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clear; close; clc; cox=1.6*10^(-6);//from_previous_example v=0.4; vto=0.08;//from previus example qe=1.602*10^(-19); n1=(cox*(v-vto))/qe; disp(n1,'ion implant doses(in ions/cm^2)');
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//Chapter 6 Solutions of Electrolytes clc; clear; //Initialisation of Variables M= 0.001 //molar M1= 0.002 //molar M2= 0.004 //molar n= 1 //moles n1= 2 //moles v= 0.509 //CALCULATIONS Is= 0.5*(M*n**2+M1*n**2+M1*n1**2+M2*n**2) r= 10**(-v*n**2*sqrt(Is))*M r1= 10**(-v*n1**2*sqrt(Is))*M1 //RESULTS mprintf("Ionic streng...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART III : SWITCHGEAR AND PROTECTION // CHAPTER 8: PROTECTION OF ALTERNATORS AND AC MOTORS // EXAMPLE : 8.7 : // Page number 626-627 clear ; clc ; close ; // Clear the wor...
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function []=gauss_el() a=evstr(x_matrix('enter a 3x3 matrix ',rand(3,3))) b=evstr(x_matrix('enter a 3x1 matrix ',rand(3,1))) ab=[a b] a=ab n=length(b) for i=2:n for j=2:n+1 a(i,j)=a(i,j)-a(1,j)*a(i,1)/a(1,1) end a(i,1)=0; end for i=3:n ...
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exec('/home/andreu/dev/ros_ws/src/pipol_tracker/scilab/munkres.sci'); AA = [10 19 8 15; 10 18 7 17; 13 16 9 14; 12 19 8 18; 14 17 10 19]; //AA = [10 19 8 15; 10 18 10 17; 13 11 9 14; 12 13 8 18; 11 17 10 13]; //AA = [10 19 8 15; 10 18 7 17; 11 16 9 14; 12 19 8 18; 14 17 10 19]; //AA = [10 1 8 15; 10 18 7 17; 11 16 9 1...
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'''''''''''''''''''''''''''''''''''''''''''''' ' Luis Ricardo Salgado Garza '''''''''''''''''''''''''''''''''''''''''''''' function nuevoStr=leerYcodificar(dist) strCaracteres=('0':'9')+' '+('A':'Z'); strCaracteresCodigo=generaCodigoCesar(strCaracteres,dist); vStrCaracteres=strsplit(strCaracteres); ...
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//Car on road //refer fig. 19.8 //Consider dynamic equilibrium of car v=sqrt(0.4*9.81*50)*((60*60)/(1000)) //kmph //Limiting speed from the consideration of preventing overturning //Taking moment about point of contact of outer wheel with road and noting that R1=0 when the vehicle is about to overturn //Limiting...
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function p = sumpit3(a,b) p = max(abs(a),abs(b)) q = min(abs(a),abs(b)) while (q < > 0.0) r = (q/p)^2 s = r /(4+ r) q = s * q p = p + 2*s*p end endfunction
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function [x,y,typ] = FLEX_MTB_encoder(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then exprs = arg1.graphics.exprs; enc_type = exprs(1); standard_draw(arg1); case 'getinputs' then [x,y,typ] = standard_inputs(arg1); case 'getoutputs' then [x,y,typ] = standar...
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clc; C=2; //capacitance in Farad d=0.5*10^-2; //distance in m eo=8.85*10^-12; //constant A=(C*d)/(eo); //calculating area disp(A,"Area in m square = "); //displaying result
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// Scilab code Exa5.9 : : Page 205(2011) clc; clear; a_v = 14; // Volume energy constant, MeV a_s = 13; // Surface energy constant, MeV a_c = 0.60; // Coulomb energy constant, MeV a_a = 19; // Asymmetric energy constant, MeV A = 202; // Mass number Z = 82; // Atomic numb...
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@relation @attribute Mcg real[0.0,0.89] @attribute Gvh real[0.16,1.0] @attribute Lip real[0.48,1.0] @attribute Chg real[0.5,1.0] @attribute Aac real[0.0,0.88] @attribute Alm1 real[0.03,1.0] @attribute Alm2 real[0.0,0.99] @attribute Class{positive,negative} @inputs Mcg,Gvh,Lip,Chg,Aac,Alm1,Alm2 @outputs Class @data po...
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//start clc ; clear ; //line inputs linedata = input("Enter line data:") Yshunt=input("Enter shunt admittance:") // line data extraction from= linedata(: ,1) to= linedata(: ,2) imp= linedata(: ,3)+ linedata(: ,4)*%i half_adm= -linedata(: ,5)*%i bus_no= max(max(from,to)); Ybus= zeros(bus_no,bus_no); //...
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//=========================================================================== //chapter 3 example 4 clc; clear all; //variable declaration ep = 5; //percentage error Am = 20; //measuredd value in H //calculations er = ep/(100); //relative error //A = Am+dA //dA = ...
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Filter type is: H5Z_FILTER_FLETCHER32 Maximum value in DS1 is: 1890
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function [varargout]=rlocusplot(sys,kmax) //plots root locus and returns plot handle // //Calling Seqence //h=rlocusplot(H,Kmax) // //Parameters //H :- Siso linear system given by a transfer function or a state space //representation. //Kmax real(maximum gain desired for th...
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clear// //Variables R = 8 //Resistance (in ohm) I = 2.5 //Current (in Ampere) //Calculation V = I*R //Voltage (in volts) //Result printf("\n The maximum safe voltage is %0.3f volts.",V)
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// Ejemplo de una ecuaci�n diferencial parcial en 1D // Autor: Antonio Carrillo Ledesma // -Uxx-k^2U=0 // 0<=U<=1 // U(0)=1 y Ux(1)=ikU(1) TEST = 1; // (0) Diferencias finitas, (1) Diferencias finitas exactas segun Yau Shu Wong y Guangrui Li function y=LadoDerecho(x) y=0.0; endfunction function y=SolucionAnali...
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//Chapter-11 example 28 //============================================================================= clc; clear; //input data BW = 100//band width in Mhz PW = 4;//pulse width in us //Calculations CPW = 1/BW;//compressed pulse width in us CR = PW/CPW;//compression ratio //output mprintf('compressed pu...
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K P1=1.5; V1=3; T1=27+273; P2=30; T2=60+273; R=0.287; m1=(P1*100*V1)/(R*T1)...
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clear; clc; G=(integrate('(sin(P))^3','P',0,%pi))*integrate('1','Q',0,2*%pi) Gd=4*%pi/G; disp(Gd)
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//<s>=%lsst(s) //<s>=%lsst(s) calcule le dual d'un systeme lineaire decrit par repre- //sentation d'etat s. //Cette macro correspond a l'operation s' //! // origine s. steer inria 1987 // [a,b,c,d,x,dom]=s(2:7) s=list('lss',a',c',b',d',x,dom) //end
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// chapter 5 // example 5.7 // Calculate the total power loss // page-183 clear; clc; // given V_DS=120; // in V (DC power supply) I_D=4; // in A (drain current) t_r=80; // in ns (rise time) t_f=120; // in ns (fall time) I_DSS=2; // in mA (drain current at saturation) R_DS_on=0.2; // in ohm (drainn ot source resistance...
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//Chapter 21, Problem 6 clc; N=10; //turns ratio v1=2.5e3; //primary voltage P=5000; //power v2=v1/N; //secondary voltage i2=P/v2; //secondary current Rl=v2/i2; ...
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//A simple demo for the MUMPS interface, with the return of the schur complement //to run it, You just have to execute the instruction within Scilab // exec sparse_example.sce; //*********************** MATRIX INITIALISATION ***********************// n=10; mat=sprand(n,n,.5)+speye(n,n); size_schur=3; //...
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//Ex 1.10.1 clc;clear;close; format('v',9); //Given : l=4*10^-2;//m A=10*10^-6;//m^2 V=1;//Volt I=5*10^-3;//A q=1.6*10^-19;//Coulomb mu=1300;//cm^2/V-s J=I/A;//A/m^2 E=V/l;//V/m n=J/(q*mu*10^-4*E); v=mu*10^-4*E;//m/s disp(n,"Concentration of electron(per m^3) : "); disp(v,"Electron velocity(m/s) : ");...
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// Example 1.70 clc;clear;close; // Given data format('v',6); V=440;//in Volt f=50;//in Hz phase=3;//no. of phase P=6;//no. of poles Pin=80;//rotor input in KW f1=50;//in Hz f2=100;//in rotation/min I=65;//rotor current in Ampere //calculations f2=f2/60;//in Hz S=f2/f1;//slip disp(S,"Slip(p.u) : "...
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clc; clear all; F=1000110;//ASCII value of F r=1110010;//ASCII value of r a=1100001;//ASCII value of a n=1101110;//ASCII value of n k=1101011;//ASCII value of k SP=0100000;//ASCII value of SP D=1000100;//ASCII value of D u=1110101;//ASCII value of u g=1100111;//ASCII value of g disp(F,r,a,n,k,SP,D,u,n,g,a,n,...
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//voltage standing wave ratio //given clc clear format Vr=0.37//volts Vi=1//volts row=Vr/Vi if(row>=0) VSWR=(1+row)/(1-row) VSWR=round(VSWR*10)/10///rounding off decimals disp(VSWR,'THE voltage standing wave ratio is:') else disp('not possible') end
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// Scilab code Ex10.12: Pg.465 (2008) clc; clear; a = 0.1; // Lattice spacing, nm k = %pi/a; // Wave number E_F = 1; // Fermi energy gap, eV E_g = 1e-04; // Binding energy of coper pairs, eV // Since E_g/E_F = 2*delta_k/k, solving for delta_k delta_k = E_g/E_F*k/2; // Uncertainty in the value of ...
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clc //para los 11 dias y0 = [31.237385*10^6;6;0]; t= [1:11] Infec_exac = [1;6;7;9;11;17;22;38;43;71;86] y=ode(y0, 1, t, virus) Infec_SIR=y(2,:) disp([Infec_exac Infec_SIR'])
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//error - address not mapped inputimage1 = imread('image_0197.jpg'); //read an image a=pyramid(inputimage1,'expand',3); //perform 'expand' operation imshow(a); //view the output
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//Example 2.10 //inverse Z transform of 1/(1-a*z^-1) clear;clc; xdel(winsid()); // a=1 function y=f(z); y=z/(z-1) //upon simplification of the given equation endfunction intc(1+%i,2-%i,f)
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true-class positive negative positive 0.9 0.1 positive 0.8 0.2 positive 0.7 0.3 positive 0.6 0.4 positive 0.55 0.45 positive 0.54 0.46 positive 0.53 0.47 positive 0.52 0.48 positive 0.51 0.49 positive 0.505 0.495 negative 0.4 0.6 negative 0.39 0.71 negative 0.38 0.72 negative 0.37 0.73 negative 0.36 0.74 negative 0.35 ...
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function h = freqs (b, a, w) //Compute the s-plane frequency response of the IIR filter. //Calling Sequence //h = freqs (b, a, w) //Parameters //b: vector containing the coefficients of the numerator of the filter. //a: vector containing the coefficients of the denominator of the filter. //w: vector containing freque...
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clc // // // //Variable declaration e=0.14 //width of the slit y=1.6 //Distance of center of dark band from middle of central bright band n=2 //no. of dark band D=2 //Distance from the slit //Calculations lambdaa=((e*y)/(D*n))*10**5 //Result printf("\n The Wavelength is %i Angstrom",lambdaa)
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mes = input("Digite o mês: "); select mes case 1&&8 then mprintf("Boa"); case 9 then mprintf("hdfjhfdjs"); else mprintf("nmdj"); end
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clc disp("Example 1.34") printf("\n") disp("find out diode current") //given V=2 Vr=0.6 rd1=0 rd2=0.2 R=14 //when rd=0 //diode current I1=(V-Vr)/R printf("Diode current when rd=0 is \n%f ampere\n",I1) //when rd=0.2 //diode current I2=(V-Vr)/(R+rd2) printf("Diode current when rd=0.2 is \n%f ampere\n",I2...
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x1=1:3; x0=0:2 x1**2 x0**2 x1**2.000000001 x0**2.000000001 x1**(-2) x1**(-2.000000001) p=2+%eps*%i; x1**p x0**p x1**(-p) x1**0 //x0**(-p) y=%eps*%eps*ones(1,3) x1=x1+y x0=x0+y x1**2 x0**2 x1**2.000000001 x0**2.000000001 x1**(-2) x1**(-2.000000001) p=2+%eps*%i; x1**p x0**p x1**(-p) x1**0 x0**(-p)
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//example 11.7 //calculate leading dimension of hydraulic jump stilling basin clc;funcprot(0); //given q=7.83; //discharge through spillway w=12.5; //width of fall d=2; //depth of water in downstream g=9.8; y1=0.5; v1=q/y1; F1=v1/(g*y1)^0.5; //F>1,flow is super-critical v2=q/...
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//Example 2.2.2 page 2.5 clc; clear; z=30; //Length of the fibre in kms alpha= 0.8; //in dB P0= 200; //Power launched in uW pz= P0/10^(alpha*z/10); printf("The output power is:%.4f uW",pz);
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//CHAPTER 7_ Flow Measurement //Caption : Sonic nozzle // Example 6// Page 443 disp("Let uncertainty in mass flow rate be represented by wm") disp("Let uncertainty with pressure be represented by wp") disp("Let uncertainty with temperature measurement be represented by wt") // To calculate the uncertainty in the ...
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//clear// clear; clc; //Example 9.4 //Given Dt = 6; //[ft] Da = 2; //[ft] n = 80/60; //[rps] T = 70; //[F] rho = 62.3; //[lb/ft^3], From Appendix 14 mu = 6.6*10^-4; // [lb/ft-s], From Appendix 14 Nre = Da^2*n*rho/mu; //From Fig. 9.15 ntT = 36; tT = ntT/1.333 //[s]
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clear //Given L=800.0*10**-7 C=3.0*10**8 f1=4.5*10**6 //Hz //Calculation f=C/L d=(1/100.0)*f E=d/L G=d/f1 //Result printf("\n (i) number of channels for audio signal is %0.1f *10**8",E*10**-14) printf("\n (ii) number of channels for video tv signal is %0.1f *10**5",G*10**-3)
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//Compute the control limits //page no 105 clear clc; K = 25; n = 5; X1 = 357.5; R1 = 8.8; USL=14.8; LSL= 14.0; X2=X1/K; R2=R1/K; A2 = 0.58; d2 = 2.326; d3 = 0.0; D4 = 2.11; //Control limits for R-chart UCLR = D4*R2; LCL = d3*R2; CL = R2; //(a) Control limits for X -chart. UCL = X2 + A2*R2; mprint...
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// Test # 6 : Range test for Input Argument #4 or Input Argument #5 exec('./zpkbpc2bpc.sci',-1); [z,p,k,n,d]=zpkbpc2bpc(7.3,5.2,9.7,[-0.9,0.6],[4,0.8]); //!--error 10000 //Wt must lie between -1 and 1 //at line 55 of function zpkbpc2bpc called by : //[z,p,k,n,d]=zpkbpc2bpc(7.3,5.2,9.7,[-0.9,0.6],[4,0.8]);
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/////////////////////////////// // Un calcul de flot optique // // BRUNEAU Basile // // MASSET Camille // // MAP411 // /////////////////////////////// // Programme Scilab du projet. // Les fonctions utilisées ont été définies dans 'functions.sci' exec('functions.sci', -1); //...
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// calculating output voltage due to offset voltage clc; V1=1; V2=-2; Rf=500; R1=250; R2=100; Vo=-{[(Rf/R1)*V1]+[(Rf/R2)*V2]}; disp(Vo,'output voltage(V)=')
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// Calculating the bridge output clc; ei=6; R=10000; disp('if dR=0.05R') dR=0.05*R; eo=[(dR/R)/(4+2*(dR/R))]*ei; disp(eo,'output voltage (V)') disp('if dR=-0.05R') dR=-0.05*R; eo=[(dR/R)/(4+2*(dR/R))]*ei; disp(eo,'output voltage (V)')
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[Read-the-docs-example-2] # Read the docs - example 2 indice_name: ETR in_files: [['tasmax_day_MPI-ESM-LR_historical_r1i1p1_19900101-19991231.nc'], ['tasmin_day_MPI-ESM-LR_historical_r1i1p1_19900101-19991231.nc']] dt1: 1990-01-01 dt2: 1999-12-31 slice_mode: year
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clc;funcprot(0);//Example 2.25 //Initilisation of Variables T1=150;....//temparature at material A surface in degrees celcius T3=50;.....//temparature between materials B&C in degrees celcius K1=0.1;....//thermal conductivity of material A in W/m*degrees celcius K2=1.0;.....//thermal conductivity of material B in ...
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clc //ex6.2 //given V_in(t)=3+2*cos(2000*%pi*t)+cos(4000*%pi*t-A), A=70*%pi/180 //the three parts of V_in(t) are V_in_1=3, V_in_2=2*cos(2000*%pi*t),V_in_3=cos(4000*%pi*t-A) //first component V_1 V_in_1=3; f_1=0; //as omega is zero //equation of straight line of H_magnitude vs f is x+1000*y-4000=0 H_1_max...
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//skipped groundPlane_transform //skipped Manipulator1 //skipped UniversalManip //skipped CubeCompass ///////////////////////////////////////////// // object_Trim_Char_x_1_1__ ///////////////////////////////////////////// #if 0 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1 #endif DX3DMATERIAL_STA...
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function []=gauss_jord() A=evstr(x_matrix('enter a 3x3 matrix ',rand(3,3))) disp(A, "Matrix A : ") Aug = [A,eye(n,n)]; for j=1:n-1 for i=j+1:n Aug(i,j:2*n) = Aug(i,j:2*n)-Aug(i,j)/Aug(j,j)*Aug(j,j:2*n); end end for j=n:-1:2 Aug(1:j-1,:)=Aug(1:j-1,:)-Aug(1:j-1,j)/Aug(j,j)*Aug(j,:); end...
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clc //initialisation of variables clear T= 25 //C I= 4.33*10^-40 // gcm^2 I1= 2.78*10^-40 //g cm^2 s= 3 //CALCULATIONS S= 4.576*(0.5*log10(I1^2*I)+1.5*log10(273.2+T)-log10(s)+58.51) //RESULTS printf ('Standard entropy = %.1f cal deg^-1 mole^-1',S)
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// b) b = [1 0 0; -.1 0 .1; -.1 -.1 2] disp('Autovalores de b', spec(b)) // d) d = [4 -1 0; -1 4 -1; -1 -1 4] disp('Autovalores de d', spec(d)) // f) f = [4.75 2.25 -.25; 2.25 4.75 1.25; -.25 1.25 4.75] disp('Autovalores de f', spec(f)) // Resultado de Scilab // "Autovalores de b" // 1.9949...
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favour = 0.45; samplesize = 200; expec= favour*samplesize; sd = sqrt(samplesize*favour*(1-favour)); disp(expec, "The expected value is ") disp(sd, "The standard deviation is ") function result= bino(n, k, p) result = factorial(n)*(p^k)*((1-p)^(n-k))/(factorial(k)*factorial(n-k)) endfunction //newsum = ...
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M=2;//mach no at which F-104 is flying S=19.5;//wing planform area in m^2 //in steady flight lift equals to weight so: L=7262*9.8 //lift (N) R=287 ;//gas constant,J/Kg.K y=1.4; //specific heat ratio for air //part a(at sea level) D=1.23;//density at sea level(Kg/m^3) T=288;//sea level temperature(K) V=(y*R*T)^...
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clear; clf; clc; N = 256; n = 0:N-1; a = 0.5; x = a**n; y1 = fft(x); y = fftshift(y1); r = real(y); i = imag(y); angle = atan(i./r); yabs = abs(y); w = 0 : 2*%pi/ (N-1) : 2*%pi; subplot(211); plot(w,yabs); title("Magnitude spectrum : a = 0.5", "fontsize", 2); xlabel("W","fontsize",2); ylabel("abs(Y)","fontsize...
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clc clear //Input data V1=0.6;//Initial volume of an engine working on otto cycle in m^3 P1=1;//Initial pressure in bar T1=308;//Initial temperature in K P2=10;//Pressure at the end of compression stroke in bar Q=210;//Heat added during constant heat process in kJ r=1.4;//Isentropic constant of air //Calcula...
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//Problem 44.10: An open wire line is 300 km long and is terminated in its characteristic impedance. At the sending end is a generator having an open-circuit e.m.f. of 10.0 V, an internal impedance of (400 + j0) ohmand a frequency of 1 kHz. If the line primary constants are R = 8 ohm/loop km, L = 3 mH/loop km, C = 7500...
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clc clear //Initialization of variables G=-30050 //kJ/kmol R=8.314 T=573 //K //calculations lnk=G/(R*T) k=exp(lnk) x=poly(0,"x") vec=roots(4*x^2 - k*(1-x)^2) x2=vec(2) //results printf("Mole fraction of HCN = %.4f",x2)
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T=23+273 //kelvin P=3+14.7 //psi //conversion of pressure from psig to psi requires addition of 14.67 which is 1 atm R=0.08206 //lt-atm MN2=28 //molecular wt. weight=100 //grams
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clc; //page no 571 //prob no. 16.4 //A dipole antenna with efficency=85% given n=0.85;D_dBi=2.14;//Directivity in dBi //Determination of gain in dB D=10^(D_dBi/10); G=D*n;//Determination of gain G_dBi=10*log10(G);//Converting to dBi disp('dBi',G_dBi,'The gain is');
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clear; clc; //Example 7.15 V1=5; V=-5; Rs=0.1; R1=40; R2=5.72; Re=0.5; Rc=5; Rl=10; b=150; Vbe=0.7; C1=35; C2=4; Vt=0.026; Icq=1.02; gm=39.2; r=3.82; x=Re*Rs/(Re+Rs); t=r/(1+b); y=t*x/(t+x); Tp=y*C1; printf('\ntime constant=%.3f ns\n',Tp) Tp=0.679*10^-3;//micro sec f=1/(2*%pi*Tp); printf('\nup...
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// problem 7.2 b=5 d=3 i=1/1000 C=55 A=b*d m=A/(b+2*d) Q=A*C*((i*m)^0.5) v=Q/A disp(Q,v,"flow rate assuming chezys constant eqaul to 55 in m3/sec & velocity of flow in m/sec")
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//Ex11_6 clc; //Given: // Relative biological effectiveness(RBE) a7=10;// for alpha partical a6=1;//for gamma radiations tn=2.5;// for thermal neutrons g=1;// for gamma radiation rd=0.6;//radiation dose in gray //Formulas //1.The Rontgen equivalent mammal (REM)=RBE*rads //2.The sievert is the SI unit...
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//example 6.3 //page 233 clc; funcprot(0); //initialisation of variable k=1/50;//lm/lp; C=3.8; L=300; Q=100000; Qm=Q*k^2.5; disp(Qm,"flow rate on model(m^3/s)") H=(Q/C/L)^(2/3); disp(H/50,"Head over model(ft)"); clear
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-- VectorCAST 6.4d (02/29/16) -- Test Case Script -- -- Environment : MANAGER_W -- Unit(s) Under Test: manager -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCRIPT_FE...
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function [y]=sinc_new(x) i=find(x==0); x(i)= 1; // From LS: don't need this is /0 warning is off y = sin(%pi*x)./(%pi*x); y(i) = 1; endfunction
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clear; clc; // Example: 5.15 // Page: 169 printf("Example: 5.15 - Page: 169\n\n"); // Solution //*****Data*****// m1 = 5;// [kg] m2 = 20;// [kg] C = 4.2;// [kJ/kg K] T1 = 350;// [K] T2 = 250;// [K] //**************// // Suppose the final temperature is T deff('[y] = f(T)','y = m1*C*(T1 - T) - m2...
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//Example 11.2 //Find the circular convolution clc; x1=[3,1,3,1]; x2=[1,2,3,4]; X1=fft(x1,-1); X2=fft(x2,-1); X3=X1.*X2; x3=fft(X3,1); disp(x3,'x3(n)=x1(n)(N)x2(n)');
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clc //Example 13.1 //Calculate the pressure gradient v=1//ft/s d=0.5//ft A=(%pi)/4*d^2//ft^2 Q=v*A//ft^3/s //Let DP denote the pressure gradient n=0.41//dimentionless K=0.66//kg/m/s //1 m = 3.281 ft Q1=Q/3.281^3//m^3/s d1=d/3.281//m DP=(Q1*8*(3*n+1)/(n*(%pi)*d1^3))^n*(4*K/d1)//Pa/m printf("The pressure g...
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//Caption: Amount of Information //Example 9.3 //page no 395 //Find Amount og Information clc; clear; px1=1/2; px2=1/2; Ix1=log2(1/px1);//entropy Ix2=log2(1/px2); printf(" \n The amount of Information \n \n\t I(X1) = %.2d bit\n",Ix1); printf(" \n The amount of Information \n \n\t I(X2) = %.2d bit",Ix2);
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clear; clc; // Stoichiometry // Chapter 4 // Material Balances involving Chemical Reaction // Example 4.9 // Page 125 printf("Example 4.9, Page 125 \n \n"); // solution m = 100 //[kg] soya fatty acid (basis) // use table 4.6 M1 = m/.3597 // M(avg) of soya fatty acid //3 mol of fatty acid + 1 mol o...
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//ques-24.3 //Finding molality of a solution clc x=2/100;//mole fraction of solute X=1-x;//mole fraction of solvent m=x/(X*18/1000); printf("The molarity of the solution is %.3f mol/kg.",m);
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// Scilab Code Ex 10.14 Hall coefficient calculation of sodium based on free electron model: Page-353 (2010) e = 1.6D-19; // Electronic charge, C a = 4.28D-10; // lattice parameter (side) of the unit cell of sodium crystal, m N = 2; // Number of atoms per unit cell in bcc structure of sodium n = N/a^3...
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/////////Chapter 10 Properties Of Steam ///Example 10.3 Page No:184 //Find Saturation temperature of bar ///Input data clc; clear; P1=28; ///Absolute pressure in bar P2=5.5; //Absolute pressure in MPa P3=77; ///Absolute pressure in mm of Hg ///Calcutation ts1=230.05; //Saturation temperature i...
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errcatch(-1,"stop");mode(2);// Example 1.4 page no-13 V0=10 //volts siince energy is 10ev xm=2 theta=%pi/4 V=(2*V0*sin(2*theta))/xm printf("V=%.0fd Volts",V) exit();
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clear; clc; printf("\t\t\tExample Number 3.12\n\n\n"); // Three-dimensional numerical formulation // Example 3.12 (page no.-110-113) // solution Tinf = 10;// [degree celsius] environment temperature h = 500;// [W/square meter degree celsius] Ts = 100;// [degree celsius] four side temperature k = 2;// [W/m de...
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K T1=27+273; V1=0.06; P1=150; Ro=8.314; M=28; R=Ro/M; m=(P1*100*V1)/(R*T1);...
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clc //initialisation of variables G= 2054.7 //cal R= 1.9872 //cal/mol K T= 298.16 //K //CALCULATIONS P= 10^(-G/(2.303*T*R)) //RESULTS printf (' pressure = %.5f atm',P)
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// Example No. 3.1 // To calculate the Einstein A and B coefficients // Page no.99 clc; clear; // Given data tsp=2*10^-9; // Spontaneous lifetime associated with 2 → 1 transition in seconds deltaE=2.4*10^(-19); ...
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4_5.sce
//mass-spring system //free body diagram and state diagram are drawn as shown in figure 4-19(b) and 4-19(c) //applying gain formula to state diagram syms K M B s=%s //considering y1 as output M1=(1/M) L11=-(B/M)*(s^-1) L21=-(K/M)*(s^-2) L31=(K/M)*(s^-2) delta=1-(L11+L21+L31) delta1=1-(L11+L21) x=M1*delta1/d...
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clear; clc; // Stoichiometry // Chapter 4 // Material Balances involving Chemical Reaction // Example 4.16 // Page 144 printf("Example 4.16, Page 144 \n \n"); // solution // basis : 1day operation // NaCl = Na+ + Cl- //H2O = H+ + OH- //Na+ + OH- = NaOH //H+ + e = (1/2)H2 //Cl- - e = (1/2)Cl2 E ...
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126.sce
// problem 12.6 no=0.8 P=147*1000 H=10 g=9.81 u1=0.95*(sqrt(2*g*H)) Vf1=0.3*(sqrt(2*g*H)) N=160/60 Vw2=0 nh=(H-(0.2*H))/H Vw1=nh*g*H/u1 x1=atand(Vf1/Vw1) y1=atand(Vf1/(u1-Vw1)) D1=u1/(3.142*N) w=9810 p=147*1000 Q=p/(w*H*no) B1=Q/(3.142*D1*Vf1) disp(B1*100,D1,y1,x1,"guide blade angle,wheel vane angle,d...
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clc //initialisation of variables pH= 7.10 pH1= 7.21 //CALCULATIONS r= 10^(pH-pH1) //RESULTS printf (' ratio of salt to acid = %.3f ',r)
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testSwayCorrection3ddl.sci
// this code test the asser visu // given as an input to Andreis function // for step computing // // // test another correction //;exec('main/testAVrobotErreurMarche.sce'); function testSway3ddl(OPT_CORR,OPT_L_COURANT) disp('Entering testSway3ddl') maxiter = 100; OPT_DISPLAY = %T; OPT_SAT = %F; ...
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//Example 3.72:resistance and inductance clc; clear; close; r2=100;//ohm r4=834;//ohm c3=0.1;//micro-F l1=r2*r4*c3*10^-3;//mH c4=0.124;//micro-F r1=(c3/c4)*r2;// f=2;//kHz z1=sqrt(r1^2+(2*%pi*f*10^3*l1*10^-3)^2);// disp(l1,"inductance is ,(mH)=") disp(r1,"resistance is,(ohm)=") disp(z1,"impedence is ,(ohm)=")
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clear //Given l1=5890*10**-10 //m l2=5896*10**-10 d=2.0*10**-6 //m D=2 //m //Calculation x=(3*D*(l2-l1))/(2*d) //Result printf("\n Spacing between the first maxima of two sodium lines is %0.3f *10**-4 m",x*10**4)
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clc //initialisation of variables p=100//ft q=27000//acre-ft p1=10//ft s=8250//acre-ft //CALCULATIONS R=p*s/q//percent //RESULTS printf('the ratio of peak inflow from fuller values=% f percent',R)
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clc clear //Input data C=(2*10^-6)//Capacitance in F er=80//Permitivity of the dielectric V=1000//Applied voltage in V //Calculations E1=(1/2)*C*V^2//Energy stored in the capacitor in Joule Co=C/er//Capacitance of the capacitor when the dielectric is removed in F E2=(1/2)*Co*V^2//Energy stored in the capaci...
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disp("enter the matrix") A = [input("value"), input("value"), input("value"); input("value"), input("value"), input("value"); input("value"), input("value"), input("value")]; disp("the matrix is:") disp(A) function Gauss(A) n= 3; for i=2:n for j=2:n A(i,j) = A(i,j) - A(1,j)*A(i,1)/A(...
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// Exa 4.7 clc; clear; // Given // Two sinusoidal voltage signals are applied to vertical and horizontal plates of CRO // Solution printf('Theta = asin(dvo/DV'); // Referring fig(a) Theta_a = asind(0) ; // dvo = 0 printf(' Theta for trace shown in fig(a) = %d degrees\n',Theta_a); // Referring fig(b) ...
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clc //Example 7.6 //Parameters of single degree of freedom system //------------------------------------------------------------------------------ res6=mopen(TMPDIR+'6_parameters_of_sdof.txt','wt') mfprintf(res6,'(a) General equation of any single degree of freedom system is given by\n') mfprintf(res6,'ma +...
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N(3,2) CDF.sce
//Gaussian N(u,sigma^2) Distribution CDF // Le Thu Huong ADEO1 clc N = 10000; x0 = -10; xmax = 10; delx = 0.2; x = [x0:delx:xmax]; sigma1 = 0.5; sigma2 = 0.4; mu1 = 7; mu2 = 5; for k = 1:length(x) c1 = 0; c2 = 0; z1 = 0; z2 = 0; for i = 1:N u1 = rand(); ...
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clc; clear all; h=80;//height of transmitting antenna antenna Dt=4*sqrt(h);//radio horizon distance disp(Dt,'radio horizon distance of transmitting antenna in km is='); h=40;//height of receiving antenna Dr=4*sqrt(h);//radio horizon distance disp(Dr,'radio horizon distance of receiving antenna in km is='); Dm=D...
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Dotfilldata.sci
// 08.05.31 // 10.01.01 // 10.03.07 (Kosa ) function ShaL=Dotfilldata(varargin) global XMIN XMAX YMIN YMAX MilliIn; Nargs=length(varargin); ShaL=[]; Eps=0.01; Kakudo=45; Kosa=0.5; Tmp=Doscaling([XMIN,YMIN]); Xmn=Tmp(1); Ymn=Tmp(2); Tmp=Doscaling([XMAX,YMAX]); Xmx=Tmp(1); Ymx=Tmp(2); for N=Nargs:...