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clc I=2*10^-3 disp("I = "+string(I)+" amphere") //initializing value of current flowing through the sample. B=1000*10^-4 disp("B= "+string(B)+" Tesla") //initializing value of magnetic field. w=0.2*10^-3 disp("w = "+string(w)+" mm") //initializing value of width of sample. l=2*10^-3 disp("l = "+string(l)+" m")...
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//Problem 4.07: //initializing the variables: mdt1 = 1000; // in lb/min mdt2 = 1000; // in lb/min mdt3 = 200; // in lb/min //calculation: mdt5 = mdt1 + mdt2 - mdt3 mdt6 = mdt2 mdt = mdt5 - mdt6 printf("\n\nResult\n\n") printf("\n amount of water lost by evaporation is %.0f lb/min",mdt)
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//chapter 16 Ex 4 clc; clear; close; //let pipes be A B and C t1=12; t2=15; //time taken by A and B to fill cistern individually t3=20; //time taken by waste pipe to empty the cistern A1min=1/t1; B1min=1/t2; //part filled by A and B in 1 min each ABC1min=1/t3; //part filled by all 3 pipes in 1 ...
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//CHAPTER 8 ILLUSRTATION 3 PAGE NO 223 //TITLE:BALANCING OF ROTATING MASSES pi=3.141 clc clear mA=200// mass of A in kg mB=300// mass of B in kg mC=400// mass of C in kg mD=200// mass of D in kg rA=80// radius of A in mm rB=70// radius of B in mm rC=60// radius of C ...
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clc; clear; Vm=3;// amplitude of message signal in V Vc=5;//amplitude of carrier signal in V m=Vm/Vc; //modulation index disp("modulation index"); disp(m,"="); disp("Upper Sideband Frequency(in MHz)"); Fm=4;//Frequency in KHz Fc=5;//Frequency in MHz disp(Fc+(Fm*10^(-3)),"="); disp("Lower Sideband Frequency(i...
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function drop_duplicates() // Return DataFrame with duplicate rows removed. // // Syntax // dfr.drop_duplicates(input_string) // // Parameters // input_string : String containing additional parameters supported can be passed // // For additional information on parameters, see https://pan...
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clc; close; t = 0:0.001:1; x = sin(2*%pi*5*t); L = 8; //quantization xmax = max(abs(x)); xq = x/xmax; en_code = xq; d = 2/L; q = d*[0:L-1]; q = q-((L-1)/2)*d; for i = 1:L xq(find(((q(i)-d/2)<= xq)&(xq<=(q(i)+d/2))))=q(i).*ones(1,length(find(((q(i)-d/2)<=xq)&(xq<=(q(i)+d/2))))); en_code(find(...
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clear; clc; D=20;Ro=500; N=10^(D/20); R1=Ro*(N-1)/(N+1); R2=Ro*(N+1)/(N-1); printf("The elements of the attenuator are:\n"); printf("R1 = %f ohms\n",round(R1*100)/100); printf(" R2 = %f ohms\n\n",round(R2*100)/100); r1=R1; r2=(R2-R1)/2; printf("The equivalent T structure of the designed lattice:\n"); printf...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 3.8w //calculation of total distance and number of trips //given data dcar=20//distance(in km) travelled by the car vcar=40//speed(in km/h) of the car vfly=100//speed(in km/h) of the fly //calculation tcar=dcar/v...
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PL/SQL Developer Test script 3.0 4 begin -- Call the function :result := get_frecuencia_ejercicio(pfrecuencia_ejercicio_id => :pfrecuencia_ejercicio_id); end; 2 result 1 1 vez por semana 5 pfrecuencia_ejercicio_id 1 1 4 0
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//ques28 syms s t f=integ(exp(-s*t)*exp(-t),t,0,2); disp('Laplace of given function is'); disp(f);
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a a m e r আ ম ে র a a n আ ন a b a z i l a আ ব া জ ি ল a b i r a আ ব ি র া a b i s s o আ ব ি স ো a b o আ ব ো a b u l k a m a l আ ব ু ল ক া ম া ল a c h h n e r a আ ছ ন ে র a c h r a আ চ র া a d a n i আ দ া ন ী a d a s আ দ শ a d h i r c h a n d r a অ ধ ী র চ ন ্ দ ্ র a d i t p a r a আ দ ি ৎ প া র া a g a i n s t এ গ ে ন ...
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function [out] = GeometricShearer(inputimage,direction,value) // Shear the image // // Calling Sequence // output_image = GeometricShearer(inputimage,direction,value); // // Parameters // // inputimage : image matrix on which geometric shear has to be applied // direction : An input string that like. 'Horizontal' to s...
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clear; clc; clf; c = ffilt("lp", 1000, 0.05); subplot(211); plot(c); [hm ,fr] = frmag(c,1,100); subplot(212); plot(fr,hm);
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// Updated(19-7-07) // 13.6 // Viscosity control problem of MacGregor A = [1 -0.44]; dA = 1; B = [0.51 1.21]; dB = 1; C = [1 -0.44]; dC = 1; k = 1; int1 = 1; F = [1 -1]; dF = 1; V = 1; W = 1; dV = 0; dW = 0; rho = 1; getf lqg.sci; [R1,dR1,Sc,dSc] = lqg(A,dA,B,dB,C,dC,k,rho,V,dV,W,dW,F,dF); [Nu,dNu,Du,dD...
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//Chapter 7: Solid State //Problem: 11 clc; mprintf("AB remain in BCC structure if the edge length is a then body diagonal ,is root(3)a\n") mprintf(" root(3)a = 2(r+ + r-)\n") A = (sqrt(3) * 0.4123 - 2 * 0.81) / 2 mprintf(" A+ = %.2f nm",A)
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function [AA, BB, Q, Z, V]=mtlb_qz(A,B) // Copyright INRIA [lhs,rhs]=argn(0) [AA, BB, Q, Z]=gschur(A,B) if lhs==5 then n=size(A,1) LA=diag(AA) LB=diag(BB) V=zeros(n,n) for k=1:n K=kernel(A*LB(k)-B*LA(k)) if size(K,2)<>1 then error('qz : pencil is not diagonalizable') end V(:,k)=K end e...
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function xint=bizinter(x) N=length(x); im = 0; if sum(abs(imag(x)))>0 im = 1; imx = imag(x); x = real(x); end; x2=x(:); x2=[x2.'; zeros(1,N)]; x2=x2(:); xf=fft(x2); if modulo(N,2)==1 //N = odd N1=fix(N/2+1); N2=2*N-fix(N/2)+1; xint=2*real(ifft([xf(1:N1); zeros(N,1) ;xf(N2:2*N)].')); el...
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//Section-1,Example-3,Page no.-AC.182 //To calculate the percentage of sulphur in the given coal sample. clc; W_BaSO4=0.01 W_coal=0.1 P_S=(W_BaSO4*32*100)/(W_coal*233) disp(P_S,'Percentage of sulphur in the given coal sample')
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//Tested on Windows 7 Ultimate 32-bit //Chapter 7 Field Effect Transistors Pg no. 241 clear; clc; //Given Data //Figure 7.31 gm=5D-3;//transconductance in Siemens RD=2.7D3;//drain resistance in ohms RL=3.3D3;//load resistance in ohms //Solution RL_eq=RD*RL/(RD+RL);//equivalent load resistance in ohms ...
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// example 1.18<c> //determine the values of power and energy clc ; t =0:0.01:100; A=1; x=A*cos (t); P=(integrate('(A*cos(t))^2','t',0,2*%pi ))/(2*%pi); disp(P,'The power of the signal is:'); E=(integrate('(A*cos(t))^2','t',0,2*%pi)); disp(E,'The energy is:'); disp('As t tends to infinity energy also tends to...
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// steady speed=10km/hr syms K Kg D (((A-10)*K1)-(-D*Kg))K=100; A=(60.8*10)/60; K=1.5; Kg=100; D=((100/K)-((A-10)*K))/Kg; disp(D,"Down slope=")
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PL/SQL Developer Test script 3.0 4 begin -- Call the function :result := get_color_pelo(pcolor_pelo_id => :pcolor_pelo_id); end; 2 result 1 Rubio 5 pcolor_pelo_id 1 1 4 0
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steps step condition True responses response sensors.SetSensor("Altitude", 10.0), response sensors.SetSensor("Heading", 0.0) response sensors.SetSensor("Roll", 0.0) response sensors.SetSensor("RollRate", 0.0) response sensors.SetSensor("Pitch", 0.0) response sensors.SetSensor("PitchRate", 0.0) response ...
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function [nt,dt,rk]=trzeros(Sl) //Transmission zeros of Sl = nt./dt // Syntax : [nt,dt]=trzeros(Sl) //! // Copyright INRIA [LHS,RHS]=argn(0); if type(Sl)==2 then D=Sl; [m,n]=size(D); if m<>n then error('Trzeros: Polynomial matrix--> must be square');return;end chis=det(D);nt=roots(chis);dt=ones(nt); if LHS...
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function s=%svlss(d1,s2) //s=%svlss(d1,s2) <=> s=d1/.s2 // origin s. steer inria 1987 [a2,b2,c2,d2,x2,dom2]=s2(2:7) e12=1/(eye+d2*d1) e21=eye-d1*e12*d2;b21=b2*e21 s=tlist(['lss','A','B','C','D','X0','dt'],a2-b21*d1*c2,b21*d1,... -e21*d1*c2,e21*d1,x2,dom2)
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 5 : INDUCTION MACHINES // EXAMPLE : 5.10 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA m = 3; // Total Number of phase in Induction...
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//example 8.9 //calculate streeses at heel and toe of dam clc;funcprot(0); //given c=1; hw=6; //heigth of water in reservior Bt=1.5; //width of top of dam H=6; //heigth of the dam wb=4.5; //width of base of dam Sg=2.4; //specific gravity of masonary gamma...
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// SAMPLE PROBLEM 3/23 clc;funcprot(0); // Given data m_1=0.050;// kg m_2=4;// kg v_1=600;// m/s v_2=12;// m/s theta=30;// degree // Calculation v_2=[(m_2*v_2*cosd(theta))/(m_1+m_2),((m_1*v_1)+(m_2*v_2*sind(theta)))/(m_1+m_2)];// m/s v_x=v_2(1);// m/s v_y=v_2(2);// m/s V_2=sqrt((v_x^2+v_y^2));// m/s thet...
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clc A=0.01; // m^2 L=0.3; // m N=60/60; // rps V_act=10.6/3600; // m^3/s rho=1000; // kg/m^3 g=9.81; // m/s^2 Q=10.6/3600; // m^3/s H=15; // m V=A*L*N; Cd=V_act/V; disp("Coefficient of discharge =") disp(Cd) P=rho*g*Q*H; disp("The power required =") disp(P) disp("W")
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/////////////////////////////////////////////////////////////////////////////// // // // MONITEUR D'ENCHAINEMENT POUR LE CALCUL DE L'EQUILIBRE D'UN RESEAU D'EAU // // // ...
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//Example 1_33 clc; clear; close; format('v',5); //given data : V1=12;//V R1=3;//ohm R2=3;//ohm I2=6;//A //Converting currrent sources into Voltage sources V2=I2*R2;//V //writing KVL equation for the loop I=poly(0,'I'); eqn=V1-R1*I-R2*I-V2;//KVL equation I=roots(eqn);//A VOC=V2+R2*I;//V Req=R1*R2/(R1+R...
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// problem 7.16 Q=10 V=2 A=Q/V n=1 d=(A/1.828)^0.5 b=0.828*d A1=(b+(2*d*((n*n+1)^0.5))) disp(A1,"area in m2 of lining required for 1m canal lenght")
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//chapter 1 //example 1.5 //page 28 printf("\n") printf("given") I0=30;Vd=.7;n=2;Vt=26*10^-3; k=Vd/(n*Vt); disp("junction current") Id=I0*((2.7^k)-1)*10^-6 printf(" forward bais current is %dmA\n",Id) disp("b)") Vd=-10// reverse bais k=Vd/(n*Vt); Id=I0*((2.7^k)-1) printf(" forward bais current is %dnA\n",...
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//chapter 18 //example 18.4 //page 766 printf("\n") printf("given") hFE3=50;hFE1=20;Ie1=200*10^-3+10*10^-3;Ic2=1*01^-3;Vs=20;Vb3=13.4;Vo=12;Vbe=.7; Ib1=Ie1/hFE1 Ib3=Ib1/hFE3 R1=(Vs-Vb3)/(Ic2+Ib3) disp("select I6=.5*10^-3") I6=.5*10^-3; R6=(Vo+Vbe)/I6 Pd=(Vs-Vo)*Ie1
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//(4.5) Air enters a compressor operating at steady state at a pressure of 1 bar, a temperature of 290 K, and a velocity of 6 m/s through an inlet with an area of 0.1 m2. At the exit, the pressure is 7 bar, the temperature is 450 K, and the velocity is 2 m/s. Heat transfer from the compressor to its surroundings occu...
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// Problem 8.6,Page no.209 clc;clear; close; W=200 //N //weight v=4 //m/s //velocity of spring sigma=600 //MPa //max allowable stress in spring G=80 //GPa //Modulus of rigidity rho=78000 //N/m**3 //density d=8 //mm //diameter of spring D=5 //cm //Mean Diameter of coil //Calculation E=W*v**2*(2*9.81)**-1 //N*m //...
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Dataset before extension: [ 0 -1 -2 -3 -4 -5 -6] [ 0 0 0 0 0 0 0] [ 0 1 2 3 4 5 6] [ 0 2 4 6 8 10 12] Dataset after extension: [ 0 -1 -2 -3 -4 -5 -6 7 8 9] [ 0 0 0 0 0 0 0 7 8 9] [ 0 1 2 3 4 5 6 7 8 9] [ 0 ...
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// Negation of vector elements function vneg(V) R = -V; endfunction
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ns=1000 s=(ns-940)/ns news=2*s n=1000*(1-news) disp(n)
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// Theory and Problems of Thermodynamics // Chapter 9 // Air_water Vapor Mixtures // Example 10 clear ;clc; //Given data RH = 0.6 // relative humidity moist air T1 = 313.15 // Temp of air entering cooling device in K T2 = 293.15 // temperature at air required to leav...
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// Scilab Code Ex3.1 : Page-71 (2010) beta = 0.51e-02; // Fringe width, cm d = 2.2e-02; // Distance between the slits, cm D = 2e+02; // Distance between the slits and the screen, cm // As beta = D*lambda/d, solving for lambda lambda = beta*d/D; // Wavelength of light, m printf("\nThe wavelength of ...
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//Example 24_2 clc(); clear; //To find by how much does thickness of air gap increases lamda=589 //units in nm gap=round(lamda/2) //units in nm printf("The thickness of air gap increases by=%d nm",gap)
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clc //initialisation of variables g= 32.2 //ft/sec^2 D= 9 //in //CALCULATIONS d= D/(2^0.4) //RESULTS printf ('diameter of paralle mains = %.2f in ',d)
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errcatch(-1,"stop");mode(2);//Example 21.1 ; V_max=200//in V V_rms=(V_max)/sqrt(2) R=100//in ohm I_rms=V_rms/R disp(V_rms,"Voltage in V=") disp(I_rms,"Current in Amps=") exit();
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clc //Chapter 5:High Frequency amplifiers and automatic gain control //Example 5.14 page no 189 //Example on voltage to current feedback gm=0.4//transconductance RL=600//load resistance Rs=500//source resistance (refer figure 5.54) disp('Av=-gm*RL/(1+gf*RL+gm*RL*(Rs/RF))')//Voltage gain disp('GB=Av*B') disp('...
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errcatch(-1,"stop");mode(2); //Initialization of variables g=9.81 //kN/m^3 V2=12 //m/s V3=12 //m/s A2=10^2 A1=15^2 A3=7.5^2 t1=15 t2=30 //calculations V1=(A2*V2 + A3*V3)/A1 Q1=%pi /4 *A1*10^-4 *V1 Q2=%pi /4 *A2*10^-4 *V2 Q3=%pi /4 *A3*10^-4 *V3 P1g=V3^2 /(2*g) - V1^2 /(2*g) P1=P1g*g rho=10^3 V2x=V2*...
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//check o/p when i/p is a vector u = int8([-1 1 2 -5]); y = udecode(u,3); disp(y); //output //- 0.25 0.25 0.5 - 1.
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function arduino = open_source(port, configs) // Description of open_source(input) try disp("Abriendo el puerto " + string(port) + " con la configuración: " + configs) arduino = openserial(port, configs) catch disp(lasterror()) disp("Error al abrir la comunicación serial, utiliza...
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function [mod,fase]=polar2(z) mod = abs(z) fase = atan(imag(z),real(z)) endfunction function [mod,fase]=polard(z) mod = abs(z) fase = atand(imag(z),real(z)) endfunction
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// Updated(19-7-07) // 14.1 // A,B are available from code 2.1 getf pol2cart.sci; C = eye(4,4); D = zeros(4,1); Ts = 0.01; G = syslin('c',A,B,C,D); H = dscr(G,Ts); [a,b,c,d] = H(2:5); rise = 5; epsilon = 0.1; N = rise/Ts; omega = %pi/2/N; r = epsilon^(omega/%pi); r1 = r; r2 = 0.9*r; [x1,y1] = pol2cart(omega,r1); [x2,...
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//Chapter 8 //Example 8_27 //Page 196 clear;clc; c=8; l=300; s=10; slope=15; printf("On level ground: \n") wbyt=8*s/l^2; h=s+c; printf("Height of tower = %d m \n\n", h); printf("On sloping ground: \n"); hs=l/slope; printf("Vertical distance between two towers = %d m \n", hs); x1=75; x2=225; printf("From the graph: ...
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// Example 1.2 Find the velocity of charge leading to 1 A current which flows in a copper conductor of cross-section 1 cm^2 and length 10 Km. Free electron density of copper = 8.5X10^28 per m^3. How long will it take the electric charge to travel from one end of the conductor to the other. // 1 metre = 100 centimetre...
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// to determine the raise time displayed waveform // example9-13 in page 279 clc; // Data given fH=[20e+6 50e+6];// upper cut-off frequency in hertz tri=21D-9;// input raise time in seconds // calculation for n=1:2 tro=0.35/fH(n);// tro is the raise time in seconds trd=sqrt(tri^2+tro^2);// trd is the ...
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; get-value after an assertion set command (set-option :produce-models true) (set-logic QF_UF) (declare-fun x () Bool) (assert true) (check-sat) ; sat (push 1) (get-value (x)) ; invalid because of the push
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// // printf("\n section 1') b=10,n=5,s=1,s1=2, d=50,h1=0.5,h2=0.7, ac=0.5*(((0.5*b+n*h1)*(0.5*b+n*h1))/(n-s)) af=0.5*(((0.5*b-n*h1)*(0.5*b-n*h1))/(n-s1)) printf("\n ac=%0.3f,af=%0.3f",ac,af) printf("\n section 2') ac1=0.5*(((0.5*b+n*h2)*(0.5*b+n*h2))/(n-s)) af1=0.5*(((0.5*b-n*h2)*(0.5*b-n*h2))/(n-s1)) D...
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tpyrun $p/bin/util/markdown_test
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clc T1_ = 80 // Initial temperature of air in degree Celsius T2_ = 5 // Final temperature of air in degree Celsius V2 = 2 // Assumed final volume V1 = 1 // Assumed initial volume P0 = 100 // Final pressure of air in kPa P1 = 500 // Initial pressure of air in kPa R = 0.287 // Gas constant cv = 0.718 // Specifi...
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example12_12.sce
//clc() //1 - N2, 2 - H2, 3 - NH3 a1 = 27.31; a2 = 29.09; a3 = 25.48; b1 = 5.2335*10^-3; b2 = -8.374*10^-4; b3 = 36.89 * 10^-3; c1 = -4.1868 * 10^-9; c2 = 2.0139*10^-6; c3 = -6.305*10^-6; H1 = -46191;//J T1 = 298;//K //1/2 N2 + 3/2 H2 = NH3 H = -46.191kJ //Ht = H + a*T + b*T^2 / 2+ c*T^3 / 3...
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//Example 5.10 clc; clear; close; format('v',8); //Given data : Q=200*10^-3;//m^3/s D1=250/1000;//meter D2=200/1000;//meter A1=%pi*D1^2/4;//m^2 A2=%pi*D2^2/4;//m^2 v1=Q/A1;//m/s v2=Q/A2;//m/s Z1=2;//meter Z2=8;//meter g=9.81;//constant w=1000;//kg/m^3 p1=w*(Z1-v1^2/2/g);//kg/m^2 p2=v1^2/2/g*w+p1+Z2*w-...
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//Example 3.3 // Thickness of doubly refracting crystal clc; clear; //given data : Uo=1.55;//refractive index for O ray Ue=1.54;//refractive index for E ray w=6D-7;// wavelength of light used in m p=w/2;// path difference in m t=w/(2*(Uo-Ue));//thickness of in m disp(t*1D2,"thickness of doubly refracting crys...
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//Example 3.11 //Program to compare the total first order dispersion and determine //waveguide dispersion clear; clc ; close ; //Given data lambda0=1310; //nm - ZERO DISPERSION WAVELENGTH So=0.09*10^(-12); //s/nm^2/km - DISPERSION SLOPE //Dt at 1280nm lambda1=1280; //nm - OPE...
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AdrienTP4.sce
P1=[1 3]; P2=[-1 2]; P3=[2 -1]; Ps=[P1;P2;P3]; function interpol(Ps) xdata= [-2:.1:3]; nbrPs= size(Ps, 1); X=[]; Y=[]; for i=1:1:nbrPs Y= [Y;Ps(i,2)]; end for i=1:1:nbrPs pi=[] for expo=1:1:nbrPs-1 pi=[pi,Ps(i,1)^expo]; ...
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// exercice 1 scilab // 1. a) l = (sqrt(5)-1)/2; n1 = 10; u1 = zeros(n, 1); u1(1) = 1; for i = 1:n1-1 u1(i+1) = 1 / (1 + u1(i)); end l u1 // 1. b) sigma = 2^-52; i = 1; u2 = i; u2 = [u2; 1/(1+u2(i))]; while abs(u2(i+1)-u2(i)) > sigma n2 = i; i = i + 1; u2 = [u2; 1/(1+u2(i))]; end [sigma n2] u2 //...
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ex_3_75.sce
//Example 3.75:iron loss clc; clear; close; r2=18;//ohm r4=550;//ohm r3=1250;//ohm r1=(r2*r4)/r3;//ohm c3=0.5;//micro-F l1=r2*r4*c3*10^-3;//mH r4=550;//ohm r31=1125;//ohm r11=(r2*r4)/r31;//ohm c31=3.85;//micro-F l11=r2*r4*c31*10^-3;//mH v=50;//volts w=4000;//rad/s i1=v/(sqrt((r1+r11)^2+(w^2*(l11*10^-3)^2)));// tl=i1^2*...
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7_2.sce
clc //initialisation of variables L= 203 //mm A= 10.3 //cm^2 a= 0.39 //cm^2 h0= 508 //mm h180= 305 //mm t= 180 //sec //calculations k= 2.303*a*L*log10(h0/h180)/(A*t) //results printf ('hydraulic conductivity of sand = % 2f in/sec ',k)
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// Exa 6.6 // To calculate frame efficiency and the number of channels per frame. clc; clear all; Nr=2;// number of reference bursts per frame Nt=24; // number of traffic bursts (slots) per frame(120msec) FL=120; //Frame length in msec Br=148; // number of overhead bits per reference burst Bp=34; // number...
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12_5.sce
clear; clc; //Example - 12.5 //Page number - 426 printf("Example - 12.5 and Page number - 426\n\n"); //Given T = 40 + 273.15;//[K] - Temperature x1=[0.083,0.176,0.268,0.353,0.428,0.720,0.780,0.850,0.900];// Mole fraction of component 1 delta_H_mix=[0.250,0.488,0.670,0.790,0.863,0.775,0.669,0.510,0.362];//...
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clear; clc; close; x=poly(0,'x'); p1=(3*x+7); p2=(2*x+1); p3=p1*p2; disp(p3,"product=")
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// Example 2.60:hybrid parameters clc; clear; Ic= 10; //in milli amperes Vt=26;//volatge ft=500;//frequency in mega hertz Cbc=3;//in pico farad gm=Ic/Vt;//transconductance //H Paramters are hie=500;//in killo ohms hfe=100; hre=0.1;// hoe=4*10^-5;// in ampere per volt rbe=hfe/gm;// in ohms rbc= ((rbe)/hre)*10^-3;// x=h...
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//scilab 5.4.1 //windows 7 operating system //chapter 5:Semiconductor Junction Diodes clc clear V=35//V=supply voltage Iz=25*10^(-3)//Iz=diode current Il=5*10^(-3)//Il=load current Vzo=7//Vzo=knee voltage of zener diode rZ=6//rZ=dynamic resistance in ohms Vz=Vzo+(rZ*Iz)//Vz=zener voltage disp("V",Vz,"Vz=") ...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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r= 2.4; //distance between centre of the protons, fm r= r*(10^(-15)); //converting to m e= 1.6*(10^(-19)); //charge of an electron, C Po= 8.85*(10^(-12)); //Permittivity of free space, F/m K=1/(4*(%pi)*Po); //constant, N.m^2/C^2 F= K*(e^2)/(r^2); //N disp(F,"The repulsive force, in N, is: ") //Result // Th...
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w=2 L=1 C=0.5 Xl=w*L*%i Xc=1/(w*C*%i) V=1 I=V/(1+%i) Y=I/V R=1/real(Y) disp(R,Y)
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clear // L=20//cm2 t0=20//kg/cm2 p0=5//per degree C pm=16//kg tm=32//degree C a=0.03//cm2 al=11/(1000000)//per degree C E=2.1*(1000000)//cm2 w=0.6//kg ml=680//m n=1 ct=al*L*(tm-t0) printf("\n the temperature correction is %0.5f meters',ct) cp=(pm-p0)*L/(a*E) printf("\n the pull correction is %0.5f meters',cp) ...
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//Chapter 24 clc //Example 5 //given n=1.6 //refractive index of plastic transparent layer lambda=780 //wavelength of laser light in nm //for destructive interference we have condition for minimn thickness 2t=lambda/2n t=lambda/(4*n) disp(t,"Pit depth in a CD in nm is")
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//chapter28 //example28.5 //page598 disp(" A B A` Y_dash = A`. B B` Y = Y_dash + B` ") disp(" 0 0 1 0 1 1 ") disp(" 1 0 0 0 1 1 ") disp(" 0 1 1 1 0 1 ") disp(" 1 ...
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//Section-1,Example-2,Page no.AC-242 //To calculate Temporary hardness of given sample of water. clc; V_1=25 //Volume of EDTA solution reqd. by 20 ml of standard hard water. V_2=100 //Volume of water sample that requires 18 ml EDTA. E_1=300/V_1 //weight of CaCO3 in 1mL of EDTA(mg). Total_H=E_1*18*(1000/V_2) ...
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//pathname=get_absolute_file_path('11.15.sce') //filename=pathname+filesep()+'11.15-data.sci' //exec(filename) //Atmospheric air temperature: 15C //Steam generation: 40 bar, 400C //Steam generated per kg of coal = 8 kg //Feed water temperature at inlet to economiser = 27C //Feed water temperature at exit of econ...
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Name=QC Combo PlayerCharacters=QC-Quaker RL KB BotCharacters=Quaker Bot Passive.bot IsChallenge=true Timelimit=300.0 PlayerProfile=QC-Quaker RL KB AddedBots=Quaker Bot Passive.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=pool.map MapScale=3.8125 BlockProjectilePredictors=false BlockC...
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function L=cholesky (A,n) L=zeros(n,n); for k=1:1:n S=0; P=0; for j=1:1:k-1 S=S+(L(k,j)^2); P=P+L(i,j)*L(k,j) end L(k,k)=sqrt(A(k,k)-S); for i=k+1:1:n L(i,k)=(A(i,k)-P)/L(k,k); end end endfunction
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clc clear //Initialization of variables ma=500 //kg/h cp1=3.2 //kJ/kg K ta=20 //C mb=200 mc=300 //kg/h cp2=2.8 //kJ/kg K tc=80 //C tb=80 //C me=50 //kg/h te=120 //C td=120 //C hg=503.7 he=2706.3 //calcualtions Ws=(mb+me)*hg + mc*cp2*(tc) - me*he -ma*cp1*(ta) //results printf("Net work done = %d kJ/h"...
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//Example 15.3 Q_h=2.5*10^14;//Heat transfer from coal (J) Q_c=1.48*10^14;//Heat transfer into the environment (J) W=Q_h-Q_c;//Work done (J) printf('a.Work done by the power station = %0.2e J',W) Eff=W/Q_h;//Efficiency printf('\nb.Efficiency of the power station = %0.3f or %0.1f%%',Eff,Eff*100) q=2.5*10^6;//Heat...
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clc //initialisation of variables R= 0.082 //l-atm deg^-1 mole^-1 T= 25 //C V= 85*10^-6 //l-atm g^-1 //CALCULATIONS M= R*(273+T)/V //RESULTS printf ('average molecular weight of this polystrene = %.f g mole^-1',M)
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// Exa 1.5 clc; clear; close; // Given data B_h = 755;// Barometric height in mm M_h= 240;// Manometer height in mm P = B_h+M_h;// in mm P = P/750;// absolute pressure in bar P= P*10^5;// in N/m^2 disp(P*10^-6,"The absolute pressure in the vessel in MN/m^2 is"); disp(P*10^-5,"The absolute pressure in the ve...
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//To find velocity and resisting torque clc //Given: NAD=100 //rpm TA=50 //N-m DA=300/1000,CB=360/1000,AB=CB,DC=600/1000 //m eta=70/100 //% //Solution: //Refer Fig. 7.25 //Calculating the angular velocity of the crank AD omegaAD=2*%pi*NAD/60 //rad/s //Calculating the velocity of A with respect to D vAD=omeg...
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//Chapter 5 //Example 5-4 //ProbOnZenerCurrentAndVoltage //Page 125,126, Figure 5-3(a) clear;clc; //Given Vo = 10.3 ; //Voltage across the load resistor Ei = 5 ; //Input voltage Ri = 1*10^3 ; //Input Resistance //Example 5-4(a) I = Ei / Ri ; //Zener Current printf ( "\n\n Zener Current = %.4f A", I ) //Exa...
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// Nessa funcao assumo que os valores em p0 sao em unidades (1000000) e nao em milhoes (1) function [] = crescPop (p0, k) a = gca() // a.isoview = "on"; // preciso quebrar a simetria entre os eixos de modo que apareçam 30 unidades em X e um numero potencialmente muito alto em Y L = [ 0, 0, 45 ; ...
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@relation ecoli @attribute Mcg real [0.0, 89.0] @attribute Gvh real [1.0, 88.0] @attribute Lip real [1.0, 48.0] @attribute Chg real [1.0, 5.0] @attribute Aac real [0.0, 88.0] @attribute Alm1 real [1.0, 94.0] @attribute Alm2 real [0.0, 99.0] @attribute Site {cp, im, imS, imL, imU, om, omL, pp} @data cp pp cp cp cp cp ...
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//Example 4_9 clc;funcprot(0); //Given data Q=30;//m^/sec H=7.5;// m n_t=0.85; N=50;///r.p.m Sr=0.85;//Speed ratio g=9.81;//The acceleration due to gravity in m/s^2 //Calculation w=1000*9.81;// N P_t=(w*Q*H*n_t)/1000;// kW N_s=(N*sqrt(P_t))/(H)^(5/4);//Specific speed if(N_s>=174) printf('\n (a)As N_...
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//Chapter 15, Problem 16, Fig 15.16 clc; V=40; //supply voltage f=20e3; //supply frequency R1=8; //resistance in ohm L=130e-6; //inductance in henry R2=5; //resistance i...
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//Page Number: 498 //Example 9.19 clc; //Given n=0.1; Vdc=100; //V Idc=0.9; //A t=0.01D-9; //s f=16D+9; //Hz //(i)Power output Pdc=Vdc*Idc; Pout=n*Pdc; disp('W',Pout,'Power output:'); //(ii)Duty cycle D=(t/2)+(1/(2*f)); disp('s',D,'Duty cycle:');
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//fiber optic communications by joseph c. palais //example 12.2 //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given //from example 12.1 lambda=0.82//wavelength in um ER=10^-9//Error rate datarate=100//dta rate for RZ system in Mbps NRZ_Qpl=-63//powerl level for NRZ in dBm NRZ_TL=-36//thermal l...
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funcprot(0) test_cases = list() test_cases($+1) = struct('input', struct('pizzas', [5], 'bonnen', [0,1]), 'output', struct('prijs', 0)) test_cases($+1) = struct('input', struct('pizzas', [5,2,1], 'bonnen', [0,1]), 'output', struct('prijs', 3)) test_cases($+1) = struct('input', struct('pizzas', [5,2,1], 'bonnen', [1,1])...
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//chapter3 //example3.2 //page49 mu=20 rp=8000 // ohm gm=mu/rp // since mu=rp*gm gm_micro=gm*10^6 //micro mho printf("mutual conductance of triode = %f mho or %.3f micro mho",gm,gm_micro)