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clear; clc; d = 9;// inches p = 5000/2240;// lb/in^2 f = 8;// tons/in^2 PR = 0.3;// Poisson's ratio //(i) Maximum principal stress hypothesis: k_limit1 = sqrt((f + p)/(f - p));//k_limit = r1/r2 r_limit1 = k_limit1*0.5*d;//inches printf('The outer radius in case(i), r2 = %.3f inches',r_limit1); //(ii) Maximum ...
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// Exa 8.6 clc; clear; close; //given data omega= 200*%pi;// in radians/seconds f=omega/(2*%pi);// in Hz T=1/f;// in sec T=T*10^3;//in ms Vin= 7;//in volt t1= 1/omega*asin(6/Vin);// in sec t1=t1*10^3;// in ms // The output of the schmitt trigger is at -10 volt t1= T/2+t1;// in ms // The output of the schm...
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//clc; clear; exec 'constrpoly.sci'; exec 'mcnorm.sci'; t1 = [0,1,2]'; y1 = [1,3,7]'; [A1] = constrpoly(t1); [x1] = mcnorm(A1,y1); plot(t1,A1*x1,'o-b'); plot(t1,y1,'*-r'); legend("result1", "y1"); t2 = [0:0.25:2]'; y2 = [1, 1.7, 1.95, 1.8, 3., 3.6, 4.45, 5.9, 6.6]'; [A2] = constrpoly(t2); [x2] = mcnorm(A2,y2); f = scf...
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//Exa4.15 clc; clear; close; //given data Vz=15;//in volts Izk=6;//in mA Vout=15;//in Volts Vs=20;//in Volts ILmin=10;//in mA ILmax=20;//in mA disp("the zener current will be minimum i.e. Izk = 6mA when load current is maximum i.e. ILmax = 20mA"); RS=(Vs-Vout)/(Izk+ILmax);//in ohm disp("when the load curre...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Convergence: Taylor Vortex IMEXOrder2 dt=0.01</description> <executable>IncNavierStokesSolver</executable> <parameters>TaylorVor_dt1.xml</parameters> <files> <file description="Session File">TaylorVor_dt1.xml</file> </files> <met...
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// Scilab code Exa6.9.2 : To calculate the w/B ratio for a completely stripped nitrogen to move in a stable orbit : Page 274(2011) E_k = 1200; // Kinetic energy of the proton, MeV q = 7; // Number of proton in nitrogen E_r = 13040 // Rest mass energy of the electron, MeV E = (E_k+E_r)*1.6e-013; // Total energy,j ...
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pathname=get_absolute_file_path('6_2.sce') filename=pathname+filesep()+'6_2data.sci' exec(filename) F=[-W;M;0;0]; P=EI*[(27/(2*L^3)) (9/(2*L^2)) (6/L^2) -(3/(2*L^2)); (9/(2*L^2)) (6/L) (2/L) (1/L); (6/L^2) (2/L) (4/L) 0; -(3/(2*L^2)) (1/L) 0 (2/L)]; V=inv(P)*F; Sy12= EI*(-(6*V(3)/(L^2))-(12*V(1)/(L^3)...
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// Exa 1.19 clc; clear; close; // given : A_p=16 // power gain A_p_Np=log(sqrt(A_p)) // power gain in nepers disp(A_p_Np,"power gain in nepers:")
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// SAMPLE PROBLEM 8/6 clc;funcprot(0); // Given data W=100;// The weight of the piston in lb k=200;// The spring modulus in lb/in c=85;// The damping coefficient in lb-sec/ft a=80;// The top surface area in in^2 omega=30;// rad/s g=32.2;// The acceleration due to gravity in ft/sec^2 p=0.625;// lb/in^2 // Ca...
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function secanteM(f,xi,tol,imax) //f es la función que se ingresara entre comillas //xi es un punto //tol es la tolerancia //imax es el numero maximo de iteraciones i=1; d=2; printf('+-----------+----------------------+----------------------+\n'); printf('| Iteracion | xi | error |\n...
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function [x,y] = RK4(a,b,h,y0) x = a:h:b; n = length(x); y(1) = y0; for i = 2:n k1 = df(x(i-1),y(i-1)); k2 = df(x(i-1) + h/2, y(i-1) + h/2*k1); k3 = df(x(i-1) + h/2, y(i-1) + h/2*k2); k4 = df(x(i),y(i-1) + h*k3); y(i) = y(i-1) + h/6*(k1 + 2*k2 + 2*k3 + k4...
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clc disp("Example 2.58") printf("\n") disp("Design a voltage regulator using zener diode to meet following specification") printf("Given\n") printf("1 Resistance are in ohms \n 2 Current are in ampere \n 3 voltage sources are in volt\n") //unregulated dc input voltage Vimin=20 Vimax=30 //regulated dc output vo...
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//Ex 2.1 clc; clear; close; format('v',5); v1=7;//mV v2=9;//mV Ad=80;//dB CMRR=90;//dB vid=v2-v1;//mV vcm=(v1+v2)/2;//mV Ad=10^(Ad/20);//unitless CMRR=10^(CMRR/20);//unitless vout=Ad*(vid+vcm/CMRR)/1000;//V disp(vout,"Output Voltage(V)");;
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// 08.08.16 function Out=Sfparadata(varargin) Nargs=length(varargin); Fd=varargin(1); Ndu=25 ; Ndv=25; Np=[50,50]; if Nargs>=3 Ndu=varargin(2); Ndv=varargin(3); end; if Nargs>=4 Np=varargin(4); end; Tmp=Sf3data(Fd,Ndu,Ndv,Np); Out=Projpara(Tmp); endfunction
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clc; pathname=get_absolute_file_path('10_3_soln.sce') filename=pathname+filesep()+'10_3_data.sci' exec(filename) // Solution: // wall thickness, t=(Do-Di)/2; //in // burst pressure, BP=(2*t*S)/Di; //psi // working pressure, WP=BP/FS; //psi // Results: printf("\n Results: ") printf("\n The working pressure of ste...
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function [x,y,typ]=sigma_delta(job,arg1,arg2) // Copyright INRIA x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then ...
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clc; clear all; disp("heat flow rate") La=0.03;//m Aa=0.1*0.1;//m^2 kA= 150;//W/(m*C) RthA=La/(kA*Aa); Lb=0.08;//m Ab=0.1*0.03;//m^2 kB= 30;//W/(m*C) RthB=Lb/(kB*Ab); Lc=0.08;//m Ac=0.1*0.07;//m^2 kC= 65;//W/(m*C) RthC=Lc/(kC*Ac); Ld=0.05;//m Ad=0.1*0.1;//m^2 kD= 50;//W/(m*C) RthD=Ld/(kD*Ad); Req=Rt...
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// Chapter 5 additional Example 1 //============================================================================== clc; clear; // input data // Copper has FCC structure a = 3.6; // lattice parameter of copper in Å // Calculations r = a*sqrt(2)/4; // atomic radius of copper // Output mpri...
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//Given that Radius_earth = 6.37 * 10^6 h_alti = 520 * 10^3 //in meter velocity = 7.6 * 10^3 //in m/s converted from km/s mass = 79 //in kg //Sample Problem 6-6a printf("**Sample Problem 6-6a**\n") acce = velocity^2/(h_alti + Radius_earth) printf("The acceleration is equal to %f m/s^2\n", acce) //Sample...
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clc //initialisation of variables Q= 450 //ft^3/sec k= 0.5 i= 1/2000 C= 105 //ft^1/2/sec //CALCULATIONS d= (((Q*sqrt(2/i))/(2*sqrt(1+k^2-k)*C))^(2/5))*(5.41/7.55) b= d/2 s= d*sqrt(1+k^2) //RESULTS printf (' vertical= %.2f ft',d) printf (' \n horizontal= %.2f ft',s)
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clc; clear; a=[[10,1,1];[2,10,1];[2,2,10]]; b=[12,13,14]; x0=[0,0,0]; for k=1:5000 x=x0; for i=1:3 sump=0; for j=1:3 if i~=j sump=sump+a(i,j)*x(j); end end x0(i)=(b(i)-sump)/a(i,i); end end mprintf("Solution of the equation is (%f,%f,%f)",x(1),x(2),x(3));
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0090.tst
sPLIttER F {} fIlTer CI { } fIlTER EFoO {Not M oR t Or NoT nCD oR WU } q BRAnch w gROUpER a {MODULE XC{ ued >= V YbUx = Sx dELTa 84S } mOduLE diAM{ CN = Q rDeLTa 9533 } modUle O{ } mODULe Et{ } mODUlE I{ W = auX DeLTA 46M } agGRegAte xUm ,vWmt.GWMHn ,D.C } unGrOUper l { } GROUpFilter wi {} mErGEr UO { mo...
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//****************************************************************** // File name: playSignal.sci //****************************************************************** // This program assumes that an IQ data file contains data that is // sampled at 256000S/s. Data segments should be powers of 2 so // that no zero paddi...
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MB_INIT_RTU.sci
function [x,y,typ]=MB_INIT_RTU(job,arg1,arg2) x=[];y=[];typ=[] select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) ca...
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// Exa 5.11 clc; clear; close; // Given data r = 10; Gamma = 1.4; P1 = 1;// in bar P2 = 1 * ((r)^(Gamma));// in bar P3 = 40;// in bar P4 = P3;// in bar T1 = 80;// in degree C T1 = T1+273;// in K T2 = T1 * ((r)^(Gamma-1));// in K T3 = (P3/P2)*T2;// in K T4 = 1700;// in degree C T4 = T4 + 273;// in K Vc=...
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pathname=get_absolute_file_path('16_10.sce') filename=pathname+filesep()+'16_10data.sci' exec(filename) clear function[si]=sing(a,b) if(a<b) then si=0; else si=(a-b); end endfunction deff("[v]=f(z)","v=(1/EI)*(((L*W*z^3)/64) -((W/24)*(sing(z,0.5*L))^4)+((W/24)*(sing(z,0.75*L))^4)-...
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clc; RC=2*10**3; R3=20*10**3; rbb=200; C1=1000*10**-12; T=0.69*C1*R3; disp('microsec',T*10**6,"T=");
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clc //initialisation of variables p=90//deg h=48//in p1=100//psig P=(1/2*%pi)*h^2*p1*0.7071//lb r=3000/54-31//ft s=9000//psi l=170//in b=6.5*10^-6//ft w=46//ft w1=1000//ft //CALCULATIONS D=(1/4*%pi)*h^2*p1//lb P=[r]*h^2//lb T=%pi*h*(1/4)*s//lb T1=(1/2)*l//tons Del=b*w*w1//ft per //RESULTS printf('the...
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//<wft,wfm,fr>=wfir(ftype,forder,cfreq,wtype,fpar) //<wft,wfm,fr>=wfir(ftype,forder,cfreq,wtype,fpar) //Macro which makes linear-phase, FIR low-pass, band-pass, //high-pass, and stop-band filters //using the windowing technique. //Works interactively if called with no arguments. // ftype :Filter type ('lp','hp','bp',...
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clc pathname=get_absolute_file_path('4_8_4.sce') filename=pathname+filesep()+'484.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") disp("N2 balance") na=basis*xN2/0.79 printf("na=%f mol air",na) disp("Atomic C balance") n...
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//Calculations on Otto cycle clc,clear //Given: r=8 //Compression ratio P1=1,P3=50 //Pressure at 1, 3 in bar T1=100+273 //Temperature at 1 in K m=1 //Air flow in kg R=0.287 //Specific gas constant in kJ/kgK g=1.4 //Specific heat ratio(gamma) //Solution: //Refer fig 2.22 //Point 1 V1=m*R*10^3*T1/(P1*10^5) //...
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1_13.sce
//taylor series //example 1.13 //page 16 clc;clear;close; deff('y=f(x)','y=sin(x)'); deff('y=f1(x)','y=cos(x)'); deff('y=f2(x)','y=-sin(x)'); deff('y=f3(x)','y=-cos(x)'); deff('y=f4(x)','y=sin(x)'); deff('y=f5(x)','y=cos(x)'); deff('y=f6(x)','y=-sin(x)'); deff('y=f7(x)','y=-cos(x)'); D=[f(%pi/6) f1(%pi/6) f...
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main begin int a; a <= 0; begin print(a); a <= a + 1; end for( ; a < 6 ; ) begin print(a); a <= a + 1; end return a; end
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// RESIDUOS ARX // Calcular o erro de predicao um passo a frente (residuo) entre a saida de // um sistema e a saida prevista pelo modelo ARX, descrito pelo vetor de // parametros theta, para uma entrada u determinada function res=multi_resARX(u1,u2,y,theta,delay) test_parametersUY(u1,y); test_parameters...
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clc Cd=0.97; d1=0.28; // m d2=0.14; // m g=9.81; // m/s^2 d=0.05; // difference in mercury level in metre rho=1000; // kg/m^3 rho_m=13600; // kg/m^3 A1=%pi/4*d1^2; A2=%pi/4*d2^2; p_diff=(rho_m-rho)*g*d; h=p_diff/rho/g; Q=Cd*A1*((2*g*h)/((A1/A2)^2-1))^(1/2); disp("Flow rate = ") disp(Q) disp("...
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7ex16.sci
u=3; //mean of distribution of random variable X x=[0,1,2,3,4,5,6]; //values of X in the distribution as x where it is the number of times heads occurs when a coin is tossed six times p=[1/64,6/64,15/64,20/64,15/64,6/64,1/64]; //probabilities of occurrence of each value of X (x) in the distribution ...
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MultTime.tst
// Measure running time of Mult.asm load Mult.asm, output-file MultTime.out, output-list RAM[0]%D2.6.2 RAM[1]%D2.6.2 RAM[2]%D2.6.2 time%S1.5.1; set RAM[0] 2, set RAM[1] 3, set RAM[2] -1; while RAM[2] <> 6 { ticktock; } output; set PC 0, set RAM[0] 17, set RAM[1] 123, set RAM[2] -1; while RAM[2] <> 2091 { ticktoc...
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//Exa 4.2 clc; clear; close; // given data disp("As the input impedence of an op-amp circuit is very high & no current will enter the op-amp, hence node voltages at (a) & (b) will be at same potential, let Va=Vb=V"); disp("writing KCL at node (b) we have (6-V)/30+(8-V)/40+(0-V)/30=0"); V=48/11;//in volts disp(V...
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//Section-14,Example-2,Page no.-PC.112 //To calculate the pH in the following cases. clc; V_1=150 //volume of 0.1 NaOH solution(ml) V_2=150 //volume of 0.2 HCl solution(ml) N_1=0.1 //(N) N_2=0.2 //(N) V=V_1+V_2 //Total volume of the solution(m...
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clc; //e.g 32.7 R1=1*10**3; R2=10*10**3; ACL=R2/R1 disp("Voltage at node A increases from 1V to 4v");
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exec training.sci a_char = ReadImage("characters/single_char 1.png"); path = path + "training_feature_data/"; // dic is defined in training.sci [content_vector, list_rowsum, list_colsum] = read_feature(path, dic); // given_image should be grayscale function [sorted_array_row, sorted_array_col] = compare_features(...
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example13_sce.sce
//chapter 19 //example 19.13 //page 848 printf("\n") printf("given") Rl=20;Po=2.5;Rd=4;Vr6=1;Vr9=Vr6;Vth=1;gFS=250*10^-3;Vbe=.7; Vp=sqrt(2*Rl*Po) Ip=Vp/Rl Vcc=(Vp+Ip*Rd) vr6=Ip/gFS Vr2=vr6+1 Vce=Vr2; Vce3=1; Vr2=Vcc-Vce Vee=Vcc; Vr3=Vee-Vbe Vr7=Vr2-Vr6 Vr8=Vcc-(-Vee)-Vr6-Vr7-Vr9
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function [J,G]=cost1(v); n = length(v) J = 0 G = [] for i=1:n J = J + (v(i) - 1)^2 gradient = 2*(v(i)-1) G = cat(1, G, gradient) end endfunction function [J,G]=cost2(v); n = length(v) J = 0 G = [] for i=1:n J = J + (v(i) - i)^2 gradient = 2*(...
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# --- Dynamic Affect: Posttest --- # # Experimental script to run the Posttest scenario # of the Dynamic Affect paradigm. Runs an event-related # presentation of stimuli, which are in 50% of the trials # (counterbalenced over conditions) followed by a # likert-scale evaluation (very pos - very neg). # # Creates ...
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//Example 3.31: Capacitance, power loss, loss resistance and loss angle clc; clear; close; //given data : r2=1500/%pi;// in ohm r3=120;// in ohm C2=0.95*10^-6;//F C1=50*10^-12;// F Cs=round(C1*r2*10^12/r3); f=50; w=round(2*%pi*f); disp(Cs," Cable caacitance,Cs(PF) = ") rs=(r3/(w^2*C1*10)); disp(rs*10^-6,"Parallel loss ...
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// Scilab Code Ex5.17: Page:305 (2011) clc;clear; a = 1; // For simplicity assume slit width to be unity, unit theta = 1; // For simplicity assume diffraction angle to be unity, unit // As a*sin(theta) = m*lambda, solving for lambdas lambda1 = a*sin(theta); // First wavelength, angstrom lambda2 = a*sin(thet...
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// implementação da Regra Delta para treinamento do adaline // Levantamento do Erro Quatrático Total // aplicação: funções lógicas bipolares // data: 14/04/2021 // autor: Keiji Yamanaka clc; // limpa area de comando clear;// limpa as variáveis da area de trabalho // dados de treinamento // tabela verdade ...
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//Use SPICE methods to simulate this amplifier //Example 9.25 page no 281 clear clc R1=10*10^3 //Ω R2=20*10^3 //Ω R3=20*10^3 //Ω Av=-((R2*R3)/(R1*(R2+R3))) printf("\n The value of Av=%0.3f ",Av)
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ex11_8_a.sce
//Example 11.8(a) clc; //Given values of bridge elements R1=470000; R2=5100; R3=100000; C1=0.01*10^-6; //We Know Balanced bridge equations as Rx=R2*R3/R1; //For the calculation of Capacitance //we have Lx=R2*R3*C1 Lx=R2*R3*C1; disp(Rx,Lx,'The unknown impedence is the series combination of Lx & Rx')
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lagrange.sci
function f=lagrange(xd,x,y) [mx,nx]=size(x); [my,ny]=size(y); ierror=0; if (nx~=ny)|(mx~=1)|(my~=1), ierror=1; disp( 'data dimension error ') abort end xx=gsort(x); for k=1:nx-1, if xx(k)==xx(k+1), ierror=1; break, end e...
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function rec01(fx,x,denominador) if denominador == x then fx=return(fx) end ((x^denominador)/(denominador))+rec01(fx,x,denominador+1) endfunction
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//chapter-2,Example2_4,pg 484 Vp=1//peak input voltage f=50//frequency //R1=R2 //since halfwave rectification is done,integration gives the value Vo=0.5*((2*Vp)/3.14)//output voltage,pi=3.14 printf("output voltage\n") printf("Vo=%.4f V\n",Vo)
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clc; clear; e=1.6*10^-19 //charge in C h=6.63*10^-34 //Plancks constant in J-s c=3*10^8 //velocity of light in m/s n1=1 //first order maxima n2=2 //second order maxima V=50*10^3 //voltage in V tetha=26 //Braggs angle in degree //calculation lambda_min=(h*c)/(e*V) //wavelength in m d=(n1*lambda_min)/(2*sind...
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clear; clc; printf("\t\t\tProblem Number 3.19\n\n\n"); // Chapter 3 : The First Law Of Thermodynamics // Problem 3.19 (page no. 120) // Solution h1=3450*1000 //Unit:J/kg //Enthalpy of steam when it enters a nozzle h2=2800*1000 //Unit:J/kg //Enthalpy of steam when it leaves a nozzle //V2^2/2=h1-h2; V2=sqrt...
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.idc.ac.il/tecs // File name: projects/07/MemoryAccess/PointerTest/PointerTest.tst load PointerTest.asm, output-file PointerTest.out, compare-to PointerTest.cmp, outpu...
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//Example 7.1, Page Number 296 //Detector sensitivity clc; D=10**9 //in meter square root hertz per watt l=2*(10**-6) //Wavelength in meter A=25*(10**-6) //Area in meter square db=10*(10**3) //Detection Bandwidth in hertz //From equation 7.2 NEP=(sqrt(A*db))/D //NEP is the detector sensitivty in W mprint...
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clc; //page no 182 //prob no. 5.4 //Class C amplifier with carrier o/p power of 100W with efficiency of 70% & with 100% modulation Pc=100;eta=0.7; //Determination of o/p power Po=1.5*Pc; disp('W',Po,'The o/p power with 100% modulation is'); //Determination of supply power Ps=Po/eta; disp('W',Ps,'The value of ...
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// Example 2.8 page no-49 clear clc L=1400 E_diff=12400/L //eV del_E=2.15 L2=12400/del_E printf("\nE2-E1=%.2f eV\n1850 A° line is from 6.71 eV to 0 eV\nTherefore, second photon must be from %.2f to 6.71 eV.\nLambda=%d A°.",E_diff,E_diff,L2)
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clc //initialisation of variables p = 17.4 //mm m= 1000 //gms M= 18 //gms n= 2 //moles //CALCULATIONS P= p*((m/M)/((m/M)+n)) P1= p*(n/((m/M)+n)) dp= p-P1 //RESULTS printf (' vapour pressure of solution= %.2f mm',P1)
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function Funcion1(x) // Autores: Jorge Zavaleta,Hector E. Gomez Morales // Funcion que grafica la funcion definida en intervalos // // | cos(2x) si 0 <= x <= Pi/4 // f1(x) = | // | 0 si Pi/4 < x <= Pi/2 // // para un conjunto de argumentos dados x //****************************...
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2_3.sce
//To determine the diversified demand //Page 47 clc; clear; TCDi=[9,9,9,9,9,9]; //Load for each house all in kilowatt DFi=0.65; //Demand factor Fd=1.1; //Diversity factor Dg=sum(TCDi)*DFi/Fd; printf('The diversified demand of the group on the distribution transformer is %g kW\n',Dg)
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ex5_16.sce
//Example 5.16, page no-209 clear clc bw=3.2 // voice channel band limited frequency in kHz r=1.2 //1.2 times the Nyquist rate n=24 //no of voice channel b=8 // 8-bit PCM sr=2*bw*r p=10^6/(sr*10^3) N=(n*b)+1 bit_d=p/N bit_d=ceil(bit_d*1000)/1000 tr=1/bit_d pri...
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11_02.sci
//value// s=%s; sys1=syslin('c',(s+1)/(s+4)); evans(sys1,100) printf("rootlocus begins at s=-4 & ends at s=-1")
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clc A = [1 0 1; 1/2 sqrt(3)/2 1; -1/2 sqrt(3)/2 1; 1 0 1; -1/2 -sqrt(3)/2 1; 1/2 -sqrt(3)/2 1] y = [1 1.6 1.4 0.6 0.2 0.8]' disp(A, "A") disp(y, "y") [Q R] = qr(A) R = R(1:3,:) Q = Q(:,1:3) disp(Q, "Q") disp(R, "R") c = inv(R)*Q'*y disp(c,"c")
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EX5_9.sce
// Exa 5.9 format('v',6) clc; clear; close; // Given data V_G= 1.5;// in V V_P= -3;// in V R_S= 750;// in Ω R_D= 1800;// in Ω I_DSS= 6*10^-3;// in A V_DD= 18;// in V // V_GS= V_G-I_D*R_S // I_D= I_DSS*(1-V_GS/V_P)^2 or I_DSS*(1-(V_G-I_D*R_S)/V_P)^2 //I_D^2*R_S^2+I_D*(2*R_S*(V_P-V_G)-V_P^2/I_DSS)+(V_P-V_G)...
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clear //Given P_Max = 10 //N - the maximum distribution in a triangular distribution L = 3 //mt the total length of force distribution L_X = 5 //mt - the horizontal length of the rod //calculations F_y = P_Max*L*0.5 //N - The force due to triangular distribition L_com = 2*L /3 //mt - the resu...
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x y z v w f(xs) -20.668359 31.817591 22.043469 -1.303162 -18.677385 -2.229534 16.344869 -30.117498 -7.161659 -0.254790 -29.088851 -1.399490 43.239118 17.208574 36.516138 -47.451602 -39.609219 2.883158 -5.669018 5.548560 26.600526 -30.100493 6.687362 0.060864 -23.820626 -45.377436 -29.444117 -32.220204 -46.259096 ...
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Ch2_2_66.sce
clc disp("Example 2.66") printf("\n") disp("Calculate the effect of a 10% variation supply voltage on diode current") printf("Given\n") //input voltage Vi=25 //output voltage Vo=10 //test current(lies b/w Izmin & Izmax) Izt=20*10^-3 //load current(assume zero, no load operation) IL=10^-3 //select R such th...
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Ex16_2.sce
//Example 16.2 clc; syms z n; x1=(2^n); x2=(3^n); X1=symsum(x1*(z^-n),n,0,%inf); X2=symsum(x2*(z^-n),n,-%inf,0); X=X1+X2; disp(X,"ans=")
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isstable1.sce
b=[1 2 3 4 5]; a=[0.1 0.2 0.3 1.4 0.5]; flag=isstable(b,a); disp(flag); //output // unstable system // // 0.
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jacobi.sce
function x = jacobi(A, b, x, maxit) n=size(A, 1) for k=1:1:maxit for i=1:1:n sumatoria=0 for j=1:n if (j<>i) then sumatoria=sumatoria+A(i,j)*x(j) end x(i)=1/A(i,i) * (b(i) - sumatoria) end end end endfunction
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Ex9_2.sce
clc //initialisation of variables p1=1//lbf/in^2 p2=600//lbf/in^2 T=800//F v=0.01614//lbm Wp=v*(p2-p1)*144/778//Btu/lbm h1=69.70 h2=h1+Wp//Btu/lbm h3=1407.7//lbm s3=1.6343//lbm h4=913.3//lbm Wt=h3-h4//Btu/lbm Wnet=Wt-Wp//Btu/lbm qH=h3-h2//Btu/lbm //CALCULATIONS N=Wnet/qH*100//per-cent qL=h4-h1//Btu/l...
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3_10.sce
//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 3.10 //calculation of velocity of the swimmer with respect to ground //given data vsr=4//velocity(in km/h) of the swimmer with respect to water vrg=3//velocity(in km/h) of the river water with respect to ground //...
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Ex4_10_2.sce
clear clc Pt=747.3;//toatal pressure in torr PB=638.6;//vapour pressure of water PA=Pt-PB;//vapour pressure of liquid WA=1.27;//in gm WB=1;//in gm MB=18;//molar mass of water in gm/mol MA=(WA/WB)*((PB*MB)/PA);//molar mass of liquid in gm/mol printf('MA=%.1f gm/mol',MA) //page 192
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example_10_20.sce
clear; clc; disp("--------------Example 10.20---------------") n=21; // compute one's complement bin=dec2bin(n); s=strsplit(bin,1); a=bin2dec(s(1)); b=bin2dec(s(2)); f=a+b; complement=dec2bin(f,4); //1's complement dec_complement=bin2dec(complement); // convert 1's complement to decimal printf("The number %...
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~BivLCM-SR-bfi_o_vrt_col-PLin-VLin.tst
ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.248158D+00 2 0.137016D-03 0.213689D-02 3 -0.541331D-02 -0.12265...
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13_2.sci
// Chapter 13 Example 22// clc clear // air density factor=d0 ,barometric pressure=b,temperature=t,rating of transmission line=vcc// vcc=220; // in kV// b=73;// in cm of Hg// t=20;// in celsius// d0=3.92*b/(273+t); printf("\n Air density factor = %.4f \n",d0); // phase to neutral critical disruptive voltage=vc...
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diffuse_x3d.m
//save xyz values function diffuse_x3d(filename, n1,n2,n3,concs,h,maxconc,minconc) sDescription='Simple X3D example'; sCreated='30 October 2000'; sRevised='6 March 2003'; sURL='http://www.shef.ac.uk/personal/m/mikeg/x3d/diffuse_out.x3d'; sAuthor='Mike Griffiths'; fd=writex3d(filename ,sDescription, sCreate...
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EX15_1.sce
// Grob's Basic Electronics 11e // Chapter No. 15 // Example No. 15_1 clc; clear; // A sine wave of voltage varies from zero to a maximum of 100 V. How much is the voltage at the instant of 30° of the cycle? 45°? 90°? 270°? // Given data Vm = 100; // Vm=100 Volts t1 = 30; // Theta 1=30°. t2 = 4...
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clear; //clc(); l=80 cap=0.00914*10^(-6)*l; vl=132*1000; vph=vl/sqrt(3); f=50; l=1/(3*(2*(%pi)*f)^(2)*cap); printf("The inductance is:%.2f H\n",l) il=vph/((2*(%pi)*f)*l); kvar=vph*il/1000; printf("The rating of the arc suppression coil is:%.2f kVA",kvar)
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clc; clear; xx = [0.00 0.50 1.00 1.50 2.00 2.50 3.00 3.50 4.00 4.50 5.00] yy = [2.26 3.80 4.43 5.91 6.18 7.26 8.15 9.14 10.87 11.58 12.55] clf(); set(gca(),"auto_scale", "on"); set(gca(),"data_bounds", [-1,-1;7,14]); title("Dados"); xlabel("X"); ylabel("Y"); dxa=gda(); dxa.y_location="origin"; dxa.x_l...
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//chapter 17 Example 7 clc; clear; close; s1=200;s2=400;s3=600;s4=800; avgspeed=4/(1/s1+1/s2+1/s3+1/s4); printf("The average speed is %3.0f km/hr",avgspeed);
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clc //Initialization of variables p=0.1 //m T=30+273.2 //K R=0.08206 //lt atm /deg/mol P1=1 //atm //calculations w=1000/p V=w/1000 dP=R*T/V P=dP+P1 //results printf("Osmotic Pressure =%.2f atm ",P)
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//ex6.3 I_E=3.8*10^-3; B_ac=160; R1=22*10^3; R2=6.8*10^3; R_s=300; V_s=10*10^-3; r_e=25*10^-3/I_E; R_in_base=B_ac*r_e; R_in_tot=(R1*R2*R_in_base)/(R_in_base*R1+R_in_base*R2+R1*R2); V_b=(R_in_tot/(R_in_tot+R_s))*V_s; disp(V_b,'voltage at the base of the transistor in volts')
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// // //(a) BB_AB=30+(30/60) FB_AB=BB_AB mins=(FB_AB-int(FB_AB))*60 deg=int(FB_AB) printf("\n S %0.3f degrees %0.3f minutes E",deg,mins) //(b) BB_BC=40+(15/60) FB_BC=BB_BC mins=(FB_BC-int(FB_BC))*60 deg=int(FB_BC) printf("\n N %0.3f degrees %0.3f minutes W",deg,mins) //(c) BB_CD=60+(45/60) FB_CD=BB_CD mins=(FB_CD-i...
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clc; P=100000; // VA rating of two winding transformer E1=2000; // rated voltage of h v side E2=200; // rated voltage of l v side l=2.5; // percentage of loss in two winding transformer vr=3; // percentage of voltage regulation in two winding transformer z=4; // percentage of leakage impedance in two winding tr...
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//CHAPTER 3- THREE-PHASE A.C. CIRCUITS //Example 9 disp("CHAPTER 3"); disp("EXAMPLE 9"); //VARIABLE INITIALIZATION v_ab=400; //in Volts v_bc=400; //in Volts v_ac=400; //in Volts z_ab=100; //in Ohms z_bc=100; //in Ohms ...
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pa=-30//kPa p=9810//N/m^3 S=0.83//specific gravity of kerosene
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clc clear //Initialization of variables heat=54.5 //Btu/hr ft d=0.811 //in h=2.5 //Btu/hr ft^2 F ts=100 //F km=220 //Btu/hr ft F //calculations t2=heat*12/(h*%pi*d) +ts w=heat*4*144/(%pi*d^2) t1=w*(d/2)^2 /(4*144*km) + t2 //results printf("Surface temperature of transmission line = %.1f F",t2) printf("\n ...
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clc he=2609.9 //in kJ/kg hi=3072.1 //in kJ/kg ve=sqrt(2*(hi-he)*10^3) mprintf("ve=%fm/s",ve)//ans vary due to roundoff error
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//Determine the reliability of the system for 20 hrs. of operating period //page no 220 clear clc; dA = 0.01; dB = 0.015; dC = 0.02; dD = 0.02; dE = 0.025; t=20; RA =%e^(-dA*t); RB =%e^(-dB*t); RC =%e^(-dC*t); RD =%e^(-dD*t); RE =%e^(-dE*t); RBC = 1-((1-RB)*(1-RC)); RABC = RA*RBC; RABCD = 1-((1-RABC)*(...
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{ "EGTE 150800Z 1509/1518 18005KT 9999 BKN040 TEMPO 1511/1512 BKN010 TEMPO 1512/1513 BKN006 TEMPO 1513/1514 BKN003 TEMPO 1514/1515 BKN001": { "TAF base conditions cover METAR - cloud BKN050": { "metar": "EGTE 150850Z 18005KT 9999 BKN050", "test time": "20200615T0900Z", "e...
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//variable initialization mu=9.27*10^-24; //(J/T) B=0.45; //magnetic field (μb/m^2) h=1.054*10^-34; //Plank's constan...
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//fiber optic communications by joseph c. palais //example 4.3 //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given lambda=0.82//wavelength in um n1=3.6//refractive index of core AlGaAs slab n2=3.55//refractive index of cladding n3=3.55//refractive index of cladding n0=1//refractive index of Air ...
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clear; clc; //for low loads p1(1)=20; p2(1)=30; t1(1)=.1*p1(1)+20; t2(1)=.12*p2(1)+16; //when load is further increased t2(4)=22; p2(4)=(t2(4)-16)/.12; t1(4)=t2(4); //upper limit 125MW p2(5)=125; t1(5)=1.12*p2(5)+16; p1(5)=(t1(5)-20)/.1; n=7; t2(1)=19.6; t2(2)=20; t2(3)=21; t2(4)=22; t2(5)=31; t2(6...
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//Example 12.4 clc clear V_A=0 //a=input("Enter the binary digit(5 bits) :" ); a=11010 for i=1:5 r=modulo(a,10); b(1,i)=r; a=a/10; a=floor(a); end for j=1:5 V_A = V_A + 10*b(1,j)*2^(j-1); end; V_A=V_A/2^5; disp("The output voltage in volts is '); disp(V_A); // displaying the value
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//Example No. 3.13.1 clc; clear; close; format('v',6); Irms=15;//A(Current Drawn) Prad=5;//kW(Radiated Power) Rr=Prad*10^3/Irms^2;//Ω(Radiation Resistance) disp(Rr,"Radiation resistance in Ω : ");
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clc; clear; D_4=0.4 //diameter of the 4th dark ring in cm D_12=0.7 //diameter of the 12th dark ring in cm //calculation D_20=sqrt(2*((0.7^2)-(0.4^2))+0.4^2) mprintf("The diameter of the 20th dark ring is = %1.3f cm",D_20)
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