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clear// //Variables T = 398.0 //Temperature (in kelvin) I0 = 30 * 10**-6 //Reverse saturation current (in Ampere) V = 0.2 //Voltage (in volts) //Calculation VT = T/11600 //Volt equivalent of temperature (in volts) I = I0 * (exp(V/VT)-1) ...
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clear; clc; //Example - 4.8 //Page number - 157 printf("Example - 4.8 and Page number - 157\n\n"); //Given P_1 = 40;//[bar] - Initial pressure T_1 = 500;//[C] - Initial temperature Vel_1 = 140;//[m/s] - Initial velocity T_2 = 100;//[C] - Final temperature Vel_2 = 80;//[m/s] - Final velocity W = 746.0;//[...
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// Variable Declaration V = 400.0 //Voltage of induction motor(V) f = 50.0 //Frequency(Hz) I = 40.0 //Line current(A) pf_1 = 0.78 //Lagging power factor of motor pf_2 = 0.95 //Raised lagging power factor // Calculation Section theta_1 = acos(pf_1) /...
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//Example 1_48 clc(); clear; //To calculate the refractive index of the liquid D8=1.42 //units in cm d8=1.25 //units in cm u=(D8)^2/(d8)^2 printf("The refractive index of the liquid is %.2f",u)
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clear; clc; disp('Example 8.17'); // aim : To determine // (a) the partial pressure of each gas in the vessel // (b) the volume of the vessel // (c) the total pressure in the gas when temperature is raised to228 C // given values MO2 = 8;// mass of O2, [kg] MN2 = 7;// mass of N2, [kg] MCO2 = 22;// mas...
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// Example 18.18, page no-471 clear clc A=1000*10^-6 //m^2 d=5*10^-3 epsr=4 Q=3*10^-10 eps=8.854*10^-12 c=(eps*epsr*A)/d v=Q/c E=v/d printf("The voltage across capacitor is %.2f V\nThe electric field strength is %.2f V/m",v,E)
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*Testcase KMC fc0 sysclear archmode esame r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000000 # LA R0,0 R0->function code 0 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=41200000 # LA R2,FO ...
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wA=162; wB=100; VPB=641;//vapour pressure of water// VPA=119;//vapour pressure of oraganic substance// MB=18;//Molecular weight of H2O// printf('Even though the boiling part of A might be higher,it distills out at a low temperature 95.3degrees.'); printf('\nIf A were to distill at 95.3degrees,the distillation wil...
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//a função recebe A, a matrix que representa a imagem e o parâmetro p //o parâmetro p indica o percentual de valores positivos //quanto maior esse percentual mais nítida é a imagem function compressed_image=compress_im(A,b) //para limpar o "canvas" vou limpar o ambiente da imagem anterior // os comandos abaixo...
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sPliTTER NhE {} FilTER ZKv { ::FBeC:ac:e:ca8a:FbE:251.81.254.226/8 in 246.9.254.87 Or 836704 << f ( 225.203.250.235, ) nOt c:f::B:FcEe:7 >> 192.241.180.5 oR cG ( , ) } FIltEr galCYl {NOT N } TuG BRANCh G gRoUPEr N {MODUlE a{ } mOdUlE vgag{ } MOdUlE nz{ KKY > Kny hT >= XR RDeltA 15MS } aGgrEGatE couNt(p.JQ...
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// Nemo Frame preliminary design script // // Finite Element Aproach for frame design //.Working Beam elements for 2D and 3D with Mesh refinement // // Diego Montero; Fernando Valentini; Gustavo Violato; // First release: Oct. 2015 clc; xdel(winsid()); clear; //Add the NEMO_ROOT enviroment variable as the project fo...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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clear; clc; printf("\t\t\tExample Number 4.7(Page no.-154-155)\n\n\n"); // long cylinder suddenly exposed to convection // Example 4.7 // solution d = 0.05;// [m] diameter of cylinder Ti = 200;// [degree celsius] initial temperature of aluminium cylinder Tinf = 70;// [degree celsius] temperature of environme...
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// Cette fonction permet de faire une translation sur la matrice mat de vecteur. function res=translation(mat, vector) res = mat; for i = 1:size(mat, 'r') for j = 1:size(mat, 'c') res(i, j) = mat(i, j) + vector(i); end end endfunction // Cette fonction retourne la posit...
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clear all; clc; funcprot(0); //given data T01 = 1200;//Stagnation temperature at which gas enters in K p01 = 4;//Stagnation pressure at which gas enters in bar c2 = 572;//exit velocity in m/s p2 = 2.36;//exit pressure in bar Cp = 1.160*1000;//in J/kgK gamma = 1.33 //calculations T2 = T01 - 0.5*(c2^2)/Cp;...
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n = 69; k = 8; x = [ [1, 1, 1, 50.7, 15.4, 8.2, 0, 1, 0, 15.9]; [1, 3, 1, 88.9, 31.2, 10.7, 0, 1, 0, 27.0]; [1, 1, 1, 45.2, 12.3, 10.7, 0, 1, 12, 13.5]; [1, 1, 1, 50.7, 15.4, 8.5, 0, 1, 12, 15.1]; [1, 2, 1, 71.1, 21.5, 10.7, 0, 1, 12, 21.1]; [1, 3, 1, 97.1, 35.6, 10.7, 0, 1, 12, 28.7]; [1, 3, 1, 93.2, 35.3, 10.7, 0, 0...
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clear; clc; close; Vcc = 12; //part a V_p = 12; Vceq = Vcc; Vce_max = Vceq + V_p; Vce_min = Vceq - V_p; n = 50*((Vce_max-Vce_min)/(Vce_max+Vce_min))^2; disp(n,'Efficiency(Percentage) = '); //part b V_p = 6; Vceq = Vcc; Vce_max = Vceq + V_p; Vce_min = Vceq - V_p; n = 50*((Vce_max-Vce_min)/(Vce_...
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//============================================================================ // chapter 5 example 1 clc; clear; //input data d = 2*10^-3; //diameter in m I = 5*10^-3; //current in A e = 1.6*10^-19; //charge of electron in coulombs a ...
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class A public integer d; public A(){} public integer test1(real y) { return(y+9);} end class B public A ma; public B(){} public A getA(integer a) { return(ma); } end class MaClasse public integer c; public MaClasse() {} public integer ajout(integer a, integer b) { VAR A mc; VAR B mc2; VAR integer d; mc :...
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clc //initialisation of variables Gama=1.33//ft/lb p=100//lb/in^2 p1=20//lb/in^2 v2=10.05//ft^3 v=3//ft/lb //CALCULATIONS W=144*(p*v-p1*v2)/0.33//ft lb //RESULTS printf('The work done=% f ft lb',W)
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// Exa 5.12 clc; clear; close; // Given data f_c = 10;// in kHz f_c = f_c * 10^3;// in Hz omega_c= 2*%pi*f_c;// in rad/sec C = 0.01;// in µF C= C*10^-6;// in F Ri= 10*10^3;// in Ω n=2; Q= 1/1.414; R= 1/(2*%pi*f_c*C);// in Ω Af= 3-1/Q; Rf= (Af-1)*Ri;// in Ω disp(C*10^6,"The value of C in µF is : ") disp...
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// Exa 7.4 clc; clear; // Given G = 3.8; // Gauge factor // Solution P = (G-1)/2; printf(' Poissons ratio of thin circular/wire of soft iron = %.1f \n',P);
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//clear// //Caption:Calculation of photocurrent //Example6.3 //page226 clear; clc; close; R = 0.65; //Responsivity of photodiode Pin = 10*(10^-6); //Optical power level in watts Ip = R*Pin; disp(Ip*10^6,'The amount of photocurrent generated in uA =') //Result //The amount of photocurrent generated in uA = ...
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s=%s; sys1=(s/(s+1)); sys2=(5*s+1)/(s*s+5) k=stack(3,sys1,sys2)
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//Example 14.5 A=0.950;//Area (m^2) d=2.5*10^-2;//Thickness (m) T1=0;//Temperature inside the box (C) T2=35;//Temperature outside the box (C) t=24*60*60;//Time, convert 1 day to seconds (s) k=0.010;//Thermal conductivity of styrofoam (J/s.m.C) rate=[k*A*(T2-T1)]/d;//Rate of conductive heat transfer (J/s) Q=rate...
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//Example 14.4, Page 516 clc uo=4*%pi*10^-7//T-m/amp u=2.2*9.3*10^-24//in Tesla x=3*10^-10//in m E=(uo*u*u)/(2*%pi*x**3) printf("\n The Energy required is %e Joule",E) k=1.38*10^-23//in J/k T=E/k printf("\n The temperature is %f K",T)
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Fitting results: x_S_P ( 1 ) = 0.365224 x_S_I ( 1 ) = 0.130228 x_S_L ( 1 ) = 0.053782 x_Sp = 436.352041 the square sum term is 27.404203
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clc clear //INPUT DATA n=1.3;//index of compression p1=1;//pressure in bar va=2;//volume of air in m^3 N=2;//No.of stages p3=50;//delivery pressure in bar R=0.287;//gas constant t1=303;//temperature in K t31=314;//temperature in K vcs=0.05;//ratio of clearance volume to stroke volume //CALCULATIONS ip1=(...
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//Example 8.2 //Simpsons 1/3rd Rule and Richardson Extrapolation //Page no 264 clc;clear;close; a=1;b=2; // simpsons rule when h=0.5 h=0.5 n=(b-a)/h+1; for i=1:n if i==1 then x(1,i)=a else x(1,i)=x(i-1)+h end y(1,i)=1/x(i) end disp(y,"f(x) = ",x,"x = ") S=0; for i=1:n ...
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////////////////////////////////////////////////////////////////////////////////////////////////////// //// Неделя 4. //// Оценивание константы обобщенным методом наименьших квадратов //// при наличии двух измерителей с различной дисперсией. //// Количество измерений для датчиков одинаково. ////////////////////////////...
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load FPM.hdl, output-file FPM.out, compare-to FPM.cmp, output-list x%B1.16.1 y%B1.16.1 z%B1.16.1 isoverflow%B5.1.4; //test case for same sign //first the sign is same and positive set x %B0100000000100000, //2.5 set y %B0100000010100000, //5 eval, output; //second the sign is same and negative set x %B101111111100...
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clc; c=3*10^8; //velocity in m/sec l=5*10^-7; //wavelength in m f=c/l; //calculating frequency disp(f,"Frequency in Hz = "); //displaying reuslt h=6.63*10^-34; //planck's constant in J.sec E=h*f; //calculating energy disp(E,"Energy in Joule = "); //displaying reuslt disp(E/(1.6*1...
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clear // //given and derived a=100/0.32 //area required to dissipate 100W power d=5 //length of cyclinder L,length of wire if l,diameter of the wire is d L=a/(3.14*d) r=100/1**2 //spacing is d cm //distance along the axis of the cylinder is 2d cm //no of turns is 10/d //length of one turn of the wire is 3.14*5 cm //len...
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function dydt = f(t,y) dydt = [y(2);-g/L*sin(y(1))] endfunction function y=euler(theta0,t) n=length(t); h=t(2)-t(1); y(1,1)=theta0; y(2,1)=0; for i=1:n-1 y(1,i+1)=y(1,i)+h*y(2,i); y(2,i+1)=y(2,i)+h*(-g/L*sin(y(1,i))); end endfunction function y = solution_approx(theta0,t) ...
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//Chapter 2, Problem 2 clc D=300e-3 //distance in meter between the two wire d=4e-3 //diameter in meter of a conductor e=1 //relative dielectric //calculating the characteristic impedance of the type of parallel transmission line z0=(276/sqrt(e)...
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clc //Intitalisation of variables clear dH= 12300 //cal T= 25 //C dS= -60.1 //cal deg^-1 mole^-1 //CALCULATIONS dF= dH-dS*(273+T) //RESULTS printf ('Standard free energy of formation = %.f cal mole^-1 ',dF-10)
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//Chapter-2,Example 2_26,Page 2-48 clc() //Given Data: m=2 //order lam=6*10^-7 //Wavelength of light dlam=6*10^-10 //difference in wavelength W=2*10^-2 //Width of surface //Calculations: //We know that R.P.=lam/dlam=m*N N=lam/dlam/m //Number of lines on grating G...
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// Exa 1.8 clc; clear all; // Given data X= 100; // Range of voltmeter(V) x= 70; // Measured value on voltmeter(V) Y= 150; // Range of milliammeter y= 80; // Measurex d value on milliammeter Accu= 0.015; // Accuracy of instruments // Solution X_mag= Accu*X; //Magnitude of limiting error for voltmet...
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boardsize 10 play w s10 play b r11 play w q12 play b p13 play w o14 play b n15 play w m16 play b l17 play w k18 play b j19 play w i18 play b h17 play w g16 play b f15 play w e14 play b d13 play w c12 play b b11 play w a10 play b a9 play w a8 play b a7 play w a6 play b a5 play w a4 play b a3 play w a2 play b a1 play w b...
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//Exa:1.30 clc; clear; close; f=50;//in hertz P1=6;//No. of poles P2=4;//No.of poles N_sc=120*f/(P1+P2);//Synchronous Speed (in rpm) s=0.02;//slip N=N_sc*(1-s);//Actual Speed (in rpm) N_s=120*f/P1;//Synchronous Speed of 6-pole motor s1=(N_s-N)/N_s; f1=s1*f; disp(f1,'Frequency of rotor current of 6-pole mot...
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; expm1.tst ; ; Copyright (c) 2009-2023, Arm Limited. ; SPDX-License-Identifier: MIT OR Apache-2.0 WITH LLVM-exception func=expm1 op1=7ff80000.00000001 result=7ff80000.00000001 errno=0 func=expm1 op1=fff80000.00000001 result=7ff80000.00000001 errno=0 func=expm1 op1=7ff00000.00000001 result=7ff80000.00000001 errno=0 st...
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clc //initialization of variables Mn=3 Mni=0.2 w=10 //lbm/sec g=1.4 P=200 //lb/in^2 T=400+460 //R //calculations Astar=w*sqrt(53.3*T) *((g+1)/2)^3 /(P*sqrt(g*32.2)) A1ratio=(2/(g+1) + (g-1)*Mni^2 /(g+1))^3 /Mni A1=A1ratio*Astar A2ratio=(2/(g+1) + (g-1)*Mn^2 /(g+1))^3 /Mn A2=A2ratio*Astar Pexit=P/(1+ Mni*M...
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clear; clc; disp("--------------Example 3.41---------------") SNR=63; B=10^6; // bandwidth = 1 MHz b=4*10^6; // chosen bit rate =4 Mbps C= B*log2(1+SNR); // Shannon's capacity formula c=C*10^-6; //multiply with conversion factor L=2^(b/(2*B)); // bit rate = 2*bandwidth*log2(L) ; L= number of signal levels //d...
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V2=1 V1=1 V2=0 I1=0.05*V1 I2=-0.05*V1 Y11=I1/V1 Y21=I2/V1 I2=0.05*V2 I1=-0.05*V2 Y12=-0.05 Y22=0.05 A=[Y11,Y12;Y21,Y22] printf("\nA=") disp(A)
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function [Pn,Rt,T]=faurre(n,H,F,G,r0) //[Pn,Rt,T]=faurre(n,H,F,G,r0) //macro which computes iteratively the minimal solution of the algebraic //Riccati equation and gives the matrices Rt and Tt of the filter model. // n : number of iterations. // H,F,G : estimated triple from the covariance sequence of y. // ...
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r1=0.4; r2=1; rl=2; v1=12; v2=15; disp("Part a"); vx=(v1/r1+v2/r2)/(1/r1+1/r2+1/rl); disp("load voltage (in V) is"); disp(vx); il=vx/rl; disp("the load current (in A) is"); disp(il); disp("Part b"); ib=(vx-v1)/r1; disp("the battery current (in A) is"); disp(ib);
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disp("E=(ħ*k*ħ*k)/(2*me)"); m0=9.1*10^-31; E=0.8*10^-19; me=0.067*m0; b=(sqrt(2*me*E))*(10^25); printf('the value of ħ*k =%f *(10^-26)',b);
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clear // // // //Variable declaration h=6.626*10^-34; //planck's constant(J-sec) e=1.60*10^-19; //charge of electron(c) L=10^-10; //width(m) m=9.1*10^-31; //mass of electron(kg) n1=1; n2=2; //Calculations E=h^2/(8*m*e*L^2); //energy(eV) E1=n1^2*h^2/(8*m*e*L^2); //1st...
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C = 10*10^-6 ; //capacitance(in farads) R = 0.2*10^6; //resistance (in ohms) Vi = 40; //initial voltage of the capacitor (in volts) Wc = (1/2)*C*Vi^2; //energy stored in the capacitor //current flowing in circuit as a function of time i(t) = 2*10^-4*exp(-t/2) //power dissipated in the resistor = R*i^2 Wr = integrate('R...
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//Example3.5 // To determine emitter resistance of the difference amplifier clc; clear; close; Vcc = 10 ; // volt Vee = -10 ; //volt Iq = 0.8 ; //mA Ie = 0.8 ; //mA CMRRdb = 90 ; //dB Vt = 0.026 ; // Transistor parameter beta = 100 ; // CMRR = abs(Ad/Acm); // the CMRR of the difference amplifie...
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clc clear //Input data Ns=210//Specific speed P=30//Power in MW N=180//Speed in rpm Q=0.6//Discharge in m^3/s h=4.5//Head in m e=88//Efficiency in percent d=1000//Density in kg/m^3 //Calculations Pm=(d*Q*9.81*h*(e/100)*10^-3)//Power in kW Nm=(Ns*h^(5/4))/sqrt(Pm)//Speed in rpm Hp=((N*sqrt(P*1000))/Ns)^...
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// PG (620) T = [2 1 0 0 0 0;1 2 1 0 0 0;0 1 2 1 0 0;0 0 1 2 1 0;0 0 0 1 2 1;0 0 0 0 1 2] lam = spec(T)' lam1 = lam(1,1) B = [2-lam1 1 0 0 0 0;1 2-lam1 1 0 0 0;0 1 2-lam1 1 0 0;0 0 1 2-lam1 1 0;0 0 0 1 2-lam1 1;0 0 0 0 1 2] f0 = abs(det(B)) f1 = 2-lam1
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//Example No 137. //Page No 4.9. //The de-Broglie wavelength of alpha particle. clc;clear; V = 1000;//Potential difference applied -[V]. h = (6.626*10^(-34));//Planck's constant -[J-s]. m = (1.67*10^(-27));//Mass of a proton -[kg]. e = (1.6*10^(-19));//charge of electron -[J]. w = h/sqrt(2*m*e*V);//de-Brogl...
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// Scilab Code Ex2.63:: Page-2.49(2009) clc; clear; R1 = 4; // Radius of curvature of the convex surface, m R2 = 5; // Radius of curvature of the concave surface, m lambda = 6600e-010; // Wavelength of light used, cm n = 15; // Order of Newton ring // As D_n^2*(1/R1-1/R2) = 4*n*lambda, solving for D_n D...
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#include "alu.inc" .code prolog #define RSB(N, I0, I1, V) ALU(N, , rsb, I0, I1, V) RSB(0, 1, 0x7fffffff, 0x7ffffffe) RSB(2, 1, 0x80000000, 0x7fffffff) RSB(3, 0x7fffffff, 0x80000000, 1) RSB(4, 0xffffffff, 0xffffffff, 0) RSB(5, 0x7fffffff, 0xffffffff, 0x80000000) RSB(6, 0, 0x7fffffff, 0x7fffffff) #if _...
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clc; j=sqrt(-1) x_mag1=[]; x_phase1=[]; w1=[w1 w]; x=1/(1-0.5*exp(-j*w)) for w=-2*%pi:0.01:2*%pi x_mag=abs(x); x_phase=phasemag(x) x_mag1=[x_mag1 x_mag] x_phase1=[x_phase1 x_phase]; w1=[w1 w] end plot(w1,x_mag1) figure; plot(w1,x_phase1)
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//Calcul la solution au sens des moindres carrés //x : un vecteur de points (données) //y : un vecteur de points (valeur) ax^n+bx^(n-1)+..p = y //n : l'ordre du modèle function X = moindresCarres(x,val,ordre) A = [x,ones(size(x,1),1)]; xT = x; for i = (2:1:ordre) xT = xT.*x; A = [xT A]; ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 1 Example # 1.3 ") //Area of room in m2 is given as A = 20*20; //Air temperature in C Tair = -3; //Roof temperature in C Troof = 27; //Hea...
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function [res] = kiks_checkpoint() // Ouput variables initialisation (not found in input variables) res=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.ts...
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// header-start //////////////////////////////////////////////////////////////////////////////// // \project yuv-viewer // // \file filter_design_7tap.sce // // \brief scilab script of a 7 TAP FIR filter for decimation by 2 // // \legal Copyright (c) 2020 // // \author Bernard // ////////////////////...
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pathname=get_absolute_file_path('9_3.sce') filename=pathname+filesep()+'9_3_data.sci' exec(filename) //Power output per cylinder Pc=P/k //Fuel consumption per cylinder Fc=Pc*bsfc //Fuel injected per cycle mf=(Fc/60)/(N/2) //Time for injection t=(Tc*60)/(360*N) //Pressure at beginning dpb=P1-Pc1 //Pressure ...
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PPSO3=1;//partial pressure of SO3 in atm// PPSO2=0.2;//partial pressure of SO2 in atm// PPO2=0.05;//partial pressure of O2 in atm// Kp=3.5; R=0.0821;//universal gas constant// T=1000;//temperture in kelvin// n1=3; n2=2; dn=n2-n1;//change in no. of moles// Kc=Kp/((R*T)^dn); printf('Kc for the reaction=Kc=%flit...
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kūlõ V;FIN;PL;1;NEG;PRS;ACT;LGSPEC1 kōdkimdõz ADJ;IN+ABL;PL līdõ V;FIN;IND;SG;2;NEG;PST;ACT tūlda V;FIN;IND;PL;2;POS;PST;ACT nēļatuoistõnz ADJ;IN+ABL;SG;LGSPEC6 kūlõ V;FIN;SG;3;POS;PRS;ACT;LGSPEC1 jellõ V;FIN;IMP;PL;2;POS;PRS;ACT tas N;DAT;PL seiskimdõz ADJ;DAT;SG bäzmõr N;IN+ABL;PL nēļasadāz ADJ;DAT;PL pānda V;PRF;FIN...
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//Transport Processes and Seperation Process Principles //Chapter 2 //Example 2.8-2 //Principles of Momentum Transfer and Overall Balances //given data V=0.03154;//vol flow rate in si units D1=0.0635;// upstream ID A1=(%pi/4)*D1*D1;//area of cross section D2=0.0286;// downstream ID A2=(%pi/4)*D2*D2;//area of cross sect...
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// 22-5 clc; clear; n1=4; n2=3; n=(n1+n2-1); R2=80; R1=50; //According to Uniform Pressure Theory //W=p*pi*((R2^2)-(R1^2)) T=n*2*u*W*((R2^3)-(R1^3))/(((R2^2)-(R1^2))*3) P=15*10^3; N=1400; u=0.25; w=2*%pi*N/60; T=P/w; W=T*3*((R2^2)-(R1^2))/(n*2*u*((R2^3)-(R1^3)))*10^3; p=W/(%pi*((R2^2)-(R1^2))); // ...
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function x=%sp_ceil(a) // Copyright INRIA [ij,v,mn]=spget(a) x=sparse(ij,ceil(v),mn)
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clc // Given that d = 0.05 // diameter of fiber in mm NA = 0.22 // numerical aperture lambda = 8.5e-4 // wavelength of light in mm // Sample Problem 7 on page no. 5.18 printf("\n # PROBLEM 7 # \n") Vn = (%pi * d * NA) / lambda Mm = 0.5 * (Vn)^2 printf("\n Standard formula used \n Vn = (pi * d * NA) / lambda. \n Mm = 0...
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clc //Variable declaration d=1.18 theta=90*%pi/180 lamda=1.540 //Calculations n=(2*d*sin(theta))/lamda //Result printf('n =%0.3f \n',(n))
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//programa: trilha.sce //Solução Numérica da Equação de Laplace //Potencial na Trilha Condutiva clear; N = 9; //Número de Quadrados Vmax = 5; //Tensão máxima aplicada W = 1; //Tamanho do Quadrado //Construindo a Matriz: A = zeros(N,N); i = 1:N; //Diagonal Principal for l = 1:N A(l,l) = 1; end //Direita for l =...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>2D cylinder flow, mixed elements, P=5</description> <executable>IncNavierStokesSolver</executable> <parameters>Cyl_AdaptiveSFD.xml.gz Cyl_AdaptiveSFD.xml</parameters> <files> <file description="Session File">Cyl_AdaptiveSFD.xml.gz</file>...
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a=rand(2000000,1); b=zeros(2000000,1); for i=1:2000000 if a(i)>0.5 b(i) = %pi+acos(4*a(i)-3); else b(i) = acos(1-4*a(i)); end end scf(0); freq = histplot(20,b); rfreq = freq/2000000; bar(.025+(0:19)/20,20*rfreq); xlabel("Class") ylabel("Distribution") scf(1); freq = histplot(20,a); rfreq = freq/2000000; bar(.025+(0:1...
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TDR=2000//transmission data rate Size=20*8 dtt=Size/TDR//data transfer time printf('data transfer time= %.f ms',dtt*10^3)
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clc // Given that delta_x = 1e-10 // width of box in m e = 1.6e-19 // charge on an electron in C m = 9.1e-31 // mass of electron in kg c = 3e8 // speed of light in m/sec h = 6.62e-34 // Planck constant in J-sec // Sample Problem 14 on page no. 15.29 printf("\n # PROBLEM 14 # \n") printf("Standard formula used \n") pri...
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switch_desturbance = 1; gamm = 1500; sigm = 0.01; path = get_absolute_file_path("plot_graph.sce"); //importXcosDiagram(path + "adapt_desturbance_robust.zcos"); importXcosDiagram(path + "adapt_desturbance_robust_and_adapt.zcos"); xcos_simulate(scs_m, 4); subplot(2,1,1); a = gca(); if sigm == 0 then if switch_dest...
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{ "EGTE 150800Z 1509/1518 18005KT 9999 FEW040 TEMPO 1511/1512 8000 TEMPO 1512/1513 4000 TEMPO 1513/1514 1000 TEMPO 1514/1515 0500 TEMPO 1515/1516 0200": { "TAF base conditions cover METAR - visibility 9999": { "metar": "EGTE 150850Z 18005KT 9999 FEW040", "test time": "20200615T0900Z"...
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clc // Example 5.2.py // A supersonic wind tunnel is designed to produce Mach 2.5 flow in the test section // with standard sea level conditions. Calculate the exit area ratio and reservoir // conditions necessary to achieve these design conditions. // Variable declaration Me = 2.5 // exit mach number pe = 1....
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//page no 472 //prob no 10.20 //Gaussian PDF: Q(x)= %e^((-x^2)/2)/ (x*sqrt(2*%pi)) clc; x=input("input for the function Q = "); Q(x)= (%e^-((x^2)/2))/ (x*sqrt(2*%pi)); P=1-(2*Q(x)); disp(P);// P gives the width or spread of Gaussian PDF
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ERROR: type should be string, got "https://\nhttps://blah.com\nhttps://void.org\nthis is inline https:// yes yes no no\n\n"
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//2.15 clc; Vm=230*2^0.5; Vo=2*Vm/%pi; Idc=Vo/10; printf("dc output voltage = %.2f V", Vo ) Pdc=Idc*Vo; printf("\ndc power = %.2f W", Pdc )
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clc //ex5.3 //V_1 and V_2 are phasors of given voltages theta_1=-%pi/4; //for V_1 theta_2=-%pi/6; //for V_2 (in cos form) V_1=complex(20*cos(theta_1),20*sin(theta_1)); V_2=complex(10*cos(theta_2),10*sin(theta_2)); V_s=V_1+V_2; V=sqrt((real(V_s)^2)+(imag(V_s)^2)); //peak voltage of resultant summa...
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function memory_usage() // Get Multiplication of dataframe and other, element-wise (binary operator mul). // // Syntax // df.memory_usage(index = False) // // Parameters // index : bool, default True // deep: bool, default False // For additional information on parameters, see https...
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clc pathname=get_absolute_file_path('4_8_2.sce') filename=pathname+filesep()+'482.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") nO2Theoretical=basisButane*6.5 nAirTheoretical=nO2Theoretical*4.76 percent=(basisAir-nAirThe...
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A = [0.16 0.10; 0.17 0.11; 2.02 1.29] b = [0.26; 0.28; 3.31] b2 = [0.27; 0.25; 3.33] s = A\b s2 = A\b2 disp("Tenemos la matriz A") disp(A) disp("Con b del sistema Ax = b:") disp(b) disp("La solucion del sistema es:") disp(s) disp("Ahora si cambiamos b por:") disp(b2) disp("La solucion del sistema es:") disp(s2) dis...
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T1: T2 T4 T7 P1 T2: T3 T5 P2 T3: P3 T4: T5 T6 P4 T5: P5 T6: T5 P6 T7: T6 P7
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//Example 10.5// //(a) = For 0.5 wt % C steel indicates that complete bainite formation will have ocuurred 5degree C above Ms,by a=180;//s //second b=1;//m //minute c=60;//s//seconds d=a*(b/c) mprintf("d= %i min",d) //(b)= For 0.77 wt % C steel gives a time of a1=1.9*10^4;//s //seconds b1=3600;//s/h //seconds ...
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//Engineering and Chemical Thermodynamics //Example 7.10 //Page no :343 clear ; clc ; //Given gama_a_inf = 0.88 ; gama_b_inf = 0.86 ; R = 8.314 ; T = 39.33 + 273 ; A_1 = R * T * log(gama_a_inf) ; A_2 = R * T * log(gama_b_inf) ; A = (A_1 + A_2) / 2 ; disp(" Example: 7.10 Page no : 343") ; printf("\n ...
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clc clear //Input data L=500;//The length of a steel rod in cm t=40;//The increase in temperature in degree centigrade y=2*10^12;//The youngs modulus of elasticity of steel in dynes/cm^2 e=12*10^-6;//The coefficient of linear expansion of steel in per degree centigrade //Calculations S=y*e*t;//The stress i...
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onebound.sce
function [ var ] = onebound(ibound,nx,ny,nz,var ) //[ var ] = onebound(ibound,nx,ny,nz,var ) // Simple boundary conditions on one variable //============================================================================== // // [ROUTINE NAME] Onebound // [AUTHOR] Joan Masso, NCSA & UIB // // [PURPOSE] Simple boundary...
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clc //soltuion //given //ref fig 15.24 p=0.2//N/mm^2 d=600//mm ftc=17.5//N/mm^2 fts=52.5//N/mm^2 fcs=52.5//N/mm^2 ts=42//n/mm^2 //let t be thickness of vessel //t=(p*d)/(2*ftc)//mm printf("the thickness of vessel si,%f mm\n",(p*d)/(2*ftc)) printf("the thickness can not be less then 6mm,therfore we take 6 as thickness\...
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//Example 8//frequency clc; clear; close; r=3;//m w=10;//s^-1 vs=r*w;//m/s A=6;//m fd=5/%pi;//s^-1 vmax=A*2*%pi*fd;//m/s v=330;//m/s n=340;//Hz nmax=((v+vmax)/(v-vs))*n;//Hz nmin=((v-vmax)/(v+vs))*n;//Hz disp(nmax,"maximum frequency is,(Hz)=") disp(nmin,"minimum frequency is ,(Hz)=")
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clear; clc; f=150;S=4.48;Ymin=6*(10^-2); lo=300/(f); //lo=wavelength b=(2*%pi)/lo; phi=round(((2*b*Ymin)-%pi)*100)/100; phi1=-phi; ampK=round(((S-1)/(S+1))*10)/10; Ls=(lo/(4*%pi))*(phi1+%pi-round(acos(ampK))); printf("Point of attachment = %f cm\n",round(Ls*(10^4))/100); Lt=(lo/(2*%pi))*(atan(sqrt(1+(ampK*amp...
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clear; clc; close; Vcc = 20; Rb = 1*10^(3); Rc = 20; Beta = 25; Ib_p = 10*10^(-3); Ibq = (Vcc-0.7)/Rb; Ib = Ibq; Icq = Beta*Ibq; Ic= Icq; Vceq = Vcc-Ic*Rc; Ic_p = Beta*Ib_p; Po_ac = (Ic_p^2)*Rc/2; Pi_dc = Vcc*Icq; n = (Po_ac/Pi_dc)*100; disp(Po_ac,'Output power = '); disp(Pi_dc,'Input power = '...
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//Example 2.1 //Computation of power absorbed by each part //From figure 2.13a V=2;I=3; //We have Power(P)=V*I P=V*I printf("a) Power =%dW\n",P) if P>0 then printf("Power is absorbed by the element\n") else printf("Power is supplied by the element\n"); end clear P; //From figure 2.13b V=-2;I=-3...
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//Caption: step size,noise power, SNR //Example 4.32 //page no 203 //Find step size,noise power, SNR //assume bandwidth of the singal is 4kHz clear; clc; fs=32000; A=2; fm=4000; BW=4000; del=(2*%pi*fm*A)/fs; disp("Volt",del,"i)step size"); Nq=del^2/3 disp("W",Nq,"ii)noise power"); SNR=(3*fs^3)/(8*%pi^2*f...
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img_input = readpbm("C:\Users\DimitriXPS\Documents\GitHub\Exolife\Exolife\Images\Mission 7\HD215497.pbm"); // dossier destination images séparées imgDestination = ("C:\Users\DimitriXPS\Documents\GitHub\Exolife\Exolife\Stockage_Images_Missions\") // filtre jaune + normalisation imgEau = normalisati...
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//Chapter 19,Example 4,page 670 //Determine the vertical displacement of the drop clear clc d = 0.03*10^-3 // m p = 2000 // kg/m^3 q = 100*10^-15 // C V0 = 3500 // V d2 = 2*10^-3 // m L1 = 15*10^-3 // m L2 = 12*10^-3 // m Vz = 25 // m/s m = 4/3*%pi*(1/2*d)^3*p t0 = L1/Vz Vx0 = q*V0*t0/(m*d2) x0 = 1/2*Vx0*t0 t1 = (L1+L...