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// Author :Rutuja Moharil //evalfr calculates frequency response at complex number f //the function works for both SISO and MIMO model . function[fr]=evalfr(sys,f) z=poly(0,'z'); //define z and s as polynomials s=poly(0,'s'); if (imag(f)==[]) then //check whether desired point is a...
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// Example 6.8: [0_7/45/-45/90]_r clc; mode(0); P = 1000;//Newton L = 2000;// mm delta = L/300; // E-glass/polyester trQ = 57160; //MPa Table 1.2 G12 = 3300; // Table 1.2 Gs = 7597; // G* Table 1.2 tk = 0.125; // one ply t = 10*tk // laminate thickness // carpet plot 80/10/10 x = 20; // %pm45 Exs = 0.53; ...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-9,Example 22,Page 349 //Title: Fugacity of liquid n-octane //================================================================================================================ clear clc //INPUT T=427.85;//temp...
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/////////Chapter 10 Properties Of Steam ////Example 10.7 Page No:188 ///Find Volume of wet steam ///#Input data clc; clear; P=15; //Absolute pressure in bar //From steam table (pressure basis at 15 bar) ts=198.3+273; //In degree celsius vg=0.1317; //In m^3/Kg vf=0.001154; ...
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//Example 2.12 // calculate the unknown resistance clc; clear; close; //given data : R1=20; // in kilo-ohm R2=30; // in kilo-ohm R3=80; // in kilo-ohm Rx=(R2*R3)/R1; disp(Rx,"the unknown resistance,Rx(killo-ohm) = ")
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 2 Example # 2.6 ") //diameter of fin in m d = 0.0025; //Perimeter in m P = %pi*d; //Area in m2 A = ((%pi*d)*d)/4; //Surface temperature in...
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function Est = RBF_one_time_evaluation(X, Y, A) [W, r0] = RBF_weights(X,Y); Est = RBF_evaluate(A, X, W, r0); endfunction
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clc clear //input data W=980//The weight of the object being dropped by parachute in N C=5//The maximum terminal velocity of dropping in m/s d=1.22//The density of the air in kg/m^3 Cd=1.3//The drag coefficient of the parachute //calculations A=W/(Cd*d*((C^2)/2))//The area of cross section in m^2 D=((A*4)/(3...
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//Chapter 10 //Example 10.2 //Page 256 //loadedfault clear;clc; //Given Pgm = 30e6; Vgm = 13.2e3; Xgm = 0.20; Xl = 0.10; Pm = 20e6;pfm = 0.8;Vt_m = 12.8e3; Pbase = Pgm; Vbase = Vgm; Vf = Vt_m / Vbase; Ibase = Pbase / (sqrt(3) * Vbase); I_L = (Pm / (pfm * sqrt(3) * Vt_m)) * (cos(36.9 * %pi/180) + %i * sin(36.9 * %pi / 1...
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//stability of non minimum phase loop transfer_function s=%s; sys=syslin('c',1/(s+2)*(s^2+4)) nyquist(sys) show_margins(sys,'nyquist') Z=0//no of zeroes of 1+G(s)H(s) in RHP(for sys to be stable) P=0//no of poles in RHP Pw=2//no of poles on jw axis including origin theta=(Z-P-0.5*Pw)*180 disp(theta,"for stabil...
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// Scilab Code Ex7.10:: Page-7.14 (2009) clc; clear; n1 = 1.480; // Refractive index of core material n2 = 1.47; // Refractive index of cladding material lambda = 850e-006; // Wavelength of light used, m NA = sqrt(n1^2-n2^2); // Numerical aperture of the step index fibre theta0 = asind(NA); // Maximum...
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clc //initialisation of variables Ww= 261 //lb/min a= 1 //in^2 h= 4 //ft y= 5 //ft W1= 10.65 //lb l= 1 //ft Q= 261 //lb/min w= 62.4 //lb/ft^3 g= 32.2 //ft/sec^2 //CALCULATIONS v= Q*144/(w*60) F= W1*l/y v= F*g*60/Q vth= sqrt(2*g*h) Cv= v/vth Q1= Ww/w Qth= vth*60/144 Cd= Q1/Qth Cc= Cd/Cv //RESULTS ...
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clc //Chapter4 //Ex_8 //Given e=1.6*10^-19 // in coulombs h=6.626*10^-34 //in Js me=9.1*10^-31 //in Kg d=10.5 // in g/cm Mat=107.9 //g/mol NA=6.023*10^23 // mol^-1 E_ctr=5 //in ev E_ctr=E_ctr*e // in Joules S_band=2*(16*%pi*sqrt(2)/3)*(me/h^2)^(3/2)*(E_ctr)^(3/2)// in states m^-3 //convesion of units S_ba...
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Name=Bounce CT Dodge Park PlayerCharacters=Bouncepark dodge man BotCharacters=Bounce Park Pigeons.rot IsChallenge=true Timelimit=60.0 PlayerProfile=Bouncepark dodge man AddedBots=Bounce Park Pigeons.rot;Bounce Park Pigeons.rot;Bounce Park Pigeons.rot;Bounce Park Pigeons.rot;Bounce Park Pigeons.rot;Bounce Park Pigeons.r...
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clc;funcprot(0);//EXAMPLE 3.25 // Initialisation of Variables D=0.25;.................//Engine bore in m L=0.3;.............//Engine stroke in m p1=1;................//Initial pressure in bar N=3;...............//No of cycles per second p3=60;................//Maximum pressure in bar t1=303;..............//Initi...
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// Example 12.9, page no-355 clear clc alfe=20*10^-6//per K t1=293//K sig=172///MPa E=100 //GPa delT=(sig*10^6)/(E*alfe*10^9) printf("\nTf-Ti=%.0f",delT) printf("\n\nthe maximum temperature at which the rod may be heated without\nexceeding a compresssive stress of %.0f MPa is %.0f K",sig,delT+t1)
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//Chapter 22 //Example 22_5 //Page 538 clear;clc; v1=220; v2=11000; v=220; i1=600; i2=5; lc=sqrt(3)*i2; pap=sqrt(3)*v*i1; i=pap/sqrt(3)/v2; ratio=i/lc; printf("Line current of delta connected CTs on %d V side = %.2f A \n\n", v1, lc); printf("Phase current of star connected CTs on %d V side = %.2f A \n\n", v2, lc);...
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function f=%pfr(m,f) // %pfr(m,f) retourne la concatenation d'une matrice de polynomes m et //et d'une matrice de fractions rationnelles f //Cette macro correspond a l'operation [m;f] //! [n1,d1]=f(2:3), [p,q]=size(m), f=tlist('r',[m;n1],[ones(p,q);d1],f(4)), //end
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2020-04-09T02:43:26.499817
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2018-02-03T05:31:52
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sce
ex3_10.sce
// Exa 3.10 format('v',7) clc; clear; close; // given data R_Z= 7;// in Ω I_Z1=12.2;// in mA I_Z2=60.2;// in mA deltaV_Z=(I_Z2-I_Z1)*R_Z;// in mV deltaV_Z= deltaV_Z*10^-3;// in V Vz= 12;// in V // The output voltage, Vout= Vz+deltaV_Z;// in V disp(Vout,"The output voltage in V is : ");
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/Scripts/Calculate_spectrum_occupancy.sce
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pflynn/Spectrum_analysis
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2016-09-05T17:10:44.896865
2011-06-27T15:01:20
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sce
Calculate_spectrum_occupancy.sce
// Calculates and saves the percentage of spectrum occupied over frequency and time! printf('Calculating percentage of spectrum occupied..\n') // This is the percentage of values in the matrix that exceed the noise floor // e.g. the percentage of spectrum occupied over time and frequency spectrum_occupancy = string(me...
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2020-05-20T13:36:05.842840
2013-07-31T06:53:59
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tst
bow.6_13.tst
6 9:0.3333333333333333 17:0.09090909090909091 18:1.0 21:0.1111111111111111 25:0.2 32:1.0 48:1.0 83:0.16666666666666666 185:1.0 221:0.5 242:1.0 368:0.5 593:1.0 6 6:0.5 17:0.18181818181818182 21:0.2222222222222222 23:0.3333333333333333 32:1.0 40:0.16666666666666666 44:0.02127659574468085 59:0.5 66:1.0 78:0.5 82:1.0 107:0...
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2020-04-09T02:43:26.499817
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37,975,407
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340
sce
Ex6_2.sce
//Chapter 06: Counting clc; clear; letters=26 //Total no of letters in the english alphabet post=100 //Total positive no.s not beyond 100 sol=letters*post //number of chairs to be labelled with an alphabet and an integer using product rule mprintf("Total number of chairs that can be labelled with an alphabet and an ...
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sce
Ex3_2.sce
// Example 3_2 clc;funcprot(0); // Given data T_1=250;// K T_2=800;// K beta_1=48.0*10^-6;// K^-1 beta_2=60.7*10^-6;// K^-1 V_1=1.00;// cm^3 // Solution beta_avg=(beta_2+beta_1)/2;// K^-1 beta=beta_avg;// K^-1 V_2=V_1*exp(beta*(T_2-T_1));// The final volume in cm^3 printf('\nThe volume of the block,V_2=%1...
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2020-04-09T02:43:26.499817
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Ex8_15.sce
//CHAPTER 8- DIRECT CURRENT MACHINES //Example 15 clc; disp("CHAPTER 8"); disp("EXAMPLE 15"); //VARIABLE INITIALIZATION v_t=230; //in Volts I_a1=3.33; //in Amperes N1=1000; //in rpm r_a=0.3; //armature resistance in Ohms r_f=160; ...
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sce
Ex7_1.sce
//Example 7.1 F=75;//Force (N) d=25;//Horizontal distance traversed (m) theta=35;//Angle (deg) W=F*d*cosd(theta);//Work (J) W1=W/4184;//Work (kcal) printf('Work done = %0.2e J or %0.3f kcal',W,W1) ratio=W1/2400;//Ratio of work done to the daily consumption printf('\nRatio of work done to the daily consumption =...
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hohiroki/Scilab_TBC
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sce
problem2_2.sce
errcatch(-1,"stop");mode(2);//problem 2.2 ; ; //given data : P=2;//No. of poles(Assumed for induction motor) f=50;//in Hz N=120*f/P;//in rpm disp(N,"Maximum speed in rpm : "); exit();
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Ex3_1.sce
//Initilization of variables F1=150 //lb F2=200 //lb F3=80 //lb F4=180 //lb theta1=((30*%pi)/180) //radians theta2=((150*%pi)/180) //radians theta3=((240*%pi)/180) //radians theta4=((315*%pi)/180) //radians //Calculations F1x=F1*cos(theta1) //lb F1y=F1*sin(theta1) //lb F2x=F2*cos(theta2) //lb F2y=F2*sin(...
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sce
Ch03Ex2.sce
// Scilab Code Ex3.2: Page-79 (2006) clc; clear; V0 = 11e-05; // Atomic volume of Cu, metre cube per kg K = 0.75e-011; // Compressibility of Cu, metre square per newton alpha = 49e-06; // Coefficient of thermal expansion, per K gama = 1.9; // The Grunesien parameter for Cu = 2.4 Cv = alpha*V0/(K*gama); ...
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gvela024/Elements-Of-Computing-Systems
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tst
AND2-1.tst
load AND2-1.hdl, output-file AND2-1.out, output-list in0 in1 out0; set in0 0, set in1 0, eval, output; set in0 0, set in1 1, eval, output; set in0 1, set in1 0, eval, output; set in0 1, set in1 1, eval, output;
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sce
Ex21_3.sce
clc; Vout=8; Vd=40; Vin=Vout+Vd; disp('V',Vin,"Vin=");//The answers vary due to round off error
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2020-04-09T02:43:26.499817
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sce
Example4_5.sce
clc //Given that R_e = 6.4e6 // radius of earth in m T = 8.64e4 // time period of one rotation of earth theta_pole = 90 // angle between pole and rotational axis theta_equator = 0 // angle between equator and rotational axis g_pole = 9.8 // gravitational acceleration at pole in m/s^2 // sample Problem 5 Page N...
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14_7w.sce
//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 14.7w //calculation of the longitudinal strain developed in each wire //given data m=3//mass(in kg) of each block A=.005*10^-4//area(in m^2) of the cross section Y=2*10^11///Young modulus(in N/m^2) of the wire g=10/...
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2020-12-09T08:52:58
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DMUX.tst
load DMUX.hdl, output-file DMUX.out, compare-to DMUX.cmp, output-list z%B3.1.3 s%B3.1.3 x%B3.1.3 y%B3.1.3; set z 0, set s 0, eval, output; set s 1, eval, output; set z 1, set s 0, eval, output; set s 1, eval, output;
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guilhermedpadua/trabalhos
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2021-09-23T02:02:37
2021-09-23T02:02:37
null
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sce
questao_11_matriz.sce
clear; clc; function [resultado] = verifica_linhas(matriz) resultado = %F; [linhas, colunas] = size(matriz); for i=1:linhas diferente_de_zero = 0; for j=1:colunas if(matriz(i, j) <> 0) diferente_de_zero = diferente_de_zero + 1; end end ...
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%imp2for.sci
function [stk,nwrk,txt,top]=%imp2for(nwrk) //fortran code for 1:n // // Voir s'il est possible d'ameliorer dans le cas ou ces vecteurs implicite // servent dans la designation d'une sous matrice //! // Copyright INRIA if forexp==1 then s1=stk(top-1);s2=stk(top) if op(3)=='2' then stk=list(s1(1)+','+s2(1),'2') ...
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sce
ch_5_eg_3.sce
clc disp("the solution of eg 5.3 -->Discretization in 1-D space"); //given the source term f(x)=4x^2-2x-4 //given eqn d2y/dx2-2y=f(x) y_1=0 y_4=-1 delta_x=1/3 //since given 3 parts and length=1 for i=0:3,j=0:delta_x:1; end //given to divide the line in 3 parts //at node 2 //y_3-2*y_2 function d=fx...
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tst
FM05.prev.tst
ID1000023609 !OK IDA0000001J1 !OK HRPLVARA0004 !OK HRRIBAO011A2 !OK HRVABAPA0005 !OK HRRH00O110A8 !OK EU0009658145 !OK ES0178430E18 !OK FR0000131104 !OK FR0000120537 !OK FR0000131906 !OK IT0000062072 !OK IE0000197834 !OK NL0000009538 !OK NL0000301760 !OK BE0003801181 !OK GB0007980591 !OK CH0012005267 !OK SE0000108656 !...
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15_2.sce
P=10;//assumed for calculation purpose disp("Pin=0.5*P"); printf('\n'); Pin=0.5*P; disp("Pe=0.013*Pin"); printf('\n'); Pe=0.013*Pin; disp("ηext=Pe/p"); n=Pe/P; printf('\n The external power efficiency is %fpercent',n*100);
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//Caption:Determine Resistors Rc and Rb //Ex14.1 clc; clear; close; Vcc=5//Collector voltage(in volts) Vi=5//Input voltage(in volts) Vf=1.2//Diode forward voltage(in volts) hfe=100 I=20//Diode minimum forward current(in mA) Vce=0.2//Collector emitter saturated voltage(in volts) Vbe=0.7//Base emitter voltage(...
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## Test path modification of debranch # # Here's the topology of debranch3.fi: # # :2 # | # :4 # | # :6 # | # +-----------+ # | | # :9 :15 # | | # :11 :17 # | | # :13 ...
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//skipped groundPlane_transform //skipped Manipulator1 //skipped UniversalManip //skipped CubeCompass ///////////////////////////////////////////// // object_Trim_Char_x_1_1__ ///////////////////////////////////////////// #if 0 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1 #endif DX3DMATERIAL_STA...
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clc; clear; mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-18.1 Page No.399\n'); //Torque Dp=(1.5+1.208)/2; F=5800; L=1/3; f=0.15; Tup=(F*Dp/4)*(L+%pi*f*Dp)/(%pi*Dp-f*L); mprintf('\n Torque up = %f in-lb.',Tup);
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//citer:invocation // paramétrer x = [ -1 ; 1 ] XMIN = -1 XMAX = 1 // à ajuster NOMBRE_DE_TANGENTES = 100 exec("./dessiner.sci", -1) //finCiter //citer:commandes clf() axes = gca() cosmetiqueAxes(axes) // optionnel dessinerParabole() //tTangentesAsynchrone() // version image fixe ...
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// Given data: clc T11=320+273.0 // temp at source 1 in kelvin Q1=10000.0 // heat transfer rate at source 1 in kJ/min T12=65+273.0 // temp at source 2 in kelvin Q2=120000.0 // heat transfer rate at source 2 in kJ/min T2=35+273.0 // temp of surrounding in kelvin n1=1-(T2/T11) // efficiency by source 1 n2=1-(T...
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//ques4 //Efficiency of Refrigeration cycle clc clear //from previous examples h1=191.8;//kJ/kg h5=3213.6;//kg/kg h6=2685.7;//kJ/kg h7=2144.1;//kJ/kg h3=604.7;//kJ/kg //1-Inlet state of pump //2-Exit state of pump P2=400;//Exit pressure in kPa P1=10; //Inlet pressure in kPa v=0.00101;//specific weight of...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.484986D+00 ...
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clear; clc; Rc=2500; il=1500; H=4; rg=2; f=50; D=il/f; Dpu=D/Rc; Kps=1/Dpu; Tps=(2*H)/(Dpu*f); Dl=Dpu*Rc; delP=-(Dl/Rc); mprintf("Constant step change in load is %.3f pu MW\n",delP); c=Dpu+1/rg; delf=-(delP/(Dpu+1/rg)); mprintf("change in frequency and increase in frequency are %.4f pu MW/Hz and %.4f Hz...
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clear; clc; R=20;C=0.03*(10^-6);L=0;G=0;r=18.2;l=78*(10^-3);d=2.1;f=3000/(2*%pi); Rc=R+(r/d); Lc=L+(l/d); Fc=1/(%pi*(sqrt(Lc*C*d))); printf("(i)Cutoff frequency = %f kHz\n",round(Fc*(10^-3)*100)/100); al=((Rc/2)*sqrt(C/Lc))+((G/2)*sqrt(Lc/C)); printf("(ii)Attenuation per km = %f neper/km\n",fix(al*10000)/10000)...
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// Como usar? // Na questão você recebe o intervalo e os nós/pontos // Ex: find_w(0,1,[0.1 0.9 1]), exemplo de questão embaixo do código function W = find_w(a, b, nodos) n_nodos = length(nodos) mat = zeros(n_nodos, n_nodos) mat_b = zeros(n_nodos) for i = 0:(n_nodos-1) mat_b(i+1) = (b^...
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// Implementation of example 7.1 // Basic and Applied Thermodynamics by P.K.Nag clc clear // T is temperature,dS is entropy change T1=35 // degree celsius T2=37 // degree celsius t1=T1+273; t2=T2+273; // change in entropy is given by dS=mCvlog(t2/t1) m=1 // kg Cv=4.187 dS=m*Cv*log(t2/t1); printf("chang...
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//Example No. 13_04 //Euler's Method //Pg No. 417 clear ; close ; clc ; deff('DY = dy(x)','DY = 3*x^2 + 1') x0 = 1 y(1) = 2 ; //h = 0.5 h = 0.5 mprintf('for h = %f\n',h) for i = 2 : 3 y(i) = y(i-1) + h*dy(x0+(i-2)*h) mprintf('y(%f) = %f\n',x0+(i-1)*h,y(i)) end //h = 0.25 h = 0.25 mprintf('\nfo...
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// Scilab Code Ex1.2 : Page-1.8 (2004) clc;clear; A = 4.1; // Ionization energy of K, eV B = 3.6; // Electron affinity of Cl, eV C = A - B; // Net energy to produce the ion pair, eV E = C; // Coulomb energy, eV e = 1.6e-19; // Electronic charge, C E_o = 8.85e-12; //Permittivity of free space, C/N...
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//Caption: probabilities channel matrix //Example 9.21 //Find probabilities channel matrix clc; clear; p=0.2; PX=[0.5 0.5]; PXY=[1-p p 0;0 p 1-p]; //P(Y)=[P(X)]*[P(Y|X)] PY=PX*PXY disp(PY,"[P(Y)]"); disp(PY(1),"P(y1)="); disp(PY(2),"P(y2)="); disp(PY(3),"P(y3)=");
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//Chapter 2 //Example 2.2 //Page 58 clear; clc; R1 = 10; Vs = 5; R_low = 4; R_high = 12; printf("a. The solution is given by VsR2/R1+R2.For R2=4k.ohm,we have\n") //Calculation of Vd x = (Vs*R_low)/(R1+R_low); printf("VD = %.2f V\n",x) printf("For R2=12k.ohm,we have\n") //Calculation of Vd y = (Vs...
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clc //Given that T =40 // Thickness of steel bar in cm t1 = 40 // Time in ms t2 = 80 // Time in ms printf("Example 6.3\n") X = T*t1/t2 // Calculation of depth of defect printf("Depth of defect is %d cm.\n\n\n",X)
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//Example 5_8 clc; clear; close; format('v',4); //given data : e=1.6*10^-19;//C/electron NA=2.5*10^20;//atoms/m^3 epsilon=16/(36*%pi*10^9);//F/m(For Ge) Vd=0.2;//V//Barrier height //Part(a) V0=10;//V(reverse bias) W=sqrt((V0+Vd)*2*epsilon/e/NA)*10^6;//micro m disp(W,"(a) Width of depletion layer(micro m)"...
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clc; f=1e6 //frequency in Hz L=1 //inductance in henry //f=(1/2*pi)*(sqrt(1/(L*C))) c=1/(4*%pi^2*f^2*L);//capacitance disp(+'F',c,'capacitance =')
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clear;lines(0); A=rand(5,2)*rand(2,5);[Bk,Ck]=fullrfk(A,3); norm(Bk*Ck-A^3,1)
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// Variable Declaration V_1 = complex(1.04,0) //Voltage at bus 1(p.u) S_D1 = complex(0.55,0.15) //Power at bus 1(p.u) S_D2 = complex(1.0,0.3) //Power at bus 2(p.u) Y_11 = complex(0.988,-9.734) //Admittance at bus 1(p.u) Y_22 = Y_11 //Admittance at bus 2(p.u) Y_12 = complex...
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//Example 20.2 //Forming Limit Criteria //Page No. 675 clc;clear;close; d=0.1; //in inches mj_d=0.18; //in inches mn_d=0.08; //in inches e1=(mj_d-d)/d; e2=(mn_d-d)/d; printf('\nMajor Strain = %g percent \nMinor Strain = %g percent',e1*100,e2*100);
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clc //initialisation of variables clear p1= 17.222 //mm p2= 17.535 //mm n= 1 //mole m= 1000 //gms M= 18.016 //gms //CALCULATIONS a= p1/p2 N1= (m/M)/(n+(m/M)) //RESULTS printf ('activity = %.4f ',a) printf ('\n activity coefficient = %.4f ',N1)
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errcatch(-1,"stop");mode(2);//Initilization of variables X=12 //mm me_M=1.3 //mm //Calculations d=(me_M)/(2*X) //Result printf('The damping ratio is %f',d) exit();
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//Given that g = 9.8 //in m/s^2 M = 3.3 //in kg m = 2.1 //in kg //Sample Problem 5-5 printf("**Sample Problem 5-5**\n") //from FBD1 //both will have common acceleration //mg - T = ma //T = Ma //adding -> mg = (M+m)a a = m * g /(M + m) T = m *g - m *a printf("The acceleration of both the blocks is %f m/...
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% Miscellaneous matrix tests. % Tests of eigenfunction/eigenvalue code. v := mat((1,1,-1,1,0),(1,2,-1,0,1),(-1,2,3,-1,0), (1,-2,1,2,-1),(2,1,-1,3,0))$ mateigen(v,et); eigv := third first ws$ % Now check if the equation for the eigenvectors is fulfilled. Note % that also the last component is z...
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clear close // Zeit Größenordung Regelung // Änderung der PWM bis 90% der Enddrehzahl erreicht sind Theta=9; //[kg m^2] M1=3.597; //[Nm] M2=4.533; M3=4.106; w1=194.24*2*%pi/60; //[rad/s] //=w2 w3=185.48*2*%pi/60; N1=194.24; //[rad/s] //=w2 N3=185.48; goal2=N1+0.2*(N3-N1); goal5=N1+0.5*(N3-N1); goal8=N1+0.8*(N3-N1...
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//9.20 clc; a='D70'; disp('The decimal no. is') x=hex2dec(a); disp('',x)
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clc Nc=2.8*10^19 disp("Nc = "+string(Nc)+" /cm^3") //initializing value of number of electron in the conduction band. Nv=1.04*10^19 disp("Nv = "+string(Nv)+" /cm^3") //initializing value of number of electron in the valence band.. no=1.5*10^10 disp("no = "+string(no)+" cm^-3") //initializing value of intrinsic ca...
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function bool = comparer(I,J) [n,m]=size(I); I=I*255; I=uint8(I); [n,m]=size(J); J=J*255; J=uint8(J); bool= %T; for i=1:n for j= 1:m if I(i,j)~=J(i,j) then bool = %F; end end end endfunction
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// Exa 4.20 format('v',6) clc; clear; close; // Given data V_BE= 0.8;// in V V_CE= 0.2;// in V Beta = 100; h_FE = Beta; V1 = 3;// in V V2 = -10;// in V R_B = 7*10^3;// in ohm R_E = 3*10^3;// in ohm R_C = 500;// in ohm //Applying KVL to input side, V1 - (I_B+I_C)*Rc - V_BEsat - (R1*I_B) = 0 or I_B*(R_B+R_...
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clc clf h=6.626e-34 //planks constant k=1.38e-23 //boltzmann constant c=3e8 //speed of light t=[1000,1200,1400] //temp (KELVIN) n=1400 r=linspace(0.1e-6,15e-6,n) r0=linspace(5e-6,15e-6,n) for i=1:n for j=1:3 u(j,i)=(8*%pi*h*c)/((r(i))^5*(exp(h*c/(r(i)*k*t(j)))-1)) m(j,i)=(8*%pi*k*t(j))/(r0(i))^4 v(j,i)=(...
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//Variable declaration d=7300 //density in (kg/m**3) N=6.02*10**26 //Avagadro Number A=118.7 //Atomic Weight E=1.9 //Effective mass e=1.6*10**-19 //Calculations n=(d*N)/A m=E*9.1*10**-31 x=4*%pi*10**-7*n*e**2 lamda_L=sqrt(m/x) //Result pri...
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//rand(1) gera numero aleatorio de 0 a 1 // numero inteiro: x=rand(1)*100 --> ceil(x) arredonda para numero inteiro mais proximo //padrao de x é radiano function val=funcao(x,y) val= sin(x).*cos(y); endfunction //funcao para plotar o grafico function grafico() x = [intNeg:0.3:intPos]'; y = [intNeg:0.3:in...
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clc// // // //Variable declaration k=1.38*10^-23; //boltzmann constant EF=0.18; //fermi shift(eV) E=1.2; //energy gap(eV) e=1.6*10^-19; r=5; //Calculation T=EF*e*4/(3*k*log(r)); //temperature(K) //Result printf("\n temperature is %0.0f K",T)
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function t = stlread(filename, fmt) [lhs,rhs] = argn(0); if rhs < 2 then error("Not enough input argument") end if type(filename) <> 10 | type(fmt) <> 10 then error("Arguments must be strings") end if isfile(filename) == %f then error("File not found"); end if...
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codeblock readtextfile(ScriptDir+"\TOOLS.sci"); sf=T_scene_create; sss=T_getscene; myviewport=T_getviewport; sss.ambientlightcolor=color(0.15,0.15,0.15); rootframe=sss.Universe; rootframe.add("sphere","radius":0.02); rootframe.add("sphere","radius":0.02,"position":point(1,0,0),"color":color(1,0,0)); rootframe.add("...
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// Test #8 : When output arguments are less than 5 exec('./zpkbpc2bpc.sci',-1); [z,p,k]=zpkbpc2bpc(4,2.2,1,[0.5,0.6],[-0.8,0.34]); disp(k); disp(p); disp(z); // //Scilab Output //k= 1.4967554 + 0.3078635i //p= -0.7456261 + 0.5534776i //z= -0.8709140 + 0.6869281i // //Matlab Output //z=-0.8709 + 0.6869i //...
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//Condición inicial Ciclohexano_Tolueno clear clc //Dirección de la carpeta donde se encuentran los experimentos path='/Users/Jarvis/Desktop/Datosnmr/2019-07-18-ciclohexano_tolueno/' //Carpeta inicial nb=170 //Carpeta final nf=849 //Numero de puntos nt=17 //Numero de mapeos nm=40 //Hora del primer experime...
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//EXAMPLE 2-67 PG NO-108-109 Z1=5; V=100+%i*200; I1=16; //CURRENT P1=I1*I1*Z1; disp('i) POWER (P1) is = '+string (P1) +' W '); P2=5000-P1; disp('ii) POWER (P2) is = '+string (P2) +' W '); Q1=-69.02; cos(-69.02)=0.35; Z2=Z1/0.358; disp('iii) IMPED...
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clc clear //DATA GIVEN T1=38+273; //initial temperature in K T3=1950+273; //maximum temperature K rp=15; //pressure ratio //for air, gamma=1.4 g=1.4; //for adiabatic compression 1-2 //p1(V1^gamma)=p2(V2^gamma) //(V1/V2)=r r=(rp)^(1/g); //T...
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//Ex:4.11 clc; clear; close; printf("A=pi*a^2=pi(y/25)^2=pi*y^2/625"); printf("\n Rr=31171.2*(A/y^2)^2"); printf("\n and finally, Rr=(31171.2*pi^2)/(625^2)"); Rr=(31171.2*%pi^2)/(625^2);// radiation resistance for single turn N2=82; Rr1=Rr*N2;// radiation resistance for turn loop printf("\n The radiation resi...
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Eaa=111;Ia=120;Ra=0.1; Rfw=80;Eac=85;If=0.5; v=100; Vt=Eaa-(Ia*Ra) Rf=v/1 Rfc=Rf-Rfw Rfcrit=Eac/If Rfc=Rfcrit-Rfw
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A = [1 2 3 4; 1 4 9 16;1 8 27 64;1 16 81 256] b = [2;10;44;190] //[L,U]=lu(A) //x = A\b
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// Example no 9.5 // To find the frame efficiency // Page no. 456 clc; clear all; // Given data Btrail=6; // Number of trailing bits per slot Bg=8.25; // Number of guard bits per slot Btrain=26; ...
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//Eg-14.1 //pg-580 clear clc close() //Note that the subscripts of the variables y have been increased by 1 since the subscript 0 is not possible in scilab! deff('out = f1(in1,in2,in3,in4)','out = in3') deff('out = f2(in1,in2,in3,in4)','out = in4') deff('out = f3(in1,in2,in3,in4)','out = -in2^2*in3 - ...
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clear; clc; //Example 3.2 b=100;//common emitter current gain BVcbo=120;//(V) break down voltage of the B-C junction n=3;//empirical constant BVceo=BVcbo/(b)^(1/n); printf('\nbreakdown voltage=%.2f V\n',BVceo)
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//Ex10_4 clc Av1 = 100//initial voltage gain beta = 0.001//feedback ratio disp("Av1 = "+string(Av1)) disp("beta = "+string(beta)) Af1 = Av1/(1+beta*Av1)//initial gain with negative feedback disp("Af1 = Av1/(1+beta*Av1) = "+string(Af1)) Av2 = 150//final voltage gain beta = 0.001//feedback ratio disp("Av2 = "...
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function [values, vectors] = eigenVV(A) values = spec(A)'; [vec, val] = spec(A); vectors = vec'; endfunction A = [1 -3 3; 3 -5 3; 6 -6 4]; [val, vec] = eigenVV(A); disp(val); disp(vec); /* 4. -2. -2. -0.4082483 -0.4082483 -0.8164966 -0.8103421 -0.3185154 0.4918268 0.1932607 -0.5903833...
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PL/SQL Developer Test script 3.0 46 declare l_lob blob; begin -- 1.on/0.off debug. oramail.debug := 0; -- init attachment table type. oramail.attachments := oraemailAttach_tb(); -- add attachment base oracle directory. oramail.addAttachment('DATA_PUMP_DIR','dp.log','text/plain'); oramail.addAttachment('...
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//Ex8_13 clc Iio=0.1*10^(-9) disp("Iio = "+string(Iio)+" ampere/degree _celsius") //Input offset current Vio=10*10^(-6) disp("Vio= "+string(Vio)+" volt/degree _celsius") //Input offset voltage Vs=10*10^(-3) disp("Vs= "+string(Vs)+" volts") //Input voltage R1=10*10^(3) disp("R1= "+string(R1)+ " ohm") // resi...
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clear clc // CHEMISTRY FOR ENVIRONMENTAL AND ENGINEERING SCIENCE FIFTH EDITION disp(' Chapter 2: Basic Concepts from General Chemistry') disp('example 2.1a') // To calculate the equivalent weight disp("What is the equivalent weight of a calcium ion") // Let the equivalent weight be denoted by EW, formula...
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//Finding of Discharge //Given d=0.3; l=400; f=0.00225; h=5; g=9.81; //To Find x=(h*2*g*d)/(f*l); v=sqrt(x); disp(v); A=(%pi/4)*d^2; q=A*v;disp(A); disp(" Discharge ="+string(q)+" m^3/sec");
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clear; clc; // Stoichiometry // Chapter 2 // Basic Chemical Calculations // Example 2.8 // Page 21 printf("Example 2.8, Page 21 \n \n"); // solution // CH.35O.35S.14 // mass % C = 12.0107 //[kg] H = 1.00794*.35 // [kg] O = 15.9994*.35// [kg] S = 32.065*.14 //[kg] m = C+H+O+S m1 = (C/m)*100 m2 ...
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#include "alu.inc" .code prolog #define RSH(N, I0, I1, V) ALU(N, , rsh, I0, I1, V) #define URSH(N, I0, I1, V) ALU(N, _u, rsh, I0, I1, V) RSH(0, 0xfe, 1, 0x7f) RSH(1, 0x1fffc, 2, 0x7fff) RSH(2, 0x40000000, 30, 1) RSH(3, 0x20000000, 29, 1) RSH(4, 0x10000000, 28, 1) RSH(5, 0x810000, ...
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//To calculate the temperature H = 2; //magnetic field, Wb/m^2 mew = 9.4*10^-24; k = 1.38*10^-23; //np = C*n0*exp(mew*H/(k*T)) //na = C*n0*exp(-mew*H/(k*T)) // np/na = exp(mew*H/(k*T))/exp(-mew*H/(k*T)) = exp(2*mew*H/(k*T)) //given np/na = 2. therefore exp(2*mew*H/(k*T)) = 2 T = 2*mew*H/(k*log(2)); //tem...
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i d like to start tonight by something completely different asking you to join me by stepping off the land and jumping into the open ocean for a moment 90 percent of the living space on the planet is in the open ocean and it s where life the title of our seminar tonight it s where life began and it s a lively and a lov...
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// Grob's Basic Electronics 11e // Chapter No. 17 // Example No. 17_4 clc; clear; // At what frequency will a 10 uF capacitor have Xc equal to 100 Ohms? // Given data Xc = 100; // Capacitive Reactance=100 Ohms C = 10*10^-6; // Cap=10 uF f = 1/(2*%pi*C*Xc); disp (f,'The Frequency in Hertz') disp ('appox...
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clc w = 10 // width of cut in cm h = 0.32 // depth of cut in cm n = 8 // number of teeth in cutter ft = 0.033 // feed rate per tooth N = 200 // cutter speed in rpm ita = 60/100 // efficiency f = n*ft*N // feed rate in cm/min. mrr = w*h*f // metal removal rate in cm^3/min. k = 8.2 // machinibility factor from t...
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// Example 6.7 page no-353 clear clc hie = 1100 hfe = 50 hre = 2.50*10^-4 hoe = 25*10^-6 Rl=0.1*hie/((hfe*hre)-(0.1*hoe*hie)) Rl=Rl/1000 printf("Rl= %.1f K Ohm",Rl)