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example75.sce
//Example 7.5 clc; syms Wo n z; x1=exp(sqrt(-1)*Wo*n); X1=symsum(x1*(z^-n),n,0,%inf); x2=exp(-sqrt(-1)*Wo*n); X2=symsum(x2*(z^-n),n,0,%inf); X=(X1+X2)/2; disp(X,'X(z)=');
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example15_sce.sce
//chapter 12 //example 12.15 //page 407 printf("\n") printf("given") Vgsoff=-6;Idss=20*10^-3;Yfs=4000*10^-6;Id=2*10^-3;Vcc=20;Zi=500*10^3;R2=560*10^3;Rl=80*10^3;Vbe=.7;Vce=3; Vgs=Vgsoff*(1-sqrt(Id/Idss)) Vds=(-Vgsoff)+1-(-Vgs) Vr3=(Vcc-Vds)/2 Vr4=Vr3; R3=Vr4/Id//use 3.9kohm as standard and recalculate Vr3 and...
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clear; //clc(); // Example 11.11 // Page: 293 printf("Example-11.11 Page no.-293\n\n"); //***Data***// T_inlet = 68;//[F] T_outlet = 110;//[F] // from the figure 11.13 we read that at 68F the solubility of CaCO3 and CaSO4.2H2O are s_inlet_carbonate = 60;//[ppm] s_inlet_sulphate = 2020;//[ppm] // At...
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i=2.6; r=300; x_l=400; z=sqrt(r^2+x_l^2); p=i^2*z; disp("the apparent power drawn (in kVA) by the circuit is"); disp(p*10^(-3));
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clc // // //Variable declaration p=180 // Internal gage pressure(psi) t=(5/16.0) // Length(in) r=(15-t) //...
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clc //initialisation of variables x1= 4 x2= %pi/x1 L= 400 //mm h= 5 //m d=20 //mm W= 1000*10^3 //KN Ys= 200000 //N/mm^2 Yc= 15000 //N/mm^2 //CALCULATIONS As= x1*x2*(d^2) Ac= L^2-As sigmas= (Ys*W)/(Ac*Yc+As*Ys) sigmac= (Yc*W)/(Ac*Yc+As*Ys) delta= (sigmac*h*10^3)/(Yc) //RESULTS printf ('As= %.f mm^2',As)...
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clear //Given n=10 I=3 A=7.85*10**-3 B=10**-2 //T //Calculation // M=n*I*A U1=-M*B*cos(0) Uf=-M*B*cos(90) w=-U1 t=M*B*sin(90*3.14/180.0) //Result printf("\n Work done is %0.1f *10**-3 Nm",t*10**3)
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// Grob's Basic Electronics 11e // Chapter No. 01 // Example No. 1_6 clc; clear; //The charge of 12 C moves past a given point every second. How much is the intensity of charge flow? // Given data Q = 12; // Charge=12 Columb T = 1; // Time=1 Sec i.e every second I = Q/T; disp (I,'The Inte...
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l=1.5//m(Length of rectangular weir) D=2.25//m(Upstream depth) Q=0.45//m^3/s
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// Simulação via integração numérica do espaço de estados C = [[1,0,0,0]; [0,1,0,0]; [0,0,1,0]; [0,0,0,1]] D = [[0,0]; [0,0]; [0,0]; [0,0]] function entradas = u(t) // Entradas para simulação via integração numérica do espaço dos estados if t < 4 then u1 = 0 u2 = 0 ...
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//example 10.2 //page 366 clc; funcprot(0); //initialisation of variable z=1; b=3; y=1.5; S=0.0009; n=0.012; A=(b+z*y)*y; P=b+2*y*sqroot(1+z^2); R=A/P; Q=A/n*R^(2/3)*S^0.5; disp(Q,"flow rate (m^3/s)"); clear
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//To draw a spiral curve t=0:0.1:10; r=10; x=r*sin(t); y=r*cos(t); z=t; param3d(x,y,z,35,45,"X@Y@Z",[2,4]) e=gce(); e.foreground=color('red'); param3d([0,0],[0,0],[0,10]); e=gce(); e.line_style=4;
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// Theory and Problems of Thermodynamics // Chapter 10 // Chemical Thermodynamics // Example 4 clear ;clc; //Given data T = 298 // reaction temperature in K H_SO2 = -296.83 // heat of formation of SO2 in kJ H_SO3 = -395.72 // heat of formation of SO3 in kJ H_CO = -110.53 ...
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//7.11 clc; Vm=675*2^0.5; Ia1=30; N1=350; N2=500; Ia2=Ia1*N2/N1; printf("Armature current of the semi converter=%.2f A",Ia2) Va1=(1+cos(90.5*%pi/180))*Vm/%pi; Eb1=Va1-Ia1*(0.22+0.22); Eb2=Eb1*Ia2*N2/(Ia1*N1); Va2=Eb2+Ia2*(0.22+0.22); alph_a=acosd(Va2*%pi/Vm-1); printf("\nFiring angle of the semi converter=...
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// Scilab Code Ex4.11: Page-122 (2006) clc; clear; m = 9.1e-031; // Mass of an electron, kg e = 1.6e-019; // Charge on an electron, C lambda = 1.0e-09; // Mean free path of electron in metal, m v = 1.11e+05; // Average velocity of the electron in metal, m/s // For Lead n = 13.2e+028; // Electronic co...
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clc; clear; // -------------------- // Part a s = poly(0, 's'); A = -1:0.01:1; scf(); for i=1:size(A, 2) a = A(i); [N, D] = simp(s + 5 + a, s^2 + 11*s + 30); sla = syslin('c', N, D); t=0:0.05:10; plot(t, csim('step', t, sla), color('blue'), 'LineWidth', 2); xlabel("$t$", 'fontsize', 3); ylab...
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{% import "20300/DCC/Workflow/vars.sls" as base %} {% set trialset = salt['network.ipaddrs']( ) %} {% set val= trialset | replace("[u'", "") %} {% set machine_ip= val| replace("']", "") %} {% set dcc_master = grains['dcc_master'] %} {% set auth = grains['auth'] %} check_service_running: module_and_function: service.s...
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clear clc dat = csvRead("C:\Users\Immanuel\Documents\SCILAB\EDL.csv"); frange = dat(2:41,1) Mdb = dat(2:41,12) phdeg = dat(2:41,16) f1 = 100; f2 = 1000; eta1 = 0.1; eta2 = 1; //comp = 50*((1+%i.*frange./f2)./(1+%i.*frange./f1))^10; //comp = 10*((1+%i.*frange./f2)./(1+%i.*frange./f1))^4; comp = 2.5*((1+2.*...
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//Section-10,Example-2,Page no.-CT.41 //To calculate Entropy change(dl_S). clc; n=10 C_v=(3/2)*R T_2=323 T_1=298 V_2=2 V_1=1 R=8.314 dl_S=n*((C_v*log(T_2/T_1))+(R*log(V_2/V_1))) disp(dl_S,'Entropy change(JK^-1)')
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clear // //i1=20*sin(314t+60),i2=-10*sin(314t),i3=15*sin(314t-45)-->angles are in degrees //I1=(7.7072+j12.25),I2=(-7.072),I3=7.5-j7.5 //adding phasor currents I1,I2 and I3 //I=7.702+j12.25-7.702+7.5-j7.5=7.5+j4.75 printf("\n I=7.5+j4.75. Its value in polar form is obtained as 8.8776 at angle 32.34") //i=2**0.5*8.8776*...
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clc; x = [-1 -2 -3 -4 -5 0 1 2 3 4 5 ]; y = [0 0 0 0 0 1 1 1 1 1 1 ]; plot(x,y, 'ro') xlabel(' VALUES OF x'); ylabel('VALUES OF y'); title('UNIT STEP FUNCTION');
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//Tested on Windows 7 Ultimate 32-bit //Chapter 1 Introduction to Electronics Pg no. 33 //Solved Problem 4 clear; clc; //Given Data R=10;//resistance in ohms P=4;//power in watts //Solution I=sqrt(P/R);//current in amperes printf("Maximum safe current is I=%.3f Amperes.",I);//Displaying upto 3 place...
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//Example_a_7_3 page no:271 clc; Vmag=10; Vang=0; R1=-%i*5; R2=4-(%i*5); R1mag=sqrt(real(R1)^2+imag(R1)^2); R2mag=sqrt(real(R2)^2+imag(R2)^2); R2ang=atand(imag(R2)/real(R2)); Ztmag=6.24; Ztang=29.26; Itmag=Vmag/Ztmag; Itang=Vang-Ztang; Inmag=Itmag*R1mag/R2mag; In=0.466-(%i*1.149); Zn=4+((3+(%i*5))*(-%i*5...
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//pagenumber 294 example 14 clear hie=2*10^3;//ohm beta1=100; colres=5*10^3;//ohm volgai=beta1*colres/hie; disp("voltage gain = "+string((volgai))+"<180"); disp("input impedance = "+string((hie))+"ohm"); disp("current gain = "+string((beta1)));
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// Example 8.3: yield strength of material clc; clear; close; ys1=120;// yeild strength in MN/mm^2 ys2=220;// yeild strength in MN/mm^2 d1=0.04;//diamtere in mm d2=0.01;//diamtere in mm A=[2 10; 1 10]; B=[240;220]; x=A\B; si=x(1,1);// in MN/mm^2 k=x(2,1);// d3=0.025;//in mm sy= si +(k/sqrt(d3));//yeild strength for a g...
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errcatch(-1,"stop");mode(2);//Ex:13.2 ; ; c=3*10^8; f=150*10^6; wl=c/f; printf("The wavelength =%d m",wl); exit();
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//clear// clc clear exec("4.2data.sci"); FA0 = FC/X; vA0 = FA0/CA01; vB0 = vA0; v0 = vA0+vB0; V = v0*X/(k*(1-X)); // CSTR in parallel V1 = 800/7.48; Tau =V1/(v0/2); Da= Tau*k; Xparallel = Da/(1+Da) // CSTR in series Tau =V1/v0; n=2; Xseries = 1- (1/(1+Tau*k)^n); disp("Reacto...
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//<>=arspec(z) //<>=arspec(z) // Estimation de la puissance spectrale d'un processus // ARMA z // test de mese et de arsimul //! [lhs,rhs]=argn(0) m=18 [sm,fr]=mese(z,m); plot2d([fr]',[20*log(sm/sm(1))/log(10)]', [-1,1],"121",... "log(p) : estimee ar"); //end
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// Example 7.1 format('v',6) clc; clear; close; // given data V_CC= 10;// in V R_E= 430;// in Ω V_BE= 0.7;//in V V_B= 5;//in V // The collector saturation current, I_Csat= V_CC/R_E;// in A // The collector emitter voltage, V_CEcutoff= V_CC;// in V // The collector current, I_C= (V_B-V_BE)/R_E;// in A //...
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clc clear //Input data r=7//Compression ratio v=1//Specific heat at constant volume increases by 1 percent g=1.4//Ratio of specific heats //Calculations e=(1-(1/r^(g-1)))//Air standard efficiency dee=-(((1-e)*(g-1)*log(r)*(v/100))/e)*100//Change in efficiency to the original efficiency x=-(dee)//For Output p...
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clear; clc; close; disp("Example 11.9") g=9.8 //in m/s^2 Is=421 //in s Qr=120000000 v=5000 //in m/s c=g*Is disp(c,"(a)Effective exhaust speed c in m/s :") ep=2*(v/c)/(1+(v/c)^2) disp(ep,"(b)propulsive efficiency :") eo=c*v/Qr disp(eo,"(c)Overall efficiency :")
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clc m=6; //kg T1=25; //0C T2=125; //0C disp("(i) Heat transferred") Q=integrate('m*(0.4+0.004*T)','T',T1,T2); disp("heat tranferred=") disp(Q) disp("kJ") disp("(ii) Mean specific heat of the gas") c_n=Q/m/(T2-T1); disp("Mean specific heat=") disp(c_n) disp("kJ/kg.0C")
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//n = 100; xdata = [10:10:100]; for n = xdata; i=n/10; A=rand(n,n); B=rand(n,n); tic(); C3B= matmat3b(A,B); times1(i) = toc() tic(); C2B= matmat2b(A,B); times2(i) = toc() tic(); C1B= matmat1b(A,B); times3(i) = toc() tic(); Cnorm=A*B; times4(i) = toc() end xtitle("Comparaison temps execution d...
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// Variable declaration alpha = 0.05 // level of significance n = 10 R = [5,8,6,10,3,7,9,4,2,1] S = [5,8,6,10,4,7,9,3,2,1] // Calculation RS = 0 for i = 1:10 RS = RS + R(i)*S(i) end rs = (RS - n*((n+1)^2)/4.0)/(n*(n^2-1)/12.0) // Result printf ( "rs value: %.3f i.e. there is strong assoc...
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// Exa 3.9 format('v',5) clc; clear; close; // given data disp("(i) For 200 Ω load resistance"); R_L= 200;// in Ω Vz= 12;// in V Vout= Vz;// in V Vin= 25;// in V R_S= 180;// in Ω // The value of I_S I_S= (Vin-Vout)/R_S;// in A // The value of I_L I_L= Vout/R_L;// in A // The value of I_Z I_Z= I_S-I_...
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clc; //Example 10.5 //page no 103 printf("\n Example 10.5 page no 103\n\n"); //a hydrometer is a liquid specific gravity indicator with the value being indicated by the level at which the surface of the liquid intersects the sten when floating in avliquid F=0.13//the total hydrometer weight, N SG=1.3//sp. gravity...
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// Résolution d'une équation différentielle // y' + b y = c // on cherche la solution y(x) // S. Celles // 08/12/2004 clear x_ini=0; // MODIFIABLE defaut : x_ini=0; x_pas=0.1; // MODIFIABLE defaut : x_pas=0.1; x_fin=10; // MODIFIABLE defaut : x_fin=10; x=[x_ini:x_pas:x_fin]'; // le prime sert à transposer pour av...
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#************************************************************ # Scenario of Ikea # # date : Mon Nov 23 15:46:58 2009 #************************************************************ p3d_sel_desc_name P3D_ENV Ikea p3d_sel_desc_name P3D_ROBOT HUMAN p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0....
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clc clear //Page number 485 //Input data t1=127;//The temperature of the black body in degree centigrade t2=27;//The temperature of the walls maintained in degree centigrade s=5.672*10^-8;//Stefans constant in SI units //Calculations T1=t1+273;//The temperature of the black body in K T2=t2+273;//The te...
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clc //initialisation of variables ti= 149 //C t0= 27 //C D0= 0.1149 //m l= 1 //m h0= 23 //W/m^2 C hi= 227 //W/m^2 C k= 0.19 //W/m C Di= 0.0889 //cm //CALCULATIONS D1= D0*100 D2= Di*100 R0=(1/(D0*%pi*l*h0)) Rins=(log(D1/D2)/(2*%pi*k*l)) Ri=1/(Di*%pi*l*hi) q= (ti-t0)/(R0+Rins+Ri) //RESULTS printf ('Heat...
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clear; close; clc; W = -%pi:(1/500):%pi; z = exp(sqrt(-1)*W); H = z./(z-0.8); Mag_H = abs(H); [Phase_H,m] = phasemag(H); //phasemag used to calculate phase and magnitude in dB subplot(2,1,1) plot2d(W,Mag_H) xlabel('Frequency in Radians') ylabel('abs(H)') title('Magnitude Response') subplot(2,1,2) plot2d(...
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P=15E3 a=3000/250 /////OC Parameters Poc=105 Ioc=0.62 Voc=250 /////SC Parameters Psc=360 Isc=5.2 Vsc=157 Y0=Ioc/Voc Gi=Poc/Voc/Voc Bm=sqrt(Y0*Y0-Gi*Gi) Z=Vsc/Isc R=Psc/Isc/Isc X=sqrt(Z*Z-R*R) ///////////Referred to HV side GiHV=Gi/a/a disp(GiHV) BmHV=Bm/a/a disp(BmHV) disp(R) disp(X) ...
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L11=300; L12=320; L1=12000; L2=15000; A1=50000; A2=95000; A21=49000; A22=A2-A21; theta=15*(%pi/180);
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clc; clear all; disp("heat transfer coefficient") Fd=10.5;//N ts=95;//degree C ta=25;//degree C U=30;//m/s rho=1.06;//kg/m^3 cp=1005;//J/kg.K v=18.97*10^(-6);// m^2/s Pr=0.696; //ReL=U*L/v //Cf=0.072/ReL^0.2 //A=L^2; //F=Cf*0.5*rho*A*U^2; //10.5=2.05*L^0.8 L=(10.5/2.05)^(1/1.8) ReL=U*L/v; Cf=0.072/ReL...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>LocProject_Diff2D Tet Ortho Basis, P=6, Q=7</description> <executable>LocProject</executable> <parameters>-s triangle -b Ortho_A Ortho_B -o 6 6 -p 7 7 -c 0.0 0.0 1.0 1.0 0.5 1.0 -d</parameters> <metrics> <metric type="L2" id="1"> ...
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// Exa 8.1 clc; clear; close; format('v',6) // Given data a = 3;// in cm^2 a = a * 10^-4;// in m^2 d = 20;// in cm N = 500; phi = 0.5*10^-3;// in Wb miu_r = 833.33; miu_o = 4*%pi*10^-7; l = %pi*d;// in cm l = l * 10^-2;// in m S = l/(miu_o*miu_r*a);// in AT/Wb //Calculation of the current with the hel...
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//Example 20.6 clc emf=120//in Volt R=10//in Ohm e_back=70 I=emf/R disp("Solution a") disp(I,"Maximum Current in A=") disp("Solution b") I=(emf-e_back)/R; disp(I,"Current in A=")
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// Grob's Basic Electronics 11e // Chapter No. 25 // Example No. 25_7 clc; clear; // In Fig. 25–9, assume that with a 4-mVac input signal for VT, the voltage across R1 is 2 mV when R1 is 225-kOhms. Determine Zeq and Q. // Given data vin = 4*10^-3; // Input AC signal=4 mVac R1 = 225*10^3; // Resist...
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// Example 4_13 clc;funcprot(0); // Given data P_1=8000;// kPa T_1=300;// °C P_2=1600;// kPa h_1=2785;// kJ/kg h_g=2794;// kJ/kg // Calculation // By using steam tables T_2=201.4;// The final temperature in °C h_f2=859;// kJ/kg h_fg2=1935;// kJ/kg h_2=h_1;// kJ/kg x_2=(h_2-h_f2)/h_fg2;// The quality of ...
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//caption:determine_steady_state_error_and_error_coefficient //example 6.10.21 //page 191 s=%s; syms t; r=2+3*t+2*t^3; //since for 'r' only upto 2nd order derivative is non zero, so only coeff. C0 C1 C2 exist G=sym('1/(s*(s+2))'); A=1/(1+G); A=simple(A); disp(A,"E(s)/R(s)="); C0=limit(A,s,0); B=sym('((1)/(s...
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//Chapter 11 //Example 11_12 //Page 282 clear;clc; d_in=2; d_out=8; e1=5; e2=4; e3=3; g_max=40; d1=e1*d_in/e2; d2=e1*d_in/e3; printf("GRADED CABLE: \n"); printf("d1 = %.2f cm \n", d1); printf("d2 = %.2f cm \n", d2); v=g_max/2*(d_in*log(d1/d_in)+d1*log(d2/d1)+d2*log(d_out/d2)); sv=v/sqrt(2); printf("Permissible pe...
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// Calculating the number of turns and no load current clc; disp('Example 5.20, Page No. = 5.101') // Given Data E = 6600;// Primary winding voltage (in volts) f = 60;// Frequency (in Hz) Ai = 22.6*10^(-3);// Area of cross section (in meter square) Bm = 1.1;// Maximum flux density of core (in Wb per meter square...
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clear // //Given //Variable declaration L=3*1000 //Length in mm w=10 //Uniformly distributed load in N/mm a=2*1000 //Length of Uniformly distributed load from fixed end in mm I=1e8 //Moment of Inertia in mm^4 E=2e5 //Youngs modulus in N/sq.mm //Calculation /...
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clc clear //Input data n=6//Number of cylinders d=0.089//Bore in m l=0.1016//Stroke in m vc=3.183//Compression ratio rn=55//Relative efficiency in percent m=0.218//Petrol consumption in kg/hp.hr Pm=(8.4/10^-4)//Indicated mean effective pressure in kg/m^2 N=2500//Speed in r.p.m //Calculations an=(1-(1/(vc-...
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// Scilab Code Ex2.17 First excitation energy of hydrogen atom: Pg: 58 (2008)s n1 = 1; // Principle quantum number of first orbit in H-atom n2 = 2; // Principle quantum number of second orbit in H-atom m = 9.1e-031; // Mass of the electron, C e = 1.6e-019; // Charge on an electron, coulomb h = 6.624e-0...
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clear exec('C:\Users\Julien Guégan\Desktop\PFE\algorithmes\fonctions test.sce',-1) function [xmin,cpt] = purecmaes(f, x0, s0, lambda, mu, itermax, tol)//CMA-ES // -------------------- Initialization -------------------------------- // User defined input parameters (need to be edited) N = length(x0); ...
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//Chapter 06: Counting clc; clear; function result=combination(n,r) //function definition i=n num=1 denominator=1 l=(n-r)+1 u=n for i=l:u //to compute the value of the numerator num=num*i end for j=1:r //to compute the value of the denominator denominator=denominator*j end result=num/denominator return result endfun...
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//chapter12,Example12_4,pg 358 NA=0.5 n1=1.48 n2=sqrt((n1^2)-(NA^2)) printf("refractive index of cladding\n") printf("n2=%.2f ",n2) alpha=asin(NA) alpha=alpha*(180/%pi) printf("\nacceptance angle\n") printf("alpha=%.2f deg",alpha)
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clf reset;clear;clc;close;close;close; myfigure=figure(1) //------------------------------------------Declaration of constant--------------------------------------------------------------------------------------------------------------------------------------------------------------------- global("nom1");global("nom...
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clc clear //Input data r=8.5;//The compression ratio sv=1.4;//The specific heat at constant volume in percent //Calculations n=1-(1/r)^(sv-1);//The efficiency of the otto cycle ef=[((1-n)/n)*(sv-1)*(log(r))*(sv/100)]*100;//The percentage change in efficiency of an otto cycle and is negative //Output prin...
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//pathname=get_absolute_file_path('5.20.sce') //filename=pathname+filesep()+'5.20-data.sci' //exec(filename) //Mass in tank A(in kg): ma=0.6 //Mass in tank B(in kg): mb=1 //Temperature in tank A(in K): Ta=90+273 //Temperature in tank B(in K): Tb=45+273 //Pressure in tank A(in bar): pa=1 //Pressure in tank ...
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foster4_s.sci
//Function of 4 order Foster Network //The coefficient vector will be of the form [R1 C1 R2 C2 R3 C3 R4 C4] //The output will be a linear system in s so I can work with it function [Z]=foster4_s(c) s=poly(0,'s'); //we extract the coefficients R1=c(1); C1=c(2); R2=c(3); C2=c(4); R3=c(5);...
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clear// //Variables P = 36 //Power (in watt) V = 230.0 //Voltage (in volts) //Calculation R = V**2/P //Resistance (in ohm) //Result printf("\n Resistance of the heating element is %0.0f ohm.",R)
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ATWM1_Working_Memory_MEG_Salient_Cued_Run1.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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//To find equivalent system clc //Given: h=650/1000, l1=(650-25)/1000 //m m=37.5 //kg tp=1.87 //seconds //Solution: //Refer Fig. 15.18 and Fig. 15.19 //Calculating the radius of gyration of the connecting rod about an axis passing through its centre of gravity kG=sqrt((tp/(2*%pi))^2*(9.81*h)-h^2) //m //Calcul...
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//Calculate volume of conductor required in 1 phase 2 wire and 3 phase 3 wire system clear; clc; //solution //given pf=0.8;//power factor pMVA=(2.5*10^6);//volt ampere v=(33*10^3);//volts l=50*10^3;//m//length of the line p=pMVA*pf;//watts//power trasmitted = power in MVA* p.f. w=0.2*p;//watts//line losses = ...
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//Chapter 8 //Example 8_10 //Page 177 clear;clc; shunt_cap=0.15; line_cap=0.1; n=3; v1=13.25/40.55; v2=12.5*v1/13.25; v3=14.8*v1/13.25; pv1=v1*100; pv2=v2*100; pv3=v3*100; eff=1/n/v3*100; printf("V1 = %.3f V \n", v1); printf("V2 = %.3f V \n", v2); printf("V3 = %.3f V \n\n", v3); printf("(i) Voltage expressed as ...
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//Finding of Pressure //Given //Left Limb h=0.6; rho=1000; g=9.81; //Right Limb h1=0.45; spgr1=13.6; h2=0.30; spgr2=0.88; //To Find P=(h1*spgr1)+(h2*spgr2)-(h); disp("Pressure is ="+string(P)+" cm of water"); p1=P*rho*g; disp("Pressure is = "+string(p1)+" N/m^2");
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//Calculating new full load speed //Chapter 4 //Example 4.15 //page 310 clear; clc; disp("Example 4.15") f=50;.....................//frequency of induction motor in hertz P=4; //number of poles Nr=1440; //rotor speed in rpm R2=0.1; //rotor resistan...
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PL/SQL Developer Test script 3.0 18 -- Created on 11/30/2018 by VZHURAVOV declare -- Local variables here i integer; begin -- Test statements here logger.set_session( p_channels => logger.GC_CH_BOTH, p_msg_level => logger.GC_LVL_DEBUG ); /*pdh_gateway_pkg.launch( p_module => 'ReportGenerator'...
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function [A_f,B_f,C_f,D_f]=fullobs(A,B,C,D,poles) // Find the full order observer for the system A,B,C,D, with observer poles "poles" L = ppol(A',C',poles)' A_f = A-L*C; B_f = [B-L*D,L]; [m1,n1]=size(A_f); [m2,n2]=size(B_f); C_f = eye(m1,n1); D_f = zeros(m1,n2); endfunction
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x=[1,0,0,0,1,0,1] l=length(x); a=gca(); a.data_bounds=[0,-10;10,+10]; for i=1:l if(x(i)==1) n=i:0.001:i+1 y=3*sin(2*%pi*n/.05) plot(y) else plot(i:i+1,0) end end xgrid(5)
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clear; clc; disp("for 8-KHz sampling,the frequencies present are...(in KHz)"); Fs=8; //sampling frequency Fst=3.5 //single tone frequency disp(Fst); disp(-Fst); disp(Fs-Fst); disp(-(2*Fs+Fst),(2*Fs+Fst),-(Fs+Fst),(Fs+Fst),(Fs-Fst)); disp("...etc..."); disp("in this case, if the LPF is designed with cut-...
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load HackComputer.hdl, output-file LoopStatement.out, compare-to LoopStatement.cmp, output-list RAM64[16]%D1.10.1 RAM64[18]%D1.10.1 RAM64[19]%D1.10.1 RAM64[20]%D1.10.1; ROM32K load LoopStatement.hack, // start = 1, inc = 1, end = 100 set RAM64[16] 1, set RAM64[18] 1, set RAM64[19] 100, // No.of...
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function t=cotg(x) //Eelemt wise cotangent of x if type(x)<>1 then error(53),end t=sin(x).\cos(x)
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//Exa:1.9 clc; clear; close; V=200;//in volts I_1=20//in amperes R_a=0.5;//in ohms E_b1=V-I_1*R_a;//in volts N1=700;//in rpm I_2=sqrt(1.44)*I_1;//in amperes E_b2=V-I_2*R_a;//in volts N2=N1*(E_b2/E_b1)*(I_1/I_2); disp(int(N2),'(a) Speed (in rpm)='); I_3=10;//in amperes E_b3=V-I_3*R_a;//in volts N3=N1*(E_b...
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//Example 1.6, apge 39 clc g=9.8//in m/s^2, constant l=.1//in m m=0.01//in kg h=6.63*10^-34//Joule-sec theta=0.1//in radians v=(1/(2*%pi)*sqrt(g/l)) printf("\n Oscillation frequency of pendulam %f per sec.",v) E=m*g*l*(1-cos(theta)) printf("\n Energy of pendulum at its maximum potential %e Joule.",E) Delta_e=h*v printf...
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clc; // page no 128 // prob no 4_2_3 //Parallel tuned ckt tuned at resonant freq f=120 MHz f=120*10^6; c=25*10^-12;//capacitance of 12 pF Q=30;//Q-factor of the ckt is 30 BW=10*10^3;//cahnnel BW of the receiver is 10 KHz k=1.38*10^-23 //Boltzman constant in J/K T=290;//Room temp //Determination of effective n...
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Ex5_16.sce
// Scilab Code Ex5.16: Page-292 (2008) clc; clear; h = 6.62e-034; // Planck's constant, Js e = 1.602e-019; // Energy equivalent of 1 eV, J lambda = 0.40e-010; // de-Broglie wavelength associated with the moving electron, m m = 9.11e-031; // Rest mass of an electron, kg V = (h/lambda)^2/(2*m*e); // Vol...
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Ex11_6.sce
clear; clc; t = 1/2;// inches a = 1/2;// inches P = 42;// tons d = 3/4;// inches f_t = 7.5;// tons/in^2 f_s = 6;// tons/in^2 f_b = 12;// tons/in^2 P_s = 2*0.25*%pi*d^2 *f_s;// tons P_b = d*t*f_b;// tons n = P/min(P_s,P_b); n = round(n+1); b1 = P/(t*f_t) + d;// inches b = round(b1); e = (b-d)/b;// efficie...
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//OptoElectronics and Fibre Optics Communication, by C.K Sarkar and B.C Sarkar //Example 6.7 //OS=Windows 10 ////Scilab version Scilab 6.0.0-beta-2(64 bit) clc; clear; //given A=(100)*(50);//area in u-meter^2 Id=10e-9;//Measured dark current in nanoampere eta=0.6;//Quantum efficiency is 60% lamda=1.2e-6;//...
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Gauss elimination.sce
n=input("Number of variables? ") A=input("A=") b=input("b=") //A=[1 2 3 -1; 2 3 -3 -1; 3 2 -4 3; 2 -1 2 3] //b=[10;1;2;7] a=[A,b] for i=2:n for j=1:i-1 a(i,:)=a(i,:)-(a(i,j)/a(j,j))*a(j,:) end end printf ("Executed") disp (a) transformed_A=a(:,1:n) transformed_b=a(:...
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19_1.sce
clear; clc; V=400e3; X=96; Y=.001 * exp(%i * 90/180*%pi); Sb=500e6; Pr=2; Z=complex(0,X); Zb=V*V/Sb; A=1+(Z*Y/2); B=Z/Zb; Vs=1; Vr=.95; d1=asin(Pr*abs(B)/(Vs*Vr)); Qr1=((Vs*Vr)/abs(B)) * cos(d1) - (abs(A)* Vr*Vr/abs(B)) Qs1= (abs(A)* Vs*Vs/abs(B)) - ((Vs*Vr)/abs(B)) * cos(d1) mprintf("\n(a) Qr...
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// Chapter4 // Page.No-136, Figure.No-4.24 // Example_4_13 // Change in output offset voltage // Given clear;clc; delta_Vio=5*10^-6; // Change in input offset voltage delta_t=1; // Unit change in time delta_Iio=2*10^-9; // Change in input offset current t=4; // Time elapsed(weeks) R1=1*10^3;Rf=100*10^3;Rl=10*...
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ex9_1.sce
clc; clear all; deltas = 10e8; // Difference between principal stress in newton per square meters c = 1e-12; // The stress optic coefficient in squared meters per newton N = c*deltas; disp('',N,'The difference between the refractive indices along with the principal stresses is')
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Example9_19.sce
// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 9: POLYPHASE INDUCTION (ASYNCHRONOUS) DYNAMOS // Example 9-19 clear; clc; close; // Clear the work space and console. // Given data P = 8 ; // Number of poles in WRIM f = 60 ; // Operating frequency of the W...
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Ex1_5.sce
// Ex1_5 Page:13 (2014) clc; clear; c = 3e+08; // Speed of light in vacuum, m/s v = 0.9*c; // Speed of beam of particles, m/s delta_t = 5e-06; // Mean lifetime of particles as measured in the Lab frame, s delta_tau = delta_t*sqrt(1-(v/c)^2); // The proper lifetime of the particles from Time Dilation Relati...
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style.fontSize=12; style.displayedLabel="HH_RG"; pal1_1=xcosPalAddBlock(pal1_1,"HH_RG",[],style);
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Example2_12.sce
//Example 2.12 //Program to determine relative refractive index difference using ESI //technique clear; clc ; close ; //Given data lambda_c=1.19*10^(-6); //metre - CUTOFF WAVELENGTH w0=5.2*10^(-6); //metre - SPOT SIZE n1=1.485; //MAXIMUM REFRACTIVE INDEX OF THE CORE ...
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13_6.sce
//To find governor effort and power clc //given c=0.01 W=120//lb w=15//lb k=.720 h=8.944//in Q=c*(W+2*w/(1+k)) x=(2*c/(1+2*c))*(1+k)*h P=Q*x printf("Governor power = Q*x = %.3f in lb",P)
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Example14_7.sce
exec ("Gravitation.sci",-1) //Given that //Both the stars are moving around the centre of mass of the two particale system //m1 = mass of visible star //m2 = mass of invisible star //r1 = distance of m1 from center of mass //r2 = distance of m2 from center of mass //r = r1+r2 distance between both the stars /...
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// Scilab code Exa6.5.1 : To calculate the difference between the electron's speed and speed of light. Page 265 (2011) v = 2.999999997e+08; // Velocity of the electron, m/s c = 3e+08; // Velocity of light,m/s D = c-v; // difference between electron's speed and speed of light,m/s printf("\nThe difference between ...
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ex6_32.sce
// Exa 6.32 clc; clear; close; // Given data P1 = 15;// in bar P2 = 0.15;// in bar T_sat = 198.3;// in degree C T_sat = T_sat + 273;// in K h_fg1 = 1947;// in kJ/kg h_fg2= 2369;// in kJ/kg h_g1 = 845;// in kJ/kg h_f2 = 232;// in kJ/kg f_g2 = 7.985;// in kJ/kg-K x1 = 0.8; Phi_f1 = 2.315;// in kJ/kg-K Phi...
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5_03_example.sci
//Example 5-3 Performance of Hydraulic Turbine-Generator h = 50 //depth of water [m] mdot = 5000 //water mass flow rate [kg/s] Wdot_elect = 1862 //electricity generated [kW] eta_generator = 95 //generator efficiency [%] rho = 1000 //density of water [kg/m^3] g = 9.81 //gravitational acceleration [m/s^2]
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EX4.sce
// Example 3.4: (a) DC load current // (b) DC power in load // (c) Rectification efficiency // (d) Percentage regulation // (e) PIV of each diode clc, clear Vrms=40; // Input in volts Rf=1; // Forward conduction resistance of diodes in ohms RL=29; // Load resi...
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9_12.sce
clc //initialisation of variables t1=303 //temparature in k p2=4.08 //pressure in bar p1=1 //pressure in bar t5=303 //temparature in k x=0.3247 //x=v2/v1 where the relation is v2=v1*(1/rp)^1/n y=0.0385 //y=v3/v1 vo=0.2862 //vo=volume of air delivered/v1 vf=0.8299 //vf=vome of free air /v1 n=1.25 p3=17.5 //pr...
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// Calculate the resistance clc; R25=100; ath=-0.05; dth=35-25; R35=R25*[1+ath*dth]; disp(R35,'resistance at 35 degree C(ohm)=')
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clc C1=12; //m/s p1=1*10^5; //N/m^2 v1=0.5; //m^3/kg C2=90; //m/s p2=8*10^5; //N/m^2 v2=0.14; //m^3/kg dh=150; //kJ/kg Q=-11.67; //kJ/s m=0.2; //kg/s disp("(i) Motor power required to drive the compressor") W=m*[-dh + (C1^2-C2^2)/2/1000] +Q; disp("Power=") disp(-W) disp("kW") disp("(ii)Ratio of inl...
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sce
Ex3_3.sce
//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex3_3(b).sce. clc; clear; R=1; L=1; C=0.1; //case (b) s=0; //Z=R+(L*s)+(1/(C*s)) Z=0; //Z=s/(s^2+s+10) //voltage across the resistancce and inductance are zero...