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clc clear //input data R=0.5//Degree of reaction P0=2.2//Inlet pressure in bar T0=443//Inlet temperature in K N=2400//Rotor running speed in rpm Dm=0.5//Rotor mean diameter in m a1=36//Rotor inlet angle in degree a2=19//Stator exit angle in degree ns=0.88//Stage efficiency m=1//Mass flow rate of steam in kg/...
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function out=S(x,p) somme=0; for i=0:p somme=somme+(sin(x*(2*i+1))/(2*i+1)); end out=somme*(4/%pi); endfunction clf; gamme_n = [10,100,500,1000]; nom_n = ["n=10","n=100","n=500","n=1000"]; x=linspace(-%pi,%pi,10000); for i=1:length(gamme_n) n=gamme_n(i); subplot(2,2,i); plot(x,S(x...
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function b=fact(n) if n<=1 then //si n=0 ou 1 alors n!=1 b=1 else //si n>1 alors n!=n*(n-1)! b=n*fact(n-1) end endfunction function max1=f(x) max1=max(100-x,0) endfunction function p=price1(N, Rn, Hn, Bn, s,f,fact) g=0 q=(Rn-Bn)/(Hn-Bn) for i =[0,N] g=g+(fact(N)/(fact(i)*fact(N-i)))*(q^i)*((1-q...
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//Problem 7.13: Figure 7.4 shows a ring formed with two differentmaterials—cast steel and mild steel. The dimensions are: // mean length cross-sectional area // Mild steel 400 mm 500 mm2 // Cast steel 300 mm 312.5 mm2 //Find the...
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errcatch(-1,"stop");mode(2);//Chapter 22, Problem 14 ; Ra=0.25; //armature resistance V=300; //supply voltage Ia1=100; //current 1 Ia2=80; //current 2 E1=V+(Ia1*Ra); //e.m.f (generator) E2=V-(Ia2*Ra); ...
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// RSA Encryption scheme p = 7 //Large prime numbers q = 17 //Small values taken here for convenience of calculation //and explanation n = p*q z = (p-1)*(q-1) e = 5 // e<n and e & z are coprime i=1 d = i ...
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scenario = "run5_VisoddballPlusMMN_pronetSZAMP_09042021"; #======================================== # #Visual Task: # #Tone1 16 #Tone2 18 #Response 17 #Standard 32 #Target 64 #Novel 128 # #======================================== #attenuation updated for ER1 insert earphones and X-fi gamer card pcl_file = "nvMMNComman...
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clear; clc; close; a=1; dt=.01; t=0:dt:10; x=exp(-a*t); y=[x($:-1:1) x]; t1=-10:dt:10.01; a=gca(); plot(t1,y); poly1=a.children.children; poly1.thickness=3; poly1.foreground=2; xtitle('x(t)','t') //clf(); //stacksize(10000,100000) wmax=10; w=0:0.01:wmax; Xw=x*exp(-%i*(w'*t))*dt; Xw_mag=(Xw); Xw_ma...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 9 //Chemical Reaction Equilibria //Example 19 clear; clc; //Given: //Reaction: 1/2N2 + 3/2H2 --> NH3 Kp = 1.25*10^-2 ;//equilibrium constant P = 50; //pressure in bar v = 1-(3/2)-(1/2); //change in number of moles in reaction //Initial c...
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Y = [8 0 0 1 3 4 0 2 12 5 1 8 0 2 0 1 9 3 4 5 3 3 4 7 4 0 1 2 1 2]; weeks = 30; lamda = sum(Y)/weeks; p = zeros(5,1); p(1) = cdfpoi("PQ", 0, lamda); p(2) = cdfpoi("PQ", 1, lamda) - p(1); p(3) = cdfpoi("PQ", 3, lamda) - cdfpoi("PQ", 1, lamda); p(4) = cdfpoi("PQ", 5, lamda) - cdfpoi("PQ", 3, lamda); p(5) = 1 - c...
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clc; clear; mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-10.2 Page No.198\n'); Pa=100; //[lb/in^2] Air pressure Da=4; //[in] Diameter Aa=%pi*Da^2/4; //[in^2] Cross section area F1=Pa*Aa; //[lb] Do=1; //[in] Ao=%pi*Do^2/4; //[in] P...
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//Example No. 13_09 //Optimum step size //Pg No. 444 clear ; close ; clc ; x = 0.8 ; h1 = 0.05 ; y1 = 5.8410870 ; h2 = 0.025 ; y2 = 5.8479637 ; //d = 4 h = ((h1^4 - h2^4)*10^(-4)/(2*(y2 - y1)))^(1/4) disp(h,'h = ','for four decimal places') //d = 6 h = ((h1^4 - h2^4)*10^(-6)/(2*(y2 - y1)))^(1/4) dis...
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//Sketch plot of given s-domain signal,X(s)=(s+2)*(s.^2+8*s+20)/(s+3)/(s.^2+2*s+2) clc; clear; s=poly(0,"s"); X=(s+2)*(s.^2+8*s+20)/(s+3)/(s.^2+2*s+2); disp(X,'given s-domain signal=>'); plzr(X);
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clc //initialisation of variables W= 600 //lb/ft L1= 8 //in L2= 4 //in b= 6 //in h= 8 //in t= 1 //in //CALCULATIONS R1= W*(L1+L2)*((L1+L2)/2)/L1 R2= W*(L1+L2)*(L1-(L1+L2)/2)/L1 Vmax= 3000 //lb I= (b*h^3/12)-(L2*b^3/12) Ay= b*L2*(L2/2)-L2*b/2*b/4 b= t+t Tmax= Vmax*Ay/(I*b) //RESULTS printf ('maximum she...
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///Chapter No 7 Fluid Mechanics ///Example 7.20 Page No:130-131 /// Find Continuity eqation //Input data clc; clear; D11=0.25; //Diameter at inlet in m D12=0.175; //Diameter at outlet in m P1=450*10^3; //Intensity of pressure at inlet in kPa P2=200*10^3; ...
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before x, phead=0, pbody=8, ptail= - 108*y^3 + 72, mlead= + 9*x^2, flead=324, root2=18, widev=36 after x, phead=x^2, pbody=8, ptail= - 108*y^3 + 8, vmapt={x=>8+18*x,y=>y} ("8*x + 9*x^2 - 3*y^3 + 2").getReductionMap(1) = {=>x^2 - 4*y^3 + 8,x=>18*x + 8,y=>3*y}
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clear; //system specifications f_samp = 2000*10^6; fc = 800*10^6; Ts = 1/f_samp; n = linspace(1,2000,2000); n_points = 10000; A = linspace(0.1,10,20)*(10^-3); j = 1; R = 100*10^(-3) PLdB = 128.1 + 37.6*log10(R); PL = sqrt(10^(-PLdB/10)/2); // outer loop for different amplitude values whil...
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// Example 2.27, page no-46 clear clc h=1 k=1 l=0 d=2*10^-10//m a=d*sqrt(h^2+k^2+l^2) R=a/(2*sqrt(2)) printf("The lattice constant is %.3f*10^-10 m\nThe atomic radius of the crystal is %.1f *10^-10 m",a*10^10,R*10^10)
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//Example_a_17_2 page no:864 clc; fc=1.5*10^3; k=500; fa=1600; m=sqrt(1-(fc/fa)^2); L=k/(%pi*fc); C=1/(%pi*k*fc); //calculating T-section elements L_t=m*L/2; L_t=L_t*1000; C_t=m*C; C_t=C_t*10^6; L1_t=(1-m^2)*L/(4*m);//the inductance value is wrong in text book, correct calculation is done here L1_t=L1_t*1...
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//Two blocks on an inclined plane //refer fig. 15.11 (a,b,c) and (d) //Let block A move with an acceleration a1 and block B with an acceleration a2 //Consider block A //Using equilibrium conditions //NA=WA*cosd(30) mu1=0.2 WA=100 //N //From the law of friction FA=mu1*WA*cosd(30) // a1=3.2058 //m/sec^2 //...
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//Authors: //Sachin Gopal (15BCE1188) //Aashay Gondalia (15BCE1284) //Dhruv Dixit (15BCE1324) //VIT Chennai //Code to compute the CPU time taken by each routing algorithm to return the //Vector of the total distance between each network node and the source node and //Vector composed by the predecessor of each node in...
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// Example 4_2 clc;funcprot(0); // Given data E_fuel=15000;// Btu/min E_exhaust=500;// Btu/min W_1=200;// hp W_2=50;// hp E_thl=180000;// Top heat loss in Btu/h E_Bhl=54000;// Bottom heat loss in Btu/h // Solution Q=-E_thl-E_Bhl;// The net heat transfer into the system in Btu/h W=W_1+W_2;// The net work ra...
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clear; clc; B=10 //current gain IB=0.6 //in A VBE=1 //in V RC=10 //in ohm VCC=100 //in Vs //Calculation IC=B*IB //in A VCE=VCC-(IC*RC) //in V VCB=VCE-VBE //in V PT=(VCE*IC)+(VBE*IB) mprintf("Total power dissipation= %.1f W",PT) disp("The BJT is working outside the SOA")
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//check o/p when i/p along with unit string and reference load are passed as args to the function v=1e-3; u=db(v,'power',50); disp(u); //output //power // - 30.
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// Scilab code Ex8.3 : Pg:328(2008) clc;clear; function [deci]= binary_decimal(ni) // Function to convert binary to decimal deci = 0; i = 0; while (ni <> 0) rem = ni-fix(ni./10).*10; ni = int(ni/10); deci = deci + rem*2.^i; i = i + 1; end endfunction function [d...
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//clear// //Caption:Program to determine the pulse width at the optical fiber output //Example13.11 //page474 clear; clc; T = 10; //width of light pulse at the optical fiber input in pico secs beta2 = 20; //dispersion in pico seconds square pre kilometre z = 15; // length of optical fiber in kilometre delta_t ...
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clc clear //Initialization of variables g=9.81 //m/s^2 rho=10^3 //kg/m^3 P1=80*10^3 //N/m^2 P2=12*10^6 + 101300 //N/m^2 Hq=-400 //J/N //calculations g1=g*rho Hs= -Hq+ (P2-P1)/(g1) //results printf("Energy added by pump = %d J/N",Hs) disp("The answer given in textbook is wrong. Please verify using a calcula...
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clear //Given M=4.8*10**-2 //J/T a=30 //degree B=3*10**-2 //t //Calculation // t=M*B*sin(a*3.14/180.0) //Result printf("\n Torque acting on the needle is %0.1f *10**-4 Nm",t*10**4)
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${ using Typewriter.Extensions.WebApi; Template(Settings settings) { settings.OutputFilenameFactory = file => GetCamelCaseFileName(file.Name); } string debug(Func<string> action) { try{return action();} catch (Exception ex) {return ex.ToString();} } string GetCa...
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clear // //e=b*l*u*sin(angle) b=0.5 l=40 u=1.5 //when angle=90 sin(90)=1=s s=1 e=b*l*u*s printf("\n e= %0.1f V",e) //when angle=30 sin(angle)=s=0.5 s=0.5 e=b*l*u*s printf("\n e= %0.1f V",e)
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; TASK DESCRIPTION FILE ; ; Task set descriptions, from which tasks are instantiated. ; Keywords are at the line's beginning ; ; Lines beginning with '*' or ";" are ignored ; No line can be longer than MAX_STRING characters ; No task name can be longer than MAX_NAME_LENGTH ; ; title Article's Ex...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 7, Example 4") disp("Nozzle Throat area in m2, A = m/(rho2*Ca2)") disp("rho2 = P2/(RT2)") disp("T2 = T02 - C2^2 /(2Cp)") T02 = 1100;/...
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//Chapter 9, Problem 11 clc; L=150*10^-3; E=40; //since the current is reversed, dI =6−(−6)=12A dI=12; //calculating change in time dt dt=(L*dI)/E; printf("Change in time dt = %f sec",dt);
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#************************************************************ # Scenario of test # # date : Mon Jun 8 10:04:16 2009 #************************************************************ p3d_sel_desc_name P3D_ENV test p3d_sel_desc_name P3D_ROBOT CylinderRob p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000...
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clc h_f2=158.2; //kJ/kg x2=0.62; h_fg2=1280.8; h1=298.9; //kJ/kg h_f4=h1; s_f2=0.630; //kJ/kg K T2=268; //K T3=298; //K s_f3=1.124; //kJ/kg K h_fg3=1167.1; //kJ/kg m=6.4; //kg/min cp=4.187; L=335; //kJ/kg h_f3=298.9; //kJ/kg h2=h_f2+x2*h_fg2; x3=((s_f2-s_f3)+x2*h_fg2/T2)/h_fg3*T3; h3=h_f3+x3*h_fg3; ...
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//Scilab Code for Example 11.6 of Signals and systems by //P.Ramakrishna Rao //Hilbert Transform clc; clear A T t x; T=2; A=1; n=1; for t=-10:0.01:10; if t>-T/2 & t<T/2 then x(n)=A; n=n+1; else x(n)=0; n=n+1; end end t=-10:0.01:10; //Signal x(t) plot(t,x); title('G...
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function [x1,x2]=create_linear_separation(data,W) x=min(data):0.2:max(data); x1=(-W(3)/W(2)).*x + (W(1)/W(2)); x2=(-W(2)/W(3)).*x + (W(1)/W(3)); x1=x; endfunction
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clear; clc; disp("--------------Example 19.10---------------") // address :- 190.100.0.0/16 i.e 65,536 addresses num_of_ISP_addresses=65536; //total number of addresses printf('\n'); function [total]= addresses (num_of_customers,num_of_addresses) //function to find total number of addresses allocated to a group ...
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clear ; clc; // Example 16.3 printf('Example 16.3\n\n'); //Page no. 494 // Solution //Given T1 = 110 ;// Temperature of chlorobenzene - [degree C] T1F = (9*T1)/(5) + 32 ;// Temperature of chlorobenzene - [degree F] P1 = 400 ;//Pressure of chlorobenzene - [mm of Hg] P1_psia = P1*14.7/760 ;//Pressure of chl...
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//Example 7.1.1 //Find the laplace transform and Roc of the following signal clc; close; syms t; a=5; x=exp(-a*t); b=6;c=7; s=b+c*%i; X=integrate((exp(-(a+s)*t)),'t',0,%inf); disp(X); disp(real(s)); disp('Since real(s)>-a,so the integral converges');
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clear; clc; syms t s a H=1/(s+a); h=ilaplace(H) disp(h*'u(t)',"h(t)=")
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*Testcase bfp-020-multlonger.tst: MDEBR, MDEB, MXDBR, MXDB #Testcase bfp-020-multlonger.tst: Multiplication to longer format tests Multiply (4) #..Includes only multiply to increased precision MDEBR/MDEB and MXDBR/MXDB #..Test cases evaluate NaN propagation, NaN generation, operations #..using non-finite values, trapp...
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//Ex:2.3 clc; clear; close; v=28;//in volts i=0.1;//in A r=v/i; p=v*i; printf("Resistance Value = %f ohms & Power dissipated = %f W",r,p);
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//Chapter-1, Example 1.5, Page 20 //============================================================================= clc clear //INPUT DATA k=0.145;//Thermal conductivity of Firebrick in W/m.K e=0.85;//Emissivity L=0.145;//Thickness of the wall in m Tg=800;//Gas temperature in degree C Twg=798;//Wall temperatur...
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clear; clc; printf("\t\t\tExample Number 5.10\n\n\n"); // turbulent-boundary-layer thickness // illustration5.10 // solution // we have to use the data from example 5.8 and 5.9 Rel = 1.553*10^6;// from previous example L = 0.75;// [m] length of plate // it is a simple matter to insert this value in equati...
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//Problem 25.01: Determine the admittance, conductance and susceptance of the following impedances: (a)-i5 ohm, (b)25+i40 ohm, (c)3-i2 ohm, (d)50/_40°ohm. //initializing the variables: Z1 = 0 - %i*5; // in ohms Z2 = 25 + %i*40; // in ohms Z3 = 3 - %i*2; // in ohms r4 = 50; // in ohms theta4 = 40; // in degrees ...
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/////////////////////////////////////////////////////////////////////////////// // Author: Ran He // Version: 0.1 // Date: May 2009 // Description: Weighted principal component analysis(WPCA) // Reference: C.M. Bishop. Pattern Recognition and Machine Learning. Information Science and Statistics,2006 // // Backgroun...
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// //given BB_AB=13+(0/60) BB_BC=222+(30/60) BB_CD=200+(30/60) BB_DE=62+(45/60) BB_EA=147+(45/60) FB_AB=191+(45/60) FB_BC=39+(30/60) FB_CD=22+(15/60) FB_DE=242+(45/60) FB_EA=330+(15/60) //(a) interiorA=FB_AB-BB_EA interiorB=FB_BC-BB_AB exteriorC=BB_BC-FB_CD interiorC=360-(200+(15/60)) interiorD=FB_DE-BB_CD interio...
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\name DIGITAL_READ_SB \palette Arduino \smalldescription Allows to receive a logical value 0 or 1 on a given port. \description The Arduino board has a set of logical ports (digital) that are used for writing or reading data from a component. To map a UNO, ports 2-13 are available (0 and 1 are used for se...
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clc; clear; white_ball=3; red_ball=2; total=white_ball+red_ball; P_W=white_ball/total; P_SRFW=1/2; //Prob. of second red given first white P_FWSR=P_W *P_SRFW// prob. of first white and second red disp(P_FWSR," P(First Ball is White and second is red)=");
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clc //initialisation of variables i= 1/4500 w=3 //ft d= 3 //ft k= 0.003 g= 32.2 //ft/sec^2 //CALCULATIONS A= 0.5*%pi*d^2/4 P= %pi*d/2 m= A/P f= k*(1+(0.1/m)) C= sqrt(2*g/f) V= C*sqrt(m*i) Q= A*V //RESULTS printf ('Discharge= %.2f cuses',Q)
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pathname=get_absolute_file_path('3_13.sce') filename=pathname+filesep()+'3_13_data.sci' exec(filename) //Cutoff ratio rc=(p2/p1)^(1/y)/re //Temperature at the end of compression stroke(in K) T2=T1*(p2/p1)^((y-1)/y) //Temperature at the start of expansion stroke(in K) T3=T2*(rc) //Temperature at the end of expa...
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//water and its treatment// //example 2.18.31// clc Purity_Lime=.80 Purity_soda=.88 W1=84;//amount of MgCO3 in ppm// W2=25;//amount of SiO2 in ppm// W3=68;//amount of CaSO4 in ppm// W4=30;//amount of MgSO4 in ppm// W5=19;//amount of MgCl2 in ppm// W6=120;//amount of CaCO3 in ppm// M1=100/84.004;//multipl...
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clc; Pout=2; //watt Pin=0.0001; //watt ApdB=10*log10(Pout/Pin); disp('dB',ApdB,"ApdB=");//The answers vary due to round off error
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//chapter 6 //page no181 //Ex6_14 //given clear;clc; dV=50; //in mV di=4; //in Amp fL=120; //in kHz Lcable=dV*10^-3/di/2/%pi/fL/10^3; printf("\n The maximum allowed parasitic cable inductance (Lcable) must not exceed %0.1f nH",Lcable*10^9);
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// Exa 6.4 clc; clear; close; // Given data R1= 200;// in kohm R1=R1*10^3;// in ohm R2=R1;// in ohm C1= 200;// in pF C1= C1*10^-12;// in F C2=C1;// in F f= 1/(2*%pi*R1*C1);// in Hz disp(f*10^-3,"Frequency of oscilltions in kHz is : ") // Note: Calculation to find the value of f in the book is wrong, so a...
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function vpcGui() //Coneção com o Banco de bdVpcConect(); dimensaoTela = get(0, "screensize_px"); //Cria a Figura Principal mainFig = figure('layout', 'gridbag',...//plotGraph = createWindow(); 'closerequestfcn','vpcGuiClose',... 'toolbar', 'none',... ...
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exp7_31.sce
//example7.31 clc disp("As the impurity is accepter, it forms a p-type material.") disp("Therefore, N_A = 10^22 /m^3 = p_p") disp("Now, (p_p)*(n_p)=(n_i)^2 i.e. (10^22)*(n_p)=(1.4*10^16)^2") n=((1.4*10^16)^2)/(10^22) disp(n,"Therefore, n(in /m^3)= ") r=((1.96*0.145*10^10)+(0.05*10^22))*(1.6*10^-19) disp(r,...
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PiLab_flq.sci
// **** Purpose **** // PiLab Floquet Operator generator // **** variables **** // ==== << PiLab inputs >> ==== // [flq.Frequency]: 1x1 real // <= field frequency, // [flq.Order]: 1x1, int // <= order of photon process, // [flq.Amplitude]: 1x1 / 1x2 / 1x3, real // <= AC amplitude, // [flq.Phase]: 1x1 / 1x2 / 1x3, r...
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plotOptimizationFunction.sci
function plotOptimizationFunction() //Gerando o grafico da funcao a ser otimizada deff("[x1,x2,y]=rast(x1,x2)",["x1=x1";.. "x2=x2";.. "y = x1^2+x2^2-cos(12*x1)-cos(18*x2)"]); [x1x1,x2x2,yy]=eval3dp(rast,linspace(-1,1,100),linspace(-1,1,100)); clf();plot3d(x1x1,x2x2,yy) endfunction
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @output...
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exa1_3.sce
// Example 1.3 // Magnitude Manipulations P_max=20; // Maximum power rating of the device V_max=50; // Maximum voltage rating of the device in kV i_max=P_max/(V_max*10^3);// Maximum current that can be drawn from the device disp(P_max,"Maximum power rating of the device(in Watt)=") disp(V_max,"Maximum voltage rat...
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ex4_8.sce
// Exa 4.8 clc;clear;close; // Given data format('v',8) n = 4;// number of bit R = 1/(10^n); disp(R,"Part (i) : The resolution is"); // There are 5 digit places in 4 1/2 digits, so disp("Part (ii) : 11.87 would be displayed as 11.870") Reading= 0.5573; format('v',7) disp(Reading,"Part (iii) : On 1 V range, 0...
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//Ex:94 clc; clear; close; b_c=72;//carrier BW in MHz f_l1=2100;//first local oscillator frequency in MHz f_i=140;// first intermediate freq in MHz f_smx=11700;//max downlink freq spectrum in MHz f_smn=10700;//min downlink freq spectrum in MHz f_c=f_l1+f_i;//in MHZ f_l2mx=f_smx-f_c;// in MHz f_l2mn=f_smn-f_c...
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/tests/edgePreservingFilter/test9.sce~
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test9.sce~
//using flag RECURS_FILTER = 1 src = imread("../images/image_0197.jpg"); output = edgePreservingFilter(src,1,180, 0.6 ); imshow(output);
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5_10_Finite_Difference2_slab.sce
clear; clc; printf('FUNDAMENTALS OF HEAT AND MASS TRANSFER \n Incropera / Dewitt / Bergman / Lavine \n EXAMPLE 5.10 Page 311 \n'); //Example 5.10 // Using Explicit Finite Difference method, determine temperatures at the surface and 150 mm from the surface after an elapsed time of 2 min // Repeat the calculations ...
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ATWM1_Working_Memory_MEG_Salient_Cued_Run1.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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adiabatic.sce
// Adiabatic // Creates a model of an adiabatic plug-flow reactor // Reaction : A + E --> R // given the final conversion rate, and the thermodynamic and kinetic data // Author : Mathieu Besançon // UTC student // Process Engineering // Execute the enthalpy.sce first, which contains the enthalpy function ...
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Ex9_7.sce
//Tested on Windows 7 Ultimate 32-bit //Chapter 9 Frequency Response of Amplifier Pg no. 308 clear; clc; //Given VCC=12;//collector supply voltage in volts RE=1D3;//emitter resistance in ohms R1=47D3;//divider network resistance R1 in ohms R2=15D3;//divider network resistance R2 in ohms VBE=0.7;//forward v...
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3_13.sce
clear; clc; //Example - 3.13 //Page number - 99 printf("Example - 3.13 and Page number - 99\n\n"); //Given V = 36;//[L] - Vol of gas on each side P_1 = 1;//[atm] - pressure on left side of the piston P_1 = P_1*101325;//[Pa] T = 273.15;//[K] P_2 = 3.375;//[atm] - Pressure on right side of the piston P_2 = P_2*101325;/...
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Ex15_1.sce
//Caption:Determine the errors due to Rs and Rd //Ex15.1 clc; clear; close; Vs=1//Source voltage(in volts) Rs=100//Source resistance(in ohm) Rl=10//Load resistance(in kilo ohm) Rd=30//Drain resistance(in ohm) Vgs=10//Gate source voltage(in volts) V1=-(Vs+Vgs+1) Id=Vs/(Rs+Rd+Rl) e1=(Id*Rs)*100/(Vs) e2=(Id*R...
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Metodo_potencia_2.sce
function [lambda,x1,k,n_erro] = Metodo_potencia_2(A,x0,epsilon,M) k=1; x0=x0/norm(x0,2); x1=A*x0; while (k<=M) lambda = (x0')*x1; // Quociente de Rayleigh x0 é unitário x1 = x1/ norm(x1, 2); n_erro = norm(abs(x1) - abs(x0), 2); if (n_erro < epsilon) break; end x0 = x1 x1 = A*x0 ...
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14_11.sce
//Problem 14.11: //initializing the variables: P = 2; // in atm T1 = 373; // in K nA = 1; nB = 2.5; nC = 2; T2 = 273; // in K R = 1.987; v = 1 - 2 -1; //calculation: n = nA + nB + nC yA = nA/n yB = nB/n yC = nC/n K = (yC/(yB*yA^2))*P^v DG0273 = R*T2*log(K) printf("\n\nResult\n\n") printf("\n sta...
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Ex16_13.sce
// Example 16_13 clc;funcprot(0); // Given data p_os=3.00;// atm T_os=20.0;// °C p_B=1.00;// atm A_r=2.0;// The exit to throat area ratio fo r the nozzle k=1.4;// The specific heat ratio R=286;// m^2/(s^2.K) g_c=1;// The gravitational constant // Calculation p_a=p_os*(2/(k+1))^(k/(k-1));// atm // Since we...
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2019-11-24T20:15:20
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Add16CC.tst
load Add16CC.hdl, output-file Add16CC.out, compare-to Add16CC.cmp, output-list a%B1.16.1 b%B1.16.1 cin%B1.1.1 out%B1.16.1 cout%B1.1.1; set a %B0000000000000000, set b %B0000000000000000, set cin 0, eval, output; set a %B0000000000000000, set b %B0000000000000000, set cin 1, eval, output; set a %B000...
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//developed in windows XP operating system //platform Scilab 5.4.1 clc;clear; //example 6.6 //calculation of front and tail time //given data n=12//number of stages C=0.126*10^-6//capacitance(in Farad) R1=800//wavefront resistance(in ohm) R2=5000//xavetail resistance(in ohm) C2=1000*10^-12//load capacitance...
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//Choppers and Transportation System Application// //Example 13.5// f=200;//chopper frequency in HZ// E=220;//dc supply voltage in volts// Iav=100;//Average current in the circuit in amps// Ra=0.02;//Armature resistance in ohms// Rf=0.01;//Field resistance in ohms// Ebav=50;//Average value of the Back emf in vol...
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// tracer une ou plusieurs trajectoires de la marche de Bernoulli croissante // Paramètres : N = 1 // nombre de trajectoires T = 10^1 // longueur des trajectoires p =.5 // probabilité de succès q = 1-p // probabilité d'échec echBer = grand(N,T,"bin",1,p) // sauts marche = cumsum(echBer, "c") // trajectoires ...
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clc; clear; l=1.8 //distance between plates in cm E=3/2 //in V t=0.6*10^-3 //time taken by the pulse in s del_t=236*10^-6 //pulse width in s //Calculation vd=l/t //in cm/s myu_p=vd/E Dp=(del_t*l)^2/(16*t^3) mprintf("1)\nHole mobility= %i cm^2/Vs\n",myu_p) mprintf("2)\nDiffusion coefficient= %2.2f cm^2/s...
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// find output voltage // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 22-8, page 868 clear;clc; close; // Given data fin=10^3;// frequency in hertz` Vp=5;// peak voltage in volts C=10*10^-6;// capacitance in faraday R=10^3;// resist...
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clear; clc; printf("\t Example 2.26\n"); u=20*10^-6; //viscosity in Ns/m^2 pt=2666; //total pressure in N/m^2 pa1=pt; //pressure at 1 pa2=0; //pressure at 2 mw=32; //molecular weigh...
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clc; clear all; disp("Heat transfer rate") disp("k=k1+(k2-k1)*(t-t1)/(t2-t1)") disp("A=4*%pi*r^2") disp("Q=-k*4*%pi*r^2*dt/dr") disp("Q=-(k1+(k2-k1)*(t-t1)/(t2-t1))*4*%pi*r^2*dt/dr") disp("Q*dr/r^2 =-(k1+(k2-k1)*(t-t1)/(t2-t1))*4*%pi*dt ") disp("By integrating both sides in the limits r1 to r2 and t1 to t2, we ...
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clc clear //Initialization of variables x1=8.7 x2=8.9 x3=0.3 N=78.1 z=113 M=29 //calculations co2=(x1+x2+x3)*100/(N+x1+x2+x3) a=2.325 AF=103*M/(a*z) //results printf("Air fuel ratio = %.2f",AF)
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//Example 4_10 clc;funcprot(0); //Given data h=36;// m p=135;// kW q=0.44;// m^3/sec H=100;// m N=428;// r.p.m d_r=4;// d_r=D/d // Calculation w=1000*9.81;// N n=N*d_r*sqrt(h/H);// r.p.m n_m=(p*1000)/(1000*9.81*q*h);// The efficiency of the model n_p=n_m+0.03;//The efficiency of the prototype P=p*(n_p/n...
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mode(2);errcatch(-1,"stop");driver("GIF");//Example 15.40 //Nyquist plot clear; clc; s = %s/2/%pi; num=(1); den=(s^2+0.8*s+1); G=syslin('c',num,den) clf(); nyquist(G) xinit('/home/fossee/Downloads/tbc_graphs/Control_Engineering_-_Theory_And_Practice_M._N._Bandyopadhyay_1299/example15_40');xend(...
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// Scilab Code Ex5.33: Page:313 (2011) clc;clear; i = 60; // Angle of incidence, degrees mu = tand(i); // Brewester's Law to calculate refractive index A = 60;....// Angle of prism, degrees // As mu = sind((A+delta_m)/2)/sind(A/2), solving for delta_m delta_m = 2*asind(mu*sind(A/2))-A; // Angle of minimu...
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//Problem 24.10: A 240 V, 50 Hz voltage is applied across a series circuit comprising a coil of resistance 12 ohm and inductance 0.10 H, and 120 μF capacitor. Determine the current flowing in the circuit. //initializing the variables: R = 12; // in ohms L = 0.10; // in henry C = 120E-6; // in Farads f = 50; // ...
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//signals and systems //representation of a signal clear close clc t=[-2:0.1:5]; a=gca(); plot(t,2.*((t>=-1.5)&(t<0))+2*exp(-t/2).*((t>=0)&(t<3))); a.thickness=2; a.y_location="middle"; xtitle=('the signal x(t-1)') //this is a cobination of a constant function and an exponential function disp("x(t)=x1(t)+x2...
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clear clc Ia=10*exp(%i *30 *%pi/180) Ib=15*exp(%i *-60*%pi/180) Ic=0-(Ia+Ib) Iac=(Ia +Ia +Ib)/3 Icb=Ic +Iac Iba=Iac-Ia Ia0=(Ia +Ib +Ic)/3 a=exp(%i * 2 * %pi/3) Ia1=(Ia + a*Ib + a*a*Ic)/3 Ia2=(Ia + a*Ic + a*a*Ib)/3 disp(round(Ia1*100)/100, "Ia1","(a)Symmetrical Line Components") disp(round(Ia2*100...
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clc; clear; disp("f(x,y,z)=x^y^z+xy^z^+x^yz^"); disp("since interchanging any two variables gives us the same equation"); disp("for example interchange x and y"); disp("f(y,x,z)=y^x^z+yx^z^+y^xz^"); disp("f(x,y,z)=f(y,x,z)"); disp("So the function f(x,y,z) is symmetric");
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clc // producer's risk n = 71 // sample size AQL = 0.005 LTPD = 0.05 l_s = 500 // lot size z1 = n*AQL // mean number of defects pp1 = exp(-z1)+z1*exp(-z1) // poisson proability for 1 or less defective alpha = (1-pp1)*100 // producer's risk alpha = ceil(alpha) // consumer's risk z2 = n*LTPD // mean number of ...
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errcatch(-1,"stop");mode(2);//example 4.4, page 92 n=1.6 r1=.080//in cm r2=-0.080 P=(n-1)*((1/r1)-(1/r2)) printf("\n The power is %f D",P) exit();
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clear;lines(0); int8([1 -120 127 312]) uint8([1 -120 127 312]) x=int32(-200:100:400) int8(x)
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function %i_Matplot(z,varargin) xsetech([0 0 1 1]) strf='011' [N,M]=size(z) rect=[1 1 N M] // je fixe le cadre de l'image complete nax=[2 10 2 10] nv=size(varargin) if nv>=1 then strf=varargin(1),end if nv>=2 then rect=varargin(1),end if nv>=3 then nax=varargin(1),end if part(strf,2)<>'0' then //je dessine le cadre et ...
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//example 11 clear vbe=0.65;//volt colres=2*10^3;//ohm voltag=10;//volt i1=voltag/10; q=(1.65-vbe)/(1*10^3); disp("current = "+string((q))+"ampere");
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//Book - Power system: Analysisi & Design 5th Edition //Authors - J. Duncan Glover, Mulukutla S. Sarma, and Thomas J.Overbye //Chapter-9 ;Example 9.5 //Scilab Version - 6.0.0; OS - Windows clc; clear; Sb=100 //Base value of system in MVA Vb=13.8 ...
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// The equation x^3-5*x+1==0 has real roots. // the graph of this function can be observed here. xset('window',15); x=-2:.01:4; // defining the range of x. deff('[y]=...