost = 0
n_a = 0
n_b = 0
for i in range(5,0,-1):
for j in range(i):
n_a += n // (a + b)
n_b += n // (a + b)
ost = n % (a + b)
if ost >= a and n_a < 4:
... | Title: Door Frames
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has equal wooden bars of length *n*. He wants to make a frame for two equal doors. Each frame has two vertical (left and right) sides of length *a* and one top side of length *b*. A solid (i.e. continuous without brea... | ```python
n = int(input())
a = int(input())
b = int(input())
if (2*a+b)*2 <= n:
print(1)
exit()
if a+b > n:
print(6)
exit()
res = 6
ost = 0
n_a = 0
n_b = 0
for i in range(5,0,-1):
for j in range(i):
n_a += n // (a + b)
n_b += n // (a + b)
ost = n % (a + b)
if ost >= a and n_a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,688,179,358 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | # LUOGU_RID: 113642709
a,b,c,d,e,f,g,h=list(map(int,input().split()));print(min(min(b*c//g,d*e),f//h)//a) | Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
# LUOGU_RID: 113642709
a,b,c,d,e,f,g,h=list(map(int,input().split()));print(min(min(b*c//g,d*e),f//h)//a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
257 | C | View Angle | PROGRAMMING | 1,800 | [
"brute force",
"geometry",
"math"
] | null | null | Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex at the origin of coordinates and with all mannequins standing inside or on the boarder of this a... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of mannequins.
Next *n* lines contain two space-separated integers each: *x**i*,<=*y**i* (|*x**i*|,<=|*y**i*|<=≤<=1000) — the coordinates of the *i*-th mannequin. It is guaranteed that the origin of the coordinates has no mannequin. It is gu... | Print a single real number — the value of the sought angle in degrees. The answer will be considered valid if the relative or absolute error doesn't exceed 10<=-<=6. | [
"2\n2 0\n0 2\n",
"3\n2 0\n0 2\n-2 2\n",
"4\n2 0\n0 2\n-2 0\n0 -2\n",
"2\n2 1\n1 2\n"
] | [
"90.0000000000\n",
"135.0000000000\n",
"270.0000000000\n",
"36.8698976458\n"
] | Solution for the first sample test is shown below:
Solution for the second sample test is shown below:
Solution for the third sample test is shown below:
Solution for the fourth sample test is shown below: | 1,500 | [
{
"input": "2\n2 0\n0 2",
"output": "90.0000000000"
},
{
"input": "3\n2 0\n0 2\n-2 2",
"output": "135.0000000000"
},
{
"input": "4\n2 0\n0 2\n-2 0\n0 -2",
"output": "270.0000000000"
},
{
"input": "2\n2 1\n1 2",
"output": "36.8698976458"
},
{
"input": "1\n1 1",
... | 1,461,368,890 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 560 | 4,608,000 | #!/usr/bin/env python3
from sys import stdin
from math import atan2, pi
def main():
num_points = int(stdin.readline())
# use the first point as baseline
x, y = map(int, stdin.readline().split())
initial_angle = atan2_deg(y, x)
min_angle = initial_angle
max_angle = initial_angle
for po... | Title: View Angle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex ... | ```python
#!/usr/bin/env python3
from sys import stdin
from math import atan2, pi
def main():
num_points = int(stdin.readline())
# use the first point as baseline
x, y = map(int, stdin.readline().split())
initial_angle = atan2_deg(y, x)
min_angle = initial_angle
max_angle = initial_angle
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,694,143,072 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | nums = input()
numLst = nums.split(" ")
m = int(numLst[0])
n = int(numLst[1])
size = m*n
domNum = size//2
print(domNum) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
nums = input()
numLst = nums.split(" ")
m = int(numLst[0])
n = int(numLst[1])
size = m*n
domNum = size//2
print(domNum)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,692,990,341 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 124 | 0 | n, k, l, c, d, p, nl, np = map(int, input().split())
d_toasts = (k*l)//nl
l_toasts = c*d
s_toasts = p//np
print(min(d_toasts, l_toasts, s_toasts)//n) | Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
n, k, l, c, d, p, nl, np = map(int, input().split())
d_toasts = (k*l)//nl
l_toasts = c*d
s_toasts = p//np
print(min(d_toasts, l_toasts, s_toasts)//n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,595,916,709 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 108 | 6,963,200 | def function(s):
if len(s)<=4:
return 'NO'
a=['h', 'e', 'l', 'l', 'o']
l=list(s)
total=0
j=0
for i in range(0, len(l)):
if l[i]==a[j]:
total+=1
j+=1
if total==5:
return 'YES'
return 'NO'
if __name__ == '__main__':
... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def function(s):
if len(s)<=4:
return 'NO'
a=['h', 'e', 'l', 'l', 'o']
l=list(s)
total=0
j=0
for i in range(0, len(l)):
if l[i]==a[j]:
total+=1
j+=1
if total==5:
return 'YES'
return 'NO'
if __name__ == '_... | 3.93303 | MatrixStudio/Codeforces-Python-Submissions |
985 | C | Liebig's Barrels | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to exactly one barrel.
Let volume *v**j* of barrel *j* be equal to the length of the minimal stave in it.
... | The first line contains three space-separated integers *n*, *k* and *l* (1<=≤<=*n*,<=*k*<=≤<=105, 1<=≤<=*n*·*k*<=≤<=105, 0<=≤<=*l*<=≤<=109).
The second line contains *m*<==<=*n*·*k* space-separated integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=109) — lengths of staves. | Print single integer — maximal total sum of the volumes of barrels or 0 if it's impossible to construct exactly *n* barrels satisfying the condition |*v**x*<=-<=*v**y*|<=≤<=*l* for any 1<=≤<=*x*<=≤<=*n* and 1<=≤<=*y*<=≤<=*n*. | [
"4 2 1\n2 2 1 2 3 2 2 3\n",
"2 1 0\n10 10\n",
"1 2 1\n5 2\n",
"3 2 1\n1 2 3 4 5 6\n"
] | [
"7\n",
"20\n",
"2\n",
"0\n"
] | In the first example you can form the following barrels: [1, 2], [2, 2], [2, 3], [2, 3].
In the second example you can form the following barrels: [10], [10].
In the third example you can form the following barrels: [2, 5].
In the fourth example difference between volumes of barrels in any partition is at least 2 so... | 0 | [
{
"input": "4 2 1\n2 2 1 2 3 2 2 3",
"output": "7"
},
{
"input": "2 1 0\n10 10",
"output": "20"
},
{
"input": "1 2 1\n5 2",
"output": "2"
},
{
"input": "3 2 1\n1 2 3 4 5 6",
"output": "0"
},
{
"input": "10 3 189\n267 697 667 4 52 128 85 616 142 344 413 660 962 194... | 1,639,939,804 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 186 | 12,288,000 | #from itertools import *
#from math import *
#from bisect import *
#from collections import *
#from random import *
#from decimal import *
#from heapq import *
#from itertools import * # Things Change ....remember :)
import sys
input=sys.stdin.readline
def inp():
return int(input())
def st():... | Title: Liebig's Barrels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to ex... | ```python
#from itertools import *
#from math import *
#from bisect import *
#from collections import *
#from random import *
#from decimal import *
#from heapq import *
#from itertools import * # Things Change ....remember :)
import sys
input=sys.stdin.readline
def inp():
return int(input())
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,698,042,845 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 46 | 0 | a = list(input())
def byk1(a):
for i in a[1:]:
if i.istitle() == False:
r = ''.join(a)
return r
g = []
for i in a:
if i.istitle() == False:
b = i.upper()
g.append(b)
elif i.istitle() == True:
... | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
a = list(input())
def byk1(a):
for i in a[1:]:
if i.istitle() == False:
r = ''.join(a)
return r
g = []
for i in a:
if i.istitle() == False:
b = i.upper()
g.append(b)
elif i.istitle() == True:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
62 | A | A Student's Dream | PROGRAMMING | 1,300 | [
"greedy",
"math"
] | A. A Student's Dream | 2 | 256 | Statistics claims that students sleep no more than three hours a day. But even in the world of their dreams, while they are snoring peacefully, the sense of impending doom is still upon them.
A poor student is dreaming that he is sitting the mathematical analysis exam. And he is examined by the most formidable profess... | The first line contains two positive integers not exceeding 100. They are the number of fingers on the Venusian girl's left and right hand correspondingly. The second line contains two integers not exceeding 100. They are the number of fingers on the Marsian boy's left and right hands correspondingly. | Print YES or NO, that is, the answer to Petr Palych's question. | [
"5 1\n10 5\n",
"4 5\n3 3\n",
"1 2\n11 6\n"
] | [
"YES",
"YES",
"NO"
] | The boy and the girl don't really care who goes to the left. | 500 | [
{
"input": "5 1\n10 5",
"output": "YES"
},
{
"input": "4 5\n3 3",
"output": "YES"
},
{
"input": "1 2\n11 6",
"output": "NO"
},
{
"input": "1 1\n1 1",
"output": "YES"
},
{
"input": "2 2\n1 1",
"output": "YES"
},
{
"input": "3 3\n1 1",
"output": "NO"... | 1,445,826,988 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <stdio.h>
int comfort(int girl, int boy){
if(girl>boy){
if(girl>=boy+2) return 0;
else return 1;
}
else if(girl<boy){
if((boy-1)-girl>=2) return 0;
else return 1;
}
else return 1;
}
int main(void)
{
int al, ar, bl, br;
scanf("%d %d\n%... | Title: A Student's Dream
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Statistics claims that students sleep no more than three hours a day. But even in the world of their dreams, while they are snoring peacefully, the sense of impending doom is still upon them.
A poor student is dreaming t... | ```python
#include <stdio.h>
int comfort(int girl, int boy){
if(girl>boy){
if(girl>=boy+2) return 0;
else return 1;
}
else if(girl<boy){
if((boy-1)-girl>=2) return 0;
else return 1;
}
else return 1;
}
int main(void)
{
int al, ar, bl, br;
scanf... | -1 | MatrixStudio/Codeforces-Python-Submissions |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,579,632,454 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 307,200 | n,m,z=map(int,input().split())
n1=[]
m1=[]
for i in range(1,z+1):
if(i*n<=z):
n1.append(i*n)
for j in range(1,z+1):
if(j*m<=z):
m1.append(j*m)
c=0
flag=0
for i in range(len(n1)):
for j in range(len(m1)):
if(n1[i]==m1[j]):
c=c+1
flag=1
if(flag==1):
break
print(c) | Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
n,m,z=map(int,input().split())
n1=[]
m1=[]
for i in range(1,z+1):
if(i*n<=z):
n1.append(i*n)
for j in range(1,z+1):
if(j*m<=z):
m1.append(j*m)
c=0
flag=0
for i in range(len(n1)):
for j in range(len(m1)):
if(n1[i]==m1[j]):
c=c+1
flag=1
if(flag==1):
break
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
522 | A | Reposts | PROGRAMMING | 1,200 | [
"*special",
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the n... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and ... | Print a single integer — the maximum length of a repost chain. | [
"5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n",
"6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n",
"1\nSoMeStRaNgEgUe repos... | [
"6\n",
"2\n",
"2\n"
] | none | 500 | [
{
"input": "5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya",
"output": "6"
},
{
"input": "6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforc... | 1,598,111,388 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 109 | 7,065,600 | from collections import deque
n = int(input())
m = {}
adj = []
for i in range(202):
adj.append([])
j = 1
for i in range(n):
arr = input().split()
u = (arr[2]).lower()
if(not u in m.keys()):
m[u] = j;
j+=1;
v = (arr[0]).lower()
if(not v in m.keys()):
m[v] =... | Title: Reposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
... | ```python
from collections import deque
n = int(input())
m = {}
adj = []
for i in range(202):
adj.append([])
j = 1
for i in range(n):
arr = input().split()
u = (arr[2]).lower()
if(not u in m.keys()):
m[u] = j;
j+=1;
v = (arr[0]).lower()
if(not v in m.keys()):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
955 | B | Not simply beatiful strings | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Let's call a string adorable if its letters can be realigned in such a way that they form two consequent groups of equal symbols (note that different groups must contain different symbols). For example, ababa is adorable (you can transform it to aaabb, where the first three letters form a group of *a*-s and others — a ... | The only line contains *s* (1<=≤<=|*s*|<=≤<=105) consisting of lowercase latin letters. | Print «Yes» if the string can be split according to the criteria above or «No» otherwise.
Each letter can be printed in arbitrary case. | [
"ababa\n",
"zzcxx\n",
"yeee\n"
] | [
"Yes\n",
"Yes\n",
"No\n"
] | In sample case two zzcxx can be split into subsequences zc and zxx each of which is adorable.
There's no suitable partition in sample case three. | 1,000 | [
{
"input": "ababa",
"output": "Yes"
},
{
"input": "zzcxx",
"output": "Yes"
},
{
"input": "yeee",
"output": "No"
},
{
"input": "a",
"output": "No"
},
{
"input": "bbab",
"output": "No"
},
{
"input": "abcd",
"output": "Yes"
},
{
"input": "abc"... | 1,521,823,673 | 773 | Python 3 | OK | TESTS | 56 | 170 | 7,782,400 | import getpass
import sys
import math
from decimal import Decimal
import decimal
files = True
debug = False
if getpass.getuser() == 'frohenk' and files:
debug = True
sys.stdin = open("test.in")
# sys.stdout = open('test.out', 'w')
elif files:
# fname = "gift"
# sys.stdin = open("%s.... | Title: Not simply beatiful strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a string adorable if its letters can be realigned in such a way that they form two consequent groups of equal symbols (note that different groups must contain different symbols). For example, abab... | ```python
import getpass
import sys
import math
from decimal import Decimal
import decimal
files = True
debug = False
if getpass.getuser() == 'frohenk' and files:
debug = True
sys.stdin = open("test.in")
# sys.stdout = open('test.out', 'w')
elif files:
# fname = "gift"
# sys.stdin =... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
703 | A | Mishka and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they started playing the game.
Rules of the game are very simple: at first number of rounds *n* is defined.... | The first line of the input contains single integer *n* *n* (1<=≤<=*n*<=≤<=100) — the number of game rounds.
The next *n* lines contains rounds description. *i*-th of them contains pair of integers *m**i* and *c**i* (1<=≤<=*m**i*,<=<=*c**i*<=≤<=6) — values on dice upper face after Mishka's and Chris' throws in *i*-th ... | If Mishka is the winner of the game, print "Mishka" (without quotes) in the only line.
If Chris is the winner of the game, print "Chris" (without quotes) in the only line.
If the result of the game is draw, print "Friendship is magic!^^" (without quotes) in the only line. | [
"3\n3 5\n2 1\n4 2\n",
"2\n6 1\n1 6\n",
"3\n1 5\n3 3\n2 2\n"
] | [
"Mishka",
"Friendship is magic!^^",
"Chris"
] | In the first sample case Mishka loses the first round, but wins second and third rounds and thus she is the winner of the game.
In the second sample case Mishka wins the first round, Chris wins the second round, and the game ends with draw with score 1:1.
In the third sample case Chris wins the first round, but there... | 500 | [
{
"input": "3\n3 5\n2 1\n4 2",
"output": "Mishka"
},
{
"input": "2\n6 1\n1 6",
"output": "Friendship is magic!^^"
},
{
"input": "3\n1 5\n3 3\n2 2",
"output": "Chris"
},
{
"input": "6\n4 1\n4 2\n5 3\n5 1\n5 3\n4 1",
"output": "Mishka"
},
{
"input": "8\n2 4\n1 4\n1 ... | 1,675,949,345 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | a,b=0,0
for r in range(int(input())):
c=list(map(int,input().split()))
a+=c[0]
b+=c[1]
if a>b:
print("Mishka")
elif a<b:
print("Chris")
else:
print("Friendship is magic!") | Title: Mishka and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they st... | ```python
a,b=0,0
for r in range(int(input())):
c=list(map(int,input().split()))
a+=c[0]
b+=c[1]
if a>b:
print("Mishka")
elif a<b:
print("Chris")
else:
print("Friendship is magic!")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
377 | A | Maze | PROGRAMMING | 1,600 | [
"dfs and similar"
] | null | null | Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to a... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*k*<=<<=*s*), where *n* and *m* are the maze's height and width, correspondingly, *k* is the number of walls Pavel wants to add and letter *s* represents the number of empty cells in the original maze.
Each of the next *n* lines co... | Print *n* lines containing *m* characters each: the new maze that fits Pavel's requirements. Mark the empty cells that you transformed into walls as "X", the other cells must be left without changes (that is, "." and "#").
It is guaranteed that a solution exists. If there are multiple solutions you can output any of t... | [
"3 4 2\n#..#\n..#.\n#...\n",
"5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#\n"
] | [
"#.X#\nX.#.\n#...\n",
"#XXX\n#X#.\nX#..\n...#\n.#.#\n"
] | none | 500 | [
{
"input": "5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#",
"output": "#XXX\n#X#.\nX#..\n...#\n.#.#"
},
{
"input": "3 3 2\n#.#\n...\n#.#",
"output": "#X#\nX..\n#.#"
},
{
"input": "7 7 18\n#.....#\n..#.#..\n.#...#.\n...#...\n.#...#.\n..#.#..\n#.....#",
"output": "#XXXXX#\nXX#X#X.\nX#XXX#.\nXXX#... | 1,663,684,229 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 4 | 62 | 2,867,200 | directions = [[0, 1], [0, -1], [1, 0], [-1, 0]]
n, m, k = [int(x) for x in input().split()]
ss = []
for i in range(n):
ss += [[x for x in input()]]
Q = []
indegree, vis = {}, {}
for x, s in enumerate(ss):
for y, c in enumerate(s):
if c != '.':
continue
pos = (x, y)
tot = 0
... | Title: Maze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze w... | ```python
directions = [[0, 1], [0, -1], [1, 0], [-1, 0]]
n, m, k = [int(x) for x in input().split()]
ss = []
for i in range(n):
ss += [[x for x in input()]]
Q = []
indegree, vis = {}, {}
for x, s in enumerate(ss):
for y, c in enumerate(s):
if c != '.':
continue
pos = (x, y)
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
817 | A | Treasure Hunt | PROGRAMMING | 1,200 | [
"implementation",
"math",
"number theory"
] | null | null | Captain Bill the Hummingbird and his crew recieved an interesting challenge offer. Some stranger gave them a map, potion of teleportation and said that only this potion might help them to reach the treasure.
Bottle with potion has two values *x* and *y* written on it. These values define four moves which can be perfo... | The first line contains four integer numbers *x*1,<=*y*1,<=*x*2,<=*y*2 (<=-<=105<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=105) — positions of Captain Bill the Hummingbird and treasure respectively.
The second line contains two integer numbers *x*,<=*y* (1<=≤<=*x*,<=*y*<=≤<=105) — values on the potion bottle. | Print "YES" if it is possible for Captain to reach the treasure using the potion, otherwise print "NO" (without quotes). | [
"0 0 0 6\n2 3\n",
"1 1 3 6\n1 5\n"
] | [
"YES\n",
"NO\n"
] | In the first example there exists such sequence of moves:
1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c939890fb4ed35688177327dac981bfa9216c00.png" style="max-width: 100.0%;max-height: 100.0%;"/> — the first type of move 1. <img align="middle" class="tex-formula" src="https://espr... | 0 | [
{
"input": "0 0 0 6\n2 3",
"output": "YES"
},
{
"input": "1 1 3 6\n1 5",
"output": "NO"
},
{
"input": "5 4 6 -10\n1 1",
"output": "NO"
},
{
"input": "6 -3 -7 -7\n1 2",
"output": "NO"
},
{
"input": "2 -5 -8 8\n2 1",
"output": "YES"
},
{
"input": "70 -81... | 1,613,630,044 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 77 | 0 | x1,y1,x2,y2=map(int,input().split())
x,y=map(int,input().split())
if x1==x2 and y1==y2:print("YES")
elif x2==x1 and abs(y2-y1)%y==0:
move_y=abs(y2-y1)//y
if move_y%2==0:print("YES")
else:print("NO")
elif y2==y1 and abs(x2-x1)%x==0:
move_x=abs(x2-x1)//x
if move_x%2==0:print("YES")
else:print(... | Title: Treasure Hunt
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Captain Bill the Hummingbird and his crew recieved an interesting challenge offer. Some stranger gave them a map, potion of teleportation and said that only this potion might help them to reach the treasure.
Bottle with... | ```python
x1,y1,x2,y2=map(int,input().split())
x,y=map(int,input().split())
if x1==x2 and y1==y2:print("YES")
elif x2==x1 and abs(y2-y1)%y==0:
move_y=abs(y2-y1)//y
if move_y%2==0:print("YES")
else:print("NO")
elif y2==y1 and abs(x2-x1)%x==0:
move_x=abs(x2-x1)//x
if move_x%2==0:print("YES")
e... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,591,342,293 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 307,200 | n,m = map(int, input().split())
data = []
for _ in range(n):
data.append(list(input()))
L,R = 100000, -1
U,D = 100000, -1
for i in range(n):
for j in range(m):
if data[i][j]=='*':
if j<L: L = j
if j>R: R = j
if i<U: U = i
if i>D: D = i
... | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
n,m = map(int, input().split())
data = []
for _ in range(n):
data.append(list(input()))
L,R = 100000, -1
U,D = 100000, -1
for i in range(n):
for j in range(m):
if data[i][j]=='*':
if j<L: L = j
if j>R: R = j
if i<U: U = i
if i>D... | 3.888711 | MatrixStudio/Codeforces-Python-Submissions |
431 | C | k-Tree | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"trees"
] | null | null | Quite recently a creative student Lesha had a lecture on trees. After the lecture Lesha was inspired and came up with the tree of his own which he called a *k*-tree.
A *k*-tree is an infinite rooted tree where:
- each vertex has exactly *k* children; - each edge has some weight; - if we look at the edges that goes... | A single line contains three space-separated integers: *n*, *k* and *d* (1<=≤<=*n*,<=*k*<=≤<=100; 1<=≤<=*d*<=≤<=*k*). | Print a single integer — the answer to the problem modulo 1000000007 (109<=+<=7). | [
"3 3 2\n",
"3 3 3\n",
"4 3 2\n",
"4 5 2\n"
] | [
"3\n",
"1\n",
"6\n",
"7\n"
] | none | 1,500 | [
{
"input": "3 3 2",
"output": "3"
},
{
"input": "3 3 3",
"output": "1"
},
{
"input": "4 3 2",
"output": "6"
},
{
"input": "4 5 2",
"output": "7"
},
{
"input": "28 6 3",
"output": "110682188"
},
{
"input": "5 100 1",
"output": "16"
},
{
"inp... | 1,676,518,854 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 31 | 109 | 2,560,000 | import functools
n,k,d=map(int,input().split())
mod=10**9+7
dp=[[0]*k for _ in range(n+1)]
dp[0][0]=1
dp[0][1]=0
for i in range(1,n+1):
for j in range(1,k+1):
if i-j>=0:
if j>=d:
dp[i][1]+=dp[i-j][0]+dp[i-j][1]
else:
dp[i][0]+=dp[i-j][0]
... | Title: k-Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently a creative student Lesha had a lecture on trees. After the lecture Lesha was inspired and came up with the tree of his own which he called a *k*-tree.
A *k*-tree is an infinite rooted tree where:
- each vertex ... | ```python
import functools
n,k,d=map(int,input().split())
mod=10**9+7
dp=[[0]*k for _ in range(n+1)]
dp[0][0]=1
dp[0][1]=0
for i in range(1,n+1):
for j in range(1,k+1):
if i-j>=0:
if j>=d:
dp[i][1]+=dp[i-j][0]+dp[i-j][1]
else:
dp[i][0]+=dp[... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
303 | D | Rotatable Number | PROGRAMMING | 2,600 | [
"math",
"number theory"
] | null | null | Bike is a smart boy who loves math very much. He invented a number called "Rotatable Number" inspired by 142857.
As you can see, 142857 is a magic number because any of its rotatings can be got by multiplying that number by 1,<=2,<=...,<=6 (numbers from one to number's length). Rotating a number means putting its las... | The only line contains two space-separated integers *n*,<=*x* (1<=≤<=*n*<=≤<=5·106,<=2<=≤<=*x*<=≤<=109). | Print a single integer — the largest *b* you found. If no such *b* exists, print -1 instead. | [
"6 11\n",
"5 8\n"
] | [
"10\n",
"-1\n"
] | none | 2,500 | [] | 1,689,417,906 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1689417905.018489")# 1689417905.018509 | Title: Rotatable Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bike is a smart boy who loves math very much. He invented a number called "Rotatable Number" inspired by 142857.
As you can see, 142857 is a magic number because any of its rotatings can be got by multiplying that nu... | ```python
print("_RANDOM_GUESS_1689417905.018489")# 1689417905.018509
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,647,379,500 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 93 | 2,252,800 |
def free_ice_cream():
n,ice_cream = map(int,input().split())
num_distressed = 0
for _ in range(n):
operation,amount = input().split()
amount = int(amount)
if operation == '+':
ice_cream += amount
else:
if amount > ice_cream:
... | Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
def free_ice_cream():
n,ice_cream = map(int,input().split())
num_distressed = 0
for _ in range(n):
operation,amount = input().split()
amount = int(amount)
if operation == '+':
ice_cream += amount
else:
if amount > ice... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
848 | C | Goodbye Souvenir | PROGRAMMING | 2,600 | [
"data structures",
"divide and conquer"
] | null | null | I won't feel lonely, nor will I be sorrowful... not before everything is buried.
A string of *n* beads is left as the message of leaving. The beads are numbered from 1 to *n* from left to right, each having a shape numbered by integers between 1 and *n* inclusive. Some beads may have the same shapes.
The memory of a ... | The first line of input contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100<=000) — the number of beads in the string, and the total number of changes and queries, respectively.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the initial shapes of beads ... | For each query, print one line with an integer — the memory of the recalled subsegment. | [
"7 6\n1 2 3 1 3 2 1\n2 3 7\n2 1 3\n1 7 2\n1 3 2\n2 1 6\n2 5 7\n",
"7 5\n1 3 2 1 4 2 3\n1 1 4\n2 2 3\n1 1 7\n2 4 5\n1 1 7\n"
] | [
"5\n0\n7\n1\n",
"0\n0\n"
] | The initial string of beads has shapes (1, 2, 3, 1, 3, 2, 1).
Consider the changes and queries in their order:
1. 2 3 7: the memory of the subsegment [3, 7] is (7 - 4) + (6 - 6) + (5 - 3) = 5; 1. 2 1 3: the memory of the subsegment [1, 3] is (1 - 1) + (2 - 2) + (3 - 3) = 0; 1. 1 7 2: the shape of the 7-th bead ch... | 1,750 | [] | 1,693,302,417 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n, m = map(int, input().split())
beads = list(map(int, input().split()))
positions = [[] for _ in range(n + 1)]
for i, bead in enumerate(beads, start=1):
positions[bead].append(i)
memory = [0] * (n + 1)
for i in range(1, n + 1):
if positions[i]:
memory[i] = positions[i][-1] - positions[i][0]... | Title: Goodbye Souvenir
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
I won't feel lonely, nor will I be sorrowful... not before everything is buried.
A string of *n* beads is left as the message of leaving. The beads are numbered from 1 to *n* from left to right, each having a shape nu... | ```python
n, m = map(int, input().split())
beads = list(map(int, input().split()))
positions = [[] for _ in range(n + 1)]
for i, bead in enumerate(beads, start=1):
positions[bead].append(i)
memory = [0] * (n + 1)
for i in range(1, n + 1):
if positions[i]:
memory[i] = positions[i][-1] - posit... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
359 | A | Table | PROGRAMMING | 1,000 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | Simon has a rectangular table consisting of *n* rows and *m* columns. Simon numbered the rows of the table from top to bottom starting from one and the columns — from left to right starting from one. We'll represent the cell on the *x*-th row and the *y*-th column as a pair of numbers (*x*,<=*y*). The table corners are... | The first line contains exactly two integers *n*, *m* (3<=≤<=*n*,<=*m*<=≤<=50).
Next *n* lines contain the description of the table cells. Specifically, the *i*-th line contains *m* space-separated integers *a**i*1,<=*a**i*2,<=...,<=*a**im*. If *a**ij* equals zero, then cell (*i*,<=*j*) isn't good. Otherwise *a**ij* e... | Print a single number — the minimum number of operations Simon needs to carry out his idea. | [
"3 3\n0 0 0\n0 1 0\n0 0 0\n",
"4 3\n0 0 0\n0 0 1\n1 0 0\n0 0 0\n"
] | [
"4\n",
"2\n"
] | In the first sample, the sequence of operations can be like this:
- For the first time you need to choose cell (2, 2) and corner (1, 1). - For the second time you need to choose cell (2, 2) and corner (3, 3). - For the third time you need to choose cell (2, 2) and corner (3, 1). - For the fourth time you need to c... | 500 | [
{
"input": "3 3\n0 0 0\n0 1 0\n0 0 0",
"output": "4"
},
{
"input": "4 3\n0 0 0\n0 0 1\n1 0 0\n0 0 0",
"output": "2"
},
{
"input": "50 4\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 1 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0... | 1,673,718,850 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 | n,m = list(map(int, input().split()))
lst=[]
f=1
for i in range(n):
x = list(map(int, input().split()))
lst.append(x)
if lst[0].count(1)>0 or lst[n-1].count(1)>0:
f=0
if f:
for i in range(n):
for j in [0,m-1]:
if lst[i][j]:
f=0
... | Title: Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon has a rectangular table consisting of *n* rows and *m* columns. Simon numbered the rows of the table from top to bottom starting from one and the columns — from left to right starting from one. We'll represent the cell on t... | ```python
n,m = list(map(int, input().split()))
lst=[]
f=1
for i in range(n):
x = list(map(int, input().split()))
lst.append(x)
if lst[0].count(1)>0 or lst[n-1].count(1)>0:
f=0
if f:
for i in range(n):
for j in [0,m-1]:
if lst[i][j]:
f=0
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed ... | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,699,506,934 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | if __name__ == '__main__':
a=int(input())
f=[]
t=0
count=1
p=0
x=0
for i in range(a):
f.append(int(input()))
for j in range(a-1):
if f[t]>f[t+1]:
if t==0:
large=f[t]
x=1
if x==0:
large=... | Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the re... | ```python
if __name__ == '__main__':
a=int(input())
f=[]
t=0
count=1
p=0
x=0
for i in range(a):
f.append(int(input()))
for j in range(a-1):
if f[t]>f[t+1]:
if t==0:
large=f[t]
x=1
if x==0:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
595 | A | Vitaly and Night | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vitaly sees a building of *n* floors and 2·*m* windows on each floor. On each floor there are *m* flats num... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of floors in the house and the number of flats on each floor respectively.
Next *n* lines describe the floors from top to bottom and contain 2·*m* characters each. If the *i*-th window of the given floor has lights on,... | Print a single integer — the number of flats that have lights on in at least one window, that is, the flats where, according to Vitaly, people aren't sleeping. | [
"2 2\n0 0 0 1\n1 0 1 1\n",
"1 3\n1 1 0 1 0 0\n"
] | [
"3\n",
"2\n"
] | In the first test case the house has two floors, two flats on each floor. That is, in total there are 4 flats. The light isn't on only on the second floor in the left flat. That is, in both rooms of the flat the light is off.
In the second test case the house has one floor and the first floor has three flats. The ligh... | 500 | [
{
"input": "2 2\n0 0 0 1\n1 0 1 1",
"output": "3"
},
{
"input": "1 3\n1 1 0 1 0 0",
"output": "2"
},
{
"input": "3 3\n1 1 1 1 1 1\n1 1 0 1 1 0\n1 0 0 0 1 1",
"output": "8"
},
{
"input": "1 5\n1 0 1 1 1 0 1 1 1 1",
"output": "5"
},
{
"input": "1 100\n1 1 1 1 1 1 1 ... | 1,558,210,959 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 124 | 102,400 | n, m = map(int, input().split())
c = 0
for i in range(0, n):
l = list(map(int, input().split()))
for j in range(0, 2*m, 2):
if l[j] == 0 and l[j+1] == 0:
continue
else:
c += 1
print(c)
| Title: Vitaly and Night
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vital... | ```python
n, m = map(int, input().split())
c = 0
for i in range(0, n):
l = list(map(int, input().split()))
for j in range(0, 2*m, 2):
if l[j] == 0 and l[j+1] == 0:
continue
else:
c += 1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
299 | B | Ksusha the Squirrel | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to the end of the road, that is, get to sector *n*. Unfortunately, there are some rocks on the road. We know ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=3·105,<=1<=≤<=*k*<=≤<=3·105). The next line contains *n* characters — the description of the road: the *i*-th character equals ".", if the *i*-th sector contains no rocks. Otherwise, it equals "#".
It is guaranteed that the first and the last characters e... | Print "YES" (without the quotes) if Ksusha can reach the end of the road, otherwise print "NO" (without the quotes). | [
"2 1\n..\n",
"5 2\n.#.#.\n",
"7 3\n.#.###.\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 1,000 | [
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "5 2\n.#.#.",
"output": "YES"
},
{
"input": "7 3\n.#.###.",
"output": "NO"
},
{
"input": "2 200\n..",
"output": "YES"
},
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "2 2\n..",
"output": "Y... | 1,694,969,188 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 374 | 921,600 | a, b = map(int, input().split())
road_ = input()
ans_ = 0
no_ = 0
for i in range(0, a):
if road_[i] == ".":
for _ in range(i+1, a):
if road_[_] == '#':
ans_ += 1
elif road_[_] == '.':
if ans_ >= b:
no_ += 1
... | Title: Ksusha the Squirrel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to t... | ```python
a, b = map(int, input().split())
road_ = input()
ans_ = 0
no_ = 0
for i in range(0, a):
if road_[i] == ".":
for _ in range(i+1, a):
if road_[_] == '#':
ans_ += 1
elif road_[_] == '.':
if ans_ >= b:
no_ += 1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,610,530,163 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 6 | 109 | 2,150,400 | a = input()
if int(a[-1])<=5:
print(a[:(len(a)-1)]+'0')
else:
k = int(a[-2])+1
print(a[:(len(a)-2)]+str(k)+'0')
| Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
a = input()
if int(a[-1])<=5:
print(a[:(len(a)-1)]+'0')
else:
k = int(a[-2])+1
print(a[:(len(a)-2)]+str(k)+'0')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,646,238,155 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 186 | 0 | n,a,b=map(int,input().split())
c=0
for i in range(1,n+1):
if i>a and n-i<=b:
c+=1
print(c) | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
n,a,b=map(int,input().split())
c=0
for i in range(1,n+1):
if i>a and n-i<=b:
c+=1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
46 | C | Hamsters and Tigers | PROGRAMMING | 1,600 | [
"two pointers"
] | C. Hamsters and Tigers | 2 | 256 | Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap the animals' positions so that all the hamsters stood together and all the tigers also stood together... | The first line contains number *n* (2<=≤<=*n*<=≤<=1000) which indicates the total number of animals in the arena. The second line contains the description of the animals' positions. The line consists of *n* symbols "H" and "T". The "H"s correspond to hamsters and the "T"s correspond to tigers. It is guaranteed that at ... | Print the single number which is the minimal number of swaps that let the trainer to achieve his goal. | [
"3\nHTH\n",
"9\nHTHTHTHHT\n"
] | [
"0\n",
"2\n"
] | In the first example we shouldn't move anybody because the animals of each species already stand apart from the other species. In the second example you may swap, for example, the tiger in position 2 with the hamster in position 5 and then — the tiger in position 9 with the hamster in position 7. | 0 | [
{
"input": "3\nHTH",
"output": "0"
},
{
"input": "9\nHTHTHTHHT",
"output": "2"
},
{
"input": "2\nTH",
"output": "0"
},
{
"input": "4\nHTTH",
"output": "0"
},
{
"input": "4\nHTHT",
"output": "1"
},
{
"input": "7\nTTTHTTT",
"output": "0"
},
{
... | 1,691,861,587 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 62 | 0 | n = int(input())
s = input()
s = s+s
count = s.count("H") // 2
x = 0
for i in range(n):
z = s[i:i + count].count('H')
x = max(x,z)
print(count-x)
| Title: Hamsters and Tigers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap ... | ```python
n = int(input())
s = input()
s = s+s
count = s.count("H") // 2
x = 0
for i in range(n):
z = s[i:i + count].count('H')
x = max(x,z)
print(count-x)
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
678 | B | The Same Calendar | PROGRAMMING | 1,600 | [
"implementation"
] | null | null | The girl Taylor has a beautiful calendar for the year *y*. In the calendar all days are given with their days of week: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday.
The calendar is so beautiful that she wants to know what is the next year after *y* when the calendar will be exactly the same. Help ... | The only line contains integer *y* (1000<=≤<=*y*<=<<=100'000) — the year of the calendar. | Print the only integer *y*' — the next year after *y* when the calendar will be the same. Note that you should find the first year after *y* with the same calendar. | [
"2016\n",
"2000\n",
"50501\n"
] | [
"2044\n",
"2028\n",
"50507\n"
] | Today is Monday, the 13th of June, 2016. | 0 | [
{
"input": "2016",
"output": "2044"
},
{
"input": "2000",
"output": "2028"
},
{
"input": "50501",
"output": "50507"
},
{
"input": "1000",
"output": "1006"
},
{
"input": "1900",
"output": "1906"
},
{
"input": "1899",
"output": "1905"
},
{
"i... | 1,485,348,628 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 62 | 4,608,000 | '''Codeforces Problem 678B'''
from time import process_time
from sys import argv
def solve():
'''Solve the problem'''
n = int(input())
w = 0 # week day offset
n2 = n
def isLeap(n):
'''Is the year n a leap year?'''
return n % 400 == 0 or (n % 4 == 0 and n % 100 != 0)
... | Title: The Same Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The girl Taylor has a beautiful calendar for the year *y*. In the calendar all days are given with their days of week: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday.
The calendar is so beautiful t... | ```python
'''Codeforces Problem 678B'''
from time import process_time
from sys import argv
def solve():
'''Solve the problem'''
n = int(input())
w = 0 # week day offset
n2 = n
def isLeap(n):
'''Is the year n a leap year?'''
return n % 400 == 0 or (n % 4 == 0 and n % 100 !... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
678 | D | Iterated Linear Function | PROGRAMMING | 1,700 | [
"math",
"number theory"
] | null | null | Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find the value of *g*(*n*)(*x*) modulo 109<=+<=7. | The only line contains four integers *A*, *B*, *n* and *x* (1<=≤<=*A*,<=*B*,<=*x*<=≤<=109,<=1<=≤<=*n*<=≤<=1018) — the parameters from the problem statement.
Note that the given value *n* can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you c... | Print the only integer *s* — the value *g*(*n*)(*x*) modulo 109<=+<=7. | [
"3 4 1 1\n",
"3 4 2 1\n",
"3 4 3 1\n"
] | [
"7\n",
"25\n",
"79\n"
] | none | 0 | [
{
"input": "3 4 1 1",
"output": "7"
},
{
"input": "3 4 2 1",
"output": "25"
},
{
"input": "3 4 3 1",
"output": "79"
},
{
"input": "1 1 1 1",
"output": "2"
},
{
"input": "3 10 723 6",
"output": "443623217"
},
{
"input": "14 81 51 82",
"output": "908... | 1,539,954,084 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 109 | 0 | # from dust i have come, dust i will be
mod=int(1e9)+7
A,B,n,x=map(int,input().split())
'''
if we expand the given formula for some test cases
e.g-> for n=2,3,4.. we get
A^n*x + B(A^0+A^1+...+A^{n-1})
for the geometric progression, 1+r+r^2+...+r^{n-1}
the ans=(r^n-1)/(r-1) when r>1, if r==1, ans=nr
'''
... | Title: Iterated Linear Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find th... | ```python
# from dust i have come, dust i will be
mod=int(1e9)+7
A,B,n,x=map(int,input().split())
'''
if we expand the given formula for some test cases
e.g-> for n=2,3,4.. we get
A^n*x + B(A^0+A^1+...+A^{n-1})
for the geometric progression, 1+r+r^2+...+r^{n-1}
the ans=(r^n-1)/(r-1) when r>1, if r==1, an... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
156 | B | Suspects | PROGRAMMING | 1,600 | [
"constructive algorithms",
"data structures",
"implementation"
] | null | null | As Sherlock Holmes was investigating a crime, he identified *n* suspects. He knows for sure that exactly one of them committed the crime. To find out which one did it, the detective lines up the suspects and numbered them from 1 to *n*. After that, he asked each one: "Which one committed the crime?". Suspect number *i*... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=*n*) — the total number of suspects and the number of suspects who told the truth. Next *n* lines contain the suspects' answers. The *i*-th line contains either "+*a**i*" (without the quotes), if the suspect number *i* says that the cri... | Print *n* lines. Line number *i* should contain "Truth" if suspect number *i* has told the truth for sure. Print "Lie" if the suspect number *i* lied for sure and print "Not defined" if he could lie and could tell the truth, too, depending on who committed the crime. | [
"1 1\n+1\n",
"3 2\n-1\n-2\n-3\n",
"4 1\n+2\n-3\n+4\n-1\n"
] | [
"Truth\n",
"Not defined\nNot defined\nNot defined\n",
"Lie\nNot defined\nLie\nNot defined\n"
] | The first sample has the single person and he confesses to the crime, and Sherlock Holmes knows that one person is telling the truth. That means that this person is telling the truth.
In the second sample there are three suspects and each one denies his guilt. Sherlock Holmes knows that only two of them are telling th... | 1,000 | [
{
"input": "1 1\n+1",
"output": "Truth"
},
{
"input": "3 2\n-1\n-2\n-3",
"output": "Not defined\nNot defined\nNot defined"
},
{
"input": "4 1\n+2\n-3\n+4\n-1",
"output": "Lie\nNot defined\nLie\nNot defined"
},
{
"input": "1 0\n-1",
"output": "Lie"
},
{
"input": "2... | 1,583,561,520 | 2,147,483,647 | PyPy 3 | OK | TESTS | 97 | 1,964 | 20,889,600 | from collections import Counter
c = Counter()
n, m = map(int, input().split())
sumdc = 0
mark = []
suspect = set()
for _ in range(n):
k = int(input())
mark.append(k)
if k < 0: sumdc += 1
c = Counter(mark)
k = 0
for i in range(1, n + 1):
if c[i] + sumdc - c[-1 * i] == m:
suspe... | Title: Suspects
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As Sherlock Holmes was investigating a crime, he identified *n* suspects. He knows for sure that exactly one of them committed the crime. To find out which one did it, the detective lines up the suspects and numbered them from... | ```python
from collections import Counter
c = Counter()
n, m = map(int, input().split())
sumdc = 0
mark = []
suspect = set()
for _ in range(n):
k = int(input())
mark.append(k)
if k < 0: sumdc += 1
c = Counter(mark)
k = 0
for i in range(1, n + 1):
if c[i] + sumdc - c[-1 * i] == m:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed ... | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,684,860,775 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 92 | 0 | t=int(input())
s=list(map(int,input().split()))
c=0
v=0
for i in range(len(s)-1):
if s[i+1]>s[i]:
c+=1
if c==0:
for i in range(len(s)-1):
if s[i+1]<s[i]:
v+=1
print(v)
else:
print(c) | Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the re... | ```python
t=int(input())
s=list(map(int,input().split()))
c=0
v=0
for i in range(len(s)-1):
if s[i+1]>s[i]:
c+=1
if c==0:
for i in range(len(s)-1):
if s[i+1]<s[i]:
v+=1
print(v)
else:
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
747 | A | Display Size | PROGRAMMING | 800 | [
"brute force",
"math"
] | null | null | A big company decided to launch a new series of rectangular displays, and decided that the display must have exactly *n* pixels.
Your task is to determine the size of the rectangular display — the number of lines (rows) of pixels *a* and the number of columns of pixels *b*, so that:
- there are exactly *n* pixels o... | The first line contains the positive integer *n* (1<=≤<=*n*<=≤<=106) — the number of pixels display should have. | Print two integers — the number of rows and columns on the display. | [
"8\n",
"64\n",
"5\n",
"999999\n"
] | [
"2 4\n",
"8 8\n",
"1 5\n",
"999 1001\n"
] | In the first example the minimum possible difference equals 2, so on the display should be 2 rows of 4 pixels.
In the second example the minimum possible difference equals 0, so on the display should be 8 rows of 8 pixels.
In the third example the minimum possible difference equals 4, so on the display should be 1 ro... | 500 | [
{
"input": "8",
"output": "2 4"
},
{
"input": "64",
"output": "8 8"
},
{
"input": "5",
"output": "1 5"
},
{
"input": "999999",
"output": "999 1001"
},
{
"input": "716539",
"output": "97 7387"
},
{
"input": "1",
"output": "1 1"
},
{
"input":... | 1,597,805,728 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 27 | 1,000 | 0 | # Display Size
def display(p):
for a in range(p, 0, -1):
b = a
while True:
cur = a * b
if cur > p:
break
if cur == p:
print(a, b)
return
b += 1
p = int(input())
display(p) | Title: Display Size
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A big company decided to launch a new series of rectangular displays, and decided that the display must have exactly *n* pixels.
Your task is to determine the size of the rectangular display — the number of lines (rows) ... | ```python
# Display Size
def display(p):
for a in range(p, 0, -1):
b = a
while True:
cur = a * b
if cur > p:
break
if cur == p:
print(a, b)
return
b += 1
p = int(input())
display(p)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
855 | B | Marvolo Gaunt's Ring | PROGRAMMING | 1,500 | [
"brute force",
"data structures",
"dp"
] | null | null | Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he... | First line of input contains 4 integers *n*,<=*p*,<=*q*,<=*r* (<=-<=109<=≤<=*p*,<=*q*,<=*r*<=≤<=109,<=1<=≤<=*n*<=≤<=105).
Next line of input contains *n* space separated integers *a*1,<=*a*2,<=... *a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Output a single integer the maximum value of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* that can be obtained provided 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*. | [
"5 1 2 3\n1 2 3 4 5\n",
"5 1 2 -3\n-1 -2 -3 -4 -5\n"
] | [
"30\n",
"12\n"
] | In the first sample case, we can take *i* = *j* = *k* = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.
In second sample case, selecting *i* = *j* = 1 and *k* = 5 gives the answer 12. | 1,000 | [
{
"input": "5 1 2 3\n1 2 3 4 5",
"output": "30"
},
{
"input": "5 1 2 -3\n-1 -2 -3 -4 -5",
"output": "12"
},
{
"input": "5 886327859 82309257 -68295239\n-731225382 354766539 -48222231 -474691998 360965777",
"output": "376059240645059046"
},
{
"input": "4 -96405765 -495906217 6... | 1,606,414,304 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 22 | 311 | 8,908,800 | a=[int(i) for i in input().split()]
arr=[int(i) for i in input().split()]
p,q,r=a[1],a[2],a[3]
suff=[0 for i in range(a[0])]
suff[(len(suff)-1)]=arr[len(arr)-1]*r
for i in range(len(arr)-2,-1,-1):
suff[i]=max(suff[i+1],arr[i]*r)
pre=arr[0]*p
ma=10**(-10)
for i in range(0,len(arr)):
pre=max(pre,arr[i]*... | Title: Marvolo Gaunt's Ring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed i... | ```python
a=[int(i) for i in input().split()]
arr=[int(i) for i in input().split()]
p,q,r=a[1],a[2],a[3]
suff=[0 for i in range(a[0])]
suff[(len(suff)-1)]=arr[len(arr)-1]*r
for i in range(len(arr)-2,-1,-1):
suff[i]=max(suff[i+1],arr[i]*r)
pre=arr[0]*p
ma=10**(-10)
for i in range(0,len(arr)):
pre=max(p... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | B | Hard Work | PROGRAMMING | 1,300 | [
"strings"
] | B. Hard Work | 2 | 256 | After the contest in comparing numbers, Shapur's teacher found out that he is a real genius and that no one could possibly do the calculations faster than him even using a super computer!
Some days before the contest, the teacher took a very simple-looking exam and all his *n* students took part in the exam. The teach... | The first three lines contain a string each. These are the initial strings. They consists only of lowercase and uppercase Latin letters and signs ("-", ";" and "_"). All the initial strings have length from 1 to 100, inclusively.
In the fourth line there is a single integer *n* (0<=≤<=*n*<=≤<=1000), the number of stud... | For each student write in a different line. Print "WA" if his answer is wrong or "ACC" if his answer is OK. | [
"Iran_\nPersian;\nW_o;n;d;e;r;f;u;l;\n7\nWonderfulPersianIran\nwonderful_PersIAN_IRAN;;_\nWONDERFUL___IRAN__PERSIAN__;;\nIra__Persiann__Wonderful\nWonder;;fulPersian___;I;r;a;n;\n__________IranPersianWonderful__________\nPersianIran_is_Wonderful\n",
"Shapur;;\nis___\na_genius\n3\nShapur__a_is___geniUs\nis___shapu... | [
"ACC\nACC\nACC\nWA\nACC\nACC\nWA\n",
"WA\nACC\nACC\n"
] | none | 1,000 | [
{
"input": "Iran_\nPersian;\nW_o;n;d;e;r;f;u;l;\n7\nWonderfulPersianIran\nwonderful_PersIAN_IRAN;;_\nWONDERFUL___IRAN__PERSIAN__;;\nIra__Persiann__Wonderful\nWonder;;fulPersian___;I;r;a;n;\n__________IranPersianWonderful__________\nPersianIran_is_Wonderful",
"output": "ACC\nACC\nACC\nWA\nACC\nACC\nWA"
},
... | 1,696,304,186 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | # LUOGU_RID: 127232094
a=[];b=[];c=[]
for i in input():
if i in'qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM':a.append(i)
for i in input():
if i in'qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM':b.append(i)
for i in input():
if i in'qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM':c.appe... | Title: Hard Work
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
After the contest in comparing numbers, Shapur's teacher found out that he is a real genius and that no one could possibly do the calculations faster than him even using a super computer!
Some days before the contest, the teache... | ```python
# LUOGU_RID: 127232094
a=[];b=[];c=[]
for i in input():
if i in'qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM':a.append(i)
for i in input():
if i in'qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM':b.append(i)
for i in input():
if i in'qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVB... | 0 | MatrixStudio/Codeforces-Python-Submissions |
765 | C | Table Tennis Game 2 | PROGRAMMING | 1,200 | [
"math"
] | null | null | Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scores exactly *k* points, the score is reset and a new set begins.
Across all the sets Misha scored *a* poi... | The first line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=109, 0<=≤<=*a*,<=*b*<=≤<=109, *a*<=+<=*b*<=><=0). | If the situation is impossible, print a single number -1. Otherwise, print the maximum possible number of sets. | [
"11 11 5\n",
"11 2 3\n"
] | [
"1\n",
"-1\n"
] | Note that the rules of the game in this problem differ from the real table tennis game, for example, the rule of "balance" (the winning player has to be at least two points ahead to win a set) has no power within the present problem. | 1,250 | [
{
"input": "11 11 5",
"output": "1"
},
{
"input": "11 2 3",
"output": "-1"
},
{
"input": "1 5 9",
"output": "14"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "1 1000000000 1000000000",
"output": "2000000000"
},
{
"input": "2 3 5",
"output": "... | 1,607,767,112 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
using namespace std;
int main() {
cout<<"Hello World!";
}
| Title: Table Tennis Game 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scor... | ```python
#include <iostream>
using namespace std;
int main() {
cout<<"Hello World!";
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
144 | A | Arrival of the General | PROGRAMMING | 800 | [
"implementation"
] | null | null | A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their... | The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginnin... | Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like. | [
"4\n33 44 11 22\n",
"7\n10 10 58 31 63 40 76\n"
] | [
"2\n",
"10\n"
] | In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76)... | 500 | [
{
"input": "4\n33 44 11 22",
"output": "2"
},
{
"input": "7\n10 10 58 31 63 40 76",
"output": "10"
},
{
"input": "2\n88 89",
"output": "1"
},
{
"input": "5\n100 95 100 100 88",
"output": "0"
},
{
"input": "7\n48 48 48 48 45 45 45",
"output": "0"
},
{
"... | 1,695,037,275 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | n = int(input())
l = list(map(int, input().split()))
a,b = l.index(max(l)), l.index(min(l))
count = 0
if a > b:
while a != 0 or b != len(l)-1:
a-=1
b+=1
count+=1
else:
while b != 0 or a != len(l)-1:
b-=1
a+=1
count+=1
print(count) | Title: Arrival of the General
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on t... | ```python
n = int(input())
l = list(map(int, input().split()))
a,b = l.index(max(l)), l.index(min(l))
count = 0
if a > b:
while a != 0 or b != len(l)-1:
a-=1
b+=1
count+=1
else:
while b != 0 or a != len(l)-1:
b-=1
a+=1
count+=1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
879 | B | Table Tennis | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | null | null | *n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so on. They play until someone wins *k* games in a row. This player becomes the winner.
For each of t... | The first line contains two integers: *n* and *k* (2<=≤<=*n*<=≤<=500, 2<=≤<=*k*<=≤<=1012) — the number of people and the number of wins.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — powers of the player. It's guaranteed that this line contains a valid permutation, i.e. all ... | Output a single integer — power of the winner. | [
"2 2\n1 2\n",
"4 2\n3 1 2 4\n",
"6 2\n6 5 3 1 2 4\n",
"2 10000000000\n2 1\n"
] | [
"2 ",
"3 ",
"6 ",
"2\n"
] | Games in the second sample:
3 plays with 1. 3 wins. 1 goes to the end of the line.
3 plays with 2. 3 wins. He wins twice in a row. He becomes the winner. | 1,000 | [
{
"input": "2 2\n1 2",
"output": "2 "
},
{
"input": "4 2\n3 1 2 4",
"output": "3 "
},
{
"input": "6 2\n6 5 3 1 2 4",
"output": "6 "
},
{
"input": "2 10000000000\n2 1",
"output": "2"
},
{
"input": "4 4\n1 3 4 2",
"output": "4 "
},
{
"input": "2 21474836... | 1,606,573,350 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 108 | 0 | a,b=map(int,input().split())
powers=list(map(int , input().split()))
c_player_power=powers[0]
c_player_win=0
for i in range(1,a):
if powers[i]<c_player_power:
c_player_win+=1
else:
c_player_power=powers[i]
c_player_win=1
if c_player_win==b:
break
print(c_player_power)
... | Title: Table Tennis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so o... | ```python
a,b=map(int,input().split())
powers=list(map(int , input().split()))
c_player_power=powers[0]
c_player_win=0
for i in range(1,a):
if powers[i]<c_player_power:
c_player_win+=1
else:
c_player_power=powers[i]
c_player_win=1
if c_player_win==b:
break
print(c_player_p... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | B | Phone numbers | PROGRAMMING | 1,100 | [
"implementation"
] | B. Phone numbers | 2 | 256 | Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33. Your task is to find for a given phone number any of its divisions into groups of two or three... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of digits in the phone number. The second line contains *n* digits — the phone number to divide into groups. | Output any of divisions of the given phone number into groups of two or three digits. Separate groups by single character -. If the answer is not unique, output any. | [
"6\n549871\n",
"7\n1198733\n"
] | [
"54-98-71",
"11-987-33\n"
] | none | 0 | [
{
"input": "6\n549871",
"output": "54-98-71"
},
{
"input": "7\n1198733",
"output": "119-87-33"
},
{
"input": "2\n74",
"output": "74"
},
{
"input": "2\n33",
"output": "33"
},
{
"input": "3\n074",
"output": "074"
},
{
"input": "3\n081",
"output": "08... | 1,557,089,034 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 218 | 0 | n = int(input())
num = input()
if n%2 == 0:
s = ''
for i in range(0,len(num),2):
s += (num[i:i+2] + '-')
print(s[:len(s)-1])
else:
s = num[0:3]+'-'
for i in range(3,len(num),2):
s += (num[i:i+2] + '-')
print(s[:len(s)-1]) | Title: Phone numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33.... | ```python
n = int(input())
num = input()
if n%2 == 0:
s = ''
for i in range(0,len(num),2):
s += (num[i:i+2] + '-')
print(s[:len(s)-1])
else:
s = num[0:3]+'-'
for i in range(3,len(num),2):
s += (num[i:i+2] + '-')
print(s[:len(s)-1])
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,647,311,452 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 31 | 0 | d = [int(x) for x in input().split()]
x = [(d[0]+d[1])*2,(d[2]+d[1])*2,d[2]+d[1]+d[0],(d[0]+d[2])*2]
print(min(x))
| Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
d = [int(x) for x in input().split()]
x = [(d[0]+d[1])*2,(d[2]+d[1])*2,d[2]+d[1]+d[0],(d[0]+d[2])*2]
print(min(x))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
127 | A | Wasted Time | PROGRAMMING | 900 | [
"geometry"
] | null | null | Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count the time he has wasted signing papers.
Mr. Scrooge's signature can be represented as a polyline ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). Each of the following *n* lines contains the coordinates of the polyline's endpoints. The *i*-th one contains coordinates of the point *A**i* — integers *x**i* and *y**i*, separated by a space.
All points *A**i* are different. Th... | Print one real number — the total time Scrooges wastes on signing the papers in seconds. The absolute or relative error should not exceed 10<=-<=6. | [
"2 1\n0 0\n10 0\n",
"5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0\n",
"6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0\n"
] | [
"0.200000000",
"6.032163204",
"3.000000000"
] | none | 500 | [
{
"input": "2 1\n0 0\n10 0",
"output": "0.200000000"
},
{
"input": "5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0",
"output": "6.032163204"
},
{
"input": "6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0",
"output": "3.000000000"
},
{
"input": "10 95\n-20 -5\n2 -8\n14 13\n10 3\n17 11\n13 -12\n-6 11\n1... | 1,655,772,791 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | from math import sqrt
n,k = map(int,input().split())
prev = tuple(map(int,input().split()))
dis = 0
for i in range(n-1):
curr = tuple(map(int,input().split()))
dis += sqrt((curr[0] - prev[0])**2 + (curr[1]-prev[1])**2)
prev = curr
print(dis *k / 50)
| Title: Wasted Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count ... | ```python
from math import sqrt
n,k = map(int,input().split())
prev = tuple(map(int,input().split()))
dis = 0
for i in range(n-1):
curr = tuple(map(int,input().split()))
dis += sqrt((curr[0] - prev[0])**2 + (curr[1]-prev[1])**2)
prev = curr
print(dis *k / 50)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,597,591,192 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 109 | 716,800 | N, M = map(int, input().split())
map = {}
for i in range(M):
w1, w2 = input().split()
map[w1] = w2
res = []
for w in input().split():
if len(w) <= len(map[w]):
res.append(w)
else:
res.append(map[w])
print(' '.join(res)) | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
N, M = map(int, input().split())
map = {}
for i in range(M):
w1, w2 = input().split()
map[w1] = w2
res = []
for w in input().split():
if len(w) <= len(map[w]):
res.append(w)
else:
res.append(map[w])
print(' '.join(res))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
768 | B | Code For 1 | PROGRAMMING | 1,600 | [
"constructive algorithms",
"dfs and similar",
"divide and conquer"
] | null | null | Jon fought bravely to rescue the wildlings who were attacked by the white-walkers at Hardhome. On his arrival, Sam tells him that he wants to go to Oldtown to train at the Citadel to become a maester, so he can return and take the deceased Aemon's place as maester of Castle Black. Jon agrees to Sam's proposal and Sam s... | The first line contains three integers *n*, *l*, *r* (0<=≤<=*n*<=<<=250, 0<=≤<=*r*<=-<=*l*<=≤<=105, *r*<=≥<=1, *l*<=≥<=1) – initial element and the range *l* to *r*.
It is guaranteed that *r* is not greater than the length of the final list. | Output the total number of 1s in the range *l* to *r* in the final sequence. | [
"7 2 5\n",
"10 3 10\n"
] | [
"4\n",
"5\n"
] | Consider first example:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/288fbb682a6fa1934a47b763d6851f9d32a06150.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Elements on positions from 2-nd to 5-th in list is [1, 1, 1, 1]. The number of ones is 4.
For the second example:
<img al... | 1,000 | [
{
"input": "7 2 5",
"output": "4"
},
{
"input": "10 3 10",
"output": "5"
},
{
"input": "56 18 40",
"output": "20"
},
{
"input": "203 40 124",
"output": "67"
},
{
"input": "903316762502 354723010040 354723105411",
"output": "78355"
},
{
"input": "335343... | 1,697,694,683 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 4 | 1,512 | 268,390,400 | def transform_sequence(n):
if n <= 1:
return [n]
else:
x = n // 2
y = n % 2
return transform_sequence(x) + [y] + transform_sequence(x)
def count_ones_in_range(sequence, l, r):
return sequence[l - 1:r].count(1)
def main():
n, l, r = map(int, input().split())
sequence... | Title: Code For 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jon fought bravely to rescue the wildlings who were attacked by the white-walkers at Hardhome. On his arrival, Sam tells him that he wants to go to Oldtown to train at the Citadel to become a maester, so he can return and ta... | ```python
def transform_sequence(n):
if n <= 1:
return [n]
else:
x = n // 2
y = n % 2
return transform_sequence(x) + [y] + transform_sequence(x)
def count_ones_in_range(sequence, l, r):
return sequence[l - 1:r].count(1)
def main():
n, l, r = map(int, input().split())
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
81 | B | Sequence Formatting | PROGRAMMING | 1,700 | [
"implementation",
"strings"
] | B. Sequence Formatting | 2 | 256 | Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected ... | The input data contains a single string *s*. Its length is from 1 to 255 characters. The string *s* does not begin and end with a space. Its content matches the description given above. | Print the string *s* after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it. | [
"1,2 ,3,..., 10\n",
"1,,,4...5......6\n",
"...,1,2,3,...\n"
] | [
"1, 2, 3, ..., 10\n",
"1, , , 4 ...5 ... ...6\n",
"..., 1, 2, 3, ...\n"
] | none | 1,000 | [
{
"input": "1,2 ,3,..., 10",
"output": "1, 2, 3, ..., 10"
},
{
"input": "1,,,4...5......6",
"output": "1, , , 4 ...5 ... ...6"
},
{
"input": ",,,,,,,,,,,,,",
"output": ", , , , , , , , , , , , ,"
},
{
"input": "123456789",
"output": "123456789"
},
{
"input": "... | 1,509,475,289 | 2,488 | Python 3 | WRONG_ANSWER | TESTS | 23 | 122 | 0 | ans = input().replace("...", " ...")
ans = ans.replace(" ,", ",").replace(",", ", ")
while " " in ans:
ans = ans.replace(" ", " ")
if ans[0] == " ": ans = ans[1:]
if ans[-1] == " ": ans = ans[:-1]
print(ans, end="")
| Title: Sequence Formatting
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he ... | ```python
ans = input().replace("...", " ...")
ans = ans.replace(" ,", ",").replace(",", ", ")
while " " in ans:
ans = ans.replace(" ", " ")
if ans[0] == " ": ans = ans[1:]
if ans[-1] == " ": ans = ans[:-1]
print(ans, end="")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
792 | C | Divide by Three | PROGRAMMING | 2,000 | [
"dp",
"greedy",
"math",
"number theory"
] | null | null | A positive integer number *n* is written on a blackboard. It consists of not more than 105 digits. You have to transform it into a beautiful number by erasing some of the digits, and you want to erase as few digits as possible.
The number is called beautiful if it consists of at least one digit, doesn't have leading z... | The first line of input contains *n* — a positive integer number without leading zeroes (1<=≤<=*n*<=<<=10100000). | Print one number — any beautiful number obtained by erasing as few as possible digits. If there is no answer, print <=-<=1. | [
"1033\n",
"10\n",
"11\n"
] | [
"33\n",
"0\n",
"-1\n"
] | In the first example it is enough to erase only the first digit to obtain a multiple of 3. But if we erase the first digit, then we obtain a number with a leading zero. So the minimum number of digits to be erased is two. | 0 | [
{
"input": "1033",
"output": "33"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "-1"
},
{
"input": "3",
"output": "3"
},
{
"input": "1",
"output": "-1"
},
{
"input": "117",
"output": "117"
},
{
"input": "518",
"output"... | 1,691,651,437 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 162 | 685 | 9,728,000 | n = input()
def rm(s, mod):
for i in range(len(s) - 1, -1, -1):
if int(s[i]) % 3 == mod:
return s[:i] + s[i + 1:]
return s
def S(s):
if not s or int(s) % 3:
return -1
else:
return int(s)
a = (n, rm(n, 1), rm(rm(n, 1), 1), rm(n, 2), rm(rm(n, 2), 2))
print(m... | Title: Divide by Three
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A positive integer number *n* is written on a blackboard. It consists of not more than 105 digits. You have to transform it into a beautiful number by erasing some of the digits, and you want to erase as few digits as p... | ```python
n = input()
def rm(s, mod):
for i in range(len(s) - 1, -1, -1):
if int(s[i]) % 3 == mod:
return s[:i] + s[i + 1:]
return s
def S(s):
if not s or int(s) % 3:
return -1
else:
return int(s)
a = (n, rm(n, 1), rm(rm(n, 1), 1), rm(n, 2), rm(rm(n, 2), 2)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
405 | A | Gravity Flip | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity.
There are *n* columns of toy cubes in the box arranged in a line. The *i*-th column contains *a**i* cubes. At first, the gravity in the box is... | The first line of input contains an integer *n* (1<=≤<=*n*<=≤<=100), the number of the columns in the box. The next line contains *n* space-separated integer numbers. The *i*-th number *a**i* (1<=≤<=*a**i*<=≤<=100) denotes the number of cubes in the *i*-th column. | Output *n* integer numbers separated by spaces, where the *i*-th number is the amount of cubes in the *i*-th column after the gravity switch. | [
"4\n3 2 1 2\n",
"3\n2 3 8\n"
] | [
"1 2 2 3 \n",
"2 3 8 \n"
] | The first example case is shown on the figure. The top cube of the first column falls to the top of the last column; the top cube of the second column falls to the top of the third column; the middle cube of the first column falls to the top of the second column.
In the second example case the gravity switch does not ... | 500 | [
{
"input": "4\n3 2 1 2",
"output": "1 2 2 3 "
},
{
"input": "3\n2 3 8",
"output": "2 3 8 "
},
{
"input": "5\n2 1 2 1 2",
"output": "1 1 2 2 2 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n4 3",
"output": "3 4 "
},
{
"input": "6\n100 40 60 20... | 1,696,004,809 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | n=int(input())
li=list(map(int,input().split()))
if li!=sorted(li):
li.sort()
for i in li:
print(i,end=" ")
| Title: Gravity Flip
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity.
There are *n* columns of toy cubes in the bo... | ```python
n=int(input())
li=list(map(int,input().split()))
if li!=sorted(li):
li.sort()
for i in li:
print(i,end=" ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,636,007,707 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 46 | 4,505,600 | s = str(input())
h = 0
h1 = 0
e = 0
l1 = 0
l2 = 0
l = 0
k = 0
for index in range(len(s)):
if s[index] == "h" and h1 == 0:
h = index
h1 +=1
for index2 in range(len(s)):
if s[index2] == "e":
if index2 > h:
e = index2
for index3 in range(len(s)):
if s[... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = str(input())
h = 0
h1 = 0
e = 0
l1 = 0
l2 = 0
l = 0
k = 0
for index in range(len(s)):
if s[index] == "h" and h1 == 0:
h = index
h1 +=1
for index2 in range(len(s)):
if s[index2] == "e":
if index2 > h:
e = index2
for index3 in range(len(s)):
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
8 | A | Train and Peter | PROGRAMMING | 1,200 | [
"strings"
] | A. Train and Peter | 1 | 64 | Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy start... | The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second lin... | Output one of the four words without inverted commas:
- «forward» — if Peter could see such sequences only on the way from A to B; - «backward» — if Peter could see such sequences on the way from B to A; - «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A; - «fanta... | [
"atob\na\nb\n",
"aaacaaa\naca\naa\n"
] | [
"forward\n",
"both\n"
] | It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | 0 | [
{
"input": "atob\na\nb",
"output": "forward"
},
{
"input": "aaacaaa\naca\naa",
"output": "both"
},
{
"input": "aaa\naa\naa",
"output": "fantasy"
},
{
"input": "astalavista\nastla\nlavista",
"output": "fantasy"
},
{
"input": "abacabadabacaba\nabacaba\nabacaba",
... | 1,665,819,758 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | s = input()
a = input()
b = input()
k = a + b
c = 0
forward = False
back = False
for i in s:
if k[c] == i:
c += 1
if c == len(k):
break
if c == len(k):
forward = True
c1 = 0
k = (b + a)[::-1]
for i in s:
if k[c1] == i:
c1 += 1
if c1 == len(k):
break
if... | Title: Train and Peter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the... | ```python
s = input()
a = input()
b = input()
k = a + b
c = 0
forward = False
back = False
for i in s:
if k[c] == i:
c += 1
if c == len(k):
break
if c == len(k):
forward = True
c1 = 0
k = (b + a)[::-1]
for i in s:
if k[c1] == i:
c1 += 1
if c1 == len(k):
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,680,277,785 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | num = int(input())
result = 0
def solve(num):
global result
fact = []
d = 2
while d * d < num:
while num % d == 0:
fact.append(d)
num //= d
d += 1
if num > 1:fact.append(num)
if len(set(fact)) == 2:
return 1
return 0
for i in ran... | Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
num = int(input())
result = 0
def solve(num):
global result
fact = []
d = 2
while d * d < num:
while num % d == 0:
fact.append(d)
num //= d
d += 1
if num > 1:fact.append(num)
if len(set(fact)) == 2:
return 1
return 0
fo... | 0 | MatrixStudio/Codeforces-Python-Submissions |
336 | A | Vasily the Bear and Triangle | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasily the bear has a favorite rectangle, it has one vertex at point (0,<=0), and the opposite vertex at point (*x*,<=*y*). Of course, the sides of Vasya's favorite rectangle are parallel to the coordinate axes.
Vasya also loves triangles, if the triangles have one vertex at point *B*<==<=(0,<=0). That's why today he... | The first line contains two integers *x*,<=*y* (<=-<=109<=≤<=*x*,<=*y*<=≤<=109,<=*x*<=≠<=0,<=*y*<=≠<=0). | Print in the single line four integers *x*1,<=*y*1,<=*x*2,<=*y*2 — the coordinates of the required points. | [
"10 5\n",
"-10 5\n"
] | [
"0 15 15 0\n",
"-15 0 0 15\n"
] | <img class="tex-graphics" src="https://espresso.codeforces.com/a9ea2088c4294ce8f23801562fda36b830df2c3f.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Figure to the first sample | 500 | [
{
"input": "10 5",
"output": "0 15 15 0"
},
{
"input": "-10 5",
"output": "-15 0 0 15"
},
{
"input": "20 -10",
"output": "0 -30 30 0"
},
{
"input": "-10 -1000000000",
"output": "-1000000010 0 0 -1000000010"
},
{
"input": "-1000000000 -1000000000",
"output": "-... | 1,620,094,599 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 154 | 0 | def bear_and_triangle(x,y):
l=[]
diff=abs(x)-abs(y)
if(x>0 and y>0):
x1=0
y1=3*y
x2=x+diff
y2=0
elif(x<0 and y>0):
x1=x-diff
y1=0
x2=0
y2=3*y
elif(x<0 and y<0):
x1=x-diff
y1=0
x2=0
y2=3*y... | Title: Vasily the Bear and Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the bear has a favorite rectangle, it has one vertex at point (0,<=0), and the opposite vertex at point (*x*,<=*y*). Of course, the sides of Vasya's favorite rectangle are parallel to the coordinate ... | ```python
def bear_and_triangle(x,y):
l=[]
diff=abs(x)-abs(y)
if(x>0 and y>0):
x1=0
y1=3*y
x2=x+diff
y2=0
elif(x<0 and y>0):
x1=x-diff
y1=0
x2=0
y2=3*y
elif(x<0 and y<0):
x1=x-diff
y1=0
x2=0
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
182 | D | Common Divisors | PROGRAMMING | 1,400 | [
"brute force",
"hashing",
"implementation",
"math",
"strings"
] | null | null | Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive integer *x* such that if we write out string *a* consecutively *x* times, we get string *b*. For exam... | The first input line contains a non-empty string *s*1.
The second input line contains a non-empty string *s*2.
Lengths of strings *s*1 and *s*2 are positive and do not exceed 105. The strings only consist of lowercase Latin letters. | Print the number of common divisors of strings *s*1 and *s*2. | [
"abcdabcd\nabcdabcdabcdabcd\n",
"aaa\naa\n"
] | [
"2\n",
"1\n"
] | In first sample the common divisors are strings "abcd" and "abcdabcd".
In the second sample the common divisor is a single string "a". String "aa" isn't included in the answer as it isn't a divisor of string "aaa". | 1,000 | [
{
"input": "abcdabcd\nabcdabcdabcdabcd",
"output": "2"
},
{
"input": "aaa\naa",
"output": "1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaa\naaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "3"
},
{
"input": "aaaaaaaaaaaaaa\naaaaaaaaaaaaaa",
"output": "4"
},
{
"input": "a\nb",
... | 1,666,145,102 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 2,870 | 3,788,800 | import math
s = input()
t = input()
gcd = math.gcd(len(s), len(t))
def test(k):
for i in range(k):
if s[i] != t[i]:
return False
for i in range(len(s)):
if s[i] != s[i % k]:
return False
for i in range(len(t)):
if t[i] != t[i % k]:
return False... | Title: Common Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive ... | ```python
import math
s = input()
t = input()
gcd = math.gcd(len(s), len(t))
def test(k):
for i in range(k):
if s[i] != t[i]:
return False
for i in range(len(s)):
if s[i] != s[i % k]:
return False
for i in range(len(t)):
if t[i] != t[i % k]:
re... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | A very brave explorer Petya once decided to explore Paris catacombs. Since Petya is not really experienced, his exploration is just walking through the catacombs.
Catacombs consist of several rooms and bidirectional passages between some pairs of them. Some passages can connect a room to itself and since the passages ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=2·105) — then number of notes in Petya's logbook.
The second line contains *n* non-negative integers *t*1,<=*t*2,<=...,<=*t**n* (0<=≤<=*t**i*<=<<=*i*) — notes in the logbook. | In the only line print a single integer — the minimum possible number of rooms in Paris catacombs. | [
"2\n0 0\n",
"5\n0 1 0 1 3\n"
] | [
"2\n",
"3\n"
] | In the first sample, sequence of rooms Petya visited could be, for example 1 → 1 → 2, 1 → 2 → 1 or 1 → 2 → 3. The minimum possible number of rooms is 2.
In the second sample, the sequence could be 1 → 2 → 3 → 1 → 2 → 1. | 0 | [
{
"input": "2\n0 0",
"output": "2"
},
{
"input": "5\n0 1 0 1 3",
"output": "3"
},
{
"input": "7\n0 1 0 0 0 0 0",
"output": "6"
},
{
"input": "100\n0 0 0 0 0 0 1 4 4 0 2 2 4 1 7 1 11 0 8 4 12 12 3 0 3 2 2 4 3 9 1 5 4 6 9 14 6 2 4 18 7 7 19 11 20 13 17 16 0 34 2 6 12 27 9 4 29 ... | 1,510,506,720 | 4,020 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 62 | 0 | n = int(input())
a = input()
a = list(map(int, a.split()))
b = []
for i in range(n):
if not(a[i] in b):
b.append(a[i])
if len(b) == 1:
print(n)
else:
print((n// (len(b)-1)) + 1)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A very brave explorer Petya once decided to explore Paris catacombs. Since Petya is not really experienced, his exploration is just walking through the catacombs.
Catacombs consist of several rooms and bidirectional passages betw... | ```python
n = int(input())
a = input()
a = list(map(int, a.split()))
b = []
for i in range(n):
if not(a[i] in b):
b.append(a[i])
if len(b) == 1:
print(n)
else:
print((n// (len(b)-1)) + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain num... | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,691,075,129 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 62 | 1,740,800 | n, x = list(map(int, input().split()))
if x == 1 or x == n * n:
print(1)
else:
out = 0
for i in range(1, n + 1):
if x % i == 0 and x // i <= n:
out += 1
print(out)
| Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
Y... | ```python
n, x = list(map(int, input().split()))
if x == 1 or x == n * n:
print(1)
else:
out = 0
for i in range(1, n + 1):
if x % i == 0 and x // i <= n:
out += 1
print(out)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375.
W... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=8). | Print the *k*-rounding of *n*. | [
"375 4\n",
"10000 1\n",
"38101 0\n",
"123456789 8\n"
] | [
"30000\n",
"10000\n",
"38101\n",
"12345678900000000\n"
] | none | 0 | [
{
"input": "375 4",
"output": "30000"
},
{
"input": "10000 1",
"output": "10000"
},
{
"input": "38101 0",
"output": "38101"
},
{
"input": "123456789 8",
"output": "12345678900000000"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output":... | 1,508,378,454 | 1,854 | Python 3 | OK | TESTS | 96 | 78 | 6,041,600 | # -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
import itertools
"""
created by shhuan at 2017/10/19 09:32
"""
N, K = map(int, input().split())
ans = float('inf')
for a in range(int(math.log(10**K, 2))+2):
for b in range(100000)... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000... | ```python
# -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
import itertools
"""
created by shhuan at 2017/10/19 09:32
"""
N, K = map(int, input().split())
ans = float('inf')
for a in range(int(math.log(10**K, 2))+2):
for b in ran... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
416 | B | Art Union | PROGRAMMING | 1,300 | [
"brute force",
"dp",
"implementation"
] | null | null | A well-known art union called "Kalevich is Alive!" manufactures objects d'art (pictures). The union consists of *n* painters who decided to organize their work as follows.
Each painter uses only the color that was assigned to him. The colors are distinct for all painters. Let's assume that the first painter uses color... | The first line of the input contains integers *m*,<=*n* (1<=≤<=*m*<=≤<=50000,<=1<=≤<=*n*<=≤<=5), where *m* is the number of pictures and *n* is the number of painters. Then follow the descriptions of the pictures, one per line. Each line contains *n* integers *t**i*1,<=*t**i*2,<=...,<=*t**in* (1<=≤<=*t**ij*<=≤<=1000), ... | Print the sequence of *m* integers *r*1,<=*r*2,<=...,<=*r**m*, where *r**i* is the moment when the *n*-th painter stopped working on the *i*-th picture. | [
"5 1\n1\n2\n3\n4\n5\n",
"4 2\n2 5\n3 1\n5 3\n10 1\n"
] | [
"1 3 6 10 15 ",
"7 8 13 21 "
] | none | 1,000 | [
{
"input": "5 1\n1\n2\n3\n4\n5",
"output": "1 3 6 10 15 "
},
{
"input": "4 2\n2 5\n3 1\n5 3\n10 1",
"output": "7 8 13 21 "
},
{
"input": "1 1\n66",
"output": "66 "
},
{
"input": "2 2\n1 1\n1 1",
"output": "2 3 "
},
{
"input": "2 2\n10 1\n10 1",
"output": "11 2... | 1,571,159,943 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 810 | 0 | n, m = [int(i) for i in input().split()]
lst = [0 for i in range(m)]
for i in range(n):
c = [int(x) for x in input().split()]
lst[0] += c[0]
for j in range(1, m):
lst[j] = max(lst[j], lst[j - 1]) + c[j]
print(lst[m - 1], end=' ')
| Title: Art Union
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A well-known art union called "Kalevich is Alive!" manufactures objects d'art (pictures). The union consists of *n* painters who decided to organize their work as follows.
Each painter uses only the color that was assigned t... | ```python
n, m = [int(i) for i in input().split()]
lst = [0 for i in range(m)]
for i in range(n):
c = [int(x) for x in input().split()]
lst[0] += c[0]
for j in range(1, m):
lst[j] = max(lst[j], lst[j - 1]) + c[j]
print(lst[m - 1], end=' ')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
253 | B | Physics Practical | PROGRAMMING | 1,400 | [
"binary search",
"dp",
"sortings",
"two pointers"
] | null | null | One day Vasya was on a physics practical, performing the task on measuring the capacitance. He followed the teacher's advice and did as much as *n* measurements, and recorded the results in the notebook. After that he was about to show the results to the teacher, but he remembered that at the last lesson, the teacher h... | The first line contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of measurements Vasya made. The second line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=5000) — the results of the measurements. The numbers on the second line are separated by single spaces. | Print a single integer — the minimum number of results Vasya will have to remove. | [
"6\n4 5 3 8 3 7\n",
"4\n4 3 2 4\n"
] | [
"2\n",
"0\n"
] | In the first sample you can remove the fourth and the sixth measurement results (values 8 and 7). Then the maximum of the remaining values will be 5, and the minimum one will be 3. Or else, you can remove the third and fifth results (both equal 3). After that the largest remaining result will be 8, and the smallest one... | 1,000 | [
{
"input": "6\n4 5 3 8 3 7",
"output": "2"
},
{
"input": "4\n4 3 2 4",
"output": "0"
},
{
"input": "6\n5 6 4 9 4 8",
"output": "1"
},
{
"input": "4\n5 4 1 5",
"output": "1"
},
{
"input": "2\n3 2",
"output": "0"
},
{
"input": "10\n39 9 18 13 6 16 47 15 ... | 1,659,196,406 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 186 | 2,764,800 | import sys
_ = sys.stdin.buffer.readline()
ms = list(map(int, sys.stdin.buffer.readline().split(' ')))
max = max(ms)
count = sum([1 for n in ms if n*2 < max])
print(count) | Title: Physics Practical
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya was on a physics practical, performing the task on measuring the capacitance. He followed the teacher's advice and did as much as *n* measurements, and recorded the results in the notebook. After that he... | ```python
import sys
_ = sys.stdin.buffer.readline()
ms = list(map(int, sys.stdin.buffer.readline().split(' ')))
max = max(ms)
count = sum([1 for n in ms if n*2 < max])
print(count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
659 | D | Bicycle Race | PROGRAMMING | 1,500 | [
"geometry",
"implementation",
"math"
] | null | null | Maria participates in a bicycle race.
The speedway takes place on the shores of Lake Lucerne, just repeating its contour. As you know, the lake shore consists only of straight sections, directed to the north, south, east or west.
Let's introduce a system of coordinates, directing the *Ox* axis from west to east, and ... | The first line of the input contains an integer *n* (4<=≤<=*n*<=≤<=1000) — the number of straight sections of the track.
The following (*n*<=+<=1)-th line contains pairs of integers (*x**i*,<=*y**i*) (<=-<=10<=000<=≤<=*x**i*,<=*y**i*<=≤<=10<=000). The first of these points is the starting position. The *i*-th straight... | Print a single integer — the number of dangerous turns on the track. | [
"6\n0 0\n0 1\n1 1\n1 2\n2 2\n2 0\n0 0\n",
"16\n1 1\n1 5\n3 5\n3 7\n2 7\n2 9\n6 9\n6 7\n5 7\n5 3\n4 3\n4 4\n3 4\n3 2\n5 2\n5 1\n1 1\n"
] | [
"1\n",
"6\n"
] | The first sample corresponds to the picture:
The picture shows that you can get in the water under unfortunate circumstances only at turn at the point (1, 1). Thus, the answer is 1. | 1,250 | [
{
"input": "6\n0 0\n0 1\n1 1\n1 2\n2 2\n2 0\n0 0",
"output": "1"
},
{
"input": "16\n1 1\n1 5\n3 5\n3 7\n2 7\n2 9\n6 9\n6 7\n5 7\n5 3\n4 3\n4 4\n3 4\n3 2\n5 2\n5 1\n1 1",
"output": "6"
},
{
"input": "4\n-10000 -10000\n-10000 10000\n10000 10000\n10000 -10000\n-10000 -10000",
"output": ... | 1,613,677,889 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | def main():
loop = True
while(loop):
retas = int(input())
if(retas >= 4 and retas <= 1000):
loop = False
loop = True
for i in range(0,retas+1):
x = int(input())
y = int(input())
danger = (retas - 4)/2
print(danger)
main()
| Title: Bicycle Race
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Maria participates in a bicycle race.
The speedway takes place on the shores of Lake Lucerne, just repeating its contour. As you know, the lake shore consists only of straight sections, directed to the north, south, east ... | ```python
def main():
loop = True
while(loop):
retas = int(input())
if(retas >= 4 and retas <= 1000):
loop = False
loop = True
for i in range(0,retas+1):
x = int(input())
y = int(input())
danger = (retas - 4)/2
print(danger)
main()
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
990 | A | Commentary Boxes | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation should get the same number of the commentary boxes. If any box is left unoccupied then the delegations wil... | The only line contains four integer numbers $n$, $m$, $a$ and $b$ ($1 \le n, m \le 10^{12}$, $1 \le a, b \le 100$), where $n$ is the initial number of the commentary boxes, $m$ is the number of delegations to come, $a$ is the fee to build a box and $b$ is the fee to demolish a box. | Output the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$). It is allowed that the final number of the boxes is equal to $0$. | [
"9 7 3 8\n",
"2 7 3 7\n",
"30 6 17 19\n"
] | [
"15\n",
"14\n",
"0\n"
] | In the first example organizers can build $5$ boxes to make the total of $14$ paying $3$ burles for the each of them.
In the second example organizers can demolish $2$ boxes to make the total of $0$ paying $7$ burles for the each of them.
In the third example organizers are already able to distribute all the boxes eq... | 0 | [
{
"input": "9 7 3 8",
"output": "15"
},
{
"input": "2 7 3 7",
"output": "14"
},
{
"input": "30 6 17 19",
"output": "0"
},
{
"input": "500000000001 1000000000000 100 100",
"output": "49999999999900"
},
{
"input": "1000000000000 750000000001 10 100",
"output": "... | 1,568,286,327 | 327 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 140 | 0 | n,m,a,b=map(int,input().split())
if n%m == 0:
print(0)
else:
k=n%m
print(min(k*b,abs((n-k*m)*a))) | Title: Commentary Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation shou... | ```python
n,m,a,b=map(int,input().split())
if n%m == 0:
print(0)
else:
k=n%m
print(min(k*b,abs((n-k*m)*a)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
978 | B | File Name | PROGRAMMING | 800 | [
"greedy",
"strings"
] | null | null | You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin letters "x") in a row, the system considers that the file content does not correspond to the socia... | The first line contains integer $n$ $(3 \le n \le 100)$ — the length of the file name.
The second line contains a string of length $n$ consisting of lowercase Latin letters only — the file name. | Print the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. If initially the file name dost not contain a forbidden substring "xxx", print 0. | [
"6\nxxxiii\n",
"5\nxxoxx\n",
"10\nxxxxxxxxxx\n"
] | [
"1\n",
"0\n",
"8\n"
] | In the first example Polycarp tried to send a file with name contains number $33$, written in Roman numerals. But he can not just send the file, because it name contains three letters "x" in a row. To send the file he needs to remove any one of this letters. | 0 | [
{
"input": "6\nxxxiii",
"output": "1"
},
{
"input": "5\nxxoxx",
"output": "0"
},
{
"input": "10\nxxxxxxxxxx",
"output": "8"
},
{
"input": "100\nxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx",
"output": "98"
},
{
... | 1,687,967,543 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 13 | 62 | 0 | a, s, t = int(input()), input(), 0
for i in range(2, a):
if s[i - 2] == s[i - 1] == s[i] == 'x':
t += 1
print (t) | Title: File Name
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin let... | ```python
a, s, t = int(input()), input(), 0
for i in range(2, a):
if s[i - 2] == s[i - 1] == s[i] == 'x':
t += 1
print (t)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
660 | D | Number of Parallelograms | PROGRAMMING | 1,900 | [
"geometry"
] | null | null | You are given *n* points on a plane. All the points are distinct and no three of them lie on the same line. Find the number of parallelograms with the vertices at the given points. | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of points.
Each of the next *n* lines contains two integers (*x**i*,<=*y**i*) (0<=≤<=*x**i*,<=*y**i*<=≤<=109) — the coordinates of the *i*-th point. | Print the only integer *c* — the number of parallelograms with the vertices at the given points. | [
"4\n0 1\n1 0\n1 1\n2 0\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "4\n0 1\n1 0\n1 1\n2 0",
"output": "1"
},
{
"input": "1\n0 0",
"output": "0"
},
{
"input": "1\n6 6",
"output": "0"
},
{
"input": "5\n1 5\n4 2\n4 4\n8 1\n8 2",
"output": "0"
},
{
"input": "10\n1 7\n2 14\n3 7\n3 13\n5 13\n13 10\n15 12\n17 1\n18 8\n19 0",
... | 1,639,214,340 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | def k(p1, p2):
x1=p1[0]
x2=p2[0]
y1=p1[1]
y2=p2[1]
if y1==y2:
return 10**18
return (x1-x2)/(y1-y2)
def d(p1, p2):
x1=p1[0]
x2=p2[0]
y1=p1[1]
y2=p2[1]
return (x1-x2)**2 + (y1-y2)**2
n = int(input())
points = []
for i in range(n):
x, y = map... | Title: Number of Parallelograms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on a plane. All the points are distinct and no three of them lie on the same line. Find the number of parallelograms with the vertices at the given points.
Input Specification:
The fir... | ```python
def k(p1, p2):
x1=p1[0]
x2=p2[0]
y1=p1[1]
y2=p2[1]
if y1==y2:
return 10**18
return (x1-x2)/(y1-y2)
def d(p1, p2):
x1=p1[0]
x2=p2[0]
y1=p1[1]
y2=p2[1]
return (x1-x2)**2 + (y1-y2)**2
n = int(input())
points = []
for i in range(n):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be sw... | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,661,338,754 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 46 | 0 | res = [[1] * 3 for _ in range(3)]
for i in range(3):
row = [int(i) % 2 for i in input().split()]
for j in range(3):
if row[j] == 1:
res[i][j] = abs(res[i][j] - 1)
if i > 0:
res[i - 1][j] = abs(res[i - 1][j] - 1)
if i < 2:
res[i... | Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the ... | ```python
res = [[1] * 3 for _ in range(3)]
for i in range(3):
row = [int(i) % 2 for i in input().split()]
for j in range(3):
if row[j] == 1:
res[i][j] = abs(res[i][j] - 1)
if i > 0:
res[i - 1][j] = abs(res[i - 1][j] - 1)
if i < 2:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
976 | A | Minimum Binary Number | PROGRAMMING | 800 | [
"implementation"
] | null | null | String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" "110"... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=100) — the length of string *s*.
The second line contains the string *s* consisting of characters "0" and "1". It is guaranteed that the string *s* is correct. | Print one string — the minimum correct string that you can obtain from the given one. | [
"4\n1001\n",
"1\n1\n"
] | [
"100\n",
"1\n"
] | In the first example you can obtain the answer by the following sequence of operations: "1001" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "1010" <img align="middle" class="tex-formula" src="ht... | 0 | [
{
"input": "4\n1001",
"output": "100"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "100\n1110111100001111011111111010110011111111011110000111101101011100110110001011000000101010110101011100",
"output": "1000000000000000000000000000000000000000"
},
{
"input": "100\n100000... | 1,643,982,484 | 2,147,483,647 | Python 3 | OK | TESTS | 14 | 31 | 0 | n=int(input())
s=input()
res = [int(x) for x in str(s)]
c=list(set(res))
if len(c)==1:
if c[0]==0:
print(s)
else:
print(1)
else:
t=res.count(0)
t1=[]
t1.append(1)
t2=[0]*t
t3=t1+t2
print(''.join(map(str, t3))) | Title: Minimum Binary Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two... | ```python
n=int(input())
s=input()
res = [int(x) for x in str(s)]
c=list(set(res))
if len(c)==1:
if c[0]==0:
print(s)
else:
print(1)
else:
t=res.count(0)
t1=[]
t1.append(1)
t2=[0]*t
t3=t1+t2
print(''.join(map(str, t3)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,636,993,947 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 46 | 0 | s=input()+''
n=len(s)
t='aeiou'
k=0
for i in range(n-1):
if (s[i] not in t+'n' and s[i+1] not in t):
k=k+1
break
if k==1:
print('NO')
else:
print('YES')
| Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
s=input()+''
n=len(s)
t='aeiou'
k=0
for i in range(n-1):
if (s[i] not in t+'n' and s[i+1] not in t):
k=k+1
break
if k==1:
print('NO')
else:
print('YES')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
697 | A | Pineapple Incident | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morn... | The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively. | Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output. | [
"3 10 4\n",
"3 10 3\n",
"3 8 51\n",
"3 8 52\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and ... | 500 | [
{
"input": "3 10 4",
"output": "NO"
},
{
"input": "3 10 3",
"output": "YES"
},
{
"input": "3 8 51",
"output": "YES"
},
{
"input": "3 8 52",
"output": "YES"
},
{
"input": "456947336 740144 45",
"output": "NO"
},
{
"input": "33 232603 599417964",
"ou... | 1,602,475,237 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 130,662,400 | t,s,x=map(int,input().split())
a=[]
a.append(t)
for i in range(1,x+1):
a.append(t+i*s)
a.append(t+i*s+1)
if x in a:
print('YES')
else:
print('NO')
| Title: Pineapple Incident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times... | ```python
t,s,x=map(int,input().split())
a=[]
a.append(t)
for i in range(1,x+1):
a.append(t+i*s)
a.append(t+i*s+1)
if x in a:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
420 | A | Start Up | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Recently, a start up by two students of a state university of city F gained incredible popularity. Now it's time to start a new company. But what do we call it?
The market analysts came up with a very smart plan: the name of the company should be identical to its reflection in a mirror! In other words, if we write out... | The first line contains a non-empty name that needs to be checked. The name contains at most 105 large English letters. The name will be written with the next sans serif font: | Print 'YES' (without the quotes), if the given name matches its mirror reflection. Otherwise, print 'NO' (without the quotes). | [
"AHA\n",
"Z\n",
"XO\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "AHA",
"output": "YES"
},
{
"input": "Z",
"output": "NO"
},
{
"input": "XO",
"output": "NO"
},
{
"input": "AAA",
"output": "YES"
},
{
"input": "AHHA",
"output": "YES"
},
{
"input": "BAB",
"output": "NO"
},
{
"input": "OMMMAAMMMO"... | 1,608,485,236 | 2,147,483,647 | Python 3 | OK | TESTS | 80 | 124 | 307,200 | s = input()
a = ['A','H','I','M','O','T','U','V','W','X','Y']
flag = 1
for i in s:
if i not in a: flag=0;break
if flag==1 and s == s[::-1]: print("YES")
else: print("NO") | Title: Start Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, a start up by two students of a state university of city F gained incredible popularity. Now it's time to start a new company. But what do we call it?
The market analysts came up with a very smart plan: the name of ... | ```python
s = input()
a = ['A','H','I','M','O','T','U','V','W','X','Y']
flag = 1
for i in s:
if i not in a: flag=0;break
if flag==1 and s == s[::-1]: print("YES")
else: print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
675 | B | Restoring Painting | PROGRAMMING | 1,400 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Vasya works as a watchman in the gallery. Unfortunately, one of the most expensive paintings was stolen while he was on duty. He doesn't want to be fired, so he has to quickly restore the painting. He remembers some facts about it.
- The painting is a square 3<=×<=3, each cell contains a single integer from 1 to *n*,... | The first line of the input contains five integers *n*, *a*, *b*, *c* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*a*,<=*b*,<=*c*,<=*d*<=≤<=*n*) — maximum possible value of an integer in the cell and four integers that Vasya remembers. | Print one integer — the number of distinct valid squares. | [
"2 1 1 1 2\n",
"3 3 1 2 3\n"
] | [
"2\n",
"6\n"
] | Below are all the possible paintings for the first sample. <img class="tex-graphics" src="https://espresso.codeforces.com/c4c53d4e7b6814d8aad7b72604b6089d61dadb48.png" style="max-width: 100.0%;max-height: 100.0%;"/> <img class="tex-graphics" src="https://espresso.codeforces.com/46a6ad6a5d3db202f3779b045b9dc77fc2348cf1.... | 1,000 | [
{
"input": "2 1 1 1 2",
"output": "2"
},
{
"input": "3 3 1 2 3",
"output": "6"
},
{
"input": "1 1 1 1 1",
"output": "1"
},
{
"input": "1000 522 575 426 445",
"output": "774000"
},
{
"input": "99000 52853 14347 64237 88869",
"output": "1296306000"
},
{
... | 1,463,596,672 | 892 | Python 3 | OK | TESTS | 58 | 77 | 4,915,200 | n, a, b, c, d = map(int, input().split())
ans = n * (n - abs(a - d) - abs(b - c))
print(max(0, ans))
| Title: Restoring Painting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a watchman in the gallery. Unfortunately, one of the most expensive paintings was stolen while he was on duty. He doesn't want to be fired, so he has to quickly restore the painting. He remembers some ... | ```python
n, a, b, c, d = map(int, input().split())
ans = n * (n - abs(a - d) - abs(b - c))
print(max(0, ans))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
290 | B | QR code | PROGRAMMING | 1,500 | [
"*special",
"implementation"
] | null | null | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=32), separated by a single space. | Output a single integer. | [
"1 1\n",
"3 7\n",
"13 10\n"
] | [
"0\n",
"0\n",
"1\n"
] | none | 0 | [
{
"input": "1 1",
"output": "0"
},
{
"input": "3 7",
"output": "0"
},
{
"input": "13 10",
"output": "1"
},
{
"input": "6 12",
"output": "1"
},
{
"input": "14 14",
"output": "0"
},
{
"input": "19 14",
"output": "0"
},
{
"input": "21 18",
... | 1,618,036,079 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 716,800 | l=( 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 0, 1, 0, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1,
1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1,
1, 0, 1, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 1,
1, 0, 1, 1, 1... | Title: QR code
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Input Specification:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=32), separated by a single space.
Output Specification:
Output a single integer.
Demo Input:
['1 1\n', '3 7\n', '13 10\n']
Demo Output:
['0... | ```python
l=( 1, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 0, 1, 0, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1,
1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1,
1, 0, 1, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 1,
1, ... | 0 | MatrixStudio/Codeforces-Python-Submissions | ||
331 | C3 | The Great Julya Calendar | PROGRAMMING | 2,500 | [
"dp"
] | null | null | Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on it. The translation from Old Beaverish is as follows:
"May the Great Beaver bless you! May your chacres open ... | The single line contains the magic integer *n*, 0<=≤<=*n*.
- to get 20 points, you need to solve the problem with constraints: *n*<=≤<=106 (subproblem C1); - to get 40 points, you need to solve the problem with constraints: *n*<=≤<=1012 (subproblems C1+C2); - to get 100 points, you need to solve the problem with co... | Print a single integer — the minimum number of subtractions that turns the magic number to a zero. | [
"24\n"
] | [
"5"
] | In the first test sample the minimum number of operations can be reached by the following sequence of subtractions: | 60 | [
{
"input": "24",
"output": "5"
},
{
"input": "0",
"output": "0"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "1"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "31",
"output": "6"
},
... | 1,379,476,283 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS3 | 0 | 92 | 0 | def magic(num,count):
if num<=9:
print(count+1)
else:
maxval=-1
for i in range(len(str(num))):
if int(str(num)[i])>maxval:
maxval=int(str(num)[i])
magic(num-maxval,count+1)
magic(240,0)
| Title: The Great Julya Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on i... | ```python
def magic(num,count):
if num<=9:
print(count+1)
else:
maxval=-1
for i in range(len(str(num))):
if int(str(num)[i])>maxval:
maxval=int(str(num)[i])
magic(num-maxval,count+1)
magic(240,0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
29 | B | Traffic Lights | PROGRAMMING | 1,500 | [
"implementation"
] | B. Traffic Lights | 2 | 256 | A car moves from point A to point B at speed *v* meters per second. The action takes place on the X-axis. At the distance *d* meters from A there are traffic lights. Starting from time 0, for the first *g* seconds the green light is on, then for the following *r* seconds the red light is on, then again the green light ... | The first line contains integers *l*, *d*, *v*, *g*, *r* (1<=≤<=*l*,<=*d*,<=*v*,<=*g*,<=*r*<=≤<=1000,<=*d*<=<<=*l*) — the distance between A and B (in meters), the distance from A to the traffic lights, car's speed, the duration of green light and the duration of red light. | Output a single number — the minimum time that the car needs to get from point A to point B. Your output must have relative or absolute error less than 10<=-<=6. | [
"2 1 3 4 5\n",
"5 4 3 1 1\n"
] | [
"0.66666667\n",
"2.33333333\n"
] | none | 1,000 | [
{
"input": "2 1 3 4 5",
"output": "0.66666667"
},
{
"input": "5 4 3 1 1",
"output": "2.33333333"
},
{
"input": "862 33 604 888 704",
"output": "1.42715232"
},
{
"input": "458 251 49 622 472",
"output": "9.34693878"
},
{
"input": "772 467 142 356 889",
"output"... | 1,624,000,515 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | l,d,v,g,r=input().split(" ")
l=int(l)
d=int(d)
v=int(v)
g=int(g)
r=int(r)
if d/v <=g :
print(l/v)
else :
print((d/v)+r+(l-d)/v) | Title: Traffic Lights
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A car moves from point A to point B at speed *v* meters per second. The action takes place on the X-axis. At the distance *d* meters from A there are traffic lights. Starting from time 0, for the first *g* seconds the green ... | ```python
l,d,v,g,r=input().split(" ")
l=int(l)
d=int(d)
v=int(v)
g=int(g)
r=int(r)
if d/v <=g :
print(l/v)
else :
print((d/v)+r+(l-d)/v)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,612,122,561 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 154 | 0 | y, w = map(int, input().split())
roll = max(y,w)
need = 6 - roll + 1
result = (need/6).as_integer_ratio()
ans = str(result[0]) + '/' + str(result[1])
print(ans) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
y, w = map(int, input().split())
roll = max(y,w)
need = 6 - roll + 1
result = (need/6).as_integer_ratio()
ans = str(result[0]) + '/' + str(result[1])
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
374 | A | Inna and Pink Pony | PROGRAMMING | 2,000 | [
"greedy",
"implementation"
] | null | null | Dima and Inna are doing so great! At the moment, Inna is sitting on the magic lawn playing with a pink pony. Dima wanted to play too. He brought an *n*<=×<=*m* chessboard, a very tasty candy and two numbers *a* and *b*.
Dima put the chessboard in front of Inna and placed the candy in position (*i*,<=*j*) on the board.... | The first line of the input contains six integers *n*,<=*m*,<=*i*,<=*j*,<=*a*,<=*b* (1<=≤<=*n*,<=*m*<=≤<=106; 1<=≤<=*i*<=≤<=*n*; 1<=≤<=*j*<=≤<=*m*; 1<=≤<=*a*,<=*b*<=≤<=106).
You can assume that the chessboard rows are numbered from 1 to *n* from top to bottom and the columns are numbered from 1 to *m* from left to rig... | In a single line print a single integer — the minimum number of moves needed to get the candy.
If Inna and the pony cannot get the candy playing by Dima's rules, print on a single line "Poor Inna and pony!" without the quotes. | [
"5 7 1 3 2 2\n",
"5 5 2 3 1 1\n"
] | [
"2\n",
"Poor Inna and pony!\n"
] | Note to sample 1:
Inna and the pony can move the candy to position (1 + 2, 3 + 2) = (3, 5), from there they can move it to positions (3 - 2, 5 + 2) = (1, 7) and (3 + 2, 5 + 2) = (5, 7). These positions correspond to the corner squares of the chess board. Thus, the answer to the test sample equals two. | 500 | [
{
"input": "5 7 1 3 2 2",
"output": "2"
},
{
"input": "5 5 2 3 1 1",
"output": "Poor Inna and pony!"
},
{
"input": "1 1 1 1 1 1",
"output": "0"
},
{
"input": "23000 15500 100 333 9 1",
"output": "15167"
},
{
"input": "33999 99333 33000 99000 3 9",
"output": "3... | 1,622,308,937 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | n,m,i,j,a,b=map(int,input().split())
if n-i == m-j:
print((n-i)//a,(m-j)//b)
else:
print("Poor Inna and pony!") | Title: Inna and Pink Pony
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and Inna are doing so great! At the moment, Inna is sitting on the magic lawn playing with a pink pony. Dima wanted to play too. He brought an *n*<=×<=*m* chessboard, a very tasty candy and two numbers *a* and *... | ```python
n,m,i,j,a,b=map(int,input().split())
if n-i == m-j:
print((n-i)//a,(m-j)//b)
else:
print("Poor Inna and pony!")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
727 | A | Transformation: from A to B | PROGRAMMING | 1,000 | [
"brute force",
"dfs and similar",
"math"
] | null | null | Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - append the digit 1 to the right of current number (that is, replace the number *x* by 10·*x*<=+<=1).
You need to he... | The first line contains two positive integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=109) — the number which Vasily has and the number he wants to have. | If there is no way to get *b* from *a*, print "NO" (without quotes).
Otherwise print three lines. On the first line print "YES" (without quotes). The second line should contain single integer *k* — the length of the transformation sequence. On the third line print the sequence of transformations *x*1,<=*x*2,<=...,<=*x... | [
"2 162\n",
"4 42\n",
"100 40021\n"
] | [
"YES\n5\n2 4 8 81 162 \n",
"NO\n",
"YES\n5\n100 200 2001 4002 40021 \n"
] | none | 1,000 | [
{
"input": "2 162",
"output": "YES\n5\n2 4 8 81 162 "
},
{
"input": "4 42",
"output": "NO"
},
{
"input": "100 40021",
"output": "YES\n5\n100 200 2001 4002 40021 "
},
{
"input": "1 111111111",
"output": "YES\n9\n1 11 111 1111 11111 111111 1111111 11111111 111111111 "
},
... | 1,678,906,393 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | a,b = [int(x) for x in input().split()]
def solve(i,prev):
if i>b:
return False
elif i<b:
prev.append(2*i)
choose2= solve(2*i,prev)
prev.pop()
prev.append(10*i+1)
choose1 = solve(10*i + 1,prev)
prev.pop()
elif i==b:
print... | Title: Transformation: from A to B
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - app... | ```python
a,b = [int(x) for x in input().split()]
def solve(i,prev):
if i>b:
return False
elif i<b:
prev.append(2*i)
choose2= solve(2*i,prev)
prev.pop()
prev.append(10*i+1)
choose1 = solve(10*i + 1,prev)
prev.pop()
elif i==b:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
125 | B | Simple XML | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Let's define a string <x> as an opening tag, where *x* is any small letter of the Latin alphabet. Each opening tag matches a closing tag of the type </x>, where *x* is the same letter.
Tegs can be nested into each other: in this case one opening and closing tag pair is located inside another pair.
Let's d... | The input data consists on the only non-empty string — the XML-text, its length does not exceed 1000 characters. It is guaranteed that the text is valid. The text contains no spaces. | Print the given XML-text according to the above-given rules. | [
"<a><b><c></c></b></a>\n",
"<a><b></b><d><c></c></d></a>\n"
] | [
"<a>\n <b>\n <c>\n </c>\n </b>\n</a>\n",
"<a>\n <b>\n </b>\n <d>\n <c>\n </c>\n </d>\n</a>\n"
] | none | 1,500 | [
{
"input": "<a><b><c></c></b></a>",
"output": "<a>\n <b>\n <c>\n </c>\n </b>\n</a>"
},
{
"input": "<a><b></b><d><c></c></d></a>",
"output": "<a>\n <b>\n </b>\n <d>\n <c>\n </c>\n </d>\n</a>"
},
{
"input": "<z></z>",
"output": "<z>\n</z>"
},
{
"input": "<u><d... | 1,689,509,939 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 0 | s = input()
l=[]
for i in range(0,len(s)):
if s[i] >= 'a' and s[i] <= 'z':
l.append(s[i])
stack = []
i=0
# stack.append(s[0])
for c in l:
if(len(stack)==0 or c != stack[len(stack)-1]):
print(2*len(stack)*' '+'<'+c+'>')
stack.append(c)
elif c == stack[len(stack)-1]:
... | Title: Simple XML
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's define a string <x> as an opening tag, where *x* is any small letter of the Latin alphabet. Each opening tag matches a closing tag of the type </x>, where *x* is the same letter.
Tegs can be nested into ea... | ```python
s = input()
l=[]
for i in range(0,len(s)):
if s[i] >= 'a' and s[i] <= 'z':
l.append(s[i])
stack = []
i=0
# stack.append(s[0])
for c in l:
if(len(stack)==0 or c != stack[len(stack)-1]):
print(2*len(stack)*' '+'<'+c+'>')
stack.append(c)
elif c == stack[len(stack)-... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,686,230,452 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 62 | 0 | a, b = map(int, input().split())
diff_socks = min(a, b)
same_socks = (max(a, b) - diff_socks) // 2
print(diff_socks, same_socks)
| Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
a, b = map(int, input().split())
diff_socks = min(a, b)
same_socks = (max(a, b) - diff_socks) // 2
print(diff_socks, same_socks)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
404 | A | Valera and X | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the... | The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper. | Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes. | [
"5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n",
"3\nwsw\nsws\nwsw\n",
"3\nxpx\npxp\nxpe\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox",
"output": "NO"
},
{
"input": "3\nwsw\nsws\nwsw",
"output": "YES"
},
{
"input": "3\nxpx\npxp\nxpe",
"output": "NO"
},
{
"input": "5\nliiil\nilili\niilii\nilili\nliiil",
"output": "YES"
},
{
"input": "7\nbwccccb\nck... | 1,626,472,741 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 93 | 7,372,800 |
if __name__ == '__main__':
n = int(input())
s = [list(input()) for i in range(n)]
f = True
c = s[0][0]
c2 = s[0][1]
k = 0
for i in range(n):
if s[i][k] == s[i][n-k-1] == c:
k += 1
else:
f = False
break
for j in rang... | Title: Valera and X
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a... | ```python
if __name__ == '__main__':
n = int(input())
s = [list(input()) for i in range(n)]
f = True
c = s[0][0]
c2 = s[0][1]
k = 0
for i in range(n):
if s[i][k] == s[i][n-k-1] == c:
k += 1
else:
f = False
break
for... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,649,077,755 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 23 | 61 | 1,843,200 | n, t = map(int, input().split())
g = list(range(n))
k = 0
for i in map(int, input().split()):
g[k] += i
k += 1
def dfs(v):
if v == t - 1:
return 'YES'
if v >= t:
return 'NO'
return dfs(g[v])
print(dfs(0)) | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
n, t = map(int, input().split())
g = list(range(n))
k = 0
for i in map(int, input().split()):
g[k] += i
k += 1
def dfs(v):
if v == t - 1:
return 'YES'
if v >= t:
return 'NO'
return dfs(g[v])
print(dfs(0))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
-... | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,489,590,212 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 62 | 4,608,000 | arr = [int(x) for x in input().split()]
arr.sort()
s = set(arr)
le = len(s)
if le==1:
print("Elephant")
elif le==2:
a,b = s
if arr.count(a)==4 or arr.count(b)==4:
print("Elephant")
else:
print("Bear")
elif le==3:
a,b,c=s
if arr.count(a)==4 or arr.count(b)==4 or arr.count(c)==4:
print("Bear")
else:
print(... | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an... | ```python
arr = [int(x) for x in input().split()]
arr.sort()
s = set(arr)
le = len(s)
if le==1:
print("Elephant")
elif le==2:
a,b = s
if arr.count(a)==4 or arr.count(b)==4:
print("Elephant")
else:
print("Bear")
elif le==3:
a,b,c=s
if arr.count(a)==4 or arr.count(b)==4 or arr.count(c)==4:
print("Bear")
else... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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