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Are USB TRNGs still useful given the recent /dev/(u)random merger?
In target app users are equivalent to adversaries. They are allowed to pick chosen keys. \ If we use standard AES (in ECB mode) $$c = AES(m,k) $$ Every user $u$ gets a cipher $c_u$. Two users $u_1, u_2$ have the goal to find a suitable key $k_u$ which leads to a common message $m$ (any 128-bit number) with $$m = ...
In target app users are equivalent to adversaries. They are allowed to pick chosen keys. \ If we use standard AES (in ECB mode) $$c = AES(m,k) $$ Every user $u$ gets a cipher $c_u$. Two users $u_1, u_2$ have the goal to find a suitable key $k_u$ which leads to a common message $m$ (any 128-bit number) with $$m = ...
In target app users are equivalent to adversaries. They are allowed to pick chosen keys. \ If we use standard AES (in ECB mode) $$c = AES(m,k) $$ Every user $u$ gets a cipher $c_u$. Two users $u_1, u_2$ have the goal to find a suitable key $k_u$ which leads to a common message $m$ (any 128-bit number) with $$m = ...
In target app users are equivalent to adversaries. They are allowed to pick chosen keys. \ If we use standard AES (in ECB mode) $$c = AES(m,k) $$ Every user $u$ gets a cipher $c_u$. Two users $u_1, u_2$ have the goal to find a suitable key $k_u$ which leads to a common message $m$ (any 128-bit number) with $$m = ...
In target app users are equivalent to adversaries. They are allowed to pick chosen keys. \ If we use standard AES (in ECB mode) $$c = AES(m,k) $$ Every user $u$ gets a cipher $c_u$. Two users $u_1, u_2$ have the goal to find a suitable key $k_u$ which leads to a common message $m$ (any 128-bit number) with $$m = ...
Some projects (e.g., https://zkpass.org/) are claiming that interactive ZKPs can be more efficient than non-interactive ZKPs. What is the rationale behind this?
I am asking it again because no one answered my previous question with more clarity. I have deleted that question One more co-CDH in Type three pairing groups $G_1 \times G_2 \to G_T$: means given a generator $g_2$ in $G_2$, $A = g_2^a$ with random $a$ and an oracle $\mathcal{O}$ which which accepts query $Q \in G_1...
I am exploring a modification to ECDSA to produce shorter signatures, even though it compromises security. My rationale behind this change is in [this discussion on Crypto Stack Exchange](https://crypto.stackexchange.com/questions/110942/creating-a-weak-bls). Here is my new ECDSA method: (the notation I'm using alig...
I am exploring a modification to ECDSA to produce shorter signatures, even though it compromises security (in a controllable way). My rationale behind this change is in [this discussion on Crypto Stack Exchange](https://crypto.stackexchange.com/questions/110942/creating-a-weak-bls). Here is my new ECDSA method: (the...
I am exploring a modification to ECDSA to produce shorter signatures, even though it compromises security (in a controllable way). My rationale behind this change is in [this discussion](https://crypto.stackexchange.com/questions/110942/creating-a-weak-bls). Here is my new ECDSA method: (the notation I'm using align...
If I was to use AES-NI as a high performance 128-bit permutation/PRF would AESDEC offer faster/better diffusion than AESENC? The reason I ask is because both instructions have the same cost, but the inverse MixColums step of AES has a more complicated matrix, so it appears to me as if there are more operations being pe...
When using AES-NI as a high-speed permutation, does AESDEC offer better diffusion?
I am exploring a modification to ECDSA to produce shorter signatures, even though it compromises security (in a controllable way). My rationale behind this change is in [this discussion](https://crypto.stackexchange.com/questions/110942/creating-a-weak-bls). Here is my new ECDSA method: (the notation I'm using align...
Given public key $pk$, message $M$ and its signature $\sigma$, is it possible to get another $pk'\not =pk$, $M'$ with the totally same signature $\sigma$? In other word, the following ones are both satisfied: verifySig$(pk,M,\sigma)=1$ and verifySig$(pk',M',\sigma)=1$. I am uncertain whether all signature schemes po...
Can signature be repurposed?
I'm referencing Jason A. Donenfeld's Random number generator enhancements for Linux 5.17 and 5.18 available [here][1]. In summary:- >significant outward-facing change is that /dev/random and /dev/urandom are now exactly the same thing, with no differences between them at all... So entropy is collected at boot, Ch...
I am exploring a modification to ECDSA to produce shorter signatures, even though it compromises security (in a controllable way). My rationale behind this change is in [this discussion](https://crypto.stackexchange.com/questions/110942/creating-a-weak-bls). Here is my new ECDSA method: (the notation I'm using align...
In vitalik's post [here][1] the below is mentioned, > This is the pairing. Mathematicians also sometimes call it a bilinear map; the word “bilinear” here basically means that it satisfies the constraints: * $e(P, Q + R) = e(P, Q) * e(P, R)$ * $e(P + S, Q) = e(P, Q) * e(S, Q)$ Whereas the textbook definition ...
I was reading [this paper](https://web.eecs.umich.edu/~cpeikert/pubs/swifft.pdf), and there, they use the ring $\mathbb{Z}_{\large p}[\alpha]/(\alpha^{\large n}+1)$ for all their operations. And that looks like a construction of finite field $\mathbb{F}_{\large p^{\Large n}}$ as the quotient ring of the polynomial ring...
I was reading [this paper](https://web.eecs.umich.edu/~cpeikert/pubs/swifft.pdf), and there, they use the ring $\mathbb{Z}_{\large p}[\alpha]/(\alpha^{\large n}+1)$ for all their operations. And that looks like a construction of finite field $\mathbb{F}_{\large p^{\Large n}}$ as the quotient ring of the polynomial ring...
>But then I am thinking, since any element $X \in \mathbb{F}_{\large p^{\Large n}}$ can be thought of as a polynomial, can you "evaluate" that polynomial at some point $s \in \mathbb{F}_{\large p}$? I mean obviously you can in the sense that you can just compute $X(s)$: $$\mathbb{Z}_{\large p} \ni X(s) = {\sum_{\large...
I am exploring a modification to ECDSA to produce shorter signatures, even though it compromises security (in a controllable way). My rationale behind this change is in [this discussion](https://crypto.stackexchange.com/questions/110942/creating-a-weak-bls). In my application, the main focus is on keeping the signature...
I'll only address your comment > And in the paper they use $n=2^k$ and $q−1=2n$, which makes $\alpha^n+1$ the cyclotomic polynomial $\Phi_{2n}(\alpha)$ (which makes polynomial multiplication more efficient because Chinese remainder theorem? I'm not too sure), namely I'll explain the last part briefly. This is a ...
I'll only address your comment > And in the paper they use $n=2^k$ and $q−1=2n$, which makes $\alpha^n+1$ the cyclotomic polynomial $\Phi_{2n}(\alpha)$ (which makes polynomial multiplication more efficient because Chinese remainder theorem? I'm not too sure), namely I'll explain the last part briefly. This is a ...
I read the paper "Provable Security Evaluation of Structures against Impossible Differential and Zero Correlation Linear Cryptanalysis" - author: Bing Sun. In this paper proof of theorem 2 mentioned that from 1 difference in input state spreads to all other differences in other state after R_1(P) round, where R_1(P) is...
Why need characteristic matrix positive so that from 1 difference in input state spreads to all other differences in output state after R rounds?
I read the paper "Provable Security Evaluation of Structures against Impossible Differential and Zero Correlation Linear Cryptanalysis" - author: Bing Sun. In this paper proof of theorem 2 mentioned that from 1 difference in input state spreads to all other differences in other state after R_1(P) round, where R_1(P) is...
Alice and Bob have a shared symmetric key k ∈ {0, 1}^256, which Alice uses to identify herself to Bob, who holds a database of usernames and shared keys. The identification protocol they use begins when Alice sends her username, Bob responds with a challenge c ∈ {0, 1}^256, and Alice chooses a response r ∈ {0, 1}^∗...
I was reading [this paper](https://web.eecs.umich.edu/~cpeikert/pubs/swifft.pdf), and there, they use the ring $\mathbb{Z}_{\large p}[\alpha]/(\alpha^{\large n}+1)$ for all their operations. And that looks like a construction of finite field $\mathbb{F}_{\large p^{\Large n}}$ as the quotient ring of the polynomial ring...
I have two statements which I think are correct: 1) $\beta, s$ are unknown. Only $g^\beta$ is known to the prover but not any of $g^{\beta s^i}$ for $i \ge 1$. If the prover is able to find group elements $A$ and $B$ such that $e(A, g^\beta) = e(B, g)$ then the prover knows a field element $a$ such that $A = g^a$...
I am exploring a modification to ECDSA to produce shorter signatures, even though it compromises security (in a controllable way). My rationale behind this change is in [this discussion](https://crypto.stackexchange.com/questions/110942/creating-a-weak-bls). In my application, the main focus is on keeping the signature...
I would like to know how many combinations per second we are able to brute-force today with a powerful server farm. Can someone give me some info on that? Also what would be the rental costs? TIA
I think I roughly understand how the RSA algorithm works. However, I don't understand why we need the $N$, which we use as a modulus, to be $pq$ for some large primes $p, q$. I vaguely know it has something to do with factorization, but I am kind of lost. So, hypothetical questions. - What would happen if the ...
How to find p and q in RSA algorithm in python?
RFC8446 states that: `the full encoded TLSInnerPlaintext MUST NOT exceed 2^14 + 1 octets` It also states: ```length: The length (in bytes) of the following TLSCiphertext.encrypted_record, which is the sum of the lengths of the content and the padding, plus one for the inner content type, plus any expansion added b...
RFC8446 states that: > the full encoded TLSInnerPlaintext MUST NOT exceed 2^14 + 1 octets It also states: > length: The length (in bytes) of the following `TLSCiphertext.encrypted_record`, which is the sum of the lengths of the content and the padding, plus one for the inner content type, plus any expansion a...
PBKDF2 should only be used to generate a larger output than the hash function it uses if the output is used in such a way that it has a flat keyspace. As far as I am aware, XTS does not have a flat keyspace, and the first half of the input is far more sensitive than the second half, which is only the tweak key. Am I co...
I’ve a signature scheme as follow for 1024‒Bits rsa with a 65537 exponent : > 760‒Bits fully_user_controlled_message_content+8 Bits incremental nonce+sha256(fully_user_controlled_message_content+Nonce) So that checking the resulting signature is correct is as follow : * the nonce in the remainder must be ++pre...
I’ve a signature scheme for 1024‒Bits rsa with a 65537 exponent. The signed message is as follow : > 760‒Bits fully_user_controlled_message_content+8 Bits incremental nonce+sha256(fully_user_controlled_message_content+Nonce) So that checking the resulting signature is correct is as follow : * the nonce in the ...
How do I find decryption algorithm and key using a encrypted version of a file and a decrypted version of a file? I have 4 files, 2 encrypted and 2 decrypted, I think the contents are the same if the encrypted one would be decrypted, I'm a noob at this and don't know what to do, so can someone do this for me or help me...
I'm no mathematician but when thinking about block ciphers such as AES I find it much easier to think of them as a mathematical function $f$ (rather than an 'algorithm') such that $c=f(m,k)$ with $c$ the cyphertext, $m$ the plaintext and $k$ the key. When I think about breaking such a cipher the first thing I think ...
I'm no mathematician but when thinking about block ciphers such as AES I find it much easier to think of them as a mathematical function $f$ (rather than an 'algorithm') such that $c=f(m,k)$ with $c$ the cyphertext, $m$ the plaintext and $k$ the key. When I think about breaking such a cipher the first thing I think ...
When directly invoking the ntt and invntt function in Dilithium's code with any polynomial $a \in R_q$, I get a unexpected running result: $NTT(a) \neq iNTT(NTT(a))$. And in the test code of Dilithium(\test\test_mul.c), if want get an correct running, we need multiple the coefficients with -114592 before invoking the...
I’ve a signature scheme for 1024‒bit RSA with a 65537 exponent. The signed message is constructed as follows: > 760‒Bits fully_user_controlled_message_content+8 Bits incremental nonce+sha256(fully_user_controlled_message_content+Nonce) Verification then consists of: * the nonce in the remainder must be ++prev_...
When directly invoking the ntt and invntt function in Dilithium's code with any polynomial $a \in R_q$, I get a unexpected running result: $NTT(a) \neq iNTT(NTT(a))$. And in the test code of Dilithium(\test\test_mul.c), if want get an correct running, we need multiple the coefficients with -114592 before invoking the...
I’m interested in the tradeoffs of signing individual files vs. signing a manifest of cryptographic hashes and file names. Let’s say I do some work that results in a handful of files (10s to hundreds), and then I send all that work out for someone else to look at and maybe pass on to others. Later, I may wish t...
I understand that the secp256k1 key space is 2^1 all the way upto 2^256.. So now let's assume that my private key is not 256 bit and it's only 100 bits **example private key:- 0x000000000000000000000000000000000000000f1c7de58b4064936a6dc50ee8** so now this **037a5952fa338291f2219b451500f13f6a887a023f332937fcd74483ed778...