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Ex1_5_1.sce
clear ; clc ; T1 = 234.5 ;// Temperature in K P = 1 ; // Pressure in atm rho1 = 14.19 // Density of solid Hg in g/(cm^3) rho2 = 13.70 // Density of liquid Hg in g/(cm^3) V = 200.59 // volume of liquid and solid in g/mol delV = ((V/rho2)-(V/rho1))*(10^-3)// in dm^3/mol delTdelP = 0.0051 // K/atm R1 = 8.314 // in J R2 = ...
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// Example 10_9 clc;funcprot(0); // Given data T=400;// °C P=1;// MPa v=0.3066;// m^3/kg // Calculation ds=7.619-7.302;// kJ/kg.K dT=450-350;// K c_p=(T+273)*(ds/dT);// kJ/kg.K dv=0.3304-0.2825;// m^3/kg mu_j=(1/(c_p*10^3))*[((T+273)*(dv/dT))-v];// K/Pa printf("\nThe Joule thomson coefficient,mu_j=%1.2e K...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 23 clc; disp("CHAPTER 1"); disp("EXAMPLE 23"); //VARIABLE INITIALIZATION I1=20; //current source in Amperes v1=10; //voltage source in Volts v2=40; //voltage source in Vo...
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//Example 5.20 clc;clear;close; z=poly(0,'z'); x=[-1 1 0 -1];n=0:length(x)-1; X=x*(z^-n)'; H=0.2-0.5*z^-2+0.4*z^-3 Y=H*X; l=coeff(numer(Y)); y=l(:,$:-1:1); disp(X,'Input sequence x(n)={-1,1,0,-1} X(z)='); disp(H,'System Transfer Function H(z)='); disp(Y,'Z transform of output response Y(z)='); disp(y,'Dig...
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//Example 2.6.4:limiting error clc; clear; close; format('v',6) r1=120;//in ohms er1=0.5;//limiting error in resistance 1 in ohms ± r2=2;//in amperes er2=0.02;//limiting error in amperes ± e1=er2/r2;//limiting error in current e2=er1/r1;//limiting eror in resistance et=(2*e1+e2);//totak error etp=et*100;//percentage li...
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clc //Chapter 12:Frequency mixers //example 12.4 //given f=1*10^3//maximum frequency of unknown signal df=1//maximum error in signal fs=f^2/df//sampling frequency disp(fs,'the required sampling frequency is')
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clear //Given v=2.0*10**8 //m/s c=3*10**8 //m/s d=6.0 //cm //Calculation ug=c/v a=d/ug D=d-a //Result printf("\n Distance through which ink dot appears to be raised is %0.3f cm", D)
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src = imread("../images/color2.jpeg"); //reading an image gray = rgb2gray(src); //converting to grayscale depth = getDepth(gray) ; //get the depth disp(depth) ; //view the output
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vnl=1.2; vfl=1.1; disp("Part a"); p_v=(vnl-vfl)*100/vfl; disp("the percentage voltage regulation of the cell (in %) is"); disp(p_v); disp("Part b"); p_v1=40; vnl1=21; vfl1=vnl1/(1+p_v1/100); disp("the full-load voltage (in V) is"); disp(vfl1);
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//Chapter 1 Example1// //core refractive index of silica optical fibre =n1,cladding refractive index of silica optical fibre =n2,critical angle =p,angle of obliqueness=pm// n1=1.5;n2=1.450; p=asind(n2/n1); pm=90-p; printf("\n a)angle of obliqueness=%f\n",pm); //refractive index for air=na,acceptance angle in air=...
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// Test # 13 : Valid input test case #3 exec('./allpassshiftc.sci',-1); [n,d]=allpassshiftc(-0.261,-0.346); disp(d); disp(n); // //Scilab Output //d=1. 0. //n=0 0.9645574 - 0.2638730i // //Matlab Output //d=1 0 //n=0.0000 + 0.0000i 0.9646 - 0.2639i
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clear //Given Vcc=8 //V V=0.5 //V Rc=800.0 //ohm a=0.96 //Calculation Vce=Vcc-V Ic=V/Rc*10**3 B=a/(1-a) Ib=Ic/B //Result printf("\n (i) Collector-emitter voltage is %0.3f V",Vce) printf("\n (ii) Base current is %0.3f mA",Ib)
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//<-function-- function tour = tspGreedy(start) // // INPUT: // start ... start index (optional = 1) // // OUTPUT: // tour ... nearly optimal greedy tour global dist; if argn(2) == 0 then start = 1; end n = size(dist,'r'); tour = start; rest = 1:n; re...
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// scilab Code Exa 18.50 Centrifugal pump 1500 rpm N=1500; // rotor Speed in RPM H=5.2; // head in m b=2/100; // width in m d1=2.5/100; // entry diameter of the blade ring in m d2=0.1; // exit diameter of the blade ring in m rho=1e3; g=9.81; // Gravitational acceleration in m/s^2 n_o=0.75; // overall Efficien...
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int fib(int n) begin int i1; int i2; int k; int ret; if (2 < n) then begin i1 = 1; i2 = 1; k = 2; do begin ret = i1 + i2; i1 = i2; i2 = ret; k = k + 1; end while(k < n); end if (!(2 < n)) then begin ret = 1; end return ret; end main begin ...
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mode(-1) // function definition deff('[x]=t1(a,b,n)',[ 'z=n+m+n,' 'c(1,1)=z,' 'c(2,1)=z+1,' 'c(1,2)=2,' 'c(2,2)=0,' 'if n=1 then,' ' x=a+b+a,' 'else,' ' x=a+b-a''+b,' 'end,' 'y=a(3,z+1)-x(z,5),' 'x=2*x*x*2.21,' 'sel=1:5,' 't=a*b,' 'for k=1:n,' ' z1=z*a(k+1,k)+3,' 'end,' 't(sel,5)=a(2:4,7),' 'x=[a b;-b'' a'']'],'n') //...
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% Some interpreted tests of PROG for MAIN9 (Dashed "Expect 1 printed") (shouldbe "Prog Value" (PROG NIL (print 1)) NIL) (Dashed "Expect 1 and 2 printed") (shouldbe "Prog value" (PROG NIL (print 1) (print 2) (return 3)) 3) (Dashed "Test 1 var PROG binding") (ShouldBe "Before PROG, x=" (setq x 2) 2) (Shouldbe "Prog ...
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//Chapter 2, Problem 15 clc; V=15; //e.m.f I=2; //current t=6*60; //time period E=V*t*I; //calculating energy printf("Energy = %f kJ",E/1000);
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function []=delete(sd) //destruction d'un objet xx=locate(1);eps=0.2 mm=clearmode(); //recherche de l'objet contenant le point for ko=2:ksd; obj=sd(ko); to='rien';if size(obj)<>0 then to=obj(1);end, select to case 'ligne' then z=obj(2),[nw,npt]=size(z), for kpt=2:npt ...
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function [lambda,eigen_vec] = Metodo_pot_desloc_inv(A,initial_vector,epsilon,alfa) [row_num,col_num] = size(A) I = eye(row_num,col_num) //parte crucial do método, redefinindo a matriz A //A passa a ser A menos o produto de alfa vezes a matriz identidade A = A - (alfa*I) //f...
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clc; p1=1; // Pressure of fluid at inlet in bar T1=60; // Temperature of fluid at inlet in degree celcius p2=2.8; // Pressure of fluid at outlet in bar eff_d=0.80; // Diffuser efficiency k=1.4; // Index of reversible adiabatic process Cpo=1.0035; // Specific heat at constant pressure in kJ/kg K // (a).Actual D...
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//Chapter-10, Example 10.15, Page 430 //============================================================================= clc clear //INPUT DATA D=0.2;//Diameter of each disc in m L=2;//Distance between the plates in m T=[800+273,300+273];//Temperatures of the plates in K e=[0.3,0.5];//Emissivities of plates /...
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//example1.4 clc disp("The equivalent resistance of two is,") r=(10*20)/30 format(5) disp(r,"R_eq(in ohm)=(R1*R2)/(R1+R2)=") i=50/6.67 format(4) disp(i,"I_t(in amp)=V/R_eq=") disp("As per the current distribution in parallel circuit,") i=(7.5*20)/30 disp("I_1(in amp)=(I_t*R2)/(R1+R2)=") i=75/30 disp(i,"and...
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clc // Given that lambda = 1e-10 // wavelength of light in meter theta = 90 // angle at which scattered radiation is viewed in degree h = 6.62e-34 // Planck constant in J-sec c = 3e8 // speed of light in m/sec e = 1.6e-19 // charge on an electron in C m = 9.1e-31 // mass of an electron in kg // Sample Problem 23 on p...
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//example 10.2 clc; funcprot(0); // Initialization of Variable phi1=0.8; pg1=0.01228; pa1=0.9902*10^5;; R=8314;//gasconstant T=283; pv1=phi1*pg1; va1=R/28.97*T/pa1; madot=150/va1; omega=0.622*(pv1/(1-pv1)); Qcvdot=madot*(303.2-283.1)+omega*(2556.3-2519.8); disp(Qcvdot,"heat flow rate in kJ/min"); pv2=pv1;...
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clc T=300 //K k=8.617*10**-5//eV/K e=1.6*10**-19 //C Cox=6.9*10^-8//F/cm2 esp0=8.85*10^-14 Vtau=0.65//V VGS1=1.5//V VGS2=2.5//V VDS=0.10//V L=2*10^-6//cm u=650//cm^2/Vs ID1=35*10^-6//A ID2=75*10^-6//A W=15*10^-6//m un=(ID2-ID1)*L/(W*Cox*(VGS2-VGS1)*VDS) disp(un,"un in cm^2/Vs is=")
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex11_3.sce clc; clear; Ra=0.8; Va=40; Td=1.2; Ka=600; phi_p=0.004; printf("\n (a)") n=(Va/(Ka*phi_p))-(2*%pi*Ra*Td/(Ka*phi_p)^2); N=n*60; printf("\n The spe...
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0.359684 0.1875 0 0 0 0.0152091 2.98764e-05 0.0186335 0.000408754 0.878389 0.845219 0.932253 0.85191 0.324627 0.597647 0.345351 0.932253 0.176061 0.120435class1 0.0118577 0.120833 0 0 0 0.0456274 0.00273375 0.0248447 0.00152815 0.119804 0.114263 0.154639 0.0880748 0.757463 0.327059 0.341556 0.154639 0.46306 0.211624cla...
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// Example 2.4 // a)To convert transmitted power into dBm b)To convert received power into mW // Page no. 61 clc; clear; // Given data Ptr=0.012; // Transmitted power in watt PrdBm=-5; // Received power in dBm // a)To convert transmitted power ...
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clc disp("Example 3.50") printf("\n") disp("Draw a DC load line for the base bias circuit") printf("Given\n") //given Rc=2.2*10^3 Rb=470*10^3 Vcc=18 Vbe=0.7 hFE=100 //find the Ib Ib=(Vcc-Vbe)/Rb // from ciruit //find the Ic Icq=hFE*Ib //find the Vceq Vceq=Vcc-(Icq*Rc) //to draw Dc load line Ic1=Vcc/...
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clc; // page no 731 // prob no 19.7 // In given problem a TV receiver is tuned to channel 6. //All modern Rx uses a picture IF of 45.75 MHz with high-side injection of the signal into the cable. // The picture carrier of channel 6 is at a frequency of 83.25MHz,so ch=6; Fc=83.25;// expressed in MHz IF=45.75;//ex...
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//Example 10.10 m=0.75;//Mass of the cylinder (kg) h=2;//Height of incline (m) R=4*10^-2;//Radius of cylinder (m) g=9.8;//Acceleration due to gravity (m/s) v=sqrt((m*g*h)/[(1/2*m)+(1/2*1/2*m*R^2/R^2)]);//Final velocity, See Equation 10.86 (m/s) printf('Final speed = %0.2f m/s',v) //Openstax - College Physics /...
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//chapter 5 Ex 15 clc; clear; close; //let the value to be found out be z z=(1+sqrt(2))^2+(1-sqrt(2))^2; mprintf("The value of expression (x^2+y^2) is %.0f",z);
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(" - 24 + 16*x + 64*x^2 - 216*y - 576*y^2 - 512*y^3").getGrowingFactors (" - 24 + 8*x + 16*x^2 - 108*y - 144*y^2 - 64*y^3") = 1,2,4,2,4,8
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clc p=100000 //Assigning values to parameters il=80 vl=1100 f=50 vph=vl/sqrt(3) iph=il zph=vph/iph t=acosd(p/(sqrt(3)*vl*il)) zph1=5.21-%i*6 [r]=real(zph1) [xc]=abs(imag(zph1)) c=1/(2*%pi*f*xc) disp("ohms",r,"The resistive circuit constant is") disp("ohms",xc,"The capacitive circuit cons...
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clear;lines(0); A=diag([-1,-2]);B=[1;1];C=[1,1];D=1;s=poly(0,'s'); W1=syslin('c',A,B,C,D); phi=gtild(W1,'c')+W1; phis=clean(ss2tf(phi)) clean(phis-horner(phis,-s)'); //check this is 0... [A,B,C,D]=abcd(W1); [W0,L]=specfact(A,B,C,D); W=syslin('c',A,B,L,W0) Ws=ss2tf(W); horner(Ws,-s)*Ws
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//check o/p when i/p is a matrix containing imaginary and nan elements v=[3 5 2 ;1+6*%i 6 3; %nan 7 8 ]; m=cummax(v,'reverse'); disp(m); //output // Nan 7. 8. // Nan 7. 8. // Nan 7. 8. // //corresponding MATLAB o/p //1.0000 + 6.0000i 7.0000 + 0.0000i 8.0000 + 0.0000i // 1.0000 + 6...
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EXAMPLE11_56.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 11 //Information Theory clear all; clc; printf("EXAMPLE 11.56(PAGENO 538)"); //given B = 3.4*10^3//bandwidth SbyN = 30//signal to the noise ratio in dB //calculations SbyN1 = exp((SbyN/10)*log(10))//signal to noise ratio C = B*log2(1+...
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clc disp("the soln of eg 9.2-->Transient Conduction in Rectangular Slab"); delta_t=1, delta_x=.05, alpha=10^-5 t1=alpha*delta_t/delta_x^2 for i=2:9, a(i)=-t1 end for i=1:9,b(i)=1+2*t1 end for i=1:8, c(i)=-t1 end t=1,tf=3000 for i=1:9, x(i)=300 end e1=425, disp("time when centre temp is 425 K in secs. is")...
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/*------------------------------------------------- Auteur : Manon Cassagne & Valentin Labat Vous trouverez ci-dessous la fonction IRLS ---------------------------------------------------*/ /* ENTRÉES : x : signal donné D : dictionnaire p : un entier nb_it_max : nombre maximal d'itérations SORTIES :...
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errcatch(-1,"stop");mode(2);//Example 19.5 q=1.6*10^-19 B=.35 r=14*10^-2//in m m=1.67*10^-27//kg v=(q*B*r)/m disp(v,"Velocity in m/s=") exit();
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// Scilab Code Ex1.16: Page-1.18 (2009) clc; clear; h = 6.6e-034; // Planck's constant m = 9.1e-031; // Mass of a electron, kg e = 1.6e-019; // Electronic charge, C V = 100; // Accelerating potential for electron, V E = e*V; // Energy of the electron, J lambda = h/sqrt(2*m*E); // de-Broglie w...
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clear; clc; close; disp("dy(t)/dt+2y(t)=x(t)"); w=0.1:0.1:10; t=w; dw=.1; Xw=ones(1,length(w))./(%i*w); Hw=ones(1,length(w))./(2+%i*w); Yw=Xw.*Hw; y=Yw*exp(%i*t'*w)*dw; d=gca() plot(t,y); poly1=d.children.children; poly1.thickness=3; poly1.foreground=2; xtitle('y(t)','t') yy=0.5*(1-exp(-2*t)); disp("y...
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////Chapter 13 Steam Engines ////Example 13.14 Page No 294 ///Example Mechanical efficiency //Input data clc; clear; D=300*10^-3; //steam engine bor L=400*10^-3; //stroke Db=1.5; //effective brake diameter W=6.2*10^3; //net load on the brake ...
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a=imread('bima.jpg'); d=double(a); A=1.1; BB=(9*A)-1; m1=[-1 -1 -1;-1 BB -1;-1 -1 -1]; m=[-1 -1 -1;-1 8 -1;-1 -1 -1]; dme=d(:,:,1); dhi=d(:,:,2); dbi=d(:,:,3); [r1,c1]=size(a); for i=2:1:r1-1 for j=2:1:c1-1 new1(i,j)=(m1(1)*dme(i-1,j-1))+(m1(2)*dme(i-1,j))+(m1(3)*dme(i-1,j+1))+(m1(4)*dme(i,j-1))+(m1(5)*dme(...
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k=[1 2 3 4 5 7]; [num,den] = latc2tf(k,'min'); disp(num); disp(den); //output // column 1 to 5 // // 1. 76. 1013. 2512. 1859. // // column 6 to 7 // // 292. 7. // // 1. //
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getd ('../../libs/'); img = readpbm('Europa_surface.pbm'); xmax = size(img,1); ymax = size(img,2); noyau = [ 1/24 1/24 1/24 1/24 15/24 1/24 1/24 1/24 1/24 ]; scf(0) display_gray(img) // Garde uniquement les blancs for x=1:xmax for y=1:ymax if(img(x,y) < 255)then img(x,y) = 0; ...
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//clear// //Example9.38:Unilateral Laplace Transform:Solving Differential Equation //Y(S)=[beta(s+3)/((s+1)(s+2))]+[gamma/((s+2)(s+2))]+[alpha/(s(s+1)(s+2))] s = %s; syms t; alpha = 2; //input constant beta_B = 3; //intial condition gamma_v = -5; //initial condition Y1 = 1/s; Y2 = 1/(s+1); Y3 = 3/(s+2); Y =...
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clear; clc; printf("\t\t\tProblem Number 11.2\n\n\n"); // Chapter 11: Heat Transfer // Problem 11.2 (page no. 553) // Solution deltaX=0.150; //Given,150 mm =0.150 meter // //deltaX=length //Unit:meter k=0.692; //Unit:W/(m*celcius) //k=proportionality constant //k=thermal conductivity T1=70; //temperature ma...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 9: POLYPHASE INDUCTION (ASYNCHRONOUS) DYNAMOS // Example 9-18 clear; clc; close; // Clear the work space and console. // Given data // three-phase WRIM V_o = 220 ; // Rated voltage in volt P_o = 10 ; // Rate...
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clear; i1=1; i2=1; //a=zeros(2,2); //PRIMERA MATRIZ while i1<3 then x1=input("agregue el valor par la posicion 1,"+ string(i1) +" de la matriz 1:"); a(1,i1)=x1; i1=i1+1; end while i2<3 then x2=input("agregue el valor par la posicion 2,"+ string(i2) +" de la matriz 1:"); a(2,i2)=x2; i2=i2+1; en...
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//Example 1.9: clc; clear; close; //given data : e=1.6*10^-19;// in V Pp=10^-1;// p-type silicon in ohm-m Pn=10^-1;// n-type silicon in ohm-m mu_hsi=0.048;// holes mobilities in m^2/V-s mu_esi=0.135;// electrons mobilities in m^2/V-s nisi=1.5*10^16;//in m^-3 nesi=nisi;// nhsi=nisi;// mu_hge=0.19;// holes mobilities in...
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//Example 1.9 Conversion from binary number to Hexadecimal number. clc; x = bin2dec('1011101010'); // decimal equivalent of binary number z = dec2hex(x); //hexadecimal equivalent of decimal number disp('The hexadecimal number is = '); disp(z) // answer in hexadecimal form
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// Exa 5.4 clc; clear; close; // Given data R1 = 4.3;// in K ohm R1= R1*10^3;// in ohm R2 = 10;// in K ohm R2= R2*10^3;// in ohm r_e = (R1*R2)/(R1+R2);// in ohm bita = 200; V=25;// in mV I= 1;// in mA r_e_desh= V/I;// in ohm Zin_base = bita*(r_e + r_e_desh);// in ohm disp(Zin_base*10^-3,"The input impede...
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//Chapter-1,Example1_3_6,pg 1-18 a=0.4049*10^-9 //lattice constant t=0.006*10^-2 //thickness of Al foil A=50*10^-4 //Area of foil V1=a^3 //volume of unit cell V=A*t ...
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// Topografia IV // Allan Turini Speroto 78233 // Fernando Martins Pimenta 80018 // Gabriel Batista Freitas 82718 // Matheus Lopes Vieira 80020 // Interface gráfica // Tela da aplicação f=figure('figure_size',[1000,480],... 'auto_resize','on',... 'figure_name','Ajustamento por I...
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//Variable declaration: Ts = 200.0+460.0 //Surface temperature of pipe (°R) Too = 70.0+460.0 //Air temperature (°R) D = 0.5 //Diameter of pipe (ft) R = 0.73 //Universal gas constant (ft^3.atm.R^−1.lb.mol^−1) P = 1.0 //A...
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بحث کردن V;PROG;PL;3;COL;PST فارغالتحصیل شدن V;PRF;PL;1;PRS اغوا کردن V;PL;2;FUT پاک کردن V;PROG;PL;2;PST باختن V;IPFV;PL;1;PRS طرفداری کردن V;IPFV;SG;2;PRS منتشر کردن V;PFV;PL;1;COL ازدواج کردن V;PROG;PL;2;PRS گشادن V;SG;1;FUT آغاز شدن V;PROG;PL;2;COL;PRS اغوا کردن V;IPFV;SG;2;COL;PST به کار بردن V;PFV;SG;2 وا کردن V;...
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[[3,1,2,-1],[-2,0,-2,1],[-1,-2,1,-1],[-2,-1,-1,1]] * [a,b,c,d] = 10*a^3+9*a^2*b-9*a*b^2-8*b^3+21*a^2*c+36*a*b*c+15*b^2*c+3*a*c^2+3*b*c^2-6*a^2*d-18*a*b*d-12*b^2*d+6*a*c*d+6*b*c*d-6*a*d^2-6*b*d^2
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sce
Chapter17_example2.sce
clc clear //Input data L2=0.032//Length of the wax melted portion in the iron rod in m L1=0.08//Length of the wax melted portion in the copper rod in m K1=385//Thermal conductivity of copper in W/m.K //Calculations K2=(K1*L2^2)/L1^2//Thermal conductivity of iron in W/m.K //Output printf('Thermal conductivi...
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2020-04-09T02:43:26.499817
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7_1.sce
//7.1 clc; Vzb=14.8; Vt=0.85; V=Vzb+Vt; printf("The value of Voltage which will turn On the crowbar=%.2f V",V)
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hohiroki/Scilab_TBC
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2021-01-18T02:07:29.200029
2016-04-29T07:01:39
2016-04-29T07:01:39
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UTF-8
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sce
exa_2_12.sce
errcatch(-1,"stop");mode(2);// Exa 2.12 ; ; // Given data format('v',9) IB1= 10;// in mA IB2= 7.5;// in mA I_in_bias= (IB1+IB2)/2;// in mA disp(I_in_bias,"Input bias current in mA") I_in_offset= IB1-IB2 ;// in mA disp(I_in_offset,"Input offset current in mA") // Note: Units in Answer in the book is wrong...
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/htym.sce
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2020-09-08T07:59:31.719500
2019-11-11T21:14:13
2019-11-11T21:14:13
221,070,925
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281
sce
htym.sce
clc; f=figure(); set(f,'position',[200,20,400,300]); set(f,'figure_name','Лабораторная работа №21'); set(f,'BackgroundColor',[1,0.9,0.9]); rbt1=uicontrol(f,'style','radiobutton','string','sin(x)','value',0,'position',[90,225,70,30],'BackgroundColor',[1,1,1]);
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sce
Ex11_1.sce
clear; clc; //Example 11.1 V1=10; V2=-10; Iq=1; Rc=10; Vbe=0.7; iC1=Iq/2; iC2=iC1; printf('\ncollector currents =%.2fmA\n',iC1) Vc1=V1-iC1*Rc; Vc2=Vc1; printf('\ncollector voltages =%.2fV\n',Vc1) Vcm=0; Ve=Vcm-Vbe; Vce1=Vc1-Ve; printf('\ncollector emitter voltage=%.2f V\n',Vce1) Vcm=-5; Ve=Vcm-Vbe; ...
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/3733/CH24/EX24.10/Ex24_10.sce
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sce
Ex24_10.sce
// Example 24_10 clc;funcprot(0); //Given data T_1=20+273;// K p_1=1;// bar T_6=700+273;// K p_r=6;// Pressure ratio e=0.7;// The effectiveness of regenerator m_air=200;//Air flow through the plant in kg/sec n_c=0.82;// Isentropic efficiency of both compressors n_t=0.92;// Isentropic efficiency of turbine n...
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2020-04-09T02:43:26.499817
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37,975,407
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sce
11_08.sce
//pathname=get_absolute_file_path('11.08.sce') //filename=pathname+filesep()+'11.08-data.sci' //exec(filename) //Specific heat of hot gases(in kJ/kg.K): Cpg=1.0032 //Temperature of burnt gases(in K): Tg=177+273 //Ambient air temperature(in K): Ta=27+273 //Natural draught temperature(in K): Tn=327+273 //Mass ...
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/69/CH4/EX4.1/4_1.sce
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2020-04-09T02:43:26.499817
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37,975,407
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Scilab
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sce
4_1.sce
clear; clc; close; Vcc = 12; Vbe = 0.7; Vce = 4.23; Rb = 240*10^(3); Rc = 2.2*10^(3); Beta = 75; Ic = 3.53*10^(-3); Ibq = (Vcc-Vbe)/Rb; Icq = Beta*Ibq; Vceq = Vcc-Ic*Rc; Vb = Vbe; Vc = Vce; Vbc = Vb-Vc; disp(Ibq,'Ibq(Amperes) is :'); disp(Icq,'Icq(Amperes) is :'); disp(Vceq,'Vceq(volts) is :'); ...
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/3878/CH1/EX1.3/Ex1_3.sce
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2020-04-09T02:43:26.499817
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37,975,407
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431
sce
Ex1_3.sce
clear // Variable Declaration P=1.013// Pressure in bar h_fg=2257// The latent heat of boiling water in kJ/kg T_b=100 // The boiling point temperature of water in °C m=1 // The mass of water in kg T_i=30 // The initial temperature of water in °C C_p=4.19// The specific heat of water in kJ/kg°C // Calculation Q=m*((C_p...
fa755cd6be41d1623420aa7c9bf8a5ec42b27edc
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/projects/02/Ng16.tst
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btesf/nand_to_tetris
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2023-05-28T00:08:37.728944
2021-06-19T17:09:22
2021-06-19T17:09:22
356,931,420
0
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296
tst
Ng16.tst
load Ng16.hdl, output-file Ng16.out, compare-to Ng16.cmp, output-list a%B1.16.1 out%B1.1.1; set a %B0000000000000000, eval, output; set a %B1111111111111111, eval, output; set a %B1010101010101010, eval, output; set a %B0011110011000011, eval, output; set a %B0001001000110100, eval, output;
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2020-04-09T02:43:26.499817
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sce
EX1_13.sce
//Example 1.13<i> //Check whether the given signal is periodic or not clc; t1=-10:.01:10; y1=2*cos(10*t1+1)-sin(4*t1-1); subplot(221) plot(t1,y1); disp('(a) The following signal is periodic with period %pi' ); //Example 1.13<ii> //Show whether the given signal is periodic or not clc; t2=-1:.01:1; x2=cos(60*%pi*t2)+sin(...
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/lab4/Signed/Wtreesigned.tst
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bharath1729/lab4-unsigned
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2023-08-05T10:49:46.886409
2021-09-19T13:52:43
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2021-09-19T13:52:52
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Scilab
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tst
Wtreesigned.tst
load Wtreesigned.hdl, output-file Wtreesigned.out, output-list a%B3.8.3 b%B3.8.3 out%B3.8.3 of%B3.1.3; set a %B00001000, set b %B00000101, eval, output; set a %B10001000, set b %B10100000, eval, output; set a %B11111101, set b %B11110101, eval, output; set a %B00100000, set b %B00000100, eval, output; set a %B1000...
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/2258/CH2/EX2.12/2_12.sce
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2020-04-09T02:43:26.499817
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2018-02-03T05:31:52
37,975,407
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sce
2_12.sce
clc(); clear; // To calculate the relaxation time of conduction electrons rho=1.43*10^-8; //resistivity in ohm-m n=6.5*10^28; //electron/m^3 m=9.11*10^-34; //mass in kg e=1.6*10^-19; //charge in coulomb tow=m/(n*(e^2)*rho); printf("relaxation time of conduction electrons in sec is"); disp(tow);
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/2216/CH5/EX5.2/ex_5_2.sce
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sce
ex_5_2.sce
// Example 5.2;//difference between propogation constant and modal birefringence clc; clear; close; format('v',6) disp("part (a)") bl=10;//beat length in cm h=1;//in micro meter db=((2*%pi)/(bl*10^-2));//in m^-1 disp(db,"difference between propogation constant in m^-1") disp("part (b)") format('v',8) mb=db*((h*10^-6)/(...
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/1172/CH2/EX2.13/Example2_13.sce
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2020-04-09T02:43:26.499817
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37,975,407
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sce
Example2_13.sce
clc // Given That r = 7e8 // radius sun in meter power_sun = 3.8e26// power radiated by sun in W //Sample Problem 13 Page No. 86 printf("\n # Problem 13 # \n ") s = power_sun /(4 * %pi * (r^2)) //calculation of Pressure applied by sun radiations on earth printf("Pressure applied by sun radiations on earth is %e...
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/Metodos/Clase4/ejemplos/jacobi.sce
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2020-11-14T00:45:57
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sce
jacobi.sce
clc() clear all x1 = 0 x2 = 0 x3 = 0 disp("Jacobi") for i=2:1:4 disp("iteración "+string(i-1)) xa1= x1 xa2 = x2 xa3 = x3 x1 = (588.6+100*xa2)/150 x2 = (686.7+100*xa1+50*xa3)/150 x3 = (784.8 + 50*xa2)/50 disp("variables") disp([x1,x2,x3]) disp("errores aproximados") disp(100*(...
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/548/CH6/EX6.4.b/6_4b.sce
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739
sce
6_4b.sce
pathname=get_absolute_file_path('6_4b.sce') filename=pathname+filesep()+'6_4b_data.sci' exec(filename) clf(); V=linspace(40,300,500); i = 1; Cl = 0;Cd = 0;Cl_Cd =0;Thrust = 0; while(i<=length(V)) Cl(i) = 2*W/(D*S*V(i)^2); Cd(i) = Cdo + Cl(i)^2/(%pi*e*AR); Cl_Cd(i) = Cl(i)/Cd(i); Thrust(i) = ...
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sce
Ex1_23.sce
// Ex 23 Page 364 clc;clear;close; // Given Zo=50;//ohm VSWR=2;//ratio //lm=0.2*lamda lmBYlamda=0.2 betaINTOlamda=2*%pi rho=(VSWR-1)/(VSWR+1);//reflection coefficient theta=2*betaINTOlamda*lmBYlamda;//radian //exp(j*theta)=cos(theta)+%i*sin(theta) ZL=Zo*(1-rho*(cos(theta)+%i*sin(theta)))/(1+rho*(cos(theta)+%i*sin(thet...
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sci
75.sci
clc; clear all; disp("Thickness of insulation") r1=8/2;//mm k=0.18;// W/(m*C) ho=12.5;// W/(m^2*C) rc=1000*k/ho;//mm r2=rc;//mm t=r2-r1;//mm L=1;//m disp("mm",t,"Thickness of insulation = ") t1=45;// degree C t2=20;// degree C delT=t1-t2; A=2*3.1416*L*r1/1000; Q1=ho*A*delT; disp("W/m",Q1,"heat flow pe...
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/2780/CH3/EX3.17/Ex3_17.sce
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clc //to calculate angle of diffraction n=1 //order lambda=5000*10^-8 //wavelength of light in cm eplusd=1/5000 // in cm theta=asind(n*lambda/(eplusd)) disp("angle of diffraction for maximum intensity in the first order is theta="+string(theta)+"degree")
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clc; l=1; // m b=0.3; // m n=0.014; // s/m^(1/3) i=1/1000; A=l*b; P=2*b+l; m=A/P; Q=A/n*m^(2/3)*sqrt(i); disp("The delivery of water through the channel is found to be ") disp(Q) disp("m^3/s")
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// Scilab Code Ex 1.24 Miller-Bravias indices for Miller indices: Page-29 (2010) function [i] = f(h,k) i = -(h + k); endfunction h1 = 1; k1 = 1; l1 = 0 ; // First set of Miller indices h2 = 1; k2 = -1; l2 = 0; // Second set of miller indices h3 = 3; k3 = 4; l3 = 5; // Third set of miller indices ...
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//Electric Power Generation, Transmission and Distribution by S.N.Singh //Publisher:PHI Learning Private Limited //Year: 2012 ; Edition - 2 //Example 17.2 //Scilab Version : 6.0.0 ; OS : Windows clc; clear; V=110; //Supply voltage in kV P1=30; ...
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clc; vpp=25; //peak to peak voltage in volt vp=vpp/2; //calculating peak value in volt rms=vp/sqrt(2); //calculating rms value disp(rms,"Rms value in volt = "); //displaying result
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errcatch(-1,"stop");mode(2); syms n; v=n u=((1/n)^2)/((3/n+1)*(3/n+4)*(3/n+7)) disp(limit(u/v,n,0)); disp('both u and v converge and diverge together,hence u is divergent') exit();
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//Chapter-7, Example 7.11, Page 298 //============================================================================= clc clear //INPUT DATA Ta=30;//Temperature of air stream in degree C v=25;//Velocity of stream in m/s x=0.05;//Side of a square in m D=0.05;//Diameter of circular cylinder in m Ts=124;//Surface...
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//convert practical current source to voltage source V=10*5 //KVLs A=[35,-20;-20,50] I=inv(A)*[50;-100] v=20*(I(1)-I(2)) disp(v)
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//check o/p for an all pole filter impr=[0.00482434335771622 0.0307287177680858 0.0905946819548830 0.167944821844737 0.224641271344028 0.233457187867600 0.193512552162805 0.123765243571014 0.0496036031380564 -0.00850905187491905 -0.0406738350178078 -0.0475631979469693 -0.0368517338223927 -0.0185628385243508 -0.00125221...
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clc //Initialization of variables P1=700 //kN/m^2 P2=400 //kN/m^2 D2=12.5 //cm D1=25 //cm C=0.985 g=9.81 R=287 //m^2/s^2 K T=273+20 //K //calculations Pr=P2/P1 Dr=D2/D1 Y=0.72 gam1=P1*g/(R*T) G=C*Y*%pi/4 *(D2/100)^2 *sqrt(2*g*gam1*(P1-P2)/(1- Dr^4)) //results printf("Weight flow rate = %.4f kN/s",G)
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clc //initialisation of variables w= 15 //ft D= 15 //ft W= 62.4 //lb/ft^3 a= 120 //degrees h1= 15 //ft h2= 4 ///ft h3= 18 //ft //CALCULATIONS Pu= w*D*W*w/2 hu= ((w*D^3/12)/(w^2*D/2))+w/2 Pd= W*h2*w*h2/2 hd= ((w*h2^3/12)/(h2*h1*(h2/2)))+(h2/2) P= Pu-Pd h= (Pu*(h1-hu)-Pd*(h2-hd))/P F= P/(2*sind(a/4)) RT...
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// Scilab Code Ex12.5 : Page-605 (2011) clc; clear; mu_o = 4*%pi*1e-07;....// Magnetic permeability of the free space, henery/m mu_r = 600; mu = mu_o*mu_r; // Magnetic permeability of the medium, henery/m n = 500;...// Turns in a wire i = 0.3;....// Current flows through a ring,amp r = 12e-02/2;....// Mean r...
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//Example 2.6.8. // limiting value of current and % limiting error clc; clear; close; //given data : As=2.5;// in A fsd=10;//full scale reading in A A=1.5/100; del_A=A*fsd; At1=As+del_A; At2=As-del_A; disp(At1,"limiting value of current,At1(A) = ") disp(At2,"limiting value of current,At2(A) = ") e=(del_A/As)*100; disp(...
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clc //Intitalisation of variables clear T= 100 //C v1= 1674 //cc v2= 1 //cc lv= 539.9 //cal g^-1 sp= 13.595 //kg/m63 g= 980 //cm/sec^2 //CALCULATIONS r= (273.2+T)*(v1-v2)*sp*g/(lv*4.187*10^7) Tf= T+r //RESULTS printf ('Final temperature = %.2f C',Tf)
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//Example 5.9 clc clear x = 2:5; y = [27 40 55 68]; delx = x(2) - x(1); mu1 = delx * sum(y); mu2 = delx * sum(x.*y); n = length(y); l = x(1) - delx/2; u = x(n) + delx/2; M1 = [integrate("x",'x',l,u) u-l; integrate("x^2",'x',l,u) integrate("x",'x',l,u)]; M2 = [mu1; mu2]; M = M1\M2; a = M(1); b...
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//Numerical Differentiation clc; clear; close(); format('v',9); deff('[y]=f(x)','y=exp(-x)'); h = [1 .2 .1 .02 .01 .002 .001 .0002]; x0 = 1 - h; x1 = ones(1,8); x2 = 1+h; f0 = f(x0); f1 = f(x1); f2 = f(x2); dif = (f2-f0)./(2*h); max_trun_err = exp(h-1).*h.^2/6; act_err = abs(- exp(-1)-dif); answer = [h' f0' f2' dif' ma...
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// function[fun, grad]= simuladorf1(x) k=1:length(x); fun = (k'.*x)'*x; grad = (2*k)'.*x; // hes = diag(2*k) endfunction
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//Caption:determine_unit_step_response //example 12.10 //page 524 s=%s; syms t; CL=sym('1/((s+1)*(s^2+1))') disp(CL,"C(s)/R(s)="); //for unit step response R(s)=1/s; d=CL*(1/s); a=s*d; c=ilaplace(d,s,t); disp(c,"c(t)=");
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errcatch(-1,"stop");mode(2); //example 12.1 //page 443 ; funcprot(0); //initialisation of variable Q=0.25; Gamma=9810*0.8; pi=3.14; H=25; T=350;//torque N=1800;//rpm omega=N/60*2*pi; neta=Gamma*Q*H/T/omega; disp(neta*100,"efficiency (%)"); exit();
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ch10_ex_12.sce
//CHAPTER 10- THREE-PHASE INDUCTION MACHINES //Example 12 disp("CHAPTER 10"); disp("EXAMPLE 12"); //VARIABLE INITIALIZATION v=440; //in Volts I=1200; //in Amperes eff=0.85; //full load efficiency pow_fact=0.8; //full load pow...