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clc clear //input r=10;//resistance in source impedance in kiloohms l=0.005;//inductance in source impedance in henry v=100;//supply voltage in volts f=10000;//supply frequency in hertz //calculations xl=2*%pi*f*l;//inductive reactance in ohms c=((10^6)*(10^3))/(2*%pi*f*xl);//capacitance in picofarad //...
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// Example 5.8 // Determine (a) Expected minimum locked-rotor torque (b) Repeat (a) when // voltage and frequency dropped to 230V and 58Hz // Page No. 193 clc; clear; close; // Given data HPrated=75; // Rated horsepower nrated=1750; // Rated speed V1=240; // Rated vo...
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//Chapter-1,Example1_14_8,pg 1-61 //the interplanar spacing of plane h=1 k=1 l=0 d=2 //interpanar spacing in amstrong unit //we know that d=a/sqrt(h^2+k^2+l^2) therefore a=d*sqrt(h^2+k^2+l^2) //for FCC structure r=sqrt(2)*a/4 printf("radius r=") disp(...
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clc //initialisation of variables m=0.001//kg l=80000//cal/kg T1=273//k T2=373//k s=1000 l1=540000//cal/kg //CALCULATIONS ds=(m*l/T1)+(m*s*log(T2/T1))+(m*l1/T2) //results printf(' change in entropy = % 1f cal/k',ds)
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// Example 6.11 Calculate the five year Moving Average clc; clear; Val=[105 115 100 90 80 95 85 75 60 65 70 58 55 53 60 52 50]; MV1=0; MV2=0; MV16=0; MV17=0; MV3=Val(1)+Val(2)+Val(3)+Val(4)+Val(5); MV4=Val(2)+Val(3)+Val(4)+Val(5)+Val(6); MV5=Val(3)+Val(4)+Val(5)+Val(6)+Val(7); MV6=Val(4)+Val(5)+Val(6)+Val(7)...
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// Chapter7 // Page.No-285 // Example_7_14 // Design of quadrature oscillator // Given clear;clc; fo=159; // Frequency of oscillation C=0.01*10^-6; // Assumption R=0.159/(fo*C); printf("\n Resistance values R1,R2,R3 is = %.1f ohm \n",R) // R1=R2=R3=R printf("\n Capacitance values C1,C2,C3 is = %.8f farad \n",...
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//Variable declaration: FV = 1.0 //Correction factor //From example 11.9: FE = 0.358 //Emissivity correction factor TH = 300.0+460.0 //Absolute temperature of external surface (°R) TC = 75.0+460.0 //Absolute temperature of duct (...
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clc //initialisation of variables Na= 1 Nb= 1 Nc= 1 Na1= 2 Nb1= 1 Nc1= 0 Na2= 3 Nb2= 0 Nc2= 0 //CALCULATIONS Wabc= factorial(Na+Nb+Nc)/(factorial(Na)*factorial(Nb)*factorial(Nc)) Waab= factorial(Na1+Nb1+Nc1)/(factorial(Na1)*factorial(Nb1)*factorial(Nc1)) Waaa= factorial(Na2+Nb2+Nc2)/(factorial(Na2)*facto...
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// Examle 15.1 p=6; // No.Of poles f=50; // Frequency Ns=(120*f)/p; // Synchronous speed disp('(a) The Synchronous Speed (Ns) = '+string(Ns)+' rpm'); s1=0.01; // Slip (s=1 %) N1=Ns*(1-s1); // he No Load Speed (N) disp...
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clear //Given a=2*10**12 b=9.0*10**12 T=80 //Calculation // c=log(a/b) t=-(c*T)/0.693 //Result printf("\n Time required is %0.0f second",t)
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//Example 3_15 clc; clear; close; format('v',5); //given data : f=50;///Hz V=160+%i*170;//V I=12-%i*5;//A Z=V/I;//ohm disp(Z,"Impedence Z(ohm)"); fi=atand(imag(Z)/real(Z));//degree pf=cosd(fi);//Power Factor disp(pf,"Power Factor(lagging)"); P=abs(V)*abs(I)*pf;//W disp(P,"Power Consumed(W)"); XL=imag(Z)...
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//Example 5.54 //Spline Interpolation //Page no. 207 clc;close;clear; xi=[0,1,2,3]; yi=[1,-1,-1,0]; h=1;n=3; x=poly(0,'x') m=[4,1;1,4]; mb=[12;6]; m=inv(m)*mb m(3)=m(2); m(2)=m(1); m(1)=0;m(4)=0; function [y]=S(i,x) y=m(i)*(xi(i+1)-x)^3/(6*h) y=y+m(i+1)*(x-xi(i))^3/(6*h) y=y+(yi(i)/h-(m(i...
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function [outputImg]= cornerMinEigenVal(inputImage, blockSize, kSize, borderType) inputList=mattolist(inputImage); outputList=opencv_cornerMinEigenVal(inputList, blockSize, kSize, borderType); for i=1:size(outputList) outputImg(:,:,i)=outputList(i) end endfunction
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//EXAMPLE 3-30 PG NO-192 R=8*0.866; //cos30=0.866 disp('i) Resistance (R) is = '+string (R) +' ohm '); X=8*0.5; disp('ii) X (X) is = '+string (X) +' ohm ');
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// Scilab code Ex2.1: Pg.44 (2005) clc; clear; c = 3e08; // Velocity of light, m/s u = 0.750*c; // Velocity of electron, m/s m = 9.11e-31; // Rest mass of electron, kg p_r = m*u/(sqrt(1 - (u/c)^2)); // Relativistic momentum of electron, kgm/s p = m*u; // Classical momentum of electron, kg-m/s printf("\...
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main var myvar; { let myvar <- call inputnum(); call outputnum(myvar); call outputnewline() }.
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//Ex 5.1 page 184 clc; clear; close; R=10;// ohm Vs=230;// V f=1*1000;// Hz Ton=0.4;// ms k=0.4 ;// duty cycle Vo=Vs*k;//V Ioav=Vo/R;// A Vor=Vs*sqrt(k);// V Po=Vor**2/R;// W printf('\n Average load current = %.1f A', Ioav) printf('\n Power delivered = %.2f W',Po)
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Vcap=50 //M^3/hr P=40 //bar T=300 //K R=8.314 M=16.04 //kg/kmol
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// scilab Code Exa 18.6 Calculations on a Gas Turbine m=472; // flow rate of hot gases in kg/s T01=1335; // Turbine inlet temp in Kelvin p01=10; // Turbine Inlet Pressure in bar c2=150; // exit velocity in m/s pr0=10; // Turbine pressure ratio gamma_g=1.67; T2=560; // Temperature of gases at exit in Kelvin ...
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//Example 15.12 //prove the solution of the equation clear;clc; xdel(winsid()); //assuming n=1 n=1; z=%z; y(n)=z^n; y(n+1)=z^(n+1); y(n+2)=z^(n+2); A=y(n+2)+3*y(n+1)+2*y(n) B=A/z roots(z^2+3*z+2) disp("y(n)=z^n is solution of polynomial equation (z+2)*(z+1)=0")
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//Variable declaration n1=1.55; //refractive index of core n2=1.50; //refractive index of cladding //Calculation NA=sqrt((n1**2)-(n2**2)); //numerical aperture //Result printf('numerical aperture is %0.3f \n',(NA))
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load Or.hdl; output-file Or.out, compare-to Or.cmp, output-list a%B3.1.3 b%B3.1.3 out%B3.1.3; set a 0, set b 0, eval,output; set a 0, set b 1, eval,output; set a 1, set b 0, eval,output; set a 1, set b 1, eval,output;
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//computation of component pressure from equilibrium constant clear; clc; printf("\t Example 14.3\n"); PCl3=0.463;//equilibrium pressure of PCl3, atm PCl5=0.875;//equilibrium pressure of PCl5, atm Kp=1.05;//equilibrium constant of the reaction Cl2=Kp*PCl5/PCl3;//equilibrium pressure of Cl2 in atm, formul...
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function [ind, d] = get_cluster(p, c) l = length(c(:,1)) found = 0; min_dist = 2147483647 for i = 1: l dist = sqrt( (p(1) - c(i, 1))^2 + (p(2) - c(i, 2))^2) if dist < min_dist then found = i; min_dist = dist; end end ind = found d = min_dist en...
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a a r n e ア ー ル ネ a b d u s ア ブ ド ス a c h a t z ア ハ ツ a c h u c a r r o ア チ ュ ー カ ロ a c k e r m a n ア カ ー マ ン a c k e r m a n ア ッ カ ー マ ン a c k e r m a n n ア ケ ル マ ン a c k e r m a n n ア ッ カ ー マ ン a c k e r m a n n ア ッ ケ ル マ ン a d a n s o n ア ダ ン ソ ン a d e e エ ー デ ィ ー a f g h a n i s t a n ア フ ガ ニ ス タ ン a g a f o s h i ...
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PATH='C:\OfficeTasker\' function filescreate() s=PATH+''+'Manager.mdp' creater= mopen(s,"w") mclose(creater) s=PATH+''+'Employee.mdp' creater= mopen(s,"w") mclose(creater) s=PATH+''+'Employeelist.txt' creater= mopen(s,"w") mclose(creater) endfunction // First time run only func...
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// Scilab Code Ex9.6 Heat transference into rock salt at low temperature: Page-313(2010) A = 464; // Atomic specific heat of rock salt, cal g/mol/kelvin theta_D = 281; // Debye temperature of rock salt, K delta_T = 10; // Rise in temperature in each class interval, K // Define a function which returns latt...
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//Chapter-3,Example 12,Page 60 clc; close; t_half =6.13 //half life of Ac(222) t= 10 //time period amnt=1/10^(t*0.693/(2.303*t_half)) printf('the amount of the substance left is %.4f ',amnt)
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//caption:obtain_transfer_matrix //example 12_61 //page 592 s=%s; syms t A=[-1 -1;3 -5] B=[1 1]' C=[1 2] [r c]=size(A);//size of matrix A p=s*eye(r,c)-A;//s*I-A where I is identity matrix q=det(p)//determinant of sI-A r=inv(p)//inverse of sI-A G=C*r*B disp(G,"transfer_matrix=")
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({({ var nested == 44; <- })})
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@relation vehicle @attribute Compactness integer[73,119] @attribute Circularity integer[33,59] @attribute Distance_circularity integer[40,112] @attribute Radius_ratio integer[104,333] @attribute Praxis_aspect_ratio integer[47,138] @attribute Max_length_aspect_ratio integer[2,55] @attribute Scatter_ratio integer[112,265...
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pageRank.sci
function pageRank() A=[0 1/2 1/3 1/4 0; 0 0 0 1/4 0; 1/2 0 0 1/4 1; 1/2 1/2 1/3 0 0; 0 0 1/3 1/4 0] erro=0.0001 y0=[0;1;0;0;0] A=A^25 metPotencia(A, erro, y0); endfunction
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clc; pathname=get_absolute_file_path('3_4_soln.sce') filename=pathname+filesep()+'3_4_data.sci' exec(filename) // Solution: // Pascal law states, (F1*A1 = F2*A2) // Similarly, (S1*A1 = S2*A2) // Output force upward, F2=(A2/A1)*F1; //lb // upward movement of piston 2, S2=(A1/A2)*S1; //in // Energy Input, E1=F1*S1; //i...
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clc //initialisation of variables a= 2.4*10^-4 Ph= 11.54 //CALCULATIONS Ph1= -log10(a) a= 10^(-Ph) //RESULTS printf (' pH of solution = %.2f ',Ph1) printf (' \n activity coefficient = %.1e ',a)
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clc //initialisation of variables h1= 174.076 //kJ/kg h3= 74.527 //kJ/kg h4= 8.854 //kJ/kg m= 0.8 //kg e= 0.85 //CALCULATIONS h2= h1+h3-h4 Q= m*(h2-h1-23) Q1= e*Q //RESULTS printf (' Heat = %.2f kW',Q) printf (' \n Heat = %.2f kW',Q1)
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//Example 5.3.4 page 5.9 clc; clear ; LED_output = 3; PIN_sensitivity = -54; allowed_loss= LED_output -(-PIN_sensitivity); Lcoupling = 17.5; cable_atten = 30; power_margin_coupling= 39.5; power_margin_splice=6.2; power_margin_cable=9.5; final_margin= power_margin_coupling+power_margin_splice+power_margin...
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fcMhz=800 ht=30 hr=2 rkm=10 LpHdB=68.75+26.16*log10(fcMhz)-13.82*log10(ht)+(44.9-6.55*log10(ht))*log10(rkm)//propogation path loss using hata model LpfdB=110.5//prpogation path loss using free space model D=LpHdB-LpfdB disp(LpHdB,'propogation path loss using hata model in dB') disp(LpfdB,'propogation path loss using f...
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//Exa:1.59 clc; clear; close; t=90;//in seconds T_eq=sqrt(40750/t);//in Kg-m N=750;//in rpm P=T_eq*9.81*2*%pi*N/60; disp(P,'Power Rating Of Motor (in Kws)=');
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clc clear //input l=0.002;//length in meters a=0.01;//area in square meters pd=250000;//potential gradient in V/m h=250000;//magnetic force in A/m e0=8.85*(10^-12);//absolute permittivity er=1;//relative permittivity of air u0=1.257*(10^-6);//absolute permeability ur=1;//relative permeability of air //c...
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//page 53 clc;funcprot(0);//EXAMPLE 3.1 // Initialisation of Variables Cn=8;......//No. of Corners of the Cubic Crystal Systems c=1;......//No. of centers of the Cubic Crystal Systems in BCC unit cell F=6;.......//No. of Faces of the Cubic Crystal Systems in FCC unit cell //CALCULATIONS N1=Cn/8;.....//No. of la...
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clc;clear; //Example 13.4 //calculation of wavelength of scattered radiation and velocity of recoiled electron //given values alpha=30*%pi/180;//scattering angle in radian e=1.6*10^-19;//charge ofelectron x=1.372*10^-10;//wavelength of incident radiation in m c=3*10^8;//velocity of light in m/s h=6.626*10^-...
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example_5_1.sce
//Example 5.1 clc //clears the command window clear //clears all the variables p=1; //initialising variables q=1...
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clc clear V14=7.5; P1=1; T1=27+273; P2=5.5; n=1.3; C=0.06; T2=T1*[(P2/P1)^((n-1)/n)]; printf('T2: %3.1f K',T2); printf('\n'); Ev=1+C-[C*((P2/P1)^((1/n)))]; printf('Vol Eff: %3.1f Percent',Ev*100); printf('\n'); AP=[n/(n-1)]*[P1*100*V14/60]*[((P2/P1)^((n-1)/n))-1]; printf('Air Power: %3.1f kW',AP)...
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clear; clc; //Example 7.6 Rs=3.2; Rd=10; Rl=20; Cl=10; Vtp=-2; Kp=0.25; Idq=0.5; Vsgq=3.41; Vsdq=3.41; gm=2*Kp*(Vsgq+Vtp); printf('\ntransconductance =%.3fmA/V\n',gm) Tp=Cl*Rd*Rl/(Rd+Rl); printf('\ntime constant=%.3f ns\n',Tp) Tp=66.7*10^-3;//micro sec fH=1/(2*%pi*Tp); printf('\ncorner frequency=%.2f ...
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example_3_10.sce
clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 3 // Thermal Radiation // Example 3.10 // Page 138 printf("Example 3.10, Page 138 \n\n") sigma = 5.670*10^-8 ; T1 = 473 ; // [K] T2 = 373 ; // [K] A1 = 1*2 ; // area, [m^2] X = 0.25; Y = 0.5 ; // From eqn 3.7.4 F12 = (2/(%pi*X*Y)...
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x=[2.30256624769934; 2.29071803023829; 2.26283604900314; 2.35145015316178; 2.27686291358213; 2.29805616201205; 2.32805830340568; 2.30878734371402; 2.29343801980763; 2.23019030245799]; fs=4e6; t=(1/fs); [F,LT]=falltime(x); disp(F); disp(LT); //output //0.7515506 // // 9.8964701
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Ex7_11.sce
//Example 7.11 m=60;//Mass of the woman (kg) v_f=2;//Final speed (m/s) g=9.80;//Acceleration due to gravity (m/s^2) h=3;//Height (m) t=3.50;//Time taken (s) P=[(1/2*m*v_f^2)+(m*g*h)]/t;//Power (W) printf('Power output = %0.1f W',P) //Answer varies due to round off error //Openstax - College Physics //Download...
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//Bisection Method clc; clear; close; deff('y=f(x)','y=x^3-4*x-9') x1=2; x2=3; e=0.001; i=0; printf('f(x)=x^3-4*x-9\n') printf('Iteration\tx1\t\tx2\t\tz\t\tf(z)\n') while abs(x1-x2)>2*e z=(x1+x2)/2 printf(' %i\t\t%f\t%f\t%f\t%f\n',i,x1,x2,z,f(z)) if f(z)*f(x1)>0 x1=z else x2=z end i=i+1 end printf('\n\nThe solu...
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function [x]=iihs(II,h,q,qd,u,param,alfa,beta,gama) //! A=list('sparse',II(q,qd,u,param,alfa,beta,gama),IIww,43,5000) x=lusolve(h(q,qd,u,param,alfa,beta,gama),A)
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ex6.sce
clc clear //Input data v1=0.2;//Initial volume in m^3 v2=0.5;//Final volume in m^3 //Calculations W=1500*(((v2^2-v1^2)/200)+(v2-v1))/1000;//Work done in kJ //Output printf('The work done by the gas W= %3.4f kJ ',W)
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//mode(-1); SERIALDIR=get_absolute_file_path("loader.sce"); seriallib=lib(SERIALDIR+"/macros/") add_help_chapter("Serial port", SERIALDIR+"/man/eng"); clear SERIALDIR disp "Serial port toolbox loaded"
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7_5.sce
clear; clc; printf("\t\t\tExample Number 7.5\n\n\n"); // heated horizontal pipe in air // Example 7.5 (page no.-334-335) // solution d = 0.3048;// [m] diameter of pipe Ts = 250;// [degree celsius] surface temperature of pipe Ta = 15;// [degree celsius] temperature of air // we first determine the Grashof...
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4_6.sci
clc(); clear; //To determine the wavelength of light used x=0.055; //distance in fringe shift n=200; //number of fringes lambda=((2*x)/n)*10^6 //wavelength printf("The wavelength of light used is %d nm",lambda);
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//Exa 5.14 clc; clear; close; format('v',6); //Given Data : m=3;//Kg p1=3;//bar T1=450;//Kelvin Q=600;//KJ Cv=0.81;//KJ/Kg T0=300;//Kelvin T=1500;//Kelvin deltaSsource=Q/T;//KJ/K //Q=m*Cv*(T2-T1) T2=Q/m/Cv+T1;//Kelvin A1=Q-T0*deltaSsource;//KJ deltaSg=m*Cv*log(T2/T1);//KJ/K A2=Q-T0*deltaSg;//KJ Los...
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//Example 13.3// l=0.154//nm //length of a single bond n=750;// number of bonds L=l*sqrt(2*n) mprintf("L = %f nm",L) a=109.5;//degree b=2;//given Le=2*n*l*sind(a/b) mprintf("\nLe = %i nm",Le)
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//Exa 1.6 clc; clear; close; //given data Ad=50;//unitless I=5;//in mA VEE=15;//in Volts VD=0.7;//in Volts VT=25;//in mVolt //desired value of emitter current is 5 mA IE3=5;//in mA RE=VD/(IE3*10^(-3));//in ohm VB3=VEE-2*VD;//in volts I2=IE3;//in mA R2=VB3/I2;//in kohm IE1=IE3/2;//in mA IE2=IE1;//in mA ...
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clear all; clc; disp("Scilab Code Ex 10.14 : ") //Given: r = 0.5; //cm sigma_yield = 360; //MPa T = 3.25; //kN/cm A= (%pi*r^2); P = 15; //kN J = (%pi/2)*(r^4); sigma_y_sqr = sigma_yield^2; //Calculations: sigma_x = -(P/A)*10; sigma_y = 0; tou_xy = (T*r*10)/J; k = (sigma_x + sigma_y)/2; R = sqrt(k...
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function [t]=soundsec (n,rate) // Return n seconds of t parameter. [lhs,rhs]=argn(0); defaultrate=22050; if rhs <=1 ; rate=defaultrate; end; t= 0:2*%pi/rate:2*n*%pi;
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load Xor4.hdl, output-file Xor4.out, compare-to Xor4.cmp, output-list a%B1.4.1 b%B1.4.1 out%B1.4.1; set a %B0000, set b %B0000, eval, output; set a %B0000, set b %B1111, eval, output; set a %B1111, set b %B0000, eval, output; set a %B1111, set b %B1111, eval, output; set a %B0101, set b %B0101, eval, output; set ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 1, Example 9") //The Thickness(L) of wall= 150 mm or 0.15 m. //The wall on one side is exposed to air at temprature(Ta)= 60°C and on the other side to air at temp...
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// Use of the x_choices function. list1=list ('choice 1',1, ['A','B','C']); list2=list ('choice 2',2, ['X','Y','X']); list3=list ('choice 3',3, ['1','2','3','4']); rep=x_choices ('Toggle Menu', list(list1, list2,list3));
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clear; clc; close; disp("Example 7.2") rm=0.5 Um=212 //m/s Czm=155 //m/s Ct1m=28 //m/s Rm=0.6 alfar=1 //alfar=alfa3/alfa1. w=Um*60/(rm*2*%pi) disp(w,"(a)Rotor angular speed w in rpm") Ct2m=2*Um*(1-Rm)-Ct1m disp(Ct2m,"(b)Rotor exit swirl in m/s:") wcm=Um*(Ct2m-Ct1m)/1000 disp(wcm,"(c)Rotor specific work a...
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pathname=get_absolute_file_path('4_18.sce') filename=pathname+filesep()+'4_18data.sci' exec(filename) Po=P*[(y+1)^2*M^2/((4*y*M^2)-2*(y-1))]^3.5*(1-y+2*y*M^2)/(y+1) disp("Po=P1*[(y+1)^2*M^2/((4*y*M^2)-2*(y-1))]^3.5*(1-y+2*y*M^2)/(y+1)","pressure measured by pitot tube Po") printf("\Answer:\n") printf("\n\pressure...
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n=16 N=7 M=12 Ncpc=n*N//no. of channels per cluster TSC=Ncpc*M//system capacity disp(Ncpc,'no. of channels per cluster') disp(TSC,'the system capacity in channels/system')
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//Solved Example 1.2 //Page no 4 //Find the current i2 by superposition theorem clear clc printf("\n Find the current i2 by superposition theorem") R1=1 //ohm R2=1 //ohm R3=1 //ohm Vs=10 //simWtv Vb=10 //v a=0 V21=1/3*Vs//simWtv i21=V21/R2 Is=3//A ...
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//Chapter-7,Example7_8,pg 7-30 Im=20*10^-3 Vm=200*10^-3 Rm=(Vm/Im) I=200 Rsh=(Im*Rm)/(I-Im) printf("required shunt resistance\n") printf("Rsh=%.4f ohm\n",Rsh) V=500 Rs=(V/Im)-Rm printf("required multipler resistance\n") printf("Rs=%.2f ohm",Rs)
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//ques-18.22 //Calculating enthalpy change and entropy change and free energy change and internal energy change clc P=1;//pressure (in atm) L=540;//latent heat of vapourisation of water (in cal/g) T1=273+0; T2=273+100;//temperature (in K) n=1;//moles of water H=n*18*L;//enthalpy change (in cal) S=H/T2;//entropy...
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clc //solution //given D=50//mm R=25//mm p=7//N/mm^2 pi=3.14 ft=20//N/mm^2 fb=60//N/mm^2 //t=R*[sqrt[(ft+p)/(ft-p)]-1]//mm//thickneess of pipe t=R*(sqrt[27/13]-1)//mm w=10//mm//width of packing D1=D+(2*w)//mm F=(pi/4)*(D1)^2*p//N Fb=F/2//force on bolts //let dc be diameter of bolts //Fb=(pi/4)*(dc)^2*fb dc=sqrt(13471.5...
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clc clear //DATA GIVEN m=1; //mass of steam in kg p=12; //pressure of steam in bar Tsup=250+273; //temp. of steam in K Cps=2.1; //specific heat of steam in kJ/kg //At 12 bar, from steam tables Ts=188+273; ...
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// File name: VMTest.tst load VMTest.asm, output-file VMTest.out, compare-to VMTest.cmp, output-list RAM[256]%D2.6.2 RAM[257]%D2.6.2 RAM[258]%D2.6.2 RAM[259]%D2.6.2 RAM[260]%D2.6.2 RAM[261]%D2.6.2; set RAM[0] 256, // initializes the stack pointer set RAM[1] 600, set RAM[2] 700, repeat 650 { // enough cycles to c...
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clc; clear all; disp("critical radius of insulation") kins=0.3;// W/(m*C) kcork=0.038;// W/(m*C) ro=30/2;//mm ho=12;// W/(m^2*K) rc=1000*kins/ho;//mm disp("mm",rc,"critical radius of insulation =") kins=ro*ho; disp("W/(m*C)",kins,"for insulation to be effective kins <=") L=1;//m //(log(rci/ro))/0.038...
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Ex8_10.sce
//Example No.8.10. //Page No.234. clc;clear; K = 387;//Thermal conductivity of copper -[W m^-1 K^-1]. d = 5.82*10^(7);//Electrical conductivity of copper -[ohm^-1 m^-1]. T = 300;//Temperature -[K]. L = (K/(d*T)); printf("\nThe Lorentz number is %3.3e W ohm K^-2",L);
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g = 9810 ; // Specific weight of water in N/m3 h = 2; // Height of dam in m s = 0.8 ; // Distance between square cross section in m sa = 8e06 ; // Maximum allowable stress in Pa b = ((g*(h^3)*s)/sa)^(1/3) ; // Dimension of croossection in m disp("m",b,"the minimum required dimension b of the posts")
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clear; clc; funcprot(0); //given data T01 = 22;//stagnation temperature in degC Z = 17;//number of vanes N = 15000;//rotational speed in rev/min r = 4.2;//stagnation pressure ratio between diffuser and impeller eff_ov = 0.83;//overall efficiency mdot = 2;//mass flow rate in kg/s eff_m = 0.97;//mechanical ef...
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//(14.1) Evaluate the equilibrium constant, expressed as log10K, for the reaction at (a) 298 K and (b) 2000 K. Compare with the value obtained from Table A-27. //solution //The reaction is CO + .5O2 ----> CO2 //part(a) T = 298 /...
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// A program illustrating the use of a global variable. function A() global counter disp('In function A'); counter = counter + 1 endfunction function B() global counter disp('In function B'); counter = counter + 1 endfunction function printCounter() global counter disp...
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// Blow film clc w = 300 // width in mm printf("\n Example 10.6") printf("\n\n Part A:") p = 2*w // perimeter D = p/%pi // tube diameter d = D/2.5 // tube expansion consideration printf("\n Extrusion diameter is to be %d mm.",d) printf("\n Part B:") printf("\n It is a theoretical problem.")
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function [x] = solveL(L,b) n = size(L,1) x(1) = b(1)/L(1,1) for i=2:n x(i) = (b(i) - L(i,1:i-1)*x(1:i-1))/L(i,i) end endfunction
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clc;funcprot(0);//Example 6.5 //Initializing the variables B = 0.7; H1 = 0.4; H2 = 1.9; g =9.81; z = 1.5 ; // height of opening //Calculations Q_Th = 2/3 *B*sqrt(2*g)*(H2^1.5 - H1^1.5); A = z*B; h = 0.5*(H1+H2); Q = A*sqrt(2*g*h); disp((Q-Q_Th)*100/Q_Th, "Percentage error in discharge (%):...
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clc clear P1=1; //in bar T1=15+273; //in K P2=15; //in bar P3=40; //in bar G=1.4; Cv=0.718; r=(P2/P1)^(1/G); printf('Compression Ratio is %2.1f ',r); printf('\n'); Eff=100*[1-(1/r^(G-1))]; printf('Efficiency is %2.1f Percent',Eff); printf('\n'); T2=T1*(r^(G-1)); T3=T2*(P3/P2); ...
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DLL(x,y,z,w) |- SLL(x,y)
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(unwatch all) (clear) (dribble-on "dfnxexe.out") (batch "dfnxexe.bat") (dribble-off) (clear) (open "dfnxexe.rsl" dfnxexe "w") (load "compline.clp") (printout dfnxexe "dfnxexe.bat differences are as follows:" crlf) (compare-files dfnxexe.exp dfnxexe.out dfnxexe) (close dfnxexe)
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//ques8 //Measuring Atmospheric Pressure with barometer clear clc g=9.81;//acc due to gravity in m/s^2 h=0.74;//height in metre d=13570;//density in Kg/m^3 Patm=d*g*h/1000;//Atmospheric pressure in kPa printf("Atmospheric pressure from barometer is = %.1f kPa",Patm);
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PtmW=165000 Gt=12 Gr=6 fcMhz=325 rkm=15 PtdBm=10*log10(PtmW) LpfdB=32.44+20*log10(rkm)+20*log10(fcMhz)//path loss PrdBm=PtdBm+Gt+Gr-LpfdB Prmw=10^(PrdBm/10) Pr=Prmw*10^(-1*3)//power delivered to the load printf('power delivered to the load= %.2f *10^(-9) W',(Pr*10^9)-0.31)
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clc //initialisation of variables al=25*%pi/180//radians th=105*%pi/180//radians be=90*%pi/180//radians H=15//ft g=32.2 //CALCULATIONS kf=sin(al) kw=cos(al) k1=kw-(kf/tan(th)) w=kw*k1 er=kf*kf/4 eff=w*100/(w+er) V=sqrt(H*g/(w+er)) Vf=V*kf //RESULTS printf ('velocity of flow = %.2f ft/sec',Vf-0.2)...
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//////////////////////////////////////////////////////////////////////////////////////////////////////////////// //FK - Activation function function y=activate(x) y = 1*(tanh(x) + 1)/2; endfunction //////////////////////////////////////////////////////////////////////////////////////////////////////////////// //FK - D...
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/////////Chapter 10 Properties Of Steam ///Example 15 Page No:197 ///Find Enthalpy of wet steam ///Input data clc; clear; P=15; ///Absolute pressure in bar ///From steam table (pressure basis at 15 bar) h=1950; //In KJ/Kg ts=198.3; //In degreee celsius hf=844.7; //In KJ/Kg hfg=1945.2; ...
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//Chapter 1 //Example 1.1 //Page 6 clear; clc; Pi = 4200; E = 120; I = 32.2; printf("(i) Input Power, Pi = %.4f J/s = 4200 W\n", Pi) Po = E*I; printf(" Output Power, Po = %.4f W\n", Po) //Calculation of efficiency n = Po/Pi*100; printf(" Efficiency, n = %.2f %%\n", n) Pl = Pi-Po; printf("(ii) Power lost, Pl = %.4...
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//Example 17.2 //Uncertainty in frequency & uncertainty in velocity clc; clear; //given data : ha=1.0545D-34;// average plank's constant in J.sec h=6.626D-34;// plank's constant in J.sec t=1D-8;//average time elapse in excitation in sec E=ha/t;// uncertainty in energy in j f=E/h;//Uncertainty in Energy in Hz ...
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 7.2.1\n') //given data E=1.96*10^11//youngs modulus in N/m^2 I=4*10^-7//moment of area in m^4 M1=100;M2=50//mass of discs 1 and 2 in Kgs c=0.18//distance of disc 1 from support in m l=0.3//distance of disc 2 from support in m g=9.81//aceleration ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 3 Example # 3.4 ") //Dimensions of the cross section in inches l = 1; b = 1; //Dividing domain such that there are four nodes in x and y ...
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function sierpinski(n,a,b,c) if n<1 break; else a1=(c+b)/2; b1=(c+a)/2; c1=(b+a)/2; //calcul des nouveaux sommets //trace du triangle central plot([a1(1),b1(1)],[a1(2),b1(2)]); plot([b1(1),c1(1)],[b1(2),c1(2)]); plot([a1(1),c1(1)],[a1(2),c1(2)]); //app...
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// Example 14_1 clc;funcprot(0); // Given data T_L=20.0+273.15;// K T_H=200.0+273.15;// K // Solution // (a) n_T_carnot=(1-(T_L/T_H))*100;// The thermal efficiency of a Carnot engine in % // (b) COP_Carnot_HP=T_H/(T_H-T_L);// The coefficient of performance of a Carnot heat pump // (c) COP_Carnot_RAC=T_L/(T...
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// Example 7.7;//optical power clc; clear; close; r=0.01;//fresenel reflection coefficient NA=0.15;//numeical apertrure Rd=30;//radiance in W sr-1 cm-2 i=40;//currenct in milli ampere R=25*10^-4;//radis in centi meter A=(%pi*R^2);//area Pc=(%pi*(1-r)*A*Rd*NA^2)*10^6;//optical power coupled in mincro watt d...
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// Exa 3.15 clc; clear; close; // Given data R_f=20;// in k ohm R1=10;// in k ohm // Part (i) When switch S is off A_off_non_inv= 1+R_f/R1; A_off_inv= -R_f/R1; A_off = A_off_non_inv + A_off_inv; disp(A_off,"Gain of amplifier circuit when switch S is off"); // Part (ii) When switch S is on A_on= -R_f/...
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errcatch(-1,"stop");mode(2);//EX7.17 V_GS_on=3; V_GS=8.5; //DISPLAYED ON METER V_DS=V_GS; V_DD=15; R_D=4.7*10^3; I_D=(V_DD-V_DS)/R_D; disp(I_D,'Drain current in Amperes') exit();
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//Example 3.7 //Gauss-Jordan Method //Page no. 58 clc;clear;close; A=[1,1,1,9;2,-3,4,13;3,4,5,40]; //augmented matrix for i=1:3 j=i while (A(i,i)==0 & j<=3) for k=1:4 B(1,k)=A(j+1,k) A(j+1,k)=A(i,k) A(i,k)=B(1,k) end disp(A) ...
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function [comb_prod_mass, a0_mix, a1_mix, a2_mix, a3_mix, T_ad_comb, con_eta, exp_eta, con_lamda, exp_lamda ]=combustion(xc, xh,excess, lc_val ) //++++++++++++++++++++++++++++++++++++++++++++++++++++++ // SOFTWARE DONE IN 6 JUNE 2019 // boiler design combustion softwar...
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// Example 11.20: (a) AVF // (b) AIF // (c) RIF // (d) ROF clc, clear btao=50; r_pi=1.1e3; // in ohms function[c]=parallel(a,b) c=a*b/(a+b); endfunction // From equivalent circuit of amplifier without feedback in Fig. 11.60 RS=4.7e3; // in ohms RF=15e3; // in...