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clear; clc; d = 9;// inches p = 5000/2240;// lb/in^2 f = 8;// tons/in^2 PR = 0.3;// Poisson's ratio //(i) Maximum principal stress hypothesis: k_limit1 = sqrt((f + p)/(f - p));//k_limit = r1/r2 r_limit1 = k_limit1*0.5*d;//inches printf('The outer radius in case(i), r2 = %.3f inches',r_limit1); //(ii) Maximum principal strain: k_limit2 = sqrt(((f/p - PR)+1)/(f/p - PR -1)); r_limit2 = k_limit2*0.5*d;// inches printf('\n The outer radius in case(ii), r2 = %.3f inches',r_limit2); //(iii) Maximum shear stress: k_limit3 = sqrt(f/(2*p) /((f/(2*p)) - 1)); r_limit3 = k_limit3*0.5*d;// inches printf('\n The outer radius in case(iii), r2 = %.3f inches',r_limit3); //(iv) Maximum strain energy K1 = (f^2 /p^2)/(2*((f^2 /(2*p^2)) - (1+PR))); K2 = K1^2; K3 = ((f^2 /(2*p^2)) - (1-PR))/((f^2 /(2*p^2)) - (1+PR)); k_limit4 = sqrt(K1+sqrt(K2-K3)); r_limit4 = k_limit4*0.5*d;// inches printf('\n The outer radius in case(iv), r2 = %.3f inches',r_limit4); //there are calculation errors in the answer given in text book
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// Exa 8.6 clc; clear; close; //given data omega= 200*%pi;// in radians/seconds f=omega/(2*%pi);// in Hz T=1/f;// in sec T=T*10^3;//in ms Vin= 7;//in volt t1= 1/omega*asin(6/Vin);// in sec t1=t1*10^3;// in ms // The output of the schmitt trigger is at -10 volt t1= T/2+t1;// in ms // The output of the schmitt trigger is at +10 volt t2= 10-t1;// in ms disp(t1,"The output of the schmitt trigger is at -10 volt in ms") disp(t2,"The output of the schmitt trigger is at +10 volt in ms")
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//clc; clear; exec 'constrpoly.sci'; exec 'mcnorm.sci'; t1 = [0,1,2]'; y1 = [1,3,7]'; [A1] = constrpoly(t1); [x1] = mcnorm(A1,y1); plot(t1,A1*x1,'o-b'); plot(t1,y1,'*-r'); legend("result1", "y1"); t2 = [0:0.25:2]'; y2 = [1, 1.7, 1.95, 1.8, 3., 3.6, 4.45, 5.9, 6.6]'; [A2] = constrpoly(t2); [x2] = mcnorm(A2,y2); f = scf() plot(t2,A2*x2,'o-b'); plot(t2,y2,'*-r'); legend("result2", "y2");
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//Exa4.15 clc; clear; close; //given data Vz=15;//in volts Izk=6;//in mA Vout=15;//in Volts Vs=20;//in Volts ILmin=10;//in mA ILmax=20;//in mA disp("the zener current will be minimum i.e. Izk = 6mA when load current is maximum i.e. ILmax = 20mA"); RS=(Vs-Vout)/(Izk+ILmax);//in ohm disp("when the load current will decrease and become 10 mA, the zener current will increase and become 6+10 i.e. 16 mA. Thus the current through series resistance Rs will remain unchanged at 6+20 i.e. 26 mA. Thus voltage drop in series resistance Rs will remain constant. Consequently, the output voltage will also remain constant. ");
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Convergence: Taylor Vortex IMEXOrder2 dt=0.01</description> <executable>IncNavierStokesSolver</executable> <parameters>TaylorVor_dt1.xml</parameters> <files> <file description="Session File">TaylorVor_dt1.xml</file> </files> <metrics> <metric type="L2" id="1"> <value variable="u" tolerance="1e-12">5.95129e-06</value> <value variable="v" tolerance="1e-12">4.9951e-06</value> <value variable="p" tolerance="1e-12">0.000232625</value> </metric> <metric type="Linf" id="2"> <value variable="u" tolerance="1e-12">4.1544e-06</value> <value variable="v" tolerance="1e-12">4.51559e-06</value> <value variable="p" tolerance="1e-12">0.00016244</value> </metric> </metrics> </test>
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// Scilab code Exa6.9.2 : To calculate the w/B ratio for a completely stripped nitrogen to move in a stable orbit : Page 274(2011) E_k = 1200; // Kinetic energy of the proton, MeV q = 7; // Number of proton in nitrogen E_r = 13040 // Rest mass energy of the electron, MeV E = (E_k+E_r)*1.6e-013; // Total energy,j c = 3e+08; // Velocity of light, m/s R_w_B = q*1.6e-019*c^2/E; // Ratio of w/B, m^2/W printf("\nThe ratio of w/B : %4.2e m^2/W ", R_w_B) // Result // The ratio of w/B : 4.42e+007 m^2/W
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pathname=get_absolute_file_path('6_2.sce') filename=pathname+filesep()+'6_2data.sci' exec(filename) F=[-W;M;0;0]; P=EI*[(27/(2*L^3)) (9/(2*L^2)) (6/L^2) -(3/(2*L^2)); (9/(2*L^2)) (6/L) (2/L) (1/L); (6/L^2) (2/L) (4/L) 0; -(3/(2*L^2)) (1/L) 0 (2/L)]; V=inv(P)*F; Sy12= EI*(-(6*V(3)/(L^2))-(12*V(1)/(L^3)) -(6*V(2)/(L*L)));//Sy,12 deff("[M12]=f(x)","M12=EI*(((-6*x/L*L)+(4/L))*V(3) + ((-12*x/L^3)+(6/L^2))*V(1) +((-6*x/L*L)+(2/L))*V(2))"); x=[0:0.05:L]; fplot2d(x,f); xgrid(3); xtitle( 'M12 versus x', ' -x- ', 'M12'); datatipToggle(); printf("\nυ2: %f m",V(1));//v2 printf("\nθ2: %f ",V(2));//θ2 printf("\nθ2: %f ",V(3));//θ1 printf("\nθ2: %f ",V(4));//θ3 printf("\nSy,12: %f",Sy12);//Sy,12
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// Exa 1.19 clc; clear; close; // given : A_p=16 // power gain A_p_Np=log(sqrt(A_p)) // power gain in nepers disp(A_p_Np,"power gain in nepers:")
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// SAMPLE PROBLEM 8/6 clc;funcprot(0); // Given data W=100;// The weight of the piston in lb k=200;// The spring modulus in lb/in c=85;// The damping coefficient in lb-sec/ft a=80;// The top surface area in in^2 omega=30;// rad/s g=32.2;// The acceleration due to gravity in ft/sec^2 p=0.625;// lb/in^2 // Calculation omega_n=sqrt((k*12)/(W/g));// The natural frequency of the system in rad/sec eta=c/(2*(W/g)*omega_n);// The damping ratio F_0=p*a;// lb X=(F_0/(k*12))/((1-(omega/omega_n)^2)^2+(2*eta*omega/omega_n)^2)^(1/2);// The steady-state amplitude in ft phi=atan((2*eta*omega/omega_n)/(1-(omega/omega_n)^2));// The phase angle in rad // x_p=Xsin(omega*t-phi); F_trmax=X*sqrt((k*12)^2+(c^2*omega^2));// The maximum force transmitted to the base in lb printf("\nThe steady-state displacement as a function of time,x_p=%0.5fsin(%2.0ft-(%1.3f))ft \nThe maximum force transmitted to the base,(F_tr)_max=%2.1f lb",X,omega,phi,F_trmax);
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function secanteM(f,xi,tol,imax) //f es la función que se ingresara entre comillas //xi es un punto //tol es la tolerancia //imax es el numero maximo de iteraciones i=1; d=2; printf('+-----------+----------------------+----------------------+\n'); printf('| Iteracion | xi | error |\n'); printf('+-----------+----------------------+----------------------+\n'); printf('| %9d | %20.15f | %20.15f |\n',i,xi,tol); ea(i)=100; while (i<imax) xid=xi+d; x=xi fxi=evstr(f); x=xid fxid=evstr(f); if(abs(ea(i))>=tol) xr=xi-(fxi*(fxid-xi))/(fxid-fxi); ea(i+1)=abs((xr-xi)/xr); xi=xr; X(i)=xr; Y(i)=i; printf('| %9d | %20.15f | %20.15f |\n',i,xi,ea(i+1)); i=i+1; else imax=i; end end plot(X,Y); endfunction
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function [x,y] = RK4(a,b,h,y0) x = a:h:b; n = length(x); y(1) = y0; for i = 2:n k1 = df(x(i-1),y(i-1)); k2 = df(x(i-1) + h/2, y(i-1) + h/2*k1); k3 = df(x(i-1) + h/2, y(i-1) + h/2*k2); k4 = df(x(i),y(i-1) + h*k3); y(i) = y(i-1) + h/6*(k1 + 2*k2 + 2*k3 + k4); end endfunction function z = df(x,y) z = 12-y; endfunction
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clc disp("Example 2.58") printf("\n") disp("Design a voltage regulator using zener diode to meet following specification") printf("Given\n") printf("1 Resistance are in ohms \n 2 Current are in ampere \n 3 voltage sources are in volt\n") //unregulated dc input voltage Vimin=20 Vimax=30 //regulated dc output voltage Vo=10 //minimum zener current Izmin=2*10^-3 //maximum zener current Izmax=100*10^-3 //load current ILmin=0 ILmax=25*10^-3 //load resistance RL=Vo/ILmax //maximum Resistance Rmax=(Vimin-Vo)/(Izmin+ILmax) //minimum resistance Rmin=(Vimax-Vo)/(Izmax+ILmin) //Required resistance R=(Rmax+Rmin)/2 printf("minimum resistance %d ohm \n",Rmin) printf("maximum resistance %d ohm \n",Rmax) printf("required resistance %d ohm \n",R) printf("load resistance %d ohm \n",RLmin)
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//Ex 2.1 clc; clear; close; format('v',5); v1=7;//mV v2=9;//mV Ad=80;//dB CMRR=90;//dB vid=v2-v1;//mV vcm=(v1+v2)/2;//mV Ad=10^(Ad/20);//unitless CMRR=10^(CMRR/20);//unitless vout=Ad*(vid+vcm/CMRR)/1000;//V disp(vout,"Output Voltage(V)");;
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// 08.08.16 function Out=Sfparadata(varargin) Nargs=length(varargin); Fd=varargin(1); Ndu=25 ; Ndv=25; Np=[50,50]; if Nargs>=3 Ndu=varargin(2); Ndv=varargin(3); end; if Nargs>=4 Np=varargin(4); end; Tmp=Sf3data(Fd,Ndu,Ndv,Np); Out=Projpara(Tmp); endfunction
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10_3_soln.sce
clc; pathname=get_absolute_file_path('10_3_soln.sce') filename=pathname+filesep()+'10_3_data.sci' exec(filename) // Solution: // wall thickness, t=(Do-Di)/2; //in // burst pressure, BP=(2*t*S)/Di; //psi // working pressure, WP=BP/FS; //psi // Results: printf("\n Results: ") printf("\n The working pressure of steel tube is %.0f psi.",WP) printf("\n The answer in the program is different than that in textbook. It may be due to no.s of significant digit in data and calculation")
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function [x,y,typ]=sigma_delta(job,arg1,arg2) // Copyright INRIA x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; graphics=arg1.graphics;exprs=graphics.exprs model=arg1.model; while %t do [ok,in_out_num,gbias1,gbias2,fbias,exprs]=getvalue('Set ADC Parameters',.. ['Number of ADC blocks';'Gain Bias 1';'Gain bias 2';'Feedback Bias'],list('vec',1,'vec',-1,'vec',-1,'vec',-1),exprs) if ~ok then break,end if length(gbias1) ~= in_out_num then message('The number of gain biasn that you have entered does not match the number of C4 blocks.'); ok=%f; end if length(gbias2) ~= in_out_num then message('The number of gain biasp that you have entered does not match the number of C4 blocks.'); ok=%f; end if length(fbias) ~= in_out_num then message('The number of feedback biases that you have entered does not match the number of C4 blocks.'); ok=%f; end if ok then model.in=[in_out_num;in_out_num;in_out_num] model.out=in_out_num model.ipar=in_out_num model.rpar = [gbias1;gbias2;fbias] model.state = zeros(2*in_out_num,1) graphics.exprs=exprs; x.graphics=graphics;x.model=model break end end case 'define' then gbias1 = 300e-9 gbias2 = 300e-9 fbias = 300e-9 xx=zeros(2,1) in_out_num =1 model=scicos_model() model.sim=list('sigma_delta',5) model.in=[in_out_num;in_out_num;in_out_num] model.in2=[1;1;1] model.intyp=[-1;-1;-1] model.out=in_out_num model.out2=1 model.outtyp=-1 model.rpar = [gbias1;gbias2;fbias] model.ipar=in_out_num model.state=xx model.blocktype='d' model.dep_ut=[%f %t] exprs=[sci2exp(in_out_num); sci2exp(gbias1) ; sci2exp(gbias2) ; sci2exp(fbias)] gr_i=['txt=''sigma_delta'';';'xstringb(orig(1),orig(2),txt,sz(1),sz(2),''fill'')'] x=standard_define([12 5],model,exprs,gr_i) end endfunction
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clc; clear all; disp("heat flow rate") La=0.03;//m Aa=0.1*0.1;//m^2 kA= 150;//W/(m*C) RthA=La/(kA*Aa); Lb=0.08;//m Ab=0.1*0.03;//m^2 kB= 30;//W/(m*C) RthB=Lb/(kB*Ab); Lc=0.08;//m Ac=0.1*0.07;//m^2 kC= 65;//W/(m*C) RthC=Lc/(kC*Ac); Ld=0.05;//m Ad=0.1*0.1;//m^2 kD= 50;//W/(m*C) RthD=Ld/(kD*Ad); Req=RthB*RthC/(RthB+RthC); Rtotal=RthA+Req+RthD t1=400;// degree C t2=60;// degree C Q=(t1-t2)/Rtotal; disp ("W",Q,"heat transfer = ")
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// Chapter 5 additional Example 1 //============================================================================== clc; clear; // input data // Copper has FCC structure a = 3.6; // lattice parameter of copper in Å // Calculations r = a*sqrt(2)/4; // atomic radius of copper // Output mprintf('Atomic Radius of copper = %3.3f Å',r); //==============================================================================
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//Given that Radius_earth = 6.37 * 10^6 h_alti = 520 * 10^3 //in meter velocity = 7.6 * 10^3 //in m/s converted from km/s mass = 79 //in kg //Sample Problem 6-6a printf("**Sample Problem 6-6a**\n") acce = velocity^2/(h_alti + Radius_earth) printf("The acceleration is equal to %f m/s^2\n", acce) //Sample Problem 6-5b printf("\n**Sample Problem 6-6b**\n") Force_total = mass * acce printf("The net force is equal ro %f N", Force_total)
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clc //initialisation of variables Q= 450 //ft^3/sec k= 0.5 i= 1/2000 C= 105 //ft^1/2/sec //CALCULATIONS d= (((Q*sqrt(2/i))/(2*sqrt(1+k^2-k)*C))^(2/5))*(5.41/7.55) b= d/2 s= d*sqrt(1+k^2) //RESULTS printf (' vertical= %.2f ft',d) printf (' \n horizontal= %.2f ft',s)
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clc; clear; a=[[10,1,1];[2,10,1];[2,2,10]]; b=[12,13,14]; x0=[0,0,0]; for k=1:5000 x=x0; for i=1:3 sump=0; for j=1:3 if i~=j sump=sump+a(i,j)*x(j); end end x0(i)=(b(i)-sump)/a(i,i); end end mprintf("Solution of the equation is (%f,%f,%f)",x(1),x(2),x(3));
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sPLIttER F {} fIlTer CI { } fIlTER EFoO {Not M oR t Or NoT nCD oR WU } q BRAnch w gROUpER a {MODULE XC{ ued >= V YbUx = Sx dELTa 84S } mOduLE diAM{ CN = Q rDeLTa 9533 } modUle O{ } mODULe Et{ } mODUlE I{ W = auX DeLTA 46M } agGRegAte xUm ,vWmt.GWMHn ,D.C } unGrOUper l { } GROUpFilter wi {} mErGEr UO { modULe z { braNches Av } MOdule f { BrANChEs q, B, uMD a s j deLTa 80s OR k S ENpp Or Y Oi uJ deLtA 23S Or f Di d } MoDuLe NJRCb { brancHeS y nOT aQAsOV ( F ( ::fE:6.8.32.213 ), 14, 76.40.201.255 ) } MODULe S { bRaNChES X, FG } exPOrT RR }
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//****************************************************************** // File name: playSignal.sci //****************************************************************** // This program assumes that an IQ data file contains data that is // sampled at 256000S/s. Data segments should be powers of 2 so // that no zero padding is needed for the case that an FFT is run. //****************************************************************** //********************************************************************** // // Name: playSignal // // Purpose: The purpose of this function is to to read a file of // IQ data samples and display the signal and the spectrum in an // animated fashion. // The data stream arrives as I,Q,I,Q.... The data format is // 8-bit 2's complement. // // Calling Sequence: state = playSignal(fileName, // segmentSize, // totalSamples, // dwellTime, // sig) // // Inputs: // // fileName - The name of the rile that contains the IQ samples. // // segmentSize - The number of samples to read each time. The // number of complex samples that are read is segmentSize / 2. // The duration of each segment of complex samples is, // (segmentSize / 2) / sampleRate, // where sampleRate is the system sample rate in samples (complex) // per second. For example, with a sample rate of 256000S/s, and // a segment size of 4096 bytes (8-bit samples), the segment duration // is 2048 / 256000 = 8ms. // // totalSamples - The total number of samples in the file. // // dwellTime - The time, in milliseconds, to pause after each // plot of the magnitude data. // // sig - An indicator of the type of data to display. Valid values // are: // 1 - Display signal magnitude. // 2 - Display magnitude spectrum. // 3 -- Display signal magnitude and magnitude spectrum. // // Outputs: // // None. // //********************************************************************** function playSignal(fileName,segmentSize,totalSamples,dwellTime,sig) // Construct Hanning window. win = window('hn',segmentSize/2); // Convert to microseconds. delay = dwellTime * 1000; // Open the file. fd = mopen(fileName); // Set up the display. scf(1); // Initialize or loop entry. done = 0; while done == 0 // This helps to figure out where, in the file, interesting parts are. filePosition = mtell(fd); printf("%d\n",filePosition); // Grab the next segment of the signal. x = mget(segmentSize,'c',fd); if length(x) == 0 // All data has been read, so bail out. done = 1; else // Separate the in-phase and quadrature components. i = x(1:2:$); q = x(2:2:$); // Compute the magnitude of the signal. m = sqrt(i.*i + q.*q); // Window the data. i = i .* win; q = q .* win; // Form complex vector. z = i + %i*q; // Form frequency domain vector. Z = fft(z,-1); // Place zero frequency at the center. Z = fftshift(Z); select sig case 1 // Display the signal magnitude. title('Signal Magnitude sqrt(i^2 + q^2)'); plot(m); case 2 // Display spectrum magnitude in decibels. title('Power Spectrum, dB'); plot(20 * log10(abs(Z))); case 3 // Display the signal magnitude. subplot(211); title('Signal Magnitude sqrt(i^2 + q^2)'); plot(m); // Display spectrum magnitude in decibels. subplot(212); title('Power Spectrum, dB'); plot(20 * log10(abs(Z))); end // select // Pause for a little bit. xpause(delay); end // Clear the display. clf(1); if filePosition > totalSamples // We're done. done = 1; end // if end // while // We're done with the file. mclose(fd); // We're done with this figure. delete(gcf()); endfunction //******************************************************************* // Mainline code. //******************************************************************* playSignal('yoyo.iq',4096,3000000,500,2); //playSignal('f135_4.iq',4096,3000000,500,1); //playSignal('f120_35.iq',4096,40000000,500,2); //playSignal('f162_425.iq',4096,40000000,500,1); //playSignal('f154_845.iq',4096,40000000,500,1); //playSignal('f90_1.iq',4096,40000000,500,1);
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function [x,y,typ]=MB_INIT_RTU(job,arg1,arg2) x=[];y=[];typ=[] select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1 graphics=arg1.graphics exprs=graphics.exprs model=arg1.model while %t do [ok,device,baud,parity,data,stop,debugMode,exprs]=.. getvalue('Set MB_INIT_RTU block parameters',.. ['Device';'Baud Rate';'Parity';'Data Bits';.. 'Stop Bits';'Debug Mode (No=0/Yes=1)'],.. list('str',1,'vec',1,'str',1,'vec',1,.. 'vec',1,'vec',1),exprs) if ok then model.ipar=[baud;data;stop;debugMode;.. length(device);ascii(device)';.. length(parity);ascii(parity)'] graphics.exprs=exprs x.graphics=graphics x.model=model end break end case 'define' then // default parameters device='/dev/ttyS0' baud=19200 parity='none' data=8 stop=1 debugMode=1 // computational function model=scicos_model() model.sim=list('mb_init_rtu',4) // inputs model.in=[] model.in2=[] model.intyp=1 // outputs model.out=[] model.out2=[] model.outtyp=1 // event ports model.evtin=[] model.evtout=[] // states model.state=[] model.dstate=[] model.odstate=list() // parameters model.ipar=[baud;data;stop;debugMode;.. length(device);ascii(device)';.. length(parity);ascii(parity)'] model.rpar=[] model.opar=list() model.blocktype='d' model.firing=[] model.dep_ut=[%f,%f] model.label='' model.nzcross=0 model.nmode=0 model.equations=list() exprs=[device;sci2exp(baud);parity;sci2exp(data);sci2exp(stop);sci2exp(debugMode)]; gr_i=list(["xstringb(orig(1)+sz(1)*0.1,orig(2)+sz(2)*0.6,[""Modbus""],sz(1)*0.8,sz(2)*0.3,''fill'');";.. "xstringb(orig(1)+sz(1)*0.1,orig(2)+sz(2)*0.1,[""RTU""],sz(1)*0.8,sz(2)*0.4,''fill'');"],8) x=standard_define([2,2],model,exprs,gr_i) x.graphics.id="RTU Connection" end endfunction
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// Exa 5.11 clc; clear; close; // Given data r = 10; Gamma = 1.4; P1 = 1;// in bar P2 = 1 * ((r)^(Gamma));// in bar P3 = 40;// in bar P4 = P3;// in bar T1 = 80;// in degree C T1 = T1+273;// in K T2 = T1 * ((r)^(Gamma-1));// in K T3 = (P3/P2)*T2;// in K T4 = 1700;// in degree C T4 = T4 + 273;// in K Vc= 1;// in m^3(assumed) V4= Vc*T4/T3; V1= 10*Vc;// volume at beginning of compression in m^3 Vs= V1-Vc;// in m^3 PercentageStroke= (V4-Vc)/Vs*100;// in % disp(PercentageStroke,"Percentage of stroke at which heat reception must stop is : ") r= V1/V4; P5= P4/r^Gamma;// in bar disp("Ratio of work done during expansion to that done during compression is ") ratio= (P4*V4-P5*V1)/(P2*Vc-P1*V1); disp(ratio)
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pathname=get_absolute_file_path('16_10.sce') filename=pathname+filesep()+'16_10data.sci' exec(filename) clear function[si]=sing(a,b) if(a<b) then si=0; else si=(a-b); end endfunction deff("[v]=f(z)","v=(1/EI)*(((L*W*z^3)/64) -((W/24)*(sing(z,0.5*L))^4)+((W/24)*(sing(z,0.75*L))^4)-((27*W*z*L^3)/2048))"); funcprot(); for i=1:100*L x0=f((i-1)/100),x1=f(i/100),x2=f((i+1)/100); y1=(x0-x1),y2=(x1-x2); if(y1*y2<0) then P=i/100; P1=f(i/100); printf("\nmaximum deflection: %f m",P1); printf("\nat z= %f m",P); end end z=[0:0.05:L]; fplot2d(z,f); xgrid(3); datatipToggle(); xtitle( 'deflection curve', ' -z- ', '-v-'); printf("\n\nclick on the point to view its coordinate on the plot");
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clc; RC=2*10**3; R3=20*10**3; rbb=200; C1=1000*10**-12; T=0.69*C1*R3; disp('microsec',T*10**6,"T=");
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clc //initialisation of variables p=90//deg h=48//in p1=100//psig P=(1/2*%pi)*h^2*p1*0.7071//lb r=3000/54-31//ft s=9000//psi l=170//in b=6.5*10^-6//ft w=46//ft w1=1000//ft //CALCULATIONS D=(1/4*%pi)*h^2*p1//lb P=[r]*h^2//lb T=%pi*h*(1/4)*s//lb T1=(1/2)*l//tons Del=b*w*w1//ft per //RESULTS printf('the accorance with unless otherwise stated=% f ft per',Del)
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//<wft,wfm,fr>=wfir(ftype,forder,cfreq,wtype,fpar) //<wft,wfm,fr>=wfir(ftype,forder,cfreq,wtype,fpar) //Macro which makes linear-phase, FIR low-pass, band-pass, //high-pass, and stop-band filters //using the windowing technique. //Works interactively if called with no arguments. // ftype :Filter type ('lp','hp','bp','sb') // forder :Filter order (pos integer)(odd for ftype='hp' or 'sb') // cfreq :2-vector of cutoff frequencies (0<cfreq(1),cfreq(2)<.5) // :only cfreq(1) is used when ftype='lp' or 'hp' // wtype :Window type ('re','tr','hm','hn','kr','ch') // fpar :2-vector of window parameters // : Kaiser window: fpar(1)>0 fpar(2)=0 // : Chebyshev window: fpar(1)>0 fpar(2)<0 or // : fpar(1)<0 0<fpar(2)<.5 // wft :Time domain filter coefficients // wfm :Frequency domain filter response on the grid fr // fr :Frequency grid //! //author: C. Bunks date: 12 March 1988 //check arguments of macro call [lhs,rhs]=argn(0); //if macro called with no arguments query user for values if rhs<=0 then, //Query user for filter type and filter length write(%io(2),'Input type of filter to be designed (lp, hp, bp, sb):') ftype=read(%io(1),1,1,'(a2)') write(%io(2),'Input filter length (n=pos. integer):') forder=read(%io(1),1,1); //Select filter type and Query user for cut-off frequencies flag=0; select ftype case 'lp' then write(%io(2),'Input cut-off frequency (0.[frequ[.5):') fl=read(%io(1),1,1); fh=0; case 'hp' then write(%io(2),'Input cut-off frequency (0.[fcut[.5):') fl=read(%io(1),1,1); fh=0; flag=1; case 'bp' then write(%io(2),'Input low freqency cut-off (0.[flow[.5):') fl=read(%io(1),1,1) write(%io(2),'Input high freqency cut-off (0.[flow[fhi[.5):') fh=read(%io(1),1,1) case 'sb' then write(%io(2),'Input low freqency cut-off (0.[flow[.5):') fl=read(%io(1),1,1) write(%io(2),'Input high freqency cut-off (0.[flow[fhi[.5):') fh=read(%io(1),1,1) flag=1; else error('Unknown filter type --- program termination'), end if flag=1 then if forder-2*int(forder/2)=0 then write(%io(2),'*****************************************'); write(%io(2),'Even length hp and sb filters not allowed'); write(%io(2),'---Filter order is being incremented by 1'); write(%io(2),'*****************************************'); forder=forder+1; end end //Query user for window type and window parameters write(%io(2),'Input window type (re,tr,hm,kr,ch):') wtype=read(%io(1),1,1,'(a2)'); if wtype='kr' then, write(%io(2),'Input beta value of kaiser window (beta]0):'); fpar(1)=read(%io(1),1,1); fpar(2)=0; else if wtype='ch' then, write(%io(2),'The Chebyshev window length is:'), write(%io(2),forder), write(%io(2),'Input two values the first giving the maximum'), write(%io(2),'value of the window side-lobe height the second giving'), write(%io(2),'the width of the window main lobe. These two vaules'), write(%io(2),'indicate which of the two Chebyshev window'), write(%io(2),'parameters is to be calculated automatically.'), write(%io(2),'The parameter to be calculated automatically is indicated'), write(%io(2),'by a negative value. The other parameter takes a value'), write(%io(2),'in its appropriate range (i.e., 0[dp or 0[df[.5)'), fpar=read(%io(1),1,2), else fpar=[0 0]; end, end, else, fl=cfreq(1); fh=cfreq(2); end, //Calculate window coefficients [win_l,cwp]=window(wtype,forder,fpar); [dummy,forder]=size(win_l); //Get forder samples of the appropriate filter type hfilt=ffilt(ftype,forder,fl,fh); //Multiply window with sinc function wft=win_l.*hfilt; //Calculate frequency response of the windowed filter [wfm,fr]=frmag(wft,256); //end
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clc pathname=get_absolute_file_path('4_8_4.sce') filename=pathname+filesep()+'484.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") disp("N2 balance") na=basis*xN2/0.79 printf("na=%f mol air",na) disp("Atomic C balance") nc=basis*xCO + basis*xCO2 printf("nc=%f mol C",nc) disp("Atomic O balance") nw=0.21*na*2-basis*(xCO + xCO2*2 + xO2*2) printf("nw=%f mol oxygen",nw) disp("Atomic H2 balance") nh=nw*2 printf("nh=%f mol H2",nh) ratio=nh/nc printf("\n C/H ratio in fuel=%f mol H/mol C",ratio) disp("percent excess air") nO2theoretical=nc + nh/4 printf("nO2 theoretical=%f mol O2",nO2theoretical) nO2fed=0.21*na printf(" \n nO2fed=%f mol O2",nO2fed) percent=(nO2fed-nO2theoretical)*100/nO2theoretical printf("\n percentage excess air=%f excess air",percent)
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//Calculations on Otto cycle clc,clear //Given: r=8 //Compression ratio P1=1,P3=50 //Pressure at 1, 3 in bar T1=100+273 //Temperature at 1 in K m=1 //Air flow in kg R=0.287 //Specific gas constant in kJ/kgK g=1.4 //Specific heat ratio(gamma) //Solution: //Refer fig 2.22 //Point 1 V1=m*R*10^3*T1/(P1*10^5) //Ideal gas equation, Volume at 1 in m^3 //Point 2 P2=P1*r^g //Pressure at 2 in bar V2=V1/r //Volume at 2 in m^3 T2=P2*V2*T1/(P1*V1) //Temperature at 2 in K //Point 3 V3=V2 //Constant volume process, Volume at 3 in m^3 T3=(P3/P2)*T2 //Temperature at 3 in K (Wrong in book) //Point 4 P4=P3*(1/r)^g //Pressure at 4 in bar V4=V1 //Constant volume process, Volume at 4 in m^3 T4=T1*(P4/P1) //Temperature at 4 in K cv=R/(g-1) //Specific heat at constant volume in kJ/kgK ratio=(cv*(T3-T2))/(cv*(T4-T1)) //Ratio of heat supplied to the heat rejected (Round off error) //Results: printf("\n Point 1:\n Pressure = %d bar, Volume = %.4f m^3, Temperature = %d degreeC",P1,V1,T1-273) printf("\n\n Point 2:\n Pressure = %.1f bar, Volume = %.4f m^3, Temperature = %.1f degreeC",P2,V2,T2-273) printf("\n\n Point 3:\n Pressure = %.1f bar, Volume = %.4f m^3, Temperature = %.1f degreeC",P3,V3,T3-273) printf("\n\n Point 4:\n Pressure = %.2f bar, Volume = %.4f m^3, Temperature = %.1f degreeC",P4,V4,T4-273) printf("\n\n Ratio of heat supplied to the heat rejected = %.3f\n\n",ratio) //Textbook answer for T3 is wrong //Round off error in the value of 'ratio'
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//taylor series //example 1.13 //page 16 clc;clear;close; deff('y=f(x)','y=sin(x)'); deff('y=f1(x)','y=cos(x)'); deff('y=f2(x)','y=-sin(x)'); deff('y=f3(x)','y=-cos(x)'); deff('y=f4(x)','y=sin(x)'); deff('y=f5(x)','y=cos(x)'); deff('y=f6(x)','y=-sin(x)'); deff('y=f7(x)','y=-cos(x)'); D=[f(%pi/6) f1(%pi/6) f2(%pi/6) f3(%pi/6) f4(%pi/6) f5(%pi/6) f6(%pi/6) f7(%pi/6)]; S1=0; h=%pi/6; printf('order of approximation computed value of sin(pi/3) absolute eror\n\n'); for j=1:8 for i=1:j S1=S1+h^(i-1)*D(i)/factorial(i-1); end printf('%d %0.9f %0.9f\n',j,S1,abs(sin(%pi/3)-S1)); S1=0; end
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main begin int a; a <= 0; begin print(a); a <= a + 1; end for( ; a < 6 ; ) begin print(a); a <= a + 1; end return a; end
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// RESIDUOS ARX // Calcular o erro de predicao um passo a frente (residuo) entre a saida de // um sistema e a saida prevista pelo modelo ARX, descrito pelo vetor de // parametros theta, para uma entrada u determinada function res=multi_resARX(u1,u2,y,theta,delay) test_parametersUY(u1,y); test_parametersUY(u2,y); test_parameterT(theta,3); test_parameterD(delay); order = size(theta,"r")/3; num_pontos = size(u1,"r"); // Inicializa com zeros (poderia ser dispensado) res = zeros(num_pontos,1); // Simulacao for (i=1:num_pontos) y_sim = 0.0; for (j=1:order) // Parte AR y_sim = y_sim + theta(j,1)*test_zero(y,i-j); // Parte X y_sim = y_sim + theta(j+order,1)*test_zero(u1,i-delay-j); y_sim = y_sim + theta(j+(order*2),1)*test_zero(u2,i-delay-j); end res(i,1) = y(i,1)-y_sim; end // Os primeiros pontos do residuo sao descartados res = res(1+order+delay:num_pontos,1); endfunction // SIMULACAO // // SIMULACAO ARX // Simula a saida de um sistema ARX, descrito pelo vetor de parametros theta, // para uma entrada u determinada // O vetor de erros eh gerado aleatoriamente (normal, media 0.0, desvio padrao sdev) function y=multi_simulARX(u1,u2,theta,delay,sdev) test_parameterU(u1); test_parameterT(theta,3); test_parameterD(delay); test_parameterS(sdev); order = size(theta,"r")/3; num_pontos = size(u1,"r"); // Gera uma semente aleatoria para o gerador de numeros aleatorios semente=getdate("s"); rand("seed",semente); // Gera o vetor de sinais de erro e = sdev*rand(num_pontos,1,"normal"); // Inicializa com zeros (poderia ser dispensado) y = zeros(num_pontos,1); // Simulacao for (i=1:num_pontos) // Ruido dinamico y(i,1) = e(i,1); for (j=1:order) // Parte AR y(i,1) = y(i,1) + theta(j,1)*test_zero(y,i-j); // Parte X y(i,1) = y(i,1) + theta(j+order,1)*test_zero(u1,i-delay-j); y(i,1) = y(i,1) + theta(j+(order*2),1)*test_zero(u2,i-delay-j); end end endfunction // IDENTIFICACAO // // IDENTIFICACAO ARX // Para um conjunto de pontos <u,y>, identifica o melhor sistema ARX com ordem e // tempo de atraso (delay) dados que se adequa aos pontos. Retorna o vetor de parametros // theta e os residuos (erro de predicao um passo a frente) function [theta,res]=multi_identifyARX(u1,u2,y,order,delay) test_parametersUY(u1,y); test_parametersUY(u2,y); test_parameterO(order); test_parameterD(delay); num_pontos = size(y,"r"); num_minimo_pontos = 3*order + delay; if (num_pontos < num_minimo_pontos) then error('The u and y parameters must have a minimal of 3*order+delay points.'); end // Montagem das matrizes da equacao matricial A*theta = B // A = matriz de regressores // theta = vetor de parametros (a ser identificado) // B = vetor com sinais de saida num_equacoes = num_pontos-order-delay; // Inicializa com zeros (poderia ser dispensado) B = zeros(num_equacoes,1); A = zeros(num_equacoes,3*order); // Preenche os valores corretos dos elementos de A e B for (i=1:num_equacoes) for (j=1:order) A(i,j) = y(i+order+delay-j,1); A(i,j+order) = u1(i+order-j,1); A(i,j+(order*2)) = u2(i+order-j,1); end B(i,1) = y(i+order+delay,1); end // Calcula theta pela pseudoinversa: theta = inv(A'*A)*A'*B theta = pinv(A)*B; // Calcula os residuos (erros de predicao) y_pred = A*theta; res = B-y_pred; endfunction /////////////ARMAX///////////////////////////// function res=multi_resARMAX(u1,u2,y,theta,delay) test_parametersUY(u1,y); test_parametersUY(u2,y); //test_parameterT(theta,4); test_parameterD(delay); order = size(theta,"r")/4; num_pontos = size(u1,"r"); // Inicializa com zeros (poderia ser dispensado) res = zeros(num_pontos,1); // Simulacao for (i=1:num_pontos) y_sim = 0.0; for (j=1:order) // Parte AR y_sim = y_sim + theta(j,1)*test_zero(y,i-j); // Parte X y_sim = y_sim + theta(j+order,1)*test_zero(u1,i-delay-j); //segunda aprte X y_sim = y_sim + theta(j+2*order,1)*test_zero(u2,i-delay-j); // Parte MA y_sim = y_sim + theta(j+3*order,1)*test_zero(res,i-j); end res(i,1) = y(i,1)-y_sim; end // Os primeiros pontos do residuo sao descartados res = res(1+order+delay:num_pontos,1); endfunction function y=multi_simulARMAX(u1,u2,theta,delay,sdev) test_parameterU(u1); //test_parameterT(theta,4); test_parameterD(delay); test_parameterS(sdev); order = size(theta,"r")/4; num_pontos = size(u1,"r"); // Gera uma semente aleatoria para o gerador de numeros aleatorios semente=getdate("s"); rand("seed",semente); // Gera o vetor de sinais de erro e = sdev*rand(num_pontos,1,"normal"); // Inicializa com zeros (poderia ser dispensado) y = zeros(num_pontos,1); // Simulacao for (i=1:num_pontos) // Ruido dinamico y(i,1) = e(i,1); for (j=1:order) // Parte AR y(i,1) = y(i,1) + theta(j,1)*test_zero(y,i-j); // Parte X y(i,1) = y(i,1) + theta(j+order,1)*test_zero(u1,i-delay-j); y(i,1) = y(i,1) + theta(j+2*order,1)*test_zero(u2,i-delay-j); // Parte MA y(i,1) = y(i,1) + theta(j+3*order,1)*test_zero(e,i-j); end end endfunction function [theta,res]= multi_identifyARMAX_int(u1,u2,e,y,order,delay) test_parametersUY(u1,y); test_parameterO(order); test_parameterD(delay); if ~iscolumn(e) then error('The e parameter must be a column.'); end if (size(e,"r") ~= size(y,"r")) then error('The e and y parameters must have the same size.'); end num_pontos = size(y,"r"); num_minimo_pontos = 5*order + delay; if (num_pontos < num_minimo_pontos) then error('The u, e and y parameters must have a minimal of 4*order+delay points.'); end // Montagem das matrizes da equacao matricial A*theta = B // A = matriz de regressores // theta = vetor de parametros (a ser identificado) // B = vetor com sinais de saida num_equacoes = num_pontos-order-delay; // Inicializa com zeros (poderia ser dispensado) B = zeros(num_equacoes,1); A = zeros(num_equacoes,4*order); // Preenche os valores corretos dos elementos de A e B for (i=1:num_equacoes) for (j=1:order) A(i,j) = y(i+order+delay-j,1); A(i,j+order) = u1(i+order-j,1); A(i,j+2*order) = u2(i+order-j,1); A(i,j+3*order) = e(i+order+delay-j,1); end B(i,1) = y(i+order+delay,1); end // Calcula theta pela pseudoinversa: theta = inv(A'*A)*A'*B theta = pinv(A)*B; // Calcula os residuos (erros de predicao) y_pred = A*theta; res = B-y_pred; endfunction // IDENTIFICACAO ARMAX function [theta,res]=multi_identifyARMAX(u1,u2,y,order,delay) // Os testes dos parametros serao feitos ao chamar a funcao identifyARX [theta,res] = multi_identifyARX(u1,u2,y,order,delay); residuo = stdev(res); residuo_ant = 2.0*residuo; // Para garantir que execute o laco ao menos uma vez N = 0; while (abs(residuo_ant-residuo)/residuo > 0.01 & N < 30) e_estim = [zeros(order+delay,1) ; res]; // Os testes dos parametros serao feitos ao chamar a funcao identifyARMAX_int [theta,res] = multi_identifyARMAX_int(u1,u2,e_estim,y,order,delay); residuo_ant = residuo; residuo = stdev(res); N = N+1; end endfunction
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clc Cd=0.97; d1=0.28; // m d2=0.14; // m g=9.81; // m/s^2 d=0.05; // difference in mercury level in metre rho=1000; // kg/m^3 rho_m=13600; // kg/m^3 A1=%pi/4*d1^2; A2=%pi/4*d2^2; p_diff=(rho_m-rho)*g*d; h=p_diff/rho/g; Q=Cd*A1*((2*g*h)/((A1/A2)^2-1))^(1/2); disp("Flow rate = ") disp(Q) disp("m^3/s")
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u=3; //mean of distribution of random variable X x=[0,1,2,3,4,5,6]; //values of X in the distribution as x where it is the number of times heads occurs when a coin is tossed six times p=[1/64,6/64,15/64,20/64,15/64,6/64,1/64]; //probabilities of occurrence of each value of X (x) in the distribution such that 1/64 gives the probability of occurrence of no heads at all,6/64 gives that of occurrence of heads for only one time and so on k=0; for i=1:7; k=k+((x(i)-u)^2)*p(i); end disp(k,'Variance of X is') s=sqrt(k); disp(s,'Standard deviation of X is') u=0.75; //mean x=[0,1,2,3]; //values of random variable X as x in the probability distribution of X p=[84/220,108/220,27/220,1/220]; //probability of values in x which appear in distribution table of X g=0; for i=1:4; g=g+((x(i))^2)*p(i); end h=g-(u*u); disp(h,'variance of X is') sd=sqrt(h); disp(sd,'Standard deviation for X')
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// Measure running time of Mult.asm load Mult.asm, output-file MultTime.out, output-list RAM[0]%D2.6.2 RAM[1]%D2.6.2 RAM[2]%D2.6.2 time%S1.5.1; set RAM[0] 2, set RAM[1] 3, set RAM[2] -1; while RAM[2] <> 6 { ticktock; } output; set PC 0, set RAM[0] 17, set RAM[1] 123, set RAM[2] -1; while RAM[2] <> 2091 { ticktock; } output; set PC 0, set RAM[0] 197, set RAM[1] 137, set RAM[2] -1; while RAM[2] <> 26989 { ticktock; } output; set PC 0, set RAM[0] 13, set RAM[1] 2333, set RAM[2] -1; while RAM[2] <> 30329 { ticktock; } output; set PC 0, set RAM[0] 2333, set RAM[1] 13, set RAM[2] -1; while RAM[2] <> 30329 { ticktock; } output; set PC 0, set RAM[0] 8888, set RAM[1] 3, set RAM[2] -1; while RAM[2] <> 26664 { ticktock; } output; set PC 0, set RAM[0] 3, set RAM[1] 8888, set RAM[2] -1; while RAM[2] <> 26664 { ticktock; } output;
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//Exa 4.2 clc; clear; close; // given data disp("As the input impedence of an op-amp circuit is very high & no current will enter the op-amp, hence node voltages at (a) & (b) will be at same potential, let Va=Vb=V"); disp("writing KCL at node (b) we have (6-V)/30+(8-V)/40+(0-V)/30=0"); V=48/11;//in volts disp(V,"Voltage V in Volt is ; "); disp("writing KCL at node (a) we have (3-V)/10+(4-V)/20=(V-Vo)/40"); Vo=-(20-7*V);//in Volts disp(Vo,"Output Voltage of the circuit Vo in Volt is ; ");
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//Section-14,Example-2,Page no.-PC.112 //To calculate the pH in the following cases. clc; V_1=150 //volume of 0.1 NaOH solution(ml) V_2=150 //volume of 0.2 HCl solution(ml) N_1=0.1 //(N) N_2=0.2 //(N) V=V_1+V_2 //Total volume of the solution(ml) m_eq=(V_2*N_2)-(V_1*N_1) //Total milligram equivalents of excess HCl(gm equivalents) N=m_eq/V //(N) C_1=N //Since HCl is a strong acid so[HCl]=[H3O+] (M) pH_1=-log10(C_1) disp(pH_1,'pH of the required solution') pH1=5 C1=10^-5 //[H3O+] (M) pH2=3 C2=10^-3 //[H3O+] (M) C_3=(C1+C2)/2 //[H3O+] (M) pH_2=-log10(C_3) disp(pH_2,'pH of the required solution')
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clc; //e.g 32.7 R1=1*10**3; R2=10*10**3; ACL=R2/R1 disp("Voltage at node A increases from 1V to 4v");
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exec training.sci a_char = ReadImage("characters/single_char 1.png"); path = path + "training_feature_data/"; // dic is defined in training.sci [content_vector, list_rowsum, list_colsum] = read_feature(path, dic); // given_image should be grayscale function [sorted_array_row, sorted_array_col] = compare_features(given_img, feature_content, feature_list_rowsum, feature_list_colsum) // Extract feature of given_image first given_img_bin = gray2inv_bin(given_img); given_img_feature_struct = extract_feature(given_img_bin); scale_vector = []; given_img_fr_size = max(size(given_img_feature_struct.row_vector)); // neglecting 1 in (1, size) given_img_fc_size = max(size(given_img_feature_struct.col_vector)); // neglecting 1 in (1, size) scaling_diff_row = [] * 23 for i = 1 : 23 // change it to 26 when problem for i j l are solved list_rowsum_size = max(size(list_rowsum(i))) // neglecting 1 in (1, size) // make row_vector of each equal if (given_img_fr_size >= list_rowsum_size) then dec_given_img_rv = decimate_vector(given_img_feature_struct.row_vector, list_rowsum_size); // using given_img_feature_struct.row_vector as output doesnt work!! dec_list_rs = list_rowsum(i); else dec_given_img_rv = given_img_feature_struct.row_vector; dec_list_rs = decimate_vector(list_rowsum(i), given_img_fr_size);a// using list_rowsum(i) output doesnt work!! end // Pattern matching FOR ROW size_dec_vectors = max(size(dec_given_img_rv)); // can be replaced with dec_list_rs too since sizes are equal now scaling = [] * size_dec_vectors for j = 1:size_dec_vectors if dec_given_img_rv(j) <> 0 then scaling(j,1) = dec_list_rs(j)/dec_given_img_rv(j); else scaling(j,1) = 1; end end scaling_diff_row(i,1) = i; scaling_diff_row(i,2) = (max(scaling)) - min(scaling); end for i = 1 : 23 // change it to 26 when problem for i j l are solved list_colsum_size = max(size(list_colsum(i))) // neglecting 1 in (1, size) // make row_vector of each equal if (given_img_fc_size >= list_colsum_size) then dec_given_img_cv = decimate_vector(given_img_feature_struct.col_vector, list_colsum_size); // using given_img_feature_struct.row_vector as output doesnt work!! dec_list_cs = list_colsum(i); else dec_given_img_cv = given_img_feature_struct.col_vector; dec_list_cs = decimate_vector(list_colsum(i), given_img_fc_size);// using list_rowsum(i) output doesnt work!! end // Pattern matching FOR ROW size_dec_vectors = max(size(dec_given_img_cv)); // can be replaced with dec_list_rs too since sizes are equal now scaling = [] * size_dec_vectors for j = 1:size_dec_vectors if dec_given_img_cv(j) <> 0 then scaling(j,1) = dec_list_cs(j)/dec_given_img_cv(j); else scaling(j,1) = 1; end end scaling_diff_col(i,1) = i; scaling_diff_col(i,2) = (max(scaling)) - min(scaling); end sorted_array_row = scaling_diff_row; sorted_array_col = scaling_diff_col; endfunction
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//chapter 19 //example 19.13 //page 848 printf("\n") printf("given") Rl=20;Po=2.5;Rd=4;Vr6=1;Vr9=Vr6;Vth=1;gFS=250*10^-3;Vbe=.7; Vp=sqrt(2*Rl*Po) Ip=Vp/Rl Vcc=(Vp+Ip*Rd) vr6=Ip/gFS Vr2=vr6+1 Vce=Vr2; Vce3=1; Vr2=Vcc-Vce Vee=Vcc; Vr3=Vee-Vbe Vr7=Vr2-Vr6 Vr8=Vcc-(-Vee)-Vr6-Vr7-Vr9
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function [J,G]=cost1(v); n = length(v) J = 0 G = [] for i=1:n J = J + (v(i) - 1)^2 gradient = 2*(v(i)-1) G = cat(1, G, gradient) end endfunction function [J,G]=cost2(v); n = length(v) J = 0 G = [] for i=1:n J = J + (v(i) - i)^2 gradient = 2*(v(i)-i) G = cat(1, G, gradient) end endfunction function [J,G]=costR(v); n = length(v) J = 0 G = [] for i=1:(n-1) J = J + ((v(i+1) - v(i)^2)^2 + (v(i)- 1)^2) if i == 1 then gradient = 0 // padding for i=1 elseif i > 1 then gradient = 2*(v(i)-v(i-1)^2)-(4*v(i)*(v(i+1) - v(i)^2)) + (2*(v(i)-1)) end G = cat(1, G, gradient) end G = cat(1, G, 0) // padding when i=N endfunction function [J, G]=costH(v) x = v(1) y = v(2) J = (x^2 + y -2)^2 + (y^2 - 2*x +1)^2 G(1) = (4*x*(x^2+y-2)) - (4*(y^2-2*x+1)) G(2) = (2*(x^2+y-2)) + (4*y*(y^2-2*x+1)) endfunction
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# --- Dynamic Affect: Posttest --- # # Experimental script to run the Posttest scenario # of the Dynamic Affect paradigm. Runs an event-related # presentation of stimuli, which are in 50% of the trials # (counterbalenced over conditions) followed by a # likert-scale evaluation (very pos - very neg). # # Creates a Presentation-logfile and custom logfile. # # Note: to convert edf file to asc type in windows cmd: # edf2asc D:\USERS\Snoek\log\<file>.edf # # Lukas Snoek, Dynamic Affect project (15/16), # Research Master Psychology # --------------- SDL headers --------------- # scenario_type = fMRI; #scenario_type = fMRI_emulation; #scan_period = 2000; pulses_per_scan = 1; pulse_code = 100; default_text_color = 255,255,255; default_background_color = 0,0,0; default_font_size = 25; default_font = "arial"; response_matching = simple_matching; active_buttons = 3; button_codes = 1,2,3; response_logging = log_all; no_logfile = false; begin; # --------------- SDL definitions: objects --------------- # # Introduction text (example) # --------------- SDL definitions: PICTURES --------------- # TEMPLATE "DynAff_SDL_prepost.tem"; # --------------- START OF PCL --------------- # begin_pcl; # Set trk_test in "global_variables.pcl" include "DynAff_globalvariables.pcl"; include "DynAff_PCL_prepost.pcl"; output_file out = new output_file; out.open (filename + "_DynAff_posttest_" + version + ".txt"); # Fix filename string logname = logfile.filename(); string new_name = logname.replace(".log","") + "_" + version + ".log"; logfile.set_filename(new_name); out.print("Cat"); out.print("\t"); out.print("T_abs"); out.print("\t"); out.print("T_rel"); out.print("\t"); out.print("Val"); out.print("\n"); include "DynAff_functions.pcl"; # --------------- EYETRACKING STUFF ---------- # # Some parameter for the eyetracker. # Suffix for .edf filename string filename_suffix = "p"; include "DynAff_tracker_init.pcl" # --------------- Logfile stuff --------------- # introtrial1.present(); introtrial2.present(); # --------------- WAIT FOR PULSE-trial ------------- # pulsetrial.present(); int current_pulse = pulse_manager.main_pulse_count(); loop until ( pulse_manager.main_pulse_count() > current_pulse ) begin end; # timer = start of experiment timer = clock.time(); tracker.send_message("start_exp"); # Write starting time out.print("Start"); out.print("\t"); out.print(string(timer)); out.print("\t"); out.print(string(0)); out.print("\n"); # Wait 5 secs wait_ISI(timer, 5000); # --------------- MAIN EXPERIMENTAL LOOP ------------- # # Loops until all stimuli have been presented. # In 50% of the trials (counterbalenced over conditions), # an evaluation-trial is presented. loop int i = 1 until i > stimuli_condition.count() begin; stimulus_category = stimuli_condition[i]; # random condition is drawn box_position.shuffle(); # Random starting position is draw (as first index, later) exp_bitmap.unload(); # Check condition, set stimulus, and update counter (i_xx) if (stimulus_category == 10) then exp_bitmap.set_filename(face_stim[1]); if face1_eval[i_f1] == 1 then go_eval = 1; else go_eval = 0; end; i_f1 = i_f1 + 1; elseif (stimulus_category == 11) then exp_bitmap.set_filename(face_stim[2]); if face2_eval[i_f2] == 1 then go_eval = 1; else go_eval = 0; end; i_f2 = i_f2 + 1; elseif (stimulus_category == 12) then exp_bitmap.set_filename(face_stim[3]); if face3_eval[i_f3] == 1 then go_eval = 1; else go_eval = 0; end; i_f3 = i_f3 + 1; elseif (stimulus_category == 20) then exp_bitmap.set_filename(house_stim[1]); if house1_eval[i_h1] == 1 then go_eval = 1; else go_eval = 0; end; i_h1 = i_h1 + 1; elseif (stimulus_category == 21) then exp_bitmap.set_filename(house_stim[2]); if house2_eval[i_h2] == 1 then go_eval = 1; else go_eval = 0; end; i_h2 = i_h2 + 1; elseif (stimulus_category == 22) then exp_bitmap.set_filename(house_stim[3]); if house3_eval[i_h3] == 1 then go_eval = 1; else go_eval = 0; end; i_h3 = i_h3 + 1; end; # Present experimental trial! exp_bitmap.load(); start_pic = clock.time(); experimental_event.set_event_code(string(stimulus_category+go_eval*100)); tracker.send_message(string(stimulus_category+go_eval*100)); experimental_trial.present(); # Write to custom logfile out.print(string(stimulus_category)); out.print("\t"); out.print(string(start_pic)); out.print("\t"); out.print(string(start_pic-timer)); out.print("\t"); if go_eval == 0 then out.print("\n"); else run_evaluation(0, 0, 1000, 1); end; wait_ISI(start_pic, stim_dur+ISI); i = i + 1; end; include "tracker_wrapup.pcl" end_trial.present();
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//Example 3.31: Capacitance, power loss, loss resistance and loss angle clc; clear; close; //given data : r2=1500/%pi;// in ohm r3=120;// in ohm C2=0.95*10^-6;//F C1=50*10^-12;// F Cs=round(C1*r2*10^12/r3); f=50; w=round(2*%pi*f); disp(Cs," Cable caacitance,Cs(PF) = ") rs=(r3/(w^2*C1*10)); disp(rs*10^-6,"Parallel loss resistance,rs(M-ohm) = ") del=atand(100*%pi*C2*r2);// disp(del,"loss angle is,(degree)=") v=100;//kV pl=(v*10^3)^2;// disp(pl,"power loss is,=")
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// Scilab Code Ex5.17: Page:305 (2011) clc;clear; a = 1; // For simplicity assume slit width to be unity, unit theta = 1; // For simplicity assume diffraction angle to be unity, unit // As a*sin(theta) = m*lambda, solving for lambdas lambda1 = a*sin(theta); // First wavelength, angstrom lambda2 = a*sin(theta)/2; // First wavelength, angstrom printf("\nlambda1 = %d*lambda2", lambda1/lambda2); // Result // lambda1 = 2*lambda2
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// implementação da Regra Delta para treinamento do adaline // Levantamento do Erro Quatrático Total // aplicação: funções lógicas bipolares // data: 14/04/2021 // autor: Keiji Yamanaka clc; // limpa area de comando clear;// limpa as variáveis da area de trabalho // dados de treinamento // tabela verdade // x1 x2 x=[ 1 1 -1 1 1 -1 -1 -1]; t=[1 1 1 -1]; // gera gráfico dos pontos clf(); // limpa a janela de gráficos title("Erro Quadrático Total"); xlabel("ciclos"); ylabel("Erro quadrático "); da=gda(); da.y_location="origin"; da.x_location="origin"; /// ------treinamento do adaline ------ // inicialização das variáveis e dos parâmetros want=0.5- rand(1,2,"uniform"); // inicialização dos pesos bant=0.5- rand(); teta = 0;// limiar da função de ativação degrau(rede treinada) alfa = 0.1; // taxa de aprendizagem(0<alfa<=1) numciclos=50; // número total de ciclos de treinamento ciclos=0; // conta o número de vezes que os dados foram apresentados // treinar enquanto condição de parada não for satisfeita mprintf("Treinamento do Adaline\n"); while ciclos<=numciclos // limite de treinamento erroquadratico=0; // cálculo do erro quadratico total ciclos=ciclos+1; // conta número de ciclos de treinamento mprintf("ciclos = %d\n", ciclos); for entrada =1:4 // apresenta todos os padrões de entrada yliquido = want(1)*x(entrada,1)+ want(2)*x(entrada,2)+bant; // função de ativação: linear y=yliquido; // cálculo do erro quadrático erroquadratico= erroquadratico+(t(entrada)-y)^2; // atualização dos pesos wnovo(1)= want(1)+alfa*(t(entrada)-y)*x(entrada,1); wnovo(2)= want(2)+alfa*(t(entrada)-y)*x(entrada,2); bnovo=bant+alfa*(t(entrada)-y); // salva os pesos para a próxima atualização want=wnovo; bant=bnovo; end plot(ciclos, erroquadratico, 'r*'); end // ----- teste da rede treinada ------ mprintf('Teste da rede treinada\n\n'); for entrada =1:4 // apresenta todos os padrões de entrada yliquido = wnovo(1)*x(entrada,1)+ wnovo(2)*x(entrada,2)+bnovo; mprintf('t(%d)= %d y(%d): %f\n',entrada, t(entrada),entrada, yliquido); end
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//Use SPICE methods to simulate this amplifier //Example 9.25 page no 281 clear clc R1=10*10^3 //Ω R2=20*10^3 //Ω R3=20*10^3 //Ω Av=-((R2*R3)/(R1*(R2+R3))) printf("\n The value of Av=%0.3f ",Av)
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//Example 11.8(a) clc; //Given values of bridge elements R1=470000; R2=5100; R3=100000; C1=0.01*10^-6; //We Know Balanced bridge equations as Rx=R2*R3/R1; //For the calculation of Capacitance //we have Lx=R2*R3*C1 Lx=R2*R3*C1; disp(Rx,Lx,'The unknown impedence is the series combination of Lx & Rx')
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function f=lagrange(xd,x,y) [mx,nx]=size(x); [my,ny]=size(y); ierror=0; if (nx~=ny)|(mx~=1)|(my~=1), ierror=1; disp( 'data dimension error ') abort end xx=gsort(x); for k=1:nx-1, if xx(k)==xx(k+1), ierror=1; break, end end if ierror~=0, disp( 'data error ') abort end [m,n]=size(xd); f=zeros(m,n); p=zeros(m,n); q=zeros(m,n); w=ones(1 ,nx); for i =1:nx, for j =1:nx, if i~=j , w( i)=w( i )*(x( i)-x( j )) , end end end for i =1:m, for j =1:n, u=find(x==xd(i , j )); if ~isempty(u) , f (i , j)=y(u); else for k=1:nx, p(i , j)=p(i , j)+y(k)/(xd(i , j)-x(k))/w(k); q(i , j)=q(i , j )+1/(xd(i , j)-x(k))/w(k); end f (i , j)=p(i , j )/q(i , j ); end end end endfunction
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rec01.sci
function rec01(fx,x,denominador) if denominador == x then fx=return(fx) end ((x^denominador)/(denominador))+rec01(fx,x,denominador+1) endfunction
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Example2_4.sce
//chapter-2,Example2_4,pg 484 Vp=1//peak input voltage f=50//frequency //R1=R2 //since halfwave rectification is done,integration gives the value Vo=0.5*((2*Vp)/3.14)//output voltage,pi=3.14 printf("output voltage\n") printf("Vo=%.4f V\n",Vo)
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clc; clear; e=1.6*10^-19 //charge in C h=6.63*10^-34 //Plancks constant in J-s c=3*10^8 //velocity of light in m/s n1=1 //first order maxima n2=2 //second order maxima V=50*10^3 //voltage in V tetha=26 //Braggs angle in degree //calculation lambda_min=(h*c)/(e*V) //wavelength in m d=(n1*lambda_min)/(2*sind(tetha)) mprintf("The interplanar spacing is = %1.2e m\n",d) tetha2=asind((n2*lambda_min)/(2*d)) mprintf("The Braggs angle for second order reflection is = %2.1f degree",tetha2) //The answer varies due to round off error.
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clear; clc; printf("\t\t\tProblem Number 3.19\n\n\n"); // Chapter 3 : The First Law Of Thermodynamics // Problem 3.19 (page no. 120) // Solution h1=3450*1000 //Unit:J/kg //Enthalpy of steam when it enters a nozzle h2=2800*1000 //Unit:J/kg //Enthalpy of steam when it leaves a nozzle //V2^2/2=h1-h2; V2=sqrt(2*(h1-h2)); //V2=Final velocity //Unit:m/s printf("Final velocity = %f m/s\n",V2);
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.idc.ac.il/tecs // File name: projects/07/MemoryAccess/PointerTest/PointerTest.tst load PointerTest.asm, output-file PointerTest.out, compare-to PointerTest.cmp, output-list RAM[256]%D1.6.1 RAM[3]%D1.6.1 RAM[4]%D1.6.1 RAM[3032]%D1.6.1 RAM[3046]%D1.6.1; set RAM[0] 256, repeat 450 { ticktock; } output;
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Ex7_1.sce
//Example 7.1, Page Number 296 //Detector sensitivity clc; D=10**9 //in meter square root hertz per watt l=2*(10**-6) //Wavelength in meter A=25*(10**-6) //Area in meter square db=10*(10**3) //Detection Bandwidth in hertz //From equation 7.2 NEP=(sqrt(A*db))/D //NEP is the detector sensitivty in W mprintf("The Sensitivty of the device at given wavelength is:%.0e W",NEP)
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5_4.sce
clc; //page no 182 //prob no. 5.4 //Class C amplifier with carrier o/p power of 100W with efficiency of 70% & with 100% modulation Pc=100;eta=0.7; //Determination of o/p power Po=1.5*Pc; disp('W',Po,'The o/p power with 100% modulation is'); //Determination of supply power Ps=Po/eta; disp('W',Ps,'The value of supply power is'); //Determination of power dissipated Pd Pd=Ps-Po; disp('W',Pd,'Power dissipated is');
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// Example 2.8 page no-49 clear clc L=1400 E_diff=12400/L //eV del_E=2.15 L2=12400/del_E printf("\nE2-E1=%.2f eV\n1850 A° line is from 6.71 eV to 0 eV\nTherefore, second photon must be from %.2f to 6.71 eV.\nLambda=%d A°.",E_diff,E_diff,L2)
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4_5.sce
clc //initialisation of variables p = 17.4 //mm m= 1000 //gms M= 18 //gms n= 2 //moles //CALCULATIONS P= p*((m/M)/((m/M)+n)) P1= p*(n/((m/M)+n)) dp= p-P1 //RESULTS printf (' vapour pressure of solution= %.2f mm',P1)
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Ejercicio3.sci
function Funcion1(x) // Autores: Jorge Zavaleta,Hector E. Gomez Morales // Funcion que grafica la funcion definida en intervalos // // | cos(2x) si 0 <= x <= Pi/4 // f1(x) = | // | 0 si Pi/4 < x <= Pi/2 // // para un conjunto de argumentos dados x //************************************************************************ //-> Entrada // x ( Vector Real) - Define los puntos donde se evaluara y graficara la funcion // //-> Salida // La grafica de f1 //************************************************************************ xdel(winsid()) x = x(:); s = length(x) x1 = x; //Definimos el espacio para los puntos mayores o iguales 0 y menores o iguales a Pi/4 x2 = x; //Definimos el espacio para los puntos mayores a Pi/4 y menores o iguales a Pi/2 y1 = x; //Definimos el espacio para la evaluacion para cos(2x) y2 = x; //Definimos el espacio para la constante 0 c1 = 0; //Contador de puntos en x1 c2 = 0; //Contador de puntos en x2 // Utilizamos la definicion para separar los puntos for i = 1 : s if x(i) <= %pi/4 & x(i) >= 0 then c1 = c1 + 1; x1(c1) = x(i); y1(c1) = cos(2*x(i)); elseif x(i) <= %pi/2 & x(i) > %pi/4 c2 = c2 + 1; x2(c2) = x(i); y2(c2) = 0; end end // Eliminamos los espacios sobrantes con las siguienetes lineas x2(c2+1:s) = []; x1(c1+1:s) = []; y2(c2+1:s) = []; y1(c1+1:s) = []; //Graficamos la funcion if c1 == 0 & c1 == 0 then // No hay puntos del dominio plot2d(0,0,1,rect=[-1 -1 1 1]) str = "$\mbox{Los argumentos no se encuentran en el dominio}[0,pi/2]$" xtitle(str); a = gca() a.title.font_size = 3 a.x_location = "origin" a.y_location = "origin" a.isoview = "on" return elseif c2 == 0 // Solo hay puntos en el intervalo [0,pi/4] plot2d(x1,y1,2) elseif c1 == 0 // Solo hay puntos en el intervalo (pi/4,pi/2] plot2d(x2,y2,2) else // Hay puntos para en los dos intervalos plot2d(x1,y1,2) plot2d(x2,y2,2) end // Damos formato a la grafica // Creamos las etiquetas y titulo str = "$ f1(x) = \left\{\begin{array}{rl}"+... " cos(2x) & \mbox{ si } x \in [0,pi/4] \\"+... " & \\"+... " 0 & \mbox{ si } x \in (pi/4,pi/2] \end{array}\right.$" xtitle(str); //Obtenemos las propiedades de la figura y cambiamos algunos valores a = gca() a.title.font_size = 3 a.x_label.font_size = 3; a.y_label.font_size = 3; a.isoview = "on" endfunction function Funcion2(x) // Autores: Hector E. Gomez Morales // Funcion que grafica la funcion definida en intervalos // // | 10 si -2 <= x <= 0 // f2(x) = | // | -10 si 0 < x <= 2 // // para un conjunto de argumentos dados x //************************************************************************ //-> Entrada // x ( Vector Real) - Define los puntos donde se evaluara y graficara la funcion // //-> Salida // La grafica de f2 //************************************************************************ xdel(winsid()) x = x(:); s = length(x) x1 = x; //Definimos el espacio para los puntos mayores o iguales -2 y menores o iguales a 0 x2 = x; //Definimos el espacio para los puntos mayores a 0 y menores o iguales a 2 y1 = x; //Definimos el espacio para la constante 10 y2 = x; //Definimos el espacio para la constante -10 c1 = 0; //Contador de puntos en x1 c2 = 0; //Contador de puntos en x2 // Utilizamos la definicion para separar los puntos for i = 1 : s if x(i) <= 0 & x(i) >= -2 then c1 = c1 + 1; x1(c1) = x(i); y1(c1) = 10; elseif x(i) <= 2 & x(i) > 0 c2 = c2 + 1; x2(c2) = x(i); y2(c2) = -10; end end // Eliminamos los espacios sobrantes con las siguienetes lineas x2(c2+1:s) = []; x1(c1+1:s) = []; y2(c2+1:s) = []; y1(c1+1:s) = []; //Graficamos la funcion if c1 == 0 & c1 == 0 then // No hay puntos del dominio plot2d(0,0,1,rect=[-1 -1 1 1]) str = "$\mbox{Los argumentos no se encuentran en el dominio}[-2,2]$" xtitle(str); a = gca() a.title.font_size = 3 a.x_location = "origin" a.y_location = "origin" a.isoview = "on" return elseif c2 == 0 // Solo hay puntos en el intervalo [-2,0] plot2d(x1,y1,2) elseif c1 == 0 // Solo hay puntos en el intervalo (0,2] plot2d(x2,y2,2) else // Hay puntos para en los dos intervalos plot2d(x1,y1,2) plot2d(x2,y2,2) end // Damos formato a la grafica // Creamos las etiquetas y titulo str = "$ f2(x) = \left\{\begin{array}{rl}"+... " 10 & \mbox{ si } x \in [-2,0] \\"+... " & \\"+... " -10 & \mbox{ si } x \in (0,2] \end{array}\right.$" xtitle(str); //Obtenemos las propiedades de la figura y cambiamos algunos valores a = gca() a.title.font_size = 3 a.x_label.font_size = 3; a.y_label.font_size = 3; a.isoview = "on" endfunction function Funcion3(x) // Autores: Jorge Zavaleta, Hector E. Gomez Morales // Funcion que grafica la funcion definida en intervalos // // | 4*(x+1) si -1 <= x <= 0 // f3(x) = | // | 4*(x-1) si 0 < x <= 1 // // para un conjunto de argumentos dados x //************************************************************************ //-> Entrada // x ( Vector Real) - Define los puntos donde se evaluara y graficara la funcion // //-> Salida // La grafica de f3 //************************************************************************ xdel(winsid()) x = x(:); s = length(x) x1 = x; //Definimos el espacio para los puntos mayores o iguales -1 y menores o iguales a 0 x2 = x; //Definimos el espacio para los puntos mayores a 0 y menores o iguales a 1 y1 = x; //Definimos el espacio para la evaluacion 4*(x+1) y2 = x; //Definimos el espacio para la evaulacion 4*(x-1) c1 = 0; //Contador de puntos en x1 c2 = 0; //Contador de puntos en x2 // Utilizamos la definicion para separar los puntos for i = 1 : s if x(i) <= 0 & x(i) >= -1 then c1 = c1 + 1; x1(c1) = x(i); y1(c1) = 4*(x(i)+1); elseif x(i) <= 1 & x(i) > 0 c2 = c2 + 1; x2(c2) = x(i); y2(c2) = 4*(x(i)-1); end end // Eliminamos los espacios sobrantes con las siguienetes lineas x2(c2+1:s) = []; x1(c1+1:s) = []; y2(c2+1:s) = []; y1(c1+1:s) = []; //Graficamos la funcion if c1 == 0 & c1 == 0 then // No hay puntos del dominio plot2d(0,0,1,rect=[-1 -1 1 1]) str = "$\mbox{Los argumentos no se encuentran en el dominio}[-1,1]$" xtitle(str); a = gca() a.title.font_size = 3 a.x_location = "origin" a.y_location = "origin" a.isoview = "on" return elseif c2 == 0 // Solo hay puntos en el intervalo [-1,0] plot2d(x1,y1,2) elseif c1 == 0 // Solo hay puntos en el intervalo (0,1] plot2d(x2,y2,2) else // Hay puntos para en los dos intervalos plot2d(x1,y1,2) plot2d(x2,y2,2) end // Damos formato a la grafica // Creamos las etiquetas y titulo str = "$ f3(x) = \left\{\begin{array}{rl}"+... " 4*(x+1) & \mbox{ si } x \in [-1,0] \\"+... " & \\"+... " 4*(x-1) & \mbox{ si } x \in (0,1] \end{array}\right.$" xtitle(str); //Obtenemos las propiedades de la figura y cambiamos algunos valores a = gca() a.title.font_size = 3 a.x_label.font_size = 3; a.y_label.font_size = 3; a.isoview = "on" endfunction function Funcion4(x) // Autores: Jorge Zavaleta, Hector E. Gomez Morales // Funcion que grafica la funcion definida en intervalos // // | ln(-x) si -Infinito < x < -1 // f4(x) = | x^2 - 1 si -1 <= x <= 1 // | ln(x) si 1 < x < Infinito // // para un conjunto de argumentos dados x //************************************************************************ //-> Entrada // x ( Vector Real) - Define los puntos donde se evaluara y graficara la funcion // //-> Salida // La grafica de f3 //************************************************************************ xdel(winsid()) x = x(:); s = length(x) x1 = x; //Definimos el espacio para los puntos menores a -1 x2 = x; //Definimos el espacio para los puntos mayores o iguales a -1 y menores o iguales a 1 x3 = x; //Definimos el espacio para los puntos mayores a 1 y1 = x; //Definimos el espacio para la evaluacion ln(-x) y2 = x; //Definimos el espacio para la evaluacion x^2-1 y3 = x; //Definimos el espacio para la evaluacion ln(x) c1 = 0; //Contador de puntos en x1 c2 = 0; //Contador de puntos en x2 c3 = 0; //Contador de puntos en x3 // Utilizamos la definicion para separar los puntos for i = 1 : s if x(i) < -1 then c1 = c1 + 1; x1(c1) = x(i); y1(c1) = log(-x(i)); elseif x(i) <= 1 & x(i) >= -1 c2 = c2 + 1; x2(c2) = x(i); y2(c2) = (x(i)^2)-1; else c3 = c3 + 1; x3(c3) = x(i); y3(c3) = log(x(i)) end end // Eliminamos los espacios sobrantes con las siguienetes lineas x3(c3+1:s) = []; x2(c2+1:s) = []; x1(c1+1:s) = []; y3(c3+1:s) = []; y2(c2+1:s) = []; y1(c1+1:s) = []; if c1 > 0 plot2d(x1,y1,2) end if c2 > 0 plot2d(x2,y2,2) end if c3 > 0 plot2d(x3,y3,2) end // Damos formato a la grafica // Creamos las etiquetas y titulo str = "$ f4(x) = \left\{\begin{array}{rl}"+... " ln(-x) & \mbox{ si } x \in [-\infty,-1] \\"+... " & \\"+... " ln(x) & \mbox{ si } x \in (1,\infty] \end{array}\right.$" xtitle(str); //Obtenemos las propiedades de la figura y cambiamos algunos valores a = gca() a.title.font_size = 3 a.x_label.font_size = 3; a.y_label.font_size = 3; a.isoview = "on" endfunction // Script para utilizar la funciones 1, 2, 3 y 4 // Interfaz en consola opc = 'n' while opc ~= 's' clc opc = input('Indique que funcion (1..4) quiere graficar: ') while opc ~= 1 & opc ~= 2 & opc ~= 3 & opc ~= 4 disp('') disp('Opcion desconocida. Responda solamente 1, 2, 3 o 4') opc = input('Indique que funcion (1..4) quiere graficar: '); end disp('Evaluacion de la funcion') disp('') liminf = input('Indique el valor inferior del intervalo de graficacion: ') disp('') limsup = input('Indique el valor superior del intervalo de graficacion: ') disp('') np = input('Indique el numero de puntos en el intervalo de graficacion: ') disp('') x = linspace(liminf,limsup,np) select opc case 1 Funcion1(x) case 2 Funcion2(x) case 3 Funcion3(x) case 4 Funcion4(x) end disp('La funcion se evaluo correctamente') disp('') opc = input('¿Quieres salir? (s/n) ','s'); if opc == 's' then disp('El script se ejecuto satisfactoriamente') end end
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//To determine the diversified demand //Page 47 clc; clear; TCDi=[9,9,9,9,9,9]; //Load for each house all in kilowatt DFi=0.65; //Demand factor Fd=1.1; //Diversity factor Dg=sum(TCDi)*DFi/Fd; printf('The diversified demand of the group on the distribution transformer is %g kW\n',Dg)
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//Example 5.16, page no-209 clear clc bw=3.2 // voice channel band limited frequency in kHz r=1.2 //1.2 times the Nyquist rate n=24 //no of voice channel b=8 // 8-bit PCM sr=2*bw*r p=10^6/(sr*10^3) N=(n*b)+1 bit_d=p/N bit_d=ceil(bit_d*1000)/1000 tr=1/bit_d printf("Number of bits in each frame = %.0f \n Bit duration = %.3f micro second \n Transmission rate = %.3f Mbps",N,bit_d,ceil(tr*1000)/1000)
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//value// s=%s; sys1=syslin('c',(s+1)/(s+4)); evans(sys1,100) printf("rootlocus begins at s=-4 & ends at s=-1")
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clc A = [1 0 1; 1/2 sqrt(3)/2 1; -1/2 sqrt(3)/2 1; 1 0 1; -1/2 -sqrt(3)/2 1; 1/2 -sqrt(3)/2 1] y = [1 1.6 1.4 0.6 0.2 0.8]' disp(A, "A") disp(y, "y") [Q R] = qr(A) R = R(1:3,:) Q = Q(:,1:3) disp(Q, "Q") disp(R, "R") c = inv(R)*Q'*y disp(c,"c")
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// Exa 5.9 format('v',6) clc; clear; close; // Given data V_G= 1.5;// in V V_P= -3;// in V R_S= 750;// in Ω R_D= 1800;// in Ω I_DSS= 6*10^-3;// in A V_DD= 18;// in V // V_GS= V_G-I_D*R_S // I_D= I_DSS*(1-V_GS/V_P)^2 or I_DSS*(1-(V_G-I_D*R_S)/V_P)^2 //I_D^2*R_S^2+I_D*(2*R_S*(V_P-V_G)-V_P^2/I_DSS)+(V_P-V_G)^2 A= R_S^2; B=(2*R_S*(V_P-V_G)-V_P^2/I_DSS); C=(V_P-V_G)^2; // Evaluating the value of I_D by using polynomial I_D= [A B C] I_D= roots(I_D);// in A I_D= I_D(2);// in A I_DQ= I_D;// in A V_DS= V_DD-I_D*(R_D+R_S);// in V V_DSQ= V_DS;// in V disp(I_DQ*10^3,"The value of I_DQ in mA is : ") disp(V_DSQ,"The value of V_DSQ in volts is : ")
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clear //Given P_Max = 10 //N - the maximum distribution in a triangular distribution L = 3 //mt the total length of force distribution L_X = 5 //mt - the horizontal length of the rod //calculations F_y = P_Max*L*0.5 //N - The force due to triangular distribition L_com = 2*L /3 //mt - the resultant force acting as a result of distribution acting position //F_X = 0 forces in x directions R_A_X = 0 // since there are no forces in X-direction R_B_X = 0 //M_A = 0 momentum at point a is zero //F_y*L_com - R_B_Y*L_X = 0 R_B_Y = F_y*L_com/L_X //M_B= 0 momentum at point b is zero //- R_A_Y*L_X = F_y*(L_X-L ) R_A_Y = - F_y*L/L_X printf("The X,Y components of reaction force at A is %0.3f,%0.3f N",R_A_X,R_A_Y) printf("\n The X,Y components of reaction force at B is %0.3f,%0.3f N",R_B_X,R_B_Y)
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FOSSEE/Scilab-TBC-Uploads
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Ch2_2_66.sce
clc disp("Example 2.66") printf("\n") disp("Calculate the effect of a 10% variation supply voltage on diode current") printf("Given\n") //input voltage Vi=25 //output voltage Vo=10 //test current(lies b/w Izmin & Izmax) Izt=20*10^-3 //load current(assume zero, no load operation) IL=10^-3 //select R such that Iz=Izt //series resistance R=(Vi-Vo)/(Iz+IL) //maximum input voltage Vimax=25+2.5 //minimum input voltage Vimin=25-2.5 //ciruit current I1=(Vimax-Vo)/R //zener current when Vimax Izmax=I1-IL //cicuit current when Vimin I2=(Vimin-Vo)/R //zener current when Vimin Izmin=I2-IL printf("circuit current when Vimax is %f ampere\n",I1) printf("zener current when Vimax is %f ampere\n",Izmax) printf("circuit current when Vimin is %f ampere\n",I2) printf("zener current when Viin is %f ampere\n",Izmin)
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2018-10-26T06:57:45
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sce
Ex16_2.sce
//Example 16.2 clc; syms z n; x1=(2^n); x2=(3^n); X1=symsum(x1*(z^-n),n,0,%inf); X2=symsum(x2*(z^-n),n,-%inf,0); X=X1+X2; disp(X,"ans=")
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/Toolbox Test/isstable/isstable1.sce
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deecube/fosseetesting
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2016-09-27T05:12:48
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sce
isstable1.sce
b=[1 2 3 4 5]; a=[0.1 0.2 0.3 1.4 0.5]; flag=isstable(b,a); disp(flag); //output // unstable system // // 0.
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jere1882/Numerical-Analysis-Assignments
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sce
jacobi.sce
function x = jacobi(A, b, x, maxit) n=size(A, 1) for k=1:1:maxit for i=1:1:n sumatoria=0 for j=1:n if (j<>i) then sumatoria=sumatoria+A(i,j)*x(j) end x(i)=1/A(i,i) * (b(i) - sumatoria) end end end endfunction
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/2141/CH9/EX9.2/Ex9_2.sce
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FOSSEE/Scilab-TBC-Uploads
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sce
Ex9_2.sce
clc //initialisation of variables p1=1//lbf/in^2 p2=600//lbf/in^2 T=800//F v=0.01614//lbm Wp=v*(p2-p1)*144/778//Btu/lbm h1=69.70 h2=h1+Wp//Btu/lbm h3=1407.7//lbm s3=1.6343//lbm h4=913.3//lbm Wt=h3-h4//Btu/lbm Wnet=Wt-Wp//Btu/lbm qH=h3-h2//Btu/lbm //CALCULATIONS N=Wnet/qH*100//per-cent qL=h4-h1//Btu/lbm Wnet=qH-qL//Btu/lbm //RESULTS printf('The cycle efficiency=% f Btu/lbm',Wnet)
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3_10.sce
//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 3.10 //calculation of velocity of the swimmer with respect to ground //given data vsr=4//velocity(in km/h) of the swimmer with respect to water vrg=3//velocity(in km/h) of the river water with respect to ground //calculation vsg=sqrt((vsr*vsr)+(vrg*vrg));//formula for relative velocity vsg = vsr + vrg theta=atand(4/3); printf('the velocity of the swimmer with respect to ground is %f km/h and angle made by him with X axis is %f degree',vsg,theta);
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Ex4_10_2.sce
clear clc Pt=747.3;//toatal pressure in torr PB=638.6;//vapour pressure of water PA=Pt-PB;//vapour pressure of liquid WA=1.27;//in gm WB=1;//in gm MB=18;//molar mass of water in gm/mol MA=(WA/WB)*((PB*MB)/PA);//molar mass of liquid in gm/mol printf('MA=%.1f gm/mol',MA) //page 192
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example_10_20.sce
clear; clc; disp("--------------Example 10.20---------------") n=21; // compute one's complement bin=dec2bin(n); s=strsplit(bin,1); a=bin2dec(s(1)); b=bin2dec(s(2)); f=a+b; complement=dec2bin(f,4); //1's complement dec_complement=bin2dec(complement); // convert 1's complement to decimal printf("The number %d in ones complement arithmetic using only four bits is %s or %d.",n,complement,dec_complement); // display result
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psdlab/life-in-time-values-and-personality
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~BivLCM-SR-bfi_o_vrt_col-PLin-VLin.tst
ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.248158D+00 2 0.137016D-03 0.213689D-02 3 -0.541331D-02 -0.122656D-02 0.335735D+00 4 -0.147708D-02 -0.236240D-04 -0.351354D-02 0.280073D-02 5 0.114809D-02 -0.684638D-04 -0.876461D-03 -0.979890D-04 0.405635D-02 6 0.410475D-03 0.836414D-04 0.115789D-03 0.556662D-04 -0.185777D-03 7 0.738979D-03 0.103699D-03 -0.137514D-03 0.150907D-03 -0.141102D-03 8 0.685099D-03 0.135640D-03 0.207665D-03 0.353688D-04 -0.173258D-03 9 -0.453383D+00 0.102946D-01 0.219623D-01 0.382260D-02 -0.138953D-02 10 -0.218521D+00 0.566623D-03 0.818049D-01 -0.106007D-01 0.157679D+00 11 -0.154364D+00 0.306929D-01 -0.186291D+00 0.318239D-01 0.332624D-01 12 -0.263392D+00 0.405299D-02 -0.131725D+01 0.547152D-01 -0.174982D-01 13 0.175732D-01 -0.181273D-02 0.298141D-01 0.272514D-02 -0.108417D-01 14 0.818453D-01 -0.302230D-02 -0.318762D+00 0.107285D-01 -0.386234D-01 15 -0.843181D+00 -0.427395D-01 -0.322595D+00 -0.200825D-02 -0.118221D+00 16 0.229517D-02 -0.934233D-02 0.904011D-02 -0.193944D-02 0.251368D-03 17 -0.530762D-02 0.735102D-04 -0.165700D-02 0.276151D-03 -0.279489D-03 18 -0.553471D+00 -0.450076D-01 0.187446D+00 -0.327213D-01 0.581522D-01 19 -0.123799D+00 -0.213035D-02 0.576355D-01 -0.321626D-02 0.447434D-02 20 -0.155386D+00 -0.132684D-01 -0.329910D+01 -0.281953D-01 0.934988D-01 21 0.141238D+00 -0.120603D-02 -0.387589D-01 0.333481D-02 -0.325967D-03 22 0.690767D-03 0.335222D-03 0.229629D-05 0.334770D-03 -0.444538D-03 23 0.176236D-01 0.846092D-03 -0.181173D-01 -0.127056D-01 0.105288D-02 24 0.144160D-02 0.264450D-03 0.445954D-02 -0.407614D-03 -0.266290D-03 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 0.805206D-03 7 0.828872D-03 0.381433D-02 8 0.175116D-03 -0.102238D-03 0.263212D-02 9 0.147415D-02 -0.109019D-01 0.433469D-02 0.236613D+02 10 0.656674D-03 -0.227851D-02 -0.379630D-02 -0.144489D+01 0.140387D+02 11 0.117295D-02 -0.970246D-02 0.339855D-01 0.455413D+01 0.128819D+01 12 -0.655352D-03 0.574085D-01 -0.463409D-01 0.995922D+00 0.168836D+01 13 0.539708D-01 0.121623D+00 0.494889D-02 -0.642455D+00 0.248180D+00 14 0.373592D-01 0.235718D-01 0.241757D+00 0.238536D+00 -0.376519D+00 15 -0.132763D-03 0.456371D-01 0.233653D-01 0.388558D+01 -0.486477D+01 16 -0.103610D-02 0.341200D-03 -0.134257D-02 0.444459D+00 -0.514389D-01 17 -0.104432D-03 -0.313105D-03 -0.398445D-03 -0.986915D-01 -0.190295D-01 18 -0.502373D-01 -0.703896D-01 -0.549569D-01 -0.268048D+01 0.378924D+01 19 -0.132894D-01 0.184589D-02 -0.855516D-03 0.224106D+00 -0.742582D-01 20 -0.991459D-02 0.749188D-01 -0.159363D+00 -0.370553D+01 0.443134D+01 21 0.110025D-01 -0.489942D-02 -0.177297D-02 -0.165002D+00 0.374166D+00 22 0.333174D-04 -0.129839D-03 0.276256D-03 0.903775D-02 -0.266321D-01 23 0.895198D-03 0.981896D-03 0.120615D-02 -0.189085D-01 0.112169D+00 24 -0.771172D-04 -0.600150D-03 -0.149326D-03 0.268214D-01 -0.323894D-01 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 0.228193D+02 12 0.283870D+01 0.897762D+02 13 -0.317588D+01 0.248210D+01 0.105330D+02 14 0.223773D+01 -0.251943D+01 0.218449D+01 0.542910D+02 15 -0.269796D+01 -0.422083D+01 0.139946D+01 0.654653D+00 0.167032D+03 16 -0.559230D-01 0.125920D+00 0.680864D-01 -0.274591D-01 0.184581D+01 17 -0.151980D-01 0.647600D-01 -0.724571D-02 -0.107651D-01 -0.821102D+00 18 -0.175917D+01 -0.598614D+00 -0.319510D+01 -0.577157D+01 0.248851D+02 19 0.162143D+00 -0.894019D+00 -0.633892D+00 0.252070D+00 0.155646D+01 20 -0.380477D+01 -0.882847D+00 0.220799D+01 -0.202413D+02 0.172496D+02 21 -0.229993D+00 0.826022D+00 0.466174D+00 -0.464849D+00 -0.973925D+00 22 -0.706594D-02 0.347583D-02 -0.208592D-02 0.153267D-01 -0.133426D+00 23 -0.701905D-01 -0.407193D+00 0.622270D-01 0.296676D+00 0.581095D+00 24 0.993796D-02 -0.103361D+00 -0.252466D-01 -0.715577D-01 -0.969407D-01 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 0.255371D+00 17 -0.151214D-01 0.907967D-02 18 0.372003D+00 -0.138481D+00 0.150999D+03 19 0.192090D-01 -0.907840D-02 0.279041D+01 0.311524D+01 20 0.734087D+00 -0.961344D-01 0.383775D+02 0.388616D+01 0.427396D+03 21 0.340438D-01 -0.145272D-02 0.117242D+01 -0.289862D+01 -0.350576D+01 22 -0.436411D-02 0.124008D-02 -0.703486D+00 -0.906519D-02 -0.153401D+00 23 0.355713D-01 -0.720321D-02 -0.500637D+00 -0.205721D-01 0.380882D+01 24 -0.767808D-02 0.800656D-03 -0.824756D-01 -0.103948D-01 -0.200219D+01 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 0.355792D+01 22 -0.301228D-01 0.667230D-02 23 0.148237D-01 -0.247949D-02 0.518951D+00 24 -0.126847D-02 -0.151115D-03 -0.332918D-01 0.197490D-01 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 1.000 2 0.006 1.000 3 -0.019 -0.046 1.000 4 -0.056 -0.010 -0.115 1.000 5 0.036 -0.023 -0.024 -0.029 1.000 6 0.029 0.064 0.007 0.037 -0.103 7 0.024 0.036 -0.004 0.046 -0.036 8 0.027 0.057 0.007 0.013 -0.053 9 -0.187 0.046 0.008 0.015 -0.004 10 -0.117 0.003 0.038 -0.053 0.661 11 -0.065 0.139 -0.067 0.126 0.109 12 -0.056 0.009 -0.240 0.109 -0.029 13 0.011 -0.012 0.016 0.016 -0.052 14 0.022 -0.009 -0.075 0.028 -0.082 15 -0.131 -0.072 -0.043 -0.003 -0.144 16 0.009 -0.400 0.031 -0.073 0.008 17 -0.112 0.017 -0.030 0.055 -0.046 18 -0.090 -0.079 0.026 -0.050 0.074 19 -0.141 -0.026 0.056 -0.034 0.040 20 -0.015 -0.014 -0.275 -0.026 0.071 21 0.150 -0.014 -0.035 0.033 -0.003 22 0.017 0.089 0.000 0.077 -0.085 23 0.049 0.025 -0.043 -0.333 0.023 24 0.021 0.041 0.055 -0.055 -0.030 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 1.000 7 0.473 1.000 8 0.120 -0.032 1.000 9 0.011 -0.036 0.017 1.000 10 0.006 -0.010 -0.020 -0.079 1.000 11 0.009 -0.033 0.139 0.196 0.072 12 -0.002 0.098 -0.095 0.022 0.048 13 0.586 0.607 0.030 -0.041 0.020 14 0.179 0.052 0.640 0.007 -0.014 15 0.000 0.057 0.035 0.062 -0.100 16 -0.072 0.011 -0.052 0.181 -0.027 17 -0.039 -0.053 -0.082 -0.213 -0.053 18 -0.144 -0.093 -0.087 -0.045 0.082 19 -0.265 0.017 -0.009 0.026 -0.011 20 -0.017 0.059 -0.150 -0.037 0.057 21 0.206 -0.042 -0.018 -0.018 0.053 22 0.014 -0.026 0.066 0.023 -0.087 23 0.044 0.022 0.033 -0.005 0.042 24 -0.019 -0.069 -0.021 0.039 -0.062 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 1.000 12 0.063 1.000 13 -0.205 0.081 1.000 14 0.064 -0.036 0.091 1.000 15 -0.044 -0.034 0.033 0.007 1.000 16 -0.023 0.026 0.042 -0.007 0.283 17 -0.033 0.072 -0.023 -0.015 -0.667 18 -0.030 -0.005 -0.080 -0.064 0.157 19 0.019 -0.053 -0.111 0.019 0.068 20 -0.039 -0.005 0.033 -0.133 0.065 21 -0.026 0.046 0.076 -0.033 -0.040 22 -0.018 0.004 -0.008 0.025 -0.126 23 -0.020 -0.060 0.027 0.056 0.062 24 0.015 -0.078 -0.055 -0.069 -0.053 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 1.000 17 -0.314 1.000 18 0.060 -0.118 1.000 19 0.022 -0.054 0.129 1.000 20 0.070 -0.049 0.151 0.107 1.000 21 0.036 -0.008 0.051 -0.871 -0.090 22 -0.106 0.159 -0.701 -0.063 -0.091 23 0.098 -0.105 -0.057 -0.016 0.256 24 -0.108 0.060 -0.048 -0.042 -0.689 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 1.000 22 -0.196 1.000 23 0.011 -0.042 1.000 24 -0.005 -0.013 -0.329 1.000
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// Chapter 13 Example 22// clc clear // air density factor=d0 ,barometric pressure=b,temperature=t,rating of transmission line=vcc// vcc=220; // in kV// b=73;// in cm of Hg// t=20;// in celsius// d0=3.92*b/(273+t); printf("\n Air density factor = %.4f \n",d0); // phase to neutral critical disruptive voltage=vc,distance between conductors=d// // surface irregularity factor=m ,diameter of conductor=d1// d=400;// in cms// m=0.96; d1=2;// in cms// r=d1/2; go=21.1; vc=r*go*m*d0*log(d/r); printf("\n Phase-to-neutral critical disruptive voltage = %.2f kV\n",vc); vp=vcc/sqrt(3); printf("\n Line to line critical disruptive voltage = %.2f kV\n",vp); // Since vp > vc cornoa will be present, corona loss is given by// f=50;// in Hz// pc=241*(10^-5)*((f+25)/d0)*sqrt(r/d)*(vp-vc)^2; printf("\n Corona loss is given by %.2f kW/phase/km\n",pc); // in rainy weather vc=0.8*vc// pc1=241*(10^-5)*((f+25)/d0)*sqrt(r/d)*(vp-0.8*vc)^2; printf("\n Corona loss for rainy weather is given by %.2f kW/phase/km\n",pc1);
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//save xyz values function diffuse_x3d(filename, n1,n2,n3,concs,h,maxconc,minconc) sDescription='Simple X3D example'; sCreated='30 October 2000'; sRevised='6 March 2003'; sURL='http://www.shef.ac.uk/personal/m/mikeg/x3d/diffuse_out.x3d'; sAuthor='Mike Griffiths'; fd=writex3d(filename ,sDescription, sCreated, sRevised, sURL, sAuthor); openxml(fd, 'Group'); viewp=zeros(3); viewrot=zeros(4); viewp(1)=6; viewp(2)=-1; viewp(3)=0; viewrot(1)=0; viewrot(2)=1; viewrot(3)=0; viewrot(4)=1.57 writex3dviewpoint(fd, 'diffuse', viewrot, viewp); writex3dnavinfo(fd) //writex3ddefobject(fd) for i=1:n1 for j=1:n2 for k=1:n3 writex3dobject(fd, concs, n1,n2,n3,i,j,k,h,maxconc,minconc) end end end closexmlelement(fd, 'Group'); closex3d(fd); endfunction function diffuse_elevgrid_x3d(filename, n1,n2,n3,concs,maxconc,minconc,p1,p2,p3,layer) sDescription='Simple X3D example'; sCreated='30 October 2000'; sRevised='6 March 2003'; sURL='http://www.shef.ac.uk/personal/m/mikeg/x3d/diffuse_out.x3d'; sAuthor='Mike Griffiths'; fd=writex3d(filename ,sDescription, sCreated, sRevised, sURL, sAuthor); openxml(fd, 'Group'); viewp=zeros(3); viewrot=zeros(4); viewp(1)=6; viewp(2)=-1; viewp(3)=0; viewrot(1)=0; viewrot(2)=1; viewrot(3)=0; viewrot(4)=1.57 writex3dviewpoint(fd, 'diffuse', viewrot, viewp); writex3dnavinfo(fd); //p1=1; //p2=2; //p3=3; np(1)=n1; np(2)=n2; np(3)=n3; selevmat=zeros(np(1),np(2)); selevvec=zeros(np(1)*np(2)); printf('concs: %f, %f\n',concs(1,1,1), concs(n1,n2,n3)); selevmat=difselectlayer(concs, n1,n2,n3,p1,p2,p3,layer); printf('selected layer %f, %f\n',selevmat(1,1), selevmat(np(1),np(2))); //convert layer matrix to vector selevvec=difmat2vec(selevmat,np(1) ,np(2)); //convert vector to string sevecstr=difvec2str(selevvec, np(1)*np(2)); printf('difmatvec completed \n'); //open transform writex3delevgrid(fd,sevecstr, np(1),np(2)); printf('x3d elev grid written\n'); //close transform closexmlelement(fd, 'Group'); closex3d(fd); endfunction function diffuse_faceset_x3d(filename, n1,n2,n3,concs,maxconc,minconc,p1,p2,p3,layer) sDescription='Simple X3D example'; sCreated='30 October 2000'; sRevised='6 March 2003'; sURL='http://www.shef.ac.uk/personal/m/mikeg/x3d/diffuse_out.x3d'; sAuthor='Mike Griffiths'; fd=writex3d(filename ,sDescription, sCreated, sRevised, sURL, sAuthor); openxml(fd, 'Group'); viewp=zeros(3); viewrot=zeros(4); viewp(1)=6; viewp(2)=-1; viewp(3)=0; viewrot(1)=0; viewrot(2)=1; viewrot(3)=0; viewrot(4)=1.57 writex3dviewpoint(fd, 'diffuse', viewrot, viewp); writex3dnavinfo(fd); //p1=1; //p2=2; //p3=3; np(1)=n1; np(2)=n2; np(3)=n3; mprintf('n1,n2,n3,p1,p2,p3,layer %d %d %d %d %d %d %d\n', n1,n2,n3,p1,p2,p3,layer); selevmat=zeros(np(1),np(2)); //selevvec=zeros(np(1)*np(2)); printf('concs: %f, %f\n',concs(1,1,1), concs(n1,n2,n3)); selevmat=difselectlayer(concs, n1,n2,n3,p1,p2,p3,layer); mprintf('Selected layer \n'); maxmin(1)=maxconc; maxmin(2)=minconc; //open transform writex3dfaceset(fd, selevmat, np(p1), np(p2),maxmin); printf('x3d elev grid written\n'); //close transform closexmlelement(fd, 'Group'); closex3d(fd); endfunction function writex3dfaceset(fd, selevmat,np1, np2,maxcolvec) rotvec(1)=0; rotvec(2)=0; rotvec(3)=1; rotvec(4)=%pi/10; //translation is just j,j,k translation=zeros(3); translation(1)=2; translation(2)=2; translation(3)=2; colvec(1)=0; colvec(2)=0.6; colvec(3)=1; printf('Writing x3d elev grid.\n'); writex3dIndexedFaceSet(fd, selevmat,np1,np2, colvec, rotvec, translation, maxcolvec) endfunction function writex3dobject(fd, concs, n1,n2,n3,i,j,k,h,maxconc,minconc) //Determine concentration gradient nns=zeros(3,3,3); nns=getconcsub(concs,n1,n2,n3,i,j,k); grad=grad(nns,h); //determine rotation vector rotvec=rotvec(grad); if rotvec(1)==0 if rotvec(2)==0 if rotvec(3)==0 rotvec(1)=1; end end end //translation is just j,j,k translation=zeros(3); translation(1)=4*i; translation(2)=4*j; translation(3)=4*k; crange=zeros(2) cwid=(maxconc-minconc)/3; if cwid<=0 cwid=1; end crange(1)=minconc+cwid; crange(2)=minconc+2*cwid; //diffuse colour vector colvec=zeros(3) if concs(i,j,k)>crange(2) colvec(1)=(concs(i,j,k)-crange(2))/cwid; colvec(2)=0; colvec(3)=0; elseif concs(i,j,k)>crange(1) colvec(1)=0; colvec(2)=(concs(i,j,k)-crange(1))/cwid; colvec(3)=0; else colvec(1)=0; colvec(2)=0; colvec(3)=concs(i,j,k)/cwid; end shapeprops=zeros(2); writex3dColouredShape(fd, 'cone', shapeprops, colvec, rotvec, translation) endfunction
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// Grob's Basic Electronics 11e // Chapter No. 15 // Example No. 15_1 clc; clear; // A sine wave of voltage varies from zero to a maximum of 100 V. How much is the voltage at the instant of 30° of the cycle? 45°? 90°? 270°? // Given data Vm = 100; // Vm=100 Volts t1 = 30; // Theta 1=30°. t2 = 45; // Theta 2=45°. t3 = 90; // Theta 3=90°. t4 = 270; // Theta 4=270°. v1 = Vm*sind(t1); disp (v1,'The Voltage at 30° in Volts') v2 = Vm*sind(t2); disp (v2,'The Voltage at 45° in Volts') v3 = Vm*sind(t3); disp (v3,'The Voltage at 90° in Volts') v4 = Vm*sind(t4); disp (v4,'The Voltage at 270° in Volts')
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clear; //clc(); l=80 cap=0.00914*10^(-6)*l; vl=132*1000; vph=vl/sqrt(3); f=50; l=1/(3*(2*(%pi)*f)^(2)*cap); printf("The inductance is:%.2f H\n",l) il=vph/((2*(%pi)*f)*l); kvar=vph*il/1000; printf("The rating of the arc suppression coil is:%.2f kVA",kvar)
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clc; clear; xx = [0.00 0.50 1.00 1.50 2.00 2.50 3.00 3.50 4.00 4.50 5.00] yy = [2.26 3.80 4.43 5.91 6.18 7.26 8.15 9.14 10.87 11.58 12.55] clf(); set(gca(),"auto_scale", "on"); set(gca(),"data_bounds", [-1,-1;7,14]); title("Dados"); xlabel("X"); ylabel("Y"); dxa=gda(); dxa.y_location="origin"; dxa.x_location="origin"; plot(xx,yy,'bd'); wa = 0.5-rand(1,1,"uniform"); ba = 0.5-rand(); teta = 0; alfa = 0.01; nc=50; cc=0; mprintf("Train\n"); while cc<=nc erroq=0; cc=cc+1 for inp=1:11 yl=wa*xx(inp)+ba; yc=yl; erroq=erroq+(yy(inp)-yc)^2; wn=wa+alfa*(yy(inp)-yc)*xx(inp); bn=ba+alfa*(yy(inp)-yc); wa=wn; ba=bn; end end mprintf("y=%fx+%f", wn, bn); for abc=0:0.1:6 ord = abc*wn+bn; plot(abc,ord,'g.'); end
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17Ex7.sce
//chapter 17 Example 7 clc; clear; close; s1=200;s2=400;s3=600;s4=800; avgspeed=4/(1/s1+1/s2+1/s3+1/s4); printf("The average speed is %3.0f km/hr",avgspeed);
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12_9.sce
clc //Initialization of variables p=0.1 //m T=30+273.2 //K R=0.08206 //lt atm /deg/mol P1=1 //atm //calculations w=1000/p V=w/1000 dP=R*T/V P=dP+P1 //results printf("Osmotic Pressure =%.2f atm ",P)
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ex6_3.sce
//ex6.3 I_E=3.8*10^-3; B_ac=160; R1=22*10^3; R2=6.8*10^3; R_s=300; V_s=10*10^-3; r_e=25*10^-3/I_E; R_in_base=B_ac*r_e; R_in_tot=(R1*R2*R_in_base)/(R_in_base*R1+R_in_base*R2+R1*R2); V_b=(R_in_tot/(R_in_tot+R_s))*V_s; disp(V_b,'voltage at the base of the transistor in volts')
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Ex3_6.sce
// // //(a) BB_AB=30+(30/60) FB_AB=BB_AB mins=(FB_AB-int(FB_AB))*60 deg=int(FB_AB) printf("\n S %0.3f degrees %0.3f minutes E",deg,mins) //(b) BB_BC=40+(15/60) FB_BC=BB_BC mins=(FB_BC-int(FB_BC))*60 deg=int(FB_BC) printf("\n N %0.3f degrees %0.3f minutes W",deg,mins) //(c) BB_CD=60+(45/60) FB_CD=BB_CD mins=(FB_CD-int(FB_CD))*60 deg=int(FB_CD) printf("\n S %0.3f degrees %0.3f minutes W",deg,mins) //(d) BB_DE=45+(30/60) FB_DE=BB_DE mins=(FB_DE-int(FB_DE))*60 deg=int(FB_DE) printf("\n N %0.3f degrees %0.3f minutes E",deg,mins)
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clc; P=100000; // VA rating of two winding transformer E1=2000; // rated voltage of h v side E2=200; // rated voltage of l v side l=2.5; // percentage of loss in two winding transformer vr=3; // percentage of voltage regulation in two winding transformer z=4; // percentage of leakage impedance in two winding transformer ih=P/E1; // full load current of h v side il=P/E2; // full load current of l v side V1=E1; // rated voltage on l v side of autotransformer V2=E1+E2; // rated voltage on h v side of autotransformer Il=il+ih; // rated current on l v side of autotransformer printf('Rated voltage on l v and h v side of autotransformer are %f v and %f v respectively\n,',V1,V2); printf('Rated current on h v and l v side of autotransformer are %f A and %f A respectively\n,',il,Il); k=E1/V2; // turns ratio for auto transformer K=((1/(1-k))*P)/1000; printf('Rated KVA of autotransformer is %f KVA\n',K); pl=(1-k)*l; //percent full load losses in autotransformer n=100-pl; printf('Efficiency of auto transformer is %f percent\n',n); Z=(1-k)*z; printf('Percentage impedance as an auto transformer is %f \n',Z); VR=(1-k)*vr; printf('percentage voltage regulation as an auto transformer is %f \n',VR); Is=(1/(1-k))*(100/z); // short circuit p u current Ish=(Is*il)/1000; printf('Short circuit of auto transformer on h v side is %f KA \n',Ish); Isl=(Is*Il)/1000; printf('Short circuit of auto transformer on l v side is %f KA \n',Isl);
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ch3_ex_9.sce
//CHAPTER 3- THREE-PHASE A.C. CIRCUITS //Example 9 disp("CHAPTER 3"); disp("EXAMPLE 9"); //VARIABLE INITIALIZATION v_ab=400; //in Volts v_bc=400; //in Volts v_ac=400; //in Volts z_ab=100; //in Ohms z_bc=100; //in Ohms z_ac=100; //in Ohms //solution (a) //function to convert from polar to rectangular form function [x,y]=pol2rect(mag,angle1); x=mag*cos(angle1); y=mag*sin(angle1); endfunction; I_AB=v_ab/z_ab; mag1=abs(real(I_AB)); ang1=0; I_BC=v_bc/z_bc; ang2=-210*(%pi/180); I_AC=v_ac/z_ac; ang3=210*(%pi/180); [x1,y1]=pol2rect(I_AB,ang1); [x2,y2]=pol2rect(I_BC,ang2); [x3,y3]=pol2rect(I_AC,ang3); I_A=(x1-x3)+(%i*(y1-y3)); I_B=(x2-x1)+(%i*(y2-y1)); I_C=(x3-x2)+(%i*(y3-y2)); disp(sprintf("(a) The line current I_A in rectangular form is (%f + j%d) A",real(I_A),imag(I_A))); disp(sprintf("The line current I_B in rectangular form is (%f + j%d) A",real(I_B),imag(I_B))); disp(sprintf("The line current I_C in rectangular form is (%d - j%d) A",real(I_C),-imag(I_C))); //solution (b) //since power is consumed only by 100Ω resistance in the arm AB r1=100; p1=(I_AB^2)*r1; p2=160000; r2=p2/p1; disp(sprintf("(b) The star connected balanced resistance is %d Ω",r2)); //END
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pa=-30//kPa p=9810//N/m^3 S=0.83//specific gravity of kerosene
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Ex20_1.sce
clc clear //Initialization of variables heat=54.5 //Btu/hr ft d=0.811 //in h=2.5 //Btu/hr ft^2 F ts=100 //F km=220 //Btu/hr ft F //calculations t2=heat*12/(h*%pi*d) +ts w=heat*4*144/(%pi*d^2) t1=w*(d/2)^2 /(4*144*km) + t2 //results printf("Surface temperature of transmission line = %.1f F",t2) printf("\n Rate of heat generaton per unit volume of wire = %d Btu/hr ft^2",w) printf("\n Max. temperature in the line = %.2f F",t1) disp("The answers in the textbook are a bit different due to rounding off errors")
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Ex6_2.sce
clc he=2609.9 //in kJ/kg hi=3072.1 //in kJ/kg ve=sqrt(2*(hi-he)*10^3) mprintf("ve=%fm/s",ve)//ans vary due to roundoff error
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Ex9_7.sce
//Determine the reliability of the system for 20 hrs. of operating period //page no 220 clear clc; dA = 0.01; dB = 0.015; dC = 0.02; dD = 0.02; dE = 0.025; t=20; RA =%e^(-dA*t); RB =%e^(-dB*t); RC =%e^(-dC*t); RD =%e^(-dD*t); RE =%e^(-dE*t); RBC = 1-((1-RB)*(1-RC)); RABC = RA*RBC; RABCD = 1-((1-RABC)*(1-RD)); RABCDE = RE*RABCD; mprintf("RABCDE = Rs = %.4f \n",RABCDE);
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06-civil_cloud_height_thresholds.tst
{ "EGTE 150800Z 1509/1518 18005KT 9999 BKN040 TEMPO 1511/1512 BKN010 TEMPO 1512/1513 BKN006 TEMPO 1513/1514 BKN003 TEMPO 1514/1515 BKN001": { "TAF base conditions cover METAR - cloud BKN050": { "metar": "EGTE 150850Z 18005KT 9999 BKN050", "test time": "20200615T0900Z", "expected": "" }, "TAF base conditions do not cover METAR - cloud BKN010": { "metar": "EGTE 150950Z 18005KT 9999 BKN010", "test time": "20200615T1000Z", "expected": "EGTE TAF bust by cloud" }, "TAF base conditions cover METAR - cloud BKN010": { "metar": "EGTE 151050Z 18005KT 9999 BKN010", "test time": "20200615T1100Z", "expected": "" }, "TAF base conditions do not cover METAR - cloud BKN006": { "metar": "EGTE 151050Z 18005KT 9999 BKN006", "test time": "20200615T1100Z", "expected": "EGTE TAF bust by cloud" }, "TAF base conditions cover METAR - cloud BKN006": { "metar": "EGTE 151150Z 18005KT 9999 BKN006", "test time": "20200615T1200Z", "expected": "" }, "TAF base conditions do not cover METAR - cloud BKN003": { "metar": "EGTE 151150Z 18005KT 9999 BKN003", "test time": "20200615T1200Z", "expected": "EGTE TAF bust by cloud" }, "TAF base conditions cover METAR - cloud BKN003": { "metar": "EGTE 151250Z 18005KT 9999 BKN003", "test time": "20200615T1300Z", "expected": "" }, "TAF base conditions do not cover METAR - cloud BKN001": { "metar": "EGTE 151250Z 18005KT 9999 BKN001", "test time": "20200615T1300Z", "expected": "EGTE TAF bust by cloud" }, "TAF base conditions cover METAR - cloud BKN001": { "metar": "EGTE 151350Z 18005KT 9999 BKN001", "test time": "20200615T1400Z", "expected": "" } }, "description": "A contrived test with 1 hour tempo groups descending the civil cloud thresholds. Each cloud height is tested twice, once in the hour preceding the tempo group it requires, making the TAF invalid, and once during the hour of the tempo group making the TAF valid." }
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//variable initialization mu=9.27*10^-24; //(J/T) B=0.45; //magnetic field (μb/m^2) h=1.054*10^-34; //Plank's constant (Js) k=[5/3 1 1/3 -1/3 -1 -5/3]; //value of g'Mj'-gMj //calculation c=(mu*B)/h; //constant (rad/s) deltaomega1=c*k(1); //displacement of Zeeman component (rad/s) deltaomega2=c*k(2); //displacement of Zeeman component (rad/s) deltaomega3=c*k(3); //displacement of Zeeman component (rad/s) deltaomega4=c*k(4); //displacement of Zeeman component (rad/s) deltaomega5=c*k(5); //displacement of Zeeman component (rad/s) deltaomega6=c*k(6); //displacement of Zeeman component (rad/s) printf("\ndisplcement of Zeeman component = %.2e, %.2e, %.2e, %.2e, %.2e, %.2e rad/s",deltaomega1,deltaomega2,deltaomega3,deltaomega4,deltaomega5,deltaomega6);
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//fiber optic communications by joseph c. palais //example 4.3 //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given lambda=0.82//wavelength in um n1=3.6//refractive index of core AlGaAs slab n2=3.55//refractive index of cladding n3=3.55//refractive index of cladding n0=1//refractive index of Air //to find NA=sqrt(n1^2-n2^2)//Numerical aperture alpha0=asind(NA/n0)//Acceptance angle in degree mprintf(' Numerical aperture =%f ',NA) mprintf(' \nAcceptance angle in range =+%fdegree to -+%fdegree',alpha0,alpha0)
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clear; clc; //for low loads p1(1)=20; p2(1)=30; t1(1)=.1*p1(1)+20; t2(1)=.12*p2(1)+16; //when load is further increased t2(4)=22; p2(4)=(t2(4)-16)/.12; t1(4)=t2(4); //upper limit 125MW p2(5)=125; t1(5)=1.12*p2(5)+16; p1(5)=(t1(5)-20)/.1; n=7; t2(1)=19.6; t2(2)=20; t2(3)=21; t2(4)=22; t2(5)=31; t2(6)=32; t2(7)=32.5; p1(5)=110; p1(6)=120; p1(7)=125; for j=1:4 p1(j)=20; end; mprintf("incremental cost(rs./MWhr)\tloading of unit 1(MW) \t loading of unit 2(MW)\ttotal generating power(MW)"); for i=1:n p2(i)=(-16+t2(i))/.12; if(t2(i)>=31) p2(i)=125; end; pt(i)=p1(i)+p2(i); mprintf("\n%f\t\t\t%f\t\t\t%f\t\t%f",t2(i),p1(i),p2(i),pt(i)); end;
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//Example 12.4 clc clear V_A=0 //a=input("Enter the binary digit(5 bits) :" ); a=11010 for i=1:5 r=modulo(a,10); b(1,i)=r; a=a/10; a=floor(a); end for j=1:5 V_A = V_A + 10*b(1,j)*2^(j-1); end; V_A=V_A/2^5; disp("The output voltage in volts is '); disp(V_A); // displaying the value
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//Example No. 3.13.1 clc; clear; close; format('v',6); Irms=15;//A(Current Drawn) Prad=5;//kW(Radiated Power) Rr=Prad*10^3/Irms^2;//Ω(Radiation Resistance) disp(Rr,"Radiation resistance in Ω : ");
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clc; clear; D_4=0.4 //diameter of the 4th dark ring in cm D_12=0.7 //diameter of the 12th dark ring in cm //calculation D_20=sqrt(2*((0.7^2)-(0.4^2))+0.4^2) mprintf("The diameter of the 20th dark ring is = %1.3f cm",D_20)
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