contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
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value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
515 | A | Drazil and Date | PROGRAMMING | 1,000 | [
"math"
] | null | null | Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit distance in horizontal or vertical direction. In other words, from position (*x*,<=*y*) he can go to ... | You are given three integers *a*, *b*, and *s* (<=-<=109<=≤<=*a*,<=*b*<=≤<=109, 1<=≤<=*s*<=≤<=2·109) in a single line. | If you think Drazil made a mistake and it is impossible to take exactly *s* steps and get from his home to Varda's home, print "No" (without quotes).
Otherwise, print "Yes". | [
"5 5 11\n",
"10 15 25\n",
"0 5 1\n",
"0 0 2\n"
] | [
"No\n",
"Yes\n",
"No\n",
"Yes\n"
] | In fourth sample case one possible route is: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/0d30660ddf6eb6c64ffd071055a4e8ddd016cde5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 500 | [
{
"input": "5 5 11",
"output": "No"
},
{
"input": "10 15 25",
"output": "Yes"
},
{
"input": "0 5 1",
"output": "No"
},
{
"input": "0 0 2",
"output": "Yes"
},
{
"input": "999999999 999999999 2000000000",
"output": "Yes"
},
{
"input": "-606037695 9983201... | 1,602,626,865 | 165 | Python 3 | WRONG_ANSWER | TESTS | 8 | 109 | 0 | a, b, s = [int(x) for x in input().split(' ')]
if a + b <= s and (a + b - s) % 2 == 0:
ans = 'Yes'
else:
ans = 'No'
print(ans) | Title: Drazil and Date
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit ... | ```python
a, b, s = [int(x) for x in input().split(' ')]
if a + b <= s and (a + b - s) % 2 == 0:
ans = 'Yes'
else:
ans = 'No'
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge... | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,569,155,935 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 108 | 204,800 | class FibonacciHeap:
# internal node class
class Node:
def __init__(self, data):
self.data = data
self.parent = self.child = self.left = self.right = None
self.degree = 0
self.mark = False
# function to iterate through a doubly linked li... | Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* a... | ```python
class FibonacciHeap:
# internal node class
class Node:
def __init__(self, data):
self.data = data
self.parent = self.child = self.left = self.right = None
self.degree = 0
self.mark = False
# function to iterate through a doubly... | 0 | MatrixStudio/Codeforces-Python-Submissions |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,654,706,145 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 |
m = int(input())
n = int(input())
board_size = m*n
max_dominos = int(board_size/2)
print(max_dominos) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
m = int(input())
n = int(input())
board_size = m*n
max_dominos = int(board_size/2)
print(max_dominos)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
508 | B | Anton and currency you all know | PROGRAMMING | 1,300 | [
"greedy",
"math",
"strings"
] | null | null | Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed to be an integer.
Reliable sources have informed the financier Anton of some information about the exchange rate of... | The first line contains an odd positive integer *n* — the exchange rate of currency you all know for today. The length of number *n*'s representation is within range from 2 to 105, inclusive. The representation of *n* doesn't contain any leading zeroes. | If the information about tomorrow's exchange rate is inconsistent, that is, there is no integer that meets the condition, print <=-<=1.
Otherwise, print the exchange rate of currency you all know against the burle for tomorrow. This should be the maximum possible number of those that are even and that are obtained fro... | [
"527\n",
"4573\n",
"1357997531\n"
] | [
"572\n",
"3574\n",
"-1\n"
] | none | 1,000 | [
{
"input": "527",
"output": "572"
},
{
"input": "4573",
"output": "3574"
},
{
"input": "1357997531",
"output": "-1"
},
{
"input": "444443",
"output": "444434"
},
{
"input": "22227",
"output": "72222"
},
{
"input": "24683",
"output": "34682"
},
... | 1,695,037,665 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 500 | 163,532,800 | import sys as sys
s= list(input())
le= len(s)
q=[]
for i in range(len(s)):
if int(s[i])%2==0:
sex= s.copy()
sex[i],sex[-1]= sex[-1],sex[i]
q.append(sex)
if len(q)==0:
print(-1)
sys.exit()
q.sort()
for e in q[-1]:
print(e, end="") | Title: Anton and currency you all know
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed... | ```python
import sys as sys
s= list(input())
le= len(s)
q=[]
for i in range(len(s)):
if int(s[i])%2==0:
sex= s.copy()
sex[i],sex[-1]= sex[-1],sex[i]
q.append(sex)
if len(q)==0:
print(-1)
sys.exit()
q.sort()
for e in q[-1]:
print(e, end="")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,589,909,782 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 16 | 1,029 | 13,414,400 | #https://codeforces.com/problemset/problem/862/B
def dfs(node,flag):
a[flag]+=1
visited[node]=1
for i in range(len(tree[node])):
if visited[tree[node][i]]==0:
dfs(tree[node][i],flag^1)
n=int(input())
a=[0]*2
visited=[0]*(n+1)
tree=[[] for i in range(n+1)]
for i in range(n-1):
... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
#https://codeforces.com/problemset/problem/862/B
def dfs(node,flag):
a[flag]+=1
visited[node]=1
for i in range(len(tree[node])):
if visited[tree[node][i]]==0:
dfs(tree[node][i],flag^1)
n=int(input())
a=[0]*2
visited=[0]*(n+1)
tree=[[] for i in range(n+1)]
for i in ra... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third ... | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain ... | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,635,242,174 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 4,505,600 | n = int(input())
x=input()
m = 0
y = len(x)
for j in range(len(x)):
if x.count(x[j]) > 1:
if m < x.count(x[j]):
m = x.count(x[j])
print(m)
| Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from... | ```python
n = int(input())
x=input()
m = 0
y = len(x)
for j in range(len(x)):
if x.count(x[j]) > 1:
if m < x.count(x[j]):
m = x.count(x[j])
print(m)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,695,233,176 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 62 | 0 | t=int(input())
n = t // 5
x = t % 5
L=n + (x > 0)
print(L) | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
t=int(input())
n = t // 5
x = t % 5
L=n + (x > 0)
print(L)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,538,591,448 | 1,068 | Python 3 | OK | TESTS | 21 | 124 | 0 | n,k=int(input()),0
l=set(map(int,input().split()))
if 0 in l: k=1
print(len(l)-k)
| Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
n,k=int(input()),0
l=set(map(int,input().split()))
if 0 in l: k=1
print(len(l)-k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
489 | C | Given Length and Sum of Digits... | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should be non-negative integers written in the decimal base without leading zeroes. | The single line of the input contains a pair of integers *m*, *s* (1<=≤<=*m*<=≤<=100,<=0<=≤<=*s*<=≤<=900) — the length and the sum of the digits of the required numbers. | In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes). | [
"2 15\n",
"3 0\n"
] | [
"69 96\n",
"-1 -1\n"
] | none | 1,500 | [
{
"input": "2 15",
"output": "69 96"
},
{
"input": "3 0",
"output": "-1 -1"
},
{
"input": "2 1",
"output": "10 10"
},
{
"input": "3 10",
"output": "109 910"
},
{
"input": "100 100",
"output": "1000000000000000000000000000000000000000000000000000000000000000000... | 1,681,806,769 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | l = input().split()
m = int(l[0])
s = int(l[1])
if(m>0 and s==0):
print(-1, -1)
else:
m1 = m
s1 = s
r = ""
while m > 0:
if (m-1)*9 > s:
r += "1"
s -= 1
else:
r += str(s-((m-1)*9))
s -= (s-((m-1)*9))
m -= 1
p... | Title: Given Length and Sum of Digits...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should ... | ```python
l = input().split()
m = int(l[0])
s = int(l[1])
if(m>0 and s==0):
print(-1, -1)
else:
m1 = m
s1 = s
r = ""
while m > 0:
if (m-1)*9 > s:
r += "1"
s -= 1
else:
r += str(s-((m-1)*9))
s -= (s-((m-1)*9))
m -... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
755 | B | PolandBall and Game | PROGRAMMING | 1,100 | [
"binary search",
"data structures",
"games",
"greedy",
"sortings",
"strings"
] | null | null | PolandBall is playing a game with EnemyBall. The rules are simple. Players have to say words in turns. You cannot say a word which was already said. PolandBall starts. The Ball which can't say a new word loses.
You're given two lists of words familiar to PolandBall and EnemyBall. Can you determine who wins the game, i... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=103) — number of words PolandBall and EnemyBall know, respectively.
Then *n* strings follow, one per line — words familiar to PolandBall.
Then *m* strings follow, one per line — words familiar to EnemyBall.
Note that one Ball cannot know a w... | In a single line of print the answer — "YES" if PolandBall wins and "NO" otherwise. Both Balls play optimally. | [
"5 1\npolandball\nis\na\ncool\ncharacter\nnope\n",
"2 2\nkremowka\nwadowicka\nkremowka\nwiedenska\n",
"1 2\na\na\nb\n"
] | [
"YES",
"YES",
"NO"
] | In the first example PolandBall knows much more words and wins effortlessly.
In the second example if PolandBall says kremowka first, then EnemyBall cannot use that word anymore. EnemyBall can only say wiedenska. PolandBall says wadowicka and wins. | 1,000 | [
{
"input": "5 1\npolandball\nis\na\ncool\ncharacter\nnope",
"output": "YES"
},
{
"input": "2 2\nkremowka\nwadowicka\nkremowka\nwiedenska",
"output": "YES"
},
{
"input": "1 2\na\na\nb",
"output": "NO"
},
{
"input": "2 2\na\nb\nb\nc",
"output": "YES"
},
{
"input": "... | 1,639,400,152 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | n, m = map(int, input().split())
n_palavras = {input() for i in range(n)}
m_palavras = {input() for i in range(m)}
m_apenas = m_palavras - n_palavras
if n > m or len(n_palavras) > len(m_apenas): print("YES")
else: print("NO")
| Title: PolandBall and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is playing a game with EnemyBall. The rules are simple. Players have to say words in turns. You cannot say a word which was already said. PolandBall starts. The Ball which can't say a new word loses.
You... | ```python
n, m = map(int, input().split())
n_palavras = {input() for i in range(n)}
m_palavras = {input() for i in range(m)}
m_apenas = m_palavras - n_palavras
if n > m or len(n_palavras) > len(m_apenas): print("YES")
else: print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,690,441,145 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n=int(input())
l=list(input().strip().split())[:n]
s=set(l)
print(len(s))
| Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
n=int(input())
l=list(input().strip().split())[:n]
s=set(l)
print(len(s))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,695,042,043 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 31 | 0 | def min_rotations_to_print(name):
rotations = 0
current_letter = 'a'
for letter in name:
clockwise_distance = (ord(letter) - ord(current_letter) + 26) % 26
counterclockwise_distance = (ord(current_letter) - ord(letter) + 26) % 26
rotations += min(clockwise_distanc... | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
def min_rotations_to_print(name):
rotations = 0
current_letter = 'a'
for letter in name:
clockwise_distance = (ord(letter) - ord(current_letter) + 26) % 26
counterclockwise_distance = (ord(current_letter) - ord(letter) + 26) % 26
rotations += min(clockwi... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,693,487,679 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 77 | 0 | word = input()
hello_word = ["h", "e", "l", "o"]
formed_hello = ""
i = 0
for s in word:
if i >3:
break
if s == hello_word[i]:
if i != 2:
formed_hello += s
i += 1
elif i == 2:
if(formed_hello.count("l") == 1):
i+=1
... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
word = input()
hello_word = ["h", "e", "l", "o"]
formed_hello = ""
i = 0
for s in word:
if i >3:
break
if s == hello_word[i]:
if i != 2:
formed_hello += s
i += 1
elif i == 2:
if(formed_hello.count("l") == 1):
i+=1
... | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
451 | A | Game With Sticks | PROGRAMMING | 900 | [
"implementation"
] | null | null | After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.
In the grid show... | The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). | Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game. | [
"2 2\n",
"2 3\n",
"3 3\n"
] | [
"Malvika\n",
"Malvika\n",
"Akshat\n"
] | Explanation of the first sample:
The grid has four intersection points, numbered from 1 to 4.
If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this.
Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remov... | 500 | [
{
"input": "2 2",
"output": "Malvika"
},
{
"input": "2 3",
"output": "Malvika"
},
{
"input": "3 3",
"output": "Akshat"
},
{
"input": "20 68",
"output": "Malvika"
},
{
"input": "1 1",
"output": "Akshat"
},
{
"input": "1 2",
"output": "Akshat"
},
... | 1,686,228,914 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 31 | 0 | # t = int(input())
# while t>0:
n,m = (int(i) for i in input().split())
if(min(n,m)%2==0):
print("Malvika")
else:
print("Akshat")
# t-=1 | Title: Game With Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid... | ```python
# t = int(input())
# while t>0:
n,m = (int(i) for i in input().split())
if(min(n,m)%2==0):
print("Malvika")
else:
print("Akshat")
# t-=1
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
789 | B | Masha and geometric depression | PROGRAMMING | 1,700 | [
"brute force",
"implementation",
"math"
] | null | null | Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric progression is a sequence of integers *b*1,<=*b*2,<=*b*3,<=..., where for each *i*<=><=1 the respective term satisfi... | The first line of input contains four integers *b*1, *q*, *l*, *m* (-109<=≤<=*b*1,<=*q*<=≤<=109, 1<=≤<=*l*<=≤<=109, 1<=≤<=*m*<=≤<=105) — the initial term and the common ratio of progression, absolute value of maximal number that can be written on the board and the number of "bad" integers, respectively.
The second lin... | Print the only integer, meaning the number of progression terms that will be written on the board if it is finite, or "inf" (without quotes) otherwise. | [
"3 2 30 4\n6 14 25 48\n",
"123 1 2143435 4\n123 11 -5453 141245\n",
"123 1 2143435 4\n54343 -13 6 124\n"
] | [
"3",
"0",
"inf"
] | In the first sample case, Masha will write integers 3, 12, 24. Progression term 6 will be skipped because it is a "bad" integer. Terms bigger than 24 won't be written because they exceed *l* by absolute value.
In the second case, Masha won't write any number because all terms are equal 123 and this is a "bad" integer.... | 1,000 | [
{
"input": "3 2 30 4\n6 14 25 48",
"output": "3"
},
{
"input": "123 1 2143435 4\n123 11 -5453 141245",
"output": "0"
},
{
"input": "123 1 2143435 4\n54343 -13 6 124",
"output": "inf"
},
{
"input": "3 2 25 2\n379195692 -69874783",
"output": "4"
},
{
"input": "3 2 3... | 1,491,595,983 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 14,745,600 | b, q, l, m = map(int, input().split())
s = set(map(int, input().split()))
if q == 1:
if b not in s and abs(b) <= l:
print("inf")
exit()
else:
print(0)
exit()
if q == -1:
if abs(b) <= l and (b not in s or b * -1 not in s):
print("inf")
exit()
e... | Title: Masha and geometric depression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric pro... | ```python
b, q, l, m = map(int, input().split())
s = set(map(int, input().split()))
if q == 1:
if b not in s and abs(b) <= l:
print("inf")
exit()
else:
print(0)
exit()
if q == -1:
if abs(b) <= l and (b not in s or b * -1 not in s):
print("inf")
exi... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
607 | A | Chain Reaction | PROGRAMMING | 1,600 | [
"binary search",
"dp"
] | null | null | There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of decreasing coordinates) within distance *b**i* inclusive. The beacon itself is not destroyed however.... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the initial number of beacons.
The *i*-th of next *n* lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=1<=000<=000, 1<=≤<=*b**i*<=≤<=1<=000<=000) — the position and power level of the *i*-th beacon respectively. No two beac... | Print a single integer — the minimum number of beacons that could be destroyed if exactly one beacon is added. | [
"4\n1 9\n3 1\n6 1\n7 4\n",
"7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1\n"
] | [
"1\n",
"3\n"
] | For the first sample case, the minimum number of beacons destroyed is 1. One way to achieve this is to place a beacon at position 9 with power level 2.
For the second sample case, the minimum number of beacons destroyed is 3. One way to achieve this is to place a beacon at position 1337 with power level 42. | 500 | [
{
"input": "4\n1 9\n3 1\n6 1\n7 4",
"output": "1"
},
{
"input": "7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1",
"output": "3"
},
{
"input": "1\n0 1",
"output": "0"
},
{
"input": "1\n0 1000000",
"output": "0"
},
{
"input": "1\n1000000 1000000",
"output": "0"
},
{
... | 1,591,193,669 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | n = int(input())
a = []
b = []
d = {}
for i in range(n):
x, y = map(int, input().split())
d[x] = y
a.append(x)
b.append(y)
m = max(a)
ans = [0] * (m + 1)
for i in range(1, m + 1):
if d.get(i, -1) == -1:
ans[i] = ans[i - 1]
else:
ans[i] = 1 + (ans[i - d[i] - 1] if i - d[i] - 1 >= ... | Title: Chain Reaction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of d... | ```python
n = int(input())
a = []
b = []
d = {}
for i in range(n):
x, y = map(int, input().split())
d[x] = y
a.append(x)
b.append(y)
m = max(a)
ans = [0] * (m + 1)
for i in range(1, m + 1):
if d.get(i, -1) == -1:
ans[i] = ans[i - 1]
else:
ans[i] = 1 + (ans[i - d[i] - 1] if i - d[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,614,318,665 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 124 | 614,400 | n=int(input())
l=list(map(int,input().split()))
s=set(l)
c=0
for i in s:
if((i>n) or (i<0)):
c=c+1
c=c+(n-(len(s)))
print(c) | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
n=int(input())
l=list(map(int,input().split()))
s=set(l)
c=0
for i in s:
if((i>n) or (i<0)):
c=c+1
c=c+(n-(len(s)))
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
954 | A | Diagonal Walking | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence moving up is described by character U and moving right is described by character R. Mikhail can replace an... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence. The second line contains the sequence consisting of *n* characters U and R. | Print the minimum possible length of the sequence of moves after all replacements are done. | [
"5\nRUURU\n",
"17\nUUURRRRRUUURURUUU\n"
] | [
"3\n",
"13\n"
] | In the first test the shortened sequence of moves may be DUD (its length is 3).
In the second test the shortened sequence of moves can be UUDRRRDUDDUUU (its length is 13). | 0 | [
{
"input": "5\nRUURU",
"output": "3"
},
{
"input": "17\nUUURRRRRUUURURUUU",
"output": "13"
},
{
"input": "100\nUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU",
"output": "100"
},
{
"input": "100\nRRURRUUUURURRRURRRRURRRRRR... | 1,637,472,899 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n=int(input())
s=input()
for i in range(n):
if s[i]=='RU' or s[i]=='UR':
n=n-1
print(n)
| Title: Diagonal Walking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence movi... | ```python
n=int(input())
s=input()
for i in range(n):
if s[i]=='RU' or s[i]=='UR':
n=n-1
print(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
448 | D | Multiplication Table | PROGRAMMING | 1,800 | [
"binary search",
"brute force"
] | null | null | Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multiplication table, where the element on the intersection of the *i*-th row and *j*-th column equals *i*·*j* ... | The single line contains integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=5·105; 1<=≤<=*k*<=≤<=*n*·*m*). | Print the *k*-th largest number in a *n*<=×<=*m* multiplication table. | [
"2 2 2\n",
"2 3 4\n",
"1 10 5\n"
] | [
"2\n",
"3\n",
"5\n"
] | A 2 × 3 multiplication table looks like this: | 2,000 | [
{
"input": "2 2 2",
"output": "2"
},
{
"input": "2 3 4",
"output": "3"
},
{
"input": "1 10 5",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "10 1 7",
"output": "7"
},
{
"input": "10 10 33",
"output": "14"
},
{
"input": "... | 1,693,712,301 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n,m,k=map(int, input().split())
def check(value):
num=0
for i in range(1,n+1):
num+=value//i
return num
lower = 1
upper = n*m
mid = (lower+upper)//2
ans = 9999999999
while lower<=upper:
if check(mid)<=k:
upper-=1
if check(mid)>k:
lower+=1
mid = (upper+lower)//2
ans ... | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multi... | ```python
n,m,k=map(int, input().split())
def check(value):
num=0
for i in range(1,n+1):
num+=value//i
return num
lower = 1
upper = n*m
mid = (lower+upper)//2
ans = 9999999999
while lower<=upper:
if check(mid)<=k:
upper-=1
if check(mid)>k:
lower+=1
mid = (upper+lower)//... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
620 | A | Professor GukiZ's Robot | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of them) by one (decrease or increase). So the robot can move in one of the 8 directions. Find the minimal numbe... | The first line contains two integers *x*1,<=*y*1 (<=-<=109<=≤<=*x*1,<=*y*1<=≤<=109) — the start position of the robot.
The second line contains two integers *x*2,<=*y*2 (<=-<=109<=≤<=*x*2,<=*y*2<=≤<=109) — the finish position of the robot. | Print the only integer *d* — the minimal number of steps to get the finish position. | [
"0 0\n4 5\n",
"3 4\n6 1\n"
] | [
"5\n",
"3\n"
] | In the first example robot should increase both of its coordinates by one four times, so it will be in position (4, 4). After that robot should simply increase its *y* coordinate and get the finish position.
In the second example robot should simultaneously increase *x* coordinate and decrease *y* coordinate by one th... | 0 | [
{
"input": "0 0\n4 5",
"output": "5"
},
{
"input": "3 4\n6 1",
"output": "3"
},
{
"input": "0 0\n4 6",
"output": "6"
},
{
"input": "1 1\n-3 -5",
"output": "6"
},
{
"input": "-1 -1\n-10 100",
"output": "101"
},
{
"input": "1 -1\n100 -100",
"output":... | 1,655,999,786 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 30 | 0 | '''
set the first coordinate to the origin by finding the difference
of the two coordinates
'''
xa, ya = map ( int, input () .split () )
xb, yb = map ( int, input () .split () )
x = xb - xa
y = yb - ya
if x == y:
_print = x
elif x == -y:
_print: abs ( y )
elif x > y:
_print = y + ( x - y )
elif y > x:
... | Title: Professor GukiZ's Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of ... | ```python
'''
set the first coordinate to the origin by finding the difference
of the two coordinates
'''
xa, ya = map ( int, input () .split () )
xb, yb = map ( int, input () .split () )
x = xb - xa
y = yb - ya
if x == y:
_print = x
elif x == -y:
_print: abs ( y )
elif x > y:
_print = y + ( x - y )
elif ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,653,548,771 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | M,N= input().split()
domino_number=(int(M)*int(N))//2
print(domino_number) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
M,N= input().split()
domino_number=(int(M)*int(N))//2
print(domino_number)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,677,078,348 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 18 | 92 | 0 | n,m = map(int,input().split())
f = list(map(int,input().split()))
f.sort()
counter = 100000
for i in range(m-n+1):
counter = min(counter,f[i+n-1]-f[i])
print(counter) | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
n,m = map(int,input().split())
f = list(map(int,input().split()))
f.sort()
counter = 100000
for i in range(m-n+1):
counter = min(counter,f[i+n-1]-f[i])
print(counter)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
287 | B | Pipeline | PROGRAMMING | 1,700 | [
"binary search",
"math"
] | null | null | Vova, the Ultimate Thule new shaman, wants to build a pipeline. As there are exactly *n* houses in Ultimate Thule, Vova wants the city to have exactly *n* pipes, each such pipe should be connected to the water supply. A pipe can be connected to the water supply if there's water flowing out of it. Initially Vova has onl... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=1018, 2<=≤<=*k*<=≤<=109).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print a single integer — the minimum number of splitters needed to build the pipeline. If it is impossible to build a pipeline with the given splitters, print -1. | [
"4 3\n",
"5 5\n",
"8 4\n"
] | [
"2\n",
"1\n",
"-1\n"
] | none | 1,500 | [
{
"input": "4 3",
"output": "2"
},
{
"input": "5 5",
"output": "1"
},
{
"input": "8 4",
"output": "-1"
},
{
"input": "1000000000000000000 1000000000",
"output": "-1"
},
{
"input": "499999998500000001 1000000000",
"output": "999955279"
},
{
"input": "49... | 1,644,396,009 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 12 | 62 | 0 |
n,k = map(int,input().split())
def check(s,k):
incr = k
temp = 0
noofsplt = 0
while noofsplt<=mid:
if temp+1<n:
noofsplt+=1
temp+=(incr-1)
incr-=1
else:
return True,noofsplt
return False,float("inf")
l = 0
... | Title: Pipeline
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vova, the Ultimate Thule new shaman, wants to build a pipeline. As there are exactly *n* houses in Ultimate Thule, Vova wants the city to have exactly *n* pipes, each such pipe should be connected to the water supply. A pipe c... | ```python
n,k = map(int,input().split())
def check(s,k):
incr = k
temp = 0
noofsplt = 0
while noofsplt<=mid:
if temp+1<n:
noofsplt+=1
temp+=(incr-1)
incr-=1
else:
return True,noofsplt
return False,float("inf")
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,586,852,458 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | mdollar=[7,9,8,5,4,3,2]
mdays=[1,2,3,4,5,6,7]
minimum=0
for i in range(len(mdollar)):
if mdollar[0]>mdollar[1]:
minimum=mdollar[1]
elif mdollar[1]>mdollar[2]:
minimum=mdollar[2]
mdollar+=mdays
print(minimum)
| Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
mdollar=[7,9,8,5,4,3,2]
mdays=[1,2,3,4,5,6,7]
minimum=0
for i in range(len(mdollar)):
if mdollar[0]>mdollar[1]:
minimum=mdollar[1]
elif mdollar[1]>mdollar[2]:
minimum=mdollar[2]
mdollar+=mdays
print(minimum)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
902 | B | Coloring a Tree | PROGRAMMING | 1,200 | [
"dfs and similar",
"dsu",
"greedy"
] | null | null | You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
You have to color the tree into the given colors using the smallest possible number of steps. On eac... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=104) — the number of vertices in the tree.
The second line contains *n*<=-<=1 integers *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=<<=*i*), where *p**i* means that there is an edge between vertices *i* and *p**i*.
The third line contains *n* integers *c*1,<... | Print a single integer — the minimum number of steps you have to perform to color the tree into given colors. | [
"6\n1 2 2 1 5\n2 1 1 1 1 1\n",
"7\n1 1 2 3 1 4\n3 3 1 1 1 2 3\n"
] | [
"3\n",
"5\n"
] | The tree from the first sample is shown on the picture (numbers are vetices' indices):
<img class="tex-graphics" src="https://espresso.codeforces.com/10324ccdc37f95343acc4f3c6050d8c334334ffa.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On first step we color all vertices in the subtree of vertex 1 into color ... | 1,000 | [
{
"input": "6\n1 2 2 1 5\n2 1 1 1 1 1",
"output": "3"
},
{
"input": "7\n1 1 2 3 1 4\n3 3 1 1 1 2 3",
"output": "5"
},
{
"input": "2\n1\n2 2",
"output": "1"
},
{
"input": "3\n1 1\n2 2 2",
"output": "1"
},
{
"input": "4\n1 2 1\n1 2 3 4",
"output": "4"
},
{
... | 1,597,393,814 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | R=lambda:map(int,raw_input().split())
n=input()
p=[0,0]+R()
c=[-1]+R()
print sum(c[x]!=c[p[x]] for x in range(n+1)) | Title: Coloring a Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
... | ```python
R=lambda:map(int,raw_input().split())
n=input()
p=[0,0]+R()
c=[-1]+R()
print sum(c[x]!=c[p[x]] for x in range(n+1))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
182 | D | Common Divisors | PROGRAMMING | 1,400 | [
"brute force",
"hashing",
"implementation",
"math",
"strings"
] | null | null | Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive integer *x* such that if we write out string *a* consecutively *x* times, we get string *b*. For exam... | The first input line contains a non-empty string *s*1.
The second input line contains a non-empty string *s*2.
Lengths of strings *s*1 and *s*2 are positive and do not exceed 105. The strings only consist of lowercase Latin letters. | Print the number of common divisors of strings *s*1 and *s*2. | [
"abcdabcd\nabcdabcdabcdabcd\n",
"aaa\naa\n"
] | [
"2\n",
"1\n"
] | In first sample the common divisors are strings "abcd" and "abcdabcd".
In the second sample the common divisor is a single string "a". String "aa" isn't included in the answer as it isn't a divisor of string "aaa". | 1,000 | [
{
"input": "abcdabcd\nabcdabcdabcdabcd",
"output": "2"
},
{
"input": "aaa\naa",
"output": "1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaa\naaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "3"
},
{
"input": "aaaaaaaaaaaaaa\naaaaaaaaaaaaaa",
"output": "4"
},
{
"input": "a\nb",
... | 1,605,854,190 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 248 | 0 | #!/usr/bin/env python3
import io
import os
import sys
input = io.Byte... | Title: Common Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive ... | ```python
#!/usr/bin/env python3
import io
import os
import sys
input... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
847 | A | Union of Doubly Linked Lists | PROGRAMMING | 1,500 | [
"implementation"
] | null | null | Doubly linked list is one of the fundamental data structures. A doubly linked list is a sequence of elements, each containing information about the previous and the next elements of the list. In this problem all lists have linear structure. I.e. each element except the first has exactly one previous element, each eleme... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of memory cells where the doubly linked lists are located.
Each of the following *n* lines contains two integers *l**i*, *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=*n*) — the cells of the previous and the next element of list for cell *i*. Value *l**... | Print *n* lines, the *i*-th line must contain two integers *l**i* and *r**i* — the cells of the previous and the next element of list for cell *i* after all lists from the input are united in a single list. If there are many solutions print any of them. | [
"7\n4 7\n5 0\n0 0\n6 1\n0 2\n0 4\n1 0\n"
] | [
"4 7\n5 6\n0 5\n6 1\n3 2\n2 4\n1 0\n"
] | none | 0 | [
{
"input": "7\n4 7\n5 0\n0 0\n6 1\n0 2\n0 4\n1 0",
"output": "4 7\n5 6\n0 5\n6 1\n3 2\n2 4\n1 0"
},
{
"input": "2\n2 0\n0 1",
"output": "2 0\n0 1"
},
{
"input": "1\n0 0",
"output": "0 0"
},
{
"input": "4\n0 2\n1 0\n0 4\n3 0",
"output": "0 2\n1 3\n2 4\n3 0"
},
{
"i... | 1,674,658,479 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 9 | 77 | 0 | n=int(input())
L,L2,lst=[],[],[]
c=0
for _ in range(n):
l,r=map(int,input().split())
L.append([l,r])
if r==0:
c+=1
else:
L2.append(r)
for i in range(n):
if n-i not in L2:
lst.append(n-i)
p=0
for i in range(n):
if L[i][1]==0 and lst[p]!=L[i][0] and i+1!=lst[... | Title: Union of Doubly Linked Lists
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Doubly linked list is one of the fundamental data structures. A doubly linked list is a sequence of elements, each containing information about the previous and the next elements of the list. In this proble... | ```python
n=int(input())
L,L2,lst=[],[],[]
c=0
for _ in range(n):
l,r=map(int,input().split())
L.append([l,r])
if r==0:
c+=1
else:
L2.append(r)
for i in range(n):
if n-i not in L2:
lst.append(n-i)
p=0
for i in range(n):
if L[i][1]==0 and lst[p]!=L[i][0] and... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,480,494,951 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 0 | n=int(input())
s=0
L=input().split()
M=L
while len(L)>0:
for i in range(0,len(L)):
s=s+int(L[i])
zuixiao=min(L)
s=s+int(zuixiao)
for i in range(0,len(L)):
if int(L[i])==int(zuixiao):
del(L[i])
break
else:
pass
print(s-int(zuixiao... | Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all... | ```python
n=int(input())
s=0
L=input().split()
M=L
while len(L)>0:
for i in range(0,len(L)):
s=s+int(L[i])
zuixiao=min(L)
s=s+int(zuixiao)
for i in range(0,len(L)):
if int(L[i])==int(zuixiao):
del(L[i])
break
else:
pass
print(s-i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
810 | B | Summer sell-off | PROGRAMMING | 1,300 | [
"greedy",
"sortings"
] | null | null | Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an assistant.
Shop, where Noora is working, has a plan on the following *n* days. For each day sales manag... | The first line contains two integers *n* and *f* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*f*<=≤<=*n*) denoting the number of days in shop's plan and the number of days that Noora has to choose for sell-out.
Each line of the following *n* subsequent lines contains two integers *k**i*,<=*l**i* (0<=≤<=*k**i*,<=*l**i*<=≤<=109) denotin... | Print a single integer denoting the maximal number of products that shop can sell. | [
"4 2\n2 1\n3 5\n2 3\n1 5\n",
"4 1\n0 2\n0 3\n3 5\n0 6\n"
] | [
"10",
"5"
] | In the first example we can choose days with numbers 2 and 4 for sell-out. In this case new numbers of products for sale would be equal to [2, 6, 2, 2] respectively. So on the first day shop will sell 1 product, on the second — 5, on the third — 2, on the fourth — 2. In total 1 + 5 + 2 + 2 = 10 product units.
In the s... | 1,000 | [
{
"input": "4 2\n2 1\n3 5\n2 3\n1 5",
"output": "10"
},
{
"input": "4 1\n0 2\n0 3\n3 5\n0 6",
"output": "5"
},
{
"input": "1 1\n5 8",
"output": "8"
},
{
"input": "2 1\n8 12\n6 11",
"output": "19"
},
{
"input": "2 1\n6 7\n5 7",
"output": "13"
},
{
"inpu... | 1,495,777,664 | 2,864 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 11,264,000 | [n, f] = map(int, input().split())
seq, maxl = [], []
for _ in range(n):
[k, l] = [int(x) for x in input().split()]
if 2 * k >= l:
maxl.append(l)
else:
maxl.append(2 * k)
seq.append([k, l])
maxf = sorted(maxl)
maxf = maxf[-f:]
m = 0
for i in range(n):
[k, l] = seq[i]
if 2 * k >= ... | Title: Summer sell-off
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an ass... | ```python
[n, f] = map(int, input().split())
seq, maxl = [], []
for _ in range(n):
[k, l] = [int(x) for x in input().split()]
if 2 * k >= l:
maxl.append(l)
else:
maxl.append(2 * k)
seq.append([k, l])
maxf = sorted(maxl)
maxf = maxf[-f:]
m = 0
for i in range(n):
[k, l] = seq[i]
if... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
454 | A | Little Pony and Crystal Mine | PROGRAMMING | 800 | [
"implementation"
] | null | null | Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You need to draw a crystal of size *n*. The diamond cells of the matrix should be represented by character "D". All ot... | The only line contains an integer *n* (3<=≤<=*n*<=≤<=101; *n* is odd). | Output a crystal of size *n*. | [
"3\n",
"5\n",
"7\n"
] | [
"*D*\nDDD\n*D*\n",
"**D**\n*DDD*\nDDDDD\n*DDD*\n**D**\n",
"***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***\n"
] | none | 500 | [
{
"input": "3",
"output": "*D*\nDDD\n*D*"
},
{
"input": "5",
"output": "**D**\n*DDD*\nDDDDD\n*DDD*\n**D**"
},
{
"input": "7",
"output": "***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***"
},
{
"input": "11",
"output": "*****D*****\n****DDD****\n***DDDDD***\n**... | 1,641,000,724 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 12 | 93 | 1,331,200 | n = int(input())
n1 = int(n / 2 + 1)
n2 = int(n / 2)
for i in range(n1):
s = '' # string initialization
total_diamonds = i * 2 + 1
diamond_begin_location = n1 - i - 1
diamond_end_location = diamond_begin_location + total_diamonds
for j in range(n):
if (j >= diamond_begin_location an... | Title: Little Pony and Crystal Mine
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You ... | ```python
n = int(input())
n1 = int(n / 2 + 1)
n2 = int(n / 2)
for i in range(n1):
s = '' # string initialization
total_diamonds = i * 2 + 1
diamond_begin_location = n1 - i - 1
diamond_end_location = diamond_begin_location + total_diamonds
for j in range(n):
if (j >= diamond_begin_l... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
313 | B | Ilya and Queries | PROGRAMMING | 1,100 | [
"dp",
"implementation"
] | null | null | Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting only of characters "." and "#" and *m* queries. Each query is described by a pair of integers *l**i*,<... | The first line contains string *s* of length *n* (2<=≤<=*n*<=≤<=105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. Each of the next *m* lines contains the description of the corresponding query. The *i*-t... | Print *m* integers — the answers to the queries in the order in which they are given in the input. | [
"......\n4\n3 4\n2 3\n1 6\n2 6\n",
"#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4\n"
] | [
"1\n1\n5\n4\n",
"1\n1\n2\n2\n0\n"
] | none | 1,000 | [
{
"input": "......\n4\n3 4\n2 3\n1 6\n2 6",
"output": "1\n1\n5\n4"
},
{
"input": "#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4",
"output": "1\n1\n2\n2\n0"
},
{
"input": ".#...#..\n6\n1 5\n2 3\n6 7\n2 4\n2 5\n1 3",
"output": "2\n0\n0\n1\n2\n0"
},
{
"input": "#.#.#..\n5\n3 4\n4 5\n5 7\n5... | 1,699,364,788 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 102,400 | s=input()
m=int(input())
for _ in range(m):
l,r=map(int,input().split())
t=0
for i in range(l-1,r-1):
if s[i]==s[i+1]:
t+=1
print(t) | Title: Ilya and Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting ... | ```python
s=input()
m=int(input())
for _ in range(m):
l,r=map(int,input().split())
t=0
for i in range(l-1,r-1):
if s[i]==s[i+1]:
t+=1
print(t)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
510 | A | Fox And Snake | PROGRAMMING | 800 | [
"implementation"
] | null | null | Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*-th cell of *r*-th row as (*r*,<=*c*). The tail of the snake is located at (1,<=1), then it's body ... | The only line contains two integers: *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=50).
*n* is an odd number. | Output *n* lines. Each line should contain a string consisting of *m* characters. Do not output spaces. | [
"3 3\n",
"3 4\n",
"5 3\n",
"9 9\n"
] | [
"###\n..#\n###\n",
"####\n...#\n####\n",
"###\n..#\n###\n#..\n###\n",
"#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#########\n"
] | none | 500 | [
{
"input": "3 3",
"output": "###\n..#\n###"
},
{
"input": "3 4",
"output": "####\n...#\n####"
},
{
"input": "5 3",
"output": "###\n..#\n###\n#..\n###"
},
{
"input": "9 9",
"output": "#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#... | 1,690,979,413 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 46 | 0 | n, m = [int(i) for i in input().split()]
paint = []
counter = 0
for i in range(n):
if i%2 == 0:
paint.append('#'*m)
elif counter%2 == 0:
paint.append('.'*(m-1) + '#')
counter += 1
else:
paint.append('#' + '.'*(m-1))
counter += 1
print('\n'.join(paint)) | Title: Fox And Snake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*... | ```python
n, m = [int(i) for i in input().split()]
paint = []
counter = 0
for i in range(n):
if i%2 == 0:
paint.append('#'*m)
elif counter%2 == 0:
paint.append('.'*(m-1) + '#')
counter += 1
else:
paint.append('#' + '.'*(m-1))
counter += 1
print('\n'.join(p... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,697,544,566 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 92 | 0 | def lucky_number(x):
lst=list(x)
lst_temp=[]
flag=0
while flag<=len(lst)-1:
if lst[flag]!="4" and lst[flag]!="7":
lst_temp.append(lst[flag])
flag+=1
else:
flag+=1
if len(lst_temp)!=0:
return False
else:
return True
... | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
def lucky_number(x):
lst=list(x)
lst_temp=[]
flag=0
while flag<=len(lst)-1:
if lst[flag]!="4" and lst[flag]!="7":
lst_temp.append(lst[flag])
flag+=1
else:
flag+=1
if len(lst_temp)!=0:
return False
else:
re... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
253 | B | Physics Practical | PROGRAMMING | 1,400 | [
"binary search",
"dp",
"sortings",
"two pointers"
] | null | null | One day Vasya was on a physics practical, performing the task on measuring the capacitance. He followed the teacher's advice and did as much as *n* measurements, and recorded the results in the notebook. After that he was about to show the results to the teacher, but he remembered that at the last lesson, the teacher h... | The first line contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of measurements Vasya made. The second line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=5000) — the results of the measurements. The numbers on the second line are separated by single spaces. | Print a single integer — the minimum number of results Vasya will have to remove. | [
"6\n4 5 3 8 3 7\n",
"4\n4 3 2 4\n"
] | [
"2\n",
"0\n"
] | In the first sample you can remove the fourth and the sixth measurement results (values 8 and 7). Then the maximum of the remaining values will be 5, and the minimum one will be 3. Or else, you can remove the third and fifth results (both equal 3). After that the largest remaining result will be 8, and the smallest one... | 1,000 | [
{
"input": "6\n4 5 3 8 3 7",
"output": "2"
},
{
"input": "4\n4 3 2 4",
"output": "0"
},
{
"input": "6\n5 6 4 9 4 8",
"output": "1"
},
{
"input": "4\n5 4 1 5",
"output": "1"
},
{
"input": "2\n3 2",
"output": "0"
},
{
"input": "10\n39 9 18 13 6 16 47 15 ... | 1,678,352,328 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
using namespace std;
int main()
{
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
long long i,j,t,m,ans;
while(cin>>t)
{
long long arr[100000];
for(i=1;i<=t;i++)
{
cin>>arr[i];
}
sort(arr,arr+t+1);
... | Title: Physics Practical
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya was on a physics practical, performing the task on measuring the capacitance. He followed the teacher's advice and did as much as *n* measurements, and recorded the results in the notebook. After that he... | ```python
#include<bits/stdc++.h>
using namespace std;
int main()
{
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
long long i,j,t,m,ans;
while(cin>>t)
{
long long arr[100000];
for(i=1;i<=t;i++)
{
cin>>arr[i];
}
sort(arr,arr+t+1)... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
920 | E | Connected Components? | PROGRAMMING | 2,100 | [
"data structures",
"dfs and similar",
"dsu",
"graphs"
] | null | null | You are given an undirected graph consisting of *n* vertices and edges. Instead of giving you the edges that exist in the graph, we give you *m* unordered pairs (*x*,<=*y*) such that there is no edge between *x* and *y*, and if some pair of vertices is not listed in the input, then there is an edge between these verti... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=200000, ).
Then *m* lines follow, each containing a pair of integers *x* and *y* (1<=≤<=*x*,<=*y*<=≤<=*n*, *x*<=≠<=*y*) denoting that there is no edge between *x* and *y*. Each pair is listed at most once; (*x*,<=*y*) and (*y*,<=*x*) are considered the sa... | Firstly print *k* — the number of connected components in this graph.
Then print *k* integers — the sizes of components. You should output these integers in non-descending order. | [
"5 5\n1 2\n3 4\n3 2\n4 2\n2 5\n"
] | [
"2\n1 4 "
] | none | 0 | [
{
"input": "5 5\n1 2\n3 4\n3 2\n4 2\n2 5",
"output": "2\n1 4 "
},
{
"input": "8 15\n2 1\n4 5\n2 4\n3 4\n2 5\n3 5\n2 6\n3 6\n5 6\n4 6\n2 7\n3 8\n2 8\n3 7\n6 7",
"output": "1\n8 "
},
{
"input": "12 58\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 10\n1 11\n1 12\n2 3\n2 4\n2 5\n2 6\n2 7\n2 8\n2 9\n... | 1,678,763,508 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 84 | 358 | 35,225,600 | import sys
import math
import string
def solve(s, l, a):
c = 0
v = l[0]
l.pop(0)
rem = list(s)
for i in rem:
if((min(i,v), max(i,v)) not in a):
c += 1
l.append(i)
s.remove(i)
for i in l:
c += solve(s, [i], a)
return c
if __name__ == "__m... | Title: Connected Components?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an undirected graph consisting of *n* vertices and edges. Instead of giving you the edges that exist in the graph, we give you *m* unordered pairs (*x*,<=*y*) such that there is no edge between *x* ... | ```python
import sys
import math
import string
def solve(s, l, a):
c = 0
v = l[0]
l.pop(0)
rem = list(s)
for i in rem:
if((min(i,v), max(i,v)) not in a):
c += 1
l.append(i)
s.remove(i)
for i in l:
c += solve(s, [i], a)
return c
if __name... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,668,697,589 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | r,c=[int(i) for i in input().split()]
rows,columns=[],['' for i in range(c)]
er, ec = 0,0
for i in range(r):
x=input().lower()
rows.append(x)
if 's' not in x:
er += 1
for i in range(c):
for row in rows:
columns[i] += row[i]
if i == c-1 and 's' not in columns[i]:
e... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
r,c=[int(i) for i in input().split()]
rows,columns=[],['' for i in range(c)]
er, ec = 0,0
for i in range(r):
x=input().lower()
rows.append(x)
if 's' not in x:
er += 1
for i in range(c):
for row in rows:
columns[i] += row[i]
if i == c-1 and 's' not in columns[i]:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
743 | B | Chloe and the sequence | PROGRAMMING | 1,200 | [
"binary search",
"bitmasks",
"constructive algorithms",
"implementation"
] | null | null | Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following algorithm of generating a sequence of integers. Initially we have a sequence consisting of a single element eq... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=2*n*<=-<=1). | Print single integer — the integer at the *k*-th position in the obtained sequence. | [
"3 2\n",
"4 8\n"
] | [
"2",
"4"
] | In the first sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1]. The number on the second position is 2.
In the second sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1]. The number on the eighth position is 4. | 1,000 | [
{
"input": "3 2",
"output": "2"
},
{
"input": "4 8",
"output": "4"
},
{
"input": "5 27",
"output": "1"
},
{
"input": "7 44",
"output": "3"
},
{
"input": "15 18432",
"output": "12"
},
{
"input": "20 259676",
"output": "3"
},
{
"input": "30 6... | 1,687,028,153 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 46 | 0 | def find_kth(n, k):
if n == 1:
return 1
mid = (2**(n - 1)) - 1 # calculate the mid position
if k == mid:
return n
elif k < mid:
return find_kth(n - 1, k)
else:
return find_kth(n - 1, k - mid - 1)
n, k = map(int,input().strip().split())
print(find_kth(n, k... | Title: Chloe and the sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following a... | ```python
def find_kth(n, k):
if n == 1:
return 1
mid = (2**(n - 1)) - 1 # calculate the mid position
if k == mid:
return n
elif k < mid:
return find_kth(n - 1, k)
else:
return find_kth(n - 1, k - mid - 1)
n, k = map(int,input().strip().split())
print(fin... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
84 | C | Biathlon | PROGRAMMING | 1,700 | [
"binary search",
"implementation"
] | C. Biathlon | 1 | 256 | Perhaps many have heard that the World Biathlon Championship has finished. Although our hero Valera was not present at this spectacular event himself and only watched it on TV, it excited him so much that he decided to enroll in a biathlon section.
Of course, biathlon as any sport, proved very difficult in practice. I... | The first line of the input file contains the integer *n* (1<=≤<=*n*<=≤<=104), which is the number of targets. The next *n* lines contain descriptions of the targets. Each target is a circle whose center is located on the *Ox* axis. Each circle is given by its coordinate of the center *x* (<=-<=2·104<=≤<=*x*<=≤<=2·104)... | Print on the first line a single number, the number of targets hit by Valera. Print on the second line for each of the targets the number of its first hit or "-1" (without quotes) if this number does not exist. Separate numbers with spaces. | [
"3\n2 1\n5 2\n10 1\n5\n0 1\n1 3\n3 0\n4 0\n4 0\n",
"3\n3 2\n7 1\n11 2\n4\n2 1\n6 0\n6 4\n11 2\n"
] | [
"2\n3 3 -1 \n",
"3\n1 2 4 \n"
] | none | 1,500 | [
{
"input": "3\n2 1\n5 2\n10 1\n5\n0 1\n1 3\n3 0\n4 0\n4 0",
"output": "2\n3 3 -1 "
},
{
"input": "3\n3 2\n7 1\n11 2\n4\n2 1\n6 0\n6 4\n11 2",
"output": "3\n1 2 4 "
},
{
"input": "2\n0 5\n10 5\n2\n7 2\n6 1",
"output": "1\n-1 1 "
},
{
"input": "3\n-3 3\n-10 2\n10 2\n4\n10 2\n2 ... | 1,603,292,438 | 1,838 | PyPy 3 | RUNTIME_ERROR | TESTS | 3 | 186 | 2,457,600 | import sys
from array import array # noqa: F401
from math import hypot
def input():
return sys.stdin.buffer.readline().decode('utf-8')
n = int(input())
circle = sorted((x - r, x, r, i) for i, (x, r) in enumerate((map(int, input().split()) for _ in range(n))))
m = int(input())
shoot = sorted(tuple(m... | Title: Biathlon
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Perhaps many have heard that the World Biathlon Championship has finished. Although our hero Valera was not present at this spectacular event himself and only watched it on TV, it excited him so much that he decided to enroll in a... | ```python
import sys
from array import array # noqa: F401
from math import hypot
def input():
return sys.stdin.buffer.readline().decode('utf-8')
n = int(input())
circle = sorted((x - r, x, r, i) for i, (x, r) in enumerate((map(int, input().split()) for _ in range(n))))
m = int(input())
shoot = sort... | -1 | MatrixStudio/Codeforces-Python-Submissions |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,668,272,698 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 17 | 92 | 0 | n , m = map(int,input().split())
a1 = []
b1= []
for i in range(m):
a,b = map(int,input().split())
a1.append(a)
b1.append(b)
maximum = 0
ptr = 0
ans =0
require = n
for j in range(len(a1)) :
for i in range(len(a1)):
if maximum<b1[i]:
maximum = b1[i]
ptr = i
... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
n , m = map(int,input().split())
a1 = []
b1= []
for i in range(m):
a,b = map(int,input().split())
a1.append(a)
b1.append(b)
maximum = 0
ptr = 0
ans =0
require = n
for j in range(len(a1)) :
for i in range(len(a1)):
if maximum<b1[i]:
maximum = b1[i]
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
946 | B | Weird Subtraction Process | PROGRAMMING | 1,100 | [
"math",
"number theory"
] | null | null | You have two variables *a* and *b*. Consider the following sequence of actions performed with these variables:
1. If *a*<==<=0 or *b*<==<=0, end the process. Otherwise, go to step 2;1. If *a*<=≥<=2·*b*, then set the value of *a* to *a*<=-<=2·*b*, and repeat step 1. Otherwise, go to step 3;1. If *b*<=≥<=2·*a*, then s... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1018). *n* is the initial value of variable *a*, and *m* is the initial value of variable *b*. | Print two integers — the values of *a* and *b* after the end of the process. | [
"12 5\n",
"31 12\n"
] | [
"0 1\n",
"7 12\n"
] | Explanations to the samples:
1. *a* = 12, *b* = 5 <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> *a* = 2, *b* = 5 <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0... | 0 | [
{
"input": "12 5",
"output": "0 1"
},
{
"input": "31 12",
"output": "7 12"
},
{
"input": "1000000000000000000 7",
"output": "8 7"
},
{
"input": "31960284556200 8515664064180",
"output": "14928956427840 8515664064180"
},
{
"input": "1000000000000000000 100000000000... | 1,554,913,232 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 124 | 0 | x, y = map(int, input().split())
ans = []
k = 0
while True:
if x >= 2 * y:
x %= 2 * y
else:
y %= 2 * x
if x == 0 or y == 0:
break
if ans == [x, y]:
k += 1
else:
ans = [x, y]
k = 0
if k == 5:
break
print(x, y) | Title: Weird Subtraction Process
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have two variables *a* and *b*. Consider the following sequence of actions performed with these variables:
1. If *a*<==<=0 or *b*<==<=0, end the process. Otherwise, go to step 2;1. If *a*<=≥<=2·*b*, then... | ```python
x, y = map(int, input().split())
ans = []
k = 0
while True:
if x >= 2 * y:
x %= 2 * y
else:
y %= 2 * x
if x == 0 or y == 0:
break
if ans == [x, y]:
k += 1
else:
ans = [x, y]
k = 0
if k == 5:
break
print(x, y)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,556,463,196 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 109 | 0 | #imgur.com/Pkt7iIf.png
#n, m = map(int, input().split())
#n = int(input())
#d = list(map(int, input().split()))
import math
n = int(input())
print(math.ceil(n/4)-1) if n%2 == 0 else print (0)
| Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
#imgur.com/Pkt7iIf.png
#n, m = map(int, input().split())
#n = int(input())
#d = list(map(int, input().split()))
import math
n = int(input())
print(math.ceil(n/4)-1) if n%2 == 0 else print (0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,629,206,848 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 6,656,000 | l=input("")
o=0
while (o<l):
o=input("")
s=int(l)*int(o)
print(s//2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
l=input("")
o=0
while (o<l):
o=input("")
s=int(l)*int(o)
print(s//2)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
386 | A | Second-Price Auction | PROGRAMMING | 800 | [
"implementation"
] | null | null | In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is, each bidder secretly informs the organizer of the auction price he is willing to pay. After that, the au... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=1000) — number of bidders. The second line contains *n* distinct integer numbers *p*1,<=*p*2,<=... *p**n*, separated by single spaces (1<=≤<=*p**i*<=≤<=10000), where *p**i* stands for the price offered by the *i*-th bidder. | The single output line should contain two integers: index of the winner and the price he will pay. Indices are 1-based. | [
"2\n5 7\n",
"3\n10 2 8\n",
"6\n3 8 2 9 4 14\n"
] | [
"2 5\n",
"1 8\n",
"6 9\n"
] | none | 500 | [
{
"input": "2\n5 7",
"output": "2 5"
},
{
"input": "3\n10 2 8",
"output": "1 8"
},
{
"input": "6\n3 8 2 9 4 14",
"output": "6 9"
},
{
"input": "4\n4707 7586 4221 5842",
"output": "2 5842"
},
{
"input": "5\n3304 4227 4869 6937 6002",
"output": "4 6002"
},
{... | 1,592,300,970 | 2,147,483,647 | PyPy 3 | OK | TESTS | 42 | 155 | 1,228,800 | n=int(input())
lst=[int(i) for i in input().split()]
max1=max(lst)
d=lst.index(max1)+1
lst.remove(max1)
print(d,max(lst))
| Title: Second-Price Auction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is... | ```python
n=int(input())
lst=[int(i) for i in input().split()]
max1=max(lst)
d=lst.index(max1)+1
lst.remove(max1)
print(d,max(lst))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
7 | A | Kalevitch and Chess | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms"
] | A. Kalevitch and Chess | 2 | 64 | A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch decided to put an end to this tradition and to introduce a new attitude to chessboards.
As before, th... | The input file contains 8 lines, each of the lines contains 8 characters. The given matrix describes the client's requirements, W character stands for a white square, and B character — for a square painted black.
It is guaranteed that client's requirments can be fulfilled with a sequence of allowed strokes (vertical/c... | Output the only number — the minimum amount of rows and columns that Kalevitch has to paint on the white chessboard to meet the client's requirements. | [
"WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\n",
"WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\n"
] | [
"3\n",
"1\n"
] | none | 0 | [
{
"input": "WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW",
"output": "3"
},
{
"input": "WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW",
"output": "1"
},
{
"input": "WWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWW... | 1,676,097,805 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 154 | 0 | # LUOGU_RID: 101910065
a = [input() for _ in range(8)]
x = a.count('BBBBBBBB')
y = list(zip(*a)).count(tuple('BBBBBBBB'))
print(x == y == 8 and 8 or x + y) | Title: Kalevitch and Chess
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch de... | ```python
# LUOGU_RID: 101910065
a = [input() for _ in range(8)]
x = a.count('BBBBBBBB')
y = list(zip(*a)).count(tuple('BBBBBBBB'))
print(x == y == 8 and 8 or x + y)
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
437 | A | The Child and Homework | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Once upon a time a child got a test consisting of multiple-choice questions as homework. A multiple-choice question consists of four choices: A, B, C and D. Each choice has a description, and the child should find out the only one that is correct.
Fortunately the child knows how to solve such complicated test. The chi... | The first line starts with "A." (without quotes), then followed the description of choice A. The next three lines contains the descriptions of the other choices in the same format. They are given in order: B, C, D. Please note, that the description goes after prefix "X.", so the prefix mustn't be counted in description... | Print a single line with the child's choice: "A", "B", "C" or "D" (without quotes). | [
"A.VFleaKing_is_the_author_of_this_problem\nB.Picks_is_the_author_of_this_problem\nC.Picking_is_the_author_of_this_problem\nD.Ftiasch_is_cute\n",
"A.ab\nB.abcde\nC.ab\nD.abc\n",
"A.c\nB.cc\nC.c\nD.c\n"
] | [
"D\n",
"C\n",
"B\n"
] | In the first sample, the first choice has length 39, the second one has length 35, the third one has length 37, and the last one has length 15. The choice D (length 15) is twice shorter than all other choices', so it is great choice. There is no other great choices so the child will choose D.
In the second sample, no ... | 500 | [
{
"input": "A.VFleaKing_is_the_author_of_this_problem\nB.Picks_is_the_author_of_this_problem\nC.Picking_is_the_author_of_this_problem\nD.Ftiasch_is_cute",
"output": "D"
},
{
"input": "A.ab\nB.abcde\nC.ab\nD.abc",
"output": "C"
},
{
"input": "A.c\nB.cc\nC.c\nD.c",
"output": "B"
},
... | 1,567,013,545 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 124 | 0 | def func(l):
x=0
k=2
for i in range(4):
p = [int(not 2*l[i]<=l[j]) for j in range(4) if i!=j]
f = [int(2*l[j]<=l[i]) for j in range(4) if i!=j]
if p==f:
x+=1
k=i
if x==1:
return chr(ord('A')+k)
return 'C'
a,b,c,d = len(input())-2,len(input())-2,len(input())-2,len(input())-2
x = func([a,b,c,d])
print... | Title: The Child and Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once upon a time a child got a test consisting of multiple-choice questions as homework. A multiple-choice question consists of four choices: A, B, C and D. Each choice has a description, and the child should fin... | ```python
def func(l):
x=0
k=2
for i in range(4):
p = [int(not 2*l[i]<=l[j]) for j in range(4) if i!=j]
f = [int(2*l[j]<=l[i]) for j in range(4) if i!=j]
if p==f:
x+=1
k=i
if x==1:
return chr(ord('A')+k)
return 'C'
a,b,c,d = len(input())-2,len(input())-2,len(input())-2,len(input())-2
x = func([a,b,c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,678,282,248 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | d = []
c = []
e = 0
кол_строк = int(input())
for i in range(кол_строк):
a, b = list(input().split())
d.append(a)
c.append(b)
for i in range(кол_строк):
for j in range(кол_строк):
if d[i] == c[j]:
e+=1
print(e)
| Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
d = []
c = []
e = 0
кол_строк = int(input())
for i in range(кол_строк):
a, b = list(input().split())
d.append(a)
c.append(b)
for i in range(кол_строк):
for j in range(кол_строк):
if d[i] == c[j]:
e+=1
print(e)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
602 | B | Approximating a Constant Range | PROGRAMMING | 1,400 | [
"dp",
"implementation",
"two pointers"
] | null | null | When Xellos was doing a practice course in university, he once had to measure the intensity of an effect that slowly approached equilibrium. A good way to determine the equilibrium intensity would be choosing a sufficiently large number of consecutive data points that seems as constant as possible and taking their aver... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of data points.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100<=000). | Print a single number — the maximum length of an almost constant range of the given sequence. | [
"5\n1 2 3 3 2\n",
"11\n5 4 5 5 6 7 8 8 8 7 6\n"
] | [
"4\n",
"5\n"
] | In the first sample, the longest almost constant range is [2, 5]; its length (the number of data points in it) is 4.
In the second sample, there are three almost constant ranges of length 4: [1, 4], [6, 9] and [7, 10]; the only almost constant range of the maximum length 5 is [6, 10]. | 1,000 | [
{
"input": "5\n1 2 3 3 2",
"output": "4"
},
{
"input": "11\n5 4 5 5 6 7 8 8 8 7 6",
"output": "5"
},
{
"input": "2\n3 2",
"output": "2"
},
{
"input": "4\n1001 1000 1000 1001",
"output": "4"
},
{
"input": "4\n1 1 2 3",
"output": "3"
},
{
"input": "3\n1 ... | 1,692,965,899 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 124 | 17,817,600 | n = int(input())
dataPoints = [[0 , 0 , 0]]
l = -1
for e in input().split():
if e == l:
dataPoints[-1][1] += 1
else:
lastPoint = dataPoints[-1]
dataPoints.append([int(e) , 1 , lastPoint[1] + lastPoint[2]])
l = e
maxLength = 0
lRng = 0
uRng = 0
cMin = dataPoints[1... | Title: Approximating a Constant Range
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Xellos was doing a practice course in university, he once had to measure the intensity of an effect that slowly approached equilibrium. A good way to determine the equilibrium intensity would be choo... | ```python
n = int(input())
dataPoints = [[0 , 0 , 0]]
l = -1
for e in input().split():
if e == l:
dataPoints[-1][1] += 1
else:
lastPoint = dataPoints[-1]
dataPoints.append([int(e) , 1 , lastPoint[1] + lastPoint[2]])
l = e
maxLength = 0
lRng = 0
uRng = 0
cMin = da... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
903 | B | The Modcrab | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Vova is again playing some computer game, now an RPG. In the game Vova's character received a quest: to slay the fearsome monster called Modcrab.
After two hours of playing the game Vova has tracked the monster and analyzed its tactics. The Modcrab has *h*2 health points and an attack power of *a*2. Knowing that, Vova... | The first line contains three integers *h*1, *a*1, *c*1 (1<=≤<=*h*1,<=*a*1<=≤<=100, 2<=≤<=*c*1<=≤<=100) — Vova's health, Vova's attack power and the healing power of a potion.
The second line contains two integers *h*2, *a*2 (1<=≤<=*h*2<=≤<=100, 1<=≤<=*a*2<=<<=*c*1) — the Modcrab's health and his attack power. | In the first line print one integer *n* denoting the minimum number of phases required to win the battle.
Then print *n* lines. *i*-th line must be equal to HEAL if Vova drinks a potion in *i*-th phase, or STRIKE if he attacks the Modcrab.
The strategy must be valid: Vova's character must not be defeated before slayi... | [
"10 6 100\n17 5\n",
"11 6 100\n12 5\n"
] | [
"4\nSTRIKE\nHEAL\nSTRIKE\nSTRIKE\n",
"2\nSTRIKE\nSTRIKE\n"
] | In the first example Vova's character must heal before or after his first attack. Otherwise his health will drop to zero in 2 phases while he needs 3 strikes to win.
In the second example no healing needed, two strikes are enough to get monster to zero health and win with 6 health left. | 0 | [
{
"input": "10 6 100\n17 5",
"output": "4\nSTRIKE\nHEAL\nSTRIKE\nSTRIKE"
},
{
"input": "11 6 100\n12 5",
"output": "2\nSTRIKE\nSTRIKE"
},
{
"input": "25 27 91\n10 87",
"output": "1\nSTRIKE"
},
{
"input": "79 4 68\n9 65",
"output": "21\nSTRIKE\nHEAL\nHEAL\nHEAL\nHEAL\nHEAL... | 1,686,925,259 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def battle_strategy(h1, a1, c1, h2, a2):
# Calculate the number of strikes required
strikes = h2 // a1
if h2 % a1 != 0:
strikes += 1
# Determine the strategy
strategy = []
if h1 > a2:
# Defeat the Modcrab without healing
strategy.extend(['STRIKE'] * strikes)
... | Title: The Modcrab
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vova is again playing some computer game, now an RPG. In the game Vova's character received a quest: to slay the fearsome monster called Modcrab.
After two hours of playing the game Vova has tracked the monster and analyze... | ```python
def battle_strategy(h1, a1, c1, h2, a2):
# Calculate the number of strikes required
strikes = h2 // a1
if h2 % a1 != 0:
strikes += 1
# Determine the strategy
strategy = []
if h1 > a2:
# Defeat the Modcrab without healing
strategy.extend(['STRIKE'] * s... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
1,005 | B | Delete from the Left | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't choose a string if it is empty.
For example:
- by applying a move to the string "where", the result is ... | The first line of the input contains $s$. In the second line of the input contains $t$. Both strings consist only of lowercase Latin letters. The number of letters in each string is between 1 and $2\cdot10^5$, inclusive. | Output the fewest number of moves required. It is possible that, in the end, both strings will be equal to the empty string, and so, are equal to each other. In this case, the answer is obviously the sum of the lengths of the given strings. | [
"test\nwest\n",
"codeforces\nyes\n",
"test\nyes\n",
"b\nab\n"
] | [
"2\n",
"9\n",
"7\n",
"1\n"
] | In the first example, you should apply the move once to the first string and apply the move once to the second string. As a result, both strings will be equal to "est".
In the second example, the move should be applied to the string "codeforces" $8$ times. As a result, the string becomes "codeforces" $\to$ "es". The m... | 0 | [
{
"input": "test\nwest",
"output": "2"
},
{
"input": "codeforces\nyes",
"output": "9"
},
{
"input": "test\nyes",
"output": "7"
},
{
"input": "b\nab",
"output": "1"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "abacabadabacaba\nabacabadacaba",
... | 1,693,383,668 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 819,200 | a = input()
b = input()
x = len(a)
y = len(b)
n = 0
flg = 0
if x>y:
for i in range(y):
if a.endswith(b[i:y]):
flg = 1
break
if flg == 1:
print(x+y-(2*(y-i)))
else:
print(x+y)
else:
for i in range(x):
if b.endswith(a[i:x]):
... | Title: Delete from the Left
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't ... | ```python
a = input()
b = input()
x = len(a)
y = len(b)
n = 0
flg = 0
if x>y:
for i in range(y):
if a.endswith(b[i:y]):
flg = 1
break
if flg == 1:
print(x+y-(2*(y-i)))
else:
print(x+y)
else:
for i in range(x):
if b.endswith(a[i:x])... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,699,101,464 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 62 | 0 | a = input()
s = 0
ch = "".join(a[1:len(a)-1].split(", "))
for i in range(len(ch)):
if ch[i] not in ch[:i]:
s += 1
print(s)
| Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
a = input()
s = 0
ch = "".join(a[1:len(a)-1].split(", "))
for i in range(len(ch)):
if ch[i] not in ch[:i]:
s += 1
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,681,849,413 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | N = int(input())
A = list(map(int,input().split()))
x = 0
a, b = map(int,input().split())
for i in range(a-1, b-1):
x+ = A[i]
print(x)
| Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
N = int(input())
A = list(map(int,input().split()))
x = 0
a, b = map(int,input().split())
for i in range(a-1, b-1):
x+ = A[i]
print(x)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,699,267,540 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 46 | 0 | a=[int(i) for i in input().split()]
print(min(abs(a[0]-a[1])+abs(a[0]-a[2]),abs(a[1]-a[0])+abs(a[1]-a[2]),abs(a[2]-a[0])+abs(a[2]-a[1]))) | Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
a=[int(i) for i in input().split()]
print(min(abs(a[0]-a[1])+abs(a[0]-a[2]),abs(a[1]-a[0])+abs(a[1]-a[2]),abs(a[2]-a[0])+abs(a[2]-a[1])))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
451 | A | Game With Sticks | PROGRAMMING | 900 | [
"implementation"
] | null | null | After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.
In the grid show... | The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). | Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game. | [
"2 2\n",
"2 3\n",
"3 3\n"
] | [
"Malvika\n",
"Malvika\n",
"Akshat\n"
] | Explanation of the first sample:
The grid has four intersection points, numbered from 1 to 4.
If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this.
Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remov... | 500 | [
{
"input": "2 2",
"output": "Malvika"
},
{
"input": "2 3",
"output": "Malvika"
},
{
"input": "3 3",
"output": "Akshat"
},
{
"input": "20 68",
"output": "Malvika"
},
{
"input": "1 1",
"output": "Akshat"
},
{
"input": "1 2",
"output": "Akshat"
},
... | 1,682,369,923 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | # Enter your code here. Read input from STDIN. Print output to STDOUT
import math
if __name__ == '__main__':
n, m = [int(x) for x in input().strip().split(" ")]
if n == 1 and m == 1:
print("Malvika")
print("Akshat" if ((n+m)//2)%2 == 1 else "Malvika") | Title: Game With Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid... | ```python
# Enter your code here. Read input from STDIN. Print output to STDOUT
import math
if __name__ == '__main__':
n, m = [int(x) for x in input().strip().split(" ")]
if n == 1 and m == 1:
print("Malvika")
print("Akshat" if ((n+m)//2)%2 == 1 else "Malvika")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,530,193,270 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 93 | 0 | piso = input()
pasos = 1
piso = str(int(piso) + 1)
while "8" not in piso :
piso = str(int(piso) + 1)
pasos +=1
print(pasos)
| Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
piso = input()
pasos = 1
piso = str(int(piso) + 1)
while "8" not in piso :
piso = str(int(piso) + 1)
pasos +=1
print(pasos)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
958 | F1 | Lightsabers (easy) | PROGRAMMING | 1,500 | [
"implementation"
] | null | null | There is unrest in the Galactic Senate. Several thousand solar systems have declared their intentions to leave the Republic. Master Heidi needs to select the Jedi Knights who will go on peacekeeping missions throughout the galaxy. It is well-known that the success of any peacekeeping mission depends on the colors of th... | The first line of the input contains *n* (1<=≤<=*n*<=≤<=100) and *m* (1<=≤<=*m*<=≤<=*n*). The second line contains *n* integers in the range {1,<=2,<=...,<=*m*} representing colors of the lightsabers of the subsequent Jedi Knights. The third line contains *m* integers *k*1,<=*k*2,<=...,<=*k**m* (with ) – the desired co... | Output YES if an interval with prescribed color counts exists, or output NO if there is none. | [
"5 2\n1 1 2 2 1\n1 2\n"
] | [
"YES\n"
] | none | 0 | [
{
"input": "5 2\n1 1 2 2 1\n1 2",
"output": "YES"
},
{
"input": "1 1\n1\n1",
"output": "YES"
},
{
"input": "2 1\n1 1\n1",
"output": "YES"
},
{
"input": "2 1\n1 1\n2",
"output": "YES"
},
{
"input": "2 2\n1 2\n1 1",
"output": "YES"
},
{
"input": "3 3\n1 ... | 1,588,690,222 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 109 | 307,200 | t = list(map(int, input().split(" ")))
n = t[0]
m = t[1]
k = list(map(int, input().split(" ")))
req = list(map(int, input().split(" ")))
state = "YES"
col = [0 for i in range(m)]
# Counts de amount of light sabers of each color
for i in range(0, n):
col[k[i]-1] += 1
col.sort()
req.sort()
for i in range(0, m):
... | Title: Lightsabers (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is unrest in the Galactic Senate. Several thousand solar systems have declared their intentions to leave the Republic. Master Heidi needs to select the Jedi Knights who will go on peacekeeping missions througho... | ```python
t = list(map(int, input().split(" ")))
n = t[0]
m = t[1]
k = list(map(int, input().split(" ")))
req = list(map(int, input().split(" ")))
state = "YES"
col = [0 for i in range(m)]
# Counts de amount of light sabers of each color
for i in range(0, n):
col[k[i]-1] += 1
col.sort()
req.sort()
for i in ran... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
397 | A | On Segment's Own Points | PROGRAMMING | 0 | [
"implementation"
] | null | null | Our old friend Alexey has finally entered the University of City N — the Berland capital. Alexey expected his father to get him a place to live in but his father said it was high time for Alexey to practice some financial independence. So, Alexey is living in a dorm.
The dorm has exactly one straight dryer — a 100 ce... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). The (*i*<=+<=1)-th line contains integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=100) — the endpoints of the corresponding segment for the *i*-th student. | On a single line print a single number *k*, equal to the sum of lengths of the parts of the dryer which are inside Alexey's segment and are outside all other segments. | [
"3\n0 5\n2 8\n1 6\n",
"3\n0 10\n1 5\n7 15\n"
] | [
"1\n",
"3\n"
] | Note that it's not important are clothes drying on the touching segments (e.g. (0, 1) and (1, 2)) considered to be touching or not because you need to find the length of segments.
In the first test sample Alexey may use the only segment (0, 1). In such case his clothes will not touch clothes on the segments (1, 6) and... | 500 | [
{
"input": "3\n0 5\n2 8\n1 6",
"output": "1"
},
{
"input": "3\n0 10\n1 5\n7 15",
"output": "3"
},
{
"input": "1\n0 100",
"output": "100"
},
{
"input": "2\n1 9\n1 9",
"output": "0"
},
{
"input": "2\n1 9\n5 10",
"output": "4"
},
{
"input": "2\n1 9\n3 5",... | 1,561,638,591 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | n = int(input())
sags = list()
i = 1
while i <= n:
a, b = input().split(' ')
sags.append(set(range(int(a), (int(b)+1))))
i += 1
mysag = sags[0]
tochk = list(sags[0])
# print(mysag)
# exit()
j = 1
while j < len(sags):
curSag = sags[j]
mysag = mysag-curSag
# print(mysag)
j += 1
# print(my... | Title: On Segment's Own Points
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our old friend Alexey has finally entered the University of City N — the Berland capital. Alexey expected his father to get him a place to live in but his father said it was high time for Alexey to practice some... | ```python
n = int(input())
sags = list()
i = 1
while i <= n:
a, b = input().split(' ')
sags.append(set(range(int(a), (int(b)+1))))
i += 1
mysag = sags[0]
tochk = list(sags[0])
# print(mysag)
# exit()
j = 1
while j < len(sags):
curSag = sags[j]
mysag = mysag-curSag
# print(mysag)
j += 1
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
448 | D | Multiplication Table | PROGRAMMING | 1,800 | [
"binary search",
"brute force"
] | null | null | Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multiplication table, where the element on the intersection of the *i*-th row and *j*-th column equals *i*·*j* ... | The single line contains integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=5·105; 1<=≤<=*k*<=≤<=*n*·*m*). | Print the *k*-th largest number in a *n*<=×<=*m* multiplication table. | [
"2 2 2\n",
"2 3 4\n",
"1 10 5\n"
] | [
"2\n",
"3\n",
"5\n"
] | A 2 × 3 multiplication table looks like this: | 2,000 | [
{
"input": "2 2 2",
"output": "2"
},
{
"input": "2 3 4",
"output": "3"
},
{
"input": "1 10 5",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "10 1 7",
"output": "7"
},
{
"input": "10 10 33",
"output": "14"
},
{
"input": "... | 1,645,467,245 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 1,740,800 | import sys
input = sys.stdin.readline
n, m, k = map(int, input().split())
m, n = min(m, n), max(m, n)
def countLessElements(x):
cnt = 0
for i in range(1, m+1):
cnt += min(n, (x-1)//i)
return cnt
l, r = 1, n*m + 1
while l < r:
mid = l + (r-l)//2
if countLessElements(mid) < k... | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multi... | ```python
import sys
input = sys.stdin.readline
n, m, k = map(int, input().split())
m, n = min(m, n), max(m, n)
def countLessElements(x):
cnt = 0
for i in range(1, m+1):
cnt += min(n, (x-1)//i)
return cnt
l, r = 1, n*m + 1
while l < r:
mid = l + (r-l)//2
if countLessElement... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
437 | B | The Child and Set | PROGRAMMING | 1,500 | [
"bitmasks",
"greedy",
"implementation",
"sortings"
] | null | null | At the children's day, the child came to Picks's house, and messed his house up. Picks was angry at him. A lot of important things were lost, in particular the favorite set of Picks.
Fortunately, Picks remembers something about his set *S*:
- its elements were distinct integers from 1 to *limit*; - the value of wa... | The first line contains two integers: *sum*,<=*limit* (1<=≤<=*sum*,<=*limit*<=≤<=105). | In the first line print an integer *n* (1<=≤<=*n*<=≤<=105), denoting the size of *S*. Then print the elements of set *S* in any order. If there are multiple answers, print any of them.
If it's impossible to find a suitable set, print -1. | [
"5 5\n",
"4 3\n",
"5 1\n"
] | [
"2\n4 5\n",
"3\n2 3 1\n",
"-1\n"
] | In sample test 1: *lowbit*(4) = 4, *lowbit*(5) = 1, 4 + 1 = 5.
In sample test 2: *lowbit*(1) = 1, *lowbit*(2) = 2, *lowbit*(3) = 1, 1 + 2 + 1 = 4. | 1,500 | [
{
"input": "5 5",
"output": "2\n4 5"
},
{
"input": "4 3",
"output": "3\n2 3 1"
},
{
"input": "5 1",
"output": "-1"
},
{
"input": "54321 12345",
"output": "7008\n8958 8925 11009 10808 8221 9771 11269 7017 6416 11723 10324 5654 6569 10454 9164 10754 6069 7913 12154 11111 73... | 1,647,496,723 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 124 | 5,734,400 |
def solve() :
ans=[]
for i in range(1,n+1):
x=i
c=0
while x>0 :
if x%2==1 :
ans.append((2**c,i))
break
else:
c+=1
x=x//2
ans.sort(reverse=True)
s2=s
ans2=[]
for i in range(n):
if ... | Title: The Child and Set
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
At the children's day, the child came to Picks's house, and messed his house up. Picks was angry at him. A lot of important things were lost, in particular the favorite set of Picks.
Fortunately, Picks remembers some... | ```python
def solve() :
ans=[]
for i in range(1,n+1):
x=i
c=0
while x>0 :
if x%2==1 :
ans.append((2**c,i))
break
else:
c+=1
x=x//2
ans.sort(reverse=True)
s2=s
ans2=[]
for i in range(n):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,691,333,439 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 9,420,800 | v = [input() for i in range(int(input()))]
print(1 + sum(a != b for a, b in zip(v, v[1:]))) | Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
v = [input() for i in range(int(input()))]
print(1 + sum(a != b for a, b in zip(v, v[1:])))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
992 | C | Nastya and a Wardrobe | PROGRAMMING | 1,600 | [
"math"
] | null | null | Nastya received a gift on New Year — a magic wardrobe. It is magic because in the end of each month the number of dresses in it doubles (i.e. the number of dresses becomes twice as large as it is in the beginning of the month).
Unfortunately, right after the doubling the wardrobe eats one of the dresses (if any) with ... | The only line contains two integers *x* and *k* (0<=≤<=*x*,<=*k*<=≤<=1018), where *x* is the initial number of dresses and *k*<=+<=1 is the number of months in a year in Byteland. | In the only line print a single integer — the expected number of dresses Nastya will own one year later modulo 109<=+<=7. | [
"2 0\n",
"2 1\n",
"3 2\n"
] | [
"4\n",
"7\n",
"21\n"
] | In the first example a year consists on only one month, so the wardrobe does not eat dresses at all.
In the second example after the first month there are 3 dresses with 50% probability and 4 dresses with 50% probability. Thus, in the end of the year there are 6 dresses with 50% probability and 8 dresses with 50% prob... | 1,500 | [
{
"input": "2 0",
"output": "4"
},
{
"input": "2 1",
"output": "7"
},
{
"input": "3 2",
"output": "21"
},
{
"input": "1 411",
"output": "485514976"
},
{
"input": "1 692",
"output": "860080936"
},
{
"input": "16 8",
"output": "7937"
},
{
"in... | 1,532,271,338 | 5,558 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | n,k = input().split(" ")
n = int(n)*2
k = int(k)
for i in range(k):
n = 2*n -1
print(n) | Title: Nastya and a Wardrobe
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya received a gift on New Year — a magic wardrobe. It is magic because in the end of each month the number of dresses in it doubles (i.e. the number of dresses becomes twice as large as it is in the beginning ... | ```python
n,k = input().split(" ")
n = int(n)*2
k = int(k)
for i in range(k):
n = 2*n -1
print(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,647,652,399 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 31 | 0 | a = int(input())
n = []
for i in range(a):
p = [1] * a
n.append(p)
for i in range(1, a):
for j in range(1, a):
n[i][j] = n[i-1][j]+n[i][j-1]
print(n[-1][-1]) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
a = int(input())
n = []
for i in range(a):
p = [1] * a
n.append(p)
for i in range(1, a):
for j in range(1, a):
n[i][j] = n[i-1][j]+n[i][j-1]
print(n[-1][-1])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,691,078,870 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | def hf(n):
f = []
for i in range(n):
if i % 2 == 0:
f.append("I hate")
else:
f.append("I love")
if i < n - 1:
f.append("that")
f.append("it")
return " ".join()
n = int(input())
print(hf(n))
| Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
def hf(n):
f = []
for i in range(n):
if i % 2 == 0:
f.append("I hate")
else:
f.append("I love")
if i < n - 1:
f.append("that")
f.append("it")
return " ".join()
n = int(input())
print(hf(n))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
248 | A | Cupboards | PROGRAMMING | 800 | [
"implementation"
] | null | null | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on *n* woode... | The first input line contains a single integer *n* — the number of cupboards in the kitchen (2<=≤<=*n*<=≤<=104). Then follow *n* lines, each containing two integers *l**i* and *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=1). Number *l**i* equals one, if the left door of the *i*-th cupboard is opened, otherwise number *l**i* equal... | In the only output line print a single integer *t* — the minimum number of seconds Karlsson needs to change the doors of all cupboards to the position he needs. | [
"5\n0 1\n1 0\n0 1\n1 1\n0 1\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "5\n0 1\n1 0\n0 1\n1 1\n0 1",
"output": "3"
},
{
"input": "2\n0 0\n0 0",
"output": "0"
},
{
"input": "3\n0 1\n1 1\n1 1",
"output": "1"
},
{
"input": "8\n0 1\n1 0\n0 1\n1 1\n0 1\n1 0\n0 1\n1 0",
"output": "7"
},
{
"input": "8\n1 0\n1 0\n1 0\n0 1\n0 1\n1 ... | 1,652,451,861 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | def gcd(a,b):
if a==0:
return b
else:
return gcd(b%a, a)
def lcm(a,b):
return (a*b)/gcd(a,b)
k = int(input())
l = int(input())
m = int(input())
n = int(input())
d = int(input())
print(int((d//k + d//l + d//m + d//n) - (d//lcm(k,l) + d//lcm(k,m) + d//lcm(k,n) + d//lcm(l,m) + d//lcm... | Title: Cupboards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any long... | ```python
def gcd(a,b):
if a==0:
return b
else:
return gcd(b%a, a)
def lcm(a,b):
return (a*b)/gcd(a,b)
k = int(input())
l = int(input())
m = int(input())
n = int(input())
d = int(input())
print(int((d//k + d//l + d//m + d//n) - (d//lcm(k,l) + d//lcm(k,m) + d//lcm(k,n) + d//lcm(l,m... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
844 | A | Diversity | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"strings"
] | null | null | Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too. | First line of input contains string *s*, consisting only of lowercase Latin letters (1<=≤<=|*s*|<=≤<=1000, |*s*| denotes the length of *s*).
Second line of input contains integer *k* (1<=≤<=*k*<=≤<=26). | Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible. | [
"yandex\n6\n",
"yahoo\n5\n",
"google\n7\n"
] | [
"0\n",
"1\n",
"impossible\n"
] | In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'*a*', '*h*', '*o*', '*y*'}. To get 5 different letters it is necessary to change one occurrence of '*o*' to some letter, which doesn't occur in the string, for... | 500 | [
{
"input": "yandex\n6",
"output": "0"
},
{
"input": "yahoo\n5",
"output": "1"
},
{
"input": "google\n7",
"output": "impossible"
},
{
"input": "a\n1",
"output": "0"
},
{
"input": "z\n2",
"output": "impossible"
},
{
"input": "fwgfrwgkuwghfiruhewgirueguhe... | 1,517,879,912 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 62 | 5,632,000 | s = input()
k = int(input())
if len(s) < k:
print("impossible")
else:
found = set(s)
diff = k - len(found)
if diff < 0:
print(0)
else:
print(k - len(found)) | Title: Diversity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it... | ```python
s = input()
k = int(input())
if len(s) < k:
print("impossible")
else:
found = set(s)
diff = k - len(found)
if diff < 0:
print(0)
else:
print(k - len(found))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
360 | A | Levko and Array Recovery | PROGRAMMING | 1,700 | [
"greedy",
"implementation"
] | null | null | Levko loves array *a*1,<=*a*2,<=... ,<=*a**n*, consisting of integers, very much. That is why Levko is playing with array *a*, performing all sorts of operations with it. Each operation Levko performs is of one of two types:
1. Increase all elements from *l**i* to *r**i* by *d**i*. In other words, perform assignments... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=5000) — the size of the array and the number of operations in Levko's records, correspondingly.
Next *m* lines describe the operations, the *i*-th line describes the *i*-th operation. The first integer in the *i*-th line is integer *t**i* (1<=≤<=*t*... | In the first line print "YES" (without the quotes), if the solution exists and "NO" (without the quotes) otherwise.
If the solution exists, then on the second line print *n* integers *a*1,<=*a*2,<=... ,<=*a**n* (|*a**i*|<=≤<=109) — the recovered array. | [
"4 5\n1 2 3 1\n2 1 2 8\n2 3 4 7\n1 1 3 3\n2 3 4 8\n",
"4 5\n1 2 3 1\n2 1 2 8\n2 3 4 7\n1 1 3 3\n2 3 4 13\n"
] | [
"YES\n4 7 4 7",
"NO\n"
] | none | 500 | [
{
"input": "4 5\n1 2 3 1\n2 1 2 8\n2 3 4 7\n1 1 3 3\n2 3 4 8",
"output": "YES\n8 7 4 7 "
},
{
"input": "4 5\n1 2 3 1\n2 1 2 8\n2 3 4 7\n1 1 3 3\n2 3 4 13",
"output": "NO"
},
{
"input": "97 29\n2 78 82 356152\n2 14 29 430177\n1 59 84 3680\n1 49 89 -2247\n1 92 96 3701\n2 54 89 377271\n1 62... | 1,689,595,092 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | print("_RANDOM_GUESS_1689595092.7812223")# 1689595092.7812436 | Title: Levko and Array Recovery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves array *a*1,<=*a*2,<=... ,<=*a**n*, consisting of integers, very much. That is why Levko is playing with array *a*, performing all sorts of operations with it. Each operation Levko performs is of one... | ```python
print("_RANDOM_GUESS_1689595092.7812223")# 1689595092.7812436
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,668,890,136 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a,b = list(map(int,input().split()))
m =[ ]
for i in range (a):
m.append(list(input()))
c=0
for i in range (a):
for j in range (b):
if "s" not in m [i] :
C+=1
m [i] [j ]= "0"
else:
break
im= [ ]
im+= [ 0] *b
for i in range (b) :
im [i... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
a,b = list(map(int,input().split()))
m =[ ]
for i in range (a):
m.append(list(input()))
c=0
for i in range (a):
for j in range (b):
if "s" not in m [i] :
C+=1
m [i] [j ]= "0"
else:
break
im= [ ]
im+= [ 0] *b
for i in range (b) :
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,675,146,888 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | n, m = list(map(int, input().split()))
z = [int(i) for i in input().split()]
z = sorted(z)
sm_mx = z[:n]
sm_mn = z[-1:-n - 1: -1]
sm_mx = (abs(sm_mx[0] - sm_mx[-1]))
sm_mn = (abs(sm_mn[0] - sm_mn[-1]))
print(min(sm_mx, sm_mn)) | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
n, m = list(map(int, input().split()))
z = [int(i) for i in input().split()]
z = sorted(z)
sm_mx = z[:n]
sm_mn = z[-1:-n - 1: -1]
sm_mx = (abs(sm_mx[0] - sm_mx[-1]))
sm_mn = (abs(sm_mn[0] - sm_mn[-1]))
print(min(sm_mx, sm_mn))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
446 | A | DZY Loves Sequences | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"two pointers"
] | null | null | DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | In a single line print the answer to the problem — the maximum length of the required subsegment. | [
"6\n7 2 3 1 5 6\n"
] | [
"5\n"
] | You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | 500 | [
{
"input": "6\n7 2 3 1 5 6",
"output": "5"
},
{
"input": "10\n424238336 649760493 681692778 714636916 719885387 804289384 846930887 957747794 596516650 189641422",
"output": "9"
},
{
"input": "50\n804289384 846930887 681692778 714636916 957747794 424238336 719885387 649760493 596516650 1... | 1,449,249,882 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n=int(input())
a=list(map(int,input().split()))
pre=[1]*n
suf=[1]*n
for i in range(1,n):
if a[i]>a[i-1]:
pre[i]=pre[i-1]+1
for i in range(n-2,0,-1):
if a[i]<a[i+1]:
suf[i]=suf[i+1]+1
ans=max(pre)
for i in range(1,n-1):
if a[i-1]<=a[i+1]-2:
ans=max(ans,pre[i-1]+suf[i+1]+1... | Title: DZY Loves Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the... | ```python
n=int(input())
a=list(map(int,input().split()))
pre=[1]*n
suf=[1]*n
for i in range(1,n):
if a[i]>a[i-1]:
pre[i]=pre[i-1]+1
for i in range(n-2,0,-1):
if a[i]<a[i+1]:
suf[i]=suf[i+1]+1
ans=max(pre)
for i in range(1,n-1):
if a[i-1]<=a[i+1]-2:
ans=max(ans,pre[i-1]+... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
305 | A | Strange Addition | PROGRAMMING | 1,600 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Unfortunately, Vasya can only sum pairs of integers (*a*, *b*), such that for any decimal place at least one number has digit 0 in this place. For example, Vasya can sum numbers 505 and 50, but he cannot sum 1 and 4.
Vasya has a set of *k* distinct non-negative integers *d*1,<=*d*2,<=...,<=*d**k*.
Vasya wants to choo... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=100) — the number of integers.
The second line contains *k* distinct space-separated integers *d*1,<=*d*2,<=...,<=*d**k* (0<=≤<=*d**i*<=≤<=100). | In the first line print a single integer *n* the maximum number of the chosen integers. In the second line print *n* distinct non-negative integers — the required integers.
If there are multiple solutions, print any of them. You can print the numbers in any order. | [
"4\n100 10 1 0\n",
"3\n2 70 3\n"
] | [
"4\n0 1 10 100 ",
"2\n2 70 "
] | none | 500 | [
{
"input": "4\n100 10 1 0",
"output": "4\n0 1 10 100 "
},
{
"input": "3\n2 70 3",
"output": "2\n2 70 "
},
{
"input": "39\n16 72 42 70 17 36 32 40 47 94 27 30 100 55 23 77 67 28 49 50 53 83 38 33 60 65 62 64 6 66 69 86 96 75 85 0 89 73 29",
"output": "4\n0 6 30 100 "
},
{
"inp... | 1,648,409,384 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | n= int(input())
lst=list(map(int,input().split()))
ans=[]
ex=0
for i in lst:
if i==0 or i%10 ==0:
ans.append(i)
else:
ex=i
if len(ans)==n:
print(n)
print(*ans)
else:
print(len(ans)+1)
ans.append(ex)
print(*ans)
| Title: Strange Addition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unfortunately, Vasya can only sum pairs of integers (*a*, *b*), such that for any decimal place at least one number has digit 0 in this place. For example, Vasya can sum numbers 505 and 50, but he cannot sum 1 and 4.
... | ```python
n= int(input())
lst=list(map(int,input().split()))
ans=[]
ex=0
for i in lst:
if i==0 or i%10 ==0:
ans.append(i)
else:
ex=i
if len(ans)==n:
print(n)
print(*ans)
else:
print(len(ans)+1)
ans.append(ex)
print(*ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
609 | A | USB Flash Drives | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives. | The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabyt... | Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives. | [
"3\n5\n2\n1\n3\n",
"3\n6\n2\n3\n2\n",
"2\n5\n5\n10\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second. | 0 | [
{
"input": "3\n5\n2\n1\n3",
"output": "2"
},
{
"input": "3\n6\n2\n3\n2",
"output": "3"
},
{
"input": "2\n5\n5\n10",
"output": "1"
},
{
"input": "5\n16\n8\n1\n3\n4\n9",
"output": "2"
},
{
"input": "10\n121\n10\n37\n74\n56\n42\n39\n6\n68\n8\n100",
"output": "2"
... | 1,597,693,052 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 140 | 0 | n = int(input())
m = int(input())
arr = []
for _ in range(n):
arr.append(int(input()))
arr = sorted(arr, reverse=True)
ans = 0
total_val = 0
for i in arr:
total_val += i
ans += 1
if total_val >= m:
break
print(ans) | Title: USB Flash Drives
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of... | ```python
n = int(input())
m = int(input())
arr = []
for _ in range(n):
arr.append(int(input()))
arr = sorted(arr, reverse=True)
ans = 0
total_val = 0
for i in arr:
total_val += i
ans += 1
if total_val >= m:
break
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,692,566,075 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<iostream>
using namespace std;
void test(int number)
{
int sum=0;
for(int i=1 ; i<=number ; i++)
{
if(i%2==0)
sum+=i;
else
sum-=i;
}
cout<<sum<<endl;
}
int main()
{
int number;
cin>>number;
test(number);
... | Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
#include<iostream>
using namespace std;
void test(int number)
{
int sum=0;
for(int i=1 ; i<=number ; i++)
{
if(i%2==0)
sum+=i;
else
sum-=i;
}
cout<<sum<<endl;
}
int main()
{
int number;
cin>>number;
test(... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
120 | A | Elevator | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through the front door, he goes out through the back one and vice versa. The elevator has two rails n... | The first line indicates the door through which the very important person entered the elevator. It contains "front" if the person enters the elevator through the front door and "back" if he entered the elevator through the back door. The second line contains integer *a* (1<=≤<=*a*<=≤<=2) which denotes the number of the... | Print character "R" if the VIP is right-handed or "L" if he is left-handed. | [
"front\n1\n"
] | [
"L\n"
] | none | 0 | [
{
"input": "front\n1",
"output": "L"
},
{
"input": "back\n1",
"output": "R"
},
{
"input": "front\n2",
"output": "R"
},
{
"input": "back\n2",
"output": "L"
}
] | 1,624,685,927 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | d=str(input())
r=int(input())
if d=='front':
if r==1:
print('L')
else:
print('R')
elif d=='back':
if r==1:
print('R')
else:
print('L') | Title: Elevator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through... | ```python
d=str(input())
r=int(input())
if d=='front':
if r==1:
print('L')
else:
print('R')
elif d=='back':
if r==1:
print('R')
else:
print('L')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
157 | B | Trace | PROGRAMMING | 1,000 | [
"geometry",
"sortings"
] | null | null | One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall into several parts. Some parts were painted red and all the other were painted blue. Besides,... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integers *r**i* (1<=≤<=*r**i*<=≤<=1000) — the circles' radii. It is guaranteed that all circles are different. | Print the single real number — total area of the part of the wall that is painted red. The answer is accepted if absolute or relative error doesn't exceed 10<=-<=4. | [
"1\n1\n",
"3\n1 4 2\n"
] | [
"3.1415926536\n",
"40.8407044967\n"
] | In the first sample the picture is just one circle of radius 1. Inner part of the circle is painted red. The area of the red part equals π × 1<sup class="upper-index">2</sup> = π.
In the second sample there are three circles of radii 1, 4 and 2. Outside part of the second circle is painted blue. Part between the secon... | 1,000 | [
{
"input": "1\n1",
"output": "3.1415926536"
},
{
"input": "3\n1 4 2",
"output": "40.8407044967"
},
{
"input": "4\n4 1 3 2",
"output": "31.4159265359"
},
{
"input": "4\n100 10 2 1",
"output": "31111.1920484997"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output"... | 1,641,723,066 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | import math
n = int(input())
s = input().split()
s = [int(i) for i in s]
s.sort()
diff = []
for i in range(1,n):
if(i%2 == 0):
diff.append(s[i]**2 - s[i-1]**2)
diff.append(s[0]**2)
print(math.pi * sum(diff)) | Title: Trace
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall in... | ```python
import math
n = int(input())
s = input().split()
s = [int(i) for i in s]
s.sort()
diff = []
for i in range(1,n):
if(i%2 == 0):
diff.append(s[i]**2 - s[i-1]**2)
diff.append(s[0]**2)
print(math.pi * sum(diff))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
400 | A | Inna and Choose Options | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There always is something to choose from! And now, instead of "Noughts and Crosses", Inna choose a very unusual upgrade of this game. The rules of the game are given below:
There is one person playing the game. Before the beginning of the game he puts 12 cards in a row on the table. Each card contains a character: "X"... | The first line of the input contains integer *t* (1<=≤<=*t*<=≤<=100). This value shows the number of sets of test data in the input. Next follows the description of each of the *t* tests on a separate line.
The description of each test is a string consisting of 12 characters, each character is either "X", or "O". The ... | For each test, print the answer to the test on a single line. The first number in the line must represent the number of distinct ways to choose the pair *a*,<=*b*. Next, print on this line the pairs in the format *a*x*b*. Print the pairs in the order of increasing first parameter (*a*). Separate the pairs in the line b... | [
"4\nOXXXOXOOXOOX\nOXOXOXOXOXOX\nXXXXXXXXXXXX\nOOOOOOOOOOOO\n"
] | [
"3 1x12 2x6 4x3\n4 1x12 2x6 3x4 6x2\n6 1x12 2x6 3x4 4x3 6x2 12x1\n0\n"
] | none | 500 | [
{
"input": "4\nOXXXOXOOXOOX\nOXOXOXOXOXOX\nXXXXXXXXXXXX\nOOOOOOOOOOOO",
"output": "3 1x12 2x6 4x3\n4 1x12 2x6 3x4 6x2\n6 1x12 2x6 3x4 4x3 6x2 12x1\n0"
},
{
"input": "2\nOOOOOOOOOOOO\nXXXXXXXXXXXX",
"output": "0\n6 1x12 2x6 3x4 4x3 6x2 12x1"
},
{
"input": "13\nXXXXXXXXXXXX\nXXXXXXXXXXXX\n... | 1,569,256,156 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 109 | 0 | le=int(input())
for _ in range(le):
str1=input()
count=0
arr=[12,6,4,3,2,1]
arr1=[]
for num in arr:
j=0
flag=True
while(j<12):
j+=num
if(str1[j-1]!="X"):
flag=False
break
if(flag):
coun... | Title: Inna and Choose Options
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There always is something to choose from! And now, instead of "Noughts and Crosses", Inna choose a very unusual upgrade of this game. The rules of the game are given below:
There is one person playing the game.... | ```python
le=int(input())
for _ in range(le):
str1=input()
count=0
arr=[12,6,4,3,2,1]
arr1=[]
for num in arr:
j=0
flag=True
while(j<12):
j+=num
if(str1[j-1]!="X"):
flag=False
break
if(flag):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
559 | B | Equivalent Strings | PROGRAMMING | 1,700 | [
"divide and conquer",
"hashing",
"sortings",
"strings"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 1,000 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,582,071,558 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 90 | 2,000 | 10,240,000 | def strn(A,B,x):
if A==B: return True
if x==1: return False
if x%2!=0:return False
x=x//2
return (strn(A[:x],B[:x],x) and strn(A[x:],B[x:],x)) or (strn(A[:x],B[x:],x) and strn(A[x:],B[:x],x))
A=input()
B=input()
if strn(A,B,len(A))==True:
print("YES")
else:
print("NO") | Title: Equivalent Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split str... | ```python
def strn(A,B,x):
if A==B: return True
if x==1: return False
if x%2!=0:return False
x=x//2
return (strn(A[:x],B[:x],x) and strn(A[x:],B[x:],x)) or (strn(A[:x],B[x:],x) and strn(A[x:],B[:x],x))
A=input()
B=input()
if strn(A,B,len(A))==True:
print("YES")
else:
print("... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,656,491,160 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 512,000 | n = int(input())
s = input()
zeros = s.count("0")
ones = s.count("1")
mincount = min(zeros,ones)
print(n-2*mincount) | Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
n = int(input())
s = input()
zeros = s.count("0")
ones = s.count("1")
mincount = min(zeros,ones)
print(n-2*mincount)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,691,847,286 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | d1,d2,d3 = map(int,input().split())
print(min(d1,d2)+min(d1+d2,d3)+min(d1+d3,d2)) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
d1,d2,d3 = map(int,input().split())
print(min(d1,d2)+min(d1+d2,d3)+min(d1+d3,d2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,645,510,039 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | a,b=map(int,input().split())
if b%2==0:
print(a+b+1)
else:
print(a+b-1)
| Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
a,b=map(int,input().split())
if b%2==0:
print(a+b+1)
else:
print(a+b-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of *n* questions; the questions are to be answered strictly in the order in which they are given, from question 1 t... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). It is the number of questions in the test. The second line contains space-separated *n* positive integers *a**i* (1<=≤<=*a**i*<=≤<=109), the number of answer variants to question *i*. | Print a single number — the minimal number of clicks needed to pass the test it the worst-case scenario.
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"2\n1 1\n",
"2\n2 2\n",
"1\n10\n"
] | [
"2",
"5",
"10"
] | Note to the second sample. In the worst-case scenario you will need five clicks:
- the first click selects the first variant to the first question, this answer turns out to be wrong. - the second click selects the second variant to the first question, it proves correct and we move on to the second question; - the ... | 0 | [
{
"input": "2\n1 1",
"output": "2"
},
{
"input": "2\n2 2",
"output": "5"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "3\n2 4 1",
"output": "10"
},
{
"input": "4\n5 5 3 1",
"output": "22"
},
{
"input": "2\n1000000000 1000000000",
"output": "... | 1,567,712,813 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 216 | 0 | n = int(input())
cnt = 1
cnt2 = 0
s = input()
l = [int(i) for i in s.split()]
for i in range(0, len(l)):
if l[i] > 1:
cnt *= l[i]
else:
cnt2 += 1
if n == 1:
print(cnt + cnt2)
elif cnt2 == n:
print(cnt2)
else:
print(cnt + cnt2 + 1)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of *n* questions; the que... | ```python
n = int(input())
cnt = 1
cnt2 = 0
s = input()
l = [int(i) for i in s.split()]
for i in range(0, len(l)):
if l[i] > 1:
cnt *= l[i]
else:
cnt2 += 1
if n == 1:
print(cnt + cnt2)
elif cnt2 == n:
print(cnt2)
else:
print(cnt + cnt2 + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
622 | B | The Time | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedi... | The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes... | The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format. | [
"23:59\n10\n",
"20:20\n121\n",
"10:10\n0\n"
] | [
"00:09\n",
"22:21\n",
"10:10\n"
] | none | 0 | [
{
"input": "23:59\n10",
"output": "00:09"
},
{
"input": "20:20\n121",
"output": "22:21"
},
{
"input": "10:10\n0",
"output": "10:10"
},
{
"input": "12:34\n10000",
"output": "11:14"
},
{
"input": "00:00\n10000",
"output": "22:40"
},
{
"input": "00:00\n14... | 1,648,472,065 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
using namespace std;
int main(){
int a,b,c,d,e,f;
char s;
cin>>a>>s>>c>>d;
e=d%60;
f=d/60;
a+=f;
c+=e;
if(c>=60){
a=a+c/60;
c%=60;
}
if(a>=24){
a-=24;
}
if(a<10){
cout<<0<<a<<s;
}
else{
cout<<a<<s;
}
if(c<10){
cout<<0<<c;
}
else{
cout<<c... | Title: The Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read mo... | ```python
#include<bits/stdc++.h>
using namespace std;
int main(){
int a,b,c,d,e,f;
char s;
cin>>a>>s>>c>>d;
e=d%60;
f=d/60;
a+=f;
c+=e;
if(c>=60){
a=a+c/60;
c%=60;
}
if(a>=24){
a-=24;
}
if(a<10){
cout<<0<<a<<s;
}
else{
cout<<a<<s;
}
if(c<10){
cout<<0<<c;
}
else{
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
616 | A | Comparing Two Long Integers | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can r... | The first line contains a non-negative integer *a*.
The second line contains a non-negative integer *b*.
The numbers *a*,<=*b* may contain leading zeroes. Each of them contains no more than 106 digits. | Print the symbol "<" if *a*<=<<=*b* and the symbol ">" if *a*<=><=*b*. If the numbers are equal print the symbol "=". | [
"9\n10\n",
"11\n10\n",
"00012345\n12345\n",
"0123\n9\n",
"0123\n111\n"
] | [
"<\n",
">\n",
"=\n",
">\n",
">\n"
] | none | 0 | [
{
"input": "9\n10",
"output": "<"
},
{
"input": "11\n10",
"output": ">"
},
{
"input": "00012345\n12345",
"output": "="
},
{
"input": "0123\n9",
"output": ">"
},
{
"input": "0123\n111",
"output": ">"
},
{
"input": "9\n9",
"output": "="
},
{
... | 1,605,590,536 | 2,147,483,647 | PyPy 3 | OK | TESTS | 120 | 264 | 8,908,800 | a=input().lstrip('0')
b=input().lstrip('0')
if(len(a)>len(b)):
print('>')
elif(len(a)<len(b)):
print('<')
else:
if(a>b):
print('>')
elif(a<b):
print('<')
else:
print('=') | Title: Comparing Two Long Integers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use th... | ```python
a=input().lstrip('0')
b=input().lstrip('0')
if(len(a)>len(b)):
print('>')
elif(len(a)<len(b)):
print('<')
else:
if(a>b):
print('>')
elif(a<b):
print('<')
else:
print('=')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
225 | D | Snake | PROGRAMMING | 2,200 | [
"bitmasks",
"dfs and similar",
"graphs",
"implementation"
] | null | null | Let us remind you the rules of a very popular game called "Snake" (or sometimes "Boa", "Python" or "Worm").
The game field is represented by an *n*<=×<=*m* rectangular table. Some squares of the field are considered impassable (walls), all other squares of the fields are passable.
You control a snake, the snake consi... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=15) — the number of rows and columns of the game field.
Next *n* lines describe the game field. Each of these lines contains *m* characters. Character "#" represents a wall, "." is a passable square, "@" is an apple. The snake's firs... | Print a single integer to the output — the minimum number of moves needed to reach the apple. If the snake can't reach the apple, print -1. | [
"4 5\n##...\n..1#@\n432#.\n...#.\n",
"4 4\n#78#\n.612\n.543\n..@.\n",
"3 2\n3@\n2#\n1#\n"
] | [
"4\n",
"6\n",
"-1\n"
] | none | 3,000 | [] | 1,673,695,696 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
#define enl '\n'
#define int long long
#define sz(s) (int)s.size()
#define all(v) (v).begin(),(v).end()
mt19937 rng (chrono::high_resolution_clock::now().time_since_epoch().count());
template <typename A, typename B> ostream& operator<< (... | Title: Snake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let us remind you the rules of a very popular game called "Snake" (or sometimes "Boa", "Python" or "Worm").
The game field is represented by an *n*<=×<=*m* rectangular table. Some squares of the field are considered impassable (... | ```python
#include <bits/stdc++.h>
using namespace std;
#define enl '\n'
#define int long long
#define sz(s) (int)s.size()
#define all(v) (v).begin(),(v).end()
mt19937 rng (chrono::high_resolution_clock::now().time_since_epoch().count());
template <typename A, typename B> ostream& op... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
793 | B | Igor and his way to work | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"implementation",
"shortest paths"
] | null | null | Woken up by the alarm clock Igor the financial analyst hurried up to the work. He ate his breakfast and sat in his car. Sadly, when he opened his GPS navigator, he found that some of the roads in Bankopolis, the city where he lives, are closed due to road works. Moreover, Igor has some problems with the steering wheel,... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the grid.
Each of the next *n* lines contains *m* characters denoting the corresponding row of the grid. The following characters can occur:
- "." — an empty cell; - "*" — a cell with road ... | In the only line print "YES" if there is a path between Igor's home and Igor's office with no more than two turns, and "NO" otherwise. | [
"5 5\n..S..\n****.\nT....\n****.\n.....\n",
"5 5\nS....\n****.\n.....\n.****\n..T..\n"
] | [
"YES",
"NO"
] | The first sample is shown on the following picture:
In the second sample it is impossible to reach Igor's office using less that 4 turns, thus there exists no path using no more than 2 turns. The path using exactly 4 turns is shown on this picture: | 1,000 | [
{
"input": "5 5\nS....\n****.\n.....\n.****\n..T..",
"output": "NO"
},
{
"input": "1 2\nST",
"output": "YES"
},
{
"input": "3 1\nS\n*\nT",
"output": "NO"
},
{
"input": "3 3\n*..\n...\nTS.",
"output": "YES"
},
{
"input": "3 3\nT.*\n*.*\n*S*",
"output": "YES"
... | 1,492,969,461 | 3,561 | Python 3 | WRONG_ANSWER | TESTS | 40 | 171 | 7,168,000 | n,m = tuple(map(int, input().split()))
s = []
startX, startY, endX, endY = 0,0,0,0
for i in range(n):
row = input()
if 'S' in row:
startY = row.index('S')
startX = i
if 'T' in row:
endY = row.index('T')
endX = i
s.append(row)
def validway(fromX, toX, Y):
... | Title: Igor and his way to work
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Woken up by the alarm clock Igor the financial analyst hurried up to the work. He ate his breakfast and sat in his car. Sadly, when he opened his GPS navigator, he found that some of the roads in Bankopolis, th... | ```python
n,m = tuple(map(int, input().split()))
s = []
startX, startY, endX, endY = 0,0,0,0
for i in range(n):
row = input()
if 'S' in row:
startY = row.index('S')
startX = i
if 'T' in row:
endY = row.index('T')
endX = i
s.append(row)
def validway(fromX, toX,... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,575,377,292 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 139 | 409,600 | from collections import deque as d
n = int(input())
f = 1
l = d()
while n >= f:
if n-f*2-1 < 0:
l.append(n)
break
l.append(f)
n -= f
f += 1
print(len(l))
for i in l:
print(i)
| Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
from collections import deque as d
n = int(input())
f = 1
l = d()
while n >= f:
if n-f*2-1 < 0:
l.append(n)
break
l.append(f)
n -= f
f += 1
print(len(l))
for i in l:
print(i)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
484 | A | Bits | PROGRAMMING | 1,700 | [
"bitmasks",
"constructive algorithms"
] | null | null | Let's denote as the number of bits set ('1' bits) in the binary representation of the non-negative integer *x*.
You are given multiple queries consisting of pairs of integers *l* and *r*. For each query, find the *x*, such that *l*<=≤<=*x*<=≤<=*r*, and is maximum possible. If there are multiple such numbers find the... | The first line contains integer *n* — the number of queries (1<=≤<=*n*<=≤<=10000).
Each of the following *n* lines contain two integers *l**i*,<=*r**i* — the arguments for the corresponding query (0<=≤<=*l**i*<=≤<=*r**i*<=≤<=1018). | For each query print the answer in a separate line. | [
"3\n1 2\n2 4\n1 10\n"
] | [
"1\n3\n7\n"
] | The binary representations of numbers from 1 to 10 are listed below:
1<sub class="lower-index">10</sub> = 1<sub class="lower-index">2</sub>
2<sub class="lower-index">10</sub> = 10<sub class="lower-index">2</sub>
3<sub class="lower-index">10</sub> = 11<sub class="lower-index">2</sub>
4<sub class="lower-index">10</su... | 500 | [
{
"input": "3\n1 2\n2 4\n1 10",
"output": "1\n3\n7"
},
{
"input": "55\n1 1\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n2 2\n2 3\n2 4\n2 5\n2 6\n2 7\n2 8\n2 9\n2 10\n3 3\n3 4\n3 5\n3 6\n3 7\n3 8\n3 9\n3 10\n4 4\n4 5\n4 6\n4 7\n4 8\n4 9\n4 10\n5 5\n5 6\n5 7\n5 8\n5 9\n5 10\n6 6\n6 7\n6 8\n6 9\n6 10... | 1,547,895,661 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 409,600 | from sys import stdin
from collections import defaultdict
import math
#stdin = open('input.txt', 'r')
def countSetBits(n):
count = 0
while (n):
n &= (n-1)
count+=1
return count
def brute(l,r):
num = 0
tim = 0
for i in range(l,r+1):
if(countSetBits(i)... | Title: Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's denote as the number of bits set ('1' bits) in the binary representation of the non-negative integer *x*.
You are given multiple queries consisting of pairs of integers *l* and *r*. For each query, find the *x*, such that ... | ```python
from sys import stdin
from collections import defaultdict
import math
#stdin = open('input.txt', 'r')
def countSetBits(n):
count = 0
while (n):
n &= (n-1)
count+=1
return count
def brute(l,r):
num = 0
tim = 0
for i in range(l,r+1):
if(count... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
891 | B | Gluttony | PROGRAMMING | 2,000 | [
"constructive algorithms",
"greedy"
] | null | null | You are given an array *a* with *n* distinct integers. Construct an array *b* by permuting *a* such that for every non-empty subset of indices *S*<==<={*x*1,<=*x*2,<=...,<=*x**k*} (1<=≤<=*x**i*<=≤<=*n*, 0<=<<=*k*<=<<=*n*) the sums of elements on that positions in *a* and *b* are different, i. e. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=22) — the size of the array.
The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — the elements of the array. | If there is no such array *b*, print -1.
Otherwise in the only line print *n* space-separated integers *b*1,<=*b*2,<=...,<=*b**n*. Note that *b* must be a permutation of *a*.
If there are multiple answers, print any of them. | [
"2\n1 2\n",
"4\n1000 100 10 1\n"
] | [
"2 1 \n",
"100 1 1000 10\n"
] | An array *x* is a permutation of *y*, if we can shuffle elements of *y* such that it will coincide with *x*.
Note that the empty subset and the subset containing all indices are not counted. | 1,000 | [
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "4\n1000 100 10 1",
"output": "100 1 1000 10"
},
{
"input": "5\n1 3 4 5 2",
"output": "5 2 3 4 1 "
},
{
"input": "1\n10000000",
"output": "10000000 "
},
{
"input": "4\n1 5 8 4",
"output": "8 4 5 1 "
},
{
... | 1,546,095,192 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | n = int(input())
A = [int(a) for a in input().split(' ')]
A.sort()
A = [A[-1]] + A[:-1]
print(A) | Title: Gluttony
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a* with *n* distinct integers. Construct an array *b* by permuting *a* such that for every non-empty subset of indices *S*<==<={*x*1,<=*x*2,<=...,<=*x**k*} (1<=≤<=*x**i*<=≤<=*n*, 0<=<<=*k*<=<<=*n*... | ```python
n = int(input())
A = [int(a) for a in input().split(' ')]
A.sort()
A = [A[-1]] + A[:-1]
print(A)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
794 | A | Bank Robbery | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and steal some money from the safes. There are many safes arranged in a line, where the *i*-th safe f... | The first line of input contains three space-separated integers, *a*, *b* and *c* (1<=≤<=*b*<=<<=*a*<=<<=*c*<=≤<=109), denoting the positions of Oleg, the first security guard and the second security guard, respectively.
The next line of input contains a single integer *n* (1<=≤<=*n*<=≤<=105), denoting the numbe... | Output a single integer: the maximum number of banknotes Oleg can take. | [
"5 3 7\n8\n4 7 5 5 3 6 2 8\n",
"6 5 7\n5\n1 5 7 92 3\n"
] | [
"4\n",
"0\n"
] | In the first example Oleg can take the banknotes in positions 4, 5, 6 (note that there are 2 banknotes at position 5). Oleg can't take the banknotes in safes 7 and 8 because he can't run into the second security guard. Similarly, Oleg cannot take the banknotes at positions 3 and 2 because he can't run into the first se... | 500 | [
{
"input": "5 3 7\n8\n4 7 5 5 3 6 2 8",
"output": "4"
},
{
"input": "6 5 7\n5\n1 5 7 92 3",
"output": "0"
},
{
"input": "3 2 4\n1\n3",
"output": "1"
},
{
"input": "5 3 8\n12\n8 3 4 5 7 6 8 3 5 4 7 6",
"output": "8"
},
{
"input": "7 3 10\n5\n3 3 3 3 3",
"output... | 1,651,215,646 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 264 | 14,745,600 | #!/usr/bin/env python
import math
import sys
import itertools
import fractions
if __name__ == '__main__':
wtf = sys.stdin.read()
wtf = wtf.strip().split('\n')
a,b,c = map(int, wtf[0].split())
n = int(wtf[1])
X = list(map(int, wtf[2].split()))
S = dict()
for i,v in enumerate(X... | Title: Bank Robbery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and... | ```python
#!/usr/bin/env python
import math
import sys
import itertools
import fractions
if __name__ == '__main__':
wtf = sys.stdin.read()
wtf = wtf.strip().split('\n')
a,b,c = map(int, wtf[0].split())
n = int(wtf[1])
X = list(map(int, wtf[2].split()))
S = dict()
for i,v in e... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
171 | D | Broken checker | PROGRAMMING | 1,300 | [
"*special",
"brute force"
] | null | null | "This problem is rubbish! There is not statement, and there are only 5 test cases. The problemsetter took liberties with this problem!" — people complained in the comments to one round on Codeforces. And even more... No, wait, the checker for the problem was alright, that's a mercy. | The only line of the input contains an integer between 1 and 5, inclusive. All tests for this problem are different. The contents of the test case doesn't need to be equal to its index. | The only line of the output contains an integer between 1 and 3, inclusive. | [] | [] | This problem has no samples, since there so few test cases. | 0 | [
{
"input": "3",
"output": "1"
},
{
"input": "1",
"output": "2"
},
{
"input": "4",
"output": "2"
},
{
"input": "2",
"output": "3"
},
{
"input": "5",
"output": "1"
}
] | 1,689,346,419 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1689346418.23841")# 1689346418.2384262 | Title: Broken checker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"This problem is rubbish! There is not statement, and there are only 5 test cases. The problemsetter took liberties with this problem!" — people complained in the comments to one round on Codeforces. And even more... No,... | ```python
print("_RANDOM_GUESS_1689346418.23841")# 1689346418.2384262
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
921 | 05 | Labyrinth-5 | PROGRAMMING | 3,200 | [] | null | null | See the problem statement here: [http://codeforces.com/contest/921/problem/01](//codeforces.com/contest/921/problem/01). | none | none | [] | [] | none | 82.088 | [] | 1,517,509,921 | 9,121 | PyPy 3 | PARTIAL | TESTS | 1 | 61 | 19,660,800 | print("""for-10000
for-351
move-down
move-right
move-up
move-right
end
move-down
move-down
if-ok else
move-up
break
endif
for-351
move-down
move-left
move-up
move-left
end
move-down
move-down
end""") | Title: Labyrinth-5
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
See the problem statement here: [http://codeforces.com/contest/921/problem/01](//codeforces.com/contest/921/problem/01).
Input Specification:
none
Output Specification:
none
Note:
none | ```python
print("""for-10000
for-351
move-down
move-right
move-up
move-right
end
move-down
move-down
if-ok else
move-up
break
endif
for-351
move-down
move-left
move-up
move-left
end
move-down
move-down
end""")
``` | 2 | MatrixStudio/Codeforces-Python-Submissions | |
812 | C | Sagheer and Nubian Market | PROGRAMMING | 1,500 | [
"binary search",
"sortings"
] | null | null | On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains *n* different items numbered from 1 to *n*. The *i*-th item has base cost *a**i* Egyptian pounds. If Sagheer buys *k* items with indices *x*1,<=*x*2,<=...,<... | The first line contains two integers *n* and *S* (1<=≤<=*n*<=≤<=105 and 1<=≤<=*S*<=≤<=109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the base costs of the souvenirs. | On a single line, print two integers *k*, *T* — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these *k* souvenirs. | [
"3 11\n2 3 5\n",
"4 100\n1 2 5 6\n",
"1 7\n7\n"
] | [
"2 11\n",
"4 54\n",
"0 0\n"
] | In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the... | 1,500 | [
{
"input": "3 11\n2 3 5",
"output": "2 11"
},
{
"input": "4 100\n1 2 5 6",
"output": "4 54"
},
{
"input": "1 7\n7",
"output": "0 0"
},
{
"input": "1 7\n5",
"output": "1 6"
},
{
"input": "1 1\n1",
"output": "0 0"
},
{
"input": "4 33\n4 3 2 1",
"outp... | 1,496,514,385 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 920 | 7,372,800 | n,s = list(map(int,input().split()))
arr = list(map(int,input().split()))
def buy(k):
global n,s,arr
if k==0:
return 0
temp = sorted([arr[i-1]+i*k for i in range(1,n+1)])
return sum(temp[:k])
def main():
f,l = 0,n
while f<l:
if f==l-1:
a,b=buy(f),b... | Title: Sagheer and Nubian Market
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains *n* different items numbered from 1 to *n*. T... | ```python
n,s = list(map(int,input().split()))
arr = list(map(int,input().split()))
def buy(k):
global n,s,arr
if k==0:
return 0
temp = sorted([arr[i-1]+i*k for i in range(1,n+1)])
return sum(temp[:k])
def main():
f,l = 0,n
while f<l:
if f==l-1:
a,... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,632,430,269 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 92 | 6,963,200 | k = int(input())
s = input()
ns = set(s)
if len(ns) > k:
print(-1)
else:
if len(s) % len(ns) == 0:
count = 0
for i in ns:
count += (s.count(i) / k)
if count == (len(s) / k):
temp = " "
for i in ns:
temp += ((s.count(i) //... | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
k = int(input())
s = input()
ns = set(s)
if len(ns) > k:
print(-1)
else:
if len(s) % len(ns) == 0:
count = 0
for i in ns:
count += (s.count(i) / k)
if count == (len(s) / k):
temp = " "
for i in ns:
temp += ((s.c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,619,278,221 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 124 | 0 | n=int(input())
l=list(map(int,input().split()))
a,b=map(int,input().split())
s=0
for i in range(a,b):
s+=l[i-1]
print(s)
| Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
n=int(input())
l=list(map(int,input().split()))
a,b=map(int,input().split())
s=0
for i in range(a,b):
s+=l[i-1]
print(s)
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,654,186,700 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 62 | 2,150,400 | a, b = tuple(map(int, input().split()))
a_burned = 0
hours = 0
while a:
a -= 1
a_burned += 1
hours += 1
if a_burned == b:
a += 1
a_burned = 0
print(hours) | Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
a, b = tuple(map(int, input().split()))
a_burned = 0
hours = 0
while a:
a -= 1
a_burned += 1
hours += 1
if a_burned == b:
a += 1
a_burned = 0
print(hours)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
152 | C | Pocket Book | PROGRAMMING | 1,400 | [
"combinatorics"
] | null | null | One day little Vasya found mom's pocket book. The book had *n* names of her friends and unusually enough, each name was exactly *m* letters long. Let's number the names from 1 to *n* in the order in which they are written.
As mom wasn't home, Vasya decided to play with names: he chose three integers *i*, *j*, *k* (1<=... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of names and the length of each name, correspondingly. Then *n* lines contain names, each name consists of exactly *m* uppercase Latin letters. | Print the single number — the number of different names that could end up in position number 1 in the pocket book after the applying the procedures described above. Print the number modulo 1000000007 (109<=+<=7). | [
"2 3\nAAB\nBAA\n",
"4 5\nABABA\nBCGDG\nAAAAA\nYABSA\n"
] | [
"4\n",
"216\n"
] | In the first sample Vasya can get the following names in the position number 1: "AAB", "AAA", "BAA" and "BAB". | 1,500 | [
{
"input": "2 3\nAAB\nBAA",
"output": "4"
},
{
"input": "4 5\nABABA\nBCGDG\nAAAAA\nYABSA",
"output": "216"
},
{
"input": "1 1\nE",
"output": "1"
},
{
"input": "2 2\nNS\nPD",
"output": "4"
},
{
"input": "3 4\nPJKD\nNFJX\nFGFK",
"output": "81"
},
{
"inpu... | 1,588,158,249 | 2,147,483,647 | PyPy 3 | OK | TESTS | 60 | 280 | 1,331,200 | # Author: S Mahesh Raju
# Username: maheshraju2020
# Date: 29/04/2020
from sys import stdin,stdout
from math import gcd, ceil, sqrt
ii1 = lambda: int(stdin.readline().strip())
is1 = lambda: stdin.readline().strip()
iia = lambda: list(map(int, stdin.readline().strip().split()))
isa = lambda: stdin.readline().s... | Title: Pocket Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day little Vasya found mom's pocket book. The book had *n* names of her friends and unusually enough, each name was exactly *m* letters long. Let's number the names from 1 to *n* in the order in which they are written.
... | ```python
# Author: S Mahesh Raju
# Username: maheshraju2020
# Date: 29/04/2020
from sys import stdin,stdout
from math import gcd, ceil, sqrt
ii1 = lambda: int(stdin.readline().strip())
is1 = lambda: stdin.readline().strip()
iia = lambda: list(map(int, stdin.readline().strip().split()))
isa = lambda: stdin.re... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,692,992,100 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 46 | 307,200 | from collections import Counter
n=int(input())
a=list(map(int,input().split()))
d=Counter(a)
a_=list(set(a));a_.sort()
score1=0;x=len(a_);i=0
while i<x:
if a_[i]*d[a_[i]]+(a_[i]+2)*d.get(a_[i]+2,0)>=(a_[i]+1)*(d.get(a_[i]+1,0)):
score1+=a_[i]*d[a_[i]]
if d.get(a_[i]+1,0)==0:i+=1
else:i+=2
... | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
from collections import Counter
n=int(input())
a=list(map(int,input().split()))
d=Counter(a)
a_=list(set(a));a_.sort()
score1=0;x=len(a_);i=0
while i<x:
if a_[i]*d[a_[i]]+(a_[i]+2)*d.get(a_[i]+2,0)>=(a_[i]+1)*(d.get(a_[i]+1,0)):
score1+=a_[i]*d[a_[i]]
if d.get(a_[i]+1,0)==0:i+=1
e... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,475,773,767 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n = int(input())
while n > 0:
pr = input().split()
scores = {pr[0]: int(pr[1])}
n -= 1
print(max(scores)) | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n = int(input())
while n > 0:
pr = input().split()
scores = {pr[0]: int(pr[1])}
n -= 1
print(max(scores))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
113 | C | Double Happiness | PROGRAMMING | 2,200 | [
"brute force",
"math",
"number theory"
] | C. Double Happiness | 3 | 128 | On the math lesson a teacher asked each pupil to come up with his own lucky numbers. As a fan of number theory Peter chose prime numbers. Bob was more original. He said that number *t* is his lucky number, if it can be represented as:
Now, the boys decided to find out how many days of the interval [*l*,<=*r*] (*l*<=≤... | The first line of the input contains integer numbers *l*,<=*r* (1<=≤<=*l*,<=*r*<=≤<=3·108). | In the only line print the number of days on the segment [*l*,<=*r*], which are lucky for Peter and Bob at the same time. | [
"3 5\n",
"6 66\n"
] | [
"1\n",
"7\n"
] | none | 1,500 | [] | 1,621,745,340 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 234 | 2,867,200 | import math
l,r = map(int,input().split())
cnt = 0
for i in range(1,r):
if i * i> r: break
nx = int(math.sqrt(max(0,l-i*i))) + 1
for j in range(max(i+1, nx),r):
num = (i * i) + (j * j)
if num > r: break
if num<l or num % 4 != 1: continue
prime = True
for k in range(3,... | Title: Double Happiness
Time Limit: 3 seconds
Memory Limit: 128 megabytes
Problem Description:
On the math lesson a teacher asked each pupil to come up with his own lucky numbers. As a fan of number theory Peter chose prime numbers. Bob was more original. He said that number *t* is his lucky number, if it can be rep... | ```python
import math
l,r = map(int,input().split())
cnt = 0
for i in range(1,r):
if i * i> r: break
nx = int(math.sqrt(max(0,l-i*i))) + 1
for j in range(max(i+1, nx),r):
num = (i * i) + (j * j)
if num > r: break
if num<l or num % 4 != 1: continue
prime = True
for k i... | 0 | MatrixStudio/Codeforces-Python-Submissions |
202 | A | LLPS | PROGRAMMING | 800 | [
"binary search",
"bitmasks",
"brute force",
"greedy",
"implementation",
"strings"
] | null | null | This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string *s* consisting of lowercase English letters only. Find its lexicographically largest palindromic subsequence.
We'll call a non-empty string *s*[*p*1*p*2... *p**k*] = *s**p*1*... | The only input line contains a non-empty string *s* consisting of lowercase English letters only. Its length does not exceed 10. | Print the lexicographically largest palindromic subsequence of string *s*. | [
"radar\n",
"bowwowwow\n",
"codeforces\n",
"mississipp\n"
] | [
"rr\n",
"wwwww\n",
"s\n",
"ssss\n"
] | Among all distinct subsequences of string "radar" the following ones are palindromes: "a", "d", "r", "aa", "rr", "ada", "rar", "rdr", "raar" and "radar". The lexicographically largest of them is "rr". | 500 | [
{
"input": "radar",
"output": "rr"
},
{
"input": "bowwowwow",
"output": "wwwww"
},
{
"input": "codeforces",
"output": "s"
},
{
"input": "mississipp",
"output": "ssss"
},
{
"input": "tourist",
"output": "u"
},
{
"input": "romka",
"output": "r"
},
... | 1,665,460,838 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 124 | 0 | '''
# Submitted By M7moud Ala3rj
Don't Copy This Code, CopyRight . [email protected] © 2022-2023 :)
'''
# Problem Name = "LLPS"
# Class: A
import sys
#sys.setrecursionlimit(2147483647)
input = sys.stdin.readline
def print(*args, end='\n', sep=' ') -> None:
sys.stdout.write(sep.join(map(str, args)) + end... | Title: LLPS
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string *s* consisting of lowercase English letters only. Find its lexicographically largest ... | ```python
'''
# Submitted By M7moud Ala3rj
Don't Copy This Code, CopyRight . [email protected] © 2022-2023 :)
'''
# Problem Name = "LLPS"
# Class: A
import sys
#sys.setrecursionlimit(2147483647)
input = sys.stdin.readline
def print(*args, end='\n', sep=' ') -> None:
sys.stdout.write(sep.join(map(str, ar... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
56 | A | Bar | PROGRAMMING | 1,000 | [
"implementation"
] | A. Bar | 2 | 256 | According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya happened to determine either the age or the drink the person is having. Vasya can chec... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of the bar's clients. Then follow *n* lines, each describing one visitor. A line either contains his age (an integer from 0 to 1000) or his drink (a string of capital Latin letters from 1 to 100 in length). It is guaranteed that the input da... | Print a single number which is the number of people Vasya should check to guarantee the law enforcement. | [
"5\n18\nVODKA\nCOKE\n19\n17\n"
] | [
"2\n"
] | In the sample test the second and fifth clients should be checked. | 500 | [
{
"input": "5\n18\nVODKA\nCOKE\n19\n17",
"output": "2"
},
{
"input": "2\n2\nGIN",
"output": "2"
},
{
"input": "3\nWHISKEY\n3\nGIN",
"output": "3"
},
{
"input": "4\n813\nIORBQITQXMPTFAEMEQDQIKFGKGOTNKTOSZCBRPXJLUKVLVHJYNRUJXK\nRUM\nRHVRWGODYWWTYZFLFYKCVUFFRTQDINKNWPKFHZBFWBHWI... | 1,633,171,050 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 154 | 6,963,200 | drinks = ["ABSINTH", "BEER", "BRANDY", "CHAMPAGNE", "GIN", "RUM", "SAKE", "TEQUILA", "VODKA", "WHISKEY", "WINE"]
n = int(input(""))
count = 0
for i in range(n):
info = input("")
if info.isnumeric():
if int(info) <= 17:
count += 1
else:
if info in drinks:
c... | Title: Bar
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya h... | ```python
drinks = ["ABSINTH", "BEER", "BRANDY", "CHAMPAGNE", "GIN", "RUM", "SAKE", "TEQUILA", "VODKA", "WHISKEY", "WINE"]
n = int(input(""))
count = 0
for i in range(n):
info = input("")
if info.isnumeric():
if int(info) <= 17:
count += 1
else:
if info in drinks:
... | 3.94853 | MatrixStudio/Codeforces-Python-Submissions |
870 | C | Maximum splitting | PROGRAMMING | 1,300 | [
"dp",
"greedy",
"math",
"number theory"
] | null | null | You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prim... | The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query. | For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings. | [
"1\n12\n",
"2\n6\n8\n",
"3\n1\n2\n3\n"
] | [
"3\n",
"1\n2\n",
"-1\n-1\n-1\n"
] | 12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | 1,500 | [
{
"input": "1\n12",
"output": "3"
},
{
"input": "2\n6\n8",
"output": "1\n2"
},
{
"input": "3\n1\n2\n3",
"output": "-1\n-1\n-1"
},
{
"input": "6\n1\n2\n3\n5\n7\n11",
"output": "-1\n-1\n-1\n-1\n-1\n-1"
},
{
"input": "3\n4\n6\n9",
"output": "1\n1\n1"
},
{
... | 1,527,058,359 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 93 | 1,024,000 | def f(x):
t=1
for i in range(2,x):
if x%i==0:
t=-1
break
else:continue
return t
a=int(input())
while a:
a-=1
z=0
y=0
t=0
b=int(input())
if b%4==0:
print(b/4)
else:
z=b//4
y=b%4
while z and f(y)==1:
... | Title: Maximum splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, o... | ```python
def f(x):
t=1
for i in range(2,x):
if x%i==0:
t=-1
break
else:continue
return t
a=int(input())
while a:
a-=1
z=0
y=0
t=0
b=int(input())
if b%4==0:
print(b/4)
else:
z=b//4
y=b%4
while z and f(y)==1:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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