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//Example 11_1 clc(); clear; //To find out how much heat is required to change the temperature //With 400 Grams of water c=1 //units in cal/g Centigrade m=400 //Units in gm t=5 //Units in centigrade q=c*m*t //Units in Cal printf("The heat required for 400 gm of water is Q=%d Cal\n",q) //With 400 g...
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clc clear //INPUT DATA r=1.246*10^-10//atomic radius of Fcc crystal in m h1=1//miller indices with respect to x axis in 1st plane k1=1//miller indices with respect to y axis in 1st plane l1=1//miller indices with respect to z axis in 1st plane h2=2//miller indices with respect to x axis in 2nd plane k2=0//mille...
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f=50 w=2*%pi*f P=2E6 V=11000 pf=0.8 phi=acos(pf) Xl=10 IR=P/sqrt(3)/V/pf Vr=V/sqrt(3) Vs=Vr+IR*Xl*sin(phi) Vsll=Vs*sqrt(3) disp(Vsll) VR=Vsll/V-1 disp(VR) pf=1 disp(pf) Qc=P*tan(phi) C=Qc/V/V/w disp(C)
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clear; clc; printf("\t\t\tProblem Number 6.11\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.11 (page no. 253) // Solution T2=500+460; //absolute final temperature //unit:R T1=80+460; //absolute initial temperature //unit:R //cp=0.219 + (3.42*10^-5*T) - (2.93*10^-9*T^2); //Unit:Btu/lbm*R //Comparing w...
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T1 = 363; T2 = 293; W = 1; // Kj/s e_max = 1-(T2/T1); Qmin = W/e_max ; Qmin_ = Qmin*3600; E = 1880; // in kJ/m2 h Amin = Qmin_/E ; disp("m2",Amin,"Minimum area required for the collector plate")
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a + b > 0 ; vgcd=1; gcd=1; isZero=false; hasVariable=true; isBiased=true; mergeVariables=2*x_y_z > 0; relation=GT_0 ; evaluate=failure biased /01;1 -> a + b
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<?xml version="1.0" encoding="utf-8" ?> <test> <description>Kovasznay Flow variable P, periodic BC (parallel)</description> <executable>IncNavierStokesSolver</executable> <parameters>--use-scotch -I GlobalSysSoln=XxtMultiLevelStaticCond KovaFlow_varP_per.xml</parameters> <processes>2</processes> <fi...
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clc // Given that D = 120 // Distance between eyepiece and screen in cm d = 0.075 // DISTANCE BETWEEN TWO VIRTUAL COHERENT SOURCE in cm x = 1.888 // Distance of 20th bright fringe from center in cm n = 20 // Number of fringes // Sample Problem 15 on page no. 99 printf("\n # PROBLEM 15 # \n") printf("\n Sta...
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//1 kilometer = 0.621371192 miles k=0.621371192; D_cm=29*2.54 U_cm=D_cm*%pi v_kmh=[0:50]'; //km/h v_mph=v_kmh*k; //miles/h v_cms = v_kmh*1e3*100/3600; f_hz=v_cms/U_cm; scf(1) clf(1) plot2d(v_kmh,[f_hz f_hz*k]) xtitle('Speedsensor','km/h','Hz')
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//Example 2.6 page 29 //Given the DSP system shown in Figure 2.16, where a sampling rate of //40,000 Hz is used, the anti-aliasing filter is a Butterworth lowpass filter //with a cutoff frequency of 8 kHz, and the percentage of aliasing level at the //cutoff frequency is required to be less than 1%, determine the order...
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clc; //page 13 //ex-1.8 G1=5000; L=2000; G2=400; G=G1*(1/L)*G2; //Absolute gain disp(G,'(a) Net absolute gain is:'); GdB=10*log10(G); //System decibell gain disp('dB',GdB,+'(b) System Decibel gain is:'); G1dB=10*log10(G1); LdB=10*log10(L); G2dB=10*log10(G2); disp('(c) Individual stage gains are:...
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// Example 7.33:Design R-C phase shift oscillator clc; clear; close; rd=40;//resistane in killo ohms fo=1//resonant frequency in killo hertz gm= 5000;//in killo mh R=10;;//assume Resistance in killo ohms C=((1/(2*%pi*fo*10^3*R*10^3*sqrt(6)))*10^9);//C in nano farad Av=29;//VOLTAGE GAIN Vdd=12;//drain voltage ...
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//Ex 6.6 clc; clear; close; format('v',6); //Data given R1=1;//kohm R2=1;//kohm R=1;//kohm C=4.7;//micro F f0=1/(2*%pi*R*10^3*C*10^-6);//Hz//Oscillating Frequency disp(f0,"Oscillation frequency(Hz)");
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clear() A = [[-3,1,0];[2,-3,2];[0,1,-3]]; dt = 0.1 phi = expm(A*dt); vetor_tempo = 0:dt:10; X = [zeros(vetor_tempo); zeros(vetor_tempo); zeros(vetor_tempo)]; X(1,1) = 3.7; X(2,1) = 1.2; X(3,1) = 2.6; m=size(vetor_tempo); n=m(2); for i = 1:n-1 X(:,i+1) = phi*X(:,i); end; clf() //scf(0) //plot(vetor_tempo, X(1...
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//Chapter 10 //Example 10.2 //page no 390 //To draw sequence networks of the system clear;clc; //selecting generator rating as base in generator circuit mvab=25; kvGb=11; //base voltage for generator kvTLb=kvGb*(121/10.8); //base voltage for TL kvMb=kvTLb*(10.8/121); //base voltage for motors xG=%i*0.2; xT=%i*0.1; ...
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mode(2);errcatch(-1,"stop");driver("GIF");// from the nyquist plot N=-2; // no of encirclements P=0; // given Z=P-N printf("Since Z=2 therefore two roots of the characteristic equation lies in the right half of s-plane,hence the system is unstable") xinit('/home/fossee/Downloads/tbc_graphs/Control_Systems_Eng...
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// Copyright (c) 2017, Linz Center of Mechatronics GmbH (LCM) http://www.lcm.at/ // All rights reserved. // // This file is licensed according to the BSD 3-clause license as follows: // // Redistribution and use in source and binary forms, with or without // modification, are permitted provided that the followin...
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clc;clear; //Example 1.5 //given values Patm=14.5; Pvac=5.8; //calculation Pabs=Patm-Pvac;//pressure in vaccumm is always treated to be negative disp(Pabs,'the absolute pressure in the chamber in psi is')
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.302871D+00 ...
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//Caption: Probability //Example 2.1.a //page no 43 //Find the Probability clc; clear; redballs=3; whiteballs=4; blackballs=5; //P=ways of choosing a red ball/Total no. of ways choosing a ball Pro=redballs/(redballs+whiteballs+blackballs); disp("Probability Getting red ball is"); disp(Pro,"P(R)=");
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Ex_9_19_b.sce
// Example 9.19.a;//OPTICAL POWER clc; clear; close; Ip=10^-6;//optical current in ampere e=1.6*10^-19;//elecronic charge C=3*10^8;//SPEED of light in meter per second n=0.50;//quantum efficiency h=0.9;//wavelength in nano meter ht=6.62*10^-34;//plank constt. R=((n*e*h*10^-6)/(ht*C));//responsivity Po=(Ip/R)...
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clear function y=f(t,u) y=u*t endfunction function y=ft(t,u) y=(u*t)*t+u endfunction function y=ftt(t,u) y=(u*t^3)+2*u*t+u*t endfunction a = 0.1 T = 2 h = 0.1 u(1)=a; //cond inicial t(1)=1; N=(T-t(1))/h for n=1:N t(n+1)=t(n)+h; F=f(t(n),u(n)); Ft=ft(t(n),u(n)) Ftt=ftt(t...
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clc;clear; //Example 9.8 //given data T1=300; T6=1300; r=8;//overall compression ratio //calculations //as it is case of intercoolimg ri=sqrt(r);//ri stands for P2/P1 = P4/P3 = P6/P7 = P8/P9 //from A-17 at T1 h1=300.19; Pr1=1.386; Pr2=ri*Pr1; //from A-17 at Pr2 T2=403.3; h2=403.31; //from A-17 at T6...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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ex9_7.sce
// Example 9.7 format('v',6) clc; clear; close; // given data I_CQ= 5*10^-3;// in A R_C= 1*10^3;// in Ω R_L= 1*10^3;// in Ω // The load resistance r_L= R_C*R_L/(R_C+R_L);// in Ω // The ac compliance, PP= 2*I_CQ*r_L;// in V I_CQ= 5.15*10^-3;// in A PP= 2*I_CQ*r_L;// in V disp(PP,"The ac compliance in volt...
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straightlineapprox.sce
function [P]=straightlineapprox(x,f) n=length(x);m=length(f); if m<>n then error('linreg - Vectors x and f are not of the same length.'); abort; end; s=0; for i=1:n s=s+x(i)*f(i); end c0=det([sum(f) sum(x); s sum(x^2)])/det([n sum(x);sum(x) sum(x^2)]); c1=det([ n sum(f); sum(x) s])/det([n sum(x)...
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clc //initialisation of variables Cd= 0.8 g= 32.2 //ft/sec^2 d= 3 //in //CALCULATIONS t= (60*2/(%pi*(d/12)^2*sqrt(2*g)/4*Cd))*(6-d)^(3/2)/(3*60/2) //RESULTS printf ('time to emptify biler = %.2f min',t)
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 4.10.2\n') //given data m=75//mass of machine in kg K=11.76*10^5//stiffness of springs in N/m zeta=0.2 mo=2//mass of piston in kg stroke=0.08//in m e=stroke/2//in m N=3000//spee in c.p.m //calculations Wn=sqrt(K/m) W=2*%pi*N/60 bet=(W/Wn) y...
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clc; clear all; V = 1000; // Volume of hall in cubic meter s = 400; // Surface area of hall in square meters a = 0.2; // Average absorption coefficient of hall in sabine T = (0.163*V)/(a*s);//'Reverberation time of hall disp('s',T,'Reverberation time of hall is') // there is slight variation in the answer.. the...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.22w //calculation of object distance from the lens with one side silvered //given data v=-25; //image distance (in cm) R=25; //radius of curvature of the spherical convex surface (in cm) mu1=1; //refractive index ...
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function a=df1(x,y,z) a=z; endfunction function b=df2(x,y,z) b=sin(y) endfunction function [x,y,z]=EulerM(xo, yo, zo, h) x(1) = xo for j = 2:136 x(j) = x(j-1) + h end n=length(x) y(1)=yo z(1)=zo for i=2:n y(i)=y(i-1)+df1(x(i-1),y(i-1),z(i-1))*h ...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex15_4.sce. clc; clear; //There is a mistake in the question , given height is 5 instead of 4 h=4; x=[2:2:14]; for i=1:length(x) Ed(i)=(64/(4^2+x(i)^2)^(3/2))+1;...
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//To Calculate the Temperature of Deutrons for a specific Average Kinetic Energy //Example 46.7 clear; clc; e=1.6*10^-19;//Charge on an electron in Coloumbs E=9*10^9;//Value of Constant (1/(4*%pi*e0)) in N-m^2/C^2 d=2*10^-15;//Closest Seperation between 2 deutrons in metres K=e^2*E/(2*d);//Initial K...
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// Example 8.3 // Calculation of the maximum transmission distance. // Page no 394 clc; clear; close; //Given data p=3; // Peak power tb=40*10^9; // Bit rate c=3*10^8; // Velocity of light lambda=1550*10^-9; ...
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clc; a=20; //amplitude in cm n=6; //frequency per second w=2*(%pi)*n; //omega in radians/sec disp(w,"Omega in radians/sec = "); //displaying result
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//Example 6.4 // Period of Oscillation clc; clear; //given data : m1=8;// mass suspended in kg l=.32;// length of spring stretched in m m=.5;// new mass suspended in kg g=9.8;//acceleration of gravity in m/s2 k=m1*g/l;// force constant of spring in N/m disp(k) T=2*%pi*sqrt(m/k);// time period of Oscillation...
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clc //initialisation of variables S2= 5.8328 //kJ/kg S1= 5.8712 //kJ/kg //CALCULATIONS S= S2-S1 //RESULTS printf (' change in entropy = %.5f kJ/K',S)
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clc; warning("off"); printf("\n\n example7.7 - pg293"); // given Uo=1; //[m/sec] // using Ux/Uo=y/yo // assuming any particular value of yo will not change the answer,therefore yo=1; Uxavg=integrate('(Uo*y)/yo','y',0,yo); Ux3avg=integrate('((Uo*y)/yo)^3','y',0,yo); // using the formula alpha=(Uxavg)^3/Ux3avg...
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/* * Include the ICI file that defines the Complex type */ /* * Create a Complex number */ auto c = utype.new(Complex.type); printf("After creation, re = %f im = %f\n", c["re"], c["im"]); printf("typeof(c) = %s\n", typeof(c)); try c.foo = 1; onerror printf("%s\n", error); c.re = 27.9; c.im = 1; printf(...
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clc; eo=8.85*10^-12; //constant r=1.2; //r in m t=80*10^-6; //surface sharge density in c/m square q=t*4*(%pi)*(r^2); //calculating charge fi=q/eo; //calculating flux disp(fi,"Flux in N m square/c = "); //displaying result
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 36 clc; disp("CHAPTER 8"); disp("EXAMPLE 36"); //VARIABLE INITIALIZATION v_t=250; //in Volts I_l=150; //in Amperes loss1=1200; //core loss at full load in Watts loss2=800; //mechanical loss in Watts r...
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//Example 19.2 delta_PE=-30;//Energy lost per second (J) delta_V=12;//Potential difference (V) q=delta_PE/delta_V;//Charge moved (C) n_e=q/(-1.60*10^-19);//Number of electrons passing per second //-1.60*10^-19 C is the charge of an electron printf('Number of electrons passing per second = %0.2e',n_e) //Openstax ...
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function [x,y,typ]=CONST_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) graphics=arg1(2); [orig,sz]=graphics(1:2) model=arg1(3);C=model(8) dx=sz(1)/5;dy=sz(2)/10 xstringb(orig(1)+dx,orig(2)+dy,string(C),sz(1)-2*dx,sz(2)-2*dy,'fill') case 'getinputs' then x=[];y=[];typ=[];...
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//Ex 5.2 clc;clear;close; Rf=100;//kohm C=0.1;//micro F T=2*Rf*1000*C*10^-6;//s disp(T*10^3,"Time period(ms)"); f=1/T;//Hz disp(f,"Frequency(Hz) : ");
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////Given m=9.1*10**-31 //Kg h=1.05*10**-34 //Js ev=1.6*10**-19 n1=1 n2=2 n3=3 a=10**-10 //m //Calculation // E1=((n1**2*%pi**2*h**2)/(8.0*m*a**2))/(1.6*10**-19) //ev E2=n2**2*E1 E3=n3**2*E1 ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; //clf; clc; // Constants g = 9.81; u0 = 0; v0 = 0; b = 2; h0 = 5030; damp=0.0; force=0.1; forcefreq=0.1; k=2.5; // Define the x domain ni = 1001; xmax = 10.0; dx = xmax/(ni-1); x = 0:dx:xmax; /...
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clc //Initialization of variables p=14.7 //psia ps=0.363 //psia n2=7.52 //moles n1=1 //moles //calculations x= (n1+n2)*ps/p /(1-ps/p) n=n1+n2+x y1=n1/n y2=n1/(n1+n2) //results printf("Percentage of co2 on a wet basis = %.1f percent",y1*100) printf("\n percentage of co2 on a dry basis = %.2f percent",y2*100...
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//Fluid Systems - By Shiv Kumar //Chapter 16- Hydraulic Power and Its Transmissions //Example 16.5 //To Calculate the Increase in Pressure Intensity. clc clear //Given Data:- d=200; //diameter of Pipe, mm Q=40; //Discharge, Litres/s l=600; //Length of Pipe, m ...
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//Exam:8.2 clc; clear; close; d_o=12.7;//tensile test specimen diameter (in mm) d=12;//tensile test specimen diameter after load (in mm) P=76*10^3;//load(in N) pi=22/7; A_o=(pi/4)*(d_o^2);//Initial area of cross section(in mm^2) A=(pi/4)*(d^2);//area of cross section after load of 76 kN E_stress=P/A_o;//engin...
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// chapter 2 // exapmle 2.11 // fig. 2.8 // Find the total elongation of the bar // page-21-22 clear; clc; // given A=500; // in mm^2 (cross-sectional area of the bar) E=80; // in GPa (modulus of elasticity) PA=100, PB=80, PC=50, PD=30 ; // in kN (forces acting at the points A,B,C,D) l_AB=500; // in mm (length of part ...
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X = [48 52 70 62 57 81 56 59 77 82 78 80 74 82 68 84]; u = 62; n = 4; sigma = 24; alpha = 0.25; W = zeros(17); W(1) = 60; for i =2:17 W(i) = (0.25*X(i-1)) + (0.75*W(i-1)); end disp(W , "The values of W are") val = 3*sigma*sqrt(alpha/(n*(2-alpha))); lcl = u- val; ucl = u+ val; disp(lcl, "LCL is"); dis...
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//Exa 5.23 clc; clear; close; //Given data : A=0.936+%i*0.016;//parameter of 3-phase line D=A;//parameter of 3-phase line B=33.5+%i*138;//parameter of 3-phase line C=(-0.9280+%i*901.223)*10^-6;//parameter of 3-phase line VRL=200*10^3;//Volt VR=VRL/sqrt(3);//Volt P=40*10^6;//W pf=0.86;//power factor cos_fi_...
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// Exa 6.14 clc; clear; close; format('v',6) // Given data Av =10000;// open loop gain Beta = 1/10;// feedback ratio Avf = Av/(1+(Av*Beta));// closed loop gain dAvByAv = 50/100;// change in open loop gain dAvByAvf = 1/(1+(Beta*Av))*dAvByAv*100;// change in closed loop gain in % disp(dAvByAvf,"The percentage...
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// Exa 8.19 clc; clear; close; // Given data GCR= 110;// gas consumption rate in m^3/hour rpm= 300;// round per minute Vs= 0.1;// swept volume of engine in m^3 V_H2=0.50;// in m^3 V_CO= 0.05;// in m^3 V_CH4=0.25;// in m^3 V_CO2= 0.10;// in m^3 V_N2= 0.10;// in m^3 V_O2= 5.8;// in m^3 AirRequired= (0.5*(V_...
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//error no internal error //ques5 clc disp('definite integral'); syms x m n n=input('Enter n :'); m=input('Enter m : '); g=(cos(x))^m*cos(n*x); f=integ(g,x,0,%pi/2); disp(float(f)); g2=(cos(x))^(m-1)*cos((n-1)*x); f2=m/(m+n)*integ(g2,x,0,%pi/2); disp(float(f2)); disp('Equal');
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//variable initialization zH=1 //atomic no. of H zHe=2 //atomic no. of He deltaHe=5.84 //doublet spli...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex8_6.sce. clc; clear; N=360; phi=45e-3; s=120; E=260; p=4; n=N/60; a=8; Z=(E*a)/(2*phi*p*n); coductors_per_slot=Z/s; total_no_of_conductors=coductors_per_slo...
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clc;funcprot(0);//EXAMPLE 16.3 // Initialisation of Variables ec=3600*10^(-6);.............//Engine capacity in m^3 pw=13;...............//Power developed in kW per m^3 of free air induced per minute etaV=0.82;............//Volumetric Efficiency N=3000;................//Engine rpm p1=1.0132;.........................
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testpause.sce
x=1 pause x=2 halt('hit ''Enter'' to resume') x=3
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qW4-0=/;6 z (; [ 3["" [%Xcc; / 7E ; v ] / *cl ]] *7""; [*"pA" ; ; ] 6""; ); v
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Ex7_2.sce
// Example 7.2 clc; clear; close; // Given data format('v',6); f_H= 2*10^3;//cut-off frequency in Hz C= 0.033*10^-6;// in F R= 1/(2*%pi*f_H*C);// in Ω // 2*R= Rf*R1/(Rf+R1)= 0.586*R1^2/(1.586*R1) since Rf= 0.586*R1 R1= 2*R*1.586/0.586;// in Ω R1= round(R1*10^-3);// in kΩ disp("The value of R1 is : "+string(...
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// Exa 9.17 clc; clear; close; // Given data k = 0.12;// in mA/V^2 V_T = -2.5;// in V V_GS = 0; I_D = k*((V_GS-V_T)^2);// in mA disp(I_D,"The value of I_D in mA is"); V_DD = 6;// in V R_S = 4.7;// in k ohm V_DS = V_DD -(I_D*R_S);// in V disp(V_DS,"The value of V_DS in V is "); V_S = 0;// in V V_DSsat ...
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load And16.hdl, output-file And16.out, output-list a%B1.16.1 b%B1.16.1 out%B1.16.1; set a %B111111111111111, set b %B000000000000000, eval, output; set a %B101010101010101, set b %B101010101010101, eval, output; set a %B111111111111111, set b %B111111111111111, eval, output;
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FACES_sce.sce
########################################################### # This experiment presents pictures of faces with different # expression. The aim is to study emotional contagion in # the context of sleep deprivation. # The paradigm is adapted from Wright et al, Neuroimage # 42 (2008) 956-968. # # By Gustav Nilsonne 12112...
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ex_23.sce
// The equation 3*x^3+4*x^2+4*x+1==0 has three real roots. // the graph of this function can be observed here. xset('window',22); x=-1.5:.001:1.5; // defining the range of...
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example11_13.sce
//clc() T1 = 1500;//K Tr = 273;//K T2 = 400;//K Cpm1 = 50;//kJ/kmol Cpm2 = 35;//kJ/mol H = Cpm1 * ( T1 - Tr ) - Cpm2 * ( T2 - Tr ); disp("kJ/kmol",H,"Enthalpy change = ")
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6_7.sce
//Eg-6.7 //pg-290 clear clc //sorting data in ascending order x=[233;216;229;238]; m1=median(x); y=[56;62;51]; m2=median(y); disp("medians of given data are as follows") disp(m1) disp(m2)
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clc; clear; omega=500 //frequency in radian/s L=0.08 //inductance in H R=15 //resistance in ohm C=30*10^-6 //capacity in F //calculation L_omega=L*omega //in ohm C_omega=1/(C*omega) //in ohm tan_phi=(L_omega-C_omega)/R //in degrees phi=atand(tan_phi) mprintf("The current leads the applied voltage by =...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART I : GENERATION // CHAPTER 7: TARIFFS AND ECONOMIC ASPECTS IN POWER GENERATION // EXAMPLE : 7.13 : // Page number 77 clear ; clc ; close ; // Clear the work space and ...
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//Resistance R, Voltage V, Current I close(); clear; clc; R1 = 5;//ohm R2 = 15; R3 = 5; R4 = 4; R5 = 12; V5 = 132;//V I = V5/R5; I1 = (R1+R2)/(R1+R2+R3)*I; I2 = R3/(R1+R2+R3)*I; mprintf('I1 = %0.1f A\nI2 = %0.1f A',I1,I2);
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//Chapter 2_Thick Film and Thin Film Hybrid ICs //Caption : Sheet Resistivity //Example2.3: Calculate the sheet resistivity of a square of thick film resistor material with the following properties: bulk resistivity=10^-1ohm-cm and thick film thickness=10micrometer. //Solution: clear; clc; function Ps=myfunction4...
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10 964:0.16666666666666666 965:1.0 10 6:1.0 14:0.030303030303030304 30:0.2 186:0.5 344:1.0 10 3:1.0 6:1.0 55:0.5 56:0.25 66:0.5 69:0.6666666666666666 84:0.25 183:0.25 199:0.125 301:1.0 331:1.0 346:1.0 349:0.3333333333333333 369:1.0 394:1.0 971:1.0 973:1.0 1056:0.5 1256:1.0 1317:1.0 1327:1.0 10 14:0.030303030303030304 2...
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clear; getd(); // Get data from file disp("Loading ballistic data file..."); DATA=fscanfMat('BallisticsDataFile.txt'); d=DATA(:,2); t=DATA(:,1); // Create G from the time data disp("Creating matrix G..."); n=size(t)(1); G=ones(n,1); G=[G t -0.5*t^2]; // Compute model disp("Computing model..."); m=inv(G'*G)*G'*d; /...
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load DMux.hdl, output-file dmuxOutput.out, output-list in sel a b; set in 0, set sel 0, eval, output; set in 0, set sel 1, eval, output; set in 1, set sel 0, eval, output; set in 1, set sel 1, eval, output;
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#material stream example $thermo = VirtualMaterials.Advanced_Peng-Robinson / -> $thermo thermo + WATER TRIETHYLENE_GLYCOL #generate WATER/TEG bubble temperature curve units Field s = Stream.Stream_Material() s.In.P = 1 atm s.In.VapFrac = 0.0 s.In.Fraction = 0.0 1.0 s.Out.T s.In.Fraction = 0.1 0.9 s.Out....
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A = [1 2 -2;1 1 1;2 2 1] b = [1;-2;3] function [x]=GaussSansPivot(A,b) // résout le système Ax=b par [m,n]=size(A);o=length(b); if m~=n | o~=n then, error('probleme de dimensions'), end; // initialisation zero=1.e-16; for k=1:n-1 u=A(k,k:n);pivot=A(k,k);i0=k if abs(pivot)<zero then, error('stop : pivot nul')...
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clear; clc; //Caption:Value of theta for Ge Transistor //Given Data Vcc=30;//in V Rc=2;//in K Re=4.7;//in K Ic=1.5;//in mA //We know that dPc/dIc = Vcc - (2*Ic*(Rc+Re)) //Let D=dPc/dIc D = Vcc - (2*Ic*(Re+Rc)); disp('Ic increases by 0.131mA over a temprature range of 35 to 75 degree C'); disp('theta...
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// 2.14 clc; mo=0.8; sr=250; sm=sr/mo; R=sm*1*10^-3; printf("Resolution of 1mm movement = %.4f degree/mm",R) Rq=300/1000; printf("\nRequired Resolution of 1mm movement = %.3f degree/mm",Rq) disp('Since the resolution of potentiometer is higher than the resolution required so it is suitable for the application'...
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// Решение уравнения теплопроводности методом разностных схем // ∂u / ∂t - a ^ 2 * ∂ ^ 2 u / ∂t ^ 2 = 0 // a ^ 2 = λ / cρ, 0 <= x <= L, 0 <= t <= T, (T - время, любое число до ∞) // u(0, t) = 0, u(L, t) = 0, u(x, 0) = fi(x), // a ^ 2 - коэффициент температуропроводности, // λ - коэффициент теплопроводности м...
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errcatch(-1,"stop");mode(2);//Example 7.5: The number of longitudinal modes excited ; ; format('e',10) //given data : lamda=632.8*10^-9;// in m n=1; L=20*10^-2;// in m del_lamda=((lamda)^2/(2*n*L))*10^9; disp(del_lamda,"The number of longitudinal modes excited,(nm) = ") exit();
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//Example 20.4 //Seven Point Formula //Page no. 686 clc;clear;close; printf('Itr\t\t U111\t\t U211\t\t U121\t\t U221\n-----------------------------------------------------------------------\n') for i=1:4 for j=1:4 for k=3:-1:1 if k==3 then u(i,j,k)=100 elsei...
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clear //Given B=1 //T l=0.5 //m v=40 //m/s //Calculation // e=B*l*v*sin(60*3.14/180.0) //Result printf("\n emf induced in the conductor is %0.2f ",e)
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toolbox_dir = get_absolute_file_path("builder.sce"); tbx_builder_macros(toolbox_dir); tbx_build_loader(toolbox_dir); tbx_build_cleaner(toolbox_dir); tbx_builder_src(toolbox_dir); tbx_builder_gateway(toolbox_dir); tbx_build_localization(toolbox_dir); tbx_builder_help(toolbox_dir);
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// Example:7.4 //Write a program to compute and print a multiplication table for numbers 1 to 5 ROWS=5;COLUMNS=5; disp("MULTIPLICATION TABLE"); printf("*|") for j=1:COLUMNS printf("%4d",j); end disp("________________________"); for i=1:ROWS printf("%1d|",i); for j=1:COLUMNS ...
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//example 24.14 clc; disp('The kanaurgh map for given truth table will be :'); disp(' A''B'' A''B AB AB'''); //displaying the given kmap disp('C'' 1 0 0 1'); disp('C 0 1 1 0'); disp("The adjacent cells that can be combined together are cells 000 and 100 and the cells 011 and 111")...
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//================================================================================================== // chapter 3 example 20 clc; clear; //input data f = 50; //number of reversals/s in Hz W = 50; //weight in kg d = 7500; //density in kg/m^3...
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clc alpha=45 sigmayp=35*10^6 //Pa k=840//MPa n=0.2 L0=3 //m Aad=10*10^-5 //m^2 Acd=10*10^-5 //m^2 Abd=15*10^-5 //m^2 P=sigmayp*Abd+2*sigmayp*Aad*cosd(45) disp(P,"plastic yeilding in N is= ") sigma=k*n^n disp(sigma,"maxi allowable stress in MPa is= ") epsilon1=n disp(epsilon1,"axial stress is= ") epsi...
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function [x,h] = puntofijo(g,x0,kmax,tol) h=zeros(1,kmax); i=1; p0=x0; while(i<kmax) x=g(p0); r=abs(x-p0); h(1,i)=r; i=i+1; if (r<tol) then return; end p0=x; end endfunction
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//Caption: Mean,Variance //Example 2.31 //page no 85 //find i)Mean // ii)Variance of given function clc; clear; //Mean Value function X=f(x), z=3*(1-x)^2,//Marginal Probability Density Function X=x*z endfunction a=0; b=1; EX=intg(a,b,f);//Mean value of X function Y=c(y) z=3*(1-y)^2...
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Example5_2_a.sce
//Example 5.2(a) clear; clc; R=100*10^3; C=1*10^(-9); vo0=0; IB=80*10^(-9); IOS=20*10^(-9); Vsat=13; Rp=0; Ip=((2*IB)+IOS)/2; In=((2*IB)-IOS)/2; vo1=(R*IB)/(R*C); t=Vsat/vo1; printf("Time taken by the op amp to enter saturation (t)=%.4f sec",t);
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//Eg-11.8 //pg-485 clear clc a = 0; b = 1; h = b-a; deff('out = func(in)','out = 1/(1+in^2)') //From equations [30],[31],[32] & [33] //Please note that the subscripts(i&j) we use here are different from that used in //text book i.e they are increased by 1, because we cant give the index zero in /...
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//Example 2.2 // Wavelength of light clc; clear; //given data : a=.2D-3;//slit width in m D=2;// screen is placed at distance in m x=5D-3;// first minima lies at distance to central maxima w=(a*x)/D;// wavelength of light in m w=w*1D10;// to convert in A disp(w,"wavelength of light used in A")
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//Chapter 23, Problem 13 clc; p = 4/2; // no. of pole pairs f = 50 ; // in Hz nr = 24; // in rev/sec V = 415; // in Volts R2 = 0.35; // in Ohms X2 = 3.5; // in Ohms //At the moment of starting, slip, s = 1 //Maximum to...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 17 clc; disp("CHAPTER 1"); disp("EXAMPLE 17"); //VARIABLE INITIALIZATION v=7; //voltage source in Volts I=7; //current source in Amperes r1=1; //in Ohms r2=2; ...
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//example 4 //calculating required specific work clear clc Cp=1.004 //specific heat of air at constant pressure in kJ/kg-K Ti=290 //initial temperature in kelvins Pi=100 //initial pressure in kPa Pe=1000 //final pressure in kPa k=1.4 Te=Ti*(Pe/Pi)^((k-1)/k) //final temperature in kelvins we=Cp*(Ti-Te) //requ...